HW2-Solutions
Murata Power Solutions MP-HW80EVAL-01评估板用户指南说明书
MP-HW80EVAL-01MP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY1.IntroductionMP-HW80EVAL-01 Evaluation Board User GuideThe MP-HW80EVAL-01 Evaluation Board is designed to assist with the evaluation of the IRH-W80, 250W, 10:1input range DC/DC converter module from Murata Power Solutions. The IRH-W80 series of isolated regulatedconverter modules, deliver an impressive 250W single output from a wide input range of 16V – 160Vdc, complyingwith the input battery voltage transient range of EN50155.The half brick module offers high efficiency levels up to 90%, with an input – output isolation voltage of 4242Vdc.The module features Overvoltage, Overcurrent, Short Circuit, Adjustable output voltage, Adjustable Current Limit,Positive or Negative Logic enable, Pulse output signal and Hold up function for an external capacitor. See Page 10for full schematic.Figure 1 – Evaluation BoardMP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY2.Setup2.1 ConnectionsThis section describes the connector locations/pinouts on the evaluation board, to enable correct set up.Figure 2 - Connectors Position / Resistor Functions (Top View)H1 Input Voltage ConnectorH2 Signal Connector Resistor / Function Pin 1 VIN- Pin 1 PULSE R1 UVLOPin 2 VIN- Pin 2 VIN- R2 TRIM DOWNPin 3 VIN+ Pin 3 ON/OFF R3 TRIM UPPin 4 VIN+ Pin 4 PE R4 CHARGER5 SENSE (+) H3 Output Voltage Connector H4 External Hold Up Connector R6 SENSE (-)Pin 1 VOUT- Pin 1 VIN- R7 OCPPin 2 VOUT- Pin 2 CHOLD+ R1, R2, R3, R5, R6, R7 = SMD0805 Pin 3 VOUT+Pin 4 VOUT+MP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY2.2 On Board Component Values2.2.3 OCP Resistor ValueR7 = OCP – Overcurrent Protection.By adding a resistor SMD0805 to position R7 on the PCB, it is possible to set the overcurrent threshold point.Leave unconnected if not used.Figure 3 - OCP Resistor SelectionR7 OCP Value 562Ω 665Ω 845Ω 1.13kΩ 1.69kΩ 3.32kΩ 6.65kΩ 10kΩ Open 24Vin 14.5A 16.2A 18.2A 20.2A 22.4A 24.3A 25A 25.5A 26A48Vin 15.5A 17.4A 19.4A 21.1A 23A 24.5A 25.4A 25.9A 26.5A72Vin 15.5A 17.4A 19.4A 21.1A 23A 24.5A 25.4A 25.9A 26.5A110Vin 11.6A 14A 17.1A 19.8A 22.1A 24.5A 25.4A 25.8A 27A2.2.4 Under Voltage Lockout. (UVLO)By adding a SMD0805 resistor to R1 position as per the table below, the converter will shut down if the inputvoltage drops below the threshold. The converter will automatically restart when the input voltages rises above theUVLO threshold. Leave unconnected if not used.Figure 4 - UVLO Resistor Value TableVin 24V 36V 48V 72V 96V 110VTurn Off 10V-12V 17.5V-19.5V 26V-28V 40V-43V 56V-60V 65V-70VTurn On 13V-15V 22V-24V 31V-34V 48V-51V 68V-72V 80V-84VResistor Value Open 27.4kΩ 13kΩ 6.8kΩ 4.3kΩ 3.57kΩ2.2.5 Output Voltage Trim ResistorsR3 and R2 – Trimming the Output Voltage.The trim pin of the converter allows the user to adjust the output either +10% or -20% by using SMD0805fixed value resistors.Figure 5 - Output Trim Resistor Values12V OutputOutput Voltage 9.6V 10.8V 11.4V 12.6V 13.2VR3 - Trim Up NA NA NA 188kΩ 97kΩR2 - Trim Down 4kΩ 8.9kΩ 18.7kΩ NA NAMP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY2.2.6 Sense ConnectionsIf intended to utilize the output sense feature, please ensure that you short out, or add a zero ohm link in positionsR5, Sense (+) and R6, Sense (-). If it is proposed to use the sense function, then please leave R5 and R6 opencircuit, and connect output sense lines to the load. The sense connections can compensate up to 0.5V voltage dropof output leads.Figure 6 - Remote Sense Connection2.2.7 Hold Up CircuitThe BUS pin of the IRH250W80 module, is a voltage source output of 80Vdc to allow external capacitors to be connected in order to provide hold up power of the converter. The eval board houses a resistor (R4) to slowlycharge the capacitors up, and a feed forward diode (D1) for rapid discharge into the module during hold up mode.The capacitor value can be as per the below table to provide 10msec or 20msec of hold up. Connect the capacitorto H4 Pin 1 = VIN-, Pin 2 = CHOLD+. As per Figure 2.Figure 7 - Hold-Up Capacitor ValuesHold-up time 24Vin36Vin 48Vin 72Vin 96Vin 110Vin 10ms 2200uF 2200uF 2200uF 2200uF 1100uF 700uF20ms 4400uF 4400uF 4400uF 4400uF 2200uF 1400uF2.2.8 External FusingThe evaluation board does not have any fusing protection, the user must provide external fusing, circuit breaker protection as required.MP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY2.2.9 Pulse OutThis pin outputs a 1kHz 50% duty cycle pulse voltage with 12V amplitude. It is designed to provide a bootstrapsignal for the input inrush current limit circuit and could also indicate operating status with a LED connected.Leave unconnected if not used.2.2.10 On/Off ControlConnect the On/Off pin (Pin 3, H2) to -VIN (Pin 2, H2) connection if “Negative” logic level is used in the part numberof the IRH-W80. Leave the On/Off pin open if “Positive” logic level is used.Note: A mechanical On/Off switch is also provided on the top side of the evaluation board.MP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY3. EMI CircuitThe following schematic below meets EN55011 Class A.Figure 8 - EMI SchematicFigure 9 - EMI BOMReference Manufacturer MPN Type Specifications QtyMOV1 Epcos B72214S0141K101 Varistor 180V, 36J 1TVS1 Littel Fuse 1.5KE220A TVS diode 185V, 1.5KW 1C1 Faratronic C212E475K9AC000 Polyester capacitor 250V, 4.7uF 1C2, C3, C4 Murata GRM43DR72E474KW01L Capacitor MLCC 250V, 0.47uF 3C5, C6, C11, C12, C13, C14 Murata DE1E3RA102MA4BQ01F Safety ceramic cap 500V, 1000pF 6C9, C10 NCC EKXJ251EXX271ML40S E-cap 250V, 270uF 2C15, C16 Murata DE1E3RA472MA4BQ01F Safety ceramic cap 500V, 4700pF 2L1 Wurth 7448262013 CM choke 1.3mH, 20A 1L2, L3 Bourns 2300HT-220-V-RC1951 DM choke 22uH, 19A 2C7, C8 NA NOT USED NA NA 0C17, C18 NA NOT USED NA NA 0MP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARYFigure 10 - EMI ResultsLimit Line as per EN55011 level AVin = 110V, Line LMP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY4. Circuit SchematicMP-HW80EVAL-01Analog DC-DC Evaluation BoardUser GuidePRELIMINARY5. Mechanical Drawings / Dimensions3: UNIT WEIGHT = 690 gramsMP-HW80EVAL-01 Analog DC-DC Evaluation Board User GuideDCAN-70_MP-HW80EVAL-01_A01.D08 Page 12 of 12PRELIMINARY6. Packaging InformationMurata Power Solutions, Inc.129 Flanders Rd., Westborough, MA 01581 USAISO 9001 and 14001 REGISTERED This product is subject to the following operating requirements and the Life and Safety Critical Application Sales Policy : Refer to: /requirements/Murata Power Solutions, Inc. makes no representation that the use of its products in the circuits described herein, or the use of other technical information contained herein, will not infringe upon existing or future patent rights. The descriptions contained herein do not imply the granting of licenses to make, use, or sell equipment constructed in accordance therewith. Specifications are subject to change w ithout notice. © 2021 Murata Power Solutions, Inc.MP-HW80EVAL-01。
腾讯NDA限制-腾讯NDA限制-Jacinto6Eco SoC电源解决方案-DRA72 TDA2
TPS22965 + TPS51200
8
New PDN Concept
0.40 = $3.25
(3 AVS @ 1‐2.5A, Dual 1.8/3.3V IO, DDR3L)
18 + 4 + 4.6 + 4.6 + 4 + 9 = 44
$4.42 128 $2.53 74
$7.32 190 $4.64 119
5. “PDN’s AVS Capability” is the achievable power if all AVS power rails are increased to 90% of capacity while other power rails remain at typical Use Case modelled values.
(3 AVS @ 1‐3.5A, Dual 1.8/3.3V IO, DDR3L) (similar to EVM PDN #0)
49 + 9 + 4 = 62
#8.2 – LP87524 + LP5912 + TLV713 + LP5907 +
9.92
1.26 + 0.19 + 0.07 + 0.10 + 0.10 +
2. PDN Support component (Rs, Cs & Ls) pricing from Mouser Distribution website using single 4k – 10k/reel qty costs as of May 2016. Both PDN Support & PDN Total Costs have been provided for relative comparison only, individual customer volume pricing may vary.
hw2-consumer theory
Advanced Microeconomics Fall2014Homework#2Due date:Oct.28in class1.Let x1,x2,x3and x4be consumption bundles in the consumption set R n+.Use theaxioms and definitions in the lecture note to prove the following statements.(a)If both x1 x2and x2 x1are false,then x1∼x2.(b)If x1 x2and x2∼x3and x3 x4,then x1 x4.2.Consider the consumer’s problem:max x1,x2≥0x51x72s.t.p1x1+p2x2≤ywhere p1,p2and y are(positive)prices and income.(a)Is it possible for this problem to have a solution(x∗1,x∗2)with x∗1=0or x∗2=0?Why or why not?(b)Is it possible for this problem to have a solution(x∗1,x∗2)with p1x∗1+p2x∗2<y?Why or why not?(c)Derive the Marshallian demand functions x1(p1,p2,y)and x2(p1,p2,y),and theindirect utility function v(p1,p2,y).3.Suppose the utility function of a consumer is u(x1,x2)=min{a1x1,a2x2}where a1and a2are positive parameters.(a)Is the consumer’s preference continuous?Is it locally nonsatiated?Is it strictlymonotonic?Is it convex?Is it strictly convex?(b)Derive the Marshallian demand functions and indirect utility function.(c)Verify that the Marshallian demand functions and indirect utility function arehomogeneous of degree0.(d)Verify the Roy’s identity for this example.4.For CES utility function u(x1,x2)=(xρ1+xρ2)1/ρ,where0=ρ<1.(a)Find the Marshallian demand functions x i (p 1,p 2,y ),i =1,2;(b)Show that the limits of the Marshallian demand functions x i (p 1,p 2,y ),i =1,2that you found in part (a)exist when ρgoes to 0.Moreover,verify that the limits equals the Marshallian demand function for u (x 1,x 2)=√x 1x 2(Cobb-Douglas utility function).(c)Show that the limits of the Marshallian demand functions x i (p 1,p 2,y ),i =1,2that you found in part (a)exist when ρgoes to −∞.Moreover,verify that the limits equals the Marshallian demand function for u (x 1,x 2)=min (x 1,x 2).5.Find the Marshallian demand functions x i (p 1,p 2,y ),i =1,2with the following utility functions(a)u (x 1,x 2)=2√x 1+x 2.(b)u (x 1,x 2)=ln(1+x 1)+x 2.(Caution:the solution may be in the corner.)6.Suppose that there are n goods,and a consumer’s preference relation is represented by some utility function u (·).Suppose that the indirect utility function isv (p,y )=y ni =1p −a i i ,where a 1,...,a n >0are parameters with ni =1a i =1.Derive the Marshallian de-mand functions x i (p,y ),expenditure function e (p,u ),and Hicksian demand functions x h i (p,u ).7.LetM = 1ββ1 .What are the eigenvalues of M ?when is M positive definite?8.Suppose a consumer has the following quasi-linear utility function:u (x 1,x 2,x 3)=a 1x 1+a 2x 2+x 3−12(x 21+x 22+2βx 1x 2),where a 1>0,a 2>0,β∈(−1,1).Normalize the price of x 3to be 1,i.e.,p 3=1.(a)Derive the Marshall demand function x i (p 1,p 2,1,y ),i =1,2for this consumer.(You can assume the constants a 1,a 2are sufficiently large so that the solutions x i given by the FOCs are positive ).(b)Find the sign of∂x 1(p 1,p 2,1,y )∂p 2and relate it to the sign of β?How to interpret theparameter β?2。
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LTLX Swiss International Air LinesLY El Al Israel AirlinesLZMA Malev Hungarian AirlinesMB MNG AirlinesMD Air MadagascarME Middle East AirlinesMF Xiamen AirlinesMH Malaysia AirlinesMI Silk AirMJ Lineas Aereas Privadas Argentinas MK Air MauritiusMM Peach AviationMP MartinairMR Air MauritaniaMS EgyptairMT Thomas Cook AirlinesMU China Eastern AirlinesMV Armenian International Airways MX Mexicana de AviacionMZ Merpati Nusantara AirlinesN3Omskavia AirlineNB Sterling EuropeanNE Sky Europe AirlinesNG Lauda AirNH All Nippon AirwaysNI PortugaliaNK Spirit AirlinesNL Shaheen Air InternationalNQ Air JapanNS Hebei AirlinesNVNX Air MacauNW Northwest AirlinesNZ Air New ZealandO3SF AirlinesOA Olympic AirlinesOB Astrahan AirlinesOH ComairOK CSA Czech AirlinesOM Miat-Mongolian AirlinesOO SkyWestOQOS Austrian AirlinesOU Croatia AirlinesOV Estonian AirOW Executive AirlinesOX Orient Thai AirlinesOZ Asiana AirlinesPAP2UTairP7EastLinePC Fiji AirPDPE Air Europe SPAPG Bangkok AirwaysPK Pakistan International Airlines PN West AirPO PolarPR Philippine AirlinesPS Ukraine International AirlinesPX Air NiuginiPY Surinam AirwaysQ3PB AirQ540-Mile AirQF Qantas AirwaysQTQQ Alliance Airlines Reno AirQR Qatar AirwaysQS Travel Service AirlinesQS Smart WingsQV Lao AviationQWQX Horizon AirQZQZ Indonesia AirAsiaR2Orenburg AirlinesRA Royal Nepal AirlinesRB Syrian Arab AirlinesRC Atlantic AirwaysRE Aer ArannRF Florida West International Airways RG Varig BrasilRI Mandala AirlinesRJ Royal Jordanian AirlineRQ Kam AirRN Air HorizonsRN EuralairRO TaromS2Air SaharaS4SATA InternationalS7S7 AirlinesS9East African Safari AirSA South African AirwaysSC Shandong AirlinesSD Sudan AirwaysSG JetsgoSG SpicejetSH FlyMeSJ Freedom AirSK SAS Scandinavian Airlines SN Brussels AirlinesSQ Singapore AirlinesSR SwissAirSU Aeroflot Russian Airlines SV Saudi Arabian AirlinesSW Air NamibiaSY Sun Country AirlinesSZ Air China Southwest Company T4Hellas JetT5TurkmenistanT7Twin JetT9TransMerridian AirlinesTA Taca InternationalTE flyLALTG Thai AirwaysTH Transmile Air ServicesTH British Airways CitiExpress TL Trans Mediterranean Airways TL Airnorth RegionalTK Turkish AirlinesTN Air Tahiti NuiTP TAP AirTQ Tandem AeroTR Tiger AirwaysTS Air TransatTT Air LithuaniaTU Tunis AirTX Air CaraibesTZ ATAU2easyJetU2UFSU5USA 3000 AirlinesU6Ural AirlinesU8ArmaviaU9Tatarstan AirlinesUA United AirlinesUB Myanmar AirwaysUL SriLankan AirlinesUM Air ZimbabweUNUO HK ExpressUQ O'Connor AirlinesUS US AirwaysUU Air AustralUX Air Europa Lineas Aereas UY Cameroon AirlinesV7Air SenegalV9BALVA Virgin AustraliaVD Air LiberteVF ValuAirVH AeropostalVI Volga-Dnepr AirlinesVN Vietnam AirlinesVR Cape Verde AirlinesVS Virgin Atlantic Airlines VV AerosvitVY Formosa AirlinesVY Vueling AirlinesVZ MyTravel AirwaysW2Canadian Western Airlines W3Flyhy Cargo AirlinesW5Mahan AirW6WizzairW8Cargojet Airways Ltd.W9Sky Service BvbaW9Eastwind Airlines Inc. 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hygropalm hp32说明书
English1 The HP32 is a highly accurate handheld instrument compatible with all HC2 and HC2A probes to perform measurement and logging of relative humidity, temperature and calculated psychro-metric parameters.1.1 • HygroPalm HP32• Soft Case• Micro-USB Service Cable (AC0006)• Belt Buckle Set • Lanyard • Certificate• HW4-LITE license key 22.1 PROBEThe HP32 is compatible with all HC2 and HC2A probes. Simply connect it to the probe input on top.A calibration of the HP32 after changing the probe is not necessary.range of conventional mounting accessories. For example, camera tripods or, the belt buckle delivered with the device.2.3 MAGNETICThe magnet integrated at the back of the HP32 enables easy installation on metallic surfaces such as, for example, ventilation shafts.ered cable to charge it.The device has a stand-by and an auto switch off feature. After 5 minutes without user interac-tion, the display is dimmed. Moreover, after a total of 10 minutes without user interaction, the device is switched off to save battery.These features do not affect data logging operations. While data logging is active, although the screen is dimmed or off, data points are still logged and saved.3.3 DISPLAY AND HOME SCREEN4 GENERAL SETTINGS 4.1 LANGUAGETo change the display language, go into:Main menu [OK] ✂Settings ✂ LanguageAvailable languages: English, Deutsch, Français, Italiano 4.2 DATE/TIMETo set up the date and time, go into:Main menu [OK] ✂Settings ✂ Date / TimeThe following settings can also be set beside the date and time.• Date format: DIN, US, ISO • Time format: 12 h, 24 hThe date and time must be set correctly for proper operation of the device.4.3 UNITSSet units used and displayed by the HP32 into:Main menu [OK] ✂ Settings ✂ Units Your options are as follow:• Distance: m, ft • Temperature: °C, °F • Pressure: hPa, mmHg • Weight: kg, lbs[POWER]Switches the HP32 on or off.Probe connector Tripod socket Reset button Integrated magnet Lanyard fixation USB port[DOWN]Cursor down[LEFT] [RIGHT]Action buttons, their action are indicated by the on-screen labels.[UP]• Cursor up• Parameter selection (home screen)Status Bar• Time and date • Hold indicator • Log indicator • Battery status Measured valuesAction Buttons labels[OK]• Opens the main menu / submenus • Confirm entries 4.4 Beside relative humidity and temperature, the HP32 can display 2 of the following 10 psychro-metric parameters:• Dew / Frost point (Dp/Fp)• Wet bulb temperature (Tw)• Enthalpy (H)• Vapor concentration (Dv)• Specific humidity (Q)however, still possible.You must name storage locations before use. Simply use the [Rename] action button when selecting a storage location to assign it a name.6 VIEWING SAVED DATA 6.1 SPOT MEASUREMENTSReview the spot measurements by selecting their storage location within:Main Menu [OK] ✂ Memory – Capture6.2 LOGGED DATAReview the logged data by selecting its storage location within:Main Menu [OK] ✂ Memory – LogSwitch between graphic displays and MIN / MAX / AVG values of the 4 parameters with [UP] and [DOWN].7 ALARMSet up upper, lower limits as well as hysteresis for every displayed parameter in:Main Menu [OK] ✂ AlarmsBroken alarm limits are shown in red on the home screen.You can also enable an acoustic signal for broken alarms in:Main Menu [OK] ✂ Settings ✂Buzzerlicense key.To download the HW4 software and learn more about its capabilities, please visit our webpage: /hw4.10 Belt Buckle SetProbe HC2A-S (not included)HP32Lanyard。
新思科技光学解决方案客户技术支持使用指南说明书
新思科技光学解决方案客户技术支持使用指南（2022.12版）目录一 、简介1.服务对象2.平台使用注意事项3.关于软件版本4.客户支持服务内容二、 SolvNetPlus 技术资源整合平台1.SolvNetPlus 注册及登入方法2.下载软件安装程序、授权档案3.Learning Center 线上学习平台4.咨询技术问题三、常见问题一、 简介感谢您使用新思科技光学产品（软件和设备）。
为了提供更好的服务，我们为软件 （CODE V、LightTools、LucidShape 产品系列、RSoft 产品系列）在租赁或维护期内的用户，以及购买硬件测量设备（Mini-DiffV2、Mini-Diff VPro、REFLET、TIS Pro）的用户提供技术支持和服务。
我们使用 SolvNetPlus 技术资源整合平台提供软件与授权文件下载、线上课程学习（Learning Center）以及线上技术支持。
1.服务对象我们对以下用户提供技术支持和服务●软件维护期内用户●软件租赁期内用户●硬件测量设备用户2.平台使用注意事项我们在技术支持过程中会涉及光学专业术语，因此我们预设您对光学术语已经有所了解。
建议您参考光学书籍，也可通过 Learning Center 观看线上学习平台学习基础课程相关知识。
3.关于软件版本我们建议您使用最新版本软件，如您的软件未更新至最新版，请提前告知。
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4.客户支持服务内容●软件下载与获取授权文件●常见问题锦集（FAQ）●下载手册、技术文件、范例模型、宏程序范例●有关光学软件和设备软件的安装和启动问题●光学软件和设备软件的操作问题●光学软件和设备软件的故障排查●光学测量设备的操作问题●线上光学软件培训课程、网络研讨会录播视频及讲义（Learning Center）●光学产品技术研讨会（点击查看）如需获得以上服务，请先在 SolvNetPlus 技术资源整合平台进行注册，具体注册方式请见点此。
维克斯45VPF系列-21设计-高压高性能梭形泵部件手册说明书
45VPF Series – 21 DesignHigh Pressure, High PerformanceVane PumpParts ManualAX439856912957en-000101High Pressure, High Performance Vane Pump45VPF Series – 21 DesignService DataViton is a registered trademark of E.I. DuPont Co.Parts prefixed with symbols areavailable only in kits (see back page).NOTE: Lubricate all parts and seals with a thin coat of oil at assembly.45VPF–***–***–*–*–01Model Code45VPF–***–***–*–*–0245VPF–***–***–*–*–0345VPF–***–***–*–*–0545VPF–***–***–*–*–06883356883357883358883359860370Key 928543928547Shaft Included in Cartridge Kit (see table)Included in Flange Kit (see table)928542Model CodeTypical sectional viewTo reverse Cartridge rotation remove Retaining Ring and Bearing Carrier S/A. Install Bearing Carrier S/A and Retaining Ring in opposite end ofCartridge and reinstall Cartridge facing in opposite direction. For R.H. rotation the end of the Cartridge with screw heads showing will be installed toward the cover end. For L.H. rotation the end of the Cartridge with screw heads showing will be installed toward the shaft end.02–142427 STD Seal Kit, Single Shaft Seal or02–142429 Viton Seal Kit, Single Shaft seal.02–142428 STD Seal Kit, Double Shaft Seal or02–142430 Viton Seal Kit, Double Shaft Seal.Shaft Seal OptionC –Primary and secondary seals:both with spring loaded sealing member facing inward.B –Primary and secondary seals:primary seal with spring loaded sealing member facing inward and secondary seal with spring loaded sealing member facing outward.A –Primary seal only: sealing member facing inward.Danfoss Power Solutions is a global manufacturer and supplier of high-quality hydraulic and electric components. We specialize in providing state-of-the-art technology and solutions marine sector. Building on our extensive applications expertise, we work closely with you to ensure exceptional performance for a broad range of applications. We help you and other customers around the world speed up system development, reduce costs and bring vehicles and vessels to market faster.Danfoss Power Solutions – your strongest partner in mobile hydraulics and mobile Go to for further product information.outstanding performance. And with an extensive network of Global Service Partners, we also provide you with comprehensive global service for all of our components.Local address:DanfossPower Solutions GmbH & Co. OHG Krokamp 35D-24539 Neumünster, Germany Phone: +49 4321 871 0DanfossPower Solutions ApS Nordborgvej 81DK-6430 Nordborg, Denmark Phone: +45 7488 2222DanfossPower Solutions (US) Company 2800 East 13th Street Ames, IA 50010, USA Phone: +1 515 239 6000DanfossPower Solutions Trading (Shanghai) Co., Ltd.Building #22, No. 1000 Jin Hai Rd Jin Qiao, Pudong New District Shanghai, China 201206Phone: +86 21 2080 6201Danfoss can accept no responsibility for possible errors in catalogues, brochures and other printed material. Danfoss reserves the right to alter its products without notice. This also applies to productsagreed.All trademarks in this material are property of the respective companies. Danfoss and the Danfoss logotype are trademarks of Danfoss A/S. All rights reserved.© Danfoss | September 2022•Cartridge valves •DCV directional control valves•Electric converters •Electric machines •Electric motors •Gear motors •Gear pumps •Hydraulic integrated circuits (HICs)•Hydrostatic motors •Hydrostatic pumps •Orbital motors •PLUS+1® controllers •PLUS+1® displays •PLUS+1® joysticks and pedals•PLUS+1® operator interfaces•PLUS+1® sensors •PLUS+1® software •PLUS+1® software services,support and training •Position controls and sensors•PVG proportional valves •Steering components and systems •TelematicsHydro-GearDaikin-Sauer-Danfoss。
hw2
【输出样例】
14
【限制】
1 ≤ N ≤ 10^5，最后解的范围为[1, 2^31)。
【提示】
树的直径
2012 年春季学期
第 3 / 10 页
清华大学计算机系(c)版权所有
a2,1 a3,1 ... an-2,1 an-1,1
a3,2 ... an-2,2 an-1,2
... ... ...
an-2,n-3 an-1,n-3
an-1,n-2
其中 n = |V|为顶点总数，顶点从 0 到 n-1 编号； ai,j 表示顶点 i 和 j 之间有无联边，有则为 1，没有为 0。
【输入样例】
6 2 2 5 1 1 2 2 2 2 3 1 2 100 200 150 100 300 200
【输出样例】
200.00
【限制】
1 ≤ N < 10,000,000 1 ≤ X < 1,000 股市的营业期不超过 2^31 - 1 天
【提示】
在队列基础上扩充操作接口
2012 年春季学期
【输入】
第一行是正整数 N，表示村庄的总数，各村庄从 1 到 N 编号。 接下来的 N-1 行各有以空格分隔的三个整数，表示由一条贸易通道联通的两个村庄（的编号） ， 以及 Donkey 在走这段路的时候会吃掉的草料的量。
【输出】
仅有一行，含一个整数，即 Shrek 所需背包的最小体积。
【输入样例】
【输入】
第一行含一个正整数 n，表示初始在墙上的 01 串总数。接下来的 n 行依次给出第 1~n 个 01 串。
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PART A: Minimum Inventory Production Plan (i.e., one that allows arbitrary hiring and firing) A B C D E F G H I J KForecast Net Cummulative Minimum # # Units Cummulative Inv. above Actual Demand Demand Net Demand of Workers Produced Production Min required InventoryC/32 E x 32 I - DJuly 1250 1050 1050 33 2 0 1056 1056 6 306Aug 1100 1100 2150 35 0 2 1120 2176 26 326Sep 950 950 3100 30 5 0 960 3136 36 336Oct 900 900 4000 29 1 0 928 4064 64 364Nov 1000 1000 5000 32 0 3 1024 5088 88 388Dec 1150 1250 6250 40 0 8 1280 6368 118 5188 13 338 2238A B C D E F G H I J KForecast Net Cummulative Minimum # # Units Cummulative Inv. above Actual Demand Demand Net Demand of Workers Produced Production Min required InventoryC/32 E x 32 I - DJuly 1250 1050 1050 33 2 0 1056 1056 6 306Aug 1100 1100 2150 35 0 2 1120 2176 26 326Sep 950 950 3100 29 6 0 928 3104 4 304Oct 900 900 4000 28 1 0 896 4000 0 300Nov 1000 1000 5000 32 0 4 1024 5024 24 324Dec 1150 1250 6250 39 0 7 1248 6272 22 4229 13 82 1982A B C D E G H I J Forecast Net Cummulative Cum. Units Monthly Cummulative Inv. Above Actual Demand Demand Net Demand produced Production Production Min required Inventory per worker 32 x 34 H - DJuly 1250 1050 1050 32 1088 1088 38 338Aug 1100 1100 2150 64 1088 2176 26 326Sep 950 950 3100 96 1088 3264 164 464Oct 900 900 4000 128 1088 4352 352 652Nov 1000 1000 5000 160 1088 5440 440 740Dec 1150 1250 6250 192 1088 6528 278 6781298 3198PROBLEM # 1Month Fire Hire Minimum inventory required per month = 300Ending Inventory = 400Employee-hours required per hour = 5 hoursWorking days per months = 20Each employee works 8-hour-dayWorkforce at the end of June = 35K CALCULATION K (Units produced by one worker in one day)Initial Inventory = 500TOTALK = 8/5 = 1.6# Units Produced by 1 worker in a month = 1.6 x 20 = 32In this problem there is sufficient inventory on hand to reduce the workforce by one worker in the months of Sep, Oct and Dec.That decision will allow to reduce the total inventory above minimum required from 338 units to 82.Month FMonth Fire Hire TOTALD/EPART B: Production Plan that meets demand but does not hire or fire workers during the six-month periodTOTAL323233Because there are 35 workers employed at the end of June, the constant workforce plan require fire 1 worker at thebeginning of July. No further hiring or firing of workers are required. The inventory levels that results from a constantworkforce of 34 workers appear in the following table.33Ratio 3334PROBLEM # 2Constant Workforce = 137. Therefore, hire 51 workers at the beginning of April.The inventory levels that results from a constant workforce of 137 shown in the table below.In 26 days 100 workers produced 12000 cases of beer Holding Cost = $0.75 per case per month Initial Inventory = 4500Ending Inventory = 3000Minimum inventory required per month = 1000PART A: Minimum constant workforce planCOST = (107) x (300) + (111) x (125) + (8802) x (0.75) = 52576.50PART B: Zero Inventory PlanPART B: Zero Inventory PlanK CALCULATION K (Units produced by one worker in one day)K = 12000 / (26 x 100) = 4.6153Hiring Cost = $125 per worker Firing Cost = $300 per worker Workforce at the end of March = 86COST = (51) x (125) + (31976) x (0.75) = 30357COST = (106) x (300) + (110) x (125) + (8285) x (0.75) = 51763.75In this problem there is sufficient inventory on hand to reduce the workforce by one worker in the months of June and August.PART C & DLINDO INPUTMINIMIZE125H1+125H2+125H3+125H4+125H5+125H6+300F1+300F2+300F3+300F4 +300F5+300F6+0.75I1+0.75I2+0.75I3+0.75I4+0.75I5+0.75I6SUBJECT TOW1-H1+F1=86W2-W1-H2+F2=0W3-W2-H3+F3=0W4-W3-H4+F4=0W5-W4-H5+F5=0W6-W5-H6+F6=0P1-50.7692W1=0P2-101.5384W2=0P3-92.3077W3=0P4-106.1538W4=0P5-73.8462W5=0P6-92.3077W6=0P1-I1=4000P2+I1-I2=9300P3+I2-I3=12200P4+I3-I4=17600P5+I4-I5=14000P6+I5-I6=6300I1>1000I2>1000I3>1000I4>1000I5>1000I6>3000ENDGIN W1GIN W2GIN W3GIN W4GIN W5GIN W6LINDO OUTPUTOBJECTIVE FUNCTION VALUE24445.35VARIABLE VALUE REDUCED COSTW199.000000228.461395W299.000000380.768982W3158.000000276.923096W4158.000000363.846039W5158.000000410.769287W6158.000000-230.769226H113.000000 0.000000H20.0000000.000000H359.0000000.000000H40.0000000.000000H50.000000125.000000H60.000000425.000000F10.000000425.000000F20.000000425.000000F30.000000425.000000F40.000000425.000000F50.000000300.000000F60.0000000.000000I11026.1507570.000000I21778.4522710.000000I34163.0688480.000000I43335.3696290.000000I51003.0689700.000000I69287.6855470.000000P15026.1508790.000000P210052.3017580.000000P314584.6171880.000000P416772.3007810.000000P511667.6992190.000000P614584.6171880.000000I NTERPRETATION OF THE SOLUTIONTotal Cost = $24445.35Total # of workers in April and May = 99Total # of workers in June, July, August and September = 158Total # of workers hired in April = 13Total # of workers hired in June = 59Total # of workers hired in May, July, August and September = 0Total # of workers fired in April, May, June, July, August and September = 0Inventory at the end of April = 1026 cases of beer.Inventory at the end of May = 1778 cases of beer.Inventory at the end of June = 4163 cases of beer.Inventory at the end of July = 3335 cases of beer.Inventory at the end of August = 1003 cases of beer.Inventory at the end of September = 9287 cases of beer.Total # of cases of beer produced in April = 5026Total # of cases of beer produced in May = 10052Total # of cases of beer produced in June = 14584Total # of cases of beer produced in July = 16772Total # of cases of beer produced in August = 11667Total # of cases of beer produced in September = 14584P LAN FOR P ART B WOULD BE THE SAME AS FOR P ART D. (N O FIRING)。