北京邮电大学2009-2010通原II期末试题
北京邮电大学2009-2010通原II期末考试一．填空
北邮网络学院大学英语2阶段作业3
一、阅读理解（共1道小题，共25.0分） 1. A pretty, well―dressed young lady stopped a taxi in a big square, and a said to the driver, "Do you see that young man at the other side of the square?" "Yes," said the taxi driver. The young man was standing outside a restaurant and looking impatiently (不耐烦地) at his watch every few seconds. "Take me over there," said the young lady. There were a lot of cars and buses in the square, so the taxi driver asked, "Are you afraid to cross the street?" "Oh, no!" said the young lady. "But I promised that I would meet the young man for lunch at one o' clock, and it is now a quarter to two. If I arrive in a taxi, it will at least seem as if I had tried not to be late." 1.How did the young woman get to the square? A.She arrived in a taxi. B.She drove there in a car. C.She got there by bus. D.The story doesn't tell us. 2.Why did the lady stop the taxi? A.Because she didn't want to be late for her appointment (约会). B.Because she wanted to get out of the taxi. C.Because she wanted to go to the restaurant in it. D.Because she was afraid of walking across the street. 3.The young man at the other side of the square_______. A.had probably been waiting for a long time B.had some problem with his watch C.was probably a waiter of the restaurant D.was someone the young lady didn't want to see 4.The young lady was_______. A.clever at making excuse B.not late at all C.45 minutes earlier D.15 minutes late 5.Had she tried not to be late? A.Yes, she had tried her best. B.No, she was just pretending that she had tried. C.Yes, she had tried but she was still late. D.No, she thought being late was better than being early.
北邮scilab_通信原理软件实验报告
信息与通信工程学院通信原理软件实验报告
实验二时域仿真精度分析 一、实验目的 1. 了解时域取样对仿真精度的影响 2. 学会提高仿真精度的方法 二、实验原理 一般来说，任意信号s(t)是定义在时间区间(-无穷，+无穷)上的连续函数，但所有计算机的CPU 都只能按指令周期离散运行，同时计算机也不能处理这样一个时间段。为此将把s(t)按区间[-T/2 ,+T/2 ]截短为按时间间隔dert T均匀取样，得到的取样点数为N=T/dert T. 仿真时用这个样值集合来表示信号s(t)。Dert T反映了仿真系统对信号波形的分辨率，越小则仿真的精确度越高。据通信原理所学，信号被取样以后，对应的频谱是频率的周期函数，其重复周期是1/t; 。如果信号的最高频率为 那么必须有 才能保证不发生频域混叠失真，这是奈奎斯特抽样定理。设 则称为仿真系统的系统带宽。如果在仿真程序中设定的采样间隔是，那么不能用 此仿真程序来研究带宽大于这的信号或系统。换句话说，就是当系统带宽一定的情况下，信号的采样频率最小不得小于2*Bs，如此便可以保证信号的不失真，在此基础上时域采样频率越高，其时域波形对原信号的还原度也越高，信号波形越平滑。也就是说，要保证信号的通信成功，必须要满足奈奎斯特抽样定理，如果需要观察时域波形的某些特性，那么采样点数越多，可得到越真实的时域信号。 三、实验步骤 1.将正弦波发生器模块、示波器模块、时钟模块按下图连接：
时钟设置0.01，得到的结果如下： 时钟设置0.3，以后得到的结果如下：
五、思考题 （1）观察分析两图的区别，解释其原因。 答：因为信号周期是1，而第一个图的采样周期是0.01，所以一个周期内能采样100个点，仿真出来的波形能较精确地显示成完整波形，而第二个图采样周期是0.3，所以一个周期内只有三个采样点，故信号失真了。 （2）将示波器的控制时钟的period的参数改为0.5，观察仿真结果，分析其原因。 结果如下：
北邮大学英语3-期末考试总复习题阶段作业一、二、三汇总,考试必备你懂的
大学英语3词汇选择练习题 第一单元选择题 1. It __________that the necklace was made of glass. A. turned out B. made out C. looked out D. took out 解析：该题选A，题目大意是“原来那串项链是用玻璃做的”。 turn out: 结果是；证明是 The party turned out to be very successful. 晚会结果开得很成功。 2. ___________, he can finish the work in a couple of weeks. A. Giving good health B. If give good health C. Given good health D. If he is good given health 解析：该题选C，题目大意是“倘若身体好，他能在一两周内完成这项工作”。given 引导方式状语，意为“倘若，假设，考虑到”。如： 1. Given their inexperience, the y’ve done a good job.考虑到他们缺乏经验，他们 的工作已经做得不错了。 2. Given some more time, I would do the job better.假如时间再多些，我能把工作 做得更好。 3. Given good health, the old lady can look after her grand-daughter for her son.假 如身体好的话，这位老太太能帮她儿子照看孙女。 3. ___________ to speak at the meeting, I couldn’t very well refuse. A. Called up B. Called off C. Called at D. Called on 解析：该题选D，题目大意是“要让我在会上发言，我是不会拒绝的”。 call on sb. to do st h：invite/require sb. to do sth.请/要求某人做某事 1. A teacher can call on individual students to compose similar questions. 老师可以要求每个学生提出类似的问题。 2. The chairman called on his people to organize so that they could be more powerful.主席号召他的民众组织起来，这样才能更有力量。 4. The poor police had never __________ of winning. A. made a chance B. took a chance C. stood a chance D. kept a chance 解析：该题选C，题目大意是“可怜的警察毫无胜诉的机会”。 stand a chanc e：have a prospect (of sth.) 有…希望 1. stand a chance of winning the game有可能赢得这场比赛 2. I think you stand a good chance of being elected president.我认为你极有可能 当选为公司总裁。 3. Weak and lame in one leg, he never stood a chance of getting the job of taxi-driver.由于身体虚弱，并且有一条跛腿，他从未有机会得到出租车司机的工作。 5. If our neighbor continues to refuse to keep his dog under control, we have to take him to ___________. A. solicitor B. brush C. prisoner D. court 解析：该题选D，题目大意是“如果我们的邻居仍然拒绝看管好他的狗，我们就不得不法庭上见了”。 take sb. to court：控告某人，对某人提出诉讼 1. If you don't pay up, I'll take you to court. 如果你不还清欠款, 我就到法院告
北邮第三次阶段作业大学英语2
1. People have been talking about health for a long time because people know the importance of it. People's understanding of health also becomes deeper with the progress in scientific research. Recently the term "health" has come to have a wider meaning than it used to. It no longer means just the absence of illness. Today, health means the well-being of your body, your mind and your relationship with other people. This new concept of health is closely related to another term----quality of life. Quality of life is the degree of overall satisfaction that a person gets from life. Why has the emphasis of health shifted from the absence of disease to a broader focus on the quality of a person's life？One reason for this has to do with the length and conditions of life that people can now expect. Medical advances have made it possible for people today to live longer, healthier lives. Imagine for a moment that you were born in the year 1900. You could have expected on average to live until about the age of 47. In contrast, if you were born in the year 1999, you could expect to live to the age of 75. 2. 1. ______leads to people's deeper understanding of health. 2. https://www.360docs.net/doc/669797789.html,mon knowledge 2.Progress in scientific research 3.Better conditions of living 4.Quality of life 3. According to the passage, to people of today, health means______. 4. 1.absence of illness 2. a long life 3.good conditions of living 4.overall satisfaction with life
北邮通原软件实验
实验一 实验目的：假设基带信号为m(t)=sin(2000πt)+2cos(1000πt)，载波频率为20kHz,请仿真出AM，DSB-SC，SSB信号，观察已调信号的波形和频谱。 1．AM信号： （1）信号的表达式 （3）流程图 AM信号 s= (1+0.3*m).*cos(2*pi*fc*t); 绘制时域波形及频谱 傅氏变换S= t2f(s,fs) （2）源代码 %AM信号的产生 fs= 800; %采样频率KHz T= 200; %截短时间ms N= T*fs; %采样点数 dt= 1/fs; t= [-T/2:dt:T/2-dt]; df= 1/T; f=[-fs/2:df:fs/2-df]; fm= 1; % kHz fc= 20; % kHz m= sin(2*pi*fm*t)+2*cos(1*fm*pi*t); s= (1+0.3*m).*cos(2*pi*fc*t); %AM 信号 S= t2f(s,fs); figure(1) plot(f,abs(S1)) title('AM信号频谱') xlabel('f') ylabel('S(f)') axis([-25,25,0,max(abs(S1))]); %xset('window',2)figure(2) plot(t,s1) title('AM信号波形') xlabel('t') ylabel('s(t)') axis([-3,3,-3,3]); （4）实验结果
精选文库 -3 -2-1 0123 -3-2 -1 1 2 3 AM 信号波形 t(ms) s (t ) -25 -20 -15 -10 -5 05 10 15 20 25 0102030405060708090 100AM 信号频谱 f(kHz) S (f )
北京邮电大学通信原理软件实验报告
北京邮电大学实验报告 题目：基于SYSTEMVIEW通信原理实验报告
实验一：验证抽样定理 一、实验目的 1、掌握抽样定理 2. 通过时域频域波形分析系统性能 二、实验原理 低通滤波器频率与m（t）相同 三、实验步骤 1. 要求三个基带信号相加后抽样，然后通过低通滤波器恢复出原信号。 2. 连接各模块完成系统，同时在必要输出端设置观察窗。 3. 设置各模块参数。 三个基带信号的频率从上到下分别设置为10hz、12hz、14hz。 抽样信号频率设置为28hz，即2*14hz。（由抽样定理知，） 将低通滤波器频率设置为14hz，则将恢复第三个信号（其频率为14hz）进行系统定时设置，起始时间设为0，终止时间设为1s.抽样率设为1khz。 3.观察基带信号、抽样后的信号、最终恢复的信号波形
四、实验结果 最上面的图为原基带信号波形，中间图为最终恢复的信号波形，最下面的图为抽样后的信号波形。 五、实验讨论 从实验结果可以看出，正如前面实验原理所述，满足抽样定理的理想抽样应该使抽样后的波形图如同冲激信号，且其包络图形为原基带信号波形图。抽样后的信号通过低通滤波器后，恢复出的信号波形与原基带信号相同。 由此可知，如果每秒对基带模拟信号均匀抽样不少于2次，则所得样值序列含有原基带信号的全部信息，从该样值序列可以无失真地恢复成原来的基带信号。 讨论：若抽样速率少于每秒2次，会出现什么情况？ 答：会产生失真，这种失真被称为混叠失真。 六、实验建议、意见 增加改变抽样率的步骤，观察是否产生失真。
实验二:奈奎斯特第一准则 一、实验目的 （1）理解无码间干扰数字基带信号的传输； （2）掌握升余弦滚降滤波器的特性； （3）通过时域、频域波形分析系统性能。 二、实验原理 在现代通信系统中，码元是按照一定的间隔发送的，接收端只要能够正确地恢复出幅度序列，就能够无误地恢复传送的信号。因此，只需要研究如何使波形在特定的时刻无失真，而不必追求整个波形不变。 奈奎斯特准则提出：只要信号经过整形后能够在抽样点保持不变，即使其波形已经发生了变化，也能够在抽样判决后恢复原始的信号，因为信息完全恢复携带在抽样点幅度上。 奈奎斯特准则要求在波形成形输入到接收端的滤波器输出的整个传送过程传递函数满足：,其充分必要条件是x(t)的傅氏变换X ( f )必须满足 奈奎斯特准则还指出了信道带宽与码速率的基本关系。即R B =1/T B =2? N =2B N。 式中R b 为传码率，单位为比特/每秒（bps）。f N 和B N 分别为理想信道的低通截止 频率和奈奎斯特带宽。上式说明了理想信道的频带利用率为R B /B N =2。 在实际应用中，理想低通滤波器是不可能实现的，升余弦滤波器是在实际中满足无码间干扰传输的充要条件，已获得广泛应用的滤波器。 升余弦滤波器的带宽为：。其中，α为滚降系数，0 ≤α≤1， 三、实验步骤 1.根据奈奎斯特准则，设计实现验证奈奎斯特第一准则的仿真系统，同时在必 要输出端设置观察窗。设计图如下
北邮英语试题答案(2)
一、阅读理解（共1道小题，共50.0分） 1.Robert Bruce was a famous Scottish general. In the early 14th century he tried to drive the English out of Scotland, but he was not successful because the English were too strong. Finally, Bruce had to run away and hide in a cave. One day, he lay in his cave thinking of the sad state of Scotland. A spider began to make a web above his head. Simply to pass the time, Bruce broke the web. Immediately the spider began to make a new one. Six times Bruce broke the web and six times the spider immediately made a new one. Bruce was surprised at this. He told himself that he would break the web a 7th time. If the spider made a new one, it would be a good lesson to him, for like the spider, he had been defeated six times. Bruce then broke the web. Again the spider made a new one. From this simple fact, Bruce became encouraged. He again got an army together. This time he was successful and drove the English out of Scotland. 1. Who was Robert Bruce? A. He was an English general. B. He was a Scottish general. C. He was a spider researcher D. He was a biologist from Scotland. 2. Why did Bruce hide in a cave? A. Because he was defeated by the English. B. Because he was afraid of the English army. C. Because he was looking for spiders D. Because he was badly injured in the battle. 3. In the beginning he broke the spider web just because______.
北邮大学英语3第二次阶段作业
北邮大学英语3第二次阶段作业 一、完形填空（共1道小题，共50.0分） 1.Many years ago there was a poor man. He had an orange tree 1 his garden. On the tree there were many fine oranges. 2 he found one 3 his oranges was much bigger 4 the others. It was as 5 as a football. Nobody had ever seen 6 orange. The poor man took the orange to the king. The king was so happy ___7 __he gave the man a lot of money for it. When a rich man heard of it, he said to hi mself, “It's only an orange. Why has the king given so much money 8__ it? I'II take my gold cup to the king. He'll give me 9 money.” The next day when the king received the gold cup, he said to the rich man, 'What a beautiful cup! I'll show you __10__ , please take this great orange." a. A.on B.in C.over D.with 学生答案: B; 标准答 案: B b. A.One day B.Yesterday C.When D.This morning 学生答案: A; 标准答 案: A c. A.for B.in
北邮大学英语2答案【精选】word版本
北邮大学英语2答案 【精选】
一、完形填空（共1道小题，共50.0分） 1.(错误) I first saw the baby panda when she was only 10 days old. She looked like a white mouse. We ____1___her Xi Wang. It means “hope”. When Xi Wang was born, she weighed____2___100 grams. Xi Wang drank her mothe r’s milk for as much as 14 hours a day. When she was six months old, she started to eat bamboo shoots (嫩芽) and ____3____. Eight months later, she was not a small baby any more. She grew into a____4___young panda and weighed 35 kilos. When Xi Wang was 20 months old, she had to look after herself _____5___ her mother had another baby. ____6_____, it is very difficult for pandas to live in the wild. Here are some of the _____7____that pandas like Xi Wang may have in the future. If hunters catch a panda, they will kill it for its fur. If farmers____8____trees and forests, pandas will have no place to live in. When mothers leave baby pandas alone, people will often take them away. People think that the baby pandas need ____9_____. If pandas are in danger, we should try our best to protect them. If we do____10_____, soon there will be no more pandas in the world!?? a. A.made B.called C.told D.kept 学生答案: B; 标准答 案: B b. A.quite
北邮-通原软件实验报告-16QAM
实验一： 16QAM调制与解调 一、实验目的 1、熟悉16QAM信号的调制与解调，掌握SYSTEMVIEW软件中，观察眼图与星座图的方 法。 2、强化SYSTEMVIEW软件的使用，增强对通信系统的理解。 二、实验原理 1、16QAM 16QAM是指包含16种符号的QAM调制方式。 16QAM 调制原理方框图： 图一16QAM调制框图 16QAM解调原理方框图： 图二16QAM解调框图 16QAM 是用两路独立的正交 4ASK 信号叠加而成，4ASK 是用多电平信号去键控载波而得到的信号。它是 2ASK 体制的推广，和 2ASK 相比，这种体制的优点在于信息传
输速率高。 正交幅度调制是利用多进制振幅键控（MASK）和正交载波调制相结合产生的。 16 进制的正交振幅调制是一种振幅相位联合键控信号。16QAM 的产生有 2 种方法： （1）正交调幅法，它是有 2 路正交的四电平振幅键控信号叠加而成； （2）复合相移法：它是用 2 路独立的四相位移相键控信号叠加而成。 在这里我们使用第一种方法。 16QAM信号的星座图： 图三16QAM星座图 上图是16QAM的星座图，图中f1(t)和f2(t)是归一化的正交基函数。各星座点等概出现。 星座图中最近的距离与解调误码率有很密切的关系。上图中的最小距离是dmin=2。 16QAM的每个星座点对应4个比特。哪个星座点代表哪4比特，叫做星座的比特映射。通常采用格雷映射，其规则是：相邻的星座点只差一个比特。 实验所需模块连接图如下所示： 图四模块连接图 各个模块参数设置：
三、实验步骤 （1）按照实验所需模块连接图，连接各个模块 （2）设置各个模块的参数： ①信号源部分：PN序列发生器产生双极性NRZ序列，频率10HZ 图五信号源设置示意图 ②载频：频率设置为100Hz。
北邮英语试题答案 (3)
一、完形填空（共1道小题，共50.0分） 1.Many years ago there was a poor man. He had an orange tree 1 his garden. On the tree there were many fine oranges. 2 he found one 3 his oranges was much bigger 4 the others. It was as 5 as a football. Nobody had ever seen 6 orange. The poor man took the orange to the king. The king was so happy ___7 __he gave the man a lot of money for it. When a rich man heard of it, he said to himself, “It's only an orange. Why has the king given so much money 8__ it? I'II take my gold cup to the king. He'll give me 9 money.” The next day when the king received the gold cup, he said to the rich man, 'What a beautiful cup! I'll show you __10__ , please take this great orange." a. A.on B.in C.over D.with 学生答案: B; 标准答 案: B b. A.One day B.Yesterday C.When D.This morning 学生答案: A; 标准答 案: A c. A.for B.in C.of D.among
北邮大学英语2阶段作业2
A . anyone else B . anything C . some of the things D . anything else A . more larger, all B . much larger, that C . very larger, both D . larger, those
A . flooded B . were flooded C . was flooded D . flood √4. A . being B . C . having D . having A . happened to see B . was happened to see C . happened to be seen D . was happened to be seen
A . rather B . enough C . quite a D . fairly A . the much best B . much the most best C . the very best D . very the best A . will put off
B . will be put off C . will be put D . has put off A . When B . What time C . How often D . How long A . take good care of B . has taken good care of C . took good care of D . are taken good care of
北邮通信原理软件实验报告
通信原理软件实验报告 学院：信息与通信工程学院班级：
一、通信原理Matlab仿真实验 实验八 一、实验内容 假设基带信号为m(t)=sin(2000*pi*t)+2cos(1000*pi*t),载波频率为20kHz，请仿真出AM、DSB-SC、SSB信号，观察已调信号的波形和频谱。 二、实验原理 1、具有离散大载波的双边带幅度调制信号AM 该幅度调制是由DSB-SC AM信号加上离散的大载波分量得到，其表达式及时间波形图为： 应当注意的是，m(t)的绝对值必须小于等于1，否则会出现下图的过调制： AM信号的频谱特性如下图所示： 由图可以发现，AM信号的频谱是双边带抑制载波调幅信号的频谱加上离散的大载波分量。
2、双边带抑制载波调幅（DSB—SC AM）信号的产生 双边带抑制载波调幅信号s(t)是利用均值为0的模拟基带信号m(t)和正弦载波c(t)相乘得到，如图所示： m(t)和正弦载波s(t)的信号波形如图所示： 若调制信号m(t)是确定的，其相应的傅立叶频谱为M(f)，载波信号c(t)的傅立叶频谱是C(f),调制信号s(t)的傅立叶频谱S(f)由M(f)和C(f)相卷积得到，因此经过调制之后，基带信号的频谱被搬移到了载频fc处，若模拟基带信号带宽为W，则调制信号带宽为2W，并且频谱中不含有离散的载频分量，只是由于模拟基带信号的频谱成分中不含离散的直流分量。 3、单边带条幅SSB信号 双边带抑制载波调幅信号要求信道带宽B=2W, 其中W是模拟基带信号带宽。从信息论关点开看，此双边带是有剩余度的，因而只要利用双边带中的任一边带来传输，仍能在接收机解调出原基带信号，这样可减少传送已调信号的信道带宽。 单边带条幅SSB AM信号的其表达式： 或 其频谱图为：
北邮网络教育学院大学英语试题
一、单项选择题（共20道小题，共100.0分）1Her brother ______ to leave her in the dark room alone when she disobeyed his order. 1declared 1threatened 1warned 1exclaimed 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0提示:2It is certain that he will ______ his business to his son when he gets old.1take over 1think over 1hand over 1go over 知识点:Vocabulary 学生答案:[C;]标准答案:C 得分:[5]试题分值: 5.0提示:3The president spoke at the business meeting for nearly an hour without ______ his notes. 1bringing up 1referring to 1looking for 1trying on 知识点:Vocabulary 学生答案:[B;]标准答案:B 得分:[5]试题分值: 5.0 提示: 4 With oil prices keeping ______, people are hesitating whether to buy a car or not.1 rising 1 arising 1raising 、管路敷设技术通过管线敷设技术不仅可以解决吊顶层配置不规范高中资料试卷问题，而且可保障各类管路习题到位。在管路敷设过程中，要加强看护关于管路高中资料试卷连接管口处理高中资料试卷弯扁度固定盒位置保护层防腐跨接地线弯曲半径标高等，要求技术交底。管线敷设技术中包含线槽、管架等多项式，为解决高中语文电气课件中管壁薄、接口不严等问题，合理利用管线敷设技术。线缆敷设原则：在分线盒处，当不同电压回路交叉时，应采用金属隔板进行隔开处理；同一线槽内，强电回路须同时切断习题电源，线缆敷设完毕，要进行检查和检测处理。、电气课件中调试对全部高中资料试卷电气设备，在安装过程中以及安装结束后进行高中资料试卷调整试验；通电检查所有设备高中资料试卷相互作用与相互关系，根据生产工艺高中资料试卷要求，对电气设备进行空载与带负荷下高中资料试卷调控试验；对设备进行调整使其在正常工况下与过度工作下都可以正常工作；对于继电保护进行整核对定值，审核与校对图纸，编写复杂设备与装置高中资料试卷调试方案，编写重要设备高中资料试卷试验方案以及系统启动方案；对整套启动过程中高中资料试卷电气设备进行调试工作并且进行过关运行高中资料试卷技术指导。对于调试过程中高中资料试卷技术问题，作为调试人员，需要在事前掌握图纸资料、设备制造厂家出具高中资料试卷试验报告与相关技术资料，并且了解现场设备高中资料试卷布置情况与有关高中资料试卷电气系统接线等情况，然后根据规范与规程规定，制定设备调试高中资料试卷方案。、电气设备调试高中资料试卷技术电力保护装置调试技术，电力保护高中资料试卷配置技术是指机组在进行继电保护高中资料试卷总体配置时，需要在最大限度内来确保机组高中资料试卷安全，并且尽可能地缩小故障高中资料试卷破坏范围，或者对某些异常高中资料试卷工况进行自动处理，尤其要避免错误高中资料试卷保护装置动作，并且拒绝动作，来避免不必要高中资料试卷突然停机。因此，电力高中资料试卷保护装置调试技术，要求电力保护装置做到准确灵活。对于差动保护装置高中资料试卷调试技术是指发电机一变压器组在发生内部故障时，需要进行外部电源高中资料试卷切除从而采用高中资料试卷主要保护装置。
北邮通原软件实验报告
北京邮电大学实验报告题目：基于SYSTEMVIEW通信原理实验报告 班级： 专业： 姓名： 成绩： 实验1：抽样定理 一．实验目的 （1）掌握抽样定理 （2）通过时域频域波形分析系统性能
二．实验原理 抽样定理：设时间连续信号m（t），其最高截止频率为fm ，如果用时间间隔为T<=1/2fm 的采样序列对m（t）进行抽样时，则m（t）就可被样值信号唯一地表示。 抽样过程原理图（时域）重建过程原理图（频域） 具体而言：在一个频带限制在（0，f h）内的时间连续信号f（t），如果以小于等于1/(2 f h)的时间间隔对它进行抽样，那么根据这些抽样值就能完全恢复原信号。或者说，如果一个连续信号f（t）的频谱中最高频率不超过f h，这种信号必定是个周期性的信号，当抽样频率f S≥2 f h时，抽样后的信号就包含原连续信号的全部信息，而不会有信息丢失，当需要时，可以根据这些抽样信号的样本来还原原来的连续信号。根据这一特性，可以完成信号的模-数转换和数-模转换过程。 三．实验步骤 1.将三个基带信号相加后抽样，然后通过低通滤波器恢复出原信号。实现验证抽样定理的仿真系统，同时在必要的输出端设置观察窗。如下图所示 2.设置各模块参数 三个基带信号频率从上至下依次为10hz、20hz、40hz。 抽样信号频率fs设置为80hz，即2*40z。（由抽样定理知，fs≥2fH）。低通滤波器频率设置为40hz 。设置系统时钟，起始时间为0，终止时间设为1s.抽样率为1khz。 3.改变抽样速率观察信号波形的变化。
五．实验建议、意见 将抽样率fs设置为小于两倍fh的值，观察是否会产生混叠失真。 实验2：验证奈奎斯特第一准则 一．实验目的 （1）理解无码间干扰数字基带信号的传输； （2）掌握升余弦滚降滤波器的特性； （3）通过时域、频域波形分析系统性能。 二．实验原理 基带传输系统模型 奈奎斯特准则提出：只要信号经过整形后能够在抽样点保持不变，即使其波形已经发生了变化，也能够在抽样判决后恢复原始的信号，因为信息完全恢复携带在抽样点幅度上。 无码间干扰基带传输时，系统冲击响应必须满足x(nTs)=1(n=0); x(nTs)=0(n=!0)。相应的推导出满足x(t)的傅里叶变换X(f)应满足的充分必要条件： 该充要条件被称为无码间干扰基带传输的奈奎斯特准则。 奈奎斯特准则还指出了信道带宽与码速率的基本关系。即Rb=1/Tb=2?N=2BN。说明了理想信道的频带利用率为Rb/BN=2。 在实际应用中，理想低通滤波器是不可能实现的，升余弦滤波器是在实际中满足无码间干扰传输的充要条件，已获得广泛应用。 三．实验步骤 1.根据奈奎斯特准则，设计实现验证奈奎斯特第一准则的仿真系统，同时在必要输出端设置观察窗。如下图所示
北邮英语统考题库
北邮英语统考题库 a ted Test（1） 第一部分：交际用语（共10 题?；每 题1分?，满分10分?） 部分共 ?10? ， 每 ??部分 4?选项，请从A、B、 C、D 选项?选 ?? 选项?。 1. — How are you, Bob? —___ Ted. A. How are you? you. C. How do you do? D. Nice to meet you. 2. —s for your help. —_ u re. mind. me. 3. —r. —__. A. call my e s e s e s e s me 4. —___? — Oh, r. D. whic is that 5. —with you? —____, and how are you? o n it B. Ahem, not too bad s y fast 6. —you have on! —___ s. I got it ye r day. . C. You can have it. . — r day? — r. e s. e s. e nt. — m e back! Had a nice trip? —____ day. C. By d ays. call. — now?
— __ e r here. r. s g. h op, you know. 10. — n g now. — ____ r ful. ? C. Not at all. D. Good luck! 第二部分：阅读理解（共15 题?；每 题2分?，满分30分?） 部分共 ?3 ，每 ?5 题?。请从每 ?题A、B、C、D 选项?，选 ??选项。 Passa?g e 1 Commu?n ity servi?c e is an impor?t ant compo?n ent of educa?t ion here at our unive?r s ity?.We encou?r age all stude?n ts to volun?t eer for at least? one commu?n ity activ?ity befor?e they gradu?a te. A new commu?n ity progr?a m calle?d“One On One” helps? eleme?n tary?stude?n ts who ve falle?n behin?d. Your educa?t ion major?s might? be espec?ially?inter?e sted?i n it becau?s e it offer?s the oppor?t unit?y to do some teach?ing, that is, tutor?ing in math and Engli?s h. You d have to volun?t eer two hours? a week for one semes?t er. You can choos?e to help a child?with math, Engli?s h, or both. Half-hour lesso?n s are fine, so you could?do a half hour of each subje?ct two days a week. Profe?s sor Dodge?will act as a mento?r（导师）to the tutor?s—he ll be avail?a ble to help you with lesso?n plans? or to offer? sugge?s tion?s for activ?ities?. He has offic?e hours? every? Tuesd?a y and Thurs?d ay after?n oon. You can sign up for the progr?a m with him and begin?the tutor?ing next week. I m sure you ll enjoy?this commu?n ity servi?c e and you ll gain valua?b le exper?ience?at the same time. It looks?good on your resum?e, too, showi?n g that you ve had exper?ience?with child?ren and that you care about?your commu?n ity. If you d like to sign up, or if you have any quest?ions, stop by Profe?s sor Dodge?s offic?e this week. (220wo?r ds) 11. What is the purpo?s e of the talk? _____?B____? A. To expla?in a new requi?r e men?t for gradu?a tion?. B. To inter?e st stude?n ts in a new commu?n ity progr?a m. C. To discu?s s the probl?e ms of eleme?n tary?schoo?l stude?n t s. D. To recru?it eleme?n tary?schoo?l teach?e rs for a speci?a l progr?a m. 12. What is the purpo?s e of the progr?a m that the speak?e r descr?ibes?____C?____ A. To find jobs for gradu?a ting?stude?n ts. B. To help educa?t ion major?s p repa?r e for final? exams?. C. To offer? tutor?ials to eleme?n tary?schoo?l stude?n ts. D. To provi?d e fundi?n g for a commu?n ity servi?c e proje?c t. 13. What does Profe?s sor Dodge?do? _____?__A__? A. He advis?e s stude?n ts to parti?c ipat?e in certa?in progr?a m. B. He teach?e s part-time in an eleme?n tary?schoo?l.