历年机械振动机械波的高考题答案

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3 2 B. 3 2C.- 1 2 D. 1 2 A.-

第3题图第4题图第5题图5.执行如图所示的程序框图,则输出s的值为() A.3 4 B. 5 6 C. 11 12 D. 25 24 6.执行下面的程序框图,若输入的a,b,k分别为1,2,3,则输出的M=() A.20 3 B. 16 5 C. 7 2 D. 15 8

第6题图第7题图 7.执行上面的程序框图,如果输入的x,t均为2,则输出的S=() A.4 B.5 C.6 D.7 8.执行如图所示的程序框图,输出S的值为() A.3 B.-6 C.10 D.12 第8题图 答案 1.C[当x=1时,执行y=9-1=8.输出y的值为8,故选C.] 2.C[运行相应的程序.第1次循环:i=1,S=10-1=9; 第2次循环:i=2,S=9-2=7;

第3次循环:i =3,S =7-3=4; 第4次循环:i =4,S =4-4=0;满足S =0≤1, 结束循环,输出i =4.故选C.] 3.B [第一次循环:a =3×12=3 2,k =1; 第二次循环:a =32×12=3 4,k =2; 第三次循环:a =34×12=3 8,k =3; 第四次循环:a =38×12=316<1 4,k =4. 故输出k =4.] 4.D [每次循环的结果为k =2,k =3,k =4,k =5>4,∴S =sin 5π6=1 2.] 5.D [s =12+14+16+18=2524,即输出s 的值为25 24.] 6.D [当n =1时,M =1+12=32,a =2,b =3 2; 当n =2时,M =2+23=83,a =32,b =8 3; 当n =3时,M =32+38=158,a =83,b =15 8; n =4时,终止循环.输出M =15 8.] 7.D [k =1,M =1 1×2=2,S =2+3=5; k =2,M =2 2×2=2,S =2+5=7; k =3,3>t ,∴输出S =7,故选D.] 8.C [当i =1时,1<5为奇数,S =-1,i =2; 当i =2时,2<5为偶数,S =-1+4=3,i =3; 当i =3时,3<5为奇数,S =3-33=-5,i =4; 当i =4时,4<5为偶数,S =-6+42=10,i =5; 当i =5时,5≥5,输出S =10.]

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本题考查波的干涉和衍射。难度:易。 4. 2010·上海物理·3声波能绕过某一建筑物传播而光波却不能绕过该建筑物,这是因为 (A )声波是纵波,光波是横波 (B )声波振幅大,光波振幅小 (C )声波波长较长,光波波长很短 (D )声波波速较小,光波波速很大 【解析】C 本题考查波的衍射条件:障碍物与波长相差不多。难度:易。 5.2010·北京·17一列横波沿x 轴正向传播,a 、b 、c 、d 为介质中沿波传播方向上四个质点的平衡位置。某时刻的波形如图1所示,此后,若经过3 4 周期开始计时,则图2描述的是 A.a 处质点的振动图象 B.b 处质点的振动图象 C.c 处质点的振动图象 D.d 处质点的振动图象 【答案】B 【解析】由波的图像经过 4 3 周期a 到达波谷,b 到达平衡位置向下运动,c 到达波峰,d 到达平衡位置向上运动,这是四质点在0时刻的状态,只有b 的符合振动图像,答案B 。 11.2010·重庆·14一列简谐波在两时刻的波形如题14图中实践和虚线所示,由图可确定这列波的 A .周期 B .波速 C .波长 D .频率 【答案】C 【解析】只能确定波长,正确答案C 。题中未给出实线波形和虚线波形的时刻,不知道时间

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5.执行如图所示的程序框图,则输出s的值为() A. 10 B. 17 C. 19 D. 36 6.执行下面的程序框图,如果输入的x=0,y=1,n=1,则输出x,y的值满足() A. y=2x B. y=3x C. y=4x D. y=5x 7.执行如图程序框图,如果输入的a=4,b=6,那么输出的n=( ) A. 3 B. 4 C. 5 D. 6

8.如图所示的程序框图是为了求出满足3n-2n>1000的最小偶数n,那么在和 两个空白框中,可以分别填入() A. A>1000和n=n+1 B. A>1000和n=n+2 C. A≤1000和n=n+1 D. A≤1000和n=n+2 9.执行如图的程序框图,为使输出S的值小于91,则输入的正整数N的最小值为 A. 5 B. 4 C. 3 D. 2 10.执行如图所示的程序框图,输出的S值为() A. 2 B. C. D. 11.若执行右侧的程序框图,当输入的x的值为4时,输出的y的值为2,则空白判断 框中的条件可能为() A.x>3 B. x>4 C. x≤4 D. x≤5

高中物理-机械振动、机械波高考真题演练

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历年机械振动机械波的高考题答案

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