06兰州交通大学试卷
兰州交通大学函授本科期末考试试卷

兰州交通大学函授本科期末考试试卷本试卷21题,共8页,满分为160分。
考试时间150分钟。
注意事项:1.答卷前,考生务必用黑色字迹的钢笔或签字笔将自己的姓名和考生号填写在答题卷上。
用2B铅笔将答题卷上的试卷类型(A)填涂在答题卡上。
在答题卷右上角的“试室号”栏填写本科目试室号,在“座位号列表”内填写座位号,并用2B铅笔将相应的信息点涂黑。
不按要求填涂的,答卷无效。
2.1—7题为单项选择题,每题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;如需改动,用橡皮擦干净后,再选涂其他答案;不能答在试卷上。
3.8—21题为非单项选择题,必须用黑色字迹钢笔或签字笔作答,答案必须写在答题卷各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
4.考生必须保持答题卷的整洁,考试结束后,将试卷和答题卷一并上交。
一、(9分)1.下列词语中,加点字的读音完全正确的一组是()A.坍圮(qǐ)熨(yù)帖恪(kè)守不渝文采斐(fěi)然B.颤(zhān)栗颓垣(yuán) 凝神屏(bǐng)息自怨自艾(ài)C.孝悌(tì)赧(nǎn)然瞠(chēng)目结舌纵横捭(bǎi)阖D.削(xiāo)平百舸(gě)余勇可贾(gǔ)毁家纾(shū)难2.下列各句中,加点的词语使用恰当的一句是( )A.然而,有关部门固执己见,坚持这种破坏历史文化遗产的“旧城改造”,私自拆除了当年是慈禧弟弟的桂公府的跨院。
B.浈江区有政协委员建议,风度路作为全市唯一的全天候步行街应尽早树立导游导购指示牌。
C.有德之人不会以权谋私,不会贪污受贿,虽然清贫点,但活得坦荡,没有东窗事发之虑,也没有半夜敲门之惊。
D.面对张海同学一家的不幸遭遇,大家纷纷伸出援助之手,你五十,我一百,二一添作五,不一会功夫,捐了三千多元钱。
3.下列各句中没有语病的一句是()A.“保护母亲河”活动的举办者认为,要让环保理念进入生活,关键在于能否建设好绿色队伍和绿色基地。
兰州交通大学铁路运输设备复习题及答案

兰州交通大学复习资料一、判断题1、同一区段,上下行方向的货物列车数目应该是相同的。
3、圆曲线和缓和曲线构成线路平面的组成要素。
6、列车下坡时不受坡道附加阻力的作用。
7、铁路沿线的一切建筑物和设备均不得侵入建筑接近限界。
8、线路标志一般埋设在计算里程方向的线路右侧的适当地点。
9、路堤是开挖形成的,而路堑是填筑形成的。
4、缓和曲线是为了防止离心力的出现而设置的。
5、列车通过缓和曲线可以平顺地从直线进入圆曲线,使离心力逐渐消失。
10、桥梁和隧道构成桥隧建筑物。
11、道岔开通的方向完全取决于两条尖轨所处的位置。
12、辙叉角越大,道岔号越大,允许的侧线过岔速度越高。
2、运行图上若上下行列车运行线在区间有交点,则该区间一定是双线区间。
13、由于活动心轨道岔消除了道岔的有害空间,可以作为提速道岔。
17、响墩是一种紧急停车信号,信号火炬是一种减速运行信号。
18、车站除了办理客货运输外,还要办理与列车有关的各项作业。
19、车站按其担负的任务量可分为特、1、2、3、4、5等站。
20、中间站上不办理调车作业。
21、铁路上绝大多数车站是技术站。
14、无缝线路就是把标准长度的钢轨全部焊接起来铺设的线路。
15、轨距指的是两钢轨内侧面之间的垂直距离。
16、曲线部分的轨距加宽是为了减小离心力的影响。
22、铁路线路上各个技术站之间的车站都是中间站。
26、所有货物列车在编组站都要进行解体和编组作业。
27、编组站是解编各种列车的车站,被称作为“列车制造工厂”。
28、调车指的是机车车辆或列车在车站线路上进行的移动。
29、牵出线调车均采用推送调车法。
1 23、中间站的股道编号是从站舍一侧向对侧依次顺序编号。
、中间站的股道编号是从站舍一侧向对侧依次顺序编号。
24、股道有效长指的是在股道上可以停放机车车辆的那部分长度。
、股道有效长指的是在股道上可以停放机车车辆的那部分长度。
25、区段站的作业项目最全但作业量并不一定最大。
、区段站的作业项目最全但作业量并不一定最大。
兰州交通大学弹性理论期末考试试卷

2
, 分别为
因此,有
( ) 0,得到C 0 2 q ( ) q, 得到B 2 2
将各系数代入应力分量表达式,得
q sin 2 q sin 2 q cos 2
足的,故不必在校核。 将系数 A、B、C、D 代入公式(a) ,得应力分量
x FN 12 M y 12 Fs xy h h3 h3 y 0 2 3FS 1 4 y xy 2h h2
六,半平面体表面上受有均布水平为 q,如图所示,试求其应力分量(25 分) ; 解:用半逆解法求解 (1)由量纲分析法可知:
3G 45 3 ( x a) y M ( x a) y xz G( ) y a a5 求应力分量: G 15 3 yz G (3 x 2 2ax 3 y 2 ) 5 M (3 x 2 2ax 3 y 2 ) x 2a a
由薄板比拟法知,在扭杆的边界上,三个边的中点将发生最大的剪应力,取 C 点进行计算:
max ( yz ) x a , y 0
15 3 M , ( xz ) x a , y 0 0; 2a 3 C 15 3 M 2G Ga 4
单位长度上的扭角: K
八(1)图中所示的薄板,厚度 1 ,三边固定,一边受到均布压力 q 的作用。试用瑞利里茨的位移变分法求解,其中取 a=b, 0 。 (10 分)
(a) (b) 因此,该应力函数可解决悬臂梁在自由端受集中力 F 作用的问题。 四,已知受力弹性体中某点的应力分量为: x 1, y 2, z 4, xy 3, yz =6, zx 5 , 单位为 Mpa,试求此点最大切应力(5 分); 解答:
兰州交通大学数值计算法考试试卷(一)

x0 0, x1 -1, x2 2 f ( x0 ) 1, f ( x1 ) 5, f ( x2 ) 1 则L2 ( x) y0 ( x x0 )( x x2 ) ( x x1 )( x x0 ) ( x x1 )( x x2 ) y1 y2 ( x0 x1 )( x0 x2 ) ( x1 x0 )( x1 x2 ) ( x2 x1 )( x2 x0 ) 1 ( x 1)( x 2) x( x 2) x( x 1) 5 1 1(2) (1)(3) 23 x 2 3x 1 即L2 (1) 1 3 1 1 R2 (1) f ''' ( ) ( x x0 )( x x1 )( x x0 )( x x1 )( x x2 ) 0 3!
1 [4.0 4(3.9 3.5 2.9 2.3) 2(3.8 3.2 2.6) 2.0] 24 75.6 24 3.15
即
1
0
f ( x)dx =3.15
四、(12 分)设有给定函数 f ( x) =0,设对一切 x, f ( x) 存在且 0 m f ( x) M ,构 造迭代过程:
故其误差为 0; 六、 (10 分)设求积公式:
1
0
f ( x)dx A0 f (0) A1 f (1) A2 f , (0)
(1)确定待定参数,使其代数精度尽量高; (2)确定求积公式的代数精度; 解答: 由于有三个待定系数, 按代数精度取 f(x)=1,x,x²; 则所求的求积公式 f(x)的余项为 0, 建立三个方程:
(2)由上可知:
(k=0,1,2…)
1 1 0 9 9 1 1 0 10 10 Jacobi 迭代矩阵: BJ = 1 1 0 15 15
2022年兰州交通大学公共课《C语言》科目期末试卷A(有答案)

2022年兰州交通大学公共课《C语言》科目期末试卷A(有答案)一、填空题1、若x=0123,则表达式(5+(int)(x))&(~2)的值是_______。
2、在C语言源程序中,一个变量代表【】。
3、一个C语言源程序由若干函数组成,其中至少应含有一个________4、在C语言中,用“\”开头的字符序列称为转义字符。
转义字符“\n”的功能是_______;转义字符“\r”的功能是_______。
5、若x和a均是int型变量,则执行表达式(1)后的x值为_______,执行表达式(2)后的x值为_______。
(1)x=(a=4,6*2)(2)x=a=4,6*26、已有一维数组a,n为元素的个数,且各元素均有值;函数void process(float*p,int n,float(*fun)(float*,int))为一个可完成下面各种计算的通用函数。
请分别写出用于以下计算的各函数中的调用语句_______、_______和_______。
(1)float arr_add(float*arr,int n)计算数组元素值之和。
(2)float odd_add(float*p,int n)计算下标为奇数的元素之和。
(3)float arr_ave(float*p,int n)计算各元素的平均值。
7、执行下面程序段后,k的值是_______。
k=1;n=263;do{k*=n%10;n/=10;} while(n);8、设有以下定义和语句,请在printf语句的_______中填上能够正确输出的变量及相应的格式说明。
union{int n;doublex;}num;num.n=10;num.x=10.5;printf("_______",_______);9、已有定义int a;float b,x;char cl,c2;为使a=3、b=6.5、x=12.6、cl='a'、c2='A',正确的scanf函数调用语句是_______,数据输入的形式应为_______。
兰州交通大学《大学物理》2018-2019学年期末试卷

兰州交通大学2018-2019学年第一学期期末考试大学物理试题B 卷题号一二三总分一、单选题(本大题共5小题,每小题4分,共计20分)1.稳恒磁场的高斯定理表明,磁场是()。
A.有源场B.无源场C.保守力场D.非保守力场2.下列表述中正确的是()。
A.支路两端电压为零时,支路中的电流一定为零。
B.当支路中的电流为零时,支路两端的电压一定为零。
C.电流一定是从电源的正极流出,流回电源的负极。
D.沿着电流的方向,电势一定降低。
3.通以稳恒电流的长直导线,在其周围空间()。
A.只产生电场B.只产生磁场C.既产生电场,又产生磁场D.既不产生电场,又不产生磁场4.波长为λ的单色光在折射率为n 的介质中,由a 点传到b 点相位改变了π,则对应的光程差为()。
A.λ/2nB.nλ/2C.λ/2D.λ5.用光强相同的蓝光和紫外光照射同一种金属表面,产生光电效应,则()。
A.这两束光每个光子的能量相同B.金属的截止频率相同C.逸出电子的初动能相同D.逸出电子的初速度相同二、填空题(本大题共5小题,每小题4分,共计20分)1.如果需要提高电容器的耐压能力,应将两个电容器使用。
2.将“220V、60W”灯炮甲和“220V、100W”灯炮乙的两只灯泡串联在220V 的电路中,得分评卷人得分评卷人灯泡较亮。
3.电磁波是横波,电矢量E 和磁矢量B 相互。
4.光速不变原理是说,光在真空中总是以确定的速度c 传播,这个速度的大小同光源或观测者的无关。
5.海森伯不确定关系式为。
三、计算题(本大题共4小题,每题15分,共计60分)1.在图1所示的电路中。
已知121=εV ,0.42=εV ,Ω=0.21R ,Ω=0.12R ,Ω==0.443R R 。
求:(1)通过各电阻的电流。
(2)A 、B 两点间的电压。
2.用波长λ=632.8nm 的红光垂直入射到平面光栅上,测得第一级主极大的偏角381=θ(sin38°≈0.6157)。
兰州交通大学《铁路运输组织学》试卷-答案

班级:姓名:学号:密封线兰州交通大学试卷(主卷)姓名班级学号一、填空题(每空1分,共20分)1.根据铁路运输及其管理的特点,一般将客流分为三种,包括直通客流、。
2.按照铁道部二○○四年列车运行图的规定,旅客列车分为四个等级,包括3__456.7.员组成,合称“三乘”。
8.二、名词解释(每题3分,共15分)1.2.核心货物3.旅客周转量4.旅客最高聚集人数5.特定运价三、简答题(每题4分,共20分)课程铁路运输组织学A卷分数班级: 姓名: 学号: 密封线兰州交通大学试卷(附卷)答:旅客、行包、车辆在客运站内的集散活动,产生一定的流动过程和路线,通常称为流线。
流线主要有两种分类方法,客运站流线从流动方向上可以分为进站和出站两大流线;从流动性质上可分为旅客流线、行包流线和车辆流线。
3. 简要说明铁路货场出车安排的主要内容和具体方法,这样做的经济意义?答:(1)定点、定线、定编组内容出车,也就是按列车的到达站、运行线和列车编组计划的要求整列或成组出车。
①重车出车内容,应按照本站或前方技术站的列车编组计划的组号组织成组装车或成列装车②重车出车时间,应根据空车来源,保证足够的装车、取送作业、列车编组时间和出发时间。
③卸大于装的车站,要求整列排空时,首先应按排排空空车。
(2)按阶段定时、定内容出车,即将一个班分成几个阶段,规定出车时间和出车内容,但不规定数量。
这是大货场采用的,有利于货场均衡作业,也使调车作业有规律。
(3)按指定作业列车的要求出车。
由于中间站车流一般是摘挂列车,必须按指定作业列车的到发时间、要求和内容出车,保障车流及时输出,是中间站采用的。
4. 简要说明影响货物能否受理的各种因素?答:影响货物能否受理的因素主要包括货物的性质、办理站业务范围、发到站起重能力、货物外型尺寸和包装、证明文件、技术资料以及停限装情况等。
5. 简要叙述货运业务集中化的概念和意义?答:货运业务集中化是指对路网上的货运营业站和部分运输线路的布局进行调整,停办运量小的车站、专用线或运输线路的货运业务,把货运作业集中在较大的货运营业站办理,加大货运营业站距离。
《兰州交通大学》外国语学院试卷A班一级A卷

装订线班级:姓名:学号:密封线兰州交通大学外国语学院试卷教学班号:Memorization (10point)Blanks (5points)Translation (E-C)(10points)Translation (C-E)(10points)Objective Scores (65points)TotalPart IIIMemorization (10points)81.___________82.__________83.__________84.__________85.__________86.___________87.__________88.__________89.__________90.__________Part IVBlank-Filling (5points )91.___________92.__________93.__________94.__________95.__________96.__________97.__________98.__________99.__________100.__________Part V Translation from English to Chinese (10points)101.:_________________________________________________________________________________________________________________________________________102.:_________________________________________________________________________________________________________________________________________103:_________________________________________________________________________________________________________________________________________104.:_________________________________________________________________________________________________________________________________________105.:_________________________________________________________________________________________________________________________________________Part VI Translation from Chinese to English (10points)106:_________________________________________________________________________________________________________________________________________107:________________________________________________________________________________________________________________________________________108:_________________________________________________________________________________________________________________________________________109:_________________________________________________________________________________________________________________________________________110:________________________________________________________________————————————————————————————————————Course :College English Test (Band I,A 班)Paper :A (1-3-2006)ScoreScore学生教学序号:__________________________ScoreScore勤学习祝成功守纪律莫舞弊共9页第9页班级:姓名:学号:勤学习祝成功守纪律莫舞弊共9页第1页装订线班级:姓名:学号:密封线兰州交通大学外国语学院试卷(主卷)考题书写要求:上下不得超过黑线两端点重要提示:1.阅读考试时间17:10----19:10总时为2小时2.此次考试不得提前交卷,否则视为作弊3.请各位同学在答题纸上写出所在教学班的个人序号Part IReading (40points)(60minutes)Section A Reading Comprehension (30points)Directions:Read the following 4passages and try to answer the questions as required.Passage 1One thing that needs discussion is the problem of finger pointing in reading an article.Many people consider it to be a very bad habit.Teachers in preschools or kindergartens are continually faced with children whose finger is planted firmly under the words they are learning to read.Children seem to feel that with their finger,they can more easily guide their eyes to the part of the page they wish to read.Many teachers discourage this,however,insisting that the child take his finger off the page and “read properly.”Why?The answer is not clear.I have asked a number of teachers (and teachers of teachers)and the answer usually is that the fingers “slow the child down.”This may be true if the child feels safe with his finger under a word and does not wish to move on to the next word.But it is not a perfect answer.For surely if the finger is placed on the book by the child because it helps his eyes,and if the teacher feels that the actual placing of the finger slows the child down,then the answer is not to tell the child to take his finger off the page,but to tell him to speed it up.If you happen to be a finger-pointer,don’t be too worried –it is a natural habit and,if used properly,may lead to a great increase in reading speed.To begin with,you may find difficulty in speeding up your finger,because you will have become used to a certain rhythm and speed,but if you keep on,solid gains should not be too far away.(277words)1.The passage is concerned primarily with ________.A)relationships between teachers and preschool children B)reading speed and comprehensionC)the problem of finger pointing in reading an article D)how to get rid of bad habits in reading2.The reason many teachers discourage finger pointing is that ________.A)the finger may probably take the child’s attention away B)finger pointing may slow down a child’s reading speedC)finger pointing prevents a child from understanding properly D)the finger covers some words the child is going to read 3.Children who are finger-pointers ________.A)use their fingers as a guide of their eyes while readingB)realize that finger-pointing is a bad habit but can’t help doing so C)are usually careless and very slow language readersD)do not know where to put their fingers if not placing them under words 4.The attitude of the writer towards finger-pointing in reading ________.A)negative B)active C)positive D)passive5.According to the passage,finger-pointing in reading ________.A)slows reading down B)is a bad habit C)speeds reading up D)is a natural habit Passage 2Nuclear power’s danger to health,safety,and even life itself can be summed up in one word:radiation.Nuclear radiation has a certain mystery about it,partly because it cannot be detected by human senses.It can’t be seen or heard,or touched or tasted,even though it may be all around us.There are other things like that.For example,radio waves are all around us but we can’t detect them,sense them,without a radio receiver.Similarly,we can’t sense radioactivity without radiation detector.But unlike common radio waves,nuclear radiation is not harmless to human beings and other living things.At very high levels,radiation can kill an animal or human being outright by killing masses of cells in vital organs.But even the lowest level of radiation can do serious damage.There is no level of radiation that is completely safe.If the radiation does not hit anything important,the damage may not be significant.This is the case when only a few cells are hit,and if they are killed outright,your body will replace the dead cells with healthy ones.But if the few cells are only damaged,and if they reproduce themselves,you may be trouble.They reproduce themselves in a deformed way.They can grow into cancer.Sometimes this does not show up for many years.This is another reason for some of the mystery about the nuclear radiation.Serious damage can be done without the victim being aware at the time that damage has occurred.A person can be irradiated and feel fine,then die of cancer five,ten,or twenty years later as a result.Or a child can be born week or liable to serious illness as result of radiation absorbed by its grandparents.Radiation can hurt us.We must know the truth.College English Test Band I (A 班)Paper A (2006-1-3)勤学习祝成功守纪律莫舞弊共9页第2页装订线班级:姓名:学号:密封线兰州交通大学外国语学院试卷考题书写要求:上下不得超过黑线两端点6.According to the author,the danger of nuclear power lies in ____.A.nuclear mystery B.nuclear radiation C.radiation level D.radiation detection7.Which of the following statements is NOT true according to the passage?A.Radiation can cause serious consequences at high levels.B.Radiation can cause serious consequences cause serious consequences when a fewcells are damaged and they reproduce themselves,C.Radiation can be safe at the lowest level.D.Radiation may not cause serious problem when only a few cells are hit and if they arekilled outright.8.The word “significant”in Paragraph 3has the similar meaning with _____.A.meaningful B.fatal C.remarkable D.harmful 9Radiation can hurt us in that it can _____A.affect the healthy growth of our offspringB.damage cells which may grow into cancer years laterC.kill large numbers of cells in main organs so as to cause death immediatelyD.all of the above10.What is the author’s main purpose in writing this passage?A.Emphasizing the importance of protection from radiation.B.Solving the mystery of radiation.C.Discussion the cause of the cancer.D.Introducing the nuclear power..Passage 3Trees are useful to man in three important ways :they provide him with wood and other products;they give him shade;and they help to prevent droughts and floods.Unfortunately,in many parts of the world,man has not realized that the third of these services is the most important.In his eagerness to make money from trees,he has cut them down in large numbers,only to find that without them he has lost the best friends he had.And besides,he is usually too careless to plant and look after new trees.So the forests slowly disappear.This does not only mean that man will have fewer trees.The results are even more serious:for where there are trees,their roots break up soil---allowing the rain to sink in ---and also bind the soil,thus preventing it from being washed away easily;but where there are no trees,the rain falls on hard ground and flows away,causing floods and carrying away the rich top-soil.When all the top-soil is gone,nothing remains but worthless desert.Two thousand years ago a rich and powerful country cut down its trees to build warships,with which to gain itself an empire.It set up the empire but,without its trees,itsoilits soil became poor and it grew weak.When the empire fell to pieces,the home country found itself faced with floods and starvation.11.What is the most important service of trees to man according to the passage?A.They help him make money.B.They give him wood and other products.C.They help him prevent droughts and floods.D.They give him shade.12.Why do forests in many parts of the world slowly disappear?A.New trees are not looked after properly.B.Many trees have been cut down by man.C.Man has not paid enough attention to planting trees.D.All of the above.13.Why did the country mentioned in the passage suffer from floods and starvation?A.Because an empire was set up.B.Because the empire fell to pieces.C.Because it lost all its trees.D.Because too much had been spent on wars.14.Why does land become desert after all trees are cut down?A.Because nothing remains on land except floods.B.Because there are no longer trees to keep the rain and protect the top-soil.C.Because too much rain sinks in and washes away the top-soil.D.Because roots of the trees break up the soil.15.What does the author tell us in this passage?A.How trees help prevent droughts and floods.B.The relationship between trees and man.C.How an empire fell to pieces in ancient times.D.A story of trees.Passage 4People travel for a lot of reasons.Some tourists go to see battlefields or religious shrines.Others are looking for culture,or simply want to have their picture taken in front of famous places.But most European tourists are looking for a sunny beach to lie on.Northern Europeans are willing to pay a lot of money and put up with a lot of inconveniences for the sun because they have so little of it.Residents of cities like London,Copenhagen,and Amsterdam spend a lot of their winter in the dark because the days are so short,and much of the rest of the year in the rain.This is the reason the Mediterranean has always attracted them.Every summer,more than 25million people travel to Mediterranean resort and beaches for their vacation.Theyall come for the same reason:sun!。
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兰州交通大学
2006年攻读硕士学位研究生入学考试试题
考试科目代码及名称:806材料力学
注意:所有答案必须全部写在答题纸上,写在试卷上无效。
考试结束后,必须把答题纸和试卷都装在试卷袋中。
一、填空题:请将划线处的正确答案写在答题纸上(每空2分,共28分)
1. 塑性材料拉伸试验应力超过屈服极限后逐渐卸除荷载,经过短时间后重新加载,其__将得到提高,而__变形将减小。
2. 工程上将延伸率δ≥__的材料称为塑性材料。
3. 杆件的基本变形是__、__、__、__。
4. 低碳钢圆截面试件受扭转时,沿__截面破坏;铸铁圆截面试件受扭转时,沿__破坏。
5. 连接件由两个铆钉铆接,铆钉直径均为d,钢板厚度均为t,则铆钉剪切面上的切应力为__;挤压应力为__。
6.已知yz轴为平面图形的形心轴,则图形对y轴的惯性矩I y=__,对y1轴的惯性矩I y1=__。
7. 图示重量为W 的重物从高度h 处自由下落在梁E 截面处,梁上C 截面的动应力σd =K d σst ,其中K d =1+st
h ∆+
21。
式中st ∆为静荷载作用下梁上__点的挠度。
二、单项选择题:请将划线内的正确答案的序号写在答题纸上(每小题2分,共12分)
1. 直梁横截面面积一定,试问下图所示四种截面形状中,哪一种抗弯能力最强__。
A. 矩形
B. 工字形
C. 圆形
D. 正方向
2. 偏心拉伸(压缩)实质上是__的组合变形。
A. 两个平面弯曲
B. 轴向拉伸(压缩)与平面弯曲
C. 轴向拉伸(压缩)与剪切
D. 平面弯曲与扭转
3. 用积分法求图示梁的挠曲线方程时,确定积分常数的四个条件,
除ωA=0,ØA=0外,另外两个条件是__。
A.ωC左=ωC右,ØC左=ØC右
B.ωC左=ωC右,ωB=0
C. ωC≠ 0,ωB=0
D.ωB≠ 0,ØC=0
4.图中应力圆a、b、c表示的应力状态分别为__。
A.二向应力状态、纯剪切应力状态、三向应力状态
B.单向拉应力状态、纯剪切应力状态、单向拉应力状态
C.单向压应力状态、纯剪切应力状态、单向拉应力状态
D.单向拉应力状态、单向压应力状态、纯剪切应力状态
5.矩形截面的截面核心形状为__。
A.矩形
B. 菱形
C.正方形
D.三角形
6.T形截面铸铁材料悬臂梁受力如图,轴Z为中性轴,横截面合理布置的方案为__。
A B C D
三、计算题
1、(12分)外伸梁AC承受荷载如图所示,Me =40kN.m,q=20kN.m。
试做梁的剪力图、弯矩图。
2、(18分)当矩形截面钢拉伸试样的轴向拉力F=20kN时,测得试样中段B点处与其轴线成30°方向的线应变ε30°=3.25×10-4.已知材料的弹性模量E=210Gpa,试求泊松比ν。
(单位:㎜)
3、(20分)图示受载结构,AB为T字形截面铸铁梁,I Z=5312cm4,
Mpa,[σc]=90Mpa;CD为两端铰支许用拉、压应力分别为[σ
τ]=30
的圆截面杆,直径d=40㎜,材料为A3钢,σp=200Mpa,E=200Gpa,a=304Mpa,b=112Mpa(中柔度杆的临界应力公式为σcr=a-bλ),稳定安全系数n st=2.5。
校核梁的强度和CD杆的稳定性。
4、(15分)直径为d 的圆截面钢杆处于水平面内,AB 垂直于CD ,铅垂作用力F 1=2kN ,F 2=6kN ,如图所示。
已知d =7cm ,材料的许用应力[σ]=110Mpa 。
使用第三强度理论校核该杆的强度。
5、(25分)图示结构,已知EI 、EA 、a 、q ,且=Aa 2/3,用能量法求B 点的垂直位移。
6、(20)分重物P 以初速v 自H 处下落至杆顶,证明动荷系数
K d =1+st g v H ∆++2
21。