平顶山学院大一期末试题
平顶山学院《线性代数》2021-2022第一学期期末试卷B卷

平顶山学院2021-2022第一学期期末试卷B卷《线性代数》一、单项选择题(每小题3分,共24分).a11a12a 13a332a112a313a 11-4a123a 31-4a32a 13a 23=( ).a331.设行列式a 21a 22a 31a32a 23=1,则2a213a 21-4a22A.6;B.-6;C.8;D.-8.2.设A ,B 都是n 阶矩阵,且AB =0 ,则下列一定成立的是().A.A =0或B =0;B.A =0且B =0;C.A =0或B =0;D.A =0且B =0.3.设A,B 均为n 阶可逆矩阵,则下列各式中不正确的是()....A.(A +B )T =A T +B T ;B.(A +B )-1=A -1+B -1;C.(AB )-1=B -1A -1;D.(AB )T =B T A T .4.设α1,α2是非齐次线性方程组Ax =b 的解,β是对应的齐次方程组Ax =0的解,则Ax =b 必有一个解是( ).11A .α1+α2;B .α1-α2;β+α1+α2;C .D .β+α1+α2.22⎧x 1+x 2+x3=05.齐次线性方程组⎨的基础解系所含解向量的个数为⎩2x 2-x 3-x 4=0().A.1;B.2;C.3;D. 4.6.向量组α1,α2,…,αs(s ≥2)线性无关的充分必要条件是().A.α1,α2,…,αs都不是零向量;B.α1,α2,…,αs任意两个向量的分量不成比例;C.α1,α2,…,αs每一个向量均不可由其余向量线性表示;D.α1,α2,…,αs至少有一个向量不可由其余向量线性表示.7.若(),则A 相似于B .A.A =B ;B.秩(A )=秩(B );C.A 与B 有相同的特征多项式;D.n 阶矩阵A 与B 有相同的特征值,且n 个特征值各不相同.8.正定二次型f (x 1,x 2,x 3,x 4)的矩阵为A ,则( )必成立.A.A 的所有顺序主子式为非负数;B.A 的所有顺序主子式大于零;C.A 的所有特征值为非负数;D.A 的所有特征值互不相同.二、填空题(每小题3分,共18分)⎛100⎫ ⎪1.设3阶矩阵A = 220⎪,A *为A 的伴随矩阵,则A *A =_____________.333⎪⎝⎭⎛11⎫2. ⎪=__________________(n 为正整数).⎝11⎭n⎛a b ⎫-13.设A = ,且,则det(A )=ad -bc ≠0A =________________.⎪⎝c d ⎭4.已知4阶方阵A 的秩为2,则秩(A *)=_________________.5.已知向量组a 1=(1,3,1),a 2=(0,1,1),a 3=(1,4,k )线性相关,则k =____________.6.3阶方阵A 的特征值分别为1,-2,3,则A -1的特征值为_________.三、计算题(10分,共44分)x 00a0-10x -10a10a200-1a31.(7分)计算行列式⎛12-13⎫ ⎪2.(7分)设矩阵A = 48-412⎪,问a 为何值时,36-3a ⎪⎝⎭(1)秩(A )=1; (2)秩(A )=2.⎛-2⎫⎛1⎫⎛3⎫⎛0⎫⎪ ⎪ ⎪ ⎪1-30-13.(15分)给定向量组a 1= ⎪,a 2= ⎪,a 3= ⎪,a 4= ⎪,试判断a4 0⎪ 2⎪ 2⎪ 4⎪3⎪⎪ 4⎪⎪ -1⎪⎪ 9⎪⎪⎝⎭⎝⎭⎝⎭⎝⎭是否为a 1,a 2,a 3的线性组合;若是,则求出组合系数⎧λx 1-x 2=λ⎪λx -x =λ⎪4.(15分)λ取何实值时,线性方程组⎨23⎪λx 3-x 4=λ⎪⎩-x 1+λx 4=λ有唯一解、无穷多解、无解?在有无穷多解的情况求通解。
大学生心理健康教育_平顶山学院中国大学mooc课后章节答案期末考试题库2023年

大学生心理健康教育_平顶山学院中国大学mooc课后章节答案期末考试题库2023年1.压力越小越好。
答案:错误2.爱情基本倾向是奉献,衡量一个人对异性有无爱情、强度如何的标志。
答案:正确3.心理咨询通常一次咨询的时间为( )分钟。
答案:504.焦虑是一种内心不安或无根据、无来由的恐惧体验,是人们遇到某些事情如挑战、困难或危险时出现的一种正常的情绪反应。
答案:正确5.从内容层面上看,自我意识可以分为生理自我、()、社会自我三个方面。
答案:心理自我6.性格有好坏之分。
答案:正确7.时间管理就是要把所有的事情都做完。
答案:错误8.下列表述中不属于“文饰”的是()。
答案:把失恋的痛苦转化为奋发图强的动力9.恰当的批评方式不包括()。
答案:直截了当的提出他人的错误10.投射效应提醒我们不要用对别人的感受去评价对方,也不要用别人对你的感受来评价自己。
答案:正确11.根据1946年的第三届国际心理健康卫生大会对心理健康的定义,我们可以明确知道心理健康不只是强调“没病”,更强调个体身体潜能。
答案:正确12.压力的大小由个人的身心承受能力决定。
答案:正确13.心理咨询是咨询师一个人的事情,来访者只要呆在咨询室就行,不需要积极主动配合。
答案:错误14.人格异常都是突然出现的,没有持续很长时间。
答案:错误15.下列哪个不是大学生常见的学习问题?答案:恋爱影响16.如何处理好学习与社会工作的关系、学习与恋爱的关系,如何拥有更多的朋友,探讨更有效的学习方法等等,这些问题属于是大学生( )的内容。
答案:发展咨询17.某位电视演员在扮演的一个角色里,这个角色情绪的反应摇摆不定、跌宕起伏、大起大落,喜欢时花草皆笑,悲伤时草木流泪。
这反映了情绪的什么特点?答案:两极性18.心理危机给人的影响一定是消极的。
答案:错误19.某大一学生小明,经常感觉自己的自行车没有上锁,然后跑到停车点查看,请问该生属于什么症状()。
答案:强迫症状20.某生患有一种严重的心理疾病,一旦发病起来,情绪会异常兴奋或低落,或兴奋与低落交替出现。
2021-2022学年河南省平顶山市高一(上)期末生物试卷(附答案详解)

2021-2022学年河南省平顶山市高一(上)期末生物试卷1.下列有关细胞学说及其建立过程的叙述,错误的是()A. 细胞学说的建立者主要是施莱登和施旺B. 一切生物都由细胞和细胞产物所构成C. 魏尔肖认为细胞通过分裂产生新细胞D. 细胞学说揭示了动物和植物的统一性2.生命系统包含多个不同的结构层次,下列有关叙述正确的是()A. 病毒是生物,也是最基本的生命系统B. 动植物个体都是由系统结构层次直接构成的C. 变形虫既是细胞结构层次也是个体结构层次D. 水、空气等无机环境不参与生命系统的组成3.自然界的生物种类繁多,生物体的结构也存在明显差异。
下列生物中,细胞内无核膜包被的细胞核的一组生物是()①酵母菌②念珠蓝细菌③草履虫④结核杆菌⑤支原体⑥颤蓝细菌A. ①③⑤⑥B. ①②④⑥C. ③④⑤⑥D. ②④⑤⑥4.如图表示人体活细胞中含量较多的四种化学元素。
据图分析,下列有关叙述错误的是()A. 元素在细胞中的相对含量与在无机环境中的不同B. 除图中元素外,细胞内的其他元素均为微量元素C. 这四种元素在人体细胞干重中的含量为②>①>④>③D. 活细胞中含量最多的有机化合物含有元素①②③④5.细胞中的人机盐含量较少,但作用很大,生物体内某种无机盐含量偏少或缺乏会引起相应的症状。
下列关于无机盐缺之及其对应的症状,错误的是()A. 人体缺Fe2+——缺铁性贫血B. 人体缺I-——地方性甲状腺肿大C. 人体缺Ca2+——肌无力D. 人体缺Na+——肌肉酸痛、无力等6.下列有关细胞中的糖类的叙述,正确的是()A. 所有糖类都能为生物体的生命活动提供能量B. 生物体内的糖类绝大多数以葡萄糖的形式存在C. 麦芽糖能否被麦芽糖酶水解可用斐林试剂检测D. 甲壳类动物的几丁质可用于制作食品添加剂7.人体血红蛋白是一种由574个氨基酸组成的蛋白质,含有4条多肽链,其形成过程如图所示。
下列有关叙述错误的是()A. 血红蛋白分子中至少含有4个游离的羧基B. N元素主要位于血红蛋白的氨基中C. 形成血红蛋白的过程中至少会产生570个水分子D. 通过②③④过程形成的复杂空间结构与血红蛋白的功能密切相关8.科学家发现,癌细胞中存在一种单链DNA分子,可促进癌细胞分裂,该单链DNA分子中富含G,每4个G之间通过氢键连接成一个正方形的“G-4平面”,使该DNA分子形成独特的四联体螺旋结构。
2022年平顶山学院临床医学专业《病理学》科目期末考试卷A

2022年平顶山学院临床医学专业《病理学》科目期末考试卷A一、判断题1、在炎症中,巨噬细胞的功能包括:搬运、吸收坏死组织,刺激纤维组织增生,吞噬杀灭病原体,形成炎性肉芽肿,参与免疫反应。
()2、原发性免疫缺陷病,与遗传有关,多发生于青少年。
()3、维持人体健康所需的维生素有13种,其中维生素A、B、D、K是脂溶性的,其余为水溶性的。
()4、唐氏综合征患者可合并先天性心脏病。
()5、营养不良时,因为脂蛋白、载脂蛋白合成减少,也可发生肝脂肪变。
()6、蜂窝织炎性阑尾炎是一种纤维素性炎。
()7、肝硬化表现为肝内纤维组织增生,肝质地变硬,不伴有肝小叶结构的破坏。
()8、慢性粒细胞白血病常出现外周血白细胞明显升高。
()9、慢性子宫颈炎是育龄女性最常见的妇科疾病。
()10、肾益肾炎男性发病多于女性。
()11、风湿病是一种与草绿色链球菌感染有关的变态反应性疾病。
()12、小叶性肺炎因其病变常以细支气管为中心,故又称为支气管肺炎。
()13、颅内无固有的淋巴组织和淋巴管。
()14、功能性肾上腺皮质腺瘤临床上均表现为Cushing综合征。
()15、病灶中发现抗酸染色阳性的细菌即可诊断为结核病。
()二、选择题16、可致猝死的栓塞是()A.脾动脉栓塞B.肾动脉栓塞C.肺动脉主干栓塞D.股动脉栓塞E.脑中动脉栓塞17、中性粒细胞最有效的杀菌系统是()A.活性氮B.HO,-MPO-卤素C.酸性水解酶D.防御素E.溶菌酶18、下列肿瘤的发生与化生有关的是()A.肠型胃癌B.肛管鳞癌C.肝胆管细胞癌D.混合细胞型肝癌E.膀胱尿路上皮癌a19、下列描述不符合一期愈合的是()A.组织缺损少、创缘整齐的伤口B.手术切口C.伤口周围有明显的炎症反应词D.表皮再生在1~2天内即可覆盖伤口E.愈合后留下线状瘢痕20、恶性肿瘤发生淋巴结转移时,肿瘤细胞首先出现在()A.淋巴结副皮质区B.淋巴滤泡的生发中心C.边缘窦D.淋巴结门部E.被膜21、下列哪项参与体内能量平衡调节()A.胰岛素B.胃促生长激素C.瘦素D.神经多肽YE.以上均参与22、关于lgA肾病的肾小球基本病理特征,不正确的是()A.系膜细胞增生B.IgA沉积为主C.系膜区电子致密物沉积D.系膜基质增多E.毛细血管壁明显增厚23、成年人甲状腺功能低下表现为()A.眼球突出B.黏液水肿C.尿崩症D.软骨病E.佝偻病24、子宫颈原位癌可发生()A.血道转移B.淋巴道转移C.直接蔓延D.三者都有E.三者皆无25、哪一项不是肝细胞肝癌的组织形态特点()A.猫细胞分泌胆汁B.癌细胞有角化珠和细胞间桥C.癌细胞血管多,似血窦D.癌细胞间质少,分化低者异型明显E.癌细胞排列成巢状,小梁状,腺管状26、下列有关心肌梗死的描述中错误的是()A.多发生于左冠状动脉前降支供血的区域B.多为出血性梗死C.斑块性病变多发生于血管的心壁侧D.是心源性猝死的主要原因E.临床上有剧烈而较持久的胸骨后疼痛,用硝酸酯类制剂或休息后症状不能完全缓解27、家族性高胆固醇血症属于()A.血浆蛋白病B.受体蛋白病C.膜转运蛋白病D.运输性蛋白病E.蛋白质构象病28、患者,男,3岁,蚊虫叮咬后出现高热、嗜睡、抽搐、昏迷,可能的疾病的是()A.流行性脑脊髓膜炎B.脊髓灰质炎C.克雅病D.库鲁病E.流行性乙型脑炎29、男性患者,42岁,长期胸闷、气短、心痛,没及时就医,不幸死亡,尸解发现心包狭窄,包内有绒毛状物。
2008-2009学年河南平顶山第一学期高一期末考试

2008-2009 学年度河南省平顶山市第一学期高一期末考试地理试卷本试卷分第i 卷(选择题)和第n 卷(非选择题)两部分。
第i 卷 I 至4页,第n 卷5至 6 页,共 100 分。
第i 卷(选择题共40分)考生注意:1.答题前,考生在答题卡上务必用直径 0.5 毫米黑色墨水签字笔将自己的姓名、准考号填写清楚。
2.每小题选出答案后,用 2B 铅笔把答题卡上对应题目的答案标号涂黑,如需改动, 用橡皮擦干净后,再选涂其他答案标号。
在试题卷上作答无效。
3.本卷共 40 小题,每小题 1 分,共 40 分。
在每小题给出的四个选项中,只有一项符 合题目要求。
1.不同历史时期,不同国家人口发展的特点,从根本上说主要取决于3.在人口增长模式转变过程中,先变化的是A.出生率 B .死亡率4. 古今中外的人口迁移资料表明,在影响人口迁移的诸因素中起着最重要作用的因素是A .战争B .国家政策C .经济D .生态环境变化5. 新中国成立后到 20 世纪 80年代中期,人口迁移的特点是A •规模小,频率低B •规模小,频率高C .规模大,频率高D .规模大,频率低6. 随着我国西部大开发的实施,很多人向西部迁移,这种局面形成的主要原因是A .各国控制人口的政策 C .人口死亡率的高低 2.人口增长模式类型决定于A .人口出生率、死亡率、人口总数B .人口出生率、死亡率、社会生产力C .人口出生率、死亡率、自然增长率D .人口出生率、人口总数、社会生产力B .生产力水平的高低 D .自然灾害和战争C •自然增长率D •生育率7. 制约环境人口容量的主要因素是B .科技发展水平 D .生活消费水平8 .关于全球环境人口容量,乐观者认为A .现今世界人口已超过了全球的环境人口容量 B. 未来世界人口不会达到全球环境人口容量的极限值 C.未来全球环境人口容量可稳定在 100亿左右D. 由于环境污染和生态退化问题,全球人口不能再增长9. 《中国土地资源生产能力及人口承载力研究》报告中指出我国人口承载量最高应控制在 A. 12亿左右B . 13亿左右C . 16亿左右D . 20亿左右10. 城市功能区是指A .提供城市职能的地区B .城市内由交通线路分隔的地带C .城市人口统计区D .相同功能活动集中的建设地区11. 城市中,最广泛的土地利用方式是A .商业区功能用地B .工业区功能用地C .住宅区功能用地D .行政区功能用地12. 下列城市内部职能分区中,一般来说地价最高的是A .成片住宅区B .中心商务区C .大型绿地区D .招商引资的工业小区13. 影响城市内部空间结构的主要因素是A .经济因素B .收入高低C .知名度高低D .种族和宗教 14. 确定城市级别与服务范围,其作用在于A .确定城市的职能B. 确定城市规模,规划城市的发展方向C. 确定城市的形态D. 确定城市的功能区分布 15. 我国城市等级划分的主要依据是A •水源条件的改善B .民族政策的变化C .交通与通讯的进步D .经济布局的改变A .资源状况 C .人口的文化C .城市的经济规模D •城市的地域位置16. 在城市化过程中A •城市居民的人均收入差别不断扩大 B. 城乡居民的文化水平差别扩大 C. 城乡居民的价值观念有显著差别 D. 城乡居民的生活方式逐渐趋同17 •从世界各国城市化进程来看,城市化水平随时间的变化趋势可以表示为A .上升的直线B .下降的直线C .稍被拉平的“ S ”形曲线D •抛物线18 •我国西北地区发展农业生产最主要的限制条件是A .劳动力不足B .化肥、农药不足C .水资源不足D .土地资源不足19. 较陡的山坡不适宜修梯田的原因是A .技术力量达不到B .不利于水土保持C .不能耕作D .交通不便 20. 近年来,我国“温室无土栽培生产”得到推广的重要因素是A .农业生产的地域性和周期性特点B .热量和水分的需要C .城市和工业发展的需要D .市场经济和农业技术的发展21. 亚洲地区的水稻种植业有单季稻、双季稻和三季稻之分,其原因是A .热量条件的差异B .降水条件的差异C .地形、地势的差异D .水源条件的差异22 .关于亚洲季风水田农业特点的叙述,正确的是A .机械化水平高B .水利工程量大C .单产量低、商品率低D .大规模经营23. 关于亚洲水田农业的叙述,正确的是A .人口稠密,劳动力素质高B .科技水平高C .高温少雨的气候条件D .小农经营的生产方式 24. 美国中部大平原发展商品谷物农业的优势区位条件是B .高温多雨A •城市的人口规模B •城市的用地规模A .交通便利C .劳动力丰富 25.大牧场放牧业主要分布在A •南非、荷兰 C .丹麦、英国 26.潘帕斯草原属于A •热带草原 C .河漫滩草甸27 •从投入一产出的工业联系看,下列工厂中,宜靠近钢铁厂布局的是A •食品厂B •电视机厂C •化纤厂D •机床厂28 •南亚、墨西哥等地成为美国许多微电子装配工业的迁移选择地,其原因是A •禾U 用当地高科技发达的优势 C 充分利用当地优美的环境 29. 下列工厂属于市场指向型的是A .炼铝厂 C 造船厂30. 下列工业部门中属原料导向型工业的是A •服装工业、电子装配工业 C .制糖、水产品加工31.关于工业集聚的叙述,正确的是A .可以加大运输成本 C .与获得利润的多少无关 32.传统工业区一般是建立在A •丰富的劳动力资源基础上C .丰富的煤、铁资源基础上 33.与新兴工业比较,传统工业具有的明显特点是A .企业集中分布B .企业分散分布C .企业以中小型为主D .企业资本集中程度低34.我国许多经济技术开发区的工业联系主要是指B .消费市场上的联系 D .信息和工业基础设施方面的联系D •以中小型农场为主B •阿根廷、美国 D •澳大利亚、丹麦B •温带草原 D •高山草甸 B •充分利用当地大量的廉价劳动力 D .当地拥有广阔的市场潜力B .家具厂 D .服装厂B •集成电路、飞机制造 D .电解铝工业、化工 B .可以加强信息交流和协作 D •可以增加能源消耗 B .优越的地理位置上 D .暖湿的气候资源基础上 A .生产上的投入一产出联系C .销售网络上的联系35 •“四大工程”中属于交通运输建设项目的是38. 仓储超市是一种以批发为主的大型超市,其选址的主要依据是①位于城市中心 ②环境优美 ③交通便利 ④地租较低 A .①②B .②③C .③④D .②④39. 人地矛盾迅速激化,大自然对人类的报复愈演愈烈的时期是第n 卷(非选择题共60分)注意事项:1.答题前,考生先在答题卷上用直径 0.5毫米黑色墨水签字笔将自己的姓名、准考号 等密封线内的内容填写清楚。
2020-2021学年河南省平顶山市高一上学期期末考试英语试卷及答案

2020-2021学年河南省平顶山市高一上学期期末考试英语试卷及答案一、阅读选择Art Activities for TeensArt&Design Lab for TeensFriday,3p.m.——5p.m.Start your weekend off with some art and inspiration(灵感)!Each Friday we offer new gallery adventures, different materials,and techniques to feed your creativity.Stay the whole time or stop by to connect with artists and other creative teens.For ages13——18,no registration(登记)required.Fee:Free.Five-Day CourseMonday,July17——Friday,July21This year's Teenage Art School explores how artists react to a place,combining text and pictures to create statements about life.Artist-producer Sarah Yates will guide your exploration of working with paint.This free course is for14-to17-year-olds.Whether art is just a hobby or something you are studying, Teenage Art School will help you develop your skills as an artist.There is also a chance to win Bronze Arts Award.China in the MakingSaturday,June8,10a.m.——3p.m.What can art-making materials tell us about the natural world,global trade,social and cultural frameworks, and artists'ideas?This series of gallery conversations and studio experiences immerse(浸入)participants in hands-on exploration while exploring the history of a material once so highly valued in China that it was known as"white gold".Materials provided;Pre-registration required.Fee:$50(members:$30).Contemporary GalleryJuly26——August2,4:00p.m.——5:30p.m.Join us as we close out our Teen Artist Academy with an exhibition and a dance performance.Artworks created by youth in our Teen Artist Academy,a3-week summer camp where teens,ages14-17,learned to plan public artworks will be on exhibit.This event is free and open to the public.1.What's the purpose of"Five-Day Course"?A.To offer you some inspiration for painting.B.To develop your interest in painting.C.To make sure you get an award.D.To teach you some skills in art.2.What is special about China in the Making?A.You have to pay for it.B.You can join in it without registration.C.You can take part in it at any time.D.You can learn about Chinese arts there.3.Which event will exhibit artworks created by teenagers?A.Five-Day Course.B.Contemporary Gallery.C.China in the Making.D.Art&Design Lab for Teens.Our daughter had a new close friend,one we had heard many good things about,and we couldn’t wait to get to know her.After my husband rolled out his homemade pizza,we sat down to enjoy his hard work as well as learn more about each other.Wanting to make our guest feel cared for and valued,we showed interest in her life by asking questions to get to know her better.We chatted about hobbies,work and family.When we landed on the topic of holidays,she turned the question on us.“So how do you all celebrate Christmas?”she asked.My husband,our daughter and I waited and looked at one another for a moment.For some,this question is easy to answer.Their family has traditions they follow year after year.For others,it is more go-with-the-flow.As we pondered which details to share,my daughter spoke first,“For some,Christmas is only about their family.But for us,you never know who will be at our Christmas dinner.We invite in those who might not have a place to celebrate,asking them to join us.”My eyes became wet with tears as I listened to our girl.I hadn’t really noticed what she had seen as our normal.The way I saw it,inviting someone who needed a family on Christmas day was a natural thing for us.But as I look back,I see it has,in fact,become our holiday tradition.Giving a person a home for the holiday brings my heart joy.Christmas isn’t naturally a happy holiday for all.I remember that first Christmas without my dad.He died when I was five,and that first year was painful,an emptiness filling the room without his quiet presence with us.For those whose family lives are less than what they want,the holidays can be a very hard time.If this is you, take a few moments to talk to someone and share how you are feeling today.4.Why did the author mention the girl’s question?A.To express the girl’s interest in holidays.B.To introduce the topic of the text.C.To present the friendly atmosphere.D.To show the girl’s excitement of being invited.5.What does the underlined word“pondered”in paragraph3probably mean?A.Rejected.B.Skipped.C.Considered.D.Emphasized.6.How did the author react to her daughter’s words?A.She was moved to tears.B.She took pride in her daughter.C.She didn’t agree with her daughter.D.She felt she had misunderstood her daughter before.7.What can be learned about the author as a child?A.She had no one to share her feelings with.B.She didn’t feel lonely on Christmas.C.Her family lived a poor life.D.Her father passed away.Taylor Swift won three American Music Awards on Sunday night,including the top"favorite artist" honor-explaining her absence for being busy in the studio re-recording her entire Big Machine album.The favorite artist award came as a surprise,since Swift's name had not come up as a winner any time earlier in the three hours."The reason why I'm not there tonight is that I'm actually recording all of my old music in the studio where we firstly recorded it,"Swift told the viewing audience."So it's been amazing and I can't wait for you to hear it."This was not a surprise to fans,since Swift had said that she was already at work on a re-do of the album this past week.Swift seems very much to want to promote her present recordings to fans.Earlier Sunday,Swift had posted on Twitter a black-and-white photo of herself resting on a couch with the message,"Not a lot going on at the moment."Fans immediately knew this was one of the star's Easter egg moments,not an admission(承认)of laziness,since she'd posted the same ironic(反语的)title when she was secretly beginning the recording of"Folklore".This time,she definitely doesn't want to keep it a secret."This is a fan-voted award,which means so much to me,"she said."You guys have been absolutely wonderful all the years of my career,but especially this one,when we've been so far apart.We haven't been ableto see each other in concert,but I still feel really connected to you through the music,"Swift said,citing(引用)"your reaction to'Folklore'and all of the ways in which your imagination honored that album."8.What was Swift doing during the award presentation?A.Attending another award ceremony.B.Communicating with her fans.C.Performing at a concert.D.Working in the studio.9.What can we learn about Swift's re-recorded album?A.Swift thinks highly of it.B.Swift can't wait to sell it.C.Swift fears fans won't like it.D.Swift regrets missing the ceremony because of it.10.What can we infer from Swift's Twitter on Sunday?A.She was busy with her album.B.She was serious all the time.C.She was interested in taking photos.D.She was a little lazy.11.Why does Swift value the award given to her?A.It suggests her album will sell well.B.It shows she is loved by her fans.C.It is completely unexpected.D.It brings her a lot of money.A new report says English ability is improving in many parts of the world.The report is a yearly look at English levels around the world.This year,the study was based on information from more than2.2milliontest-takers in100countries.The Netherlands had the highest level of English proficiency(精通),while Tajikistan had the lowest.Europe had the highest scores of any region(区域).Within the continent,northern European countries had the best ratings(等级),with the Netherlands,Denmark,and Finland at the top.The report notes that schools in northern Europe have high levels of English ability for several reasons.They include early attention to communication skills,daily speaking and listening in English,and career-targeted language teaching.The report notes that not all countries have the same ability levels.France,Spain,and Italy still fall behind most other European Union states.However,English ability levels in France have improved over the past three years.Asia had the second-highest regional score,behind Europe.But the report notes that Asia has room for has the widest differences in English ability levels.Singapore had the highest score among Asian countries,coming in at number ten in the world.Yet several Central Asian countries were toward the bottom of the list.Their low rating is partly because Russian is the second language that is most commonly taughtin schools.Africa came in third in regional scores,with South Africa in the lead.The report notes that ability test results across Africa were not equal.Kenya and Nigeria were also in the upper part of the list,while other African countries were much lower.One limitation(局限)is that the report only had enough information to include just13African countries.But there could also be less of a difference in skill levels than the information suggests.12.Which European country has the lowest English ability?A.France.B.Finland.C.Denmark.D.The Netherlands.13.Which is a reason for the low level of English in Central Asia?A.Low education level.B.Another foreign language.C.Remote location.D.Traditional culture.14.What is a shortcoming of the report about Africa?A.It didn't study Africa carefully.B.It reached a false conclusion.C.It didn't have enough information.D.It refused to include all African countries.15.Which of the following can be the best title for the text?A.Huge Differences in English Ability among CountriesB.English in Many Countries Needing ImprovingC.English Ability Improving in Many CountriesD.Different Countries'Opinions about English二、七选五Four Memory Exercises Proven to Keep Your Brain SharpTake a class.To keep your brain in tip-top shape,it's important to keep learning-no matter your age.Experts believe that continuing to learn throughout your life can prevent mental aging and improve your memory.16.Trust us,your brain will thank you.Learn a foreign language.Studies show that learning something new over a long period of time can protect an aging brain.Not only can listening and hearing exercises bring great mental excitement,but learning a new language can also reduce yourrisk of cognitive(认知的)drop.17.If you don't have time,Rosetta Stone or Duolingo will help you according to your time.Increase your speed in dealing with things.Quick on your feet,or slow to your action?If your answer is the latter,your brain might be in trouble.18.It can avoid dementia(痴呆),according to research published in the journal Frontiers in Aging Neuroscience.Try PQRST,a five-step method for dealing with long written information quickly.PQRST stands for:Preview or read the material quickly,ask Questions about the document's main points,Reread it,Study the answers to your questions,and Test yourself.19.Saying information out loud can increase your chances of remembering it later,research says.In a study published in the journal Memory,those who read written information out loud showed a5to15percent improvement in memory.To remember something you have just done,heard,or read,do it again and again.20.A.Repeat it out loud.B.Check out your test results.C.Learn to react and do things at a fast speed.D.Doing so will nail the memory down in your mind.E.Here are more habits of people with impressive memory.F.Sign up for a foreign language course at your local college or online.G.Whether it is cooking or maths,attend a class that will teach you something new.三、完形填空One action can set off a chain reaction.The phrase"One Person Can Make a Difference"is one of those 21that we teach youngsters,to encourage them to do something kind,22another person,or dream big about how they will23the world.As adults,do we believe this?Or is it a24just for young people?I am writing to tell you that indeed "one person can".I25this because one day one person did an act of26that changed my life and the lives of millions more.Almost15years ago,while driving across town,I was27a radio interview and heard a story of selflessness that was28.Over Thanksgiving weekend,a woman29ten heavy winter coats on a bus in hopes of donating(捐赠)them at"A Warm Coat"drive.She knew the city had many30people in need and that her31could make a difference between cold and32for ten people that winter.She was only one person,yet it was her action that encouraged me to33that there would always bea34for more coats and that more people would be able to35clothes if there were more convenient clothing collection36.Now,nearly15years later,One Warm Coat has37over4 million coats across the country.As the national founder,my heart is full and38,knowing that we,each one of us,make a real difference in the lives of thousands.So when you step forward to donate your time,or give a(n)39,or help your neighbor,perhaps wondering"will it40matter?",I can tell you that it will!21.A.warnings B.directions C.sayings D.requests22.A.impress B.help C.guard D.calm23.A.change B.guide C.survey D.understand24.A.sign B.goal C.dream D.lesson25.A.treasure B.know C.rediscover D.forget26.A.kindness B.exploration C.forecast D.challenge27.A.caring about B.taking part in C.listening to D.getting involved with 28.A.common B.relaxing C.urgent D.moving29.A.brought B.checked C.chose D.rented30.A.social B.peaceful C.volunteer D.homeless 31.A.apartments B.foods C.shoes D.coats32.A.charity B.sickness C.comfort D.struggle33.A.suffer B.realize C.complain D.stress34.A.need B.choice C.reason D.preference35.A.save B.design C.offer D.make 36.A.advertisements B.locations C.partners D.conclusions37.A.lost B.stored C.received D.created38.A.honest B.peaceful C.generous D.warm39.A.invitation B.attempt C.medal D.thing40.A.really B.formally C.gradually D.equally四、用单词的适当形式完成短文阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式,并将答案填写在答题卡上.A reporter was interviewing an astronaut.She asked him,"How have you become an astronaut and, 41.(general)speaking,what are the requirements to become an astronaut?"The astronaut answered,"My experience as an astronaut was born thanks to the Aeronautica Militare.When I42.(enter)the Air Force in1995,my project was to become a pilot of tactical aircraft.After43.(complete)my training at the Euro-NATO Joint Jet Pilot training school,at Sheppard Air Force Base,Texas,I returned to Italy to be a fighter pilot.Then,I was allowed44.(become)an experimental pilot and I graduated from the EPNER,the French test pilot school,in Istres.In2008,with the experimental pilot identity,I could apply45.a career as an ESA astronaut.There were(and there still are)two46.(path)to make oneself become an astronaut: a pilot method,for those who have pilot experience,and a non-pilot method for those who have a science (engineering,physics,medical,etc)background.If you are in the pilot path,being a test pilot gives you more points in the selection(选拔)because there47.(be)much similarity between the pilot's work and48.of the astronaut.When I applied,back in2008,two astronauts49.(choose)from the pilot method and four-actually five, including one50.was later added-came from the non-pilot method."五、短文改错51.假定英语课上老师要求同桌之间交换修改作文,请你修改你同桌写的以下作文.文中共有10处语言错误,每句中最多有两处.每处错误仅涉及一个单词的增加、删除或修改.增加:在缺词处加一个漏字符号(^),并在其下面写出该加的词.删除:把多余的词用斜线(\)划掉.修改:在错的词下划一横线,并在该词下面写出修改后的词.注意:1.每处错误及其修改均仅限一词;2.只允许修改10处,多者(从第11处起)不计分.With the winter holiday coming,and I'd like to share my plan with you.First,I wanted to read a Chinese classic,which can help me learn some knowledges.Second,I will spend as more time as possible with my parents, communicating with us and helping do some housework.Helping them prepare for the Spring Festival is also a important task.Third,I will go to the nursing home do volunteer activities.I will help those lonely old people,and let them find their happy during the festival.Of course,I have to spend some time to my holiday homework.The holiday will be so exciting and meaningful which I am looking forward to it.六、提纲类作文52.假定你是李华,你校要开办一个校园艺术画廊,请你给外教Mr.Smith写一封信,内容包括:1.开办艺术画廊目的;2.艺术画廊内容(中外名画复制品及学生习作);3.请他推荐一些欧美绘画作品。
(完整版)大一高等数学期末考试试卷及答案详解

一、1 B;2 C; 3 D;4 A.
二、1 2 3 0; 4 0.
三、1解原式 6分
2 解 2分
4分
3解原式 3分
ቤተ መጻሕፍቲ ባይዱ2分
1分
4 解令 则2分
5 1分
6 1分
1分
1分
7 两边求导得 2分
8 1分
1分
2分
9 解 2分
10 4分
11 解原式= = 6分
四、1解令 则 3分
= 2分
2分
1分
2 解 3分
-----------3
3.求摆线 在 处的切线的方程.
解:切点为 -------2
-------2
切线方程为 即 . -------2
4.设 ,则 .
5.设 ,求 .
解: ---------2
--------------2
= ------------2
故 =
四.应用题(每小题9分,3题共27分)
1.求由曲线 与该曲线过坐标原点的切线及 轴所围图形的面积.
(A)必不可导 (B)一定可导(C)可能可导 (D)必无极限
二、填空题(共12分)
1.(3分) 平面上过点 ,且在任意一点 处的切线斜率为 的曲线方程为.
2. (3分) .
3. (3分) =.
4. (3分) 的极大值为.
三、计算题(共42分)
1.(6分)求
2.(6分)设 求
3.(6分)求不定积分
4.(6分)求 其中
(D)(D)若可积函数 为奇函数,则 也为奇函数.
4.设 ,则 是 的(C).
(A)连续点;(B)可去间断点;
(C)跳跃间断点;(D)无穷间断点.
大一高等数学期末考试试卷及复习资料详解

大一高等数学期末考试试卷及复习资料详解大一高等数学期末考试试卷(一)一、选择题(共12分)1.(3分)若/3= 2XXV0,为连续函数,则d的值为().a+ x,x>0(A)I (B) 2 (C)3 (D)-I2.(3分)已知厂⑶=2,则Ii y "7⑶的值为().λ→0 2hOOl (B) 3 (C)-I (D)I23.(3分)定积分∫>Λ∕1-COS23Xdx的值为()•■⑷ 0 (B)-2 (C)I (D) 24.(3分)若/⑴在“勺处不连续,则/3在该点处()・(A)必不可导(B)—定可导(C)可能可导(D)必无极限二、填空题(共12分)1.(3分)平面上过点(0,1),且在任意一点(Λ∙,y)处的切线斜率为3疋的曲线方程为_________________________ .2.( 3 分)∫ ι(x2+x4 Sin XyIX = _______ 1-3.(3 分)IilnX2 Sin丄= ・.r→υX4.(3分)y = 2√ -3√的极大值为________________ —2 (6分)设尸冕,求*JT + 1三、计算题(共42分)1.(6 分)求Iim史S.∙*→υ Sin 3x^3.(6分)求不定积分JXIn(I+十)厶.x .v<ι4.(6 分)求J /(X-1)JΛ∖其中/(x)= < l + cosχ,e' +l,x> 1.5.(6分)设函数y = f(x)由方程JO e,M + [cos∕d∕ = 0所确定,求dy.6.( 6 分)设 f f{x)dx = Sin + C,求j + 3)dx.7.(6 分)求极限IinJI÷-Γn→30k 2/7 7四、解答题(共28分)1.(7 分)设,Γ(lnx) = l+x,且/(0) = 1,求32.(7分)求由曲线y = cosx[-^-<x<^及X轴所围成图形绕着X轴旋I 2 2)转一周所得旋转体的体积.3.(7分)求曲线y = x3-3√÷24x-19在拐点处的切线方程•4.(7分)求函数y = x + √∏7在[-5,1]上的最小值和最大值.五、证明题(6分)设厂(X)在区间[“]上连续,证明i a f^dx = ¥ [/(“) + f(b)]+1 [(X - a)(x - b)fj)dx.(二)一、填空题(每小题3分,共18分)1.设函数/(χ)= 2χ2~1 ,则"1是心)的第_________ 类间断点.X -3x + 23.=∙v→∞V X)4・ 曲线 V 在点(扣)处的切线方程 为 ・5 .函数J = 2X 3-3X 2在[-1,4]上的最大值 _________________ ,最小值 __________ .二、 单项选择题(每小题4分,共20分)1.数列&”}有界是它收敛的( )•(A)必要但非充分条件; (C)充分必要条件; 2.下列各式正确的是((B)充分但非必要条件; (D)无关条件.)・(A) je-χdx=e"x+C i(B) J In X(IX = _ + C ; (C)JI 2∕x=2hl (l 2x)+C ;(D) f —5—JX = Inlllx+ C ・' ,J XInX3-设/(x)在RM 上,广(x)>O 且厂(x)>0,则曲线y = f(x)在[“问上•6.∣∙arctanx J l +x 2(IX(小沿X轴正向上升且为凹(B)沿兀轴正向下降且为凹的;的;(D)沿X轴正向下降且为凸(C)沿兀轴正向上升且为凸的;的.则/(x)在兀=0处的导? :( )•4. 设/(*)=XInX ’⑷等于1;(C)等于O ;(D)不存在•5.已知Ihn/(x)= 2,以下结论正确的是()•G)函数在工=1处有定义且/(1)=2 ; (B)函数在;V = I处的某去心邻域内有定义;(C)函数在2 1处的左侧某邻域内有定义;(D)函数在21处的右侧某邻域内有定义.三、计算(每小题6分,共36分)1.求极限:HlnX2 sinx→0X2.已知y = ln(l + χ2),求几3.求函数J = >0)的导数.5.J X COS XdX ・丄 16.方程y x =X y确定函数y = f(x)f求八四、(H)分)已知/为/(X)的一个原函数,求∫x2∕(x}∕x.五、(6分)求曲线,=壮7的拐点及凹凸区间.六、(10 分)设J广(√∑)/X = X(e、' +1)+C ,求/(X)・(三)填空题(本题共5小题,每小题4分,共20分)・±J_(1)⅛(COSX)r = ________ 石________ .(2)曲线A = Xlnx上及直线X-y + l= °平行的切线方程为y =x-∖(3 )已知f f(e x) = xe~x,且/(D = O ,则大一高等数学期末考试试卷及复习资料详解/(X)= _________ /Cv)= 2(In X)________ .X 211(4)曲线V =3777的斜渐近线方程为 _______ V= 3Λ^9,二、选择题(本题共5小题,每小题4分,共20分)・(1)下列积分结果正确的是(D )(2)函数/W 在[恥]内有定义,其导数广⑴的图形如图1-1所示, 则(D ) •(A)刁宀都是极值点.⑻ g ,/3)),(£,/(£))都是拐点.(C) F 是极值点.,U 是拐点. (D) WJy))是拐点,勺是极值点.(3) 函数y = qe v ÷C 2e-÷A -e'满足的一个微分方程是(D ).(A) /-y-2>∙ = 3xe t . (B) /-y-2y = 3e v . (C) / + y-2y = 3Λ∙e c .(D) / + y~2y = 3e r .lim∕(⅞)-∕(⅞~z0 (4) 设/W 在%处可导,则I h 为(A ) •⑷ 广仇). (B) -f ,M.(C) O. (D)不存在.(5)下列等式中正确的结果是((A) (J* /(x)"∙χ)'Z=/W-(C) 町 /(χ)"χ]=/W -) 微分方程= (V+1)-的通解为三、计算J (本 共4小题,每小题6分,共24分).y =3 _5 "3 O(或令 √Γ+χ = r)四、解答题(本题共4小题,共29分)•1. (本题6分)解微分方程r-5∕÷6j = xe -.解:特征方程r 2-5r + 6 = 0 ------------- 1分 特征解斤=2,r 2 =3. ------------ 1分 3x大一高等数学期末考试试卷及复习资料详解 恤(丄—丄)1∙求极限j X-I In —X 11. xlnx-x+1Iim (—— _ ——)IIm ---------In XIUn I XTl x-1 I---- + In xh ∖x Iim x →,X -1 + xln1.1 + In X 1 IUn -------- =— j 1 + In X +1 2Λ = In Sin t2.方程尸COSWSinf 确定V 为X 的函数,dy y ,(f)-=-一 =∕sm∕, 解 JX 十⑴求dx 及Jx 2 .(3分) (6分)arctan JX3. 4.计算不定积分J石(1+『. arctanA∕√7—— (i + χ)=21 arctan √7t∕ arctan y ∕x ——解 Hatan 仇=2 J √x(l + x)=(arctan2+C ——「一 dx4.计算定积分如+曲.'3χ(l -VTTX) 0解 分)oT7⅛7_ V dx = 一J(:(I-、/i+x)〃X(6分)LL i∖l4/1 «\ ? r V 八2.(本题7分)一个横放着的圆柱形水桶(如图4-1),桶内盛有半桶水,设桶的底半径为R ,水的比重为乙计算桶的一端面上所受的压力.解:建立坐标系如图3.(本题8分)设/B在S】上有连续的导数,f(u) = f(b) = θ9且∫O∕2(X)JΛ =1^试求∫>∕ω∕解:J:Xf(X)f∖x)dx = £ Xf(X)df(x) 2 分= -∫n^^W ------------ 2 分=IV 2(Λ-)⅛-|£72(X)厶一一2 分4.(本题8分)过坐标原点作曲线>, = h^的切线,该切线及曲线y =lnx及X轴围成平面图形D.⑴(3) 求D的面积A;⑵(4) 求D绕直线X = e旋转一周所得旋转体的体积V.解:(1)设切点的横坐标为",则曲线y = In Λ在点(⅞Jn ⅞)处的切线方程y = Inx0 + —(X-X0).氐__I分由该切线过原点知山心-1 = 0,从而心=匕所以该切线的方程为1y = -X.平面图形D的面积1V = -X(2)切线"及X轴及直线Xe所围成的三角形绕直线Xe旋转V I = -7te1所得的圆锥体积为,3 2分曲线尸IZ及X轴及直线所围成的图形绕直线Xe旋转所得的旋转体体积为V2=(oπ(e-e>)2dy9】分因此所求旋转体的体积为V=V l-V2=-^2-e y)2dy = -(5e2-∖2e + 3).五、证明题(本题共1小题,共7分)•1.证明对于任意的实数Y , eJl + x.e x = l + x + —Λ2≥l + x2解法二设fM = e x-x~^则/(0) = 0.因为f f M = e x-∖. 1 分当Xno时,f,M≥o.f(χ)单调增加,/(χ)≥∕(θ)=o.当x≤0时,∕,ω≤0.∕(Λ∙)单调增加,/(X)≥/(0) =0. 所以对于任意的实数X, ∕3≥°∙即e'≥l + I 解法三:由微分中值定理得,R -1 = “ -60 =^(X-O) = ^Xt 其中§位于0 到X 之一1分2分A = V -ey)dy = ~e~^∙解法一:2分2分1分2分间。
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高等数学(下册)考试试卷(一)一、填空题(每小题3分,共计24分)1、 z =)0()(log 22>+a y x a 的定义域为D= 。
2、二重积分⎰⎰≤++1||||22)ln(y x dxdy y x 的符号为 。
3、由曲线x y ln =及直线1+=+e y x ,1=y 所围图形的面积用二重积分表示为 ,其值为 。
4、设曲线L 的参数方程表示为),()()(βαψϕ≤≤⎩⎨⎧==x t y t x 则弧长元素=ds 。
5、设曲面∑为922=+y x 介于0=z 及3=z 间的部分的外侧,则=++⎰⎰∑ds y x )122( 。
6、微分方程x yx y dx dy tan +=的通解为 。
7、方程04)4(=-y y的通解为 。
8、级数∑∞=+1)1(1n n n 的和为 。
二、选择题(每小题2分,共计16分)1、二元函数),(y x f z =在),(00y x 处可微的充分条件是( ) (A )),(y x f 在),(00y x 处连续;(B )),(y x f x ',),(y x f y '在),(00y x 的某邻域内存在;(C ) y y x f x y x f z y x ∆'-∆'-∆),(),(0000当0)()(22→∆+∆y x 时,是无穷小;(D )0)()(),(),(lim2200000=∆+∆∆'-∆'-∆→∆→∆y x yy x f x y x f z y x y x 。
2、设),()(x y xf y x yf u +=其中f 具有二阶连续导数,则2222yuy x u x ∂∂+∂∂等于( )(A )y x +; (B )x ; (C)y ; (D)0 。
3、设Ω:,0,1222≥≤++z z y x 则三重积分⎰⎰⎰Ω=zdV I 等于( )(A )4⎰⎰⎰22013cos sin ππϕϕϕθdr r d d ;(B )⎰⎰⎰2012sin ππϕϕθdr r d d ;(C )⎰⎰⎰ππϕϕϕθ2020103cos sin dr r d d ;(D )⎰⎰⎰ππϕϕϕθ2013cos sin dr r d d 。
4、球面22224a z y x =++与柱面ax y x 222=+所围成的立体体积V=( )(A )⎰⎰-2cos 202244πθθa dr r a d ; (B )⎰⎰-20cos 202244πθθa dr r a r d ;(C )⎰⎰-20cos 202248πθθa dr r a r d ; (D )⎰⎰--22cos 20224ππθθa dr r a r d 。
5、设有界闭区域D 由分段光滑曲线L 所围成,L 取正向,函数),(),,(y x Q y x P 在D 上具有一阶连续偏导数,则⎰=+LQdy Pdx )((A )⎰⎰∂∂-∂∂Ddxdy x Q y P )(; (B )⎰⎰∂∂-∂∂D dxdy x P y Q )(; (C )⎰⎰∂∂-∂∂Ddxdy y Q x P )(; (D )⎰⎰∂∂-∂∂Ddxdy y P x Q )(。
6、下列说法中错误的是( ) (A ) 方程022=+''+'''y x y y x 是三阶微分方程; (B ) 方程x y dxdyx dx dy ysin =+是一阶微分方程; (C ) 方程0)3()2(22232=+++dy y x y dx xy x 是全微分方程; (D )方程xy x dx dy 221=+是伯努利方程。
7、已知曲线)(x y y =经过原点,且在原点处的切线与直线062=++y x 平行,而)(x y 满足微分方程052=+'-''y y y ,则曲线的方程为=y ( )(A )x e x2sin -; (B ))2cos 2(sin x x e x-; (C ))2sin 2(cos x x e x-; (D )x e x2sin 。
8、设0lim =∞→n n nu , 则∑∞=1n nu( )(A )收敛; (B )发散; (C )不一定; (D )绝对收敛。
三、求解下列问题(共计15分)1、(7分)设g f ,均为连续可微函数。
)(),,(xy x g v xy x f u +==,求yu x u ∂∂∂∂,。
2、(8分)设⎰+-=t x tx dz z f t x u )(),(,求tux u ∂∂∂∂,。
四、求解下列问题(共计15分)。
1、计算=I ⎰⎰-2022xy dy edx 。
(7分) 2、计算⎰⎰⎰Ω+=dV y x I )(22,其中Ω是由x 21,222===+z z z y 及所围成的空间闭区域(8分) 五、(13分)计算⎰++-=L y x ydxxdy I 22,其中L 是xoy 面上的任一条无重点且分段光滑不经过原点)0,0(O 的封闭曲线的逆时针方向。
六、(9分)设对任意)(,,x f y x 满足方程)()(1)()()(y f x f y f x f y x f -+=+,且)0(f '存在,求)(x f 。
七、(8分)求级数∑∞=++--11212)2()1(n n nn x 的收敛区间。
高等数学(下册)考试试卷(二)1、设z y x z y x 32)32sin(2-+=-+,则=∂∂+∂∂yzx z 。
2、=+-→→xyxyy x 93lim0 。
3、设⎰⎰=202),(x xdy y x f dx I ,交换积分次序后,=I 。
4、设)(u f 为可微函数,且,0)0(=f 则⎰⎰≤+→=++222)(1lim 223t y x t d y x f t σπ 。
5、设L 为取正向的圆周422=+y x ,则曲线积分⎰=-++Lx x dy x ye dx ye y )2()1( 。
6、设→→→+++++=k xy z j xz y i yz x A )()()(222,则=A div 。
7、通解为xxe c e c y 221-+=的微分方程是 。
8、设⎩⎨⎧<<<≤--=ππx x x f 0,10,1)(,则它的Fourier 展开式中的=n a 。
二、选择题(每小题2分,共计16分)。
1、设函数⎪⎩⎪⎨⎧=+≠++=0,00,),(2222422y x y x yx xy y x f ,则在点(0,0)处( )(A )连续且偏导数存在; (B )连续但偏导数不存在; (C )不连续但偏导数存在; (D )不连续且偏导数不存在。
2、设),(y x u 在平面有界区域D 上具有二阶连续偏导数,且满足02≠∂∂∂y x u及 +∂∂22x u 022=∂∂yu ,则( )(A )最大值点和最小值点必定都在D 的内部; (B )最大值点和最小值点必定都在D 的边界上;(C )最大值点在D 的内部,最小值点在D 的边界上; (D )最小值点在D 的内部,最大值点在D 的边界上。
3、设平面区域D :1)1()2(22≤-+-y x ,若⎰⎰+=Dd y x I σ21)(,⎰⎰+=Dd y x I σ32)(则有( )(A )21I I <; (B ) 21I I =; (C )21I I >; (D )不能比较。
4、设Ω是由曲面1,,===x x y xy z 及0=z 所围成的空间区域,则⎰⎰⎰Ωdxdydz z xy 32 =( ) (A )3611; (B )3621; (C )3631 ; (D )3641。
5、设),(y x f 在曲线弧L 上有定义且连续,L 的参数方程为⎩⎨⎧==)()(t y t x ψϕ )(βα≤≤t ,其中)(),(t t ψϕ在],[βα上具有一阶连续导数,且0)()(22≠'+'t t ψϕ, 则曲线积分⎰=Lds y x f ),(( )(A) ⎰βαψϕdt t t f ))(),((; (B)⎰'+'αβψϕψϕdt t t t t f )()())(),((22 ;(C)⎰'+'βαψϕψϕdt t t t t f )()())(),((22; (D)⎰αβψϕdt t t f ))(),((。
6、设∑是取外侧的单位球面1222=++z y x , 则曲面积分⎰⎰∑++zdxdy ydzdx xdydz =( )(A) 0 ; (B) π2 ; (C)π ; (D)π4。
7、下列方程中,设21,y y 是它的解,可以推知21y y +也是它的解的方程是( ) (A) 0)()(=++'x q y x p y ; (B) 0)()(=+'+''y x q y x p y ;(C) )()()(x f y x q y x p y =+'+''; (D) 0)()(=+'+''x q y x p y 。
8、设级数∑∞=1n na为一交错级数,则( )(A)该级数必收敛; (B)该级数必发散;(C)该级数可能收敛也可能发散; (D)若)0(0→→n a n ,则必收敛。
三、求解下列问题(共计15分) 1、(8分)求函数)ln(22z y x u ++=在点A (0,1,0)沿A 指向点B (3,-2,2)的方向的方向导数。
2、(7分)求函数)4(),(2y x y x y x f --=在由直线0,0,6===+x y y x 所围成的闭区域D 上的最大值和最小值。
四、求解下列问题(共计15分) 1、(7分)计算⎰⎰⎰Ω+++=3)1(z y x dvI ,其中Ω是由0,0,0===z y x 及1=++z y x 所围成的立体域。
2、(8分)设)(x f 为连续函数,定义⎰⎰⎰Ω++=dv y x f z t F )]([)(222, 其中{}222,0|),,(t y x h z z y x ≤+≤≤=Ω,求dtdF 。
五、求解下列问题(15分) 1、(8分)求⎰-+-=Lx x dy m y e dx my y e I )cos ()sin (,其中L 是从A (a ,0)经2x ax y -=到O(0,0)的弧。
2、(7分)计算⎰⎰∑++=dxdy z dzdx y dydz x I 222,其中∑是)0(222a z z y x ≤≤=+ 的外侧。
六、(15分)设函数)(x ϕ具有连续的二阶导数,并使曲线积分⎰'++-'Lx dy x ydx xe x x )(])(2)(3[2ϕϕϕ与路径无关,求函数)(x ϕ。