高一月考试卷
2024-2025学年江苏省南通市如皋中学高一(上)月考数学试卷(一)(含答案)

2024-2025学年江苏省南通市如皋中学高一(上)月考数学试卷(一)一、单选题:本题共8小题,每小题5分,共40分。
在每小题给出的选项中,只有一项是符合题目要求的。
1.函数y=2sin(−x2+π3)的最小正周期是( )A. πB. −4πC. 4πD. 2π2.下列三角函数值为正数的是( )A. tan300°B. sin210°C. cos210°D. sin(−5π3)3.全集U=R,集合A={x|xx−4≤0},集合B={x|log2(x−1)>2},则∁U(A∪B)为( )A. (−∞,0]∪[4,5]B. (−∞,0)∪(4,5]C. (−∞,0)∪[4,5]D. (−∞,4]∪(5,+∞)4.已知幂函数f(x)=(m2−5m+7)x m+1为奇函数,则实数m的值为( )A. 4或3B. 2或3C. 3D. 25.若a=(1.1)−12,b=(0.9)−12,c=log1.10.6,则它们的大小顺序是( )A. a<b<cB. b<a<cC. c<a<bD. a<c<b6.幂函数y=x a,当a取不同的正数时,在区间[0,1]上它们的图象是一组美丽的曲线(如图),设点A(1,0),B(0,1),连结AB,线段AB恰好被其中的两个幂函数y=x a,y=x b的图象三等分,即有BM=MN=NA,那么a−1b=( )A. 0B. 1C. 12D. 27.已知a>0且a≠1,函数在区间(−∞,+∞)上既是奇函数又是增函数,则函数g(x)=log a||x|−b|的图象是( )A. B. C. D.8.已知函数其中ω>0.若f(x)= 2sin (ωx +π4),f(x)在区间(π2,3π4)上单调递增,则ω的取值范围是( )A. (0,4] B. (0,13] C. [52,3] D. (0,13]∪[52,3]二、多选题:本题共3小题,共18分。
高一化学第一次月考试卷人教版

高一化学第一次月考试卷人教版一、选择题(每题3分,共48分)1. 下列物质的分类正确的是()A. 纯碱 - 碱。
B. 碘酒 - 纯净物。
C. 液氯 - 单质。
D. 盐酸 - 化合物。
2. 下列实验操作中,正确的是()A. 用托盘天平称量药品时,左盘放药品,右盘放砝码。
B. 向试管中滴加液体时,滴管应伸入试管内。
C. 用燃着的酒精灯去点燃另一盏酒精灯。
D. 取用块状固体药品时,直接将固体从试管口投入。
3. 下列关于物质的量的叙述中,错误的是()A. 1mol任何物质都含有6.02×10^23个分子。
B. 0.012kg^12C中含有约6.02×10^23个碳原子。
C. 1mol H_2O中含有2mol氢和1mol氧。
D. 1mol Ne中约含有6.02×10^24个电子。
4. 同温同压下,等体积的CO和CO_2相比较,下列叙述中正确的是()A. 质量之比为7:11B. 分子数之比为1:1C. 密度之比为11:7D. 所含原子数之比为2:35. 下列溶液中Cl^-浓度最大的是()A. 200mL 2mol/L MgCl_2溶液。
B. 1000mL 2.5mol/L NaCl溶液。
C. 250mL 1mol/L AlCl_3溶液。
D. 300mL 5mol/L KClO_3溶液。
6. 下列关于胶体的说法正确的是()A. 胶体外观不均匀。
B. 胶体不能透过滤纸。
C. 胶体一定是液体。
D. 胶体粒子直径在1 - 100nm之间。
7. 下列反应中,不属于氧化还原反应的是()A. 2KClO_3frac{_MnO_2}{}2KCl + 3O_2↑B. CaO + H_2O = Ca(OH)_2C. Fe + CuSO_4=FeSO_4+CuD. 2H_2O_2frac{_MnO_2}{}2H_2O+O_2↑8. 下列离子方程式书写正确的是()A. 铁与稀硫酸反应:2Fe + 6H^+=2Fe^3 + + 3H_2↑B. 碳酸钙与稀盐酸反应:CaCO_3+2H^+=Ca^2 + +H_2O + CO_2↑C. 氢氧化钡溶液与稀硫酸反应:Ba^2 + +OH^-+H^++SO_4^2 - =BaSO_4↓+H_2OD. 铜与硝酸银溶液反应:Cu + Ag^+=Cu^2 + +Ag9. 下列物质在水溶液中的电离方程式书写正确的是()A. H_2SO_4=H_2^++SO_4^2 -B. NaOH = Na^++O^2 - +H^+C. Al_2(SO_4)_3=2Al^3 + +3SO_4^2 -D. Ba(OH)_2=Ba^2 + +(OH)^-10. 下列关于氧化还原反应基本概念的说法正确的是()A. 失电子的物质是还原剂,得电子的物质是氧化剂。
辽宁省沈阳市东北育才中学2024-2025学年高一上学期第一次月考(10月)数学试题(含解析)

东北育才高中2024-2025学年度上学期高一年级数学科第一次月考试卷时间:120分钟 满分:150分一、单选题:本大题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是正确的.1.已知集合,则中元素个数为( )A.2B.3C.4D.62.设集合,则集合的真子集的个数为( )A.3B.4C.15D.163.命题“,不等式”为假命题的一个必要不充分条件是( )A.B.C. D.4.设,则下列命题正确的是( )A.若,则B.若,则C.若则D.若,则5.若集合,若,则实数的取值范围是( )A.B.C.D.6.对于实数,当且仅当时,规定,则不等式的解集是()A. B.C. D.7.已知,则的最小值为( )(){}(){}*,,,,,8A x y x y y x B x y x y =∈≥=+=N ∣∣A B ⋂{}{}{}1,2,3,4,5,,,A B M xx a b a A b B ====+∈∈∣M x ∃∈R 2210ax x -+≤0a >1a >102a <<2a >,a b ∈R ,x y a b >>a x b y ->-a b >11a b<,x y a b >>ax by >a b >22a b >{}30,101x A xB x ax x ⎧⎫-===+=⎨⎬+⎩⎭∣B A ⊆a 13⎧⎫-⎨⎬⎩⎭1,13⎧⎫-⎨⎬⎩⎭10,3⎧⎫-⎨⎬⎩⎭10,,13⎧⎫-⎨⎬⎩⎭x ()1n x n n ≤<+∈N []x n =[]24[]36450x x -+<{28}xx ≤<∣31522xx ⎧⎫<<⎨⎬⎩⎭{}27xx ≤≤∣{27}x x <≤∣0,0,23x y x y >>+=23x yxy+A. B.8.方程至少有一个负实根的充要条件是( )A. B.C.D.或二、多选题:本大题共3小题,每小题6分,共18分.在每小题给出的四个选项中,有多项符合题目要求.全部选对得6分,选对但不全的得部分分,有选错的得0分,9.设均为非空集合,且满足,则下列各式中正确的是( )A. B.C.D.10.下列四个命题中正确的是( )A.由所确定的实数集合为B.同时满足的整数解的集合为C.集合可以化简为D.中含有三个元素11.已知关于的不等式的解集为,则下列结论正确的是()A. B.的最大值为C.的最小值为8 D.的最小值为三、填空题:本大题共3小题,每小题5分,共15分.12.的解集是__________.13.某班举行数学、物理、化学三科竞赛,每人至少参加一科,已知参加数学竞赛的有27人,参加物理竞赛的有25人,参加化学竞赛的有27人,其中同时只参加数学、物理两科的有10人,同时只参加物理、化学两科的有7人,同时只参加数学、化学两科的有11人,而参加数学、物理、化学三科的有4人,则全班共有__________人.3-11-1+2210ax x ++=01a <≤1a <1a ≤01a <≤0a <A B U 、、A B U ⊆⊆()U A B U ⋃=ð()()U U U A B B ⋂=ððð()U A B ⋂=∅ð()()U U A B U⋃=ðð(),a b a b ab+∈R {}2,0,2-240,121x x x +>⎧⎨+≥-⎩{}1,0,1,2-(){},3216,,x y x y x y +=∈∈N N ∣()()(){}0,8,2,5,4,26,3A aa a ⎧⎫=∈∈⎨⎬-⎩⎭N Z x ()()()2323100,0a m x b m x a b +---<>>11,2⎛⎫- ⎪⎝⎭21a b +=ab 1812a b +224a b +1222150x x -->14.已知关于的不等式(其中)的解集为,若满足(其中为整数集),则使得集合中元素个数最少时的取值范围是__________.四、解答题:本题共5小题,共77分.解答应写出文字说明,证明过程或演算步骤.15.(本小题13分)已知集合为全体实数集,或.(1)若,求;(2)若,求实数的取值范围.16.(本小题15分)已知全集,集合,集合.(1)若,求实数的取值集合;(2)若集合,且集合满足条件__________(从下列三个条件中任选一个作答),求实数的取值集合.条件①是的充分不必要条件:②是的必要不充分条件:③,使得.17.(本小题15分)设,且.(1介于之间;(2)求;(3)你能设计一个比的吗?并说明理由.18.(本小题17分)对于二次函数,若,使得成立,则称为二次函数的不动点.(1)求二次函数的不动点:(2)若二次函数有两个不相等的不动点,且,求的最小值.x ()()2640mx m x --+<m ∈R A A B ⋂=Z Z B m U {2M xx =<-∣{}5},121x N x a x a >=+≤≤-∣3a =()U M N ⋃ðU N M ⊆ða U =R A x y ⎧⎪==⎨⎪⎩()(){}2440B x x m x m =---<∣B =∅m B ≠∅,A B m x A ∈x B ∈x A ∈x B ∈12,x A x B ∀∈∃∈12x x =10a >1a ≈21111a a =++12,a a 12,a a 2a 3a ()20y ax bx c a =++≠0x ∃∈R 2000ax bx c x ++=0x ()20y ax bx c a =++≠222y x x =+-()2221y x a x a =-++-12,x x 12,0x x >2112x x x x +19.(本小题17分)已知是非空数集,如果对任意,都有,则称是封闭集.(1)判断集合是否为封闭集,并说明理由:(2)判断以下两个命题的真假,并说明理由:命题:若非空集合是封闭集,则也是封闭集;命题:若非空集合是封闭集,且,则也是封闭集:(3)若非空集合是封闭集合,且为实数集,求证:不是封闭集.A ,x y A ∈,x y A xy A +∈∈A {}{}0,1,0,1BC ==-p 12,A A 12A A ⋃q 12,A A 12A A ⋂≠∅12A A ⋂A ,A ≠R R A R ð东北育才高中2024-2025学年度上学期高一年级数学科第一次月考答案【解析】1.解:在集合中,观察集合的条件,当是正整数且时,有等4个元素,则中元素个数为4个.故选C.2.解:由题意可知,集合,集合中有4个元素,则集合的真子集有个,故选C.3.解:命题“,不等式”为假命题,则命题“,不等式”为真命题,所以,解得,所以使得命题“,不等式”为假命题,则实数的取值范围为1,则命题“,不等式”为假命题的一个必要不充分条件是,故选:A.4.解:A :令,则,故错误;B :令,则,故错误;C :令,则,故错误;D :因为,所以即,故正确;故选D.5.解:由题可知:.当时,显然不成立即,则满足;B 8x y +=A ,x y y x ≥()()()()1,7,2,6,3,5,4,4A B ⋂{}5,6,7,8M =M 42115-=x ∃∈R 2210ax x -+≤x ∀∈R 2210ax x -+>0Δ440a a >⎧⎨=-<⎩1a >x ∃∈R 2210ax x -+≤a a >x ∃∈R 2210ax x -+≤0a >1,3,2,0x y a b ==-==13a x b y -=<-=0,0a b ><11a b>0,1,1,0x y a b ==-==0ax by ==a a b >…22||a b >22a b >{}3031x A xx ⎧⎫-===⎨⎬+⎩⎭0a =10…B =∅B A ⊆当时,,由可得:;综上所述实数的取值范围为.故选C.6.解:由,根据的定义可知:不等式的解集是.故选A.7.解:因为,则,当且仅当时,即当,且,等号成立,故的最小值为故选B.8.当时,方程为有一个负实根,反之,时,则于是得;当时,,若,则,方程有两个不等实根,,即与一正一负,反之,方程有一正一负的两根时,则这两根之积小于,于是得,若,由,即知,方程有两个实根,0a ≠1B x x a ⎧⎫==-⎨⎬⎩⎭B A ⊆1133a a -=⇒=-a 10,3⎧⎫-⎨⎬⎩⎭[]24[]36450x x -+<[]()[]()232150x x ⇒--<[]31522x ⇒<<[]x []24[]36450x x -+<{28}xx <∣…0,0,23x y x y >>+=()22222322111x x y y x y x xy y x y xy xy xy y x +++++===+++=+…222x y =3x =-y =23x y xy+1+0a =210x +=12x =-12x =-0,a =0a =0a ≠Δ44a =-0a <Δ0>12,x x 1210x x a=<1x 2x 1a0,0a <0a <0a >Δ0≥01a <≤12,x x必有,此时与都是负数,反之,方程两根都为负,则,解得,于是得,综上,当时,方程至少有一个负实根,反之,方程至少有一个负实根,必有.所以方程至少有一个负实根的充要条件是.故选:9.解:因为,如下图所示,则,选项A 正确:,选项B 正确:,选项正确:,选项D 错误.故选ABC.10.解:分别取同正、同负和一正一负时,可以得到的值分别为,故A 正确;由得,12122010x x a x x a ⎧+=-<⎪⎪⎨⎪=>⎪⎩1x 2x 2210ax x ++=12,x x 1212Δ4402010a x x a x x a ⎧⎪=-≥⎪⎪+=-<⎨⎪⎪=>⎪⎩01a <≤01a <≤1a ≤2210ax x ++=2210ax x ++=1a ≤2210ax x ++=1a ≤CA B U ⊆⊆()U U U ,B A A B U ⊆⋃=ððð()()UUUA B B ⋂=ððð()U A B ⋂=∅ðð()()UUUA B A U ⋃=≠ððð,a b (),a b a b ab+∈R 2,2,0-240,121,x x x +>⎧⎨+≥-⎩22x -<≤所以符合条件的整数解的集合为,故B 正确;由,可以得到符合条件的数对有,故C 正确;当时,;当时,,当时,;当时,;当时,;当时,,所以集合含有四个元素,故D 错误,故选ABC.11.解:由题意,,且方程的两根为和,所以,所以,所以A 正确;因为,所以,可得,当且仅当时取等号,所以的最大值为B 正确;,当且仅当,即时取等号,所以的最小值为C 错误;,当且仅当时取等号,所以的最小值为,所以D 正确.故选ABD.12.解:由,,{}1,0,1,2-3216,,x y x y +=∈∈N N ()()()0,8,2,5,4,22a =666332a ==∈--N 1a =663331a ==∈--N 0a =662330a ==∈--N 1a =-66331a =∉-+N 2a =-6635a =∉-N 3a =-66136a ==∈-N A 2,1,0,3-30a m +>()()232310a m x b m x +---=1-12123111,12323b m a m a m--+=-⨯=-++32,231a m b m +=-=-21,a b +=0,0a b >>21a b +=≥18ab ≤122a b ==ab 1,8()121222255549b a a b a b a b a b ⎛⎫+=++=++≥+=+= ⎪⎝⎭22b a a b =13a b ==12a b+9,22222114(2)(2)22a b a b a b +=+≥+=122a b ==224a b +1222150x x -->2||2150x x ∴-->()()530x x ∴-+>解得:或(舍去),或,即所求的解集为,故答案为.13.解:设参加数学、物理、化学三科竞赛的人分别组成集合,各集合中元素的个数如图所示,则全班人数为.故答案为43.14.解:分情况讨论:当时,,解得;当时,,当且仅当解得或;当时,,当且仅当由,解得.因为,集合中元素个数最少,所以不符合题意;所以要使集合中元素个数最少,需要,解得.故答案为:.15.(本小题13分)5x >3x <-5x ∴<-5x >()(),55,∞∞--⋃+()(),55,∞∞--⋃+,,A B C 24510711443++++++=0m =()640x -+<{}4A xx =>-∣0m <()2266640,4m m x x m m m m ⎛⎫++-+>=+-<- ⎪⎝⎭…m =26{|m A x x m +=<4}x >-0m >2664m m m m+=+≥>m =()2640m x x m ⎛⎫+-+< ⎪⎝⎭264m A x x m ⎧⎫+⎪⎪=-<<⎨⎬⎪⎪⎩⎭A B ⋂=Z B 0m ≤B 265m m +≤23m ≤≤{}23mm ∣……【答案】解:(1)当时,,所以或,又或,所以或;(2)由题可得,①当时,则,即时,此时满足;②当时,则,所以,综上,实数的取值范围为.16.(本小题15分)【答案】解:(1)若,则,解得,所以实数的取值集合为(2)集合,集合,则此时,则集合,当选择条件①时,是的充分不必要条件,有 ,则,且不能同时取等,解得,所以实数的取值集合为当选择条件②时,是的必要不充分条件,有 ,则,且不能同时取等,解得,所以实数的取值集合为当选择条件③时,,使得,有,则,解得,所以实数的取值集合为3a ={}45N xx =≤≤∣U {4N x x =<∣ð5}x >{2M xx =<-∣5}x >()U {4M N x x ⋃=<∣ð5}x >{}U 25M xx =-≤≤∣ðN =∅121a a +>-2a <U N C M ⊆N ≠∅12112215a a a a +≤-⎧⎪+≥-⎨⎪-≤⎩23a ≤≤a {}3aa ∣…B =∅244m m =+2m =m {}2{}2200{45}A xx x x x =-++>=-<<∣∣B ≠∅2,m ≠2244(2)0m m m +-=->{}244B xm x m =<<+∣x A ∈x B ∈A B 24445m m ≤-⎧⎨+≥⎩1m <-m (),1∞--x A ∈x B ∈B A 24445m m ≥-⎧⎨+≤⎩11m -<≤m (]1,1-12,x A x B ∀∈∃∈12x x =A B ⊆24445m m ≤-⎧⎨+≥⎩1m ≤-m (],1∞--17.(本小题15分)【答案】解:(1)证明:.之间.(2比.(3)令,则比.证明如下:由(2.故比18.(本小题17分)【答案】解:(1)由题意知:,,解得,所以,二次函数的不动点为和1.(2)依题意,有两个不相等的正实数根,即方程有两个不相等的正实数根,所以,解得,所以,所以))12111101a a a a ⎫=-⋅--=<⎪+⎭12a a 、11a --1a -2a ∴1a 32111a a =++3a 2a 32a a -=--3a 2a 222x x x +-=()()120x x ∴-+=122,1x x =-=222y x x =+-2-()2221x a x a x -++-=()22310x a x a -++-=()2Δ(3)810a a =+-->12302a x x ++=>1a >12102a x x -⎛⎫=> ⎪⎝⎭121231,22a a x x x x +-+==()222121221121212122x x x x x x x x x x x x x x +-++==,当且仅当,即时等号成立,所以的最小值为6.19.(本小题17分)【答案】(1)解:对于集合,因为,所以是封闭集;对于集合,因为,所以集合不是封闭集;(2)解:对命题:令,则集合是封闭集,但不是封闭集,故错误;对于命题:设,则有,又因为集合是封闭集,所以,同理可得,所以,所以是封闭集,故正确;(3)证明:假设结论成立,设,若,矛盾,所以,所以有,设且,否则,所以有,矛盾,故假设不成立,原结论成立,证毕.()()()22231(1)41162132121212a a a a a a a a a +⎛⎫-+ ⎪-+-+++⎝⎭===---1822621a a -=++≥=-1821a a -=-5a =1221x x x x +{}0B =000,000B B +=∈⨯=∈{}0B ={}1,0,1C =-()112,112,C C -+-=-∉+=∉{}1,0,1C =-p {}{}122,,3,A xx k k A x x k k ==∈==∈Z Z ∣∣12,A A 12A A ⋃q ()12,a b A A ∈⋂1,a b A ∈1A 11,a b A ab A +∈∈22,a b A ab A +∈∈()()1212,a b A A ab A A +∈⋂∈⋂12A A ⋂2a A a A ∈⇒∈2R ()a A a A -∈⇒-∈R ðða A -∈0a a A -+=∈2R R b A b A ∈⇒∈ððR b A -∈ð2()b A b A -∈⇒-∈R 0b b A -+=∈ð。
山东省滕州市第一中学2024-2025学年高一上学期10月月考数学试卷

山东省滕州市第一中学2024-2025学年高一上学期10月月考数学试卷一、单选题1.设集合{}0123,,,A =,{},,101,23,B =-,则R ()A B =I ð( ) A .∅B . {}1,2C .{}1-D .{}1,2,32.设集合{}260M x x x =+-=,{}N 16N x x =∈<<,则M N =I ( )A .{}12x x <<B .{}3C .{}36x x -<<D .{}23.“1a a<”是“1a <-”的( ) A .充分不必要条件 B .必要不充分条件 C .充要条件D .既不充分也不必要条件4.若正数x ,y 满足44x y +=,则11x y+的最小值为( )A .2B .94C .3D .835.下列四组函数中,不是同一个函数的一组是( )A .()f x x =与()g x =B .()21f x x =+与()21g t t =+C .()xf x x =与()1,01,0x g x x >⎧=⎨-<⎩D .()2f x =与()g x =6.已知函数()f x 的定义域为[)0,+∞,则函数()25f x y x -=-的定义域为( )A .()()2,55,-+∞UB .[)()2,55,-+∞UC .()()2,55,⋃+∞D .[)()2,55,+∞U7.下列命题中真命题的个数是( )①函数()1f x =和()0g x x =是同一个函数;②“()2210a b +-=”是“()10a b -=”的必要条件;③集合{|A y y ==,{|B x y ==表示同一集合.A .0B .1C .2D .38.若a b >,且2ab =,则22(1)(1)a b a b-++-的最小值为( )A .2B .4C .4D .2二、多选题9.下列四个结论中正确的是( ) A .22,,4250x y x y x y ∃∈+-++=RB .命题“2,3210x x x ∀∈--<R ”的否定是“2000,3210x x x ∃∈-->R ” C .21,4x x x ∀∈+>R D .“a b >”是“1a b >+”的必要不充分条件10.已知非零实数,a b >,下列结论中错误的结论有( )A .11a b< B .22a b > C .22ab a b > D .2211ab a b> 11.已知关于x 一元二次不等式220ax ax b -+>的解集为{}A x m x n =<<(其中m n <),关于x 一元二次不等式222ax ax b -+>-的解集为{}B x p x q =<<,则( )A .AB B =I B .()A B B ⋃⊆C .m n p q +=+D .当2b <-时,2q p q+的最小值为3三、填空题12.已知集合{}221,,0A a a =-,{}1,5,9B a a =--,若满足{}9A B ⋂=,则实数a 的值为.13.已知关于x 的不等式210mx mx -+≤,若此不等式的解集为∅,则实数m 的取值范围是 14.已知关于x 的不等式组()224502525x x x x x k ⎧-++<⎪⎨+<-+⎪⎩的解集中存在整数解且只有一个整数解,则k 的取值范围为.四、解答题15.设集合{}{}|121,|25A x a x a B x x =+<<-=-<<. (1)若3a =,求()R A B ⋃ð;(2)是否存在实数a ,使得A B A =U ,若存在,求实数a 的取值范围,否则说明理由. 16.设m ∈R ,已知集合3211x A xx +⎧⎫=<⎨⎬-⎩⎭,(){}2220B x x m x m =+--<. (1)当1m =时,求A B U ;(2)若“x B ∈”是“x A ∈”的必要不充分条件,求m 的取值范围.17.中国建设新的芯片工厂的速度处于世界前列,这是朝着提高半导体自给率目标迈出的重要一步.根据国际半导体产业协会(SEMI)的数据,在截至2024年的4年里,中国计划建设31家大型半导体工厂.某公司打算在2023年度建设某型芯片的生产线,建设该生产线的成本为300万元,若该型芯片生产线在2024年产出x 万枚芯片,还需要投入物料及人工等成本()V x (单位:万元),已知当05x <≤时,()125V x =;当520x <≤时,()240100V x x x =+-;当20x >时,()160081600V x x x=+-,已知生产的该型芯片都能以每枚80元的价格售出. (1)已知2024年该型芯片生产线的利润为()P x (单位:万元),试求出()P x 的函数解析式. (2)请你为该型芯片的生产线的产量做一个计划,使得2024年该型芯片的生产线所获利润最大,并预测最大利润.18.已知函数()f x 对任意x 满足:()()324f x f x x --=,二次函数()g x 满足:()()24g x g x x +-=且()14g =-.(1)求()f x ,()g x 的解析式;(2)若R a ∈,解关于x 的不等式()()()()2143a x a x g x f x +-+->-.19.对于函数()f x ,若()f x x =,则称实数x 为()f x 的“不动点”,若()()f f x x =,则称实数x 为()f x 的“稳定点”,函数()f x 的“不动点”和“稳定点”组成的集合分别记为A 和B ,即(){}A x f x x ==,()(){}B x f f x x ==.(1)对于函数()21f x x =-,分别求出集合A 和B ; (2)对于所有的函数()f x ,证明:A B ⊆;(3)设()2f x x ax b =++,若{}1,3A =-,求集合B .。
高一英语月考试卷人教版

高一英语月考试卷人教版一、听力部分(共20分)A. 对话理解(每题1分,共5分)1. 听下面一段对话,回答后面的问题。
- 问题1:What is the man going to do?- 问题2:Why does the woman suggest going to the library?2. 听下面一段对话,回答后面的问题。
- 问题1:What are the speakers mainly talking about?- 问题2:What is the man's opinion about the topic?B. 短文理解(每题2分,共15分)1. 听下面一段短文,回答后面的问题。
- 问题1:What is the main idea of the passage?- 问题2:What does the speaker think about the importanceof reading?2. 听下面一段短文,回答后面的问题。
- 问题1:What is the speaker's purpose of the speech?- 问题2:What advice does the speaker give to the students?二、词汇和语法部分(共30分)A. 词汇填空(每题1分,共10分)根据句子意思,用括号中所给词的适当形式填空。
1. The _______ (science) of studying the stars is called astronomy.2. She is _______ (extreme) talented and has won many awards.B. 语法填空(每题1分,共10分)根据句子结构,填入适当的词或词组。
1. I don’t think it is necessary to argue about the matter _______.2. _______ the help of the teacher, he passed the exam.C. 完形填空(每题1分,共10分)阅读下面短文,从括号中选择适当的选项填入空白处。
高一全科月考试卷

高一全科月考试卷一、语文(共60分)(一)文言文阅读(共15分)阅读下面文言文,完成1-3题。
(文言文选段略)1. 解释下列句子中加点词的含义。
(5分)(例句略)2. 将下列句子翻译成现代汉语。
(5分)(例句略)3. 简述本文作者的主要观点及其论证方法。
(5分)(二)现代文阅读(共20分)阅读下面现代文,完成4-6题。
(现代文选段略)4. 概括文章的主旨大意。
(5分)5. 分析文章中某一人物形象的特点。
(5分)6. 根据文章内容,谈谈你对某一问题的看法。
(10分)(三)作文(共25分)根据以下材料,自选角度,自拟题目,写一篇不少于800字的文章。
(材料略)二、数学(共60分)(一)选择题(每题5分,共20分)1. (题目略)2. (题目略)3. (题目略)4. (题目略)(二)填空题(每题4分,共16分)1. (题目略)2. (题目略)3. (题目略)4. (题目略)(三)解答题(每题8分,共24分)1. (题目略)2. (题目略)3. (题目略)三、英语(共60分)(一)阅读理解(共20分)阅读下面四篇短文,完成1-10题。
(短文略)1. 根据短文内容,选择正确答案。
(每题2分,共20分)(二)完形填空(共20分)阅读下面短文,从所给选项中选出最佳选项填空。
(短文及选项略)(三)书面表达(共20分)根据题目要求,写一篇不少于120词的短文。
(题目要求略)四、物理(共40分)(一)选择题(每题4分,共16分)1. (题目略)2. (题目略)3. (题目略)4. (题目略)(二)实验题(共12分)根据实验目的和要求,设计实验方案并完成实验报告。
(实验题目及要求略)(三)计算题(共12分)1. (题目略)2. (题目略)五、化学(共40分)(一)选择题(每题4分,共16分)1. (题目略)2. (题目略)3. (题目略)4. (题目略)(二)填空题(共12分)1. (题目略)2. (题目略)(三)计算题(共12分)1. (题目略)2. (题目略)六、生物(共40分)(一)选择题(每题4分,共16分)1. (题目略)2. (题目略)3. (题目略)4. (题目略)(二)简答题(共12分)1. (题目略)2. (题目略)(三)实验题(共12分)根据实验目的和要求,设计实验方案并完成实验报告。
2023-2024学年高一上学期月考语文试卷含参考答案
2023—2024学年高一上学期月考语文试卷含参考答案一、现代文阅读(总29分)(一)现代文阅读(13分)阅读下面的文字,完成下面小题。
材料一国家的希望在青年,民族的未来在青年。
作为整个社会力量中最积极、最有生气的力量,新时代中国青年要牢记党的教诲,立志民族复兴,勇做走在时代前列的奋进者、开拓者、奉献者,在实现中国梦的生动实践中放飞青春梦想,在矢志奋斗中谱写新时代的青春之歌,创造出让世界刮目相看的新奇迹。
国家深刻指出:“青年工作,抓住的是当下,传承的是根脉,面向的是未来,攸关党和国家前途命运。
”共青团是党的青年工作的重要力量,肩负引领凝聚青年、组织动员青年、联系服务青年的职责,必须坚持“党旗所指就是团旗所向”,坚持把培养社会主义建设者和接班人作为根本任务,把巩固和扩大党执政的青年群众基础作为政治责任,把围绕中心、服务大局作为工作主线,不断创新工作思路,增强对青年的凝聚力、组织力、号召力。
新时代是追梦者的时代,也是广大青年成就梦想的时代。
与新时代同向同行、共同前进,当代中国青年生逢盛世,肩负重任;身处中华民族发展的最好时期,把理想追求融入党和国家事业,方能不负韶华、不负时代、不负人民。
广大青年要树立对马克思主义的信仰、对中国特色社会主义的信念、对中华民族伟大复兴中国梦的信心,不断增强做中国人的志气、骨气、底气,树立为祖国为人民永久奋斗、赤诚奉献的坚定理想;要自觉树立和践行社会主义核心价值观,矢志追求更有高度、更有境界、更有品位的人生;要敢为人先、敢于突破,以聪明才智贡献国家,以开拓进取服务社会;要擦亮奋斗这个青春最亮丽的底色,在青春的赛道上奋力奔跑,在真刀真枪的实干中成就一番事业,让青春在为祖国、为民族、为人民、为人类的不懈奋斗中绽放绚丽之花。
材料二青春因磨砺而精彩,人生因奋斗而升华。
青年是国家的希望、民族的未来。
一百年来,从石库门到天安门,从兴业路到复兴路,为人民谋幸福,为民族谋复兴这一初心和使命,一代代中国青年前赴后继、英勇奋斗,以血肉之躯、忘我情怀谱写了一曲曲感天动地、荡气回肠的英雄壮歌,用青春浇灌热血,用行动诠释理想信念的力量。
月考试卷高一试题及答案
月考试卷高一试题及答案一、选择题(每题3分,共30分)1. 下列关于细胞结构的描述,错误的是:A. 细胞壁是植物细胞特有的结构B. 细胞核是细胞遗传和代谢的控制中心C. 线粒体是细胞内的能量转换器D. 细胞膜具有选择性通透性答案:A2. 光合作用中,光能被转化为化学能的场所是:A. 叶绿体B. 细胞质C. 细胞核D. 细胞壁答案:A3. 以下哪种物质不是细胞内的主要能源物质?A. 葡萄糖B. 脂肪C. 蛋白质D. 核酸答案:D4. 人体细胞中,负责合成蛋白质的结构是:A. 核糖体B. 内质网C. 高尔基体D. 线粒体答案:A5. 细胞分裂过程中,染色体的变化顺序是:A. 复制→排列→分离→恢复B. 排列→复制→分离→恢复C. 排列→分离→复制→恢复D. 分离→复制→排列→恢复答案:A6. 细胞分化的实质是:A. 细胞体积的增大B. 细胞数量的增加C. 基因的选择性表达D. 细胞形态的改变答案:C7. 细胞凋亡与细胞坏死的区别在于:A. 细胞凋亡是程序性死亡,细胞坏死是意外死亡B. 细胞凋亡是意外死亡,细胞坏死是程序性死亡C. 细胞凋亡和细胞坏死都是程序性死亡D. 细胞凋亡和细胞坏死都是意外死亡答案:A8. 细胞周期中,DNA复制发生在:A. G1期B. S期C. G2期D. M期答案:B9. 细胞膜上的受体蛋白主要功能是:A. 物质转运B. 信号传导C. 细胞识别D. 细胞间连接答案:B10. 细胞内遗传物质的主要载体是:A. 染色体B. 线粒体C. 核糖体D. 高尔基体答案:A二、填空题(每空2分,共20分)1. 细胞膜的主要成分是______和______。
答案:磷脂;蛋白质2. 细胞内负责储存遗传信息的物质是______。
答案:DNA3. 细胞质的流动可以加速______的扩散。
答案:营养物质4. 细胞分裂过程中,染色体数目加倍发生在______期。
答案:M5. 细胞分化的结果是形成了______。
安徽省蚌埠市A层高中2024-2025学年高一上学期第一次月考数学试卷
安徽省蚌埠市A 层高中2024-2025学年高一上学期第一次月考数学试卷一、单选题1.已知集合{}|12A x x =-<≤,{}|13B x x =<<,则A B =U ( ) A .{}0,1,2 B .{}11x x -<<C .{}|13x x -<<D .{|11x x -<<或}13x <<2.数集(){}21,A x x n n Z π==+∈,(){}41,B x x k k Z π==±∈,则A ,B 之间的关系是( )A .AB B .B AC .A B =D .A B ≠3.已知函数()f x 的定义域是[1,3]-,则函数()g x= ) A .[]3,5-B .[)(]3,00,5-UC .(]0,2D .[]0,24. “22530x x --<”的一个必要不充分条件是( ) A .132x -<<B .16x -<<C .132x -<<D .102x -<<5.已知实数x ,y 满足41x y -≤-≤-,145x y -≤-≤,则3x y +的最大值为( ) A .8B .9C .16D .186.下列命题中,正确的是( )A .4xx+的最小值是4B 的最小值是2C .如果a b >,c d >,那么a c b d -<-D .如果22ac bc >,那么a b >7.已知函数()24f x x x =-+,[],4x m ∈的值域是[]0,4,则实数m 的取值范围是( )A .(),2-∞B .(]0,2C .[]0,2D .[]2,48.《九章算术》中有“勾股容方”问题:“今有勾五步,股十二步.问:勾中容方几何?”魏晋时期数学家刘徽在《九章算术注》中利用出入相补原理给出了这个问题的一般解法:如图1,用对角线将长和宽分别为b 和a 的矩形分成两个直角三角形,每个直角三角形再分成一个内接正方形(黄)和两个小直角三角形(朱、青)将三种颜色的图形进行重组,得到如图2所示的矩形,该矩形长为a b +,宽为内接正方形的边长d .由刘徽构造的图形可以得到许多重要的结论,如图3,设D 为斜边BC 的中点,作直角三角形ABC 的内接正方形对角线AE ,过点A 作AF BC ⊥于点F ,则下列推理正确的是( )A .由图1和图2面积相等得2ab d a b=+B .由AE AF ≥C .由AD AE ≥211a b≥+ D .由AD AF ≥可得22a b a b +≥+二、多选题9.下列说法中正确的有( )A .命题2000:,220p x x x ∃∈++<R ,则命题p 的否定是2,220∀∈++≥R x x x B .“x y >”是“x y >”的必要条件 C .命题“2,0x x ∀∈>Z ”的是真命题D .“0m <”是“关于x 的方程220x x m -+=有一正一负根”的充要条件 10.已知函数()22,1,12x x f x x x +≤-⎧=⎨-<<⎩,则 ( )A .()02f =B .()f x 的值域为(),4-∞C .()1f x <的解集为()(),11,1-∞--UD .若()3f x =,则x = 1三、单选题11.已知()f x 是定义在R 上的偶函数,()g x 是定义在R 上的奇函数,且()f x ,()g x 在(],0-∞单调递减,则( )A .()()()()12f f f f <B .()()()()12f g f g <C .()()()()12g f g f <D .()()()()12g g g g >四、填空题12.已知函数()2145f x x -=+,若()13f a =,则a =. 13.若命题:“任意实数x 使得不等式()21204ax a x +-+>成立”为假命题,则实数a 的范围是.14.已知定义在R 上的单调函数()f x 满足对任意的12,x x ,都有()()()1212f x x f x f x +=+成立,若正实数,a b 满足()()210f a f b +-=,则12a b+的最小值是五、解答题15.已知全集U R =,集合{|121}P x a x a =+≤≤+,{|25}Q x x =-≤≤.(1)若3a =,求()U P Q⋂;ð (2)若“x P ∈”是“x ∈Q ”充分不必要条件,求实数 a 的取值范围. 16.函数()f x 为定义在R 上的奇函数,已知当0x ≥时,()1=+x f x x . (1)当0x <时,求()f x 的解析式 ;(2)判断()f x 在[)0,∞+上的单调性,并利用单调性的定义证明;(3)若()()22120f a f a ++->,求a 的取值范围.17.设()212y mx m x m =+-+-.(1)若不等式2y ≥-对一切实数x 恒成立,求实数m 的取值范围;(2)解关于x 的不等式()()2121R +-+-<-∈mx m x m m m .18.某单位有员工1000名,平均每人每年创造利润10万元,为了增加企业竞争力,决定优化产业结构,调整出()*N x x ∈名员工从事第三产业,调整出的员工平均每人每年创造利润为310500x a ⎛⎫- ⎪⎝⎭万元()0a >,剩余员工平均每人每年创造的利润可以提高0.2%x .(1)若要保证剩余员工创造的年总利润不低于原来1000名员工创造的年总利润,则最多调整出多少名员工从事第三产业?(2)在(1)的条件下,若调整出的员工创造的年总利润始终不高于剩余员工创造的年总利润,则a 的取值范围是多少?19.对于四个正数m n p q 、、、,若满足mq np <,则称有序数对(,)m n 是(,)p q 的"下位序列".(1)对于2、3、7、11,有序数对(3,11)是(2,7)的"下位序列"吗?请简单说明理由;(2)设a b c d 、、、均为正数,且(,)a b 是(,)c d 的“下位序列”,试判断a c a c b d b d ++、、之间的大小关系;(3)设正整数n 满足条件:对集合{02021,}mm m <<∈N ∣内的每个m ,总存在正整数k ,使得(,2021)m 是(,)k n 的“下位序列”,且(,)k n 是(1,2022)m +的“下位序列”,求正整数n 的最小值.。
珠海市2024-2025学年第一学期高一年级第一次月考试卷
2024-2025学年第一学期高一年级第一次月考(数学)(考试时间:120分钟 试卷满分:150分)出题人: 审题人:第I 卷(选择题)一、单选题:本题共8小题,每小题5分,共40分。
在每小题给出的选项中,只有一项是符合题目要求的。
1.设全集U ={1,2,3,4,5,6,7},集合A ={1,2,4,5},B ={2,3,6},则韦恩图中阴影部分表示的集合为 ( )A. {2,5}B. {2,6}C. {3,6}D. {2,3,6}2 下列命题中,存在量词命题的个数是 ( )①实数的绝对值是非负数;②正方形的四条边相等;③存在整数n ,使n 能被11整除.A .1B .2C .3D .03.已知集合A ={1,2,3,5,7,11},B ={x |3<x <15},则A ∩B 中元素的个数为 ( )A. 2B. 3C. 4D. 54. 设是实数,则“”是“”的 ( )A .充分不必要条件B .必要不充分条件C .充分必要条件D .既不充分也不必要条件5.已知集合A ={(x ,y )|x , y ∈N ∗,y ≥x },B ={(x ,y )|x +y =8},则A ∩B 中元素的个数为 ( )A. 2B. 3C. 4D.6,a b a b >22a b >6.已知a<b,则b―a+1b―a+b―a的最小值为( )A. 3B. 2C. 4D. 17.已知集合M={s|s=2n+1,n∈Z},N={t|t=4n―1,n∈Z},则M∩N= ( )A. ⌀B. MC. ND. Z8.已知a>0,b>0,4a+b=2,则1a +1b的最小值是 ( )A. 4B. 92C. 5D. 9二、多选题:本题共3小题,共18分。
在每小题给出的选项中,有多项符合题目要求。
9. 下列各组中M,P表示不同集合的是 ( ) A.M={3,-1},P={(3,-1)}B.M={(3,1)},P={(1,3)}C.M={y|y=x2+1,x∈R},P={x|x=t2+1,t∈R}D.M={y|y=x2-1,x∈R},P={(x,y)|y=x2-1,x∈R}10.下列命题中,正确的是 ( )A. “a<b<0”是“1a >1b”的充分不必要条件B. “―2≤λ≤3”是“―1≤λ≤3”的必要不充分条件C. “x2≠y2”是“x≠y”的充要条件D. “x∈(A∪B)∩C”是“x∈(A∩B)∪C”的必要不充分条件11.设a>0,b>0,且a+2b=2,则 ( )A. ab的最大值为12B. a+b的最小值为1C. a2+b2的最小值为45D. a―b+2ab的最小值为92第II卷(非选择题)三、填空题:本题共3小题,每小题5分,共15分。
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高一英语月考试卷I. 单项选择1.The Great Wall goes its way from west to east, _____ deserts,then ___ forests, and at last reaches the sea.A.over, acrossB. across, throughC. through, pastD. past, over2. Professor Smith is famous ____ the field of biology, but he is ____ known ____ a writer.A. in, better, asB. in, much, forC. for, more, asD. for, well, for3. Paris is the capital and largest city of France, ____ on the river Seine.A. situatingB. is situatedC. being situatingD. situated4. A poet and artist ____ coming to speak to us about Chinese literature and painting tomorrow afternoon.A. wereB. areC. wasD. is5. He left home in 1990 and has been out _____.A. ever sinceB. ever beforeC. for everD. since ever6. Great changes ____ in the city, and a lot of factories ____.A. have taken place, have been set upB. have been taken place, have been set upC. have taken place, have set upD. were taken place, were set up7. ____ of the land in that district ___ covered with trees and grass.A. Two fifth, isB. Two fifth, areC. Two fifths, areD. Two fifths, is8. Since then the number of people taking driving lessons _____ 20%.A. has increased byB. increase byC. has increased toD. having increased by9. This dress is ____ that.A. as three times expensive asB. as expensive three times asC. expensive as three times asD. three times as expensive as10. The number of people that moved out of poverty in my hometown has grown from 1,000 to 1,200. This means it has increased _____ 20 percent.A. withB. atC. toD. by11. --- I don’t like chicken ____ fish.--- I don’t like chicken, ____ I like fish very much.A. and, andB. or, butC. and, butD. or, and12. --- Would you like to come to dinner tonight?--- I’d like to, ____ I’m too busy.A. butB. soC. asD. and13. The forest guards often find camp fires that have not been ____completely.A. turned downB. picked upC. put awayD. put out14. Kathy ____ a lot of Spanish by playing with the native boys and girls.A. picked upB. took upC. made up C. turned up15. The house _____ last night when a lightning hit it.A. set fire toB. set on fireC. caught fireD. was caught fire16. Please ____ the address before you forget it.A. put upB. put outC. put onD. put down17. When he arrived at his hometown, he found great changes ___ I the city, and a lot of factories____.A. had been taken place, had been set upB. had taken place, had been set upC. had taken place, had set upD. were taken place, had set up18. The fish can eat a person in two minutes, ____ only bones.A. leaveB. leftC. to be leftD. leaving19. More than one _____ seen the film.A. student haveB. student hasC. students haveD. students has20.The storm hit the land, only sand ____.A. leaveB. leftC. to be leftD. leaving完形填空There are about fifteen hundred languages in the world. But __21_ a few of them are very __22_. English is one of these. Many, many people use it, not only in England and the USA, __23__ in other parts of the world. About 200,000,000 __24__ it as their own language. It is difficult to say how many people are learning it as a __25__ language. Many millions are __26__ to do so. Is it easy __27__ difficult to learn English? Different people may have different __28__. Have you ever ___29__ ads of this kind in the newspapers or magazines? “Learn English in six weeks, or your __30__ back…”“Easy and funny! Our records and tapes __31__ you master your English in a month。
From the first day your __32__ will be excellent. Just send…” Of course, it never happened quite like this.The only language that seems easy to learn is the mother tongue. We should __33__ that we all learned our own language well when we were children. If we could learn English in the same way, it would not seem so difficult. __34___what a small child does. He listens to what people say. He tries __35__ he hears. When he is using the language, talking __36_ it, thinking in it all the time. Just imagine how much __37_ that gets.So it is hard to say that learning English is easy, because a good command of English ___38__ upon a lot of practice. And practice needs great effort and ___39__ much time. Good teachers, records, tapes, books, and dictionaries will __40__. But they cannot do the student’s work for him.21. A. not B. quite C. only D. very22. A. difficult B. important C. necessary D. easy23. A. but B. and C. or D. so24. A. speaks B. speaking C. spoken D. spoke25. A. native B. foreign C. useful D. mother26. A. learning B. enjoying C. trying D. liking27. A. or B. but C. and D. so28. A. questions B. problems C. ideas D. answers29. A. found B. watched C. noticed D. known30. A. knowledge B. time C. money D. English31. A. make B. help C. let D. allow32. A. spelling B. grammar C. English D. pronunciation33. A. know B. remember C. understand D. think34. A. Imagine B. Mind C. Do D. Think of35. A. what B. when C. that D. which36. A. in B. up C. to D. out37. A. time B. money C. language D. practice38. A. depends B. tries C. has D. takes39. A. uses B. takes C. gets D. costs40. A. do B. work C. help D. masterIII. 阅读理解AA Frenchman had arrived a small Italian town and was staying with his wife at the best hotel there. One night he went out for a walk alone. Suddenly he heard footsteps behind him. He turned his head and saw an Italian young man who quickly walked past him. The man was nearly out of sight when the Frenchman suddenly found his watch was gone. He decided to follow him and force him to return the watch.Soon the Frenchman caught up with the Italian. Neither of them understood the other’s language. The Frenchman threatened the Italian with his hand and pointed to his own watch, In the end, the Italian gave his watch to him.When he came to the hotel, the Frenchman told his wife what had happened. He was greatly surprised when his wife pointed to the watch onthe table. Now he realized what a mistake he had made.41. The Frenchman went to Italy ____.A. aloneB. with his wifeC. with an ItalianD. with his friend42. When the Frenchman found his watch gone, _____.A. the Italian had run far away.B. he could still see the Italian.C. the Italian quickly walked past him.D. he had reached home.43. The Italian gave his watch to the Frenchman because ____.A. he knew it was not his ownB. he was helpfulC. he was frightenedD. he was kind-hearted44. How was the Frenchman feeling when he saw the watch on the table? _____.A. HappyB. SatisfiedC. AngryD. Surprised45. Who had made a big mistake?A. The FrenchmanB. The ItalianC. Both of themD. Neither of themBIn 1826, a Frenchman named Niepce needed pictures for his business. But he was not a good artist. So he invented a very simple camera. He put it in a window of his house and took a picture of his garden. That was the first photo.The next important date in the history of photography was in 1837. That year, Daguere, another Frenchman, took a picture of his reading room. He used a new kind of camera in a different way. In his picture you could see everything very clearly, even the smallest thing. This kind of photo was called a Daguerreotype.Soon, other people began to use Daguerre’s way. Travellers brought back wonderful photos from all around the world. People took pictures of famous buildings, cities and mountains.In about 840, photography was developed. Then photographers could take pictures of people and moving things. That was not simple. The photographers had to carry a lot of films and other machines. But this did not stop them, for example, some in the United States worked so hard. Mathew Brady was a famous American photographers. He took many pictures of great people. The pictures were unusual because they were very lifelike(栩栩如生的) .Photographers also became one kind of art by the end of the 19th century. Some photos were not just copies of the real world. They showed feelings, like other kinds of art.46. The first photo taken by Niepce was a picture of _____.A. his businessB. his houseC. his gardenD. his window47. The Daguerrotype was _____.A. a FrenchmanB. a kind of pictureC. a kind of cameraD. a photographer48. If a photographer wanted to take pictures of moving things in the year of 1840, he had to _____.A. watch lots of filmsB. buy an expensive cameraC. stop in most citiesD. take many films and something else with him49. Mathew Brady ____.A. was very lifelikeB. was famous for his unusual picturesC. was quite strongD. took many pictures of moving people50. This passage tells us _____.A. how photography was developedB. how to show your ideas and feelings in picturesC. how to take pictures in the worldD. how to use different camerasCAmericans with small families own a small car or a large one. If both parents are working, they usually have two cars. When the family is large,one of the cars is sold and they will buy a van(住房汽车)。