人教版小学数学六年级期末复习重点难点知识点

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六年级数学上册期末复习知识点汇总(人教版)

六年级数学上册期末复习知识点汇总(人教版)

六年级数学上册期末复习知识点汇总(人
教版)
1. 数的读写和数位在数表中的比较
- 掌握百以内数的读写方法
- 进一步练百以内数字的大小比较
- 在数表中比较数位的大小
2. 术语的认识和深化
- 理解单位和量的关系,研究长度、容量、时间等单位的名称和换算
- 认识图线表、拔河运动、神奇图等特殊的数学问题
- 进一步掌握理论题中的数学术语,如加法、减法、乘法、除法等
3. 两位数和三位数的认识
- 认识两位数和三位数,并通过具体的例子进行演算
- 进一步研究如何将两位数和三位数的大小进行比较
- 在实际问题中运用两位数和三位数进行计算
4. 数量和对应关系的探讨
- 了解相等的概念,并通过具体例子进行对比
- 研究图表和表格的分析,找出其中的规律
- 运用对应关系解决实际问题,如物品的分组、排列等
5. 探究几何图形和图形的特征
- 了解常见的平面图形和立体图形,如三角形、四边形、圆、长方体、正方体等
- 掌握几何图形的命名及其特征
- 研究分析和比较不同几何图形的性质和关系
6. 数据的收集和分析
- 研究如何进行数据的收集、整理和表示
- 给出简单的表格和图表,进行数据的分析和总结
- 运用数据分析解决实际问题,如人数统计、天气变化等
以上是六年级数学上册的期末复习知识点汇总,希望同学们认真复习,并做好复习笔记和习题,以便顺利应对期末考试。

祝大家取得好成绩!。

(完整版)人教版六年级数学总复习资料

(完整版)人教版六年级数学总复习资料

(完整版)人教版六年级数学总复习资料
本文档是人教版六年级数学总复资料的完整版,旨在帮助学生全面复数学知识。

目录
1. 数的认识
2. 数的读写与数的大小比较
3. 数的运算
4. 简便计算法
5. 乘法
6. 除法
7. 解方程和表示思想方法
8. 长度单位
9. 面积与体积
10. 角与直线的认识
11. 同、异角的认识
12. 三角形与四边形
13. 分数的认识与运算
14. 概率
15. 数据的整理和分析
内容概述
本文档涵盖六年级数学各个模块的核心知识点。

每个模块都包含了相关概念、方法和例题,以帮助学生加深对数学知识的理解。

本文档的复资料是从人教版六年级数学教材中提炼出来的,结构简明清晰,适合学生进行系统性的复。

使用建议
学生可以按照目录中的顺序逐个模块进行复,先理解每个模块的基本概念和方法,然后通过例题进行练,加深对知识点的掌握。

建议学生在复过程中积极思考,加深对数学思维的培养。

可以利用课余时间进行复,逐步提高对数学知识的掌握和运用能力。

注意事项
本文档中的知识点都是经过精心整理和筛选的,但仍需注意一些重要的细节。

在研究过程中,遇到不理解的地方可以查阅相关教材进行进一步研究和理解。

建议学生在复过程中多做笔记,方便回顾和巩固知识。

结语
本文档是人教版六年级数学总复习资料的完整版,提供了全面的知识点和例题,旨在帮助学生系统复习数学知识,夯实基础,迎接考试。

希望同学们能够认真阅读、理解和运用本文档中的内容,取得优异的成绩!祝大家学习进步!。

六年级数学上册难点和重点

六年级数学上册难点和重点

六年级数学上册难点和重点六年级数学上册(人教版)重点与难点学习资料一、分数乘法1. 重点- 理解分数乘法的意义。

分数乘整数的意义与整数乘法的意义相同,就是求几个相同加数的和的简便运算;一个数乘分数的意义就是求这个数的几分之几是多少。

例如:(2)/(3)×5表示5个(2)/(3)相加的和;3×(2)/(5)表示3的(2)/(5)是多少。

- 掌握分数乘法的计算方法。

分数乘整数,用分数的分子和整数相乘的积作分子,分母不变;分数乘分数,用分子相乘的积作分子,分母相乘的积作分母。

例如:(2)/(3)×4=(2×4)/(3)=(8)/(3);(2)/(3)×(4)/(5)=(2×4)/(3×5)=(8)/(15)。

- 能解决简单的分数乘法实际问题,如求一个数的几分之几是多少的问题。

例如:一本书有120页,小明第一天看了全书的(1)/(4),求小明第一天看了多少页?就是求120的(1)/(4)是多少,列式为120×(1)/(4) = 30(页)。

2. 难点- 理解分数乘法计算法则的算理。

尤其是分数乘分数时,为什么分子相乘的积作分子,分母相乘的积作分母,需要通过图形等直观方式来理解。

例如:把一个长方形看作单位“1”,平均分成3份,取其中的2份表示(2)/(3),再把这(2)/(3)平均分成5份,取其中的4份,相当于把单位“1”平均分成了3×5 = 15份,取了2×4 = 8份,所以结果是(8)/(15)。

- 解决较复杂的分数乘法实际问题,如连续求一个数的几分之几是多少的问题。

例如:果园里有苹果树100棵,梨树的棵数是苹果树的(3)/(4),桃树的棵数是梨树的(2)/(3),求桃树有多少棵?需要先求出梨树的棵数100×(3)/(4)=75棵,再求出桃树的棵数75×(2)/(3)=50棵。

二、位置与方向(二)1. 重点- 能根据方向和距离确定物体的位置。

(完整版)新人教版六年级数学总复习知识点归纳

(完整版)新人教版六年级数学总复习知识点归纳

小学六年级数学总复习知识点归纳一、常用的数量关系式1、每份数×份数=总数总数÷每份数=份数总数÷份数=每份数2、1倍数×倍数=几倍数几倍数÷1倍数=倍数几倍数÷倍数=1倍数3、速度×时间=路程路程÷速度=时间路程÷时间=速度4、单价×数量=总价总价÷单价=数量总价÷数量=单价5、工作效率×工作时间=工作总量工作总量÷工作效率=工作时间工作总量÷工作时间=工作效率6、加数+加数=和和-一个加数=另一个加数7、被减数-减数=差被减数-差=减数差+减数=被减数8、因数×因数=积积÷一个因数=另一个因数9、被除数÷除数=商被除数÷商=除数商×除数=被除数二、小学数学图形计算公式1、正方形(C:周长 S:面积 a:边长)周长=边长×4 C=4a面积=边长×边长S=a×a2、正方体(V:体积a:棱长)表面积=棱长×棱长×6 S表=a×a×6体积=棱长×棱长×棱长V=a×a×a3、长方形(C:周长 S:面积 a:边长)周长=(长+宽)×2 C=2(a+b)面积=长×宽S=ab4、长方体(V:体积 s:面积 a:长 b: 宽 h:高)(1)表面积(长×宽+长×高+宽×高)×2 S=2(ab+ah+bh)(2)体积=长×宽×高V=abh5、三角形(s:面积 a:底 h:高)面积=底×高÷2 s=ah÷2三角形高=面积×2÷底三角形底=面积×2÷高6、平行四边形(s:面积 a:底 h:高)面积=底×高s=ah7、梯形(s:面积 a:上底 b:下底 h:高)面积=(上底+下底)×高÷2 s=(a+b)× h÷28、圆形(S:面积 C:周长л d=直径 r=半径)(1)周长=直径×л=2×л×半径C=лd=2лr(2)面积=半径×半径×л9、圆柱体(v:体积 h:高 s:底面积 r:底面半径 c:底面周长)(1)侧面积=底面周长×高=ch(2лr或лd) (2)表面积=侧面积+底面积×2(3)体积=底面积×高10、圆锥体(v:体积 h:高 s:底面积 r:底面半径)体积=底面积×高÷311、总数÷总份数=平均数14、相遇问题相遇路程=速度和×相遇时间相遇时间=相遇路程÷速度和速度和=相遇路程÷相遇时间15、利润与折扣问题利息=本金×利率×时间税后利息=本金×利率×时间×(1-5%)三、常用单位换算1、长度单位换算1千米=1000米1米=10分米 1分米=10厘米1米=100厘米 1厘米=10毫米面积单位换算1平方千米=100公顷 1公顷=10000平方米 1平方米=100平方分米1平方分米=100平方厘米 1平方厘米=100平方毫米2、体(容)积单位换算1立方米=1000立方分米 1立方分米=1000立方厘米 1立方分米=1升1立方厘米=1毫升 1立方米=1000升重量单位换算1吨=1000 千克 1千克=1000克 1千克=1公斤人民币单位换算1元=10角 1角=10分 1元=100分3、时间单位换算1世纪=100年 1年=12月大月(31天)有:1\3\5\7\8\10\12月小月(30天)的有:4\6\9\11月平年2月28天, 闰年2月29天平年全年365天, 闰年全年366天 1日=24小时1时=60分 1分=60秒 1时=3600秒4、基本概念第一章数和数的运算一概念(一)整数1 整数的意义自然数和0都是整数。

人教版六年级数学知识点整理(详细)

人教版六年级数学知识点整理(详细)

人教版六年级数学知识点整理(详细)人教版六年级数学知识点整理(详细)嗨,亲爱的小伙伴们!今天咱们来一起梳理梳理人教版六年级数学的重要知识点哟。

先来说说分数乘法。

这个可有意思啦,记住分子乘分子,分母乘分母就行。

但要注意能约分的先约分,这样计算起来更简单呢。

比如2/3 乘以 3/4,约分后就是 1/2 啦。

接着是位置与方向。

这就像是给咱们一个地图,要能准确找到目标在哪里。

得搞清楚方向,什么东偏北、西偏南的,角度也要看准哟。

还有分数除法,它和乘法正好相反。

除以一个分数,就等于乘以它的倒数。

比如说 3 除以 1/2 ,就等于 3 乘以 2,等于 6 。

百分数也很重要呢!它常常出现在我们的生活中,像打折、利率啥的。

要会把百分数和小数、分数互相转换。

比的知识也不能少。

什么前项、后项,比值,都要弄得明明白白。

圆这部分可得好好学,圆的周长和面积公式要牢记。

知道半径或者直径,就能算出周长和面积啦。

扇形统计图能让我们一眼看出各种数据的占比情况,可直观啦。

数学可有趣啦,小伙伴们加油学哟!人教版六年级数学知识点整理(详细)哈喽呀,小伙伴们!咱们继续聊聊六年级数学的知识点。

数学广角里的鸡兔同笼问题是不是很有趣?咱们可以用假设法或者方程来解决。

百分数的应用也不少,比如求增加或减少百分之几,要先算出增加或减少的量,再除以原来的量。

还有统计方面,不仅要会看统计图,还要能根据数据进行分析和预测。

数学中的解决问题策略也很关键哦。

像用画图、列举、假设等方法,能帮助咱们更快地找到答案。

在图形的放大和缩小中,要注意对应边的比例关系不变。

比例的知识也很重要哟,判断两个比能否组成比例,就看它们的比值是否相等。

六年级的数学虽然有点难,但只要咱们认真学,都能掌握哒!加油哟!。

人教版六年级上册数学期末专题复习(知识要点、易错易混题目、按类型整理)

人教版六年级上册数学期末专题复习(知识要点、易错易混题目、按类型整理)

六年级上册数学期末复习(概念与题型)一、分数、百分数应用题解题公式单位“1” 已知: 单位“1” × 对应分率 = 对应数量求单位“1”或单位“1”未知:对应数量 ÷ 对应分率 = 单位“1” 1、求一个数是另一个数的几分之几(或百分之几)公式: 一个数 ÷ 另一个数 = 一个数是另一个数的几分之几(百分之几) 2、求一个数比另一个数多几分之几(或百分之几)公式:多的数量÷单位“1” = 一个数比另一个数多几分之几(百分之几) 3、求一个数比另一个数少几分之几(或百分之几)公式:少的数量÷单位“1” = 一个数比另一个数少几分之几(百分之几) 二、熟练掌握:百分数和分数、小数的互化,熟练背诵:1 2 = 0.5 = 50% 1 4 = 0.25=25% 34 = 0.75 = 75% 1 5 = 0.2 = 20% 2 5 = 0.4 = 40% 35 = 0.6 = 60% 4 5 = 0.8 = 80% 1 8 =0.125=12.5% 38 =0.375=37.5% 5 8 =0.625=62.5% 7 8 =0.875=87.5% 1 10 =0.1=10% 1 20 =0.05=5% 1 25 =0.04=4% 150 =0.02=2% 1100=0.01=1%三、基本题型:(1)一条路全长1200米,第一天修了全长的 15 ,第二天修了全长的 14 ,还剩几分之没有修?(2)果园里有桃树200棵,梨树比桃树少 15 ,果园里有梨树多少棵?(3)果园里有桃树200棵,比梨树少 15 ,果园里有梨树多少棵?(4)一件上衣,打八折后是72元,这件上衣原价多少元?(5)一条路,第一天修了全长的 1 5 ,第二天修了全长的 14 ,第一天比第二天少修60米,这条路全长多少米?(6)五月份比六月份节约用水20吨,五月份用水80吨。

五月份比六月份用水节约百分之几?(7)一杯盐水,盐10克,水90克,这杯盐水的含盐率。

六年级数学知识点归纳总结人教版

六年级数学知识点归纳总结人教版

六年级数学知识点归纳总结人教版
六年级数学知识点归纳总结(人教版)
一、数与代数
1. 数的认识
* 整数、小数、分数、百分数等基本概念及其性质
* 正数、负数、零的概念及其关系
* 数的读写方法
* 数的四则运算(加、减、乘、除)
* 分数和小数的互化
2. 数的运算
* 四则运算的意义、运算法则和运算定律
* 简便计算的方法
* 运算顺序
3. 式与方程
* 用字母表示数,用含有字母的式子表示简单的数量关系和计算公式* 解简易方程的方法
4. 正比例和反比例
* 正比例、反比例的概念及其性质
* 正比例关系图象的特征
* 求解正比例和反比例的问题
二、空间与图形
1. 图形的认识
* 线和角的基本概念及性质(直线、射线、线段、角的度量)* 相交线和平行线的概念及其性质
* 三角形、四边形、圆等基本图形及其性质
2. 图形的测量
* 周长、面积、体积等基本测量概念及其计算方法
* 圆的周长和面积计算公式
3. 图形的运动
* 平移、旋转的概念及其性质
* 平移和旋转的作图方法
三、统计与概率
1. 统计初步知识
* 统计表和统计图的概念及其制作方法
* 数据的整理和表示方法(平均数、中位数、众数等)
2. 概率初步知识
* 确定性和随机现象的概念及其关系
* 可能性的大小(概率)的概念及计算方法
* 简单概率模型的应用
四、综合与实践
1. 有趣的数学图形
2. 密铺的奥秘
3. 互联网的普及率。

人教版小学六年级数学毕业总复习知识点概括归纳完整版

人教版小学六年级数学毕业总复习知识点概括归纳完整版

小学数学总复习资料【常用的数量关系】1、每份数×份数=总数;总数÷每份数=份数;总数÷份数=每份数2、速度×时间=路程;路程÷速度=时间;路程÷时间=速度3、单价×数量=总价;总价÷单价=数量;总价÷数量=单价4、工作效率×工作时间=工作总量;工作总量÷工作效率=工作时间;工作总量÷工作时间=工作效率;5、加数+加数=和;和-一个加数=另一个加数6、被减数-减数=差;被减数-差=减数;差+减数=被减数7、因数×因数=积;积÷一个因数=另一个因数8、被除数÷除数=商;被除数÷商=除数;商×除数=被除数【小学数学图形计算公式】1、正方形(C:周长, S:面积, a:边长)正方形周长=边长×4; C=4a正方形面积=边长×边长; S=a×a2、正方体(V:体积, a:棱长)正方体表面积=棱长×棱长×6; S=a×a×6表正方体体积=棱长×棱长×棱长; V= a×a×a3、长方形(C:周长, S:面积, a:边长, b:宽)长方形周长=(长+宽)×2; C=2(a+b)长方形面积=长×宽; S=a×b4、长方体(V:体积, S:面积, a:长, b:宽, h:高)(1)长方体表面积=(长×宽+长×高+宽×高)×2; S=2(ab+ah+bh)(2)长方体体积=长×宽×高; V=abh5、三角形(S:面积, a:底, h:高)三角形面积=底×高÷2 ; S=ah÷2三角形的高=面积×2÷底三角形的底=面积×2÷高6、平行四边形(S:面积, a:底, h:高)平行四边形面积=底×高; S=ah7、梯形(S:面积, a:上底, b:下底, h:高)梯形面积=(上底+下底)×高÷2; S=(a+b)×h÷28、圆形(S:面积, C:周长,π:圆周率, d:直径, r:半径)(1)圆周长=π×直径π=2×π×半径; C=πd=2πr(2)圆面积=π×半径×半径; S= πr29、圆柱体(V:体积, S:底面积, C:底面周长, h:高, r:底面半径)(1)圆柱体侧面积=底面周长×高=Ch=πdh=2πrh(2)圆柱体表面积=侧面积+底面积×2(3)圆柱体体积=底面积×高 v=sh=πr2h10、圆锥体(V:体积, S:底面积, h:高, r:底面半径)体积=底面积×高÷311、平均数=总数÷总份数12、和差问题的公式:已知两数的和及它们的差,求这两个数各是多少的应用题,叫做和差应用题,简称和差问题。

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人教版小学数学六年级期末复习重点难点知识点_百度知道(Know the sixth grade primary school mathematics review of key and difficult knowledge points _ Baidu teach)Know the Baidu home page | Baidu know | login | registered experts interpret the job hunt version of the sixth grade primary school mathematics review of key and difficult knowledge points _ Baidu teach= graduate unemployment! There are job experts to solve your problems; all kinds of job information for you to read at any time; more famous positions, you apply for!Go to seePost Bar news page MP3 photo video encyclopedia library help | setBaidu knows [education / Science] primary school educationPEP edition, primary mathematics, grade six, final review, key points, difficulties, knowledge pointsViews: 1117 reward points: 50 | question time: 2009-12-12 19:20 | questionger: why is closed | arrive happinessTo list, to recite, to refine. Problem supplement:More popular, I can understand, please.It is better to add 3 simple to difficult questions at the backof each knowledge point.I want to understand! I was only back, there's a reason I. Will offer a reward!There are 4 other answers1 number per copy = totalThe total number of copies per =.The total number of copies of each number =.21 multiples * multiples = multiplesA few times, 1 times times =A few times, ratio = 1 times3 speed x time = distanceDistance / speed = timeTime = distance / speed4 unit price = quantity = total pricePrice / price = numberThe total number of 83019 = price5 work efficiency * working hours = work amountThe total amount of work, work efficiency = working time The total amount of work, work time = work efficiency6 addend addend = + andAnd a = other addend addend7 - meiosis difference = minuendMinuend - difference = meiosisPoor + = subtrahend minuend8 factor X factor = productProduct, a factor = another factor9 dividend, divisor = BusinessDividend, divisor = BusinessQuotient * divisor = divisorMathematical formulas for elementary school mathematics 1 squaresC perimeter, S area, a side length Circumference = side length * 4C=4aArea = side length * side lengthS=a * a2.V: volume a: edge lengthSurface = edge length x x x * 6S table =a x a * 6Volume = edge length x edge long x edge length V=a * a * a3 rectangleC perimeter, S area, a side length Circumference = (length + width) * 2C=2 (a+b)Area = length * widthS=ab4 cuboidV: volume s:, area a: long, b: width, h: height(1) surface area (length * width + length * height + width * height) * 2S=2 (ab+ah+bh)(2) volume = * * width * heightV=abh5 triangleS area a, bottom h highBottom area = x height / 2S=ah / 2Triangle area high = x 2 / bottomTriangle area = x 2 / high6 parallelogramS area a, bottom h highArea = base * heightS=ah7 trapezoidS area a, bottom B, bottom h highArea = (+ down on the bottom end) * / 2S= (a+b) * H / 28 roundS C - d= r= diameter, perimeter area radius(1) = =2 * * * perimeter diameter pi * radiusC= II d=2 II R(2) * * * area = radius radius9 cylinderV: volume h: high S; bottom area r:; base radius c:; bottom perimeter(1) the side area = the circumference of the bottom * high(2) surface area = side area + base area * 2(3) volume = base area * height(4) = 2 / X volume side area radius10 coneV: volume h:, high S; base area r:, bottom radius Volume = bottom area x height / 3The total, the total number of copies = average number Equation of sum and difference(+ and difference) 83019 2 = number(and poor) 83019 2 = decimalDoubling problemAnd (1 = decimal multiples).Decimal = multiple = large number(or sum = decimal = large number)Difference problem(1 / difference multiples) = decimalDecimal = multiple = large number(or decimal + difference = large number)Tree planting problem1, the problem of tree planting on non closed lines can be divided into the following three cases:If a non closed line at both ends are planting trees, so:Number = number of + 1 / 1 = length spacing* (1 = length spacing number)Full length (1 / spacing = number)If you want to plant trees in the end of non closed line, the other end is not planting, so:Number = number = length / spacingLength = x number of rows= length / number of rowsIf both ends in non closed line are not planting trees, so:Number section number = - 1 / 1 = length spacing* (number = length spacing + 1)= length / spacing (number 1)2 the number of trees on closed lines is as followsNumber = number = length / spacingLength = x number of rows= length / number of rowsProfit and loss(profit + loss), the two distribution of the difference between the number of copies in the distribution of =(large surplus - small surplus) / two distribution of the difference between the number of copies in the distribution of =(burned - a small loss of two times), the difference between the number of copies is assigned to participate in the distribution of theEncounter problemEncounter distance = speed and X meeting timeMeet time = distance / speed and meetThe speed and distance, the encounter time = meetCatch up with problemsTracking distance = speed difference * tracking timeChase and chase and distance / time = speed differenceThe speed difference and distance = chase chase and time.Flow problemDownstream velocity = hydrostatic velocity + flow velocityCountercurrent velocity = hydrostatic velocity - flow velocityHydrostatic speed = (downstream velocity and velocity), 2Flow rate = (downstream speed velocity), 2Concentration problemThe weight of the solute + the weight of the solvent = the weight of the solutionThe weight, the weight of the solute solution x 100% = concentrationWeight of solution = concentration = solute weightThe weight, concentration of solute solution = weightProfit and discount problemsProfit = selling price - costThe rate of profit, profit = cost X 100% = (sold / cost 1) * 100%Amount of fluctuation = principal * Change PercentageThe actual price discount, the original price x = 100% (< 1 discount)Interest = principal * interest rate * timeAfter tax interest rates * * * = principal time (120%)1, 100 ml (1.5 cm3) = M = ().1500 DM3 = (M3)2, a cylindrical bottom diameter is 4 cm, 10 cm high, its side area is () square centimeter, volume is () cubic centimeter.3, do some cylindrical iron pipe, how many iron sheets are required, that is, to ask for it. Asking how much water the pipe can hold is asking for it.5. Dig a cylindrical pool on the ground. The depth of the pool is 4 meters. The diameter is 6 meters. The pool covers an area of square meters and needs cubic meters of earth.6. Spread the sides of a cylinder to get a square. The radius of the bottom of this column is 2 cm, and the height of the cylinder is () cm, its volume is () cubic centimeter.Two, good referee. (10 points)1, the lateral expansion of the cylinder can get a rectangle, the length of this rectangle is equal to the circumference of the bottom of the cylinder, and the width is equal to the height of the column. ()2. A cylinder with a radius of 2 meters. Its bottom circumference is equal to its base area. ()3, the broken line statistical chart is more likely to see the relationship between the parts and the whole. ()Three. Write the serial number of the correct answer in brackets (10 points)1, such as high at the end of a cylindrical, square, rectangular volume comparison, ()A. cube cuboidB. large volume; large volume;C. cylinders are large, as big asD..2, the radius and height of the bottom of the cylinder are enlarged 3 times, and its volume enlargement is multiplesA. 3,B. 6,C. 9,D. 273, with a piece of 28.26 cm long, 15.7 cm wide rectangular iron sheet, should be equipped with a diameter () cm of circular iron sheet, you can make a volume of the largest container.A.2.5B. 4.5C. 5D. 9Four, solve the problem1, a cylindrical pool, the bottom surface radius of 3 meters, the pool height of 1.5 meters, the pool can hold up to how many tons (1 cubic meters of water weighing 1 tons)2, a cap of cylindrical metal bucket, 50 cm high, the bottom diameter of 30 cm, the bucket about too much iron? (he retained integer)3, had a 1.5 meter long cylindrical wood, sawed off 4 decimeter long after the surface area decreased by 50.24 square decimeter. What's the original volume of this piece of wood?4, the internal diameter of the water pipe is 2 centimeters, the water flow rate of the pipe is 8 centimeters per second, how many liters can the water flow in 5 minutes?6, a workshop to produce 5 radius of 0.6 meters, 20 meters high cylindrical iron pipe, and in its appearance painted antirust paint. By 0.3 kilograms per square meter with antirust paint, how many kilograms should be used with antirust paint? (retain a decimal number in one way)First, determine the problem (each question 1 points total of 5 points)1.100 tons of peanut kernels can oil 38 tons, peanut oil yield is 38% tons ().Two3. two rectangular bodies of equal length, they must be equal in length, width, heightFour5. the reciprocal of all natural numbers is less than 1. ()Two, RadioButtonList (each 1 points only a total of 5 points)One2. ask how much water a glass fish tank can hold, that is, ask for the glass fish tank [...]A. surface areaB.Volume C., volume D., material area3. Uncle Li's time to process a part has been reduced from 10 minutes to 8 minutes, and his work efficiency has been increasedA.80%B.25%C.20%D.125%FourA. is higher than B,B. is lower than B,C. is equal to B.5. a 15 book, more than B 5, B the number of more than a few percent of correct type is []?Three, fill in the blanks (2 points each day a total of 20 points)(1.) a 1 cubic decimeter cube can be placed to grow 5 wide and 3 decimeter decimeter and high cuboid 2 decimeter.2., 1.05, forming fractions are (), percentages are (), and writing amounts to ()ThreeFour5. a wire is welded into a 6 cm long, 5 cm wide and 4 cm high cuboid, if the wire is welded into a cube, the cube of the surface area is (). The volume is (?).Six7., a project, a single to do 12 days to complete, B only do 15 days to complete. A work 4 days, B work 3 days, completed the project8. dissolve 10 grams of salt in (grams) of water, so that thesalt content of the brine is 5%.NineTenFour, Jane (B. 3 points each computation. A total of 6 points)OneTwoFive, calculation (first items 2, second A. 3 3-5, each of 4 points, a total of 17 points)OneTwoThreeFourFiveSix, text title (4 points each day a total of 16 points)OneTwoThreeFourSeven, application (first items with 4 points, 5 points for each question 2-4 5-6, each of 6 points, a total of 31 points)1., Xinhua steel plant last year produced 2 million 700 thousand tons of steel, more than planned production of 300 thousand tons, the actual production of more than the plan, a few percent?2., a project, if you do alone, a team to use 12 days, B team to use 10 days, team C will use 15 days. Now a team did 3 days later, the remaining B, C, the two teams do, it still takes a few days to complete the task?3., a workshop to produce a batch of parts, 4 hours produced 40% of these parts, according to this calculation, 2.5 hours can produce 30, how many of these parts?4., a factory has two workshops, the first workshop accounted for 65% of the total number of the factory, if from the first workshop to 24 to second workshop, then the number of two workshops on the same, the original first workshop how many people?5. according to the conditions, the algorithm is calculated and the result is calculatedB two road team, a team of 4.8 km road, ________, team B repaired many kilometers?SixFirst, determine the problem (each question 1 points total of 5 points)1.100 tons of peanut kernels can oil 38 tons, peanut oil yield is 38% tons ().Two3. two rectangular bodies of equal length, they must be equal in length, width, heightFour5. the reciprocal of all natural numbers is less than 1. ()Two, RadioButtonList (each 1 points only a total of 5 points)One2. ask how much water a glass fish tank can hold, that is, ask for the glass fish tank [...]A. surface area,B. volume,C. volume,D. material area3. Uncle Li's time to process a part has been reduced from 10 minutes to 8 minutes, and his work efficiency has been increasedA.80%B.25%C.20%D.125%FourA. is higher than B,B. is lower than B,C. is equal to B.5. a 15 book, more than B 5, B the number of more than a few percent of correct type is []?Three, fill in the blanks (2 points each day a total of 20 points)(1.) a 1 cubic decimeter cube can be placed to grow 5 wide and 3 decimeter decimeter and high cuboid 2 decimeter.2., 1.05, forming fractions are (), percentages are (), and writing amounts to ()ThreeFour5. a wire is welded into a 6 cm long, 5 cm wide and 4 cm high cuboid, if the wire is welded into a cube, the cube of the surface area is (). The volume is (?).Six7., a project, a single to do 12 days to complete, B only do 15 days to complete. A work 4 days, B work 3 days, completed the project8. dissolve 10 grams of salt in (grams) of water, so that the salt content of the brine is 5%.NineTenFour, Jane (B. 3 points each computation. A total of 6 points)OneTwoFive, calculation (first items 2, second A. 3 3-5, each of 4 points, a total of 17 points)OneTwoThreeFourFiveSix, text title (4 points each day a total of 16 points)OneTwoThreeFourSeven, 4 points (first A. application questions,2-4 5 points for each item, 5-6 for each item, 6 points for 31 points1., Xinhua steel plant last year produced 2 million 700 thousand tons of steel, more than planned production of 300 thousand tons, the actual production of more than the plan, a few percent?2., a project, if you do alone, a team to use 12 days, B team to use 10 days, team C will use 15 days. Now a team did 3 days later, the remaining B, C, the two teams do, it still takes a few days to complete the task?3., a workshop to produce a batch of parts, 4 hours produced 40% of these parts, according to this calculation, 2.5 hours can produce 30, how many of these parts?4., a factory has two workshops, the first workshop accounted for 65% of the total number of the factory, if from the first workshop to 24 to second workshop, then the number of two workshops on the same, the original first workshop how many people?5. according to the conditions, the algorithm is calculated and the result is calculatedB two road team, a team of 4.8 km road, ________, team B repaired many kilometers? Reference: it can add someAnswer: cowboy001win | four | 2009-12-13 16:48Mathematics is by understanding, by your head, by the back, not by mathematics!! There are junior high school physics, do not go back, to understand!!! Answer: you Guo 12 | level |2009-12-13 20:24Mathematics is good, but the book is not necessary before examination!!!!!!!I'm a math teacher!!!!!!!!! Answer: LZ152 | level | 2009-12-14 21:00(*_*) 1 copies of each number x = totalThe total number of copies per =.The total number of copies of each number =.21 multiples * multiples = multiplesA few times, 1 times times =A few times, ratio = 1 times3 speed x time = distanceDistance / speed = timeTime = distance / speed4 unit price = quantity = total pricePrice / price = numberThe total number of 83019 = price5 work efficiency * working hours = work amountThe total amount of work, work efficiency = working time The total amount of work, work time = work efficiency6 addend addend = + andAnd a = other addend addend7 - meiosis difference = minuendMinuend - difference = meiosisPoor + = subtrahend minuend8 factor X factor = productProduct, a factor = another factor9 dividend, divisor = BusinessDividend, divisor = BusinessQuotient * divisor = divisorMathematical formulas for elementary school mathematics1 squaresC perimeter, S area, a side lengthCircumference = side length * 4C=4aArea = side length * side lengthS=a * a2.V: volume a: edge lengthSurface = edge length x x x * 6S table =a x a * 6Volume = edge length x edge long x edge lengthV=a * a * a3 rectangleC perimeter, S area, a side lengthCircumference = (length + width) * 2C=2 (a+b)Area = length * widthS=ab4 cuboidV: volume s:, area a: long, b: width, h: height(1) surface area (length * width + length * height + width * height) * 2S=2 (ab+ah+bh)(2) volume = * * width * heightV=abh5 triangleS area a, bottom h highBottom area = x height / 2S=ah / 2Triangle area high = x 2 / bottomTriangle area = x 2 / high6 parallelogramS area a, bottom h highArea = base * heightS=ah7 trapezoidS area a, bottom B, bottom h highArea = (+ down on the bottom end) * / 2S= (a+b) * H / 28 roundS C - d= r= diameter, perimeter area radius (1) = =2 * * * perimeter diameter pi * radius C= II d=2 II R(2) * * * area = radius radius9 cylinderV: volume h: high S; bottom area r:; base radius c:; bottom perimeter(1) the side area = the circumference of the bottom * high(2) surface area = side area + base area * 2(3) volume = base area * height(4) = 2 / X volume side area radius10 coneV: volume h:, high S; base area r:, bottom radiusVolume = bottom area x height / 3The total, the total number of copies = average numberEquation of sum and difference(+ and difference) 83019 2 = number(and poor) 83019 2 = decimalDoubling problemAnd (1 = decimal multiples).Decimal = multiple = large number(or sum = decimal = large number)Difference problem(1 / difference multiples) = decimalDecimal = multiple = large number(or decimal + difference = large number)Tree planting problem1, the problem of tree planting on non closed lines can be divided into the following three cases:If a non closed line at both ends are planting trees, so:Number = number of + 1 / 1 = length spacing* (1 = length spacing number)Full length (1 / spacing = number)If you want to plant trees in the end of non closed line, the other end is not planting, so:Number = number = length / spacingLength = x number of rows= length / number of rowsIf both ends in non closed line are not planting trees, so:Number section number = - 1 / 1 = length spacing* (number = length spacing + 1)= length / spacing (number 1)2 the number of trees on closed lines is as followsNumber = number = length / spacingLength = x number of rows= length / number of rowsProfit and loss(profit + loss), the two distribution of the difference between the number of copies in the distribution of =(large surplus - small surplus) / two distribution of the difference between the number of copies in the distribution of =(burned - a small loss of two times), the difference between the number of copies is assigned to participate in thedistribution of theEncounter problemEncounter distance = speed and X meeting timeMeet time = distance / speed and meetThe speed and distance, the encounter time = meetCatch up with problemsTracking distance = speed difference * tracking timeChase and chase and distance / time = speed differenceThe speed difference and distance = chase chase and time. Flow problemDownstream velocity = hydrostatic velocity + flow velocity Countercurrent velocity = hydrostatic velocity - flow velocity Hydrostatic speed = (downstream velocity and velocity), 2 Flow rate = (downstream speed velocity), 2Concentration problemThe weight of the solute + the weight of the solvent = the weightof the solutionThe weight, the weight of the solute solution x 100% = concentrationWeight of solution = concentration = solute weightThe weight, concentration of solute solution = weightProfit and discount problemsProfit = selling price - costThe rate of profit, profit = cost X 100% = (sold / cost 1) * 100%Amount of fluctuation = principal * Change PercentageThe actual price discount, the original price x = 100% (< 1 discount)Interest = principal * interest rate * timeAfter tax interest rates * * * = principal time (120%) answer: 71774614 | two | 2009-12-18 17:35Relevant content2011-1-6 PEP on the sixth grade math final review key and difficult point 42011-4-2 where did someone teach the final revision papers for grade six in primary school mathematics? Two2011-1-25 document: PEP primary school mathematics review lesson on the sixth grade2008-6-18 who can give me a primary school math PEP edition, grade six final review material 47?2009-8-2 primary school teaching mathematics knowledge points on the sixth grade 137More questions about the knowledge of the final revision of mathematics in grade sixSee the same subject: PEP, elementary school, math, grade sixWaiting for you to answer 0 answer 5 where Jiangsu GB the fourth grade mathematics teaching and the teaching postscript 0 answer 5 my notebook is ASUS, a work plan will continue to switch power supply mode of vibration, to answer what is the 5 1... Its bonus system? 0 answer 10 jijiaoban mathematics lesson of a practice on the sixth grade two unit ratio and the proportion of 2.3thanExample (Ninth pages) basis: 2 answer why Yunnan primary and secondary school teacher education technology ability training website studio can not enter? 0 answer 10, ask for advanced mathematics two teaching video, it is better to publish from Tongji University, from the first chapter to the last one...1 answer 5 students moderator speechWork plan 0 answer 15, who has employee training system to one, thank you! "More questions waiting for you to answer" is forwarded to: username:Cipher code:Remember my login statusLogin forgot passwordRegister Baidu account, surf the knowledge oceanBaidu to promote primary educationThe use of Baidu Hi, you can receive the first time "questions, new answers", "answer was adopted" "net friend for help" notice. View detailsWould you like to display your questions and answers on Baidu's "know" on your website? 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