期末复习测试题10
初三语文期末测试题附答案

初三语文期末测试题附答案初三语文期末测试题附答案时间越来越紧迫了,初三语文期末考试的复习具有知识点多,时间紧迫,收效低微,缺乏新鲜感的特点。
以下是店铺为你整理的初三语文期末测试题,希望对大家有帮助!初三语文期末测试题一、基础•运用(共21分)1.阅读下面文段,完成第(1)一(5)题。
(共9分)闲章,是印章的一脉,是区别于姓名印、斋室印、职官印、藏书印一类的印章。
书画家或自拟词句,或① (采取/撷取)格言警句刻在闲章上,以示对艺术和人生的感悟。
好的闲章,【甲】内容广泛,【乙】意趣盎然,除了让人玩味,【丙】可体现书画家的学识与修养。
闲章有的【丁】。
如徐悲鸿画白梅用“一尘不染”印,李苦禅画鹰用“搏击万里”印,李可染画牛用“师牛堂”印。
有的【戊】。
如齐白石出身木匠,半生② (漂泊/漂移)不定,晚年定居北京,以卖画为生,他常在书画中钤盖“木居士”“鲁班门下”印,以示其独特的经历;张大千出身贫寒,他用“乞食人间尚未归”和“苦瓜滋味”两方闲章,表明自己的出身和处境。
有的还【己】。
如郑板桥有名的闲章“难得糊涂”,幽默隽永中带有几分苦涩,书写人生况味可谓入木三分;邓石如的闲章“胸有方心,身无媚骨”,直抒胸臆,表现了他刚正不阿的品格。
闲章虽小,却融书法、绘画、雕刻于一体,是一种独特的造型艺术,犹如万绿丛中一点红,绽放出绚丽的光彩。
言情亦言志,造景亦绘心,故而闲章不“闲”了。
(1)对文中加点字读音的判断,全都正确的一项是(2分)A.藏书( cang) 处境(chu) 隽永(jun) 刚正不阿(a)B.藏书(zang) 处境(chu) 隽永(jun) 刚正不阿(e)C.藏书( cang) 处境(chu) 隽永(juan) 刚正不阿(e)D.藏书(zang) 处境(chu) 隽永(juan) 刚正不阿(a)(2)从文中括号内选择恰当的词语填写在横线①②处,①处应填____,②处应填。
(2分)(3)在文中【甲】【乙】【丙】处依次填人关联词语,最恰当的一项是(2分)A.即使也并且B.虽然但是也C.尽管还又D.不但而且还(4)根据语境,在文中【丁】【戊】【己】处依次填写句子正确的一项是(2分)①表现书画家的生平、境遇②反映作者的主观认识、情趣志向③紧密配合作品内容,深化作品主题A.②①③B.③①②C.②③①D.③②①(5)仔细观察下面的闲章,请选择其中一枚,将其内容用规范的正楷字书写在答题纸上的田字格内。
人教版八年级英语上册第10单元期末复习测试题(含答案)

人教版八年级英语上册第10单元期末复习测试题(含答案)一、语篇填空。
(每小题2分,共20分)A king was old and he knew it was 1._______ to choose a new king. He told all the young people in his country, “I will give each of you a seed(种子). Plant it and bring it back one year later. Show me the plant that you bring. And I’ll choose a new king from you.” A boy named Peter got a seed, too. He 2._________ it carefully. But the seed didn’t 3._______ at all. A year later, Peter had to take his empty box to the palace. Others all brought beautiful plants there and Peter felt 4.__________.The king reached the palace and looked 5._________. When the king found there was 6._________in Peter’s box, he smiled and said to the others, “One year 7.________, I 8._______ everyone a seed that couldn’t grow. But all of you, except Peter, have brought me plants and flowers. Peter was the only one to bring such an empty box. He is 9.______ honest and full of courage that I decide to choose him as our new king!” The other young people didn’t know10._______to say.二、完形填空(每小题2分,共20分)There was once a boy who was so interested in watching TV that he never finished his breakfast or 11. ______else on time.One day, in his postbox, there was a pair of 12. ______,along with a piece of paper saying, “Time is flowers. With these you’ll be able to see time.”The boy felt surprised. He13. ______ the glasses on,looked at his brother and saw many beautiful flowers on top of his head. The14. ______ were falling down to the ground,one by one. And it wasn’t just his brother. Whenever h e 15. ______ anyone through the glasses, really the same was happening. But if the persons were older, there 16. ______fewer flowers on their heads.The next morning, while having his breakfast, the boy17. ______ his glasses. Putting them on, he was18. ______ to see that the flowers were moving to the television. The television now had a big mouth. It was 19. ______ all the flowers. And everywhere he went, he would see televisions eating flowers.Finally, after knowing20. ______ televisions really were, the boy decided he would never again allow them to eat up all his time.( )11.A. anything B. something C. Nothing( )12.A. trousers B. socks C. glasses( )13.A. wore B. put C. took( )14.A. heads B. televisions C. flowers( )15.A. saw B. heard C. said( )16.A. had B. were C. came( )17.A. remembered B. cleaned C. forgot( )18.A. excited B. happy C. surprised( )19.A. looking at B. playing with C. eating up( )20.A. what B. how C. when三、阅读理解(每小题2分,共28分)AEveryone has worries. But what do you do with your worries? Whether(无论)your worries are big or small, you can take these steps to deal with them.Try to find out what you’re worried about.Maybe you know what you are worried about. But if you don’t know, try t o find it out first. If you can’t, you can ask for help.Think of ways to make it better.You can always find something to help you feel less worried. It’s not helpful for you to solve your problems if you only sit there worrying.For students at school, grades are often a top worry. If you are worried about grades, askyourself these questions:·Why are grades important. What do grades mean to me?·How do I get ready for class? Do I go over my notes even when there isn’t a test?·Do I have a good place to do my homework?·Have I tried different ways of studying?If your worry is to lose a friend after a fight, you might write down all the things you could do—write a note to him or her, invite him or her to a basketball game, say sorry to him or her, etc. Once you have a list of things you could do, you can choose the one that gets your friend back. Ask for help.When you’re worried, it can help to find someone to talk to. You can ask your parents, friends, or teachers for help.( )21.When you don’t know what you are worried about, ______ .A. you should try to find it out firstB. you can’t ask for helpC. you only need to ask your teachers( )22.If you’re worried about grades, you can ask yourself these questions EXCEPT(除了)“______ ”. A. Why are grades importantB. What do grades mean to meC. Why are my parents worried about me( )23.Jack had a fight with his friend yesterday, so now he may ______ to get his friend back.A. make friends with other peopleB. not talk to him or her anymoreC. invite him or her to a basketball game( )24.The passage mainly tells us ______ .A. who is often worriedB. when people are worriedC. what to do with our worriesBIf you want to plan a great party, you should be careful of three parts—before the party, at the party and after the party.25.____First, you should do a survey about your guests before you send the invitations. If some guests are too busy to come to your party, you don’t need to send invitations to them. 26.____ Then, the most important thing is to make your guests enjoy your party. For example, you may prepare some simple but fun games. 27.____ Dancing and singing are two popular activities for young people. But as for old people, it’s necessary to prepare a quiet place for them t o have a rest.28.____ If you do that, they’ll feel good and then next time they’ll be happier to accept your invitation.29._____ You have to think about many things. But if you follow my advice, I’m sureCIf you’re having a hard time getting along with your teacher, going to class will make you feel sad. There are some ways to help you get along well with your teacher.Talk to your teacher.When you can’t follow your teacher, you need to talk to your teacher. Ask your teacher if there is a right time you can talk with him or her in private(私下地). Ask a friend or family member to practice the discussion with you beforehand(事先地).Ask your teacher how you can do well in the class.Teachers have years of education in the subjects they teach, so they are experienced in teaching and learning the s ubject. They’re ready to help anyone who has trouble in their class. But remember to ask your teacher how to do well in the class in a polite and serious way.Learn to understand your teacher’s teachingway.Remember that teachers are all different, and you may just need a little time to understand your teacher’s teaching style. In most cases, respecting your teacher and trying to do well in class is enough to improve your relationship. Remember, not every relationship starts off great, butA: Ken, you look upset. What happened?B: Yes. 35.____ She always asks me to do this or to do that.A: Really?36.____B: A lot of things, such as getting up on time and finishing my homework.A:37._____ She says these things to you because she cares about you. You should try to understand her.B: 38._____ She loves me.A: If you let her know that everything is fine, she will not be worried about you.B:39._____ Thank you so much.for 40.___________ to make some mistakes unless they are very careful. If you make mistakes, don’t be upset or angry. Here’s some 41.________that experts give us.First, don’t keep them to 42.___________. We can talk to a person who we trust. Parents and teachers are understanding43.________have more experience. We can ask them for help. Sharing a problem is like 44._________ it in half.45._________, an important step is to find a way to solve the problem. For example, Ben has to get out of the taxi after 46.__________several miles, but he leaves his wallet in the taxi halfway. He can call the taxi agent first. If he knows the 47._________phone number, he can call the driver certainly. There is also something48.______ he can do by himself.Third, don’t be 49._________next time. Experts advise that teenag ers should organize a meeting so that they can help each other.40.______ 41.______ 42.______ 43.______ 44.______45.______ 46.______ 47.______ 48.______ 49._____参考答案1.necessary2.planted3.grow4.sad5.around6.nothing7.ago8.gave9.so10.what11-15:ACBCA 16-20:BACCA21-24ACCC25-29:CFBEA30.happy31.discussion32.experience33.seriously34.Mostly35-39:CEGAD40.teenagers 41.advice 43.and 44.cutting45.Second 46.traveling 47.driver’s48.else 49.careless。
九年级数学上册期末复习综合测试题(含答案)

(第4题)九年级数学上册期末复习综合测试题(含答案)一、选择题(本大题共6小题,每小题2分,共12分.) 1.一元二次方程 x 2=x 的根是( )A .x 1=0,x 2=1B .x 1=0,x 2=-1C .x 1=x 2=0D .x 1=x 2=12.一个不透明布袋中有2个红球,3个白球,这些球除颜色外无其他差别,摇匀后从中随机摸出一个小球,该小球是红色的概率为( )A .12B .23C .15D .253.若一组数据 2,3,4,5,x 的方差比另一组数据 5,6,7,8,9 的方差大,则 x 的值可能是( ) A .1B .4C .6D .84.如图,OA 、OB 是⊙O 的半径,C 是⊙O 上一点.若∠OAC =16°,∠OBC =54°,则 ∠AOB 的度数是( )A .70°B .72°C .74°D .76°5.若关于x 的一元二次方程ax 2+k =0的一个根为2,则二次函数y =a (x +1)2+k 与x 轴的交点坐标为( ) A .(-3,0)、(1,0) B .(-2,0)、(2,0) C .(-1,0)、(1,0)D .(-1,0)、(3,0)6.如图,在Rt △ABC ,∠ACB =90°,AC =4,BC =3,点D ,E 分别在AB ,AC 上,连接DE ,将△ADE 沿DE 翻折,使点A 的对应点F 落在BC 的延长线上,若FD 平分∠EFB ,则AD 的长为( ) A . 157B .207C .258D .259二、填空题(本大题共10小题,每小题2分,共20分.) 7(第12题)l 1 l 2l 3A BCEFD (第11题)8.若a b =43,则a -b b= .9.设x 1、x 2是方程x 2+mx -m +3=0的两个根,则x 1+x 2-x 1x 2= .10.把抛物线y =-x 2向左平移2个单位,然后向上平移3个单位,则平移后该抛物线相应的函数表达式为 .11.如图,l 1∥l 2∥l 3,若AD =1,BE =3,CF =6,则ABBC的值为 .12.如图,点A 、B 、C 在⊙O 上,⊙O 的半径为3,∠AOC =的长为 . 13.已知关于x 的函数y =x 2+2mx +1,若x >1时,y 随x 的增大而增大,则m 的取值范围是 .14.如图,弦AB 是⊙O 的内接正六边形的一边,弦AC 是⊙O 的内接正方形的一边,若 BC =2+23,则⊙O 的半径为 .15.如图,正方形ABCD 的边长是4,点E 在DC 上,点F 在AC 上,∠BFE =90°,若 CE =116.如图,在矩形ABCD 中,AB =2,AD =4,点E 、F 分别为AD 、CD 边上的点,且EF 的长为2,点G 为EF 的中点,点P 为BC 上一动点,则P A +PG 的最小值为 . 三、解答题(本大题共11小题,共88分.请在答题卡指定区域.......内作答,解答时应写出文字说明、证明过程或演算步骤)17.(8分)解方程:(1)x 2-4x -5=0; (2)x 2-4=2x (x -2).18.(8分)甲乙两人在相同条件下完成了5次射击训练,两人的成绩(单位:环)如下(1)甲射击成绩的中位数为 环,乙射击成绩的众数为 环;(2)计算两人射击成绩的方差;(3)根据训练成绩,你认为选派哪一名队员参赛更好,为什么?19.(8分)某校开展秋季运动会,需运动员代表进行发言,从甲、乙、丙、丁四名运动员中随机抽取.(1)若随机抽取1名,甲被抽中的概率为 ; (2)若随机抽取2名,求甲在其中的概率.20.(7分)如图,在△ABC 中,点D 、E 分别在AB 、AC 上,且∠BCE +∠BDE =180°. (1)求证:△ADE ∽△ACB ;(2)连接BE 、CD ,求证:△AEB ∽△ADC .21.(8分)如图是二次函数y =-x 2+bx +c 的图像. (1)求该二次函数的关系式及顶点坐标; (2)当y >0时 x 的取值范围是 ;(3)当m <x <m +4时,-5<y ≤4,则m 的值为 .22.(7分)在Rt △ABC ,∠BAC =90°,AB =AC ,D 、E、F 分别为BC 、AB 、AC 边上的点,且∠EDF =45°.(1)求证:△EBD ∽△DCF ;(2)当D 是BC 的中点时,连接EF ,若CF =5,DF =4,则EF 的长为 .23.(8分)某超市销售一种商品,成本为每千克50元.当每千克售价60元时,每天的销售量为60千克,经市场调查,当每千克售价增加1元,每天的销售量减少2千克. (1)为保证某天获得750元的销售利润,则该天的销售单价应定为多少? (2)当销售单价定为多少时,才能使当天的销售利润最大?最大利润是多少?24.(8分)如图,AB 为⊙O 的直径,弦CD ⊥AB 于点P ,连接BC ,过点D 作DE ⊥CD ,交⊙O 于点E ,连接AE ,F 是DE 延长线上一点,且∠BCD =∠F AE . (1)求证:AF 是⊙O 的切线;(2)若AF =2,EF =1,求⊙O 的半径.25.(8分)已知二次函数y =(x -2)(x -m )(m 为常数). (1)求证:不论m 为何值,该函数的图像与x 轴总有公共点;(2)若M (-1,0), N (3,0),该函数图像与线段MN 只有1个公共点,直接写出 m 的取值范围;(3)若点A (-1,a ),B (1,b ),C (3,c )在该函数的图像上,当abc <0时,结合函数图像,直接写出m 的取值范围.26.(8分)如图,四边形ABCD 内接于⊙O ,AB =AC ,BD ⊥AC ,垂足为E . (1)求证:∠BAC =2∠DAC ; (2)若AB =10,CD =5,求BC 的长.27.(10分)定义:圆心在三角形的一边上,与另一边相切,且经过三角形一个顶点(非切点)的圆,称为这个三角形圆心所在边上的“伴随圆”.(1) 如图①,在△ABC 中,∠C =90°,AB =5,AC =3,则BC 边上的伴随圆的半径为 . (2)如图②,△ABC 中,AB =AC =5,BC =6,直接写出它的所有伴随圆的半径. (3)如图③,△ABC 中,∠ACB =90°,点E 在边AB 上,AE =2BE ,D 为AC 的中点,且∠CED =90°.①求证:△CED 的外接圆是△ABC 的AC 边上的伴随圆; ②DE的值为 .参考答案说明:本评分标准每题给出了一种或几种解法供参考,如果考生的解法与本解答不同,参照本评分标准的精神给分.一、选择题(本大题共6小题,每小题2分,共12分)二、填空题(本大题共10小题,每小题2分,共20分)7.9 8.13 9.-3 10.y =-(x +2)2+3 11.2312.2π 13.m ≥-1 14. 2 2 15.322 16.4 2 -1三、解答题(本大题共11小题,共88分) 17.(8分)(1)解:x 2-4x -5=0 x 2-4x +4=5+4(x -2)2=9 ········································································································ 1分x -2=±3 ········································································································ 2分 ∴ x 1=5,x 2=-1. ··························································································· 4分 (2)解:x 2-4=2x (x -2) x 2-4=2x 2-4xx 2-4x +4=0 ··································································································· 5分 (x -2)2=0 ········································································································ 6分 ∴ x 1=x 2=2. ··································································································· 8分 18.(8分)(1)7;8 ········································································································ 2分 (2)s 2甲=(7-8)2+(7-8) 2+(10-8)2+(9-8)2+(7-8)25=1.6环2. ······························ 4分s 2乙=(8-8)2+(8-8) 2+ (7-8)2+(8-8)2+(9-8)25=0.4环2. ······································ 6分(3)选择乙.因为甲乙两人平均数相同均为8,说明两人实力相当,但s 2乙<s 2甲,乙的成绩更加稳定,所以选乙. ······················································································· 8分19.(8分)(1)14. ·········································································································· 2分(2)解:随机抽取两名运动员,共有6种等可能性结果:(甲,乙)、(甲,丙)、(甲,丁)、(乙,丙)、(乙,丁)、(丙,丁).其中满足“有甲运动员”(记为事件A )的结果只有3种,所以P (A )=12. ·································································································· 8分20.(7分)(1)证明:∵ ∠BCE +∠BDE =180°, ∠EDA +∠BDE =180°,∴ ∠EDA =∠BCE . ·························································································· 1分 又 ∠A =∠A , ································································································· 2分 ∴ △ADE ∽△ACB . ·························································································· 3分 (2)∵ △ADE ∽△ACB , ∴ AD AC =AE AB, ·········································· 4分 ∴AD AE =ACAB, ······································· 5分 又 ∠A =∠A , ········································ 6分 ∴ △AEB ∽△ADC . ································· 7分21.(8分)(1)将(0,3)、 (3,0)代入,得⎩⎨⎧3=c ,0=-9+3b +c································································································· 1分解得⎩⎨⎧c =3,b =2····································································································· 2分∴ y =-x 2+2x +3 ····························································································· 3分 ∴ 顶点坐标为(1,4) ························································································ 4分 (2)-1<x <3. ······························································································ 6分 (3)-2或0 ···································································································· 8分 22.(7分)(1)解:∵∠BAC =90°,AB =AC ,∴ ∠B =∠C =45°. ··························································································· 1分 ∴ 在△BDE 中,∠BED +∠BDE =180°-∠B =135°, ∵ ∠EDF =45°,∴ ∠BDE +∠CDF =135°,∴ ∠BED =∠CDF . ·························································································· 3分 ∵ ∠B =∠C ,∴ △EBD ∽△DCF . ·························································································· 5分 (2 ········································································································ 7分23.(8分)(1)解:设每千克的销售价增加x 元,根据题意,得(60+x -50) (60-2x )=750 ··················································································· 2分 ∴ x 1=5,x 2=15. ····························································································· 3分 60+5=65或60+15=75 ···················································································· 4分 答:销售单价为65或75元时获得利润750元. (2)解:每千克的销售价增加x 元,利润为w 元.w =(60+x -50) (60-2x ) ···················································································· 6分 =-2(x -10)2+800 ···························································································· 7分 ∵ a =-2<0,∴ 当x =10时,w 有最大值800. ········································································ 8分 60+10=70答:当销售单价为70元时获得最大利润,为800元. 24.(8分) (1)连接BD .∵ AB 为⊙O 的直径,CD ⊥AB ,∴ ⌒BC = ⌒BD , ························································· 1分 ∴ ∠BDC =∠BCD .∵ 四边形ABDE 为⊙O 的内接四边形,∴ ∠BDE +∠BAE =180°,即∠BDC +∠CDF +∠BAE ····· 2分∵ DE ⊥CD , ∴ ∠CDF =90°, ∴ ∠BDC +∠BAE =90°.∵ ∠BCD =∠F AE , ·························································································· 3分 ∴ ∠BAE +∠F AE =90°,即∠F AB =90°, ∴ AF ⊥AB . 又 点A 在⊙O 上,∴ AF 与⊙O 相切. ·························································································· 4分 (2)过点O 作OG ⊥DF 垂足为G . ∵ ∠F AB =∠D =∠APD =90°, ∴ 四边形APDF 是矩形, ∴ ∠F =90°.∵ ∠F AB =∠F =∠OGF =90°, ∴ 四边形AOGF 是矩形,∴ AF =OG ,AO =GF . ···················································· 5分 设OE =OA =r ,则GE =r -1.在Rt △OGE 中,由勾股定理得OG 2+GE 2=OE 2, ···················································· 6分 即4+(r -1)2=r 2, ···························································································· 7分 解得r =5 2 . ····································································································· 8分25.(8分)(1)令y =0,即(x -2)(x -m )=0 ········································································· 1分 ∴ x 1=2,x 2=m . ····························································································· 2分 当m =2时,x 1=x 2,方程有两个相等的实数根; 当m ≠2时,x 1≠x 2,方程有两个不等的实数根. ∴ 不论m 为何值,方程总有实数根;∴ 不论m 为何值,该函数的图像与x 轴总有公共点. ·············································· 3分 (2)m =2或m >3或m <-1. ··········································································· 6分 (3)-1<m <1或m >3. ·················································································· 8分 26.(8分)。
期末复习测试卷2022-2023学年外研版英语七年级下册

期末复习测试卷一、选择题(每空1分,共20分)1. He likes singing very much and wants to be a ______ in the future.A. musicianB. writerC. workerD. doctor2.—Is this Lucy's exercise book?—Yes, it's ______ . She is looking for it everywhere.A. mineB. hisC. hersD. yours3. —Whose card is this?—It is ____. My brother Tom gave it to me on my birthday.A. myB. hersC. oursD. mine4. A robot show will be held in July, but ____ knows the date for sure.A. nobodyB. everybodyC. anybodyD. somebody5. In our hometown, _______ villagers leave for big cities to look for jobs.A. two hundreds ofB. hundred ofC. hundreds ofD. two hundreds6. T—Ken, could you please ______ the chairs? You can't put them here. —Sorry. I'm coming.A. knockB. waveC. touchD. move7. It usually ____ Mum about an hour to cook supper.A. paysB. takesC. spendsD. costs8. So many robots are worki ng in the factory. I simply can’t _______ my eyes.A. seeB. holdC. sellD. believe9. —Where did you go last winter holiday?—I ____ to London with my family.A. goB. am goingC. wentD. was going10. I'm looking forward to ______ the Palace Museum.A. visitedB. visitC. visitingD. visits11. —Tony, ______ read in bed. It's bad for your eyes.—OK, Mom.A. don'tB. doesn'tC. didn'tD. can't12. —The dress is too small for me. May I ______ that red one? —Certainly.A. turn onB. try onC. pick upD. put up13. The exam is coming. You’d better _______ your lessons carefully.A. worry aboutB. put awayC. go overD. pick up14. She saw the cup of coffee and _______.A. picks it upB. picked up itC. picked it upD. picks up it15. There _______ any schools in the future. Students will study at home.A. is going to haveB. will beC. aren’t going to haveD. won’t be16. Mr Green was happy and _______ to see Shakespeare’s plays in Beijing.A. strictB. excitedC. boredD. relaxed17. —Ann and her sister are ______ .—Yeah! Ann is friendly but her sister is a little difficult.A. sameB. quietC. differentD. tidy18. —____ hard-working boy Zhou Bin is!—Yes, I'm sure he'll pass the test.A. What aB. WhatC. How aD. How19. —The final exam is over. Will you stay at home or visit your grandparents? —______ . I miss them very much.A. Yes, I willB. I'll stay at homeC. No, I won'tD. I'll visit my grandparents20. —Tony, I will go to Dashu Mountain with my parents tomorrow.—______ .A. You're welcomeB. That's all rightC. Don't be sillyD. Have a nice day二、完形填空(每空1分,共10分)What did you do last weekend? Let me tell you how I __1____ my weekend.On Saturday I drove to Dallas to see my sister Alice. Alice is a(n) __2____. She gave a concert (音乐会) that day and it was excellent. After that, we walked to a __3____ for dinner with her friends. We had a good time together. After I went back home, I found I __4____ my bag in the restaurant. It was __5____ and I was really tired. __6____ I had to drive back to Dallas. Bad __7____!The Sunday was relaxing. __8____ I got up, it was half past nine. After having a quick breakfast, I __9____ to clean the house. Then I found a __10____ under my bed. I bought it last year and it still looked nice. So in the afternoon I took it to the park and flew it.1. A. made B. visited C. studied D. spent2. A. actress B. farmer C. singer D. teacher3. A. restaurant B. hospital C. bank D. park4. A. stopped B. left C. sold D. blew5. A. dark B. short C. cheap D. easy6. A. If B. Or C. When D. But7. A. girl B. fun C. luck D. time8. A. What B. Who C. Where D. When9. A. forgot B. started C. learned D. flew10. A. watch B. bike C. candle D. kite三、阅读理解(每题2分,共30分)AWei Hua had a busy day yesterday. She got up before 7 o’clock in the morning and quickly washed her hands and face. She got to school early. She had a rest after lunch. She played basketball after school, and then she walked home.Wei Hua’s pen was broken, so she needed a new one. On her way home, she bought a new pen at a shop. When she reached home, she had a short rest and drank a glass of water. After that she helped her parents. She quickly cooked the supper, and cleaned the house.She watched TV for half an hour after supper. Then she started doing her homework. She finished it at half past nine. She went to bed at a quarter to ten.1. Yesterday Wei Hua was _______.A. illB. busyC. sadD. happy2. How did she go home yesterday?A. By bus.B. By bike.C. On foot.D. By car.3. What did she buy on her way home?A. A book.B. Some food.C. Some drinks.D. A pen.4. She finished her homework at _______ in the evening.A. 9:30B. 9:00C. 10:00D. 4:305. She went to bed at _______.A. 10:15B. 9:45C. 10:30D. 9:30BWe spent a day in the country and picked a lot of flowers. Our car was full of flowers inside! On the way home we had to stop at traffic lights , and there my wife saw the bookshelf.It stood outside a furniture (家具)shop. "Buy it," she said at once. "We'll carry it home on the roof-rack (车顶架) . I've always wanted one like that . "What could I do? Ten minutes later I was twenty dollars poorer, and the bookshelf was tied on to the roof-rack. It was tall and narrow, quite heavy too .As it was getting darker, I drove slowly . Other drivers seemed more polite than usual that evening. The police even stopped traffic to let us through . Carrying furniture was a good idea.After a time my wife said, "There's a long line of cars behind . Why don't they overtake (超车) ?"Just at that time a police car did overtake. The two officers (警官)inside looked at us seriously when they went past . But then , with a kind smile they asked us to follow their car through the busy traffic. The police car stopped at our village church (教堂) . One of the offices came to me."Right, sir, " he said. "Do you need any more help now?"I didn't quite understand . "Thanks, officer, " I said . "You've been very kind. I lived just down the road. "He was looking at our things: first at the flowers, then at the bookshelf. "Well, Well, " he said and laughed . "It's a bookshelf you've got there ! We thought it was-er, something else . "My wife began to laugh . Suddenly I understood why the police drove here .I smiled at the officer. "Yes, it's a bookshelf, but thanks again." I drove home as fast as I could .6 . From the story we know that ___________.A . the writer was poor and didn't buy the bookshelf for his wifeB . the writer's wife didn't like the bookshelf at allC . the writer was always glad to buy something for his wifeD . the writer was not very dad to buy the bookshelf for his wife7 . What made the writer think that carrying furniture was "a good idea"?A . He could drive slowly and it was safe.B . Other drivers would let him go first .C . His wife could use a new bookshelf.D . He could save a lot of money and time.8 . Why were the police and other drivers so kind to the writer?A . Because they thought the writer liked studying very much and needed a bookshelf.B . Because they didn't think it was polite to overtake a car with a bookshelf on it .C . Because they thought somebody in the writer's family had died and he needed help .D . Because they thought it was dangerous to carry a bookshelf on a car.9. Why did the writer's wife begin to laugh?A . Because now she knew what mistake the police had made.B . Because at last her husband understood why the police had driven to the church .C . Because the officer was always looking at the flowers and the bookshelf.D . Because the police had helped them a lot .10 . When did the officers begin to realize (意识到)they had made a mistake?A . Before they arrived at the church.B . Before they overtook the writer's carC . After one of them looked at the flowers and the bookshelf carefully at the church.D . After the writer's family left the church.四、词汇运用(每空1分,共10分)A)根据句意及汉语提示写单词,完成句子。
人教版九年级数学期末考试综合复习测试题(含答案)

人教版九年级数学期末考试综合复习测试题(含答案)一.选择题(共10小题,每小题3分,共30分)1.计算,3(2)a -结果正确的是( )A .32a -B .36a -C .38a -D .38a2.据教育部统计,2022年高校毕业生约1076万人,用科学记数法表示1076万为( )A .4107610⨯B .61.07610⨯C .71.07610⨯D .80.107610⨯3.下列汽车标志中,是中心对称图形的是( ) A . B . C . D .4.如图所示,直线//EF GH ,射线AC 分别交直线EF 、GH 于点B 和点C ,AD EF ⊥于点D ,如果20A ∠=︒,则(ACH ∠= )A .160︒B .110︒C .100︒D .70︒5.如图,已知ABC ADE ∆≅∆,若70E ∠=︒,30D ∠=︒,则BAC ∠的度数是( )A .70︒B .80︒C .40︒D .30︒6.方程2210x x --=实数根的情况为( )A .有两个不相等的实数根B .有两个相等的实数根C .没有实数根D .不能确定7.在平面直角坐标系中,若点(1,)A a b -+与点(,3)B a b -关于原点对称,则点(,)C a b 在( )A .第一象限B .第二象限C .第三象限D .第四象限8.如图,小正方形的边长均为1,则下列图中的三角形(阴影部分)与ABC ∆相似的是( )A .B .C .D .9.已知正比例函数11(0)y k x k =≠的图象与反比例函数22(0)k y k x =≠的图象交于A ,B 两点,其中点A 在第二象限,横坐标为2-,另一交点B 的纵坐标为1-,则12(k k ⋅= )A .4B .4-C .1-D .110.已知(3,2)A --,(1,2)B -,抛物线2(0)y ax bx c a =++>顶点在线段AB 上运动,形状保持不变,与x 轴交于C ,D 两点(C 在D 的右侧),下列结论:①2c -;②当0x >时,一定有y 随x 的增大而增大;③若点D 横坐标的最小值为5-,则点C 横坐标的最大值为3;④当四边形ABCD 为平行四边形时,12a =. 其中正确的是( )A .①③B .②③C .①④D .①③④二.填空题(共5小题,每小题3分,共15分)11.因式分解:22416x y -= . 12.若2|2|(3)0x y -++=,则2()x y += .13.已知m ,()n m n ≠是一元二次方程220230x x +-=的两个实数根,则代数式22m m n ++的值为 .14.如图,A ,B ,C ,D 是O 上的四点,且点B 是AC 的中点,BD 交OC 于点E ,60OED ∠=︒,35OCD ∠=︒,那么AOC ∠的度数是 .15.如图,E 为正方形ABCD 内一点,5AD =,4AE =,将ADE ∆绕点A 顺时针旋转90︒到ABE ∆',则边DE 所扫过的区域(图中阴影部分)的面积为 .题14图 题15图三.解答题(一)(共3小题,每小题8分,共24分)16.(1)计算:0111(2021)()2cos45221π--++-︒+; (2)先化简,再求值:23210(1)19x x x x --⋅---,其中x 是1、2、3中的一个合适的数.17.如图,DE AB ⊥于E ,DF AC ⊥于F ,若BD CD =,BE CF =.求证:(1)AD 平分BAC ∠;(2)2AC AB BE =+.18.今年,我市某学校举办了为贫困生捐赠书包活动.该学校用2000元在某商店购进一批学生书包,随后发现书包数量不够,于是又购进第二批同样的书包,所购数量是第一批的3倍,每个书包比第一批购买时贵了4元,结果第二批用了6300元.(1)该学校第一批购进的学生书包每个多少元?(2)如果该商店第一批、第二批学生书包每个的进价分别是68元、70元,售给该学校的这些学生书包,该商店盈利多少元?四.解答题(二)(共3小题,每小题9分,共27分)19.某银行柜台在储户人数较多时常开放1、2、3、4号窗口办理日常业务,一般是先到取号机拿号,按顾客“先到达,先服务“的方式服务(1)求某储户在3号窗口办业务的概率是(2)储户乙取号时发现储户甲已办理完业务准备离开(储户甲、乙先后到达银行取号办理业务),请用树状图或列表法求储户甲、乙两人在同一柜台办理业务的概率.20.如图,在平行四边形ABCD 中,BD AB ⊥,延长AB 至点E ,使BE AB =,连接EC .(1)求证:四边形BECD 是矩形.(2)连接AC ,若3AD =,2CD =,求AC 的长.21.Rt ABO ∆的顶点A 是双曲线k y x =与直线(1)y x k =--+在第二象限的交点,AB 垂直x 轴于点B 且32ABO S ∆=. (1)求这两个函数解析式;(2)求AOC ∆的面积;(3)根据图象直接写出不等式(1)k x k x >-+的解集.五.解答题(三)(共2小题,每小题12分,共24分)22.如图,AB 是⊙O 的直径,C 、D 是⊙O 上两点,连接CD ,C 是的中点,过点C 作AD 的垂线,垂足是E .连接AC 交BD 于点F .(1)求证:CE 是⊙O 的切线;(2)求证:△CDF ∽△CAD ;(3)若DF =2,CD =,求AC 值.23.如图,在平面直角坐标系中,抛物线21y ax bx =++交y 轴于点A ,交x 轴正半轴于点(4,0)B ,交直线AD 于点5(3,)2D ,过点D 作DC x ⊥轴于点C . (1)求抛物线的解析式;(2)点P 为x 轴正半轴上一动点,过点P 作PN x ⊥轴交直线AD 于点M ,交抛物线于点N ;若点P 在线段OC 上(不与O 、C 重合),连接CM ,求PCM ∆面积的最大值。
九年级数学第一学期期末考试综合复习测试题(含答案)

九年级数学第一学期期末考试综合复习测试题(含答案)一.选择题(共10小题,每小题3分,共30分) 1.2022的相反数是( )A .2022B .2022-C .12022D .2022± 2.若代数式3125m x y -与822m nx y +-是同类项,则( )A .73m =,83n =-B .3m =,4n =C .73m =,4n =- D .3m =,4n =-3.下列四组线段中,能组成直角三角形的是( ) A .1a =,3b =,3c = B .2a =,3b =,4c = C .2a =,4b =,5c =D .3a =,4b =,5c = 4.如图所示,直线//a b ,231∠=︒,28A ∠=︒,则1(∠= )A .61︒B .60︒C .59︒D .58︒5.下列关于事件发生可能性的表述,正确的是( )A .“在地面向上抛石子后落在地上”是随机事件B .掷两枚硬币,朝上面是一正面一反面的概率为13C .在同批次10000件产品中抽取100件发现有5件次品,则这批产品中大约有500件左右的次品D .彩票的中奖率为10%,则买100张彩票必有10张中奖6.某校10名学生参加课外实践活动的时间分别为:3,3,6,4,3,7,5,7,4,9(单位:小时),这组数据的众数和中位数分别为( ) A .9和7 B .3和3 C .3和4.5 D .3和5 7.一个正多边形的每一个内角都是150︒,则它的边数为( ) A .6 B .9 C .12 D .158.若不等式组841x x x m +<-⎧⎨>⎩的解集是3x >,则m 的取值范围是( )A .3m <B .3mC .3m >D .3m9.已知关于x 的一元二次方程22(21)0x m x m --+=有实数根,则m 的取值范围是( ) A .14m 且0m ≠ B .14m C .14m < D .14m >10.如图1,一个扇形纸片的圆心角为90︒,半径为6.如图2,将这张扇形纸片折叠,使点A 与点O 恰好重合,折痕为CD ,图中阴影为重合部分,则阴影部分的面积为( )A .9632π-B .693π-C .91232π-D .94π二.填空题(共5小题,每小题3分,共15分) 11.将数据2022万用科学记数法表示为 .12.已知当3x =时,代数式35ax bx +-的值为20,则当3x =-时,代数式35ax bx +-的值是 .13.将抛物线229y x x =-+-向左平移2个单位,再向上平移1个单位后,得到的抛物线的解析式为 .14.已知ABC ∆中,点O 是ABC ∆的外心,140BOC ∠=︒,那么BAC ∠的度数为 .15.如图,在正方形ABCD 中,顶点(5,0)A -,(5,10)C ,点F 是BC 的中点,CD 与y 轴交于点E ,AF 与BE 交于点G ,将正方形ABCD 绕点O 顺时针旋转,每次旋转90︒,则第2023次旋转结束时,点G 的坐标为 .三.解答题(一)(共3小题,每小题8分,共24分) 16.计算(1)2()(2)x y x y x +--;(2)2219(1)244a a a a --÷--+.17.如图,90ACB ∠=︒,AC AD =.(1)过点D 作AB 的垂线DE 交BC 与点E ,连接AE .(尺规作图,并保留作图痕迹) (2)如果8BD =,10BE =,求BC 的长.18.如图,在四边形ABCD 中,AC 与BD 交于点O ,BE AC ⊥,DF AC ⊥,垂足分别为点E ,F ,且BE DF =,ABD BDC ∠=∠.求证:四边形ABCD 是平行四边形.四.解答题(二)(共3小题,每小题9分,共27分) 19.阳光中学为了丰富学生的课余生活,计划购买围棋和中国象棋供棋类兴趣小组活动使用,若购买3副围棋和5副中国象棋需要98元;若购买1副围棋和2副中国象棋需要36元.(1)求每副围棋和每副中国象棋各多少元;(2)阳光中学决定购买围棋和中国象棋共40副,总费用不超过538元,且围棋的副数不低于象棋的副数,问阳光中学有几种购买方案;(3)请求出最省钱的方案需要多少钱?20.我市某中学举行“中国梦⋅我的梦”的演讲比赛,赛后整理参赛学生的成绩,将学生的成绩分为A,B,C,D四个等级,并将结果绘制成如图所示的条形统计图和扇形统计图,但均不完整,请你根据统计图解答下列问题.(1)参加比赛的学生人数共有名,在扇形统计图中,表示“D等级”的扇形的圆心角为度,图中m的值为;(2)补全条形统计图;(3)组委会决定从本次比赛中获得A等级的学生中,选出两名去参加市中学生演讲比赛,已知A等级中男生只有1名,请用画树状图或列表的方法求出所选学生恰是一男一女的概率.21.22.某网店专售一款新型钢笔,其成本为20元/支,销售中发现,该商品每天的销售量y与销售单价x(元/支)之间存在如下关系:10400y x=-+,自武汉爆发了“新型冠状病毒”疫情该网店店主决定从每天获得的利润中抽出200元捐赠给武汉,同时又让顾客得到实惠,当销售单价定位多少元时,捐款后每天剩余利润为550元?五.解答题(三)(共2小题,每小题12分,共24分)22.如图,以点O为圆心,AB长为直径作圆,在O上取一点C,延长AB至点D,连接DC,过点A作O的切线交DC的延长线于点E,且DCB DAC∠=∠.(1)求证:CD是O的切线;(2)若6AD=,2:3BC CA=,求AE的长.23.如图,在平面直角坐标系中,直线33y x =--与x 轴交于点A ,与y 轴交于点C .抛物线2y x bx c =++经过A 、C 两点,且与x 轴交于另一点B (点B 在点A 右侧). (1)求抛物线的解析式;(2)若点M 是线段BC 上一动点,过点M 的直线ED 平行y 轴交x 轴于点D ,交抛物线于点E ,求ME 长的最大值及此时点M 的坐标; (3)在(2)的条件下:当ME 取得最大值时,在x 轴上是否存在这样的点P ,使得以点M 、点B 、点P 为顶点的三角形是等腰三角形?若存在,请直接写出所有点P 的坐标;若不存在,请说明理由.答案一.选择题1. B .2. D .3. D .4. C .5. C .6. C .7. C .8. B .9. B .10. C . 二.填空题11. 72.02210⨯.12. 30-.13. 228y x x =---.14. 70︒或110︒.15. (4,3)-. 三.解答题16.解:(1)2()(2)x y x y x +--22222x xy y xy x =++-- 2y =;(2)2219(1)244a a a a --÷--+ 23(3)(3)2(2)a a a a a ---+=÷-- 23(2)2(3)(3)a a a a a --=⋅---+ 23a a -=--. 17.解:(1)如图所示即为所求作的图形. (2)ED 垂直AB , 90ADE EDB ∴∠=∠=︒,在Rt BDE ∆中,22221086DE BE BD =-=-=, 在Rt ADE ∆和Rt ACE ∆中, AC ADAE AE =⎧⎨=⎩, Rt ADE Rt ACE(HL)∴∆≅∆, 6EC ED ∴==, 16BC BE EC ∴=+=.18.证明:ABD BDC ∠=∠, //AB CD ∴.BAE DCF ∴∠=∠.在ABE ∆与CDF ∆中, 90BAE DCF AEB CFD BE DF ∠=∠⎧⎪∠=∠=︒⎨⎪=⎩. ()ABE CDF AAS ∴∆≅∆. AB CD ∴=.∴四边形ABCD 是平行四边形.19.解:(1)设每副围棋x 元,每副中国象棋y 元,根据题意得:3598236x y x y +=⎧⎨+=⎩,∴1610x y =⎧⎨=⎩,∴每副围棋16元,每副中国象棋10元;(2)设购买围棋z 副,则购买象棋(40)z -副, 根据题意得:1610(40)538m m +-,40m z -,2023m ∴,m 可以取20、21、22、23则有:方案一:购买围棋20副,购买中国象棋20副方案二:购买围棋21副,购买中国象棋19副方案:购买围棋22副,购买中国象棋18副方案四:购买围棋23副,购买中国象棋17副由4种方案;(3)由上一问可知共有四种方案:方案一:购买围棋20副,购买中国象棋20副;方案二:购买围棋21副,购买中国象棋19副;方案三:购买围棋22副,购买中国象棋18副;方案四:购买围棋23副,购买中国象棋17副;方案一需要20162010520x x +=; 方案二需要21161910526x x +=; 方案三需要22161810532x x +=; 方案四需要23161710538x x +=; 所以最省钱是方案一,需要520元.20.(1)解:根据题意得:总人数为:315%20÷=(人), 表示“D 等级”的扇形的圆心角为43607220⨯︒=︒;C等级所占的百分比为8100%40% 20⨯=,所以40m=,故答案为:20,72,40.(2)解:等级B的人数为20(384)5-++=(人),补全统计图,如图所示:(3)解:根据题意,列出表格,如下:男女1女2男女1、男女2、男女1男、女1女2、女1女2男、女2女1、女2共有6种等可能结果,其中恰是一男一女的有4种,所以恰是一男一女的概率为42 63 =.21.解:由题意可得(20)(10400)200550x x--+-=解得125x=,235x=因为要让顾客得到实惠,所以25x=答:当销售单价定为25元时,捐款后每天剩余利润为550元.22.(1)证明:连接OC,OE,如图,AB为直径,90ACB∴∠=︒,即190BCO∠+∠=︒,又DCB CAD∠=∠,1CAD∠=∠,1DCB∴∠=∠,90DCB BCO ∴∠+∠=︒,即90DCO ∠=︒, CD ∴是O 的切线;(2)解:EC ,EA 为O 的切线, EC EA ∴=,AE AD ⊥, OC OA =, OE AC ∴⊥,90BAC EAC ∴∠+∠=︒,90AEO EAC ∠+∠=︒, BAC AEO ∴∠=∠, tan tan BAC AEO ∴∠=∠,∴23BC AO AC AE ==, Rt DCO Rt DAE ∆∆∽,∴23CD OC OA DA AE AE ===, 2643CD ∴=⨯=, 在Rt DAE ∆中,设AE x =,222(4)6x x ∴+=+, 解得52x =. 即AE 的长为52.23.解:(1)直线33y x =--与x 轴、y 轴分别交于点A 、C , (1,0)A ∴-,(0,3)C -抛物线2y x bx c =++经过点(1,0)A -,(0,3)C -, ∴103b c c -+=⎧⎨=-⎩,解得23b c =-⎧⎨=-⎩,∴抛物线的解析式为223y x x =--.(2)设(E x ,223)(03)x x x --<<,则(,3)M x x -, 222393(23)3()24ME x x x x x x ∴=----=-+=--+,∴当32x =时,94ME =最大,此时3(2M ,3)2-. (3)存在.如图3,由(2)得,当ME 最大时,则3(2D ,0),3(2M ,3)2-,32DO DB DM ∴===; 90BDM ∠=︒,223332()()222OM BM ∴==+=. 点1P 、2P 、3P 、4P 在x 轴上, 当点1P 与原点O 重合时,则1322PM BM ==,1(0,0)P ; 当2322BP BM ==时,则232632322OP -=-=, 2632(2P -∴,0); 当点3P 与点D 重合时,则3332P M P B ==,33(2P ,0); 当4322BP BM ==时,则432632322OP +=+=, 4632(2P +∴,0). 综上所述,1(0,0)P ,2632(2P -,0),33(2P ,0),4632(2P +,0).。
微信小程序期末复习

微信⼩程序期末复习过什么六⼀,复习不完了。
第1章作业⼀.单选题(共10题,100.0分)1以下哪个不是主流的⼿机操作系统?A、AndroidB、iOSC、Windows PhoneD、Blackberry正确答案: DBlackberry是⿊莓⼿机,是⼀种⼿机品牌,不是⼀种⼿机操作系统2微信⼩程序是于何时正式发布?A、2015年1⽉9⽇B、2016年1⽉9⽇C、2017年1⽉9⽇D、2018年1⽉9⽇正确答案: C是2017年1⽉9⽇正式发布,距离苹果第⼀代⼿机发布正好⼗年3以下哪个不是正确的⼩程序⼊⼝?A、 微信对话分享进⼊B、点击url地址进⼊C、扫码进⼊D、搜索关键词进⼊正确答案: B⼩程序有多重⼊⼝,常⽤的有:扫码、对话分享、搜索关键词4注册账号时,需要选择的类型是?A、⼩程序B、订阅号C、服务号D、企业号正确答案: A5⼩程序注册的账号是?A、学号B、邮箱C、⼿机号D、微信号正确答案: B是邮箱,并且⼀个邮箱只能注册⼀个⼩程序账号6学⽣注册⼩程序⽤于个⼈学习,选择的程序主体类型是?A、企业B、政府C、媒体D、个⼈正确答案: D7关于⼩程序账号的注册,以下说明不正确的是?A、⼀个⼿机号只能注册⼀个⼩程序B、注册时需要填写⾝份证号C、⼀个邮箱只能注册⼀个⼩程序D、个⼈类型必须是年满18周岁以上的微信实名⽤户正确答案: A⼀个⼿机号可以注册5个⼩程序8以下哪个不是⼩程序账号完善需要填写的内容?A、⼩程序名称B、⼩程序头像C、⼩程序介绍D、服务器地址正确答案: D需要填写的内容是:⼩程序名称、头像、介绍以及服务类⽬的选择9关于⼩程序成员类型,不包含以下哪个?A、开发者B、管理员C、审核者D、体验者正确答案: C只有腾讯公司官⽅才审核10关于微信web开发者⼯具的下载和安装,没有以下哪个版本?A、UnixB、Mac OSC、Windows 32D、Windows 64正确答案: A只有三个版本:MacOS、Windows32和64位操作系统第2章作业⼀.单选题(共10题,100.0分)1新建项⽬时需要填写AppID,关于此项内容以下说法不正确的是?A、不填写AppID就⽆法成功创建项⽬。
人教版七年级数学下册期末测试题及复习资料详解共五套

李庄人教版七年级数学下学期末模拟试题(一)一、选择题:(本大题共10个小题,每小题3分,共30分) 1.若m >-1,则下列各式中错误的...是( ) A .6m >-6 B .-5m <-5 C .1>0 D .1-m <2 2.下列各式中,正确的是( )16±4 B.±164 C 327- 3 2(4)- 4 3.已知a >b >0,那么下列不等式组中无解..的是( ) A . B . C . D .4.一辆汽车在马路上行驶,两次拐弯后,仍在原来的方向上平行行驶,那么两个拐弯的角度可能为 ( )(A) 先右转50°,后右转40° (B) 先右转50°,后左转40° (C) 先右转50°,后左转130° (D) 先右转50°,后左转50° 5.解为的方程组是( ) A. B. C. D.6.如图,在△中,∠500,∠800,平分∠,平分∠,则∠的大小是( ) A .1000 B .1100 C .1150 D .1200PCBA 小刚小军小华(1) (2) (3)7.四条线段的长分别为3,4,5,7,则它们首尾相连可以组成不同的三角形的个数是( ) A .4 B .3 C .2 D .1 8.在各个内角都相等的多边形中,一个外角等于一个内角的12,则这个多边形的边数是( ) A .5 B .6 C .7 D .89.如图,△A 1B 1C 1是由△沿方向平移了长度的一半得到的,若△的面积为20 cm 2,则四边形A 11的面积为( )A .10 cm 2B .12 c m 2C .15 cm 2D .17 cm 210.课间操时,小华、小军、小刚的位置如图1,小华对小刚说,假如我的位置用(•0,0)表示,小军的位置用(2,1)表示,那么你的位置可以表示成( )A.(5,4)B.(4,5)C.(3,4)D.(4,3)二、填空题:本大题共8个小题,每小题3分,共24分,把答案干脆填在答题卷的横线上. 11.49的平方根是,算术平方根是8的立方根是. 12.不等式59≤3(1)的解集是.13.假如点P(a,2)在第二象限,那么点Q(-3)在.14.如图3所示,在铁路旁边有一李庄,现要建一火车站,•为C 1A 1ABB 1CD了使李庄人乘火车最便利(即间隔 最近),请你在铁路旁选一点来建火车站(位置已选好),说明理由.15.从A 沿北偏东60°的方向行驶到B,再从B 沿南偏西20°的方向行驶到C,•则∠度.16.如图∥,∠100°平分∠,则∠.17.给出下列正多边形:① 正三角形;② 正方形;③ 正六边形;④ 正八边形.用上述正多边形中的一种可以辅满地面的是.(将全部答案的序号都填上) 18.若│x 2-25则.三、解答题:本大题共7个小题,共46分,解答题应写出文字说明、证明过程或演算步骤. 19.解不等式组:,并把解集在数轴上表示出来.20.解方程组:2313424()3(2)17x y x y x y ⎧-=⎪⎨⎪--+=⎩21.如图, ∥ , 平分∠,你能确定∠B 及∠C 的数量关系吗?请说明理由。
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测试题注意:1.本试卷共四大题,满分100分,考试时间90分钟;取g=10N/kg。
2.将答案做在答题卷上,交卷时只交答题卷。
一、选择题(本题共10小题,每小题3分,共30分.每小题给出的四个选项中,只有一个正确选项)1.一瓶食用“金龙鱼”色拉油用去一半,则剩下的油()A.质量减为原来的一半,密度减为原来的一半B.体积减为原来的一半,密度减为原来的一半C.质量、体积、密度均减为原来的一半D.体积减为原来的一半,密度保持不变2.如图1所示,划线部分有利于减小压强的是()3.下列各种微粒的空间尺度按由大到小的顺序排列正确的是()A.原子一原子核一质子一夸克 B.原子一质子-夸克一原子核C.原子-夸克一质子一原子核 D.原子-夸克一原子核一质子4.如图2所示,用水平力F拉着重为100N的物体,在水平地面上向左匀速移动了5m,物体所受地面的摩擦力大小为20N,则()A.重力做的功是500J B.拉力大小为100NC.拉力大小为120N D.拉力做的功为100J5.形状不同的甲、乙、丙三个物体,浸没在水中不同的深度,如果受到的浮力相等,则一定可以判定()A.它们的质量相等 B.它们的体积相等C.它们的密度相等 D.它们的重力相等6.下列事例中不是利用大气压的是()A.护士给病人进行注射时,用力把药水推入肌肉中B.用吸管能从瓶中吸取饮料C.茶壶的盖上留一小孔,水才容易倒出。
D.把吸盘式挂衣钩紧贴到墙上后可挂衣服7.如图3所示,电动小车沿斜面从A匀速运动到B,则在这个过程中小车()A.动能不变,重力势能增加,总的机械能增加B.动能增加,重力势能减少,总的机械能减少图3C.动能不变,重力势能增加,总的机械能不变D.动能减少,重力势能增加,总的机械能不变8.下列关于功、功率和机械效率的说法中,正确的是()A.功率大的机械,做功一定多 B.做功快的机械,功率一定大C.效率高的机械,功率一定大 D.做功多的机械,效率一定高9.当甲、乙两个小孩坐在跷跷板上静止时,跷跷板处于水平状态,如果不计其它阻力和跷跷板重力的影响,则甲、乙两个小孩()A.体重一定相等B.距转轴的距离一定相等C.转轴两侧小孩所受重力与小孩到转轴的距离的乘积相等D.甲小孩比乙小孩更重10.如图4所示,物体A通过动滑轮在水平拉力F的作用下,沿水平面以2米/秒的速度做匀速直线运动,此时物体A所受的摩擦力是10牛,如果滑轮、绳子所受重力及滑轮与轴的摩擦均不计,则拉力F的大小及拉力F做功的功率分别是()图4A.10N 40W B.5N 10W C.10N 20W D.5N 20W二、填空题(每空1分,共23分)11.“会挽雕弓如满月,西北望,射天狼”的诗句表达了诗人苏轼期望为国御敌立功的壮志,如果拉弯的弓将箭水平射出去,这一过程中能量的转化情况是:弓的能转化为箭的能。
12.用手握着两张纸,让纸自然下垂,在两张纸的中间向下使劲吹气,则这两张纸将相互(填“靠近”或“分开”),这说明:气体的流速越大,气体的压强就越(填“大”或“小”)13.一块体积为100 cm3的冰块全部熔化成水后的质量是 kg ,水的体积为 cm3。
(已知冰的密度为0.9×103 kg/ m3)14.一支步枪枪筒长0.8m,火药爆发时产生的高压气体对子弹的平均推力是2000N,子弹离开枪口后,在空气中飞行了500m落在地上.则高压气体对子弹所做的功大约是_______J。
15.木块的密度是0.6×103kg/m3,冰块的密度是0.9×103kg/m3,若它们质量相等,都漂浮在水面上,则木块受到的浮力(选填“大于”、“等于”或“小于”)冰块受到浮力。
若把质量相等的实心木块和实心铁块,放入水中静止后,木块受到浮力铁块受到的浮力(选填“大于”、“等于”或“小于”)(铁的密度为7.9×103kg/m3)。
16.如图5所示,用细线把很干净的玻璃板吊在弹簧测力计的下面,记下测力计的读数;然后使玻璃水平接触水面,稍稍向上拉玻璃板,在玻璃板离开水面之前,弹簧测力计读数(填“变大”、“变小”或“不变”),这个现象说明分子间存在相互作用的力。
17.2007年5月31日是第19个世界无烟日,吸烟有害健康。
在空气不流通的房间里,只要有一个人吸烟,整个房间就会充满烟味,这表明分子在,在公共场所,为了他人的健康,请你给吸烟者提出一条合理的建议:。
18.如图6所示,汽车是大家熟悉的交通工具,汽车应用了许多物理知识。
请你运用所学的物理知识解答下列问题:(1)轮胎上有凸凹不平的花纹,其目的是。
(2)有一辆重1.2×104N的6轮汽车,如果每个车轮与路面的接触面积为200cm2,该汽车对水平地面的压强是Pa。
(3)“五、一”假期的一天,刘小华乘坐爸爸的汽车到机场游玩, 在机场高速公路的入口处,看到如图7所示的标志牌。
在不违反交通规则的前提下,他们从入口处至少行驶小时才能到达机场。
(4)汽车在一段平直的路段上行驶了0.9km,若汽车速度计的指针一直指在如图8所示的位置,爸爸告诉小华:汽车在这段时间的功率是50kW。
请计算在这段时间内汽车的牵引力大小是N。
19.如图9所示,O为轻质杠杆的支点,OA=40厘米,OB=50厘米,B点所挂物体重60牛,要使杠杆在水平位置平衡,则在A点至少加一个竖直向上______牛的动力,这是一个______(选填“省力”或“费力”)杠杆。
20.将牛奶制成奶粉时,为了保持牛奶的营养成分,不能用高温煮沸,为此,人们制造了一种“低压锅”,可以使牛奶里的水不到100℃就沸腾。
这种“低压锅”的物理原理是。
21.有如下器材:①瓶盖起子,②剪铁皮的剪刀,③天平,④定滑轮,⑤镊子,⑥钓鱼竿。
其中属于省力杠杆的有;属于费力杠杆的有;属于等臂杠杆的有(以上各空填序号)。
三、实验与探究题(22题6分,23题9分,24题5分,共20分)22.为研究物质的某种特性,某同学测得四组数据,填在下列表中:(1)比较第1、2两次实验数据,可得出结论:同一种物质,它的质量跟它的体积成。
(2)比较第2、3两次实验数据,可得出结论:质量相同的不同物质,体积是。
(填“相等”或“不等”)(3)比较第1、4两次实验数据,可得出实验结论是。
23.图10是同学们用来测滑轮组机械效率的实验装置。
(1)如果钩码总重5.0N,每个滑轮重0.7N,不计绳重与摩擦,则钩码静止时,拉力是 N。
(2)为准确测出滑轮组的机械效率,应竖直向上拉动弹簧测力计使钩码上升。
(3)下表是某同学测图10所示滑轮组机械效率的实验记录,请帮他完成未填写的实验数据。
项目钩码重G/N拉力F/N钩码上升的高度h/cm弹簧测力计移动的距离S/cm有用功W有/J总功W总/J机械效率η%实验数据5.0 2.510(4)实验结束后,在全班交流实验结果时,老师提出:如果各组所用滑轮和串绕绳子的方式不变,哪些因素会影响滑轮组的机械效率呢?经过大家积极思考,提出了各种猜想,概括起来有如下几种:猜想1:可能与匀速提升的速度大小有关;猜想2:可能与被提升的钩码重有关;猜想3:可能与匀速提升的速度大小和被提升的钩码重都有关;猜想4:可能与钩码被提升的高度有关。
小明和小强分别根据各自的猜想进行了探究,实验记录如下表。
①请帮助小强完成表中的一项计算,其数据是 。
②根据他俩的实验记录,可得出小明的探究结论是 ;小强的探究结论是 。
24.在“探究杠杆的平衡条件”实验中,应先调节杠杆两端的平衡螺母,使杠小明的实验记较小提升速绳端钩码机械 较大提升速探究结14.79.4% 4.1物理量 控制因素79.4探究结论79.4% 绳端钩码机械 大致相同小强的实验记录 1 4.1 6.物理量 控制因素杆在水平位置平衡,这样做是为了便于测量;如发现杠杆左端偏高,则可将右端的平衡螺母向调节,或将左端的平衡螺母向调节。
图11是小明同学三次实验的情景,实验时所用的每个钩码重0.5N,杠杆上每一格长5cm,部分实验数据已记录在下表中。
实验次数动力F1/N动力臂L1/cm阻力F2/N阻力臂L2/cm1 1.5101152120210 3120 1.510(1)小明的第3次实验存在错误,其错误是(2)从表格记录的实验数据可得到杠杆的平衡条件是四、计算论述题(解答时要有必要的文字说明、公式和运算过程,直接写出结果的不能得分,25题9分,26题9分,27题9分,共 27分)25.图12中平底茶壶的质量是0.4kg ,水壶底面积是4×10-3m 2,壶内盛0.6kg 的水,水面高度在图中已标出,把壶放置在面积为l m 2的水平桌面中央。
求:(1)水对茶壶底部产生的压力 (2)茶壶对桌面的压强26.密度为3/106.03m kg ⨯=木ρ的长方体木块,长a=0.4m ,宽b=0.2m ,高c=0.1m 。
(1)求长方体木块的质量(2)当木块漂浮在水面上时,它浸入水中部分的体积是多少?(水的密度3/100.13m kg ⨯=水ρ)。
27.如图13所示,用滑轮组提起重900N 的物体,绳子自由端拉力F 为400N ,重物在20S 内匀速上升了10m 。
求:图12(1)拉力F做功的功率(2)滑轮组的机械效率。
(3)若不计绳重和滑轮与轴之间的摩擦,请求出动滑轮的重。
参考答案一、选择题1.D 2.C 3.A 4.D 5.B6.A 7.A 8.B 9.C 10.D二、填空题11.弹性势 动12.靠近 小13.0.09 9014.160015.等于 大于16.变大 引17.运动 不吸烟或者到指定吸烟处吸烟18.(1)增大摩擦(2)5110(3)0.3(4)200019.75 费力20.气压越小沸点越低21.①②⑤⑥③④三、实验与探究题22.(1)正比(2)不等(3)不同物质,体积相等,质量却不相等或者不同物质,质量与体积的比值一般不同23.(1)1.9(2)匀速(3)30 0.5 0.75 66.7%或67%(4)①83.3% ②滑轮组的机械效率与提升的速度无关滑轮组的机械效率与被提升的钩码重有关24.力臂 左或里(内) 左或外(1)把如图中所示的L 1当成3F 1的力臂(2)动力×动臂=阻力×阻力臂四、论述计算题25.解:(1)33110100.12 1.210P gh ρ==⨯⨯⨯=⨯Pa331.210410 4.8F PS -==⨯⨯⨯=N(2)'124N 6N 10N F G G =+=+=''3-3210N 2.510410m F P S ===⨯⨯Pa26.解:(1)30.40.20.1810V abc -==⨯⨯=⨯木m 3330.610810 4.8m V ρ-==⨯⨯⨯=木木木kg(2)∵木块漂浮∴48F G m g ==浮木=N ∴333348N 4.810m 110kg/m 10N/kgF V g ρ-===⨯⨯⨯浮排水27.解:(1)4400103 1.210W FS ==⨯⨯=⨯总J41.21060020W P t ⨯===总W (2)900109000W Gh ==⨯=有J 49000100%100%75%1.210W W η=⨯=⨯=⨯有总 (3)1()3F G G =+动物 ∴1()3F G G =+动物 ∴33400900300G F G =-=⨯-=动物N。