固镇一中2015年11月份段考试卷
【初中物理】安徽省蚌埠市固镇县2014-2015学年八年级上学期期末考试物理试题 人教版

安徽省固镇县2014-2015学年八年级上学期期末考试物理试题一、填空题(每空1分共30分)1、物理单位感知:人正常步行时的速度约4____ ;一位中学生额身高约1.70;一个苹果的质量约为150 ;干松木的密度为500 。
2、美国东部时间10号发射猎鹰9号可回收火箭把龙飞船带入太空,龙飞船通过机械手臂与空间站对接时要做到,但火箭回收失败,撞上回收平台。
以回收平台为参照物猎鹰9号是。
3、建设大美固镇,到处高楼林立,为能达到每天不少于2小时采光效果,楼间距大约70米,且相互错开,用到的物理知识是;高楼的玻璃幕墙会造成光污染,原因是玻璃幕墙会发生反射。
4、到KTV唱歌,某同学唱了一首玖月奇迹的《浏阳河》,该同学模仿了歌手小海的,在歌厅过久,可能会伤害听觉,原因是声音能传递。
5、夏天吃冰棒时会冒白气是现象,在很冷的地区用酒精温度计而不用水银温度计是因为酒精的;灯丝用钨制成利用了其的特性。
6、小凡同在做“观察水沸腾”实验中(1)他的操作如图1所示,其中错误之处是。
(2)纠正错误后,水沸腾时温度计示数如图2所示,为℃,这说明当时水面上方的大气压(填“高于”、“低于”或“等于”)一个标准大气压。
(3)分析如图3所示的图象,可知水在沸腾过程中温度的特点是。
(4)试验中加热至沸腾时间过长原因是。
7、一个人站在竖直放置的平面镜前2m处,则像距离人_______m远;如果此人以1m/s的速度靠近镜面,则1.5s后,人和像的距离为_______m,像和人的大小。
30角从A物质射到B物质,反射光线恰好与折射光线垂直,则入射角为8、一束光线与界面成_______,折射角为_______。
9、人的眼睛在结构上和照相机非常相似,晶状体相当于一个凸透镜,能使物体成像在视网膜上.在如图甲、乙的示意图中,属近视眼的是,矫正时配戴的眼镜镜片应选用。
(选填“丙”或“丁”)10、在物理实验中要求多次测量。
一般分为两类:一类是测量一不变的量(如用刻度尺测物体的长度),多次测量的目的是;另一类是观察物理现象或探究多个物理量间的关系(如探究质量和体积的关系),多次测量的目的是11、在用剩余法测定液体密度时,某同学测出了液体的体积,容器和液体的总质量,实验共做了三次;记录结果如下表:Array(1)该液体密度是 kg/m3;(2)容器的质量是 g;(3)m= g。
2015-2016学年安徽省蚌埠市固镇县八年级(下)期末物理试卷(解析版)

2015-2016学年安徽省蚌埠市固镇县八年级(下)期末物理试卷一、填空题:每空2分,共36分.1.(4分)生活中处处皆物理,同样的物品可以有不同的用处,比如图中的筷子,小刚喝汽水时用来起瓶盖是为了省,夹菜时是为了省。
2.(4分)有一种“回力车”,让车轮触地往后退,放手后车子就能自动地前进。
往后退得越多,前进得也就越远。
这是由于车子往后退的过程中,车内的弹簧片被拧紧,从而具有了能,因此能对车子做功,并转化成车子前进的能。
3.(4分)对静止在水平桌面上的物理书来说,它不会自动沿桌面滑动,是因为受到(选填“非平衡力”或“平衡力”)的作用,此时物理书(选填“有”或“没有”)惯性。
4.(4分)如图所示,拉力F=10N,拉着一个重20N的物体在光滑水平面上作匀速圆周运动,此时小球受(平衡力/非平衡力).若绳长0.5m,则物体运动一周,拉力做的为J。
5.(4分)小柯做了如图所示的“魔力转椅”实验。
他坐在普通转椅上用力扇扇子,椅子不转;在普通转椅的立柱和底座金属筒之间装上滚动轴承和钢珠后,用力扇扇子,“魔力转椅”随即转动。
“魔力转椅”是采用的方法减小摩擦力的;扇子能扇转“魔力转椅”是利用了原理。
6.(4分)避险车道是供速度失控车辆驶离正线安全减速的专用车道,如图所示为“上坡道型”避险车道,当车辆刹车失控时,司机将车辆驶上沙石铺成的“避险车道”,沙石的作用是为了增大;车辆原来具有的能会转化为重力势能和内能。
7.(4分)如图所示,将下口该有轻质薄塑料片的两端开口的玻璃管竖直插入水中,塑料片距离水面0.1m,移开手指,慢慢向玻璃管内注入酒精,当塑料片恰好下落时,管内液面与管外水面的位置关系是(选填“不相平”或“相平”).若注入的是水,则当塑料片恰好下落时注入水的质量(选填“大于”“等于”或“小于”)注入酒精的质量。
8.(2分)近几年足球运动日益受到人民群众的关注。
如图所示球在向左飞行的过程中带着强烈的逆时针旋转,这使得足球上方的压强(选填“大于”“小于”或“等于”)下方的压强,从而使足球在空中划过一道美丽的弧线,飞入球门。
安徽省蚌埠市固镇一中2015届高三上学期11月段考数学试卷

2014-2015学年安徽省蚌埠市固镇一中高三(上)11月段考数学试卷一、选择题(本题包括10小题,每小题5分,共50分)1.设全集U是实数集R,M={x|x2>1},N={x|0<x<2},则集合N∩∁U M=()A. {x|1<x<2} B. {x|0<x≤1} C. {x|0≤x≤1} D. {x|0<x<1}2.已知命题p:“∀x∈[0,1],a≥e x ”,命题q:“∃x∈R,x2﹣4x+a=0”,若命题p,q均是真命题,则实数a的取值范围是()A. [4,+∞) B. [1,4] C. [e,4] D.(﹣∞,1]3.下列命题正确的是()A.在()内,存在x,使B.函数的图象的一条对称轴是C.函数的周期为D.函数y=2sinx的图象可以由函数的图象向左平移个单位得到4.函数f(x)=Asin(ωx+ϕ)(其中A>0,|ϕ|<)的图象如图所示,为了得到g(x)=sin2x的图象,则只需将f(x)的图象()A.向右平移个长度单位 B.向右平移个长度单位C.向左平移个长度单位 D.向左平移个长度单位5.设f(x)为定义在R上的奇函数,当x≤0时,f(x)=2x+log2(1﹣x)+a(a为常数),则f(3)=()A. B. C.﹣6 D. 66.在△ABC中,∠A,∠B,∠C所对的边分别为a,b,c,边BC上的高AD=BC=1,则b2+c2的最小值为()A. 1 B. C. 2 D.7.在直角梯形ACBD中,AB∥CD,AD⊥AB,∠B=45°,AB=2CD=2,M为腰BC的中点,则=()A. 1 B. 2 C. 3 D. 48.设函数f(x)=cosωx(ω>0),将y=f(x)的图象向右平移个单位长度后,所得的图象与原图象重合,则ω的最小值等于()A. B. 3 C. 6 D. 99.已知函数f(x)=(x+1)2e x,设k∈[﹣3,﹣1],对任意x1,x2∈[k,k+2],则|f(x1)﹣f(x2)|的最大值为()A. 4e﹣3 B. 4e C. 4e+e﹣3 D. 4e+110.已知f(x)是定义在R上的偶函数,且当x>0时,f(x)=,若对任意实数t∈[,2],都有f(t+a)﹣f(t﹣1)>0恒成立,则实数a的取值范围是()A.(﹣∞,﹣3)∪(0,+∞) B.(﹣1,0) C.(0,1) D.(﹣∞,1)∪(2,+∞)二、填空题(本题5小题,每小题5分,共25分)11.已知f(x)=,则满足f(a)>2的a的取值范围是.12.若正数a,b满足a+2b=3,且使不等式﹣m>0恒成立,则实数m的取值范围是.13.已知向量满足||=1,||=2,(+2)(﹣)=﹣6,则|﹣2|= .14.设m>1,在约束条件下,目标函数z=x+5y的最大值为4,则m的值为.15.以下是关于函数f(x)=的四个命题:①f(x)的图象关于y轴对称;②f(x)在区间[﹣1,0]∪[1,+∞)上单调递减;③f(x)在x=﹣1处取得极小值,在x=1处取得极大值;④f(x)有最大值,无最小值;⑤若方程f(x)﹣k=0至少有三个不同的实根,则实数k的取值范围是(0,2).其中为真命题的是(请填写你认为是真命题的序号).三、解答题(本题计6小题,共75分.解答应写出必要的文字说明、证明过程)16.已知函数f(x)=sin2x+cos2x+a﹣2,(1)求函数f(x)的单调递增区间;(2)设函数f(x)在[0,]上的最小值为﹣,求函数f(x)(x∈R)的值域.17.已知函数y=ln(2﹣x)[x﹣(3m+1)]的定义域为集合A,集合B={x|<0}(1)当m=3时,求A∩B;(2)求使B⊆A的实数m的取值范围.18.在数列{a n}中,已知a1=﹣1,a n+1=2a n﹣n+1,(n=1,2,3,…).(1)证明数列{a n﹣n}是等比数列;(2)为数列{b n}的前n项和,求S n的表达式.19.已知函数f(x)=ax2﹣(a+2)x+lnx.(1)当a=1时,求曲线y=f(x)在点(1,f (1))处的切线方程;(2)当a>0时,若f(x)在区间[1,e)上的最小值为﹣2,求a的取值范围.20.已知数列{a n},a1=a,a2=p(p为常数且p>0),S n为数列{a n}的前n项和,且S n=.(Ⅰ)求a的值;(Ⅱ)试判断数列{a n}是不是等差数列?若是,求其通项公式;若不是,请说是理由.(Ⅲ)若记P n=+(n∈N*),求证:P1+P2+…+P n<2n+3.21.设函数f(x)=a x﹣x(a>0,a≠1)(1)若a=e(e是自然对数的底数),求f(x)的单调区间和极值;(2)若函数y=f(|x|)在全体实数R上恰有4个零点,求实数a的取值范围.2014-2015学年安徽省蚌埠市固镇一中高三(上)11月段考数学试卷参考答案与试题解析一、选择题(本题包括10小题,每小题5分,共50分)1.设全集U是实数集R,M={x|x2>1},N={x|0<x<2},则集合N∩∁U M=()A. {x|1<x<2} B. {x|0<x≤1} C. {x|0≤x≤1} D. {x|0<x<1}考点:交、并、补集的混合运算.专题:集合.分析:根据补集的定义求得∁U M,再根据两个集合的交集的定义求得N∩∁U M.解答:解:∵M={x|x2>1},N={x|0<x<2},∴∁U M={x|x2≤1}={x|﹣1≤x≤1},∴集合N∩∁U M={x|0<x≤1},故选:B.点评:本题主要考查补集的定义,两个集合的交集的定义和求法,属于基础题.2.已知命题p:“∀x∈[0,1],a≥e x ”,命题q:“∃x∈R,x2﹣4x+a=0”,若命题p,q均是真命题,则实数a的取值范围是()A. [4,+∞) B. [1,4] C. [e,4] D.(﹣∞,1]考点:复合命题的真假.专题:规律型.分析:分别求出命题p,q成立的等价条件,利用p,q都是真命题,确定实数a的取值范围.解答:解:∀x∈[0,1],a≥e x,则∴a≥e,即p:a≥e.若∃x∈R,x2﹣4x+a=0,则判别式△=16﹣4a≥0,解得a≤4,即q:a≤4.∵p,q都是真命题,∴,解得e≤a≤4.即实数a的取值范围是[e,4].故选C.点评:本题主要考查复合命题的与简单命题真假之间的关系,求出命题p,q成立的等价条件是解决此类问题的关键.3.下列命题正确的是()A.在()内,存在x,使B.函数的图象的一条对称轴是C.函数的周期为D.函数y=2sinx的图象可以由函数的图象向左平移个单位得到考点:命题的真假判断与应用;函数y=Asin(ωx+φ)的图象变换;复合三角函数的单调性.专题:综合题.分析:根据正弦函数和余弦函数在()内的值域,可判断A的真假;根据正弦型函数的对称性,可以判断B的真假;利用同角三角函数的基本关系及降次公式化简函数的解析式,进而根据余弦型函数的周期性,可以判断C的真假;根据正弦型函数的平移变换法则,可以判断D的真假.解答:解:当()内,cosx<0,故,故A错误;当时,函数=0,不等最值,故不是函数的对称轴,故B错误;函数=cos2x=+cos2x,∵ω=2,故T=π,故C错误将函数的图象向左平移个单位,可得函数=2sinx的图象故选D点评:本题考查的知识点是命题真假判断与应用,三角函数图象和性质的综合应用,熟练掌握三角函数的值域,对称性,周期性及平移变换法则,是解答本题的关键.4.函数f(x)=Asin(ωx+ϕ)(其中A>0,|ϕ|<)的图象如图所示,为了得到g(x)=sin2x的图象,则只需将f(x)的图象()A.向右平移个长度单位 B.向右平移个长度单位C.向左平移个长度单位 D.向左平移个长度单位考点:由y=Asin(ωx+φ)的部分图象确定其解析式;函数y=Asin(ωx+φ)的图象变换.专题:计算题.分析:利用函数的图象求出A,T,求出ω,利用函数的图象经过的特殊点,集合ϕ的范围,求出ϕ得到函数的解析式,然后推出平移的单位与方向,得到选项.解答:解:由图象可知,从而,将代入到f(x)=sin(2x+φ)中得,,根据|ϕ|<得到,所以函数f(x)的解析式为.将f(x)图象右移个长度单即可得到g(x)=sin2x的图象.故选A.点评:本题考查由y=Asin(ωx+φ)的部分图象确定其解析式,函数y=Asin(ωx+φ)的图象变换,考查计算能力.5.设f(x)为定义在R上的奇函数,当x≤0时,f(x)=2x+log2(1﹣x)+a(a为常数),则f(3)=()A. B. C.﹣6 D. 6考点:函数奇偶性的性质.专题:函数的性质及应用.分析:利用函数的奇偶性,结合解析式求解.解答:解:∵f(x)为定义在R上的奇函数,∴f(﹣x)=﹣f(x),得f(0)=0,20+0=0即a=﹣1,∵当x≤0时,f(x)=2x+log2(1﹣x)+a(a为常数),∴f(3)=﹣f(﹣3)=﹣2﹣3﹣log2(1+3)+1=﹣故选:A点评:考查了函数概念和性质,容易题.6.在△ABC中,∠A,∠B,∠C所对的边分别为a,b,c,边BC上的高AD=BC=1,则b2+c2的最小值为()A. 1 B. C. 2 D.考点:基本不等式.专题:计算题.分析:由三角形的面积公式可得,可得bc=,结合已知A的范围可求sinA的范围,进而可求bc的范围,然后由基本不等式可求b2+c2的最小值解答:解:由三角形的面积公式可得,∴bc=∵0<A<π∴0<sinA≤1∴,即bc≥1当A=时取等号∵b2+c2≥2bc≥2当且仅当b=c=时取等号故选C点评:本题主要考查了三角形的面积公式、正弦函数的性质及基本不等式在求解最值中的综合应用,属于知识的综合应用7.在直角梯形ACBD中,AB∥CD,AD⊥AB,∠B=45°,AB=2CD=2,M为腰BC的中点,则=()A. 1 B. 2 C. 3 D. 4考点:向量在几何中的应用.专题:计算题.分析:以直角梯形的两个直角边为坐标轴,写出点的坐标,求出向量的坐标,利用向量数量积的坐标形式的公式求.解答:解:以A为原点,AB为x轴,AD为y轴,建立直角坐标系.则:A(0,0),B(2,0),D(0,1),C(1,1),M(.因为AB=2CD=2,∠B=45,所以AD=DC=1,M为腰BC的中点,则M点到AD的距离=(DC+AB)=,M点到AB的距离=DA=所以,,所以=9/4﹣1/4=2.故答案为B点评:本题考查通过建立直角坐标系将几何问题问题转化为代数问题;考查向量的坐标形式的数量积公式.8.设函数f(x)=cosωx(ω>0),将y=f(x)的图象向右平移个单位长度后,所得的图象与原图象重合,则ω的最小值等于()A. B. 3 C. 6 D. 9考点:由y=Asin(ωx+φ)的部分图象确定其解析式.专题:三角函数的求值.分析:函数图象平移个单位长度后,所得的图象与原图象重合,说明函数平移整数个周期,容易得到结果.解答:解:f(x)的周期T=,函数图象平移个单位长度后,所得的图象与原图象重合,说明函数平移整数个周期,所以,k∈Z.令k=1,可得ω=6.故选C.点评:本题是基础题,考查三角函数的图象的平移,三角函数的周期定义的理解,考查技术能力,常考题型.9.已知函数f(x)=(x+1)2e x,设k∈[﹣3,﹣1],对任意x1,x2∈[k,k+2],则|f(x1)﹣f(x2)|的最大值为()A. 4e﹣3 B. 4e C. 4e+e﹣3 D. 4e+1考点:利用导数求闭区间上函数的最值.专题:综合题;导数的综合应用.分析:求导函数,求得函数的单调区间,进而可求函数的最值,即可求得结论.解答:解:求导函数,可得f′(x)=(x+1)2e x=(x2+4x+3)e x,令f′(x)>0,可得x<﹣3或x>﹣1;令f′(x)<0,可得﹣3<x<﹣1∴函数的单调增区间为(﹣∞,﹣3),(﹣1,+∞),单调减区间为(﹣3,﹣1)∵k∈[﹣3,﹣1],x1,x2∈[k,k+2],f(﹣3)=4e﹣3,f(﹣1)=0,f(1)=4e∴f(x)max=f(1)=4e,f(x)min=f(﹣1)=0∴|f(x1)﹣f(x2)|的最大值为4e,故选B.点评:本题考查导数知识的运用,考查函数的最值,求导确定函数的最值是关键.10.已知f(x)是定义在R上的偶函数,且当x>0时,f(x)=,若对任意实数t∈[,2],都有f(t+a)﹣f(t﹣1)>0恒成立,则实数a的取值范围是()A.(﹣∞,﹣3)∪(0,+∞) B.(﹣1,0) C.(0,1) D.(﹣∞,1)∪(2,+∞)考点:函数奇偶性的性质.专题:函数的性质及应用.分析:当x>0时,f(x)==1﹣,可得f(x)在(0,+∞)单调递增.由于对任意实数t∈[,2],都有f(t+a)﹣f(t﹣1)>0即f(t+a)>f(t﹣1)恒成立,又f(x)是定义在R上的偶函数,可得|t+a|>|t﹣1|,转化为(2a+2)t+a2﹣1>0,利用一次函数的单调性即可得出.解答:解:∵当x>0时,f(x)==1﹣,∴f(x)在(0,+∞)单调递增.∵对任意实数t∈[,2],都有f(t+a)﹣f(t﹣1)>0即f(t+a)>f(t﹣1)恒成立,又f(x)是定义在R上的偶函数,∴|t+a|>|t﹣1|,∴(2a+2)t+a2﹣1>0,∴,解得a>0或a<﹣3则实数a的取值范围是a>0或a<﹣3.故选:A.点评:本题考查了函数的奇偶性、单调性、不等式的解法,考查了转化能力,考查了推理能力与计算能力,属于难题.二、填空题(本题5小题,每小题5分,共25分)11.已知f(x)=,则满足f(a)>2的a的取值范围是x<﹣1或x>4 .考点:指、对数不等式的解法.专题:函数的性质及应用;不等式的解法及应用.分析:本题先对参数a进行讨论,确定f(a)的表达式,再解不等式f(a)>2,得到a 的取值范围,即本题结论.解答:解:∵f(x)=,f(a)>2,∴当a≥1时,原不等式转化为log2a>2,解得:a>4.∴a>4;当a<1时,原不等式转化为a2﹣a>2,解得:a<﹣1或a>2,∴a<﹣1.综上,x<﹣1或x>4.故答案为:x<﹣1或x>4.点评:本题考查的是对数不等式的解法、一元二次不等式的解法,还有分类讨论的数学思想,本题难度适中,有一定的运算量,属于中档题.12.若正数a,b满足a+2b=3,且使不等式﹣m>0恒成立,则实数m的取值范围是m.考点:基本不等式在最值问题中的应用;函数恒成立问题.专题:函数的性质及应用;不等式的解法及应用.分析:分离参数m,然后利用基本不等式求出的最小值得答案.解答:解:不等式﹣m>0恒成立,即恒成立,∵a+2b=3,∴,则.当且仅当,即a=b=1时上式等号成立.∴实数m的取值范围是.故答案为:.点评:本题考查了恒成立问题,考查了分离变量法,训练了利用基本不等式求最值,是中档题.13.已知向量满足||=1,||=2,(+2)(﹣)=﹣6,则|﹣2|= .考点:平面向量数量积的运算.专题:平面向量及应用.分析:先根据已知条件求出,然后根据求出结果即可.解答:解:=;∴;∴=.故答案为:.点评:考查数量积的运算,以及求向量长度的方法:对向量的平方开方.14.设m>1,在约束条件下,目标函数z=x+5y的最大值为4,则m的值为 3 .考点:简单线性规划的应用.专题:计算题;压轴题;数形结合.分析:根据m>1,我们可以判断直线y=mx的倾斜角位于区间(,)上,由此我们不难判断出满足约束条件的平面区域的形状,再根据目标函数z=x+5y在直线y=mx与直线x+y=1交点处取得最大值,由此构造出关于m的方程,解方程即可求出m 的取值范围.解答:解:满足约束条件的平面区域如下图所示:目标函数z=x+5y可看做斜率为﹣的动直线,其纵截距越大z越大,由可得A点(,)当x=,y=时,目标函数z=x+5y取最大值为4,即;解得m=3.故答案为:3.点评:本题考查的知识点是简单线性规划的应用,其中判断出目标函数z=x+my在点取得最大值,并由此构造出关于m的方程是解答本题的关键.15.以下是关于函数f(x)=的四个命题:①f(x)的图象关于y轴对称;②f(x)在区间[﹣1,0]∪[1,+∞)上单调递减;③f(x)在x=﹣1处取得极小值,在x=1处取得极大值;④f(x)有最大值,无最小值;⑤若方程f(x)﹣k=0至少有三个不同的实根,则实数k的取值范围是(0,2).其中为真命题的是①④⑤(请填写你认为是真命题的序号).考点:根的存在性及根的个数判断;函数的图象.专题:函数的性质及应用.分析:先求出函数的对称性,单调性,画出函数的草图,从而得出答案.解答:解:①定义域关于原点对称,f(﹣x)=f(x),f(x)的图象关于y轴对称,故①正确;②x>0时,f(x)=,f′(x)=,令f′(x)≤0,解得:x>1,∴f(x)在[1,+∞)递减,x≤0时,f(x)=,f′(x)=,令f′(x)≤0,解得:﹣1≤x≤0,∴f(x)在[﹣1,0]递减,画出函数f(x)的草图:∴f(x)分别在区间[﹣1,0]和[1,+∞)上单调递减,故②错误;③f(x)在x=﹣1处取得极大值,在x=1处取得极大值,故③错误;④由②中的图象得:④正确;⑤由②中的图象得:⑤正确;故答案为:①④⑤.点评:本题考查了函数的单调性,函数的极值问题,是一道中档题.三、解答题(本题计6小题,共75分.解答应写出必要的文字说明、证明过程)16.已知函数f(x)=sin2x+cos2x+a﹣2,(1)求函数f(x)的单调递增区间;(2)设函数f(x)在[0,]上的最小值为﹣,求函数f(x)(x∈R)的值域.考点:三角函数中的恒等变换应用;正弦函数的图象.专题:三角函数的图像与性质.分析:(1)直接结合三角恒等变换公式化简,然后,借助于三角函数的单调性求解其单调区间;(2)结合[0,],然后,借助于三角函数的单调性确定其值域.解答:解:(1)∵函数f(x)=sin2x+cos2x+a﹣2,∴,其单调递增区间为.(2)∵,则,∴.∴函数f(x)(x∈R)的值域[﹣,].点评:本题重点考查了三角恒等变换公式、三角函数的图象与性质等知识,属于中档题.17.已知函数y=ln(2﹣x)[x﹣(3m+1)]的定义域为集合A,集合B={x|<0}(1)当m=3时,求A∩B;(2)求使B⊆A的实数m的取值范围.考点:集合关系中的参数取值问题;集合的包含关系判断及应用.专题:计算题;集合.分析:(1)当m=3时,(2﹣x)(x﹣10)>0,<0,从而求A∩B;(2)分类讨论,先以B是否是空集讨论,再讨论2与3m+1的大小关系,从而解得.解答:解:(1)当m=3时,由(2﹣x)(x﹣10)>0得,2<x<10,A=(2,10);由<0解得,3<x<8,即B=(3,8);则A∩B=(3,8).(2)若B=∅,则m2﹣m﹣1=0,即m=±时,A≠∅,成立;若3m+1>2,即m>时,A=(2,3m+1),则若使B⊆A,即,解得,2≤m≤,若3m+1<2,即m<时,A=(3m+1,2),则若使B⊆A,即,解得,≤m≤,综上所述,实数m的取值范围为≤m≤或2≤m≤或m=+.点评:本题考查了集合的包含关系的应用及分类讨论的数学思想,属于基础题.18.在数列{a n}中,已知a1=﹣1,a n+1=2a n﹣n+1,(n=1,2,3,…).(1)证明数列{a n﹣n}是等比数列;(2)为数列{b n}的前n项和,求S n的表达式.考点:数列的求和;等比关系的确定.专题:计算题;证明题.分析:(I)此证明题应从结论中找方法,要证明数列{a n﹣n}是等比数列,将题设中的条件a n+1=2a n﹣n+1变形为a n+1﹣(n+1)=2(a n﹣n)即可;(II)由(I)结论可求出b n,由通项公式的形式可以看出,本题宜先用分组求和的技巧,然后对其一部分用错位减法求和.最后将结果综合起来.解答:解:∵a n+1=2a n﹣n+1,∴a n+1﹣(n+1)=2(a n﹣n)∴=2,a1﹣1=﹣2∴数列{a n﹣n}是以﹣2为首项,2为公比的等比数列.(6分)(2)由(1)得:a n﹣n=(﹣2)×2n﹣1=﹣2n,∴a n=n﹣2n,b n=∴Sn=b1+b2+…+b n==令Tn=,则Tn=,两式相减得:Tn==∴T n=,即S n═﹣n (12分)点评:本题是一道综合性较强的题,要观察分析,判断,选择合适的方法,如(I)的求解要从证明的结论中找变形方向;(II)中的求解要边变形边观察,化整为零,分块求解,这对答题者分析判断的能力要求较高19.已知函数f(x)=ax2﹣(a+2)x+lnx.(1)当a=1时,求曲线y=f(x)在点(1,f (1))处的切线方程;(2)当a>0时,若f(x)在区间[1,e)上的最小值为﹣2,求a的取值范围.考点:利用导数求闭区间上函数的最值;利用导数研究曲线上某点切线方程.专题:导数的综合应用.分析:(1)先求出f(1)及f′(1)的值,然后代入点斜式方程即可得到曲线y=f(x)在点(1,f (1))处的切线方程;(2)确定函数的定义域,求导函数,利用导数的正负,分类讨论,即可求得函数的单调区间,从而可求出f(x)在区间[1,e)上的最小值,建立等式可求出所求.解答:解:(1)当a=1时,f(x)=x2﹣3x+lnx,f′(x)=2x﹣3+,∵f′(1)=0,f(1)=﹣2,∴切线方程为:y=﹣2.(2)函数f(x)=ax2﹣(a+2)x+lnx的定义域为(0,+∞).当a>0时,f′(x)=2ax﹣(a+2)+=(x>0),令f′(x)=0,即f′(x)==0,∴x=或x=,当,即a≥1时,f(x)在[1,e]上单调递增,所以f(x)在[1,e]上的最小值是f(1)=﹣2;当时,f(x)在[1,e]上的最小值是,不合题意;当时,f(x)在[1,e]上单调递减,所以f(x)在[1,e]上的最小值是f(e)<f(1)=﹣2,不合题意,故a的取值范围为[1,+∞).点评:本题考查了导数的几何意义,导数的几何意义即在某点处的导数即该点处切线的斜率,解题时要注意运用切点在曲线上和切点在切线上.利用导数研究函数在闭区间上的最值,一般是求出导函数对应方程的根,然后求出跟对应的函数值,区间端点的函数值,然后比较大小即可得到函数在闭区间上的最值.属于中档题.20.已知数列{a n},a1=a,a2=p(p为常数且p>0),S n为数列{a n}的前n项和,且S n=.(Ⅰ)求a的值;(Ⅱ)试判断数列{a n}是不是等差数列?若是,求其通项公式;若不是,请说是理由.(Ⅲ)若记P n=+(n∈N*),求证:P1+P2+…+P n<2n+3.考点:数列的求和;等差关系的确定.专题:综合题;等差数列与等比数列.分析:(Ⅰ)由a1=S1可求a;(Ⅱ)由(Ⅰ)可得,则,两式相减得(n﹣1)a n+1=na n,利用累乘法可求得a n,由a n可得结论;(Ⅲ)由(Ⅱ)可得P n=+==2+,由裂项相消法可求得P1+P2+…+P n,于是可得结论;解答:解:(Ⅰ)依题意a1=a,又a1==0,∴a=0;(Ⅱ)由(Ⅰ)知a1=0,∴,则,两式相减得(n﹣1)a n+1=na n,故有=(n﹣1)p,n≥2,又a1=0也满足上式,∴a n=(n﹣1)p,n∈N+,故{a n}为等差数列,其公差为p.(Ⅲ)由题意,∴P n=+==2+,∴P1+P2+…+P n=(2+﹣)+(2+﹣)+…+(2+)=2n+3﹣<2n+3.点评:该题考查等差关系的确定、数列求和等知识,裂项相消法、累乘法是解决数列问题的基本方法,要熟练掌握.21.设函数f(x)=a x﹣x(a>0,a≠1)(1)若a=e(e是自然对数的底数),求f(x)的单调区间和极值;(2)若函数y=f(|x|)在全体实数R上恰有4个零点,求实数a的取值范围.考点:根的存在性及根的个数判断;指数函数综合题.专题:函数的性质及应用.分析:(1)将a=e代入求出函数解析式,可得导函数的解析式,进而求出f′(x)>0时和f′(x)<0时自变量的范围,得到f(x)的单调区间,同时根据极值的定义,求出极值;(2)函数y=f(|x|)是偶函数,要使它在全体实数R上恰有4个零点,只须y=f(x)在(0,+∞)上有2个零点,即在(0,+∞)有2解,构造函数,利用导数法,可求出满足条件的实数a的取值范围.解答:解:(1)f(x)=e x﹣x,则f′(x)=e x﹣1…(2分)当f′(x)>0时,解得x>0,f(x)在[0,+∞)上单调递增,当f′(x)<0时,解得x<0,f(x)在(﹣∞,0]上单调递减.…(2分)所以x=0是极小值点,f极小值=f(0)=1…(2分)(2)函数y=f(|x|)是偶函数,要使它在全体实数R上恰有4个零点,只须y=f(x)在(0,+∞)上有2个零点,…(2分)要使方程a x=x在(0,+∞)有2解,则有在(0,+∞)有2解,…(2分)设,则…(1分)当x>e时,g'(x)<0,g(x)单调递减,且当0<x≤e时,g'(x)>0,g(x)单调递增,且…(4分)根据图象可知,∴…(2分)点评:本题考查的知识点是根的存在性及根的个数判断,指数函数的图象和性质,导数法求函数的单调区间及最值,其中熟练掌握利用导数确定函数单调区间和极值的方法步骤是解答的关键.。
安徽省示范高中2015届高三11月阶段测评物理试题(扫描版)

2015安徽省示范高中高三11月阶段测评 物理答案 一、简要答案:442T =-223mgLU=q12(1)hg μ=+二、详细解析:1.B 解析:物体连续两个t 的位移大小相等,即112()',,',22v v v x x x t x t +-=-==而得:速度大小之比为21:2:1v v =,B 正确。
2.C 解析:根据万有引力提供向心力可得2224Mm G m r r Tπ=,球体积公式343V R π=因为在天体表面附近,所以R r =,联立可得23T G πρ=,则'TT T n==,C 正确。
3.B 解析:作出v t -图像不难得出t t >乙甲,A 错误;设摩擦因数为μ图甲中斜面的倾角为θ,摩擦力做功为:cos sin hmg mgx μθμθ-=-底边,由于底边等长故可得图甲与图乙,摩擦力做功等大产生内能等大,而重力做功相等,由动能定理可得到达底端时动能等大,B 正确,C 、D 错误。
4.A 解析:从起点A 到最高点B 可看做平抛运动的逆过程,则有2tan 4α=,所以tan 2tan 1θα==,A 正确。
5.A 解析:根据向心力公式,刚好能过最高点,则最高点的速度gL ,设最低点时动能为0k E ,根据机械能守恒定律mgL gL m L mg E k 25)(21220=+⋅=, 从最低点转至与竖直方向成θ角,根据机械能守恒定律)cos 1(2120θ-+=mgL mv E k ,又因为Lm v m g F 2cos =-θ,化简可得θcos 33mg mg F +=,可见F 与cos θ是一次函数关系,因此θcos -F 图象应该是一条直线,选项A 错误。
6.D 解析:由题意知,小球A 受重力、库仑力及杆的拉力,由平衡条件可知杆对球A 的2,故A 、B 错误;对B 受力分析如图: 根据物体的平衡条件可知:当摩擦力为零时,B 受mg 、F N 、F 库三力即2tan mgL Q qk α=,所以C 错误;当2tan mgL Q qkα>时B 受向下的静摩擦力,所以D 正确。
安徽省固镇县第一中学七年级英语期末复习测试试题 牛

安徽省固镇县第一中学2015-2016学年七年级英语期末复习测试一、单项选择(15分)( )1. There______a fashion show on the square tomorrow evening.A. is going toB. will haveC. is going to haveD. will be( )2. interesting film it is!A. HowB. What aC. What anD. What( )3. What kind of clothes do people like to________?A. wearB. put onC. dressD. in( )4. Please call me if you ________ next Sunday.A. will be freeB. are freeC. have freeD. are going to be free( )5. Who are you waiting _________the bus stop.A. forB. atC. for atD. at for( )6. Does it take Millie two and a half hours her housework at weekends?A. to doB. doC. doesD. doing( )7. We have finished our homework today. ________ shall we do tomorrow?A. What otherB. What othersC. What thingD. What else( )8. There are so many tall buildings on _____ sides of the road.A. allB. anyC. bothD. either( )9. ---How long the shop every day?----It at 8 a.m. and at 8 p.m.A. does, open, is open, is closedB. is, open, is open, is closedC. does, open, opens, closesD. is ,open, opens, closes( )10. The teacher asks us ________ in the classroom between classes.A.don’t shoutB. not shoutC. not shoutingD. not to shout( )11. ---What do you think of the game called “trick or treat”?--- .A. Very muchB. A littleC. I think soD. It is wonderful( )12. --- Would you like some more turkey ? ---- .I am full.A. Yes, thank youB. Ok, pleaseC. That’s nice of youD. No, thanks( )13. Eating too much meat and candy bad for your health.A. areB.haveC. isD. are( )14. He gets up early the school bus every day.A. catchesB. to catchingC. catchingD. to catch( )15. ---The boy with a pair of glasses never helps his classmates, does he?--- . He often helps me with my English.A. Yes, he doesn’tB. Yes, he doesC. No, he doesD. No,he doesn’t二、完形填空(15分)One day, a grandmother stays at home with her 14-month-old ____16____. He is ____17____ with her yellow car key. At that time, the phone rings ____18____ the grandmother goes to ____19____ the phone. After the grandmother comes ____20____, she can’t ___21___ the key. She thinks that the little boy puts ____22____ somewhere.She looks ____23____ it in the room, but she can’t find it ____24____. Then she has a ____25____ idea. The grandmother ____26____ the child a blue key and pretends(假装) not to look. After a few ____27____, the boy goes into his ____28____ bedroom and he carefully puts ____29____ blue key under her bed, next to the yellow ____30____.( )16. A. granddaughter B. grandson C. sister D. son( )17. A. playing B. carrying C. putting D. sending( )18. A. because B. and C. but D. or( )19. A. call B. answer C. take D. catch( )20. A. down B. out C. back D. down( )21. A. look for B. bring C. buy D. find( )22. A. it B. them C. that D. they( )23. A. at B. after C. for D. of( )24. A. anywhere B. everywhere C. somewhere D. nowhere( )25. A. well B. better C. good D. bad( )26. A. gives B. buys C. draws D. makes( )27. A. weeks B. days C. years D. minutes( )28. A. mother B. grandmother’s C. grandson D. grandmother( )29. A. a B. an C. some D. the( )30. A. phone B. coat C. key D. shoes三、阅读理解(30分)AOne evening Tim is driving his car in the country and looking for a hotel. Then he sees an old man on the side of the road, so he stops his car and says to the old man, “W here is the Sun Hotel? Will you please tell me how to get there?” “ Yes, ” the old man answers, “I’ll show you the way.” He gets into Tim’s car, and they drive for about 12 kilometers. When they come to a small house, the old man says,” Stop here.” Tim sto ps and looks at the house. And he says to the old man, “But this isn’t a hotel.” “No,” the old man answers, “This is my house. And now I’ll show you the way to the Sun Hotel. Turn back and go 9 kilometers. Then you’ll see the hotel on your left.”( )31. Tim wants to stay__________ for the night.A. in his carB. in the old man’s houseC. in the hotelD. in the street( )32. Tim stops to__________.A. drive the old man homeB. ask the wayC. buy somethingD. say “hello” to the old man( )33. The old man takes Tim to__________.A. a hospitalB. a policemanC. a hotelD. his homeBEveryone needs friends. There is an old saying,“Friends are God’s way of taking care of us.” But how do you find friends and keep them?The American writer Sally Seamans tells young students some smart ways to find friends. Sally says finding friendship is just like planting a tree. You plant the seed (种子) and take care of it to make it grow.First, you should look for a friend. A good friend should be kind. For example, when you are not happy, a good friend should listen to you and do his or her best to help you. To make a friend, you cannot be too shy . You should make each other happy.But things cannot always be happy. Even the best friends have fights. What should you do when you fight with your friend? You have to talk to him or her. When there is no one around, have a talk. If he or she doesn’t want to talk, you could write a letter.There are three steps to being friends again. Tell him or her how you are feeling;say what your friend does wrong;and tell him or her why you do this or that. Remember that friends are the most important in your life.( )34. Sally wants to tell students the way to ___________.A. find friendsB. plant treesC. get happyD. keep fit( )35. What makes good friends? A good friend should .A. be lovely and coolB. be kindC. have lots of moneyD. be beautiful( )36. According to the passage, you can ___________ your friend after a fight.A. buy a present forB. never say a word toC. have dinner withD. write a letter to( )37. Which is True according to the passage?A. Best friends never fight.B. A good friend should listen to you when you are unhappy.C. We must be unkind to make a good friend.D. We shouldn’t say what our friend does wrong.CMany children think mobile phones are cool. They have fun colours and let you talk with a friend anytime and anywhere.In the USA, more than 90 million people use mobile phones. Many of these people are children. For children, mobile phones are more than phone calls. They are fashionable.Some scientists say that mobile phones give off radiation(辐射) and it may be bad for people using mobile phones. One study(研究) shows that mobile phone radiation can make people get some kinds of cancer (癌症). But other scientists don’t think so. They say that they can not find any link (联系) between mobile phone use and cancer.Scientists say that people can stop themselves away from mobile phone radiation. One way is to use a headset (耳机). Or people can make short calls.( )38. Many children like mobile phones because they think mobile phones are ______.A. coolB. smallC. cheapD. their toys( )39. The underlined words “give off” in the passage mean_______________A. 发出B. 放弃C. 拒绝D.戒掉( )40.To stop themselves away from mobile phone radiation, people can____________.A. make longer callsB. use a headsetC. make shorter callsD. both B and CDA bee goes to a river. When it is drinking, the running water carries him away. A kind bird sees the bee’s danger. It picks a leaf off a tree and throws it into the water in front of the bee. The bee climbs onto the leaf, and comes to the bank (岸) of the river. The bee thanks the bird and then flies away.Several days later, the bird is sitting in the tree. It doesn’t see that a man is aiming his gun (用枪瞄准) at it. But the bee sees what the man is doing. So it flies into the man’s eye. The man can’t see the bird clearly and cannot kill it. So the bird can fly away very quickly. The bee and the bird help to save each other’s lives and later they become very good friends. ( )41. What does the bee do at the beginning of the story?A. It saves the bird’s life.B. It comes to river to have some water.C. It flies over the river to find a leaf.D. It finds a leaf on the water and stays on it for a ride.( )42. ___________ takes the bee to the bank of the river.A. A manB. A birdC. The water in the riverD. A leaf that the bird picks for it ( )43. What happens when the bird is sitting in the tree one day?A. It falls on a leaf in the river.B. A man is climbing up the tree to catch the bird.C. Someone is going to kill the bird.D. The bird sees a man with a gun in his head.( )44. What does the bee do to help the bird?A. It flies over to tell the bird about the man.B. It flies into the man’s eye.C. It flies over to stay on one of the man’s hands.D. It puts a leaf to cover one of the man’s eyes.( )45. Which of the following can be the best title for the passage?A. Help Each OtherB. Man: No Good!C. Animal aren’t FriendsD. Ants and Birds四、单词拼写(10分)46. Let the girl with big eyes (paint) the wall white.47. Lucy, what about (dress) up as a terrible lion?48. I always have fun (get) delicious dishes ready for my family at the weekend.49. How long do they spend (take) photos of the dolphins.50. The new teacher often practises (ask) questions before teaching his students.51. Lucy, together with her friends often (庆祝) her birthday in KFC.52. Are your (祖父母) red packets for you and your brother?53. ---Where are my rice (粽子)? ---I can see them in your bowl.54. There are twenty comic books. One is mine, the (其他)are my classmates.55. One of my favourite (餐馆) is near the Slender West Lake.五、任务型阅读(10分)Each year, we welcome many holidays here in America.On January 1, we welcome the coming of a new year like many people in other countries. And we have another four holidays on the first day of a month: April Fool’s Day, May Day, Friendship Day (Aug.1) and Grandparents Day (Sept.1).The most important holiday for the young people comes in February. It is Valentine’s Day. Lots of boys give red roses to girls as a present.People celebrate some holidays for their family members. We say thanks to our mother in May and celebrate Father’s Day in the following month. In November many people come back home f or Thanksgiving Day, so all the family can stay together.There are also some interesting holidays for children. For example, Halloween comes at the end of October. Children often play with pumpkin lanterns and wear all kinds of masks.Of course, the most important festival is Christmas. After a year of work and study, people六、缺词填空(10分)Food is important. Everyone n 66 to eat well if he or she wants to have a strong body. Ourminds(头脑) also need a kind of food. This kind of food is knowledge(知识). we b 67 to get knowledge even when we are very young. Small children are very interested ine 68 around them. They learn something while they are w 69 and listening. When theyare getting older,they begin to read science books, s 70 books ---anything they like. Whenthey find something new, they love to ask questions and try to find out the a 71 . What isthe best way to g 72 knowledge? If we learn by ourselves,we will get the most knowledge.If we are always getting answers from others and do not ask w 73 , we will n 74 learnwell. When we study in the right way, we will learn m 75 and understand better.七、完成句子。
安徽固镇县第一中学高一 物理上学期11月质量检测考试试题

安徽固镇县第一中学高一物理上学期11月质量检测考试试题一、选择题1.关于摩擦力,下列说法正确的是()A.一个物体可以同时受到滑动摩擦力和静摩擦力的作用B.摩擦力的存在依赖于弹力,所以有弹力必定有摩擦力C.运动的物体可能受到静摩擦力作用,静止的物体不可能受到滑动摩擦力作用D.摩擦力的方向可能与运动方向相同,也可能相反,但一定与运动方向在同一直线上2.关于速度的描述,下列说法中正确的是A.京沪高速铁路测试时的列车最高时速可达484km/h,指的是瞬时速度B.电动自行车限速20 km/h,指的是平均速度C.子弹射出枪口时的速度为500m/s,指的是平均速度D.某运动员百米跑的成绩是10s,则他冲刺时的速度一定为10m/s3.如图所示,此时表演者静止在弯曲倾斜的竹竿上,则下列说法正确的是()A.表演者对竹竿的弹力是由竹竿形变产生的B.表演者对竹竿的力竖直向下C.表演者对竹竿的摩擦力一定为零D.表演者对竹竿的力大于竹竿对表演者的力4.将一小球竖直向上抛出,经时间t回到抛出点,此过程中上升的最大高度为h.在此过程中,小球运动的路程、位移和平均速度分别为()A.路程2h、位移0、平均速度2htB.路程2h、位移0、平均速度0C.路程0、位移2h、平均速度0 D.路程2h、位移h、平均速度2ht5.关于位移和路程,下列说法正确的是()A.在某段时间内物体运动的位移为零,该物体不一定是静止的B.在某段时间内物体运动的路程为零,该物体不一定是静止的C.某同学沿着400 m的环形操场跑了一圈,位移为400 mD.高速公路路牌标示“上海80 km”涉及的是位移6.在平直公路上行驶的a车和b车,其位移时间图像分别为图中直线a和曲线b.t=3s时,直线a和曲线b刚好相切,下列说法正确的是()A.t=3s时,两车具有共同的加速度B.在运动过程中,b车始终没有超过a车C.a车做匀速运动,b车做加速运动D.在0-3s的时间内,a车的平均速度比b车的大7.下列各组物理量中,不都是矢量的是()A.位移、重力B.路程、弹力C.加速度、速度的变化量、速度D.摩擦力、加速度8.甲、乙两人发生争执,甲打了乙的胸口一拳致使乙受伤.法院判决甲应支付乙的医药费.甲辩解说:“我打乙一拳,根据作用力与反作用力相等,乙对我也有相同大小的作用力,所以乙并没有吃亏.”那么这一事件判决的依据是A.甲打乙的力大于乙对甲的作用力,故判决甲支付乙的医药费B.甲打乙的力等于乙对甲的力,但甲的拳能承受的力大于乙的胸能承受的力,乙受伤而甲未受伤,甲主动打乙,故判决甲支付乙的医药费C.甲打乙的力大于乙对甲的力,甲的拳和乙的胸受伤害程度不相同,甲轻而乙重,故判决甲支付乙的医药费D.由于是甲用拳打乙的胸,甲对乙的力远大于乙胸对甲拳的作用力,故判断甲支持乙的医药费9.2018年7月1日,具有完全自主产权的我国加长版“复兴号”动车组正式在京沪线上运行。
安徽省固镇县第一中学2015-2016学年七年级英语期末复习测试

安徽省固镇县第一中学2015-2016学年七年级英语期末复习测试一、单项选择(15分)( )1. There______a fashion show on the square tomorrow evening.A. is going toB. will haveC. is going to haveD. will be( )2. interesting film it is!A. HowB. What aC. What anD. What( )3. What kind of clothes do people like to________?A. wearB. put onC. dressD. in( )4. Please call me if you ________ next Sunday.A. will be freeB. are freeC. have freeD. are going to be free( )5. Who are you waiting _________the bus stop.A. forB. atC. for atD. at for( )6. Does it take Millie two and a half hours her housework at weekends?A. to doB. doC. doesD. doing( )7. We have finished our homework today. ________ shall we do tomorrow?A. What otherB. What othersC. What thingD. What else( )8. There are so many tall buildings on _____ sides of the road.A. allB. anyC. bothD. either( )9. ---How long the shop every day?----It at 8 a.m. and at 8 p.m.A. does, open, is open, is closedB. is, open, is open, is closedC. does, open, opens, closesD. is ,open, opens, closes( )10. The teacher asks us ________ in the classroom between classes.A.don’t shoutB. not shoutC. not shoutingD. not to shout( )11. ---What do you think of the game called “trick or treat”?--- .A. Very muchB. A littleC. I think soD. It is wonderful( )12. --- Would you like some more turkey ? ---- .I am full.A. Yes, thank youB. Ok, pleaseC. That’s nice of youD. No, thanks( )13. Eating too much meat and candy bad for your health.A. areB.haveC. isD. are( )14. He gets up early the school bus every day.A. catchesB. to catchingC. catchingD. to catch( )15. ---The boy with a pair of glasses never helps his classmates, does he?--- . He often helps me with my English.A. Yes, he doesn’tB. Yes, he doesC. No, he doesD. No, he doesn’t二、完形填空(15分)One day, a grandmother stays at home with her 14-month-old ____16____. He is ____17____ with her yellow car key. At that time, the phone rings ____18____ the grandmother goes to ____19____ the phone. After the grandmother comes ____20____, she can’t ___21___ the key. She thinks that the little boy puts ____22____ somewhere.She looks ____23____ it in the room, but she can’t find it ____24____. Then she has a ____25____ idea. The grandmother ____26____ the child a blue key and pretends(假装) not to look. After a few ____27____, the boy goes into his ____28____ bedroom and he carefully puts ____29____ blue key under her bed, next to the yellow ____30____.( )16. A. granddaughter B. grandson C. sister D. son( )17. A. playing B. carrying C. putting D. sending( )18. A. because B. and C. but D. or( )19. A. call B. answer C. take D. catch( )20. A. down B. out C. back D. down( )21. A. look for B. bring C. buy D. find( )22. A. it B. them C. that D. they( )23. A. at B. after C. for D. of( )24. A. anywhere B. everywhere C. somewhere D. nowhere( )25. A. well B. better C. good D. bad( )26. A. gives B. buys C. draws D. makes( )27. A. weeks B. days C. years D. minutes( )28. A. mother B. grandmother’s C. grandson D. grandmother( )29. A. a B. an C. some D. the( )30. A. phone B. coat C. key D. shoes三、阅读理解(30分)AOne evening Tim is driving his car in the country and looking for a hotel. Then he sees an old man on the side of the road, so he stops his car and says to the old m an, “Where is the Sun Hotel? Will you please tell me how to get there?” “ Yes, ” the old man answers, “I’ll show you the way.” He gets into Tim’s car, and they drive for about 12 kilometers. When they come to a small house, the old man says,” Stop here.” T im stops and looks at the house. And he says to the old man, “But this isn’t a hotel.” “No,” the old man answers, “This is my house. And now I’ll show you the way to the Sun Hotel. Turn back and go 9 kilometers. Then you’ll see the hotel on your left.”( )31. Tim wants to stay__________ for the night.A. in his carB. in the old man’s houseC. in the hotelD. in the street( )32. Tim stops to__________.A. drive the old man homeB. ask the wayC. buy somethingD. say “hello” to the old man( )33. The old man takes Tim to__________.A. a hospitalB. a policemanC. a hotelD. his homeBEveryone needs friends. There is an old saying,“Friends are God’s way of taking care of us.” But how do you find friends and keep them?The American writer Sally Seamans tells young students some smart ways to find friends. Sally says finding friendship is just like planting a tree. You plant the seed (种子) and take care of it to make it grow.First, you should look for a friend. A good friend should be kind. For example, when you are not happy, a good friend should listen to you and do his or her best to help you. To make a friend, you cannot be too shy . You should make each other happy.But things cannot always be happy. Even the best friends have fights. What should you do when you fight with your friend? You have to talk to him or her. When there is no one around, have a talk. If he or she doesn’t want to talk, you could write a letter.There are three steps to being friends again. Tell him or her how you are feeling;say what your friend does wrong;and tell him or her why you do this or that. Remember that friends are the most important in your life. ( )34. Sally wants to tell students the way to ___________.A. find friendsB. plant treesC. get happyD. keep fit( )35. What makes good friends? A good friend should .A. be lovely and coolB. be kindC. have lots of moneyD. be beautiful( )36. According to the passage, you can ___________ your friend after a fight.A. buy a present forB. never say a word toC. have dinner withD. write a letter to( )37. Which is True according to the passage?A. Best friends never fight.B. A good friend should listen to you when you are unhappy.C. We must be unkind to make a good friend.D. We shouldn’t say what our friend does wrong.CMany children think mobile phones are cool. They have fun colours and let you talk with a friend anytime and anywhere.In the USA, more than 90 million people use mobile phones. Many of these people are children. For children, mobile phones are more than phone calls. They are fashionable.Some scientists say that mobile phones give off radiation(辐射) and it may be bad for people using mobile phones. One study(研究) shows that mobile phone radiation can make people get some kinds of cancer (癌症). But other scientists don’t think so. They say that they can not find any link (联系) between mobile phone use and cancer.Scientists say that people can stop themselves away from mobile phone radiation. One way is to use a headset (耳机). Or people can make short calls.( )38. Many children like mobile phones because they think mobile phones are ______.A. coolB. smallC. cheapD. their toys( )39. The underlined words “give off” in the passage mean_______________A. 发出B. 放弃C. 拒绝D.戒掉( )40.To stop themselves away from mobile phone radiation, people can____________.A. make longer callsB. use a headsetC. make shorter callsD. both B and CDA bee goes to a river. When it is drinking, the running water carries him away. A kind bird sees the bee’s danger. It picks a leaf off a tree and throws it into the water in front of the bee. The bee climbs onto the leaf, and comes to the bank (岸) of the river. The bee thanks the bird and then flies away.Several days later, the bird is sitting in the tree. It doesn’t see that a man is aiming his gun (用枪瞄准) at it. But the bee sees what the man is doing. So it flies into the man’s eye. The man can’t see the bird clearly and cannot kill it. So the bird can fly away very quickly. The bee and the bird help to save each other’s lives and later they become very good friends.( )41. What does the bee do at the beginning of the story?A. It saves the bird’s life.B. It comes to river to have some water.C. It flies over the river to find a leaf.D. It finds a leaf on the water and stays on it for a ride.( )42. ___________ takes the bee to the bank of the river.A. A manB. A birdC. The water in the riverD. A leaf that the bird picks for it( )43. What happens when the bird is sitting in the tree one day?A. It falls on a leaf in the river.B. A man is climbing up the tree to catch the bird.C. Someone is going to kill the bird.D. The bird sees a man with a gun in his head.( )44. What does the bee do to help the bird?A. It flies over to tell the bird about the man.B. It flies into the man’s eye.C. It flies over to stay on one of the man’s hands.D. It puts a leaf to cover one of the man’s eyes.( )45. Which of the following can be the best title for the passage?A. Help Each OtherB. Man: No Good!C. Animal aren’t FriendsD. Ants and Birds四、单词拼写(10分)46. Let the girl with big eyes (paint) the wall white.47. Lucy, what about (dress) up as a terrible lion?48. I always have fun (get) delicious dishes ready for my family at the weekend.49. How long do they spend (take) photos of the dolphins.50. The new teacher often practises (ask) questions before teaching his students.51. Lucy, together with her friends often (庆祝) her birthday in KFC.52. Are your (祖父母) red packets for you and your brother?53. ---Where are my rice (粽子)? ---I can see them in your bowl.54. There are twenty comic books. One is mine, the (其他)are my classmates.55. One of my favourite (餐馆) is near the Slender West Lake.五、任务型阅读(10分)Each year, we welcome many holidays here in America.On January 1, we welcome the coming of a new year like many people in other countries. And we have another fou r holidays on the first day of a month: April Fool’s Day, May Day, Friendship Day (Aug.1) and Grandparents Day (Sept.1).The most important holiday for the young people comes in February. It is Valentine’s Day. Lots of boys give red roses to girls as a present.People celebrate some holidays for their family members. We say thanks to our mother in May and celebrate Father’s Day in the following month. In November many people come back home for Thanksgiving Day, so all the family can stay together.There are also some interesting holidays for children. For example, Halloween comes at theend of October. Children often play with pumpkin lanterns and wear all kinds of masks.Of course, the most important festival is Christmas. After a year of work and study, people can enjoy a long六、缺词填空(10分)Food is important. Everyone n 66 to eat well if he or she wants to have a strong body. Our minds(头脑) also need a kind of food. This kind of food is knowledge(知识). we b 67 to get knowledge even when we are very young. Small children are very interested in e 68 around them. They learn something while they are w 69 and listening. When they are getting older,they begin to read science books, s 70 books ---anything they like. When they find something new, they love to ask questions and try to find out the a 71 . What is the best way to g 72 knowledge? If we learn by ourselves,we will get the most knowledge. If we are always getting answers from others and do not ask w 73 , we will n74 learn well. When we study in the right way, we will learn m 75 and understand better.七、完成句子。
固镇一中高三月考英语试卷

固镇一中高三月考英语试卷命题人:曹溪本试卷分第一卷(选择题)和第二卷(非选择题)两部分。
共150分。
考试时间120分钟。
第一卷(三大题,共115分)第一部分:听力理解(共两节,30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一道小题,从每题所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你将有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话你将听一遍1.What are they talking about?A. Games.B. The T-shirt.C. Sports.2. How did Margaret travel?A. By air.B. By train.C. By ship.3. Who would like to go to college?A. The man‟s wife.B. The man‟s daughter.C. The man‟s sister.4. What did the man mean?A. He wanted a quiet place.B. He wanted to sit near the door.C. He wanted a table near the window.5. Which of the following places is NOT mentioned?A. America.B. Canada.C. Moscow.第二节(共15小题;每题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6至第8题。
6. Why does the girl make the telephone call?A. She wants to know more about the club.B. She hopes to find a job in Washington.C. She wants to know the number of members.7. What do the club members do on Thursday evening?A. They have sports events.B. They have language classes.C. They have dinner together.8. What language does the girl speak besides English?A. Spanish.B. French.C. Italian.听第7段材料,回答第9至第11题。
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固镇一中2015届高三12月数学试卷(2)
(满分150分 时间120分钟) 命题人:徐 波
一、选择题(本题包括10小题,每小题5分,共50分)
1.设全集U 是实数集R ,{}2|1M x x =>,{}|02N x x =<<,则集合U N M ð=( )
A .{}|21x x -≤<
B .{}|01x x <≤
C .{}|11x x -≤≤
D .{}|1x x <
2. 已知命题:p “[]0,1,x x a e ∀∈≥”,命题:q “2,40x R x x a ∃∈-+=”,若命题,p q 均是真命题,则实数a 的取值范围是 ( )
A .[4,)+∞
B .[1,4]
C .[,4]e
D .(,1]-∞ 3.下列命题正确的是( )
A .在(,2ππ)内,存在x ,使5
sin cos 4
x x +=
B .函数2sin()5y x π=+的图像的一条对称轴是4
5x π=
C .函数2
1
1tan y x
=
+的周期为2π D .函数2sin y x =的图像可以由函数2sin(2)4y x π=-的图像向左平移8π
个单位得
4.函数)sin()(ϕω+=x A x f (其中2
||,0πϕ<>A )的图象如下图所示,为了得到x x g 2sin )(= 的
图象,则只需将)(x f 的图象( ) A .右移6
π
个长度单位 B .右移12
π
个长度单位 C .左移
6
π
个长度单位 D .左移
12
π
个长度单位
5.设()f x 为定义在R 上的奇函数,当0x ≤时,2()2log (1)(x f x x a a =+-+为常数),则(3)f = ( )
A .98-
B .9
8
C .-6
D .6
6.在ABC ∆中,C B A ∠∠∠,,所对的边分别为c b a ,,,边BC 上的高1==BC AD ,则22c b +的最小值为( ) A .1 B .
2
3 C .2 D .2
5
7.在直角梯形ABCD 中,//AB CD ,AD AB ⊥,45B ∠=,22AB CD ==,M 为腰BC 的
中点,则MA MD =( )
A .1
B .2
C .3
D .4
8.设函数()cos (0)f x x ωω=>,将()y f x =的图像向右平移
原图像重合,则ω的最小值等于( )
A .3 C .6 D .9
9.已知函数x e x x f 2)1()(+=,设[]1,3--∈k ,对任意[]2,,21+∈k k x x ,则)()(21x f x f -的最大值为 (A )34-e (B )e 4 (C )34-+e e (D )14+e 10.已知()f x 是定义在R 上的偶函数,且当0x >时,()21x f x x -=
+,若对任意实数1,22t ⎡⎤
∈⎢⎥⎣⎦
,都有()()10f t a f t +-->恒成立,则实数a 的取值范围是( ) A .()
(),30,-∞-+∞ B .()1,0- C .()0,1 D .()(),12,-∞+∞
二、填空题 (本题5小题,每小题5分,共25分)
11.已知221,1,
(),1,og x x f x x x x ≥⎧=⎨-<⎩则满足()2f a >的a 的取值范围是 。
12.若正数,a b 满足23a b +=,且使不等式
11
02m a b
+->恒成立,则实数m 的取值范围是 13.已知向量,a b 满足||1,||2,(2)()6,|2|a b a b a b a b ==+-=--则=
14.设1m >,在约束条件001x y mx y x y -≤⎧⎪
-≥⎨⎪+≤⎩
下,目标函数5z x y =+的最大值为4,则m 所取的值
为 15.以下是关于函数24||
()1
x f x x =
+的四个命题: ①()f x 的图像关于y 轴对称; ②()f x 在区间[1,0][1,)-+∞上单调递减;
③()f x 在1x =-处取得极小值,在1x =处取得极大值;④()f x 的有最大值,无最小值; ⑤若方程()0f x k -=至少有三个不同的实根,则实数k 的取值范围是(0,2)。
⑥若函数1
1sin )(22+++=x x x x f 的最大值为M ,最小值为m ,则=+m M 0
其中为真命题的是____ (请填写你认为是真命题的序号).
三、解答题(本题计6小题,共75分。
解答应写出必要的文字说明、证明过程)
16.已知函数3
()2cos 222
f x x x a =
++-, (1)求函数()f x 的单调递增区间;
(2)设函数()f x 在[0,]2π上的最小值为3
2
-,求函数()()f x x R ∈的值域。
17.已知函数y =ln(2-x)[x -(3m +1)]的定义域为集合A ,集合B =⎩⎪⎨⎪⎧⎭
⎪⎬⎪⎫x|
x -2
+1x -m <0. (1)当m =3时,求A∩B;
(2)求使B ⊆A 的实数m 的取值范围. .
18.在数列{}n a 中,已知111,21(1,2,3,...).n n a a a n n +=-=-+= (1)证明:数列{}n a n -是等比数列; (2)令,2n
n n n
a b S =
为数列{}n b 的前n 项和,求n S 的表达式;
19.已知函数2()(2)ln f x ax a x x =-++,其中a R ∈, (1)当1a =时,求曲线()y f x =在点(1,(1))f 处的切线方程; (2)若()f x 在区间[1,]e 上的最小值为2-,求a 的取值范围。
20.已知数列{}n a ,12,a a a p ==(p 为常数,且0p >),n S 为{}n a 的前n 项和,且1()
2
n n n a a S -= (1)求a 的值;
(2)试判断{}n a 是不是等差数列,若是,求其通项公式;若不是,说明理由。
(3)记21
12
(*)n n n n n S S P n N S S ++++=+∈,求证:12323n P P P P n ++++<+
21. 设函数)1,0()(≠>-=a a x a x f x
(1)若e a =(e 是自然对数的底数),求)(x f 的单调区间和极值;
(2)若函数)||(x f y =在全体实数R 上恰有4个零点,求实数a 的取值范围.。