甘肃省天水市第一中学2017-2018学年高二上学期第二阶
甘肃省天水市第一中学2017-2018学年高二第二次学业水平模拟考试地理试题

甘肃省天水市第一中学2017-2018学年高二第二次学业水平模拟考试地理试题注意事项:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
答题前,考生务必将自己的姓名、考生号填写在答题卡上。
2. 回答第Ⅰ卷时,选出每小题的答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其他答案标号。
写在试卷上无效。
3. 回答第Ⅱ卷时,将答案填写在答题卡上,写在试卷上无效。
4. 考试结束,将本试卷和答题卡一并交回。
第Ⅰ卷本卷共35小题。
每小题2分,共70分。
在每个小题给出的四个选项中,只有一项是符合题目要求的。
近期研制出利用玉米叶片加工、编织购物袋的技术,这种购物袋易分解且物美价廉。
据此完成1-2题。
1. 该种购物袋的生产厂应接近A.能源产地B.销售产地 C.原料产地D.研发基地2. 该种购物袋的生产原料在我国的最大产地是A.河南省B.吉林省 C.四川省 D.广东省德国鲁尔区丰富的煤炭资源使它成为世界最著名的工业区之一:山西省是我国的煤炭生产大省,但尚未成为经济强省。
据此完成3-4题。
3.与鲁尔区相比,山西省发展经济的有利条件是A.劳动力廉价B.科技发达C.水源丰富D.交通便利4.山西省由能源大省转变为经济强省的发展策略应该有①大力增加煤炭工业的比重②调整产业结构,积极发展第三产业③增加科技投入,走可持续发展之路④治理水土流失,改善和保护生态平衡A.①②③B. ②③④C. ①③④D. ①②④目前中国人口约13亿,劳动力众多,中国劳动力总量大约是欧盟、美国、日本劳动力总和的二倍,因此中国被称为世界工厂。
但过去几年外商开始抱怨我国沿海地区工资上涨过快,劳动力短缺。
完成以下问题。
5. 我国农业人口众多,2012年全国农业户口人口所占比重达64.71%。
如果要使农业部门释放出更多的劳动力到工业部门,则中国的农业将会朝向下列何种方式发展A.机械化 B.立体农业 C.休闲农业D.节水农业6. 中国20至29岁的劳动力已由1990年的2.33亿减到2005年的1.65亿。
甘肃省天水市一中2017-2018学年高二下学期第二学段考试数学(理)试题(精品Word版,含答案解析)

天水市一中2017-2018学年度第二学期高二第二阶段考试数学试题(理科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 不等式的解集是( )A. 或B.C. 或D.【答案】B【解析】分析:根据绝对值几何意义解不等式.详解:因为,所以,因此解集为,选B.点睛:含绝对值不等式的解法有两个基本方法,一是运用零点分区间讨论,二是利用绝对值的几何意义求解. 2. 已知,则下列不等式一定成立的是( ) A.B.C.D.【答案】C【解析】分析:令,可得,;对B ,当时不成立,由此得出结论.解析:令,可得,,故C 正确;对B ,当时不成立.故选:C.点睛:判断不等式是否成立,需要逐一给出推理判断或反例说明.常用的推理判断需要利用不等式的性质或者利用特殊值代入法,排除不符合条件的选项. 3. 圆心在且过极点的圆的极坐标方程为( )A.B.C.D.【答案】C【解析】分析:先根据圆心与半径写出圆标准方程,再化为极坐标方程.详解:因为圆心在且过极点,所以半径为1,圆方程为所以因此选C.点睛:(1)直角坐标方程化为极坐标方程,只要运用公式及直接代入并化简即可; (2)极坐标方程化为直角坐标方程时常通过变形,构造形如的形式,进行整体代换.其中方程的两边同乘以(或同除以)及方程两边平方是常用的变形方法.但对方程进行变形时,方程必须同解,因此应注意对变形过程的检验.4. 从名同学(其中男女)中选出名参加环保知识竞赛,若这人中必须既有男生又有女生,则不同选法的种数为()A. B. C. D.【答案】A【解析】从名同学选出名同学共有种情况,其中,选出的人都是男生时,有种情况,因女生有人,故不会全是女生,所以人中,即有男生又有女生的选法种数为.故选.5. 若随机变量的分布列如表所示,,则()A. B. C. D.【答案】B【解析】分析:先根据所有概率和为1得a+b=0.8,再根据数学期望公式得a+2b=1.3,解方程组得a,b,即得值.详解:因为分布列中所有概率和为1,所以a+b=0.8,因为,所以a+2b+0.3=1.6, a+2b=1.3,解得a=0.3,b=0.5,a-b=-0.2,点睛:分布列中6. 已知随机变量服从正态分布,且,则()A. B. C. D.【答案】B【解析】分析:先根据随机变量服从正态分布,得,计算得结果.详解:因为随机变量服从正态分布,所以因此选B.点睛:正态分布下两类常见的概率计算(1)利用正态分布密度曲线的对称性研究相关概率问题,涉及的知识主要是正态曲线关于直线x=μ对称,及曲线与x轴之间的面积为1.(2)利用3σ原则求概率问题时,要注意把给出的区间或范围与正态变量的μ,σ进行对比联系,确定它们属于(μ-σ,μ+σ),(μ-2σ,μ+2σ),(μ-3σ,μ+3σ)中的哪一个.7. 设曲线的参数方程为(为参数),直线的方程为,则曲线上到直线的距离为的点的个数为()A. B. C. D.【答案】B【解析】分析:将参数方程化为普通方程,求出圆心和半径,再求圆心到直线的距离,判断直线和圆的位置关系,观察即可得到点的个数.解析:曲线的参数方程为(为参数),化为普通方程为圆C:.圆心为,半径为2.则圆心到直线的距离,则直线与圆相交,则通过观察,曲线上到直线的距离为的点的个数为3个.点睛:本题考查参数方程和普通方程的互化,考查直线与圆的位置关系,考查判断和运算能力.8. 已知变量之间的线性回归方程为,且变量之间的一组关系数据如下表所示,则下列说法错误的是()A. 变量之间呈现负相关关系B. 可以预测,当时,C. D. 由表格数据知,该回归直线必过点【答案】C【解析】由题意得,由,得变量,之间呈负相关,故A正确;当时,则,故B正确;由数据表格可知,,则,解得,故C错;由数据表易知,数据中心为,故D正确.故选C.9. 若动点在曲线上运动,则的最大值为()A. B. C. D.【答案】A【解析】由题意得,选A.点睛:利用曲线的参数方程来求解两曲线间的最值问题非常简捷方便,是我们解决这类问题的好方法.椭圆参数方程:,圆参数方程:,直线参数方程:10. 将一个底面半径为,高为的圆锥形工件切割成一个圆柱体,能切割出的圆柱最大体积为()A. B. C. D.【答案】C【解析】设圆柱的半径为,高为,体积为,则由题意可得∴圆柱的体积为则∴圆柱的最大体积为,此时故选:B.【点睛】本题主要考查基本不等式在生活中的优化问题,利用条件建立体积函数是解决本题的关键.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)11. 设是不相等的正数则的大小关系是__________.(用“ ” “ ” “=”连接)【答案】.【解析】由于为不相等的正数,,,所以.12. 在的二项展开式中常数项是__________.【答案】【解析】分析:先根据二项展开式通项公式得,再根据次数为零确定r,代入即得结果.详解:因为,所以由得常数项是点睛:求二项展开式有关问题的常见类型及解题策略(1)求展开式中的特定项.可依据条件写出第项,再由特定项的特点求出值即可.(2)已知展开式的某项,求特定项的系数.可由某项得出参数项,再由通项写出第项,由特定项得出值,最后求出其参数.13. 设随机变量,随机变量,则的方差__________.【答案】.【解析】分析:先根据二项分布方差公式得,再由,得4得结果.详解:因为,所以,因为,所以4.点睛:二项分布),则若),则.14. 在航天员进行的一项太空实验中,要先后实施个程序,其中程序只能出现在第一步或最后一步,程序和实施时必须相邻,请问实验顺序的编排方法共有__________种(用数字作答).【答案】.【解析】试题分析:先排程序有两种方法,再将和捆在一起后排,有种方法,因此共有种方法.考点:排列组合【方法点睛】求解排列、组合问题常用的解题方法:(1)元素相邻的排列问题——“捆邦法”;(2)元素相间的排列问题——“插空法”;(3)元素有顺序限制的排列问题——“除序法”;(4)带有“含”与“不含”“至多”“至少”的排列组合问题——间接法.三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)15. 某公司为庆祝成立二十周年,特举办《快乐大闯关》竞技类有奖活动,该活动共有四关,由两名男职员与两名女职员组成四人小组,设男职员闯过一至四关概率依次是,女职员闯过一至四关的概率依次是(1)求女职员闯过四关的概率;(2)设表示四人小组闯过四关的人数,求随机变量的分布列和数学期望.【答案】(1).(2)分布列见解析;.【解析】试题分析:(1)利用相互独立事件的概率计算公式即可得出.(2)记女生四关都闯过为事件B,则P(B)=,ɛ的取值可能为0,1,2,3,4,利用相互独立与互斥事件的概率计算公式即可得出.试题解析:(1)记事件A为“女职员闯过四关”,则P(A)=×××=.(2)记“男职员闯过四关”为事件B,则P(B)=×××=,易知P()=1-=,P()=1-=,易知X的所有可能取值为0,1,2,3,4,则P(X=0)=22=,P(X=1)=C×××2+C×××2=,P(X=2)=C×22+C×22+C×××C××=,P(X=3)=C×××2+C×××2=,P(X=4)=22=,所以X的分布列为X01234PE(X)=0×+1×+2×+3×+4×=.点睛:求解离散型随机变量的数学期望的一般步骤为:第一步是“判断取值”,即判断随机变量的所有可能取值,以及取每个值所表示的意义;第二步是:“探求概率”,即利用排列组合、枚举法、概率公式(常见的有古典概型公式、几何概型公式、互斥事件的概率和公式、独立事件的概率积公式,以及对立事件的概率公式等),求出随机变量取每个值时的概率;第三步是“写分布列”,即按规范形式写出分布列,并注意用分布列的性质检验所求的分布列或事件的概率是否正确;第四步是“求期望值”,一般利用离散型随机变量的数学期望的定义求期望的值,对于有些实际问题中的随机变量,如果能够断定它服从某常见的典型分布(如二项分布X~B(n,p)),则此随机变量的期望可直接利用这种典型分布的期望公式(E(X)=np)求得.16. 已知函数(1)解不等式;(2)若关于的不等式恒成立,求实数的取值范围.【答案】(1).(2).【解析】分析:第一问首先应用绝对值的意义,利用零点分段法去掉绝对值符号,,写出分段函数,即可解出不等式的解集,第二问将不等式恒成立转化为其最小值满足条件即可,此时需要用到绝对值不等式的性质.详解:(1)不等式等价于或或,解得或则不等式的解集为 .(2)∵关于的不等式恒成立,∴,故实数的取值范围为.点睛:该题考查的是有关绝对值不等式的问题,一是利用零点分短法解绝对值不等式,将其转化为分段函数或者若干个不等式组来完成,二是利用绝对值不等式的性质,也可以利用绝对值的几何意义,将恒成立问题转化为其最值考虑即可.17. 在直角坐标系中,以为极点,轴正半轴为极轴建立极坐标系,已知曲线的参数方程为(为参数),过点的直线交曲线于两点,且直线的倾斜角为(Ⅰ)求直线和曲线的极坐标方程;(Ⅱ)求的值.【答案】(1);.(2).【解析】分析:(Ⅰ)依题意,直线的极坐标方程为=(). 参数方程化为普通方程,然后化为极坐标方程可得曲线的极坐标方程为.(Ⅱ)将=代入,得,结合韦达定理可得.详解:(Ⅰ)依题意,直线的极坐标方程为=().由消去,得.将,代入上式,得:.故曲线的极坐标方程为.(Ⅱ)依题意可设,, 且,均为正数.将=代入,得,所以,所以.点睛:本题主要考查参数方程与普通方程,极坐标与直角坐标方程的互化,直线参数方程的几何意义及其应用等知识,意在考查学生的转化能力和计算求解能力.18. 在十九大“建设美丽中国”的号召下,某省级生态农业示范县大力实施绿色生产方案,对某种农产品的生产方式分别进行了甲、乙两种方案的改良。
甘肃省天水市第一中学2017-2018学年高二第二次学业水平模拟考试化学试题及参考答案

可能用到的相对原子质量: H-1 C-12 N-14 O-16 Na -23 S-32 Fe-56 Ba-137第 I卷选择题,(共40分)一、选择题(本题25小题,其中1-10小题,每题1分,11-25小题,每题2 分,共40分。
每小题的的四个选项中,只有一个选项符合题意。
)1、中华民族的发明创造为人类文明进步做出了巨大贡献。
下列我国古代发明中,不涉及化学反应的是2、电解质是一类在水溶液里或熔融状态下能够导电的化合物。
下列物质属于电解质的是A.FeB.NaClC.SiO2D. KNO33、合金在生产及科研中具有广泛的应用。
下列物质属于合金的是A.水银B.石墨C.硅晶体D.不锈钢4、下列各组离子中,能在溶液中大量共存的是A.H+、Na+、CO32-、Cl-B.Mg2+、Na+、 Cl-、SO42-C.K+、NH4+、SO42- OH-D.Fe2+、Al3+、NO3-、H+5、下列物质属于同分异构体的是A.麦芽糖和蔗糖B.蛋白质和氨基酸C.油和脂D.淀粉和纤维素6、下列关于Na2CO3和NaHCO3的说法中,不正确的是A. 均溶于水B.均为白色固体C.受热均易分解D.其水溶液均能使酚酞溶液变红7、钴(6027Co)是一种穿透力很强的核辐射元素,可用来治疗癌症。
下列关于6027Co的说法不正确的是A.钴的一种核素B.质子数为27C.核外电子数为27D.中子数为608、在下列反应中,盐酸作氧化剂的是A.NaOH+HCl===NaCl+H2OB.Zn+2HCl===ZnCl2+H2↑C.MnO2+4HCl(浓)MnCl2+Cl2↑+2H2OD.CuO+2HCl==CuCl2+H2O9、下列说法正确的是A某试样焰色反应呈黄色,则试样中含有K+B.广泛pH试纸测得来某碱性溶液的pH为12.5C.容量瓶不能用作溶解物质的容器D.粗盐的提纯试验中,滤波在坩埚中加热蒸发结晶10、下列过程属于物理变化的是A.煤的干馏B.石油分馏C.石油裂化D.乙烯聚合11、下列物质中,不能发生水解反应的是A.油脂B.淀粉C.蔗糖D.葡萄糖12、若1mol 某气态烃C x H y完全燃烧,需用2mlO2,则此气态烃的分子式为A. CH4B.C2H4C.C2H6D.C3H813、制备氯乙烷最好的方法是A.乙烯和氯化氢反应B.乙烯和氯气反应C.乙烷和氯气反应D.乙炔和氯化氢反应14、下列物质中,能使酸性高锰酸钾溶液褪色的是A.甲烷B.乙烯 C、苯 D.乙酸15、下列物质的电子式书写正确的是A.Cl:ClB.C.D.16、能实现下列物质间直接转化的元素是单质氧化物酸或碱盐A.硅B.硫C.铜D.铁17、羰基硫(COS) 可作为一种粮食熏蒸剂,能防止某些昆虫的危害。
甘肃省天水市第一中学2017_2018学年高二英语下学期第二学段考试试题201806070218

天水一中高二级2017-2018学年度第二学期第二阶段考试英语试题(满分100分,时间90分钟)第I卷选择题(共60分)I. 阅读理解(共10小题每小题2分,满分20分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中选出最佳选项,并在答题卡上将该项涂黑。
AThe writer Margaret Mitchell is best known for writing Gone with the Wind, firstpublished i n 1936. H er b ook a nd t he m ovie b ased o n i t, t ell a s tory o f l ove a nd s urvivalduring the American Civil War. Visitors to the Margaret Mitchell House in Atlanta,Georgia, can go where she lived when she started composing the story and learn moreabout her life.Our first stop at the Margaret Mitchell House is an exhibit area telling aboutthe writer’s life. She was born in Atlanta in 1900. She started writing stories whenshe was a child. She started working as a reporter for the Atlanta Journal newspaperin 1922. One photograph of Ms. Mitchell, called Peggy, shows her talking to a groupof young college boys. She was only about one and a half meters tall. The young mentower over her, but she seems very happy and sure of herself. The tour guide explains:“Now in this picture Peggy is interviewing some boys from Georgia Tech, asking themsuch questions as ‘Would you really marry a woman who works?’ And today it’d be‘Would you marry one who doesn’t?’”The Margaret Mitchell House is a building that once contained several apartments.Now we enter the first floor a partment w here Ms. Mitchell l ived w ith her husband, JohnMarsh. They made fun of the small apartment by calling it “The Dump ” .Around 1926, Margaret Mitchell had stopped working as a reporter and was at home healing after an injury. Her husband brought her books to read from the library. Sheread so many books that he bought her a typewriter and said it was time for her towrite her own book. Our guide says Gone with the Wind became a huge success. Margaret Mitchell r eceived t he P ulitzer P rize f or t he b ook. I n 1939 t he f ilm v ersion w as r eleased.It won ten Academy Awards, including Best Picture.1.The book Gone with the Wind was _________.A. first published on a newspaperB. awarded ten Academy AwardsC. written in “The Dump”D. adapted from a movie2.The underlined phrase “tower over”in Paragraph 2 is closest in meaningto_________.A. be very pleased withB. show great respect forC. be much taller thanD. show little interest in3.Why did Ms. Mitchell stop working as a reporter according to the passage?A. Because she was rich enough.B. Because she was injured then.C. Because her husband didn’t like it.D. Because she wanted to write books. 4.Which is the best title for the passage?A. Gone with the Wind: A Huge Success.B. Margaret Mitchell: A Great Female Writer.C. An Introduction of the Margaret Mitchell House.D. A Trip to Know Margaret Mitchell.BPeople who have lost the ability to understand or use words due to brain damage are called aphasics(失语症患者).Such patients can be extremely good at something else.From the changing expressions on speakers' faces and the tones of their voices,they can tell lies from truths.Doctors studying the human brain have given a number of examples of this amazing power of aphasics.Some have even compared this power to that of a dog with an abilityto find out the drugs hidden in the baggage.Recently,scientists carried out tests to see if all that was said about aphasicswas t rue.They s tudied a m ixed g roup o f p eople.Some w ere n ormal;others w ere a phasics.It was proved that the aphasics were far ahead of the normal people in recognizing false speeches—in most cases,the normal people were fooled by words,but the aphasics were not.Some years ago,Dr.Oliver Sacks wrote in his book about his experiences withaphasics.He mentioned a particular case in a hospital.Some aphasics were watching the president giving a speech on TV.Since the president had been an actor earlier,makinga good speech was no problem for him.He was trying to put his feelings into every wordof his speech.But his way of speaking had the opposite effect on the patients.They didn't seemto believe him.Instead,they burst into laughter.The aphasics knew that the presidentdid not mean a word of what he was saying.He was lying!Many doctors see aphasics as people who are not completely normal because they lack the ability to understand words.However,according to Dr.Sacks,they are more gifted than normal people.Normal people may get carried away by words.Aphasics seem to understand human expressions better,though they cannot understand words. 5.What is so surprising about aphasics?A. They can fool other people.B. They can tell whether people are lying.C. They can understand language better.D. They can find out the hidden drugs. 6.How did the scientists study aphasics?A. By asking them to watch TV together.B. By organizing them into acting groups.C. By comparing them with normal people.D. By giving them chances to speak on TV.7.What do we learn from this text?A. What ones says reflects how one feels.B. Aphasics have richer feelings than others.C. Normal people often tell lies in their speeches.D. People poor at one thing can be good at another.CDo you want to get home from work knowing you have made a real difference in someone’s life?If yes, don’t care about sex or age! Come and join us, then you’ll make it!Position: Volunteer Social Care Assistant(No Pay with Free Meals)Place: ManchesterHours: Part TimeWe arc now looking for volunteers to support people with learning disabilities to live active lives! Only 4 days left. Don’t miss the chance of lending your warm hands to help others!Role:You w ill p rovide p eople w ith l earning d isabilities w ith a ll a spects o f t heir d aily lives. You will help them to develop new skills. You will help them to protect their rights and their safety. But your primary concern is to let them know they are valued.Skills and Experience Required:You will have the right values and great listening skills. You will be honest and patient. You will have the ability to drive a car and to communicate in fluent written and spoken English since you’ll have to help those people with different learning disabilities. Previous care-related experience will be a great advantage for you. 8.What does the underlined part mean?A. You’ll make others’ lives more meaningful with this jobB. You’ll arrive home just in time from this jobC. You’ll earn a good salary from this jobD. You’ll succeed in getting this job9.The volunteers’primary responsibility is to help people with learning disabilities______.A. to get some financial supportB. to properly protect themselvesC. to learn some new living skillsD. to realize their own importance 10.Which of the following can first be chosen as a volunteer?A. The one who can drive a carB. The one who has done similar work beforeC. The one who has patience to listen to othersD. The one who can use English to communicateII.阅读七选五(共5小题,每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
甘肃省天水市一中2017-2018学年高二上学期第二阶段期

天水一中2017-2018学年第一学期2016级第二阶段考试试题英语(B卷)本试卷分为第I卷(选择题)和第Ⅱ卷(非选择题)两部分,满分100分。
考试时间为90分钟。
第I卷(满分50分)第一部分阅读理解(共15小题,每小题2分,满分30分)第一节阅读下列短文,从每题所给的四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
AHere are some of the most influential print journalists in history.John Peter ZengerThis man published the New York Weekly Journal in the 1700s. He wrote honestly about the British government, and in 1735 he was arrested (逮捕). He was found not guilty, since what he wrote was based on truth. His case helped influence the American Revolution.Benjamin FranklinWe know that Benjamin Franklin had a lot of interests. But many people don’t realize that the inventor and founding father was also a journalist. His The Pennsylvania Gazette began in the 1730s, and Franklin used it to help get his ideas out and influence the public leading up to the American Revolution.William Randolph HearstHearst was well known as one of the biggest publishers and journalists of his time. He started with The San Francisco Examiner, and went from there. Hearst was one of the starters of “yellow journalism”, which started a new field of journalism that used eye-catching headlines to draw the attention of readers.Helen ThomasThis woman is the first lady of print journalism. Helen Thomas has been a White House reporter since 1961. She is known for her bold (大胆的) questions, and for her ability to get to the heart of the matter. Thomas gained new influence and fame when George W. Bush was President for her sharp questions and comments.1. Why was John Peter Zenger not guilty?A. He didn’t lie at all.B. The police got the wrong guy.C. He took part in the American Revolution.D. His achievements were greater than his faults.2. Which role of Franklin may surprise you most?A. A father.B. A leader.C. An inventor.D. A journalist.3. What’s the biggest feature of “yellow journalism”?A. It was created by Hearst.B. Its newspapers were in yellow.C. It used little tricks to attract readers.D. It came from The San Francisco Examiner.4. Who has the most contact with the White House?A. John Peter Zenger.B. Helen Thomas.C. Benjamin Franklin.D. William Randolph Hearst.BHave you ever had trouble sleeping in a new place? Lots of people have. Now researchers from Brown University in Rhode Island think they know why.They found that one half of the brain remains more awake than the other half when people aretrying to sleep in a new place. This appears a case of the brain keeping people ready for trouble in a new place, the researchers said.The sleep findings were reported in Current Biology and by Brown University. In their report, the researchers said many people reported they had a harder time sleeping the first night at a hotel or other places outside their home.They call it “first-n ight effect”. “In Japan, if you change your pillow, you can’t sleep,” said Yuka Sasaki, one of the report’s authors. “You don’t sleep very well in a new place. We all know about it.”The researchers measured brain waves for 35 volunteers over two nights in a laboratory. The two nights were a week apart. They found during the first night the left hemisphere (半球) of the brain was more active than the right hemisphere. This was during the first deep-sleep period, the researchers said.Sasaki said a lot of questions remain. Researchers did not keep measuring brain waves all night long, so they don’t know if the left hemisphere keeps “watch” all night. Or whether it “works in shifts (轮流)” with the right hemisphere later in the night. They also do not know why the extra brain activity, at least during the first phase of deep sleep, is always on the left hemisphere.For some, this research may be calming. It is good to know that our brain is “looking out for us” in a new place. But it may not help with sleep. That extra brain activity, at least according to this new research, makes it harder to get the sleep people need to feel well rested in the morning.5. What can be learnt from the study?A. Brain waves were measured in two separate days.B. The left brain develops better than the right one.C. The extra activity is limited to the left brain.D. The left brain keeps “watch” all night.6. The text aims to _________ .A. give some advice to people with sleep problemsB. show the real link between the brain and sleepC. call attention to the brain activityD. explain the “first-night effectCArchitecture and the urban design are struggling for a green fever dream:Everywhere you look there are plans for sustainable(可持续的)buildings and eco-cities.This year, the dreamers' goal is even bigger: "eco-cities" going beyond the last century's development patterns and delivering to us a low-carbon,green future in stylish comfort. In part,the dream reflects a push for energy efficiency,recycled materials and lower carbon emissions (排放物). The dream also includes an effort to turn buildings green by covering them in plants. Green roofs appear on Wal-Marts, and green walls appear on hotels, banks, museums一even at the mall. All of this is surely a good idea, at some level. But today's green urban dream is too often about bringing a technologically controlled version of nature into the city and declaring the problem solved, rather than looking at the deeper causes of our current environmental and urban discontents.Today's signature eco-building, Apple's "spaceship" campus now under construction in Silicon Valley, is a good example of the shortcomings of the green dream. Though said to be sustainable and energy efficient, it is by any measure a complex, massively resource-intensive(密集的)andexpensive building, achievable only by one of the richest corporations on Earth.Projects like this are really the fulfillment of a set of blue-sky dreams. In the end, those dreams are about leaving Earth itself behind for an engineered habitat, in the sky or at least on the roof. Instead of making "nature" into a feature of eco-cities, architects and planners must work to design better relationships between our cities and nature, and to promote just relationships between the people in them. This year's Pritzker Prize winner, the Chilean architect Alejandro Aravena, is a case in point. He is less interested in making technologically impressive buildings than in co-operating with residents themselves to design low-cost, efficient housing solutions for the urban working class, especially in the wake of natural disasters. It is a more productive path forward than growing plants on tall buildings.7.What's the dreamers' goal this year?A. To build more sustainable and bigger eco-cities.B. To change the former development patterns.C. To create a green future in fashionable ways.D. To provide people with low-carbon action plans.8.What can we know about Apple's "spaceship" campus?A.It's an eco-building with signatures.B.Its construction has been completed.C. It consumes lots of money and resources.D. It's the best example of the urban green dream.9.What's the tone of the text?A. Humorous.B. Serious.C. Optimistic.D. Depressing.10.Which statement may Alejandro Aravena agree with?A. Disaster-proof buildings are worth any cost.B. Architects should create user-friendly buildings.C. Growing plants on tall buildings is really practical.D. A technologically controlled version of nature is a must.第二节根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,选项中有两项为多余选项(七选五)If you enjoy reading, you should first choose a good book. _____11_____if you like comedy, get a funny book. If you like fantasy, get a book about fairy tales or fantasy. If you get a book that’s not right for you,you may lose interest in the book and won’t want to read it. ____12____If you’re thinking of buying a book, why not head to your local library and read a little part of it to see if it is worth buying?Don’t force yourself to read something you’re not enj oying at all. There is a difference between giving the book a chance and being halfway through the book and still hating the story or information it depicts(描绘). If you think you are not enjoying a book that you have picked, stop reading it, because if you keep on at it, it will put you off reading. ____13____If you find it boring because it is too hard, try an easier one. Or vice versa, if you wish to challenge yourself more._____14____Think of what the characters are probably feeling and what their next moves might be before you find out what the author actually has them do.Read every day. Reading makes you a lot smarter. ___15_____A.Work out why you are reading.B.Try a different book that you might enjoy more.C.Make sure you have a book that’s just right for you.D.Imagine in your mind the setting of what you’re reading.E.Peaceful and quiet places will help you focus on the book.F.Reading a small section of a book is helpful for deciding its value to you.G.If you read every once in a while, you may forget about it and not continue reading.第二部分完形填空(共20小题,每小题1.5分,满分30分)请认真阅读下面短文,从短文后各题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
最新高二生物-甘肃省天水一中2018学年高二上学期第二

天水市一中2018级2018-2018学年第一学期第二阶段考试试题生物(理科)第Ⅰ卷(选择题45题,共70分)1、能维持和延续生命的生物基本特征是A、新陈代谢和细胞结构B、应激性和适应性C、遗传变异和生殖D、新陈代谢和生殖2.下列用于鉴定蛋白质的试剂及其颜色反应是A.苏丹Ⅲ染液,橘黄色 B.双缩脲试剂,紫色C.碘液,蓝色 D.斐林试剂,砖红色3.下列属于蛋白质的是A.胰岛素B.性激素C.纤维素D.胆固醇4.动物细胞中储存能量的多糖是A.葡萄糖B.乳糖C.淀粉D.糖元5.DNA完全水解后,得到的化学物质是A.氨基酸、葡萄糖、含氮碱基B.氨基酸、核苷酸、葡萄糖C.核糖、含氮碱基、磷酸D.脱氧核糖、含氮碱基、磷酸6.胶原蛋白分子具有3条肽链,每条肽链有1180个氨基酸。
该分子中肽键的数目为A.3147个 B.3150个 C.3153个 D.1187个7.下列仅属于植物细胞有丝分裂特征的是A.由两组中心粒发出的星射线形成纺锤体B.分裂间期,染色体复制形成姐妹染色单体C.分裂期的中期,着丝点排列在赤道板上D.分裂期的末期,在细胞中部形成细胞板8.对能量释放和转移具有重要意义的一组细胞器是A.线粒体、叶绿体 B.内质网、叶绿体C.高尔基体、核糖体 D.高尔基体、叶绿体9.组成染色体和染色质的主要物质是A.DNA和RNA B.蛋白质和DNAC.蛋白质和RNA D.DNA和脂质10.在线粒体、叶绿体和高尔基体中都含有的化学成分是A.磷脂和蛋白质B.脂肪和核酸C.蛋白质和核酸D.胆固醇和淀粉11.下列结构中,原核细胞具有A.核膜B.核孔C.核糖体D.线粒体12.与正常细胞相比,癌细胞A.不再分裂B.呼吸作用降低C.可以无限增殖D.水分减少13.下列生理活动中可以使ATP转化成ADP的是A.光合作用的暗反应阶段B.呼吸作用过程中的丙酮酸分解C.植物根细胞吸收水分D.氧分子穿过毛细血管壁14.人体进行各种生理活动所需要的能量直接来源于A.蛋白质B.葡萄糖C.脂肪D.ATP15.落叶中钾的含量比植株上正常叶中钾的含量低,其原因是A.钾在叶片中只能利用一次B. 钾在叶片中形成稳定的化合C. 钾在叶片中形成不稳定的化合物D. 钾在叶片中呈离子状态,可以转移16.在有氧呼吸过程中,氧的作用是A.与葡萄糖中的碳结合生成二氧化碳B.与[H]结合生成水C.参与酶的催化作用D.氧化葡萄糖形成丙酮酸17. 如下实验装置,玻璃槽中是蒸馏水,半透膜允许单糖透过。
甘肃省天水市第一中学2017-2018学年高二上学期第二阶段(期中)考试A数学(理)试题

甘肃省天水市第一中学2020-2021学年高二上学期第二阶段(期中)考试A 数学(理)试题学校:___________姓名:___________班级:___________考号:___________一、单选题1.双曲线2213y x -=的渐近线方程为( ) A.y = B .3y x =± C .13y x =± D.y x = 2.命题“x R ∀∈,均有2sin 10x x ++<”的否定为A .R ∀∈,均有2sin 10x x ++≥B .x R ∃∈,使得2sin 10x x ++<C .x R ∃∈,使得2sin 10x x ++≥D .x R ∀∈,均有2sin 10x x ++>3.椭圆2211612x y +=的左顶点到右焦点的距离为( ) A .2 B .3 C .4 D .64.“方程22121x y n n +=-+表示焦点在x 轴的椭圆”是“12n -<<”的( ) A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件5.若实数,x y 满足约束条件10060x x y x y -≥⎧⎪-≤⎨⎪+-≤⎩,则2z x y =+的最大值为( )A .9B .7C .6D .36.中心在原点的椭圆长轴右顶点为(2,0),直线1y x =-与椭圆相交于,M N 两点,MN 中点的横坐标为23,则此椭圆标准方程是( ) A .22124x y += B .22143x y += C .22132x y += D .22142x y += 7.直线:l y kx =与双曲线22:2C x y -=交于不同的两点,则斜率k 的取值范围是( )A .(0,1) B.( C .(1,1)- D .[1,1]-8.已知12,F F 是椭圆22:184x y C +=的两个焦点,在C 上满足120PF PF ⋅=的点P 的个数为( )A .0B .2C .4D .无数个9.P 是双曲线22221(0,0)x y a b a b-=>>上的点,12F F 、是其焦点,且12·0PF PF =,若12F PF △的面积是9,7a b +=,则双曲线的离心率为( )A .74B .2C .2D .5410.椭圆22154x y +=的左焦点为F ,直线x t =与椭圆相交于点,M N ,当FMN ∆的周长最大时,FMN ∆的面积是A B C D二、填空题11.已知12,F F 是椭圆221259x y +=的两个焦点,P 为椭圆上一点,且01260F PF ∠=则12PF F ∆的面积为__________ .12.已知12,F F 为椭圆221259x y += 的两个焦点,过1F 的直线交椭圆于A B , 两点,若2212F A F B += ,则||AB = ________13.已知,且 ,则的最小值是__________ .14.设双曲线221222:1(0,0),,x y C a b F F a b-=>>分别为双曲线C 的左、右焦点.若双曲线C 存在点M ,满足1213MF MO MF ==(O 为原点),则双曲线的离心率为__________ .三、解答题15.的内角的对边分别为,,a b c ,已知2sin()8sin 2B AC +=. (1)求cos B ;(2)若6a c +=,ABC ∆面积为2,求b .16.已知{}n a 是公差不为零的等差数列,11a = ,且139,,a a a 成等比数列.(1)求数列{}n a 的通项;(2)求数列{}2n n a 的前n 项和.17.双曲线的右焦点为. (1)若双曲线的一条渐近线方程为且,求双曲线的方程;(2)以原点为圆心,为半径作圆,该圆与双曲线在第一象限的交点为A ,过A 作圆的切线,斜率为18.椭圆222:1(03)9x y C b b+=<<的右焦点为F ,P 为椭圆上一动点,连接PF 交椭圆于Q 点,且||PQ 的最小值为83. (1)求椭圆方程;(2)若2PF FQ =,求直线PQ 的方程.参考答案1.A【解析】双曲线实轴在x轴上时,渐近线方程为by xa=±,本题中1,a b==得渐近线方程为y=,故选A.2.C【解析】因为全称命题的否定是特称命题,所以,命题“x R∀∈,均有2sin10x x++<”的否定为:x R∃∈,使得2sin10x x++≥,故选C.3.D【解析】椭圆2211612x y+=,可得4,2a b c===,椭圆2211612x y+=的左顶点()4,0-到右焦点()2,0的距离为()246--=,故选D.4.A【解析】方程22121x yn n+=-+表示焦点在x轴的椭圆,201021nnn n->⎧⎪∴+>⎨⎪->+⎩,解得112n-<<,因为()11,1,22⎛⎫-⊆-⎪⎝⎭,∴方程22121x yn n+=-+表示焦点在x轴的椭圆是“12n-<<”的充分不必要条件,故选A.5.A【解析】由约束条件10060x x y x y -≥⎧⎪-≤⎨⎪+-≤⎩作出可行域如图,联立060x y x y -=⎧⎨+-=⎩,解得()3,3A ,化目标函数2z x y =+为2y x z =-+,由图可知,当直线2y x z =-+过A 时,直线在y 轴上的截距最大,z 有最大值为9,故选A.【方法点晴】本题主要考查线性规划中利用可行域求目标函数的最值,属简单题.求目标函数最值的一般步骤是“一画、二移、三求”:(1)作出可行域(一定要注意是实线还是虚线);(2)找到目标函数对应的最优解对应点(在可行域内平移变形后的目标函数,最先通过或最后通过的顶点就是最优解);(3)将最优解坐标代入目标函数求出最值.6.D【解析】 设椭圆方程为()222210x y a b a b+=>>,由椭圆长轴右顶点为()20,可得2,a =∴椭圆方程可以化为22214x y b+=,把直线1y x =-代入得()22248440b x x b +-+-=,设()()1122,,,M x y N x y ,则1228,4x x MN b +=+的中点的横坐标为23,2182243b ∴⨯=+,解得22,b =∴椭圆的标准方程是22142x y +=,故选D. 7.C【解析】由双曲线22:2C x y -=与直线:l y kx =联立可()22120k x --= ,因为直线:l y kx=与双曲线22:2C x y -=交于不同的两点,所以()2210810k k ⎧-≠⎪⎨->⎪⎩ 可得11k -<< ,斜率k的取值范围是()1,1-,故选C.8.B【解析】由22:184x y C +=,得2,2,2a b c b c =====,∴以原点为圆心,c 为半径的圆与椭圆有2个交点,12PF PF ∴⊥的点P 的个数为2,即满足120PF PF ⋅=的点P 的个数为2,故选B.9.D【解析】 设12,PF m PF n ==,由题意得,120PF PF ⋅=,且12F PF ∆的面积是9,192mn ∴=,得1218,mn Rt PF F =∆中,根据勾股定理得,2224m n c +=,()22222436m n m n mn c ∴-=+-=-,结合双曲线定义,得()224m n a -=,224364c a ∴-=,化简整理得,229c a -=,即29b =,可得3b =,结合7a b +=得4a =,5,c ∴==∴该双曲线的离心率为54c e a ==,故选D. 10.D【分析】先确定周长最大时t 的取值,再求解三角形的面积.【详解】 设椭圆右焦点为2F ,FMN ∆的周长为c ,则11c MF NF MN MF NF MN=++=++11()MN MF NF =-+.因为11MF NF +MN ≥,所以c ≤;此时1t =,故FMN ∆的面积是112S FF MN == D. 【点睛】本题主要考查利用椭圆的定义求解最值问题.利用定义式实现两个焦半径之间的相互转化是求解关键.11.【解析】由椭圆221259x y +=方程可知,5,3,4a b c ==∴=,P 点在椭圆上,12,F F 为椭圆的左右焦点,1212210,28PF PF a F F c ∴+====,在12PF F ∆中,()2222212121212121212122cos 22PF PF PF PF F F PF PF F F F PF PF PF PF PF +--+-∠==221212121210283621cos60222PF PF PF PF PF PF PF PF ---====,1212127242,12PF PF PF PF PF PF ∴-=∴=,又在12F PF ∆中,1212121112603322F PFS PF PF sin F PF sin ∆=∠=⨯=故答案为12.8【分析】运用椭圆的定义,可得三角形ABF 2的周长为4a =20,再由周长,即可得到AB 的长.【详解】 椭圆22259x y +=1的a =5, 由题意的定义,可得,|AF 1|+|AF 2|=|BF1|+|BF 2|=2a ,则三角形ABF 2的周长为4a =20,若|F 2A |+|F 2B |=12,则|AB |=20﹣12=8.故答案为8【点睛】本题考查椭圆的方程和定义,考查运算能力,属于基础题.13.16【解析】()191991,101016x y x y x y x y x y y x ⎛⎫+=∴+=++=++≥+= ⎪⎝⎭,当且仅当9x y y x =时,取等号,则x y +的最小值是16,故答案为16.14.【解析】∵ 1213MF MO MF == ∴M 在双曲线的右支,即12222a MF MF MF =-=在1FOM ∆中,1FO c =,2MF a =,13MF a =, MO a = ∴22222198cos 236a c a a c MFO a c ac+-+∠==⋅⋅ 在12F F M ∆中,122F F c =,13MF a =,2MF a =∴22222129484cos 23212a c a a c MF F a c ac+-+∠==⋅⋅ ∵112MF O MF F ∠=∠∴2222884612a c a c ac ac++=,即224a c = ∴2c a= 点睛:解决双曲线的离心率的求值或取值范围问题其关键是确立一个关于a b c ,,的方程或不等式,再根据a b c ,,的关系消掉b 得到关于a c ,的方程或不等式,或通过双曲线的几何性质直接找出关于a c ,的方程或不等式即可.15.(1)1517;(2)2. 【解析】试题分析:(1)利用三角形的内角和定理可知A C B π+=-,再利用诱导公式化简()sin A C +,利用降幂公式化简28sin 2B ,结合22sin cos 1B B +=,求出cos B ;(2)由(1)可知8sin 17B =,利用三角形面积公式求出ac ,再利用余弦定理即可求出b . 试题解析:(1)()2sin 8sin2B AC +=,∴()sin 41cos B B =-,∵22sin cos 1B B +=, ∴()22161cos cos 1B B -+=,∴()()17cos 15cos 10B B --=,∴15cos 17B =; (2)由(1)可知8sin 17B =, ∵1sin 22ABC S ac B =⋅=,∴172ac =, ∴()2222222217152cos 2152153617154217b ac ac B a c a c a c ac =+-=+-⨯⨯=+-=+--=--=,∴2b =. 16.(1)n a n =;(2)1(1)22n n S n +=-+【解析】试题分析:(1)设数列{}n a 的公差为0d ≠,由11a =,且139,,a a a 成等比数列,可得3129a a a =⋅,即()()212118d d +=⨯+,解出d 即可得出通项公式;(2)由(1)可得n a n =,22n n n a n =⨯,根据等比数列的前n 项和公式利用错位相减法求和即可.试题解析:(1)数列{}n a 的公差为0d ≠,由11a =,且139,,a a a 成等比数列,可得3129a a a =⋅,即()()212118d d +=⨯+,可得()1,111n d a n n ==+-⨯= (2)231122232122n n n S n n -=⨯+⨯+⨯++-⨯+⨯() ①②①-②得:∴()1122n n S n +=-+【易错点晴】本题主要考查等差数列的通项公式、等比数列的求和公式以及“错位相减法”求数列的和,属于中档题. “错位相减法”求数列的和是重点也是难点,利用“错位相减法”求数列的和应注意以下几点:①掌握运用“错位相减法”求数列的和的条件(一个等差数列与一个等比数列的积);②相减时注意最后一项 的符号;③求和时注意项数别出错;④最后结果一定不能忘记等式两边同时除以1q -.17.(1)222x y -=;(2【解析】试题分析:(1)根据双曲线的一条渐近线方程为y x =,可得1b a =,解得a b =,结合2c ==算出a b ==(2)根据渐近线与圆相切先算出点12A c ⎛⎫⎪ ⎪⎝⎭,将此代入双曲线方程,并结合222c a b =+化简整理得到该双曲线的离心率.试题解析:(1)由题意, 222221,2,2b c a b c a b a==+=∴==, ∴所求双曲线方程为 222x y -=(2)由题意,设(),A m n ,则3OA k =,从而3n m =, 222m n c +=, ∴ ,2c A ⎫⎪⎪⎝⎭将,2c A ⎫⎪⎪⎝⎭代入双曲线22221x y a b -=得: 22223144c c a b -= ()2222234c b a a b ∴-= 且222c a b =+ ()()222222422434320a b b a a b b a b a ∴+-=∴--=从而18.(1)22194x y +=;(2)2(y x =±. 【解析】试题分析:(1)由3a =,利用椭圆的简单性质,可得PQ 的最小值为通径2283b a =可求出b 的值,从而得到椭圆方程;(2)设:PQ l x my =224936x y +=,联立,设()()1122,,,P x y Q x y ,利用韦达定理以及判别式,结合2PF FQ =,列方程求出m ,即可得到直线方程.试题解析:(1)由题意得2283b a =,且3a =∴24b =,故椭圆方程为22194x y +=, (2)设:PQ l x my =+224936x y +=联立得:()2249160m y ++-=, 设()11P x y ,,()22Q x y ,,则1212201649y y y y m ⎧∆>⎪⎪⎪+=⎨⎪-⎪=⎪+⎩, 由2PF FQ =得122y y =-,()212121221122y y y y y y y y +=++=-, 即33201492m m -=-+∴314m =∴PQ l:(2y x =±.。
甘肃省天水市第一中学2017-2018学年高二上学期第二阶段(期中)考试(A卷)物理(理)试题Word版含解析

甘肃省天水市第一中学2017-2018学年高二上学期第二阶段(期中)考试物理(理)试(满分:100分时间:90分钟)一、选择题:(本大题共12小题,每小题4分,共48分,其中1-9是单选,10-12是多选)1. 物理学中,通过引入检验电流来了解磁场力的特性,对检验电流的要求是A. 将检验电流放入磁场,测量其所受的磁场力F,导线长度L,通电电流I,应用公式B=,即可测得磁感应强度BB. 检验电流宜大些C. 利用检验电流和运用公式B=只能应用于匀强磁场D. 只要满足长度L很短,电流很小,将其垂直放入磁场的条件,公式B=对任何磁场都适用【答案】D【解析】ABD、用检验电流来了解磁场,要求检验电流对原来磁场的影响很小,可以忽略,所以导体长度L应很短,电流应很小,垂直磁场方向放置,故AB错误D正确;C、磁感应强度的定义式适用于所有磁场,选项C错误;故选D。
2. 下列关于电源的说法中正确的是A. 电源电动势的大小,等于电源没有接入电路时电源两极间的电压的大小,所以当电源接入电路时,电动势大小将发生变化B. 闭合电路中,并联在电源两端的电压表的示数就是电源电动势的值C. 电源的电动势是表示电源把其它形式的能转化为电能的本领的大小的物理量D. 在闭合电路中,电源的内电压就等于电源两端的电压【答案】C【解析】电源电动势的大小是由电源本身决定的量,与是否接入电路无关;选项A错误;闭合电路中,当电源不接入电路时,并联在电源两端的电压表的示数大小等于电源电动势的值,选项B错误;电源的电动势是表示电源把其它形式的能转化为电势能的本领的大小的物理量,选项C正确;在闭合电路中,电源的外电压就等于电源两端的电压,即路端电压,选项D错误;故选C.3. 一电流表的满偏电流Ig=1mA,内阻为200Ω。
要把它改装成一个量程为0.5A的电流表,则应在电流表上A. 并联一个0.4Ω的电阻B. 并联一个200Ω的电阻C. 串联一个0.4Ω的电阻D. 串联一个200Ω的电阻【答案】A【解析】试题分析:改装成电流表需要并联一个电阻分流,根据串并联电路规律可得,代入数据可得,故A正确;考点:考查了电流表的改装4. 如图所示,电路中、均为可变电阻,电源内阻不能忽略,平行板电容器C的极板水平4. 放置。