例题-圆曲线坐标计算

例题-圆曲线坐标计算
例题-圆曲线坐标计算

1、该路线为一圆曲线,R=500,请将上表补充完整

解:JD1方位角=arctan((3192.8803-3145.8062)/(1000.1723-1285.1157))

=170.6191759(可用Arg(X+Yi)或者Pol(X,Y)得出,在excel中,使用DEGREES(ATAN2(X,Y))得出

JD2里程=JD1里程+√((1000.1723-1285.1157)^2+(3192.8803-3145.8062)^2))

=100000+288.805665(可用Abs(X+Yi)或者Pol(X,Y)得出,在Excel中,可使用SQRT(X^2+Y^2)得出

JD2方位角因为和JD1在一条直线上,所以方位角相等

JD3里程=√((739.4631-1000.1723)^2+(3108.2597-3192.8803)^2))

=100288.805665+274.098435

JD3方位角=arctan((3108.2597-3192.8803)/(739.4631-1000.1723))

=197.9823157

ZY点里程=JD1里程+√((1120.2611-1285.1157)^2+(3173.041-3145.8062)^2))

=100000+167.0891

YZ点里程=ZY点里程+圆曲线长

∵ 圆曲线转角=YZ点方位角-ZY点方位角

∵ ZY点方位角=JD3方位角

∴ YZ点里程=ZY点里程+(π*R*(YZ点方位角-ZY点方位角)/180

=100167.0891+(π*500*(197.9823157-170.6191759))/180

=100617.0891+238.7884=100405.8775

YZ点坐标等于

X YZ =X ZY +弦长*cos(α弦长)弦长=2R*sin(△YZ )△YZ =(ZY点方位角-YZ点方位角)/2

Y YZ =Y ZY +弦长*sin(α弦长)=2*500*SIN(RADIANS((197.9823157-170.6191759)/2))

=236.525619570512

X YZ =1120.2611+236.5256196*cos(RADIANS(184.3007458))α弦长=αZY +△YZ

Y YZ =3173.041+236.5256196*sin(RADIANS(184.3007458))=170.6191759+(197.9823157-170.6191759)/2

X =884.401499=184.3007458

Y =3155.303540

QZ点里程为圆曲线长度二分之一加ZY点里程

∵圆曲线L=238.7884

∴QZ点里程=238.7884/2+100167.0891

=100286.4833

方位角αQZ =αZY +α圆曲/2

=170.6191759+(197.9823157-170.6191759)/2

=184.3007458

QZ点坐标等于

X QZ =X ZY +弦长QZ *cos(αQZ )

弦长QZ =2R*sin(α圆曲/4)Y QZ =Y ZY +弦长QZ *sin(αQZ )

=2*500*SIN(RADIANS(197.9823157-170.6191759)/4)X QZ =1120.2611+119.11076*cos(177.45996085)

=119.11076253761Y QZ =3173.041+119.11076*sin(177.45996085)

αQZ =αZY +α圆曲/4=1001.267367

=170.6191759+((197.9823157-170.6191759)/4)=3178.319694=177.45996085

2、若待测点i坐标为

求该点里程;若道路净宽10.5m,测设基线为路线中心往左4.375m,求i点的偏距,以及左右边桩坐标。解:ZY点到圆曲线圆心方位角=αZY +90°

=170.6191759+90

=260.6191759

则有,圆心坐标为:

X 圆心=X ZY +R*cos(α圆心)

Y 圆心=Y ZY +R*sin(α圆心)

X =1120.2611+500*COS(RADIANS(260.6191759))

Y =3173.041+500*SIN(RADIANS(260.6191759))

X =1038.763218

Y =2679.727616

以圆心为坐标原点,则有圆心到ZY点方位角为αZY-圆心-180°

=260.6191759-180

=80.619176

待测点i至圆心方位角等于

αi=arctan((3147.3126-2679.727616)/(939.3381-1038.763218))

αi =DEGREES(ATAN2((939.3381-1038.763218),(3147.3126-2679.727616)))

αi =102.004322

待测点i所对应的角度=αi -αO-ZY

△i =102.004322-80.619176

△i =21.385146

该段弧长Li=π*R*△i/180

Li =(PI()*500*21.385146/180)

Li =186.620604i点所对应的路线到ZY点的弦的方位角αi=αZY+△i/2该段弦长Ci=2R*sin(△i/2)=170.6191759+21.385146/2

Ci =2*500*SIN(RADIANS(21.385146/2))=181.3117489

Ci =185.53924

i点对应里程位于测设基线的里程为:

Ki=186.620604+100167.0891

Ki

=K100+353.7097

i点对应里程位于测设基线的坐标为:

X i =X ZY +C i *cos(αi )

Y i =Y ZY +C i *sin(αi )

=1120.2611+185.53924*COS(RADIANS(181.3117489))

=3173.041+185.53924*SIN(RADIANS(181.3117489))

=934.770483

=3168.793573

=170.6191759+21.385146

=192.0043219

左偏角为αi-90°=192.0043219-90=102.0043219

右偏角为αi+90°=192.0043219+90=282.0043219

左边桩距测设基线距离为:10.5/2-4.375=0.875m

右边桩距测设基线距离为:10.5/2+4.375=9.625m

左右边桩坐标:

X左=Xi+M*cos α左=934.770483+0.875*COS(RADIANS(102.0043219))=934.588496

Y左=Yi+M*sin α左=3168.793573+0.875*SIN(RADIANS(102.0043219))=3169.649438

X右=Xi+M*cos α右=934.770483+9.625*COS(RADIANS(282.0043219))=936.772343

Y右=Yi+M*sinα右=3168.793573+9.625*SIN(RADIANS(282.0043219))=3159.37905

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