高三物理上学期第4周周练题

四川省宜宾市一中高2014级2016-2017学年上学期

第四周物理试题

第Ⅰ卷

一、单项选择题(本题共14个小题,每小题3分。在每小题只有一项是符合题目要求的) 1.下列说法中正确的是( )

A.亚里士多德认为重物与轻物下落得同样快

B.伽利略提出力是维持物体运动的原因

C.牛顿总结万有引力定律 并测出了引力常量G

D.开普勒总结出开普勒三大定律(行星运行三定律)

2.已知地球质量为M ,半径为R ,自转周期为T ,地球同步卫星质量为m ,引力常量为G .有关同步卫星,下列表述正确的是( ) A .卫星距地面的高度为 3GMT 2

4π2

B .卫星的运行速度小于第一宇宙速度

C .卫星运行时受到的向心力大小为G Mm

R

2

D .卫星运行的向心加速度等于地球表面的重力加速度

3.马航客机失联后,西安卫星测控中心启动应急机制,对在轨运行卫星测控计划进行调整,紧急调动海洋、风云、高分、遥感4个型号近10颗卫星,为地面搜救行动提供技术支持,个别卫星还变轨,全力投入搜救。如图所示,假设卫星在A 点从圆形轨道Ⅰ进入椭圆轨道Ⅱ,

B 为轨道Ⅱ上的一点,下列说法中错误的是( )

A. 在轨道Ⅱ上经过A 的速度小于在轨道Ⅰ上经过A 的速度

B. 在轨道Ⅱ上经过A 的速度小于经过B 的速度

C. 在轨道Ⅱ上运行的周期小于在轨道Ⅰ上运行的周期

D. 在轨道Ⅱ上经过A 的加速度小于在轨道Ⅰ上经过A 的加速度

4.a 、b 、c 、d 是在地球大气层外的圆形轨道上运行的四颗人造卫星.其中a 、c 的轨道相交于P ,b 、d 在同一个圆轨道上,b 、c 轨道在同一平面上.某时刻四颗卫星的运行方向及位置如图1所示.下列说法中正确的是( )

图1

A .a 、c 的加速度大小相等,且大于b 的加速度

B .b 、c 的角速度大小相等,且小于a 的角速度

C .a 、c 的线速度大小相等,且小于d 的线速度

D .a 、c 存在在P 点相撞的危险

5.“北斗”卫星导航定位系统由地球静止轨道卫星(同步卫星)、中轨道卫星和倾斜同步卫星组成.地球静止轨道卫星和中轨道卫星都在圆轨道上运行,它们距地面的高度分别约为地球半径的6倍和3.4倍.下列说法正确的是( ) A .静止轨道卫星的周期约为中轨道卫星的2倍 B .静止轨道卫星的线速度大小约为中轨道卫星的2倍 C .静止轨道卫星的角速度大小约为中轨道卫星的

1

7

D .静止轨道卫星的向心加速度大小约为中轨道卫星的

17

6.由于稀薄空气的阻力作用,低轨道卫星的运行轨道半径会逐渐减小,卫星只受地球引力和稀薄空气阻力作用,在此过程中下列判断中正确的是( ) A.卫星的动能逐渐减小 B.系统引力势能一定减小 C.系统机械能保持不变

D.卫星克服阻力做的功等于引力势能的减小

7.已知某星球的自转周期为T 0,在该星球赤道上以初速度v 竖直上抛一物体,经t 时间后物体落回星球表面,已知物体在赤道上随星球自转的向心加速度为a ,要使赤道上的物体“飘”起来,则该星球的转动周期为( ) A.02at

T T v

=

B.0at

T T v = C.T = at at +2v

T 0 D.0at

T T at v

=

+

8. (多选)P 1、P 2为相距遥远的两颗行星,距各自表面相同高度处有一颗卫星s 1、s 2做匀速圆周运动。图中纵坐标表示行星对周围空间各处物体的引力产生的加速度a ,横坐标表示物

体到行星中心的距离r 的平方,两条曲线分别表示P 1、P 2周围的a 与r 2

的反比关系,它们左端点横坐标相同,则( )

A .P 1的平均密度比P 2的大

B .P 1的“第一宇宙速度”比P 2的小

C .s 1的向心加速度比s 2的大

D .p 1的公转周期比p 2的大

9.在漫长的宇宙形成过程中,有的星球往往会在相互作用力的影响下形成稳定的多星系统。如图,a 、b 、c 、d 四颗质量均为m 的星球构成一个边长为L 的正方形而绕它们的中心转动,不考虑其他星球的影响,则下列关于该系统的说法正确的是( )

A.每颗星球受的合力为: 2

2

52Gm

F L

=

B.每颗星球转动的角速度为: 3

(42)2Gm

L ω+=

C.每颗星球转动的速度为: (22)2Gm

v L

+=

D.每颗星球转动的周期可以不同

10. (多选)如图所示,a 为地球赤道上的物体,b 为沿地球表面附近做匀速圆周运动的人造卫星,c 为地球同步卫星。关于a 、b 、c 做匀速圆周运动的说法中正确的是( )

A. 地球对b 、c 两星的万有引力提供了向心力,因此只有a 受重力,b 、c 两星不受重力

B. 周期关系为T a =T c >T b

C. 线速度的大小关系为v a

D. 向心加速度的大小关系为a a >a b >a c

11. (多选)火星直径约为地球的一半,质量约为地球的十分之一,它绕太阳公转的轨道半径约为地球公转半径的1.5倍。则下列说法正确的是( )

A .火星表面重力加速度约为地球表面的重力加速度的110

B .火星公转的周期比地球的大

C .火星的第一宇宙速度约为地球宇宙第一速度的1

5

D .火星公转的向心加速度比地球的大

12.(多选)已知月球半径为R ,飞船在距月球表面高度为R 的圆轨道上飞行,周期为T 。万有引力常量为G ,则根据以上条件:( ) A .可以求出飞船的势能 B .可以求出飞船的动能 C .可以求出月球质量

D.可以求出月球的第一宇宙速度

13(多选)某行星和地球绕太阳公转的轨道均可视为圆。每过N 年,行星会运行到日地连线的延长线上(相距最近),如图所示。设该行星与地球的公转周期之比为k 1,公转半径之比为

k 2,则( )

A .k 1=

N +1

N

B .k 1=

N

N -1

C .k 2=? ????N +1N 23

D .k 2=? ????N N -123

14.宇航员驾驶太空飞船降落在某未知星球表面上,探测到该星球也和地球一样在自转且自转角速度为ω,该星球半径为R 。宇航员又把一小螺帽以v 0的速度竖直向上抛出,测出期其上升的最大高度为H ,如果要发射一颗该星球的同步卫星,则同步卫星的高度为:

2032V R R H ω2

3

22V R H ω 2

032

2V R R H ω

-0322V R H ω 第II 卷

二、计算题

15.双星系统由两颗恒星组成,两恒星在相互引力的作用下,分别围绕其连线上的某一点做

周期相同的匀速圆周运动.研究发现,双星系统演化过程中,两星的总质量、距离和周期均可能发生变化.若某双星系统中两星做圆周运动的周期为T,经过一段时间演化后,两星总质量变为原来的k倍,两星之间的距离变为原来的n倍,则此时圆周运动的周期为多少?

16.由三颗星体构成的系统,忽略其他星体对它们的作用,存在着一种运动形式:三颗星体在相互之间的万有引力作用下始终连成一条直线,中央星体保持静止,另外两颗星体等距离的绕着它做匀速圆周运动。如图,若A星体质量为2m,B、C两星体的质量均为m,BA、BC 间的距离均为r,求:

(1)B星体所受合力大小F B

(2)星体做圆周运动的周期T。

17.据每日邮报2014年4月18日报道,美国国家航空航天局(NASA)目前宣布首次在太阳系外发现“类地”行星Kepler-186f。假如宇航员乘坐宇宙飞船到达该行星,进行科学观测:该行星自转周期为T;宇航员在该行星“北极”距该行星地面附近h处自由释放一个小球(引力视为恒力),落地时间为t。已知该行星半径为R,引力常量为G,则: ( B )

(1)宇宙飞船绕该星球做圆周运动的最小周期为多少?

(2)该行星的质量为多少?

(3)如果该行星存在一颗同步卫星,其距行星表面高度为多少?

参考答案:

1D 2B 3D 4A 5A 6B 7C 8AC 9B 10BC 11BC 12CD 13BD 14C

15.答案:

解析:设双星质量分别为m 1和m 2,轨道半径分别为r 1和r 2,二者距离为L,则有:

r 1+r 2=L

2

1211224Gm m m r L T π= 2

1222224Gm m m r L T

π=

得: 2T =

同理:'2T π=

所以 'T =

16.答案 (1)T =

2

2

94B Gm F r = (2)

T =解析: (1)由万有引力定律,B 星体所受A 、C 星体引力作用,则:

22

22

2(2)

B G m Gm F r r =+ 即 2

2

94B Gm F r =

(2)对B(或C):

22

2

2944B Gm F m r r T

π==

得:T =

17.解析: (1)由h =12

gt 2

解得行星表面的重力加速度:g =2h

t

2,

又 2

20

4mg m R T π=

得:0T π

=0T π= (2)由

2GMm mg R = 2

GMm mg R

= 得:222hR M Gt = 2

2

2hR M Gt

= (3)由

2

()GMm R H +=m ? ????2πT 2(R +H )

得:H = 3hT 2R 2

2π2t

2-R

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