《材料成形工艺基础》第2版课后习题答案(柳秉毅)

《材料成形工艺基础》第2版课后习题答案(柳秉毅)
《材料成形工艺基础》第2版课后习题答案(柳秉毅)

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高数课后习题及答案 第二章 2.3

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新视野大学英语册第二版课后习题答案全解

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(完整版)微观经济学第二章课后习题答案

第二章需求、供给和均衡价格 1.解: (1)将需求函数Q d= 50-5P和供给函数Q s=-10+5P代入均衡条件Q d=Q s ,有:50- 5P= -10+5P 得: Pe=6 以均衡价格Pe =6代入需求函数Q d=50-5p ,得: Qe=50-5×6 或者,以均衡价格 Pe =6 代入供给函数Q s =-10+5P ,得:Qe=-10+5×6 所以,均衡价格和均衡数量分别为Pe =6 , Qe=20 图略. (2)将由于消费者收入提高而产生的需求函数Q d=60-5p和原供给函数Q s=-10+5P, 代入均 衡条件Q d=Q s有: 60-5P=-10+5P 解得Pe =7 以均衡价格Pe =7代入Q d=60-5p ,得 Qe=25 或者,以均衡价格Pe =7代入Qs =-10+5P, 得Qe=25 所以,均衡价格和均衡数量分别为Pe =7,Qe=25 (3)将原需求函数Q d=50-5p 和由于技术水平提高而产生的供给函数Q s=-5+5p ,代入均衡条件Q d=Q s,有: 50-5P=-5+5P得 P e=5.5 以均衡价格Pe=5.5代入Q d=50-5p, 得Qe=50-5×5.5=22.5 所以,均衡价格和均衡数量分别为Pe=5.5,Qe=22.5图略。 (4)(5)略 2.解: (1)根据中点公式计算,e d=1.5 (2)由于当P=2时,Q d=500-100*2=300,

所以,有: 22 .(100)3003 d dQ P dP Q e =- =--*= (3)作图,在a 点P=2时的需求的价格点弹性为:e d =GB/OG=2/3或者e d =FO/AF=2/3 显然,利用几何方法求出P=2时的需求的价格弹性系数和(2)中根据定义公式求出结果是相同的,都是e d =2/3 3解: (1) 根据中点公式 求得:4 3 s e = (2) 由于当P=3时,Qs=-2+2×3=4,所以 3 .2 1.54 s dQ P dP Q e = =?= (3) 作图,在a 点即P=3时的供给的价格点弹性为:e s =AB/OB=1.5 显然,在此利用几何方法求出的P=3时的供给的价格点弹性系数和(2)中根据定义公式求出的结果是相同的,都是e s =1.5 4.解: (1)根据需求的价格点弹性的几何方法,可以很方便地推知:分别处于不同的线性需求曲线上的a 、b 、e 三点的需求的价格点弹性是相等的,其理由在于,在这三点上都有: e d =FO/AF (2)根据求需求的价格点弹性的几何方法,同样可以很方便地推知:分别处于三条线性需求曲线上的a 、e 、f 三点的需求的价格点弹性是不相等的,且有e da

第二章习题答案

第2章程序控制结构 2.1 选择题 1.已知int i=0, x=1, y=0;,在下列选项中,使i的值变成1的语句是( C )。 (A)if( x&&y ) i++; (B)if( x==y ) i++; (C)if( x||y ) i++; (D)if( !x ) i++; 2.设有函数关系为y= 10 00 10 x x x -< ? ? = ? ?> ? ,下列选项中,能正确表示上述关系的是( C )。 (A)y = 1; (B)y = -1; if( x >= 0 ) if( x != 0 ) if( x == 0 ) y = 0; if( x > 0 ) y = 1; else y = -1; else y = 0 (C)if( x <= 0 ) (D)y = -1; if( x < 0 ) y = -1; if( x <= 0 ) else y = 0; if( x < 0 ) y = -1; else y = 1; else y = 0; 3.假设i=2,执行下列语句后i的值为(B )。 switch( i ) { case 1 : i ++; case 2 : i --; case 3 : ++ i; break; case 4 : -- i; default : i ++; } (A)1 (B)2 (C)3 (D)4 4.已知int i=0,x=0;,在下面while语句执行时循环次数为(D )。 while( !x && i< 3 ) { x++; i++; } (A)4 (B)3 (C)2 (D)1 5.已知int i=3;,在下面do_while 语句执行时的循环次数为(B )。 do{ i--; cout<=0 ); (C)int a=5; while( a ) { a--; };

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全新版大学英语综合教程第二版课后练习答案精编W O R D版 IBM system office room 【A0816H-A0912AAAHH-GX8Q8-GNTHHJ8】

Unit1 Ways of Learning Vocabulary I 1. 1)insert 2)on occasion 3)investigate 4)In retrospect 5)initial 6)phenomen a 7)attached 8)make up for 9)is awaiting 10)not; in the least 11)promote 12)emerged 2. 1)a striking contrast between the standards of living in the north of the country and the south. 2)is said to be superior to synthetic fiber. 3)as a financial center has evolved slowly. 4)is not relevant to whether he is a good lawyer.

5)by a little-known sixteen-century Italian poet have found their way into some English magazines. 3. 1)be picked up; can’t accomplish; am exaggerating 2)somewhat; the performance; have neglected; they apply to 3)assist; On the other hand; are valid; a superior II 1)continual 2)continuous 3)continual 4)continuous 5)principal 6)principal 7)principle 8)principles 9)principal III 1.themselves 2.himself/herself 3.herself/by herself/on her own 4.itself

第二章 习题答案

第二章 需求、供给和均衡价格 2. 假定表2—1(即教材中第54页的表2—5)是需求函数Q d =500-100P 在一定价格范围内的需求表: 表2—1 (1)求出价格2元和4元之间的需求的价格弧弹性。 (2)根据给出的需求函数,求P =2元时的需求的价格点弹性。 (3)根据该需求函数或需求表作出几何图形,利用几何方法求出P =2元时的需求的价格点弹性。它与(2)的结果相同吗? 解答:(1)根据中点公式e d =-ΔQ ΔP ·P 1+P 22,Q 1+Q 22 ),有 e d =2002·2+42,300+1002)=1.5 (2)由于当P =2时,Q d =500-100×2=300,所以,有 e d =-d Q d P ·P Q =-(-100)·2300=23 (3)根据图2—4,在a 点即P =2时的需求的价格点弹性为 e d =GB OG =200300=23 或者 e d =FO AF =23 图2—4 显然,在此利用几何方法求出的P =2时的需求的价格点弹性系数和(2)中根据定义公式 求出的结果是相同的,都是e d =23 。 3. 假定表2—2(即教材中第54页的表2—6)是供给函数Q s =-2+2P 在一定价格范围内的供给表:

表2—2 (1)求出价格(2)根据给出的供给函数,求P =3元时的供给的价格点弹性。 (3)根据该供给函数或供给表作出几何图形,利用几何方法求出P =3元时的供给的价格点弹性。它与(2)的结果相同吗? 解答:(1)根据中点公式e s =ΔQ ΔP ·P 1+P 22,Q 1+Q 22 ),有 e s =42·3+52,4+82)=43 (2)由于当P =3时,Q s =-2+2×3=4,所以,e s =d Q d P ·P Q =2·34 =1.5。 (3)根据图2—5,在a 点即P =3时的供给的价格点弹性为 e s =AB OB =64 =1.5 图2—5 显然,在此利用几何方法求出的P =3时的供给的价格点弹性系数和(2)中根据定义公式求出的结果是相同的,都是e s =1.5。 4. 图2—6(即教材中第54页的图2—28)中有三条线性的需求曲线AB 、AC 和AD 。 图2—6 (1)比较a 、b 、c 三点的需求的价格点弹性的大小。

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