2011学年第二学期上海奉贤区调研测试二模2012.05

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2011年上海市奉贤区初中化学二模卷试题及参考答案【纯word版,完美打印】

2011年上海市奉贤区初中化学二模卷试题及参考答案【纯word版,完美打印】

奉贤区2010学年第二学期初三化学调研考试卷(完卷时间40分钟 满分60分)相对原子质量:H-1 C-12 O-16 Ca-40 K-39 Cl-35.5一、选择题(共20分)27、.近来自然灾害频频发生,以下自然灾害属于化学变化的是A .台风B .雪灾C .森林火灾D .山体滑坡28、日常生活中常见的物质属于纯净物的是 ( )A 、食用醋B 、冰水混合物C 、冰红茶D 、加碘盐29、马铃薯富含淀粉,检测马铃薯中含有淀粉所用的试剂是 ( )A 、石蕊试液B 、碳酸试液C 、硝酸银溶液D 、碘水30.掌握化学用语是学好化学的基础。

以下化学符号既能表示某种元素,又能表示该元素的一个原子,还能表示一种物质的是 ( )A .ZnB .O 2C .HD . SO 231、实验基本操作必须规范才能确保安全,下列图示的实验基本操作正确的是 ( )A 点燃酒精灯B 加热液体C 倾倒液体D 气体验满32、化学在工农业发展中发挥着巨大作用,以下物质的用途主要和其化学性质有关的是 ( )A 、干冰用于人工降雨B 、用盐酸除铁锈C 、氢气用于填充气球D 、用钨作灯泡中的灯丝33、市场上有一种新型饭盒“即热饭盒”,加热饭盒时发生的化学反应如下:↑+→+222)(2H OH Mg O H Mg 。

该反应中氧化剂是 ( )A 、MgB 、H 2OC 、Mg(OH)2D 、H 234、有A 、B 、C 三种+2价金属,它们之间有如下关系:B NO A NO B A +→+2323)()(;不反应→+42SO H A ;↑+→+2442H CSO SO H C 。

则它们的金属活动性由强到弱排列是 ( )A 、A>B>CB 、B>A>C C 、C>A>BD 、A>C>B35、我们已经认识了较多的化学式,下列化学式与所表述的意义不符合的是…( )A 、NO 3 —硝酸根B 、N 2 —两个氮原子C 、CuSO 4·5H 2O —胆矾D 、Mg —镁元素36、在实验课上,为鉴别两无色溶液稀盐酸与稀硫酸,需要选用的试剂是( )A 、石蕊试液B 、酚酞试液C 、硝酸银溶液D 、硝酸钡溶液37、实验小组的同学将100克溶质质量分数为5%的溶液,她们将其溶质的质量分数提高到20%,应采取的措施是 ( )A 、蒸发55克水B 、蒸发75克水C 、加入5克固体食盐D 、加入15克固体食盐38、农作物生长需要氮、磷、钾等营养元素。

2012奉贤区二模试卷及答案

2012奉贤区二模试卷及答案

上海市奉贤区2011-2012学年第二学期中考语文质量抽查试卷(完卷时间100分钟满分150分)一、文言文(42分)(一)默写(18分)1.欲把西湖比西子,。

(《饮湖上初晴后雨》)2.,烟波江上使人愁。

(《黄鹤楼》)3.出师一表真名世,。

(《书愤》)4.土地平旷,。

(《桃花源记》)5.,濯清涟而不妖。

(《爱莲说》)6.叫嚣乎东西,。

(《捕蛇者说》)(二)阅读下面的诗,完成第7—8题(4分)青玉案〃元夕宋辛弃疾东风夜放花千树。

更吹落,星如雨。

宝马雕车香满路。

凤箫声动,玉壶光转,一夜鱼龙舞。

蛾儿雪柳黄金缕,笑语盈盈暗香去。

众里寻他千百度,蓦然回首,那人却在,灯火阑珊处。

7.“玉壶”在词中比喻的是。

(2分)8.下列理解正确的一项是(2分)A.词的上片描写了元旦之夜的盛况。

B.“更吹落,星如雨”写了满天的星星被风吹落,像雨一般纷纷洒下。

C.“蛾儿雪柳黄金缕,笑语盈盈暗香去”表达了词人对满城观灯仕女的爱慕之情。

D.词人以“那人却在,灯火阑珊处”抒发了自甘淡漠、不与世俗同流合污的高洁品质。

(三)阅读下文,完成第9—11题(8分)陋室铭山不在高,有仙则名。

水不在深,有龙则灵。

斯是陋室,惟吾德馨。

苔痕上阶绿,草色入帘青。

谈笑有鸿儒,往来无白丁。

可以调素琴,阅金经。

无丝竹之乱耳,无案牍之劳形。

南阳诸葛庐,西蜀子云亭。

孔子云:何陋之有?9.本文作者是朝的文学家、哲学家(人名)。

(2分)10.用现代汉语翻译下面句子。

(3分)无丝竹之乱耳,无案牍之劳形。

11.下列理解错误的一项是 (3分)A.文章首句用了比喻的修辞手法,用“仙”、“龙”比喻陋室的“室主”。

B.“谈笑有鸿儒,往来无白丁”写了交往宾客的身份,以此表明作者孤傲的心情。

C.从文中看,陋室不陋的原因是“惟吾德馨”。

D.作者把陋室与“诸葛庐”、“子云亭”相比,表达了安贫乐道、洁身自好的思想感情。

(四)阅读下文,完成第12—15题(12分)巨商蓄鹦鹉一巨商姓段者,蓄一鹦鹉甚慧,能诵《陇客》诗及李白《宫词》《心经》。

上海市奉贤区2012年中考数学模拟试题参考答案

上海市奉贤区2012年中考数学模拟试题参考答案

FN 第一个观点第一个观点①②③④⑤①②③④⑤①②③④⑤①②③④⑤⑤④③②①2011学年第二学期奉贤区调研测试九年级数学试卷参考答案一、选择题:(本大题共6题,每题4分,满分24分)1.A ;2.D ;3.B ;4.D ;5. B ;6.C .二、填空题:(本大题共12题,每题4分,满分48分)7.x ≠1; 8.1.37×109 ; 9.x =1; 10.()()2121+---x x ;11. 4; 12.m >3; 13. 0.3; 14.6180120+=x x ; 15.)(21b a -; 16.内切; 17.4 ; 18.750或150.三、解答题:(本大题共7题,满分78分)19.解:原式=333334+-++-…………………………………………………(8分) =133-………………………………………………………………………(2分)20. 解:由①得 x <1. …………………………………………………………………(3分) 由②得 1-≥x .…………………………………………………………………(3分) ∴ 原不等式组的解集为11<≤-x . …………………………………………(2分) 画图略………………………………………………………………………………(2分)21.解:(1)过点B 作BF ⊥AD 于F 。

…………………………………………………(1分)在Rt ABF △中,∵35==AF BF i ,且10BF m =。

∴6AF m =………………(2分)∴AB = …………………………………………………………(2分)(2)如图,延长至点M ,AD 至点N ,连接MN ,过点E 作EG ⊥AD 于G 。

在Rt △AEG 中,∵65==AG EG i ,且10BF m =, ∴AG =12m ,BE=GF=AG - AF =6 m 。

……………………………………………(2分)∴ABE CMND S S =△梯形 ………………(1()1122BE EG MC ND ∙∙=+。

2011年上海奉贤区高三英语二模【含答案!】

2011年上海奉贤区高三英语二模【含答案!】

奉贤区调研测试(2011,04 )Section BDirections: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.People from East Asia tend to have more difficulty than those from Europe in 41 facial expressions--and a new report published online in Current Biology explains why.Rachael Jack, University of Glasgow researcher, said that rather than scanning evenly (均匀地) across a face as Westerners do, Easterners42 their attention on the eyes.“We show that Easterners and Westerners look at different face features to read facial expressions,” Jack said. “Westerners look at the eyes and the mouth in equal measure, whereas Easterners favor the eyes and 43 the mouth.”According to Jack and her colleagues, the discovery shows that human 44 of emotion is more complex than previously believed. As a result, facial expressions that had been considered universally recognizable cannot be used to 45 convey emotion in a cross-cultural situation.The researchers studied cultural differences in the 46 of facial expressions by recording the eye movements of 13Western people and 13 East Asian people while they observed pictures of 47 faces and put them into categories: happy, sad, surprised, fearful, disgusted, angry, or neutral (中立的). They compared how accurately participants read those facial expressions using their particular eye movement strategies.It turned out that Easterners focused much greater attention on the eyes and made 48 more errors than did Westerners. “The cultural difference in eye movements that they show is probably a reflection of cultural difference in facial expressions,” Jack said. “Our data suggest that whereas Westerners use the whole face to convey emotion, Easterners use the eyes more and mouth less.”In short, the data show that facial expressions are not universal signals of human emotion. From here on, 49 how cultural factors have differed in these basic social skills will help our understanding of human emotion. Otherwise, when it comes to communicating emotions across cultures, Easterners and Westerners will find themselves lost in translation.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Not long ago, people thought babies were not able to learn things until they were five or six months old. 50 doctors in the United States say babies begin learning on their first day of life.Scientists 51 that babies are strongly influenced by their 52 . They say a baby will smile if her mother does something the baby likes. A baby learns to get the best care possible by smiling to please her mother or other 53 . This is how babies learn to connect and communicate with other human beings.One study shows that babies can learn before they are born. The researchers placed a tape recorder on the stomach of a 54 woman. Then, they played a recording of a short story. On the day the baby was born, the researchers 55 to find if he knew the sounds of the story repeated while in his mother. They did this by placing a device in the mouth of the newborn baby. The baby would hear the story if he moved his mouth one way. If the baby moved his mouth the other way, he would hear a different story. The researchers say the baby 56 liked the story he heard before he was born. They say the baby would move his mouth so he could hear the story again and again.Another study shows how mothers can strongly 57 social development and language skills in their children. Researchers studied the children from the age of one month to three years. The researchers attempted to measure the sensitivity of the mothers. The women were considered 58 if they supported their children’s activities and did not interfere unnecessarily. They tested the children for thinking and 59 development when they were three years old. Also, the researchers observed the women for signs of 60 .The children of depressed women did not do as well in tests as the children of women who did not suffer from depression. The children of depressed women did 61 in tests of language skills and understanding what they hear.These children also were less 62 and had more problems 63 other people. The researchers noted that the sensitivity of the mothers was important to the intelligence development of their children. Children did better when their mothers were caring, 64 they suffered from depression.50. A. Therefore B. Otherwise C. Consequently D. Yet51. A. witness B. assume C. suppose D. note52. A. intelligence B. environment C. nutrient D. emotion53. A. professionals B. standers-by C. caregivers D. relatives54. A. respectable B. refreshing C. pregnant D. responsible55. A. offered B. happened C. claimed D. attempted56. A. unbelievably B. coincidently C. obviously D. incredibly57. A. influence B. undertake C. prove D. resolve58. A. thoughtful B. sensible C. encouraging D. sensitive59. A. reasoning B. logic C. sight D. language60. A. depression B. faith C. enthusiasm D. creativity61. A. marvelously B. reasonably C. favorably D. awfully62. A. aggressive B. cooperative C. open-minded D. imaginative63. A. taking on B. calling on C. going in for D. dealing with64. A. despite B. in case C. for fear D. even whenSection BDirections: Read the following passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B,C or D. Choose the one that suits best according to the information given in the passage you have just read.(A)Being the head of a high school for many years, I grew tired of budget meetings, funding cuts, and many other administrative chores (杂务). I started to dream of retirement. Sitting in traffic on a weekday morning, I would find my mind wandering. I would imagine spending time with my grandchildren, quiet evenings with my wife, traveling, or rediscovering some great books. I told myself th at I wouldn’t sign myself up for any committees, any classes, or anything requiring a schedule.My first day of retirement came at last! I cooked a great breakfast for my wife and me, leisurely read the paper, cleaned a bit of the house, and wrote a few letters to friends. On the second day, I cooked breakfast, read the paper. On the third day, … This is retirement? I tried to tell myself that it was just the transition, that those golden moments were right round the corner, and that I would enjoy them soon enough. But something was missing.A former colleague asked a favor. A group of students was going to Jamaica to work with children in the poorest neighborhoods. Would I interrupt my newfound “happiness” and return to the students, just this once? One tri p. That’s all. My bags were packed and by the door.The trip was very inspiring. I was moved not only by the poverty I saw but also by the sense of responsibility of the young people on the trip. When I returned home, I offered to work one day a week with a local youth organization. The experience was so positive that I was soon volunteering nearly full-time, working with students across North America to assist them in their voluntary work.Now, it seems, the tables have turned. Some days I am the teacher, other days I am the student. These young people have reawakened my commitment to social justice issues by challenging me to learn more about the situation in the world today, where people are still poor and suffer because of greed, corruption(腐败) and war. Most important, they have givenme the opportunity to continue to participate in helping to find solutions. In return, I help them do their charitable projects overseas. I’ve gone from running one school to helping oversee the construction of schools in twenty-one countries!65. What did the writer expect to do after he retired?A. To write some great books.B. To stay away from busy schedules.C. To teach his grandchildren.D. To do some voluntary work.66. Why did the writer decide to go to Jamaica?A. He missed his students in that country.B. He couldn’t refuse his colleague’s favor.C. He cared a lot about the people there.D. He was not satisfied with his retired life.67. The underlined part “the tables have turned” means that the wri ter ________.A. improved the situation in his schoolB. felt happy to work with students againC. became a learner rather than a teacherD. changed his attitude toward his retired life68. What does the writer think of his retired life now?A. Disappointing.B. Troublesome.C. Relaxing.D. Meaningful.(B)There are few areas better than Lack Myvatn for viewing the Northern Lights and discovering the wonders of the Icelandic winter.Day 1Reykjavik—Akureyri—Lake MyvatnFlight to Akureyri from where you will be picked up. Transfer to Lake Myvatn. Sightseeing tour of the Lake Myvatn area. After the tour, an introduction of the activities available.Day 2Free day at Lake Myvatn: optional tours available. Please note that all tours are dependent on weather and road-conditions, and therefore only booked locally at Lake Myvatn.Day 3Akureyri—ReykjavikThe morning will be spent at Lake Myvatn and then in the afternoon a transfer to Akureyri where you will go on a short sightseeing tour of Akureyri, enjoying the beautiful sights. Afternoon flight back to Reykjavik.Activities available at Lake MyvatnSnowmobileTake an exciting adventure on our snowmobiles out on the frozen Lake Myvatn or travel deep into the Highlands with one of our guides. 30 min and 1 hour tour available.Super-jeepSightseeing at Myvatn and a super-jeep adventure. 3 tours available: around the area of Lake Myvatn; a tour to Dettifoss, the most powerful waterfall in Europe and unforgettable at winter time; a tour further into the Myvatn area.Sightseeing toursSightseeing tours to some spectacular places: Icelandic farms, power station, museums and a search for the northern lights. These tours are recommended for all nature lovers.Cross-country skiingThe Lake Myvatn area and surrounding Highlands are great for cross-country skiing. There is a good mixture of areas from easy to more demanding and the length of each tour also depends on one’s ability.Horse ridingA wonderful area that offers a great variation of trekking(跋涉)routes. On offer (削价出售) are tours from one hour to a day tour with different destinations, something to match your desire.Go-carts on iceExperience the adventure of driving on the ice of the lake. The snow is taken away and you drive with“nailed”tire s. Also available is go-carts in the snow.Winter gardenDifferent kinds of amusements on the frozen lake: bowling, cricket, skating, mini golf etc.69. What is the purpose of the advertisement?A. To inform the timetable of a trip.B. To list the steps to see the Northern Lights.C. To introduce a special traveling package.D. To introduce the wonders of the Icelandic winter.70. Where will you spend most of the time during the trip?A. Reykjavik.B. Akureyri.C. Lake Myvatn.D. Icelandic farms.71. If you enjoy outdoor activities in winter and want to view the Northern Lights, you willjoin in ________.A. Horse ridingB. Cross-country skiingC. Go-carts on iceD. Sightseeing tours(C)A 40,000-YEAR-OLD child’s little finger bone found in a Siberia n cave probably belonged to someone from a previously unknown human species living near modern humans of the era, a study reported recently.For the study published in the journal Nature, scientists analyzed DNA from the bone discovered in the Denisova cave in southern Siberia. They found that its DNA was unrelated to either modern humans or their extinct Neanderthal (穴居人) cousins. The bone dates to a time when all three species apparently lived within 100km of each other in the Altai Mountain area.“I was amazed,” says study author Svante Paabo of Germany’s Max Planck Institute for Evolutionary Biology. “There were at least three different forms of humans in this region at one time.”The bone was discovered in a dirt layer about 40,000 years old. Its DNA shows the creature’s ancestors separated from modern humans and Neanderthals around 1 million years ago. Researchers named the bone owner “x-woman” despite its undetermined gender. From the size of the bone tip, the team estimates its owner was a 5 or 6-year-old child.“This is really cool. It is highly likely they have found a human species distinct from modern humans or Neanderthals,” says gene expert Edward Rubin of Lawrence Berkeley National Laboratory, who was not part of the study. Although the dating of the bone is based only on the cave floor dirt layer in which it was found, Rubin says, it probably couldn’t be much older than 50,000 years to have any DNA.Within months, Paabo says, the team hopes to have samples of the DNA of the species to compare with that of modern humans and Neanderthals, who became extinct about 30,000 years ago in Europe. That should offer some hints of the biology of the study species. Although genetically distant from modern humans, the new species appears much more closely related to modern humans than apes, says study lead author Johannes Krause. He said it was undoubtedly an upright-walking human species that needed clothing to survive Siberian winters.“Forty thousand years ago, the planet was more crowded than we thought,” gene scientist Terence Brown of the United Kingdom’s University of Manchester concludes in a commentary published together with the report.72. What is the article mainly about?A. A report over a previously unknown ape species.B. The discovery of a new human species.C. A new theory of human evolution.D. A study of children’s finger bones.73. Which of the following statements about the discovered bone is FALSE?A. It was discovered in the Denisova cave in southern Siberia.B. It dates back 40,000 years.C. Its owner was neither a modern human nor a Neanderthal.D. It belonged to a 5- or 6-year-old girl.74. The scientists are studying the bone to find ______.A. the biology of the new speciesB. whether it is related to modern humansC. how the species survived Siberian wintersD. the exact time the child lived75. What kind of attitude does gene expert Edward Rubin have towards the finding?A. Dissatisfied.B. Indifferent.C. Delighted.D. Uncertain.Section DDirections: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words.High-quality customer service is preached (宣扬) by many, but actually keeping customers happy is easier said than done.Shoppers seldom complain to the manager or owner of a retail store, but instead will warn their friends, relatives, co-workers, strangers and anyone who will listen.Store managers are often the last to hear complaints, and often find out only when their regular customers decide to go often to their competitors, according to a study jointly conducted by Verde Group and Wharton School.“Storytelling hurts retailers(零售商)and entertains consumers,” said Paula Courtney, President of the Verde Group. “The store loses the customer, but the shopper must also find a replacement.”On average, every unhappy customer will complain to at least four others, and will no longer visit the specific store. For every dissatisfied customer, a store will lose up to three more due to negative reviews. The resulting “snowball effect” can be very harmful to retailers.According to the research, shoppers who purchased clothing encountered the most problems. Ranked second and third were grocery and electronics customers.During peak shopping hours, some retailers solved the parking problems by gettingpart-time local police to work as parking attendants. Some hired flag wavers to direct customers to empty parking spaces.Retailers can relieve the headaches by redesigning store layouts(布局), pre-stocking sales items, hiring speedy and experienced cashiers, and having sales representatives on hand to answer questions.Most importantly, salespeople should be flexible and polite with angry customers.“Retailers who’re responsive and friendly are more likely to smooth over issues than those who aren’t so friendly.” said professor Stephen Hoch. “Maybe something as simple as a greeter at the store entra nce would help.”Customers can also improve future shopping experiences by complaining to the retailer, instead of complaining to the rest of the world. Retailers are finding it difficult to improve when they have no idea what is wrong.81. Why are store managers often the last to hear complaints?82. Shop owners often hire part-time police as parking attendants so that ________________.83. What contributes most to smoothing over issues with customers?84. To achieve better shopping experiences,customers are advised to ________________.(Note: Answer the questions or complete the statements in NO MORE THAN TEN WORDS.)Ⅰ.Translation(20分)Directions: Translate the following sentences into English. You are required to use the word given in the bracket for each respective sentence.1.这部电影的故事情节是根据真人改编的。

上海奉贤区2011年中考二模数学试题及答案[1]1

上海奉贤区2011年中考二模数学试题及答案[1]1

第6题图题图第3题图题图 A B F C D E O 奉贤区调研测试九年级数学试卷 2011. 04 (完卷时间100分钟,满分150分)考生注意:1.本试卷含三个大题,共25题.2.答题时,考生务必按答题要求在答题纸...规定的位置上作答,在草稿纸、本试卷上答题一律无效.3.除第一、二大题外,其余各题如无特别说明,都必须在答题纸...的相应位置上写出证明或计算的主要步骤.一、选择题:(本大题共6题,每题4分,满分24分)1.计算32a a ×的结果是(的结果是( ▲ )A .5a ; B .6a ;C .8a ;D .9a .2.下列运算不正确的是(.下列运算不正确的是( ▲ )A .22(2)2-=; B .236´=; C .623¸=; D .235+=. 3.如图,直线CD 是线段AB 的垂直平分线,P 为直线CD 上的一点,已知线段P A =5, 那么线段PB 的长度为(的长度为( ▲ ) A .3 ; B .4 ; C .5 ; D .6.4.小悦买书需用48元钱,付款时恰好用了1元和5元的纸币共12张.设所用的1元纸币为x 张,根据题意,下面所列方程正确的是(张,根据题意,下面所列方程正确的是( ▲ ) A .48)12(5=-+x x ; B .48)12(5=-+x x ; C .48)5(12=-+x x ; D .48)12(5=-+x x . 5.某种彩票的中奖机会是1%,下列说法正确的是(,下列说法正确的是( ▲ ) A .买1张这种彩票一定不会中奖;张这种彩票一定不会中奖; B .买100张这种彩票一定会中奖;张这种彩票一定会中奖;C .买1张这种彩票可能会中奖;D .买100张这种彩票一定有99张彩票不会中奖. 6.如图,正方形ABCD 中,E 为AB 中的中点点,AF ⊥DE 于点O 那,那么么DOAO(等于( ▲ ) A .352 ; B .31; C .32; D .21.二、填空题:(本大题共12题,每题4分,满分48分)第12题图题图第18题图题图yx-O 第11题图题图7.截止到2010年10月31日,上海世博园共接待游客73 080 000人,人, 用科学记数法表示是用科学记数法表示是 ▲▲ 人.人.人. 8.函数13y x =-中,自变量x 的取值范围是的取值范围是▲▲ .. 9. 9. 方程方程212x -=的根是的根是 ▲▲ ..10.在直角坐标系中,点)2-2(,A 与点)12(,-B 之间的距离=AB ▲▲ ..11.已知反比例函数xm y 2-=的图象如图所示,的图象如图所示,那么那么m 的取值范围是的取值范围是 ▲▲ ..12.如图,l 1表示某摩托厂一天的销售收入与摩托车销售量之间的关系;l 2表示表示 该摩托厂一天的销售成本与销售量之间的关系。

上海市奉贤区2012届高三第二次模拟调研考试(地理)

上海市奉贤区2012届高三第二次模拟调研考试(地理)

奉贤区2011学年第二学期高三地理调研测试(2012.4)(本卷满分150分,完卷时间120分钟)一、选择题(每小题2分,共50分。

每小题只有—个正确答案)(一)美国国家科学院预言:在2012年的某一天,美国南部的一些城市,在五彩斑斓的极光光幕过后,电网会突然变得闪烁不定,灯光在瞬时明亮后将会停电,一分半钟之后,这个大停电现象将会遍及美国整个东部地区,甚至整个欧洲以及中国、日本等区域也会同样经历这样的灾难,而这场灾难仅仅源于太阳打了一个强烈的“喷嚏”。

1.材料中所述的太阳打了强烈的“喷嚏”极有可能是A.太阳耀斑爆发B.太阳爆炸C.太阳辐射增强D.太阳辐射减弱2.该“喷嚏”还可能产生的明显影响不包括A.短波通讯中断B.信鸽丢失 C.指南针失灵D.地球公转速度的变化(二)2011年11月28日联合国气候变化公约第l7次缔约方会议在南非德班(29º52'S,31º02'E)开幕,右图为德班气候大会会徽。

中国代表团经过约l3时l0分的飞行。

于当地时间1l月28日7时到达南非德班。

3.中国代表团从北京出发时。

北京时间约为A.26日20时50分 B.27日23时50分C.27日13时l0分 D.28日7 时50分4.德班气候大会会徽是一棵枯萎的猴面包树扎报在扭曲的地球上,该树种粗大树干能贮存大量水分抵御干旱,它广泛分布在非洲的A.东非高原东 B.撒哈拉沙漠 C.地中海沿岸D.刚果盆地(三)岩石是组成地壳的天然矿物集合体。

5.构成大洋底部的主要岩石属于A.喷出岩B.侵入岩C.沉积岩D.变质岩6.下列事物中属于岩石的是A.长石B.方解石C.浮石D.石英7.华山为花岗岩山体,花岗岩从形成到出露地表所经历的地质过程依次是A.固结成岩—风化剥蚀—侵蚀搬运—地壳抬升B.地壳抬升—侵蚀搬运—岩浆侵入—风化剥蚀C.岩浆侵入—地壳抬升—风化剥蚀—侵蚀搬运D.侵蚀搬运—岩浆侵入—地壳抬升—固结成岩(四)地理信息技术越来越深刻的影响着人们的生活和生产。

2012年奉贤区中考化学第二次模拟复习考试题及答案

2012年奉贤区中考化学第二次模拟复习考试题及答案

2012年奉贤区中考化学第二次模拟复习考试题及答案2011学年奉贤区化学调研考试卷完卷时间40分钟满分60分(2012、4)相对原子质量:H-1;k-39;Mg-24;Na-23;Zn-65;O-16;C-12;Fe-56;一、选择题(共20分,每题只有一个答案)27、化学科学的发展促进了人类社会的进步,下列各项不属于化学学科研究范畴的是()A、物质的运动状态B、物质的组成和结构C、物质的性质和用途D、物质的制取和应用28、有关物质的性质中属于物理性质的是()A.浓盐酸的挥发性B.浓H2SO4的脱水性C.硝酸的氧化性D.碳酸的不稳定性29、海南椰树集团生产的“椰树牌矿泉水”荣获“中国国宴饮料”称号。

这种矿泉水是一种()A.纯净物B.化合物C.氧化物D.混合物30、下列烹饪用的调味品与足量水充分搅拌,不能形成溶液的是()A.食盐B.橄榄油C.白糖D.黄酒31、X.Y.Z三元素的化合价为+1.+4.-2,组成的化合物的化学式可能是------()A.XYZ4B.X4YZ3C.X2YZ3D.X3YZ232、秋冬干燥,医生建议在室内放盆热水增加空气的湿度。

此方法说明---------()A.分子很小B.分子之间有间隔C.分子是可分的D.分子在不断运动33、属于同素异形体的是()A.氧气和液氧B.金刚石和C60C.水和过氧化氢D.冰和干冰34、农村有句谚语:“雷雨发庄稼”,这是由于在放电条件下,空气中的氮气和氧气化合生成了氮氧化物,氮氧化物再经过复杂的化学变化,最后生成了容易被农作物吸收的硝酸盐。

雷雨给庄稼施加了()A、钾肥B、磷肥C、氮肥D、复合肥35、某物质在空气中完全燃烧后,生成的气体能使澄清石灰水变浑浊,则该物质一定()A.含碳元素的化合物B.含碳、氢元素的物质C.含碳元素的单质或含碳元素的化合物D.无法判断36、滴有酚酞的氢氧化钙溶液与下列各物质恰好完全反应后溶液仍旧呈现红色的是()A、稀硫酸B、氯化铜溶液C、稀盐酸D、碳酸钠溶液37、储存烟花爆竹的仓库应贴上的标志是()ABCD38.单晶硅是制作电子集成电路的基础材料。

数学_2011年上海市奉贤区高考数学二模试卷(理科)_(含答案)

数学_2011年上海市奉贤区高考数学二模试卷(理科)_(含答案)

2011年上海市奉贤区高考数学二模试卷(理科)一、填空题(填空每个4分,共56分)1. 函数y =lg(2011x −1)的定义域是________.2. 若sinx =13,x ∈[−π2,π2],则x =________(结果用反三角函数表示) 3. 已知线性方程组的增广矩阵为[103210],则其对应的方程组为________.4. 在正方体ABCD −A 1B 1C 1D 1中,异面直线DB 与B 1C 所成角的为________.5. 若复数3+i 是实系数一元二次方程x 2−6x +b =0的一个根,则b =________.6. 已知|a →|=|b →|=2,a →与b →的夹角为π3,则b →在a →上的投影为________. 7. 在二项式(x 2−1x )5的展开式中,含x 4的项的系数是________.8. 在等比数列{a n }中,a n >0,且a 1⋅a 2•…•a 7⋅a 8=16,则a 4+a 5的最小值为________. 9. 已知双曲线k 2x 2−y 2=1(k >0)的一条渐近线的法向量是(1, 2),那么k =________.10. 设函数y =f(x)=a x (a >0, a ≠1),y =f −1(x)表示y =f(x)的反函数,定义如框图表示的运算,若输入x =−2,输出y =14,当输出y =−3时,则输入x =________.11. (理)如下表,已知离散型随机变量ξ的分布列,则Dξ为________.轴正半轴为极轴建立极坐标系,则M 的极坐标为________(角用反三角表示)13. 在平面直角坐标系中,设点P(X, Y)定义[OP]=|x|+|y|,其中O 为坐标原点,对于以下结论:①符合[OP]=1的点P 的轨迹围成的图形的面积为2;②设P 为直线√5x +2y −2=0上任意一点,则[OP]的最小值为1;③设P 为直线y =kx +b(k, b ∈R)上的任意一点,则“使[OP]最小的点P 有无数个”的必要不充分条件是“k =±1”;其中正确的结论有________(填上你认为正确的所有结论的序号) 14. (理)在空间直角坐标系O −xyz 中,满足条件[x]2+[y]2+[z]2≤1的点(x, y, z)构成的空间区域Ω2的体积为V 2([x],[y],[z]分别表示不大于x ,y ,z 的最大整数),则V 2=________.二、选择题(每个4分,共16分)15. 在△ABC 中,“ccosB =bcosC”是“△ABC 是等腰三角形”的( )A 充分不必要条件B 必要不充分条件C 充分必要条件D 既不充分也不必要条件16. 已知数列{a n }的通项公式为a n ={2n1+2nn ≤100C 2n (2n−1)(n+1)n >100(n ∈N +),则limn →+∞a n =( )A 1B 14 C 1或14 D 不存在17. (理)已知函数f(x)=2x +1,x ∈R .规定:给定一个实数x 0,赋值x 1=f(x 0),若x 1≤255,则继续赋值x 2=f(x 1) …,以此类推,若x n−1≤255,则x n =f(x n−1),否则停止赋值,如果得到x n 后停止,则称赋值了n 次(n ∈N ∗).已知赋值k 次后该过程停止,则x 0的取值范围是( )A (2k−9, 2k−8]B (2k−8−1, 2k−9−1]C (28−k −1, 29−k −1]D (27−k −1, 28−k −1] 18. 行列式|(12)x7x 13456321|中,第3行第2列的元素的代数余子式记作f(x),1+f(x)的零点属于区间( )A (23, 1) B (12, 23) C (13, 12) D (0, 13)三、解答题(12+14+16+18+18=78分)19. 用2π平方米的材料制成一个有盖的圆锥形容器,如果在制作过程中材料无损耗,且材料的厚度忽略不计,底面半径长为x ,圆锥母线的长为y (1)建立y 与x 的函数关系式,并写出x 的取值范围;(2)圆锥的母线与底面所成的角大小为π3,求所制作的圆锥形容器容积多少立方米(精确到0.01m 3)20. (理)设函数f(x)=ax +4x (x >0),a ∈R +.(1)当a =2时,用函数单调性定义求f(x)的单调递减区间(2)若连续掷两次骰子(骰子六个面上分别标以数字1,2,3,4,5,6)得到的点数分别作为a 和b ,求f(x)>b 2恒成立的概率.21. (理)已知F 1(−√2,0)和F 2(√2,0),点T(x, y)满足|TF 1→|+|TF 2→|=4,O 为直角坐标原点,(1)求点T的轨迹方程Γ;(2)任意一条不过原点的直线L与轨迹方程Γ相交于点P,Q两点,三条直线OP,OQ,PQ的斜率分别是k OP、k OQ、k PQ,k PQ2=k OP⋅k OQ,求k PQ.22. (理)已知函数f(x)=|sinx cosx−sinαcosα|,g(x)=|cosx sinxsinβcosβ|,α,β是参数,x∈R,α∈(−π2,π2),β∈(−π2,π2)(1)若α=π4,β=π4,判别ℎ(x)=f(x)+g(x)的奇偶性;若α=−π4,β=π4,判别ℎ(x)=f2(x)+g2(x)的奇偶性;(2)若α=π3,t(x)=f(x)g(x)是偶函数,求β;(3)请你仿照问题(1)(2)提一个问题(3),使得所提问题或是(1)的推广或是问题(2)的推广,问题(1)或(2)是问题(3)的特例.(不必证明命题)将根据写出真命题所体现的思维层次和对问题探究的完整性,给予不同的评分.23. 已知数列{a n}满足a1=2,前n项和为S n,a n+1={pa n+n−1(n为奇数)−a n−2n(n为偶数).(1)若数列{b n}满足b n=a2n+a2n+1(n≥1),试求数列{b n}前n项和T n;(2)若数列{c n}满足c n=a2n,试判断c n是否为等比数列,并说明理由;(3)当p=12时,问是否存在n∈N∗,使得(S2n+1−10)c2n=1,若存在,求出所有的n的值;若不存在,请说明理由.2011年上海市奉贤区高考数学二模试卷(理科)答案1. (0, +∞)2. arcsin133. {x=32x+y=0 4. π35. 106. 17. 108. 2√29. 1210. 1811. 212. (√5,π−tan12)13. ①14. 715. A16. B17. C18. B19. 所制作的圆锥形容器容积0.99立方米20. 解:(1)f(x)=2x+4x根据耐克函数的性质,f(x)=2x+4x的单调递减区间是(0,√2],证明如下:设任意0<x1<x2≤√2,则f(x1)−f(x2)=2x1+4x1−2x2−4x2=2(x1−x2)+4(x2−x1)x1x2=2(x1−x2)(1−2x1x2)∵ 0<x1<x2≤√2∴ x1−x2<0,0<x1x2<2,1−2x1x2<0∴ f(x1)−f(x2)>0所以f(x)=2x+4x的单调递减区间是(0,√2](2)∵ f(x)min≥4√a∴ 16a>b4基本事件总数为6×6=36,当a=1时,b=1;当a=2,3,4,5时,b=1,2,共2×4=8种情况;当a=6时,b=1,2,3;目标事件个数为1+8+3=12.因此所求概率为13.21. 解:(1)由题意,点T的轨迹是以F1,F2为焦点的椭圆,且a=2,c=√2从而所求轨迹方程为x 24+y22=1(2)设直线L的方程:y=kx+t(t≠0){y=kx+tx24+y22=1消去y得:(1+2k2)x2+4ktx+2t2−4=0,x1x2=2t2−41+2k2消去x得:(1+2k2)y2−2yt+t2−4k2=0,y1y2=t2−4k21+2k2∴ k OP⋅k OQ=y1x1⋅y2x2=y1y2x1x2=t2−4k22t2−4=k2,∴ k2=12∴ k=±√2222. (理)解:(1)f(x)=sinx−cosα+cosx−cosα,g(x)=cosx⋅cosα−sinx⋅sinαf(x)=sin(x +α),g(x)=cos(x +β)ℎ(x)=sin(x +π4)+cos(x +π4)=√2sin(x +π2)=√2cosx所以ℎ(x)是偶函数ℎ(x)=sin 2(x −π4)+cos 2(x +π4)=1−cos(2x −π2)2+1+cos(2x +π2)2=1−sin2x +1−sin2x 2=1−sin2x所以ℎ(x)是非奇非偶函数 (2)方法一(积化和差):t(x)=f(x)⋅g(x)为偶函数, t(x)=sin(x +π3)⋅cos(x +β)=12[sin(2x +β+π3)+sin(π3−β)]t(x)=f(x)⋅g(x)为偶函数,所以sin(2x +β+π3)是偶函数, β+π3=kπ+π2,β∈(−π2,π2), ∴ β=π6方法二(定义法):t(x)=f(x)⋅g(x)为偶函数所以t(x)=t(−x),sin(x +π3)cos(x +β)=sin(−x +π3)cos(−x +β)展开整理sinx ⋅cosx ⋅(cosβ−√3sinβ)=0对一切x ∈R 恒成立 tanβ=√33,β∈(−π2,π2),∴ β=π6方法三(特殊值法):t(x)=f(x)⋅g(x)为偶函数所以t(x)=t(−x),sin(x +π3)cos(x +β)=sin(−x +π3)cos(−x +β)∴ t(π3)=t(−π3),所以sin(π3+π3)cos(π3+β)=sin(−π3+π3)cos(−π3+β)=0 cos(π3+β)=0,β∈(−π2,π2), ∴ β=π6(3)第一层次,写出任何一种的一个(加法或乘法)均可以,1、α+β=π2,f(x)+g(x)是偶函数; 2、α+β=−π2,f(x)+g(x)是奇函数; 3、α−β=π2,f(x)+g(x)是非奇非偶函数; 4、α−β=−π2,f(x)+g(x)既奇又偶函数第二层次,写出任何一种的一个(加法或乘法)均可以,1、α+β=π2,f 3(x)+g 3(x)是偶函数;(数字不分奇偶)2、α+β=−π2,f 5(x)+g 5(x)是奇函数α+β=−π2,f 4(x)+g 4(x)是偶函数(数字只能同奇数)3、α−β=π2,f 5(x)+g 5(x)是非奇非偶函数(数字不分奇偶,但求相同)4、α−β=−π2,f 3(x)+g 3(x)是既奇又偶函数 (数字只能奇数) α−β=−π2,f 2(x)+g 2(x)是非奇非偶函数第三层次,写出逆命题任何一种的一个(加法或乘法)均可以, 1、f 3(x)+g 3(x)是偶函数(数字不分奇偶,但相同),则α+β=π2 2、f 5(x)+g 5(x)是奇函数(数字只能正奇数),则α+β=−π2f 2(x)+g 2(x)是偶函数(数字只能正偶数),则α+β=−π23、f 3(x)+g 3(x)是偶函数 (数字只能正奇数),则α−β=−π2第四层次,写出充要条件中的任何一种均可以, 1、α+β=π2的充要条件是f(x)+g(x)是偶函数2、f 5(x)+g 5(x)是奇函数(数字只能正奇数)的充要条件是α+β=−π2 f 2(x)+g 2(x)是偶函数(数字只能正偶数)的充要条件是α+β=−π2 3、f 3(x)+g 3(x)是偶函数 (数字只能正奇数)的充要条件是α−β=−π2 第五层,写出任何一种均可以(逆命题,充要条件等均可以,限于篇幅省略) 1、α+β=π2,n ∈N ∗时,f n (x)+g n (x)都是偶函数2、α+β=−π2,n ∈N ∗时,n 是正奇数,f n (x)+g n (x)是奇函数 α+β=−π2,n ∈N ∗时,n 是正偶数,f n (x)+g n (x)是偶函数3、α−β=−π2,n ∈N ∗时,n 奇数,f n (x)+g n (x)是既奇又偶函数4、α−β=−π2,n ∈N ∗时,n 偶数,f n (x)+g n (x)是非奇非偶函数23. 解:(1)据题意得b n =a 2n +a 2n+1=a 2n −a 2n −2×2n =−4n ,所以{b n }成等差数列,故T n =−2n 2−2n(2)当p =12时,数列{c n }成等比数列;当p ≠12时,数列{c n }不为等比数列理由如下:因为c n+1=a 2n+2=pa 2n+1+2n =p(−a 2n −4n)+2n =−pc n −4pn +2n , 所以c n+1c n =−p +2n(1−2p)c n,故当p =12时,数列c n 是首项为1,公比为−12等比数列;当p ≠12时,数列{c n }不成等比数列 (3)当p =12时,a 2n =c n =(−12)n−1,a 2n+1=b n −a 2n =−4n −(−12)n−1 因为S 2n+1=a 1+b 1+b 2+...+b n =−2n 2−2n +2(n ≥1) ∵ (S 2n+1−10)c 2n =1,∴ 4n 2+4n +16=4n ,设f(x)=4x −4x 2−4x −16(x ≥2), 则g(x)=f ′(x)=4x ln4−8x −4,∴ g ′(x)=(ln4)24x −8>0(x ≥2),且g(2)=f ′(2)>0, ∴ f(x)在[2, +∞)递增,且f(3)=0,f(1)≠0, ∴ 仅存在惟一的n =3使得(S 2n+1−10)c 2n =1成立。

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2011学年第二学期奉贤区调研测试九年级数学试卷 2012. 05(完卷时间100分钟,满分150分)本卷命题人员:张建忠 杨建宇 庄建红考生注意:1.本试卷含三个大题,共25题.答题时,考生务必按答题要求在答题纸规定的位置上作答,在草稿纸、本试卷上答题一律无效.2.除第一、二大题外,其余各题如无特别说明,都必须在答题纸的相应位置上写出证明或计算的主要步骤.一、选择题:(本大题共6题,每题4分,满分24分) 1.下列二次根式中属于最简二次根式的是( ▲ )A .a1;B . 3b ; C; D . 3ab .2.下列不等式组中,解集在数轴上表示出来如图所示的不等式组为( ▲A . ⎩⎨⎧-≥<;1,2x x B . ⎩⎨⎧-><;1,2x x C . ⎩⎨⎧-≤>;1,2x x D . ⎩⎨⎧-≤<.1,2x x3.在投掷一枚硬币的游戏过程中,已知“正面朝上”的概率为50%,那么下列说法正确的是( ▲ )A .投掷100次必有50次“正面朝上”;B .投掷100次可能有50次“正面朝上”;C .投掷很多次的时候,极少出现“正面朝上”;D .投掷很多次的时候,极有可能出现“正面朝上”.4.正比例函数x k y )1(+=的图象经过第二、四象限,那么k 为( ▲ )A .0>k ;B .0<k ;C .1->k ;D .1-<k . 5.下列说法错误的是( ▲ )A . 正多边形每个内角都相等;B .正多边形都是轴对称图形;C . 正多边形都是中心对称图形;D .正多边形的中心到各边的距离相等. 6.在△ABC 中,AD 是BC 边上的高,且12A DBC =,E 、F 分别是AB 、AC 的中点,以EF为直径的圆与BC 位置关系是( ▲ ) A . 相离 B . 相切; C . 相交; D . 相切或相交. 二、填空题:(本大题共12题,每题4分,满分48分) 7.计算:=÷26a a ▲ _.8.在实数范围内分解因式:=-32x ▲ _. 9.已知函数xx xx f -=2)(, 如果0)(=a f , 那么a = ▲ _.10.如果关于x 的方程042=+-k x x (k 为常数)有两个不相等的实数根,那么k ▲ _.(第2题图)A BCDFE11.方程x =- 的根是 ▲ .12.将抛物线231y x =-+向左平移2个单位,再向下平移3个单位,得到的新抛物线的表达式是 ▲ _.13.在⊙O 中,弦AB = 16cm ,弦心距OC = 6cm ,那么该圆的半径为 ▲ cm . 14.化简()()AB C D BE D E -+-的结果是 ▲ .15.将二元二次方程4222=+-y xy x 化为二个二元一次方程为 ▲ _.16.如图,一座拦河大坝的横截面是梯形ABCD ,AD ∥BC , ∠B =90°,AD =5米,坡面CD 的坡度i =1:34,且BC =CD ,那么拦河大坝的高是 ▲ _ 米.17.某厂四月份产值是3百万元,设第二季度每个月产值的增长率相同,都为x (x>0),六月份的产值为y 百万元,那么y 关于x 的关系式是: ▲ _.18.如图,已知菱形ABCD 中,∠B =60°,点E 在边BC 上,∠BAE =20°,把线段AE 绕点A 逆时针方向旋转,使点E 落在边CD 上,那么旋转角α的度数为 ▲ _.三、解答题:(本大题共7题,满分78分) 19.(本题满分10分)计算:1230cos 2)32(311-︒+++--20.(本题满分10分) 解方程:2522=+++xx x x21.(本题满分10分,其中第(1)小题5分,第(2)小题5分)平行四边形ABCD 中,AB =5,AD =8,∠C 、∠D 的平分线分别交 AD 、BC 与点E 、F ,且AF ⊥BC .(1)求tan ∠ADF ; (2)求CE 的长.(第21题图)ADCE BAD C(第16题图)(第18题图)22.(本题满分10分,其中第(1)小题4分,第(2)小题2分,第(3)小题4分) 伦敦奥运会将于2012年7月27日开幕,组委会备选的开幕式甲、乙两支仪仗队队员的身高(单位:厘米)如下:甲队:178,177,179,178,177,178,177,179,178,179; 乙队:178,179,176,178,180,178,176,178,177,180;(1)将下表填完整:(2)甲队队员身高的平均数为 厘米,乙队队员身高的平均数为 厘米; (3)你认为哪支仪仗队更为整齐?简要说明理由.23.(本题满分12分,其中第(1)小题5分,第(2)小题7分) 如图,已知直线l 经过点A (1,0),与双曲线y =mx(x >0)交于点B (2,1).过点P (a ,a -1)(a >1)作x 轴的平 行线分别交双曲线y =m x (x >0)和y =-mx(x <0)于点M 、N .(1)求m 的值和直线l 的解析式;(2)若点P 在直线y =2上,求证:△PMB ∽△PNA .24.(本题满分12分,其中第(1)小题2分,第(2)小题5分,第(2)小题5分)如图,△ABC 中,AG ⊥BC 于点G ,以A 为直角顶点,分别以AB 、AC 为直角边,向△ABC 外侧作Rt △ABE 和Rt △ACF ,过点E 、F 作射线GA 的垂线,垂足分别为P 、Q , (1)若Rt △ABE 和Rt △ACF 都是等腰三角形,直接写出EP 与FQ 有怎样的数量关系;(2)若Rt △ABE 和Rt △ACF 中满足AB =k AE ,AC =k AF 时,(1)中的结论还成立吗?若成立,请证明;若不成立, 请探究EP 与FQ 有怎样的数量关系?(3)若Rt △ABE 和Rt △ACF 中满足AB =k AE ,AC =mAF 时,联结EF 交射线GA 于点D ,试探究ED 与FD 有怎样的数量关系?AB CEFG PQ(第24题图2)PFEGCBAQ (第24题图1)(第23题图)25.(本题满分14分,其中第(1)小题4分,第(2)小题6分,第(3)小题4分)已知:⊙O 的半径OA =5,弦AB =8,C 是弦AB 的中点,点P 是射线AO 上一点(与点A 不重合),直线PC 与射线BO 交于点D . (1)当点P 在⊙O 上,求OD 的长. (2)若点P 在AO 的延长线上,设OP =x ,y DBOD ,求y 与x 的函数关系式并写出自变量x 的取值范围。

(3)连接CO ,若△PCO 与△PCA 相似,求此时BD 的长。

(第25题图)A (备用图)(备用图)A2011学年第二学期奉贤区九年级数学调研测试答案 2012. 05一、选择题 (本大题共6题,每题4分,满分24分)1.C ; 2.A ; 3.B ; 4.D ; 5.C ; 6.B . 二、填空题(本大题共12题,每题4分,满分48分)7.4a ; 8.(x x +-; 9. 1 ; 10.K <4;11.1x =-; 12.()2322y x =-+-; 13. 10 ; 14.AC ;15.2x y -=和2x y -=-; 16. 15 ; 17.23(1)y x =+ ; 18.60°或 80°. 三、解答题19.解:原式12=-+-……………………………………(8分)1=- ………………………………………………………(2分)20.解:去分母,得 )2(5)2(2222+=++x x x x .……………………………………(3分)整理,得 0822=-+x x .……………………………………………………(3分) 解得 41-=x ,22=x .………………………………………………………(2分) 经检验:41-=x ,22=x 都是原方程的根.…………………………………(1分) ∴原方程的根是41-=x ,22=x . …………………………………………(1分)另解:设2+=x x y ,则原方程可化为251=+yy .…………………………………(2分)整理,得 02522=+-y y .…………………………………………………(2分) 解得 21=y ,212=y .………………………………………………………(2分)当y =2时,即22=+x x .解得 4-=x .……………………………………(1分) 当21=y 时,即212=+x x .解得 x =2.………………………………………(1分)经检验:4-=x ,2=x 都是原方程的根.…………………………………(1分)∴原方程的根是4-=x ,2=x . ………………………………………(1分)21.(1)∵四边形ABCD 是平行四边形,∴AB =CD =5,AD =BC=8, ∴A B ∥CD ,A D ∥BC∴∠ADF=∠DFC …………………………………………………………………(1分) ∵∠C 、∠D 的平分线分别交 AD 、BC 与点E 、F , ∴∠ADF=∠FDC ∴∠DFC=∠FDC∴FC=DC =5 ………………………………………(1分) 同理可证:DE=DC=5∴BF=AE=3 …………………………………………(1分) ∵AF ⊥BC .A D ∥BC ∴∠AFB=∠DAF=90°Rt △ABF 中, 222AF BF AB += ,AF=4 ……………………………………(1分) Rt △AFD 中, tan ∠ADF =4182A F A D== ……………………………………(1分)(2)联结EF ,Rt △AFD 中,AF =4,AD =8222AF AD FD += 54=DF ………………………………………(1分)∵FC=DE=5, 又∵AD ∥BC∴四边形EFCD 是平行四边形 ………………………………………(1分) 又 ∵ FC=DC ∴平行四边形EFCD 是菱形 ………………………………………(1分) ∵CF AF FD CE S EFCD ⋅=⋅=21菱形, 即12×=5×4∴CE=2 …………………………………………(2分)(算出菱形面积20得1分,或证明CE ⊥FD ,利用相似求出12CE 得1分,再求 CE得1分 ) 22……………(4分)(2)178,178; …………………………………………………(2分) (3)甲仪仗队更为整齐. …………………………………………………(1分)∵5310110101101012=+++++++++=)(甲S 5941040404101012=+++++++++=)(乙S ∵ 2甲S <2乙S ,∴可以认为甲仪仗队更为整齐.…………………………(3分)23.解:(1)由点B (2,1)在y =mx 上,有2=1m ,即m =2。

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