2023-2024学年江苏省南通市如皋市度高三上学期调研(一)英语试题
江苏省南通市如皋市2022-2023学年高二上学期期末英语试题(原卷版)
2022-2023学年度高二年级第一学期期末教学质量调研英语试题注意事项：1. 答卷前, 考生务必将自己的姓名、准考证号填写在答题卡上。
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1. What does the man believe will help the environment a lot?A. Eating less meat.B. Growing personal food.C. Getting a good education.2. How old is the man?A. 20.B. 22.C. 30.3. What are the speakers mainly talking about?A. A friend.B. A work problem.C. A sports game.4. Who will be unhappy with the file system?A. Jenny.B. Colin.C. Terry.5. What will the speakers see next?A. The statues.B. The paintings.C. The dinosaur bones.第二节(共15小题;每小题1. 5分, 满分22. 5分)听下面5段对话或独白。
江苏省南京市六校2023-2024学年高三上学期11月期中联合调研考试英语试题
江苏省南京市六校2023-2024学年高三上学期11月期中联合调研考试英语试题学校:___________姓名：___________班级：___________考号：___________一、短对话1．What is the man going to do?A．Have a picnic.B．Go fishing.C．Take a drive. 2．What are the speakers mainly talking about?A．The weather.B．Indoor activities.C．The woman’s illness. 3．Where does the conversation most probably take place?A．At a bus station.B．At a train station.C．At an airport. 4．What will the man do next?A．Put a job advertisement.B．Conduct an interview.C．Surf the Internet. 5．Why does the man talk to the woman?A．To book a room.B．To confirm his flight.C．To reschedule a meeting.二、长对话听下面一段长对话，回答小题。
6．Which place will be cleaned today?A．The hallways.B．The front office.C．The cafeteria. 7．What will the woman do next week?A．Hold a workshop.B．Design a schedule.C．Host a dinner.听下面一段长对话，回答小题。
8．What did the speakers just do?A．They practiced dancing together.B．They performed in a musical.C．They watched a show.9．What was the woman?A．A dancer.B．An actress.C．A musician.听下面一段较长对话，回答以下小题。
2023-2024学年江苏省南通市如皋市高三(上)期中数学试卷【答案版】
2023-2024学年江苏省南通市如皋市高三（上）期中数学试卷一、单项选择题：本题共8小题，每小题5分，共40分．每小题给出的四个选项中，只有一项符合题目要求．1．已知复数z 1＝1+i （i 为虚数单位），z 1z 2＝2﹣2i ，则|z 2|＝（ ） A ．1B ．√2C ．2D ．2√22．已知集合A ={x|log 12x ＞−1}，B ＝{x |x 2+2x ﹣3＜0}，则A ∩B ＝（ ） A ．（﹣3，2）B ．（0，1）C ．(0，12)D ．（0，2）3．已知定义域为R 的函数y ＝f （x ），其导函数为y ＝f ′（x ），条件p ：f ′（0）＝0是条件q ：函数在x ＝0处取得极值的（ ）条件． A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既非充分又非必要条件4．已知抛物线y ＝x 2﹣x ﹣2与x 轴交于A ，B 两点，圆M 经过A ，B ，C （2，4）三点，则圆M 的方程为（ ）A ．x 2+y 2﹣x ﹣4y ﹣2＝0B ．x 2+y 2﹣3x +2＝0C ．x 2+y 2+2x ﹣4y ﹣8＝0D ．x 2+y 2+x ﹣y ﹣18＝05．设a ＝3﹣ln 3，b ＝sin 32，c ＝2﹣ln 2，则下列判断正确的是（ ） A ．c ＞a ＞bB ．b ＞a ＞cC ．c ＞b ＞aD ．a ＞c ＞b6．设一组样本数据x 1，x 2，…，x n 的极差为1，方差为0.1，若数据ax 1+b ，ax 2+b ，…，ax n +b 的极差为2，则数据ax 1+b ，ax 2+b ，…，ax n +b 的方差为（ ） A ．0.02B ．0.04C ．0.2D ．0.47．已知圆台上、下底面的半径分别为1，4，高为1，现用过任意两条母线的平面去截这个圆台，则截面面积的最大值是（ ） A ．256B ．5C ．253D ．108．已知函数f （x ）＝A sin （ωx +φ）（A ＞0，ω＞0）的图像如图所示，则φ的一个可能值为（ ）A ．−π4B ．−3π4C ．π6D ．23π二、多项选择题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求．全部选对得5分，部分选对得2分，有项选错得0分．9．已知a ，b ，c 满足a +b +c ＝0，且a ＞b ＞c ，那么下列选项中一定成立的是（ ） A ．ac ＜0B ．ab ＞acC ．c （b ﹣a ）＜0D ．2a +2b ＞210．已知边长为2的正六边形A 1A 2A 3A 4A 5A 6的中心为O ，则A 1O →⋅A 1A i →（i ＝2，3，4，5，6）的可能值为（ ） A ．2B ．4C ．6D ．811．已知函数f （x ）＝x 3﹣3x 2+1，则下列说法正确的是（ ） A ．函数f （x ）有三个单调区间B ．函数y ＝f （x +a ）的极大值与极小值之和为﹣4C ．关于x 的方程f （x ）﹣ax ＝0不可能有三个实数解D ．存在直线与函数y ＝f （x ）的图像从左至右有三个交点，且它们横坐标成等差数列12．一个盒子里放着大小、形状完全相同的1个黑球、2个白球、2个红球，现不放回地随机从盒子中摸球，每次取一个，直到取到黑球为止，记摸到白球的个数为随机变量ξ，则下列说法正确的是（ ） A ．P(ξ=0)=14B ．P(ξ=1)=12C ．P(ξ=1)=13D ．P(ξ=2)=13三、填空题：本题共4小题，每小题5分，共20分．请把答案直接填写在答题卡相应位置上． 13．（1+x ）（1+2x ）5的展开式中x 6的系数为 ．14．已知等差数列{a n }前3项和S 3＝12，a 1﹣1，a 2﹣1，a 3+3成等比数列，则数列{a n }的公差d ＝ ． 15．现有10张奖券，有且仅有2张为有奖奖券，甲、乙两人轮流依次不放回地抽取奖券，甲先抽取，然后乙再抽取为一个轮次．则在第一轮甲、乙都未中奖的条件下，第二轮甲、乙都中奖的概率为 ． 16．已知双曲线x 2a 2−y 2b 2=1(a ＞0，b ＞0)，过点A （2a ，0）作双曲线的一条渐近线的垂线，垂足为M ，直线AM 与双曲线的左支交于点N ，且2AN →=5AM →，则双曲线的离心率为 ．四、解答题：本题共6小题，共70分．请在答题卡指定区域内作答．解答时应写出文字说明、证明过程或演算步骤．17．（10分）已知数列{a n }的前n 项和为S n ，且a n +2S n =n 2+2n ． （1）求证：数列{a n ﹣n }是常数列； （2）求数列{2n •a n }的前n 项的和．18．（12分）已知在△ABC 中，角A ，B ，C 所对的边分别为a ，b ，c ，cosC cosB−cosC +sinCsinB−sinC=0．（1）若C =π3，求角A ； （2）若b ＝3，c ＝4，求a 的值．19．（12分）如图所示，直三棱柱ABC ﹣A 1B 1C 1中，AB ＝AC ＝4，AA 1＝6，BC =4√2，M ，N 分别是对角线BC 1，A 1C 的中点． （1）证明：MN ∥面ABC ；（2）求二面角A 1﹣MN ﹣C 1的正弦值．20．（12分）2023年9月25日，在富阳银湖体育中心举行的杭州亚运会射击项目男子25米手枪速射团体决赛中，中国队以1765环的总成绩击败韩国队夺得冠军，并打破世界纪录．现已知男子25米手枪速射决赛规则如下：取资格赛前6名选手进入决赛，5发子弹为一组，每发子弹9.7环以上得1分，否则得0分．若进入决赛的每位选手每组能得5分与4分概率分别为0.6，0.4． （1）求某位进入决赛的选手三组射击后得分为14分的概率；（2）设某位进入决赛的选手三组射击后得分为随机变量ξ，求随机变量ξ的分布列与期望． 21．（12分）已知A ，B ，C 为椭圆x 22+y 2=1上的三个不同的点，且线段AB 的中点在直线x ＝1上．（1）若线段AB 的中点坐标为(1，√24)，求直线AB 的斜率；（2）F 为椭圆右焦点，且满足FA →+FB →+FC →=0→，求直线AB 的方程． 22．（12分）已知f （x ）＝xlnx +a （x ﹣1）（a ∈R ）． （1）试判断函数g(x)=f(x)x的单调性； （2）若函数y ＝f （x ）有且只有一个零点，求实数a 的取值范围．2023-2024学年江苏省南通市如皋市高三（上）期中数学试卷参考答案与试题解析一、单项选择题：本题共8小题，每小题5分，共40分．每小题给出的四个选项中，只有一项符合题目要求．1．已知复数z1＝1+i（i为虚数单位），z1z2＝2﹣2i，则|z2|＝（）A．1B．√2C．2D．2√2解：因为z2=2−2iz1=2−2i1+i=2(1−i)2(1+i)(1−i)=(1−i)2=−2i，所以|z2|=√(−2)2=2．故选：C．2．已知集合A={x|log12x＞−1}，B＝{x|x2+2x﹣3＜0}，则A∩B＝（）A．（﹣3，2）B．（0，1）C．(0，12)D．（0，2）解：因为A={x|log12x＞−1}=(0，2)，B＝{x|x2+2x﹣3＜0}＝（﹣3，1），所以A∩B＝（0，1）．故选：B．3．已知定义域为R的函数y＝f（x），其导函数为y＝f′（x），条件p：f′（0）＝0是条件q：函数在x＝0处取得极值的（）条件．A．充分不必要条件B．必要不充分条件C．充要条件D．既非充分又非必要条件解：若函数y＝f（x）在x＝0处取得极值，则f'（0）＝0，即必要性成立，反之，若f'（0）＝0，则y＝f（x）在x＝0处不一定取得极值，比如f（x）＝x3，f′（x）＝2x2≥0，且f′（0）＝0，此时f（x）是增函数，无极值，充分性不成立．综上所述，p是q的必要不充分条件．故选：B．4．已知抛物线y＝x2﹣x﹣2与x轴交于A，B两点，圆M经过A，B，C（2，4）三点，则圆M的方程为（）A．x2+y2﹣x﹣4y﹣2＝0B．x2+y2﹣3x+2＝0C．x2+y2+2x﹣4y﹣8＝0D．x2+y2+x﹣y﹣18＝0解：根据题意可知A，B两点的坐标分别为（﹣1，0），（2，0），设圆M的方程为x2+y2+Dx+Ey+F＝0，将A，B，C三点的坐标代入圆M的方程，可得{1−D +F =04+2D +F =020+2D +4E +F =0，解上述方程组，求出D ，E ，F 的值，{D =−1E =−4F =−2 即可得到圆M 的方程x 2+y 2﹣x ﹣4y ﹣2＝0． 故选：A ．5．设a ＝3﹣ln 3，b ＝sin 32，c ＝2﹣ln 2，则下列判断正确的是（ ）A ．c ＞a ＞bB ．b ＞a ＞cC ．c ＞b ＞aD ．a ＞c ＞b解：设m （x ）＝x ﹣lnx ，则当x ＞1时，m ′(x)=1−1x＞0，m(x)单调递增， 所以a ＝m （3）＞m （2）＝c ，由于c ＝2﹣ln 2＞2﹣lne ＝1，而b =sin 32＜1，所以b ＜c ， 故a ＞c ＞b ． 故选：D ．6．设一组样本数据x 1，x 2，…，x n 的极差为1，方差为0.1，若数据ax 1+b ，ax 2+b ，…，ax n +b 的极差为2，则数据ax 1+b ，ax 2+b ，…，ax n +b 的方差为（ ） A ．0.02B ．0.04C ．0.2D ．0.4解：假设两组数列是按大小顺序排序的，由题意可知，一组样本数据x 1，x 2，…，x n 的极差为1，则|x n ﹣x 1|＝1， 又数据ax 1+b ，ax 2+b ，…，ax n +b 的极差为2， 则|ax n +b ﹣（ax 1+b ）|＝|a （x n ﹣x 1）|＝2， 所以|a |＝2，故数据ax 1+b ，ax 2+b ，…，ax n +b 的方差为a 2×0.1＝22×0.1＝0.4． 故选：D ．7．已知圆台上、下底面的半径分别为1，4，高为1，现用过任意两条母线的平面去截这个圆台，则截面面积的最大值是（ ） A ．256B ．5C ．253D ．10解：如图，圆台OO1，中，设过两条母线的平面分别交上下圆面于AB和CD，因上下圆面互相平行，故有AB∥CD，则四边形ABCD为等腰梯形，分别取AB中点M，CD中点N，连接OM，O1N，则OM⊥AB，O1N⊥CD，易得OA∥O1D，OM∥O1N，故有∠AOM＝∠DO1N，不妨设∠AOM＝α，则AB＝2AM＝2sinα，CD＝8sinα，在直角梯形OO1NM中，OM＝cosα，O1N＝4cosα，故MN=√(4cosα−cosα)2+1=√9cos2α+1，则梯形ABCD的面积为：S=12(2sinα+8sinα)×√9cos2α+1=5sinα⋅√9cos2α+1=53√9sin2α(9cos2α+1)≤53×9sin2α+(9cos2α+1)2=25 3当且仅当9sin2α＝9cos2α+1时取等号，即cos2α=−19时，截面面积最大为253．故选：C．8．已知函数f（x）＝A sin（ωx+φ）（A＞0，ω＞0）的图像如图所示，则φ的一个可能值为（）A ．−π4B ．−3π4C ．π6D ．23π解：由图可知f （0）＝A sin φ＜0，又A ＞0，ω＞0， ∴sin φ＜0，∴C ，D 错误；∴f （x ）＝A sin （ωx +φ）（A ＞0，ω＞0）， ∴f ′（x ）＝A ωcos （ωx +φ），∵由图可知f ′（0）＝A ωcos φ＞0，A ＞0，ω＞0，排除B 选项． 故选：A ．二、多项选择题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求．全部选对得5分，部分选对得2分，有项选错得0分．9．已知a ，b ，c 满足a +b +c ＝0，且a ＞b ＞c ，那么下列选项中一定成立的是（ ） A ．ac ＜0B ．ab ＞acC ．c （b ﹣a ）＜0D ．2a +2b ＞2解：由于a +b +c ＝0，且a ＞b ＞c ，所以a ＞0，c ＜0，故ac ＜0，A 正确，由于b ＞c ，∴b ﹣c ＞0，又a ＞0，所以ab ﹣ac ＝a （b ﹣c ）＞0，所以ab ＞ac ，B 正确， 由于a ＞b ，∴b ﹣a ＜0，又c ＜0，所以c （b ﹣a ）＞0，故C 错误，由于a ＞b ，则2a +2b ＞2√2a+b =2√2−c ，又c ＜0，∴﹣c ＞0，因此2a +2b ＞2√2−c ＞2，D 正确． 故选：ABD ．10．已知边长为2的正六边形A 1A 2A 3A 4A 5A 6的中心为O ，则A 1O →⋅A 1A i →（i ＝2，3，4，5，6）的可能值为（ ） A ．2B ．4C ．6D ．8解：由题意，以点O 为坐标原点， 建立如图所示的平面直角坐标系，则A 1(−1，−√3)，A 2(1，−√3)，A 4(1，√3)，A 5(−1，√3)，A 3(2，0)，A 6(−2，0)，O(0，0)， A 1O →=(1，√3)，A 1A 2→=(2，0)，A 1A 3→=(3，√3)，A 1A 4→=(2，2√3)，A 1A 5→=(0，2√3)，A 1A 6→=(−1，√3)，故A 1O →⋅A 1A 2→=2，A 1O →⋅A 1A 3→=3+3=6，A 1O →⋅A 1A 4→=2+6=8， A 1O →⋅A 1A 5→=6，A 1O →⋅A 1A 6→=−1+3=2，则A 1O →⋅A 1A i →（i ＝2，3，4，5，6）的可能值为2，6，8． 故答案为：ACD ．11．已知函数f （x ）＝x 3﹣3x 2+1，则下列说法正确的是（ ） A ．函数f （x ）有三个单调区间B ．函数y ＝f （x +a ）的极大值与极小值之和为﹣4C ．关于x 的方程f （x ）﹣ax ＝0不可能有三个实数解D ．存在直线与函数y ＝f （x ）的图像从左至右有三个交点，且它们横坐标成等差数列 解：因为f （x ）＝x 3﹣3x 2+1，可得f ′（x ）＝3x 2﹣6x ＝3x （x ﹣2）， 令f ′（x ）＝0，解得x ＝0或x ＝2， 当x ＜0时，f ′（x ）＞0，f （x ）单调递增； 当0＜x ＜2时，f ′（x ）＜0，f （x ）单调递减； 当x ＞2时，f ′（x ）＞0，f （x ）单调递增，所以f （x ）的单调递增区间为（﹣∞，0），（2，+∞），单调递减区间为（0，2），所以A 正确； 当x ＝0时，函数f （x ）取得极大值，极大值为f （0）＝1， 当x ＝2时，函数f （x ）取得极小值，极小值为f （2）＝﹣3，将函数y ＝f （x ）的图像向左平移a 个单位得到函数y ＝f （x +a ）的图像， 所以函数y ＝f （x +a ）与函数y ＝f （x ）有相同的极值，所以y ＝f （x +a ）的极大值与极小值之和为﹣2，所以B 不正确； 由函数y ＝f （x ）的图像与x 轴有三个不同的交点，所以，当a ＝0时，方程f （x ）﹣ax ＝0有三个不同的实数根，所以C 不正确； 令f （x ）＝﹣x ，可得x 3﹣3x 2+1＝﹣x ，即x 3﹣3x 2+x +1＝0， 设方程x 3﹣3x 2+x +1＝0三个根从大到小分别为x 1，x 2，x 3，因为x 3﹣3x 2+x +1＝（x ﹣1）（x 2﹣2x ﹣1）＝0，可得x 1+x 3＝2，x 2＝1， 所以2x 2＝x 1+x 3，所以x 1，x 2，x 3构成等差数列，所以D 正确． 故选：AD ．12．一个盒子里放着大小、形状完全相同的1个黑球、2个白球、2个红球，现不放回地随机从盒子中摸球，每次取一个，直到取到黑球为止，记摸到白球的个数为随机变量ξ，则下列说法正确的是（）A．P(ξ=0)=14B．P(ξ=1)=12C．P(ξ=1)=13D．P(ξ=2)=13解：A选项，ξ＝0，分为第一次即取到黑球，或第一次摸到红球，第二次摸到黑球，或前两次均摸到红球，第三次摸到黑球，故P(ξ=0)=15+25×14+25×14×13=13，A错误；BC选项，ξ＝1，即第一次摸到白球，第二次摸到黑球，或前两次一次摸到红球，一次摸到白球，第三次摸到黑球，或前三次有两次摸到红球，一次摸到白球，第四次摸到黑球，故P(ξ=1)=25×14+2×25×24×13+3×25×14×23×12=13，B错误，C正确；D选项，ξ的所有可能有0，1，2，故P(ξ=2)=1−P(ξ=0)−P(ξ=1)=13，D正确．故选：CD．三、填空题：本题共4小题，每小题5分，共20分．请把答案直接填写在答题卡相应位置上．13．（1+x）（1+2x）5的展开式中x6的系数为32．解：（1+x）（1+2x）5＝（1+2x）5+x（1+2x）5，故（1+x）（1+2x）5的展开式中x6的项只能是x（1+2x）5中出现的x6，由于x（1+2x）5中含x6的项为x（2x）5＝32x6，（1+x）（1+2x）5的展开式中x6的系数为32．故答案为：32．14．已知等差数列{a n}前3项和S3＝12，a1﹣1，a2﹣1，a3+3成等比数列，则数列{a n}的公差d＝﹣6或2．解：由S3＝12，可知a1+a2+a3＝3a2＝12，即a2＝4，又a1﹣1，a2﹣1，a3+3成等比数列，所以(a2−1)2=(a1−1)⋅(a3+3)=(a2−d−1)⋅(a2+d+3)，即9＝（3﹣d）•（7+d），解得d＝2或d＝﹣6．故答案为：﹣6或2．15．现有10张奖券，有且仅有2张为有奖奖券，甲、乙两人轮流依次不放回地抽取奖券，甲先抽取，然后乙再抽取为一个轮次．则在第一轮甲、乙都未中奖的条件下，第二轮甲、乙都中奖的概率为 128．解：设事件A 为在第一轮甲、乙都未中奖，事件B 为第二轮甲、乙都中奖， 则P(A)=810×79=2845， P(AB)=810×79×28×17=145， 所以P(B|A)=P(AB)P(A)=145×4528=128． 故答案为：128． 16．已知双曲线x 2a 2−y 2b 2=1(a ＞0，b ＞0)，过点A （2a ，0）作双曲线的一条渐近线的垂线，垂足为M ，直线AM 与双曲线的左支交于点N ，且2AN →=5AM →，则双曲线的离心率为 √152． 解：不妨设双曲线的渐近线为y =ba x ，则直线AM 为y =−ab (x −2a)，由{y =b a x y =−a b (x −2a)，得{x =2a 3c 2y =2a 2b c2，即M(2a 3c 2，2a 2b c 2)， 设点N （x 0，y 0），则AN →=(x 0−2a ，y 0)，AM →=(2a 3c 2−2a ，2a 2bc2)，∵2AN →=5AM →，∴{2(x 0−2a)=5(2a 3c 2−2a)2y 0=5⋅2a 2bc2，解得{x 0=5a 3−3ac 2c 2y 0=5a 2b c2，即N(5a 3−3ac 2c 2，5a 2bc2)，由点N 在双曲线x 2a 2−y 2b 2=1上，代入得(5a 3−3ac 2c 2)2a 2−(5a 2bc 2)2b 2=1，整理得c 2a 2=154，则e =√152．故答案为：√152．四、解答题：本题共6小题，共70分．请在答题卡指定区域内作答．解答时应写出文字说明、证明过程或演算步骤．17．（10分）已知数列{a n }的前n 项和为S n ，且a n +2S n =n 2+2n ． （1）求证：数列{a n ﹣n }是常数列； （2）求数列{2n •a n }的前n 项的和． 解：（1）证明：因为a n +2S n =n 2+2n①， 所以a n−1+2S n−1=(n −1)2+2(n −1)②， ①﹣②得：3a n ﹣a n ﹣1＝2n +1， 在①中，令n ＝1，得a 1+2S 1＝3， 即3a 1＝3，所以a 1＝1，因为3（a n ﹣n ）＝a n ﹣1﹣（n ﹣1），a 1﹣1＝0， 所以a n ﹣n ＝0，所以数列{a n ﹣n }是常数列；（2）设数列{2n •a n }的前n 项的和为T n ，由（1）得：a n ＝n ， T n =2+2⋅22+3⋅23+⋯+n ⋅2n ①，2T n =22+2⋅23+⋯+(n −1)⋅2n +n ⋅2n+1②， ①﹣②得：−T n =2+22+23+⋯+2n−n ⋅2n+1=2(1−2n)1−2−n ⋅2n+1=(1−n)⋅2n+1−2，所以T n =(n −1)⋅2n+1+2．18．（12分）已知在△ABC 中，角A ，B ，C 所对的边分别为a ，b ，c ，cosCcosB−cosC +sinCsinB−sinC =0． （1）若C =π3，求角A ； （2）若b ＝3，c ＝4，求a 的值． 解：（1）因为cosC cosB−cosC +sinC sinB−sinC=0，所以cos C （sin B ﹣sin C ）+sin C （cos B ﹣cos C ）＝0， 即sin B cos C +cos B sin C ＝2sin C cos C ，即sin（B+C）＝sin2C．因为A+C+B＝π，所以sin A＝sin2C．因为A∈（0，π），2C∈（0，2π），所以A＝2C或A+2C＝π．由题意知C=π3，则当A＝2C时，A=23π，此时A+C＝π，这与A+C+B＝π矛盾，故舍去．当A+2C＝π时，因为A+C+B＝π，所以B=C=π3，所以A=π3．综上可得：A=π3．（2）因为b＝3，c＝4即b≠c，则B≠C．由（1）可得A＝2C．因为sin A＝sin2C所以sin A＝2sin C cos C在△ABC中，由正弦定理得：a＝2c cos C．因为cosC=a2+b2−c22ab，所以a=2c×a2+b2−c22ab．因为b＝3，c＝4所以a=2√7．19．（12分）如图所示，直三棱柱ABC﹣A1B1C1中，AB＝AC＝4，AA1＝6，BC=4√2，M，N分别是对角线BC1，A1C的中点．（1）证明：MN∥面ABC；（2）求二面角A1﹣MN﹣C1的正弦值．解：（1）证明：连接AC1，交A1C于N′，在直三棱柱ABC﹣A1B1C1中，侧面ACC1A1为平行四边形，因为AC1，A1C是平行四边形的对角线，所以N'为A1C的中点，所以N与N′重合，所以N为AC1的中点，在△C1AB中，因为M，N分别是BC1，AC1的中点，所以MN ∥AB ，因为MN ⊄平面ABC ，AB ⊂平面ABC ， 所以MN ∥平面ABC ．（2）在△ABC 内，因为AB ＝AC ＝4，BC =4√2， 所以AB 2+AC 2＝BC 2，所以AB ⊥AC ，在直三棱柱ABC ﹣A 1B 1C 1中，AA 1⊥平面ABC ， 因为AB ，AC ⊂平面ABC ， 所以AA 1⊥AB ，AA 1⊥AC ，以{AB →，AC →，AA 1→}为正交基底，建立如图所示的空间直角坐标系O ﹣xyz ，则A （0，0，0），B （4，0，0），C （0，4，0），A 1（0，0，6），C 1（0，4，6），M （2，2，3），N （0，2，3），所以A 1M →=(2，2，−3)，A 1N →=(0，2，−3)，C 1M →=(2，−2，−3)，MN →=(−2，0，0)， 设平面A 1MN 的一个法向量为n →=(x 0，y 0，z 0)， 因为n →⊥A 1M →，n →⊥A 1N →，所以{n →⋅A 1M →=2x 0+2y 0−3z 0=0n →⋅A 1N →=2y 0−3z 0=0， 令z 0＝2，则y 0＝3，x 0＝0， 所以n →=(0，3，2)，设平面C 1MN 的一个法向量为m →=(a ，b ，c)， 则{m →⋅C 1M →=2a −2b −3c =0m →⋅MN →=−2a =0， 令c ＝2，则b ＝﹣3，a ＝0，所以C 1MN 的一个法向量为m →=(0，−3，2)， 设二面角A 1﹣MN ﹣C 1为θ，θ∈[0，π]，则|cosθ|=|cos〈m →，n →〉|=|m →⋅n →||m →||n →|=5√13√13=513，所以sinθ=√1−cos 2θ=1213，综上所述：二面角A 1﹣MN ﹣C 1的正弦值为1213．20．（12分）2023年9月25日，在富阳银湖体育中心举行的杭州亚运会射击项目男子25米手枪速射团体决赛中，中国队以1765环的总成绩击败韩国队夺得冠军，并打破世界纪录．现已知男子25米手枪速射决赛规则如下：取资格赛前6名选手进入决赛，5发子弹为一组，每发子弹9.7环以上得1分，否则得0分．若进入决赛的每位选手每组能得5分与4分概率分别为0.6，0.4． （1）求某位进入决赛的选手三组射击后得分为14分的概率；（2）设某位进入决赛的选手三组射击后得分为随机变量ξ，求随机变量ξ的分布列与期望． 解：（1）“某位进入决赛的选手三组射击后得分为14分”记事件A ，所以P(A)=C 32(35)2×25=54125，即某位进入决赛的选手三组射击后得分为14分的概率为54125；（2）由题可得，随机变量ξ的可能取值为12，13，14，15，则P(ξ=12)=(25)3=8125，P(ξ=13)=C 31(25)2×35=36125， P(ξ=14)=C 32(35)2×25=54125，P(ξ=15)=(35)3=27125，所以随机变量ξ的分布列为：则E(ξ)=12×8125+13×36125+14×54125+15×27125=695． 21．（12分）已知A ，B ，C 为椭圆x 22+y 2=1上的三个不同的点，且线段AB 的中点在直线x ＝1上．（1）若线段AB 的中点坐标为(1，√24)，求直线AB 的斜率；（2）F 为椭圆右焦点，且满足FA →+FB →+FC →=0→，求直线AB 的方程． 解：（1）设A （x 1，y 1），B （x 2，y 2），线段AB 的中点为H ，直线AB 、OH 的斜率分别为k AB ，k OH ，因为点A ，B 在椭圆上，所以{x 122+y 12=1①x 222+y 22=1②， ①﹣②得：k AB ⋅k OH =−12，所以k AB =−12×2√2=−√2． （2）因为FA →+FB →+FC →=0→，所以F 为△ABC 的重心，因为F （1，0），线段AB 的中点在直线x ＝1上， 设A （x 1，y 1），B （x 2，y 2），C （x 3，y 3）， 所以x 1+x 2+x 33=1，y 1+y 2+y 33=0，因为x 1+x 2＝2，所以x 3＝1，代入有12+y 32=1， 所以|y 3|=√22②（分类讨论），设AB ：y ＝kx +m 与x 22+y 2=1联立，有（2k 2+1）x 2+4kmx +2m 2﹣2＝0，Δ＝16k 2m 2﹣8（2k 2+1）（m 2﹣1）＝﹣8（﹣2k 2+m 2﹣1）＞0， 所以x 1+x 2=−4km 2k 2+1=2；x 1x 2=2m 2−22k 2+1，y 1+y 2＝k （x 1+x 2）+2m =2m 2k 2+1，①当y 3=√22时，y 1+y 2=−√22，因为x 1+x 2＝2， 所以﹣2km ＝2k 2+1， 所以2m 2k 2+1=−√22，所以k=√2，m=−5√2 4．②当y3=−√22时，y1+y2=√22，所以k=−√2，m=5√2 4．综上：直线AB的方程为4x+2√2y−5=0或4x−2√2y−5=0．22．（12分）已知f（x）＝xlnx+a（x﹣1）（a∈R）．（1）试判断函数g(x)=f(x)x的单调性；（2）若函数y＝f（x）有且只有一个零点，求实数a的取值范围．解：（1）由函数f（x）＝xlnx+a（x﹣1）得，g(x)=lnx−ax+a，所以g′(x)=1x+ax2=x+ax2(x＞0)，当a≥0时，因为g′（x）＞0，所以函数g（x）在（0，+∞）上为增函数；当a＜0时，函数g（x）在（0，﹣a）上为减函数，在（﹣a，+∞）上增函数．综上所述：①当a≥0时，函数g（x）为增函数；②当a＜0时，函数g（x）在（0，﹣a）上为减函数，在（﹣a，+∞）上为增函数．（2）若函数f（x）有且只有一个零点，则函数g（x）有且只有一个零点，且g（1）＝0，由（1）知：当a≥0时，函数g（x）为增函数，此时只有一个零点，满足题意；当a＜0时，①a＜﹣1时，因为函数g（x）在（0，﹣a）上为减函数，所以g（﹣a）＜g（1）＝0，因为g(e−a)=−ae−a＞0，因为函数g（x）在（﹣a，+∞）上为增函数，所以∃唯一x0∈(−a，e−a)，使g（x0）＝0，所以函数g（x）恰有两个零点，不满足题意；②﹣1＜a＜0时，因为函数g（x）在（﹣a，+∞）上为增函数，所以g（﹣a）＜g（1）＝0，g((−aa+2)2)=ln(−aa+2)2+a[1−(a+2−a)2]＞2−2−aa+2+a[1−(a+2−a)2]=0，因为(−aa+2)2−(−a)=a(a+4)(a+1)(a+2)2＜0，函数g（x）在（0，﹣a）上为减函数，所以∃唯一x1∈(a2(a+2)2，−a)，使g（x1）＝0，所以函数g（x）恰有两个零点，不满足题意；③a＝﹣1时，函数g（x）在（0，1）上为减函数，在（1，+∞）上为增函数，所以g（x）min＝g（﹣1）＝0，函数g（x）有且只有一个零点，满足题意．综上所述：实数a的取值范围为{a|a＝﹣1或a≥0}．。
江苏省常州市联盟学校2023-2024学年高三上学期12月学情调研英语试卷(含答案)
常州市联盟学校2023—2024学年度第一学期学情调研高三年级英语试卷2023.12考试时间120分钟本试卷共四大题满分150分第一部分听力（共两节，满分30分）第一节：（共5小题；每小题1.5分，满分7.5）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What will Matthew do on the weekend?A. Attend an exhibition.B. Enter a contest.C. Visit China.2. Where do the speakers want to go?A. To a supermarket.B. To a bank.C. To a restaurant.3. When will the man see the film?A. At 1:30 p.m.B. At3:30 p.m.C. At 5:30 p.m.4. What are the speakers mainly talking about?A. A noisy night.B. A place of living.C. Their sleeping habits.5. Why did the man call the woman last night?A. To give her fruits.B. To invite her to a party.C. To ask for her cousin's number.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
江苏省苏州市2023-2024学年高三上学期期末摸底调研英语试题
江苏省苏州市2023-2024学年高三上学期期末摸底调研英语试题学校:___________姓名：___________班级：___________考号：___________一、阅读选择The Best Podcasts for EveryoneA podcast is a sound file similar to a radio broadcast, which can be downloaded and listened to on a computer or iPod. You can find a podcast about almost anything these days, but you might need a helping hand to find the podcasts worthy of your ear. Our expertly chosen list will entertain and educate you, whether you’re doing the dishes, working out, or relaxing in the bath.1. Revisionist HistoryIn this mix of strange stories, Malcolm Gladwell, a famous writer, handles misunderstood events and rarely discussed ideas, covering subjects like Toyota’s car recall and even the firebombing of Tokyo at the end of World War II. Gladwell freely mixes research and opinion and enjoys challenging conventional views, but every episode serves up facts and stories you have likely never heard before.2. The ReadKid Fury and Crissle West, famous comedians, review the latest pop culture news and offer their opinions on everything. Funny and challenging, these conversations run for a couple of hours, covering recent events and frequently touching on social justice, mental health and race.3. Forever35Forever35 started as a physical self-care podcast but expanded to discuss mental health, relationships, and any other topic that appeals to writers Doree Shafrir and Kate Spencer. They go from chatting about skin creams to seasonal emotional disorder—but always in a fun, inclusive, and down-to-earth way.4. Hidden BrainAn absorbing deep dive into human behavior related to brains with the help of scientists, Hidden Brain is packed with informative messages. The host, National Public Radio’s accomplished science journalist Shankar Vedantam, makes complex ideas accessible.5. The Infinite Monkey CageThis show, hosted by physicist Brian Cox and comedian Robin Ince, raises questions like “Does time exist?”—which are then debated by a diverse panel of three guests, usually a mix of experts and entertainers. Definite answers are in short supply, but it’s always accessible, enthusiastic, and makes audience think deeply.Special offer for readers: Get a 1-year subscription to WIRED for $5 ($25 off). This includes unlimited access to WIRED．com. If you buy something using links in our stories, this helps support our work.1．What is this text?A．A book review.B．A course plan.C．An academic article.D．An online advertisement.2．How many podcasts are associated with natural science?A．Two.B．Three.C．Four.D．Five. 3．Which podcast interests listeners who want to stay young and healthy?A．The Read.B．Forever35.C．Hidden Brain.D．The Infinite Monkey Cage.The latest data shows the population of wild Asian elephants in southwest China’s Yunnan Province has increased from around 150 to more than 300 from the 1980s to the end of 2021, according to the National Forestry and Grassland Administration.With the growth in the elephant population, conflicts between humans and elephants have become frequent. In order to fundamentally and peacefully solve the issue and protect the elephant’s habitat at the same time, construction of the Asian elephant National Park is picking up speed. Experts suggest that national parks are not meant to be entirely free of people. Instead, they should offer a method for coexistence.Asian elephants play an important role as engineers of the rainforest, said the expert. Their migration(迁徙) can speed up the replacement of forest ecosystems along the way. Elephant waste remains not only a delicacy for insects, but also attracts insectivorous birds, allowing plant seeds to spread. Therefore, protecting the elephants and their habitats guarantees the shelter to other wildlife in forest ecosystems.To cope with human-elephant conflicts, Yunnan took the lead in introducing a commercial insurance model into its compensation(补偿) system: local residents will be paid with the amount of money for the crops destroyed by the elephants by the insurance company. In the past 10 years, Yunnan has paid a total of 173 million yuan for losses caused by Asian elephants.“The standard of compensation is constantly being adjusted, and the amount of insurance coverage for compensation is also increasing,” said Yang Hua from the Forestry and Grass Bureau of Yunnan Province. “At present, the insured amount in Pu’er City and Xishuangbanna Prefecture alone has already gone beyond 50 million.”4．Why does the author mention the growing population of wild Asian elephants?A．To promote a better environment.B．To introduce a possible crisis.C．To applaud the efforts of the government.D．To stress the importance of the elephants.5．What does the underlined word “insectivorous” mean in paragraph 3?A．Feeding on insects.B．Driving away insects.C．Letting go of insects.D．Keeping track of insects.6．What has been done to tackle conflicts between elephants and humans?A．Construction of undisturbed national parks.B．Support of Asian elephants’ migration.C．Constant adjustment of insurance policies.D．Guarantee of the shelter to other wildlife.7．What might be the best title?A．Asian elephants, engineers of the rainforestB．Insurance adjusted, compensation increasedC．Population of wild Asian elephants shoots up in ChinaD．China explores solutions to achieve human-elephant harmonyCities are difficult to navigate (导航) at the best of times, but for people with disabilities they can be like courses with hurdles and bring inconvenience to disabled people.A UK national travel survey found that adults with mobility difficulties took 39% fewer trips than those with no disability in 2017. Yet that could change as devices and cities grow smarter. Assistive tech is playing a big role in the transformation. The global value of the industry is expected to increase from $14 billion in 2015 to $30.8 billion in 2024, according to Zion Market Research.One of the things that could transform lives is a smart walking stick designed by engineers from Young Guru Academy (YGA) in Turkey. The WeWalk stick has a sensor that detects hurdles above chest level and uses vibrations (振动) to warn the user. It can be paired with a smartphone to help navigation, and is connected with a voice assistant and Google Maps.Ceylan, who has been blind since birth, says that connecting the stick to the Internet of Things and smart city solutions makes it user-friendly. “As a blind person, when I am at the Metro station I don’t know which is my exit ... I don’t know which bus is approaching ... which stores are around me. That kind of information can be provided with the WeWalk,” he says.“The smart walking stick is really an exciting initiative that will make a huge difference to some people,” says Anna Lawson, the director of the Center for Disability Studies at Leeds University in the United Kingdom. “But they are very expensive ... they’re not going to be available to the vast majority of disabled people,” she added.Bryan Matthews, a lecturer at the Institute for Transport Studies at the University of Leeds, shares the concerns about cost. He says there should also be a focus on inclusive design, and anything that helps people navigate their environment is positive.8．What does “that” in the second paragraph refer to?A．The survey that compared adults’ mobility.B．The smart industry that is booming.C．The fact that the disabled traveled less.D．The role that the assistive tech plays.9．What does paragraph 3 mainly talk about?A．The working principles of the WeWalk stick.B．The introduction of the WeWalk stick inventors.C．The transformation caused by the WeWalk stick.D．The benefits brought about by the WeWalk stick.10．What’s the purpose of quoting Ceylan?A．To show the value of smart tech.B．To urge more attention to the blind.C．To increase the potential market share.D．To encourage tech research and development.11．What is the disadvantage of the WeWalk stick?A．Confusing instructions.B．Poor navigation.C．Inclusive designs.D．High prices.What strategy do you use to make tough life decisions like whether to end a relationship, quit your job, or go back to school? Maybe you weigh the advantages and disadvantages. Maybe you go with your sixth sense. Or maybe, if you’re like most people, you simply do nothing. After all, we have a tendency to prefer the status quo (现状), and focus more on the potential losses involved with change rather than the potential benefits.But here’s a simpler strategy: When you’re indecisive about a big life decision, choose the path of change. That’s the takeaway of research recently published by Steven Levitt, an economist at the University of Chicago.For the study, Levitt asked people who were facing tough decisions to flip(抛) a digital coin on the website . The coin tosses were randomized, with one side representing change, the other status quo. The study asked more than 20,000 participants to make whichever decision the coin toss directed, and then report back on how things played out after two and six months.Of course, not everyone followed through. The two-month survey found that participants chose change less frequently than they had initially predicted they would. After six months, however, this tendency toward inaction disappeared. But most surprising were the results on well-being. At both the two and six-month marks, most people who chose change reported feeling happier, better off, and that they had made the correct decision.The study had some limitations. One is that its participants weren’t selected randomly. Another limitation is that participants whose decision didn’t play out well might have beenless likely to report back on their status after two and six months. Still, the study does suggest that people who are on the edge of a tough decision are probably better off going with change. Levitt isn’t suggesting you flip a coin to make all decisions. But coin-flipping does seem to have some benefits. Levitt notes that some people might prefer giving in to their fate to randomness in order to avoid regret. But you can also use randomness a bit more sensibly. When facing a tough decision, you could flip a coin and, upon seeing the outcome, notice whether you feel relief or fright. If you feel relieved, that’s probably the path you should choose.12．What is most people’s priority when making hard choices?A．Calculating potential losses.B．Valuing potential benefits.C．Following inner voice of one’s mind.D．Making a change to the status quo.13．What are the findings of the two surveys?A．Making changes brought most participants happiness.B．All participants gave immediate feedback on their status.C．Participants’ action agreed with their initial prediction.D．More participants remained inactive after six months.14．What is a limitation of the study?A．The randomness of picking study subjects.B．The incorrect method of flipping a coin.C．The insufficiency of study statistics.D．The insensible outcome of the analysis.15．What is the main idea of the passage?A．Coin flips are beneficial to making hard choices.B．When facing a hard decision, choose the status quo.C．A study justifies making hard choices with randomness.D．A study offers a strategy for making hard decisions.you live, many of us are vaccinated (打疫苗). But it’s hard to know for sure before you hug whether or not the person you’re leaning into has got vaccinated. Meanwhile, many of us arelonging for the warmth of a hug after long stretches of social isolation. Humans biologically need touch, and a good long hug is one of the best ways to get it.Degge White, a professor at Northern Illinois University, says that our need for a hug goes all the way back to the survival of our species. When we’re born, we can’t care for ourselves and we need to be comfortable with being held in order to survive. 17 “When we hug, our brains release oxytocin, the bonding hormone (荷尔蒙), as well as serotonin and endorphins.”18 Because for humans, the security of our small groups and later communities was very important to survival. Close contact helped build civilization. As a result, our brains need each other—and when we miss out, it can have psychological repercussions (心理影响). “When we can’t hug, we don’t get that feeling of good hormones.”We may not know what we’re getting from greeting our friends and family with a hug; we just enjoy it. 19 An air greeting is not enough. Research published in the journal Psychological Science has shown that hugging has a “stress buffering (缓冲)” effect that may even protect us from illness and infections.Some people grow up in more formal households where hugging isn’t common. Others may experience abuse that makes hugging unpleasant. In both cases, when children don’t experience healthy touch, it can impact their development. Kids who didn’t grow up being held miss out on that sense of safety and protection. They may act out or isolate from those around them. 20 Some children may show too much affection, desiring any form of positive attention that they didn’t get at home.A．In some cases, the opposite may also be true.B．This bond and sense of community has an important role.C．We’re in an uncertain place in the world of greetings manner.D．It isn’t until those experiences are taken away that we feel pain and sadness.E．When friends reach out in preparation for a hug, they feel hormones increasing.F．We’re rewarded with a rush of feel-good chemicals that come from a comfortable hug.G．The lack of touching might imply cold attitudes in interpersonal relationships.二、完形填空I never imagined that an interstate trip could be so exciting.But when your world has become smaller since the pandemic hit two-and-a-bit years ago, and then slowly 21 , the most ordinary experience gives new 22 to life. And so it was with me when I was 23 given the chance to take my first flight in more than two years.I’d forgotten how it felt to be among the people coming and going. I got to the airport two hours before boarding. Time for the bar and, of course, 24 .That group of young Arab women laughing and posing for photographs by the expansive windows, aircraft in the 25 , lighting up the place with their happiness.The man in the corner drinking alone. Just another one of the 70,000 or so stories that would pass through the airport 26 .I’ve never been a calm flyer. But when the plane took off I was 27 , in that moment of weightlessness as the wheels 28 Earth, leaning towards the window to watch everything below becoming smaller and smaller.Is it possible that the denial of so much during the pandemic lockdown had added new 29 to what was the ordinary? I think so. The plane ride, the hotel stay, and the social occasion all now gave me a sense of 30 that might have previously only aroused in me nothing more than a certain nonchalance(若无其事)or even 31 .Last June, just ahead of the long Sydney lockdown, a friend 32 a birthday party. That experience for me would continue happily through some of the 33 months of the lockdown that would follow. 34 the repeated fear that the pandemic holds over us, the memory of that celebration still keeps its bright, warm light in my mind. That’s what happens when everything old is new again, when 35 is rediscovered as a virtue. 21．A．disappears B．expands C．escapes D．emerges 22．A．change B．outcome C．panic D．meaning 23．A．finally B．merely C．originally D．frequently 24．A．book-reading B．stranger-chatting C．story-telling D．people-watching 25．A．circumstance B．background C．situation D．maintenance 26．A．on a daily basis B．once in a while C．in a special wayD．all of a sudden27．A．anxious B．elegant C．excited D．energetic 28．A．slid B．attached C．floated D．departed29．A．liberation B．company C．struggle D．appeal 30．A．fear B．joy C．regret D．chaos 31．A．tiredness B．happiness C．kindness D．brightness 32．A．held B．cancelled C．attended D．forgot 33．A．permanent B．harmonious C．difficult D．dynamic 34．A．Apart from B．Despite C．Similar to D．Without 35．A．opportunity B．superiority C．equality D．simplicity三、语法填空阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式。
2023_2024学年江苏省南通市海门市高三上册第二次月考英语模拟测试卷(附答案)
2023_2024学年江苏省南通市海门市高三上册第二次月考英语模拟测试卷注意事项：1. 答卷前，考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上。
2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其它答案标号。
回答非选择题时，将答案写在答题卡上，写在本试卷上无效。
3.考试结束后，将本试卷和答题卡一并回交。
第一部分听力(共两节，满分30分)做题时，先将答案标在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题; 每小题1.5 分,满分7.5分)听下面 5 段对话。
每段对话后有一个小题，从题中所给的 A、B、C 三个选项中选出最佳选项。
听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What are the speakers likely to do?A. Move into a big house.B. Adopt a cat.C. Do some shopping.2. Why is the man unhappy with Elena?A. She didn't get a good score in a test.B. She was absent from class yesterday.C. She talked to her deskmate in class.3. What is the woman's attitude towards the man's request?A. Supportive.B. Disapproving.C. Ambiguous.4. Where does the conversation probably take place?A. In a restaurant.B. At a travel agency.C. In a hotel.5. What is the conversation mainly about?A. A dream.B. Love stories.C. Time travel.第二节(共15 小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
【高三英语】Z20名校联盟2023-2024学年高三上学期第一次联考英语试题(解析版)
Z20名校联盟（浙江省名校新高考研究联盟）2023-2024学年高三上学期第一次联考英语试题学校:___________姓名：___________班级：___________考号：___________二、阅读理解The ebike has become an essential item, and even the King has been spotted riding one. According to the market research company Mintel, sales have almost tripled over the past five years. While ebikes have become increasingly commonplace, they are still undeniably expensive. You can pick up a perfectly adequate push bike for £300, but most ebikes cost nearly £2,000. Now, Cycling Electric, designed to help consumers choose an ebike, offers the following recommendations.Best folding bikeCarbo Model XPrice: £2, 799 | Weight: 13.3kgRange: up to 34 milesThis is one of the most convenient bikes, from a little-known label. The lightweight Carbo X is the perfect example of convenience thanks to its carbon frame and belt drive, instead of a metal bike chain. This makes it lighter and less likely to get messy than an electric Brompton, with its more traditional, oily chain.Most stylishTemple Cycles ClassicPrice: from £2, 995 | Weight: 19kgRange: up to 74 milesThis Bristol-based brand is known for its elegant pushbikes, which are hand-built in the city.This is its electric version. It’s a very sleek and functional commuter option and not too heavy. Temples have fewer proprietary (品牌专卖的) parts and so are serviceable in any bike shop. Stylish as they may be, the VanMoofs and the Cowboys can be a bit more complex to get back-up and service.The money-no-object optionRiese & Müller Nevo4 GT Vario GXPrice: £5, 380 | Weight: 28.4kgRange: up to 93 milesThis is a prime example of the attention to detail delivering a high-quality experience in functionality, comfort and practicality — if you can afford it. It has the capacity to handle 25kg of luggage in a pannier, powerful road lights and a beautifully smooth motor.21．What is the advantage of the Temples over other stylish ebike brands?A．They are more lightweight. B．They have more functions.C．They have easier access to service. D．They are more comfortable.22．Which ebike will a consumer probably choose, who cares most about an excellent experience?A．Carbo Model X. B．The VanMoofs and the Cowboys.C．Temple Cycles Classic. D．Riese & Müller Nevo4 GT Vario GX. 23．Where is the text probably taken from?A．An online post. B．A magazine column.C．A market research report. D．An official document.【答案】21．C 22．D 23．B【导语】本文是一篇应用文，主要介绍的是Cycling Electric推荐的三款电动自行车。
2023-2024学年江苏省南通市如皋市高三化学第一学期期末教学质量检测模拟试题含解析
2023-2024学年江苏省南通市如皋市高三化学第一学期期末教学质量检测模拟试题请考生注意：1．请用2B铅笔将选择题答案涂填在答题纸相应位置上，请用0．5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
写在试题卷、草稿纸上均无效。
2．答题前，认真阅读答题纸上的《注意事项》，按规定答题。
一、选择题(共包括22个小题。
每小题均只有一个符合题意的选项）1、配制一定物质的量浓度的NaOH溶液时，下列因素会导致溶液浓度偏高的是A．溶解时有少量液体溅出B．洗涤液未全部转移到容量瓶中C．容量瓶使用前未干燥D．定容时液面未到刻度线2、以太阳能为热源，热化学硫碘循环分解水是一种高效、环保的制氢方法，其流程图如下：相关反应的热化学方程式为：反应I：SO2(g) + I2(g) + 2H2O(l)＝2HI(aq) + H2SO4(aq)；ΔH1 =﹣213 kJ·mol-1反应II：H2SO4(aq) ＝SO2(g) + H2O(l) +1/2O2(g)；ΔH2 = +327 kJ·mol-1反应III：2HI(aq) ＝H2(g) + I2(g)；ΔH3 = +172 kJ·mol-1下列说法不正确的是（）A．该过程实现了太阳能到化学能的转化B．SO2和I2对总反应起到了催化剂的作用C．总反应的热化学方程式为：2H2O(l)＝2H2 (g)+O2(g)；ΔH= +286 kJ·mol-1D．该过程降低了水分解制氢反应的活化能，但总反应的ΔH不变3、一种钌(Ru)基配合物光敏染料敏化太阳能电池的原理及部分反应如图所示，下列说法错误的是A．该电池将太阳能转变为电能B．电池工作时，X极电势低于Y极电势C．在电解质溶液中RuⅡ再生的反应为：2RuⅢ+3I-=2RuⅡ+I3-D．电路中每通过2mol电子生成3molI-，使溶液中I-浓度不断增加4、从制溴苯的实验中分离出FeBr 3溶液，得到溴的苯溶液和无水FeCl 3。
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2023－2024学年江苏省南通市如皋市度高三上学期调研（一）英语试题 Four beautiful trips combining bikes and trains Ohio and Erie Canal Towpath Trail (小径) The trail is an 87-mile pathway from Cleveland to Bolivar in Northeast Ohio. The Cuyahoga Valley Scenic Railroad (CVSR) stretches out separately along the trail from Akron to Thornburg Station, a 31-mile stretch that passes through Cuyahoga Valley National Park. The trail hugs the outline of the original Ohio and Erie Canal. Today, the trail passes many landmarks, including bridges, museums, and villages.
Danube Cycle Path It is a path that follows the Danube River for about 745 miles, from Donaueschingen, Germanny to Budapest, Hungary. The path is most popular in Austria featuring 245 scenic miles serviced by local and long-distance trains. Most cyclists choose to ride from west to cast with the flow of the river, to take advantage of the natural slope (斜坡) of bicycle traffic.
Lehigh Gorge Rail Trail The tail extends for 25 miles through woodlands next to the Lehigh Rive. A historic tourist railway called the Lehigh Gorge Scenic Railway follows the trail, allowing cyclists to create a one- way ride rather than backtracking. The rail trail is mostly flat and passes through Lehigh Gorge State Park. While the train operates most days, the bike service is only offered one weekend a month from May to November.
Cinder Track The Cinder Track is a 21-mile broken-stone pathway along the coast of Yorkshire, England: The towns of Scarborough and Whitby, where the trail begins and ends, both have train stations near the trail. The train journey is not a direct pathway between the two towns—in fact, the tracks of the original direct pathway were removed to create the trail. The trail, meanwhile, hugs the Yorkshire coast, with views of seaside bluffs (峭壁), fishing villages, etc.
1. What is special about the Ohio and Erie Canal Towpath Trail? A．It offers a chance to visit museums. B．It goes past many cities and villages. C．It shares most of its trail with CVSR. D．It provides cyclists with a view of the sea. 2. What’s the disadvantage of the Lehigh Gorge Rail Trail for cyclists? A．The numerous sharp slope. B．The extremely rough path. C．The connection with a railway. D．The time limit of bike service. 3. Which of the following covers the longest distance? A．The Cinder Track. B．The Danube Cycle Path. C．The Lehigh Gorge Rail Trail. D．The Ohio and Erie Canal Towpath Trail.
Born in an unknown village in Huarong county, Hunan province, Yi had few opportunities to play instruments when he was young.
At the age of 6, when most performers have already begun studying the piano at music academies, Yi learned the traditional stringed instrument the erhu from a group of people lodging at his home. It was not until much later that he first saw a piano when he visited his cousin’s house in Huarong.
“My family was too poor to buy a piano for me, so I often used to visit my cousin, even though it took about an hour to travel the 20 kilometers to his home over rocky roads just for the opportunity to sit at the keyboard,” Yi said.
Yi first arrived in Shenzhen 19 years ago and worked in factories, on construction sites and in kitchens. He had not played a piano for nearly 30 years.
The public pianos in Huaqiangbei offered him a fresh start. On a hot summer’s day, while taking a break from work at a nearby construction site, Yi and his son passed one of the instruments. Encouraged by his son, Yi decided to give it a try.
He rubbed his hands nervously on his clothes, but the moment he placed his fingers on the keys, he felt more comfortable and his confidence returned. Although his masterly performance at the piano keyboard quickly made him an online sensation in China and overseas, Yi is not the only one to benefit from the pianos in Huaqiangbei.
Inspired by the British artist Luke Jerram, who has placed more than 2,000 street pianos in over 70 cities worldwide since 2008 with the words “Play Me, I’m Yours” printed on their sides, the public piano project in Huaqiangbei was launched by the local government in 2018.
Zhang Chen, deputy director of the Huaqiangbei subdistrict office, said: “Huaqiangbei is located in the commercial district in the center of Shenzhen. We have been trying to provide diverse facilities to bring high-quality public cultural services to the area. We are surprised that the public piano project has attracted so many people to play the instruments, and others to watch them perform.”