上海高考高三数学易错题

上海高考高三数学易错题
上海高考高三数学易错题

1

1、 函数f (x )=)2(log 25.0x x +-的单调递增区间

2、 把由函数y =k x 与y =x +k (k>0)的图像围成的三角形的面积S 表示成k 的函数,则函数解析式为

3、 f (x )是周期为2的奇函数,当x []1,0∈时,f (x )=x 2,则x []2,1∈时,f (x )=

4、设函数f (x )的反函数为1()f x -,给出以下命题;

(1)若f(x)是奇函数,则1()f

x -必定是奇函数;

(2)若y =f(x )和y= 1()f x -的图像有公共点,则公共点必在直线y=x 上; (3)若y =f(x)在[]b a ,上是增函数,则y= 1()f

x -在[]b a ,上必定是增函数; 则上述命题中真命题的序号是

5、若函数f(x)=)22(log 2+-x x a 的最大值为0,则g(x)=2

1x a -有最 值为

6、设函数y={}{}7,5,3,2,1,,?q p x p q ,则所得函数是偶函数的概率是

7、设P 、Q 、M 三个集合,则“P ?Q”是“)()(M Q M P ???”成立的 条件

8、A 、B 、C 、是三个集合,写出一个使“)(C B A ??”成立的必要不充分条件

9、设f(x)=,234++x x 则()[]x f f 1-= ,()[]

x f f 1-=

10、函数f(x)=x 2lga-2x+1的图像与x 轴有两个不同的交点,则a 的取值范围是

11、若函数y=f(2x+1)是偶函数,则函数y=f(2x)的图像的对称轴的方程是

12、对定义在R 上的函数f(x),若实数x 0满足f(x 0)=x 0,则称x 0为函数f(x 0)的一个不动点,若函数f(x)=ax 2-2x-1

只有一个不动点,则实数a 的值是0,

13、若函数f(x)=)3(log 22

1m mx x +-在),2(+∞是减函数,则实数m 的取值范围是

14、函数)0(10101010?-+=--x y x

x x

x 的反函数是

15、不等式

11

?-x ax 的解集为A ,若()()()()+∞?∞-??∞-,21,1,A 则实数a 的取值范围是 16、集合??????∈=Z n n x x ,4sin π的子集的个数是

2 1.直线(1)(1)0x a y b +++=与圆222x y +=的位置关系是

2.过点P (2005,2005)且在两坐标轴上截距相等的直线方程为

3.2y kx =+与221x y -=有且仅有一个公共点,则k =

4.求焦点在直线34120x y --=上的抛物线的标准方程是

5.抛物线2y px =的焦点坐标为

5.P 是双曲线22

1918

x y -=上任意一点,F 1、F 2分别为左、右焦点, |PF 1|=8,则|PF 2|=

7.M 是抛物线220y px p =>上点,A (3,1),F 是抛物线焦点,则|AM |+|MF |的最小值为

8.222

1211t x y t t ==++化为普通方程是

9.已知点A (1,2)、B (5,-1),且A 、B 两点到直线l 的距离都是2,求直线l 方程

10.若过定点(1,0)M -且斜率为k 的直线与圆22450x x y ++-=在第一象限内的部分有交点,则k 的取值范围是

11.已知抛物线x y 42=的顶点为O ,抛物线上B A ,两点满足0=?OB OA ,则点O 到直线AB 的最大距离为

12.在坐标平面内,与点A (1,2)的距离为1,且与点B (5,5)的距离为d 的直线共有4条,则d 的取值范围是 .

13.已知实数x ,y 满足3x 2+2y 2=6x ,则x 2+y 2的最大值是

14.与圆3)5(22=++y x 相切,且纵截距和横截距相等的直线共有

15.如果不论实数 b 取何值,直线b kx y +=与双曲线1222=-y x 总有公共点,那么k 的取值范围

为 。

16.以下四个关于圆锥曲线的命题中

① 设A 、B 为两个定点,k 为非零常数,k PB PA =-||||,则动点P 的轨迹为双曲线;

② 过定圆C 上一定点A 作圆的动点弦AB ,O 为坐标原点,若),(21+=

则动点P 的轨迹为椭圆; ③ 斜率为定值k 的动直线与抛物线相交于A 、B 两点,O 为坐标原点),(21+= 则动点P 的轨迹是射线;

④ 双曲线135

192522

22=+=-y x y x 与椭圆有相同的焦点.

其中真命题的序号为 。(写出所有真命题的序号)

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