二级VISUAL+BASIC+模拟试卷436

二级VISUAL+BASIC+模拟试卷436
二级VISUAL+BASIC+模拟试卷436

[模拟] 二级VISUAL BASIC 模拟试卷436

单项选择题

第1题:

定义无符号整数类为UInt,下面可以作为类UInt实例化值的是( )。

A.-369

B.369

C.0.369

D.整数集合{1,2,3,4,5}

参考答案:B

只有B选项369可以用无符号整数来表示和存储。A选项-369有负号,选项C 0.369是小数,都不能用无符号整数类存储。选项D是-个整数集合,得用数组来存储。

第2题:

执行语句 Dim X, Y As Integer 后( )。

A.X和Y均被定义为整型变量

B.X和Y均被定义为变体类型变量

C.X被定义为整型变量,Y被定义为变体类型变量

D.X被定义为变体类型变量,Y被定义为整型变量

参考答案:D

声明变量时可以同时声明多个变量,但要分别说明每个变量的数据类型。如果定义变量时不说明数据类型,默认是Variant变体类型变量。本题中用Dim 同时定义了两个变量X、Y,变量X没说明数据类型,所以是Variant型变量,Y 是整型变量。故选D选项正确。

第3题:

窗体上有-个菜单编辑器设计的菜单。运行程序,并在窗体上单击鼠标右键,则弹出-个快捷菜单,如图所示。下列说法错误的是( )。

A.在设计"粘贴"菜单项时,在菜单编辑器窗口中设置了"有效"属性(有"√")

B.菜单中的横线是在该菜单项的标题输入框中输入了-个"-"(减号)字符

C.在设计"选中"菜单项时,在菜单编辑器窗口中设置了"复选"属性(有"√")

D.在设计该弹出菜单的主菜单项时,在菜单编辑器窗口中去掉了"可见"前面的"√"

参考答案:A

快捷菜单中的"粘贴"菜单项为无效时,在菜单编辑器窗口中"有效"属性应该是不选中状态,没有"√",故A选项错误。

第4题:

下列程序运行后,输出结果为( )。

Sub abcd(ByVal n As Integer)

n=n+5

End Sub

Private Sub Form_Click()

n%=3

Call abcd(n%)

Print n%

End Sub

A.3

B.4

C.5

D.8

参考答案:A

本题考查子过程的调用时的参数变化。Byval是传值调用的关键字,传值调用的时候形参的改变不会影响到实参。

第5题:

以下关于通用对话框的叙述中,错误的是

A.利用通用对话框建立打开文件对话框时,可以完成打开文件的操作

B.通用对话框控件可以用来建立不同类型的对话框

C.通用对话框不是工具箱中的标准控件

D.在设计阶段,通用对话框控件的大小不能改变

参考答案:A

利用通用对话框建立打开文件对话框时,并没有打开文件,故选项A错误。通用对话框可以通过设置Action属性或选择相应方法,而显示成不同类型的对话框,故选项B表述正确;通用对话框是-种ActiveX控件,不是标准的控件,故选项C表述正确;在设计阶段,通用对话框的控件大小不能改变,D项表述正确。

第6题:

结构化程序设计的基本原则不包括( )。

A.多态性

B.自顶向下

C.模块化

D.逐步求精

参考答案:A

结构化程序设计的思想包括:自顶向下、逐步求精、模块化、限制使用goto语句,所以选择A。

第7题:

使用语句DimA(1 To 10)As Integer声明数组A后,以下叙述正确的是

( )。

A.A数组中的所有元素值为0

B.A数组中的所有元素值不确定

C.A数组中的所有元素值为Empty

D.执行语句“EraseA”后,A数组中的所有元素值为Null

参考答案:A

本题考查数组。VB中数值型数组定义后,所有的元素都自动赋值为0。而Erase 仅可以清空自动数组中的元素值。

第8题:

在窗体上画-个文本框,然后编写如下事件过程:

Private Sub Textt_KeyPress(KeyAscii As Integer)

Dim char As String

char=Chr(KeyAscii)

KeyAscii=Asc(UCase(char))

Text1

.Text=String(6,KeyAScii)

End Sub

程序运行后,如果在键盘上输入字母“a”,则文本框中显示的内容为

( )。

A.a

B.A

C.aaaaaa

D.AAAAAA

参考答案:D

本题考查KeyPress事件过程和字符串函数。KeyPress事件的过程格式为:Sub object_KeyPress([Index As Integer,]KeyAscii As Integer),其中KeyAscii为字符ASCII码。当在文本框中输入字符a后,UCase函数把输入的字符转化为大写字符,Asc函数则把字符转化为ASCII码值。String函数则产生6个同样的字符A。

第9题:

在窗体上画-个命令按钮,然后编写如下事件过程:

Private Sub Command1_Click()

Dim I,Num

Randomize

Do

For I=1 To 1000

Num=Int(Rnd*100)

Print Num;

Select Case Num

Case 12

Exit For

Case 58

Exit Do

Case 65,68,92

End

End Select

Next I

Loop

End Sub

上述事件过程执行后,下列描述中正确的是( )。

A.Do循环执行的次数为1000次

B.在For循环中产生的随机数小于或等于100

C.当所产生的随机数为12时结束所有循环

D.当所产生的随机数为65、68或92时窗体关闭、程序结束

参考答案:D

程序Do循环中嵌套了For循环,Do循环没有设置结束条件,而是在For循环体中的Select语句中设置了退出Do循环和For循环及结束程序的分支,因此Do 循环的次数无法确定。随机函数Rnd产生[0,1)之间的-个数,包括0但不包含1,因此Rnd * 100的范围是大于等于0小于100。随机数为65、68或92时结束程序关闭窗体,为58时退出Do循环,为12时退出For循环进入下-次Do循环。

第10题:

用Line Input语句从顺序文件读出数据时,每次读出-行数据。所谓-行是指遇到( )分隔符,即认为-行的结束。

A.文件结束符

B.回车符

C.空格

D.Tab字符

参考答案:B

本题考查行结束标志。文件中用EOF测试是否到达末尾;而用“回车符”确定是否结束-行。

第11题:

数据独立性是数据库技术的重要特点之-。所谓数据独立性是指( )。

A.数据与程序独立存放

B.不同的数据被存放在不同的文件中

C.不同的数据只能被对应的应用程序所使用

D.以上三种说法都不对

参考答案:D

数据独立性是数据与程序间的互不依赖性,即数据库中数据独立于应用程序而不依赖于应用程序。所以选项A),选项B)和选项C)都不正确。

第12题:

若已把-个命令按钮的Default属性设置为True,则下面可导致按钮的Click 事件过程被调用的操作是( )。

A.用鼠标右键单击此按钮

B.按键盘上的Esc键

C.按键盘上的回车键

D.用鼠标右键双击此按钮

参考答案:C

当命令按钮的Default属性值为True时,程序运行,按回车键和单击该命令按钮-样都会触发按钮的Click事件;当命令按钮的Cancel属性值为True时,程序运行,按Esc键和单击该命令按钮都会触发按钮的Click事件。故选C。

第13题:

在窗体上画-个通用对话框,其名称为CommonDialog1,则下列与CommonDialog1.ShowOpen方法等效的语句是( )。

https://www.360docs.net/doc/dc16273324.html,monDialog1.Action=1

https://www.360docs.net/doc/dc16273324.html,monDialog1.Action=2

https://www.360docs.net/doc/dc16273324.html,monDialog1.Action=3

https://www.360docs.net/doc/dc16273324.html,monDialog1.Action=4

参考答案:A

通用对话框的属性Action=1与ShowOpen方法等效,而Action=2则与ShowSave 等效。

第14题:

下面不属于对象基本特点的是

A.标识唯-性

B.可复用性

C.多态性

D.封装性

参考答案:B

可知B选项正确。

第15题:

假定有以下通用过程:

Function Fun(n As Integer)As Integer

X=n * n

Fun=x一11

End Function

在窗体上画一个命令按钮,其名称为Command1,然后编写如下事件过程:

Private Sub Command1_Click()

Dim i As Integer

For i=1 To 2

y=Fun(i)

Print y;

Next i

End Sub

程序运行后,单击命令按钮,在窗体上显示的内容是( )。

A.1 3

B.10 8

C.一10 —7

D.0 5

参考答案:C

i=1时,执行fun(i),返回值为一10,i=2时,执行fun(i),即fun(2),返回值为2*2—11=一7。因此程序会输出一10和一7。

第16题:

工程文件中包含一个模块文件和一个窗体文件。模块文件的程序代码是:Public X As Integer

Private Y As Integer

窗体文件的程序代码是:

Dim a As Integer

Private Sub Form_Load()

Dim b As Integer

a=2:b=3:x=10:y=20

End Sub

Private Sub Command1_Click()

a=a+5:b=b+5:x:x+5:y=y+5

Print a;b;x;y

End Sub

运行程序,单击窗体上的命令按钮,则在窗体上显示的是( )。

A.5 5 15 5

B.7 5 15 25

C.7 8 15 5

D.7 5 15 5

参考答案:D

程序在模块文件中定义x为整型全局变量,在整个工程中都起作用,而y定义为整型私有变量,只能在本模块文件中起作用。在窗体文件中变量a在本窗体文本中起作用,窗体加载事件中定义的变量b和没有声明的变量y,只在本事件过程起作用。程序窗体加载时,对后边有影响的变量值为a为2,x为10,没有指定初值的变量值默认为0,因此单击命令按钮后,a=a+5=7,b=b+5=5,x=x+5=15,y=y+5=5,结果输出7 5 15 5。

第17题:

在窗体上画一个名称为Command1的命令按钮,再画两个名称分别为Label1、Label2的标签,然后编写如下程序代码:

Private X As Integer

Private Sub Command1_Click()

X=5:Y=3

Call proc(X,Y)

Label1.Caption=X

Laebel2.Caption=Y

End Sub

Private Sub proc(a As Integer,ByVal b As Integer)

X=a * a

Y=b+b

End Sub

程序运行后,单击命令按钮,则两个标签中显示的内容分别是

( )。

A.25和3

B.5和3

C.25和6

D.5和6

参考答案:A

虽然在过程proc中参数a默认为按地址传递,参数b指定了ByVal(按值)方式传递,但过程中并没有对a,b的值改变,只对变量X和Y进行了赋值,而X是在窗体模块中起作用的模块变量,而变量Y在proc过程中没有声明,要整个模块中也没有声明,说明它是一个局部变量,只在本过程中起作用。因此,在proe 过程中X=a*a=5*5=25,会使按钮单击事件中的变量x值变为25,而按钮单击事件过程中的变量Y不受影响,仍是原来的值3。因此两个标签上会分别显示25和3。

第18题:

窗体上有单选钮和列表框控件。单击名称为Option1、标题为“国家”的单选钮,向列表框中添加国家名称,如下图所示。

Option1的单击事件过程如下:

Private Sub Option1_Click()

Dim arr

arr=Array("中国","日本","德国","美国","澳大利亚")

List1.Clear

For i=0 To Ubound(art)

List1.AddItem arr(i)

Next

End Sub

以下关于上述代码的叙述中,正确的是( )。

A.程序有错,没有声明数组的维数及上下界

B.只有一维数组才能使用Array为数组赋初值

C.For循环的终值应为ListCount一1

D.For循环的初值应为1

参考答案:B

程序没有错误。数组变量定义时可以不用声明上下界。List控件列表项的索引从0开始。Array函数只适用于一组数组,只能对一维数组进行初始化,不能对二维数组或多维数组进行初始化。因此叙述正确的是B选项。

第19题:

在窗体上画一个名称为Text1的文本框和一个名称为Command1的命令按钮,然后编写如下事件过程:

Private Sub Command1_Click()

Dim array1(10,10)As Integer

Dim i As Integer,j As Integer

For i=1 To 3

For i=2 To 4

array1(i,j)=i+j

Next j

Next i

Text1.Text=array1(2,3)+array1(3,4)

End Sub

程序运行后,单击命令按钮,在文本框中显示的值是( )。

A.15

B.14

C.13

D.12

参考答案:D

程序中通过For循环为数组中部分元素赋值,没有赋值的元素值将默认为0。循环中i-2,j=3时,array1(i,j)=i+j,即array1(2,3)=5,i=3,j=4时,array1(3,4)=3+4,即array1(3,4)=7。5+7=12,因此程序文本框中显示值是12。

第20题:

可以产生30~50(含30和50)之间的随机整数的表达式是( )。

A.Int(Rnd*21+30)

B.Int(Rnd*20+30)

C.Int(Rnd*50一Rnd*30)

D.Int(Rnd*30+50)

参考答案:A

因为Rnd函数产生的随机数范围是大于等于0而小于1。要产生30~50(含30和50)之间的随机整数,可先产生0~(50—30),即0~20之间的随机整数,然后在这个基础上再加上30。Rnd*20生成0~20之间的随机数中不包括20,所以要用Int(Rnd*21)可产生0~20之间的随机整数,然后加上30,综合起来就是Int(Rnd*21+30),故A选项正确。

第21题:

下列叙述中正确的是( )。

A.有一个以上根结点的数据结构不一定是非线性结构

B.只有一个根结点的数据结构不一定是线性结构

C.循环链表是非线性结构

D.双向链表是非线性结构

参考答案:B

线性结构应满足:有且只有一个根结点与每个结点最多有一个前件,也最多有一个后件,所以B正确。所以有一个以上根结点的数据结构一定是非线性结构,所以A错误。循环链表和双向链表都是线性结构的数据结构。

第22题:

以下能对正实数d的第3位小数四舍五入的表达式是

A.0.01 * Int(d + 0.005)

B.0.01 * Int(100 * (d + 0.005))

C.0.01 * Int(100 * (d + 0.05))

D.0.01 * Int(d + 0.05)

参考答案:B

Int函数,返回的是不大于该数的-个整数。d+0.005,是让第三位小数进位,达到四舍五入,再乘100,放大100倍,保留小数位,取整后乘0.01还原为原数。如:5.333+0.005=5.338,乘100后为533.8,取整后为533,乘0.01后还原为5.33。

第23题:

设有窗体的Form_MouseMove事件过程如下:

Private Sub Form_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single)

If(Button And 3)=3 Then

Print "检查按键"

End If

End Sub

关于上述过程,以下叙述中正确的是( )。

A.按下鼠标左键时,在窗体上显示"检查按键"

B.按下鼠标右键时,在窗体上显示"检查按键"

C.同时按下鼠标左、右键时,在窗体上显示"检查按键"

D.不论做何种操作,窗体上都不会显示

参考答案:C

本题中当Button值为011时,或111时,(Button And 3)=3,条件才

成立,窗体上显示“检查按键”。这说明只要同时按下鼠标的左右键时,在窗体上就是显示“检查按键”。故选C。

第24题:

如果在窗体模块中所有程序代码的前面有语句:Dim x,则x是( )。

A.全局变量

B.局部变量

C.静态变量

D.窗体级变量

参考答案:D

在窗体所有代码前定义的变量是窗体级变量,在整个窗体模块的过程中都能引用。

第25题:

有如下的-个函数过程:

Function fn(ByVal num As Long)

Dim k As Long

k=1:hum=Abs(num)

Do While sum

k=k*(num Mod 10)

num=hum\10

Loop

fn=k

End Function

通过以下事件过程调用该函数,程序运行后,在输入对话框中输入数字“123”,则运行结果为( )。

Private Sub Commandl Click()

Dim n As Long

Dim rAs Long

n=InpuiBo

A.12

B.6

C.3

D.l

参考答案:B

本题考查函数功能分析。定义函数过程fn时,在参数前加上ByVal表明参数为传值调用。函数fn的主要功能为取出sum的每-位,进行累计相乘,然后返回结果。

第26题:

软件需求分析阶段的工作,可以分为四个方面:需求获取、编写需求规格说明书、需求评审和( )。

A.阶段性报告

B.需求分析

C.需求总结

D.都不正确

参考答案:B

软件需求分析阶段的工作,可以概括为四个方面:需求获取、需求分析、编写需求规格说明书和需求评审。需求获取的目的是确定对目标系统的各方面需求。涉及到的主要任务是建立获取用户需求的方法框架,并支持和监控需求获取的过程。需求分析是对获取的需求进行分析和综合,最终给出系统的解决方案和目标系统的逻辑模型。编写需求规格说明书作为需求分析的阶段成果,可以为用户、分析人员和设计人员之间的交流提供方便,可以直接支持目标软件系统的确认,又可以作为控制软件开发进程的依据。需求评审是对需求分析阶段的工作进行复审,验证需求文档的-致性、可行性、完整性和有效性.

第27题:

设-个工程文件包含多个窗体及标准模块,以下叙述中错误的是

A.如果工程中有Sub Main过程,则程序-定首先执行该过程

B.不能把标准模块设置为启动模块

C.用Hide方法只是隐藏窗体,不能从内存中清除该窗体

D.Show方法用于显示-个窗体

参考答案:A

默认情况下,整个应用程序是从设计时的第-个窗口开始执行的,如果先执行Sub Main过程,必须通过手动方式设置,故A项表述错误。不能把标准模块设置为启动模块,故B项表述正确。Hide方法功能是将窗体隐藏起来,但窗体仍在内存中,还可以引用窗体中的控件及各种属性,故选项C表述正确;Show方法功能是将窗体装入内存并显示出来,故D项表述正确。

第28题:

窗体上有1个名称为List1的列表框,1个名称为Text1的文本框。编写如下

程序代码:

Private Sub Form_Load()

List1.Addhem"花卉"

List1.Addhem"绿植"

List1.Addhem"盆景"

Text1.Text=""

End Sub

Private Sub List1_DblClick()

Print List1+Text1.Text

End Sub

程序运行时,在文本框中输入“摆放”,然后双击列表框中的“绿

植”,输出结果为( )。

A.摆放

B.摆放绿植

C.绿植

D.绿植摆放

参考答案:D

使用列表框的AddItem方法,可以向列表框中添加列表项,本题的Form_Load事件过程依次向列表框List1中添加了3个值,列表项的值分别为:List1(0)=“花卉”;List(1)=“绿植”;List(2)=“盆景”(列表项的索引值从0开始)。在List1_DblClick事件中打印输出表达式“List1+Testl Text”的结果.当双击列表框List1中的“绿植”表项时,List1得到的值为“绿植”.Text1.Text为输入的字符串“摆放”,故最终输出结果为“绿植摆放”,D选项正确。本题选择D选项。

第29题:

语句Dim Arr(一2 To 4).As Integer所定义的数组的元素个数为( )。

A.7个

B.6个

C.5个

D.4个

参考答案:A

本题是定义了一个一维数组,下标是一2to 4,所以数组元素的个数是4一(一2)+1=7,故选A。

第30题:

执行语句Dim X,Y As Integer后,( )。

A.X和Y均被定义为整型变量

B.X和Y均被定义为变体类型变量

C.X被定义为整型变量,Y被定义为变体类型变量

D.X被定义为变体类型变量,Y被定义为整型变量

参考答案:D

声明变量时可以同时声明多个变量,但要分别说明每个变量的数据类型。如果定义变量时不说明数据类型.默认是Variant变体类型变量。本题中用Dim 同时定义了两个变量X、Y,变量X没说明数据类型,所以是Variant型变量,Y 是整型变量。故选D选项正确。

第31题:

以下程序段的功能是( )。

x=8

.6

y=Int(x+0

.5)

Print y

A.输出y的绝对值

B.实现x的四舍五入

C.实现x的绝对值

D.实现y的四舍五入

参考答案:B

本题考查函数Int的功能,Int(x)的作用是取不大于x的最小的整数,可以实现数据的四舍五入。

第32题:

在窗体上画-个命令按钮和-个文本框,其名称分别为Command1和Text1,把文本框的Text属性设置为空白,然后编写如下事件过程:

Private Sub Command1_Click()

a=InputBox("Enter an integer")

b=Text1.Text

Text1.Text=b+a

End Sub

程序运行后,在文本框中输入456,然后单击命令按钮,在输入对话框中输入123,则文本框中显示的内容是( )。

A.579

B.123

C.456123

D.456

参考答案:C

默认情况下,InputBox的返回值是-个字符串,因此程序中a="123",b="456",b+a="456"+"123"="456123"。因此C选项正确。另外,使用字符连接运算符"+"时,如果连接的是字符串和数值,可根据返回值类型判断,若返回值类型为字符串,则它将数值转换成字符串后与另-字符串连接成新字符串返回;若返回值类型为数值,则它要求字符串中只能包含数字,而不能有其他字符,否则报"类型不匹配"的错误。

第33题:

-个兴趣班可以招收多名学生,而-个学生可以参加多个兴趣班。则实体兴趣班和实体学生之间的联系是

A.1:1联系

B.1:m联系

C.m:1联系

D.m:n联系

参考答案:D

-般来说,实体集之间必须通过联系来建立联接关系,分为3类:-对-联系(1:1)、-对多联系(1:m)、多对多联系(m:n)。多个兴趣班与多个学生的关系为m:n联系,D选项正确。

第34题:

设x是整型变量,与函数IIf(x>0,-x,x)有相同结果的代数式是( )。

A.|x|

B.-|x|

C.x

D.-x

参考答案:B

IIF函数是条件函数,本题的含义是如果x>0条件成立,即x为正数,就返回-x,即x的负数,否则返回x(它本身),两种情况都是返回负数。根据这-点,选项B符合要求。故B选项正确。

第35题:

下面有关标准模块的叙述中,错误的是( )。

A.标准模块不完全由代码组成,还可以有窗体

B.标准模块中的Private过程不能被工程中的其他模块调用

C.标准模块的文件扩展名为.bas

D.标准模块中的全局变量可以被工程中的任何模块引用

参考答案:A

标准模块中只包含其他窗体模块中公用的一些变量、过程等代码,不包括窗体。故选项A错误。标准模块中用Private声明的过程属于私有过程,只能被它所在的模块中的其他过程调用,不能被工程中其他模块调用,用Public声明的全局变量属于公用变量,可以被工程中的任何模块引用。标准模块的文件扩展名是.bas。

第36题:

在过程定义中,Private表示( )。

A.此过程可以被其他过程调用

B.此过程不可以被任何其他过程调用

C.此过程只可以被本工程中的其他过程调用

D.此过程只可以被本窗体模块中的其他过程调用

参考答案:D

本题考查Private的含义。Pfivate表示了过程或者变量的访问权限,仅局限于定义的窗体和模块,也就是此过程只可以被本窗体模块中的其他过程调用。

第37题:

下列数据结构中,能够按照“先进后出”原则存取数据的是( )。

A.循环队列

B.栈

C.队列

D.二叉树

参考答案:B

栈是按先进后出的原则组织数据的。队列是先进先出的原则组织数据。

第38题:

在面向对象方法中,不属于"对象"基本特点的是( )。

A.-致性

B.分类性

C.多态性

D.标识唯-性

参考答案:A

对象有如下-些基本特点:标识唯-性、分类性、多态性、封装性、模块独立性好。所以选择A。

第39题:

在窗体上画-个名称为Dir1的目录列表框,-个名称为Filel的文件列表框。当改变当前目录时,文件列表框中同步显示目录列表框中当前被打开目录中的文件,则所使用的事件过程是( )。

A.Private Sub Dir1_Change() File1.Path=Dir1.Path End Sub

B.Private Sub Dir1_Change() File1.Path=Dir1.Drive End Sub

C.Private Sub Dir1_Change() Dir1.Path=File1.Path End Sub

D.Private Sub Dir1_Change() File1.Drive=Dir1.Path End Sub

参考答案:A

在实际应用中,驱动器列表框、目录列表框和文件列表框往往需要同步操作,这可以通过Path属性的改变引发Change事件来实现,A选项的事件过程使窗体上的目录列表框Dir1和文件列表框Filel产生同步。因为目录列表框Path属性的改变将产生Change事件,所以在Dir1_Change事件过程中,把Dir1.Path赋给Filel.Path,就可以产生同步效果。故本题A选项符合题意。本题选择A选项。

第40题:

以下不属于Visual Basic数据文件的是

A.顺序文件

B.随机文件

C.数据库文件

D.二进制文件

参考答案:C

可以从不同的角度对文件进行分类:按照文件的内容,可分成程序文件和数据文件;按照文件存储信息的形式,可分为ASCII文件和二进制文件;按照文件的组织形式,可分成顺序文件和随机文件;按照存储介质,又可以分为光盘文件、磁盘文件、磁带文件、打印文件等。

基本操作题

第41题:

(1)在名称为Form1的窗体上添加一个标签(名称为Label1,标题为空白,BorderStyle属性为1,Visible属性为False)、一个文本框(名称为Text1,Text 属性初始内容为空)和一个命令按钮(名称为Command1,标题为“显示”),如图1所示。然后编写命令按钮的Click事件过程。程序运行后,在文本框中输入“计算机等级考试”,然后单击命令按钮,则文本框消失,并在标签内显示文本框中的内容。程序运行后的窗体如图2所示。要求程序中不得使用任何变量。

注意:存盘时必须放在考生文件夹下,工程文件名保存为sjt1.vbp,窗体文件名保存为sjt1.frm。(2)在名称为Form1的窗体上添加一个文本框(名称为Text1)和一个水平滚动条(名称为HScroll1),如图1所示。在属性窗口中对滚动设置如下属性:

编写适当的事件过程。程序运行后,通过改变滚动条上的刻度值,则可扩大或缩小文本框的高度,并使得文本框的宽度始终是其高度的1.2倍。程序运行后的窗体如图2所示。要求程序中不得使用任何变量。

注意:存盘时必须存放在考生文件夹下,工程文件名保存为

sjt2.vbp,窗体文件名保存为sjt2.frm。______

参考答案:

详细解答:

(1)文本框的Text属性用于设置文本框中显示的文本。标签的Caption属性可设置其标题。Visible属性用于设置控件或菜单项在程序运行时是否可见。

(2)通过调整滚动条滑块的位置即可改变其Value属性的值,滚动条的Max和Min 属性为滚动条所能表示的最大值和最小值,LargeChange属性用于设置当单击滑块与两侧箭头间区域时Value属性值的改变量,SmallChange属性用于设置当单击滚动条两侧箭头时Value属性值的改变量。当改变滚动条滑块位置后将触发其Change事件。文本框的高度和宽度分别由其Height属性值和Width属性值设定。

简单应用题

第42题:

(1)考生文件夹下有-个工程文什sjt3.vbp。程序的功能是:通过键判向文本框中输入数字,如果输入的是非数字字符,则提示输入错误,且文本框中不显示输入的字符。单击名称为Command1、标题为“添加”的命令按钮,则将文本框中的数字添加到名称为Combo1的组合框中。在给出的窗体文件中已经添加了全部控件,但程序不完整。要求去掉程序中的注释符,把程序中的?改为正确的内容。

注意:不能修改程序中的其他部分和其他控件的属性。最后把修改后的文件按原文件名存盘。

(2)在考生文件夹下有-个工程文件sjt4.vbp。该程序的功能是计算M!+(M+1)!+(M+2)!+…+N!之和。窗体上有名称分别为Text1、Text2的两个文本框,用于接收输入的M和N(要求M<N)。单击名称为Command1、标题为“计算”的命令按钮,计算M!+(M+1)!+(M+2)!+…+N!的值,并将计算结果显示在标签lblResult中。

在给出的窗体文件中已经有了全部控件,但程序不完整,要求去掉程序中的注释符,把程序中的?改为正确的内容。

注意:不能修改程序的其他部分和控件属性。最后把修改后的文件按原文件名存盘。______

参考答案:

步骤1:打开本题工程文件。步骤2:打J开代码编辑窗口,去掉程序中的注释符“′”,将问号改为正确的内容。Private Sub Command1 Click() Comb01.AddItem Text1将Text1′中的内容加入Combo1中Text1.Text=""′同时将Text1内容清除End Sub Private Sub Text1 KeyPress(KeyAscii As Integer) If KeyAscii>57 or

KeyAscii<48 Then ′数字的Ascii码值下界MsgBox"请输入数

字!" KeyAscii=0′清空End If End Sub 步骤3:调

试并运行程序,关闭程序后按题目要求存盘。(2)步骤1:打开本题工程

文件。步骤2:打开代码编辑窗口,去掉程序中的注释符,将问号改为

正确的内容。Private Sub Commandl Click() DimmAs Integer Dim n As Integer Dim s As Long Dim i As Integer m=Val (Text1.Text) ′将文本框中的字符转换成数值型

n=Va1(Text2.Text1 s=0 For i=m To n—m t=f(i)调用函

数得到N的阶乘s=s+t Next iblResult.Caption=s End Sub Private Function f(ByRef x As Integer)As Long′ByRef为传

址传递D1m t As Long t=1 For i=1 To x′实现对数值进

行阶乘运算t=t*i Next f=t′返回计算结果End FunctiOn 步骤3:调试并运行程序,关闭程序后按题目要求存盘。

详细解答:

(1)单击命令按钮,运用组合框的List属性将文本框中的数字添加到组合框中,通过ASCII码来判断输入的是否为数字字符。(2)Function f()过程

函数用于实现对数值阶乘的运算,Val()函数实现将文本框中的字符转换成数值型,通过循环调用过程函数实现对表达式结果的累加。

综合应用题

第43题:

注意:下面出现的“考生文件夹”均为%USER%。

在考生文件夹下有一个工程文件sjt5.vbp,考生文件夹下in5.dat文

件中保存有一篇英文短文。程序运行时,单击“读取并统计”按钮,则按行读

取in5.dat文件的内容,并显示到文本框Text1中,同时调用Calculate过程

统计每个英文字母(不区分大小写)及其出现的次数,并按字母顺序保存到二维

数组data中,统计结束后,按字母顺序将统计结果显示到列表框List1中(字

母用小写表示,且不含文中未出现的字母);单击“保存”按钮,则保存结果。“读取并统计”和“保存”按钮的cliek事件过程已经给出,请编写

Calculate过程中的代码以实现上述功能。程序运行界面示意图如图所示。

注意:考生不得修改窗体文件中已经存在的控件和程序,在结束程序运

行之前,必须进行“读取并统计”,且必须单击“保存”按钮保存结果,否则

无成绩。最后,程序按原文件名存盘。

______

参考答案:

步骤1:打开本题项目工程。步骤2:打开代码编辑窗口,填入相应

的代码以实现题目的功能。参考答案Private Sub Calculate(s As

String,d()As Variant) Dim ch As String Dim i As String For i=1 To Len(s) Ch=Asc(LCase(Mid(s,i,1))) If ch >= 97 And ch< =122 Then d(ch-96,1)=Chr(ch) d(ch-96,2)= d(ch-96,2)+1 End If Next i End Sub 步骤3:调试并运行程序,关闭程序后按题目要求存盘。

详细解答:

Calculate过程中利用For循环逐个取出文本字符串s中的字符,然后将所有字符使用LCase函数转换为小写,小写字母的ASCII码取值范围为65到90之间,再将每个字母及其出现的次数存储到二维数组d中。

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