Scalar and Spinor Perturbation to the Kerr-NUT Spacetime
计算理论导论(英文版)前言01

What the course is about
The theory of computation represents a fascinating landscape that intersects交叉computer science and mathematics and can be roughly divided into three overlapping areas: AUTOMATA AND LANGUAGES, COMPUTABILITY THEORY , and COMPLEXITY THEORY .
Several different computational models were devised by these early researchers. One model, the Turing machine, stores characters on an infinitely long tape, with one square at any given time being scanned by a read/write head. Another model, recursive functions, uses functions and function composition to
The first step was to define what was meant by a "simple method" for solving a problem, implying a need for a formal model of computation.
1
computational models
3
2 What the course is about
诺顿读本

诺顿读本诺顿读本格雷马库斯第四章学习的基本过程出于生存考虑,动物必须适应所处环境。
物竞天择下的进化是最长期的适应过程,正如第三章所述,它使每个物种在特定的环境下具备了生存的能力。
但是环境不是一成不变的,它因时因地而异,即便是在某个个体短暂的一生中。
为了更加有效地寻找食物,伴侣,躲避捕食者并且进行必要的生存繁衍,动物必须适应他们所处的瞬息万变的特殊环境。
换而言之,他们必须学习。
在涉及很多现象时,学习一词被不同心理学家付之以很多形式。
为了达到我们的目标,我们可以将其广义的定义为“某次经历中取得的,能够改变个体未来行为的任何过程。
”此处定义的“经历”是指个体感觉系统(视觉听觉触觉等)所传达的所有环境影响。
“未来行为”是指随后的行文,它不包括个体在学习过程中对感官刺激的即时应里。
如果在闪光入目之前做出点击之响,那么你对于点击声或者是光线(如闪烁)的即时反应就不存在发挥学习。
大部分心理学在未来行为上都与经历所带来的影响有这样或是那样的联系。
社会心理学家试图解释人们信仰和由以往经历所引发的社会行为。
临床心理学家试图解释由以往经历所引发的情绪问题。
认知心理学家试图理解包括在人类学习能力范围内的感知,记忆,思想的基本过程。
因此本书中的许多章节,或是其他相关心理学文章,都以这样或那样的形式涉及“学习”。
在这章中,我们通常仍旧在此书的一部分中将人类心理学与动物心理学联系到一起(研究)。
从进化论观点来说,学习是一套相当有历史的能力。
通过自然选择,所有具备神经系统的动物都获得了某种学习的能力。
人类在某些方面是独特的但是就基本学习原理而言,我们在许多方面都是与其他物种相似的。
接下来你将会读到许多关于我们独一无二的学习能力的内容——比若说我们学习语言的能力。
我们目前的注意力普遍集中在表征哺乳动物(和脊椎动物)的学习原理上,这其中也包括人类。
(下面)我们以古典制约(经典条件)下的种种学习为开端。
条件作用一:基本原理基本原理是指与新反射形成有关的学习过程。
1m_Q Corrections to the Bethe-Salpeter Equation for Lambda_{Q} in the Diquark Picture

a rXiv:h ep-ph/9911527v13Nov1999ADP-99-49/T3851/m Q Corrections to the Bethe-Salpeter Equation for ΛQ in the Diquark Picture X.-H.Guo 1,2,A.W.Thomas 1and A.G.Williams 1,31Department of Physics and Mathematical Physics,and Special Research Center for the Subatomic Structure of Matter,University of Adelaide,SA 5005,Australia 2Institute of High Energy Physics,Academia Sinica,Beijing 100039,China 3Department of Physics and SCRI,Florida State University,Tallahassee,FL 32306-4052e-mail:xhguo@.au,athomas@.au,awilliam@.au Abstract Corrections of order 1/m Q (Q =b or c )to the Bethe-Salpeter (B-S)equa-tion for ΛQ are analyzed on the assumption that the heavy baryon ΛQ is composed of a heavy quark and a scalar,light diquark.It is found that in addition to the one B-S scalar function in the limit m Q →∞,two morescalar functions are needed at the order 1/m Q .These can be related tothe B-S scalar function in the leading order.The six form factors for theweak transition Λb →Λc are expressed in terms of these wave functions andthe results are consistent with HQET to order 1/m Q .Assuming the kernelfor the B-S equation in the limit m Q →∞to consist of a scalar confine-ment term and a one-gluon-exchange term we obtain numerical solutions forthe B-S wave functions,and hence for the Λb →Λc form factors to order1/m Q .Predictions are given for the differential and total decay widths forΛb →Λc l ¯ν,and also for the nonleptonic decay widths for Λb →Λc plus apseudoscalar or vector meson,with QCD corrections being also included.PACS Numbers :11.10.St,12.39.Hg,14.20.Mr,14.20.LqI.IntroductionHeavyflavor physics provides an important area within which to study many important physical phenomena in particle physics,such as the structure and interac-tions inside heavy hadrons,the heavy hadron decay mechanism,and the plausibility of present nonperturbative QCD models.Heavy baryons have been studied much less than heavy mesons,both experimentally and theoretically.However,more ex-perimental data for heavy baryons is being accumulated[1,2,3,4,5,6]and we expect that the experimental situation for them will continue to improve in the near future.On the theoretical side,heavy quark effective theory(HQET)[7]provides a systematic way to study physical processes involving heavy hadrons.With the aid of HQET heavy hadron physics is simplified when m Q≫ΛQCD.In order to get the complete physics,HQET is usually combined with some nonperturbative QCD models which deal with dynamics inside heavy hadrons.As a formally exact equation to describe the hadronic bound state,the B-S equation is an effective method to deal with nonperturbative QCD effects.In fact, in combination with HQET,the B-S equation has already been applied to the heavy meson system[8,9,10].The Isgur-Wise function was calculated[8,10]and1/m Q corrections were also considered[8].In previous work[11,12,13],we established the B-S equations in the heavy quark limit(m Q→∞)for the heavy baryons ΛQ andω(∗)Q(whereω=Ξ,ΣorΩand Q=b or c).These were assumed to be composed of a heavy quark,Q,and a light scalar and axial-vector diquark, respectively.We found that in the limit m Q→∞,the B-S equations for these heavy baryons are greatly simplified.For example,only one B-S scalar function is needed forΛQ in this limit.By assuming that the B-S equation’s kernel consists of a scalar confinement term and a one-gluon-exchange term we gave numerical solutions for the B-S wave functions in the covariant instantaneous approximation, and consequently applied these solutions to calculate the Isgur-Wise functions forthe weak transitionsΛb→Λc andΩ(∗)b→Ω(∗)c.In reality,the heavy quark mass is not infinite.Therefore,in order to give moreexact phenomenological predictions we have to include1/m Q corrections,especially1/m c corrections.It is the purpose of the present paper to analyze the1/m Q cor-rections to the B-S equation forΛQ and to give some phenomenological predictionsfor its weak decays.As in the previous work[11,12,13,14],we will still assumethatΛQ is composed of a heavy quark and a light,scalar diquark.In this picture,the three body system is simplified to a two body system.In the framework of HQET,the eigenstate of HQET Lagrangian|ΛQ HQET has 0+light degrees of freedom.This leads to only one Isgur-Wise functionξ(ω)(ωis the velocity transfer)forΛb→Λc in the leading order of the1/m Q expansion [15,16,17,18,19,20].When1/m Q corrections are included,another form factor inHQET and an unknownflavor-independent parameter which is defined as the massdifference mΛQ−m Q in the heavy quark limit are involved[19].This provides some relations among the six form factors forΛb→Λc to order1/m Q.Consequently,if one form factor is determined,the otherfive form factors can be obtained.Here we extend our previous work to solve the B-S equation forΛQ to order1/m Q,in combination with the results of HQET.It can be shown that two B-S scalar functions are needed at the order1/m Q,in addition to the one scalarfunction in the limit m Q→∞.The relationship among these three scalar functions can be found.Therefore,our numerical results for the B-S wave function in the order m Q→∞can be applied directly to obtain the1/m Q corrections to the form factors for the weak transitionΛb→Λc.It can be shown that the relations among all the six form factors forΛb→Λc in the B-S approach are consistent with those from HQET to order1/m Q.We also give phenomenological predictions for the differential and total decay widths forΛb→Λc l¯ν,and for the nonleptonic decay widths forΛb→Λc plus a pseudoscalar or vector meson.Since the QCD correctionsare comparable with the1/m Q corrections,we also include QCD corrections in our predictions.Furthermore,we discuss the dependence of our results on the various input parameters in our model,and present the comparison of our results with those of other models.The remainder of this paper is organized as follows.In Section II we discuss the B-S equation for the heavy quark and light scalar diquark system to order1/m Q and introduce the two B-S scalar functions appearing at this order.We also discuss the constraint on the form of the kernel.In Section III we express the six form factors forΛb→Λc in terms of the B-S wave function.The consistency of our model with HQET is discussed.We also present numerical solutions for these form factors.In Section VI we apply the solutions for theΛb→Λc form factors,with QCD corrections being included,to the semileptonic decayΛb→Λc l¯ν,and the nonleptonic decaysΛb→Λc plus a pseudoscalar or vector meson.Finally,Section VI contains a summary and discussion.II.The B-S equation forΛQ to1/m QBased on the picture thatΛQ is a bound state of a heavy quark and a light, scalar diquark,its B-S wave function is defined as[11]χ(x1,x2,P)= 0|TψQ(x1)ϕ(x2)|ΛQ(P) ,(1)whereψQ(x1)andϕ(x2)are thefield operators for the heavy quark Q and thev is the total momentum ofΛQ and light,scalar diquark,respectively,P=mΛQv is its velocity.Let m Q and m D be the masses of the heavy quark and the light diquark inΛQ,p be the relative momentum of the two constituents,and define.The B-S wave function in momentum space is defined λ1=m Qm Q+m Dasχ(x1,x2,P)=e iP X d4pwhere X=λ1x1+λ2x2is the coordinate of the center of mass and x=x1−x2. The momentum of the heavy quark is p1=λ1P+p and that of the diquark is p2=−λ2P+p.χP(p)satisfies the following B-S equation[21]χP(p)=S F(λ1P+p) d4qE1+O(1/m2Q),(5)m Qwhere E0and E1/m Q are binding energies at the leading andfirst order in the1/m Q expansion,respectively.m D,E0and E1are independent of m Q.Since we are considering1/m Q corrections to the B-S equation,we expand the heavy quark propagator S F(λ1P+p)to order1/m Q.Wefind1S F=S0F+,(7)2(p l+E0+m D+iǫ)andS1F=i (−E1+p2t/2)(1+/v)2(p l+E0+m D+iǫ)−1−/vIt can be shown that the light diquark propagator to1/m Q still keeps its form in the limit m Q→∞,S D=ip2t+m2D.Similarly to Eq.(6),we writeχP(p)and K(P,p,q)in the following form(to order 1/m Q):χP(p)=χ0P(p)+1m QK1(P,p,q),(10)whereχ1P(p)and K1(P,p,q)arise from1/m Q corrections.As in our previous work, we assume the kernel contains a scalar confinement term and a one-gluon-exchange term.Hence we have−iK0=I⊗IV1+vµ⊗(p2+p′2)µV2,−iK1=I⊗IV3+γµ⊗(p2+p′2)µV4,(11) where vµin K0appears because of the heavy quark symmetry.Substituting Eqs.(6)and(10)into the B-S equation(3)we have the integral equations forχ0P(p)andχ1P(p)χ0P(p)=S0F(λ1P+p) d4q(2π)4K1(P,p,q)χ0P(q)S D(−λ2P+p)+S1F(λ1P+p) d4q(2π)4K0(P,p,q)χ1P(q)S D(−λ2P+p).(13) Eq.(12)is what we obtained in the limit m Q→∞,which together with Eq.(7)gives/vχ0P(p)=χ0P(p),(14)since/v/v=v2=1and so/v S0F=S0F.Therefore,S0F(λ1P+p)γµχ0P(q)=S0F(λ1P+ p)vµχ0P(q)in thefirst term of Eq.(13).So to order1/m Q,the Dirac matrixγµfrom the one-gluon-exchange term in K1(P,p,q)can still be replaced by vµ.We divideχ1P(p)into two parts by definingχ1P(p)=χ+1P(p)+χ−1P(p),/vχ±1P(p)=±χ±1P(p),(15)i.e.,χ+1P(p)≡12[χ1P(p)−/vχ1P(p)].After writingdown all the possible terms forχ0P(p)andχ±1P(p),and considering the constraintson them,Eqs.(14)and(15),we obtain thatχ0P(p)=φ0P(p)uΛQ(v,s),χ+1P(p)=φ1P(p)uΛQ(v,s),χ−1P(p)=φ2P(p)/p t uΛQ(v,s),(16) whereφ0P(p),φ1P(p)andφ2P(p)are Lorentz scalar functions.Substituting Eq.(16)into Eqs.(12)(13)and using Eqs.(7)(8)(9)we haveφ0P(p)=−1(2π)4K0(P,p,q)φ0P(q),(17)φ1P(p)=−1(2π)4K0(P,p,q)φ1P(q)−1(2π)4[K1(P,p,q)+p2t/2−E12φ0P(p).(19)φ0P(p)is the B-S scalar function in the leading order of the1/m Q expansion, which was calculated in[11].From Eq.(19)φ2P(p)can be given in terms ofφ0P(p).The numerical solutions forφ0P(p)andφ1P(p)can be obtained by discretizing the integration region into n pieces(with n sufficiently large).In this way,the integral equations become matrix equations and the B-S scalar functionsφ0P(p)andφ1P(p) become n dimensional vectors.Thusφ0P(p)is the solution of the eigenvalue equation (A−I)φ0=0,where A is an n×n matrix corresponding to the right hand side of Eq.(17).In order to have a unique solution for the ground state,the rank of(A−I) should be n−1.From Eq.(18),φ1P(p)is the solution of(A−I)φ1=B,where B is an n dimensional vector corresponding to the second integral term on the right hand side of Eq.(18).In order to have solutions forφ1P(p),the rank of the augmented matrix(A−I,B)should be equal to that of(A−I),i.e.,B can be expressed as linear combination of the n−1linearly independent columns in(A−I).This is difficult to guarantee if B=0,since the way to divide(A−I)into n columns is arbitrary.Therefore,we demand the following condition in order to have solutions forφ1P(p)d4q p l+E0+m D+iǫK0(P,p,q) φ0P(q)=0.(20) Eq.(20)provides a constraint on the form of the kernel K1(P,p,q),in which E1is also related K1(P,p,q).In this way,φ1P(p)satisfies the same eigenvalue equation asφ0P(p).Therefore,we haveφ1P(p)=σφ0P(p),(21)whereσis a constant of proportionality,with mass dimension,which can be deter-mined by Luke’s theorem[22]at the zero-recoil point in HQET.We will discuss it in the next section.Since bothφ1P(p)andφ2P(p)can be related toφ0P(p),we can calculate the 1/m Q corrections without explicitly solving the integral equations forφ1P(p)and φ2P(p).In the previous work[11]φ0P(p)was solved by assuming that V1and V2inEq.(11)arise from linear confinement and one-gluon-exchange terms,respectively. In the covariant instantaneous approximation,˜V i≡V i|p l=q l,i=1,2,wefind˜V 1=8πκ(2π)38πκ3α(eff)2sQ20Q2+Q2,to describe the internal structure of the light diquark[23]. Defining˜φ0P(p t)= d p l2(E0−W p+m D)W pd3q t(p l+E0+m D+iǫ)(p2l−W2p+iǫ)d3q t−(G 1(ω)γµ+G 2(ω)v µ+G 3(ω)v ′µ)γ5]u Λb (v ),(25)where J µis the V −A weak current,v and v ′are the velocities of Λb and Λc ,respectively,and ω=v ′·v .The form factors F i and G i (i =1,2,3)are related to each other by the following equations,to order 1/m Q ,when HQET is applied [19]F1=G 1 1+ 1m b¯Λm c¯Λm b ¯Λ(2π)4¯χP ′(p ′)γµ(1−γ5)χP (p )S −1D (p 2),(27)where P (P ′)is the momentum of Λb (Λc ).¯χP ′(p ′)is the wave function of the final state Λc (v ′)which can also be expressed in terms of the three B-S scalar functions φ0P (p ),φ1P (p )and φ2P (p )in Eq.(16)¯χP (p )=¯u ΛQ (v,s ) φ0P (p )+1m c +11+ω =−i d 4km c[φ1P ′(k ′)−(k ′l +m D )φ2P ′(k ′)]φ0P (k )(k 2l −W 2k )+1m b(f1−f2)+1(2π)4 φ0P′(k′)φ0P(k)(k2l−W2k)+1m c[φ1P′(k′)−(k′l+m D)φ2P′(k′)]φ0P(k)(k2l−W2k)+1m bφ0P′(k′)[φ1P(k)−(k l+m D)φ2P(k)](k2l−W2k) +O(1/m2Q),(30) 11+ω+2(f1−m D F) =O(1/m2Q),(31)11+ω+2f2 =O(1/m2Q),(32) where we have defined f1,f2and F by the following equations,on the grounds of Lorentz invariance:d4k(2π)4φ2P′(k′)φ0P(k)kµ(k2l−W2k)=f1vµ+f2v′µ.(34) Eq.(34)leads tof1+f2=1(2π)4φ2P′(k′)φ0P(k)(k2l−W2k)(v·k+v′·k).(35)Eqs.(29)and(30)give the expression for G1to order1/m Q.From Eqs.(31)and (32)we can see that Eq.(29)is the same as Eq.(30).Therefore,we can calculate G1to1/m Q from either of these two equations.This indicates that our model is consistent with HQET to order1/m Q.Substituting Eq.(35)into Eq.(30)and using Eq.(19)we haveG1=−i d4k+12(k′l+m D)φ0P′(k′)]φ0P(k)(k2l−W2k)+12(k l+m D)φ0P(k)](k2l−W2k)+ 1m b 1ω2−1cosθ,k′2t=k2t+k2t(ω2−1)cos2θ+k2l(ω2−1)−2k l k tω√contour we haveG 1(ω)=ξ(ω)+1m bA b (ω),(41)whereξ(ω)=−d 3k t(2π)3(ω2−1)W k +ωk t√2(ω+1)F (ω,k t ),(43)A b (ω)=d 3k tω2−1cos θE 0+m D −ωW k −k t√(2π)3˜φ0P ′(r t )[˜V 1(k ′t −r t )−2(ωW k +k t√(2π)3ρ(q 2t )4π22ρ(q 2t )(2π)3ρ(q 2t )4π2ρ(q 2t )(|p t |−|q t |)2+δ2,(47)where ρ(q 2t )is some arbitrary function of q 2t .In our model we have several parameters,α(eff)s ,κ,Q 20,m D ,E 0and E 1.The parameter Q 20can be chosen as 3.2GeV 2from the data for the electromagnetic formfactor of the proton [23].As discussed in Ref.[11],we let κvary in the region between 0.02GeV 3and 0.1GeV 3.In HQET,the binding energies should satisfy the constraint Eq.(5).Note that m D +E 0and E 1are independent of the flavor of the heavy quark.From the B-S equation solutions in the meson case,it has been found that the values m b =5.02GeV and m c =1.58GeV give predictions which are in good agreementwith experiments[8].Since in the b-baryon case the O(1/m2b)corrections are very small,we use the following equation to discuss the relations among m D,E0and E1,m D+E0+1m bE1)/E0∼ΛQCDπv1,∆G1=ξαs(¯m)πv i,∆G i=−ξαs(¯m)where v i=v i(ω)and a i=a i(ω)(i=1,2,3)are the QCD corrections calculated from the next-to-leading order renormalization group improved perturbation theory. The scale¯m is chosen such that higher-order terms(αs ln(m b/m c))n(n>1)do not contribute.Consequently,it is not necessary to apply a renormalization group summation as far as only numerical evaluations are concerned.It is shown that¯m can be chosen as2m b m c/(m b+m c)≃2.3GeV.The detailed formulae for v i and a i can be found in[25],which also includes a discussion on the infra-red cutoffemployed in the calculation of the vertex corrections.As in[25],we choose this cutoffto be 200MeV which is afictitious gluon mass.Furthermore,we useΛQCD=200MeV in our numerical calculations.Fig.1The numerical results for F i(i=1,2,3)forκ=0.02GeV3(solid lines)andκ= 0.10GeV3(dotted lines),with m D=0.7GeV.From top to bottom we have F1,F3,and F2,respectively.A.Semileptonic decaysΛb→Λc l¯νMaking use of the general kinematical formulae by K¨o ner and Kr¨a mer[26],wefind for the differential decay width of Λb →Λc l ¯ν[14]dΓ3m 4Λc m Λb AF 21√m c+1πv 1(ω−1)[3(η+η−1)+2−4ω]+αsπ(ω2−1)[v 2(1+η)+v 3(1+η−1)+a 2(1−η)+a 3(η−1−1)],(50)where η=m Λc /m Λb and A =G 2F2+)+b (0−)through which Λc is detected,since the structure for such decays isalready well known.It should be noted that in Eq.(50)O (αs ¯Λ/m Q )corrections have been ignored and the lepton mass is set to zero.The plot for A −1dΓ204060801001201 1.05 1.1 1.15 1.2 1.25 1.3 1.35 1.4 1.45ωdΓFig.2The numerical results for A −1dΓTable1:Predictions for the decay rates forΛb→Λc l¯ν,in units1010s−1B(Λc→ab)m D(GeV)Γ0Γ1/mQ Γ1/mQ+QCD0.70 5.12(7.12) 4.60(6.56) 3.34(4.72)√1We note that the results without either1/m Q and QCD corrections in Table1are bigger than those presented in Ref.[11]by about18%.This is because we employed a cutoffin the numerical integrations in Ref.[11],while the integrations are carried out to infinity in the present work.that one of the currents in the Hamiltonian(51)is factorized out and generates a meson[27,28].Thus the decay amplitude of the two body nonleptonic decay be-comes the product of two matrix elements,one is related to the decay constant of the factorized meson(P or V)and the other is the weak transition matrix element betweenΛb andΛc,M fac(Λb→Λc P(V))=G F2V cb V∗UD a1 P(V)|Aµ(Vµ)|0 Λc(P′)|Jµ|Λb(P) ,(52) where 0|Aµ(Vµ)|P(V) are related to the decay constants of the pseudoscalar meson or vector meson by0|Aµ|P =if P qµ,0|Vµ|V =f V m Vǫµ,(53) where qµis the momentum of the meson emitted from the W-boson andǫµis the polarization vector of the emitted vector meson.It is noted that in the two-body nonleptonic weak decaysΛb→Λc P(V)there is no contribution from the a2term since such a term corresponds to the transition ofΛb to a light baryon instead ofΛc. On the other hand,the general form for the amplitudes ofΛb→Λc P(V)are M(Λb→Λc P)=i¯uΛc(P′)(A+Bγ5)uΛb(P),M(Λb→Λc V)=¯uΛc(P′)ǫ∗µ(A1γµγ5+A2P′µγ5+B1γµ+B2P′µ)uΛb(P).(54)Alternatively,the matrix element forΛb→Λc can be expressed as the following on the ground of Lorentz invarianceΛc(P′)|Jµ|Λb(P) =¯uΛc(P′)[f1(q2)γµ+if2(q2)σµνqν+f3(q2)qµ−(g1(q2)γµ+ig2(q2)σµνqν+g3(q2)qµ)γ5]uΛb(P),(55) where f i,g i(i=1,2,3)are the Lorentz scalars.The relations between f i,g i andF i,G i aref1=F1+1mΛb+F32 F2mΛc ,f3=1mΛb−F32(mΛb−mΛc)G2mΛc,g2=1mΛb+G32 G2mΛc.(56)The decay widths and the up-down asymmetries forΛb→Λc P(V)are available in Refs.[29][30]:Γ(Λb→Λc P)=| P′|m2Λb|A|2+(mΛb−mΛc)2−m2P(EΛc+mΛc)|A|2+(EΛc−mΛc)|B|2,(57)where A and B are related to the form factors byA=G F2V cb V∗UD a1f P[(mΛb−mΛc)f1(m2P)+m2P f3(m2P)],B=G F2V cb V∗UD a1f P[(mΛb+mΛc)g1(m2P)−m2P g3(m2P)],(58)andΓ(Λb→Λc V)=| P′|mΛb2(|S|2+|P2|2)+E2V2m2V(|S|2+|P2|2)+E2V(|S+D|2+|P1|2),(59) whereS=−A1,D=−|P′|2P1=−| P′|EΛc+mΛcB1+mΛbB2),P2=|P′|√√√√Table2:Predictions for the decay rates(in units1010s−1a21,which is defined in Eq.(51)),and the asymmetry parameters forΛb→Λc P(V)ProcessΓ0Γ1/mQ Γ1/mQ+QCDα1/mQ+QCDΛ0b→Λ+cρ−0.44(0.78)0.51(0.94)0.42(0.77)-0.89Λ0b→Λ+c D∗−s0.78(1.17)0.89(1.35)0.76(1.15)-0.38Λ0b→Λ+c K∗−0.023(0.041)0.027(0.049)0.022(0.040)-0.85Λ0b→Λ+c D∗−0.027(0.041)0.031(0.048)0.026(0.040)-0.42In our previous work[13,14],theΛb→Λc semileptonic and nonleptonic decay widths were calculated using a hadronic wave function model in the infinite momen-tum frame by combining the Drell-Yan type overlap integrals and the results from HQET to order1/m paring the results in our present B-S model with those in Refs.[13,14],wefind that there is overlap between these two model predictions.The results withκ=0.02GeV3in the present model are close to those in Refs.[13,14]if the average transverse momentum of the heavy quark is chosen as400MeV.The Cabibbo-allowed nonleptonic decay widths have also been calculated in the nonrelativistic quark model approach[29],where the form factors are calculated at the zero-recoil point and then extrapolated to otherωvalues under the assumption of a dipole behavior.It seems that the predictions in this model are close to those in our present work if we chooseκ=0.02GeV3.V.Summary and discussionIn the present work,we assume that a heavy baryonΛQ is composed of a heavy quark,Q,and a scalar light diquark.Based on this picture,we analyze the1/m Q corrections to the B-S equation forΛQ which was established in the limit m Q→∞in previous work[11].Wefind that in addition to the one B-S scalar functionwhen m Q→∞,two more scalar functions,φ1P(p)andφ2P(p),are needed at order 1/m Q.φ2P(p)is related toφ0P(p)directly[Eq.(19)].Furthermore,with the aidof the reasonable constraint on the B-S kernel at order1/m Q,Eq.(20),and Luke’stheorem,φ1P(p)can also be related to the B-S scalar function in the leading order.Hence we do not need to solve explicitly forφ1P(p)andφ2P(p)any more.The B-Swave function in the leading order of1/m Q expansion was obtained numericallyby assuming the kernel for the B-S equation in the limit m Q→∞to consist of a scalar confinement term and a one-gluon-exchange term.On the other hand,all the six form factors forΛb→Λc are related to each other to order1/m Q, as indicated from HQET.We determine these form factors by expressing them interms of the B-S wave functions.We also show explicitly that the results from ourmodel are consistent with HQET to order1/m Q.We also discuss the dependenceof our numerical results on the various parameters in our model.It is found thatF i,G i(i=1,2,3)are insensitive to the binding energy,at order1/m Q,and theirdependence on the diquark mass,m D,is mild.However,the numerical solutions arevery sensitive to the parameterκ.Furthermore,we apply our solutions for the weak decay form factors to calculatethe differential and total decay widths for the semileptonic decaysΛb→Λc l¯ν,and the nonleptonic decay widths forΛb→Λc P(V).The QCD corrections are also included,and found to be comparable with the1/m Q corrections.Again the numer-ical results for the decay widths mostly depend onκ.We also compare our resultswith other models,including the hadronic wave function model and the norelativis-tic quark model,where1/m Q corrections are also included.Generally predictionsfrom these models are consistent with each other if we take into account the range ofmodel parameters.Data from the future experiments will help tofix the parametersand allow one to test these models.Besides the uncertainties from the parameters in our model,higher order correc-tions such as O(1/m2Q)and O(αs¯Λ/m Q)will modify our results.However,we expect them to be small.Furthermore,we take a phenomenologically inspired form for the kernel of the B-S equation and use the covariant instantaneous approximation while solving the B-S equation.All these ans¨a tze should be tested by the forthcoming experiments.Acknowledgment:This work was supported in part by the Australian Research Council and the National Science Foundation of China.References[1]OPAL collaboration,R.Akers et al.,Z.Phys.C69(1996)195;Phys.Lett.B353(1995)402;OPAL collaboration,K.Ackerstaffet al.,Phys.Lett.B426(1998) 161.[2]UA1Collaboration,C.Albarjar et al.,Phys.Lett.B273(1991)540.[3]CDF Collaboration,F.Abe et al.,Phys.Rev.D47(1993)2639.[4]S.E.Tzmarias,invited talk presented in the27th International Conference onHigh Energy Physics,Glasgow,July20-27,1994;P.Abreu et al.,Phys.Lett.B374(1996)351.[5]CDF Collaboration,F.Abe et al.,Phys.Rev.D55(1997)1142.[6]C.Caso et al.,The Particle Data Group,Eur.Phys.J.C3(1998)1.[7]N.Isgur and M.B.Wise,Phys.Lett.B232(1989)113,B237(1990)527;H.Georgi,Phys.Lett.B264(1991)447;see also M.Neubert,Phys.Rep.245 (1994)259for the review.[8]H.-Y.Jin,C.-S.Huang and Y.-B.Dai,Z.Phys.C56(1992)707;Y.-B.Dai,C.-S.Huang and H.-Y.Jin,Z.Phys.C60(1993)527;Y.-B.Dai,C.-S.Huangand H.-Y.Jin,Z.Phys.C65(1995)87.[9]F.Hussain and G.Thompson,Phys.Lett.B335(1994)205.[10]A.Abd El-Hady,K.S.Gupta,A.J.Sommerer,J.Spence and J.P.Vary,Phys.Rev.D51(1995)5245.[11]X.-H.Guo and T.Muta,Phys.Rev.D54(1996)4629;Mod.Phys.Lett.A11(1996)1523.[12]X.-H.Guo,A.W.Thomas and A.G.Williams,Phys.Rev.D59(1999)116007.[13]X.-H.Guo,Mod.Phys.Lett.A13(1998)2265.[14]X.-H.Guo and P.Kroll,Z.Phys.C59(1993)567.[15]N.Isgur and M.B.Wise,Nucl.Phys.B348(1991)276.[16]H.Georgi,Nucl.Phys.B348(1991)293.[17]T.Mannel,W.Roberts and Z.Ryzak,Nucl.Phys.B355(1991)38.[18]F.Hussain,J.G.K¨o rner,M.Kr¨a mmer and G.Thompson,Z.Phys.C51(1991)321.[19]H.Georgi,B.Grinstein and M.B.Wise,Phys.Lett.B252(1990)456.[20]A.Falk,Nucl.Phys.B378(1992)79.[21]D.Lurie,P articles and F ields(Interscience Publishers,John Willey&Sons,New York,London,Sydney,1968); C.Itzykson and J.B.Zuber, Quantum F ield T heory(McGraw-Hill,New York,1980).[22]M.E.Luke,Phys.Lett.B252(1990)447.[23]M.Anselmino,P.Kroll and B.Pire,Z.Phys.C36(1987)89;P.Kroll,B.Quadder and W.Schweiger,Nucl.Phys.B316(1988)373.[24]F.Close and A.W.Thomas,Phys.Lett.B212(1988)227.[25]M.Neubert,Nucl.Phys.B371(1992)149.[26]J.G.K¨o rner and M.Kr¨a mer,Phys.Lett.B275(1992)495.[27]J.D.Bjorken,Nucl.Phys.(Proc.Suppl.)11(1989)325.[28]M.J.Dugan and B.Grinstein,Phys.Lett.B255(1991)583.[29]H.Y.Cheng,Phys.Lett.B289(1992)455;H.Y.Cheng,Phys.Rev.D56(1997)2799;H.Y.Cheng and B.Tseng,Phys.Rev.D53(1996)1457.[30]S.Pakvasa,S.F.Tuan and S.P.Rosen,Phys.Rev.D42(1990)3746.。
The principles and behavior of transistors

The principles and behavior oftransistorsTransistors are essential components in modern electronics, enabling a vast array of devices that have transformed the way we interact with the world. From smartphones to computers, transistors play a critical role in the development and innovation of technology. However, the principles and behavior of transistors can be complex, and understanding them is essential to their effective use.A transistor is an electronic component that can amplify or switch electrical signals. It is formed from a semiconductor material, typically silicon, with three layers. These layers include an emitter, a base, and a collector. The base is the control layer, which determines the flow of current between the emitter and the collector.The behavior of a transistor depends on its mode of operation, which can be either as an amplifier or a switch. As an amplifier, a transistor increases the amplitude of an input signal, while as a switch, it can either allow or block the flow of current, depending on the voltage applied to it.One of the most important principles of transistors is their ability to act as voltage-controlled switches. When the voltage applied to the base of a transistor is high, it allows current to flow between the emitter and the collector. When the voltage is low, it blocks the flow of current. This property allows transistors to operate as digital switches in computer circuits, enabling the binary 1s and 0s that form the basis of digital computation.Another essential principle of transistors is their ability to amplify electrical signals. In an amplifier circuit, the input signal is applied to the base of the transistor, which controls the flow of current between the emitter and the collector. The output signal is taken from the collector, and its amplitude is larger than the input signal.The gain of a transistor amplifier is determined by the ratio of the output current to the input current. The higher the gain, the more efficient the amplifier is at amplifyingsignals. However, the gain is limited by the maximum amount of current that the transistor can allow to flow.To ensure the proper behavior of a transistor, several key factors must be considered. These include the voltage and current ratings, the collector-to-emitter breakdown voltage, and the noise figure. These factors will vary depending on the specific application of the transistor, and they must be carefully selected to ensure optimal performance.In addition to their principles and behavior, the use of transistors also requires specific behavior on the part of the designer and the user. Proper handling and installation are essential to avoid damage or failure of the transistor. This may include following temperature and humidity specifications, using appropriate heatsinks or thermal management solutions, and adhering to safe handling practices.In conclusion, the principles and behavior of transistors are critical to the design and operation of modern electronics. Understanding these principles and their application is essential for effective use and innovation of technology. From the behavior of transistors as voltage-controlled switches to their use as amplifiers, these components have revolutionized the way we interact with the world, and their impact will continue to be significant in the years to come.。
The QCD Coupling Constant

and Nuclear Physics, Division of High Energy Physics of the U.S. Department of Energy under Contracts DE-AC03-76SF00098.
KEYWORDS: QCD,
ABSTRACT: This paper presents a summary of the current status of determinations of the strong coupling constant αs . A detailed description of the definition, scale dependence and inherent theoretical ambiguities is given. The various physical processes that can be used to determine αs are reviewed and attention is given to the uncertainties, both theoretical and experimental.
10 15 15
αs FROM τ DECAY . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . αs FROM LATTICE GAUGE THEORY COMPUTATIONS . . . . . . . . . . . . αs FROM HEAVY QUARK SYSTEMS . . . . . . . . . . . . . . . . . . . . . . . . αs FROM HADRON-HADRON SCATTERING . . . . . . . . . . . . . . . . . . . CONCLUSION . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
法布里珀罗基模共振英文

法布里珀罗基模共振英文The Fabryperot ResonanceOptics, the study of light and its properties, has been a subject of fascination for scientists and researchers for centuries. One of the fundamental phenomena in optics is the Fabry-Perot resonance, named after the French physicists Charles Fabry and Alfred Perot, who first described it in the late 19th century. This resonance effect has numerous applications in various fields, ranging from telecommunications to quantum physics, and its understanding is crucial in the development of advanced optical technologies.The Fabry-Perot resonance occurs when light is reflected multiple times between two parallel, partially reflective surfaces, known as mirrors. This creates a standing wave pattern within the cavity formed by the mirrors, where the light waves interfere constructively and destructively to produce a series of sharp peaks and valleys in the transmitted and reflected light intensity. The specific wavelengths at which the constructive interference occurs are known as the resonant wavelengths of the Fabry-Perot cavity.The resonant wavelengths of a Fabry-Perot cavity are determined bythe distance between the mirrors, the refractive index of the material within the cavity, and the wavelength of the incident light. When the optical path length, which is the product of the refractive index and the physical distance between the mirrors, is an integer multiple of the wavelength of the incident light, the light waves interfere constructively, resulting in a high-intensity transmission through the cavity. Conversely, when the optical path length is not an integer multiple of the wavelength, the light waves interfere destructively, leading to a low-intensity transmission.The sharpness of the resonant peaks in a Fabry-Perot cavity is determined by the reflectivity of the mirrors. Highly reflective mirrors result in a higher finesse, which is a measure of the ratio of the spacing between the resonant peaks to their width. This high finesse allows for the creation of narrow-linewidth, high-resolution optical filters and laser cavities, which are essential components in various optical systems.One of the key applications of the Fabry-Perot resonance is in the field of optical telecommunications. Fiber-optic communication systems often utilize Fabry-Perot filters to select specific wavelength channels for data transmission, enabling the efficient use of the available bandwidth in fiber-optic networks. These filters can be tuned by adjusting the mirror separation or the refractive index of the cavity, allowing for dynamic wavelength selection andreconfiguration of the communication system.Another important application of the Fabry-Perot resonance is in the field of laser technology. Fabry-Perot cavities are commonly used as the optical resonator in various types of lasers, providing the necessary feedback to sustain the lasing process. The high finesse of the Fabry-Perot cavity allows for the generation of highly monochromatic and coherent light, which is crucial for applications such as spectroscopy, interferometry, and precision metrology.In the realm of quantum physics, the Fabry-Perot resonance plays a crucial role in the study of cavity quantum electrodynamics (cQED). In cQED, atoms or other quantum systems are placed inside a Fabry-Perot cavity, where the strong interaction between the atoms and the confined electromagnetic field can lead to the observation of fascinating quantum phenomena, such as the Purcell effect, vacuum Rabi oscillations, and the generation of nonclassical states of light.Furthermore, the Fabry-Perot resonance has found applications in the field of optical sensing, where it is used to detect small changes in physical parameters, such as displacement, pressure, or temperature. The high sensitivity and stability of Fabry-Perot interferometers make them valuable tools in various sensing and measurement applications, ranging from seismic monitoring to the detection of gravitational waves.The Fabry-Perot resonance is a fundamental concept in optics that has enabled the development of numerous advanced optical technologies. Its versatility and importance in various fields of science and engineering have made it a subject of continuous research and innovation. As the field of optics continues to advance, the Fabry-Perot resonance will undoubtedly play an increasingly crucial role in shaping the future of optical systems and applications.。
SCALARMULTIPLESANDTHESCALESOFJUSTICEHOW#..

Scalar Multiples and the Scales of Justice: How Mathematics Prepares One for Law SchoolAdair Ford Boroughs, Furman University Class of 2002As a group, math majors perform better on the LSAT than any other major.1 Math majors also tend to perform better in law school than their counterparts. This outcome seems obvious to those who have experienced the rigor of mathematics and a law curriculum, but to students hoping to enter the legal field, political science or history may seem a more natural fit. This essay attempts to give students a better idea about what skills are necessary for success in law school and why a mathematics major provides those skills.2The LSATThe LSAT is comprised of three section types: Logical reasoning (50%), Logic Games (25%), and Reading Comprehension (25%). The first thing you need to know is that all LSAT questions are logic questions.3 If you have not been trained to think critically and deductively, you will not do well on this test. This isn’t your SAT critical thinking, either, but higher-level logic. Just to give you an idea, understanding the following concepts are critical to LSAT performance:Fluid grasp of conditional statements, if-and-only if statements and various ways ofstating the same conditionalUniversal and Existential quantifiers (all, some, none, any, both, every, etc)Necessary versus sufficient conditionsConjunctive and Disjunctive testsDeMorgan’s LawInclusion-Exclusion PrincipalThe Pigeonhole PrincipalOther Basic arguments in symbolic logicOther Basic concepts in Set theoryCorrelation versus CausationCertainly, LSAT takers can employ these concepts without knowing their names or studying them formally. But one aspect of the LSAT makes formal study of these concepts particularly helpful—timing. LSAT takers often do not finish the test. On the Logic Games sections in particular, very few test-takers complete the sections. Unanswered questions count just like wrong answers, so being able to answer questions not only correctly but quickly matters.1 See /%7Eemillner/Economics/lsat.htm for a list of majors and average LSAT scores.2 As a disclaimer, I am writing from the perspective of a math major. Thus, my perspective is not without bias, cognitive dissonance, etc. Any a priori beliefs I held were reinforced when I found the LSAT and law school easier than many of my classmates.3 I actually taught LSAT classes long before I took the test or thought I wanted to go to law school. The director of the program was short teachers, knew that I was a math major and asked if I would take a practice LSAT. (A certain score would qualify me as a teacher.) I actually found the test to be quite fun and much like problem-solving in mathematics, and this is what let to my interest in law school. I thought if this is what law school is like, I’m in. Much of what I say here is also influenced by anecdotal evidence of students that in my LSAT classes.Students who have immersed themselves in these logical concepts in undergraduate study and are comfortable and familiar with them, recognize them quickly, apply what they know and move on. They don’t have to think about it too hard or second-guess themselves. For example, the question may be “if X, then Y and if X then Z. Which of the following is true?”(a)if Y, then X(b)Z, if Y(c)Y only when X(d)Not Z only when not XA student comfortable with logic will quickly recognize (a) and (c) as the converse, which is not necessarily true, and (d) as the contrapositive, which is necessarily true (logically equivalent). Students less comfortable with formal logic may figure this out but after losing 2 or 3 valuable minutes.Formal logic training is also helpful because the LSAT uses tricky topics to test whether you catch the logical construct underneath the sentence. The LSAT doesn’t actually use X’s and Y’s. For example the conditional in the question above might be: If a cold medicine is an effective treatment, most people with a cold will use the medication. The converse would seemingly be true: If most people with a cold will use the medication, it is an effective treatment. LSAT takers without formal logic training think, “well, this makes sense” and deal with the question’s topic. Those with lo gic training see this as a simple, If X, then Y statement and do not get trapped by lay understandings of the topics of the questions.Perhaps even more helpful than familiarity with formal logic and set theory, experience with proofs provide mathematics majors a leg up on their classmates when it comes to the LSAT. The LSAT asks a number of questions that require the identification of an assumption in an argument:What is the assumption of the argument?How can you weaken the argument? (The answer here is state that the assumption is false.)How can you strengthen the argument? (The answer here is to state that the assumption is true.)How is the reasoning of the argument vulnerable? (The answer here is to identify theassumption.)What could resolve this apparent paradox? (The answer here is to say that the assumption is false.)If mathematical proofs teach a student nothing else, they teach a student not to make assumptions. Jumps in conclusions are not allowed; everything must be proved. Math professors have a knack at finding every small assumption in your proofs, and as a student of mathematics, I learned to find all of these assumptions myself. It amazes me how much easier it is for me to identify assumptions than it is for my classmates. They are brilliant students at one of the top two law schools in the country, but assumptions in an argument just don’t pop out to my classmates, as they do to me. Their eye has not been trained by the rigor of mathematical proof to see assumptions.Other types of LSAT questions are also much easier for those who have spent considerable time writing proofs.4 Here are just a couple examples4 Experience proving statements are not true also turns out to be very useful. Students not accustomed to proof often lack strategies on how to prove statements not true.The pattern of reasoning in the argument is most closely paralleled by which of the following arguments?Students have a very difficult time with these questions. Each answer choice is an entire argument, so the question is very long. Students spend incredible amounts of time onthese questions and get lost in all the words.But students who are comfortable with proofs can read the structure of the proof without getting caught up in the actual words and can find that structure in an answer choicewithout getting caught up in WWII history, the chemical bond structure of an element or whatever other topic the LSAT has decided to confuse the student with.How is Mary’s response related to Tom’s argument?The answer may be Mary provides a counter example or Mary identifies an assumptionthat Tom is making or Mary takes the argument to its logical conclusion (which isabsurd.) Students well-versed in proof identify these easily.AdmissionsI have spoken with some undergraduates that appear to be under the assumption that a non-humanities major may hurt them in the admissions process. This assumption is completely false. Adm ission committees are primarily interested in if you’ll do well (LSAT and GPA), and secondly interested in diversity, every way you can cut it: gender, race, age, geography, and yes major. They want a student body from a mix of backgrounds. To the extent that 15,000 applicants are Political Science majors and 600 applicants are math majors, being a math major means you’ll contribute to the diversity of the class. Getting back to their primary concern, admission offices are also aware that math and hard science majors tend to perform better in law school.Law School ExamsLaw schools exams are the most daunting part of the law school experience: one 4-hour exam determines your entire grade in a course. Exams are usually made up of 2 or 3 “issue spotter s.” Sometimes the exam will include one policy question, but the issue spotter is the heart of law school exams. These questions consist of a 2-3 page fact pattern—just a story with details and facts relevant to your legal analysis. The question is always some version of: what legal claims can be brought and will they be successful?I write my answers to these questions as I would a proof: to prove Claim A, elements W, X, Y and Z must exist. Element W can be established by J,K, L or (M and N). Facts r, s, and ~t, show K, and W is thus established, and so on. There are several advantages to this structure: (1) your answers are far more organized than many of your classmates, and professors put a fair amount of point value in organization, and (2) you don’t miss anything. Going through an answer in this systematic way results in using every fact—that’s when you know you’ve “spotted” all the issues.Fact patterns are written such that many students will miss subtleties and nuances—simply students make assumptions like those tested on the LSAT. The instructions include aclue to this: “If you need more facts, state what they are and what impact they would have.” Math majors have a knack for noticing assumptions in their own proofs. In a proof, you must prove every step—assume nothing, not even the basic, seemingly familiar rules. Professors point out your assumptions until you can spot them just as easily. This training translates directly to the law exam issue spotter. For example, an average student might say, Y is shown by D and E. Where a math major might recognize, Y is shown by D and E, but only when not F, and we’re not sure whether not F is true.Cold CallingThe other daunting aspect of law school is “cold calling.” This law school feature is simply being called on in class without warning. The difference between getting called on in law school and in undergrad is that in law school, the professor will ask you a series of questions for 30-45 minutes and never switch to another student or switch to lecture. She will simply teach the whole class through Socratic method with you on the spot light. Questions are not simply recall from the reading. Examples are: What would the Lujan Court say in this case? Where do Justice O’Conner a nd Justice Scalia differ? If you were the government, how would you respond to that claim? How does this reasoning in this case compare to the reasoning in Case X?Again being able to identify assumptions, break down the logical structure of arguments, and being able to prove your own case are essentials. Unlike practically all of my classmates, I actually really enjoy the cold calling experience. I find it very intellectually stimulating—you have to think quickly and articulately on your feet. But without the logic skills to keep pace with questions, it can be humiliating. Most students develop the logic skills by the end of law school—this is part of what law school teaches, but the first 2 years can be painful. For the math major and those well-versed in logic, the entire experience can be fun and rewarding—even the infamous first year.If this essay seems to contain lots of technical logic—welcome to law school.。
托福阅读tpo60R-1原文+译文+题目+答案+背景知识

TPO60 阅读-1 Underground Life原文 (1)译文 (2)题目 (3)答案 (7)背景知识 (7)原文Underground Life①Until about the late 1980s, most scientists believed that life was restricted to the top few meters of the soil or ocean sediments. The few reports of organisms being recovered from great depths within Earth were dismissed as contamination with material from the surface layers. Two technical developments changed this view. The first was the development of drilling techniques that gave confidence that samples could be retrieved from depth without contamination. Samples were recovered using a diamond-studded drill bit that headed a great length of rotating steel pipe from a drilling derrick. A concentrated tracer material was added to the lubricating fluid so that when a deep sample of rock was removed, any contaminated material could be identified and cut away to leave a pristine sample of rock from deep within Earth. The second development was the advent of techniques for identifying microorganisms without having to grow them in culture. All organisms contain DNA, and their presence can be revealed by dyes that either stain DNA directly or can be attached to nucleic acid probes. By varying the nucleic acid probe, scientists can demonstrate the presence of different types of microorganisms.②The first scientists to use these techniques were involved in the Subsurface Science Program of the United States Department of Energy (DOE). They were interested in the possibility that if organisms existed in the depths of Earth, they might degrade organic pollutants and help maintain the purity of groundwater or, rather less usefully, degrade the containers in which the DOE was proposing to deposit the radioactive waste from nuclear facilities. They demonstrated the presence of many different types of microorganisms in rocks at depths down to 500 meters beneath the surface. Since then, microbes have been discovered in many different types of rocks and deep within ocean sediments. The record depth at which life has been found is at the bottom of a South African gold mine, 3.5 kilometers below ground. Pressure and temperature increase as you go deeperinto Earth. Some scientists think that subsurface bacteria could withstand temperatures as high as 150℃. This would allow organisms to exist to depths of about 7 kilometers beneath the seafloor and to 4 kilometers below the surface of the land. Although the organisms are often sparsely distributed, this is such an enormous volume that it has been estimated that the total biomass of deep subsurface organisms exceeds that of those living on, or just below, the surface.③Bacteria are the most numerous of these subsurface organisms, but there are also fungi and protozoa. Some 10,000 strains of microorganism have been isolated from subsurface cores. Each gram of rock contains anything from 100 bacteria to 10 million bacteria(compared with more than 1 billion per gram in agricultural soils); ocean sediments contain even higher numbers. The protozoa feed on the bacteria, forming part of a simple subterranean food chain, but what do the bacteria feed on? Sedimentary rocks are formed from sands and from ocean, river, or lake sediments that have organic material trapped within them. Microbes living in pores within the sediments can utilize these ancient nutrients and grow. As sedimentary rocks are buried more deeply, they become increasingly compacted and their pores filled with minerals. The distribution of microorganisms is thus likely to become more patchy, condensed into the remaining pores and concentrations of nutrients. The bulk of Earth's crust, however, consists of igneous rocks, such as granite and basalt, which are solidified from molten magma. These rocks were too hot to support life when they were first formed; the organisms that inhabit cracks and fissures within the rocks are carried there by the groundwater flowing through them. Subsurface bacteria do not just rely on nutrients trapped within the rock or carried there by groundwater. Some are chemotrophs, deriving their energy from the oxidation of iron or sulfur compounds and building organic material directly from the carbon dioxide and hydrogen gas dissolved in the rock. These bacteria excrete organic compounds that are then utilized by other types of bacteria. These ecosystems based on chemotrophic bacteria are completely independent of material and solar energy from the surface.译文地下生活①直到大约20世纪80年代末,大多数科学家仍认为生命仅限于土壤或海洋沉积物的顶部几米。
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a rXiv:g r-qc/3114v29J un24Scalar and Spinor Perturbation to the Kerr-NUT Space-time Banibrata Mukhopadhyay ∗&Naresh Dadhich Inter-University Centre for Astronomy and Astrophysics,Post Bag 4,Ganeshkhind,Pune-411007,India We study the scalar and spinor perturbation,namely the Klein-Gordan and Dirac equations,in the Kerr-NUT space-time.The metric is invariant under the duality transformation involving the exchange of mass and NUT parameters on one hand and radial and angle coordinates on the other.We show that this invariance is also shared by the scalar and spinor perturbation equations.Further,by the duality transformation,one can go from the Kerr to the dual Kerr solution,and vice versa,and the same applies to the perturbation equations.In particular,it turns out that the potential barriers felt by the incoming scalar and spinor fields are higher for the dual Kerr than that for the Kerr.We also comment on existence of horizon and singularity.KEY WORDS :Kerr-NUT space-time,metric perturbation,potential barrier PACS NO.:03.50.De,04.20.-q,04.70.-s,95.30.Sf I.INTRODUCTION For asymptotically flat axially symmetric stationary electro-vacuum space-time,it is well known that the Kerr family is unique [1].On relaxing the condition of asymptotic flatness,there occurs the NUT generalization of it,the Kerr-NUT family [2–4].It has recently been shown [5]that this family is also unique for the space-time admitting separable (Hamilton-Jacobi and Klein-Gordon)equations of motion.When separability is implemented a priori,it determines certain form of the metric functions which are the functions of radial and angle coordinates.Then the Einstein-Maxwell equations for electro-vacuum space-time readily admit the most general solution which turns out to be the Kerr-NUT solution [4]establishing its uniqueness in a straightforward and direct manner.When the asymptotic flatness is imposed,the NUT parameter vanishes yielding the unique Kerr family.The Kerr family is thus included in the more general Kerr-NUT family which is the most general family for a metric admitting separable equationsof motion.It would thus imply separability of the equations of motion for the Kerr family and it is indeed,as is well-known,so [1].The most remarkable feature of this method of obtaining the most general solution is that it exposes the duality transformation which keeps the metric invariant.The duality here means exchange of the mass and NUT parameters on one hand and the radial and angular coordinates on the other [5,6].Else the Kerr-NUT solution has been known for long [4],but this invariance has thus far remained unnoticed.Like mass is the measure of gravitational electric charge,NUT parameter is supposed to be the measure of magnetic charge [7].The Kerr-NUT solution is therefore a truly gravitational dyon solution [6]and it represents gravitational field of a rotating body having both the gravitationalelectric(mass)and magnetic(NUT)charges.By the duality transformation,one can obtain the space-time dual to the Kerr solution.1There exists duality between thefield of a rotating electric charge(M)and rotating magnetic charge (NUT parameter,l)[9]and vice-versa.Though there exists pure NUT solution[2]without the rotation parameter a,but for the duality transformation its presence is essential.That is,the duality between gravitational electric and magnetic charges could be exhibited only when the body is rotating.The Kerr family has been studied extensively for motion of test particles as well as for the scalar,spinor,vector and tensor perturbations of the metric.In this paper,we would like to study the scalar and spinor perturbations, i.e.the Klein-Gordon and Dirac equations in the Kerr-NUT geometry.As we said earlier that by a simple duality transformation one can switch over from the Kerr solution to the dual Kerr(where M=0).From the properties of the Kerr metric,it is possible to derive the corresponding properties of the dual Kerr metric.For instance,the scalar and spinor perturbation equations of the Kerr geometry can be translated to the corresponding equations for the dual geometry by the duality transformation which takes the Kerr metric to the dual Kerr metric.However,the duality works only at the equation level but not at the solution level;viz the solution of the scalar equation in the Kerr case can not be taken over to the solution of the corresponding equation in the dual case by any such simple transformations.This happens because the duality involves mass and NUT parameters and their presence and absence in the equation changes the nature of solution.In the Kerr metric there is mass parameter but no NUT parameter. Under the duality transformation,mass goes to NUT parameter and so the dual metric has NUT parameter but no mass.Hence the solution which is obtained with mass parameter present will have different character and would not go over to the one obtained with mass zero and NUT non-zero.In the present case,this has become more non-trivial due to the particular selection of variable transformation which reduces the equations into the form of wave equations whose solution is known.The duality would have been very interesting,had it worked at the solution level as well.That unfortunately does not happen here trivially.Considering the Kerr solution as thefield of rotating gravitational electric charge(M)and its dual as thefield of rotating gravitational magnetic charge(l-the NUT parameter).Then it should be of interest to study the scalar and spinor perturbations of these twofields and compare their behaviour.This is exactly what we wish to do.We should however note that the dual solution is indeed an exact solution of the Einstein vacuum equation which is asymptotically nonflat and its asymptoticflat limit isflat spacetime(i.e.if we impose the condition of asymptoticflatness,it reduces toflat spacetime).We shall probe this space-time with the scalar and spinorfields and compare their motion with the corresponding motion in the Kerr geometry.Our main aim here is to study the perturbationsfirst in the general Kerr-NUT space-time and then specialize to the Kerr and the dual Kerr cases by employing the duality transformation.For the duality to work it is required that a=0.Hence we cannot go to a=0 limit of the pure NUT solution.As we are not able to establish any duality relation between the solutions in the Kerr and dual Kerr cases,we will compare the solutions graphically.The paper is organized as follows.In§II,we shall recall the Kerr-NUT metric and its invariance under the dualitytransformation.Next two sections III and IV would respectively be devoted to the Klein-Gordon and Dirac equations and their transformation under the duality.In§III,we will also present the numerical solution of scalar perturbation equation.Then in§V,we shall present and discuss the various numerical solutions of the Dirac spinors which would be followed by discussion of horizon and singularity in§VI,and we end with a discussion of the main results.II.THE KERR-NUT METRIC AND THE DUALITYHere we study the interaction of particles of spin zero and spin half with the Kerr-NUT black hole.We are familiar with the Klein-Gordan and Dirac equations inflat space by which one can investigate the behaviour of spin zero and spin half particles.In the curved space-time the form of these equations are modified.The Dirac equation was written in the Kerr geometry by Teukolsky[10]and was separated by Chandrasekhar[11]into the radial and angular parts (for a comprehensive discussion,see[1]).Recently,there has been a fresh investigation of the radial Dirac equation in the Schwarzschild,Reissner-Nordstr¨o m and Kerr geometries[12–14].In the linearized testfield approximation,scalar,vector and tensor perturbations of the Kerr geometry has been studied by several authors(e.g.[1,10]).The master equations[10]governing these linear perturbations for integral spin (e.g.,gravitational and electromagnetic)fields were solved numerically by Press&Teukolsky[15]and by Teukolsky& Press[16].Particularly interesting is the fact that whereas gravitational and electromagnetic reflected wave from the black hole was found to be amplified for certain range of incoming frequencies,however Chandrasekhar[1]predicted that no such amplification should take place for the Dirac waves because of the very nature of the potential experienced by the incomingfields.The space-time metric for the Kerr-NUT geometry[5]is given byds2=−U2ρ2 (F+l2)dφ−adt 2+ρ2U2(U2,−ρ2,0,−U2P),nµ=1¯ρ√¯ρ∗√andlµ=12ρ2(F+l2,−U2,0,a),mµ=12(iP cosecθ,0,1,icosecθ),¯mµ=12(−iP cosecθ,0,1,−icosecθ),(4)where¯ρ=r+iλand¯ρ∗=r−iλ.In the next two sections,we study perturbations to the Kerr-NUT(including the Kerr as well as the dual Kerr) space-time with the Klein-Gordan and Dirac equations and the corresponding propagation of scalar and spinor waves respectively.So the perturbation can be expressed as a superposition of stationary waves with different modes given as e i(σt+mφ),whereσis the frequency of the waves and m is the azimuthal quantum number.III.THE KLEIN-GORDAN EQUATIONThe general equation of scalarfield(wave)in curved space-time can be written as1−g∂µ√U2−P2∂r(U2Φ,r)+a(2l2−Q2∗+2Mr)+2lU2cotθcosecθU2−1sinθ∂∂θ2+cotθ∂sin2θ+4lσmcotθcosecθ+λ21+m2p(l+acosθ)2−m2∂r2+2(r−M)∂U2(F+l2)2+r2m2p+a2m2U2(2l2−Q2∗+2Mr)−λ21R0=0,(8)whereλ1is the separation constant.It is interesting to note that,following[5],if we perform the duality transformation M↔il,r↔iλand R0↔S0, and with suitable redefinition of a,Eqns.(7)and(8)remain invariant.Further,under the duality transformation, M→il,r↔iλand R0↔S0,Eqns.(7)and(8)for the Kerr solution(with l=0)will go over to that of the dual Kerr solution(with M=0).Similarly,the reverse duality transformation,l→−iM,r↔iλand R0↔S0,will bring the equations back to the Kerr geometry.Let us choose the transformation of independent variables r andθasy=11+cosθ ,z=r32+r+r−r,(9)where r±=M±Thus from(7),(8),(9)and(10)we getd2S0dz2+V z Z=0,(12) whereV y=λ21sin2θ−P2σ2+4lσmcosθ+m2p sin2θ(l+acosθ)2−m2,(13)V z=1U2−2.(14)Here V y and V z are the effective gravitational potentials for angular and radial motion respectively of the scalarfield. Atθ=0andπand the corresponding y=−∞and∞,V y reduces to−(2lσ−m)2and−(2lσ+m)2respectively. From(13)it is clear that V y scales with l and a.Keeping the other parameters unchanged if l and/or a increases so does the potential.In the case of the radial potential,V z,it falls offat large r but it diverges at the horizon[see Eqn.(14)].Physically it means that the perturbation at large distance should not affect the space-time near the black hole. With the perturbation propagating towards the horizon,its effect becomes important.Here,note that in the natural units(G=c=h=1),all the parameters are dimensionless.Equations(11)and(12)are the simple one-dimensional wave equations which we solve numerically and depict in Figs.1and2for the Kerr-NUT,Kerr and dual Kerr space-times with a certain choice of parameters.In principle, one shouldfirst solve the angular equation with the eigenvalue,λ1.Then inserting that value ofλ1into the radial equation,one should solve the radial equation.However,at thefirst instance we would like to get a qualitative feeling of the solution and hence we have set hereλ1=1throughout.This is a deficiency of the solutions presented here which are not complete in this sense.However,they do provide some useful qualitative insight.In future we plan to evaluateλ1and get the complete solution.Here our main aim is just to give an indication of form of the possible solution.We use the Runge-Kutta method with the natural boundary conditions at infinity.We know that at infinity the potential barrier is either zero or constant.Therefore the wave form should be sinusoidal which defines the boundary condition at infinity.For the angular solution,first note that V y is independent of the mass M and hence it is the same for the Kerr-NUT and the dual Kerr space-times.From the Figs.1and2,the variance of solutions as a function of the rest mass of the incoming scalar as well as the space-time parameters,a,l and M,is very clear.Figure1shows that the amplitude of the solution is significantly high for the Kerr case.This is because the net gravitational effect is stronger for the Kerr case than the Kerr-NUT.It should be noted that the NUT and rotation parameters tend to oppose each other.Also the solution shows the existence of singularity in the space-time atθ→0.On the other hand,Fig.2indicates an extension of the inner space-time region down to r=0for the dual Kerr and thus the wavelength of scalar waves would therefore be wider than that for the Kerr and Kerr-NUT metrics. For the radial mode,larger is the wavelength for less massive perturbation.0.51 1.52 2.53-25-20-15-10-50.51 1.52 2.53-1500-1000-500FIG.1.Angular Klein-Gordan solution with σ=0.4,M =1for (a)Kerr-NUT,a =0.998,l =0.99,(b)Kerr,a =0.998.Solid and dotted curves indicate the cases,m p =0.4,0.1respectively.0.51 1.52-200-1001002000.51 1.52-200-10010020000.51 1.52-200200FIG.2.Radial Klein-Gordan solution with σ=0.4,for (a)Kerr-NUT,a =0.998,l =0.99,(b)Kerr,a =0.998,(c)dual Kerr,a =l =0.998.Solid and dotted curves indicate the cases,m p =0.4,0.1respectively.M =1for (a)and (b).Note that the Klein-Gordon equation remains invariant under the duality transformation and the equation for the Kerr geometry can be transformed to that for the dual Kerr geometry and vice versa,but as is mentioned in §1there is no easy way to exploit explicitly this duality for the solutions.One of the reason behind this is due to the certain choice of the independent variables to cast the equation in the familiar simple form which facilitates the analysis of motion through the behaviour of potential.The angular potential,V y ,depends upon the NUT parameter,l ,and is free of the mass of the black hole.The Kerr solution has only kinematic part coming from the rotation parameter,a .While the radial potential,V z ,depends upon both M and l .We can go to the corresponding potential and solutions for the Kerr and the dual Kerr space-times by setting l =0and M =0respectively in the Eqns.(13)and (14).IV.THE DIRAC EQUATIONFollowing [14],derivative of spinor P A can be written asD µP A =∂µP A +iqA µP A +ΓA µνP ν,(15)where AµandΓAµνare electromagnetic and gravitational gaugefields respectively.Thus,the Dirac equation in the Newman-Penrose formalism can be written asσµAB′DµP A+iµp¯Q C′ǫC′B′=0,(16)σµAB′DµQ A+iµp¯P C′ǫC′B′=0.(17) For a vector X i,σi AB′X i=X AB′;A,B=0,1;and21√ρ2,Aφ=rQ∗P¯ρ∗,β=cotθ2¯ρ,π=iasinθ2(¯ρ∗)2,ǫ=0,τ=−iasinθ2,µ=−U22ρ2,α=π−β∗.(25)Now by substituting Eqns.(23-25)into Eqns.(19-22),we reduce the Dirac equation toD0f1+2−12f2=[iµp r+µp(l+acosθ)]g1(26)U 2D †12L †12L †12g 1+212g 2=−2[iµp r −µp (l +acosθ)]f 1(29)where,D n =dU2(σ(F +l 2)+am +qQ ∗r )+2n r −M dr−i U 2(30)andL n =ddθ−(σP +m )cosecθ+ncotθ.(31)Further writing f 1(r,θ)=R −12(θ),f 2(r,θ)=R 12(θ),g 1(r,θ)=R 12(θ),g 2(r,θ)=R −12(θ),we can separate Eqns (26)-(29)into angular and radial parts asL 1/2S 1/2=−(λ2−m p (l +acosθ))S −1/2,L †1/2S −1/2=(λ2+m p (l +acosθ))S 1/2,(32)U D 0R −1/2=(λ2+im p r )UR 1/2,U D †0UR 1/2=(λ2−im p r )R −1/2.(33)Here,m p is the normalized rest mass of the incoming particle and λ2is the separation constant.Unlike the case of the scalar perturbation,the invariance of the spinor perturbation equations under the duality transformation is non trivial,as the up and down spinor components couple with each other.However,if we choose the duality relations between spinor components as iS 1/2↔U −1/2R −1/2and S −1/2↔U 1/2R 1/2,Eqns.(32-33)do remain invariant when M ↔il ,r ↔iλ.As before,then we can switch over the Dirac equation in the Kerr space-time to that in the dual Kerr space-time and vice versa by the duality transformation.Further the interesting point to note is that under theduality transformation,the up-spinor transforms to the down and vice versa,with the multiplication/division of U .Next we study the separated angular and radial equations.IV.A.Angular equations If we decouple the equations in (32)for S −12L †12+m p asinθ2S −12=0.(34)Similarly one can decouple the equations in (32)for S 12 log (1−cosθ)− λ2±m p l ∓m p aThus the decoupled equations for S−1[not given here],can be reduced to2d2S∓1+W∓S∓1du2∓±(σP+m)cotθcosecθ+σcosecθ(2asinθcosθ+2lsinθ)−cosec2θ4(λ2±m p(l+acosθ))2.(37)−(σP+m)2cosec2θ+λ22−m2p(l+acosθ)2±m p asinθ2∓(σP+m)cosecθEqn.(36)is a simple one dimensional wave equation.Here again the angular potential depends upon l and is free offM.The above gravitational potentials are related to the physical parameters and variable in a rather complicated manner compared to the case of scalar perturbation.For bothθ→0andπ,angular potential barriers reduce to zero (W±→0).We can study the potential barriers felt by the incoming spinors with different masses and frequencies.In principle one can choose any mass and frequency of thefield but to bring a significant interaction with the black hole we choose the mass and frequency in such a manner that the Compton wavelength of the incomingfields becomes same order as the radius of the outer horizon to the black hole.Also the frequency of the perturbation should be same order as the inverse of the light crossing time to the radius of the black hole.Thus we chooseσ∼m p∼r−1+.(38) Figures3and4indicate the behaviour of potentials felt by the spinors in the angular direction in the transformed coordinate system.For a particularσ,as m p decreases the coupling strength between the spinor and space-time curvature reduces then the peak of the barrier goes down.Similarly for the same m p ifσreduces the peak goes down. The interesting feature that emerges out is that the height of the barrier is quite sensitive to the spin orientation (up/down)of the incoming spinorfield.This is in accordance with the expectation that a spinning black hole(with a particular spin orientation)can distinguish the up and down spin of the perturbation separately.Further a spinor feels higher potential barrier when it is aligned with the black hole.We also note the mirror inversion symmetry between W+and W−.FIG.3.Variation of W+as a function of u+,M=1when(a)a=0.998,l=0.99,(b)a=0.998,l=0.1,(c)a=l=0.5, (d)a=0.5,l=0.1.Solid curves indicate the cases,σ=0.4;m p=0.4,0.3,0.2,0.1,0from top to bottom and dotted curves indicateσ=0.1;m p=0.1,0from top to bottom.FIG.4.Variation of W −as a function of u −,M =1when (a)a =0.998,l =0.99,(b)a =0.998,l =0.1,(c)a =l =0.5,(d)a =0.5,l =0.1.Solid curves indicate the cases,σ=0.4;m p =0.4,0.3,0.2,0.1,0from top to bottom and dotted curves indicate σ=0.1;m p =0.1,0from top to bottom.IV.B.Radial equationsDecoupling the equations in Eqn.(33)for R −12D 0R −1λ2+im p rD 0R −12=0.(39)However,following the earlier works [1,13],we cast this into the form,d 2Z ±2e i Θ/2±R −1λ ,(41)ˆr ∗=r +2Mr +−Q 2∗+2l 2+am +qQ ∗r +r +−r −log r σr −−1+1λ ,(42)V±=U(λ22+m2p r2)3/22σ]2[U(λ22+m2p r2)3/2±{(r−M)(λ22+m2p r2)+3m2p rU2}]∓U3(λ22+m2p r2)5/22σ]32r+qQ∗σ ,(43)whereω2=r2+α2,α2=a2+l2+amσ.(44)From Eqn.(42),it is clear that forσ=σs=−qQ∗r++amr+−1 vanishes and thus forσ≤σs,the relationˆr∗−r becomes multivalued.From Eqn.(43)itis clear that the potential,V±,diverges at r=|α|.This regime where V±diverges,is well known as super-radiance. Forσ>σs,|α|<r+,and the wave can not reach at r=|α|and hence there is no question of super-radiance.For σ=σs,|α|=r+,and the potential[Eqn.(43)]diverges exactly at the event horizon.Forσ>σs,ˆr∗runs from−∞to∞as r varies from r+to∞;but forσ≤σs,at both r→r+and r→∞,ˆr∗→∞.The turning point of theˆr∗−rrelation occurs at r=|α|.Thus the analogue of ergo-sphere is defined by the region r+≤r≤|α|.However,the spinor particles do not experience super-radiance and hence no energy can be extracted by the spinor perturbation (e.g.[1,13,18]).However the result is non null for the electromagnetic perturbation and energy is possible to extract from the black hole.It is clear from Eqn.(43)that,like angular potential barrier,here also the gravitational potentials are related to the physical parameters and variable in a complicated manner.Close to the horizon,the potential barrier,V±,reduces to zero but at a large distance V±→m2p.Thus from Eqn.(40),it appears thatσhas to be greater than or equal to m p,otherwise spinors can not enter into the gravitationalfield.Figures5and6show the behaviour of potential barriers(V±)for different choices of the frequency and mass of the spinor.Here also we chooseσ∼m p∼r−1+,to consider a significant interaction between the incoming spinor and the black hole.For a particular frequency,as the mass of the spinor decreases the asymptotic height of the barrier decreases.FIG.5.Variation of V+as a function ofˆr∗forσ>σs,when(a)a=0.998,l=0.99,(b)a=0.998,l=0.1.Solid curves are forσ=0.7and dotted curves forσ=0.4.From the top to bottom m p varies as0.4,0.3,0.2,0.1,0,and M=1,m=−1/2, Q∗=0.FIG.6.Variation of V−as a function ofˆr∗forσ>σs,when(a)a=0.998,l=0.99,(b)a=0.998,l=0.1.Solid curves are forσ=0.7and dotted curves forσ=0.4.From the top to bottom m p runs through0.4,0.3,0.2,0.1,0,and M=1,m=−1/2, Q∗=0.In Fig.7,the behaviour of potentials(V+)in super-radiance regime is shown.Clearly,at a certain r the potential diverges.For a particularσ,if m p increases,the singular point shifts outward.The behaviour of corresponding V−is similar.FIG.7.Variation of V+as a function ofˆr∗forσ≤σs(σ=0.1),when(a)a=0.998,l=0.5,(b)a=0.998,l=0.1.Solid and dotted curves indicate m p=0,0.1respectively with M=1,m=−1/2,Q∗=0parison of Kerr with dual KerrFor the dual Kerr solution M=0,the correspondingˆr∗would read asˆr∗=r−α22σtan−1 m p rma2−l2tan −1ra2−l2+1λ (47)for a>l.The radial potential would depend upon a and l only,keeping unchanged the form of Eqn.(43).Figures8and9show the variation of angular potential in the Kerr and dual of Kerr metrics.It is seen that the peak of the barrier(and the maximum height of it)in the dual Kerr for a particular set ofσand m p is higher than that in the Kerr case.However W±in the dual Kerr is the same as for the Kerr-NUT for the angular motion because of its M independence.As before,here again W+is higher than W−because of the opposite spin orientation of the perturbation,particularly in the higher frequency regime.FIG.8.Variation of W+for the dual Kerr(M=0)case as a function of u+for(a)a=0.998,l=0,M=1(Kerr) (b)a=l=0.998.From top to bottom,solid curves are forσ=0.4;m p=0.4,0.3,0.2,0.1,0while dotted are forσ=0.1; m p=0.1,0,and m=−1/2,Q∗=0.FIG.9.Potential W−is plotted against u−for(a)a=0.998,l=0,M=1(Kerr)(b)a=l=0.998,M=0(dual Kerr).From top to bottom,solid curves are forσ=0.4;m p=0.4,0.3,0.2,0.1,0and dotted are forσ=0.1;m p=0.1,0,and m=−1/2,Q∗=0.In Figs.10and11,we compare the radial gravitational potential in the Kerr and dual Kerr cases.It is again seen that the peak of the barrier(and the maximum height of it)in the dual Kerr for a particular set ofσand m p is higher than that in the Kerr.In the dual Kerr,for a particular m p,ifσdecreases,the peak of the barrier distinctly increases.FIG.10.Variation of V+as a function ofˆr∗,when(a)a=0.998,l=0,M=1(Kerr)(b)a=l=0.998,M=0(dual Kerr).Solid curves are from top to bottom forσ=0.7;m p=0.7,0.6,0.5,0.4,0.3,0.2,0.1,0and dotted are forσ=0.4; m p=0.4,0.3,0.2,0.1,0,and m=−1/2,Q∗=0.FIG.11.Variation of V−as a function ofˆr∗,when(a)a=0.998,l=0,M=1(Kerr)(b)a=l=0.998,M=0(dual Kerr).Solid curves are from top to bottom forσ=0.7;m p=0.7,0.6,0.5,0.4,0.3,0.2,0.1,0and dotted are forσ=0.4; m p=0.4,0.3,0.2,0.1,0,and m=−1/2,Q∗=0.Therefore,from the above discussion we now have a clear picture of the behaviour of gravitational potential barriers felt by the spinors in the Kerr-NUT,Kerr and dual Kerr space-times.We will next study their solutions.V.SOLUTION FOR SPINOR PERTURBATIONHere we like to solve Eqns.(36)and(40)for the various sets of the physical parameters.In view of the stationary and axisymmetric nature of the background space-time,it is natural to write the perturbation as superposition of waves of different modes,exp[i(σt+mφ)].We have thus to solve the radial and angular equations.These equations are however not solvable analytically and hence we are forced to seek for numerical solutions.We shall employ the well known Runge-Kutta method with the boundary conditions at infinity.With the aim of getting the qualitative feeling of the solution,we shall again setλ2=1,which should in principle be evaluated in an exact manner.The complete solution has been obtained for the Kerr geometry[17].We shall however defer this for a future consideration for the Kerr-NUT geometry.The numerical solutions are shown in the followingfigures.The boundary condition at infinity isfixed by demanding sinusoidal wave with the wave number,k±=horizon which produces a large wavelength compared to that at a small r.Forσ=0.4,cases with a=0.5lie in the super-radiance regime for the dual Kerr and then the corresponding radial potentials diverge.FIG.13.Radial spin-up and spin-down solutions withσ=m p=0.4,for(a)Kerr-NUT,a=0.998,l=0.99(b)Kerr, a=0.998,(c)dual Kerr,a=l=0.998.Solid and dotted curves indicate the up and down spinors respectively as marked in thefigure too.Other parameters are m=−1/2,Q∗=0;for(a)and(b)M=1.FIG.14.Radial spin-up and spin-down solutions withσ=m p=0.4,for(a)Kerr-NUT,a=l=0.5,(b)Kerr,a=0.5.Solid and dotted curves indicate the up and down spinors respectively as marked in thefigure too.Other parameters are m=−1/2, Q∗=0,M=1.Now we will compare the solutions of the spinor perturbation equations in the various regimes of incoming spinors so that the black hole will appear to act as a mass-spectrograph.Figures15and16bring this feature for the angular up and down spinors respectively.As before only that range ofθis chosen when the solution is harmonic and it however covers most of the range ofθ.The deviation of solutions for different sets of{σ,m p}is very clearly shown inthefigures for the Kerr and Kerr-NUT space-times.FIG.15.Angular spin-up solutions withσ=0.4,m p=0.1(solid curve);σ=0.4,m p=0.4(dotted curve);σ=0.7, m p=0.4(dashed curve);for(a)Kerr-NUT,a=0.998,l=0.99,(b)Kerr,a=0.998,(c)Kerr-NUT,a=l=0.5,(d)Kerr, a=0.5.Other parameters are m=−1/2,Q∗=0.FIG.16.Angular spin-down solutions withσ=0.4,m p=0.1(solid curve);σ=0.4,m p=0.4(dotted curve);σ=0.7, m p=0.4(dashed curve);for(a)Kerr-NUT,a=0.998,l=0.99,(b)Kerr,a=0.998,(c)Kerr-NUT,a=l=0.5,(d)Kerr, a=0.5.Other parameters are m=−1/2,Q∗=0.Figures17and18indicate the solutions for the up and down spinors respectively in the radial direction in case of the extreme Kerr-NUT,Kerr and dual Kerr space-times for different choices of{σ,m p}.The most interesting factin all thefigures is that whenσ∼m p(dotted curves)the wavelength as well as the amplitude of the spinors are high compared to two other cases.This is physically understood asσ∼m p indicates the very small wave number at least at a large distance,that trend continues up to the inner radii,except at very close to the horizon where the strong effect of a black hole suppresses any individual identity of the matter.Forσ>m p,the perturbation of higher frequency gives rise to the solution of lower wavelength which is physically understood.Again the solutions for the dual Kerr are distinctly different from others.As before the overall amplitudes of up spinors which are oriented with the black hole’s spin in a parallel sense,are high compared to that of down spinors oriented in an anti-parallel sense.。