C语言代码大全

------------------------------------------------------------------------摘自宋鲁生程序设计大赛

乘法口诀表

#include

#include

void main(void)

{

int i,j,x,y;

clrscr();

printf("\n\n * * * 乘法口诀表* * * \n\n");

x=9;

y=5;

for(i=1;i<=9;i++)

{

gotoxy(x,y);

printf("%2d ",i);

x+=3;

}

x=7;

y=6;

for(i=1;i<=9;i++)

{

gotoxy(x,y);

printf("%2d ",i);

y++;

}

x=9;

y= 6;

for(i=1;i<=9;i++)

{

for(j=1;j<=9;j++)

{

gotoxy(x,y);

printf("%2d ",i*j);

y++;

}

y-=9;

x+=3;

}

printf("\n\n");

}

用一维数组统计学生成绩

#include

void main()

{

char SelectKey,CreditMoney,DebitMoney;

while(1)

{

do{

clrscr();

puts("=========================");

puts("| Please select key: |");

puts("| 1. Quary |");

puts("| 2. Credit |");

puts("| 3. Debit |");

puts("| 4. Return |");

puts("=========================");

SelectKey = getch();

}while( SelectKey!='1' && SelectKey!='2' && SelectKey!='3' &&

SelectKey!='4' );

switch(SelectKey)

{

case '1':

clrscr();

puts("================================");

puts("| Your balance is $1000. |");

puts("| Press any key to return... |");

puts("================================");

getch();

break;

case '2':

do{

clrscr();

puts("==================================");

puts("| Please select Credit money: |");

puts("| 1. $50 |");

puts("| 2. $100 |");

puts("| 3. Return |");

puts("==================================");

CreditMoney = getch();

}while( CreditMoney!='1' && CreditMoney!='2' && CreditMoney!='3' );

switch(CreditMoney)

{

case '1':

clrscr();

puts("=========================================");

puts("| Your Credit money is $50,Thank you! |");

puts("| Press any key to return... |");

puts("=========================================");

getch();

break;

case '2':

clrscr();

puts("==========================================");

puts("| Your Credit money is $100,Thank you! |");

puts("| Press any key to return... |");

puts("==========================================");

getch();

break;

case '3':

break;

}

break;

case '3':

do{

clrscr();

puts("====================================");

puts("| Please select Debit money: |");

puts("| 1. $50 |");

puts("| 2. $100 |");

puts("| 3. $500 |");

puts("| 4. $1000 |");

puts("| 5. Return |");

puts("====================================");

DebitMoney = getch();

}while( DebitMoney!='1' && DebitMoney!='2' && DebitMoney!='3' &&DebitMoney!='4' && DebitMoney!='5' );

switch(DebitMoney)

{

case '1':

clrscr();

puts("===========================================");

puts("| Your Debit money is $50,Thank you! |");

puts("| Press any key to return... |");

puts("===========================================");

getch();

break;

case '2':

clrscr();

puts("===========================================");

puts("| Your Debit money is $100,Thank you! |");

puts("| Press any key to return... |");

puts("===========================================");

getch();

break;

case '3':

clrscr();

puts("===========================================");

puts("| Your Debit money is $500,Thank you! |");

puts("| Press any key to return... |");

puts("===========================================");

getch();

break;

case '4':

clrscr();

puts("===========================================");

puts("| Your Debit money is $1000,Thank you! |");

puts("| Press any key to return... |");

puts("===========================================");

getch();

break;

case '5':

break;

}

break;

case '4':

clrscr();

puts("================================");

puts("| Thank you for your using! |");

puts("| Good bye! |");

puts("================================");

return;

}

}

模拟ATM（自动柜员机）界面

#include void main()

{

int Password=0,Number=0,price=58,i=0;

while( Password != 1234 )

{

if( i >= 3 )

return;

i++;

puts("Please input Password: ");

scanf("%d",&Password);

}

i=0;

while( Number!=price )

{

do{

puts("Please input a number between 1 and 100: ");

scanf("%d",&Number);

printf("Your input number is %d\n",Number);

}while( !(Number>=1 && Number<=100) );

if( Number >= 90 )

{

printf("Too Bigger! Press any key to try again!\n");

}

else if( Number >= 70 && Number < 90 )

{

printf("Bigger!\n");

}

else if( Number >= 1 && Number <= 30 )

{

printf("Too Small! Press any key to try again!\n");

}

else if( Number > 30 && Number <= 50 )

{

printf("Small! Press any key to try again!\n");

}

else

{

if( Number == price )

{

printf("OK! You are right! Bye Bye!\n");

}

else if( Number < price )

{

printf("Sorry,Only a little smaller! Press any key to try again!\n");

}

else if( Number > price )

{

printf(" Sorry, Only a little bigger! Press any key to try again!\n");

}

getch();

}

}

用二维数组实现矩阵转置

/* 用二维数组实现矩阵的转置*/

#include

#define ROW 3

#define COL 4

main()

{

int matrixA[ROW][COL],matrixB[COL][ROW];

int i,j; clrscr();

printf("Enter elements of the matrixA,");

printf("%d*%d:\n",ROW,COL);

for( i=0; i

{

for( j=0; j

{

scanf("%d",&matrixA[i][j]);

}

}

for( i=0; i

{

for( j=0; j

{

matrixB[j][i] = matrixA[i][j];

}

}

printf("MatrixB,");

printf("%d*%d:\n",COL,ROW);

for( i=0; i

{

for( j=0; j

{

printf("%8d",matrixB[i][j]);

}

printf("\n");

}

printf("\n Press Any Key to Quit... \n");

getch();

}

求解二维数组的最大/最小元素

#define MAXN 20

int a[MAXN][MAXN];

main()

{

int min, /* 存储最小值*/

max; /* 存储最大值*/

int row,col,n;

clrscr();

printf("Please input the order of the matrix:\n");/* 输入方阵的阶次*/ scanf("%d",&n);

printf("Please input the elements of the matrix,\n from a[0][0] to a

[%d][%d]:\n",n-1,n-1);

for(row=0;row

for(col=0;col

scanf("%d",&a[row][col]);

for(min=a[0][0],row=0;row

{

/* 从每行选出最大数*/

for(max=a[row][0],col=1;col

if(max

max=a[row][col];

if(min>max)/* 保存至row行的最小数*/

min=max;

}

printf("The minimum of maximum number is %d\n",min);

for(max=a[0][0],row=0;row

{

/* 每行选出最小数*/

for(min=a[row][0],col=1;cola[row][col])

min=a[row][col];

if(max

max=min;

}

printf("The maximum of minimum numbers is %d\n",max);

printf("\nPress any key to quit...\n");

getch();

}

利用数组求前n个质数

#define N 50

main()

{

int primes[N];

int pc,m,k; clrscr();

printf("\n The first %d prime numbers are:\n",N);

primes[0]=2;/*2是第一个质数*/

pc =1;/*已有第一个质数*/

m =3;/*被测试的数从3开始*/

while(pc

{

/*调整m使它为下一个质数*/

k=0;

while(primes[k]*primes[k]<=m)

if(m%primes[k]==0)

{/*m是合数*/

m+=2;/*让m取下一个奇数*/

k=1;/*不必用primes[0]=2去测试m，所以k从一开始*/

}

else

k++;/*继续用下一个质数去测试*/

primes[pc++]=m;

m+=2;/*除2外，其余质数均是奇数*/

}

/*输出primes[0]至primes[pc-1]*/

for(k=0;k

printf("%4d",primes[k]);

printf("\n\n Press any key to quit...\n ");

getch();

}

编制万年历

#include "stdio.h"

long int f(int year,int month)

{/*f(年，月)＝年－1，如月<3;否则，f(年，月)＝年*/

if(month<3) return year-1;

else return year;

} long int g(int month)

{/*g(月)＝月＋13，如月<3;否则，g(月)＝月＋1*/

if(month<3) return month+13;

else return month+1;

} long int n(int year,int month,int day)

{

/*N=1461*f(年、月)/4+153*g(月)/5+日*/

return 1461L*f(year,month)/4+153L*g(month)/5+day;

} int w(int year,int month,int day)

{

/*w=(N-621049)%7(0<=w<7)*/

return(int)((n(year,month,day)%7-621049L%7+7)%7);

} int date[12][6][7];

int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},

{31,29,31,30,31,30,31,31,30,31,30,31}};

main()

{int sw,leap,i,j,k,wd,day;

int year;/*年*/

char title[]="SUN MON TUE WED THU FRI SAT";

clrscr();

printf("Please input the year whose calendar you want to know: ");/*输

入年*/

scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/

sw=w(year,1,1);

leap=year%4==0&&year%100||year%400==0;/*判闰年*/

for(i=0;i<12;i++)

for(j=0;j<6;j++)

for(k=0;k<7;k++)

date[i][j][k]=0;/*日期表置0*/

for(i=0;i<12;i++)/*一年十二个月*/

for(wd=0,day=1;day<=day_tbl[leap][i];day++)

{/*将第i＋1月的日期填入日期表*/

date[i][wd][sw]=day;

sw=++sw%7;/*每星期七天，以0至6计数*/

if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/

} printf("\n|==================The Calendar of Year %d

=====================|\n|",year);

for(i=0;i<6;i++)

{/*先测算第i+1月和第i+7月的最大星期数*/

for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/

wd+=date[i][5][k]+date[i+6][5][k];

wd=wd?6:5;

printf("%2d %s %2d %s |\n|",i+1,title,i+7,title);

for(j=0;j

{

printf(" ");/*输出四个空白符*/

/*左栏为第i+1月，右栏为第i+7月*/

for(k=0;k<7;k++)

if(date[i][j][k])

printf("%4d",date[i][j][k]);

else printf(" ");

printf(" ");/*输出十个空白符*/

for(k=0;k<7;k++)

if(date[i+6][j][k])

printf("%4d",date[i+6][j][k]);

else printf(" ");

printf(" |\n|");

}

/*scanf("%*c");/*键入回车输出下一个月的日历*/

}

puts

("=================================================================|") ;

puts("\n Press any key to quit...");

getch();

}

对数组元素排序

rest(int a[], int n)

{

int i,low,high,t; for(i=0,low=0,high=n-1;i<=high;) {

if(a[i]>0)

{

/*a[i]与a[high]交换，随之high减1*/

t=a[i];

a[i]=a[high];

a[high]=t;

high--;

}

else if(a[i]==0)

i++; /* 掠过该元素*/

else

{

/*a[i]与a[low]交换，随之low增1, i增1*/

t=a[i];

a[i]=a[low];

a[low]=t;

low++;

i++;

}

}

}

int s[]={8,4,0,-1,6,0,-5};

main()

{

int i;

clrscr();

printf("\n The arry before rest is:\n");

for(i=0;i

printf("%4d",s[i]);

rest(s,sizeof(s)/sizeof(s[0]));

printf("\n The arry after rest is:\n");

for(i=0;i

printf("%4d",s[i]);

printf("\n Press any key to quit...\n");

getch();

}

任意进制数的转换

/* 函数trans将无符号整数n翻译成d（2<＝d<＝16）进制表示的字符串s */ #define M sizeof(unsigned int)*8

int trans(unsigned n, int d, char s[])

{

static char digits[] ="0123456789ABCDEF"; /* 十六进制数字的字符*/

char buf[M+1];

int j, i = M;

if(d<2||d>16)

{

s[0]='\0'; /* 不合理的进制，置s为空字符串*/

return 0; /* 不合理的进制，函数返回0 */

}

buf[i]='\0';

do

{

buf[--i]=digits[n%d]; /*译出最低位，对应字符存入对应工作数组中*/

n/=d;

}while(n);

/* 将译出在工作数组中的字符串复制到s */

for(j=0;(s[j]=buf[i])!='\0';j++,i++);

/* 其中控制条件可简写成s[j]=buf[i] */

return j;

}

/* 主函数用于测试函数trans() */

main()

{

unsigned int num = 253;

int scale[]={2,3,10,16,1};

char str[33];

int i;

clrscr();

for(i=0;i

{

if(trans(num,scale[i],str))

printf("%5d = %s(%d)\n",num,str,scale[i]);

else

printf("%5d => (%d) Error! \n",num,scale[i]);

}

printf("\n Press any key to quit...\n");

getch();

}

判断回文数

/* 函数circle用于判断正整数n的d进制数表示形式是否是回文数*/ int circle(int n, int d)

{

int s=0,m=n;

while(m)

{

s=s*d+m%d;

m/=d;

}

return s==n;

}

/* main函数用于测试circle函数*/

int num[]={232,27,851};

int scale[]={2,10,16};

main()

{

int i,j;

clrscr();

for(i=0;i

for(j=0;j

if(circle(num[i],scale[j]))

printf("%d -> (%d) is a Circle Number!\n",num[i],scale[j]);

else

printf("%d -> (%d) is not a Circle Number!\n",num[i],scale[j]);

printf("\n Press any key to quit...\n");

getch();

}

求解钢材切割的最佳订单

#include

#define N 20

#define DELTA 2

int bestlen;

int bestsele[N];

int sele[N];

int n;

int orderlen[N];

int total;

main()

{

int i;

clrscr();

printf("\n Please enter total length of the steel:\n");/* 输入钢材总长

*/

scanf("%d",&total);

printf("\n Please enter number of order:\n"); /* 输入定单数*/ scanf("%d",&n);

printf("\n Please enter the orders:\n"); /* 输入各定单*/

for(i=0;i

scanf("%d",&orderlen[i]);

bestlen=0; /*最佳解用料的初值*/

for(i=0;i

sele[i]=bestsele[i]=0; /*置当前选择和最佳选择初值*/

try(); /* 调用函数求解*/

for(i=0;i

if(bestsele[i])

printf("order %d length = %d\n",i+1,orderlen[i]);

printf("\n Press any key to quit...");

getch();

}

try()

{

int i,len;

for(len=i=0;i

if(sele[i])

len+=orderlen[i]+DELTA;

if(len-DELTA<=total) /* 注意最后一段可能不需要切割*/

{

if(bestlen < len)

{

/* 找到一个更好的解*/

bestlen = len;

for(i=0;i

bestsele[i]=sele[i];

}

for(i=0;i

if(!sele[i])

{

sele[i]=1; /* 做选中尝试*/

try();

sele[i]=0;

}

}

}

指向数组的指针

main()

{

int x,y,z; /* 定义三个int型变量*/

int *xp = &x, /* 定义指针变量xp,并赋值为x的地址，使xp指向x */ *yp = &y, /* 定义指针变量yp,并赋值为y的地址，使yp指向y */

*zp = &z; /* 定义指针变量zp,并赋值为z的地址，使zp指向z */

int t;

printf("\nPlease input x,y,z:\n");

scanf("%d%d%d",xp,yp,zp); /* 通过变量的指针，为变量输入值*/ if(*xp>*yp) /* 通过指向变量的指针引用变量的值*/

{

t=*xp; /* 通过指向变量的指针引用变量的值*/

*xp=*yp;/* 通过指向变量x的指针xp,引用变量x的值*/

*yp=t; /* 通过指向变量y的指针yp,引用变量y的值*/

}

if(*xp>*zp) /* 通过指向变量的指针,引用变量的值*/

{

t=*xp; /* 通过指向变量x的指针xp,引用变量x的值*/

*xp=*zp;/* 通过指向变量x的指针xp,引用变量x的值*/

*zp=t; /* 通过指向变量z的指针zp,引用变量z的值*/

}

if(*yp>*zp) /* 通过指向变量的指针,引用变量的值*/

{

t=*yp; /* 通过指向变量的指针,引用变量的值*/

*yp=*zp;/* 通过指向变量y的指针yp,引用变量y的值*/

*zp=t;/* 通过指向变量z的指针zp,引用变量z的值*/

}

printf("x = %d\ty = %d\tz = %d\n",x,y,z);

printf("\nPress any key to quit...\n");

getch();

}

阿拉伯数字转换为罗马数字

#include

#define ROWS 4

#define COLS 4

int nums[ROWS][COLS]={{1000,1000,1000,1000},

{900,500,400,100},

{90,50,40,10},

{9,5,4,1}};

char *roms[ROWS][COLS]={{"m","m","m","m"}, {"cm","d","cd","c"},

{"xc","l","xl","x"},

{"ix","v","iv","i"}}; main(int argc,char *argv[ ])

{

int low,high;

char roman[25]; if(argc<2)

{ printf("Usage:roman decimal_number\n");/*运行程序需带整数参数*/

}

high=low=atoi(argv[1]);/*将第一个参数转换成整数*/

checknum(low);

if(argc>2)

{/*带两个参数*/

high=atoi(argv[2]);

checknum(high);

if(low>high)

{

low=high;

high=atoi(argv[1]);

}

}

else

low=1;

for(;low<=high;low++)

{

to_roman(low,roman);

printf("%d\t%s\n",low,roman);

}

} checknum(int val)/*检查参数合理性*/

{

if(val<1||val>9999)

{

printf("The number must be in range 1..9999.\n");

exit(0);

}

}

to_roman(int decimal,char roman[ ])/*将整数转换成罗马数字表示*/ {

int power,index;

roman[0]='\0';

for(power=0;power

for(index=0;index

while(decimal>=nums[power][index])

{

strcat(roman,roms[power][index]);

decimal-=nums[power][index];

}

}

通讯录的输入输出

#include

#define ZIPLEN 10

#define PHONLEN 15

/*struct addr类型定义*/ struct addr

{

char *name;/*姓名*/

char *address;/*地址*/

char zip[ZIPLEN];/*邮政编码*/

char phone[PHONLEN];/*电话号码*/

}; main()/*本主函数示意上述输入输出函数的用法*/

{

struct addr p[100];

int i,j;

clrscr();

for(i=0;readaddr(p+i);i++);

for(j=0;j

puts("\n Press any key to quit...");

getch();

} /* 函数readaddr用于输入一个通信录函数*/

int readaddr(struct addr *dpt)

{

int len;

char buf[120];/*输入字符串的缓冲区*/ printf("\nPlease input the

Name:\n");/*输入姓名*/

if(scanf("%s",buf)==1)

{

len=strlen(buf);

dpt->name=(char *)malloc(len+1);/*申请存贮姓名的空间*/ strcpy(dpt->name,buf);

}

else return 0;/*Ctrl+Z结束输入*/

printf("Please input the Address:\n");/*输入地址*/

if(scanf("%s",buf)==1)

{

len=strlen(buf);

dpt->address=(char *)malloc(len+1);/*申请存贮地址的空间*/ strcpy(dpt->address,buf);

}

else

{/*Ctrl+Z结束输入*/

free(dpt->name);/*释放存贮姓名的空间*/

return 0;

}

printf("Please input the Zip code:\n");/*输入邮编*/

if(scanf("%s",buf)==1)

strncpy(dpt->zip,buf,ZIPLEN-1);

else

{

free(dpt->name);/*释放存贮姓名的空间*/

free(dpt->address);/*释放存贮地址的空间*/

return 0;/*Ctrl+Z结束输入*/

}

printf("Please input the Phone number:\n");/*输入电话号码*/ if(scanf("%s",buf)==1)

strncpy(dpt->phone,buf,PHONLEN-1);

else

{

free(dpt->name);

free(dpt->address);

return 0;/*Ctrl+Z结束输入*/

}

return 1;

} /* 函数writeaddr用于输出通讯录*/

int writeaddr(struct addr*dpt)

{

printf("Name : %s\n", dpt->name);/*输出姓名*/

printf("Address : %s\n", dpt->address);/*输出地址*/

printf("Zip : %s\n", dpt->zip);/*输出邮编*/

printf("Phone : %s\n\n", dpt->phone);/*输出电话号码*/

}

扑克牌的结构表示

enum suits{CLUBS,DIAMONDS,HEARTS,SPADES}; struct card

{

enum suits suit;

char value[3];

};

struct card deck[52];

char cardval[][3]= {"A","2","3","4","5","6","7","8","9","10","J","Q","K"};

char suitsname[][9]={"CLUBS","DIAMONDS","HEARTS","SPADES"}; main() {

int i,j;

enum suits s;

clrscr();

for(i=0;i<=12;i++)

for(s=CLUBS;s<=SPADES;s++)

{

j=i*4+s;

deck[j].suit=s;

strcpy(deck[j].value,cardval[i]);

}

for(j=0;j<52;j++)

printf("(%s%3s)%c",suitsname[deck[j].suit],deck[j].value,j%

4==3?'\n':'\t');

puts("\nPress any key to quit...");

getch();

}

用“结构”统计学生成绩

#include

#define N 200

#define SCORES 5

#define NUMLEN 10

struct std_type{

char no[NUMLEN];/*学号*/

char *name;/*名字符串指针*/

int scores[SCORES];/*五门功课的成绩*/

};

struct std_type students[N];

int order[N];

int total[N]; /*[函数]输入一个学生信息函数*/

int readastu(struct std_type *spt)

{

int len,j;

char buf[120];/*输入字符串的缓冲区*/ printf("\nNumber : ");/*输入学号

*/

if(scanf("%s",buf)==1)

strncpy(spt->no,buf,NUMLEN-1);