3.已知点A (-1,0),B (1,0),C (- 5712,0),D (5712 ,0),动点P (x , y )满足AP →·BP → =0,动点Q (x , y )满足|QC →|+|QD →|=10 3 ⑴求动点P 的轨迹方程C 0和动点Q 的轨迹方程C 1; ⑵是否存在与曲线C 0外切且与曲线C 1内接的平行四边形,若存在,请求出一个这样的平行四边形,若不存在,请说明理由; ⑶固定曲线C 0,在⑵的基础上提出一个一般性问题,使⑵成为⑶的特例,探究能得出相应结论(或加强结论)需满足的条件,并说明理由。 4.已知函数f (x )=m x 2+(m -3)x +1的图像与x 轴的交点至少有一个在原点右侧, ⑴求实数m 的取值范围; ⑵令t =-m +2,求[1 t ];(其中[t ]表示不超过t 的最大整数,例如:[1]=1, [2.5]=2, [-2.5]=-3) ⑶对⑵中的t ,求函数g (t )=t +1t [t ][1t ]+[t ]+[1t ]+1的值域。
高考英语重点词汇填空专项练习题
高考英语重点词汇填空专项练习 请根据句意和汉语提示填入一个恰当的英语单词(注意形式)。 1. Prices have risen steadily during the past _________(十年), namely from 2005 to now. 2. His interest in this subject gradually _________(减少) because he dislikes the new teacher. 3. Such _________(装饰品) is a typical feature of the new year festival. 4. It was not long before the ________(潮湿的) clothes dried up in the sun. 5. I must apologize for the ________(延误) in writing back to you. 6. I am much __________(高兴) to be present at the lecture and to give you a speech. 7. The thin mailman _________(递送) letters and parcels from door to door every morning. 8. Our headteacher _________(要求) we get to the classroom before half past six in the morning. 9. He had been suffering from toothache for a few days before he went to see a _________(牙医). 10. The hero should _________ (值得/应得) praise and a reward for his brave behavior. 11. It’s admitted that everyone _________(期望/想要) to live in a world free of wars and starvation. 12. If you don’t speak good English, you will be at a big _________(劣势) when seeking a job. 13. There was a ________(失望的) look on his face when he failed to pass the driving test again. 14. Our school _________(阻止/使气馁) us from staying up late to study. 15. Every day after I get up, I _______(给……穿衣服) my son and then wash his hands and face. 16. So _________(满是灰尘的) is the window that I can’t see anything clearly outside. 17. I _______(捐赠) my blood for free each year with the hope of helping those people in need. 18. He works hard, but he does not ______(赚/挣) much money to support his family. 19. I go all out for my ideal university, for I think nothing is more important than ________(教育). 20. What is certain is that every ________(结果) must have a cause. 21. I work hard to improve my English, believing that my ________(努力) will pay off soon. 22. There are four _________(紧急情况) exits in the department store in all. 23. To save money, many shops prefer to ________(雇佣) students during summer vacation. 24. Without your _________(鼓励), I would have given up learning and dropped out of school. 25. When asked why she remained single all the time, she felt a bit _________(尴尬). 26. Some people are tired of living on the earth and want to ________ (体验) the life on Mars. 27. With the College E Examination coming, we are under great pressure. 28. Mr. Smith is an ________(专家) on foreign language teaching. 29. Only by practicing a lot can you speak (流利的) English. 30. She had the f the other day and she went to see a doctor. 31. He is so poor that he can’t afford to buy the ________ (昂贵的) furniture. 32. The whole building was in ________(火焰) and it took two hours to put out the great fire. 33. As the saying goes, f is the mother of success. 34. We should try our best to create a better living ________ (环境). 35. Mr. Wang often encourages me to join in more activities to ________ (丰富) my
1997年全国统一高考数学试卷(理科)
1997年全国统一高考数学试卷(理科) 参考答案与试题解析 一、选择题(共15小题,1-10每小题4分,11-15每小题5分,满分65分)1.(4分)设集合M={x|0≤x<2},集合N={x|x2﹣2x﹣3<0},集合M∩N=() A .{x|0≤x< 1} B . {x|0≤x< 2} C . {x|0≤x≤1}D . {x|0≤x≤2} 考点:交集及其运算. 分析:解出集合N中二次不等式,再求交集. 解答:解:N={x|x2﹣2x﹣3<0}={x|﹣1<x<3},∴M∩N={x|0≤x<2},故选B 点评:本题考查二次不等式的解集和集合的交集问题,注意等号,较简单.2.(4分)如果直线ax+2y+2=0与直线3x﹣y﹣2=0平行,那么实数a等于() A .﹣6 B . ﹣3 C . D . 考点:直线的一般式方程与直线的平行关系. 专题:计算题. 分析: 根据它们的斜率相等,可得=3,解方程求a的值.解答:解:∵直线ax+2y+2=0与直线3x﹣y﹣2=0平行, ∴它们的斜率相等,∴=3,∴a=﹣6. 故选A. 点评:本题考查两直线平行的性质,两直线平行,斜率相等.3.(4分)函数y=tan()在一个周期内的图象是() A .B . C . D . 考点:正切函数的图象. 专题:综合题. 分析:先令tan()=0求得函数的图象的中心,排除C,D;再根据函数y=tan() 的最小正周期为2π,排除B. 解答:解:令tan()=0,解得x=kπ+,可知函数y=tan()与x轴的一个交点不是,排除C,D
∵y=tan()的周期T==2π,故排除B 故选A 点评:本题主要考查了正切函数的图象.要熟练掌握正切函数的周期,单调性,对称中心等性质.4.(4分)已知三棱锥P﹣ABC的三个侧面与底面全等,且AB=AC=,BC=2.则二面角P﹣BC ﹣A的大小为() A .B . C . D . 考点:平面与平面之间的位置关系;与二面角有关的立体几何综合题. 专题:计算题. 分析:要求二面角P﹣BC﹣A的大小,我们关键是要找出二面角P﹣BC﹣A的大小的平面角,将空间问题转化为平面问题,然后再分析二面角P﹣BC﹣A的大小的平面角所在的三角形的 其它边与角的关系,解三角形进行求解. 解答:解:如图所示,由三棱锥的三个侧面与底面全等, 且AB=AC=, 得PB=PC=,PA=BC=2, 取BC的中点E,连接AE,PE, 则∠AEP即为所求二面角的平面角. 且AE=EP=, ∵AP2=AE2+PE2, ∴∠AEP=, 故选C. 点评:求二面角的大小,一般先作出二面角的平面角.此题是利用二面角的平面角的定义作出∠AEP为二面角P﹣BC﹣A的平面角,通过解∠AEP所在的三角形求得∠AEP.其解题过 程为:作∠AEP→证∠AEP是二面角的平面角→计算∠AEP,简记为“作、证、算”.5.(4分)函数y=sin()+cos2x的最小正周期是() A .B . πC . 2πD . 4π 考点:三角函数的周期性及其求法. 分析:先将函数化简为:y=sin(2x+θ),即可得到答案. 解答: 解:∵f(x)=sin()+cos2x=cos2x﹣sin2x+cos2x=(+1)cos2x﹣sin2x =sin(2x+θ) ∴T==π
2020高考数学专题训练16
六) 题号 1 2 3 4 5 6 7 8 9 10 11 12 答案 1.满足条件?≠?M ≠?{0,1,2}的集合共有( ) A .3个 B .6个 C .7个 D .8个 2.等差数列}{n a 中,若39741=++a a a ,27963=++a a a ,则前9项的和9S 等于( ) A .66 B .99 C .144 D .297 3.函数)1(log 2-=x y 的反函数图像是( ) A B C D 4.已知函数)cos()sin()(??+++=x x x f 为奇函数,则?的一个取值为( ) A .0 B .4 π - C .2π D .π 5.从10种不同的作物种子中选出6种放入6个不同的瓶子中展出,如果甲、乙两种种 子不能放入第1号瓶内,那么不同的放法共有( ) A .4 82 10A C 种 B .5 91 9A C 种 C .5 91 8A C 种 D .5 81 8A C 种 6.函数512322 3 +--=x x x y 在[0,3]上的最大值、最小值分别是( ) A .5,-15 B .5,-4 C .-4,-15 D .5,-16 7.已知9)222(-x 展开式的第7项为4 21 ,则实数x 的值是( ) A .31- B .-3 C .4 1 D .4 8.过球面上三点A 、B 、C 的截面和球心的距离是球半径的一半,且AB =6,BC =8, AC =10,则球的表面积是( ) A .π100 B .π300 C . π3100 D .π3 400 9.给出下面四个命题:①“直线a 、b 为异面直线”的充分非必要条件是:直线a 、b 不相交;②“直线l 垂直于平面α内所有直线”的充要条件是:l ⊥平面α;③“直线a ⊥b ”的充分非必要条件是“a 垂直于b 在平面α内的射影”;④“直线α∥平面β”的必要非充分条件是“直线a 至少平行于平面β内的一条直线”.其中正确命题的个数是( )
(word完整版)高考英语专题训练营每日高频词汇一.docx
高考训练营:每日高频词汇一 1.In this factory, suggestions often have to wait for months before they are fully _____. A.admitted B.acknowledged C.absorbed D.considered [ 答案 ] D. considered [ 注释 ] considered考虑;admit 承认; absorb 吸收。 [ 注意 ] acknowledge 1) (=agree or admit the truth of; confess) 承认,供认; A. He acknowledged his mistake. ( 他承认了他的错误。 ) B. 接动名词He acknowledged having beenbeaten. (他承认被打败了。) 2) (express thanks for)致谢; A. Mary acknowledged the gift with a pleasant letter. ( 玛丽致函感谢馈赠的礼 物。 ) B. His long service with the company was acknowledged with a present. ( 向他赠送礼品以感谢他长期来对公司的服务。 ) 2.The boy slipped out of the room and headed for the swimming pool without his parents' _____. A. command B. conviction C. consent D. compromise [ 答案 ] C. consent [ 注释 ] consent同意,赞成,答应。conviction深信,确信。compromise妥协,折中。 command 命令,指令;掌握,运用能力。 3.Our research has focused on a drug which is so _____ as to be able to change brain chemistry. A. powerful B. influential C. monstrous D. vigorous
最新最全高考英语词汇分类记忆大全
高考英语词汇分类记忆 1.People 1. baby 婴儿 2. being物;生物;人 3. child(复children) n. 孩子,儿童 4. citizen 公民,居民,市民 5. civil国内,平民(非军人)的;民用 6. companion同伴,同事 7. comrade n. 同志 8. crowdn..人群vt. 拥挤,群聚 9. enemy n. 敌人;敌军 10. fellow n. 同伴;伙伴 11. friend[frend] n. 朋友 12. generation n.代,一代 13. guest n. 客人,宾客 14. human a.&n. 人,人类 15. humanbeing 人 16. man (单数,无冠词) n.人,人类(包括男女) 17. neighbour(-bor) n.邻居,邻人 18. partner n. 搭档,股东,舞伴 19. people n. 人,人们;人民 20. personn. 人, 身体, 容貌,
21. population n. 人口 22. publica.公共的,公众n.公众 23. race[reis] n. 种族,民族 24. teenager (13-19)青少年 25. adult 26. kid 2.Sex 1. boyn. 男孩 2. female a. 女性的;雌性的 3. girl n. 女孩 4. gentlemann. 绅士,先生 5. ladyn. 女士,夫人 6. sex[seks] n. 性,性别, 7. madam/madame夫人,女士 8. male[meil] a. 男的, 雄的, 男 9. man (men) n.男人,成年男子 10. Mr. (mister) n.先生, 阁下 11. Mrs.(mistress)夫人, 太太 12. Ms.[miz] n. 女士, 小姐 13. sirn. 先生;阁下 14. woman n. 妇女,女人,女仆