上宝中学(初三)

上宝中学(初三)
上宝中学(初三)

上宝中学2013学年第一学期期中考试

初三数学试卷

一、选择题(本大题共6题,每题4分,满分24分)

1. 已知在△ABC 中,点D 、E 、F 分别在边AB 、AC 和BC 上,且DE ∥BC ,DF ∥AC ,那么下列比例式中,正确的是()

A. BC DE EC AE =;

B. FB

CF EC AE =;C .BC DE AC DF =;D. BC FC AC EC = 2. 已知在Rt △ABC 中,∠C=90°,∠A 、∠B 、∠C 的对边分别是a 、b 、c ,则下列关系式错误的是()

A .a =b tan A ;

B .b =ccos A ;

C .a =c sin A ;

D .c =sin b A

3. 如图,平行四边形ABCD 中,过点B 的直线与对角线AC 、边AD 分别交于点E 和F .过点E 作EG ∥BC ,交AB 于G ,则图中相似三角形有()

A .7对;

B .6对;

C .5对;

D . 4对

第3题 第4题

4.二次函数y =ax 2+bx +c (a ,b ,c 是常数,a ≠0)图象的对称轴是直线x =1,其图象的一部分如图所示.对于下列说法:

①abc >0;②a -b +c <0;③3a +c <0;④当-1<x <3时,y >0.其中正确的结论是().

A .①②;

B .①④;

C .②③;

D .②③④

5.下列说法正确的个数有()

①平分弦的直径,平分这条弦所对的弧;

②在等圆中,如果弦相等,那么它们所对的弧也相等;

③等弧所对的圆心角、弦、弦心距都分别相等;

④过三点可以画一个圆.

A .1个;

B .2个;

C .3个;

D .4个 6.下列命题中,错误命题的个数有()

①如图,若AB DE BC EF

=,则////AD BE CF ; ②已知一个单位向量e ,设a 是非零向量,则1a e a

=;

③在△ABC 中,D 在AB 边上,E 在AC 边上,且△ADE

和△ABC 相似,若AD = 3,DB = 6,AC = 5,则它们的相似比为13或35

; ④对于抛物线f (x )=x 2-4x +c ,有f (1)>f (-1);

⑤在△ABC 中,AB =23,AC =2,BC 边上的高AD =3,则BC =4,∠B =30°.

A .5个;

B .4个;

C .3个;

D .2个

二、填空题(本大题共12题,每题4分,满分48分)

7. 在比例尺为1:50000的地图上,某地区的图上面积为20平方厘米,则实际面积为 平方千米.

8. 在△ABC 中,|cosA –32

|+(1– cotB)2 = 0 ,则△ABC 的形状是. 9.将二次函数5422+-=x x y 图象向左平移1个单位,再向下平移2个单位后,所得图 象的解析式是.

10. 如图,梯形ABCD 中,AD ∥BC ,E 、F 分别是AB 、CD 上的点,且EF ∥BC ,53

AE BC BE AD ==,若AB a =,DC b =,则向量EF 可用a 、b 表示为_____________________.

第10题第11题第12题第13题

11. 如图,在△ABC 中,点D 是AB 的黄金分割点(AD >BD ),BC=AD ,如果∠A CD=90°,那么tanA=.

第6

D

B

C A E

12.如图AD 是△ABC 的中线,E 是AD 上一点,且AE=13

AD ,CE 的延长线交AB 于点F ,若AF=1.2,则AB=.

13. 如图所示,在△ABC 中,DE ∥AB ∥FG ,且FG 到DE 、AB 的距离之比为1:2.若△ABC 的面积为32,△CDE 的面积为2,则△CFG 的面积S=

14. 在△ABC 中,AB=3,AC=4,△ABC 绕着点A 旋转后能与△AB ′C ′重

合,那么△ABB ′与△ACC ′的周长之比为.

15.如图,△ABC 中,AB =AC ,AD ⊥BC 于D ,AE =EC ,AD =18,BE =15,tan ∠EBC =.

16.如图,AC 是高为30米的某一建筑,在水塘的对面有一段以BD 为坡面的

斜坡,小明在A 点观察点D 的俯角为30°,在A 点观察点B 的俯角为45°,

若坡面BD 的坡度为1:3,则BD 的长为 .

17. ⊙O 的半径为5cm ,弦AB//CD ,AB=6cm ,CD=8 cm ,则AB 与CD

的距离为cm.

18.如图,在Rt △ABC 中,∠C =90°,AB=5,BC =3,点D 、E 分别在BC 、AC 上,且BD=CE ,设点C 关于DE 的对称点为

F ,若DF ∥AB ,则BD 的长为. 三、解答题(本大题共7题,满分78分)

19.(本题第(1)题3分,第(2)题7分,满分10分)

在平面直角坐标系中,抛物线过原点O ,且与x 轴交于另一点A (A 在O 右侧),顶点为B .艾思轲同学用一把宽3cm 的矩形直尺对抛物线进行如下测量:

(1)量得OA =3cm ;(2)当把直尺的左边与抛物线的对称轴重合,使得直尺左下端点与抛物线的顶点重合时(如图),测得抛物线与直尺右边的交点C 的刻度读数为4.5cm . 艾思轲同学将A 的坐标记作(3,0),然后利用上述结论尝试完成下列各题:

A

C B

D

(1)写出抛物线的对称轴;(2)求出该抛物线的解析式.

20.(本题每小题5分,满分10分)

在Rt △ABC 中,∠ACB=90°,AB=5,sin ∠CAB

=45,D 是斜边AB 上一点,过点A 作AE ⊥CD ,垂足为E ,AE 的

延长线交BC 于点F .

(1)当tan ∠BCD =

12时,求线段BF 的长; (2)当BF =54

时,求线段AD 的长. 21.(本题每小题5分,满分10分)

如图,已知⊙O 的半径为5,弦AB 的长等于8,OD ⊥AB ,垂足为点D ,DO 的延长线

与⊙O 相交于点C ,点E 在弦AB 的延长线上,CE 与⊙O 相交于点F ,cos C =35

. 求:(1)CD 的长;(2)EF 的长.

22.(本题每小题5分,满分10分)

如图,在一笔直的海岸线l 上有AB 两个观测站,A 在B 的正东方向,AB=2(单位:km ).有一艘小船在点P 处,从A 测得小船在北偏西60°的方向,从B 测得小船在北偏东45°的方向.(1)求点P 到海岸线l 的距离;(2)小船从点P 处沿射线AP 的方向航行一段时间后,到点C 处,此时,从B 测得小船在北偏西15°的方向.求点C 与点B 之间的距离.(上述两小题的结果都保留根号)

23.(本题第(1)题5分,第(2)题7分,满分12分)

如图,在△ABC 中,AB =AC ,D 是BC 的中点,DF ⊥AC ,E 是DF 的中点,联结AE 、

BF. 求证:(1)2DF CF AF =?; (2)AE ⊥BF. 24. (本题第(1)题3分,第(2)题4分,第(3)题5分,满分12分)

已知抛物线y =x 2-2x +c 与x 轴交于A .B 两点,与y 轴交于C 点,抛物线的顶点为D 点,点A 的坐标为(-1,0).

(1)求D 点的坐标; D

A E

B

C O

F H E F C

2020-2021上海民办上宝中学小学数学小升初模拟试卷(含答案)

2020-2021上海民办上宝中学小学数学小升初模拟试卷(含答案) 一、选择题 1.7.49亿这个数中的“4”表示() A. 4亿 B. 4000万 C. 400000 D. 400万2.口袋里有3个红球和5个白球,球除颜色外完全相同。从中任意摸出一个球,摸出红球的可能性是(). A. B. C. D. 3.要想描述六年级(3)班同学身高分组的分布情况,应选用()合适。 A. 条形统计图 B. 折线统计图 C. 扇形统计图 D. 以上都行 4.一个零件长4毫米,画在图上长12厘米。这幅图的比例尺是()。 A. 1:30 B. 1:3 C. 30:1 D. 3:1 5.一项工程,甲独立完成要30天,乙独立完成要20天,现两队合作,几天后完成了这项 工程的。如果按这样的效率,算式()可以表示求剩下的工程需要多少天完成。 A. ÷( + ) B. (1- )÷( + ) C. 1÷( + ) D. (1- )÷( - ) 6.一套科技读物原价90元,商场庆“五一”搞促销打七五折,算式()表示求现价。A. 90×75% B. 90×(1-75%) C. 90÷75% D. 90÷(1-75%)7.长沙地铁1号线和地铁2号线总里程约为50千米,2019年5月随着地铁4号线的开通,长沙地铁总里程增加了67%,地铁4号线开通后,长沙地铁总里程约为() A. 67千米 B. 117.1千米 C. 33.5千米 D. 83.5千米8.一块玉璧的形状是一个圆环,外圆半径是3cm,内圆半径是1cm,这个圆环的面积是()(π取3.14) A. 3.14cm2 B. 12.56cm2 C. 25.12cm2 D. 28.26cm2 9.甲车间的出勤率比乙车间高,以下说法正确的是() A. 甲车间的总人数一定比乙车间多 B. 甲车间的出勤人数一定比乙车间多 C. 甲车间的未出勤人数一定比乙车间少 D. 以上说法都不对 10.小明五次数学考试成绩如下表,第五次考试成绩是()分。 次别第一次第二次第三次第四次第五次平均分 成绩(分)8896939993 11.有一张方格纸,每个小方格的边长是1厘米,上面堆叠有棱长1厘米的小正方体(如左下图),小正方体A的位置用(1,1,1)表示,小正方体B的位置用(2,6,5)表示,那么小正方体 C的位置可以表示成()。

上海市上宝中学数学圆 几何综合章末训练(Word版 含解析)

上海市上宝中学数学圆几何综合章末训练(Word版含解析) 一、初三数学圆易错题压轴题(难) 1.如图所示,CD为⊙O的直径,点B在⊙O上,连接BC、BD,过点B的切线AE与CD 的延长线交于点A,OE//BD,交BC于点F,交AB于点E. (1)求证:∠E=∠C; (2)若⊙O的半径为3,AD=2,试求AE的长; (3)在(2)的条件下,求△ABC的面积. 【答案】(1)证明见解析;(2)10;(3)48 5 . 【解析】 试题分析:(1)连接OB,利用已知条件和切线的性质证明:OE∥BD,即可证明:∠E=∠C; (2)根据题意求出AB的长,然后根据平行线分线段定理,可求解; (3)根据相似三角形的面积比等于相似比的平方可求解. 试题解析:(1)如解图,连接OB, ∵CD为⊙O的直径, ∴∠CBD=∠CBO+∠OBD=90°, ∵AB是⊙O的切线, ∴∠ABO=∠ABD+∠OBD=90°, ∴∠ABD=∠CBO. ∵OB、OC是⊙O的半径, ∴OB=OC,∴∠C=∠CBO. ∵OE∥BD,∴∠E=∠ABD, ∴∠E=∠C; (2)∵⊙O的半径为3,AD=2, ∴AO=5,∴AB=4. ∵BD∥OE, ∴=, ∴=, ∴BE=6,AE=6+4=10 (3)S △AOE==15,然后根据相似三角形面积比等于相似比的平方可得

S △ABC = S △AOE == 2.已知: 图1 图2 图3 (1)初步思考: 如图1, 在PCB ?中,已知2PB =,BC=4,N 为BC 上一点且1BN =,试说明: 1 2 PN PC = (2)问题提出: 如图2,已知正方形ABCD 的边长为4,圆B 的半径为2,点P 是圆B 上的一个动点,求 1 2 PD PC +的最小值. (3)推广运用: 如图3,已知菱形ABCD 的边长为4,∠B ﹦60°,圆B 的半径为2,点P 是圆B 上的一个动点,求1 2 PD PC -的最大值. 【答案】(1)详见解析;(2)5;(3)最大值37DG =【解析】 【分析】 (1)利用两边成比例,夹角相等,证明BPN ?∽BCP ?,得到PN BN PC BP =,即可得到结论成立; (2)在BC 上取一点G ,使得BG=1,由△PBG ∽△CBP ,得到1 2 PG PC =,当D 、P 、G 共线时,1 2 PD PC + 的值最小,即可得到答案; (3)在BC 上取一点G ,使得BG=1,作DF ⊥BC 于F ,与(2)同理得到1 2 PG PC =,当点P 在DG 的延长线上时,1 2 PD PC -的值最大,即可得到答案. 【详解】 (1)证明:∵2,1,4PB BN BC ===,

2017-2018上海上宝中学九上英语期中考试(附答案)

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2017-2018学年上宝中学九上英语12月月考 上海市 英语试卷

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2019-2020上海市上宝中学数学中考一模试题(含答案)

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上宝中学2018学年第一学期期中考试 上海市 英语试卷

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