南京2014~2015学年度第二学期期末复习试卷
2014-2015学年度第二学期七年级英语期末复习基础知识过关测试

A)根据所给提示及句意,写出句中所缺单词,使句子完整正确。
51. We should try not to eat the food with . /æt/. / l D kt/53. There is a dog lying in the (角落) of the room.54. The door is wide enough for three people to go at the same time. (通过)55. We were all after we heard what he said(激动的).56. Why not money for children in need? (募集)57. You can’t leave the lights when you leave the house. (开)58. It’s dangerous for the children to play with .(火柴)59. My cat is very lazy. It can sleep . (任何地方)B) 根据句意,用括号中所给词的适当形式填空。
60. When my cat is full, he always likes (lie) on the bed.61. She (weigh) twenty-five kilos when she was eight.62. When I walked past, I saw her (build) camps out of sticks.63. One of the (policeman) dogs is searching the forest for something important.64. Look at Mrs. Lin. Is she saying to (she)?65. He tried his best (carry) the boy to the safe place.66. I don’t like the train. It is hot, (noise) and dirty.67. She always asks her son (not be) late for school.68. You should (brush) your teeth twice a day.C) 根据括号中的要求,完成下列句子。
江苏省南京市第十八中学2014-2015学年七年级上学期第二阶段学业质量监测语文试题

江苏省南京市第十八中学2014-2015学年七年级语文上学期第二阶段学业质量监测试题提醒:本试卷共4页,满分100分(含3分书写分),考试时间100分钟。
请用黑色水笔书写,所有答案一律写在答题纸上。
一、积累与运用(共27分)1.用课文原句填空。
(10分)(1)乱花渐欲迷人眼,▲。
(白居易《钱塘湖春行》)(2)争渡,争渡,▲。
(李清照《如梦令》)(3) ▲,江春入旧年。
(王湾《次北固山下》)(4) ▲,夜泊秦淮近酒家。
(杜牧《泊秦淮》)(5)万籁此都寂,▲。
(常建《题破山寺后禅院》)(6)无可奈何花落去,▲。
(晏殊《浣溪沙》)(7) ▲,赚得行人空欢喜。
(杨万里《过松源晨炊漆公店》)(8)是故学然后知不足,▲?(《虽有佳肴》)(9)“▲,▲。
”孔子的名言告诉我们,立志对于一个人的成长具有极为重要的意义。
(《<论语>十二章》)2.下列各组加点字注音有误的一组是(▲)。
(2分)A.嫩.芽(nân)分歧.( qí)沉.寂(chãn )洗耳恭.听(gōng)B.潜行..(chãng)骸骨 (hái ) 骇.(hài)人听闻..(qiǎn)澄清C.啜泣(chuî)憔悴.(cuì)伫立..(zhù)忍俊不禁.(jīn)D.捶.打(chuí)葱茏(lïng)顷刻..(qǐng)头晕.目眩(yūn)3.下列词语书写都正确...的一项是(▲)。
(2分)A.训诫覆盖澄澈喜出忘外B.缭亮收敛遗撼海枯石烂C.隐秘卑微妥当花团锦簇D.宽恕威摄尴尬一丝不苟4.下列句子中加点词语运用不恰当...的一项是(▲)。
(3分)A. 自习课上,我们班的数学尖子张明同学正在专心致志....地做数学题。
B.高铁维修工每天一丝不苟....地巡查铁轨安全,绝不放过任何一处隐患。
C.有不少人花太多时间陪伴自己的宠物,每天与它们形影不离....,这种现象令人担忧。
江苏省南京市2014-2015学年高一上学期期末学情调研测试语文试题 Word版含答案

南京市2014—2015学年度第一学期期末学情调研测试卷高一语文注意事项:1.本试卷共100分,考试用时120分钟。
2.答题前考生务必将学校、姓名、班级、学号填涂在答题纸的指定区域。
每题答案写在答题纸上对应题目的空格里或横线上。
考试结束,请将答题纸交回。
一、(12分)1.下面是某位同学的听课记录,请按要求完成题目。
(4分)①学习语文,要仔细揣摩教科书的编写意图。
②必修二教材呈现出强浓厚的人文气息,“珍爱生命”“和平的祈祷”,每个专题都围绕以特定的人文主题为中心组材。
③“殒落与升华”“后人之鉴”这些板块也是如此。
④同时,非常强调语文的工具性,板块文体相对单一,比如“永恒的瞬间”集中选应用文,“永远新的旧故事”则选小说。
⑤从文体特点入手,依“体”而学,细细品位,有利于我们更好地领悟作品的思想内涵。
(1)请找出并改正上面文段中的两个错别字。
(2分)①“▲”改为“▲”②“▲”改为“▲”(2)上面文段中有一个病句,请找出并修改。
(2分)下图分别是《红楼梦》《三国演义》的插图,任选一幅,指出所描绘的故事,并概述情节。
甲乙忌:▲示例二使:“人”一旦做了“吏”,往往爱使唤别人。
悟:▲二、(13分)阅读下面的文字,完成4—7题。
严寒持续了好几个星期,鸟儿很快地死去了。
田间与灌木篱下,横陈着田凫、椋鸟、画眉等数不清的腐鸟的血衣,鸟儿的肉已被隐秘的老饕吃净了。
突然间,一个清晨,变化出现了。
风刮到了南方,海上飘来了温暖和慰藉.。
午后,太阳露出了几星光亮,鸽子开始不间断地缓慢而笨拙.地发出咕咕的叫声。
这声音显得有些吃力,仿佛还没有从严冬的打击下缓过气来。
黄昏时,从河床的蔷薇棘丛中,开始传出野鸟微弱的啼鸣。
当大地还散落着厚厚的一层鸟的尸体的时候,它们怎么会突然歌唱起来呢?从夜色中浮起的隐约而清越的声音,使人惊讶。
当大地仍在束缚中时,那小小的清越之声已经在柔弱的空气中呼唤春天了。
它们的啼鸣,虽然含糊,若断若续,却把明快而萌发的声音抛向苍穹.。
2014-2015年高二第二学期统计1-6章期末复习试题

2014-2015年⾼⼆第⼆学期统计1-6章期末复习试题2014-2015年⾼⼆第⼆学期统计1-6章期末复习试题⼀.单选题:1. 构成总体,必须同时具备()。
A.总体性、数量性与同质性 B.总体性、同质性与差异性C.社会性、同质性与差异性 D.同质性、⼤量性与差异性2. 要了解某⼯业企业职⼯的⽂化⽔平,则总体单位是()。
A.该⼯业企业的全部职⼯ B.该⼯业企业的每⼀个职⼯C.该⼯业企业每⼀个职⼯的⽂化程度D.该企业全部职⼯的平均⽂化程度3. 下列属于品质标志的是()。
A.⾝⾼ B.⼯资 C.年龄 D.⽂化程度4.⼀个总体()。
A.只能有⼀个标志 B.可以有多个标志C.只能有⼀个指标 D.可以有多个指标5.调查单位的标志总是占总体标志总量绝⼤⽐重的统计调查是()A普查 B抽样调查 C重点调查 D典型调查6. 对()进⾏调查时,要规定资料的标准时点。
A时期现象 B时点现象 C调查现象 D可变现象7. 某企业成本计划降低6%,实际降低8.6%,则企业成本计划完成程度为()A.69.8%B.97.2%C.79.2%D.143.3%8. 动态数列中,各个指标数值可以相加的是()A时点数列 B时期数列或时点数列 C时期数列和时点数列 D时期数列9. 下列动态数列中属于时期数列的是()A职⼯⼈数数列 B总产值数列 C劳动⽣产率数列 D库存额数列10.在由三个指数所组成的指数体系中,两个因素指数的同度量因素通常()。
A.都固定在基期B.都固定在报告期C.⼀个固定在基期,⼀个固定在报告期D.采⽤基期和报告期交叉11.当质量指标的加权调和平均数指数采⽤特定权数时,计算结果与综合指数相同,其特定权数是()。
A.q1p1B.q0p1C.q1p0D.q0p012.狭义上的指数是指()A.反映价格变动的相对数;B.反映动态的各种相对数;C.个体指数;D.总指数13. 已知各期环⽐增长速度为12%、12.5%、13%和14%,则相应的定基增长速度的计算⽅法为()A、112%+112.5%+113%+114%B、112%×112.5%×113%×114%C、12%×12.5%×13%×14%-100%D、112%×112.5%×113%×114%-100%14. 平均发展速度是()A、定基发展速度的算术平均数B、环⽐发展速度的算术平均数C、环⽐发展速度的⼏何平均数D、增长速度加上100%15. 某⽉份甲⼯⼚的⼯⼈出勤率属于()A. 结构相对数B. 强度相对数C. ⽐例相对数D. 计划完成相对数16. 标准差与平均差的区别主要在于()A. 意义不同B. 计算结果不同C. 计算条件不同D. 对离差的数学处理⽅式不同17. 分⼦与分母不可互换计算的相对指标是( )A. 计划完成情况相对指标B. 动态相对指标C. 结构相对指标D. 强度相对指标E. ⽐较相对指标18. 变量数列中各组频率(以百分数表⽰)的总和应该()A ⼤于100%B ⼩于100%C 不等于100%19. 对于越⾼越好的现象按连续型变量分组,如第⼀组为75以下,第⼆组为75-85,第三组为85-95,第四组为95以上,则数据()A.85在第三组B.75在第⼀组C.95在第三组D.85在第⼆组20.按连续型变量分组,其末组为开⼝组,下限为2000。
人教版2014-2015学年度上期九年级英语期末复习考试题及答案

人教版2014—2015学年度上期九年级英语期末复习考试题注意:1.本试卷分为听力和笔试两部分。
听力20分,笔试80分,总分100分。
完成时间80分钟。
答 题 卡第一节 听句子,选出该句的最佳答语。
每个句子听两遍。
(共5小题,满分5分)( ) 1. A. No, thanks. I can do it myself. B. Yes, I am. C. Sure. I’ll be glad to.( ) 2. A. No. I went straight home. B. Yes, I’d love to. C. No. I’ll go to the barber’s.( ) 3. A. My pleasure. B. Never mind. C. It’s very kind of you.( ) 4. A. I ’ve no idea. B. No problem. C. It doesn’t matter.( ) 5. A. Yes, I will B. Very well done. C. Thanks. A cup of tea for me, please.第二节 听对话和问题,选择适当的选项。
每段对话听两遍。
(共5小题,每题1分,满分5分)( ) 6. What day is it today?A. It is Monday.B. It is Saturday.C. It is Sunday.( ) 7. How long has the man waited for the bus?A. 5 minutes.B. 30 minutes.C. 35 minutes.( ) 8. How often does Mr. Green go to see his parents?A. Twice a week.B. Tree times a year.C. Twice a month.( ) 9. What’s the date today?A. May 16thB. May 15thC. June 16th( ) 10. What did the man do last night?B. He went to see his friendC. He had a long talk with his friend.第三节听下面一段长对话,然后从每小题A,B,C 中选出能回答每个问题的正确答案。
平面直角坐标系 (1)

2014——2015第二学期初一数学期末复习第七章平面直角坐标系出卷人:施磊倩一、知识梳理有序数对(a,b)和(b,a)的意义______(相同或不同).2、平面直角坐标系:在平面内画两条互相_______、原点______的数轴,组成平面直角坐标系。
其中,水平的数轴为______或______,习惯上取______为正方向;竖直的数轴称为______或______,取______方向为正方向;两坐标轴的交点叫做平面直角坐标系的________,建立了平面直角坐标系的平面叫做坐标平面.3、特殊点的坐标:(1)坐标轴上的点:x轴上点的纵坐标为___,y轴上点的横坐标为___,原点的坐标是____.象限内点的坐标的符号特征是:第一象限(+,+),第二象限______,第三象限______,第四象限______.(2)平行于坐标轴的点:(1)平行于x轴的同一直线的点的坐标特征:_________________;(2)平行于y轴的同一直线的点的坐标特征:_________________. (3)对称点:(1)关于x轴对称的两个点的横坐标___________,纵坐标__________;(2)关于y轴对称的两个点的横坐标___________,纵坐标___________;(3)关于原点对称的两个点的横坐标___________,纵坐标.(4)平面直角坐标系各象限角平分线上的点的坐标:(1)第一、三象限角平分线上的点的坐标:横坐标和纵坐标__________;(2)第二、四象限角平分线上的点的坐标:横坐标和纵坐标__________。
4、坐标平面内点的距离(1)点P(x,y)到x轴的距离是_______;到y轴的距离是_______。
(2)已知点A(x1,y1) 、点B(x2,y2),若AB∥x轴,则AB=____________;若AB∥y轴,则AB=____________。
5、坐标平面内线段的中点:在平面直角坐标系中,以任意两点P(x1,y1)、Q(x2,y2)为端点的线段中点坐标为___________.6、用坐标表示地理位置的步骤:(1)建立____________,选择一个适当的参照点为___________,确定__________的正方向. (2)根据具体问题确定_________.(3)在坐标平面内画出这些点,写出各点的_______和各个地点的______.7、用坐标表示平移(1)在平面直角坐标系中,将点(x,y)向右(或左)平移a个单位长度,能够得到对应点(,)(或(,));将点(x,y)向上(或下)平移b个单位长度,能够得到对应点(,)(或(,)).(2)在平面直角坐标系内,如果把一个图形各个点的横坐标都加(或减去)一个正数a,相对应的新图形就是把原图形向_____(或向_____)平移_____个单位长度;如果把它各个点的纵坐标都加(或减去)一个正数a,相对应的新图形就是把原图形向_____(或向_____)平移_____个单位长度.二、基础训练1、初一(1)班64名同学站成8×8实行跑操训练,小敏是第2纵队的排头,记作(1,2),小娟是第5纵队的队尾,则小娟的位置应记作_______。
江苏省南京市玄武区八年级数学下学期期末试卷(含解析)苏科版

江苏省南京市玄武区八年级数学下学期期末试卷(含解析)苏科版一、选择题(本大题共6小题,每小题2分,共12分.在每小题所给出的四个选项中,恰有一项是符合题目要求的,请将正确选项前的字母代号填涂在答题卡相应位置上)1.下列图形中,既是轴对称图形又是中心对称图形的是()A.B.C.D.2.使分式有意义,则x的取值范围是()A.x≠1 B.x=1 C.x≤1 D.x≥13.下列说法中,正确的是()A.“打开电视,正在播放河南新闻节目”是必然事件B.某种彩票中奖概率为10%是指买十张一定有一张中奖C.神舟飞船发射前需要对零部件进行抽样调查D.了解某种节能灯的使用寿命适合抽样调查4.(若A(1,y1),B(2,y2)两点都在反比例函数y=的图象上,则y1与y2的大小关系是()A.y1<y2B.y1=y2 C.y1>y2D.无法确定5.下列各式计算正确的是()A. +=B.2﹣=C. =×D.÷=6.如图,P为正方形ABCD的对角线BD上任一点,过点P作PE⊥BC于点E,PF⊥CD于点F,连接EF.给出以下4个结论:①△FPD是等腰直角三角形;②AP=EF;③AD=PD;④∠PFE=∠BAP.其中,所有正确的结论是()A.①② B.①④ C.①②④D.①③④二、填空题(本大题共10小题,每小题2分,共20分.不需写出解答过程,请把答案直接填写在答题卡相应位置上)7.要使有意义,则x的取值范围是______.8.若分式的值为零,则x=______.9.计算﹣的结果是______.10.已知反比例函数的图象经过点(m,2)和(﹣2,3),则m的值为______.11.如图,转盘被平均分成8个区域,每个区域分别标注数字1、2、3,4、5、6、7、8,任意转动转盘一次,当转盘停止转动时,对于下列事件:①指针落在标有5的区域;②指针落在标有10的区域;③指针落在标有奇数的区域;④指针落在能被3整除的区域.其中,发生可能性最大的事件是______.(填写序号)12.已知菱形的面积是5,它的两条对角线的长分别为x、y(x>0,y>0),则y与x的函数表达式为______.13.如图,▱ABCD的对角线AC,BD相交于点O,点E,F分别是线段AO,BO的中点,若AC+BD=24cm,△OAB的周长是18cm,则EF=______cm.14.已知等式=﹣,对任意正整数n都成立.计算:++++…+=______.15.如图,矩形OABC的顶点A、C的坐标分别为(4,0)、(0,2),对角线的交点为P,反比例函数y=(k>0)的图象经过点P,与边BA、BC分别交于点D、E,连接OD、OE、DE,则△ODE的面积为______.16.设函数y=x﹣2与y=的图象的交点坐标为(m,n),则﹣的值为______.三、解答题(本大题共11小题,共88分.请在答题卡指定区域内作答,解答时应写出文字说明、证明过程或演算步骤)17.解分式方程: =.18.计算:(1)•(a≥0);(2)×(2﹣3).19.先化简[﹣]÷,然后从﹣1,0,1,2中选取一个你认为合适的数作为x的值代入求值.20.在一个不透明的盒子里装有黑、白两种颜色的球共40只,这些球除颜色外其余完全相同.小颖做摸球实验,搅匀后,她从盒子里随机摸出一只球记下颜色后,再把球放回盒子中,不断重复上述过程,下表是实验中的一组统计数据:摸球的次数n 100 200 300 500 800 1000 3000摸到白球的次数m 65 124 178 302 481 599 1803摸到白球的频率0.65 0.62 0.593 0.604 0.601 0.599 0.601 (1)请估计:当n很大时,摸到白球的频率将会接近______;(精确到0.1)(2)若从盒子里随机摸出一只球,则摸到白球的概率的估计值为______;(3)试估算盒子里黑、白两种颜色的球各有多少只?21.某校为了开设武术、舞蹈、剪纸等三项活动课程以提升学生的体艺素养,随机抽取了部分学生对这三项活动的兴趣情况进行了调查(每人从中只能选一项),并将调查结果绘制成如图两幅统计图,请你结合图中信息解答问题.(1)将条形统计图补充完整;(2)本次抽样调查的样本容量是______;(3)已知该校有1200名学生,请你根据样本估计全校学生中喜欢剪纸的人数.22.小明到眼镜店调查了近视眼镜镜片的度数和镜片焦距的关系,发现镜片的度数y(度)是镜片焦距x(厘米)(x>0)的反比例函数,调查数据如表:眼镜片度数y(度)400 625 800 1000 1250 …镜片焦距x(厘米)25 16 12.5 10 8 …(1)求y与x的函数表达式;(2)若小明所戴近视眼镜镜片的度数为500度,求该镜片的焦距.23.著名数学家斐波那契曾研究一列数,被称为斐波那契数列(按照一定顺序排列的一列数称为数列),这个数列的第n个数为 [()n﹣()n](n为正整数),例如这个数列的第8个数可以表示为 [()8﹣()8].根据以上材料,写出并计算:(1)这个数列的第1个数;(2)这个数列的第2个数.24.如图,在▱ABCD中,∠BAD的平分线交BC于点E,∠ABC的平分线交AD于点F.(1)求证:四边形ABEF是菱形;(2)若AB=5,BF=8,AD=,则▱ABCD的面积是______.25.“五一”期间,某商铺经营某种旅游纪念品.该商铺第一次批发购进该纪念品共花费3 000元,很快全部售完.接着,该商铺第二次批发购进该纪念品共花费9000元.已知第二次所购进该纪念品的数量是第一次的2倍还多300个,第二次的进价比第一次的进价提高了20%.(1)求第一次购进该纪念品的进价是多少元?(2)若该纪念品的两次售价均为9元/个,两次所购纪念品全部售完后,求该商铺两次共盈利多少元?26.如图,在平面直角坐标系中,点B是反比例函数y=的图象上任意一点,将点B绕原点O顺时针方向旋转90°到点A.(1)若点A的坐标为(4,2).①求k的值;②在反比例函数y=的图象上是否存在一点P,使得△AOP是等腰三角形且∠AOP是顶角,若存在,写出点P的坐标;若不存在,请说明理由.(2)当k=﹣1,点B在反比例函数y=的图象上运动时,判断点A在怎样的图象上运动?并写出表达式.27.(1)方法回顾在学习三角形中位线时,为了探索三角形中位线的性质,思路如下:第一步添加辅助线:如图1,在△ABC中,延长DE (D、E分别是AB、AC的中点)到点F,使得EF=DE,连接CF;第二步证明△ADE≌△CFE,再证四边形DBCF是平行四边形,从而得到DE∥BC,DE=BC.(2)问题解决如图2,在正方形ABCD中,E为AD的中点,G、F分别为AB、CD边上的点,若AG=2,DF=3,∠GEF=90°,求GF的长.(3)拓展研究如图3,在四边形ABCD中,∠A=105°,∠D=120°,E为AD的中点,G、F分别为AB、CD 边上的点,若AG=3,DF=2,∠GEF=90°,求GF的长.2015-2016学年江苏省南京市玄武区八年级(下)期末数学试卷参考答案与试题解析一、选择题(本大题共6小题,每小题2分,共12分.在每小题所给出的四个选项中,恰有一项是符合题目要求的,请将正确选项前的字母代号填涂在答题卡相应位置上)1.下列图形中,既是轴对称图形又是中心对称图形的是()A.B.C.D.【考点】中心对称图形;轴对称图形.【分析】根据轴对称图形与中心对称图形的概念求解.【解答】解:A、是轴对称图形,不是中心对称图形;B、是轴对称图形,也是中心对称图形;C、不是轴对称图形,是中心对称图形;D、是轴对称图形,不是中心对称图形.故选B.【点评】本题考查了中心对称图形与轴对称图形的知识.轴对称图形的关键是寻找对称轴,图形两部分折叠后可重合,中心对称图形是要寻找对称中心,旋转180度后两部分重合.2.使分式有意义,则x的取值范围是()A.x≠1 B.x=1 C.x≤1 D.x≥1【考点】分式有意义的条件.【分析】根据分式有意义的条件:分母不等于0,即可求解.【解答】解:根据题意得:x﹣1≠0,解得:x≠1.故选:A.【点评】本题主要考查了分式有意义的条件,正确理解条件是解题的关键.3.下列说法中,正确的是()A.“打开电视,正在播放河南新闻节目”是必然事件B.某种彩票中奖概率为10%是指买十张一定有一张中奖C.神舟飞船发射前需要对零部件进行抽样调查D.了解某种节能灯的使用寿命适合抽样调查【考点】随机事件;全面调查与抽样调查;概率的意义.【分析】必然事件指在一定条件下一定发生的事件.不可能事件是指在一定条件下,一定不发生的事件.不确定事件即随机事件是指在一定条件下,可能发生也可能不发生的事件.不易采集到数据的调查要采用抽样调查的方式,据此判断即可.【解答】解:A.“打开电视,正在播放河南新闻节目”是随机事件,故A选项错误;B.某种彩票中奖概率为10%是指买十张可能中奖,也可能不中奖,故B选项错误;C.神舟飞船发射前需要对零部件进行全面调查,故C选项错误;D.解某种节能灯的使用寿命,具有破坏性适合抽样调查,故D选项正确.故选:D.【点评】本题考查了调查的方式和事件的分类.不易采集到数据的调查要采用抽样调查的方式;必然事件指在一定条件下一定发生的事件.不可能事件是指在一定条件下,一定不发生的事件.不确定事件即随机事件是指在一定条件下,可能发生也可能不发生的事件.4.若A(1,y1),B(2,y2)两点都在反比例函数y=的图象上,则y1与y2的大小关系是()A.y1<y2B.y1=y2 C.y1>y2D.无法确定【考点】反比例函数图象上点的坐标特征.【分析】根据反比例函数图象上点的坐标特征结合点A、B的横坐标,求出y1、y2的值,二者进行比较即可得出结论.【解答】解:∵A(1,y1),B(2,y2)两点都在反比例函数y=的图象上,∴1•y1=1,2•y2=1,解得:y1=1,y2=,∵1>,∴y1>y2.故选C.【点评】本题考查了反比例函数图象上点的坐标特征,解题的关键是根据反比例函数图象上点的坐标特征求出y1、y2的值.本题属于基础题,难度不大,解决该题型题目时,结合点的横坐标,利用反比例函数图象上点的坐标特征求出点的纵坐标是关键.5.下列各式计算正确的是()A. +=B.2﹣=C. =×D.÷=【考点】二次根式的混合运算.【分析】根据二次根式的加减法则对A、B进行判断,根据二次根式的性质对C进行判断,根据二次根式的除法法则对D进行判断.【解答】解:A、与不是同类项,不能合并,故本选项错误;B、2﹣=,故本选项正确;C、=,故故本选项错误;D、=,故本选项错误.故选B.【点评】本题考查的是二次根式的混合运算,熟练掌握加减乘除法则和二次根式的性质是解答此题的关键.6.如图,P为正方形ABCD的对角线BD上任一点,过点P作PE⊥BC于点E,PF⊥CD于点F,连接EF.给出以下4个结论:①△FPD是等腰直角三角形;②AP=EF;③AD=PD;④∠PFE=∠BAP.其中,所有正确的结论是()A.①② B.①④ C.①②④D.①③④【考点】四边形综合题.【分析】用正方形的性质和垂直的定义判断出四边形PECF是矩形,从而判定②正确;直接用正方形的性质和垂直得出①正确,利用全等三角形和矩形的性质得出④正确,由点P是正方形对角线上任意一点,说明AD和PD不一定相等,得出③错误.【解答】解:如图,∵P为正方形ABCD的对角线BD上任一点,∴PA=PC,∠C=90°,∵过点P作PE⊥BC于点E,PF⊥CD,∴∠PEC=∠DFP=∠PFC=∠C=90°,∴四边形PECF是矩形,∴PC=EF,∴PA=EF,故②正确,∵BD是正方形ABCD的对角线,∴∠ABD=∠BDC=∠DBC=45°,∵∠PFC=∠C=90°,∴PF∥BC,∴∠DPF=45°,∵∠DFP=90°,∴△FPD是等腰直角三角形,故①正确,在△PAB和△PCB中,,∴△PAB≌△PCB,∴∠BAP=∠BCP,在矩形PECF中,∠PFE=∠FPC=∠BCP,∴∠PFE=∠BAP.故④正确,∵点P是正方形对角线BD上任意一点,∴AD不一定等于PD,只有∠BAP=22.5°时,AD=PD,故③错误,故选C【点评】此题是四边形综合题,主要考查了正方形的性质,矩形的判定和性质,全等三角形的判定和性质,垂直的定义,解本题的关键是判断出四边形PECF是矩形.二、填空题(本大题共10小题,每小题2分,共20分.不需写出解答过程,请把答案直接填写在答题卡相应位置上)7.要使有意义,则x的取值范围是x≥3 .【考点】二次根式有意义的条件.【分析】根据二次根式的性质知,被开方数大于或等于0,据此可以求出x的范围.【解答】解:根据题意得:x﹣3≥0,解得:x≥3;故答案是:x≥3.【点评】考查了二次根式的意义和性质.概念:式子(a≥0)叫二次根式.性质:二次根式中的被开方数必须是非负数,否则二次根式无意义.8.若分式的值为零,则x= ﹣1 .【考点】分式的值为零的条件.【分析】直接利用分式的值为0,则分子为零,且分母不为零,进而求出答案.【解答】解:由题意得:x2﹣1=0,且x﹣1≠0,解得:x=﹣1,故答案为:﹣1.【点评】此题主要考查了值为零的条件,分式值为零的条件是分子等于零且分母不等于零.注意:“分母不为零”这个条件不能少.9.计算﹣的结果是.【考点】二次根式的加减法.【分析】首先把代数式中的二次根式进行化简,再合并同类二次根式即可.【解答】解:原式=﹣=,故答案为:.【点评】此题主要考查了二次根式的减法,关键是掌握计算法则:二次根式相加减,先把各个二次根式化成最简二次根式,再把被开方数相同的二次根式进行合并,合并方法为系数相加减,根式不变.10.已知反比例函数的图象经过点(m,2)和(﹣2,3),则m的值为﹣3 .【考点】反比例函数图象上点的坐标特征.【分析】此题可根据反比例函数图象上点的横纵坐标是一个定值即可求解.【解答】解:∵反比例函数的图象经过点(m,2)和(﹣2,3),∴k=xy=﹣2×3=﹣6,∴2m=﹣6,∴m=﹣3.故答案为:﹣3.【点评】本题考查了反比例函数图象上点的坐标特征,较为简单,容易掌握.11.如图,转盘被平均分成8个区域,每个区域分别标注数字1、2、3,4、5、6、7、8,任意转动转盘一次,当转盘停止转动时,对于下列事件:①指针落在标有5的区域;②指针落在标有10的区域;③指针落在标有奇数的区域;④指针落在能被3整除的区域.其中,发生可能性最大的事件是③.(填写序号)【考点】可能性的大小.【分析】确定指针落在标有数字的面积在整个转盘中占的比例,根据这个比例即可求出转盘停止转动时指针指向指针落在标有数字部分的概率.【解答】解:①指针落在标有5的区域的概率=;②指针落在标有10的区域的概率=0;③指针落在标有奇数的区域的概率=;④指针落在能被3整除的区域的概率=,故答案为:③【点评】此题考查可能性问题,用到的知识点为:概率=相应的面积与总面积之比.12.已知菱形的面积是5,它的两条对角线的长分别为x、y(x>0,y>0),则y与x的函数表达式为y=.【考点】菱形的性质.【分析】由菱形的两条对角线长分别为x和y,根据菱形的面积等于对角线积的一半,即可求得答案.【解答】解:∵菱形的两条对角线长分别为x和y,∴它的面积为:×x×y=5.即y=故答案为:y=.【点评】此题考查了菱形的性质.注意菱形的面积等于对角线积的一半是解题的关键.13.如图,▱ABCD的对角线AC,BD相交于点O,点E,F分别是线段AO,BO的中点,若AC+BD=24cm,△OAB的周长是18cm,则EF= 3 cm.【考点】平行四边形的性质;三角形中位线定理.【分析】首先由▱ABCD的对角线AC,BD相交于点O,求得OA=AB,OB=BD,又由AC+BD=24cm,可求得OA+OB的长,继而求得AB的长,然后由三角形中位线的性质,求得答案.【解答】解:∵四边形ABCD是平行四边形,∴OA=AC,OB=BD,∵AC+BD=24cm,∴OA+OB=12cm,∵△OAB的周长是18cm,∴AB=6cm,∵点E,F分别是线段AO,BO的中点,∴EF=AB=3cm.故答案为:3.【点评】此题考查了平行四边形的性质以及三角形中位线的性质.注意由平行四边形的性质求得AB的长是关键.14.已知等式=﹣,对任意正整数n都成立.计算:++++…+= .【考点】分式的化简求值.【分析】利用等式=﹣把原式化为=1﹣+﹣+﹣+﹣+…+﹣,然后合并后进行通分即可.【解答】解:原式=1﹣+﹣+﹣+﹣+…+﹣=1﹣=.故答案为.【点评】本题考查了分式的化简求值:先把分式化简后,再把分式中未知数对应的值代入求出分式的值.在化简的过程中要注意运算顺序和分式的化简.化简的最后结果分子、分母要进行约分,注意运算的结果要化成最简分式或整式.15.如图,矩形OABC的顶点A、C的坐标分别为(4,0)、(0,2),对角线的交点为P,反比例函数y=(k>0)的图象经过点P,与边BA、BC分别交于点D、E,连接OD、OE、DE,则△ODE的面积为.【考点】反比例函数系数k的几何意义.【分析】根据矩形的性质可以找出点B、P的坐标,利用反比例函数图象上点的坐标特征即可求出反比例函数解析式,再分别代入x=4、y=2即可得出点D、E的坐标,利用分割图形求面积法即可得出结论.【解答】解:∵四边形OABC是矩形,且A(4,0)、C(0,2),∴B(4,2),∵点P为对角线的交点,∴P(2,1).∵反比例函数y=的图象经过点P,∴k=2×1=2,∴反比例函数解析式为y=.令y=中x=4,则y=,∴D(4,);令y=中y=2,则x=1,∴E(1,2).S△ODE=S矩形OABC﹣S△OCE﹣S△OAD﹣S△BDE=OA•OC﹣k﹣k﹣BD•BE=.故答案为:.【点评】本题考查了矩形的性质、反比例函数图象上点的坐标特征以及反比例系数k的几何意义,解题的关键是求出反比例函数解析式以及点B、D、E的坐标.本题属于基础题,难度不大,解决该题型题目时,利用分割图形求面积法是关键.16.设函数y=x﹣2与y=的图象的交点坐标为(m,n),则﹣的值为﹣.【考点】反比例函数与一次函数的交点问题.【分析】有两函数的交点为(m,n),将(m,n)代入一次函数与反比例函数解析式中得到mn与n﹣m的值,所求式子通分并利用同分母分式的减法法则计算,将各自的值代入计算即可求出值.【解答】解:∵函数y=x﹣2与y=的图象的交点坐标为(m,n),∴n﹣m=﹣2,mn=3,∴﹣==﹣,故答案为﹣【点评】此题考查了反比例函数与一次函数的交点问题,以及分式的加减运算,求出mn与n﹣m的值是解本题的关键.三、解答题(本大题共11小题,共88分.请在答题卡指定区域内作答,解答时应写出文字说明、证明过程或演算步骤)17.解分式方程: =.【考点】解分式方程.【分析】分式方程去分母转化为整式方程,求出整式方程的解得到x的值,经检验即可得到分式方程的解.【解答】解:去分母得:1=x﹣1﹣3x+6,解得:x=2,经检验x=2是增根,分式方程无解.【点评】此题考查了解分式方程,熟练掌握运算法则是解本题的关键.18.计算:(1)•(a≥0);(2)×(2﹣3).【考点】二次根式的混合运算.【分析】(1)根据二次根式的乘法法则得出即可;(2)可以把二次根式化简,合并括号里同类二次根式,再做乘法;也可以用分配律计算;【解答】解:(1)原式===4a2.(2)原式=×(2﹣)=×=3.【点评】主要考查了二次根式的混合运算,在二次根式的混合运算中,要掌握好运算顺序及各运算律.19.先化简[﹣]÷,然后从﹣1,0,1,2中选取一个你认为合适的数作为x的值代入求值.【考点】分式的化简求值.【分析】先算括号里面的,再算除法,最后选出合适的x的值代入进行计算即可.【解答】解:原式=•=•=,当x=﹣1时,原式=﹣.【点评】本题考查的是分式的化简求值,分式中的一些特殊求值题并非是一味的化简,代入,求值.许多问题还需运用到常见的数学思想,如化归思想(即转化)、整体思想等,了解这些数学解题思想对于解题技巧的丰富与提高有一定帮助.20.在一个不透明的盒子里装有黑、白两种颜色的球共40只,这些球除颜色外其余完全相同.小颖做摸球实验,搅匀后,她从盒子里随机摸出一只球记下颜色后,再把球放回盒子中,不断重复上述过程,下表是实验中的一组统计数据:摸球的次数n 100 200 300 500 800 1000 3000摸到白球的次数m 65 124 178 302 481 599 1803摸到白球的频率0.65 0.62 0.593 0.604 0.601 0.599 0.601 (1)请估计:当n很大时,摸到白球的频率将会接近0.6 ;(精确到0.1)(2)若从盒子里随机摸出一只球,则摸到白球的概率的估计值为0.6 ;(3)试估算盒子里黑、白两种颜色的球各有多少只?【考点】利用频率估计概率.【分析】(1)计算出其平均值即可;(2)概率接近于(1)得到的频率;(3)白球个数=球的总数×得到的白球的概率,让球的总数减去白球的个数即为黑球的个数,问题得解.【解答】解:(1)∵摸到白球的频率为0.6,∴当n很大时,摸到白球的频率将会接近0.6,故答案为:0.6;(2)∵摸到白球的频率为0.6,∴假如你摸一次,你摸到白球的概率P(白球)=0.6,故答案为:0.6;(3)盒子里黑、白两种颜色的球各有40﹣24=16,40×0.6=24.【点评】本题比较容易,考查利用频率估计概率.大量反复试验下频率稳定值即概率.用到的知识点为:部分的具体数目=总体数目×相应频率.21.某校为了开设武术、舞蹈、剪纸等三项活动课程以提升学生的体艺素养,随机抽取了部分学生对这三项活动的兴趣情况进行了调查(每人从中只能选一项),并将调查结果绘制成如图两幅统计图,请你结合图中信息解答问题.(1)将条形统计图补充完整;(2)本次抽样调查的样本容量是100 ;(3)已知该校有1200名学生,请你根据样本估计全校学生中喜欢剪纸的人数.【考点】条形统计图;用样本估计总体;扇形统计图.【分析】(1)根据扇形统计图可得出女生喜欢武术的占20%,利用条形图中喜欢武术的女生有10人,即可求出女生总人数,即可得出喜欢舞蹈的人数;(2)根据(1)的计算结果再利用条形图即可得出样本容量;(3)用全校学生数×喜欢剪纸的学生在样本中所占百分比即可求出.【解答】解:(1)∵根据扇形统计图可得出女生喜欢武术的占20%,利用条形图中喜欢武术的女生有10人,∴女生总人数为:10÷20%=50(人),∴女生中喜欢舞蹈的人数为:50﹣10﹣16=24(人),如图所示:(2)本次抽样调查的样本容量是:30+6+14+50=100;(3)∵样本中喜欢剪纸的人数为30人,样本容量为100,∴估计全校学生中喜欢剪纸的人数=1200×=360人.【点评】本题考查的是条形统计图和扇形统计图的综合运用,读懂统计图,从不同的统计图中得到必要的信息是解决问题的关键.条形统计图能清楚地表示出每个项目的数据;扇形统计图直接反映部分占总体的百分比大小.22.小明到眼镜店调查了近视眼镜镜片的度数和镜片焦距的关系,发现镜片的度数y(度)是镜片焦距x(厘米)(x>0)的反比例函数,调查数据如表:眼镜片度数y(度)400 625 800 1000 1250 …镜片焦距x(厘米)25 16 12.5 10 8 …(1)求y与x的函数表达式;(2)若小明所戴近视眼镜镜片的度数为500度,求该镜片的焦距.【考点】反比例函数的应用.【分析】(1)根据图表可以得到眼镜片的度数与焦距的积是一个常数,因而眼镜片度数与镜片焦距成反比例函数关系,即可求解;(2)在解析式中,令y=500,求出x的值即可.【解答】解:(1)根据题意得:与x之积恒为10000,则函数的解析式是y=;(2)令y=500,则500=,解得:x=20.即该镜片的焦距是20cm.【点评】考查了反比例函数的应用,正确理解反比例函数的特点,两个变量的乘积是常数,是解决本题的关键.23.著名数学家斐波那契曾研究一列数,被称为斐波那契数列(按照一定顺序排列的一列数称为数列),这个数列的第n个数为 [()n﹣()n](n为正整数),例如这个数列的第8个数可以表示为 [()8﹣()8].根据以上材料,写出并计算:(1)这个数列的第1个数;(2)这个数列的第2个数.【考点】二次根式的应用.【分析】(1)把n=1代入式子化简求得答案即可.(2)把n=2代入式子化简求得答案即可.【解答】解:(1)第1个数,当n=1时,(﹣)=×=1;(2)第2个数,当n=2时,[()2﹣()2]=(+)(﹣)=×1×=1.【点评】此题考查二次根式的混合运算、化简求值以及应用,理解题意,找出运算的方法是解决问题的关键.24.如图,在▱ABCD中,∠BAD的平分线交BC于点E,∠ABC的平分线交AD于点F.(1)求证:四边形ABEF是菱形;(2)若AB=5,BF=8,AD=,则▱ABCD的面积是36 .【考点】菱形的判定与性质;平行四边形的性质.【分析】(1)根据平行四边形的性质和角平分线的性质证明∠BAE=∠BEA,从而可得AB=BE,同理可得AB=AF,再由AF∥BE可得四边形ABEF是菱形;(2)过A作AH⊥BE,根据菱形的性质可得AO=EO,BO=FO,BE=AB=5,AE⊥BF,利用勾股定理可得AO的长,进而可得AE长,利用菱形的面积公式计算出AH的长,然后可得▱ABCD的面积.【解答】(1)证明:∵四边形ABCD是平行四边形,∴AD∥BC,∴∠DAE=∠AEB,∵∠BAD的平分线交BC于点E,∴∠DAE=∠BEA,∴∠BAE=∠BEA,∴AB=BE,同理:AB=AF,∴AF=BE,∵AF∥BE,∴四边形ABEF是平行四边形,∵AB=AF∴四边形ABEF是菱形.(2)解:过A作AH⊥BE,∵四边形ABCD是菱形,∴AO=EO,BO=FO,BE=AB=5,AE⊥BF,∵BF=8,∴BO=4,∴AO==3,∴AE=6,∴S菱形ABEF=AE•BF=×6×8=24,∴BE•AH=24,∴AH=,∵四边形ABCD是平行四边形,∴BC=AD=,∴S平行四边形ABCD=×=36,故答案为:36.【点评】此题主要考查了菱形的性质和判定,以及平行四边形的性质,关键是掌握邻边相等的平行四边形是菱形,菱形的面积为对角线之积的一半.25.“五一”期间,某商铺经营某种旅游纪念品.该商铺第一次批发购进该纪念品共花费3 000元,很快全部售完.接着,该商铺第二次批发购进该纪念品共花费9000元.已知第二次所购进该纪念品的数量是第一次的2倍还多300个,第二次的进价比第一次的进价提高了20%.(1)求第一次购进该纪念品的进价是多少元?(2)若该纪念品的两次售价均为9元/个,两次所购纪念品全部售完后,求该商铺两次共盈利多少元?【考点】分式方程的应用.【分析】(1)设第一次所购该纪念品是多少元,由题意可列方程求解.(2)求出两次的购进数,根据利润=售价﹣进价,可求出结果.【解答】解:(1)设第一次所购该纪念品是x元,依题意,得。
九年级化学第一学期期末复习试卷(一)

2014-2015学年度第一学期期末复习检测(一)可能用到的相对原子质量:H--1 C--12 O--16 N—14 Cl—35.5 Ca--40一、选择题(每小题只有一个选项符合题意,共18小题,每小题2分,共36分)1.下图表示的物质变化中,属于化学变化的是()A.石蜡熔化B.活性炭净水C.汽车尾气处理D.干冰人工降雨2.下列关于水的叙述中错误的是()A.地球表面约71%被水覆盖,因而供人类生产生活用水极为丰富B.保持水化学性质的最小粒子是水分子C.电解水得到氢气与氧气的体积比为2:1 D.江河湖泊的水经沉淀、过滤、消毒、杀菌后,可供人们生活用水3.掌握正确的实验操作是做好实验的基础,下列实验操作正确的是()A.制取O2B.检查装置气密性C.加入药品D.检验CO2是否收集满4.下列现象的微观解释不正确的是()A.气体可压缩储存于钢瓶中——分子体积变小B.墙内开花,墙外可闻到花香——分子不断运动C.水蒸发为水蒸气,水的化学性质没有改变——同种分子性质相同D.1滴水中大约有1.67×1021个水分子——分子的质量和体积都很小5.燃烧是生活中的一种常见现象。
下列有关燃烧或灭火的说法错误的是()A.钠可以在氯气中燃烧,说明燃烧不一定要有氧气参与B.碳、硫在氧气中燃烧比在空气中燃烧剧烈C.锅里的油着火时可用锅盖盖灭,是因为隔绝了氧气D.用水可以灭火,是因为降低了可燃物的着火点6.下列各组物质,按单质、化合物、混合物顺序排列的是()A.固态氮、干冰、冰水共存物B.稀有气体、氯化氢气体、液化石油气C.液态氧、蒸馏水、透明的河水D.天然气、煤、石油7.鉴别O2、H2、CO2三种气体,可行简便的方法是()A.将气体分别通入澄清石灰水B.将气体分别通入石蕊试液C.试验三种气体在水中溶解性D.用燃着的木条分别伸入瓶内8.下列关于实验室制取氧气的叙述正确的是()A.用高锰酸钾制取氧气时,试管口应向上倾斜,便于气体迅速排出B.插入水槽中的导管管口刚有气泡冒出时,就立即收集,否则会造成浪费C.用排水法收集氧气完毕后,应先撤酒精灯.后撤导管D.收集氧气可用排水法或向上排空气法9.化学符号表示不同的意义,下列化学符号中,表示2个氧原子的是()A.O2B.2O C.2O2D.CO210.下列实验现象中,描述正确的是()A.木炭在氧气中燃烧,有无色刺激性气味气体生成B.镁条在盐酸中剧烈反应,产生大量气泡,试管壁发热C.红磷在氧气中剧烈燃烧,放出热量,有大量白色气体生成D.铁丝在空气中剧烈燃烧,放出大量的热,火星四射,有黑色熔融物溅落瓶底11.下图所示物质用途中,主要利用其化学性质的是()12.苹果中富含苹果酸,苹果酸的化学式为C4H4O4。
- 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
- 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
- 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。
南京2014~2015学年度第二学期巩固练习试卷高一英语注意事项:本试卷分第一卷(选择题)和第二卷(非选择题)两部分。
答案全部写在答题纸上。
总分为100分。
考试时间100分钟。
第一卷(选择题,共55分)第一部分单项填空(共20小题;每小题1分,满分20分)1. --- What do you think of the film Avengers: Age of Ultron?--- It _____ be better. I‟d like to see it again.A. needn‟tB. mustn‟tC. couldn‟tD. shouldn‟t2.----What does the sign over there mean?----No person ______ smoke or carry a lighted cigarette, cigar or pipe in this area.A. willB. shallC. mayD. must3.There ______ be any difficulty in passing the oral test since you have practiced a lot in school.A. mustn‟tB. shan‟tC.shouldn‟tD.needn‟t4. Changing the order of mixing chemicals in an experiment _____ cause fastreactions leading to an accident.A. shouldB. canC. mustD. shall5. Harry is feeling uncomfortable. He _______too much at the party last night.A. could have drunkB. should have drunkC. would have drunkD. must have drunk6. She into the thick forest alone on such a dark night.A. dared not goB. dared not to goC. didn‟t dare goD. not dare7. --- Do you really want to go out?--- It may rain. _______, I shall go out; I don‟t mind the rain.A. AnywayB. OtherwiseC. MeanwhileD. Therefore8. This English book is too difficult for me. I have no idea what subject it _____even when I read it three times.A. comes withB. does withC. deals withD. consults with9. _______is required in our agreement that nobody _____ our secret plan to others.A. It, lets outB. What, lets outC. It, let outD. What, let out10. He left the room with pain and sadness , _______never to come back.A. determinedB. to determineC. determiningD. was determined11. --- Will Prof. Proton attend our graduation ceremony?--- He has just arrived, but I didn‟t know he ______ until yesterday.A. is comingB. had comeC. was comingD. came12. It is amazing that some people in your life make you smile _____ they are not around.A. even ifB. as thoughC. if onlyD. in case13. Learning English as a foreign language is very difficult in the _____ of a nativelanguage environment.A. absenceB. convenienceC. advantageD. aspect14. ---What a nice fire you have in your fireplace! --- During the winter I like myhouse_______.A. warmly and comfortablyB. warm and comfortableC. warm and comfortablyD. warmly and comfortable15. The manager, having made ____ clear to us that he didn‟t agree with us, left themeeting room.A. thatB. whichC. whatD. it16. That day everyone wondered the girl of four went to her mother‟soffice.A. how was it thatB. how it was thatC. how was itD. how was that17. Shelly had prepared carefully for her biology examination so that she could besure of passing it at her first .A. attentionB. attractionC. approvalD. attempt18. ---How is everything going on with you in South Korean?---Quite well. Not as smoothly as I hoped, .A. thoughB. insteadC. eitherD. too19. When it football, he has no confidence.A. turns outB. comes toC. turns toD. comes out20. --- Are you going to Tom‟s birthday party?--- _____. I might have to work.A. Don‟t mention itB. It dependsC. Sounds greatD. Thank you 第二部分完形填空(共15小题;每小题1分,满分15分)The sound of the rain hitting the windows wakes me up and it sound just exactly as it did 15 years ago, which reminded me of my girlhood.It was my second day of 21 and it was raining heavily. I could not resist the habit I had at home, so I fell asleep right at my 22 . I woke up to find myself not in the classroom but carried on Dad…s back. We were 23 home. It was the last time I felt 24 to him.After that, he never carried me or hugged me as other fathers did to their children. I was not bothered much by this thought. I was proud of it, for I felt 25 and ―grown up. However, there were times when I felt depressed by not having sought 26 from him.One day, I was writing Chinese characters as homework. I hated doing this more than anything. Dad came and stood behind me for a moment, 27 me scratching (乱吐,勾抹) the paper. Then he said,―This kind of writing needs 28 .Your writing is not strong enough. Press harder. I follow his 29 for the next two words, but 30 I could see little improvement, I followed my own method-the fast way. His advice did not improve my writing but our 31 . As I grew older, I found out that he had finished his schooling in Grade 6, which was the highest grade in town then, so he was considered to be a 32 . People used to ask him to write something to put on the walls, but he never felt very useful. He often said to me, ―As you can see, this family is going to count on you. We are 33 to improve you anything for your future .Your have to get an education to change the life for yourself.As a result of his 34 , I have 35 it through high school and through college.21. A. graduation B. employment C. college D. school22. A. dormitory B. door C. desk D. bed23. A. at B. already C. beyond D. halfway24. A. close B. near C. happy D. relaxed25. A. lonely B. depressed C. independent D. comfortable26. A. comfort B. help C. support D. explanation27. A. helping B. directing C. watching D. blaming28. A. skill B. patience C. time D. practice29. A. introduction B. manner C. spirit D. advice30. A. even if B. while C. as D. though31. A. relationship B. friendship C. thought D. life32. A. writer B. scholar C. scientist D. specialist33. A. tired B. glad C. useless D. ready34. A. help B. expectations C. examination D. watch35. A. succeeded B. got C. made D. found第三部分阅读理解(3篇,共10小题;每小题2分,满分20分)AWhen I got the driving license (执照) last summer, Mom and I took our first trip around an empty parking lot. Then I found that my mother was not the best teacher for me. It wasn‟t that she shouted, or told me that I was doing poorly. As you can imagine, my mother‟s “helpful instructions (指示)” only made me more n ervous.Since I could no longer practice with her, the job was placed in the hands of my father. The idea of learning from Dad was not one that thrilled me. I loved him dearly, but I just did not see Dad as someone I could be comfortably learning from. He almost never talked. We shared a typical (典型的) father-daughter relationship. He‟d ask how school was, and I‟d say it was fine. Unfortunately, that was the most of our conversations. Spending hours alone with someone who might as well have been a stranger really scared me.As we got into the car that first time, I was not surprised at what happened. Dad and I drove around, saying almost nothing, aside from a few instructions on how to turn. As my lessons went on, however, things began to change. Dad would turn the radio up so I could fully appreciate his favorite Stones music. And he actually began talking. I was soon hearing about past failed dates, “basic body” gym class, and other tales from his past, including some of his first meeting with Mom.Dad‟s sud den chattiness (爱讲话) was shocking until I thought about why he was telling me so much in the car. In all the years, I had wondered why my father never spoke that much, but I had never stopped to consider that it was because I had never bothered to listen. Homework, friends, and even TV had all called me away from him, and, consequently (因此), I never thought my quiet father had anything to say.Since I began driving with him, my driving skill has greatly increased. More important, though, is that my knowledge of who my father is has also increased. Just living with him wasn‟t enough — it took driving with him for me to get to know someone who was a mystery.36.T he author couldn‟t practice driving with her mother because ________.A. she couldn‟t talk with her m otherB. her father wanted to teach herC. her mother made her nervousD. she didn‟t trust her mother37. What surprised the author when the driving lessons went on?A. Her Dad liked modern music.B. Her Dad was the best teacher.C. Her Dad was a chatty person.D. Her Dad told her his sad stories.38. With her story “Car Talk”, the author indicates that ________.A. fathers love their daughters dearlyB. mothers are less patient than fathersC. family members need real communicationD. it takes time to improve the father-daughter relationshipBIt is quite reasonable to blame (指责) traffic jams, the cost of gas and the great speed of modern life, but manners on the road are becoming horrible. Everybody knows that the nicest men would become fierce tigers behind the wheel. It is all right to have a tiger in a cage, but to have one in the driver‟s seat is another matter.Road politeness is not only good manners, but good sense. It takes the most cool-headed drivers great patience to give up the desire (欲望) to beat back (反击) when forced to face rude driving. On the other hand, a little politeness goes a long way towards reducing the possibility of quarrelling and fighting. A friendly nod or a wave, of thanks in answer to an act of politeness helps to create an atmosphere (氛围) of good will and becomes so necessary in modern traffic conditions. But such behaviors of politeness are by no means enough. Many drivers nowadays don‟t even seem able to recognize politeness when they see it.However, misplaced politeness can also be dangerous. A typical example is that a driver waves a child crossing the street at a wrong place into the path of oncoming cars that may not be able to stop in time. The same goes for encouraging old ladies to cross the road wherever and whenever they want to.An experienced driver, whose manners are faultless (无错误的), told me it would help if drivers learnt to correctly join in traffic stream (潮流) without causing total jams that give rise to unpleasant feelings. Unfor tunately, modern drivers can‟t even learn to drive, let alone (更不要说) master the roadmanship (驾车技能). Years ago, experts warned us that the fast increase of the car ownership would demand more give-and-take (互让,妥协) from all road users. It is high time for all of us to take this message to heart.39.What‟s the best little of the passage above?A. Road PolitenessB. Traffic JamsC. Good MannersD. Modern Drivers40.Troubles on the road are often caused by ________.A. great speedB. traffic jamsC. terrible road conditionsD. the behaviors of the drivers41.According to the writer, a good driver should ________.A. beat back when forced to face rude drivingB. be able to recognize politeness when he sees itC. join in traffic stream quickly however other people feelD. encourage children to cross the roads whenever they want to42.It is not always right for drivers to ________.A. encourage old ladies to cross the roadB. create atmosphere of good willC. master roadmanshipD. give a friendly nod to show politenessCIt‟s 10:30 pm, and 11-year-old Brandon Blanco is sound asleep at home.Suddenly, a loud noise wakes him up. Naturally, Brandon reaches for his cell phone. The message becomes clear: “R U awake?”Brandon‟s use of technology doesn‟t stop there. He also has a computer, a TV and three video-game consoles (控制台) in his room. With so many choices, it‟s no surprise that when he isn‟t at school, he spends nearly every waking minute using one or more of these devices.Brandon is hardly alone. According to a recent study by the Kaiser Family Foundation, kids aged 8 to18 are spending more time than ever before using electronic devices (电子设备). How much time? More than seven and a half hours a day on average, the study found.The jump is the result of a huge explosion (爆发) in mobile devices, says Victoria Rideout, the lead author of the study. Today, nearly seven out of ten kids have cell phones. Just five years ago, it was four out of ten.Often, kids multitask, or use more than one device at a ti me. “If you‟ve got a chance to do something on your computer and take a phone call and have the TV on in the background, why not?” media expert Cheryl Olson says.Most experts agree technology has much to offer kids. But some worry the kids could be missing out on other activities like playing outside or hanging out (闲逛) with friends. “It‟s a matter of balance,” says Olson. “You‟ve got to work on it.”Multitasking while doing homework is another concern. Some kids listen to music, watch TV or use the phone while doing their homework. “It‟s important to make sure that you can stop and concentrate on one thing deeply,” says Rideout.With new and exciting devices hitting stores every year, keeping technology use in check (在控制中) is more important than ever. “Kids should try,” adds Rideout. “but parents might have to step in sometimes.”43.Why do children spend more time in using electronic devices (电子设备)?A. Because more electronic devices are available to them.B. Because electronic devices are more exciting than before.C. Because they have less other activities.D. Because they have less homework to do.44.It is known from the passage that ________.A. Brandon Blanco feels very annoyed about his late-night textB. the teenagers using mobile devices have increased by 40% in the past five yearsC. Cheryl Olson is not surprised about kids‟ increasing use of mobile devicesD. most experts think teenagers should not use electronic devices for their studies45.According to the passage, Victoria Rideout would probably agree that ________.A. kids should do homework while surfing the InternetB. kids should do homework in a place without disturbanceC. kids should spend more time on homeworkD. kids should have more homework than before第二卷(非选择题,共45分)第四部分词汇检测(共10小题;每空格1分,满分10分)根据所给中文或首字母,写出下列各句空格处的单词,注意保持语义和形式的一致,并将答案写在答题纸上。