基本电路理论-英文版

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电路基础第一章英文版chapter1PPT课件

电路基础第一章英文版chapter1PPT课件
The charge e on one electron is negative and equal in magnitude to 1.602 10-19 C which is called as electronic charge. The charges that occur in nature are integral multiples of the electronic charge.
6
Electric current i = dq/dt. The unit of current is the ampere (A),
and it can be derived as 1 A = 1C/s. • A direct current (dc) is a current that
remains constant with time. • An alternating current (ac) is a
Basic unit meter
kilogram second ampere kelvin
mole candela
Symbol m Kg s A K
mol cd
3
The derived units commonly used in electric circuit theory
Decimal multiples and submultiples of SI units 4
11
We should pay close attention to that the arrow is a fundamental part of the definition of the current! Thus, to talk about the value of a current i (t) without specifying the arrow is to discuss an undefined entity. For example, Fig. 1.3a is the proper definitive, whereas Fig. 1.3b apresentation of i(t) symbology.

电路基础理论英文版课件Chpt08

电路基础理论英文版课件Chpt08

McGraw-Hill
1
© The McGraw-Hill Companies, Inc., 2000
CHARLES K. ALEXANDER MATTHEW N.O. SADIKU
FU N DAM E 8.8 A source-free series RLC circuit
McGraw-Hill
5
© The McGraw-Hill Companies, Inc., 2000
CHARLES K. ALEXANDER MATTHEW N.O. SADIKU
FU N DAM E NTALS O F
ELECTRIC CIRCUITS
Fig. 8.13 A source-free parallel RLC circuit
McGraw-Hill
7
© The McGraw-Hill Companies, Inc., 2000
CHARLES K. ALEXANDER MATTHEW N.O. SADIKU
FU N DAM E NTALS O F
ELECTRIC CIRCUITS
Fig. 8.22 Parallel RLC circuit with an applied current
McGraw-Hill
9
© The McGraw-Hill Companies, Inc., 2000
CHARLES K. ALEXANDER MATTHEW N.O. SADIKU
FU N DAM E NTALS O F
ELECTRIC CIRCUITS
Fig. 8.36 Schematic for the circuit in Fig. 8.35
McGraw-Hill

电路基础英文版精编版第六版课程设计

电路基础英文版精编版第六版课程设计

电路基础英文版精编版第六版课程设计1. IntroductionElectricity is an essential component of modern life, powering homes, businesses, and industries around the globe. Understanding the basics of electric circuits is therefore a critical skill for anyone interested in pursuing a career in the electrical or electronics fields. The Circuits Fundamentals course is designed to provide students with an in-depth understanding of electric circuits.This document outlines a course design for the sixth edition of the Electric Circuits Fundamentals textbook, a well-known and widely-used resource for undergraduate students studying electrical and electronics engineering.2. Course ObjectivesThe primary objective of this course is to provide students with a comprehensive understanding of the fundamental principles of electric circuits. By the end of the course, learners will be able to:•Design, analyze, and interpret electric circuits using standard tools and techniques.•Understand the physical principles that underpin electric circuits, and how these principles relate toreal-world applications.•Effectively communicate their understanding of electric circuits to others, both in written and oralformats.3. Course OutlineThe Circuits Fundamentals course comprises 14 chapters, covering a wide range of topics related to electric circuits. The following table provides an overview of the course structure:Chapter Topic Learning Objectives1 Basic Concepts To introduce the fundamentalconcepts of electric circuits2 Resistance andOhm’s Law To understand the resistance and its relationship with Ohm’s Law3 Energy and Power inCircuits Get to know energy concepts and power dissipation in circuits4 Series Circuits Understand the properties andanalyze the behavior of seriescircuits5 Parallel Circuits Understand the properties andanalyze the behavior of parallelcircuits6 Series-ParallelCircuits Understand the properties and analyze the behavior of series-parallel circuits7 Circuits withCapacitors Get to know the properties and behavior of circuits with capacitors8 Circuits withInductors Get to know the properties and behavior of circuits with inductors9 Circuits withCapacitors andInductors Understand the behavior of circuits with capacitors and inductors10 Frequency Response Understand the frequency and itsresponse in circuit elements11 AC Power Understand the properties ofalternating current power12 Three-PhaseCircuits Understand the principles and usage of three-phase circuits13 Transformers Understand the behavior andprinciples of transformers14 Circuit Analysisusing SPICESoftware Understand the usage and implementation of SPICE software4. Course Materials4.1 Required TextbookThe required textbook for this course is the sixth edition of the Electric Circuits Fundamentals textbook. This resource provides a comprehensive overview of the topics covered in the course and includes a range of helpful examples, exercises, and review questions to support learning.4.2 Required HardwareStudents will also need access to the following hardware: • A computer or laptop with appropriate software for circuit simulation, such as the SPICE software.•Basic tools for building and testing circuits, including multimeters, signal generators, andoscilloscopes.5. Course AssessmentStudent learning in this course will be assessed through a combination of homework assignments, quizzes, and exams.Homework assignments will be given regularly to reinforce key concepts introduced in each chapter. Quizzes will be given throughout the course to assess student understanding of specific topics, while exams will be given at the end of the course to evaluate overall knowledge and understanding.6. ConclusionThe Circuits Fundamentals course provides students with a comprehensive understanding of electric circuits and their applications. By completing this course, learners will develop a deep understanding of the fundamental principles of electric circuits, as well as the ability to apply this knowledge to real-world situations.。

电路基础英文版Chapter 11

电路基础英文版Chapter 11

Average power delivered to load is :
PL I RL
2
V 2 th ( Rth RL ) 2 ( X th X L ) 2
RL
(1)
Our objective is to adjust the load parameters RL and XL so that P is maximum. To do this we set P/ RL and P/ XL equal to zero. We obtain
Thus, average power is P 1 V I cos VI cos m m
2
3. Average Power absorbed by R,L,C.
When
v i 0
Voltage and current is in phase
1 1 1 2 0 2 PR Vm I m cos 0 Vm I m I m R VI I R 0 2 2 2
PL I RL
2
V 2th ( Rth RL ) 2 ( X th X L ) 2
V th RL 4Rth
2
In a situation in which the load is purely real, the condition for maximum power transfer is obtained from Eq. (2) by setting XL = 0; that is,
By the passive linear network of Fig.11.1.
Solution: The instantaneous power is given by p=vi=1200cos(377t+450)cos(377t-100) Applying the trigonometric identity 1 cos A cos B [cos( A B) cos( A B)] 2 p(t)=600[cos(754t+350)+cos550] Or p(t)=344.2+600cos(754t+350)W

电路基础理论英文版课件Chapter 9

电路基础理论英文版课件Chapter 9

Chapter 9 Sinusoids and PhasorsSinusoidsA sinusoid is a signal that has the form of the sine or cosine function.anglephase um ent t frequencyangular am plitudeVm where t V v m ==+==+=φφϖϖφϖarg )cos()cos(φϖ+=t V v m φωtfTππω22==radians/second (rad/s)f is in hertz(Hz))cos()()cos()(222111φωφω+=+=t V t v t V t v m m Phase difference:φθφθθθφφφωφωθby v lags v by v leads v phase in are v and v phaseof out are v and v if t t 210210210210)()(2121<>=≠-=+-+=Complex Numberforml exponentia form sinusoidal formpolar form r rectangula φφφφj rez jrsin rcos z r z jy x z =+=∠=+=φPhasora phasor is a complex number representing the amplitude and phase angle of a sinusoidal voltage or current.Eq.(8-1)and Eq. (8-2) Eq.(8-3)When Eq.(8-2) is applied to the general sinusoid we obtainE q.(8-4)The phasor V is written asEq.(8-5)Fig. 8-1 shows a graphical representation commonly calleda phasor diagram.Fig. 8-1: Phasor diagram Two features of the phasor concept need emphasis:1.Phasors are written in boldfacetype like V or I1 to distinguishthem from signal waveformssuch as v(t)and i1(t).2. A phasor is determined byamplitude and phase angle anddoes not contain anyinformation about the frequencyof the sinusoid.In summary, given a sinusoidal signal , the corresponding phasor representation is . Conversely, given the phasor , the corresponding sinusoid is found by multiplying the phasor by and reversing the steps in Eq.(8-4) as follows:E q.(8-6))cos()(φϖ+=t V t v m φ∠=Vm V Time domainrepresentationPhase-domain representationProperties of Phasors•additive propertyEq.(8-7)Eq.(8-8)Eq.(8-9)•derivative propertyEq.(8-10)Vj dtdv ω⇔∴Time domain representationPhase-domain representation•Integral propertyTime domain representationPhase-domainrepresentation⎰⇔ωj Vvdt The differences between v(t) and V:V(t) is the instantaneous or time-domain representation, while V is the frequency or phasor-domain representation.2.V(t) is a real signal which is time dependent, while V is just a supposed value to simplify the analysisThe complex exponential is sometimes called a rotating phasor, and the phasor V is viewed as a snapshot of the situation at t=0.Fig. 8-2: Complex exponential+ j + real-real-j ωtV mθ= 0θ= 90 or π/2θ= -90 or -π/2θ= 180 or π151050510151513.51210.597.564.531.5010V r ms ac signal at 0.5 Hzvoltage in voltsa n g u l a r f r e q u e n c y t i m e s t i m e i n r a d i a n s12.566-ω-t n⋅14.14214.142-v rea l t ()n5101515129630369121510V rms ac signal at 0.5 Hzangular frequency times time in radiansV o l t a g e i n v o l t s14.14214.142-v im a g t n ()12.5660ωt ⋅()n)sin(is axis )(imaginary j on the phasor rotating the of projection The t V v m ima g ω⋅=)cos(is axis real on the phasor rotating the of projection The t V v m rea l ω⋅=()()caseparticular In this 5.02cos 102cos t t f V v m ⋅⋅=⋅⋅=ππEXAMPLE 8-1(a)Construct the phasors for the following signals:(b) Use the additive property of phasors and the phasorsfound in (a) to find v(t)=v1(t)+v2(t).SOLUTION(a) The phasor representations of v(t)=v1(t)+ v2(t) are(b) The two sinusoids have the same frequent so the additive property of phasors can be used to obtain their sum:The waveform corresponding to this phasor sum isV1V21jVEXAMPLE 8-2(a)Construct the phasors representing the following signals:(b) Use the additive property of phasors and the phasors foundin (a) to find the sum of these waveforms.SOLUTION:(a) The phasor representation of the three sinusoidal currents are(b) The currents have the same frequency, so the additive property of phasors applies. The phasor representing the sum of these current isFig. 8-4EXAMPLE 8-3Use the derivative property of phasors to find the time derivative of v(t)=15cos(200t-30°).The phasor for the sinusoid is V=15∠-30 °.According tothe derivative property, the phasor representing the dv/dt isfound by multiplying V by jω.SOLUTION:The sinusoid corresponding to the phasor jωV isDevice Constraints in Phasor FormV oltage-current relations for a resistor in the: (a) time domain, (b) frequency domain.Resistor:RejImI VIV m m RI Vφφ==Device Constraints in Phasor FormInductor:V oltage-current relations for an inductor in the: (a) time domain, (b) frequency domain.ω︒+==90I V mm LI V φφωDevice Constraints in Phasor Form Capacitor:ωV oltage-current relations for a capacitor in the: (a) time domain, (b) frequency domain.︒+==90VImmCVIφφωConnection Constraints in Phasor Form KVL in time domainKirchhoff's laws in phasor form (in frequency domain)KVL: The algebraic sum of phasor voltages around a loop iszero.KCL: The algebraic sum of phasor currents at a node is zero.The IV constraints are all of the formV=ZI or Z= V/IEq.(8-16)where Z is called the impedance of the elementThe impedance Z of a circuit is the ratio of the phasor voltage V to the phasor current I, measured in ohms(Ω)reactance. the is Z Im X and resistance the is Z Re R where ==+=jXR Z The impedance is inductive when X is positiveis capacitive when X is negativeθθθθsin,cos tan, where 122Z X Z R and RXX R Z Z Z ===+=∠=-EXAMPLE 8-5Fig. 8-5The circuit in Fig. 8-5 is operating in the sinusoidal steady state with and . Find the impedance of the elements in the rectangular box.SOLUTION:︒VI0.278/R=37.9-∠=3L2The Admittance ConceptThe admittance Y is the reciprocal of impedance, measured in siemens (S)VI Z Y ==1Y=G+jBWhere G=Re Y is called conductance and B=Im Y is called the susceptance 2222,1XR XB X R R G jX R jB G +-=+=+=+How get Y=G+jB from Z=R+jX ?Cj Y capacitor Lj Y inductor GR Y resistor C L R ωω====:1:1:Basic Circuit Analysis with PhasorsStep 1: The circuit is transformed intothe phasor domain by representing theinput and response sinusoids as phasorand the passive circuit elements bytheir impedances.Step 2: Standard algebraic circuittechniques are applied to solve thephasor domain circuit for the desiredunknown phasor responses.Step 3: The phasor responses areinverse transformed back into time-domain sinusoids to obtain theresponse waveforms.Series Equivalence And Voltage Divisionwhere R is the real part and X is the imaginary partEXAMPLE 8-6Fig. 8-8The circuit in Fig. 8 -8 is operating in the sinusoidal steady state with(a) Transform the circuit into the phasor domain.(b) Solve for the phasor current I.(c) Solve for the phasor voltage across each element.(d) Construct the waveforms corresponding to the phasors found in (b) and (c)SOLUTION:PARALLEL EQUIVALENCE AND CURRENT DIVISIONRest ofthecircuitY1Y1Y2Y NIVI1I2I3 phasor version of the current division principleEXAMPLE 8-9Fig. 8-13The circuit in Fig. 8-13 is operating in the sinusoidal steady state with i S(t)=50cos2000t mA.(a) Transform the circuit into the phasor domain.(b) Solve for the phasor voltage V.(c) Solve for the phasor current through each element.(d) Construct the waveforms corresponding to the phasors found in (b) and (c).SOLUTION:(a) The phasor representing the input source current isIs=0.05∠0°A. The impedances of the three passive elements areFig. 8-14And the voltage across the parallel circuit isThe sinusoidal steady-state waveforms corresponding to thephasors in (b) and (c) areThe current through each parallel branch isEXAMPLE 8-10Fig. 8-15Find the steady-state currents i(t), and i C(t)in the circuit of Fig. 8-15 (for Vs=100cos2000t V, L=250mH, C=0.5 μF, and R=3kΩ).SOLUTION:Vs=100∠0°Y←→△TRANSFORMATIONSThe equations for the △to Ytransformation areThe equations for a Y-to-△transformation arewhen Z1=Z2=Z3=Z Y or Z A=Z B=Z C=Z N.Z Y=Z N/3 and Z N=3Z Y balanced conditionsEXAMPLE 8-12Use a △to Y transformation to solve for the phasor current I X in Fig. 8-18.Fig. 8-18SOLUTION:ABC△to Y。

电路基础理论英文版课件第一章

电路基础理论英文版课件第一章
Measurement
Resistance is measured in ohms (Ω) using a ohmmeter.
Definition
Definition
Capacitance is the ability of a capacitor to store electrical energy. It is measured by the capacity of the capacitor to hold a charge.
详细描述
04
Analysis methods for circuits
单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文,文字是您思想的提炼,为了最终呈现发布的良好效果,请尽量言简意赅的阐述观点;单击此处添加正文 10*16
A circuit that allows the flow of AC current, typically used in household and industrial applications.
பைடு நூலகம்
Definition of Circuit
Components
01
Circuit components include resistors, capacitors, inductors, diodes, transistors, and power sources. These components are connected to form a complete circuit.
contents
目 录

电路理论基础(英)

电路理论基础(英)

Fundamentals of circuit theoryCourse Code:Course Name:Fundamentals of circuit theoryCredit point::3 Teaching Semester:the 3 semesterStudents type:undergraduate students of specialities of automationPre-course:"Higher Mathematics" 、"Linear Algebra",and "Physics", and so on. Course Leader:Zheng Heng-qiu,Professional Title:Professor,Degree:BAchelorCourse Introduction:Circuit theory is an introductory core course of various electric specialties . This course teaches basic concepts, basic theorems and basic analysis methods of circuit theory. The principal contents are included KIRCHHOFF’S law and its equations, circuit elements, linear DC circuits, sine current circuits, non-sine period Circuits, resonance of circuits,three-phase circuits, time field analysis of the dynamic circuits and frequency field analysis of the dynamic circuits.Practice Teaching:According to the arrangement of course teaching,the course totally has 20experimental hours(ten experiments).Course Assessment:Final score=(usually result)*20%+(final exam result)*80%;Usually result is determined by the attendance rate and goodness ofassignments;The final exam takes closed book examination.Prescribed Textbook:[1]Chen xi-you .《Fundamentals of circuit theory》.Beijing: Higher EducationPress,2004.1,Third Edition.Reference Books:1.Qiu Guan-yuan,《Circuit》, Beijing: Higher Education Press,2006.5,Fifth Edition..2.Zhou shou-chang ,《Circuit Principle》Beijing: Higher Education Press,2005.9,Second Edition.。

CircuitAnalysis(电路分析基础英文版实用)

CircuitAnalysis(电路分析基础英文版实用)

Prof. C.K. Tse: Basic Circuit
Analysis
18
Star-to-delta conversion
Y (star)
For the Y circuit, we consider summing up all currents into the centre node: I1+I2+I3=0, where
3
Power and energy
Work done in moving a charge dq from A to B having a potential difference of V is
W = V dq
A
dq
B
Power is work done per unit time, i.e.,
Prof. C.K. Tse: Basic Circuit
Analysis
15
Example (something that can be done with series/parallel reduction)
Consider this circuit, which is created deliberately so that you can solve it using series/parallel reduction technique. Find V2. Solution: Resistance seen by the voltage source is
Is there some ad hoc solution?
Prof. C.K. Tse: Basic Circuit
Analysis
17
Equivalence of star and delta
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一、Basic DefinitionsElectron: an indivisible particle of negative charge. The amount of charge is measured in coulombs (C). The magnitude of the charge associated with an electron is 1.602x10-l9 C.Current: charge in motion (electrons). Current is measured in units of amperes, or more simply amp.Voltage: an electric potential difference that causes electron flow. It is also called electromotive force (EMF). An analogy often used to describe current and voltage is water in a pipe. Current is analogous to the flow of water, while voltage is analogous to the pressure.Conductor: a material that allows a continuous current to pass through it under the action of a fixed voltage. An example of a good conductor is copper or aluminum which is used in homes and offices for all electrical connections.Insulator: the opposite of a conductor, it does not allow a continuous current to pass though it under the action of a fixed voltage. An example of an insulator is the plastic on electrical cords. Using our water analogy, a conductor can be envisioned as the region inside a pipe, while an insulator can be envisioned as the actual material of the pipe which contains the water flow.Switch: used to control the flow of electrons, or current as it is commonly called. Ideally, a switch turns on or off instantly, and has no voltage across it while it is conducting. In our water analogy, an ideal switch would cut the flow immediately, from completely on to completely off in an instant.Common Passive Circuit ElementsAll circuit elements can be separated into two groups: active and passive. The electrical definition is very similar to the common definition: active circuit elements are capable of delivering power, while passive elements are capable of receiving, and possibly storing, power. In our water analogy, a pump would be an active element. A narrow section of pipe that restricts the flow, a tank, and a water wheel would all be examples of passive elements.Resistors: circuit elements that literally "resist" current flow. Voltage is higher on the end of the resistor that sees the current first. Figure 1 shows two schematic representations of a resistor. In our water analogy, a resistor would be a narrow section of pipe that restricts the flow.Figure 1. Schematic representations of a resistorThe on-resistance (R DS(on)) of our HEXFET® power MOSFETs is usually one of two parameters critical to the designer. The other is breakdown voltage (V(BR)DSS) or how much voltage the device can block when it is off. On-resistance is merely the resistance from drain to source of the power MOSFET in the "on" state. In the "off" state, the resistance is extremely high, but instead of R DS(off), we measure it as leakage current, or I DSS.Capacitors: circuit elements that store electrons. In many instances, they are used as a rechargeable battery, providing a stable voltage reference far from the input power point. They have many different uses in electrical circuits in addition to simply storing electrons. There are many different types of capacitors, including aluminum electrolytic, tantalum electrolytic, ceramic disk, mica, polycarbonate, polypropylene, and polystyrene.Two important considerations in the selection of capacitors are equivalent series inductance (ESL), and equivalent series resistance (ESR). Ideally, these two parameters should be as close to zero as possible, especially as frequency increases. The capacitors above are mentioned approximately in order of decreasing ESL and ESR. Aluminum electrolytic capacitors have extremely high capacitive values, but also high ESL and ESR. This makes them good for dc applications, such as the capacitors on the output of a bridge rectifier, to provide the dc supply to the rest of the circuit. Polypropylene and polystyrene capacitors have very low capacitive values, but also extremely low ESR and ESL values making them good for extremely high frequency applications.Stray capacitance exists in all circuits to some extent. While usually to ground, it can occur between any two points with different potentials. All semiconductor devices have capacitance between their external terminals, and are specified on the data sheets. Figure 2 shows several different schematic representations of capacitors. In our water analogy, a capacitor would be a tank storing water for later use.Figure 2.Schematic Representations of CapacitorsStray capacitance is also responsible for electro-static discharge (ESD). ESD is responsible for the shock you receive in the winter after walking across a carpeted room and touching the doorknob. ESD is particularly dangerous to MOS-gated semiconductors. The amount of static required to cause damage is so small, that a person can damage a device without knowing it. This is why anyone who handles MOS-gated semiconductors must follow strict ESD prevention procedures. Following proper procedures is essential as devices can be damaged, reducing their lifetime, with no perceivable effects at the time of damage.Figure 3. Schematic representations of inductorsInductors: circuit elements that resist change. If, after a period of current flow, an attempt is made to interrupt the current flow, the inductor will continue to force current. Figure 3 shows the schematic representations of two different inductors. In our water analogy, an inductor would be a water wheel - it is difficult to start spinning, but once it is spinning, it is difficult to stop.Figure 4.Toroidal InductorInductors are typically manufactured by winding wire in a toroidal (donut) shape shown in Figure 4. If the inductor is wound around a non-ferromagnetic material such as plastic, ceramic, cardboard, or merely air, the inductance per unit volume is considerably less than if the inductor is wound on a ferromagnetic core. The upper inductor in Figure 4 depicts an air-cored inductor, while the lower inductor depicts a ferromagnetic cored inductor. Ferromagnetic refers to magnetic materials, whose characteristics greatly vary.Figure 5. B-H Characteristics for a Magnetic Material.Figure 5 shows the B-H characteristics for a ferromagnetic material where B is the magnetic flux density, and H is the magnetic field. Operation follows the line, in the direction indicated by the arrow. Although the explanation of this figure is beyond the scope of this module, some important concepts can be observed without a thorough understanding of the plot. During operation, the operating point slides along the curve inthe direction of the arrows. If the positive magnetic flux density (B) is not offset by an equal negative magnetic flux density, the operation curve will slowly creep up, until the material saturates (magnetic flux density (B) is at a maximum and cannot further increase).At saturation the inductance drops to the value of an equivalent air-cored inductor, and the current through it is merely limited by the core's internal resistance which is usually quite low. This is seen at the top of the above curve where the lines flatten, and further increases in flux density (B) are not allowed. Saturation can be caused by one of two mechanisms. First, if the magnetic material is underdesigned, and the flux generated by the current in the winding is greater than the core can handle, the material will saturate. In the above figure, this would place the operating point at the top of the B-H curve.The second method applies if the magnetic material is not allowed to reset between consecutive pulses. Sufficient time between pulses is necessary to allow the energy stored in the magnetic element to go to zero, or reset. If the design does not allow this to occur, the flux in the magnetic element will build up, or staircase, with each consecutive pulse until the device saturates. This results in a large current which usually destroys the semiconductors in its path. This phenomenon also affects transformers which are merely special cases of the inductor.Figure 6. Schematic Representation of a TransformerThe final circuit element is the transformer. Figure 6 shows the schematic representation of a transformer. A transformer could be thought of as a ferromagnetic-cored inductor with two or more sets of wires wound on it. Saturation is also a problem in transformers. Thus transformers and inductors are sometimes lumped together and simply called magnetics.Transformers are most commonly used for one of two purposes. The first is isolation, which is typically needed between two sections of a system which have different ground levels. The second is to change voltage levels. A familiar example is the large ac adapter wall plug supplied with most portable equipment for home use. The adaptor box containsa transformer which steps the voltage down from the line voltage, usually to around 12V, which is then further conditioned by two diodes, and finally supplied to the equipment.Leakage inductance is a critical parameter for transformers, generators, and motors. Leakage inductance is the difference between the self-inductance and the mutual inductance of the primary and secondary windings. Its value is typically quite small, but very important in determining the characteristics and operation of the circuit. It is of particular interest as the switching device may be asked to dissipate the energy stored in the leakage inductance. The leakage inductance contributes to a turn-off voltage spike seen by the switching device. If the energy and/or voltage is sufficient, a snubber may need to be added to the circuit to protect the switching device from damage due to this spike. IR specifies the amount of energy HEXFET® power MOSFETs can dissipate in this mode and are tested as shown in Figure 7, the unclamped inductive test circuit.Figure 7. Unclamped Inductive Test CircuitBasic Electrical DefinitionsPower is defined as current multiplied by voltage:P=V* Iwhere P is the power measured in watts (W) (also joules per second), V is the steady state voltage measured in volts (V), and I is the steady state current measured in amps (A).Energy is defined as current multiplied by voltage, multiplied by time:E=I*V*Twhere "E" is the energy measured in joules (also watt-seconds), "V" is the instantaneous voltage measured in volts, "i" is the instantaneous current measured in amps, and "T" is the time period measured in seconds.To calculate power, given energy and frequency, multiply energy by the frequency. For example, if an IGBT has a total switching energy loss of 1.4mJ under a given set of operating conditions, and is operated at 20kHz, the total power loss due to switching will be 28W.E (1.4mJ) * f (20kHz) = P (28W)二、ac versus dcDirect current (dc) has a constant magnitude. In contrast, alternating current (ac) has a magnitude dependent on time. it follows a sinusoidal waveform, shown below. ac is generated by moving a copper winding through a magnetic field. This causes a voltage to be developed on the winding. Generators in the United States operate at 60Hz, but many places in the world, 50Hz is the standard. Hz is the abbreviation for Hertz, which is the unit of measure for frequency. Frequency is only defined for regular waveforms that repeat indefinitely. Frequency is how many times per second the same position on the waveform occurs. Thus, in the figure below, sixty peaks will pass in one second if the frequency is 60Hz. T is the period, while 1/T is the frequency.Figure 8. 60Hz Sine Wave.Nearly all current starts off as ac, which is generated through an electromechanical process, and is then converted to dc. It is difficult to generate dc directly, as it requires either a dynamo or a chemical reaction such as the one within in a solar cell which converts sunlight into dc voltage. In applications where dc is present, there is usually a nearby ac source. For example, in your automobile the battery that drives the lights, all theelectronics, and all the motors are typically 12 volts dc. This battery is charged by the alternator which is basically a small generator driven by the engine. A three-phase diode bridge is responsible for converting the ac output of the alternator to be compatible with the dc battery.The last important concept is the role of frequency on magnetics. It is beyond the scope of this training module to explain why, but as the operating frequency of a circuit increases, the physical size of the magnetics (remember this means both inductors and transformers) shrinks. This is one of the reasons designers are constantly increasing the frequency of their designs. In the power supply world, one of the benchmarks of a design is how many watts per cubic inch the power supply delivers. One way to substantially increase this number is by moving to higher frequency, and hence, physically smaller magnetic components. The tradeoff of higher frequency operation is increased switching losses in the semiconductor devices, whether it be a diode, IGBT, or power MOSFET.。

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