C Primer Plus第6版编程练习答案已下载
C++--primer-plus-(第6版)-中文版编程练习答案
第二章：开始学习C++//ex2.1--display your name and address#include<iostream>int main(void){using namespace std;cout<<"My name is liao chunguang and I live in hunan chenzhou.\n”；}//ex2.2--convert the furlong units to yard uints-把浪单位换位码单位#include<iostream>double fur2yd(double);int main(){using namespace std;cout<<"enter the distance measured by furlong units:";double fur;cin>>fur;cout<<"convert the furlong to yard"<<endl;double yd;yd=fur2yd(fur);cout<<fur<<" furlong is "<<yd<<" yard"<<endl;return 0;}double fur2yd(double t){return 220*t;}//ex2.3-每个函数都被调用两次#include<iostream>void mice();void see();using namespace std;int main(){mice();mice();see();see();return 0;}void mice(){cout<<"three blind mice"<<endl;}void see(){cout<<"see how they run"<<endl;}//ex2.4#include<iostream>int main(){using namespace std;cout<<"Enter your age:";int age;cin>>age;int month;month=age*12;cout<<age<<" years is "<<month<<" months"<<endl;return 0;}//ex2.5---convert the Celsius valve to Fahrenheit value#include<iostream>double C2F(double);int main(){using namespace std;cout<<"please enter a Celsius value:";double C;cin>>C;double F;F=C2F(C);cout<<C<<" degrees Celsius is "<<F<<" degrees Fahrenheit."<<endl;return 0;}double C2F(double t){return 1.8*t+32;}//ex2.6---convert the light years valve to astronomical units--把光年转换为天文单位#include<iostream>double convert(double);//函数原型int main(){using namespace std;cout<<"Enter the number of light years:";double light_years;cin>>light_years;double astro_units;astro_units=convert(light_years);cout<<light_years<<" light_years = "<<astro_units<<" astronomical units."<<endl; return 0;}double convert(double t){return 63240*t;//1 光年=63240 天文单位}//ex2.7--显示用户输入的小时数和分钟数#include<iostream>void show();main(){using namespace std;show();return 0;}void show(){using namespace std;int h,m;cout<<"enter the number of hours:";cin>>h;cout<<"enter the number of minutes:";cin>>m;cout<<"Time:"<<h<<":"<<m<<endl;}第三章：处理数据//ex3.1—将身高用英尺(feet)和英寸(inch)表示#include<iostream>const int inch_per_feet=12;// const 常量--1feet=12inches--1 英尺=12 英寸int main(){using namespace std;cout<<"please enter your height in inches:___\b\b\b";// \b 表示为退格字符int ht_inch;cin>>ht_inch;int ht_feet=ht_inch/inch_per_feet;//取商int rm_inch=ht_inch%inch_per_feet;//取余cout<<"your height is "<<ht_feet<<" feet,and "<<rm_inch<<" inches\n";return 0;}//ex3.2--计算相应的body mass index〔体重指数〕#include<iostream>const int inch_per_feet=12;const double meter_per_inch=0.0254;const double pound_per_kilogram=2.2;int main(){using namespace std;cout<<"Please enter your height:"<<endl;cout<<"First,enter your height of feet part〔输入你身高的英尺部分〕:_\b"; int ht_feet;cin>>ht_feet;cout<<"Second,enter your height of inch part〔输入你身高的英寸部分〕:_\b"; int ht_inch;cin>>ht_inch;cout<<"Now,please enter your weight in pound:___\b\b\b";double wt_pound;cin>>wt_pound;int inch;inch=ht_feet*inch_per_feet+ht_inch;double ht_meter;ht_meter=inch*meter_per_inch;double wt_kilogram;wt_kilogram=wt_pound/pound_per_kilogram;cout<<endl;cout<<"Your pensonal body information as follows:"<<endl;cout<<"身高:"<<inch<<"(英尺inch)\n"<<"身高:"<<ht_meter<<"(米meter)\n"<<"体重:"<<wt_kilogram<<"(千克kilogram)\n";double BMI;BMI=wt_kilogram/(ht_meter*ht_meter);cout<<"your Body Mass Index(体重指数) is "<<BMI<<endl;return 0;}//ex3.3 以度，分，秒输入，以度输出#include<iostream>const int minutes_per_degree=60;const int seconds_per_minute=60;int main(){using namespace std;cout<<"Enter a latitude in degrees,minutes,and seconds:\n";cout<<"First,enter the degrees:";int degree;cin>>degree;cout<<"Next,enter the minutes of arc:";int minute;cin>>minute;cout<<"Fianlly,enter the seconds of arc:";int second;cin>>second;double show_in_degree;show_in_degree=(double)degree+(double)minute/minutes_per_degree+(double)second/mi nutes_per_degree/seconds_per_minute;cout<<degree<<" degrees,"<<minute<<" minutes,"<<second<<"seconds="<<show_in_degree<<" degrees\n";return 0;}//ex3.4#include<iostream>const int hours_per_day=24;const int minutes_per_hour=60;const int seconds_per_minute=60;int main(){using namespace std;cout<<"Enter the number of seconds:";long seconds;cin>>seconds;int Day,Hour,Minute,Second;Day=seconds/seconds_per_minute/minutes_per_hour/hours_per_day;Hour=seconds/seconds_per_minute/minutes_per_hour%hours_per_day;Minute=seconds/seconds_per_minute%minutes_per_hour;Second=seconds%seconds_per_minute;cout<<seconds<<"seconds = "<<Day<<" days,"<<Hour<<" hours,"<<Minute<<" minutes,"<<Second<<" seconds\n";return 0;}//ex3.5#include<iostream>int main(){using namespace std;cout<<"Enter the world population:";long long world_population;cin>>world_population;cout<<"Enter the population of the US:";long long US_population;cin>>US_population;double percentage;percentage=(double)US_population/world_population*100;cout<<"The population of the US is "<<percentage<<"% of the world population.\n"; return 0;}//ex3.6 汽车耗油量-美国(mpg)or 欧洲风格(L/100Km)#include<iostream>int main(){using namespace std;cout<<"Enter the miles of distance you have driven:";double m_distance;cin>>m_distance;cout<<"Enter the gallons of gasoline you have used:";double m_gasoline;cin>>m_gasoline;cout<<"Your car can run "<<m_distance/m_gasoline<<" miles per gallon\n";cout<<"Computing by European style:\n";cout<<"Enter the distance in kilometers:";double k_distance;cin>>k_distance;cout<<"Enter the petrol in liters:";double k_gasoline;cin>>k_gasoline;cout<<"In European style:"<<"your can used "<<100*k_gasoline/k_distance<<" liters of petrol per 100 kilometers\n";return 0;}//ex3.7 automobile gasoline consumption-耗油量--欧洲风格(L/100Km)转换成美国风格(mpg) #include<iostream>int main(){using namespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"European style(liters per 100 kilometers):";double Euro_style;cin>>Euro_style;cout<<"Converts to U.S. style(miles per gallon):"<<endl;cout<<Euro_style<<" L/100Km = "<<62.14*3.875/Euro_style<<" mpg\n";return 0;}// Note that 100 kilometers is 62.14 miles, and 1 gallon is 3.875 liters.//Thus, 19 mpg is about 12.4 L/100Km, and 27 mpg is about 8.7 L/100Km.Enter the automobile gasoline consumption figure inEuropean style(liters per 100 kilometers):12.4Converts to U.S. style(miles per gallon):12.4 L/100Km = 19.4187 mpgPress any key to continue// ex3.7 automobile gasoline consumption-耗油量--美国风格(mpg)转换成欧洲风格(L/100Km)#include<iostream>int main(){using namespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"U.S. style(miles per gallon):";double US_style;cin>>US_style;cout<<"Converts to European style(miles per gallon):"<<endl;cout<<US_style<<" mpg = "<< 62.14*3.875/US_style<<"L/100Km\n";return 0;}// Enter the automobile gasoline consumption figure inU.S. style(miles per gallon):19Converts to European style(miles per gallon):19 mpg = 12.6733L/100KmPress any key to continue第四章复合类型//ex4.1 display the information of student#include<iostream>const int Asize=20;using namespace std;struct student//定义结构描述{char firstname[Asize];char lastname[Asize];char grade;int age;};void display(student);//函数原型放在结构描述后int main(){cout<<"what is your first name?"<<endl;student lcg;//创建结构变量〔结构数据对象〕cin.getline(lcg.firstname,Asize);cout<<"what is your last name?"<<endl;cin.getline(stname,Asize);cout<<"what letter grade do you deserve?"<<endl;cin>>lcg.grade;cout<<"what is your age?"<<endl;cin>>lcg.age;display(lcg);return 0;}void display(student name){cout<<"Name: "<<name.firstname<<","<<stname<<endl;cout<<"Grade:"<<char(name.grade+1)<<endl;cout<<"Age:"<<name.age<<endl;}//ex4.2 use the string-class instead of char-array#include<iostream>#include<string>int main(){using namespace std;string name,dessert;cout<<"Enter your name: \n";getline(cin,name);cout<<"Enter your favorite dessert: \n";getline(cin,dessert);cout<<"I have some delicious "<<dessert;cout<<" for you, "<<name<<".\n";return 0;}//有时候会遇到需要按下两次回车键才能正确的显示结果，这是vc++6.0 的一个BUG，更改如下：else if (_Tr::eq((_E)_C, _D)){_Chg = true;_I.rdbuf()->sbumpc();//修改后的break; }ex4.3 输入其名和姓，并组合显示#include<iostream>#include<cstring>const int Asize=20;int main(){using namespace std;char fname[Asize];char lname[Asize];char fullname[2*Asize+1];cout<<"Enter your first name:";//输入名字，存储在fname[]数组中cin.getline(fname,Asize);cout<<"Enter your last name:";//输入姓，存储在lname[]数组中cin.getline(lname,Asize);strncpy(fullname,lname,Asize);//把姓lname 复制到fullname 空数组中strcat(fullname,", ");//把“，”附加到上述fullname 尾部strncat(fullname,fname,Asize);//把fname 名字附加到上述fullname 尾部fullname[2*Asize]='\0';//为防止字符型数组溢出，在数组结尾添加结束符cout<<"Here's the information in a single string:"<<fullname<<endl;//显示组合结果return 0;}#define _CRT_SECURE_NO_WARNINGS#include <iostream>#include <cstring>const int Asize = 20;int main(){using namespace std;char firstname[Asize];char lastname[50];cout << "Enter your first name: ";cin.getline(firstname,Asize);cout << "Enter your last name: ";cin.getline(lastname,50);strcat(lastname,", ");strncat(lastname,firstname,Asize);cout << "Here's the information in a single string: "<< lastname <<endl;return 0;}//ex4.4 使用string 对象存储、显示组合结果#include<iostream>#include<string>int main(){using namespace std;string fname,lname,attach,fullname;cout<<"Enter your first name:";getline(cin,fname);//note:将一行输入读取到string 类对象中使用的是getline(cin,str) //它没有使用句点表示法，所以不是类方法cout<<"Enter your last name:";getline(cin,lname);attach=", ";fullname=lname+attach+fname;cout<<"Here's the information in a single string:"<<fullname<<endl;return 0;}//ex4.5 declare a struct and initialize it 声明结果并创建一个变量#include<iostream>const int Asize=20;struct CandyBar{char brand[Asize];double weight;int calory;};int main(){using namespace std;CandyBar snack={"Mocha Munch",2.3,350};cout<<"Here's the information of snack:\n";cout<<"brand:"<<snack.brand<<endl;cout<<"weight:"<<snack.weight<<endl;cout<<"calory:"<<snack.calory<<endl;return 0;}//ex4.6 结构数组的声明及初始化#include<iostream>const int Asize=20;struct CandyBar{char brand[Asize];double weight;int calory;};int main(){using namespace std;CandyBar snack[3]={{"Mocha Munch",2.3,350},{"XuFuJi",1.1,300},{"Alps",0.4,100}};for(int i=0;i<3;i++)//利用for 循环来显示snack 变量的内容{cout<<snack[i].brand<<endl<<snack[i].weight<<endl<<snack[i].calory<<endl<<endl;}return 0;}//ex4.7 pizza 披萨饼#include<iostream>#include<string>const int Size=20;struct pizza//声明结构{char company[Size];double diameter;double weight;};int main(){using namespace std;pizza pie;//创建一个名为pie 的结构变量cout<<"What's the name of pizza company:";cin.getline(pie pany,Size);cout<<"What's the diameter of pizza:";cin>>pie.diameter;cout<<"What's the weight of pizza:";cin>>pie.weight;cout<<"company:"<<pie pany<<endl;cout<<"diameter:"<<pie.diameter<<"inches"<<endl;cout<<"weight:"<<pie.weight<<"ounches"<<endl;return 0;}//ex4.8 pizza pie 披萨饼使用new 创建动态结构#include<iostream>#include<string>const int Size=20;struct pizza//声明结构{char company[Size];double diameter;double weight;};int main(){using namespace std;pizza *pie=new pizza;//使用new 创建动态结构cout<<"What's the diameter of pizza:";cin>>pie->diameter;cin.get();//读取下一个字符cout<<"What's the name of pizza company:";cin.get(pie->company,Size);cout<<"What's the weight of pizza:";cin>>pie->weight;cout<<"diameter:"<<pie->diameter<<" inches"<<endl;cout<<"company:"<<pie->company<<endl;cout<<"weight:"<<pie->weight<<" ounches"<<endl;delete pie;//delete 释放内存return 0;}//ex.4.9 使用new 动态分配数组—方法1#include<iostream>#include<string>using namespace std;struct CandyBar{string brand;double weight;int calory;};int main(){CandyBar *snack= new CandyBar[3];snack[0].brand="A";//单个初始化由new 动态分配的内存snack[0].weight=1.1;snack[0].calory=200;snack[1].brand="B";snack[1].weight=2.2;snack[1].calory=400;snack[2].brand="C";snack[2].weight=4.4;snack[2].calory=500;for(int i=0;i<3;i++){cout << " brand: " << snack[i].brand << endl;cout << " weight: " << snack[i].weight << endl;cout << " calorie: " << snack[i].calory << endl<<endl;}delete [] snack;return 0;}//ex.4.10 数组—方法1#include <iostream>int main(){using namespace std;const int Size = 3;int success[Size];cout<<"Enter your success of the three times 40 meters running:\n"; cin >> success[0]>>success[1]>>success[2];cout<<"success1:"<<success[0]<<endl;cout<<"success2:"<<success[1]<<endl;cout<<"success3:"<<success[2]<<endl;double average=(success[0]+success[1]+success[2])/3;cout<<"average:"<<average<<endl;return 0;}//ex.4.10 array—方法2#include <iostream>#include <array>int main(){using namespace std;array<double,4>ad={0};cout<<"Enter your success of the three times 40 meters running:\n"; cin >> ad[0]>>ad[1]>>ad[2];cout<<"success1:"<<ad[0]<<endl;cout<<"success2:"<<ad[1]<<endl;cout<<"success3:"<<ad[2]<<endl;ad[3]=(ad[0]+ad[1]+ad[2])/3;cout<<"average:"<<ad[3]<<endl;return 0;}第五章循环和关系表达式//ex.5.1#include <iostream>int main(){using namespace std;cout<<"Please enter two integers: ";int num1,num2;cin>>num1>>num2;int sum=0;for(int temp=num1;temp<=num2;++temp)//or temp++sum+=temp;cout<<"The sum from "<<num1<<" to "<<num2<<" is "<<sum<<endl; return 0;}//ex.5.2#include <iostream>#include<array>int main(){using namespace std;array<long double,101>ad={0};ad[1]=ad[0]=1L;for(int i=2;i<101;i++)ad[i]=i*ad[i-1];for(int i=0;i<101;i++)cout<<i<<"! = "<<ad[i]<<endl;return 0;}#include <iostream>#include <array>using namespace std;int main(){array<long double, 101> multiply;multiply[0] = multiply[1] = 1LL;for (int i = 2; i <= 100; i++)multiply[i] = multiply[i-1]*i;cout << multiply[100];return 0;}//ex.5.3#include <iostream>int main(){using namespace std;cout<<"Please enter an integer: ";int sum=0,num;while((cin>>num)&&num!=0){sum+=num;cout<<"So far, the sum is "<<sum<<endl;cout<<"Please enter an integer: ";}return 0;}//ex.5.4#include <iostream>int main(){using namespace std;double sum1,sum2;sum1=sum2=0.0;int year=0;while(sum2<=sum1){++year;sum1+=10;sum2=(100+sum2)*0.05+sum2;}cout<<"经过"<<year<<"年后，Cleo 的投资价值才能超过Daphne 的投资价值。
c++primerplus(第六版)课后编程练习答案培训资料
c + + p r i me r p l u s （第六版）课后编程练习答案〃ex2.1--display your n ame and address #in clude<iostream>int main(v oid){using n amespace std;cout<<"My n ame is liao chu ngua ng and I live in hunan che nzhou.\”〃ex2.2--convert the furlong units to yard uints扌把浪单位换位码单位#include<iostream>double fur2yd(double);int main(){using n amespace std;cout<<"e nter the dista nee measured by furl ong un its:"; double fur;cin»fur;cout<<"c onvert the furlo ng to yard"<<e ndl;double yd;yd=fur2yd(fur);coutvvfurvv" furlong is "<<yd<<" yard"<<e ndl;return 0;}double fur2yd(double t){return 220*t;}〃ex2.3-每个函数都被调用两次#in clude<iostream>void mice();void see();using n amespace std;int main(){mice();mice();see();see();return 0;}void mice(){cout«"three bli nd mice"«e ndl;}void see(){cout<<"see how they run"<<en dl;}〃ex2.4#in clude<iostream>int mai n(){using n amespace std;cout<<"E nter your age:";int age;cin> >age;in t mon th;mon th=age*12;coutvvagevv" years is "<<mon th<<" mon ths"<<e ndl;return 0;}〃ex2.5---convert the Celsius valve to Fahre nheit value#in clude<iostream>double C2F(double);int main(){using n amespace std;cout«"please en ter a Celsius value:";double C;cin> >C;double F;F=C2F(C);coutvvCvv" degrees Celsius is "<<F<<" degrees Fahre nheit."«e ndl; return 0; }double C2F(double t){return 1.8*t+32;}〃ex2.6---convert the light years valve to astronomical units-把光年转换为天文单位#in clude<iostream>double conv ert(double);//函数原型int main(){using n amespace std;cout<<"E nter the nu mber of light years:";double light_years;cin> >light_years;double astro_ un its;astro_ un its=co nv ert(light_years);cout<<light_years<<" light_years = "<<astro_u ni ts<<" astr ono mical un its."v<e ndl; return 0;}double conv ert(double t){return 63240*t;//1 光年=63240 天文单位}〃ex2.7--显示用户输入的小时数和分钟数#in clude<iostream>void show();mai n(){using n amespace std;show();return 0;}void show(){using n amespace std;int h,m;cout<<"e nter the nu mber of hours:"; cin> >h;cout<<"e nter the nu mber of minu tes:";cin>>m; coutvv"Time:"v<hvv":"vvmvve ndl;〃ex3.1—将身高用英尺(feet)和英寸(inch)表示#in clude<iostream> const int in ch_per_feet=12;〃cons常量--1feet=12i nches--1 英尺=12 英寸int main() {using n amespace std;cout<<"please en ter your height in inches: __ \b\b\b";〃\b表示为退格字符intht_in ch;cin> >ht_i nch;int ht_feet=ht_i nch/i nch_per_feet;//取商int rm_i nch=ht_i nch%i nch_per_feet;〃取余cout<<"your height is "<<ht_feet<<" feet,a nd " <<rm_i nch<< "in ches\n";return 0;}//ex3.2--计算相应的body mass index (体重指数)#in clude<iostream>const int in ch_per_feet=12;const double meter_per_i nch=0.0254;const double poun d_per_kilogram=2.2;int main(){using n amespace std;cout<<"Please en ter your height:"<<e ndl;cout«"First,enter your height of feet part (输入你身高的英尺部分):_\b";int ht_feet;cin> >ht_feet;cout«"Seco nd,e nter your height of inch part （输入你身高的英寸部分）:_\b";int ht_in ch;cin> >ht_i nch;cout«"Now,please en ter your weight in pound: __ \b\b\b";double wt_po und;cin> >wt_po und;int in ch;in ch=ht_feet*i nch_per_feet+ht_i nch;double ht_meter;ht_meter=i nch*meter_per_i nch;double wt_kilogram;wt_kilogram=wt_po un d/po un d_per_kilogram; cout«e ndl;cout<<"Your pensonal body in formatio n as follows:"<<e ndl;cout«"身高:"<<inch<<"（英尺inch）\n"<<"身高:"<<ht_meter<<"（米meter）\n"<<"体重:"<<wt_kilogram<<"（千克kilogram八n";double BMI;BMI=wt_kilogram/（ht_meter*ht_meter）;cout<<"your Body Mass In dex（体重指数）is "<<BMI<<e ndl;return 0;}〃ex3.3以度，分，秒输入，以度输出#in clude<iostream>const int minu tes_per_degree=60;const int sec on ds_per_m inu te=60;int main（）{using n amespace std;cout<<"E nter a latitude in degrees, minu tes,a nd sec on ds:\n"; cout<<"First,e nter the degrees:";int degree;cin> >degree;cout<<"Next,e nter the minu tes of arc:";int min ute;cin»minu te;cout«"Fia nlly,e nter the sec onds of arc:";int sec ond;cin> >sec ond;double show_i n_degree;show_in_degree=(double)degree+(double)mi nute/mi nutes_per_degree+(doubl e)seco nd/mi nu tes_per_degree/sec on ds_per_mi nu te;cout<<degree<<" degrees,"<< minu te<<" minu tes,"<<sec on d<<"sec onds ="<<show_i n_degree<<" degrees\n";return 0;}//ex3.4#in clude<iostream>const int hours_per_day=24;const int minu tes_per_hour=60;const int sec on ds_per_m inu te=60;int main(){using n amespace std;cout<<"E nter the nu mber of sec on ds:";long sec on ds;cin> >sec on ds;int Day,Hour,M inu te,Sec ond;Day=sec on ds/sec on ds_per_mi nute/mi nu tes_per_hour/hours_per_day;Hour=sec on ds/sec on ds_per_mi nute/mi nu tes_per_hour%hours_per_day;Min ute=seco nds/seco nds_per_mi nute%mi nu tes_per_hour;Secon d=sec on ds%sec on ds_per_m inu te;cout«sec on ds<<"sec onds = "<<Day<<" days,"<<Hour<<"hours,"<< Minu te<<" minu tes,"<<Sec on d<<" sec onds\n";return 0;}〃ex3.5#in clude<iostream>int mai n(){using n amespace std;cout<<"E nter the world populati on:";long long world_populati on;cin> >world_populati on;cout<<"E nter the populati on of the US:";long long US_populati on;cin»U S_populati on;double perce ntage;perce ntage=(double)US_populati on/world_populati on *100;cout<<"The population of the US is "<<percentage<<"% of the world population.\n"; return 0;}〃ex3.6汽车耗油量-美国(mpg)or欧洲风格(L/100Km)#in clude<iostream> int main(){using n amespace std;cout«"E nter the miles of dista nee you have drive n:";double m_dista nee;cin>> m_dista nee;cout<<"E nter the gallo ns of gasoli ne you have used:";double m_gasoli ne;cin>> m_gasoli ne;cout<<"Your car can run "<<m_dista nce/m_gasoli ne<<" miles per gallo n\n";cout«"Computi ng by Europea n style:\n";cout<<"Enter the distance in kilometers:";double k_dista nce;cin>> k_dista nce;cout<<"E nter the petrol in liters:";double k_gasoli ne;cin>> k_gasoli ne;cout<<"I n Europea n style:"«"your can used "<<100*k_gasoli ne/k_dista nce<<" liters of petrol per 100 kilometers\n";return 0;}//ex3.7 automobile gaso line con sumption 耗油量--欧洲风格(L/100Km)转换成美国风格(mpg)#in clude<iostream>int main(){using n amespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"Europea n style(liters per 100 kilometers):";double Euro_style;cin> >Euro_style;cout<<"C onv erts to U.S. style(miles per gallo n):"«e ndl;coutv<Euro_stylevv" L/100Km = "v<62.14*3.875/Euro_style<v" mpg\n"; return 0; }// Note that 100 kilometers is 62.14 miles, and 1 gallon is 3.875 liters.//Thus, 19 mpg is about 12.4 L/100Km, and 27 mpg is about 8.7 L/100Km.Enter the automobile gasoline consumption figure inEuropean style(liters per 100 kilometers):12.4Conv erts to U.S. style(miles per gallo n):12.4 L/100Km = 19.4187 mpgPress any key to con ti nue // ex3.7 automobile gasol ine con sumption耗油量--美国风格(mpg )转换成欧洲风格(L/100Km)#in clude<iostream>int main(){using n amespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"U.S. style(miles per gallo n):";double US_style;cin >>US_style;cout<<"C onv erts to Europea n style(miles per gall on ):"<<e ndl;cout<<US_style<<" mpg = "<< 62.14*3.875/US_style<<"L/100Km\n"; return 0; }// Enter the automobile gasoline consumption figure inU.S. style(miles per gallo n) :19Conv erts to Europea n style(miles per gallo n):19 mpg = 12.6733L/100KmPress any key to con ti nue//ex4.1 display the information of student #in clude<iostream>const int Asize=20;using n amespace std;struct stude nt/定义结构描述{char first name[Asize]; char last name[Asize]; char grade;int age;};void display(stude nt);〃函数原型放在结构描述后int main(){cout«"what is your first n ame?"<<e ndl;stude nt leg;//创建结构变量(结构数据对象)cin .getli ne(lcg.first name,Asize); cout<<"what is your last n ame?"<<e ndl;cin .getli ne(lcg .l ast name,Asize);cout<<"what letter grade do you deserve?"<<e ndl;cin> >lcg.grade;cout<<"what is your age?"<<e ndl;cin> >lcg.age;display(lcg);return 0;}void display(stude nt n ame){cout«"Name: " <<n ame.first name<<","< <n ame .l ast name«e ndl;cout<v"Grade:"vvchar( name.grade+1)«e ndl;cout<<"Age:"< <n ame.age<<e ndl;} //ex4.2 use the stri ng-class in stead of char-array #in clude<iostream>#in clude<stri ng>int main(){using n amespace std;stri ng n ame,dessert;cout<<"E nter your n ame: \n";getl in e(ci n,n ame);cout<<"E nter your favorite dessert: \n"; getli ne(ci n, dessert);cout<<"I have some delicious "<<dessert; cout«" for you, "< <n ame<<".\n";return 0;〃有时候会遇到需要按下两次回车键才能正确的显示结果，这是VC++6.0的一个BUG，更改如下：else if (_Tr::eq((_E)_C, _D)){_Chg = true;_I .rdbuf()->sbumpc(); 〃修改后的break; }ex4.3输入其名和姓，并组合显示#in clude<iostream>#in clude<cstri ng>const int Asize=20;int main(){using n amespace std;char fn ame[Asize];char In ame[Asize];char full name[2*Asize+1];cout<<"Enter your first name:";//输入名字，存储在fname[]数组中cin .getli ne(fname,Asize);cout<<"Enter your last name:";//输入姓，存储在Iname[]数组中cin .getli ne(l name,Asize);strncpy(full name,l name,Asize);〃把姓ln ame 复制到full name 空数组中strcat(full name,",");// 把“，”附加到上述full name 尾部strn cat(full name,fname,Asize);//把fname 名字附加至U 上述full name 尾部fullname[2*Asize ]='\0';//为防止字符型数组溢出，在数组结尾添加结束符cout<<"Here's the information in a single string:"<<fullname<<endl;//显示组合结果return 0;} //ex4.4使用string对象存储、显示组合结果#in clude<iostream>#in cludevstri ng>int main(){using n amespace std;stri ng fname ,ln ame,attach,full name; cout<<"E nter your first n ame:";getline(cin,fname);//note将一行输入读取到string类对象中使用的是getli ne(ci n, str)//它没有使用句点表示法，所以不是类方法cout<<"E nter your last n ame:";getli ne(ci n,ln ame);attach=",";full name=In ame+attach+f name;cout<<"Here's the information in a single string:"<<fullname<<endl; return 0;}〃ex4.5 declare a struct and in itialize it 声明结果并创建一个变量#in clude<iostream> const int Asize=20; struct Can dyBar{char bran d[Asize];double weight;int calory;};int main(){using n amespace std;Ca ndyBar sn ack={"Mocha Mun ch",2.3,350}; cout<<"Here's the information of snack:\n"; cout<<"bra nd:"<<s nack.bra nd<<e ndl; 8山<<妝6：9“:"<<$ nack.weight<<e ndl; coutvv"calory:"vvs nack.calory<<e ndl; return 0; } //ex4.6结构数组的声明及初始化#in clude<iostream> const int Asize=20;struct Can dyBar{char bran d[Asize];double weight;int calory;};int main(){using n amespace std;Ca ndyBar sn ack[3]={ {"Mocha Mun ch",2.3,350}, {"XuFuJi",1.1,300},{"Alps",0.4,100}};for(int i=0;i<3;i++)〃利用for循环来显示snack变量的内容{cout«s nack[i].bra nd<<e ndl<<s nack[i].weight<<e ndl<<s nack[i].calory«e ndl«e ndl;}return 0;}〃ex4.7 pizza 披萨饼#in clude<iostream> #in clude<stri ng> const int Size=20;struct pizza//声明结构{char compa ny [Size]; double diameter; double weight;};int main(){using n amespace std;pizza pie;//创建一个名为pie的结构变量cout<<"What's the n ame of pizzacompa ny:"; cin. getl in e(pa ny ,Size); cout«"What's the diameter ofpizza:";cin> >pie.diameter; cout<<"What's the weight of pizza:";cin> >pie.weight;cout<<"compa ny:"«pa ny«en dl; cout<v"diameter:"vvpie.diameter<v"i nches"«e ndl; cout<v"weight:"vvpie.weight<v"o un ches"<<e ndl; return 0;}〃ex4.8 pizza pie披萨饼使用new创建动态结构#in clude<iostream>#in clude<stri ng>const int Size=20;struct pizza//声明结构{char compa ny [Size];double diameter;double weight;};int main(){using n amespace std;pizza *pie=new pizza;//使用new 仓U建动态结构cout<<"What's the diameter of pizza:";cin> >pie->diameter;cin. get();//读取下一个字符cout<<"What's the n ame of pizza compa ny:";cin .get(pie->compa ny,Size); cout<<"What's the weight of pizza:";cin> >pie->weight; cout<v"diameter:"vvpie->diameter< <" in ches"<<e ndl;cout<<"compa ny:"«pie->compa ny«en dl; cout<v"weight:"vvpie->weight<v" oun ches"<<e ndl;delete pie;//delete释放内存return 0;〃ex.4.9使用new动态分配数组一方法1#in clude<iostream>#in clude<stri ng>using n amespace std;struct Can dyBar{stri ng brand;double weight;int calory;};int main(){Can dyBar *sn ack= new Can dyBar[3];snack[0].brand="A";〃单个初始化由new动态分配的内存sn ack[0].weight=1.1; sn ack[0].calory=200; sn ack[1].bra nd="B";sn ack[1].weight=2.2; sn ack[1].calory=400; sn ack[2].bra nd="C";sn ack[2].weight=4.4;sn ack[2].calory=500;for(int i=0;i<3;i++){cout << " bran d: " << sn ack[i].bra nd << en dl;cout << " weight: " << sn ack[i].weight << en dl;cout << " calorie: " << sn ack[i].calory << en dl<<e ndl; }delete [] sn ack;return 0;} //ex.4.10数组一方法1#i nclude <iostream> int main(){using n amespace std;const int Size = 3;int success[Size];cout<<"E nter your success of the three times 40 meters runnin g:\n"; cin >> success[0]»success[1]»success[2];cout<v"success1:"v<success[0]vve ndl;cout<v"success2:"vvsuccess[1]v<e ndl;cout<v"success3:"v<success[2]vve ndl;double average=(success[0]+success[1]+success[2])/3;cout<<"average:"<<average<<e ndl;return 0;}//ex.4.10 array—方法2#i nclude <iostream>#in clude <array>int main(){using n amespace std;array<double,4>ad={0};cout<<"E nter your success of the three times 40 meters runnin g:\n"; cin >> ad[0]»ad[1]»ad[2];cout<v"success1:"v<ad[0]vve ndl;cout<v"success2:"vvad[1]v<e ndl;cout<v"success3:"v<ad[2]vve ndl;ad[3]=(ad[0]+ad[1]+ad[2])/3;cout<<"average:"<<ad[3]<<e ndl;return 0;}//ex.5.1#in clude <iostream> int mai n(){using n amespace std;cout<<"Please en ter two in tegers:" int n um1, num2;cin»n um1> >n um2;int sum=O;for(i nt temp=n um1;temp<=n um2;++temp)//or temp++sum+=temp;cout<<"The sum from "<<n um1<<" to "<<n um2<<" is "<<sum<<e ndl; return 0; }//ex.5.2#in clude <iostream>#in clude<array>int mai n(){using n amespace std;array vlong double,101>ad={0};ad[1]=ad[0]=1L;for(int i=2;i<101;i++)ad[i]=i*ad[i-1];for(int i=0;i<101;i++)coutvvivv"! = "v<ad[i]v<e ndl;return 0;}〃ex.5.3#in clude <iostream>int mai n(){using n amespace std;cout<<"Please en ter an in teger:";int sum=0,n um;while((ci n»num)&&n um!=0){sum+=n um;cout<<"So far, the sum is "v<sumv<e ndl; cout<<"Please en ter an in teger:";}return 0;}//ex.5.4 #in clude <iostream>int main(){using n amespace std;double sum1,sum2;sum仁sum2=0.0;int year=0;while(sum2<=sum1){++year;sum1+=10;sum2=(100+sum2)*0.05+sum2;}coutvv"经过"vvyearvv"年后，Cleo的投资价值才能超过Daphne的投资价值。
C Primer Plus第6版编程练习答案(已下载)
Chapter 2 Programming Exercises欧阳学文PE 2‐1/* Programming Exercise 21 */#include<stdio.h> intmain(void){ printf("GustavMahler\n");printf("Gustav\nMahler\n");printf("Gustav ");printf("Mahler\n");return 0;}PE 2‐3/* Programming Exercise 23 */#include<stdio.h> intmain(void){ int ageyears; /* age inyears */ int agedays; /*age in days *//* large ages may require the longtype */ ageyears = 101; agedays = 365 * ageyears;printf("An age of %d years is %d days.\n", ageyears, agedays); return 0;}PE 2‐4/* Programming Exercise 24 */#include<stdio.h>voidjolly(void);voiddeny(void);intmain(void){ jolly();jolly();jolly();deny();return0; }void jolly(void){printf("For he's a jolly good fellow!\n"); }void deny(void){printf("Which nobody can deny!\n"); }PE 2‐6/* Programming Exercise 26 */#include<stdio.h> intmain(void){ inttoes;toes =10;printf("toes = %d\n", toes);printf("Twice toes = %d\n", 2 * toes);printf("toes squared = %d\n", toes * toes);return 0;}/* or create two more variables, set them to 2 * toes and toes * toes */PE 2‐8/* Programming Exercise 28 */#include<stdio.h>voidone_three(void); voidtwo(void); intmain(void){printf("startingnow:\n");one_three();printf("done!\n");return 0;}void one_three(void){printf("one\n");two();printf("three\n");}void two(void){printf("two\n");}Chapter 3 Programming Exercises PE 3‐2/* Programming Exercise 32 */#include<stdio.h> intmain(void){intascii;printf("Enter an ASCII code: "); scanf("%d", &ascii);printf("%d is the ASCII code for %c.\n", ascii, ascii); return 0;}PE 3‐4/* Programming Exercise 34 */#include<stdio.h> intmain(void){ float num;printf("Enter a floatingpoint value: "); scanf("%f", &num);printf("fixedpointnotation: %f\n", num);printf("exponentialnotation: %e\n", num); printf("p notation: %a\n", num); return 0;}PE 3‐6/* Programming Exercise 36 */#include<stdio.h> intmain(void){float mass_mol = 3.0e23; /* mass of watermolecule in grams */ float mass_qt = 950; /*mass of quart of water in grams */ float quarts;float molecules;printf("Enter the number of quarts of water: ");scanf("%f", &quarts);molecules = quarts * mass_qt / mass_mol;printf("%f quarts of water contain %e molecules.\n", quarts, molecules); return 0;}Chapter 4 Programming ExercisesPE 4‐1/* Programming Exercise 41 */#include<stdio.h> intmain(void){ charfname[40];charlname[40];printf("Enter your first name: "); scanf("%s", fname); printf("Enteryour last name: ");scanf("%s", lname);printf("%s, %s\n", lname, fname); return 0;}PE 4‐4/* Programming Exercise 44 */ #include<stdio.h> intmain(void){ floatheight;charname[40];printf("Enter your height in inches: "); scanf("%f",&height); printf("Enter yourname: "); scanf("%s", name);printf("%s, you are %.3f feet tall\n", name, height / 12.0);return0;}PE 4‐7/* Programming Exercise 47 */#include<stdio.h>#include<float.h> intmain(void){ float ot_f = 1.0/ 3.0; doubleot_d = 1.0 / 3.0;printf(" float values:");printf("%.4f %.12f %.16f\n", ot_f, ot_f, ot_f); printf("double values: ");printf("%.4f %.12f %.16f\n", ot_d,ot_d, ot_d);printf("FLT_DIG: %d\n", FLT_DIG); printf("DBL_DIG: %d\n",DBL_DIG); return 0;}Chapter 5 Programming Exercises PE 5‐1/* Programming Exercise 51 */#include<stdio.h> intmain(void){ const intminperhour = 60;int minutes, hours,mins;printf("Enter the number of minutes to convert: "); scanf("%d", &minutes); while (minutes > 0 ){ hours = minutes/ minperhour; mins =minutes % minperhour;printf("%d minutes = %d hours, %d minutes\n", minutes, hours, mins); printf("Enter next minutes value (0 to quit): "); scanf("%d", &minutes);}printf("Bye\n");return0;}PE 5‐3/* Programming Exercise 53 */#include<stdio.h> intmain(void){ const intdaysperweek = 7;int days, weeks,day_rem;printf("Enter the number ofdays: "); scanf("%d", &days);while (days > 0){ weeks = days /daysperweek; day_rem= days % daysperweek;printf("%d days are %d weeks and %ddays.\n", days, weeks, day_rem);printf("Enter the number of days (0 or less to end): "); scanf("%d", &days);}printf("Done!\n");return 0;}PE 5‐5/* Programming Exercise 55*/ #include <stdio.h>int main(void) /* finds sum of first n integers */{int count,sum;int n;printf("Enter the upperlimit: "); scanf("%d", &n);count = 0;sum = 0;while (count++ < n)sum = sum + count;printf("sum = %d\n",sum); return 0;}PE 5‐7/* ProgrammingExercise 57 */#include <stdio.h>voidshowCube(double x);int main(void) /* finds cube of entered number */ { double val;printf("Enter a floatingpointvalue: "); scanf("%lf", &val);showCube(val); return 0; }void showCube(double x){printf("The cube of %e is %e.\n", x, x*x*x );}Chapter 6 Programming ExercisesPE 6‐1/* pe61.c *//* this implementation assumes the character codes */ /* are sequential, as they are in ASCII. */#include <stdio.h>#define SIZE 26 intmain( void ) { charlcase[SIZE]; int i;for (i = 0; i < SIZE;i++) lcase[i] = 'a'+ i; for (i = 0; i <SIZE; i++)printf("%c", lcase[i]);printf("\n");return 0;}PE 6‐3/* pe63.c *//* this implementation assumes the character codes */ /* are sequential, as they are in ASCII. */#include<stdio.h> intmain( void ){ char let= 'F';char start;char end;for (end = let; end >= 'A'; end) {for (start = let; start >= end; start) printf("%c", start); printf("\n");}return0;}PE 6‐6/* pe66.c */#include<stdio.h> intmain( void ){ int lower,upper, index; intsquare, cube;printf("Enter startinginteger: "); scanf("%d",&lower); printf("Enterending integer: ");scanf("%d", &upper);printf("%5s %10s %15s\n", "num", "square", "cube"); for (index = lower;index <= upper; index++){ square =index * index;cube = index * square;printf("%5d %10d %15d\n", index, square, cube); }return0;}PE 6‐8/* pe68.c */#include<stdio.h> intmain( void ){ double n, m;doubleres;printf("Enter a pair of numbers: ");while (scanf("%lf %lf", &n, &m) == 2){res = (n m) / (n * m);printf("(%.3g %.3g)/(%.3g*%.3g) = %.5g\n", n, m, n, m, res); printf("Enter next pair (nonnumeric to quit): ");}return 0;}PE 6‐11/* pe611.c */#include<stdio.h>#defineSIZE 8 intmain( void ){ intvals[SIZE];int i;printf("Please enter %dintegers.\n", SIZE); for (i = 0; i <SIZE; i++) scanf("%d",&vals[i]);printf("Here, in reverse order, are the values you entered:\n"); for (i = SIZE 1; i >= 0; i) printf("%d ", vals[i]); printf("\n"); return 0;}PE 6‐13/* pe613.c *//* This version starts with the 0 power */#include<stdio.h>#defineSIZE 8 intmain( void ){inttwopows[SIZE];int i;int value = 1; /* 2 to the 0 */for (i = 0; i < SIZE; i++){ twopows[i]= value; value*= 2;}i =0;do{printf("%d ",twopows[i]);i++; } while (i <SIZE); printf("\n"); return 0;}PE 6‐14/* pe14.c *//* Programming Exercise 614 */ #include<stdio.h>#defineSIZE 8 intmain(void){ doublearr[SIZE];doublearr_cumul[SIZE];int i;printf("Enter %d numbers:\n", SIZE);for (i = 0; i < SIZE; i++){printf("value #%d: ", i+ 1); scanf("%lf",&arr[i]); /* or scanf("%lf", arr + i); */}arr_cumul[0] = arr[0]; /* set first element */ for (i = 1; i < SIZE; i++) arr_cumul[i] = arr_cumul[i1] + arr[i]; for (i = 0; i < SIZE;i++) printf("%8g ",arr[i]); printf("\n");for (i = 0; i < SIZE; i++)printf("%8g ", arr_cumul[i]);printf("\n");return 0;}PE 6‐16/* pe616.c */#include <stdio.h>#define RATE_SIMP 0.10#defineRATE_COMP0.05 #defineINIT_AMT 100.0int main( void ){double daphne =INIT_AMT;double deidre =INIT_AMT; intyears = 0;while (deidre <= daphne){ daphne +=RATE_SIMP * INIT_AMT; deidre += RATE_COMP * deidre;++years;}printf("Investment values after %d years:\n", years); printf("Daphne: $%.2f\n", daphne); printf("Deidre: $%.2f\n", deidre); return 0;}Chapter 7 Programming Exercises PE 7‐1/* ProgrammingExercise 71 */#include <stdio.h>int main(void){ charch; intsp_ct = 0;int nl_ct =0; intother = 0;while ((ch =getchar()) != '#'){if (ch == ' ')sp_ct++; elseif (ch == '\n')nl_ct++; elseother++;}printf("spaces: %d, newlines: %d, others: %d\n", sp_ct, nl_ct, other);return0;}PE 7‐3/* Programming Exercise 73 */#include<stdio.h> intmain(void){ int n;double sumeven= 0.0; intct_even = 0;double sumodd =0.0; int ct_odd= 0;while (scanf("%d", &n) == 1 && n != 0){if (n % 2 == 0){sumeven += n;++ct_even;}else // n % 2 is either 1 or 1{sumodd += n;++ct_odd;} }printf("Number of evens: %d",ct_even); if (ct_even > 0)printf(" average: %g", sumeven / ct_even); putchar('\n');printf("Number of odds: %d",ct_odd); if (ct_odd > 0)printf(" average: %g", sumodd / ct_odd); putchar('\n');printf("\ndone\n");return0;}PE 7‐5/* Programming Exercise 75 */#include<stdio.h> intmain(void){ charch; intct1 = 0;int ct2 =0;while ((ch=getchar())!= '#'){switch(ch){case '.' : putchar('!'); ++ct1;break; case '!' :putchar('!');putchar('!');++ct2;break; default :putchar(ch);} }printf("%d replacement(s) of . with !\n", ct1); printf("%d replacement(s) of ! with !!\n", ct2);return0;}PE 7‐7// Programming Exercise 77#include <stdio.h>#define BASEPAY 10 // $10 per hour#define BASEHRS 40 // hours at basepay #define OVERTIME 1.5 // 1.5 time#define AMT1 300 // 1st rate tier#define AMT2 150 // 2st rate tier#define RATE1 0.15 // rate for 1st tier#define RATE2 0.20 // rate for2nd tier #define RATE3 0.25 //rate for 3rd tier int main(void){doublehours;double gross;double net;double taxes;printf("Enter the number of hours workedthis week: "); scanf("%lf", &hours); if(hours <= BASEHRS) gross = hours *BASEPAY; elsegross = BASEHRS * BASEPAY + (hours BASEHRS)* BASEPAY * OVERTIME; if (gross <= AMT1)taxes = gross * RATE1; else if (gross <= AMT1 + AMT2)taxes = AMT1 * RATE1 + (gross AMT1)* RATE2; elsetaxes = AMT1 * RATE1 + AMT2 * RATE2 + (grossAMT1 AMT2) * RATE3; net = gross taxes;printf("gross: $%.2f; taxes: $%.2f; net: $%.2f\n", gross, taxes, net);return0;}PE 7‐9/* Programming Exercise 79 */#include<stdio.h>#include<stdbool.h> intmain(void){intlimit;int num;int div;bool numIsPrime; // use int if stdbool.h not available printf("Enter a positive integer: ");while (scanf("%d", &limit) == 1 &&limit > 0){if (limit > 1)printf("Here are the prime numbers upthrough %d\n", limit); elseprintf("No primes.\n");for (num = 2; num <= limit;num++){for (div = 2, numIsPrime = true; (div * div) <= num; div++) if (num % div == 0) numIsPrime = false; if (numIsPrime)printf("%d is prime.\n", num);}printf("Enter a positive integer (q to quit): ");}printf("Done!\n");return 0;}PE 7‐11/* pe711.c *//* Programming Exercise 711 */#include<stdio.h>#include<ctype.h> intmain(void){const doubleprice_artichokes = 2.05; const double price_beets = 1.15; const doubleprice_carrots = 1.09; const double DISCOUNT_RATE = 0.05; const double under5 = 6.50; const double under20 = 14.00; const double base20 = 14.00; const double extralb = 0.50;charch;doublelb_artichokes = 0;double lb_beets =0; doublelb_carrots = 0;double lb_temp;double lb_total;doublecost_artichokes;doublecost_beets;doublecost_carrots;double cost_total;doublefinal_total;double discount;double shipping;printf("Enter a to buy artichokes, b for beets, "); printf("c for carrots, q to quit: "); while ((ch = getchar()) != 'q' && ch != 'Q'){ if (ch == '\n') continue; while(getchar() != '\n')continue; ch =tolower(ch);switch (ch) {case 'a' : printf("Enter pounds of artichokes: "); scanf("%lf",&lb_temp); lb_artichokes +=lb_temp; break;case 'b' : printf("Enter pounds ofbeets: "); scanf("%lf",&lb_temp); lb_beets +=lb_temp; break;case 'c' : printf("Enter pounds of carrots: "); scanf("%lf",&lb_temp); lb_carrots +=lb_temp; break;default : printf("%c is not a valid choice.\n", ch);}printf("Enter a to buy artichokes, b for beets, "); printf("c for carrots, q to quit: ");}cost_artichokes = price_artichokes *lb_artichokes; cost_beets = price_beets *lb_beets; cost_carrots = price_carrots *lb_carrots; cost_total = cost_artichokes + cost_beets + cost_carrots; lb_total =lb_artichokes + lb_beets + lb_carrots; if (lb_total <= 0) shipping = 0.0; else if (lb_total < 5.0) shipping = under5; else if (lb_total < 20) shipping = under20; else shipping = base20 + extralb *lb_total; if (cost_total > 100.0)discount =DISCOUNT_RATE * cost_total;else discount = 0.0;final_total = cost_total + shipping discount; printf("Your order:\n");printf("%.2f lbs of artichokes at $%.2f per pound:$ %.2f\n", lb_artichokes, price_artichokes, cost_artichokes);printf("%.2f lbs of beets at $%.2f per pound: $%.2f\n", lb_beets, price_beets,cost_beets); printf("%.2f lbs of carrots at $%.2f per pound: $%.2f\n", lb_carrots, price_carrots, cost_carrots); printf("Total cost of vegetables: $%.2f\n", cost_total); if (cost_total > 100)printf("Volume discount: $%.2f\n", discount); printf("Shipping: $%.2f\n", shipping); printf("Total charges:$%.2f\n", final_total); return 0; } Chapter 8 Programming Exercises PE 8‐1/* Programming Exercise 81 */#include <stdio.h>int main(void) { int ch;int ct = 0; while((ch = getchar()) != EOF)ct++;printf("%d characters read\n", ct);return0;}PE 8‐3/* Programming Exercise 83 *//* Using ctype.h eliminates need to assume consecutive coding */#include<stdio.h>#include<ctype.h> intmain(void){ int ch;unsigned long uct= 0; unsignedlong lct = 0;unsigned long oct= 0;while ((ch =getchar()) != EOF)if (isupper(ch))uct++; else if(islower(ch))lct++; elseoct++;printf("%lu uppercase characters read\n", uct); printf("%lu lowercase characters read\n", lct); printf("%lu other characters read\n", oct);return0;}/* or you coulduse if (ch >= 'A'&& ch <= 'Z')uct++;else if (ch >= 'a' && ch<= 'z') lct++; elseoct++;*/PE 8‐5/* Programming Exercise 85 *//* binaryguess.c an improved numberguesser */ /* but relies upon truthful, correct responses */#include <stdio.h>#include <ctype.h>int main(void) { inthigh = 100; int low= 1; int guess =(high + low) / 2;char response;printf("Pick an integer from 1 to 100. I will try to guess "); printf("it.\nRespond with a y if my guess is right, with");printf("\na h if it is high, and with an l if it is low.\n");printf("Uh...is your number %d?\n", guess);while ((response = getchar()) != 'y') /* get response */{if (response == '\n')continue;if (response != 'h' && response != 'l'){printf("I don't understand that response. Please enterh for\n"); printf("high, l for low, or y for correct.\n"); continue;}if (response == 'h')high = guess 1;else if (response == 'l')low = guess + 1;guess = (high + low)/ 2;printf("Well, then, is it %d?\n", guess);}printf("I knew I could doit!\n"); return 0;}PE 8‐7/* Programming Exercise 87 */#include <stdio.h>#include <ctype.h>#include <stdio.h>#define BASEPAY1 8.75 // $8.75 per hour #define BASEPAY2 9.33 // $9.33 per hour #define BASEPAY3 10.00 // $10.00 per hour #define BASEPAY4 11.20 // $11.20 per hour #define BASEHRS 40 // hours at basepay #define OVERTIME 1.5 // 1.5 time#define AMT1 300 // 1st rate tier#define AMT2 150 // 2st rate tier#define RATE1 0.15 // rate for 1st tier #define RATE2 0.20 // ratefor 2nd tier #define RATE3 0.25// rate for 3rd tier int getfirst(void);void menu(void); int main(void){ doublehours;doublegross;double net;doubletaxes;double pay;charresponse;menu();while ((response = getfirst()) != 'q'){if (response == '\n') /* skip over newlines */ continue;response = tolower(response); /* accept A as a, etc.*/ switch (response){case 'a': pay = BASEPAY1;break; case 'b': pay =BASEPAY2; break; case 'c':pay = BASEPAY3; break; case'd': pay = BASEPAY4; break;default : printf("Please enter a, b, c, d, or q.\n"); menu();continue; // go to beginning of loop}printf("Enter the number of hours workedthis week: "); scanf("%lf", &hours); if(hours <= BASEHRS) gross = hours *pay; elsegross = BASEHRS * pay + (hours BASEHRS) *pay * OVERTIME; if (gross <= AMT1)taxes = gross * RATE1; else if (gross <= AMT1 +AMT2)taxes = AMT1 * RATE1 + (gross AMT1)* RATE2; elsetaxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross AMT1 AMT2) * RATE3; net = gross taxes;printf("gross: $%.2f; taxes: $%.2f; net: $%.2f\n", gross, taxes, net); menu(); }printf("Done.\n");return0;}void menu(void){printf("********************************************************""*********\n");printf("Enter the letter corresponding to the desired pay rate"" or action:\n");printf("a) $%4.2f/hr b) $%4.2f/hr\n", BASEPAY1, BASEPAY2);printf("c) $%5.2f/hr d) $%5.2f/hr\n", BASEPAY3, BASEPAY4); printf("q)quit\n");printf("*********************************************** *********""*********\n");}int getfirst(void){intch;ch = getchar();while (isspace(ch))ch = getchar();while (getchar() !='\n') continue;return ch;}Chapter 9 Programming ExercisesPE 9‐1/* Programming Exercise 91 */#include <stdio.h>double min(double,double); int main(void){double x, y; printf("Entertwo numbers (q to quit): ");while (scanf("%lf %lf", &x, &y) ==2){ printf("The smaller numberis %f.\n", min(x,y)); printf("Next two values (q to quit): ");}printf("Bye!\n");return0;}double min(double a, double b){return a < b ? a : b;}/* alternative implementation doublemin(double a, double b){ if (a< b)return a;elsereturn b;}*/PE 9‐3/* Programming Exercise 93 */#include <stdio.h>void chLineRow(char ch, int c,int r); int main(void){ char ch; int col, row; printf("Enter a character (# to quit): "); while ( (ch = getchar()) != '#') { if (ch== '\n')continue;printf("Enter number of columns and number of rows: "); if (scanf("%d %d", &col, &row) != 2) break; chLineRow(ch, col, row);printf("\nEnter next character (# to quit): "); }printf("Bye!\n");return0;}// start rows and cols at 0void chLineRow(char ch,int c, int r){int col, row;for (row = 0; row < r ; row++){for (col = 0; col < c;col++) putchar(ch);putchar('\n');}return;}PE 9‐5/* Programming Exercise 95 */#include <stdio.h>void larger_of(double *p1,double *p2); int main(void){double x, y; printf("Entertwo numbers (q to quit): ");while (scanf("%lf %lf", &x, &y) ==2){larger_of(&x, &y);printf("The modified values are %f and %f.\n", x, y); printf("Next two values (q to quit): ");}printf("Bye!\n");return0;}void larger_of(double *p1, double *p2) { if(*p1 > *p2)*p2 = *p1;else*p1 = *p2;}// alternatively:/*void larger_of(double *p1, double *p2) {*p1= *p2 = *p1 > *p2 ? *p1 : *p2; }*/PE 9‐8/* Programming Exercise 98*/ #include <stdio.h>double power(double a, int b); /* ANSI prototype */ int main(void) { double x,xpow; int n; printf("Enter a number andthe integer power"); printf(" to which\nthe number will be raised. Enter q"); printf(" toquit.\n"); while (scanf("%lf%d", &x, &n)== 2){ xpow = power(x,n); /* function call */ printf("%.3g to the power %dis %.5g\n", x, n, xpow); printf("Enter nextpair of numbers or q to quit.\n");} printf("Hope you enjoyed this powertrip bye!\n"); return 0;} double power(double a, int b) /* function definition */{ doublepow = 1;int i; if(b == 0){ if (a== 0)printf("0 to the 0 undefined; using 1 as thevalue\n"); pow = 1.0; } else if (a == 0) pow = 0.0; else if (b > 0) for(i = 1; i <= b;i++) pow *= a; else /* b < 0 */ pow = 1.0 / power(a, b);return pow; /* return the value of pow */ }PE 9‐10/* Programming Exercise 910 */#include <stdio.h> voidto_base_n(int x, int base); intmain(void) { int number; int b;int count; printf("Enter aninteger (q to quit):\n"); while(scanf("%d", &number) == 1){ printf("Enter numberbase (210): "); while ((count= scanf("%d", &b))== 1&& (b < 2 || b > 10)){printf("base should be in the range 210: ");} if(count != 1)break;。
C++-Primer-Plus(第六版)编程习题解答
using namespace std;
int degrees;
int minutes;
int seconds;
double latitude;
cout << "Enter a latitude in degrees, minutes, and seconds:\n";
cout << "First, enter the degrees: ";
const double LITERS_PER_GALLON = 3.875;
int main ( void )
{
using namespace std;
double euro_rating;
double us_rating;
cout << "Enter fuel consumption in liters per 100 km: ";
#include <iostream>
const int Inch_Per_Foot = 12;
int main(void)
{
using namespace std;
// Note: some environments don't support the backspace character
cout << "Please enter your height in inches: ___/b/b/b ";
cout << C << " degrees Celsius = "
<< F << " degrees Fahrenheit\n";
c++primerplus(第六版)课后编程练习答案
第二章：开始学习C++ n”；}<<endl;return 0;}double C2F(double t){return *t+32;,}<<endl;return 0;}double convert(double t){return 63240*t;n";return 0;}`style(miles per gallon):"<<endl;cout<<Euro_style<<" L/100Km = "<<*Euro_style<<" mpg\n";return 0;}Enter the automobile gasoline consumption figure inEuropean style(liters per 100 kilometers):Converts to . style(miles per gallon):L/100Km = mpg。
Press any key to continuestyle(miles per gallon):";double US_style;cin>>US_style;cout<<"Converts to European style(miles per gallon):"<<endl;cout<<US_style<<" mpg = "<< *US_style<<"L/100Km\n";return 0;}style(miles per gallon):19Converts to European style(miles per gallon):`19 mpg = 100KmPress any key to continue第四章复合类型n";return 0;}rand<<endl<<snack[i].weight<<endl<<snack[i].calory<<endl<<endl;&}return 0;}rand="A";eight=;snack[0].calory=200;snack[1].brand="B";snack[1].weight=;snack[1].calory=400;）snack[2].brand="C";snack[2].weight=;snack[2].calory=500;for(int i=0;i<3;i++){cout << " brand: " << snack[i].brand << endl;cout << " weight: " << snack[i].weight << endl;cout << " calorie: " << snack[i].calory << endl<<endl; （}delete [] snack;return 0;}et();car* ps=new car[num];for(int i=0;i<num;++i){cout<<"Car #"<<i+1<<":\n";—cout<<"Please enter the make: ";getline(cin,ps[i].name);cout<<"Please enter the year made: ";(cin>>ps[i].year).get();}cout<<"Here is your collection:\n";for(int i=0;i<num;++i)cout<<ps[i].year<<" "<<ps[i].name<<endl;delete [] ps;return 0;.}n";return 0;}n";return 0;}…;for(int k=0;k<=i;++k)cout<<"*";cout<<endl;}return 0;}。
C Primer Plus第6版编程练习答案(已下载)精编版
/* or create two more variables, set them to 2 * toes and toes * toes */
PE
/* Programming Exercise 2-8 */
#include <stdio.h> void one_three(void); void two(void); int main(void)
Chapter
PE
/* Programming Exercise 2-1 */
#include <stdio.h> int main(void)
{ printf("Gustav Mahler\n"); printf("Gustav\nMahler\n"); printf("Gustav "); printf("Mahler\n"); return 0;
printf("An age of %d years is %d days.\n", ageyears, agedays); return 0;
}
PE
/* Programming Exercise 2-4 */
#include <stdio.h> void jolly(void); void deny(void); int main(void)
}
PE
/* Programming Exercise 2-3 */
#include <stdio.h> int main(void)
{ int ageyears; /* age in years */ int agedays; /* age in days */
(完整word)c++primerplus(第六版)课后编程练习答案
第二章:开始学习C++//ex2。
1——display your name and address#include〈iostream〉int main（void)｛using namespace std;cout〈〈"My name is liao chunguang and I live in hunan chenzhou。
\n”；｝//ex2。
2-—convert the furlong units to yard uints-把浪单位换位码单位#include〈iostream>double fur2yd（double）;int main()｛using namespace std;cout〈〈"enter the distance measured by furlong units："；double fur；cin〉>fur;cout〈<”convert the furlong to yard"〈<endl;double yd;yd=fur2yd(fur);cout<<fur<〈" furlong is "<<yd〈〈" yard"〈〈endl；return 0；}double fur2yd(double t)｛return 220*t;｝//ex2。
3—每个函数都被调用两次＃include〈iostream〉void mice（）;void see()；using namespace std；int main（){mice()；mice（);see(）;see(）;return 0;}void mice()｛}void see(）｛cout<〈"see how they run”〈<endl;}//ex2.4＃include〈iostream〉int main（)｛using namespace std;cout〈<"Enter your age:”；int age；cin>>age;int month；month=age*12；cout<〈age<〈” years is "<〈month<〈" months"<<endl;return 0;｝//ex2。
C++-primer-plus(第6版)中文版-编程练习答案(word版)
第二章：开始学习C++//ex2.1--display your name and a ddress#include<iostream>int main(void){using namespace std;cout<<"My name is liao chunguang and I live in hunan chenzhou.\n〞；}the furlong units to yard uints-把浪单位换位码单位#include<iostream>double fur2yd(double);int main(){using namespace std;cout<<"enter the distance measured by furlong u nits:";double fur;cin>>fur;cout<<"convert the furlong to y ard"<<endl;double yd;yd=fur2yd(fur);cout<<fur<<" furlong is "<<yd<<" yard"<<endl;return 0;}double fur2yd(double t){return 220*t;}每个函数都被调用两次#include<iostream>void mice();void see();using namespace std;int main(){mice();mice();see();see();return 0;}void mice(){cout<<"three blind mice"<<endl;}void see(){cout<<"see how they run"<<endl;}#include<iostream>int main(){using namespace std;cout<<"Enter your age:";int age;cin>>age;int month;month=age*12;cout<<age<<" years is "<<month<<" months"<<endl;return 0;}the Celsius valve to Fahrenheit value#include<iostream>double C2F(double);int main(){using namespace std;cout<<"please enter a Celsius value:";double C;cin>>C;double F;F=C2F(C);cout<<C<<" degrees Celsius is "<<F<<" degrees Fahrenheit."<<endl; return 0;}double C2F(double t){return 1.8*t+32;}the light years valve to astronomical units--把光年转换为天文单位#include<iostream>double convert(double);//函数原型int main(){using namespace std;cout<<"Enter the number of light y ears:";double light_years;cin>>light_years;double astro_units;astro_units=convert(light_years);cout<<light_years<<" light_years = "<<astro_units<<" astronomical units."<<endl; return 0;}double convert(double t){return 63240*t;//1 光年=63240 天文单位}显示用户输入的小时数和分钟数#include<iostream>void show();main(){using namespace std;show();return 0;}void show(){using namespace std;int h,m;cout<<"enter the number of hours:";cin>>h;cout<<"enter the number of minutes:";cin>>m;cout<<"Time:"<<h<<":"<<m<<endl;}第三章：处理数据//ex3.1—将身高用英尺(feet)和英寸(inch)表示#include<iostream>const int inch_per_feet=12;// const 常量--1feet=12inches--1 英尺=12 英寸int main(){using namespace std;cout<<"please enter your height in inches:\b\b\b";// \b 表示为退格字符int ht_inch;cin>>ht_inch;int ht_feet=ht_inch/inch_per_feet;//取商int rm_inch=ht_inch%inch_per_feet;//取余cout<<"your height is "<<ht_feet<<" feet,and "<<rm_inch<<" inches\n";return 0;}计算相应的body mass index〔体重指数〕#include<iostream>const int inch_per_feet=12;const double meter_per_inch=0.0254;const double pound_per_kilogram=2.2;int main(){using namespace std;cout<<"Please enter your height:"<<endl;cout<<"First,enter your height of feet part〔输入你身高的英尺局部〕:_\b";int ht_feet;cin>>ht_feet;cout<<"Second,enter your height of inch p art〔输入你身高的英寸局部〕:_\b";int ht_inch;cin>>ht_inch;cout<<"Now,please enter your weight in pound:\b\b\b";double wt_pound;cin>>wt_pound;int inch;inch=ht_feet*inch_per_feet+ht_inch;double ht_meter;ht_meter=inch*meter_per_inch;double wt_kilogram;wt_kilogram=wt_pound/pound_per_kilogram;cout<<endl;cout<<"Your pensonal body information as follows:"<<endl; cout<<"身高:"<<inch<<"(英尺inch)\n"<<"身高:"<<ht_meter<<"(米meter)\n"<<"体重:"<<wt_kilogram<<"(千克kilogram)\n";double BMI;BMI=wt_kilogram/(ht_meter*ht_meter);cout<<"your Body Mass Index(体重指数) is "<<BMI<<endl;return 0;}以度，分，秒输入，以度输出#include<iostream>const int minutes_per_degree=60;const int seconds_per_minute=60;int main(){using namespace std;cout<<"Enter a latitude in degrees,minutes,and s econds:\n";cout<<"First,enter the d egrees:";int degree;cin>>degree;cout<<"Next,enter the minutes of arc:";int minute;cin>>minute;cout<<"Fianlly,enter the seconds of arc:";int second;cin>>second;double show_in_degree;show_in_degree=(double)degree+(double)minute/minutes_per_degree+(double)second/mi nutes_per_degree/seconds_per_minute;cout<<degree<<" degrees,"<<minute<<" minutes,"<<second<<"seconds ="<<show_in_degree<<" degrees\n";return 0;}#include<iostream>const int hours_per_day=24;const int minutes_per_hour=60;const int seconds_per_minute=60;int main(){using namespace std;cout<<"Enter the number of seconds:";long seconds;cin>>seconds;int Day,Hour,Minute,Second;Day=seconds/seconds_per_minute/minutes_per_hour/hours_per_day;Hour=seconds/seconds_per_minute/minutes_per_hour%hours_per_day;Minute=seconds/seconds_per_minute%minutes_per_hour;Second=seconds%seconds_per_minute;cout<<seconds<<"seconds = "<<Day<<" days,"<<Hour<<" hours,"<<Minute<<" minutes,"<<Second<<" seconds\n";return 0;}#include<iostream>int main(){using namespace std;cout<<"Enter the world population:";long long world_population;cin>>world_population;cout<<"Enter the population of the US:";long long US_population; cin>>US_population;double percentage;percentage=(double)US_population/world_population*100;cout<<"The population of the US is "<<percentage<<"% of the world population.\n"; return 0;}//ex3.6 汽车耗油量-美国(mpg)or 欧洲风格(L/100Km)#include<iostream>int main(){using namespace std;cout<<"Enter the miles of distance you have driven:";double m_distance;cin>>m_distance;cout<<"Enter the gallons of gasoline you have used:";double m_gasoline;cin>>m_gasoline;cout<<"Your car can run "<<m_distance/m_gasoline<<" miles per gallon\n";cout<<"Computing by European style:\n";cout<<"Enter the distance in k ilometers:";double k_distance;cin>>k_distance;cout<<"Enter the petrol in l iters:";double k_gasoline;cin>>k_gasoline;cout<<"In European style:"<<"your can used "<<100*k_gasoline/k_distance<<" liters of petrol per 100 kilometers\n";return 0;}//ex3.7 automobile gasoline consumption-耗油量--欧洲风格(L/100Km)转换成美国风格(mpg) #include<iostream>int main(){using namespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"European style(liters per 100 k ilometers):";double Euro_style;cin>>Euro_style;cout<<"Converts to U.S. style(miles per gallon):"<<endl;cout<<Euro_style<<" L/100Km = "<<62.14*3.875/Euro_style<<" mpg\n";return 0;}// Note that 100 kilometers is 62.14 miles, and 1 gallon is 3.875 liters.//Thus, 19 mpg is about L/100Km, and 27 mpg is about L/100Km. Enter theautomobile gasoline consumption figure inEuropean style(liters per 100 Converts to U.S.style(miles per gallon):mpgPress any key to continue// ex3.7 automobile gasoline consumption-耗油量--美国风格(mpg)转换成欧洲风格(L/100Km) #include<iostream>int main(){using namespace std;cout<<"Enter the automobile gasoline consumption figure in\n"<<"U.S. style(miles per gallon):";double US_style;cin>>US_style;cout<<"Converts to European style(miles per gallon):"<<endl;cout<<US_style<<" mpg = "<< 62.14*3.875/US_style<<"L/100Km\n";return 0;}// Enter the automobile gasoline consumption figure inU.S. style(miles per gallon):19Converts to European style(miles per gallon):19 mpg =Press any key to continue第四章复合类型//ex4.1 display the information of student#include<iostream>const int Asize=20;using namespace std;struct student//定义结构描述{char firstname[Asize];char lastname[Asize];char grade;int age;};void display(student);//函数原型放在结构描述后int main(){cout<<"what is your first name?"<<endl;student lcg;//创立结构变量〔结构数据对象〕cin.getline(lcg.firstname,Asize);cout<<"what is your last name?"<<endl;cin.getline(stname,Asize);cout<<"what letter grade do you d eserve?"<<endl;cin>>lcg.grade;cout<<"what is your age?"<<endl;cin>>lcg.age;display(lcg);return 0;}void display(student name){cout<<"Name: "<<name.firstname<<","<<stname<<endl;cout<<"Grade:"<<char(name.grade+1)<<endl;cout<<"Age:"<<name.age<<endl;}use the string-class instead of char-array#include<iostream>#include<string>int main(){using namespace std;string name,dessert;cout<<"Enter your name: \n";getline(cin,name);cout<<"Enter your favorite dessert: \n";getline(cin,dessert);cout<<"I have some delicious "<<dessert;cout<<" for you, "<<name<<".\n";return 0;}//有时候会遇到需要按下两次回车键才能正确的显示结果，这是的一个BUG，更改如下：else if (_Tr::eq((_E)_C, _D)){_Chg = true;_I.rdbuf()->sbumpc();//修改后的break; }输入其名和姓，并组合显示#include<iostream>#include<cstring>const int Asize=20;int main(){using namespace std;char fname[Asize];char lname[Asize];char fullname[2*Asize+1];cout<<"Enter your first name:";//输入名字，存储在fname[]数组中cin.getline(fname,Asize);cout<<"Enter your last name:";//输入姓，存储在lname[]数组中cin.getline(lname,Asize);strncpy(fullname,lname,Asize);//把姓lname 复制到fullname 空数组中strcat(fullname,", ");//把“，〞附加到上述fullname 尾部strncat(fullname,fname,Asize);//把fname 名字附加到上述fullname 尾部fullname[2*Asize]='\0';//为防止字符型数组溢出，在数组结尾添加结束符cout<<"Here's the information in a single string:"<<fullname<<endl;//显示组合结果return 0;}#define _CRT_SECURE_NO_WARNINGS#include <iostream>#include <cstring>const int Asize = 20;int main(){using namespace std;char firstname[Asize];char lastname[50];cout << "Enter your first name: ";cin.getline(firstname,Asize);cout << "Enter your last name: ";cin.getline(lastname,50);strcat(lastname,", ");strncat(lastname,firstname,Asize);cout << "Here's the information in a single string: "<< lastname <<endl;return 0;}//ex4.4 使用string 对象存储、显示组合结果#include<iostream>#include<string>int main(){using namespace std;string fname,lname,attach,fullname;cout<<"Enter your first name:";getline(cin,fname);//note:将一行输入读取到string 类对象中使用的是getline(cin,str)//它没有使用句点表示法，所以不是类方法cout<<"Enter your last name:";getline(cin,lname);attach=", ";fullname=lname+attach+fname;cout<<"Here's the information in a single string:"<<fullname<<endl;return 0;}//ex4.5 declare a struct and initialize it 声明结果并创立一个变量#include<iostream>const int Asize=20;struct CandyBar{char brand[Asize];double weight;int calory;int main(){using namespace std;CandyBar snack={"Mocha Munch",2.3,350};cout<<"Here's the information of snack:\n";cout<<"brand:"<<snack.brand<<endl;cout<<"weight:"<<snack.weight<<endl;cout<<"calory:"<<snack.calory<<endl;return 0;}结构数组的声明及初始化#include<iostream>const int Asize=20;struct CandyBar{char brand[Asize];double weight;int calory;};int main(){using namespace std;CandyBar snack[3]={{"Mocha Munch",2.3,350},{"XuFuJi",1.1,300},{"Alps",0.4,100}};for(int i=0;i<3;i++)//利用for 循环来显示snack 变量的内容{cout<<snack[i].brand<<endl<<snack[i].weight<<endl<<snack[i].calory<<endl<<endl;}return 0;}//ex4.7 pizza 披萨饼#include<iostream>#include<string>const int Size=20;struct pizza//声明结构char company[Size];double diameter;double weight;};int main(){using namespace std;pizza pie;//创立一个名为pie 的结构变量cout<<"What's the name of pizza company:";cin.getline(pie pany,Size);cout<<"What's the diameter of pizza:";cin>>pie.diameter;cout<<"What's the weight of pizza:";cin>>pie.weight; cout<<"company:"<<piepany<<endl;cout<<"diameter:"<<pie.diameter<<"inches"<<endl;cout<<"weight:"<<pie.weight<<"ounches"<<endl;return 0;}pizza pie 披萨饼使用new 创立动态结构#include<iostream>#include<string>const int Size=20;struct pizza//声明结构{char company[Size];double diameter;double weight;};int main(){using namespace std;pizza *pie=new pizza;//使用new 创立动态结构cout<<"What's the diameter of pizza:";cin>>pie->diameter; cin.get();//读取下一个字符cout<<"What's the name of pizza company:";cin.get(pie->company,Size);cout<<"What's the weight of pizza:";cin>>pie->weight;cout<<"diameter:"<<pie->diameter<<" inches"<<endl;cout<<"company:"<<pie->company<<endl;cout<<"weight:"<<pie->weight<<" ounches"<<endl;delete pie;//delete 释放内存return 0;}//ex.4.9 使用new 动态分配数组—方法1#include<iostream>#include<string>using namespace std;struct CandyBar{string brand;double weight;int calory;};int main(){CandyBar *snack= new CandyBar[3]; snack[0].brand="A";//单个初始化由new 动态分配的内存snack[0].weight=1.1;snack[0].calory=200;snack[1].brand="B";snack[1].weight=2.2;snack[1].calory=400;snack[2].brand="C";snack[2].weight=4.4;snack[2].calory=500;for(int i=0;i<3;i++){cout << " brand: " << snack[i].brand << endl;cout << " weight: " << snack[i].weight << e ndl;cout << " calorie: " << snack[i].calory << endl<<endl;}delete [] snack;return 0;}//ex.4.10 数组—方法1#include <iostream>int main(){using namespace std;const int Size = 3;int success[Size];cout<<"Enter your success of the three times 40 meters running:\n";cin >> success[0]>>success[1]>>success[2];cout<<"success1:"<<success[0]<<endl;cout<<"success2:"<<success[1]<<endl;cout<<"success3:"<<success[2]<<endl;double average=(success[0]+success[1]+success[2])/3;cout<<"average:"<<average<<endl;return 0;}//ex.4.10 array—方法2#include <iostream>#include <array>int main(){using namespace std;array<double,4>ad={0};cout<<"Enter your success of the three times 40 meters running:\n";cin >> ad[0]>>ad[1]>>ad[2];cout<<"success1:"<<ad[0]<<endl;cout<<"success2:"<<ad[1]<<endl;cout<<"success3:"<<ad[2]<<endl;ad[3]=(ad[0]+ad[1]+ad[2])/3;cout<<"average:"<<ad[3]<<endl;return 0;}第五章循环和关系表达式#include <iostream>int main(){using namespace std;cout<<"Please enter two integers: ";int num1,num2;cin>>num1>>num2;int sum=0;for(int temp=num1;temp<=num2;++temp)//or temp++sum+=temp;cout<<"The sum from "<<num1<<" to "<<num2<<" is "<<sum<<endl;return 0;}#include <iostream>#include<array>int main(){using namespace std;array<long double,101>ad={0};ad[1]=ad[0]=1L;for(int i=2;i<101;i++)ad[i]=i*ad[i-1];for(int i=0;i<101;i++)cout<<i<<"! = "<<ad[i]<<endl;return 0;}#include <iostream>#include <array>using namespace std;int main(){array<long double, 101> multiply;multiply[0] = multiply[1] = 1LL;for (int i = 2; i <= 100; i++)multiply[i] = multiply[i-1]*i;cout << multiply[100];return 0;}#include <iostream>int main(){using namespace std;cout<<"Please enter an integer: ";int sum=0,num;while((cin>>num)&&num!=0){sum+=num;cout<<"So far, the sum is "<<sum<<endl;cout<<"Please enter an integer: ";}return 0;}#include <iostream>int main(){using namespace std;double sum1,sum2;sum1=sum2=0.0;int year=0;while(sum2<=sum1){++year;sum1+=10;sum2=(100+sum2)*0.05+sum2;}cout<<"经过"<<year<<"年后，Cleo 的投资价值才能超过Daphne 的投资价值。
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main(void)
{
int ageyears; /* age in years
*/
int agedays; /* age in days
*/
/* large ages may require the long type */
ageyears = 101;
agedays = 365 * ageyears;
printf("Gustav\nMahler\n");
printf("Gustav ");
printf("Mahler\n");
return
0;
}
Programming Selected
Exercise Answers
PE 2---3
/* Programming Exercise 2-3 */
#include <stdio.h> int
C Primer Plus Sixth Edition
Chapter 2 Programming Exercises
PE 2---1
/* Programming Exercise 2-1 */
#include <stdio.h> int
main(void)
{
printf("Gustav
Mahler\n");
}
PE 2---6
/* Programming Exercise 2-6 */
#include <stdio.h> int
main(void)
{
int
toes;
toes = 10;
1
C Primer Plus Sixth Edition Programming Exercise
Selected Answers
int ascii; printf("Enter an ASCII code: "); scanf("%d", &ascii); printf("%d is the ASCII code for %c.\n", ascii, ascii); return 0; }
PE 3---4
/* Programming Exercise 3-4 */
main(void)
{
float mass_mol = 3.0e-23; /* mass of water molecule in grams */
float mass_qt = 950;
/* mass of quart of water in grams */
float quarts;
float molecules;
Chapter 4 Programming Exercises
PE 4---1
/* Programming Exercise 4-1 */
#include <stdio.h> int
main(void)
PE 2---8
/* Programming Exercise 2-8 */
#include <stdio.h>
void one_three(void);
void two(void); int
main(void)
{
printf("starting now:\n");
one_three();
printf("done!\n");
main(void)
{
jolly()
;
jolly();
jolly();
deny();
return 0; }
void jolly(void)
{
printf("For he's a jolly good fellow!\n");
}
void deny(void)
{
printf("Which nobody can deny!\n");
printf("p notation: %a\n", num);
return 0;
}
2
C Primer Plus Sixth Edition Programming Exercise
Selected Answers
PE 3---6
/* Programming Exercise 3-6 */
#include <stdio.h> int
printf("An age of %d years is %d days.\n", ageyears, agedays);
return 0;
}
PE 2---4
/* Programming Exercise 2-4 */
#include <stdio.h>
void jolly(void);
void deny(void); int
#include <stdio.h> int
main(void)
{
float
num;
printf("Enter a floating-point value: ");
scanf("%f", &num);
printf("fixed-point notation: %f\n", num);
printf("exponential notation: %e\n", num);
return
0;}Βιβλιοθήκη void one_three(void)
{
printf("one\n");
two();
printf("three\n");
}
void two(void)
{
printf("two\n");
}
Chapter 3 Programming Exercises
PE 3---2
/* Programming Exercise 3-2 */ #include <stdio.h> int main(void) {
printf("toes = %d\n", toes);
printf("Twice toes = %d\n", 2 * toes);
printf("toes squared = %d\n", toes * toes);
return
0;
}
/* or create two more variables, set them to 2 * toes and toes * toes */
printf("Enter the number of quarts of water: "); scanf("%f", &quarts);
molecules = quarts * mass_qt / mass_mol; printf("%f quarts of water contain %e molecules.\n", quarts, molecules); return 0; }