上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末(中考一模)英语分类汇编：完形填空
上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末（一模）英语试题分类汇编完形填空上海市杨浦区2020-2021学年度第一学期九年级期末质量调研英语试题B.Choose the best answer and complete the passage.Shawn and his class were working on a new assignment. They were writing persuasive（劝说的）articles. When Shaw first learned about the assignment, he was 65 . Shawn disliked writing articles, and he wasn’t sure how to go about planning and writing a powerful article that would persuade someone to do something. So he asked Mr. Matthews for extra help planning his article.Mr. Matthews suggested that Shawn begin by selecting a 66 that wasimportant to him. Shawn wanted to be on the football team, so he decided towrite a paper explaining why he should be on the team. 67 , Mr. Matthewssuggested that Shawn list the strongest and best reasons that would persuadepeople. When Shawn had listed his reasons, he was ready to start writing.Shawn began with his main point—that he should be allowed to be on the football team. Then, he explained why he should be on the team, using the reasons he had listed. After that, he wrote the 68 -end of the paper. After Shawn had his draft（草稿）finished, he was ready to revise what he had written.Shawn read the paper to himself and to his parents. His mom and dad suggested ways and ideas that he could revise the paper to make his arguments stronger. Then, Shawn read the paper again. This time, he 69 a few ideas himself. After the revision was finished, it was time to edit.Shawn read the paper 70 to be certain that he had spelled everything the way it should be spelled. He also checked his paper for grammatical mistakes.The paper was written well enough that Mr. Matthews gave him a very good grade. The football coach read Shawn’s paper, too, and was so convinced by Shawn’s reasons tha t he permitted Shawn to work with the team!65. A. relaxed B. unhappy C. confident D. embarrassed66. A. hobby B. team C. topic D. character67. A. Next B. In addition C. However D. As a result68. A. plots B. details C. title D. conclusion69. A. reported B. thought of C. arranged D. focused on70. A. aloud B. properly C. carefully D. immediately答案：65-70 BCADBC上海市虹口区2021届九年级上学期期终学生学习能力诊断测试（一模）英语试题B. Choose the words or expressions and complete the passage.Arrest Report Sheet NAME OF SUSPECT（嫌疑犯）：Mr. John A. Berry65 FOR ARREST：Use of bad language in a public place.●Wasting a police officer’s time.●Damaging property and causing 66 to the public.●There was something I didn’t like about him.DETAILED REPORT OF THE EVENTS LEADING UP TO THE ARRESTThe suspect came into Mean Street Police Station at 4:37 p.m. on Wednesday, February 15th, claiming（声称）to have lost his car. Of course, this story did not satisfy a police officer like myself, and I 67 started to question the suspect. After about 45 minutes, he changed his story, claiming that the car had been stolen. Something about this story, too, 68 extremely unlikely and I refused to accept it.The suspect kept telling his story. Luckily, I took a useful and 69 training course last weekend. So I used the active questioning skills from the course to get the real truth out of him.When he finally 70 under my questioning, he admitted that he had parked his car in a no-parking zone, and then blown it up（爆炸）. I have not yet worked out why he did this; my theory is that he is a mentally ill terrorist who sees parking rules as a symbol of everything hehates most in modern society.SignedDetective—Inspector Philip E. Morris65. A. REASONS B. CAUSES C. SUGGESTIONS D. EXCUSES66. A. excitement B. surprise C. danger D. variety67. A. politely B. immediately C. suddenly D. correctly68. A. looked B. tasted C. felt D. sounded69. A. noisy B. boring C. comfortable D. enjoyable70. A. broke down B. woke up C. shut up D. calmed down答案：65-70ACADDA上海市宝山区2021届九年级上学期期末（一模）英语试题B.Choose the words or expressions to complete the passage.Most people hate change, which is sad since we often go throughchanges in life. And for some of us, even the Smallest changes can upsetour day. So, the question is: Why do most of us find making adjustments（调整）to our lives so hard?Why we dislike changeFear of change is 75 new. Over a century ago, people in Paris were unhappy over an unusual addition to their city: the Eiffel Tower. In fact, the citizens were so angry about the plans for the tower that they were against its construction（建造）. As strange as it may seem, their anger was completely 76 . They were given no choice about the huge change that was going to be made, so they became angry. But we get upset over changes even when we do have to a say in the matter. Changes are brought about every day by the decisions we make: which school to attend, which job to take. V oluntary（出于自愿的）changes also make most of us uneasy because we don’t know how those changes will 77 our future.How we can overcome our fear of changePeople have discovered that the key to overcoming the fear of change is to be flexible. Whenpeople are flexible, they can 78 new situations more easily. Being flexible is especially important in the 21st century as technology makes change occur faster than ever before. Those who were against change, especially with technology in the workplace, may end up finding themselves out of a job.When change comes, and you have no choice but to 79 it. A positive（积极的）attitude helps a lot. In fact, the change may turn out to be the best thing for you. That new job you got may end up being much better than your old one. You may make the best friends of your life in the new city you moved to. 80 , don’t just focus on how you feel about change. You should learn to accept the change. The change is the reality and it’s up to you to decide whether the change will bea success or a failure. You never know—your next change may be your life’s Eiffel Tower!75. A. something B. anything C. everything D. nothing76. A. important B. natural C. unusual D. ordinary77. A. assist B. reward C. affect D. arrange78. A. be aware of B. get used to C. be interested in D. get rid of79. A. forget B. make C. face D. refuse80. A. However B. What’s more C. Besides D. Therefore答案：75-80DBCBCD上海市普陀区2021届九年级上学期质量调研（一模）英语试题B. Choose the best answer and complete the passage （选择最恰当的选项完成短文）（12分）If you live on the streets with little food and money, what will you do with a bag filled with snacks and nearly￡500 in cash in front of you? To most people. it would be a source of temptation（诱惑）Something that happened last month has made the actions of the homeless Roy Kaufman out of the ordinary.Roy saw a 65 on the front seat inside a parked car with its window down. He stood guard in the rain for along time waiting for the owner to_66 . Because of the coldness, he reached inside and pulled the bag out. He hoped to find some cards with its owner's name or phone numbers so that he could 67_ the driver. But he only discovered it contained some bars of chocolates and ￡435 in notes, with another￡50 in spare change beside it.He then took it to a nearby police station after leaving a note behind to let the owner know it was 68 . When the car's owner Mr. Anderson returned to the car, he was shocked to find two policemen standing next to it and he was told what Roy Kaufman did.Mr. Anderson was later able to thank Mr. Smith for his _69_ and said, "I couldn't believe that the man never took a penny. The man has nothing and yet he didn't take the money for himself. He thought about others instead of himself. It's unbelievable. It just proves there are _70_ men out there. "Roy Kaufman's act drew much of the public's attention. He also won praise from social media users after Mr. Anderson posted about the story onFacebook.Now Mr. Anderson has set up an organization to raise money for other homeless people in the area. For Roy Kaufman, this is a possible life-changing chance. The story once again ells us that one good turn deserves another.65. A) report B) bag C) list D) symbol66. A) apologize B) drop C) investigate D) return67. A) contact B) reward C) refuse D) greet68. A) strange B) lost C) safe D) empty69. A) encouragement B) support C) kindness D) opinion70. A) generous B) honest C) poor D) polite答案：65 B 66 D 67 A 68 C 69 C 70 B松江区2020学年度九年级第一学期英语期末试卷B. Choose the best words and complete the passage（选择最恰当的单词完成短文）（12分）Amy and Susan both live an average life. They have an average house, an average job and an average family. There is really nothing _75_ about their lives, but there is also nothing really negative （负面的）about their lives.However, when they are both happy, it always seems that Amy is happier than Susan. It looks like nothing can _76_ Amy. She is the life of the party and always has a big smile on her face.Susan can't stop thinking about this. How is Amy so happy when they both lead such _77_lives? They go to the same stores, watch the same movies, and even have the same schedules! How can Amy be so carefree when life is so stressful?Between one's daily life and personal dreams, there is no way one can be so happy and stress free all the time. There are always a million things going on.But when Susan asks Amy about this, Amy says, "I just take life as it comes. It seems pretty easy then. "So what is the _78_ between these two friends? How is it that Amy's life seems so much better most of the time?The problem with Susan is that she spreads herself too thin（试图同时干太多的工作）. Not _79_, but in her own head. But although Amy tries to do everything at once and think about everything at once, she takes everything one step _80_. She is where she is, stays present in the moment and allows herself to focus on just one thing.When you live each moment to its fullest, when you deal with where you are and are present in the now, most of your stress will go away.75. A) boring B) common C) special D) disappointing76. A) attract B) trouble C) change D) encourage77. A) similar B)successful C) traditional D)wonderful78. A) link B)relationship C) contact D)difference79. A)physically B) rarely C) correctly D) suddenly80. A) on time B)for the time being C) at a time D) from time to time。
上海杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末(中考一模)英语试题分类汇编：选词填空
上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末（一模）英语试题分类汇编选词填空上海市杨浦区2020-2021学年度第一学期九年级期末质量调研英语试题Ⅲ. Complete the following passage with the words or phrases in the box. Each can only be used once.（A）A. majorB. processC. produceD. inventionE. as well asChinese animation has a history of over 80 years, starting with the “Wan Brothers” who started to 36 Chinese cartoon films in the1920s in many kinds of categories, such as puppet, paper-cut and so on.Ink-wash animation is a 37 part of it. When it first appeared in the 1960s, it was a breakthrough in the form of expression and aesthetic（美学的）conception in animated area. Two ink-wash films called “Tadpoles Searching for Mother” and “Cowherd’s Flute,”，with Te Wei as art director and Qian Jiajun as technical director developed a high reputation both at home and abroad.The former received the Best Animated Film Prize at the First Hundred Flower Awards38 winning five international prizes, while “Cowherd’s Flute” was awarded the Golden Prize at the Odense International Fairy Tale Film Festival in Denmark. People called ink-wash animation the “fifth Chinese 39 .”（B）A. rolesB. amazingC. amusingD. exploringE. influencedBut even before the birth of Tadpoles Scarching for Mother,another Chinese animated feature film called Uproar in Heavenhad started 40 a connection between Chinese traditional painting and animation. The two-hour- long film mixed five different colors in its 41 , which included the Monkey King and the Jade Emperor. It was considered an ideal combination of Disney-style films and Chinese traditional arts.Japanese Cartoonist Osamu Tezuka, the “Godfather of Anime”. Said he was greatly 42 by Chinese ink- wash animation. Another Japanese anime artist also commented, sa ying. “It is unbelievable that ink-wash pictures could move like films. It’s 43 !”答案：36-39 CAED 40-43 DAEB上海市虹口区2021届九年级上学期期终学生学习能力诊断测试（一模）英语试题Ⅲ. Complete the following passage with the words or phrases in the box. Each word or phrase can only be used once.On October 30, 2019, 3M announced the results of its 2019 Young Scientist Challenge. 14-year-old Kara Fan’s spray-on bandage（喷雾绑带）beat out several other creative 36 to some of the wor ld’s biggest problems.The contest, which is run by 3M and Discovery Education, is open to students in grades 5-8. Hundreds of kids sent in ideas 37 . In June 2019, 10 finalists were chosen 38 their knowledge and 39 to share their idea clearly.The finalists were matched with a scientist. Students were given several months to improve their projects with the help and advice of these scientists.In October 2019, the finalists 40 met their scientists and other students face to face at 3M’s special science center in St. Paul, Minnesota. The students 41 their views in the group, and the winners were announced.Kara Fan from California won the big 42 for a special liquid bandage she created. It can be sprayed on cuts and 43 . One important part of Kara’s bandage is nano -silver（纳米银）--silver in extremely any form. Kara had to do a lot of research to get that part just right. For winning, Kara got $25,000.答案：36. D 37. A 38. E 39. C40. B 41. D 42. A 43. E上海市宝山区2021届九年级上学期期末（一模）英语试题Ⅲ. Complete the following passage with the words or phrases in the box. Each one can only be used once.A. gainedB. charactersC. rulesD. adventuresE. madeComic books are an unusual kind of storybook. They tell a story using only pictures and speech bubbles or captions. The 46 of these stories are usually superheroeswith special abilities.The Spider-Man comic books follow the 47 of a young man named Peter Parker. Peter’s parents died when he was very young. Peter accidentally 48 his spider-like abilities when he was 15. After that, Peter 49 many clever tools himself, such as his web-shooters. He uses his skills to fight evil enemies. Peter is very different when he is Spider-Man—He becomes strong and brave.A. exceptB. alsoC. femaleD. because ofE. besidesBatman is one of the world’s first superheroes. He wears special costume to make him look like a bat. He 50 has many clever tools to help him fight against his enemies. Batman has a friend named Robin who always helps Batman when he is in danger. Very few people know who Batman really is 51 Robin.Storm is the name of a 52 superhero from the X-man comic books. The X-men are born with superhero abilities. They team together to fight their enemies. Storm got her name 53 her special ability to control the weather.答案：46-49 BDAE 50-53BACD上海市普陀区2021届九年级上学期质量调研（一模）英语试题II. Complete the following passages with the words in the box. Each can only be used once （将下列单词填入空格。
上海市杨浦区2021-2022学年九年级(上)期末数学试卷(一模)及答案解析
2021-2022学年上海市杨浦区九年级（上）期末数学试卷（一模）一、选择题：（本大题共6题，每题4分，满分24分）1．（4分）将函数y＝ax2+bx+c（a≠0）的图象向下平移2个单位，下列结论中，正确的是（）A．开口方向不变B．顶点不变C．与x轴的交点不变D．与y轴的交点不变2．（4分）在Rt△ABC中，∠C＝90°，如果∠A＝α，AC＝1，那么AB等于（）A．sinαB．cosαC．D．3．（4分）已知和都是单位向量，下列结论中，正确的是（）A．＝B．﹣＝C．||+||＝2D．+＝2 4．（4分）已知点P是线段AB上的一点，线段AP是PB和AB的比例中项，下列结论中，正确的是（）A．B．C．D．5．（4分）如图，在梯形ABCD中，AD∥BC，过对角线交点O的直线与两底分别交于点E、F，下列结论中，错误的是（）A．B．C．D．6．（4分）如图，点F是△ABC的角平分线AG的中点，点D、E分别在AB、AC边上，线段DE过点F，且∠ADE＝∠C，下列结论中，错误的是（）A．B．C．D．二、填空题：（本大题共12题，每题4分，满分48分）7．（4分）已知＝，那么＝．8．（4分）计算：cos245°﹣tan30°sin60°＝．9．（4分）抛物线y＝x2+3与y轴的交点坐标为．10．（4分）二次函数y＝x2﹣4x图象上的最低点的纵坐标为．11．（4分）已知的长度为2，的长度为4，且和方向相反，用向量表示向量＝．12．（4分）如果两个相似三角形对应边之比是4：9，那么它们的周长之比等于．13．（4分）已知在△ABC中，AB＝10，BC＝16，∠B＝60°，那么AC＝．14．（4分）已知在△ABC中，∠C＝90°，AC＝8，BC＝6，点G是△ABC的重心，那么点G到斜边AB的距离是．15．（4分）在某一时刻，直立地面的一根竹竿的影长为3米，一根旗杆的影长为25米，已知这根竹竿的长度为1.8米，那么这根旗杆的高度为米．16．（4分）如图，海中有一个小岛A，一艘轮船由西向东航行，在点B处测得小岛A在它的北偏东60°方向上，航行12海里到达点C处，测得小岛A在它的北偏东30°方向上，那么小岛A到航线BC的距离等于海里．17．（4分）新定义：已知三条平行直线，相邻两条平行线间的距离相等，我们把三个顶点分别在这样的三条平行线上的三角形称为格线三角形．如图，已知等腰Rt△ABC为“格线三角形”，且∠BAC＝90°，那么直线BC与直线c的夹角α的余切值为．18．（4分）如图，已知在Rt△ABC中，∠C＝90°，tan A＝，将△ABC绕点A逆时针旋转90°后得△ADE，点B落在点D处，点C落在点E处，联结BE、CD，作∠CAD的平分线AN，交线段BE于点M，交线段CD于点N，那么的值为．三、解答题：（本大题共7题，满分78分）19．（10分）如图，已知在△ABC中，点D、E分别在边AB、AC上，DE∥BC，且DE＝BC．（1）如果AC＝6，求AE的长；（2）设＝，＝，试用、的线性组合表示向量．20．（10分）已知二次函数y＝2x2﹣4x+5．（1）用配方法把二次函数y＝2x2﹣4x+5化为y＝a（x+m）2+k的形式，并指出这个函数图象的开口方向、对称轴和顶点坐标；（2）如果将该函数图象沿y轴向下平移5个单位，所得新抛物线与x轴正半轴交于点A，与y轴交于点B，顶点为C，求△ABC的面积．21．（10分）如图，已知在△ABC中，CD⊥AB，垂足为点D，AD＝2，BD＝6，tan∠B＝，点E是边BC的中点．（1）求边AC的长；（2）求∠EAB的正弦值．22．（10分）如图，为了测量建筑物AB的高度，先从与建筑物AB的底部B点水平相距100米的点C处出发，沿斜坡CD行走至坡顶D处，斜坡CD的坡度i＝1：3，坡顶D到BC 的距离DE＝20米，在点D处测得建筑物顶端A点的仰角为50°，点A、B、C、D、E 在同一平面内，根据测量数据，请计算建筑物AB的高度（结果精确到1米）（参考数据：sin50°≈0.77；cos50°≈0.64；tan50°≈1.19）23．（12分）已知，如图，在四边形ABCD中，∠ABC＝∠BCD，点E在边BC上，AE∥CD，DE∥AB，过点C作CF∥AD，交线段AE于点F，联结BF．（1）求证：△ABF≌△EAD；（2）如果射线BF经过点D，求证：BE2＝EC•BC．24．（12分）已知在平面直角坐标系xOy中，抛物线y＝﹣x2+bx+c与x轴交于点A（﹣1，0）和点B，与y轴交于点C（0，2），点P是该抛物线在第一象限内一点，联结AP、BC，AP与线段BC相交于点F．（1）求抛物线的表达式；（2）设抛物线的对称轴与线段BC交于点E，如果点F与点E重合，求点P的坐标；（3）过点P作PG⊥x轴，垂足为点G，PG与线段BC交于点H，如果PF＝PH，求线段PH的长度．25．（14分）如图，已知在Rt△ABC中，∠ACB＝90°，AC＝BC＝5，点D为射线AB上一动点，且BD＜AD，点B关于直线CD的对称点为点E，射线AE与射线CD交于点F．（1）当点D在边AB上时，①求证：∠AFC＝45°；②延长AF与边CB的延长线相交于点G，如果△EBG与△BDC相似，求线段BD的长；＝12，求S△ABE的值．（2）联结CE、BE，如果S△ACE2021-2022学年上海市杨浦区九年级（上）期末数学试卷（一模）参考答案与试题解析一、选择题：（本大题共6题，每题4分，满分24分）1．【分析】由于抛物线平移后的形状不变，对称轴不变，a不变，抛物线的增减性不变．【解答】解：A、将函数y＝ax2+bx+c（a≠0）的图象向下平移2个单位，a不变，开口方向不变，故正确．B、将函数y＝ax2+bx+c（a≠0）的图象向下平移2个单位，顶点的横坐标不变，纵坐标改变，故错误；C、将函数y＝ax2+bx+c（a≠0）的图象向下平移2个单位，形状不变，顶点改变，与x轴的交点改变，故错误．D、将函数y＝ax2+bx+c（a≠0）的图象向下平移2个单位，与y轴的交点也向下平移两个单位，故错误．故选：A．【点评】本题主要考查了二次函数图象与几何变换，二次函数的性质，注意：抛物线平移后的形状不变，开口方向不变，顶点坐标改变．2．【分析】在Rt△ABC中，根据∠A的余弦即可解答．【解答】解：在Rt△ABC中，∠C＝90°，如果∠A＝α，AC＝1，那么：cos A＝＝，∴AB＝，故选：D．【点评】本题考查了锐角三角函数的定义，熟练掌握正弦，余弦和正切的区别是解题的关键．3．【分析】根据单位向量的定义逐一判断即可．【解答】解：根据单位向量的定义可知：和都是单位向量，但是这两个向量并没有明确方向，∴A，B，D错误，C正确，故选：C．【点评】本题考查了平面向量中的单位向量知识，熟练掌握单位向量的定义是解题的关键．4．【分析】根据黄金分割的定义判断即可．【解答】解：∵点P是线段AB上的一点，线段AP是PB和AB的比例中项，∴AP2＝PB•AB，∴点P是AB的黄金分割点，∴＝，故选：C．【点评】本题考查了黄金分割，熟练掌握黄金分割的定义，找出黄金分割中成比例的对应线段是解题的关键．5．【分析】根据相似三角形的判定得出△AOE∽△COF，△DEO∽△BFO，△AOD∽△COB，再根据相似三角形的性质得出比例式，最后根据比例的性质得出即可．【解答】解：A．∵AD∥BC，∴△AOE∽△COF，∴＝，故本选项不符合题意；B．∵AD∥BC，∴△AOE∽△COF，△DEO∽△BFO，∴＝，＝，∴＝，∴＝，故本选项符合题意；C．∵AD∥BC，∴△AOE∽△COF，△AOD∽△COB，∴＝，＝，∴＝，故本选项不符合题意；D．∵AD∥BC，∴△DEO∽△BFO，△AOD∽△COB，∴＝，＝，∴＝，∴＝，故本选项不符合题意；故选：B．【点评】本题考查了相似三角形的性质和判定，平行线分线段成比例定理和比例的性质等知识点，能熟记相似三角形的性质定理和判定定理是解此题的关键．6．【分析】通过证明△EAF∽△BAG，可得＝，通过证明△ADF∽△ACG，可得，即可求解．【解答】解：∵AG平分∠BAC，∴∠BAG＝∠CAG，∵点F是AG的中点，∴AF＝FG＝，∵∠ADE＝∠C，∠DAE＝∠BAC，∴△DAE∽△CAB，∴∠AEB＝∠B，又∵∠BAG＝∠CAG，∴△EAF∽△BAG，∴＝，∵∠ADE＝∠C，∠BAG＝∠CAG，∴△ADF∽△ACG，∴，故选：D．【点评】本题考查了相似三角形的判定和性质，掌握相似三角形的判定方法是解题的关键．二、填空题：（本大题共12题，每题4分，满分48分）7．【分析】利用设k法解答即可．【解答】解：∵＝，∴设x＝4k，y＝3k，∴＝＝＝，故答案为：．【点评】本题考查了比例的性质，熟练掌握设k法是解题的关键．8．【分析】原式利用特殊角的三角函数值计算即可得到结果．【解答】解：cos245°﹣tan30°sin60°＝﹣×＝﹣＝0，故答案为：0．【点评】此题考查了特殊角的三角函数值，实数的运算，熟练掌握运算法则是解本题的关键．9．【分析】把x＝0代入解析式求出y，根据y轴上点的坐标特征解答即可．【解答】解：当x＝0时，y＝3，则抛物线y＝x2+3与y轴交点的坐标为（0，3），故答案为：（0，3）【点评】本题考查的是二次函数图象上点的坐标特征，掌握y轴上点的横坐标为0是解题的关键．10．【分析】将二次函数解析式化为顶点式求解．【解答】解：∵y＝x2﹣4x＝（x﹣2）2﹣4，∴抛物线最低点坐标为﹣4．故答案为﹣4．【点评】本题考查二次函数的性质，解题关键是熟练掌握二次函数一般式与顶点式的转化．11．【分析】根据与的长度与方向即可得出结果．【解答】解：∵的长度为2，的长度为4，且和方向相反，∴，故答案为：﹣2【点评】本题考查了平面向量的基本知识，熟练掌握平面向量的定义和性质是解题的关键．12．【分析】根据相似三角形的性质得出即可．【解答】解：∵两个相似三角形对应边之比是4：9，∴它们的周长之比等于4：9，故答案为：4：9．【点评】本题考查了相似三角形的性质，能熟记相似三角形的周长之比等于相似比是解此题的关键．13．【分析】过A作AD⊥BC于D，解直角三角形求出BD和AD，求出CD，再根据勾股定理求出AC即可．【解答】解：过A作AD⊥BC于D，则∠ADB＝∠ADC＝90°，∵∠B＝60°，∴sin60°＝，cos60°＝，∵AB＝10，∴＝，＝，∴BD＝5，AD＝5，∵BC＝16，BD＝5，∴CD＝BC﹣BD＝11，由勾股定理得：AC＝＝＝14，故答案为：14．【点评】本题考查了解直角三角形和勾股定理，能熟记锐角三角形函数的定义和勾股定理解此题的关键．14．【分析】过C点作CE⊥AB于E，过G点作GH⊥AB于H，如图，先利用勾股定理计算出AB，再利用面积法求出CE＝，根据G是△ABC的重心得到DG＝CD，然后证明△DHG∽△DEC，利用相似比可求出GH的长度．【解答】解：过C点作CE⊥AB于E，过G点作GH⊥AB于H，如图．在Rt△ABC中，∠C＝90°，AC＝8，BC＝6，∴AB＝＝＝10，∵CE•AB＝AC•BC，∴CE＝＝，∵G是△ABC的重心，∴DG＝CG，∴DG＝CD，∵CE⊥AB，GH⊥AB，∴GH∥CE，∴△DHG∽△DEC，∴＝＝，∴GH＝CE＝×＝．故答案为：．【点评】此题考查了三角形重心的性质：三角形的重心到顶点的距离是它到对边中点的距离的2倍，也考查了勾股定理，三角形的面积，相似三角形的判定与性质．15．【分析】根据同一时刻，物高与影长成正比即可列出等式．【解答】解：根据同一时刻，物高与影长成正比得，旗杆的高度：1.8＝25：3，∴旗杆的高度为15米，故答案为：15．【点评】本题主要考查了相似三角形的应用，熟练掌握平行投影的基本特征：物高与影长成正比是解题的关键．16．【分析】过点A作AE⊥BC交BC的延长线于点E，由三角形的外角性质得∠BAC＝∠ABC，再由等腰三角形的判定得AC＝BC，锐角由锐角三角函数定义求出AE的长即可．【解答】解：过点A作AE⊥BC交BC的延长线于点E，由题意得：BC＝12海里，∠ABC＝90°﹣60°＝30°，∠ACE＝90°﹣30°＝60°，∴∠BAC＝∠ACE﹣∠ABC＝30°，∴∠BAC＝∠ABC，∴AC＝BC＝12海里，在Rt△ACE中，sin∠ACE＝，∴AE＝AC•sin∠ACE＝12×＝6（海里），即小岛A到航线BC的距离是6海里，故答案为：6．【点评】本题考查的是解直角三角形的应用﹣方向角问题，掌握方向角的概念，正确作出辅助线构造直角三角形是解题的关键．17．【分析】过B作BE⊥直线a于E，延长EB交直线c于F，过C作CD⊥直线a于D，根据全等三角形的判定得出△CDA≌△AEB，根据全等三角形的性质得出AE＝CD＝2d，AD＝BE＝d，求出CF＝DE＝AE+AD＝3d，再解直角三角形求出答案即可．【解答】解：过B作BE⊥直线a于E，延长EB交直线c于F，过C作CD⊥直线a于D，则∠CDA＝∠AEB＝90°，∵直线a∥直线b∥直线c，相邻两条平行线间的距离相等（设为d），∴BF⊥直线c，CD＝2d，∴BE＝BF＝d，∵∠CAB＝90°，∠CDA＝90°，∴∠DCA+∠DAC＝90°，∠EAB+∠DAC＝90°，∴∠DCA＝∠EAB，在△CDA和△AEB中，，∴△CDA≌△AEB（AAS），∴AE＝CD＝2d，AD＝BE＝d，∴CF＝DE＝AE+AD＝2d+d＝3d，∵BF＝d，∴cotα＝＝＝3，故答案为：3．【点评】本题考查了解直角三角形，等腰直角三角形的性质，全等三角形的性质和判定，平行线间的距离等知识点，能正确作出辅助线是解此题的关键．18．【分析】先根据题目条件作出图象，由∠C＝90°和tan A＝设BC＝5k，AC＝12k，然后由旋转的性质得到AE＝AC＝12k，ED＝BC＝5k，AB＝AD＝13k，以点C为原点、BC 和AC所在直线分别为x轴和y轴建立平面直角坐标系，则A（0，12k），B（﹣5k，0），E（12k，12k），D（12k，7k），过点N作NF⊥AC于点F，交BE于点P，NH⊥AD于点H，得到NF＝NH，得到＝＝，然后由高相等的两个三角形的面积之比为底边长之比得到的值，进而用含有k的式子表示点N的坐标，再求得直线BE的解析式，然后求得点P的坐标得到NP的长，最后通过△MAE∽△MNP得到的值，即可得到的值．【解答】解：由∠C＝90°和tan A＝可设BC＝5k，AC＝12k，∴AB＝13k，由旋转得，AE＝AC＝12k，ED＝BC＝5k，AB＝AD＝13k，如图，以点C为原点，BC和AC所在直线分别为x轴和y轴，建立平面直角坐标系，则A（0，12k），B（﹣5k，0），∵旋转角为90°，∴E（12k，12k），D（12k，7k），过点N作NF⊥AC于点F，NH⊥AD于点H，∵AN平分∠CAD，∴NF＝NH，∴＝＝，又∵△ANC在边CN上的高和△AND在边DN上的高相等，∴＝＝，∴点N的坐标为（，），设直线BE的解析式为y＝mx+n，则，解得：，∴直线BE的解析式为y＝x+，当y＝时，x+＝，解得：x＝﹣，∴P（﹣，），∴NP＝﹣（﹣）＝6k，∵NF⊥AC，∠EAC＝90°，∴AE∥NP，∴△MAF∽△MNP，∴＝2，∴＝，故答案为：．【点评】本题考查了旋转的性质、勾股定理、相似三角形的判定与性质、角平分线的性质定理、三角形的面积，解题的关键是通过旋转的性质建立平面直角坐标系．三、解答题：（本大题共7题，满分78分）19．【分析】（1）根据相似三角形的性质得出等式求解即可；（2）根据平面向量的加减运算法则即可求解．【解答】解：（1）∵DE∥BC，∴△ADE∽△ABC，∴，∵DE＝，∴AE＝4；（2）由（1）知，，∴DE＝，∵，∴＝．【点评】本题考查了平面向量，相似三角形的性质等知识，熟练掌握平面向量的加减运算法则是解题的关键．20．【分析】（1）利用配方法把一般式化为顶点式，根据二次函数的性质解答．（2）首先求得抛物线y＝2x2﹣4x+5沿y轴向下平移5个单位后解析式，利用配方法求得C的坐标，令y＝0求得A、B的坐标，然后根据三角形面积公式求解即可．【解答】解：（1）y＝2x2﹣4x+5＝2（x2﹣2x）+5＝2（x2﹣2x+1﹣1）+5＝2（x﹣1）2+3，∴开口向上，对称轴为直线x＝1，顶点（1，3）．（2）抛物线y＝2x2﹣4x+5沿y轴向下平移5个单位后解析式是y＝2x2﹣4x+5﹣5，即y ＝2x2﹣4x．∵y＝2x2﹣4x＝2（x﹣1）2﹣2，∴顶点C的坐标是（1，﹣2）．在y＝2x2﹣4x中令y＝0，则2x2﹣4x＝0，解得x＝0或2，∴A（2，0），B（0，0），∴△ABC的面积为：＝2．【点评】本题考查的是二次函数三种形式的转化，抛物线与x轴的交点，二次函数的图象与几何变换，三角形的面积，掌握配方法、平移的规律是解题的关键．21．【分析】（1）利用∠B的正切值先求出CD，再利用勾股定理求出AC；（2）过点E作EF⊥AB，垂足为F．先判断EF是三角形的中位线，再求出EF、DF、AF及AE，最后求出∠EAB的正弦值．【解答】解：（1）∵CD⊥AB，∴△ACD、△BCD均为直角三角形．在Rt△CDB中，∵BD＝6，tan∠B＝＝，∴CD＝4．在Rt△CDA中，AC＝＝＝2．（2）过点E作EF⊥AB，垂足为F．∵CD⊥AB，EF⊥AB，∴CD∥EF．又∵点E是边BC的中点，∴EF是△BCD的中位线．∴DF＝BF＝3，EF＝CD＝2．∴AF＝AD+DF＝5．在Rt△AEF中，AE＝＝＝．∴sin∠EAB＝＝＝．【点评】本题主要考查了解直角三角形和勾股定理，掌握直角三角形的边角间关系以及三角形的中位线定理是解决本题的关键．22．【分析】过D作DF⊥AB于F，由坡度的定义求出CE＝3DE＝60（米），则DF＝EB＝40（米），再解直角三角形求出AF的长，即可得出答案【解答】解：过D作DF⊥AB于F，则DF＝EB，FB＝DE＝20米，∵斜坡CD的坡度i＝1：3＝DE：CE，坡顶D到BC的距离DE＝20米，∴CE＝3DE＝60（米），∴DF＝EB＝BC﹣CE＝100﹣60＝40（米），在Rt△ADF中，∠ADF＝50°，∵tan∠ADF＝＝tan50°≈1.19，∴AF≈1.19DF＝1.19×40＝47.6（米），∴AB＝AF+BF≈47.6+20≈68（米），即建筑物AB的高度约为68米．【点评】本题考查了解直角三角形的应用—仰角俯角问题、坡度坡角问题，正确作出辅助线构造直角三角形是解题的关键．23．【分析】（1）先证AB＝AE，DE＝DC，再证四边形ADCF是平行四边形，得出AF＝CD，进而得出AF＝DE，再由平行线性质得∠AED＝∠BAF，进而证得结论；（2）通过证明△BEF∽△BCD，△DEF∽△BAF，可得，即可得结论．【解答】证明：（1）∵AE∥CD，∴∠AEB＝∠BCD，∵∠ABC＝∠BCD，∴∠ABC＝∠AEB，∴AB＝AE，∵DE∥AB，∴∠DEC＝∠ABC，∠AED＝∠BAF，∵∠ABC＝∠BCD，∴∠DEC＝∠BCD，∴DE＝DC，∵CF∥AD，AE∥CD，∴四边形ADCF是平行四边形，∴AF＝CD，∴AF＝DE，在△ABF和△EAD中，，∴△ABF≌△EAD（SAS）；（2）如图，连接FD，∵射线BF经过点D，∴点B，点F，点D三点共线，∵AE∥DC，∴△BEF∽△BCD，∴，，∵DE∥AB，∴△DEF∽△BAF，∴，∴，∵CD＝AF，∴，∴BE2＝EC•BC．【点评】本题考查了相似三角形的判定和性质，全等三角形的判定和性质，平行四边形的判定和性质，利用相似三角形的性质得到线段的关系是解题的关键．24．【分析】（1）将点A（﹣1，0）和点C（0，2）代入y＝﹣x2+bx+c，即可求解；（2）分别求出B（4，0）和直线BC的解析式为y＝﹣x+2，可得E（，），再求直线AE的解析式为y＝x+，联立，即可求点P（3，2）；（3）设P（t，﹣t2+t+2），则H（t，﹣t+2），则PH＝﹣t2+2t，用待定系数法求出直线AP的解析式为y＝x+，联立，可求出F（，），直线AP与y轴交点E（0，），则CE＝，再由PF＝PH，可得CE＝EF，则有方程（）2＝（）2+（﹣）2，求出t＝，即可求PH＝﹣t2+2t＝．【解答】解：（1）将点A（﹣1，0）和点C（0，2）代入y＝﹣x2+bx+c，∴，∴，∴y＝﹣x2+x+2；（2）∵y＝﹣x2+x+2，∴对称轴为直线x＝，令y＝0，则﹣x2+x+2＝0，解得x＝﹣1或x＝4，∴B（4，0），设直线BC的解析式为y＝kx+m，∴，∴，∴y＝﹣x+2，∴E（，），设直线AE的解析式为y＝k'x+n，∴，∴，∴y＝x+，联立，∴x＝3或x＝﹣1（舍），∴P（3，2）；（3）设P（t，﹣t2+t+2），则H（t，﹣t+2），∴PH＝﹣t2+2t，设直线AP的解析式为y＝k1x+b1，∴，∴，∴y＝x+，联立，∴x＝，∴F（，），直线AP与y轴交点E（0，），∴CE＝2﹣＝，∵PF＝PH，∴∠PFH＝∠PHF，∵PG∥y轴，∴∠ECF＝∠PHF，∵∠CFE＝∠PFH，∴∠CEF＝∠CFE，∴CE＝EF，∴（）2＝（）2+（﹣）2，∴（4﹣t）2+4＝（5﹣t）2，∴t＝，∴PH＝﹣t2+2t＝．【点评】本题是二次函数的综合题，熟练掌握二次函数的图象及性质，会求函数的交点坐标，本题计算量较大，准确的计算是解题的关键．25．【分析】（1）①如图1，连接CE，根据轴对称的性质可得：EC＝BC，∠ECF＝∠BCF，设∠ECF＝∠BCF＝α，则∠BCE＝2α，∠ACE＝90°﹣2α，再利用等腰三角形性质即可证得结论；②如图2，连接BE，CE，由△EBG∽△BDC，可得出∠G＝∠BCD＝22.5°，过点D作DH⊥AB交BC于点H，则△BDH是等腰直角三角形，推出CH＝DH＝BD，再根据CH+BH ＝BC＝5，建立方程求解即可；（2）分两种情况：Ⅰ．当点D在AB上时，如图3，过点C作CM⊥AE于点M，连接BF，利用勾股定理、三角形面积建立方程求解即可；Ⅱ．当点D在AB的延长线上时，如图4，过点C作CM⊥AE于点M，连接BF，利用勾股定理、三角形面积建立方程求解即可．【解答】解：（1）①证明：如图1，连接CE，∵点B关于直线CD的对称点为点E，∴EC＝BC，∠ECF＝∠BCF，设∠ECF＝∠BCF＝α，则∠BCE＝2α，∴∠ACE＝90°﹣2α，∵AC＝BC，∴AC＝EC，∴∠AEC＝∠EAC＝[180°﹣（90°﹣2α）]＝45°+α，∵∠AEC＝∠AFC+∠ECF＝∠AFC+α，∴∠AFC＝45°；②如图2，连接BE，CE，∵B、E关于直线CF对称，∴CF垂直平分BE，由（1）知：∠AFC＝45°，∴∠BEF＝45°，∵△EBG与△BDC相似，∠BEG＝∠DBC＝45°，∵∠EBG与∠BDC均为钝角，∴△EBG∽△BDC，∴∠G＝∠BCD＝∠BAG，∵∠G+∠BAG＝∠ABC＝45°，∴∠G＝∠BCD＝22.5°，过点D作DH⊥AB交BC于点H，则△BDH是等腰直角三角形，∴DH＝BD，BH＝BD，∠BHD＝45°，∵∠CDH＝∠BHD﹣∠BCD＝45°﹣22.5°＝22.5°＝∠BCD，∴CH＝DH＝BD，∵CH+BH＝BC＝5，∴BD+BD＝5，∴BD＝＝5﹣5，∴线段BD的长为5﹣5；（2）Ⅰ．当点D在AB上时，如图3，过点C作CM⊥AE于点M，连接BF，∵AC＝EC＝BC＝5，∴AM＝EM＝AE，∴①AM2+CM2＝AC2＝25，＝AE•CM＝12，∵S△ACE∴②AM•CM＝12，①+②×2，得：（AM+CM）2＝49③，①﹣②×2，得：（AM﹣CM）2＝49③，∵CM＞AM＞0，∴AM＝3，CM＝4，∴AE＝6，由（1）知：∠AFC＝45°，BE⊥CF，∴∠BEF＝45°，∵∠AFC＝∠ABC＝45°，∴A、C、B、F四点共圆，∴∠AFB+∠ACB＝180°，∴∠AFB＝90°，∴△BEF是等腰直角三角形，∴EF＝BF，设EF＝BF＝x，则AE＝x+6，在Rt△ABF中，AF2+BF2＝AB2，∴（x+6）2+x2＝50，解得：x＝1或x＝﹣7（舍去），∴BF＝1，＝AE•BF＝×6×1＝3；∴S△ABEⅡ．当点D在AB的延长线上时，如图4，过点C作CM⊥AE于点M，连接BF，由（1）知：∠AFC＝45°，CF垂直平分BE，∴∠BEF＝45°，BF＝EF，∴∠EBF＝∠BEF＝45°，∴∠BFE＝90°，∵AC＝EC＝BC＝5，∴AM＝EM＝AE，与Ⅰ同理可得：AM＝EM＝4，CM＝3，AE＝8，设BF＝EF＝y，则AF＝8﹣y，在Rt△ABF中，AF2+BF2＝AB2，∴（8﹣x）2+x2＝50，解得：x＝1或x＝7（舍去），∴BF＝1，＝AE•BF＝×8×1＝4；∴S△ABE的值为3或4．综上，S△ABE【点评】本题考查了三角形面积，等腰直角三角形性质和判定，相似三角形的判定和性质，轴对称变换的性质，勾股定理等，解题关键是添加辅助线构造直角三角形，运用分类讨论思想和方程思想解决问题．。
2021年上海各区一模试卷汇总及分类汇编
2021年上海各区一模试卷汇总及分类汇编2021年上海各区试卷汇总及分类汇编按题型分类目录：一、各区试卷2-97页1普陀区2奉贤区3宝山区4松江区5杨浦区6崇明区7虹口区8黄浦区9嘉定区10.金山（长宁）11.静安区12.闵行区13.青浦区14.浦东区15.徐汇区二．分类汇编185.3-140.3-140.3-140.5-140.4-140.5-140.5-140.5-140.5-140.5-140.5-140.5-140.5-140.52021年普陀区初三一模语文试题（一）文言文（40分）（一）默写（15分）1.回顾雕刻，。
狩猎2、，一点飞鸿影下。
《天净沙秋》3、关河梦断何处，。
《诉衷情》4.没有敌人或外国入侵，这个国家将永远灭亡。
生在悲伤中，死在幸福中。
完整的沙欧收藏，。
“岳阳楼”（二）阅读下面的诗，完成第6-7题（4分）水仙吟唱江南一江烟水照晴岚，两岸人家接画檐，芰荷丛一段秋光淡。
看沙鸥舞再三，卷香风十里珠帘。
画船儿天边至，酒旗儿风外s。
爱杀江南！6、“晴岚”在文中的意思是。
（2分）7、下列理解错误的是（2分）a.这首小令描绘了江南水仙的美景。
b.“芰荷丛”营造了淡淡的秋之意。
c.江南人家身处秀丽之景生活富足。
d.最后一句以抒情结尾，直抒胸臆。
（三）阅读以下内容并完成问题8-10（9分）醉翁亭记（节选）滁州周围有山。
西南部的山峰、森林和山谷格外美丽。
那些看着它们的人是壮丽而深邃的，而琅琊也是美丽的。
上山六七英里，逐渐听到两座山峰之间的流水声，酝酿着春天。
峰回路转。
有亭子的翅膀，但那些面对春天的人也醉翁亭。
谁是亭子的制造者？山僧志贤也。
你叫谁？太寿自称。
太守和客人来这里喝酒。
他们饮酒较少，饮酒频繁，年龄最高。
因此，他们被称为醉翁。
酒鬼的意思不是酒，而是山河之间的酒。
山川之乐，心与酒。
8、文中“醉翁”即“唐宋八大家”之一的。
（2分）9、用现代汉语翻译下面句子。
那些有亭翼但面对春天的人也是醉翁亭。
上海市虹口区2021-2022学年九年级(上)期末数学试卷(一模)及答案解析
2021-2022学年上海市虹口区九年级（上）期末数学试卷（一模）一、选择题（本大题共6题，每题4分，满分24分）下列各题的四个选项中，有且只有一个选项是正确的，请选择正确项的代号并填入答题纸的相应位置。
1．（4分）下列选项中的两个图形一定相似的是（）A．两个等腰三角形B．两个矩形C．两个菱形D．两个正方形2．（4分）在Rt△ABC中，∠C＝90°，BC＝12，AC＝5，那么cot B等于（）A．B．C．D．3．（4分）已知＝7，下列说法中不正确的是（）A．﹣7＝0B．与方向相同C．∥D．||＝7||4．（4分）下列函数中，属于二次函数的是（）A．y＝B．y＝（x﹣l）2﹣x2C．y＝5x2D．y＝5．（4分）在△ABC中，点E、D、F分别在边AB、BC、AC上，联结DE、DF，如果DE ∥AC，DF∥AB，AE：EB＝3：2，那么AF：FC的值是（）A．B．C．D．6．（4分）如图所示，一座抛物线形的拱桥在正常水位时，水面AB宽为20米，拱桥的最高点O到水面AB的距离为4米．如果此时水位上升3米就达到警戒水位CD，那么CD宽为（）A．4米B．10米C．4米D．12米二、填空题（本大题共12题，每题4分，满分48分）请将结果直接填入答题纸的相应位置7．（4分）如果＝，那么＝．8．（4分）已知点P是线段AB的黄金分割点，AP＞PB．若AB＝2，则AP＝．9．（4分）如果向量、、满足（+）＝﹣，那么＝（用向量、表示）．10．（4分）二次函数y＝（m﹣1）x2+x+m2﹣1的图象经过原点，则m的值为．11．（4分）如果抛物线y＝（2﹣a）x2+2开口向下，那么a的取值范围是．12．（4分）如果抛物线过点（﹣2，3），且与y轴的交点是（0，3），那么抛物线的对称轴是直线．13．（4分）已知点A（x1，y1）、B（x2，y2）为函数y＝﹣2（x﹣1）2+3的图象上的两点，若x1＜x2＜0，则y1y2（填“＞”、“＝”或“＜”），14．（4分）如果一个斜坡的坡度i＝1：，那么该斜坡的坡角为度．15．（4分）已知Rt△ABC的两直角边之比为3：4，若△DEF与△ABC相似，且△DEF最长的边长为20，则△DEF的周长为．16．（4分）如图，过△ABC的重心G作上ED∥AB分别交边AC、BC于点E、D，联结AD，如果AD平分∠BAC，AB＝6，那么EC＝．17．（4分）在网格中，每个小正方形的顶点称为格点，以格点为顶点的三角形称为“格点三角形”．如图，在4×4的网格中，△ABC是一个格点三角形，如果△DEF也是该网格中的一个格点三角形，它与△ABC相似且面积最大，那么△DEF与△ABC相似比的值是．三、解答题（本大题共7题，满分78分）19．（10分）计算：．20．（10分）已知抛物线y＝ax2+bx+c（a≠0）上部分点的横坐标x与纵坐标y的对应值如下表：x…﹣2﹣1012…y…3430﹣5…（1）求该抛物线的表达式；（2）将抛物线y＝ax2+bx+c沿x轴向右平移m（m＞0）个单位，使得新抛物线经过原点O，求m的值以及新抛物线的表达式．21．（10分）如图，在平行四边形ABCD中，延长BC到点E，使CE＝BC，联结AE交DC 于点F，设＝，＝．（1）用向量、表示；（2）求作：向量分别在、方向上的分向量．（不要求写作法，但要写明结论）22．（10分）图1是一款平板电脑文架，由托板、支撑板和底座构成．工作时，可将平板电脑吸附在托板上，底座放置在桌面上．图2是其侧面结构示意图，已知托板AB长200mm，支撑板CB长80mm，当∠ABC＝130°，∠BCD＝70°时，求托板顶点A到底座CD所在平面的距离（结果精确到1mm）．（参考数据：sin70°≈0.94，cos70°≈0.34，tan70°≈2.75，≈1.41，≈1.73）．23．（12分）如图，在梯形ABCD中，∠ABC＝90°，AD∥BC，BC＝2AD，对角线AC与BD交于点E．点F是线段EC上一点，且∠BDF＝∠BAC．（1）求证：EB2＝EF•EC；（2）如果BC＝6，sin∠BAC＝，求FC的长．24．（12分）已知开口向上的抛物线y＝ax2﹣4ax+3与y轴的交点为A，顶点为B，点A与点C关于对称轴对称，直线AB与OC交于点D．（1）求点C的坐标，并用含a的代数式表示点B的坐标；（2）当∠ABC＝90°时，求抛物线y＝ax2﹣4ax+3的表达式；（3）当∠ABC＝2∠BCD时，求OD的长．25．（14分）已知：如图，在△ABC中，∠ACB＝90°，AB＝10，tan B＝，点D是边BC 延长线上的点，在射线AB上取一点E，使得∠ADE＝∠ABC．过点A作AF⊥DE于点F．（1）当点E在线段AB上时，求证：＝；（2）在（1）题的条件下，设CD＝x，DE＝y，求y关于x的函数关系式，并写出x的取值范围；（3）记DE交射线AC于点G，当△AEF∽△AGF时，求CD的长．2021-2022学年上海市虹口区九年级（上）期末数学试卷（一模）参考答案与试题解析一、选择题（本大题共6题，每题4分，满分24分）下列各题的四个选项中，有且只有一个选项是正确的，请选择正确项的代号并填入答题纸的相应位置。
【九年级】2021年初三数学上期末试卷及答案(上海松江区2021年一模)
【九年级】2021年初三数学上期末试卷及答案（上海松江区2021年一模）松江区2021学年第一学期九年级质量调研考试数学考试（考试时间100分钟，满分150分）候选人须知：1．本试卷含三个大题，共25题．答题时，考生务必按答题要求在答题纸规定的位置上作答，在草稿纸、本试卷上答题一律无效．2.除第一和第二个主要问题外，除非另有规定，证明或计算的主要步骤必须写在答题纸的相应位置一、选择题：（本大题共6题，每题4分，满分24分）【在以下问题的四个选项中，只有一个选项是正确的。
请选择正确选项的代码，并在答题纸上填写相应的位置】1．已知，那么的值为（）（a）（b）；（c）；（d）。
2．下列函数中，属于二次函数的是（）（a）（b）；（c）；（d）。
3．已知飞机离水平地面的高度为5千米，在飞机上测得该水平地面上某观测目标a 的俯角为α，那么这时飞机与目标a的距离为（）（a）（b）；（c）；（d）。
4．已知非零向量，在下列条件中，不能判定的是（）（a）（b）；（c）；（d）。
5．在△abc中，边bc=6，高ad=4，正方形efgh的顶点e、f在边bc上，顶点h、g 分别在边ab和ac上，那么这个正方形的边长等于（a） 3；（b）2.5；（c）2.4；（d）2。
6．如图，已知在△abc中，点d、e分别在边ab、ac上，de∥bc，ad：bd=2:1，点f 在ac上，af：fc=1:2，联结bf，交de于点g，那么dg：ge等于．（a） 1:2；（b）1:3；（c）2:3；（d）2:5。
二、填空题：（本大题共12题，每题4分，满分48分）[请将结果直接填入答题纸的相应位置]7．已知线段a＝4，b=1，如果线段c是线段a、b的比例中项，那么c=▲．8.在比例为1:15000000的地图上，甲方和乙方之间的测量距离为2cm，因此甲方和乙方之间的实际距离为▲ 公里9．如果抛物线的开口向下，那么a的取值范围是▲．10.如果坡度为，则坡度的坡度为▲ 度11．已知线段ab=10，p是ab的黄金分割点，且ap>bp，那么ap=▲．12.众所周知，在等腰△ ABC，ab=AC=5，BC=6，G是物体的重心△ ABC，然后Ag=▲13．如图，已知直线a∥b∥c，直线m、n与a、b、c分别交于点a、c、e和b、d、f，如果ac=4，ce=6，bd=3，那么bf=▲．14.已知在平面直角坐标系xoy中，O为坐标原点，P点的坐标为（5,12），则OP与X 轴正半轴之间的夹角的余弦值为▲15．已知抛物线y=f(x)开口向下，对称轴是直线x=1，那么f(2)▲f(4)．（填“>”或“<”）16.向下平移抛物线。
上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末(中考一模)英语分类汇编：句型转换
上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末（一模）英语试题分类汇编句型转换上海市杨浦区2020-2021学年度第一学期九年级期末质量调研英语试题Ⅴ. Complete the following sentences as required.44.She needs to work on her interview skills.（改为否定句）She __________ to work on her interview skills.45.F rame sizes are varied to make the strip more interesting.（对划线部分提问）__________ ___________ frame sizes varied?46.I started to notice a tall dark figure watching me.（保持句意基本不变）I suddenly became _________ ____________a tall dark figure watching me.47.I won’t talk to her if she doesn’t apologize to me.（保持句意基本不变）I won’t talk to her s he to me.48.A couple stole a vase worth about $300,000 yesterday.（改为被动语态）A vase worth about $300,000 _________ __________ by a couple yesterday.49.“Is Mr. Jones behind bars?” asked Pansy.（改为间接引语）Pansy asked _________Mr. Jones __________ behind bars.50.t he chance, to meet and chat, small shops, for people, offer（连词成句）____________________________________________________________________________ 答案：52. doesn’t need53. Why are 54. aware of 55. unless, apologizes 56. was stolen57. i f/ whether; was58.Small shops offer the chance for people to meet and chat.上海市虹口区2021届九年级上学期期终学生学习能力诊断测试（一模）英语试题Ⅴ. Rewrite the following sentences as required.44.I’ve never written a feature for my school newspaper.（改为一般疑问句）you written a feature for my school newspaper?45.My father drives to work at 30km per hour in rush hours on weekdays.（对划线部分提问）_________ __________does your father drive to work in rush hours on weekdays?46.If he doesn’t taken action, the situation will probably get out of control.（保持句意不变）The situation will probably get out of control he action.47.More and more people have realized the importance of life-style.（保持句意不变）More and more people have been __________ __________ the importance of life-style. 48.W e often hang some beautiful presents on the Christmas tree.（改为被动语态）Some beautiful presents often on the Christmas tree.49.The manager asked the cler ks,“C an you come up with a new idea for sales?”（改为宾语从句）The manager asked the clerks they come up with a new idea for sales. 50.before, a medical examination, are required, all students, leaving secondary school, to have（连词成句）__________________________________________________________________________答案：52. Have, ever 53. How fast 54. unless takes 55. aware of 56. are, hung57. whether, could58. All students are required to have a medical examination before leaving secondary school.上海市宝山区2021届九年级上学期期末（一模）英语试题Ⅴ. Rewrite the following sentences as required,54.The homeless people need a big meal to eat and a warm house to live in.（改为否定句）、The homeless people ______ ___________ a big meal to eat and a warm house to live in.55.Mrs. White told us to close all the windows before we left the lab.（改为反意疑问句）Mrs. White told us to close all the windows before we left the lab, _________ ________?56.It is one and a half hours’ drive from my home to Shanghai Disneyland.（对划线部分提问）___________ _____________ is it from your home to Shanghai Disneyland?57.“Will our lives be better without computers?” Joey asked me.（改为含宾语从句的复合句）Joey asked me _____our lives be better without computers.58.Jack worked so hard that he could catch up with others in such a short time.（改为简单句）Jack worked _________ __________ to catch up with others in such a short time.59.Did Professor Smith start any hobbies when he retired from the university?（保持句意基本不变）Did Professor Smith _________any hobbies when he retired from the university?60.Jimmy, helping, teaches, parents, responsibility and independence, with housework（连词成句）__________________________________________________________________________答案：62. don’t need 63. didn’t use64. How far 65. if/whether, would66. hard enough 67. take up68. Helping parents with housework teaches Jimmy responsibility and independence.上海市普陀区2021届九年级上学期质量调研（一模）英语试题V. Complete the following sentences as required（根据所给要求完成句子。
2021-2022学年上海市虹口区九年级上学期期末数学试卷(一模)(含答案解析)
2021-2022学年上海市虹口区九年级上学期期末数学试卷(一模)一、选择题（本大题共6小题，共24.0分）1.如图(1)所示，E为矩形ABCD的边AD上一边，动点P，Q同时从点B出发，点P沿折线BE−ED−DC运动到点C时停止，点Q沿BC运动到点C时停止，它们运动的速度都是1cm/秒，设P、Q同时出发t秒时，△BPQ的面积为ycm2.已知y与t的函数关系图象如图(2)(曲线OM为抛物线的一部分)则下列结论正确的是()A. AB：AD=3：4B. 当△BPQ是等边三角形时，t=5秒C. 当△ABE∽△QBP时，t=7秒D. 当△BPQ的面积为4cm2时，t的值是√10或47秒52.已知非零向量a⃗、b⃗ 和c⃗，下列条件中，不能判定a⃗//b⃗ 的是()A. a⃗=−2b⃗B. a⃗=c⃗，b⃗ =3c⃗C. a⃗+2b⃗ =c⃗，a⃗−b⃗ =−c⃗D. |a⃗|=2|b⃗ |3.若y=(3+m)x m2−9是开口向下的抛物线，则m的值为()A. 3B. −3C. √11D. −√114.把抛物线y=(x−2)2向左平移2个单位长度，再向上平移2个单位长度，所得到的抛物线是()A. y=x2+2B. y=x2−2C. y=(x+2)2−2D. y=(x+2)2+25.如图，小王在长江边某瞭望台D处，测得江面上的渔船A的俯角为40°，若DE=3米，CE=2米，CE平行于江面AB，迎水坡BC的坡度i=1：0.75，坡长BC=25米，则此时AB的长约为()(参考数据：sin40°≈0.64，cos40°≈0.77，tan40°≈0.84)A. 10.4米B. 12.4米C. 27.4米D. 22.4米6.如图，四边形ABCD内接于⊙O，AB为直径，AD=CD，过点D作DE⊥AB于点E.连接AC交DE于点F.若cos∠CBA=35，EF=3.则AB的长为()A. 10B. 12C. 16D. 20二、填空题（本大题共12小题，共48.0分）7.如果3x−5y=0，且y≠0，那么xy=______．8.计算：2(2a⃗+3b⃗ )−13a⃗+12b⃗ =______ ．9.如图，是抛物线y=ax2+bx+c(a≠0)图象的一部分．已知抛物线的对称轴为x=2，与x轴的一个交点是(−1,0).有下列结论：①abc>0；②4a−2b+c<0；③4a+b=0；④抛物线与x轴的另一个交点是(5,0)；⑤点(−3,y1)，(6,y2)都在抛物线上，则有y1<y2.其中正确的是。
2021学年度上海杨浦区九上期末质量检测 物理学科(中考一模)
2021学年度第一学期初三期末质量检测物理学科（满分100分，时间90分钟） 2022.1 考生注意：1．本试卷物理部分含四个大题。
2．答题时，考生务必按答题要求在答题纸规定的位置上作答，在草稿纸、本试卷上答题一律无效。
一、选择题（共20分）1.下列各物理量中，可鉴别物质的是A．质量B．电阻C．体积D．密度2.研究得出“导体中电流与电压的关系”的科学家是A．牛顿B．帕斯卡C．欧姆D．伽利略3.下列生活器件中，利用连通器原理的是A．密度计B．茶壶C．抽水机D．注射器4.下列实例中，为了增大压强的是A．尖锐的逃生锤尖B．较宽的书包带C．宽大的骆驼脚掌D．有很多轮子的拖车5.九年级第一学期物理练习册共有70页，平放在水平桌面中央时，它对桌面的压强约为A．1帕B．35帕C．70帕D．140帕6.小球漂浮在酒精中，排开酒精的质量为0.2千克。
若该小球漂浮在水中，则排开水的质量A．一定大于0.2千克B．可能小于0.2千克C．一定等于0.2千克D．一定小于0.2千克7.在图1(a)(b)所示电路中，电源电压相同且不变，电路元件均完好，无论开关S1、S2同时断开，还是同时闭合，观察到电流表A1与电流表A2示数始终相同。
关于电阻R1、R2、R3的判断，以下列式中正确的是A．R3=R1+R2B．R2=R1+R3C．R1>R2>R3D．R3>R1>R28.相同柱形容器甲、乙置于水平地面上，容器内装有完全相同．．．．物块A、B，物块A与容器甲底部用一根细绳相连。
同时往两容器内注水，直至水面相平，如图2所示。
下列判断正确的是A．此时物块受到的浮力F浮A=F浮BB．此时容器对地面的压力F甲=F乙C．此时容器对地面的压强p甲>p乙D．此时水对容器底部的压力F水甲=F水乙9.在图3所示的电路中，电源电压保持不变。
闭合开关S，当滑动变阻器的滑片P由最右端向中间移动时，变小的是A．电流表 A 示数与电流表 A1 示数的差值B．电流表 A 示数与电流表 A1 示数的比值C．电压表 V 示数与电流表 A 示数的比值D．电压表 V 示数与电流表 A1 示数的比值10.如图4所示，均匀正方体甲、乙放置在水平地面上，它们的质量分别为m甲、m乙，对地面的压强分别为p甲、p乙。
2024年上海市杨浦区九年级上学期期末数学中考一模试卷含详解
C. D.
【答案】A
【分析】本题考查黄金分割点,根据黄金分割点的定义得出线段比例关系,选出正确选项,解题的关键是掌握黄金分割点的性质．
【详解】解：如图.
∵点 是线段 的黄金分割点,且 .
∴ .
故选：A．
4.如果两个非零向量 与 的方向相反,且 ,那么下列说法错误的是（）
A. 与 是平行向量B. 的方向与 的方向相同
【详解】解：因为锐角三角形三边的长都扩大为原来的两倍,所得的三角形与原三角形相似.
所以锐角 的大小没改变.
所以锐角 的正切函数值也不变．
故选：C．
【点睛】本题考查了正切的定义,解题的关键是掌握在直角三角形中,一个锐角的正切等于它的对边与邻边的比值．
3.已知 是线段 的黄金分割点,且 ,那么下列等式能成立的是（ ）
【详解】如图.
∵ .
∴ .
∴ .
∵ .
∴ .
∴ .
∵ .
∴ .
故答案为： ．
13.小华沿着坡度 的斜坡向上行走了 米,那么他距离地面的垂直高度上升了_____米．
【答案】
【分析】本题考查了坡度,根据题意画图,过点 作 于点 ,由坡度 得到 ,再利用勾股定理即可求解,熟练掌握坡度及勾股定理．
【详解】如图,过点 作 于点 ,则由题意得 米.
C.若 ,则 D.若 ,则
【答案】B
【分析】设 ,m,n都是正数, ,c,d都是负数,根据向量运算法则计算判断即可．
【详解】设 ,m,n都是正数, ,c,d都是负数.
则 .
故A正确,不符合题意.
的方向与 的方向相反.
故B错误,符合题意.
若 ,则 正确,不符合题意.
若 ,则 正确,不符合题意.
上海杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末(中考一模)英语试题分类汇编：词形转换
上海市杨浦、虹口、宝山、普陀、松江五区2021届九年级上学期期末（一模）英语试题分类汇编词形转换上海市杨浦区2020-2021学年度第一学期九年级期末质量调研英语试题Ⅳ. Complete the sentences with the given words in their proper forms.44.The thing to do is to give the stray dogs food and shelter.（one）45.His were well written but his delivery was hopeless.（speech）46.It’s a new story full of , adventure and heroic characters.（act）47.The yard doors usually have weak locks and you can open them .（easy）48.So what’s going on, you sound on the phone?（worry）49.A lot of people think that happiness is about being rich, but I .（agree）50.They tried to the police into thinking they had left the country, but failed.（foolish）51.Rita found on a desert island, in a room with no doors or windows.（she）答案：44. first 45. speeches 46. action 48. worried 49. disagree 50. fool 51. herself上海市虹口区2021届九年级上学期期终学生学习能力诊断测试（一模）英语试题Ⅳ. Complete the sentences with the given words in their proper forms.44.The hotel offers different of amusements to attract the guests.（variety）45.I chose the flat on the floor because I think “9” stands for “long lasting”.（nine）46.The local government is planning to more jobs for young people.（creative）47.It’s wrong of you to make fun of the boy. Y ou should apologize to him.（able）48.I think one of the ways to improve memory is the link method.（effect）49.Y ou need the knowledge of I.T. to apply for this job.（base）50.W e all know that success in study depends on one’s own effort.（main）51.The movie card was no available, so I threw it away.（length）答案：44. varieties 45. ninth 46. create 47. disabled 48. effective 49. basic 50. mainly51. longer上海市宝山区2021届九年级上学期期末（一模）英语试题Ⅳ. Complete the sentences with the given words in their proper forms.54.Two armed took place on the same street on Monday afternoon.（robbery）55.I have already checked the bag , but there is no sign of my wallet.（two）56.The boy was so clever that he could untie the knots and fool the kidnappers by .（he）57.To tell you the , I have worked very hard to prepare for the final exam.（true）58.The comic strip h as a dramatic plot to keep the readers in reading it.（interest）59.The cities in this country have been damaged after the war.（serious）puters were considered as one of the greatest in the 1920s though theywere very huge at that time.（invent）61.Eating food with strong smell on the underground usually makes people .（comfort）答案：54. robberies 55. twice 56. himself 57. truth 58. interested 59. seriously60. invention 61. uncomfortable上海市普陀区2021届九年级上学期质量调研（一模）英语试题IV. Complete the sentences with the given words In their proper forms（用括号中所给单词的适当形式完成下列句子。