Reaction Kinetics and Stoichiometry

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应用电化学

应用电化学

主要研究内容:
• 反应速率~电势间的依赖关系(The Reaction rate ~ Potential dependence and the nature behind)
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电化学基本定律 (the Faraday law)
O+ neR
2
Q N nF
dQ(Coulombs cm2 ) / Current density: j ( Amperes/cm ) dt( Seconds )
Electrochemical reaction
e-
Fe2O3 + 6e 2Fe + 3O2-
C + 2O2 CO2 + 4e-
Fe2O3 + C + G (W) Fe + CO2
Work → Chemical energy
电化学反应的特征
• 整个氧化还原反应由发生在电极/电解质界面(Electrodes /electrolyte interfaces)上的两个独立的半反应(half-reactions) 组成.
• 研究化学能与电能之间相互转换的原理与技术(The laws and the technologies concerning the conversion between chemical energy and electrical energy) • 研究化学现象与电现象的相关性(Interrelation between chemical phenomena (chemical reactions, chemical changes, etc.) and electric phenomena (charge, current, potential, electric field, etc.)) • 研究发生在电极与电解质界面的现象、过程和反应(The phenomena, processes and reactions occurring at interface between an electronic conductor (electrode) and an ionic conductor (electrolyte) )

section知识点总结

section知识点总结

section知识点总结In this section, we have covered a wide range of knowledge points related to various topics. These knowledge points include but are not limited to:1. Mathematics1.1. Algebra: The branch of mathematics that deals with symbols and the rules for manipulating those symbols. It includes topics such as linear equations, quadratic equations, inequalities, and functions.1.2. Geometry: The study of shapes, sizes, and patterns. It includes topics such as points, lines, angles, triangles, quadrilaterals, circles, and polygons.1.3. Calculus: The study of change. It includes topics such as limits, derivatives, integrals, and differential equations.1.4. Statistics: The study of data. It includes topics such as probability, sampling, hypothesis testing, and data analysis.2. Physics2.1. Mechanics: The study of motion and forces. It includes topics such as kinematics, dynamics, and energy.2.2. Thermodynamics: The study of heat and energy transfer. It includes topics such as temperature, heat transfer, and thermal equilibrium.2.3. Electromagnetism: The study of electric and magnetic fields. It includes topics such as electric charge, electric current, electromagnetic waves, and electromagnetic induction.2.4. Quantum physics: The study of atomic and subatomic particles. It includes topics such as wave-particle duality, quantum entanglement, and superposition.3. Chemistry3.1. Atomic structure: The study of the structure of atoms. It includes topics such as atomic models, electron configuration, and periodic trends.3.2. Chemical bonding: The study of how atoms are held together in compounds. It includes topics such as ionic bonding, covalent bonding, and metallic bonding.3.3. Chemical reactions: The study of how substances change into new substances. It includes topics such as stoichiometry, reaction kinetics, and equilibrium.3.4. Organic chemistry: The study of carbon-containing compounds. It includes topics such as hydrocarbons, functional groups, and organic reactions.4. Biology4.1. Cell biology: The study of cells. It includes topics such as cell structure, cell function, and cell division.4.2. Genetics: The study of heredity and variation. It includes topics such as DNA, genes, mutations, and genetic inheritance.4.3. Evolution: The study of how species change over time. It includes topics such as natural selection, speciation, and phylogenetics.4.4. Ecology: The study of the interactions between organisms and their environment. It includes topics such as ecosystems, food webs, and biodiversity.5. Computer Science5.1. Programming: The process of designing and building computer programs. It includes topics such as algorithms, data structures, and programming languages.5.2. Databases: The study of storing and organizing data. It includes topics such as relational databases, SQL, and database management systems.5.3. Artificial intelligence: The study of creating intelligent machines. It includes topics such as machine learning, neural networks, and natural language processing.5.4. Networks: The study of connecting computers and devices. It includes topics such as protocols, network topologies, and network security.6. History6.1. Ancient history: The study of human societies in ancient times. It includes topics such as Mesopotamia, Egypt, Greece, and Rome.6.2. Medieval history: The study of the Middle Ages. It includes topics such as feudalism, the Crusades, and the Black Death.6.3. Modern history: The study of the modern era. It includes topics such as the Renaissance, the Age of Exploration, and the World Wars.6.4. World history: The study of global events and interactions. It includes topics such as colonization, decolonization, and globalization.7. Literature7.1. Poetry: The study of poetry. It includes topics such as rhyme, meter, and figurative language.7.2. Prose: The study of writing that is not poetry. It includes topics such as novels, short stories, and essays.7.3. Drama: The study of plays and theatrical performances. It includes topics such as plot, character, and dialogue.7.4. Literary criticism: The study of analyzing and evaluating literary works. It includes topics such as formalism, structuralism, and feminism.8. Art8.1. Visual arts: The study of creating visual images. It includes topics such as painting, sculpture, and photography.8.2. Performing arts: The study of live performances. It includes topics such as dance, theater, and music.8.3. Art history: The study of the development of art throughout history. It includes topics such as ancient art, Renaissance art, and modern art.8.4. Art criticism: The study of analyzing and evaluating works of art. It includes topics such as formal analysis, iconography, and semiotics.9. Philosophy9.1. Metaphysics: The study of the nature of reality. It includes topics such as existence, time, and free will.9.2. Epistemology: The study of knowledge. It includes topics such as belief, justification, and truth.9.3. Ethics: The study of moral principles. It includes topics such as morality, justice, and virtue.9.4. Aesthetics: The study of beauty and artistic expression. It includes topics such as art, taste, and aesthetic judgment.10. Geography10.1. Physical geography: The study of Earth's natural features. It includes topics such as landforms, climate, and ecosystems.10.2. Human geography: The study of human activities and societies. It includes topics such as population, urbanization, and cultural geography.10.3. Cartography: The study of map-making. It includes topics such as map projections, scales, and geographic information systems.10.4. Geopolitics: The study of political relationships and global conflicts. It includes topics such as international relations, geopolitics, and global governance.In conclusion, this section has provided a comprehensive overview of various knowledge points in different fields. By studying and understanding these knowledge points, one can gain a deeper insight into the world and its complexities. These knowledge points are crucial in our quest for knowledge and understanding of the world around us.。

化学实验英语作文

化学实验英语作文

化学实验英语作文Title: A Chemistry Experiment: Synthesis of Aspirin。

Chemistry experiments are not only fascinating but also crucial for understanding the principles of chemical reactions and their applications in real-life scenarios. In this essay, we delve into the synthesis of aspirin, a commonly used medication, detailing the procedure, observations, and significance of the experiment.The synthesis of aspirin involves the reaction between salicylic acid and acetic anhydride in the presence of a catalyst, typically sulfuric acid. The reaction yields aspirin (acetylsalicylic acid) and acetic acid as byproducts. The process can be summarized by the following chemical equation:\[C_7H_6O_3 + (CH_3CO)_2O \rightarrow C_9H_8O_4 +CH_3COOH\]This reaction is a classic example of esterification, wherein an alcohol (the -OH group in salicylic acid) reacts with a carboxylic acid derivative (acetic anhydride) toform an ester (aspirin) and a carboxylic acid (acetic acid).The experimental procedure begins with measuring the required amounts of salicylic acid and acetic anhydride. These are then mixed in a flask along with a few drops of concentrated sulfuric acid, which acts as a catalyst. The mixture is gently heated under reflux, allowing thereaction to proceed efficiently. Refluxing prevents theloss of volatile reactants and ensures a higher yield ofthe desired product.During the reaction, one can observe changes in the appearance of the mixture. Initially, the mixture may be a white powder or small crystals of salicylic acid. As the reaction progresses, the mixture becomes more homogeneous, and the formation of aspirin can be visually confirmed bythe appearance of white crystals. The reaction is typically complete within a couple of hours.After the completion of the reaction, the mixture is cooled, and the aspirin crystals are collected via filtration. The crude product obtained may still contain impurities, such as unreacted starting materials or side products. Purification techniques, such as recrystallization, can be employed to obtain pure aspirin crystals.The purified aspirin crystals are then dried and weighed to determine the yield of the reaction. Theoretical yield calculations can be performed based on the stoichiometry of the reaction, allowing for the comparison of actual versus expected yields. Factors affecting yield, such as the purity of reagents, reaction conditions, and the efficiency of purification techniques, can be analyzed and discussed.The significance of this experiment extends beyond the synthesis of a common pharmaceutical compound. It provides insights into fundamental chemical principles, such as stoichiometry, kinetics, and the role of catalysts in chemical reactions. Moreover, it highlights the importanceof practical skills, such as accurate measurement, observation, and data analysis, in experimental chemistry.Furthermore, the synthesis of aspirin illustrates the application of chemistry in everyday life. Aspirin, withits analgesic, anti-inflammatory, and antipyretic properties, is one of the most widely used medications worldwide. Understanding its synthesis not only enhances our knowledge of chemistry but also underscores the importance of pharmaceutical chemistry in healthcare.In conclusion, the synthesis of aspirin is a classic chemistry experiment that offers valuable insights into chemical reactions, purification techniques, and the application of chemistry in the synthesis of pharmaceutical compounds. Through hands-on experience and analysis, students can deepen their understanding of chemistry while appreciating the relevance of chemical principles in society.。

大学应用化学英语教材

大学应用化学英语教材

大学应用化学英语教材The Importance of Applied Chemistry in Modern SocietyIn today's rapidly advancing world, the field of applied chemistry plays a vital role in various industries and everyday life. As technology continues to evolve, the demand for professionals equipped with a solid foundation in applied chemistry grows. For this reason, the development of an effective and comprehensive English textbook tailored specifically for university students studying applied chemistry is necessary. In this article, we will explore the key components and structure that should be included in a top-notch applied chemistry English textbook.1. IntroductionThe textbook should begin with an introduction that highlights the importance of applied chemistry in society. It should emphasize the real-world applications of chemistry, such as drug discovery, materials engineering, environmental protection, and food production. This section should provide students with a clear understanding of the relevance and significance of studying applied chemistry.2. Basic Principles of Applied ChemistryThis section is dedicated to covering the fundamental principles of applied chemistry. It should include topics such as atomic structure, chemical bonding, stoichiometry, and reaction kinetics. The content should be concise and easy to comprehend, with well-organized tables, figures, and diagrams to aid understanding.3. Laboratory TechniquesA vital component of applied chemistry is practical laboratory work. Thus, the textbook should include a section dedicated to laboratory techniques commonly used in the field. This section should cover safety protocols, experimental procedures, data analysis, and proper documentation. It should provide students with the necessary skills to conduct experiments effectively and accurately.4. Organic ChemistryOrganic chemistry is a crucial aspect of applied chemistry, as it deals with the study of carbon-based compounds. This section should cover topics such as functional groups, nomenclature, reaction mechanisms, and synthetic methods. Emphasis should be placed on the application of organic chemistry in pharmaceuticals, polymers, and agricultural chemicals.5. Analytical ChemistryAnalytical chemistry focuses on the identification and quantification of chemical compounds. In this section, students should learn about various analytical techniques such as spectroscopy, chromatography, and electrochemistry. Practical examples and case studies should be included to demonstrate the application of analytical chemistry in environmental analysis, forensic science, and quality control.6. Inorganic ChemistryInorganic chemistry is the study of non-carbon-based compounds. This section should cover topics such as periodic trends, coordination compounds, and transition metals. Students should gain an understanding of theapplications of inorganic chemistry in materials science, catalysis, and energy production.7. Physical ChemistryPhysical chemistry combines the principles of physics and chemistry to study the properties and behavior of matter. This section should cover topics such as thermodynamics, quantum mechanics, and chemical kinetics. Students should learn about the application of physical chemistry in fields like nanotechnology, energy storage, and molecular modeling.8. Environmental ChemistryThe textbook should include a dedicated section on environmental chemistry, as the protection and sustainability of the environment are pressing global concerns. This section should cover topics such as air and water pollution, greenhouse gases, and waste management. Students should gain insights into how chemistry can contribute to environmental conservation and remediation.9. Case Studies and Practical ApplicationsTo enrich students' learning experience, the textbook should incorporate case studies and practical applications throughout the content. These examples should showcase how applied chemistry principles are utilized in real-life scenarios. By analyzing and discussing these case studies, students can better understand the practical implications of their knowledge.10. Review Questions and ExercisesFinally, the textbook should include review questions and exercises at the end of each chapter to reinforce understanding and facilitate self-assessment. These questions should cover a wide range of difficulty levels, allowing students to test their knowledge and apply what they have learned.ConclusionIn conclusion, a high-quality English textbook for university students studying applied chemistry should incorporate an engaging introduction, cover the fundamental principles of chemistry, provide comprehensive laboratory techniques, delve into organic, analytical, inorganic, and physical chemistry, address environmental concerns, include case studies and practical applications, and offer review questions and exercises. By encompassing these components, the textbook can effectively equip students with the knowledge and skills needed to excel in the field of applied chemistry and contribute to the advancement of society.Word Count: 801 words。

现代化学原理

现代化学原理

现代化学原理Chemistry is the scientific discipline that studies the properties, composition, and transformation of matter. It has evolved over centuries and today, modern chemistry is based on several key principles and theories that help us understand the fundamental aspects of the subject. In this document, we will explore some of these principles and their applications in modern chemistry.Atom and MoleculeThe concept of atom and molecule forms the foundation of modern chemistry. Atoms are the basic building blocks of matter, and molecules are formed by the combination of atoms. The study of the properties and behavior of atoms and molecules is crucial in understanding chemical reactions and interactions.Atomic Structure and Periodic TableThe atomic structure includes the nucleus, which contains protons and neutrons, and the surrounding electron cloud. The arrangement of electrons in an atom determines its chemical properties. The periodic table of elements organizes all known elements based on their atomic number and chemical properties. It provides a systematic way to study and understand the behavior of elements and their compounds.Chemical BondingChemical bonding refers to the forces that hold atoms together in a molecule or a compound. There are three main types of chemical bonds: covalent bonding, ionic bonding, and metallic bonding. Covalent bonds involve the sharing of electrons between atoms, while ionic bonds result from the transfer of electrons from one atom to another. Metallic bonding occurs between metal atoms and involves the delocalization of electrons.Stoichiometry and Chemical ReactionsStoichiometry is the study of the quantitative relationships between reactants and products in chemical reactions. It involves balancing chemical equations and calculating the amount of substances involved in a reaction. Understanding stoichiometry is essential for determining the amounts of substances needed in chemical reactions and predicting their outcomes.Chemical EquilibriumChemical equilibrium occurs when the rate of the forward reaction is equal to the rate of the reverse reaction. At equilibrium, the concentrations of reactants and products remain constant. The principles of chemical equilibrium help us understand factors that affect the equilibrium position, such as temperature, pressure, and concentration. This knowledge is crucial in designing chemical processes and reactions.Kinetics and Reaction RatesKinetics is the study of the rates of chemical reactions and the factors that influence them. Reaction rates depend on factors such as temperature, concentration, and catalysts. Understanding reaction kinetics helps chemists optimize reaction conditions and develop efficient processes.ThermodynamicsThermodynamics deals with the energy changes that occur in chemical reactions. It includes concepts such as enthalpy, entropy, and Gibbs free energy. The laws of thermodynamics govern the direction and feasibility of chemical reactions. Knowledge of thermodynamics is crucial in understanding energy changes during reactions and in designing energy-efficient processes.Organic ChemistryOrganic chemistry is the study of carbon-based compounds, which are the building blocks of life. It involves the study of structures, properties, composition, reactions, and synthesis of organic compounds. Organic chemistry plays a crucial role in the development of pharmaceuticals, polymers, dyes, and many other industrial products.Analytical ChemistryAnalytical chemistry focuses on the analysis of chemical substances to determine their composition and properties. It involves a wide range of techniques, such as spectroscopy, chromatography, and electrochemistry. Analytical chemistry isused in various fields, including environmental monitoring, forensic analysis, and quality control in industries.Inorganic ChemistryInorganic chemistry deals with the study of elements other than carbon and their compounds. It includes the study of metals, minerals, and non-metallic compounds. Inorganic chemistry plays a crucial role in materials science, catalysis, and the development of advanced materials.These are just a few of the key principles and topics in modern chemistry. The field of chemistry is vast and continually evolving, with new discoveries and applications being made all the time. Understanding and applying these principles is essential for advancing our knowledge and solving real-world problems in various fields.。

一级反应动力学、二级反应动力学基本原理

一级反应动力学、二级反应动力学基本原理

Single Step (Elementary) Reaction Process 单步(基本)反应过程
• • • • • Unimolecular 单分子反应 CaCO3 Ca2+ + CO32Bimolecular 双分子反应 CO2 + H2O H2CO3 Termolecular 三分子反应 2 FeS2 + 3 O2 + 2 H2O 2 Fe3+ + 4H2SO4 • No four or more molecule processes have been identified because chances of 4 molecules colliding is very, very small (making reaction rate super small) • 没有4或者4以上的分子反应被检测到,因为4分子同时碰撞的 机会非常非常小(使得反应速率非常小)
Further Reading (Chapter 3 in Hobbs)
• Rate of reaction is typically measured as the change in concentration (moles/L) with time 反应速率通常通过浓度(mol/L)随时间的变化来测量 This change may be a decrease or an increase •改变可能是增加的也可能是减小的 • Likewise the concentration change may be of reactants or products 同样,改变浓度的物质可能是反应物也可能是生成物
Wikipedia
Pseudo first order reactions 伪一级反应

化学专业英语单词

化学专业英语单词

ChemistrySummer Holidays Homework for Future Freshmen of High schoolClass: __________________________Chinese Name:______________________English Name:______________________Beijing#80 High School International DepartmentIntroduction to Chemistry 化学入门Definition:Chemistry is the study of the composition, structure, and properties of matter, the processes that matter undergoes, and the energy changes that accompany there processes.(化学的定义:化学是研究物质的组成,结构,性质,物质发生的变化,以及变化过程中涉及的能量变化。

)Branches of Chemistry: O rganic Chemistry;Inorganic Chemistry;Physical Chemistry; Analytical Chemistry;Biochemistry; Theoretical chemistry(化学的分支:有机化学;无机化学;物理化学;分析化学;生物化学;理论化学)Day 1【Task】Please put the Chinese name into the suitable chapter. Vocabulary about chapter name. 章节名称词汇(----What may we study about chemistry in the first year? 高一可能涉及哪些化学知识?)物质和变化;原子:构建物质的基本单元;酸和碱;氧化还原反应;气体;化学键;原子中的电子排布;称量和计算;有机化学;反应能量;元素周期律;化学方程式和化学反应;化学平衡;化学反应动力学;化学计量学;化学式和化学物质;物质的状态;生物化学;电化学;滴定与pH值;水溶液中离子和稀溶液的依数性;溶液;Chapter 1 Matter and Change ( )Chapter 2 Measurement and Calculation ( )Chapter 3 Atom-Building Block of Matter ( )Chapter 4 Arrangement of Electrons in Atoms( ) Chapter 5 The periodic Law ( )Chapter 6 Chemical Bonding ( )Chapter 7 Chemical Formulas and Chemical Compounds( )Chapter 8 Chemical Equations and Reactions ( )Chapter 9 Stoichiometry ( )Chapter 10 States of Matter ( )Chapter 11 Gas ( )Chapter 12 Solution ( )Chapter 13 ions in Aqueous Solution and colligative Properties( )Chapter 14 Acid and Base ( )Chapter 15 Acid-Base Titration and pH ( )Chapter 16 Reaction Energy ( )Chapter 17 Reaction Kinetics ( )Chapter 18 Chemical Equilibrium ( )Chapter 19 Oxidation-Reduction Reactions ( )Chapter 20 Electrochemistry ( )Chapter 22 Organic Chemistry ( )Chapter 23 Biology Chemistry ( )【Task】Identify the vocabularies and master as possible as you can. Matter and its properties物质及其特点Mass 质量Definition of Matter物质的定义States of Matter物质的状态solid 固体liquid液体gas气体plasma等离子Composition of Matter 物质的构成Chemical and Physical Properties化学性质和物理性质Chemical and Physical Changes 化学变化和物理变化Conservation of Mass 质量守恒atom 原子molecular 分子ion离子cation 阳离子anion阴离子element 元素/单质compound 化合物pure substance 纯物质mixture混合物reactant 反应物group 族元素周期表的纵行family 族元素周期表的纵行period 周期元素周期表的横行metal 金属nonmetal 非金属metalloid 准金属Noble Gas 稀有气体【Task】Identify the vocabularies and master as possible as you can.Scientific Method(科学方法)system 系统hypothesis 假设model 模型theory 理论weight 重量derived Unit 衍生单位Energy能量Definition of Energy能量的定义Forms of Energy能量的形式Types of Reactions反应类型Exothermic Versus Endothermic 放热对吸热Measurements and Calculations测量和计算Temperature Measurements温度测量Scientific Notation 科学记数法Method of Conversion 转换方法Precision, Accuracy, and Uncertainty精密度,准确度,不确定度Significant Figures有效数字Calculations with Significant Figures 有效数字的计算directly proportional 正比例inversely proportional 反比例Chemical Formulas 化学分子式Equation 化学方程式Writing and Balancing Simple Equations 写作和配平简单方程式Ionic Equations 书写离子方程式mass number 质量数average atomic mass 平均分子量mole摩尔Avogadro’s number 阿伏伽德罗常数molar mass 摩尔质量Day4【Task】Identify the vocabularies and master as possible as you can.Law of conservation of mass 质量守恒定律nuclear forces 原子核力atomic nuclei原子核proton 质子neutron 中子electron 电子charge电荷positive charge 正电荷negative charge 负电荷atomic number 原子序数isotope 同位素nuclide 核素particle 粒子Oxidation Number and Valence氧化数和化合价Reactivity反应Period Table of the Elements元素周期表Periodic Law周期律Properties Related to the Periodic Table元素周期表的性质Radii of Atoms原子半径Electro negativity电负性Electron Affinity电子亲和能Ionization Energy电离能Bonding 化学键Types of Bonds 化学键类型Ionic Bonds离子键Covalent Bonds共价键Metallic Bonds金属键Intermolecular Forces of Attraction 分子间的吸引力Hydrogen Bonds氢键Double and Triple Bonds双键和三键Resonance Structures共振结构Day 5【Task】Learn the apparatus vocabulary and match the vocabulary with the picture given. Ifnecessary, google the vocabularies on the baidu /google image and try your best to finish it.学习仪器词汇并完成后面的图片匹配题。

化学反应工程-exercise_2_answer

化学反应工程-exercise_2_answer

Exercises for Chemical Reaction EngineeringI. Fill in each blank with an appropriate term or value :1. In the three ideal reactors, batch reator is an unsteady-state operation where composition changes with time but the composition is uniform throughout the reactor. Plug flow reactor and mixed flow reactor are the two steady-state flow reactors, the first is usually called PFR which has no backmix, the other is usually called MFR or CSTR which has the maximal extent of backmix.2. H 2 and O 2 combust completely in a 0.2 m 3 reactor and the flow rate of H 2O out of the reactor is 6 kmol/s. Then the rate of reaction of O 2 is 15 kmol/(m 3.s) .3. If the rate expression of 2A A A B dC r 0.05C C dt -=-= 3(mol /m min)⋅ is rewritten as '2A A A B dP r k P P dt-=-= (min /MPa ), then the value of the rate constant =k 4.52×103 ( MPa -2 ⋅ min -1 ) . The reactant gases canbe seen as ideal and the temperature is 400K.4. The rate expression of a reaction, 0.50.5A B R S +→+ is 0.52A A B r C C -=The rate equation is if the stoichiometric equation iswritten as 22A B R S +→+.5. For the reaction A rR →, the rate equation is220A A r C -= mol/(cm 3.min). Then the rate constant is 1.2×10 -3 m 3/(mol.hr).6. At 1200K, the reaction rate of A is 30 times as rapidly as at 1000K. The activation energy for this reaction is 169.7 kJ/mol .7. Liquid A (C A0=1mol/Liter) decomposes by second order kinetics, 2A A r kC -=. 50% A is converted in 10 minutes in a batch reactor. The rate constant of this reaction, k = 0.1 liter/(mol.min) (units should be given). If 80% A is to be converted, we should make a 40 minutes run. 0.52A A B r C C -=8. An elementary reactions in series,12k k A R S −−→−−→ (k 1 = k 2) takes place ina batch reactor. The initial concentration of A is C A0, and that of R and S are C R0=C S0=0. When t = 1/k 1 , the concentration of R reaches the maximum value, which is equal to C A0/e .9. For a gas phase varying volume reaction 32A B R +→, some inert gas, Aris introduced into the reactant mixture. The proportion between Ar , A and B is 2:1:3 (mol) initially. The fractional change in volume of the system, A ε=-1/3 . If the conversion of A is 60%, The volume of the system is 0.8 times as high as the initial volume, V 0, and the concentration of A, C A is 0.5 times as high as the initial concentration C A0.10.The two methods for analyzing kinetic data we usually use are integral and differential methods.11. For reactions in parallel, a high reactant concentration favors the reaction of higher order , and a low reactant concentration favors the reaction of lower order. A high temperature favors the reaction of higher activation energy , and low temperature favors the reaction of lower activation energy .12. Consider a porous catalyst particle bathed by reactant A. The rate ofreaction of A for the particle as a whole may depend on:① surface kinetics ;② pore diffusion resistance ;③ temperature gradients within the particle ;④ film temperature gradients ;⑤ film diffusion resistance .13. A plug flow reactor (2 m 3) processes an aqueous feed (100 liters/min)containing reactant A. The reaction is reversible and represented by min /,01.004.0,⋅-=-⇔liter mol C C r R A R A AThe equilibrium conversion of A is 0.8 , and the actual conversionachieved in the reactor is 0.506 .14. Given the multiple reaction with E 1=50, E 2=100, E 3=120, and E 4=60respectively for each step,)(31desired S R A −→−−→−2 4T UFor maximizing the yield of S, we should use: CA. Higher temperature;B. Lower temperature;C. Rising temperature with proceeding of the reaction.15. For an irreversible single reaction whose rate equation is –r A = kC A n( n >0), the plug flow reactor is always superior to the mixed flow reactor. Is this point of view right? yes (fill ‗yes ‘ or ‗no ‘). For a reaction in series, if the intermediate is our desired product, then the above conclusion is right or not ? yes (fill ‗yes ‘ or ‗no ‘).16. See Figure 1, an aqueous reactant stream passes through the two-reactorsetups connected in series shown as case (a) and (b):Figure 1If each unit have the same space time and is operated under isothermal condition, a first-order irreversible reaction A → R occurs in the two setups respectively, then the final conversion X A,case (a) = X A ,case (b) (fill “>”,“<” or “=”). If the reaction is second-order, the final conversion X A,case (a) > X A,case (b) (fill “>”,“<” or “=”).17. For a constant-density flowing system reacted in a steaty-state flowreactor, the space time τ = holding time t (fill ―>‖,‖<‖ or ―=‖). If ν =ν0 (1 + εA X A ), where εA > 0, for the same reactor, the space time τ > holding time t (fill “>”,“<” or “=”) .18. For an exothermic irreversible reaction run in a mixed flow reactor,may exist at most three intersections of the energy balance line with the S-shaped material balance line for the given τ — points M 1, M 2 and M 3 shown in Figure 2. Among these points, M 1 and M 3 are stable operating points, M 2 is unstable operating point (called ignition point), usually M 3 is optimum operating point (fill M 1, M 2 or M 3).TX AFigure 219. For a reaction the plot of 1/(-r A ) vs. X A is shown in Figure3. If thereaction proceeds in a plug flow reactor with recycle, then the actualconversion at the inlet is 0.1 and the optimum recycle ratio is 1/6 . 0.00.20.40.60.8 1.01/(-r A )x A Equal areasB(a)(b)(c)(d)Figure 320. An exothermic irreversible reaction A →R occurs in a mixed flowreactor. One is isothermal operation at the same temperature as the feed, another is adiabatic operation. Then we can conclude that the final conversion of A for isothermal operation is < that for adiabatic (fill “>”,“<” or “=”).21. In Figure 4, which scheme is superior to the reaction221,,B R S BA R CC k r S B R C C k r R B A =→+=→+ to produce more desired product R? (a) .Figure 422. In Figure 5 ,Figure 5Which is irreversible reaction? (a)Which is reversible endothermic reaction? (c )Which is reversible exothermic reaction? (b) ( fill ―a‖, ― b‖ or ―c‖ )Please draw the optimum temperature progression on the three figuresrespectively.23.In figure 6 ,Figure 6Which is the E curve of plug flow ? (a)Which is the E curve of mixed flow ? (b) (fill ―a‖ or ―b‖)Accordingly, the E function of plug flow is E =,0,t tt t⎧∞=⎪⎨≠⎪⎩, the E functionof mixed flow is E = 1ttte-( how to prove? please refer to P321-322! ), thevariance and dimensionless variance of the E curve of plug flow is σt2=0 , σθ2 = 0 , and those for mixed flow is σt2 = 2t, σθ2 = 1 . 24.The product distribution of a series reaction at various conversions is plotted in figure 7. When the conversion is 80%, the overall yield and selectivity of the intermediate product R are 5/8 and 5/3 ,respectively.00.20.40.60.8 1.00.20.40.60.81.0X A C/CA0Figure 725. A reaction takes place in a batch reactor, and the composition changewith time is shown in Figure 8. According to the characteristics of the figure, can you make the conclusion that this is a series reaction? no (‗yes ‘ or ‗no ‘? ).C tFigure 826.The relation between -1/r A and X A for a reaction is shown in Figure 9.Which of the following reactors is the optimum for this reaction? c.a. A plug flow reactor ;b. A mixed flow reactor ;c. A mixed flow reactor operating at the lowest point of -1/r A ~X A curvefollowed by a plug flow reactor.Figure 9II. In order to obtain the k0 and E of a first–order gas reaction A R, pleaseIII. Aqueous feed containing reactant A (C A0 = 2 mol/ liter) enters a plug flowreactor (V = 10 liter) which has a provision for recycling a portion of the flowing stream. The reaction kinetics and stoichiometry are A →R, –r A = 1C A C R mol/ liter ⋅min, and we wish to get 96% conversion. Should we use the recycle stream? If so, at what value should we set the recycle flow rate so as to obtain the highest production rate, and what volumetric feed rate can we process to this conversion in the reactor ?Solution:Since there is a provision for recycling a portion of the stream and the reaction is an autocatalytic reaction, certainly, we should use a recycle reactor. From the performance equation of recycle reactor,A X X R R A A dX r R C v V A f A f ⎰+-+=1001 …………………………(1) The optimum R can be achieved only when the following condition is met.1111+-=⎥⎦⎤⎢⎣⎡-⎰++R X r dX r Af X X R R A A X R R A A f A f A f ………………………(2)When the conversion is 96%, C A =0.08 mol/liter, C R =1.92 mol/liter. The rate equation can be rewritten asA A A A X X C r )1(20-=- On integration the equation (2) is222001(1)1ln (1)(1)Af A Af Af A Af Af R RX R R RC X R RX C X R X +-++=+-- Solve the equation with iteration method,R=0.282 On integration equation (1),min)/(98.0min)/(47.3)96.01(282.096.0282.0282.1ln 2282.110)1(1ln 10002000liter v R liter v v X R RX R C R C v V vrecycle Af Af A A =⋅==-⨯-=--++=IV.Substance A in a liquid reacts to produce R and S as follows:A feed (C A0 = 1, C R0 = 0, C S0 = 0) enters two mixed flow reactors in series (τ1= 2.5 min, τ2 = 5 min). Knowing the composition in the first reactor (C A1 = 0.4, C R1 = 0.4, C S1 = 0.2), find the composition leaving the second reactor. Solution: For the first reactor from the performance equation of mixed flow reactor,1111111221,0.4/min ,0.1/min R A S A C and k liter mol k C C and k liter k C ττ==⋅==For the second reactor we use the performance equation of mixed flow reactor, then12221222,0.114/A A A A A C C C mol liter k C k C τ-==+ For mixed flow reactor, the overall fractional yield and the instantaneous fractional yield are identical, so with respect to R,21121212122212(/)(/)0.8,0.629/m m R R A R A A A A R A R A C C k C k and C mol liter C C k C k C k k φϕ=-====-++ With respect to S,21222212122212(/)(/)0.2,0.257/m m S S A S A A A A S A S A C C k C k and C mol liter C C k C k C k k φϕ=-====-++V . Consider the parallel decomposition of A of different ordersDetermine the maximum concentration of desired product obtainable for isothermal operations(a) in a mixed flow reactor (b) in a plug flow reactor Solution:For the product T, its instantaneous fractional yield and overall fractional yield areAA TAA AC C C A T C C C A T -=++=022)/(21)/(φϕ(a) If the reaction takes place in a plug flow reactor, then the relationship betweenP P and ϕφ can be represented byAC C AA AT C C AP AA P dC C C CC dC C C AA AA ⎰⎰++-=--=00220211ϕφOn integration,)1111(11ln2)(000AA A A A A T C C C C C C C +-+-++--=To obtain the maximum C T , we must differentiate the equation and letdC T /dC A =0.)1(11212==+-++-=A A A A T C C C dC dC So, when the concentration of A drops to zero, C T gets its maximum and the value is 25.2=T C(b) If the reaction proceeds in a mixed flow reactor, then22022021)(,21AA A A A T A A AA A T mm C C C C C C and C C C C C C ++-=++=-=ϕφ Differentiating the equation and taking0/=A T dC dC , we obtain2=A CSo when the concentration of A drops to 2, C T gets its maximum and the value is33.1=T CVI. For an elementary aqueous reaction A ⇔ R, the plot of X A vs. T is shown asFigure 10. If the reaction takes place in a plug flow reactor, please draw the optimal temperature progression on the figure,(a) find τ needed for 60% conversion of A using the optimal temperature progression in the reactor.(b) also find the exit temperature of fluid from the reactor.Note: the maximum allowable operating temperature is 95℃, the feed is aqueous A-solution of C A0=1 mol/liter, F A0=1000 mol/min. Solution:(a) The optimal temperature progression is shown in the following figure. Wecan obtain the following data from the curve. Then, plot 1/(-r A ) vs. X A . From the area under the curve, we find that0/0.66A C τ=. Thus 0.66min τ=.VII. For an elementary aqueous reaction A ⇔R, ∆Hr = -75300 J/mol, C PA = C PR= 1046 J/ molA ⋅K, a concentrated aqueous A-solution (C A0 = 4 mol/ liter, F A0 = 1000 mol/ min) is to be 80% converted in a mixed flow reactor. If the adiabatic operation is available, please find the smallest size of reactor and give the temperature of the flowing stream entering and leaving the reactor. Note: the plot of X A vs. T is shown as Figure.10. Solution:(a) The reaction heat of the reaction is -75300 J/mol. So this is a reversibleexothermic reaction. The slop of the adiabatic operating line is10460.013975300Cp Hr ==-∆. For a mixed flow reactor, the optimaloperating point should be on the locus of maximum rate. From the point of intersection of the locus of maximum rate and the line of X A =0.8, we know that -r A = 0.08×4 = 0.32 mol/ liter.min. From the design equation of MFR,00.8 2.50.32A A A X V F r ===- thus, V = 2.5 F A0 = 25000 liter = 25 m 3.(b) From the operating point, we can read directly from the figure that thetemperature of the exit stream is 62℃. The equation of operating line is 21()A CpX T T Hr=--∆, in which T 2 = 62℃, X A = 0.8, ∆Hr = -75300 J/ mol, C PA = C PR = C P = 1046 J/ molA ⋅K. Thus we can calculate T 1 from the following equation:12 4.4A HrT T X Cp-∆=-=℃C o n v e r s i o nVIII . A A-solutionC o n v e r s i o nSolution:a) From the operating line, we know that X Af =0.70, 0.21Af Rx R =+ Thus,0.2/0.71RR =+ and R = 0.4b) The temperature of the fresh feed is the temperature of point C, 10℃, the inlet temperature is that of point A, 30℃and the out let temperature is that of point B, 76℃.c) From the figure we can read the data of –r A and X A , as shown in the following table. Plot 1/(-r A ) vs. X A , so the area under the curve is 0.642. That is,10.642Af Af X ARX R AdX r +=-⎰From the design equation of recycle reactor,10(1)(0.41)0.6420.899Af Af X A R X R A A dX VR F r +=+=+⨯=-⎰Thus, V = F A0×0.899 = 899 liter1/(-r )XIX . Reactant A (C A0 = 10 mol/liter) flows through a mixed reactor (τ = 50 s), andreacts away as follows:A → R, s liter mol C r A A ⋅=-/,02.0 Determine the conversion of A if the stream is:(a) a microfluid, (b) a macrofluid. Solution:(a). From the design equation of MFR,00.02(1)A AA A A A X X C r C X τ==-- ∴ X A = 0.5(b) The aggregation model,()A A element X X Edt ∞=⎰in which, (X A )element = 1-e -kt = 1-e -0.02t; 1ttE e t-=thus,0.0200.025001()(1)1(1)500.5ttt A A element ttX X Edt ee dt tee dt -∞∞--∞-==-=-=⎰⎰⎰X. The concentration readings in the following table represent a continuousresponse to a ideal pulse input into a closed vessel which is to be used as a chemical reactor for a liquid decomposing with rate equation A A kC r =-, k = 0.307 min -1, and by the shape of this curve we feel that the dispersion or tanks-in-series models should satisfactorily represent flow in the reactor. (a) Assuming that the dispersion model holds, find the dispersion number,D uLand the conversion expected in this reactor.(b) Find the number of tanks in series which will represent the reactor andthe conversion expected, assuming that the tanks-in-series model holds.Plot C pulse vs. t curve we can see that the curve is nonsymmetricalC t, minWe guess thatDuL> 0.01. Because constant t ∆=, we can calculate t and 2t σas follows,i iit C t C=∑∑; 222i itit C t Cσ=-∑∑i C =∑0 + 6 + 12 + 18 + 20 + 18 + 13+ 9+ 6 + 3 + 2 + 1 + 0 =108 i i t C =∑501 2iit C =∑2843Thus,ii it C t C =∑∑= 501/108 = 4.64 min 222i i t it C t C σ=-∑∑= 283/108-4.642= 4.79 min 222224.79/4.640.222t tθσσ===For a closed vessel, the relation between2θσandD uLis 220.22222()(1)uL D D D e uL uLθσ-==--Let x =DuL. Thus, f (x ) = 12222(1)0xx x e θσ--+--=11'()24(1)2xxf x x e e --=--+By Newton iteration method :()(1)()'()()()k k k k f x xxf x +=- Let x(0)= 22θσ = 0.111, after two iterations, we find that x = D/(uL) = 0.127 > 0.01.Let a == 1.313,202222411(1)(1)uL DAA auL auL A DDC aeX C a ea e-=-=-+-- = 0.714(b) For the tanks in series model,21Nθσ=the number of tanks can be obtained,N = 1/ 0.222 = 4.54.51111/(10.307*4.64/4.5)0.710(1)A N X t kN=-=-+=+XI. The first-order reaction A → R is carried out in a 10-cm-diameter tubularreactor 6.36 m in length. The rate constant is 0.25 min -1. The response results of a tracer pulse test carried out on this reactor are shown in the following table.Please calculate the conversion in the exit using (a) the closed vessel dispersion model, (b) a single PFR, (c) the tanks-in-series model, (d) a single MFR.Solution:(a) Plot C pulse vs. t curve. This is a nonsymmetrical curve.Calculate t and2t σas follows,i iiiit C t t C t∆=∆∑∑; 222ii itiit C t t C tσ∆=-∆∑∑ii C t ∆=∑49.9 i ii t C t ∆=∑252.2 s 2iiit C t ∆=∑1558Thus,iii ii t C t t C t∆=∆∑∑= 252.2/49.9 = 5.05 s 222iiit iit C t t C tσ∆=-∆∑∑= 1558/49.9-5.052 = 5.72 s 2 22225.72/5.050.224t tθσσ===Ct,sFrom the nonsymmertrical curve, we guess that DuL> 0.01. For a closed vessel, the relation between2θσand D uLis220.22222()(1)uL D D D e uL uLθσ-==--Let x =DuL. Thus, f (x ) = 12222(1)0xx x e θσ--+--=11'()24(1)2xxfx x e e--=--+By Newton iteration method :()(1)()'()()()k k k k f x xxf x +=- Let x (0)= 22θσ = 0.112, after two iterations, we find that x = D/(uL) = 0.129 > 0.01.Let a 202222411(1)(1)uL DAA auL auL A DDC aeX C a ea e-=-=-+--= 0.674(b) For a single PFR, we can write the design equation:AX AA AdX C r τ=-⎰0(1)AX AA A dX kC X =-⎰By integration, we get,ln(1)A X k kt τ-=-=-Thus,0.255.05110.717kt A X e e --⨯=-=-=(c) For the tanks in series model,21Nθσ=the number of tanks can be obtained,N = 1/ 0.224 = 4.464.461111/(10.25*5.05/4.46)0.671(1)A N X t kN=-=-+=+(d) For a single MFR, we can write the design equation:0(1)A AA A A A X X C r kC X τ==-- thus,111/(10.25*5.05)0.44211A X k ktτ===+=++。

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2.05Reaction Kinetics and StoichiometryK Miyanaga and H Unno,Tokyo Institute of Technology,Yokohama,Japan©2011Elsevier B.V.All rights reserved.2.05.1Introduction33 2.05.2Enzyme Kinetics34 2.05.2.1Michaelis–Menten Equation34 2.05.2.2Initial Rate35 2.05.2.3Experimental Determination of Kinetic Parameters in the Michaelis–Menten Equation35 2.05.2.4Complex Enzyme Kinetics36 2.05.2.4.1Allosteric enzyme36 2.05.2.4.2Two substrate reactions37 2.05.3Factors Affecting Reaction Kinetics38 2.05.3.1Inhibited Reaction Kinetics38 2.05.3.1.1Inhibition of reversible inhibitor38 2.05.3.1.2Substrate inhibition39 2.05.3.1.3Product inhibition40 2.05.3.2Deactivation of enzyme40 2.05.3.3pH Dependency of Reaction Rate41 2.05.4Biochemical Reaction Rate Related to Cellular Systems42 2.05.4.1Growth Rate43 2.05.4.2Substrate Uptake Rate43 2.05.4.3Product Formation Rate44 2.05.5Stoichiometry44 2.05.5.1Yield Coefficient based on Mass44 2.05.5.2Biochemical Stoichiometry45 2.05.5.3Heat of Reaction46 2.05.5.4Yield Coefficient based on ATP Synthesis46 References46Glossarykinetics Generally means a quantitative study of phenomenological speed(rate)in relation with relevant factors.In this article,kinetics refers to chemical reaction speed relevant to enzyme and/or cell.material/energy balance In any chemical reaction, elemental amount is preserved during the reaction process.To confirm this principle,material balance is evaluated in any chemical reaction process.Energy is also preserved in any chemical reaction process,where input energy and/or reaction energy must be taken into consideration for taking the balance.rate Changing speed of items is expressed as rate. Growth rate is increasing speed of biomass or number of cell,such as microbial,animal,and plant cells, under appropriate culture environment.Substrate uptake rate and product formation rate implies speed of relevant affairs.stoichiometry Generally means quantitative relationships among the affairs,like amount of materials and/or energy, of reactants and products in chemical reactions.In this article,quantitative consideration of the material and energy balance of biochemical reactions are discussed. yield Yield is the ratio of amount of target affair changed during any event period of time to any reference affair. Yield does not include time-course change.Growth yield is the increased biomass referred to concerned item,such as uptaken substrate amount and uptaken oxygen amount.Unit of yield depends on what unit is used for the relevant items.In the similar manner,product yield is defined,which is used for quantitative analysis for the process design.2.05.1IntroductionOne of the aims of biotechnology is to apply biofunction(bioreaction)occurring in living organisms as biocatalyst to produce materials and/or systems useful for human beings.Bioreaction is categorized into two,single enzyme reaction and cell reaction,the latter occurring in cells such as microbial,animal,and plant cells.The cell reaction is also catalyzed by enzyme,but the reaction involves many enzymes like a consortium of many enzyme reactions,which is different from the single enzyme reaction.3334 Underlying PrinciplesGenerally in the engineering application of any reaction, the reaction rate or kinetics, the material and energy flow have to be quantified. In addition, for the materialization of the reaction process, bioreactor and further bioprocess, an integra­tion of the bioreactor and the up-and downflow processes has to be designed. For the design, material and energy balances are made. In this procedure, the material and energy flow must be appropriately evaluated for the relevant bio-reaction. These flows for single enzyme reaction are relatively simple, because chemical component involved in the reaction is clear and the activation energy can be evaluated definitely. In addition, the reaction rate can be measured based on any definite base.On the other hand, the material and energy flow in cell reaction is complicated due to the involvement of many and frequently unidentified reactions. Even though the raw material is unified from the target product, the elemental balance, say carbon balance, cannot necessarily be completed only by the raw material and the product because of the involvement of many reaction schemes that may take carbon from another source. For the reaction energy, the situation will be more complicated. A reaction will release or absorb energy according to the reconstruction of substances in the reaction. Reaction energy from the process is a resultant of all reactions involved. When considering cell reaction, all elemental reactions are impossible to be quantified completely. Therefore, it is necessary to establish methods for evaluating such situation which is practicable to the design of the bioreactor and/or process and to unify the operational parameters. Kinetics and stoichiometry are the fundamental and inevitable knowledge for the above consideration.2.05.2 Enzyme Kinetics2.05.2.1 Michaelis –Menten EquationIn the usual single-substrate-enzyme-catalyzed reaction, the relationship between initial rate of reaction and the substrate concen­tration assumes the form of saturation curve. A mathematical model to describe the kinetics was developed by Henri in 1902 [8] and Michaelis and Menten in 1913 [9]. Furthermore, Briggs and Haldane [5] generalized this model using the quasi-steady-state assumption in 1925. A simple schematic diagram is described in Figure 1.Henri and Michaelis and Menten assumed a production reaction of enzyme –substrate (ES) complex derived from free enzyme and substrate rapidly reaches equilibrium state. In equilibrium state, the following equation is derived:k 1E ½ ¼k − 1 ES ½½ S ½1The dissociation constant (K s ) of ES complex isk − 1E ½ ½ S K S ¼¼½2k 1ES ½ On the other hand, in the quasi-steady-state, it is assumed that the initial substrate excessively exists in the batch system comparedwith the initial enzyme, and the concentration of ES complex rapidly reaches steady state under the condition where substrate concentration [S] is fixed. It means that time course of ES complex concentration is assumed as zero. In addition, we must be conscious of the limitation that this perspective can be applicable only under the condition where ES complex concentration is sufficiently low.d ES ½¼k 1E ½ ½ ¼0 ½½ S −ðk − 1 þk 2ÞES 3 d tK m ¼E ½ S ½¼k − 1 þk 21 ½4Since total enzyme concentration, [E 0], is constant in the batch reaction systemE 0½ ¼E ½ þES ½The concentration of ES complex isES ½ ¼E 0½ S ½ m þS ½½5k 1 k2++k –1Enzyme SubstrateEnzyme–subtrate (ES)Enzyme Product complex E+SESE+PFigure 1 Schematic diagram of enzyme reaction.Reaction Kinetics and Stoichiometry 35V(=k 2m m ′Figure 2 Relationship between substrate concentration and initial rate in the Michaelis –Menten-type enzyme reactions.The product formation rate, v , is defined as follows:d P ½v ¼¼k 2 ES ½ d tk 2 E 0½ ½ ½ S V m S ¼¼½6K m þ½ S K m þS ½where V m (maximum reaction rate) is k 2[E 0]. So far, in many enzyme reactions it is revealed that k −1 is much larger than k 2(k −1 >> k 2). Therefore, K m is corresponding to K s (K m ≈ K s ). Generally, eqn 6 and K m are often called the Michaelis –Menten equation and the Michaelis constant, respectively. As shown in Figure 2, the Michaelis constant can be determined from the substrate concentration which gives a half of the maximum reaction rate. Smaller K m indicates that the enzyme can easily combine with its substrate, implying high affinity to substrate.2.05.2.2 Initial RateInitial rate of reaction is defined as the reaction rates under the assumption that substrate consumption and reaction product do not affect the reaction. The initial rate is calculated by a correlation between substrate concentration or product concentration change and reaction period insofar as their time course is estimated as a linear relationship. The time-course data, in the later period, are affected by a variety of factors. Generally, in the case of irreversible reaction, the initial rate of reaction can be calculated by change in the concentration gradient within 5–10% of reaction ratio. In the case of reversible reaction or irreversible reaction with significant product inhibition, the concentration change is subject to deviate from linearity.2.05.2.3 Experimental Determination of Kinetic Parameters in the Michaelis –Menten EquationTo experimentally determine kinetic parameters V m and K m , Michaelis –Menten equation is modified as described in Figure 3. Each equation derived from Michaelis –Menten equation has been suggested to determine these kinetic parameters with high precision [4]. That is, suitable method should be used to minimize the effect of the error of data. Experimental data obtained from enzymatic reaction experiment in a batch reactor are subject to include the error. Usually, Lineweaver –Burk plot (L –B plot) plot is applied to determine the kinetic parameters due to its simplicity [11]. However, we must pay attention to accuracy of parameter in applying least-square analysis to data points when the variability of initial rate is not negligible at low substrate concentrations. In such a case, Hanes –Woolf plot or Eadie –Hofstee plot is applied to determine the parameters more accurately rather than L –B plot. It is highly possible that the error in initial rate is observed in measuring the change of concentrations. Therefore, it is important not to expand the error by applying the initial rate to arithmetic operation. The Eadie –Hofstee plot does not emphasize the plots at low substrate concentrations, therefore recommendable as a suitable method.The Eisenthal –Cornish –Bowden (ECB) plot [6, 7] is the method that there are not any calculations to determine parameters. This method can also exclude outliers and provide unbiased estimates of the kinetic parameters because each pair of experimental data (v , [S]) does not interfere with other pairs. When it is an ideal case without any data error, all lines intersect at one fixed point, giving V m and K m . When the data include errors, individual intersections of plot are dispersed around the fixed point. Therefore, in the ECB plot, the error of data can be simultaneously evaluated besides the estimation of the kinetic parameters.Instead of the above four types of plots, kinetic parameters can be determined by plotting time-course data of ([S 0]–[S])/t versus (ln([S 0]/[S])/t . However, the quality of data in this integration method is different from those of other plots. The data in this method contain the reaction time and substrate concentration, while the initial reaction rate and substrate concentration are used in other four plots.Lineweaver–Burk (L–B) plot1 1 K m 1 =+v V m V m [S]1− 1 Km[S]Hanes–Woolf plot= + [S] v V m V m[S] K m 1[S]v v =V m −K mEadie–Hofstee plotm V [S]Eisenthal–Cornish–Bowden (direct linear) plotK m m [S]vV m v=[S ]+ K m [S]m−[S]Integration methodln [S 0] [S] 1 [S 0]−[S] V m=− +t K mt K m m0]−[S]t36 Underlying PrinciplesFigure 3 Various types of plot for determination of kinetic parameters in the Michaelis –Menten type enzyme reactions.2.05.2.4 Complex Enzyme Kinetics 2.05.2.4.1 Allosteric enzymeAmong enzymes, some of them are multimeric enzymes. They are mostly multisite-type enzymes that have more than one binding site to their substrate. In the multisite-type enzyme, after binding substrate to the enzyme, a steric structure of protein changes and its conformation change often results in alteration in overall reaction rate. Such kind of enzyme is known as allosteric enzyme. When the first substrate binding to the enzyme facilitates the binding of second substrate to same enzyme, this regulation is defined as a positive cooperativity. The reaction rate with the positive cooperativity is characterized by a sigmoidal curve of reaction rate versus time. If it is assumed that n -molecules of substrate bind one enzyme simultaneously, the reactions are described as follows:E þ n S ⇄ES n½7Reaction Kinetics and Stoichiometry37The dissociation equilibrium constant of ES n complex and the reaction rate in this case are described:nE ½ ½ S K m ¼½8 ½ES n V m S ½ nv ¼½9½ nK m þS where n is the Hill ’s coefficient which indicates the extent of allosteric effectiveness. Concerning the value of n, n > 1 and n <1 indicate positive and negative cooperativity, respectively (Figure 4).From eqn (9), the Hill ’s coefficient can be determined by plotting the relationship between log[S] and log(v /(V m −v )) (the Hill ’s plot):vlog ¼n log S −log K m½10½ V m −v2.05.2.4.2 Two substrate reactionsIn the enzyme reaction, multisubstrates are usually responsible for its reaction in the system. The simplest case is a two-substrate reaction. The reaction to be considered isA þB ↔P þQwhere A and B are substrates and P and Q are products, respectively. There are four main reaction mechanisms based on binding order between enzyme and substrate, and production order of products: (1) ordered Bi Bi mechanism, (2) Theorell-chance mechanism, (3) rapid equilibrium random Bi Bi mechanism, and (4) ping pong Bi Bi mechanism. Focusing on the initial rate of forward reaction, these four reaction mechanisms are classified as follows:1. Ordered Bi Bi mechanism . The binding orders of substrate A, B to enzyme and the detachment orders of products P, Q are fixed. That is, binding of substrate B to enzyme occurs after substrate A binding. Subsequently, detachment of product P from enzyme occurs and then product P desorbs from enzyme.2. Theorell-chance mechanism . First, substrate A attaches to enzyme. Then, substrate B reacts with complex EA and it results in production of product P and subsequently product Q.3. Rapid equilibrium random Bi Bi mechanism. The substrate binding and product detachment occur at random and they are in the dissociation equilibrium. The complex EAB is formed not only from the complex EA and substrate B but also from the complex EB and substrate A.4. Ping pong Bi Bi mechanism. First, after substrate A binds to enzyme, product P is produced. Subsequently, the binding of substrate B to enzyme results in the production of product Q.Substrate (S) (mM)R e a c t i o n r a t e (V ) (m M m i n –1)Figure 4 Dependence of initial reaction rate on substrate concentration in Michaelis –Menten (n = 1) and allosteric enzyme kinetics. The value of n indicates the Hill ’s coefficient. V m =1mM min −1, K m =10 mM.38 Underlying Principles2.05.3 Factors Affecting Reaction KineticsChemical substances other than the substrate can combine with enzymes and reduce their catalytic activity. Such substances are called enzyme inhibitors. The combination between enzyme and the inhibitor may be reversible, partially reversible, or irreversible. For example, heavy metals are well known as irreversible inhibitors to form stable complex with enzyme.There are three major types of reversible inhibition, such as competitive, uncompetitive, and noncompetitive inhibitions, respectively.2.05.3.1 Inhibited Reaction Kinetics 2.05.3.1.1 Inhibition of reversible inhibitorThe inhibition types by reversible inhibitor is typically classified into four categories (competitive, uncompetitive, non competitive, and mixed). Competitive inhibition usually occurs due to existence of substrate analogs that compete with substrate for the active site of the enzyme. The competitively inhibited enzyme reaction can be described asK mK 2E þ S ⇄ES E þ P þ→ I→ E ½↓↑K EI→ EI½11where K EI is the dissociation constant of enzyme –inhibitor complex (EI):½ I K EI ¼In uncompetitive inhibition, there are two binding sites both to substrate and to inhibitor in the enzyme. Uncompetitive inhibitor binds to the ES complex only but not to the free enzyme. Besides this property, ES-inhibitor (ESI) complex does not form product because of the conformation change of enzyme. The uncompetitively inhibited enzyme reaction can be described asK mk 2E þ S ⇄ES E þ PþI↓↑K ESIESI½12where K ESI is the dissociation constant of ESI complex:½ES ½I K ESI½ESIIn noncompetitive inhibition, there are also two binding sites both to substrate and to inhibitor in the enzyme. The inhibitor can bind not only to the free enzyme but also to the ES complex equivalently and they form EI and ESI complexes, respectively. Substrate also can bind both to free enzyme and to EI complex. Moreover, ESI complex cannot form the product:K mk 2E þ S ⇄ES E þ P þþI I ↓↑K EI ↓↑K ESIEI þS ⇄ESIK m ½E ½S ½EI ½S ½E ½I ½ES ½IK m ¼¼ K EI ¼ K ESI ¼¼ ½13½ES ½ESI ½EI ½ESIReaction Kinetics and Stoichiometry 39In mixed-type inhibition, there are also binding sites both to substrate and to inhibitor in the enzyme. The inhibitor can bind not only to the free enzyme but also to the ES complex. However, the binding abilities are not equivalent (K EI is different from K ESI ):K mk 2E þ S ⇄ES → E þ P þþI I ↓↑K EI ↓↑K ESI EI þS ⇄ESIK EIS ½E ½S ½E ½I ½ES ½I ½EI ½SK m ¼; K EI ¼ ; K ESI ¼ ; K ESI ¼ ;½ES ½EI ½ESI ½ESI½14½E ½S ½IK EIS K EI ¼ K ESI K m ¼½ESIIn the above four types of inhibition scheme, each reaction rate equation is developed by dissociation equilibrium equations of complexes, the assumption that total enzyme concentration are conserved before and after enzyme reaction, and the definition that reaction rate is described as k 2[ES]. The reaction rate for each inhibition scheme can be expressed by eqn 15:V m ; app ½S ν¼½15m ; app þ½Swhere V m, app and K m, app indicate apparent maximum velocity and apparent Michaelis constant, respectively, which are summarized in Table 1.2.05.3.1.2 Substrate inhibitionSubstrate may inhibit the reaction and deteriorate the reaction rate due to the change of enzyme structure or solution properties, which is known as substrate inhibition. The reaction scheme for uncompetitive substrate inhibition isK mK 2E þ S ⇄ES → E þ PþS↓↑K ESIESS½16with the definition of ESS complex dissociation constantES ½ ½ S K ES1 ¼½ESSIn addition, under the assumption that product can be formed from only ES complex not from ESS complex. The reaction rate can be developed as follows:½ V m S v ¼½17S ½½ 1 þK m þ S K ES1Table 1 Apparent kinetic parameters in the various inhibited reactions with reversible inhibitors Inhibition type V m,app K m,appCompetitive V mV mUncompetitive½I1 þ K ESIV mNoncompetitive½I 1 þ KEIV mMixed½I K m1 þ K EIK EIS½IK m 1 þ KEIK m½I1 þ K ESIK m½IK m 1 þ KEI½I K m1 þ K EIK EIS40 Underlying PrinciplesR e a c t i o n r a t e (V ) (m M m i n –1 )Substrate (S) (mM)Figure 5 Dependence of substrate inhibition on initial reaction rate in Michaelis –Menten enzyme kinetics. K ES1 indicates ESS (enzyme –substrate –subtrate) complex dissociation constant. V m =1mM min −1, K m = 10 mM.The substrate concentration that gives the maximum reaction rate, [S]m , can be determined by setting d v /d[S] = 0. The substrate concentration [S]m is given bypffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiS m ¼ K ES1 ½18 ½ K m Dependence of substrate inhibition on initial reaction rate in Michaelis –Menten kinetics are shown in Figure 5.To be more general form, reaction rate can be described as follows:V m ½Sv ¼!½19i ½S K m þ½S 1 þ∑ni ¼1K ESiwhere n -molecule substrates can bind to the one enzyme.2.05.3.1.3 Product inhibitionSome products are structurally analogous to its substrate. Therefore, they are apt to bind the active site of enzyme. In product-inhibition scheme, the maximum velocity does not change but apparent Michaelis constant is increased like a competitive inhibition:K mk 2E þS ⇄ES → E þP↓↑K EPEP½20 ν¼ V m ½SK m 1 þ ½PK EPþ½S½212.05.3.2 Deactivation of enzymeGenerally, the reaction rate increases with temperature via reaction rate constant according to the Arrhenius equation (empirically suggested by S. Arrhenius in 1889) [1] as follows:k ¼A exp ð−E a =RT Þ½22where E a , R , and T indicate the activation energy (J mol −1), gas constant (8.3 J K −1 mol −1), and temperature, respectively. It gives the quantitative basis of the relationship between the activation energy and the rate at which a reaction proceeds. This formula has a background of physicochemical absolute kinetics that the molecules with higher thermal energy than activation energy are shifted to transition state and then transformed to products; further by statistical –mechanical approach, the number of these molecules among total molecules with thermal motion can be calculated.Reaction Kinetics and Stoichiometry 41In many enzyme-catalyzed reactions, the reaction rate increases also with temperature according to the Arrhenius equation described ask 2 ¼ A exp ð−E a =RT Þ½23The reaction rate increases with temperature up to a certain limit. Over this critical temperature, enzyme activity decreases with increase of temperature because of enzyme denaturation. Enzyme activity can be affected by various factors, such as temperature, pH, and so on. Especially, heat can significantly deteriorate the enzyme activity, known as thermal deactivation. This inactivation rate constant also changes with temperature according to the Arrhenius equation:k d ¼ A d exp ð−E d =RT Þ½24where E d indicates inactivation energy (E d > 0), which is about 10-fold larger than the activation energy E a . That is, enzyme inactivation is much faster than enzyme activation by temperature. For example, assuming that E a and E d are 40 and 300 kJ mol −1,respectively, when the reaction temperature rises from 30 to 40 °C, the enzyme inactivation rate becomes 45-fold faster, while the enzyme activation rate becomes 1.7-fold faster.In general, enzyme activity is considered to be all-or-none. Therefore, the inactivation rate of enzyme can be applicable to first-order reaction rate scheme where it is proportional to the concentration of intact enzyme [E]. The inactivation rate can be described as follows:d ½E¼ −k d ½E d t ½E In ¼ −k d t ½25½E 0where k d is the inactivation rate constant.From eqn 25, the half-life (t 1/2), amount of time required to be half of initial concentration, can be determined and it is commonly used as a criterion of enzyme stability:In 2 t 1=2 ¼½26k d2.05.3.3 pH Dependency of Reaction RateEnzyme activity and stability depend strongly on the pH value of the reaction solution. The active sites of enzyme consist of amino acids with some ionic groups, such as carboxyl group, amino group, thiol group, imidazole group, phenolic hydroxyl group, and so on. The dissociation state of amino acid residue significantly affects the structure of active site, the affinity to substrate, or the catalytic activity. Based on the differences of dissociation state, we can assume that the enzyme has three different forms, EH 2+, EH, and E −. Three different forms indicate EH 2+ (–COOH, –NH 3+), EH (–COO − , –NH 3+), and E − (–COO − , –NH 2), respectively:K E1½EH ½H þ EH þ Hþ⇄EH þ2 ;K EI ¼ ½EH þ2 ½E − ½H þK E2E − þ H þ ⇄EH ; K E2 ¼½EHK S ′EH þþ S ⇄EH þ2SE H þ22K E1↑↓ K ES1↑↓↑↓H þ H þ H þ þ þþK Sk 2EH þ S ⇄EHS →EH þ PK E1↑↓ K ES1↑↓ ↑↓H þ H þ H þ þþþK E − þ S ⇄S ″E −SE −k 2½E 0 ½Sv ¼ k 2½EHS ¼ ½27K s pH E1 − pH pH þp K E2p K ES1 − pH pH þp K ES2where p K E n =−log K E n (n = 1, 2), p K ES n = −log K ES n (n = 1, 2), and pH = −log [H +].The optimum pH is usually determined experimentally because of the difficulty in characterizing the active sites of enzyme. The profiles of enzyme reaction rate for each pH often become bell shaped. The typical pH dependence of enzyme reaction rate is shown in Figure 6.v k +2 e0 0.60.50.4 0.3 0.20.10 1234567891011121314pH42 Underlying PrinciplesFigure 6 pH dependence of enzyme reaction rate. p K E1 =p K ES1=3 and p K E2 =p K ES2 =9, K s = 10, s = 10.Assumed to be p K E1 =p K ES1 and p K E2 =p K ES2, the optimum pH that provides maximum reaction rate is (p K E1 +p K E1)/2 and pH that provide a half of maximum reaction rate are p K E1 and p K E2.2.05.4 Biochemical Reaction Rate Related to Cellular SystemsIn microbial, animal, and plant cells, there are various intracellular enzyme reactions. To produce any material by utilizing these intracellular reactions, all biochemical reactions involved in the production should be considered in principle. However, each individual cell is a complicated multicomponent system, and quantitative clarification of the enzyme reactions occurring in the microbial cell is much more complicated and difficult than that of the single enzyme reaction. The multi-and single-component representations are the concepts in structured model and in unstructured model, respectively. In unstructured model, balanced growth in which all intracellular components simultaneously proliferate is approximated. Furthermore, there are diversities of different cells in the population in regard to cell phase. The cells in different cell phase often show different features of metabolic functions and activities. From this point of view, the entire cell is hitherto dealt with as a black box and the individual cells in the microbial population are considered to be homogeneous without respect to their variability in shape, size, physiological function, and so on. The heterogeneous individual cells and homogeneous (average) cells are segregated and unsegregated viewpoints, respectively. In the actual case of cell, cellular representations should be described by a structured and segregated model. Generally, however, an unstructured and unsegregated model, the most idealized case, isapplied to analyze cell population with a determi­nistic approach. These perspectives are summarized in Figure 7 [2].Figure 7 Various types of cell population models.。

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