河南省新郑一中09届高三上学期第二次月考试题(9-20)
郑州第一中学2024届高三第二轮复习质量检测试题数学试题
郑州第一中学2024届高三第二轮复习质量检测试题数学试题注意事项：1．答卷前，考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。
用2B 铅笔将试卷类型（B ）填涂在答题卡相应位置上。
将条形码粘贴在答题卡右上角"条形码粘贴处"。
2．作答选择题时，选出每小题答案后，用2B 铅笔把答题卡上对应题目选项的答案信息点涂黑；如需改动，用橡皮擦干净后，再选涂其他答案。
答案不能答在试题卷上。
3．非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新答案；不准使用铅笔和涂改液。
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一、选择题：本题共12小题，每小题5分，共60分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1．如图，正方体的底面与正四面体的底面在同一平面α上，且//AB CD ，若正方体的六个面所在的平面与直线CE EF ，相交的平面个数分别记为m n ，，则下列结论正确的是（ ）A ．m n =B ．2m n =+C ．m n <D ．8m n +<2．已知椭圆C 的中心为原点O ，(25,0)F -为C 的左焦点，P 为C 上一点，满足||||OP OF =且||4PF =，则椭圆C 的方程为（ ）A ．221255x y +=B ．2213616x y +=C ．2213010x y += D ．2214525x y += 3．如图，设P 为ABC ∆内一点，且1134AP AB AC =+，则ABP ∆与ABC ∆的面积之比为A ．14 B ．13 C ．23D ．164．若实数,x y 满足不等式组2,36,0,x y x y x y +≥⎧⎪-≤⎨⎪-≥⎩则3x y +的最小值等于（ ）A ．4B ．5C ．6D ．75．已知ABC 是边长为3的正三角形，若13BD BC =，则AD BC ⋅=A ．32- B ．152 C ．32D ．152-6．做抛掷一枚骰子的试验，当出现1点或2点时，就说这次试验成功，假设骰子是质地均匀的.则在3次这样的试验中成功次数X 的期望为（ ） A ．B ．C ．1D ．27．已知等差数列{}n a 的公差为2-，前n 项和为n S ，1a ，2a ，3a 为某三角形的三边长，且该三角形有一个内角为120︒，若n m S S ≤对任意的*n ∈N 恒成立，则实数m =（ ）. A ．6B ．5C ．4D ．38．执行如图所示的程序框图，则输出的S 的值是（ ）A ．8B ．32C ．64D ．1289．函数()()()sin 0,0f x x ωϕωϕπ=+><<的图象如图所示，为了得到()cos g x x ω=的图象，可将()f x 的图象（ ）A ．向右平移6π个单位 B ．向右平移12π个单位C ．向左平移12π个单位D ．向左平移6π个单位 10．已知函数()cos f x x m x =+，其图象关于直线3x π=对称，为了得到函数()g x x =的图象，只需将函数()f x 的图象上的所有点（ ） A ．先向左平移6π个单位长度，再把所得各点横坐标伸长为原来的2倍，纵坐标保持不变 B ．先向右平移6π个单位长度，再把所得各点横坐标缩短为原来的12，纵坐标保持不变 C ．先向右平移3π个单位长度，再把所得各点横坐标伸长为原来的2倍，纵坐标保持不变 D ．先向左平移3π个单位长度，再把所得各点横坐标缩短为原来的12，纵坐标保持不变 11．已知命题p ：1m =“”是“直线0x my -=和直线0x my +=互相垂直”的充要条件；命题q ：对任意()2,∈=+a R f x x a 都有零点；则下列命题为真命题的是（ ）A ．()()p q ⌝∧⌝B ．()p q ∧⌝C ．p q ∨D ．p q ∧12．下列函数中，值域为R 的偶函数是（ ） A ．21y x =+B ．x x y e e -=-C ．lg y x =D．y 二、填空题：本题共4小题，每小题5分，共20分。
河南省新郑市第一中学2017-2018学年高三9月月考化学试题 Word版含解析
河南省新郑市第一中学2017-2018学年度高三化学9月月考试题（解析版）1．下列事实中，不能用勒夏特列原理解释的是（）A．开启啤酒后，瓶中马上泛起大量泡沫B．钢铁在潮湿的空气中容易生锈C．实验室中常用排饱和食盐水的方法收集氯气D．工业上生产硫酸的过程中使用过量的空气以提高二氧化硫的利用率【解答】答案B：勒夏特列原理研究的对象是可逆反应，A、开启啤酒后，降低压强，使反应向气体增大方向进行，产生大量气泡，符合勒夏特列原理，故错误；B、不涉及可逆反应，不符合勒夏特列原理，故正确；C、Cl2＋H2O H＋＋Cl－＋HClO，饱和食盐水提供Cl－，增加生成物的浓度，平衡向逆反应方向移动，符合勒夏特列原理，故错误；D、2SO2＋O22SO3，增大O2的浓度，平衡向正反应方向移动，符合勒夏特列原理，故错误。
考点：考查勒夏特列原理、钢铁的腐蚀等知识。
2．下列说法正确的是（）A．由F原子形成1molF—F键要吸收热量B．所有燃烧反应都要有氧气参与且都是放热反应C．酸碱之间的中和反应都是放热反应D．吸热反应必须加热才能进行【解答】答案C，由原子形成分子时放出热量，A不正确；燃烧反应不一定要有氧气参加，如H2可以在氯气中燃烧，B不正确；中和反应都是放热反应，C正确；有的吸热反应在常温下就能进行，如氢氧化钡和氯化铵反应，D不正确。
3．为了除去粗盐中的Ca2+、Mg2+、SO42—及泥沙，可将粗盐溶于水，然后进行下列六步操作：①过滤，②加稍过量的NaOH溶液，③向滤液中加适量盐酸，④加稍过量的Na2CO3溶液，⑤加稍过量的BaCl2溶液，⑥将滤液蒸发结晶。
下列各组操作顺序合理的是A．②④⑤①③⑥ B．⑤②④①③⑥C．④②⑤①③⑥ D．②⑤④③①⑥【解答】答案B：要先用氯化钡除硫酸根离子，然后再用碳酸钠除Ca2+，Na2CO3还可以除去过量的钡离子，所以碳酸钠一定加在氯化钡的后面，如果加反了，过量的钡离子就没法除去，加氢氧化钠除去镁离子顺序可在除硫酸根离子前或后都行，不受限制，将三种离子除完，过滤，最后加盐酸除去过量的氢氧根离子碳酸根离子，将滤液蒸发结晶得到氯化钠晶体，正确的操作顺序是⑤②④①③⑥，答案选B。
新郑一中分校0910届高三理科第二次月考生物
新郑一中分校09-10届高三理科第二次月考生物试卷一、选择题:每题只有一个最佳选项.1.关于水平衡调节的叙述中,正确的是 ( )A.水排出的途径中,只有肾脏一条途径能调节水的平衡B.不含水的饼干不能提供水的来源C.人体每天摄入的水和排出的水的量是绝对相等的D.水排出的四条途径都能以水的摄入量调节水的排出量2.关于水盐平衡调节的有关叙述中,正确的是 ( )A.钠盐可以使抗利尿激素释放增多B.钾盐可以使抗利尿激素释放C.保水的激素可以保盐D.保盐的激素可以保水3.下列关于内环境稳态调节的描述正确的是 ( )A.所有调节都有反射弧的参与B.所有的稳态都是相对的C.所有稳态的形成都有许多系统参与D.所有稳态的调节中枢都在大脑4.关于水盐平衡调节的有关叙述中,正确的是 ( )A.肾小管在吸收水的同时吸盐B.渴的时候体内水绝对少C.肾小管对Na的重吸收要消耗能量D.抗利尿激素和醛固酮有协同作用5.在葡萄糖进入细胞的过程中 ( )A.胰岛素与葡萄糖进入细胞无关B.葡萄糖进入细胞是自由扩散C.胰岛素能促进这一过程D.只要有载体和能量葡萄糖就可顺利进入细胞6.当人主要依靠出汗维持体温稳定的时候 ( )A.外环境温度较高B.外环境湿度较大,温度高C.此刻体内产热多于散热D.体温会升高较多7.下列有关抗体作用的叙述中正确的是 ( )A.能够直接杀灭所有抗原B.和相应的抗原结合使病原体失去感染机会C.产生后能够一直保持功能D.只要是进入人体的抗原,都可以排除它8.病毒进入人体后,体内发生的免疫效应是 ( )A.细胞免疫就能消灭它B.体液免疫就能消灭它C.首先由细胞免疫发挥作用D.首先由体液免疫发挥作用9.下列对光反应的描述正确的是 ( )A.水光解产生的氧进入葡萄糖,氢参与还原CO2B.水光解产生的氧以分子态释放，氢参与固定CO2C.将光能转变成化学能储存在葡萄糖中D.水光解产生的氧以分子态释放，氢参与还原CO210.下列属于大田中增加光合作用效率的措施的是 ( )A.增加CO2浓度B.补充人工光照C.合理灌溉D.合理施肥11.现有甲、乙两种植株（均为二倍体纯种），其中甲种植株的光合作用能力高于乙种植株，但乙种植株很适宜在盐碱地种植。
河南省创新发展联盟2024-2025学年高三上学期9月月考英语试题
河南省创新发展联盟2024-2025学年高三上学期9月月考英语试题一、阅读理解Join a Zion National Park ranger (护林人) to learn about what makes Zion National Park unique. Programs are free and created for classrooms and individuals. We connect to your school or home through a free web-based program. You will be provided with a link to the video conference ahead of time via an email invite. Registration is open! Click on the program below for more information. Program 1—Chat with a RangerIn Chat with a Ranger, students learn about Zion National Park, the park service, and the life of a ranger. Students prepare and send questions ahead of time. This program can be adapted to fit different curriculum objectives, and is appropriate for any age group. Program 2—Pollination InvestigationIn this distance learning program, students will discover what pollination is and how important it is to all ecosystems. Looking at the relationship between plants and pollinators, participants will see how they have influenced each other and will be challenged to create their own perfect pollinator. Program 3—Whooo’s in the Canyon?Who left these clues behind here in the high canyons of Zion National Park? A feather, small bones, and hoot hooting in the trees can be heard as your classroom goes on a virtual hike of Zion to discover the Mexican spotted owl. Learn it about how the owl uses its special adaptations to survive in this desert environment. Program 4—The Forests, Wetlands, and Deserts of Zion This distance learning program focuses on the plants and animals that live in Zion's varying ecosystems. Students will learn about their adaptations and relationships to each other in this interactive lesson with a creative and critical thinking activity.1．Which program requires participants to make preparations in advance?A．Chat with a Ranger.B．Pollination Investigation.C．Whooo's in the Canyon?D．The Forests, Wetlands, and Deserts of Zion. 2．What can participants learn from program 3?A．Survival strategies taken by owls in the park.B．Ways to prepare a hike tour in the park.C．Threats brought by the desert environment.D．A variety of ecosystems in ZionNational Park.3．What do the listed programs have in common?A．They involve interactive activities.B．They include a virtual tour of different trails.C．They are accessible through web-based program.D．They require participants to visit the park in person.On a hot June day in 2015, I retired after 34 years of teaching high school. Then, I drove to meet my new piano teacher, Mark.I had worked for more than three decades as a busy English teacher with an endless stream of papers to mark and precious little time to experiment or learn new skills. I was determined to make up for all I had been missing. I wanted to finally master the piano and learn how to make music.I told Mark I had a specific concrete goal: to play Clair de lune by Claude Debussy, a piece I remember hearing from early childhood.Determined that there would be a day when I would totally master this piece, I set myself a deadline: I would perform before a gathering of friends on my 60th birthday. For months I did nothing but furiously (猛烈地) practise. When the day came, around 30 friends and relatives crowded into my dining room to hear me play, and aside from a few minor slips, I managed to pull it off without embarrassing myself. People clapped warmly. I made it. I had risen to a challenge, but I still didn’t feel that I was really “making music”.After that, my progress was painfully slow. I had come to hate hearing myself play music badly. I got no pleasure from the act of missing notes.I began focusing on what few things I could do: gardening and cycling. I came to understand that I didn’t have to be that man I’d always thought I ought to be. I could just do what feels good. So, after nearly five years of lessons, I quit.I still love music; I regularly go out to concerts. But now my piano does nothing more than sit silently in my dining room, displaying family photos and collecting dust. And I’m perfectly happy with that.4．Why did the author learn the piano after retiring from teaching?A．To impress his friends and relatives.B．To avoid the boredom of retirement.C．To start a new career as a concert pianist.D．To pursue a long-time passion for music. 5．What can be inferred from paragraph 4?A．The author attended a concert of piano music.B．The author performed successfully despite a few errors.C．The author felt embarrassed about his piano performance.D．The author quit his piano immediately after his 60th birthday.6．What does the author do with his piano now?A．He uses it for music lessons.B．He uses it for performance.C．He uses it for something unrelated to music.D．He plays it for personal enjoyment occasionally.7．Which of the following can best describe the author?A．Inner- directed and hardworking.B．Conventional and careless.C．Ambitious and kind-hearted.D．Lazy and pessimistic.When it comes to diatoms (硅藻类) that live in the ocean, new research suggests that photosynthesis (光合作用) is not the only strategy for accumulating carbon. Instead, these single-celled are also building biomass by feeding directly on organic carbon in the ocean.These new findings could lead researchers to reduce their estimate of how much carbon dioxide diatoms pull out of the air via photosynthesis, which in turn, could take a much closer look at the understanding of the global carbon cycle, which is especially relevant given the changing climate. The new findings were published in Science Advances on July 17, 2024.The team showed that the diatom Cylindrotheca closterium, which is found in oceans around the world, regularly performs a mix of both photosynthesis and direct eating of carbon from organic sources such as plankton (浮游生物) . In more than 70% of the water samples the researchers analyzed from oceans around the world, the team found signs of simultaneous photosynthesis and direct organic carbon consumption from Cylindrotheca closterium. The team also showed that this diatom species can grow much faster when consuming organic carbon in addition to photosynthesis. Furthermore, the new research hinted at the possibility that specificspecies of bacteria are feeding organic carbon directly to a large percentage of these diatoms living all across the global ocean. This work is based on a genome-scale metabolic modeling approach that the team used to reveal the metabolism of the diatom Cylindrotheca closterium.The team’s new metabolic modeling data support recent lab experiments suggesting that some diatoms may rely on strategies other than photosynthesis to intake the carbon they need to survive, thrive and build biomass.The UC San Diego led team is in the process of expanding the scope of the project to determine how widespread this non-photosynthetic activity is among other diatom species. 8．What’s new according to the research?A．The way of the diatom’s carbon accumulation.B．The impact of climate on diverse sea plants.C．The procedure of exploring carbon.D．The system of building biomass.9．What do the new findings make researchers more focus on?A．The causes of climate change.B．The grasp of the carbon cycle.C．The bad effect of photosynthesis on diatoms.D．A rough estimate of the amount of carbon dioxide.10．What do we know from paragraph 3?A．A large number of diatoms may feed on bacteria.B．The diatom lives on plankton.C．Water samples are key factors for the research.D．Diatom species grow faster with sufficient sunlight11．Which is the most suitable title for the text?A．Photosynthesis in Diatoms B．Plankton’s Role in OceansC．New Carbon Strategies in Diatoms D．Advances in Modeling DataAccording to a report in 2023, the World Health Organization (WHO) recommended that non-sugar sweeteners not be used as a means of achieving weight control or reducing the risk of diseases. The guideline came as a surprise. After all, the very purpose of non-sugar sweeteners-which contain little to no calories—is to help consumers control their weight and reduce their risk of disease by replacing sugar.In its report, the WHO cited evidence that long-term use of non-sugar sweeteners is associated with an increased risk of diabetes (糖尿病) and death. How is it that non-sugar sweeteners are linked to the negative health effects they’re supposed to fend off?The WHO made its recommendation after reviewing hundreds of published studies. The problem is that the overwhelming majority of these studies are observational. In such studies, subjects tend to self-report their food intake, which might not guarantee inaccuracy. More importantly, observational studies cannot determine cause and effect. Are non-sugar sweeteners causing diabetes, or are people at risk of diabetes simply more likely to consume them? Lastly, there are numerous variables that researchers can’t possibly control for in these studies that could influence the results.Randomized controlled trials (RCTs) tell a different story about non-sugar sweeteners. These studies control for variables by randomly assigning people to either a treatment or control group, and they can determine cause and effect. They show that sweeteners modestly benefit weight loss and help control blood sugar, without the negative effects seen in observational research. The downside of RCTs is that they are shorter in duration, often lasting just a few months. So negative effects could appear after longer use and we wouldn’t be able to tell from these RCTs.But we also can’t tell from observational studies, which only measure correlation and not causality (因果关系) . Changing the current situation might be hard, though. RCTs are expensive and require recruiting participants, setting up diet plans, and regularly measuring subjects’ health outcomes.For change to happen, it might need to start at the top, where science is funded Government agencies, which appropriate billions for research, should start prioritizing RCTs.12．What do the underlined phrase “fend off” probably mean in paragraph 2?A．Put out.B．Defend against.C．Keep up.D．Count on. 13．What does paragraph 3 mainly talk about?A．The WHO’s suggestions on observational studies.B．The strategies to decide cause and effect in conducting studies.C．The significance of controlling variables in observational studies.D．The limitations of the observational studies in the WHO report.14．What is a feature of RCTs according to the text?A．They cost little B．They tend to last long.C．They can control variables and determine causality.D．They require participants to self-report related data15．How should the government help RCTs?A．By making appropriate plans B．By providing financial supportC．By raising people’s awareness of health D．By founding more related governmentagenciesTo make science’s stories more concrete and engaging, it’s important to use some effective strategies. Here are four of them. Put people in the storyScience’s stories often lack human characters. 16 . Characters can be also people affected by a scientific topic, or interested in learning more about it. Besides, they can be storytellers who are sharing their personal experiences.17People often think of science as objective and fair. But science is actually a human practice that continuously involves choices, missteps and biases (偏见) . If you explain science as a course, you can walk people through the sequence of how science is done and why researchers reach certain conclusions. 18 . And they can also stress the reason why people should trust the course of science to provide the most accurate conclusions possible given the available information. Include what people care aboutScientific topics are important, but they may not always be the public’s most pressing concerns. In April 2024, a polling company found that “the quality of the environment” was one of thelowest-ranked priorities among people in the US. The stories about the environment could weave in connections to higher-priority topics. 19 . Tell science's storiesScientists, of course, can be science communicators, but everyone can tell science’s stories. When we share information online about health, or talk to friends and family about the weather, we contribute to information that circulates about science topics. 20 . Think about all of a story’s characteristics - character, action, sequence, scope, storyteller and content - and how you might incorporate them into the topic.A．Explain science as a processB．Shoot attractive short science videosC．Scientists themselves can actually become ideal onesD．This practice is to stress why the content is importantE．You can tell growth stories of remarkable teenage scientistsF．Science communicators can emphasize how science is conductedG．You may as well borrow features from stories to strengthen your message二、完形填空In 2018, Molly Baker unfortunately lost her husband in a severe skiing accident. She was 21 . In the first several weeks after his passing, her friends and family 22 a great deal of support. But after a while, the cards and meals started to 23 . “People had to get back to their normal 24 . And so things kind of dropped off,” Baker recalled.That was when one of Baker's friends, Carla Vail, thought up a way to 25 the help for an entire year. She called it the “Calendar Girls”. V ail gathered the names of 31 of Baker's friends who wanted to help, and 26 each friend a particular day. Vail also gave Baker the names on the 27 , so Baker could know what to 28 each day.“And what that looked like for them was that on that day, they would reach out to me in some 29 ways—maybe via text, or a card,” Baker said.Looking back, Baker feels that Vail's 30 was essential to helping her cope with her husband's death, because she was 31 at that time.“A lot of people are really uncomfortable around 32 ,” Baker said. “So what they do is, instead of doing something, that they 33 do nothing. It was nice to have that ‘Calendar Girls’ setup.”Today, Baker tries to do something similar for her friends going through 34 . In hard times, she knows how 35 it is to have something to look forward to every day. 21．A．cautious B．unconscious C．desperate D．impassive 22．A．extended B．demanded C．announced D．assumed 23．A．pass down B．show up C．break up D．slow down24．A．exercise B．routine C．diet D．growth 25．A．resist B．continue C．explain D．test 26．A．ordered B．sent C．owed D．assigned 27．A．furniture B．file C．calendar D．Internet 28．A．expect B．absorb C．propose D．define 29．A．rare B．strange C．specific D．generous 30．A．curiosity B．thoughtfulness C．ambition D．toughness 31．A．innocent B．optimistic C．tolerant D．lonely 32．A．panic B．evidence C．failure D．grief 33．A．simply B．hardly C．skillfully D．secretly 34．A．distraction B．addiction C．loss D．annoyance 35．A．amusing B．valuable C．astonishing D．universal三、语法填空阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。
2019-2020学年河南省新郑市第一中学高三英语月考试题及参考答案
2019-2020学年河南省新郑市第一中学高三英语月考试题及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项A“Why do I feel cold when I have a fever?” “Why does the sun rise in the east?” I knew the day would come when my little girl Sophie would learn to talk and inevitably (不可避免地) start askingthose questions. The questions themselves weren’t worrying me. I was actually looking forward to seeing where her curiosity would lie.What was bothering (烦恼) me was whether or not I would know the answers. In the age of the smartphone, this may seem like a silly worry. The answers to almost everything would be just one Google away.Still, I struggled with how I was going to prepare to become an all-knowing mother. Then one day, it struck me: I didn’t need to have all the answers. What a great example I could set if I let my daughter know that I, too, was still learning. And I realized how much more I could learn if I took another look at things I thought I already knew the answer to with the curiosity of a child. My little girl’s mind is a beginner’s mind--- curious, open to new ideas, eager to learn, and not based on knowledge that already exists. I decided that I would deal with her questions with a beginner’s mind, too.Once I decided to become more curious, I started noticing that curiosity was becoming more important in the workplace, too. It seems that leaders don't need to have all the answers, but they do need to be curious.Curious about curiosity, I searched for answers and found Albert Einstein’s famous words, “I have no special talent. I am only passionately (热情地) curious.” We mightquibble overthe view that Einstein had no special talent, but there is one thing for certain---he wouldn't have solved the puzzles of the universe without his passionate curiosity. Then I came across another Einstein quote, “The important thing is not to stop questioning. Curiosity has its own reason or existence.”1. The advantage of having a beginner’s mind is that ________.A. people can learn much faster.B. people won't be afraid to make mistakes.C. people are willing to receive new things.D. people won't be expected to answer all questions.2. What does the example of Einstein’s words show?A. Einstein was passionate about curiosity.B. Einstein’s quotes are very famous.C. Curiosity is of great significance.D. Curiosity is more necessary than talent.3. What does the underlined phrase “quibble over” in the last paragraph probably mean?A. Fight against.B. Argue about.C. Work out.D. Agree withBChimps use loud calls and gestures to make their feelings known but until now, the exact meaning for individual movements has remained a mystery. Now researchers believe they have translated the key gestures used in the chimp community and identified their intentions for the first time.From 4,351 gestures, experts were able to identify 66 that are used for 19 specific message meanings, including showing a foot to tell a child they can climb on their back. The researchers were able to narrow down these 66 gestures to 36 that are used intentionally to achieve 15 purposes. The translations were made by Dr Catherine Hobaiter and her colleagues at St Andrews University in Scotland.Dr Hobaiter used behavior sampling and filmed all recorded cases of gestural communication. Other gestures include stomping their feet to ask another chimp to stop what they are doing, and slapping objects together to ask another to follow them. Of the 19 meanings,17 encouraged interactions to start, or to develop, such as “move closer,” and “change play”. Some of the gestures were found to have more than one meaning. and only 10 of the 66 gestures were used for only a single meaning.Researchers collected a total of 471 video clips from two social groups of chimps at a shelter near Kinshasa, Democratic Republic of Congo. As well as identifying what the gesture means, they also discovered the technique needed to increase the chances of success.“Human children use gestures to communicate before they produce their first words, and their earliest gestures typically appear around 10 months of age,” explained the researchers. “In great apes, there is good evidence that language-trained individuals are capable of acquiring and understanding signals, but this is far less clear in their natural communication. ”4. Chimps slap the objects to____________.A. tell others to stop what they are doingB. ask others chimps to join themC. gather other chimps to move closerD. encourage interactions to start5. What did researchers find after studying 471 video clips?A. Chimps trained in language are good at understanding signals.B. Two social groups of chimps live at a shelter near Kinshasa.C. Language-trained individuals do well in natural communication.D. Chimps’earliest gestures appear around 10 months of age.6. How is the last paragraph developed?A. By analyzing causes.B. By examining differences.C By making comparisons. D. By following time order.7. What can be a suitable title for the text?A A New Research on Chimps B. Human Children and ChimpsC. Getting the Chimps Trained for LanguageD. Translating the Sign Language of ChimpsCWhat do you think of 80s pop music? Do the names George Michael, Madonna and Michael Jackson sound familiar? Well, these are just some of the names that were well-known in the music scene of the 80s and early 90s. The 80s pop musicscene was an important step to the popularity (普及) of present-day music. A new wave in the music scene was introduced, which made such music styles as punk rock, rap music and the MTV popular. Although it was an end to the old 60s and 70s styles, it was also the beginning of something big. The popularity of music videos meant that artists now replaced their guitar-based music with visual displays. A new wave of artists came on the scene and the entire industry developed quickly.The most famous 80s pop music video is Michael Jackson’s Thriller. Introduced in 1982, few people can forget the video not only because of its never-be-foreseen images, but also because of the popularity it received. Think of how 80s pop music changed the lives of people who grew up in the 80s. Ask a young man today to tell you the names of the “New Kids on the Block” and he will start talking about the neighbor kids who just moved in. These are not the answers you might have heard in the 80s. Though today’s young men do not recognize how cool 80s pop music was, most people will always remember it for what it was and these are happy memories they will always love.Some of the 80s pop music legends (传奇人物) include Madonna, U2, AeroSmith and of course the King of Pop Michael Jackson. Let’s not forget Prince, Tina Turner, Phil Collins and Motown’s Lionel Ritchie. Some of these musicians played music that has stood the test of time. Undoubtedly, the 80s pop music scene will live on for many more years to come.8. What is the text mainly about?A. The characters of 80s pop music.B. What made 80s pop music popular.C. 80s pop music’s steps to popularity.D. The effects of 80s pop music.9. 80s pop music mainly includes the following styles EXCEPT ________.A. guitar-based musicB. the MTVC. rap musicD. punk rock10. Michael Jackson’s Thriller impressed people so deeply mainly because ________.A. it changed the lives of peopleB. he sang it in a special styleC. it was made into a music videoD. it left people with happy memories11. The purpose of the last paragraph is to tell readers that ________.A. 80s pop music is and will remain popularB. 80s pop music has many faultsC. 80s pop music is now out of dateD. we shouldn’t forget the great musicians of the 80sDPablo Picasso was born on October25 inMalaga. Spain in 1881. Taking after his father, Picasso shared apassion（热爱）for painting and art. Even though he wasn't the best student in school, Picasso excelled at drawing. Noticing his amazing talent, Picasso's father, an artist, taught him everything he knew. Before long, Picasso could paint and draw much better than his father. With this rich talent, Picasso paid less and less attention to his schoolwork and spent the majority of his day sketching and drawing in notepads and sketchbooks.When he was a little bit older, Picasso moved twice and was accepted into two fine art programs. However, he didn't care very much for the special techniques they taught and often wandered the streets by himself drawing the scenes around him. After moving to these two places, Picasso moved back home toBarcelonaand decided that he would develop new techniques of art and painting based on what he saw.Later, Picasso decided to move toParis,France, where he began perfecting his own techniques of painting, drawing and other forms of art. His drawings. paintings, and an included pieces about sadness, poverty, classics and self-portraits. One of his major types of work is calledcubism（立体派），which includes art with all sizes of geometric shapes together on the piece of an. This type of art is very important because no other artists had come up with the idea before. Picasso decided to try something new, and as a result, cubismis widely accepted today as a classic style of art.Picasso inspires us to always be thinking. He tells us to think outside the box and come up with fresh new ideas that can change the world. He surely plays a significant role in the art field.12. What do we know about Picasso as a student at school?A. He hated doing his homework.B. He was very proud of his talent.C. He showed great talent for drawing.D. He was often praised by his teacher.13. What did Picasso's father do when he found Picasso's gift?A. He tried his best to help Picasso.B. He blamed Picasso for his laziness.C. He asked Picasso to finish his work on time.D. He encouraged Picasso to do better at school.14. What was Picasso's attitude towards the special techniques at that time?A. He thought highly of them.B. He took no interest in them.C. He was confused about them.D. He was concerned about them.15. What does the author tell us in the last two paragraphs?A. Picasso has great faith in art.B. Picasso has changed the world a lot.C. Picasso can do anything he wants to.D. Picasso is a highly creative artist.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
河南省新郑一中08-09学年高三上学期第一次全真模拟考试(语文)(有解析) (1)
河南省新郑一中08-09学年高三上学期第一次全真模拟考试（语文）本试卷分第Ⅰ卷（选择题）和第Ⅱ卷1至4页，第Ⅱ卷5至8页。
考试结束后，将本试卷和答题卡一并交回。
第Ⅰ卷注意事项：1、答题前，考生在答题卡上务必用直径0.5毫米黑色墨水签字笔将自己的姓名、准考证号填写清楚，并贴好条形码。
请认真核准条形码上的准考证号、姓名和科目。
2、每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号，在试题卷上作答无效。
3、本卷共10小题，每小题3分，共30分。
在每小题给出的四个选项中，只有一项符合题目要求。
一、（12分，每小题3分）1、下列各组词中，只有一个错别字的一组是A、态然自若侯车室额手称庆迫不及待走投无路B、名门望族吊胃口开门揖盗风生水起张皇失措C、豆蔻词工打圆场偃旗息鼓常年累月人情世故D、一愁莫展挖墙脚川流不息察言观色甘拜下风2、下列各句中，加点的成语使用不恰当的一句是A、看老房屋已摇摇晃晃就要倒塌，他急来抱佛脚．．．．．,将漂浮在水面的三根木头和门板叠加起来,把群众拉上门板坐稳,且游且推,硬是将屋内被困群众一一解救出来。
B、此外，加快供热体制改革步伐，提高供热效率也是燃眉之急．．．．。
因为，我国北方地区，建筑能耗的50％～60％在采暖上，供热效率将直接影响到建筑能耗的高低。
C、为了给大部队打开一条通路，当晚，杨得志团长率一营直奔安顺场渡口，以疾风知．．．劲草．．之势全歼右岸守敌。
D、“郡县治，则天下治”，何治郡县?牢牢抓住基层政权建设这个牛鼻子．．．，千方百计奔小康。
如此，一手抓政权建设，一手抓经济建设，两手抓，两手硬，两促进，两发展，则可得民心。
3、下列各句中，没有语病的一句是A、黎以军事冲突正在不断升级，下一个阶段将会如何还不得而知。
有位专家曾打趣说，对于中东来讲，你所做的最愚蠢的事情莫过于事先对形势进行预测。
B、随着越来越多的人把资料保存在便于携带的笔记本电脑上，“网上窃贼”也把目标对准了笔记本电脑。
河南省创新发展联盟2024-2025学年高三上学期9月月考数学试题(含解析)
2024-2025年度河南省高三年级联考（二）数学注意事项：1.答题前，考生务必将自己的姓名、考生号、考场号、座位号填写在答题卡上.2.回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑.如需改动，用橡皮擦干净后，再选涂其他答案标号.回答非选择题时，将答案写在答题卡上.写在本试卷上无效.3.考试结束后，将本试卷和答题卡一并交回.4.本试卷主要考试内容：集合与常用逻辑用语，函数与导数，三角函数，平面向量，数列，不等式.一、选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的.1.已知集合{}21A x x =-<，{}3B x a x a =<<+.，若{}15A B x x =<< ，则a =（）A.0B.1C.2D.32.已知符号）（表示不平行，向量(1,2)a =--，(,7)b m m =+ .设命题:(0,)p m ∀∈+∞，a ）（b ，则（）A.:(0,)p m ⌝∃∈+∞，//a b，且p ⌝为真命题B.:(0,)p m ⌝∀∈+∞，//a b，且p ⌝为真命题C.:(0,)p m ⌝∃∈+∞，//a b，且p ⌝为假命题D.:(0,)p m ⌝∀∈+∞，//a b，且p ⌝为假命题3.若||0a b >>，则下列结论一定成立的是（）A.22a b ab> B.2211ab a b> C.33a b< D.a c c b->-4.已知等比数列{}n a 的前n 项和为n S ，且31S ma =，则“7m =”是“{}n a 的公比为2”的（）A.必要不充分条件B.充分不必要条件C.充要条件D.既不充分也不必要条件5.已知函数3()log f x x =，若0b a >>，且a ，b 是()f x 的图像与直线(0)y m m =>的两个交点对应的横坐标，则4a b +的最小值为（）A.2B.4C.6D.86.三角板主要用于几何图形的绘制和角度的测量，在数学、工程制图等领域被广泛应用.如图，这是由两块直角三角板拼出的一个几何图形，其中||||AB AC = ，||||BD BC =，0BD BC ⋅= .连接AD ，若AD x AB y AC =+，则x y -=（）A.1B.2D.327.若0a ≠，()2ππsin 066x ax bx c ⎛⎫-++≥ ⎪⎝⎭对[0,8]x ∈恒成立，则（）A.0a > B.0bc +> C.0c > D.16b c a-=-8.已知A 是函数()e 3xf x x =+图象上的一点，点B 在直线:30l x y --=上，则||AB 的最小值是（）A.72e 22e- B.3C. D.二、选择题：本题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项符合题目要求.全部选对的得6分，部分选对的得部分分，有选错的得0分.9.设数列{}n a ，{}n b 的前n 项和分别为n S ，n T ，且3n an b =，则下列结论不正确的是（）A.若{}n a 是递增数列，则{}n S 是递增数列B.若{}n a 是递减数列，则{}n S 是递减数列C.若{}n a 是递增数列，则{}n T 是递增数列D.若{}n a 是递减数列，则{}n T 是递减数列10.已知(31)f x +为奇函数，(3)1f =，且对任意x ∈R ，都有(2)(4)f x f x +=-，则必有（）A.(11)1f =-B.(23)0f =C.(7)1f =- D.(5)0f =11.已知函数()sin sin 3f x x x =+，则（）A.()f x 的图象关于点(π,0)中心对称B.()f x 的图象关于直线π4x =对称C.()f x 的值域为⎡⎢⎣⎦D.()f x 在π3π,24⎡⎤⎢⎥⎣⎦上单调递增三、填空题：本题共3小题，每小题5分，共15分.12.在ABC △中，角A ，B ，C 的对边分别是a ，b ，c ，且1a =，3b =，1cos 3C =，则ABC △外接圆的面积是__________.13.已知某种污染物的浓度C （单位：摩尔/升）与时间t （单位：天）的关系满足指数模型(1)0ek t C C -=，其中0C 是初始浓度（即1t =时该污染物的浓度），k 是常数.第2天（即2t =）测得该污染物的浓度为5摩尔/升，第4天测得该污染物的浓度为15摩尔/升，若第n 天测得该污染物的浓度变为027C ，则n =__________.14.1796年，年仅19岁的高斯发现了正十七边形的尺规作图法.要用尺规作出正十七边形，就要将圆十七等分.高斯墓碑上刻着如图所示的图案.设将圆十七等分后每等份圆弧所对的圆心角为α，则162121tan2k k α==+∑__________.四、解答题：本题共5小题，共77分.解答应写出文字说明、证明过程或演算步骤.15.（13分）在ABC △中，角A ，B ，C 的对边分别是a ，b ，c ，4cos 5A =，2cos 3cos a C c A =.（1）求sin C 的值；（2）若3a =，求ABC △的周长.16.（15分）已知函数()sin()(0,0,0π)f x A x b A ωϕωϕ=++>><<的部分图象如图所示.（1）求()f x 的解析式；（2）求()f x 的零点；（3）将()f x 图象上的所有点向右平移π12个单位长度，得到函数()g x 的图象，求()g x 在7π0,12⎡⎤⎢⎥⎣⎦上的值域.17.（15分）已知函数3()33xx a f x ⋅=+，且()()66log 3log 122f f +=.（1）求a 的值；（2）求不等式()22310f x x +->的解集.18.（17分）已知函数2()(2)ln(1)2f x ax x x x =++--.（1）当0a =时，求()f x 的单调区间与极值；（2）当0x ≥时，()0f x ≤恒成立，求a 的取值范围.19.（17分）设数列{}n a 的前n 项和为n S ，若对任意的n +∈N ，都有2n n S kS =（k 为非零常数），则称数列{}n a 为“和等比数列”，其中k 为和公比.（1）若23n a n =-，判断{}n a 是否为“和等比数列”.（2）已知{}n b 是首项为1，公差不为0的等差数列，且{}n b 是“和等比数列”，2n b nc =，数列{}n c 的前n 项和为n T .①求{}n b 的和公比；②求n T ；③若不等式2134(1)22nn n n T m -+->--对任意的n +∈N 恒成立，求m 的取值范围.2024-2025年度河南省高三年级联考（二）数学参考答案1.C 由题意可得{}13A x x =<<.因为{}15A B x x =<< ，所以1,35a a ≥⎧⎨+=⎩，解得2a =.2.A :(0,)p m ⌝∃∈+∞，//a b ，当(7)2m m -+=-，即7m =时，//a b，所以p ⌝为真命题.3.B 当3a =，2b =-时，2218,12a b ab =-=，此时22a b ab <，则A 错误.因为||0a b >>，所以a b >，且0ab ≠，所以2210a b >，所以2211ab a b>，则B 正确.当2a =，1b =-时，338,1a b ==-，此时33a b >，则C 错误.当2a =，1b =，3c =时，1a c -=-，2c b -=，此时a c c b -<-，则D 错误.4.A 设{}n a 的公比为q ，则()23123111S a a a q q a ma =++=++=.因为10a ≠，所以21q q m ++=.由7m =，得217q q ++=，即260q q +-=，解得2q =或3q =-.由2q =，得7m =，则“7m =”是“{}n a 的公比为2”的必要不充分条件.5.B 由题意可得01a b <<<，1b a=，则44a b +≥，当且仅当42a b ==时，等号成立.故4a b +的最小值为4.6.A 如图，以A 为原点，AB ，AC的方向分别为x ，y 轴的正方向，建立直角坐标系，设1AB =，则(0,0)A ，(1,0)B ，(0,1)C ，故(1,0)AB = ，(0,1)AC =.作DF AB ⊥，交AB 的延长线于点F .设||1AB = ，则||||1BF DF ==，所以(2,1)D ，所以(2,1)AD = .因为AD x AB y AC =+，所以2,1x y ==，则1x y -=.7.B 因为[0,8]x ∈，所以πππ7π,6666x ⎡⎤-∈-⎢⎥⎣⎦.当[0,1)x ∈时，ππsin 066x ⎛⎫-< ⎪⎝⎭；当()1,7x ∈时，ππsin 066x ⎛⎫-> ⎪⎝⎭；当(7,8]x ∈时，ππsin 066x ⎛⎫-< ⎪⎝⎭.因为()2ππsin 066x ax bx c ⎛⎫-++≥ ⎪⎝⎭对[0,8]x ∈恒成立，所以1，7是20ax bx c ++=的两根，且0a <，则17,17,b ac a ⎧+=-⎪⎪⎨⎪⨯=⎪⎩故80b a =->，70c a =<，15b c a -=-，0b c a +=->.8.D由题意可得()(1)e x x f x +'=.设()()g x f x '=，则()(2)e xg x x '=+，当1x <-时，()0f x '<，当1x >-时，()0g x '>，()f x '单调递增.因为(0)1f '=，所以()(1)e 1xf x x '=+=，得0x =，此时(0,3)A ，故min ||AB ==.9.ABD当7n a n =-时，{}n a 是递增数列，此时{}n S 不是递增数列，则A 错误.当12n a n =-+时，{}n a 是递减数列，此时{}n S 不是递减数列，则B 错误.由{}n a 是递增数列，得{}n b 是递增数列，且0n b >，则{}n T 是递增数列，故C 正确.由{}n a 是递减数列，得{}n b 是递减数列，且0n b >，则{}n T 是递增数列，故D 错误.10.CD由(31)f x +为奇函数，可得(31)(31)f x f x -+=-+，则()f x 的图象关于点(1,0)对称.又(2)(4)f x f x +=-，所以()f x 的图象关于直线3x =对称，则()f x 是以8为周期的周期函数，所以(7)(3)1f f =-=-，(5)(1)0f f ==，(11)(3)1f f ==，(23)(7)1f f ==-，故选CD.11.ACD因为(π)(π)sin(π)sin 3(π)sin(π)sin 3(π)0f x f x x x x x ++-=++++-+-=，所以()f x 的图象关于点(π,0)中心对称，则A 正确.由题意可得()sin sin 32sin 2cos f x x x x x =+=，则ππππ2sin 2cos 2cos 2cos 4244f x x x x x ⎛⎫⎛⎫⎛⎫⎛⎫+=++=+ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭，ππππ2sin 2cos 2cos 2cos 4244f x x x x x ⎛⎫⎛⎫⎛⎫⎛⎫-=--=- ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭，所以ππ44f x f x ⎛⎫⎛⎫+≠- ⎪ ⎪⎝⎭⎝⎭，所以()f x 的图象不关于直线π4x =对称，则B 错误.由题意可得3()2sin 2cos 4sin 4sin f x x x x x ==-.设sin [1,1]t x =∈-，则3()44y g t t t ==-+，故()22()124431g t t t '=-+=--.由()0g t '>，得3333t -<<；由()0g t '<，得313t -≤<-或313t <≤，则()g t 在31,3⎡⎫--⎪⎢⎣⎭和3,13⎛⎤⎥⎝⎦上单调递减，在33,33⎛⎫- ⎪⎝⎭上单调递增.因为(1)(1)0g g -==，38339g ⎛⎫-=- ⎪⎝⎭，38339g ⎛⎫=⎪⎝⎭，所以8383()99g t ⎡∈-⎢⎣⎦，即()f x 的值域是838399⎡-⎢⎣⎦，则C 正确.当π3π,24x ⎡⎤∈⎢⎥⎣⎦时，2sin 2t x ⎤=∈⎥⎣⎦.因为sin t x =在π3π,24⎡⎤⎢⎥⎣⎦上单调递减，且()g t在,13⎤⎥⎣⎦上单调递减，所以()f x 在π3π,24⎡⎤⎢⎥⎣⎦上单调递增，则D 正确.12.9π4由余弦定理可得22212cos 1921383c a b ab C =+-=+-⨯⨯⨯=，则c =因为1cos 3C =，所以22sin 3C =，则ABC △外接圆的半径32sin 2c R C ==，故ABC 外接圆的面积为29ππ4R =.13.7由题意可得030e 5,e 15,k kC C ⎧=⎨=⎩则2e 3k =，解得ln32k =.因为(1)00e 27k n C C -=，即3ln(1)200e 27n C C -=，所以ln 3(1)2e 27n -=，所以ln 3(1)ln 273ln 32n -==，解得7n =.14.15由题可知2π17α=，则222π11tan 1tan π217cos 17k k k α+=+=，则161616162211112π2π2π2cos 1cos 16cos 1717171tan 2k k k k k k k k α====⎛⎫==+=+ ⎪⎝⎭+∑∑∑∑.由161611π2π(21)π(21)π33πππ2sin cos sin sin sin sin 2sin 17171717171717k k k k k ==+-⎡⎤⋅=-=-=-⎢⎥⎣⎦∑∑，得1612πcos117k k ==-∑，故原式16115=-=.15.解：（1）因为4cos 5A =，且0πA <<，所以3sin 5A ==.因为2cos 3cos a C c A =，所以2sin cos 3sin cos A C C A =，所以342cos 3sin 55C C ⨯=⨯，即cos 2sin C C =.因为22sin cos 1C C +=，所以21sin 5C =.因为0πC <<，所以5sin 5C =.（2）由（1）可知3sin 5A =，4cos 5A =，5sin 5C =，25cos 5C =，则3254525sin sin()sin cos cos sin 55555B AC A C A C =+=+=⨯+⨯=.由正弦定理可得sin sin sin a b cA B C==，则sin sin a B b A ==sin sin a Cc A==，故ABC △的周长为3a b c ++=+.16.解：（1）由图可知3(1)22A --==，3(1)12b +-==，()f x 的最小正周期7ππ2π1212T ⎛⎫=-= ⎪⎝⎭.因为2π||T ω=，且0ω>，所以2ω=.因为()f x 的图象经过点π,312⎛⎫⎪⎝⎭，所以ππ2sin 2131212f ϕ⎛⎫⎛⎫=⨯++= ⎪ ⎪⎝⎭⎝⎭，即πsin 16ϕ⎛⎫+=⎪⎝⎭，所以ππ2π()62k k ϕ+=+∈Z ，即π2π()3k k ϕ=+∈Z .因为0πϕ<<，所以π3ϕ=.故π()2sin 213f x x ⎛⎫=++ ⎪⎝⎭.（2）令()0f x =，得π1sin 232x ⎛⎫+=- ⎪⎝⎭，则ππ22π()36x k k +=-∈Z 或π5π22π()36x k k +=-∈Z ，解得ππ4x k =-或7ππ()12k k -∈Z ，故()f x 的零点为ππ4k -或7ππ()12k k -∈Z .（3）由题意可得πππ()2sin 212sin 211236g x x x ⎡⎤⎛⎫⎛⎫=-++=++ ⎪ ⎪⎢⎝⎭⎝⎭⎣⎦.因为7π0,12x ⎡⎤∈⎢⎥⎣⎦，所以ππ4π2,663x ⎡⎤+∈⎢⎥⎣⎦.当ππ262x +=，即π6x =时，()g x 取得最大值π36g ⎛⎫= ⎪⎝⎭；当π4π263x +=，即7π12x =时，()g x 取得最小值7π112g ⎛⎫=- ⎪⎝⎭.故()g x 在7π0,12⎡⎤⎢⎥⎣⎦上的值域为1⎡⎤⎣⎦.17.解：（1）因为3()33x x a f x ⨯=+，所以221393(2)333933x x x x a a af x --+⨯-===+++，则33()(2)3333x xx a a f x f x a ⨯+-=+=++.又666log 3log 12log 362+==，所以()()66log 3log 12f f a +=，从而2a =.（2）由（1）可知236()23333x x x f x ⨯==-++，显然()f x 在R 上单调递增.因为1(0)2f =，所以由()22310f x x +->，可得()23(0)f x x f +>，则230x x +>，解得3x <-或0x >，故不等式()22310f x x +->的解集为(,3)(0,)-∞-+∞ .18.解：（1）当0a =时，2()2ln(1)2f x x x x =+--，其定义域为(1,)-+∞，则()222(2)22111x x x x f x x x x x ---+'=--==+++.当(1,0)x ∈-时，()0f x '>，()f x 的单调递增区间为(1,0)-，当(0,)x ∈+∞时，()0f x '<，()f x 的单调递减区间为(0,)+∞，故()f x 的极大值为(0)0f =，无极小值.（2）设1t x =+，[1,)t ∈+∞，2()(2)ln 1g t at a t t =+--+，[1,)t ∈+∞，则2()ln 2at a t t a tg -=+-+'.设()()h t g t '=，则222222()2a a t at a h t t t t --++-'=--=.设2()22m t t at a =-++-，则函数()m t 的图象关于直线4at =对称.①当2a ≤时，()m t 在[1,)+∞上单调递减.因为(1)240m a =-≤，所以2()220m t t at a =-++-≤在[1,)+∞上恒成立，即()0h t '≤在[1,)+∞上恒成立，则()h t 在[1,)+∞上单调递减，即()g t '在[1,)+∞上单调递减，所以()(1)0g t g ''≤=，所以()g t 在[1,)+∞上单调递减，则()(1)0g t g ≤=，即()0f x ≤在[0,)+∞上恒成立，故2a ≤符合题意.②当2a >时，()m t 在[1,)+∞上单调递减或在[1,)+∞上先增后减，因为(1)240m a =->，所以存在01t >，使得()00m t =.当()01,t t ∈时，()0m t >，即()0h t '>，所以()g t '在()01,t 上单调递增.因为(1)0g '=，所以()0g t '>在()01,t 上恒成立，所以()g t 在()01,t 上单调递增，则()0(1)0g t g >=，故2a >不符合题意.综上，a 的取值范围为(,2]-∞.19.解：（1）因为23n a n =-，所以121n a n +=-，所以12n n a a +-=.因为11a =-，所以{}n a 是首项为-1，公差为2的等差数列，则22n S n n =-，所以2244n S n n =-，所以222444422n n S n n n S n n n --==--.因为442n n --不是常数，所以{}n a 不是“和等比数列”.（2）①设等差数列{}n b 的公差为d ，前n 项和为n S ，则21(1)1222n n n d d S nb d n n -⎛⎫=+=+- ⎪⎝⎭，所以222(2)n S dn d n =+-.因为{}n b 是“和等比数列”，所以2n n S kS =，即222(2)22kd kd dn d n n k n ⎛⎫+-=+- ⎪⎝⎭，所以2,22,2kd d kd d k ⎧=⎪⎪⎨⎪-=-⎪⎩解得4,2,k d =⎧⎨=⎩即{}n b 的和公比为4.②由①可知12(1)21n b n n =+-=-，则212n n n c -=，所以35211232222n n n T -=++++ ，所以2352121112122222n n n n nT -+-=++++ ，所以235212121211122311111422222212nn n n n n n T -++⎡⎤⎛⎫⨯-⎢⎥ ⎪⎝⎭⎢⎥⎣⎦=++++-=- ，即2132344332n n n T ++=-⨯，所以21834992nn n T -+=-⨯.③设2121212134834348103429922992n n n n n n n n n n P T ----++++=-=--=-⨯⨯，12121103710345(1)092924n n n n nn n n P P ++-+++-=-⨯+⨯=>.不等式2134(1)22n n n n T m -+->--对任意的n +∈N 恒成立，即不等式(1)2n n P m >--对任意的n +∈N 恒成立.当n 为奇数时，()1min 23n m P P --<==-，则1m >；当n 为偶数时，()2min 122n m P P -<==-，则32m <.综上，m 的取值范围是31,2⎛⎫⎪⎝⎭.。
河南省创新发展联盟2024-2025学年高三上学期9月月考物理试题(含解析)
2024—2025年度河南省高三年级联考（二）物理本试卷满分100分，考试用时75分钟。
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一、选择题：本题共10小题，共46分。
在每小题给出的四个选项中，第1~7题只有一项符合题目要求，每小题4分；第8~10题有多项符合题目要求，每小题6分，全部选对的得6分，选对但不全的得3分，有选错的得0分。
1．关于汽车和高铁列车启动过程中的速度和加速度，下列说法正确的是（）A ．高铁列车匀速运动时的速度大，说明高铁列车的加速度一定大B ．高铁列车的速度变化量大，说明高铁列车的加速度一定大C ．在相同时间内，汽车的速度变化量越大，汽车的加速度越大D ．在相同时间内，汽车的位移越小，汽车的加速度越小2．在2024年巴黎奥运会网球女子单打决赛中，中国选手以2:0击败克罗地亚选手，成为中国网球史上首位奥运单打冠军，不计网球受到的空气阻力，下列说法正确的是（）A ．研究运动员的击球动作时，可以将运动员看成质点B ．网球在上升和下降过程中的加速度相同C ．网球向上运动到最高点之前处于超重状态，经过最高点之后向下运动处于失重状态D ．接球过程中，因为网球发生了形变，所以网球拍才对网球产生弹力3．河南博物院是面积仅次于故宫博物院的宝藏级展馆，暑假期间，甲、乙两同学相约去河南博物院参观，两人同时从各自家中出发，沿着同一直线相向而行，经过一段时间后两人会合，身上携带的运动传感器分别记录了他们在这段时间内的速度大小随时间变化的关系，如图所示。
其中，甲的速度大小随时间变化的图线为两段四分之一圆弧，422t t ，则（）A ．在1t 时刻，甲的速度大于乙的速度B ．在20~t 时间内，甲、乙所走的路程相等C ．在3t 时刻，甲、乙两人的加速度大小不可能相等D ．在40~t 时间内，甲、乙两人的平均速度大小相等4．如图所示，轻杆的一端固定在一光滑球体上，杆的另一端O 为自由转动轴，固定在竖直墙壁上，球体搁置在各面均光滑的斜面体上。
郑州市高三上学期语文9月月考试卷A卷
郑州市高三上学期语文9月月考试卷A卷姓名:________ 班级:________ 成绩:________一、选择题 (共4题；共8分)1. （2分）下面语段中划线的词语，使用不恰当的一项是（）。
虽然国家对“低碳”理念大力宣传，同时有关部门也制定并颁布了相关的法律法规对行业的“低碳”标准进行了规范，但我们许多生产“环保、低碳”产品的企业不重视产品的宣传，以致产品虽好却无人问津。
企业应该如何改变这种局面呢？首先，企业的高层要有高山仰止的战略眼光。
其次，立即开展品牌宣传。
现在不是“人怕出名猪怕壮”的时代了，你如果还顾虑重重，就只能被淘汰出局。
A . 制定B . 无人问津C . 高山仰止D . 人怕出名猪怕壮2. （2分）填入下列横线处的句子，与上下文衔接最恰当的一组是（）发展两岸关系，是两岸同胞的共同心愿，。
不管两岸关系出现什么情况，，为维护和发展两岸关系，推动和平统一大业继续努力。
A . 这个历史潮流是任何人都无法阻挡的台湾同胞来祖国大陆探亲旅游、投资经商及开展各种交流活动,我们将一如既往地表示欢迎B . 是任何人都无法阻挡的历史潮流我们将一如既往地欢迎台湾同胞来祖国大陆探亲旅游、投资经商及开展各种交流活动C . 这个历史潮流是任何人都无法阻挡的我们将一如既往地欢迎台湾同胞来祖国大陆探亲旅游、投资经商及开展各种交流活动D . 是任何人都无法阻挡的历史潮流台湾同胞来祖国大陆探亲旅游、投资经商及开展各种交流活动，我们将一如既往地表示欢迎3. （2分） (2019高二下·天津期中) 下列各项中叙述有误的一项是（）A . 黛玉性格忧郁，因一个误会触动寄人篱下的凄凉正逢饯花之期，又勾起伤春愁思，于是将残花埋葬在沁芳亭。
她由落花想到自己的命运，口吟《葬花词》。
B . 元妃回官后把那天省亲的题咏成册命人在大观园中磨石镌刻，元妃因怕大观园寥落，竟命令宝玉与诸姐妹搬进去居住。
宝玉从此每天与姐妹们一起读书写字下棋心满意足。
2009年高中毕业班郑州市第二次质量预测英语答案详解
2009年高中毕业班郑州市第二次质量预测英语答案详解新郑一中分校王留法第一部分听力1-5 BABAB 6-10 ACBCA 11-15 BBACA 16-20 CACBA第二部分英语知识运用第一节单项填空21-25 ADDCA 26-30 BADCB 31-35 ACBCD21. 【考点】冠词【句意】在英语中，部分名词在拼写时，该词的首字母使用大写字母。
【解析】the word指代certain nouns中提到的需要大写首字母的特定某个单词；a capital letter 中的a 指代“大写字母”这一类别，和“小写字母”类别区分。
【母题】Common nouns should be spelt with a small initial, but sometimes they are written with a capital to honor the person.A proper noun has to always be spelt starting with a capital letter. It is usually the name of a single, particular, person, country, or thing.22. 【考点】代词【句意】——多么激动人心的聚会呀！——是啊，这一夜似乎是永远都过不完。
（寓意：今夜快乐无止境）【解析】it 指代上文提到的the night，该句还可译为：It seems as if the night would never end.23. 【考点】交际用语【句意】——天晚了，我现在必须要走了。
——好的，再见。
【解析】take it easy不着急,不紧张,从容不迫,轻松用来安慰别人不要慌张；go slowly 慢慢走。
不能对应汉语中的告别语“慢走”。
汉语中的慢走应译为：“take care”意思为叮嘱别人路上小心。
Stay longer 多呆一会儿。
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新郑一中2008—2009学年上学期三年级第二次月考化学试卷2009-9-20时间：90分钟总分：100分第Ⅰ部分选择题(共45分)可能用到的相对原子质量：H：1 C：12 N：14 O：16 Na：23 Cu：64一、选择题（共15个小题，每小题3分，共45分。
每小题只有一个选项符合题意。
）1．容量瓶是用来配制物质的量浓度的溶液的定量仪器，其瓶上标有：①温度②浓度③容量④压强⑤刻度线⑥酸式或碱式这六项中的A．②④⑥B．③⑤⑥ C．①②④ D．①③⑤2．若不断地升高温度，实现＂雪花→水→水蒸气→氧气和氢气＂的变化。
在变化的各阶段被破坏的粒子间的相互作用依次是A．氢键；分子间作用力；非极性键B．氢键；氢键；极性键C．氢键；极性键；分子间作用力D．分子间作用力；氢键；非极性键3．下列物质中，能够导电的电解质是A．Cu丝B．熔融的MgCl2C．NaCl溶液D．蔗糖4．下列物质中，按熔点由高到低的顺序排列正确的是A．CH4＞SiH4＞GeH4＞SnH4B．KCl＞NaCl＞MgCl2＞MgOC．Rb＞K＞Na＞LiD．石墨＞金刚石＞SiO25．下列微粒的空间构型中，其中的一种与其它三种不同。
则这种微粒是A．NH3B．BF3 C．NF3 D．H3O+6．下列比例模型所表示的分子中，中心原子上存在有未成键电子对的是A．B．C．D．7．为了除去FeCl2溶液中混有的少量FeCl3，最好的方法是向此溶液中A ．通入氯气B ．加入H 2O 2C ．加入FeD ．加入Cu8．制印刷电路时常用氯化铁溶液作为“腐蚀液”，发生的反应为2FeCl 3＋Cu ＝2FeCl 2＋CuCl 2。
向盛有氯化铁溶液的烧杯中同时加入铁粉和铜粉，反应结束后，下列结果不可能出现的是烧杯中A ．有铜无铁B ．有铁无铜C ．铁、铜都有D ．铁、铜都无9．一定条件下硝酸铵受热分解的化学方程式为：5NH 4NO 3＝2HNO ＋4N ＋9H 化与被还原的氮原子数之比为 A ．5∶3 B ．5∶4 C ．1∶1 D ．3∶5 10．下图为NaCl 晶体的一个晶胞，下列叙述中不正确的是 A ．该晶胞中平均含有4个Na ＋和4个Cl － B ．与一个Na ＋最近且等距的Na ＋有12个C ．与Na ＋最近且等距的Cl －D ．若晶体中Na ＋与Cl －的最小距离为a ，则Na ＋与Na ＋最近的距离为2a 11．对三硫化四磷（P 4S 3）的分子结构研究表明，该分子中没有不饱和键，且各原子的最外层均已达到了八电子的结构。
该分子可能结构的种类和一个三硫化四磷分子中含有的共价键个数分别A ．1，7B ．3，9C ．5，19D ．不能确定12．下列排列顺序正确的是①热稳定性：H 2O ＞HBr ＞H 2S ②原子半径：O ＞Na ＞Mg③酸性：H 3PO 4＞H 2SO 4＞HClO 4 ④结合质子能力：OH -＞CH 3COO -＞Cl -A ．①③B ．②④C ．①④D ．②③13．在下列溶液中，各组离子一定能够大量共存的是A ．使酚酞试液变红的溶液： K +、NO 3-、SO 42-、Fe 3+B ．使紫色石蕊试液变红的溶液：Fe 2+、Al 3+、NO 3-、Cl -C ．c (H +)=10-12 mol ·L -1的溶液：K +、Ba 2+、Cl -、Br -D ．c (H +)水=10-12 mol ·L -1K +、SO42-、Cl -、HCO 3-14．下列离子方程式正确的是：15．某温度下，在一容积可变的密闭容器中反应2A(g) + B( g) 2C( g ) 达到平衡时，A 、B 、C 的物质的量分别是4mol 、2mol 、4mol 。
保持温度和压强不变对平衡混合物中三者的物质的量做如下调整，可使平衡右移的是蓝天家教网 伴你快乐成长A．均减半B．均加倍C．均增加1mol D．均减小1mol第Ⅱ卷（非选择题，共55分）二、（本题包括6小题，共55分）16．(8分) 膦（PH3）是一种无色有剧毒的气体，其还原能力比氨（NH3）强，是一种强还原剂，但膦在水中的溶解度远小于氨，微溶于水。
某反应体系中存在下列物质：Cu、H2SO4、CuSO4、PH3、H3PO4、H2O。
回答下列问题：(1)P在元素周期表中的位置是，用电子式表示PH3的形成过程为；(2)上述反应体系中化学反应方程式为_______________________________________，氧化产物是____ ；(3)膦（PH3）在水中的溶解度远小于氨的原因是_________________________________。
17．（9分）2008年9月13日中央电视台报导了三鹿集团在牛奶中添加三聚氰胺使全国1200多名婴幼儿患上肾结石的“三鹿奶粉重大安全事故”，国务院立即启动国家重大食品安全事故Ｉ级响应。
就下列网上查得的有关三聚氰胺的物理物质资料回答问题：三聚氰胺性状为纯白色原子晶体。
有难闻的气味，密度1.573克／厘米3(16℃)。
常压下为熔点354℃（分解），快速加热升华，升华温度为300℃。
难溶于水，易溶于醚、苯和四氯化碳，可溶于甲醇、乙酸、热乙二醇等。
（1）三聚氰胺为三个氰胺分子加聚而成如右图所示的环状物，则三聚氰胺的分子式为_________，分子中含氮的质量分数为________________；（2）已知氰胺分子中除H原子外，C、N 原子的最外层均达8个电子的结构，则氰胺的电子式为_______________，结构式为__________________。
（3）和相对分子质量相近的硝基苯比较（无色或微黄色具苦杏仁味的油状液体。
相对质量为分子量123.11。
熔点5.7℃。
沸点210.9℃）。
三聚氰胺的熔点特殊的高，基原因是____________________________________________________________。
（4）上述有关三聚氰胺的物理性质叙述中有四处明显错误。
请找出错误之处，同时在错误处下面画上横线，并根据你已有的知识把错误之处加以改正后填写在下列空格内①____________②______________③______________④______________；18．(6分)2004年7月，法俄两国科学家共同宣布，在高压下，氮气会聚合生成高聚氮。
在高聚氮晶体中，每个氮原子都通过三个单键与其它氮原子结合并向空间发展，构成立体网状结构。
已知该晶体中N-N的键能为160kJ/mol，而氮气中N≡N的键能为942kJ/mol。
则：(1)高聚氮晶体属于_____ 晶体。
(2)高聚氮转化为氮气时，将____ （“吸收”或“放出”）能量，当生成1mol N2时，能量变化是________ kJ。
19．(6分)右图表示一个晶胞，该晶胞为正方体型，原子(或分子、离子)位于正方体的顶点和面心。
试回答下列问题：(1)若这是金属铜晶体的晶胞，则每个晶胞中含有Cu2+的数目为；(2)若这是一个分子晶体的晶胞，其代表物质是；(3)若这是一个不完整的金刚石晶胞，则晶胞中其他碳原子的数目和位置是；(4)若这是一个不完整的NaCl晶胞，且顶点和面心的实心球表示Na＋，则晶胞中Cl－位置是________ ；(5)若这是一个不完整的CaF2晶胞，且已知CaF2中Ca2+周围等距离的存在着8个F－，则图中实心球表示（填Ca2＋或F—）。
20．(13分)试回答下列各问题：(1)指出下面物质分子或离子的空间构型：CS2_______________；PO43－___________________；(2)有两种活性反应中间体微粒，它们的微粒中均含有1个碳原子和3个氢原子。
请依据下面给出的这两种微粒的球棍模型，写出相应的化学式及电子式：，__________________；__________________，__________________。
(3)按要求写出第二周期非金属元素之间构成的中性分子的化学式：平面三角形分子_________，三角锥形分子_________，正四面体形分子__________。
(4) 1919年美国化学家埃文·朗缪尔(Langmuir)提出：价电子(最外层电子)数和重原子(即比氢重的原子)数相同的分子(或离子)互称为等电子体。
由第一、二周期元素组成，与F2互为等电子体的分子有_____________、___________(写两种)离子有_______。
(写一种)。
(5)下列一组微粒中为非极性分子的是____________________(用编号填写)。
①HCN ②SiF4③NH4+④SCl2⑤CH3Cl ⑥CH2＝CH221．(13分)A、B、C、D为含有相同电子数的分子或离子，均由原子序数小于10的元素组成，A有5个原子核。
通常状况下，C为无色液体，已知：A＋B△C＋D。
(1)B的电子式是_______________________。
(2)液态D与液态C的电离相似，都可电离出电子数相同的两种离子，液态D的电离方程式是_________________________。
(3)用图示装置制备气体D的催化氧化产物并验证其还原性。
有下列主要操作：a、向广口瓶内注入足量热NaOH溶液，将盛有Cu片的小烧杯放入瓶中。
b、关闭止水夹，点燃红磷，伸入瓶中，塞好胶塞。
c、待红磷充分燃烧，一段时间后打开分液漏斗旋塞，向烧杯中滴入少量稀硝酸。
①步骤c后还缺少的一步主要实验操作是_______________________________。
②红磷充分燃烧的产物与NaOH溶液反应的离子方程式是_________________。
③步骤c滴入稀硝酸后烧杯中的现象是_________________________________。
反应的离子方程式是________________________________________。
(4)一定温度下，将1molN2O4置于密闭容器中，保持压强不变，升高温度至T1的过程中，气体由无色逐渐变为红棕色，温度继续由T1升高到T2的过程中，气体逐渐变为无色。
若保持T2，增大压强，气体逐渐变为红棕色。
气体的物质的量n随温度T变化如图所示。
①温度在T1～T2之间，反应的化学方程式是___________________________。
②温度在T2～T3之间，气体的平均相对分子质量是(保留一位小数)_______________________。
新郑一中2008—2009学年上学期三年级第二次月考化学参考答案1~5 DBBDB 6~10 CCBAC 11~15 BCCDC16 (共8分)(1) 第三周期第V A 族 3H共3分 (2) PH 3＋4CuSO 4＋4H 2O ＝4Cu ＋H 3PO 4＋4H 2SO 4 H 3PO 4共4分 (3) NH 3能与水形成分子间氢键，而PH 3则不能 共1分 17 (共9分)⑴ C 3N 6H 6 或 (H 2CN 2)3 66.7%共2分⑵ H C ≡N共2分 ⑶ 由于分子间氢键的形成 共1分 ⑷ ①分子晶体 ②无气味 ③易溶于水 ④不易溶于乙醚共4分 18、(共6分)(1)原子 (2)放出 462 各2分 19、(1) 4 (2)干冰共2分 (3)其他4个碳原子位于4个互不相邻小立方体的中心共2分 (4)体心和12条棱边的中点 (5)Ca 2+共2分 20、(共13分)(1)直线形 正四面体 (2)CH 3+ CH 3— [ ]＋ [ ]—(3) BF 3、NF 3、CF 4 (4) H 2O 2、C 2H 6、CH 3NH 2、N 2H 4(任写两种 ) O 22—各1分 (5) ②⑥各1分 21—⑵ 2NH 3 NH 4+＋NH 2—各1分 ② P 2O 5 ＋6OH — ＝ PO 43—＋3H 2O各1分 ③ Cu 片逐渐溶解，有无色气泡产生，溶液由无色变为蓝色共3分 ·· N ·· · · ·· H H C N · · · ·· · · · ···· · · · · H H C H···· · · H H C H3Cu＋8H+＋2NO3—＝3Cu2+＋2NO↑＋4H2O 共2分⑷2NO2＝2NO ＋O2⑸30.7 各2分。