2021届上海市各地高三一模作文题目汇编
2021届上海市各地高三一模作文题目汇编
2021届高三宝山一模作文题
25.社会生活中，本真的人格受到许多赞美，这是否意味着把道德规范内化就不再是完美人格了呢？请写一篇文章，谈谈你对这个问题的认识和思考。
要求：（1）自拟题目；（2）不少于800字。
【2021届高三闵行一模作文题】
刻意地特立独行是否能避免随波逐流？
请写一篇文章谈谈你的思考与看法，不少于800字。
【2021届高三长宁一模作文题】
25.在日常生活中，人们有时通过说理未能让别人接受自己的主张，通过恳求倒可能让别人接受。请写一篇文章，谈谈你对这种现象的认识和思考。要求：（1）自拟题目；（2）不少于800字。
【2021届高三崇明一模作文题】
25.随着社会的不断发展，竞争越来越激烈，许多人发现自己不停地努力，却很难取得更优异的成绩。
对此你有怎样的思考？请写一篇文章，谈谈你的看法。
要求：（1）自拟题目；（2）文体不限（诗歌除外）。
【2021届高三徐汇一模作文题】
有人说，当我们认为某些事“当然应该是这样”的时候，反而是危险的。你对这句话有怎样的思考？请自拟题目，写一篇不少于800字的文章。
【2021届高三普陀一模作文题】
25.某位作家曾说：这个世界在很大程度上是以细节形式存在的，我们看世界其实是看细节，如果抹去了细节，就等于什么都没有看到。你是否认同这一说法？请写一篇文章，谈谈你的思考。
要求：（1）自拟题目；（2）不少于800字。
【2021届高三虹口一模作文题】
26.在万物互联的时代，一切似乎近在咫尺，但有时人们又会突然发现彼此之间的距离如此遥远，请写一篇文章，谈谈你对这个现象的认识和思考。
要求:（1）自拟题目；（2）不少于800字。
上海市虹口区2019届高三英语一模
状元考前提醒 拿到试卷：熟悉试卷 刚拿到试卷一般心情比较紧张，建议拿到卷子以后看看考卷一共几页， 有多少道题，了解试卷结构，通览全卷是克服“前面难题做不出，后面易 题没时间做”的有效措施，也从根本上防止了“漏做题”。 答题策略 答题策略一共有三点： 1. 先易后难、先熟后生。先做简单的、熟悉的题，再做综合题、难题。 2. 先小后大。先做容易拿分的小题，再做耗时又 复杂的大题。3. 先局部后整体。把疑难问题划分成一系列的步骤，一步一 步的解决，每解决一步就能得到一步的分数。 立足中下题目，力争高水平 考试时，因为时间和个别题目的难度，多数学生很难做完、做对全部题目，所以在答卷中要立足中下题目。中下题目通常占全卷的80%以上，是试题的主要构成，学生能拿下这些题目，实际上就是有了胜利在握的心理，对攻克高档题会更放得开。 确保运算正确，立足一次性成功 在答卷时，要在以快为上的前提下，稳扎稳打，步步准确，尽量一次 性成功。不能为追求速度而丢掉准确度，甚至丢掉重要的得分步骤。试题 做完后要认真做好解后检查，看是否有空题，答卷是否准确，格式是否规 范。 要学会“挤”分 考试试题大多分步给分，所以理科要把主要方程式和计算结果写在显要位置，文科尽量把要点写清晰，作文尤其要注意开头和结尾。考试时，每一道题都认真思考，能做几步就做几步，对于考生来说就是能做几分是几分，这是考试中最好的策略。 检查后的涂改方式要讲究 发现错误后要划掉重新写，忌原地用涂黑的方式改，这会使阅卷老师看不清。如果对现有的题解不满意想重新写，要先写出正确的，再划去错误的。有的同学先把原来写的题解涂抹了，写新题解的时间又不够，本来可能得的分数被自己涂掉了。考试期间遇到这些事，莫慌乱！
2018上海高三一模语文汇编--文言文阅读(一)
2018 年高三一模语文汇编—文言文阅读（一） 【长宁嘉定】 ①程昱字仲德，东郡东阿人也。初平中，兖州刺史刘岱辟昱，昱不应。又表昱为骑都尉，昱辞以疾。刘岱为黄巾所杀。太祖临兖州，辟昱。昱将行，其乡人谓曰：“何前后之相背也！”昱笑而不应。 ②太祖征徐州，使昱与荀彧留守鄄城。张邈等叛迎吕布，郡县响应，唯鄄城、范、东阿不动。布军降者，言陈宫欲自将兵取东阿，又使汜嶷取范，吏民皆恐。昱乃过范，说其令靳允。时汜嶷已在县允乃见嶷伏兵刺杀之归勒兵守。昱又遣别骑绝仓亭津，陈宫至，不得渡。昱至东阿，东阿令枣祗已率厉吏民，据城坚守。又兖州从事薛悌与昱协谋，卒完三城，以待太祖。太祖还，执昱手曰：“微子之力，吾无所归矣。”乃表昱为东平相，屯范。 ③刘备失徐州，来归太祖。昱说太祖杀备，太祖不听。后又遣备至徐州要击袁术，昱与郭嘉说太祖曰:“公前日 不图备，昱等诚不及也。今借之以兵，必有异心。”太祖悔，追之不及。会术病死，备至徐州，遂杀车胄，举兵背太祖。顷之，昱迁振威将军。 ④袁绍在黎阳，将南渡。时昱有七百兵守鄄城，太祖闻之，使人告昱，欲益二千兵。昱不肯，曰:“袁绍拥十万 众，自以所向无前。今见昱兵少，必轻易不来攻。若益昱兵，过则不可不攻，攻之必克，徒两损其势。愿公无疑！” 太祖从之。绍闻昱兵少，果不往。太祖谓贾诩曰: “程昱之胆，过于贲、育。” （选自《三国志?卷十四》，有删改） 15. 写出下列加点词在句中的意思。（2 分） 太祖临．兖州（2）举．兵背太祖 16. 为下列句中加点词选择释义正确的一项。（2 分） （1）言陈宫欲自将．兵取东阿（） A. 将要 B. 将军 C. 带领 D. 派遣 （2）卒完．三城（） A. 终结 B. 完好 C. 修缮D 保全 17. 第②段画横线部分断句正确的一项是（）（2 分） A.时汜嶷已在/ 县允乃见/嶷伏兵刺杀之/ 归勒兵守 B. 时汜嶷已在/县允乃见嶷伏兵/刺杀之归/勒兵守 C. 时汜嶷已在县/允乃见嶷/伏兵刺杀之/ 归勒兵守 D. 时汜嶷已在县/允乃见/嶷伏兵刺杀之归/勒兵守 18. 把第④段画线句译成现代汉语。（6 分） 袁绍拥十万众，自以所向无前。今见昱兵少，必轻易不来攻。若益昱兵，过则不可不攻，攻之必克，徒两损其势。 19. 第②段画波浪线句子反映了太祖怎样的心情？下列选项中最不恰当的一项是（）（2 分） A. 感激 B. 自豪 C. 庆幸 D. 欣慰 20. 第①段“两拒刘岱”和第③段“两劝杀备”都反映了程昱和的特点。（4 分） 【答案】： 15. （2 分）（1）到（2）发动 16. （2 分）（1）C （2）D 17. （2 分）C
上海2020高三数学一模分类汇编-函数(详答版)
2020年一模汇编——函数 一、填空题 【杨浦1】函数12 ()f x x - =的定义域为 【答案】(0,)x ∈+∞ 【解析】12 ()f x x -== (0,)x ∈+∞ 【长宁，嘉定，金山2】方程27x =的解为 【答案】2log 7x = 【解析】本题考察了对数的概念 【杨浦3】已知函数()f x 的反函数1 2()log f x x -=，则(1)f -= 【答案】 12 【解析】因为2 1log 12=-，所以1(1)2 f -= 【宝山3】函数)1(3 1 <=-x y x 的反函数是 . 【答案】1log 3+=x y ，]1,0(∈x 【解析】y x ,互换，1 3 -=y x ?1log 3 +=x y ]1,0(∈x 【普陀5】设函数()log (4)(01)a f x x a a =+≠＞且，若其反函数的零点为2，则a =__________. 【答案】2 【解析】反函数-1 (2)0f =，有2 (0)log (04)=log 2=2a a f =+，易知2a = 【崇明5】函数 ()f x =的反函数是 ． 【答案】1 2()1(0)f x x x -=-≥ 【解析】令1+= x y ,2211y x x y ∴=+?=-
【徐汇5】 已知()y f x =是定义在R 上的偶函数，且它在[0,)+∞上单调递增，那么使得(2)()f f a -≤成立的实数a 的取值范围是 【答案】 (][),22,-∞-+∞U 【解析】由题，()y f x =是定义在R 上的偶函数，且它在[0,)+∞上单调递增，则 ()f x 在 (],0-∞上单调递减，(2)()f f a -≤，则2a -≤，解得a 的取值范围是(][),22,-∞-+∞U 【闵行6】设函数22log (1)1 ()log 1 x f x x --= ，则方程()1f x =的解为 【答案】2x = 【解析】22222log (1)1 ()=log (1)log log (1)1log 1 x f x x x x x x --= -+=-=Q ()()12 100x x x x -=?? ∴-??? ＞＞2x ∴= 【奉贤8】已知点()3,9在函数()1x f x a =+的图像上，则()f x 的反函数为()1 f x -= __________. 【答案】()2log 1x - 【解析】将点()3,9代入函数()1x f x a =+中得2a =，所以()12x f x =+，用y 表示x 得 ()2log 1x y =-，所以()1f x -=()2log 1x - 【虹口8】设1()f x -为函数2()log (41)x f x =-的反函数，则当1()2()f x f x -=时，x 的值为_________. 【答案】1 【解析】由于函数2()log (41)x f x =-的反函数为)12(log 4+=x y ，当1()2()f x f x -=， 即)12(log 2)14(log 42+=-x x ，计算出1=x 【松江8】已知函数()y f x =存在反函数()-1y f x =，若函数()+2y f x =的图像经过 点 ()16 ，，则函数()-12+log y f x x =的图像必过点__________. 【答案】 ()43， .
2018届上海各区高三英语一模——summary汇编
【2018宝山区—一模】 IV. Summary Writing Secure payment without leaving a trace Computer scientist Andy Rupp, member of the “Signaling Code and Security” working group, is always surprised about lacking problem awareness: only few users are aware of the fact that by using payment systems they disclose in detail how and what they consume or which routes they have taken. To prevent control of the accounts by dishonest users, customer data and account balances of payment are usually carried out with the help of a central database. In every payment deal, the customer is identified and the details of her/his deal are transmitted to the central database. This repeated identification process produces a data trace that might be misused by the provider or third parties. The expert has now presented the basics of an “electronic purse” that works by unknown names, but prevents misuse at the same time. The “black-box addition plus” (BBA+) code system developed by them transfers all necessary account data to the card used or the smartphone and guarantees their secrets with the help of signaling code methods. At the same time, BBA+ offers security guarantees for the operator of the payment system: The code system guarantees a correct account balance and is mathematically constructed such that the identity of the user is disclosed as soon as the attempt is made to pay with a controlled account. “Our new code system guarantees privacy and security for customers during offline operation as well,” Andy Rupp says. “This is needed for ensuring the payment system’s suitability for daily use. Think of a subway doorway or a payment bridge. There you may have no internet connection at all or it is very slow.” Also its high efficiency makes the code system suited for everyday use: During first test runs, researchers completed payments within about one second. ①when customers use payment systems, most of them don’t realize the fact that by doing so, they risk( take the risk of ) losing privacy. ②Researchers have now developed a secure system called BBA+, which works anonymously and avoids misuses as well. ③moreover ( apart from / besides the security of privacy), it also proves to be efficient for daily use.(47 words) 【2018—崇明区一模】 IV. Summary Writing From Burn Survivor to Global Inspiration Last October, the Kona Ironman World Championship witnessed an unbelievable finish. Turia Pitt, an Australian woman who suffered severe burns when caught in a bush fire during a marathon six years ago, successfully challenged herself. Pitt spent 864 days in a hospital and went through more than 200 operations. Doctors said she would never run again, but she proved them wrong. Crossing the line in the Hawaiian darkness, Pitt showed incredible emotion as the race commentator（现场解说员）announced: “Turia Pitt, you are an ironman!” On social media, people around the world applauded her determination. Apart from continuing to be a star athlete, Pitt is also a motivational speaker now. She is sharing her journey of
2019届上海高三英语一模汇编：翻译
2019.12.12【一模汇编】2019届上海高三英语一模汇编：翻译 1、2019黄浦一模 Directions: Translate the following sentences into English, using the words given in the brackets. 72. 很多人对他们的潜能一无所知。(ignorant) 73. 这些政策在一定程度上对该地区的经济衰退负有责任。(extent) 74. 自古以来老百姓就希望天下太平，同各国人民友好相处。(long for) 75. 青少年问题的发展趋势值得我们关注和研究，也值得整个社会群策群力，共商对策。(which) 答案： 72. Many people are totally ignorant of their potential (abilities/talents). 73. These policies are to some extent responsible for the region’s economic decline. 74. Since ancient times people have longed for a peaceful world to live together in friendship with people from/of all countries. /Since ancient times people have longed for a peaceful world, where people of all/different countries live together in friendship. 75. The developing trend of youth/adolescent/teenager problems deserves our attention and research/ analysis, which also deserves the joint efforts of the whole society to find solutions. 2、2019普陀一模 72. 晚上别喝太多的咖啡，会睡不着觉的。(or) 73. 事实证明，保持快乐的心态会降低得心脏病的风险。(It) 74. 乐观的人不会过分怀念美好的旧时光，因为他们正忙着创造新的回忆。(create) 75. 追求稳定并不是什么坏事, 很多时候这样的态度在促使我们提升自我、挑战难度、攀登高峰。( when) 答案： 72. Don’t drink too much coffee at night, or you won’t be able to sleep. 73. It is proved that keeping a happy mind reduces the risk of heart diseases. 74. Optimistic people don’t miss the good old days too much because they are busy creating new memories. 75. The pursuit of stability is not a bad thing. （, and）There are many times when such an attitude drives us to improve ourselves, challenge difficulties, and climb peaks.
2018高三“一模”数学试题汇编(函数)
2018上海各区高三“一模”数学试题分类（函数） 一、填空题： 1．若全集U R =，集合{}02A x x x =≤≥或，则U C A = 2．设集合{2,3,4,12}A =，{}0,1,2,3B =，则A B = 3．已知集合{}1,2,5A =，{}2,B a =，若{}1,2,3,5A B =，则a = 4．已知全集U N =，集合{}1,2,3,4A =，集合{}3,4,5B =，则() U C A B = 5．设全集U Z =，集合{}1,2M =，{}2,1,0,1,2P =--，则()U P C M = 6．已知函数{}2,3A =，{}1,2,B a =，若A B ?，则实数a = 7．已知集合{}03A x x =<<，{}24B x x =≥，则A B = 8．已知集合{}1,2,A m =，{}3,4B =，若{}3A B =，则实数m = 9．函数()lg(2)f x x =-的定义域是 10．函数()f x =的定义域为 11．若行列式124 012x -=，则x = 12．不等式 10x x -<的解为 13．不等式11x <的解集是 14．不等式211 x x +>+的解集是 15．不等式2433(1)12()2x x x --->的解集是 16．不等式111 x ≥-的解集为 17．已知()f x 是定义在R 上的奇函数，则(1)(0)(1)f f f -++= 18．已知函数()21f x x =-的反函数为1()f x -，则1(5)f -= 19．若函数()f x x α=的反函数的图像经过点11 (,)24 ，则a = 20．方程222log (2)log (3)log 12x x -+-=的解x =
上海高三一模汇编(英语)阅读A篇2021
2021 一模真题汇编 上海 (高三·英语) 1
一、2020-2021 学年高三英语一模卷汇编 4. 阅读A篇 Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read. One【宝山】 (A) “Runners, to your mark, Get set…” Bang! And I was off, along with a bunch of other teenage cross-country runners from high schools across the county. The day was like any other fair-weather autumn day in Maryland. But the race that day felt unique from the get-go. For one thing, I liked the course. It was my team’s home course, one I was used to running durin g practices. It took runners along an area of land that included open fields, hills and even winding dirt paths through a small forest. It was a beautiful 5-kilometer course. This particular race was our team’s invite, and I was proud to be sharing the cou rse with competitors from other schools. It also meant a lot―more than normal that my parents were there to cheer me on. With so much to expect that day, I was ready to run! And I didn’t want to be stuck with the pack of other runners, as is typical at the beginning of most cross-country races. So when the gun sounded, I took off running, leaving everyone else in the dust. The first part of our course followed the outside edge of a large open field before disappearing into the forest. Within seconds of the start, I was far ahead of everyone, and all of the fans could see it. It felt magnificent. But that feeling didn’t last long. Little did I know my coach was laughing to himself, thinking, “Gabe is done for!” And I was. My body was telling me to slow down. My pride, however, said “No! Not until you’re out of sight of the spectators!” I was in agony, but I kept up my pace until I reached the forest. Once in among the trees. I slowed way down. I enjoyed most races, even while pushing myself, but this one was not enjoyable in the least. I finished the race, but in nowhere near the time I could have if I’d paced myself well from the beginning. Every time I reflect on that cross-country season, I’m reminded of something: Pride is no substitute for pace. 56.What is special to the author about the race? A. The weather condition was good for runners. B. He was familiar with the home course.
2021上海高三英语一模分类汇编：11选10专题
11选10专题 上海市杨浦区2021届高三英语期末（一模）试题 Section B Directions: Fill in each blank with a proper word chosen from the box. Each word can be used only once. Note that there is one word more than you need. A. including B. impressions C. standing D. restored E. missing F. fun G. comfort H. associated I. inspired J. marked K. contact Ancient Civilizations Had Game Nights Too! Morten Ramstad, a researcher at the University of Bergen, Norway, and his team spotted one of the rare objects while unearthing the remains of an Early Iron Age (400-300 BC) burial site in Western Norway. Burying loved ones with basic necessities like ceramic pots and clothing, to ensure their (31) _______ in the afterlife, was a fairly common tradition in ancient cultures. However, the families of some lucky individuals went a step further by (32) ________ a board game for entertainment. Though the game board was (33) ________, the archeologists, who revealed their findings on April 5, 2020, managed to recover the dice（骰子）and 18 circular game pieces. Unlike the modern-day cubical（立体的）dice, which are (34) _______ with a different number of dots from one to six on each face, the ancient game counter was square and had bulls-eye like (35) ________, which indicated zero to five on each of its four faces. The researchers suspect it may have been (36) ________ by the oldest-known board game —the “Game of Mercenaries”. The two-person strategy game, which dates back to the 3rd century BC, was believed to be similar to modern-day chess. The archeologists, who also unearthed remains of pottery jars and a bronze needle at the burial site believe the game pieces indicate the dead was a wealthy individual. In ancient civilizations, board games were a status symbol, signifying the owner’s high social and economic (37) ________. They indicated an individual’s intellectual ability and also proved he/she could afford to spend time on such activities.
2018年上海高三一模真题汇编——三角比三角函数专题
2018年一模汇编——三角函数专题 一、知识梳理 【知识点1】求值 【例1】已知α是第二象限的角，且a =αcos ，利用a 表示tan α=. 【答案】a a 2 1-. 【解析】由α是第二象限的角，a =αcos 知21sin a -=α，2 sin 1tan cos a a ααα-==. 【点评】熟练掌握由tan α的值求ααcos ,sin 的值的操作程序；给（一个角的三角函数）值求（另一个三角函数）值的问题，一般要用“给值”的角表示“求值”的角，再用两角和（差）的三角公式求得. 【例2】已知),,0(πα∈且51cos sin - =+αα，则tan α=. 【答案】4 3-. 【解析】由51cos sin -=+αα平方得025 24cos sin 2<-=αα，又由),0(πα∈知),2(ππα∈. 则有0cos ,0sin <>αα.2549cos sin 21)cos (sin 2= -=-αααα，得57cos sin =-αα. 有54cos ,53sin -==αα，所以3tan 4 α=-. 【点评】此类问题经常出现在各类考试中，而且错误率都比较高.原因是不能根据角所在的象限，对函数值进行正确的取舍. 【知识点2】两角和与差公式、诱导公式、倍角公式 【例1】设12cos(),sin(),2923βααβ- =--=且,0,22ππαπβ<<<<求cos().αβ+ 【答案】－ 729239. 【解析】,0,22π π απβ<<<<
,.42422π β π α π απβ∴<-<-<-< 故由1cos(),29βα- =-得45sin().29βα-= 由2sin(),23αβ-=得5cos().23 αβ-= 75cos()cos ()().22227αββααβ+??∴=---=???? 2239cos()2cos ( )1.2729αβ αβ+∴+=-=- 【点评】两角和与差公式、诱导公式、倍角公式等在应用时，都比较注重寻求角与角的联系，尤其是建立已知角与所求角的联系. 【例2】已知sin(2)2sin 0.αββ++= 求证tan 3tan().ααβ=+ 【解析】由题设：[][]sin ()+=2sin ().αβαααβ+-+ 即sin()cos cos()sin =2sin cos()2cos sin(). αβααβαααβααβ++++-+ ∴3sin()cos =sin cos()αβαααβ++ ∴tan 3tan().ααβ=+ 【点评】注意题设中的角和结论中角的关系. 【知识点3】万能公式 【例1】已知),2(,0cos 2cos sin sin 622ππ ααααα∈=-+，求)32sin(π α+的值. 【答案】26 1235-. 【解析】由0cos 2cos sin sin 622=-+αααα得：26tan tan 20αα+-=，则1tan 2α=或2tan 3α=-.又),2(ππ α∈，所以2tan 3α=-.由万能公式得22tan 12sin 21tan 13ααα==-+，221tan 5cos 21tan 13ααα-==+.知26 1235)32sin(-=+π α. 【点评】先通过正余弦的齐次式处理方法求出正切值，再根据万能公式得出答案.
上海高三一模真题汇编——函数专题(学生版)
2018年一模汇编——函数专题 一、知识梳理 【知识点1】函数的概念与函数三要素 【例1】设函数2log ,0 ()4,0x x x f x x >?=?≤? ，则((1))f f -= . 【例2】函数1 1,02 ()1,0x x f x x x ?-≥??=??，则实数a 的取值范围是 . 【知识点2】函数的奇偶性 【例1】已知()f x 、g()x 分别是定义在R 上的偶函数和奇函数，且()g()2x f x x x -=+，则 (1)g(1)f += . 【例2】已知函数()1 21 x f x a =-+为奇函数，求实数a 的值. 【知识点3】函数的单调性 【例1】已知定义在(2,2)-上的函数()f x 满足()()f x f x -=-，且在(2,2)-上单调递增， 若(2)(12)0f a f a ++->，求a 的取值范围.
【例2】如果定义在R 上的函数()f x 满足：对于任意12x x ≠，都有 ()()()()11221221x f x x f x x f x x f x +>+，则称()f x 为“H 函数”。给出下列函数：①1y x =+；②21y x =+；③1x y e =+；④0 00ln x x y x ?≠=?=? ，其中“H 函数”的序号是 . 【知识点4】函数的最值与恒成立有解问题 【例1】函数)(4)2(2)2()(2 R a x a x a x f ∈--+-=且0)(
上海市2020年高三英语一模专题汇编：翻译
2020 年上海高三英语一模分类汇编：翻译 2020 宝山一模 V. Translation Directions: Translate the following sentences into English, using the words given in the brackets. 72. 无论时走路、骑车还是开车，遵守交通规则都很重要。（follow） 73. 只有发展好、运用好、治理好互联网，才能使其更好地造福人类。（Only） 74. 鼓励你，给你建议，并提出有建设性的问题的人被称作人生教练或导师。（helpful） 75. 生命充满了挑战，但是只要你有学习新事物的意愿，就能得到克服障碍的正确态度。（willingness） 72. Whether you walk, cycle or drive a car, it ' s important to follow the rules of the road. 73. Only by developing, using and governing the internet well can it benefit mankind. 74. A person who encourage you, give you advice and asks helpful questions is called life coaching or mentor. 75. Life is full of changes, but a willingness to learn something new gives people the right attitude for overcoming obstacles. 2020 崇明一模 V. Translation Directions: Translate the following sentences into English, using the words given in the brackets. 72. 出于好奇，杰克向村民们打听了这座城堡的历史。（curiosity） 73. 我们最好分析一下公司最近几年发展减缓的原因。（analyze） 74. 人人都该意识到，减少人类活动对环境的负面影响是很有必要的。（it） 75. 我决心已定，无论你怎么劝我，我也不会同意放弃这个通过夜以继日的努力工作才获得的机会。（however） 72. Out of curiosity, Jack asked the villagers about the history of the castle. 73. We ' d better analyze（the reasons） why our company ' s development hians r eslcoewnet d down years. We' d better analyze the reasons for the slow-down of our company ' s development these years. 74. Everyone should realize that it 'qsu ite necessary to reduce the negative effect that human activity has on
上海市各区2018届高三数学(理科)一模试题分类汇编：三角函数 精品
上海市各区2018届高三数学（理科）一模试题分类汇编 三角函数 2018.01.23 （普陀区2018届高三1月一模，理）3. 在△ABC 的内角A 、B 、C 的对边分别为a 、b 、 c ，若2=a ，32=c ，3 π = C ，则=b . 3. 4； （长宁区2018届高三1月一模，理）7、设ω＞0，若函数f (x )=2sin ωx 在［－4, 3π π］上单 调递增，则ω的取值范围是_________. 7、]2 3 ,0( （徐汇区2018届高三1月一模，理）4. 已知sin 5x =，,2x ππ?? ∈ ??? ，则x = .（结果用反三角函数表示） （嘉定区2018届高三1月一模，理）6．已知θ为第二象限角，5 4 sin = θ，则=??? ?? +4t a n πθ____________． 6．7 1- （杨浦区2018届高三1月一模，理）9. 已知函数()1cos sin )(2 -+=x x x f ωω的最小正 周期为π，则=ω _________． 9. 理1±； （浦东新区2018届高三1月一模，理）4.已知tan tan αβ、是方程2670x x ++=的两根，则tan()αβ+=_______. 4. 1 （长宁区2018届高三1月一模，理）9、在△ABC 中，内角A ，B ，C 的对边分别是a ，b ， c.若bc b a 32 2=-，B C sin 32sin = ，则角A ＝._________
9、 6 π （浦东新区2018届高三1月一模，理）9.在锐角ABC V 中,4,3AC BC ==，三角形的面 积等于AB 的长为___________. 9. （徐汇区2018届高三1月一模，理）2. 函数x x y 2cos 2sin =的最小正周期是 . （普陀区2018届高三1月一模，理）17.将函数)(x f y =的图像向右平移 4 π 个单位，再向上平移1个单位后得到的函数对应的表达式为x y 2 sin 2=，则函数)(x f 的表达式可以 是………………………………………（ ） )(A x sin 2. )(B x cos 2. )(C x 2sin . )(D x 2cos . （徐汇区2018届高三1月一模，理）16. 为了得到函数2sin ,36x y x R π?? =+∈ ??? 的图像，只需把函数2sin ,y x x R =∈的图像上所有的点 --------------------------------------------------------------------------------------------------------------------------------------（ ） (A) 向右平移6π 个单位长度，再把所得各点的横坐标伸长到原来的3倍（纵坐标不变） (B) 向左平移6π 个单位长度，再把所得各点的横坐标伸长到原来的3倍（纵坐标不变） (C) 向右平移6π个单位长度，再把所得各点的横坐标缩短到原来的1 3倍（纵坐标不变） (D) 向左平移6π个单位长度，再把所得各点的横坐标缩短到原来的1 3 倍（纵坐标不变） （16. B