江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试数学(文)试卷

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江苏省常州市田家炳高级中学2017_2018学年高二生物下学期期末考试试题

江苏省常州市田家炳高级中学2017_2018学年高二生物下学期期末考试试题

2017-2018学年第二学期期末教学情况调研高二年级生物试卷一、单项选择题:本部分包括20题,每题2分,共计40分。

每题只有一个选项最符合题意。

1.下图表示只含有两个碱基对的DNA,图中含有的磷酸二酯键与游离磷酸基团数目分别是A.6、2B.6、4C.2、2D.2、42.下列有关生物工程的叙述正确的是A.大肠杆菌是基因工程常用的载体B.植物组织培养是植物细胞工程的基础C.动物细胞融合技术的最重要的用途是培育杂种动物D.人工诱变、基因工程等都能对微生物进行定向改造3.以下操作中,不能防止目的基因随花粉逃逸的是A.将目的基因导入受体细胞的线粒体中B.将目的基因导入受体细胞的叶绿体中C.将目的基因导入受体细胞的细胞核中D.将目的基因导入受体细胞的细胞质基质中4.下列有关植物细胞工程应用的叙述,正确的是A.利用组织培养技术培育脱毒苗,获得具有抗病毒的新品种B.将植物组培获得的愈伤组织外包裹上人工种皮,即获得人工种子C.利用植物细胞培养技术获得紫草素,是利用了植物细胞全能性的原理D.将萝卜(二倍体)和甘蓝(二倍体)进行体细胞杂交,可获得四倍体的“萝卜—甘蓝”5.2015年2月3日,英国议会下院通过一项历史性法案,允许以医学手段培育“三亲婴儿”。

三亲婴儿的培育过程可选用如下技术路线。

据图分析,下列叙述错误的是A.该技术可避免母亲的线粒体遗传病基因传递给后代B.捐献者携带的红绿色盲基因不能遗传给三亲婴儿C.三亲婴儿的染色体全部来自母亲提供的细胞核D.三亲婴儿的培育还需要早期胚胎培养和胚胎移植等技术6.以下关于单克隆抗体制备的叙述正确的是A.需将瘤细胞与未经免疫的B淋巴细胞融合B.第一次筛选是为了获得能够产生特定抗体的杂交瘤细胞C.第二次筛选是为了获得既能无限增殖又能产生抗体的杂种细胞D.单克隆抗体制备需要以动物细胞融合和动物细胞培养为基础7.牛雄性胚胎中存在特异性的H-Y 抗原,可在牛早期胚胎培养液中添加H-Y 单克隆抗体,筛选胚胎进行移植,以利用乳腺生物反应器进行生物制药。

江苏省田家炳中学2017-2018学年度第二学期高二数学(文科)第二次学情调研考试试题卷

江苏省田家炳中学2017-2018学年度第二学期高二数学(文科)第二次学情调研考试试题卷

江苏省田家炳实验中学
2017-2018学年度第二学期高二数学(文)第二次学情调研考试试题卷命题人:
审题人: 2018.05 一.填空题
1.命题“”的否定是____.
2.函数
的定义域是_____.3.已知幂函数
x y 的图象过点),(2,2,那么它的函数解析式为. 4.在区间2,3上随机取一个实数x ,则“1x ”的概率为__________.
5.从8名女生和4名男生中抽取
3名学生参加某娱乐节目,若按性别进行分层抽样,则女
生应抽取_________人. 6.为了防止职业病,某企业采用系统抽样方法,从该企业全体名员工中抽名员工做体检,现从名员工从
到进行编号,在中随机抽取一个数,如果抽到的是
,则从这个数中应抽取的数是__________.
7.一次考试后,从高三(
1)班抽取5人进行成绩统计,其茎叶图如右图所示,则这五人
成绩的方差为____.8.某校共有400名学生参加了一次数学竞赛,竞赛成绩都在
[50,100]内,且频率分布直方图如图所示(成绩分组为[50,60),[60,70),[70,80),[80,90),[90,100],则在本次
竞赛中,得分不低于80分的人数为______.9.春节期间支付宝开展了集福活动
,假定每次扫福都能得到一张福卡(福卡一共有五种:爱国福、富强福、和谐福、友善福、敬业福),且得到每一种类型福卡的概率相同,若小张已经得到了富强福、和谐福、友善福
,则小张再扫两次可以集齐五福的概率为_______. 10.下图是一个算法流程图,若输入值,则输出值的取值范围是____.。

江苏省常州市数学高二下学期理数期末考试试卷

江苏省常州市数学高二下学期理数期末考试试卷

江苏省常州市数学高二下学期理数期末考试试卷姓名:________ 班级:________ 成绩:________一、单选题 (共12题;共24分)1. (2分) (2018高二下·河北期中) 与极坐标表示的不是同一点的极坐标是()A .B .C .D .2. (2分) (2019高二下·吉林月考) 若直线的参数方程为(为参数),则直线的斜率为()A .B .C .D .3. (2分)(2018·安徽模拟) 设、是椭圆的左、右焦点,过的直线交椭圆于、两点,若,且轴,则椭圆的离心率等于()A .B .C .D .4. (2分) (2018高二下·济宁期中) 抛物线在点处切线的倾斜角是()A .B .C .D .5. (2分) (2017高二下·宁波期末) (已知函数f(x)= ,则y=f(x)的图象大致为()A .B .C .D .6. (2分)由曲线y=x2-1.直线x=0.x=2和x轴围成的封闭图形的面积(如图)是()A . (x2-1)dxB . |(x2-1)dx|C . |x2-1|dxD . (x2-1)dx+(x2-1)dx7. (2分) (2018高二下·黑龙江月考) 已知函数,其导函数的图象如图,则对于函数的描述正确的是()A . 在上为减函数B . 在处取得最大值C . 在上为减函数D . 在处取得最小值8. (2分) (2016高二上·福州期中) 已知M= dx,N= cosxdx,由程序框图输出S的值为()A . 1B . ln2C .D . 09. (2分) (2018高三上·重庆期末) 已知两非零复数,若,则一定成立的是()A .B .C .D .10. (2分) (2017高二下·南昌期末) 设i为虚数单位,复数为纯虚数,则实数a为()A .B . ﹣2C .D . 211. (2分)定义在R上的可导函数f(x),已知的图像如图所示,则的增区间是()A .B .C . (0,1)D . (1,2)12. (2分) (2018高三上·河南期中) 已知关于的不等式有且仅有两个正整数解(其中e=2.71828…为自然对数的底数),则实数的取值范围是()A . (, ]B . (, ]C . [ ,)D . [ ,)二、填空题 (共4题;共4分)13. (1分) (2019高二下·九江期末) 若复数()为纯虚数,则________.14. (1分) (2019高二上·武威期末) 若f(x)=x3 ,f′(x0)=3,则x0的值为________.15. (1分) (2019高三上·葫芦岛月考) 函数的极小值为________.16. (1分)(2017·东城模拟) (坐标系与参数方程选做题)已知直线(t为参数)与直线l2:2x﹣4y=5相交于点B,又点A(1,2),则|AB|=________三、解答题 (共6题;共50分)17. (5分)已知平面直角坐标系xOy中,以O为极点,x轴的非负半轴为极轴建立极坐标系,曲线C的参数方程为(α为参数),A,B在曲线C上,且A,B两点的极坐标分别为A(ρ1 ,),B(ρ2 ,).(I)把曲线C的参数方程化为普通方程和极坐标方程;(Ⅱ)求线段AB的长度.18. (10分)(2017·鄂尔多斯模拟) 已知在直角坐标系xOy中,曲线C1:(θ为参数),在以平面直角坐标系的原点O为极点,x轴的正半轴为极轴,取相同单位长度的极坐标系中,曲线C2:ρsin()=1.(1)求曲线C1的普通方程和曲线C2的直角坐标方程;(2)曲线C1上恰好存在三个不同的点到曲线C2的距离相等,分别求这三个点的极坐标.19. (10分)已知函数的图象如图,直线在原点处与函数图象相切,且此切线与函数图象所围成的区域(阴影)面积为 .(1)求的解析式;(2)若常数,求函数在区间上的最大值.20. (15分)(2017·息县模拟) 已知函数f(x)= + (1﹣a2)x2﹣ax,其中a∈R.(1)若曲线y=f(x)在点(1,f(1))处的切线方程为8x+y﹣2=0,求a的值;(2)当a≠0时,求函数f(x)(x>0)的单调区间与极值;(3)若a=1,存在实数m,使得方程f(x)=m恰好有三个不同的解,求实数m的取值范围.21. (5分)在△ABC的角A,B,C所对的边分别是a,b,c.虚数x=2+ai是实系数方程x2﹣cx+8=0的根.(1)求边长a,c.(2)若边长a,b,c成等比数列,求△ABC的面积.22. (5分)(2020·辽宁模拟) 如图,三棱柱中,平面,,,,,是的中点,是的中点.(Ⅰ)证明:平面;(Ⅱ)是线段上一点,且直线与平面所成角的正弦值为,求二面角的余弦值.参考答案一、单选题 (共12题;共24分)1-1、2-1、3-1、4-1、5-1、6-1、7-1、8-1、9-1、10-1、11-1、12-1、二、填空题 (共4题;共4分)13-1、14-1、15-1、16-1、三、解答题 (共6题;共50分)17-1、18-1、18-2、19-1、19-2、20-1、20-2、20-3、21-1、22-1、。

江苏省田家炳实验中学2017-2018学年高二数学下学期第二次学情调研考试试题 理

江苏省田家炳实验中学2017-2018学年高二数学下学期第二次学情调研考试试题 理

江苏省田家炳实验中学2017-2018学年高二数学下学期第二次学情调研考试试题理一、填空题(本大题共14小题,共70.0分)1、一组数据2,x,4,6,10的平均值是5,则此组数据的标准差是______ .2、如图,茎叶图记录了甲、乙两组各3名同学在期末考试中的数学成绩,则方差较小的那组同学成绩的方差为______ .3、将甲、乙、丙、丁四名学生分到三个不同的班,每个班至少分到一名学生,则不同的分法的总数是______ 用数字作答4、200辆汽车经过某一雷达地区,时速频率分布直方图如图所示,则时速不低于的汽车数量为______辆5、已知,则______.6、在冬奥会志愿者活动中,甲、乙等5人报名参加了A,B,C三个项目的志愿者工作,因工作需要,每个项目仅需1名志愿者,且甲不能参加A,B项目,乙不能参加B,C项目,那么共有______种不同的志愿者分配方案用数字作答7、的展开式中,的系数为______ .用数字作答8、抛掷一粒骰子,观察掷出的点数,设事件A为出现奇数,事件B为出现2点,已知,,则出现奇数点或2点的概率是______ .9、长方形ABCD中,,,O为AB的中点,在长方形ABCD内随机取一点,取到的点到O的距离大于1的概率为______ .10、口袋中装有大小质地都相同、编号为1,2,3,4,5,6的球各一只现从中一次性随机地取出两个球,设取出的两球中较小的编号为X,则随机变量X的数学期望是______ .11、设随机变量X的分布列如下:若数学期望,则方差 ______ .12、已知0,,,若随机选取m,n,则直线恰好不经过第二象限的概率是______.13、若,,则 ______ .14、甲罐中有5个红球,2个白球和3个黑球,乙罐中有4个红球,3个白球和3个黑球先从甲罐中随机取出一球放入乙罐,分别以,和表示由甲罐取出的球是红球,白球和黑球的事件;再从乙罐中随机取出一球,以B表示由乙罐取出的球是红球的事件,则下列结论中正确的是______写出所有正确结论的编号.;;事件B与事件相互独立;,,是两两互斥的事件;的值不能确定,因为它与,,中哪一个发生有关.二、解答题(本大题共6小题,共72.0分)15、4男3女站成一排,求满足下列条件的排法共有多少种?任何两名女生都不相邻,有多少种排法?男甲不在首位,男乙不在末位,有多少种排法?男生甲、乙、丙顺序一定,有多少种排法?男甲在男乙的左边不一定相邻有多少种不同的排法?16、一个袋中装有大小相同的黑球和白球共9个,从中任取2个球,记随机变量X为取出2球中白球的个数,已知.Ⅰ求袋中白球的个数;Ⅱ求随机变量X的分布列及其数学期望.17、已知展开式前三项的二项式系数和为22.Ⅰ求n的值;Ⅱ求展开式中的常数项;求展开式中二项式系数最大的项.18、已知空间三点0,,1,,0,,设,.Ⅰ求和的夹角的余弦值;Ⅱ若向量与互相垂直,求实数k的值;Ⅲ若向量与共线,求实数的值.分别是AB、PC的中点.求证:共面;求证:.20、某射击小组有甲、乙两名射手,甲的命中率为,乙的命中率为,在射击比武活动中每人射击发两发子弹则完成一次检测,在一次检测中,若两人命中次数相等且都不少于一发,则称该射击小组为“先进和谐组”;若,求该小组在一次检测中荣获“先进和谐组”的概率;计划在2011年每月进行1次检测,设这12次检测中该小组获得“先进和谐组”的次数,如果,求的取值范围.答案和解析【答案】1. :2.3. 364. 765. 1或36. 217.8. 9. 10. 11. 35 12. 13.3 14.15. 解:任何两名女生都不相邻,则把女生插空,所以先排男生再让女生插到男生的空中,共有种不同排法.甲在首位的共有种,乙在末位的共有种,甲在首位且乙在末位的有种,因此共有种排法.人的所有排列方法有种,其中甲、乙、丙的排序有种,其中只有一种符合题设要求,所以甲、乙、丙顺序一定的排法有种男甲在男乙的左边的7人排列与男甲在男乙的右边的7人排列数相等,而7人排列数恰好是这二者之和,因此满足条件的有种排法.16. 解:Ⅰ设袋中有白球n个,则,解得.Ⅱ由可知:袋中共有3个黑球,6个白球.随机变量X的取值为0,1,2,则,,.随机变量X的分布列如下:.17. 解:由题意,展开式前三项的二项式系数和为22.Ⅰ二项式定理展开:前三项系数为:,解得:或舍去.即n的值为6.Ⅱ由通项公式,令,可得:.展开式中的常数项为;是偶数,展开式共有7项则第四项最大展开式中二项式系数最大的项为.18. 解:,.Ⅰ,和的夹角的余弦值为.Ⅱ,向量与互相垂直,,或.Ⅲ,向量与共线,存在实数,使得即1,,或.19. 证明:如图,以A为原点,AB为x轴,AD为y轴,AP为z轴,建立空间直角坐标系,设,,,则:0,,0,,2b,,2b,,0,,为AB的中点,F为PC的中点,0,,b,,b,,0,,2b,,,共面.0,,b,,0,,b,,,.20. 解:,,根据“先进和谐组”的定义可得该小组在一次检测中荣获“先进和谐组”的包括两人两次都射中,两人恰好各射中一次,该小组在一次检测中荣获“先进和谐组”的概率该小组在一次检测中荣获先进和谐组”的概率而,所以由知,解得:【解析】1. 解:一组数据2,x,4,6,10的平均值是5,,解得,此组数据的方差,此组数据的标准差.故答案为:.由已知条件先求出x的值,再计算出此组数据的方差,由此能求出标准差.本题考查一组数据的标准差的求法,解题时要认真审题,注意数据的平均数和方差公式的求法.2. 解:由已知可得甲的平均成绩为,方差为;乙的平均成绩为,方差为,所以方差较小的那组同学成绩的方差为.故答案为:由茎叶图数据分别求出甲乙两组的方差,比较大小.本题考查了茎叶图的数据统计中,求平均数以及方差,关键是熟记公式.3. 解:由题意知本题是一个分步计数问题,4位同学分到三个不同的班级,每个班级至少有一位同学,先选两个人作为一个整体,问题变为三个元素在三个位置全排列,共有种结果,故答案为:36.本题是一个分步计数问题,先选两个元素作为一个元素,问题变为三个元素在三个位置全排列,得到结果.本题考查分步计数原理,是一个基础题,也是一个易错题,因为如果先排三个人,再排最后一个人,则会出现重复现象,注意不重不漏.4. 解:时速不低于的汽车的频率为时速不低于的汽车数量为故答案为:76先根据“频率组距”求出时速不低于的汽车的频率,然后根据“频数频率样本容量”进行求解.本题考查频率分布直方图的相关知识,直方图中的各个矩形的面积代表了频率,频数频率样本容量,属于基础题.5. 解:因为,可得或解得或.故答案为1或3由组合数的性质和方程,可得或,求解即可.本题考查组合及组合数公式,考查计算能力,是基础题.6. 解:若甲,乙都参加,则甲只能参加C项目,乙只能参见A项目,B项目有3种方法,若甲参加,乙不参加,则甲只能参加C项目,A,B项目,有种方法,若甲参加,乙不参加,则乙只能参加A项目,B,C项目,有种方法,若甲不参加,乙不参加,有种方法,根据分类计数原理,共有种.由题意可以分为四类,根据分类计数原理可得.本题考查了分类计数原理,关键是分类,属于中档题.7. 解:的展开式的通项为,令,求得,的系数为故答案为:.在二项展开式的通项公式中,令x的幂指数等于,求出r的值,即可求得开式中x的系数.本题主要考查二项式定理的应用,二项展开式的通项公式,求展开式中某项的系数,属于中档题.8. 解:由题意知抛掷一粒骰子出现奇数和出现2点是互斥事件,,,出现奇数点或2点的概率根据互斥事件的概率公式得到,故答案为:由题意知抛掷一粒骰子出现奇数和出现2点是互斥事件,又根据两个事件的概率,根据互斥事件的概率之和得到出现奇数点或2点的概率.本题考查互斥事件的概率,解题的关键是看清两个事件的互斥关系,再根据互斥事件的概率公式得到结果,是一个基础题.9. 解:根据几何概型得:取到的点到O的距离大于1的概率:.故答案为:本题利用几何概型解决,这里的区域平面图形的面积欲求取到的点到O的距离大于1的概率,只须求出圆外的面积与矩形的面积之比即可.本题主要考查几何概型如果每个事件发生的概率只与构成该事件区域的长度面积或体积成比例,则称这样的概率模型为几何概率模型,简称为几何概型.10. 解:由题设知X的可能取值为1,2,3,4,5.随机地取出两个球,共有:种,,,,,,随机变量X的分布列为故E.故答案为:.确定X的可能取值为1,2,3,4,5,求出相应的概率,可求随机变量X的数学期望本题考查离散型随机变量的数学期望的求法,确定X的可能取值,求出相应的概率是关键.11. 解:,化为又,联立,解得故答案为利用,分布列的性质,联立即可解得,再利用方差的计算公式即可得出本题考查了离散型随机变量的分布列的数学期望及其方差,属于基础题.12. 解:由得,要使直线恰好不经过第二象限,则或者,即或,,或,共有2个结果.0,,,,n的选择共有个结果,则根据古典概率的概率公式得所求的概率,故答案为:根据古典概型的概率公式求出相应事件的个数,即可得到结论.本题主要考查古典概型的概率的计算,根据直线不经过第二象限,分别求出对应斜率和截距的关系是解决本题的关键,比较基础.13. 解:0,,1,本题直接根据空间向量的坐标运算即对应坐标想加减和模的公式即坐标的平方和的算术平方根进行计算即可本题主要考查了空间向量的概念及基本运算,属于基础题14. 解:易见,,是两两互斥的事件,.故答案为:本题是概率的综合问题,掌握基本概念,及条件概率的基本运算是解决问题的关键本题在,,是两两互斥的事件,把事件B的概率进行转化,可知事件B的概率是确定的.概率的综合问题,需要对基本概念和基本运算能够熟练掌握.15. 任何两个女生都不得相邻,利用插空法,问题得以解决,男甲不在首位,男乙不在末位,利用间接法,故问题得以解决,男生甲、乙、丙顺序一定,利用定序法,问题得以解决.由于男甲要么在男乙的左边,要么在男乙的右边,故利用除法可得结论.本题考查排列、组合知识的运用,考查学生分析解决问题的能力,正确选用方法是关键.16. 设袋中有白球n个,利用古典概型的概率计算公式即可得到,解出即可;由可知:袋中共有3个黑球,6个白球随机变量X的取值为0,1,2,3,求出相应的概率,即可得出随机变量X的分布列及其数学期望.熟练掌握古典概型的概率计算公式和超几何分布的概率计算公式是解题的关键.17. Ⅰ利用公式展开得前三项,系数和为22,即可求出n.Ⅱ利用通项公式求解展开式中的常数项即可.利用通项公式求展开式中二项式系数最大的项.本题主要考查二项式定理的应用,通项公式的计算,属于基础题.18. 利用向量夹角公式即可得出;利用向量垂直于数量积的关系即可得出;利用向量共线定理即可得出.19. 以A为原点,AB为x轴,AD为y轴,AP为z轴,建立空间直角坐标系,设,,,求出b,,0,,2b,,从而,由此能证明共面.求出0,,b,,由,能证明.本题考查三个向量共面的证明,考查两直线垂直的证明,是基础题,解题时要认真审题,注意向量法的合理运用.20. 根据甲的命中率为,乙的命中率为,两人命中次数相等且都不少于一发,则称该射击小组为“先进和谐组”;我们可以求出该小组在一次检测中荣获“先进和谐组”的概率;由已知结合的结论,我们可以求出该小组在一次检测中荣获“先进和谐组”的概率含参数,由,可以构造一个关于的不等式,解不等式结合概率的含义即可得到的取值范围.本题考查的知识点是相互独立事件的概率乘法公式,二项分布与n次独立重复试验的模型,中关键是要列举出该小组在一次检测中荣获“先进和谐组”的所有可能性,的关键是要根据,可以构造一个关于的不等式.。

江苏省常州市重点名校2017-2018学年高二下学期期末达标测试数学试题含解析

江苏省常州市重点名校2017-2018学年高二下学期期末达标测试数学试题含解析

江苏省常州市重点名校2017-2018学年高二下学期期末达标测试数学试题一、选择题:本题共12小题,在每小题给出的四个选项中,只有一项是符合题目要求的。

1.双曲线()2222100x y a b a b-=>,>的左右焦点分别为F 1,F 2,过F 1的直线交曲线左支于A ,B 两点,△F 2AB是以A 为直角顶点的直角三角形,且∠AF 2B =30°.若该双曲线的离心率为e ,则e 2=( ) A .1143+ B .1353+ C .1663- D .19103-【答案】D 【解析】 【分析】设22BF m =,根据2F AB ∆是以A 为直角顶点的直角三角形,且230AF B ∠=o,以及双曲线的性质可得212(33),2(23)AF a AF a =-=-,再根据勾股定理求得,a c 的关系式,即可求解.【详解】由题意,设22BF m =,如图所示,因为2F AB ∆是以A 为直角顶点的直角三角形,且230AF B ∠=o, 由212AF AF a -=,所以132AF m a =-, 由212BF BF a -=,所以122BF m a =-,所以11AF BF AB +=,即3222m a m a m -+-=, 所以2(31)m a =-,所以232(31)2(33)AF a a =⋅-=-,12(33)22(23)AF a a a =--=-, 在直角12F AF ∆中,222124AF AF c +=,即222224(33)4(23)4a a c -+-=,整理得22(19103)a c -=,所以22219103c e a==-,故选D.【点睛】本题主要考查了双曲线的定义,以及双曲线的几何性质——离心率的求解,其中求双曲线的离心率(或范围),常见有两种方法:①求出,a c ,代入公式ce a=;②只需要根据一个条件得到关于,,a b c 的齐次式,转化为,a c 的齐次式,然后转化为关于e 的方程,即可得e 的值(范围)..2.已知空间向量(3,a =r 1,0),(),3,1b x =-r ,且a b ⊥r r ,则(x = )A .3-B .1-C .1D .2【答案】C 【解析】 【分析】利用向量垂直的充要条件,利用向量的数量积公式列出关于x 的方程,即可求解x 的值. 【详解】由题意知,空间向量a (3,r =1,0),()b x,3,1=-r ,且a b ⊥rr , 所以a b 0⋅=rr ,所以31(3)010x +⨯-+⨯=,即3x 30-=,解得x 1=.故选C . 【点睛】本题主要考查了向量垂直的充要条件,以及向量的数量积的运算,其中解答中熟记向量垂直的条件和数量积的运算公式,准确计算是解答的关键,着重考查了运算与求解能力,属于基础题. 3. “0x ∀>,2sin x x >”的否定是( ) A .0x ∀>,2sin x x < B .0x ∀>,2sin x x ≤ C .00x ∃≤,002sin x x ≤ D .00x ∃>,002sin x x ≤【答案】D 【解析】 【分析】通过命题的否定的形式进行判断. 【详解】因为全称命题的否定是特称命题,故“0x ∀>, 2sin x x >”的否定是“00x ∃>, 002sin x x ≤”. 故选D. 【点睛】本题考查全称命题的否定,属基础题. 4.下列关于独立性检验的叙述:①常用等高条形图展示列联表数据的频率特征; ②独立性检验依据小概率原理;③样本不同,独立性检验的结论可能有差异;④对分类变量X 与Y 的随机变量2K 的观测值k 来说,k 越小,X 与Y 有关系的把握程度就越大. 其中正确的个数为( ) A .1 B .2C .3D .4【答案】C 【解析】分析:根据独立性检验的定义及思想,可得结论.详解:①常用等高条形图展示列联表数据的频率特征;正确; ②独立性检验依据小概率原理;正确;③样本不同,独立性检验的结论可能有差异;正确;④对分类变量X 与Y 的随机变量2K 的观测值k 来说,k 越大,X 与Y 有关系的把握程度就越大.故④错误. 故选C.点睛:本题考查了独立性检验的原理,考查了推理能力,属于基础题.5.已知双曲线C :22221(0,0)x y a b a b-=>>的左、右焦点分别为1F ,2F ,以线段12F F 为直径的圆与双曲线的渐近线在第一象限的交点为P ,且P 满足122PF PF b -=,则C 的离心率e 满足( )A .2310e e -+=B .42310e e -+=C .210e e --=D .4210e e --=【答案】D 【解析】分析:联立圆与渐近线方程,求得M 的坐标,由122PF PF b -=,得点P 在双曲线右支上,代入双曲线方程化简即可求. 详解:由222b y xa x y c⎧=⎪⎨⎪+=⎩,得2222x a y b ⎧=⎨=⎩,即(),P a b , 由122PF PF b -=,,即2b =,由222cb ac e a=-=, , 化简得42240c a c a --=,即4210e e --=, 故选D.点睛:本题考查双曲线的简单几何性质,点到直线的距离公式,考查计算能力,属于中档题.6.设函数()f x 的定义域为R ,满足(1)()f x f x +=,且当(0,1]x ∈时()(1)f x x x =-.则当(2,1]x ∈--,()f x 的最小值是( )A .12-B .116-C .18-D .14-【答案】D 【解析】 【分析】先求出函数()y f x =在区间(]2,1--上的解析式,利用二次函数的性质可求出函数()y f x =在区间(]2,1--上的最小值.【详解】由题意可知,函数()y f x =是以1为周期的周期函数,设(]2,1x ∈--,则(]20,1x +∈,则()()()()222132f x f x x x x x =+=++=++,即当(]2,1x ∈--时,()22313224f x x x x ⎛⎫=++=+- ⎪⎝⎭, 可知函数()y f x =在32x =-处取得最小值,且最小值为()min3124f x f ⎛⎫=-=- ⎪⎝⎭, 故选D. 【点睛】本题考查函数的周期性以及函数的最值,解决本题的关键就是根据周期性求出函数的解析式,并结合二次函数的基本性质求解,考查计算能力,属于中等题.7.若关于x 的不等式22ln 0x a x +-<有解,则实数a 的取值范围是( ) A .1,ln 22⎛⎫-∞--⎪⎝⎭B .1,ln 22⎛⎫-∞-⎪⎝⎭C .1ln 2,02⎛⎫-- ⎪⎝⎭D .1ln 2,2⎛⎫--+∞ ⎪⎝⎭【答案】A 【解析】 【分析】先将不等式转化为2ln 2a x x <-,然后构造函数2()ln 2f x x x =-,只要a 小于()f x 的最大值即可【详解】解:由22ln 0x a x +-<,得2ln 2a x x <-,令2()ln 2(0)f x x x x =->,则2'114()4(0)x f x x x x x-=-=>当102x <<时,'()0f x >;当12x >时, '()0f x < 所以()f x 在1(0,)2上单调递增,在1(,)2+∞上单调递减所以当12x =时,()f x 取最大值1111()ln 2ln 22242f =-⨯=--,所以1ln 22a <--故选:A 【点睛】此题考查了利用导数研究函数的单调性和最值,属于中档题 8.若函数没有零点,则实数的取值范围是A .B .C .D .【答案】A 【解析】 【分析】 将问题转化为曲线与直线没有交点,并将函数表示为分段函数的形式,并作出该函数的图象,分析直线的斜率与函数图象每段折线的斜率的大小关系,结合图象得出实数的取值范围。

江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试英语试卷

江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试英语试卷

江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试英语试卷一、单项选择(★★★★★) 1 . The business school professor studies teaming, _______ people come together quickly (and often temporarily) to solve new or urgent problems.A.which B.whereC.that D.how(★) 2 . ---How are you getting along with Jim now?---Well, OK now. But he _______ until I apologized.A.didn’t forgive B.hasn’t forgivenC.hadn’t forgiven D.won’t forgive(★★★★★) 3 . ---John has just been promoted to general manager of our company.---_______. He is always devoted to his work.A.A little bird told me.B.Mind your own business.C.Good for him.D.There’s no way to tell.(★★★) 4 . You _______ how angry the boss was had you been here with us.A.would see B.had seenC.would have seen D.saw(★★★)5 . Some people don’t show _______ in their choice of books, reading whatever they can get.A.discrimination B.combinationC.conservation D.reservation(★★★★★) 6 . He found a purse on the seat and decided to return it to the owner, _______ with the address on the electricity bill.A.started B.startingC.having started D.to start(★★★★★)7 . If you use too much force, you’ll _______ the key, bending it out of shape.A.break B.seizeC.twist D.split(★★★) 8 . Sometimes wrong doings will stay covered _______ we speak up.A.if B.whenC.unless D.as long as(★★★) 9 . ---Would you like to go the football game tonight?---Oh, sorry. I _______ to see the film So Young.A.arranged B.have arrangedC.had arranged D.would arrange(★★★★★) 10 . Looking at old photographs of yourself on social websites can improve your mood, and this finding _______ previous researches, which suggested otherwise.A.conducts B.contradictsC.confuses D.condemn(★★★★★) 11 . The international situation is quite _______ at present. Any move towards a country’s own interest may cause immediate conflicts.A.stable B.violentC.delicate D.sharp(★★★★★) 12 . They have _______ a few newspapers to keep themselves informed of the hot issues of the changing time.A.subscribed to B.corresponded toC.responded to D.contributed to(★★★★★) 13 . Never for a second in our life _______ the importance of keeping our family company.A.had we forgotten B.we have forgottenC.we should forget D.should we forget(★★★★★) 14 . Just make sure you are _______ your inner voice while making these decisions.A.in tune with B.in parallel withC.in connection with D.in comparison with(★★★) 15 . In her talk, Lee focused on joy and _______ we can all find – and create – more of it in life.A.what B.whereC.when D.how二、完形填空(★★★★★) One morning, I walked down the path to my car and right into a huge spider web that had appeared overnight.I felt _______for not having seen it or having _________ myself of the web tendrils (须状物), and went______my way. During the meeting with our client, I saw a look of pure _______ crossed his face. After I went to the _________, I figured it out.The next morning, the ______ same scene occurred, and I felt even more foolish. _______a moment, I thought I should not _______ myself.On the third day, I was ______to look for the web – the spider had rewoven it,_______this time off the path in the bushes.How surprising it was to _______that the spider and I had learned the exact same _______ in the same amount of time.It is _______ for certain things in life to happen to you. There will be heartbreak, _______, and days where you feel like you aren’t special or purposeful. You cannot let these _______ you. If you don’t_______ yourself to move past what happened and what was felt, you will _______ your future with that pair of glasses, and nothing will be able to change that _______.As a saying _______, “The only mistake in life is the lesson not _______.” (Albert Einstein)16 . A.angry B.frustrated C.impatient D.foolish A.angry B.frustrated C.impatient D.foolishA.angry B.frustrated C.impatient D.foolish17 . A.removed B.rid C.reminded D.accused A.removed B.rid C.reminded D.accusedA.removed B.rid C.reminded D.accused18 . A.in B.on C.by D.downA.in B.on C.by D.downA.in B.on C.by D.down19 . A.surprise B.excitement C.curiosity D.embarrassment A.surprise B.excitement C.curiosity D.embarrassmentA.surprise B.excitement C.curiosity D.embarrassment20 . A.meetingroomB.waiting room C.bathroom D.sitting roomA.meeting room B.waitingroomC.bathroom D.sitting roomA.meeting room B.waitingroomC.bathroom D.sitting room21 . A.funny B.single C.very D.strange A.funny B.single C.very D.strangeA.funny B.single C.very D.strange22 . A.Within B.Before C.After D.For A.Within B.Before C.After D.ForA.Within B.Before C.After D.For23 . A.forgive B.blame C.annoy D.comfort A.forgive B.blame C.annoy D.comfortA.forgive B.blame C.annoy D.comfort24 . A.worried B.due C.anxious D.careful A.worried B.due C.anxious D.carefulA.worried B.due C.anxious D.careful25 . A.but B.and C.otherwise D.still A.but B.and C.otherwise D.stillA.but B.and C.otherwise D.still26 . A.prove B.confirm C.admit D.realize A.prove B.confirm C.admit D.realizeA.prove B.confirm C.admit D.realize27 . A.thought B.approach C.lesson D.trickA.thought B.approach C.lesson D.trickA.thought B.approach C.lesson D.trick28 . A.unhappy B.common C.regular D.heart-breaking A.unhappy B.common C.regular D.heart-breakingA.unhappy B.common C.regular D.heart-breaking29 . A.confusion B.conquer C.consensus D.calculation A.confusion B.conquer C.consensus D.calculationA.confusion B.conquer C.consensus D.calculation30 . A.disappoint B.weaken C.trap D.break A.disappoint B.weaken C.trap D.breakA.disappoint B.weaken C.trap D.break31 . A.promise B.allow C.deny D.require A.promise B.allow C.deny D.requireA.promise B.allow C.deny D.require32 . A.look at B.reflect on C.prepareforD.think aboutA.look at B.reflect on C.prepare for D.think aboutA.look at B.reflect on C.prepare for D.think about33 . A.saying B.occurrence C.future D.judgment A.saying B.occurrence C.future D.judgmentA.saying B.occurrence C.future D.judgment34 . A.has B.goes C.spreads D.says A.has B.goes C.spreads D.saysA.has B.goes C.spreads D.says35 . A.given B.taught C.learned D.addressed A.given B.taught C.learned D.addressedA.given B.taught C.learned D.addressed三、阅读理解(★★★) London to Brighton Bike RideThe startThe bike ride starts at Clapham Common tube stationRide carefullyWe put together as many facilities as possible to help ensure you have a trouble-free day. But we also rely on you to ride safely and with due consideration for other cyclists and road users. Although many roads are closed to oncoming traffic, this is not always the case and you should be aware of the possibility that there could be vehicles coming in the opposite direction.Please do not attempt reckless overtaking while riding---remember it is NOT a race.______________If you have an accident, ask a marshal for help; they are in contact with the support/emergency services. To call for help from our motorcycle marshals, give a ‘thumbs down’ signal. The marshal will do all he/she can to help, providing he/she is not already going to a more serious accident. If a motorcycle marshal slows down to help you, but you have just stopped for a rest and don’t need help, please give a ‘thumbs up’ signal and he/she will carry on. Remember---thumbs down means ‘I need help’.In case of breakdownRefer to your route map and make your way to a Mechanics Point. Mechanical assistance is free when you show your Rider Identity Card; you just pay for the parts.Refreshment stopsLook out for these along the route. Most are organized by voluntary clubs and their prices give you real value for money. They are also raising money for their local communities and the British Heart Foundation, so please give them your support.Rain or shine---be preparedIn the event of very bad weather, watch out for signs to wet weather stations en route. Good waterproofs, like a cycle cape, are essential. Our first aid staff can only supply bin liners and by the time you get one you may be very wet. However, the English summer is unpredictable---it may also be hot, so don’t forget the sun protection cream as well!If you have to drop outWe will try to pick up your bike for you on the day. Call Bike Events(01225310859) no more than two weeks after the ride to arrange collection. Sorry, we cannot guarantee this service nor can we accept liability for any loss or damage to your bike. Bike Events will hold your bike for three months, after which it may be disposed of. You will be charged for all costs incurred in returning your cycle.36 . Which of the following subtitles might be suitable for the blank? 37 . Which of the following is WRONG about the Bike Ride?A.Emergency service B.Attracting assistance C.Marshal’s job D.Contacting the marshal A.The weather at the time of the Bike Ride is quite changeableB.The drinks or waters along the way may be cheaper than usualC.You don’t need to pay to replace a broken part of the bikeD.If you give up halfway and abandon your bike, it may be lost.(★★★★★) In mid-January, Cape Town officials announced that the world-class South African city of four million residents would run out of water on April 12. The date, nicknamed “Day Zero,” has since been postponed multiple times, thanks to the intense conservation efforts by locals, a sharp reduction in agricultural water usage, and a 10 billion-liter donation from the private reservoirs(水库) of the Groenland Farmers Association.The city now has enough water to sustain the current level of usage until July 9, giving residents hope that the rainy season, which begins in June, will be more regular than has been the case lately.Four years ago, Cape Town’s water disaster would have seemed impossible given that the city’s six dam, which can hold 230 billion liters of water, were filled to the brim. However, three years of low rainfall – a third of normal levels – and the ever-increasing population, have reduced the dams to puddles.In an attempt to avoid Day Zero, the government has imposed a strict 50-liter daily limit for all households. Residents are being urged to reduce their water usage by making small changes like taking shorter showers and reusing bathing water to flush toilets. Those that use more have to pay heavy fines.When Day Zero strikes, a million homes or about 75 percent of the city will lose access to running water. Residents will instead have to wait in line at the over 200 water distribution centers established around the city to obtain 25 liters a day.Though conservation measures will help in the short run, only nature can solve the problem. If the city gets enough rainfall during its winter season from June to August, it will provide much-needed relief. However, the local officials are not sure it will happen.38 . What does the underlined word “brim” in the second paragraph probably mean? 39 . What effort is being made now to avoid Day Zero? 40 . What does the last paragraph mainly want to convey? 41 . What is the author’s purpose in writing this passage?A.bottom B.top edgeC.extended part D.central partA.Limiting the daily usage of water to 25 liters.B.Establishing 200 water distribution centers in the city.C.Reducing the city population as much as possibleD.Restricting water usage in agriculture significantlyA.Tomorrow is still unknown.B.Current efforts will pay off.C.Man is at the mercy of nature.D.It’s time to make joint efforts.A.To inform us of the severe situation of water shortage in Cape Town.B.To appeal to the world to come together to help people CapeTown.C.To explain the cause of the severe water shortage in Cape Town.D.To applaud the efforts by people in Cape Town to address watershortage.(★★★★) University graduates Mallorie Brodie and Lauren Hasegawa, who invented a smartphone app that tracks construction defects(缺陷)for commercial builders, had a tiger by the tail. Bridgit, which they founded in 2012, launched a cloud-based communications platform that helped manage defects on construction sites, which can delay projects and result in costly repairs if left unchecked. The smartphone application lets site supervisors take photos of cracks or damaged paint, share them with employees and track the problems to solution.More than 600 subcontractors used the pilot version in many building sites before the commercial version, called Closeout, officially launched.Feedback(反馈)was so good that they began to wonder: Why limit their invention to a specific industry? Why not turn it into some kind of a handy tool for consumers too? This became their dilemma. In other words, should they stay the course or look for wider applications of their app?The experts polled all agreed Bridgit should stay focused on its original goal. Ms. Hasegawa and Ms. Brodie took that advice.As more business customers signed on, it became clear that they made the right decision. Since then, the company’s growth has been rapid.Earlier this year, Bridgit launched Closeout ,which is designed so that even the least tech-savvy can use it easily. Today, the app is being used on sites across Canada and the United States and even by top general contractors(承包商).In October, Bridgit was named to the Canadian Innovation Exchange’s top 20 list of Canada’s most innovative companies working in digital media and information and communication technology .But Ms. Hasegawa and Ms. Brodie are not resting on their glories. They have also been collecting feedback on Closeout from customers, and they’ll launch a new version in the spring. It will target not only general contractors but developers and building owners, too.42 . The two graduates invented the smartphone application to _______. 43 . The underlined word in Paragraph 7 most probably means _______? 44 . According to the passage, what may contribute to the graduates’ success? 45 . The graduates’ future plan is to _______.A.track construction sites and commercial buildersB.provide a communication platform to share photosC.avoid project delay or costly repairs in constructionD.enable supervisors to take and share photos of buildingsA.keen on technology B.weak in technologyC.addicted to technology D.good at technologyA.Investing in your strengths B.Serving more customers C.Innovating technology D.Simplifying technologyA.launch a new application in the springB.collect feedbacks from customers on CloseoutC.include different people in construction industryD.target more consumers from various industries(★★★★) My dearest daughter, as I looked across at you sitting on the sofa watching The X Factor, I noticed that you are no longer a child, and that having just celebrated your 14th birthday, you are now a young woman starting a journey into becoming an adult woman. As I looked at you, I remembered myself at 14, and the vastly different places we are beginning this journey from.Your identity as a mixed-race young woman, with an English father and a Pakistani mother, has already influenced how you place yourself in this world. As yet, you are unaware of the personal struggles that I took at the age of 25 to marry. How it felt when my mother refused to come to my wedding. The sharp criticisms of the Asian community that such marriages do not work out and always end in divorce. The confidence I had to grow, as we chose to live in a multicultural community, as I refused to be shamed into living in the leafier white suburbs.Then, at the age of 30, I became your mum with all the joys and struggles this brought, as I refused the Asian traditions for a new baby's arrival. From your birth, your life could not have been more different from mine. I was brought up on a council estate, within a tight-knit extended Muslim family, through which poverty, racism and neglect were woven. I was never given the freedoms or the opportunity to experience new things. Now, as I hear you play your piano. I am grateful that you have these opportunities.So many doors were closed to me as a young person, and as I fought for small steps of freedom, I soon learned that it was better to do what I wanted without the knowledge of my parents, and so deceit and deception(欺骗) became woven into my life too. The pressures to obey, to be a "good Muslim" girl and keep the family honour, were choking. Behind closed doors at home, the neglect and abuse took place. It was hidden, I felt the shame, lived with the fear and suffered alongside my sister and two younger brothers. Oh, the power we thought our parents had over us! I was convinced that one day my father would indeed beat us so hard that leaving us for dead, he would, as his threats said he would, bury us in the large back garden, and tell the school he had taken us back to Pakistan for good. My sister and I longed for a different blue sky to live under.As a daughter of immigrant parents, I carried their hopes of a better education for their children--my own veins(血管) pulsing with the hard- work ethic(道德) and need to be grateful for the opportunity of a free education. And it was education that provided me with the strength to find my own blue sky.I fought to leave home to go to university at the age of 18, and never returned to live with my parents again.Now as you explore your mixed-race heritage, which I hope we have supported you to do with visits to Pakistan and ensuring you go to multi-cultural schools, I want you to take the very best of all that is Asian with you as you become a woman.I want you to know that although your journey has been vastly different. I am excited as I watch you standing on the threshold of becoming a woman for all the adventures and possibilities the futureholds for you.May you fly your blue sky with grace, confidence and hope as you find your place in this beautiful and crazy world.Loving you now and always. Mommy46 . Mommy's mother refused to attend her wedding party because _________. 47 . What can be inferred from mommy's Muslim family life? 48 . From the fourth paragraph, we can see that Mommy was very _________. 49 . Mommy sends her daughter to multicultural schools to _________. 50 . We can learn from the passage that Mommy _________.A.she struggled to break away from the family before itB.her marriage was against the tradition of the communityC.she would leave the family to settle in the white suburbsD.she refused the Asian tradition for a new baby’s arrivalA.She was forced to drop out of school.B.She behaved like a good Muslim girl.C.She fought against her Muslim identity.D.She suffered much abuse in the family.A.determined B.realistic C.ambitious D.tolerantA.prepare the daughter for different adventures in futureB.ensure the daughter more opportunities to visit PakistanC.increase the daughter’s exposure to different culturesD.encourage the daughter to grow up to be a better womanA.is regretful for giving her daughter the mixed-race identityB.encourages her daughter to explore her origin and pursue her dreamC.won’t forgive her parents for the sufferings she had during childhoodD.criticizes the social traditions and prejudice in her community四、任务型阅读(★★★★)请认真阅读下列短文, 并根据所读内容在文章后表格中的空格里填入一个最恰当的单词。

2017-2018学年江苏省田家炳高级中学高二下学期期末考试英语试题 解析版

2017-2018学年江苏省田家炳高级中学高二下学期期末考试英语试题 解析版

2017学年度第二学期期末质量调研高二英语试题第一卷 (选择题共85分)第一部分:听力(共两节,满分20 分)第一节听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What does Miss Jamison think Ted should do?A. Drive faster.B. Leave sooner.C. Check the weather forecast.2. How often do Janet’s parents call her?A. About twice a week.B. Around once a month.C. About twice a month.3. Where will the man probably write his paper?A. At home.B. In a computer lab.C. At the library.4. Where does the conversation take place?A. At the gym.B. At a movie theater.C. At school.5. What is the conversation mainly about?A. Taking math class.B. Borrowing notes.C. Visiting the amusement park.第二节听下面5段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料,回答第6、7题。

6. What goes on the second line in the center?A. The sender’s district.B. The receiver’s address.C. The receiver’s name.7. What does the woman still need to buy?A. A postage stamp.B. A proper envelope.C. Airmail insurance.听第7段材料,回答第8至10题。

江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试语文试卷

江苏省常州市田家炳高级中学2017-2018学年高二下学期期末考试语文试卷

常州市“12校合作联盟”2017学年度第二学期期末质量调研高二语文试题注意:本试卷共6页,19小题,满分160分。

考试时间150分钟。

请按照题号将答案填涂或书写在答题卡相对应的答题区域内,将答案直接书写在本试卷上无效。

一、语言文字运用(15分)1、在下面一段话空格处依次填入词语,最恰当...的一组是(3分)(▲)这环绕北京的城墙,从艺术的观点看来,是一件▲壮丽的杰作,它质朴无华的结构,单纯▲的体形,反映出为解决某种需要经由劳动血汗、劳动精神与实力而进行的技术上的创造。

它不只是一堆平凡叠积的砖堆,它是大胆的建筑▲物。

用粗暴的态度对待我们的历史遗产,是典型的▲。

A.雄伟强壮祭奠忘恩负义 B.雄浑强壮纪念忘恩负义C.雄浑壮硕祭奠数典忘祖 D.雄伟壮硕纪念数典忘祖2、下列语句中,没有..使用借代手法的一项是(3分)(▲)A.主人下马客在船,举酒欲饮无管弦。

B.桃花细逐杨花落,黄鸟时兼白鸟飞。

C.男儿何不带吴钩,收取关山五十州。

D.远芳侵古道,晴翠接荒城。

3、下列诗歌所写的季节都是..秋天的一组是(3分)(▲)①归来得问茱萸女,今日登高醉几人。

②梅子金黄杏子肥,麦花雪白菜花稀。

③醉别江楼橘柚香,江风引雨入舟凉。

④东风一夜折梅枝,舞蝶游蜂都不知。

A. ①②B. ①④C. ②③D. ①③4、在下面一段文字横线处填入词语,衔接最恰当...的一组是(3分)(▲)精神的丰富包括两个方面,一个是智力生活,另一个就是情感生活。

▲,▲,▲。

作为一个人,▲,▲,▲。

①你不但要运用你的思考能力去做事②还要运用你的感受能力去体验世界的美和人生的意义③不只是爱情、亲情、友情这些具体的情感形态④而是对于世界和人生的情感体验⑤这里说的情感是广义的⑥那样才是作为一个完整的人在生活A.①②⑥⑤③④ B.⑤①②③④⑥C.⑤③④①②⑥ D.③④⑤①②⑥5、下列对南京书展徽标理解不恰当...的一项是(3分)(▲)A.标志下方有“南京书展”四个汉字,下面又有对应的英文翻译,表明此次书展中外书籍齐全。

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常州市“12校合作联盟”
2017学年度第二学期期末质量调研
高二数学文科试题(市区)
注意事项:
1.本试卷共4页,包括填空题(第1题~第14题)、解答题(第15题~第20题)两部分。

本试卷满分160分,考试时间120分钟。

2.答题前,请务必将自己的姓名、考试号用0.5毫米黑色签字笔填写在答题卡指定位置。

3.答题时,必须用0.5毫米黑色签字笔填写在试卷卡的指定位置,在其它位置作答一律无
效。

4.如有作图需要,可用2B 铅笔作答,并加黑加粗,描写清楚。

5. 请保持答题卡卡面清洁,不要折叠、破损。

一律不准使用胶带纸、修正液及可擦洗的圆珠笔。

一、填空题:本大题共14小题,每小题5分,共70分.请把答案填写在答题纸相应位置上.
1.已知集合{1,1}A =-,{3,0,1}B =-,则集合A
B = ▲ .
2.已知复数z 满足i 34i z ⋅=-(i 为虚数单位),则z = ▲ .
3.“1x >”是“2
x x >”的 ▲ (填“充分不必要”“必要不充分”“充要”或“既不充分也不必要”) 条件.
4.函数x x y -++=)1ln(的定义域为 ▲ .
5.已知函数(),0ln ,0
x e x f x x x ⎧≤=⎨>⎩,则1()2f f ⎛⎫= ⎪⎝⎭ ▲ .
6.若1sin 4θ=,且,2πθπ⎛⎫
∈ ⎪⎝⎭
,则sin 2θ= .
7.若曲线()3
3f x x ax =+在点()1,3a +处的切线与直线6y x =平行,则a = ▲ .
8.若将函数()cos(2)4
f x x π
=+的图象向右平移
2
π
个单位后得到函数()y g x =的图象,
则()2
g π
= ▲ .
9.函数x x x f sin 2
1
)(+=
在区间]2,0[π上的极大值为 ▲ .
10.已知0a >,函数2()()f x x x a =-和2()(1)g x x a x a =-+-+存在相同的极值点, 则a = ▲ .
11.已知3
3
2
123+=,3
3
3
2
1236++=,3
3
3
3
2
123410+++=,…, 若3
3
3
3
312343025n ++++
+=,则n = ▲ .
12.已知函数()()2
4ln ,
031,0
x x f x x x ⎧->⎪=⎨++⎪⎩≤,若函数()y f x b =+(其中R b ∈)恰有 3个零点,则b 的取值集合是 ▲ .
13.已知4
5
cos sin =+βα,则cos2cos2αβ+的取值范围是 ▲ .
14.已知函数()y f x =是实数集R 上的奇函数,且()f x 在区间),0(+∞上单调递减,
0)2(=-f .设m x m x x g 3cos sin )(2-+=,集合()|0,,02M m x g x π⎧⎫⎡⎤
=∀∈<⎨⎬⎢⎥
⎣⎦


, 集合⎭
⎬⎫

⎨⎧
>∈∀=0))((],2,
0[|x g f x m N π
,则M N = ▲ .
二、解答题:本大题共6小题,共计90分.解答时应写出文字说明、证明过程或演算步骤 15.(本小题满分14分)
在平面直角坐标系xOy 中,钝角α的顶点与原点重合,始边与x 轴的非负半轴重合,它的终边与单位圆相交于点A ,且点A 的横坐标为35
-. (1)求()sin απ+的值;
(2)若角β满足()tan 2αβ+=,求tan β的值.
16.(本小题满分14分)
某同学用“五点法”画函数()()sin f x A x ωϕ=+ 0,2πωϕ⎛⎫
>< ⎪⎝

在某一个周期内的 图象时,列表并填入了部分正确数据,如下表:
(1)试根据上表数据,求出函数)(x f 的解析式; (2)设函数)()(2x f x g =,求()g x 在区间,64ππ⎡⎤
⎢⎥⎣⎦
上的最大值和最小值.
17.(本小题满分14分)
已知函数()log ()a f x x b =+(0a >且1a ≠)的图象经过点(0,2)A ,(2,1)B -. (1)试求实数,a b 的值;
(2)若方程21920x
x a m b ⎛⎫
++= ⎪⎝⎭
在区间[]1,1-上有解,求实数m 的取值范围.
18.(本小题满分16分)
常州轨道交通1号线一期工程全线长约35km (以35km 计算,全程匀速运行),预计2019年12月正式投入运营.已知运行中列车每小时所需的能源费用(万元)和列车速度(km/h)的立方成正比,当速度为10km/h 时,能源费用是每小时0.04万元,其余费用(与速度无关)是每小时5.12万元,已知最大速度不超过C (km/h)(C 为常数,800≤<C ).
(1)求列车运行全程所需的总费用y 与列车速度v 的函数关系,并求该函数的定义域; (2)当列车速度为多少时,运行全程所需的总费用最低?
19.(本小题满分16分)
设函数2
()5f x ax x
=-+,其中R a ∈. (1)当3a =时,判断()f x 在区间(),1-∞-上的单调性并证明你的结论;
(2)设()()g x f x =. ①求函数()g x 的零点;
②若对任意的正实数a ,总存在[]01,2x ∈,使得0()g x m ≥,求实数m 的取值范围.
20.(本小题满分16分)
已知函数()x f x a =,()log a g x x =,其中1a >. (1)当a e =时(其中e 为自然对数的底), ①求函数()()h x f x x =-的单调区间;
②若曲线()y f x =在点11(,())x f x 处的切线与曲线()y g x =在点22(,())x g x 处的切线平行,求122x e x +的最小值;
(2)证明:当1e
e a ≥时,存在直线l ,使l 是曲线()y
f x =的切线,也是曲线()y
g x =的切线.。

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