上机考试复习题

上机考试复习题一、填空题1、建立一个对象数组，内放5个学生的数据（学号、成绩），用指针指向首元素，输出第1、3、5个学生的数据。

#include <iostream>using namespace std;class Student{public:【1】1、Student(int n, float s){num=n; score=s;}void display();private:int num;float score;};void Student::display(){【2】2、cout<<"num: "<<num;cout<<”score:”<<score;}int main(){Student stud[5]={Student(101,78.5),Student(102,85.5),Student(103,98.5),Student(104,100.0),Student(105,95.5)};【3】3、Student *p=stud;for(int i=0;i<=2; 【4】) 4、p=p+2,i++【5】5、p->display();return 0;}2、定义一个复数类Complex，重载运算符“-”使之能用于复数的减。

运算符重载函数作为Complex类的成员函数。

编写程序，分别求两个复数之差。

#include <iostream>using namespace std;class Complex{public:Complex(){real=0;imag=0;}Complex(double r,double i){real=r;imag=i;}Complex operator-(Complex &c2);void display();private:double real;double imag;};【6】6、Complex Complex::operator-(Complex &c2){Complex c;【7】7、c.real=real-c2.real;【8】8、c.imag=imag-c2.imag;return c;}void Complex::display(){cout<<"("<<real<<","<<imag<<"i)"<<endl;}int main(){Complex c1(1,2),c2(-6,7),c3;【9】9、c3=c1-c2;cout<<"c1-c2=";【10】10、c3.display();return 0;}3、建立一个对象数组，内放5个学生的数据(学号、成绩)，设立一个函数max，用指向对象的指针作函数参数，在max函数中找出5个学生中成绩最高者，并输出其学号。

#include <iostream>using namespace std;class Student{public:Student(int n,float s):num(n),score(s){}int num;float score;};void main(){Student stud[5]={Student(101,78.5),Student(102,85.5),Student(103,98.5),Student(104,100.0),Student(105,95.5)};【11】11、void max(Student* );【12】12、Student *p=&stud[0];【13】13、max(p);}void max(Student *arr){ float max_score=arr[0].score;int k=0;for(int i=1;i<5;i++)if(【14】14、arr[i].score>max_score) {max_score=arr[i].score;k=i;} 【15】15、cout<<arr[k].num<<" "<<max_score<<endl;}4、有两个矩阵a和b，均为2行3列。

求两个矩阵之和。

重载运算符“+”，使之能用于矩阵相加（如c=a+b）。

#include <iostream.h>class Matrix{public:Matrix();【16】16、friend Matrix operator+(Matrix &,Matrix &);void input();void display();private:int mat[2][3];};Matrix::Matrix(){for(int i=0;i<2;i++)for(int j=0;j<3;j++)【17】17、mat[i][j]=0;}Matrix operator+(Matrix &a,Matrix &b){Matrix c;for(int i=0;i<2;i++)for(int j=0;j<3;j++){【18】18、c.mat[i][j]=a.mat[i][j]+b.mat[i][j];} return c;}void Matrix::input(){cout<<"input value of matrix:"<<endl;for(int i=0;i<2;i++)for(int j=0;j<3;j++)cin>>mat[i][j];}void Matrix::display(){for (int i=0;i<2;i++){for(int j=0;j<3;j++){cout<<mat[i][j]<<" ";}cout<<endl;}}int main(){Matrix a,b,c;a.input();b.input();cout<<endl<<"Matrix a:"<<endl;a.display();cout<<endl<<"Matrix b:"<<endl;b.display();【19】19、c=a+b;cout<<endl<<"Matrix c = Matrix a + Matrix b :"<<endl; 【20】20、c.display();return 0;}1、#include <iostream>using namespace std;int main( ){ int add(int x,int y);int a,b,c;cin>>a>>b;c=add(a,b);cout<<"a+b="<<c<<endl;return 0;}int add(int x,int y){ int z;z=x+y;return(z);}二、程序改错题1、#include <iostream>using namespace std;int main( ){ int add(int x,int y);int a,b,c;cin>>a>>b;c=add(a,b);cout<<"a+b="<<c<<endl;return 0;}int add(int x,int y){ int z;z=x+y;return(z);}#include <iostream>using namespace std;class Time{ public:int hour;int minute;int sec;};Time t;int main(){void set_time(void) ;void show_time(void) ;set_time();show_time();}void set_time(void){cin>>t.hour;cin>>t.minute;cin>>t.sec;}void show_time(void){cout<<t.hour<<":"<<t.minute<<":"<<t.sec<<endl; }3、#include<iostream.h>#include<math.h>class Point{public:double x,y;Point(double a,double b){x=a;y=b;}friend double distance(Point a,Point b);};double distance(Point a,Point b){double dist;dist=sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));return dist;}void main(){Point p1(2,2),p2(5,5);cout<<"上述两点之间的距离:"<<distance(p1,p2)<<endl; }3、#include<iostream.h>#include<math.h>class Point{double x,y;Point(double a,double b){x=a;y=b;}friend double distance(Point a,Point b);};double Point::distance(Point a,Point b){double dist;dist=sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y));return dist;}void main(){Point p1(2,2),p2(5,5);cout<<"上述两点之间的距离:"<<p1. distance(p1,p2)<<endl; }4、#include<cmath>#include<iostream>using namespace std;class Pixcel{public:double x;double y;void set(double ix,double iy){x=ix;y=iy;}double xoffset(){return x;}double yoffset(){return y;}double angle(){return (180/3.14159)*atan2(y,x);}double radius(){return sqrt(x*x+y*y);}};void main(){Pixcel p;double x,y;cout<<"Enter x and y: "<<endl;cin>>x>>y;p.set(x,y);p.x+=8;p.y+=9;cout<<"angle="<<p.angle()<<",radius="<<p.radius()<<",x offset="<<p.xoffset()<<",y offset="<<p.yoffset()<<endl;}4、#include<cmath>using namespace std;class Pixcel{protected:double x=0;double y=0;public:void set(double ix,double iy){x=ix;y=iy;}double xoffset(){return x;}double yoffset(){return y;}double angle(){return (180/3.14159)*atan2(y,x);}double radius(){return sqrt(x*x+y*y);}}void main(){Pixcel p;double x,y;cout<<"Enter x and y: "<<endl;cin>>x>>y;p.set(x,y);p.x+=8;p.y+=9;cout<<"angle="<<p.angle()<<",radius="<<p.radius()<<",x offset="<<p.xoffset()<<",y offset="<<p.yoffset()<<endl;}三、编程题1、分别声明Teacher(教师)类和Cadre(干部)类，采用多重继承方式由这两个类派生出新类Teacher_Cadre(教师兼干部)类。