【全国百强校】湖北省武汉市第二中学2015-2016学年高二上学期期中考试英语试题(原卷版)
湖北省武汉市第二中学2015-2016学年高二上学期期中考试英语试考试时间:2015年11月13日上午14：00—16：00 试卷满分：150分第一卷（选择题满分100分）第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答案卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题，每段对话仅读一遍。
1. What is the woman going to buy?A. A book on ships.B. A book on planes.C. Pictures of ships.2. What does the man think the weather will probably be like tomorrow?A. Rainy.B. Cloudy.C. Fine.3. Where does the conversation most probably take place?A. At a store.B. In a kitchen.C. In a garden.4. What does the man mean?A. He wants to have more sleep.B. He needs more sleep than the woman.C. He doesn’t need as much sleep as the woman.5. What does the man imply?A. The woman is careless with money.B. The woman has had enough suits.C. He’ll buy the suit for the woman.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
6. Why will the man go to Philadelphia?A. To be in a play.B. To watch a performance.C. To visit the statue of Abraham Lincoln.7. When will the man leave?A. On Friday morning.B. On Friday night.C. On Saturday morning.听第7段材料，回答第8、9题。
8. Why does the woman come to the man?A. To have an interview.B. To go on a sightseeing trip.C. To attend a business conference.9. How long has the woman been working after graduation?A. For six months.B. For two years.C. For more than three years. 听第8段材料，回答第10至12题。
10. Why did the man fail to see the woman at lunchtime?A. She ended her biology class late.B. She was busy preparing for the exam.C. She had a lot of questions to ask after class.11. What is the man’s weak subject?A. Biology.B. English.C. Maths.12. What can we learn from the conversation?A. The man hasn’t prepared for the exams.B. The final exams will come in one month.C. The woman is too busy to have lunch recently.听第9段材料，回答第13至16题。
13. Why will the speakers invite the couple next door to the party?A. The man thinks it polite to do so.B. The couple will bring something to drink.C. The couple will complain about the noise they make.14. What do the speakers usually do for a party?A. They prepare different sorts of salads.B. They invite the couple next door.C. They provide the food.15. When will the party end?A. 6:00 p.m.B. 9:00 p.m.C. 12:00 a.m.16. What can we learn from the conversation?A. Some unusual food will be provided.B. The guests have had salads enough.C. More people will attend the party.听第10段材料，回答第17至20题。
17. According to the speaker, what happened?A. Her house was broken into.B. Some guests had arrived.C. Her house was on fire.18. Why was the speaker afraid to get into the living room?A. It was too dark there.B. There might be burglars.C. The police hadn’t arrived yet.19. What did the police find out?A. The speaker forgot to turn off the TV set.B. Two men were trying to steal the TV set.C. Someone had opened the door with a special key.20. How did the woman feel in the end?A. Relieved.B. Frightened.C. Embarrassed.第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文, 从每题所给的四个选项（A、B、C和D）中, 选出最佳选项，并在答题卡上将该项涂黑。
AI always experienced guilt when I passed by without giving a coin or two to a beggar.My conscience was pricked again on a tour of Venice in 2010. I had taken refuge from the crowds in a quiet canal-side café. Outside the caféwas an old woman kneeling on the ancient cobbled stones, begging. Steady streams of tourists were walking past her. A lone young back-packer stood away from the crowds drinking something, but I noticed he was also observing the woman.A tourist group glanced at the woman and walked on. Another group of tourists arrived and, again, walked past her. The backpacker watched. Then, as I prepared to leave, I stopped at the sight of the backpacker stepping forward and placing some money in the woman’s cup. He did this rather ostentatiously（炫耀地）, just before the arrival of another tourist group. I watched as the leader of the group stopped and put some money in the cup. Having been shown the way, other tourists followed suit and added more coins to the woman’s cup.The young backpacker repeated this process in front of the next tour party going past. Once again, the subtle peer （同伴）pressure worked on the tourists, who all added coins to the cup. His work done, the young man walked over to the old beggar woman, patted her shoulder and said, “I hope that helps a bit.”I don’t know if the woman understood his English or realized what had just happened, but I did. I placed some money in the wo man’s cup and continued my travels, light-hearted after witnessing such an act of caring.21. The backpacker placed some money in the woman’s cup rather ostentatiously because______.A. he wanted to stop the tourists by doing thisB. he wanted people to know that he was rich and kindC. he wanted to help the woman by himselfD. he wanted the tourist group to follow him22. The author went to a quiet canal-side cafe to_______ .A. avoid meeting the beggarB. get away from the crowdsC. take a restD. watch the woman beggar23. We can infer from the passage that ________ .A. tourists can be cheated by beggarsB. people usually have pity on an old beggarC. tourists are willing to help beggarsD. people can do kind acts due to peer pressure24. Before the backpacker dropped some money in the woman’s cup, the tourists ______ .A. all showed pity for the womanB. didn’t notice the womanC. walked by without giving any moneyD. gave a little money to the womanBTechnology is making life easier for some dairy farmers. They use robotic systems to milk their cows. Cows are trained to follow a series of paths that lead to milking stations. Only one cow at a time can enter a station.Once inside，the cow is rewarded with food. As the cow eats，a robotic arm cleans and connects the animal to the milking machine. A few minutes later，milking is complete. The gate is opened，the cow is released and the next cow enters.The robotic systems are designed to operate 24 hours a day. The cows get to decide when they want to be milked. Cows are milked an average of about three times a day. Some are milked four to six times a day.The cows wear collars around their necks that identify them to the system. A computer keeps records on their eating and milking. A cow is released from the station if the computer decides it should not be milked.The automated system also measures the temperature and color of freshly produced milk. Milk is thrown away if it does not pass the tests.Professor Plaut believes the systems will appeal especially to the next generation of farmers. She means young people who are more interested in technology and less interested in working all the time on the farm. Still，she says the price of robotic milking systems will continue to limit their use.Doug and Tina Suhr have more than 100 cows on their family farm. Last year it became the fourth farm in southeast Minnesota to get a robotic milking system. A recent story in a local agricultural newspaper said the first robot costs 175,000 dollars. The second costs 150,000 dollars.Doug told AgriNews that wages that would have been paid for one employee in five years will pay for one robot. He says the increase in milk production reaches a high of more than six kilograms per cow per day.25. According to Doug，what is the wage of an employee per year?A．$150,000～$175,000. B．$150,000～$30,000.C．$30,000～$35,000. D．over $75,000.26. Besides milking cows，the robotic system also can ________.A．judge the quality of fresh milkB．keep fresh milk for two weeksC．adjust the temperature of milking stationsD．improve the appetite of cows27. Why is the robotic system not popular now?A．Because it usually causes the waste of milk.B．Because it is difficult to learn how to use it.C．Because young people have no interest in it.D．Because people can't afford to buy it.28. From the first paragraph，we can infer ________.A．cows can be raised by robots in the futureB．robots direct cows into milking stationsC．the robotic system is designed to reduce laborD．cows are kept clean by robots on some farmsCWhat do working mothers worry about the most? It's the kids of course. Whatever the setting, the question I get asked the most is "Will the kids be alright?" It has made me realize that we tend to look at the glass half-empty rather than half-filled when it comes to mixing work and family. We forget about all the benefits that we bring to our children when we work - and I'm not talking about the obvious financial benefits, although these of course shouldn't be taken for granted.About a year ago I remember getting a call from the school just as I was pulling up to the house after having driven 20 minutes to the school and 20 minutes back. "Mrs. Brown Quinn, your son asked us to call. He forgot his sports clothes. Can you come back to the school and drop them off?" I was exasperated(恼火)! I had already spent 40 minutes in aggressive weekday morning traffic. I replied, "Sorry, I'm working at the moment. I'm afraid my son needs to learn to be organized."Being a good parent requires delivering tough love sometimes. Kids need to learn to be independent. It can be a cruel and competitive world out there. Seeking interests, including business, outside of your kids, can give you that extra idea that you need not care for your kids with attention. This benefit of working isn't always immediately evident.It wasn't until our daughter went away to college that she realized why we had raised her in the way that we did. "Mom, I can't believe how so many of my friends struggle to manage things on their own. They are constantly calling their parents for help." You'll love that moment! After all those years of complaining about why you don't do this or why you don't give them that, your kids realize that tough love has made them better people.29. The purpose of the author is to ______.A. describe her own experience in raising childrenB. advise us to mix work and familyC. throw light on a special benefit of workingD. argue for working mothers30. How can kids become better people according to the author?A. By showing them your deep love.B. By giving them all your attention.C. By giving them tough love.D. By giving them freedom to do things on their own.31. The daughter's attitude towards the author is ______ when she grows up.A. understandingB. caringC. disappointedD. surprised32. The author refused to drop off her son's sports clothes because ______.A. she wanted her son to be organizedB. she was caught in heavy trafficC. she thought her son was lyingD. she was busy workingDA treasure trove hidden for centuries has been discovered in the underground vaults(墓穴)of a temple in southern India. The treasures include gold, diamonds and precious stones. The estimated value of the hoard is reportedly 22 billion US dollars.Hundreds of armed police have been deployed around the temple. Meanwhile, a debate about how to use the money has also broken out across the country. After discovering the treasure trove in Sri Padmanabhaswamy Temple in the southern Indian state of Kerala, the local government has assured security of the temple.Elaborating on the security arrangements, Venugopalan Nair, Additional Director General of the Kerala Police, says the latest security devices are being used to guard the temple.Venugopalan Nair, Additional Dir. Gen. of Kerala Police, said, "We are trying to bring in the latest technology with regards to surveillance(监视) cameras, with regards to, you know digitalizing the various things which areavailable inside. We are keeping a constant sort of surveillance for every movement, which happens in the whole area surrounding the temple."According to temple authorities, the crowd at the temple has increased steeply after news of the discovery of the treasure trove. And the Administrative Officer of the Temple says the government has initiated appropriate steps to control the curious crowds visiting the temple.G. Jayasekharan Nair, administrative officer, said, "To control the crowds the government itself is taking a lot of measures. They are trying to do whatever is possible from the premises of the temple. Apart from all that, the government has taken a favorable step and we are satisfied with them."Over the last week, a seven-member team of investigators broke into five secret subterranean vaults, and discovered jewels that have been lying untouched for hundreds of years.As estimates of the treasures' worth rise, a fierce debate is growing regarding what to do with the discovery. Kerala's top elected leader said the wealth would remain with the temple, while others say it should be used to pay for poverty alleviation(扶贫). However, the government is adhering to the Supreme Court's ruling on ownership of the treasure found in the temple.33. How will the government deal with the treasure mentioned in the passage?A. It will be used to pay for poverty alleviation.B. It will be returned to its owner.C. It will be kept in the vaults.D. It hasn’t been decided yet.34. Which of the following is NOT TRUE according to the passage?A. The treasures include gold, diamonds and some old coins.B. The treasure trove has been lying unknown for hundreds of years before it is discovered.C. The local people are very curious about the treasure and the temple.D. The whole area surrounding the temple is under close watch.35. What G.Jayasekharan Nair said means that .A. what the government does means littleB. the crowd will make trouble without proper controlC. more effective measures should be takenD. the temple is of great value第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
湖北省武汉市第二中学高二英语上学期期中试题
湖北省武汉市第二中学2014-2015学年高二上学期期中考试英语试题第一部分听力（共两节 30分）做题时，先将答案划在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Where does the conversation take place?A. On a train.B. On a plane.C. In a restaurant.2. Why does the woman ask the man to see her?A. To fire him.B. To ask him not to be late.C. To tell him the change of working hours.3. When will the woman stay at the hotel?A. From Feb. 2 to Feb. 16.B. From Feb. 13 to Feb. 15.C. From Feb. 2 to Feb. 12.4. What does the woman mean?A. She doesn't know which school to choose.B. She's already decided which major to choose.C. She's already been to the Academic Help Centre5. What is the woman doing?A. Having a wedding ceremony.B. Getting prepared to go to Canada.C. Making a plan for her honeymoon.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话。
湖北省武汉市第二中学高二上学期期中考试语文试题.doc
湖北省武汉市第二中学高二上学期期中考试语文试题下列各组词语中，没错别字的一组是A．嬉笑爆冷门知书达礼走投无路久旱逢甘霖B．分孽原生态牙牙学语励精图治时势造英雄C．脉搏一摊血白浪滔天嘘寒问暖真人不露相D．押韵青纱帐应接不暇叠床架屋一笑抿恩仇【答案解析】C2依次填入下列横线处的词语，最恰当的一组是①“大白菜卖出猪肉价”，进入了5月份，按说蔬菜已到了旺季，价格也应回落，可是各种菜价不落反涨，尤其是大白菜、西红柿等价格直逼猪肉，这叫人有些担心。
②说起鲁迅，一些人总会感到他严厉、苛刻、不、睚眦必报，其实这是他对敌人的一面，而对友人、对同志，尤其是对青年，可说是呵护有加。
③近来，台湾由于油价、电价的上涨，导致粮、菜、肉、蛋、奶等一系列与百姓日常生活的物品价格的上涨，有评论认为，平抑物价、保障百姓生活是对马英九新一任政府的重大考验。
A．未免大方休戚相关B．难免大度息息相关C．未免大方息息相关D．难免大度休戚相关【答案解析】B3下列各项中，没有语病的一项是A．目前，我国开放了100个左右的国家和地区作为旅游目的地，而旅行社真正投放市场供游客选择的不到30个左右，2/3的目的地资源空置。
B．北接陆上丝绸之路、南连海上丝绸之路，由京杭大运河、隋唐大运河以及浙东运河组成的“中国大运河”已申遗成功。
C．省部级高官频频落马显示了新一届党中央的反腐决心，但“打几只老虎”仅仅是第一步，当务之急的工作是建立一整套行之有效的反腐机制。
D．钓鱼岛事态激化到当前地步，直接原因是由日本的短视造成的。
但这又与美国有意无意推波助澜不无关联。
实际上，美日对钓鱼岛的私相授受，使日本的错觉不断强化。
【答案解析】B4下列各句中有关文学常识表述有误的一项是A．关汉卿与马致远、郑光祖、白朴合称为元曲四大家。
元曲是元杂剧及散曲的总称，是元代文学的代表，与唐诗宋词并称。
B．莎士比亚，欧洲文艺复兴时期英国伟大的诗人和戏剧家。
他的剧本著名的有四大悲剧《哈姆莱特》《奥赛罗》《李尔王》《麦克白》。
湖北省武汉市第二中学高二上学期期中考试英语试题
考试时间：2014年11月7日上午：9:00～11:00试卷满分：150分第一部分听力（共两节30分）做题时，先将答案划在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Where does the conversation take place?A. On a train.B. On a plane.C. In a restaurant.2. Why does the woman ask the man to see her?A. To fire him.B. To ask him not to be late.C. To tell him the change of working hours.3. When will the woman stay at the hotel?A. From Feb. 2 to Feb. 16.B. From Feb. 13 to Feb. 15.C. From Feb. 2 to Feb. 12.4. What does the woman mean?A. She doesn't know which school to choose.B. She's already decided which major to choose.C. She's already been to the Academic Help Centre5. What is the woman doing?A. Having a wedding ceremony.B. Getting prepared to go to Canada.C. Making a plan for her honeymoon.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话。
【全国百强校】湖北省武汉市第二中学2015-2016学年高二上学期期末考试文数试题解析(解析版)
一、选择题（本大题共12个小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.）1.复数25-i 的共轭复数是（ ） A ．2+i B ．i -2 C ．i --2 D ．2-i 【答案】D考点：复数的运算；共轭复数的概念．2.如图是某学校一名篮球运动员在10场比赛中所得分数的茎叶图，则该运动员在这10 场比赛中得分的中位数为（ ）A ．15B ．15.5C ．16D ．16.5【答案】A 【解析】试题分析：根据中位数的概念可知，该运动员在这10场比赛中得分的中位数为15，故选A ． 考点：茎叶图及中位数的概念．3．某学校高一、高二、高三年级的学生人数之比为3：3：4，现用分层抽样的方法从该校高中三个年级的学生中抽取容量为50的样本，则应从高二年级抽取（ ）名学生． A ．10 B ．15 C ．20 D ．25 【答案】B 【解析】试题分析：用分层抽样的方法，从该校三个年级的学生中抽取容量为50的样本，则从高二年级抽取35015334⨯=++，故选B ．考点：分层抽样．4．设函数()y f x =的定义域为R ，则"(0)0"f =是“函数()f x 为奇函数”的（ ） A ．充分而不必要条件 B ．必要而不充分条件 C ．充分必要条件 D ．既不充分也不必要条件 【答案】B考点：必要不充分条件．5.阅读如图所示的程序框图，运行相应的程序．若输出的S 为1112，则判断框中填写的内容可以是（ ） A ．6n = B ．6n < C ．6n ≤ D ．8n ≤【答案】C 【解析】试题分析：根据给定的程序框图可知，0,2S n ==，第1次循环：1,42S n ==；第2次循环： 11,624S n =+=；第3次循环：11111,824612S n =++==，此时跳出循环，输出S 的值为1112，所以判断框中填写的内容可以是6n ≤，故选C ．考点：程序框图．6．已知某种产品的支出广告额x 与利润额y （单位：万元）之间有如下对应数据：则回归直线方程必过（ ）A ．()5,36B ．()5,35C ．()5,30D ．()4,30 【答案】A 【解析】试题分析：根据回归直线方程可知，回归直线方程经过样本的中心点，此时3456755x ++++==，2030304060365y ++++==，故选A ．考点：回归直线方程．7．已知双曲线C ：x 2a 2－y 2b 2＝1(a >0，b >0)的离心率为52，则C 的渐近线方程为（ ）A ．x y 41±=B ．x y 31±=C ．x y 21±= D ．x y ±= 【答案】C考点：双曲线的简单的几何性质．8．已知函数()2log f x x =，任取一个01,22x ⎡⎤∈⎢⎥⎣⎦使()00f x >的概率为（ ）A ．14 B ．12 C ．34 D ． 23【答案】D 【解析】试题分析：由题意得总的基本事件涉及的区间长度为13222-=，由对数函数的性质解()00f x >，可得01x >，所以使得()00f x >的区间为(1,2]，长度为211-=，所求概率12332P ==，故选D ． 考点：几何概型． 9．已知函数()21sin cos 2f x x x x x =+，则其导函数()f x '的图象大致是（ ）【答案】C考点：利用导数研究函数的单调性．10．设抛物线2:2(0)C y px p =>的焦点为F ,点M 在C 上,5MF =,若以MF 为直径的圆过点)2,0(,则C 的方程为（ ） A ．24y x =或28y x = B ．22y x =或28y x = C ．24y x =或216y x = D ．22y x =或216y x =【答案】C 【解析】试题分析：因为抛物线方程为2:2(0)C y px p =>，所以焦点(,0)2pF ，设(,)M x y ，由抛物线性质 52p MF x =+=，可得52px =-，因为圆心是MF 的中点，所以根据中点坐标公式可得，圆心横坐标为552222p p -+=，由已知圆半径也为52，据此可知该圆与y 轴相切于点(0,2)，故圆心纵坐标为2，则M 点纵坐标为4，即(5,4)2p M -，代入抛物线的方程得210160p p -+=，所以2p =或8p =．所以抛物线的方程为24y x =或216y x =． 考点：抛物线的标准方程．11.在平面直角坐标系中，两点P 1(x 1，y 1)，P 2(x 2，y 2)间的“L 距离”定义为：||P 1P 2||＝|x 1－x 2|＋|y 1－y 2|，则平面内与x 轴上两个不同的定点F 1，F 2的“L 距离”之和等于定值(大 于||F 1F 2||)的点的轨迹可以是（ ）A ．B ．C ．D ．【答案】A考点：轨迹方程．【方法点晴】本题主要考查了轨迹方程的求解，着重考查了分类讨论的数学思想方法，解答的关键是正确分类，属于中档试题，本题的解答中设出设12(,0),(,0)F c F c -和动点(,)M x y 的坐标，根据题设条件列出关系式后，分类讨论去掉绝对值号，从而确定动点的轨迹方程，结合本题的选项可得动点的轨迹，得到答案．12.设函数()2ln 2x f x k x =-，0k >.若()f x 存在零点，则()f x 在区间(上有（ ）个零点 A ．0 B ．1 C ．2 D ．不确定 【答案】B考点：利用导数研究函数的单调性．【方法点晴】本题主要考查了求导公式、导数的运算法则，导数与函数单调性的关系，以及函数零点的转化，着重考查了分类讨论的数学思想、化简、变形能力，属于中档试题，本题的解答中，先求解函数的导数()f x '，判定函数的单调性，确定函数的单调区间，求解函数的最小值，由条件列出不等式求解实数k 的取值范围，对k 进行分类讨论，并分别判断在区间(上的单调性，求出()1f 和f ，判断符号，即可能证明结论．第Ⅱ卷（非选择题共90分）二、填空题（本大题共4小题，每题5分，满分20分．）13．某单位有840名职工，现采用系统抽样方法抽取42人做问卷调查，将840人按1,2，…，840随机编号，则抽取的42人中，编号落人区间[481,720]的人数为 ． 【答案】12【解析】试题分析：使用系统抽样方法，从840人中抽取42人，即从20人中抽取1人，所以从编号1840 的人中，恰好抽取4802420=人，接着从编号[]481,720共240人抽取2401220=人，故答案为12． 考点：系统抽样．14.为比较甲、乙两地某月14时的气温状况，随机选取该月中的5天，将这5天中14时的气温数据（单位：℃）制成如图所示的茎叶图.考虑以下结论：①甲地该月14时的平均气温低于乙地该月14时的平均气温； ②甲地该月14时的平均气温高于乙地该月14时的平均气温；③甲地该月14时的平均气温的标准差小于乙地该月14时的气温的标准差； ④甲地该月14时的平均气温的标准差大于乙地该月14时的气温的标准差. 其中根据茎叶图能得到的统计结论的标号为 ． 【答案】①④考点：用样本估计总体．15．点F 是抛物线2:2(0)x py p τ=>的焦点，1F 是双曲线2222:1(0,0)x y C a b a b-=>> 的右焦点，若线段1FF 的中点P 恰为抛物线τ与双曲线C 的渐近线在第一象限内的交点，则双曲线C 的离心率e 的值为．考点：抛物线的简单性质．【方法点晴】本题考查双曲线的标准方程及其简单的几何性质，同时考查了抛物线的几何性质和考生的运算能力，其中确定P的坐标是解答的关键，本题的解答中，确定双曲线C的渐近线的方程by xa=，代入22x py=，得到点2222(,)bp b pPa a，利用点P是线段1FF的中点，可得(,)24c pP，确定,a c的关系，由此即可得出双曲线C的离心率．16．某种平面分形图如下图所示，一级分形图是由一点出发的三条线段，长度均为1，两两夹角为120 ；二级分形图是在一级分形图的每条线段的末端出发再生成两条长度为原来13的线段,且这两条线段与原线段两两夹角为120 ；……；依此规律得到n级分形图．（1）4级分形图中共有______条线段；（2）n级分形图中所有线段长度之和为______．【答案】（1）45 （2）29[1()]3n-【解析】考点：归纳推理；数列求和．【方法点晴】本题主要考查了通过观察、方向、猜想、归纳数列通项公式的方法，着重了等比数列的前n 项函数公式，考查了推理能力和计算能力，属于难度较大题，本题的解答中得到当1,2,3,4n =时，线段的条数，第2问中，从1问中，得到线段条数的通项公式，2122111332232333n -+⨯⨯+⨯++⨯⨯ ，利用等比数列的前n 项和公式即可得出．三、解答题（本大题共6小题，共70分.解答应写出文字说明、证明过程或演算步骤.）17．（本小题满分10分）设命题:p 实数x 满足22430x ax a -+<,其中0a <；命题:q 实数x 满足5|72|<+x ． （1）当1-=a 时，若q p ∧为真，求x 范围；（2）若p ⌝是q ⌝的必要不充分条件，求实数a 的取值范围． 【答案】（1）()1,3--；（2）12-≤≤-a ． 【解析】试题分析：先分别求解,p q 分别为真命题时，x 的取值范围，（1）在根据q p ∧为真，求解x 的取值范围；（2）由p ⌝是q ⌝的必要不充分条件，则q 是p 的必要不充分条件，从而求解x 的取值范围． 试题解析：（1）p 真，则13-<<-x ；q 真，则16-<<-x , 因为q p ∧为真,则p 真且q 真,故x 范围为()1,3--;(2)p ⌝是q ⌝的必要不充分条件，则q 是p 的必要不充分条件，因为p 真，有a x a <<3,所以⎩⎨⎧-≥-≤631a a ，故12-≤≤-a .考点：命题真假的判定与应用． 18．（本小题满分12分）2014年“双节”期间，高速公路车辆较多．某调查公司在一服务区从七座以下小型汽车中按进服务区的先后每间隔50辆就抽取一辆的抽样方法抽取40名驾驶员进行询问调查，将他们在某段高速公路的车速 （km /h ）分成六段：[)60,65，[)65,70，[)70,75，[)75,80，[)80,85，[)85,90后得到如图的频率 分布直方图．（1）求这40辆小型车辆车速的众数、平均数和中位数的估计值；（2）若从车速在[)60,70的车辆中任抽取2辆，求车速在[)65,70的车辆恰有一辆的概率． 【答案】（1）众数与中位数的估计值均等于77.5，平均值为77；（2）158．平均数的估计值为：770.0287.50.0582.50.0677.50.0472.50.0267.50.0162.55=⨯+⨯+⨯+⨯+⨯+⨯⨯）（考点：古典概型及其概率的计算公式，频率分布直方图中众数、中位数、平均数． 19.（本小题满分12分）已知函数2()ln f x a x bx =-，,a b R ∈．若()f x 在1x =处与直线12y =-相切． （1）求b a ,的值；（2）求()f x 在1[,]e e上的最大值． 【答案】（1）11,2a b ==；（2）最大值为1(1)2f =-. 【解析】试题分析：（1）对()f x 进行求导，()f x '求出切线方程，只需求出其斜率即可，利用函数在1x =处的导数值求解斜率，再结合导数的几何意义即可求出切线的斜率，列出关于,a b 的方程求解,a b 的值；（2）研究区间上函数的最值问题，先求出函数的极值，比较极值和端点处的函数值的大小，最后确定函数的最大值． 试题解析：（1）'()2af x bx x=-． 由函数()f x 在1x =处与直线12y =-相切，得'(1)01(1)2f f ⎧=⎪⎨=-⎪⎩，即2012a b b -=⎧⎪⎨-=-⎪⎩，解得：112a b =⎧⎪⎨=⎪⎩．（2）由（1）得：21()ln 2f x x x =-，定义域为(0,)+∞．此时，2'11()x f x x x x-=-=，令'()0f x >，解得01x <<，令'()0f x <，得1x >．所以()f x 在1(,1)e 上单调递增，在(1,)e 上单调递减，所以()f x 在1[,]e e 上的最大值为1(1)2f =-．考点：导数的几何意义；利用导数求解函数的最值． 20.（本小题满分12分）（1）在区间]5,1[和]4,2[上分别任取一个整数，记为b a ,，则方程22221x y a b+=表示焦点在x 轴上且离心率?（2）在区间]5,1[和]4,2[上分别任取一个实数，记为b a ,，则方程22221x y a b+=表示焦点在x 轴上且离心率?【答案】（1）154；（2）1532．又⎪⎩⎪⎨⎧>>21a b ba ，即⎩⎨⎧>>ab b a 2，即阴影区域，则32158415===矩形阴S S P考点：古典概型和几何概型的概率的计算公式． 21．（本小题满分12分）已知椭圆C 的对称中心为原点O ，焦点在x 轴上，左右焦点分别为1F 和2F ，且2||21=F F ，点)23,1(在该椭圆上．（1）求椭圆C 的方程；（2）过1F 的直线l 与椭圆C 相交于A ，B 两点，若B AF 2∆的面积为7212，求以2F 为圆心且与直线l 相切 圆的方程．【答案】（1）22143x y +=；（2）2)1(22=+-y x ．考点：椭圆的几何性质及圆的标准方程的求解．【方法点晴】本题主要考查了椭圆的标准方程及其简单的几何性质的应用、直线的圆锥曲线的综合应用和圆的标准方程的求解，运算量较大，属于中档试题，本题第2问的解答中，把直线方程代入椭圆的方程，得出关于x 的一元二次方程，运用韦达定理得出221212228412,3434k k x x x x k k-+=-⋅=++，求解AB ，求解2AF B ∆的面积，求解k 的值，从而得到圆的半径，即可求解圆的标准方程，其中准确计算、仔细化简是解答本题的关键，也是一个易错点． 22.（本小题满分12分）已知函数()32f x x ax =-，R a ∈．（1）求)(x f y =的单调区间；（2）若曲线()y f x =与直线1y x =-只有一个交点，求实数a 的取值范围．【答案】（1）当0=a 时，)(x f y =单调递增区间是(),-∞+∞；当0>a 时，单调递增区间为()0,∞-，⎪⎭⎫⎝⎛+∞,32a ，递减区间为⎪⎭⎫ ⎝⎛32,0a ；当0<a 时，单调递增区间为：⎪⎭⎫ ⎝⎛∞-32,a ，()+∞,0；递减区间为：⎪⎭⎫⎝⎛0,32a ；（2）1a <. 【解析】试题分析：（1）求解函数的导数()(32)f x x x a '=-，分类讨论求解函数的单调区间；（2）把曲线()y f x =与直线1y x =-只有一个交点转化为关于x 的方程3210x ax x --+=只有一个根，设32()1g x x ax x =--+，利用函数()g x 的单调性和最值转化为方程3210x ax x --+=只有一个根等价于1()0g x >且2()0g x >或者1()0g x <且2()0g x <，再转化为31()122xh x x =--+，利用()h x 的性质，求解实数a 的取值范围．又232323311()111(1,2)222i i i iii ii i i i x x g x x ax x x x x x i x -=--+=--+=--+=，设31()122x h x x =--+，所以231'()022h x x =--<，所以()h x 为减函数， 又(1)0h =，所以1x <时()0h x >，1x >时()0h x <，所以(1,2)i x i =大于1或小于1，由120x x <<知，(1,2)i x i =只能小于1，所以由二次函数2'()321g x x ax =--性质可得'(1)3210g a =-->，所以1a <. 考点：利用导数求解函数的单调区间；利用导数研究函数的性质的综合应用．【方法点晴】本题主要考查了利用导数求解函数的单调区间即利用导数研究函数的最值的应用，体现了利用导数研究函数的综合应用，同时着重考查了数学转化的思想和分类讨论的解题思想方法的应用，试题南段较大，属于难题，本题第2问的解答中，把曲线()y f x =与直线1y x =-只有一个交点转化为关于x 的方程3210x ax x --+=只有一个根，设出32()1g x x ax x =--+，利用函数()g x 的单调性和最值转化为方程3210x ax x --+=只有一个根等价于1()0g x >且2()0g x >或者1()0g x <且2()0g x <，再转化为31()122xh x x =--+，利用()h x 的性质，求解实数a 的取值范围，其中步步转化为函数的性质是解答本题的一大难点，需要平时注意总结和积累．高考一轮复习：。
湖北省武汉市第二中学2016-2017学年高二上学期期中考试英语试题Word版含答案
武汉二中2016－2017学年度上学期期中考试高二英语试卷考试时间：2016年11月10日下午14:00－16:00试卷满分：150分第一部分听力（共两节, 满分30分）第一节（共5小题；每小题1.5分, 满分7.5分）听下面5段对话。
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听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does the woman ask the man to do?A. Look for his notebook in the library.B. Go to the library to borrow a book.C. Search the desk for his notebook.2. What will the woman do this afternoon?A. Go jogging with the man.B. Take care of her cousin’s son.C. Look after her cousin.3. What are the speakers talking about?A. A place.B. A flight.C. A trip.4. What does the man mean?A. The woman should keep on with her class.B. The woman needs help with the class.C. The woman can drop her class.5. How much extra money should the man pay?A. $25.B. $50.C. $75.第二节（共15小题；每小题1.5分, 满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
16—17学年上学期高二期中考试英语试题(附答案)(38)
武汉二中2016－2017学年度上学期期中考试高二英语试卷考试时间：2016年11月10日下午14:00－16:00试卷满分：150分第一部分听力（共两节, 满分30分）第一节（共5小题；每小题1.5分, 满分7.5分）听下面5段对话。
每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does the woman ask the man to do?A. Look for his notebook in the library.B. Go to the library to borrow a book.C. Search the desk for his notebook.2. What will the woman do this afternoon?A. Go jogging with the man.B. Take care of her cousin‟s son.C. Look after her cousin.3. What are the speakers talking about?A. A place.B. A flight.C. A trip.4. What does the man mean?A. The woman should keep on with her class.B. The woman needs help with the class.C. The woman can drop her class.5. How much extra money should the man pay?A. $25.B. $50.C. $75.第二节（共15小题；每小题1.5分, 满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
【全国百强校】湖北省武汉市第二中学2015-2016学年高二上学期期中考试文数试题解析(解析版)
考试时间:2015年11月13日上午8:00—10:00 试卷满分:150分第Ⅰ卷（共60分）一、选择题：（本大题共12小题；每小题5分，共60分。
在每小题给出的四个选项中，只有一个选项是符合题目要求的，把正确选项的代号填在答题卡上。
）1.已知命题022,:2>++∈∀x x R x p ,则p ⌝是( ) A . ,0R x ∈∃022020<++x x B . ,R x ∈∀0222<++x x C . ,0R x ∈∃022020≤++x x D . ,R x ∈∀0222≤++x x【答案】C考点：全称命题的否定。
2.抛物线2ax y =的准线方程是 ( )A. 2a y -=B. 4a y -=C. a y 21-=D. ay 41-= 【答案】D 【解析】试题分析：首先将方程化为标准方程y a y a x 21212⋅==.当0>a 时，a y 41-=；当0<a 时，a y 41-=。
所以抛物线2ax y =的准线方程是 ay 41-=。
故选D 。
考点：求抛物线的准线方程。
3.已知函数,cos )(x b x x f +=其中b 为常数,那么“0=b ”是“)(x f 为奇函数”的( )A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】C考点：以函数奇偶性为背景的充分性、必要性判断。
4．设()ln f x x x =，若0'()2f x =，则0x =（ ）A. 2eB. eC.ln 22D. ln 2【答案】B 【解析】试题分析：因()ln f x x x =，所以1+=x x f ln )('.由2ln )('00=+=1x x f 解得，e x =0。
故选B 。
考点：求导数并求对数方程。
5.与双曲线12322=-y x 有共同的渐近线，且经过点)52,3(A 的双曲线的方程为（ ）A ．1121622=-x yB ．14222=-y x C ．1271822=-x y D ．14622=-y x【答案】C 【解析】试题分析：与双曲线12322=-y x 有共同的渐近线的双曲线方程可设为）（0≠=-λλ2322y x ，然后将点A 的坐标代入求出-9=λ，所以所求双曲线的方程为1271822=-x y 。
【全国百强校】湖北省武汉外国语学校2015-2016学年高二上学期期中考试物理试题解析(解析版)
一、单项选择题（本题包括8小题，每小题4分，共32分。
）1.如图所示，把轻质导线圈用绝缘细线悬挂在磁铁N极附近，磁铁的轴线穿过线圈的圆心且垂直线圈平面．当线圈内通以图中方向的电流后，线圈的运动情况是()A．线圈向左运动B．线圈向右运动C．从上往下看顺时针转动D．从上往下看逆时针转动【答案】A考点：右手定则。
【名师点睛】此题是对右手定则的考查；要知道通电线圈周围的磁场用右手定则来判断，并且通电线圈周围的磁场可等效为条形磁铁；根据同名磁极相互排斥，异名磁极相互吸引来判断相互作用情况；此题是基础题.2.如图所示，一根横截面积为S的均匀长直橡胶棒上均匀带有负电荷，设棒单位长度内所含的电荷量为q，当此棒沿轴线方向做速度为v的匀速直线运动时，由于棒的运动而形成的等效电流大小为( )A．qv B. qv C．qvS D.qvS【答案】A 【解析】试题分析：设经过时间t，流过某一截面的电量为Q=vtq，则根据电流强度的概念可知Q vtqI vqt t===，故选A.考点：电流强度【名师点睛】此题是是对电流强度的考查；要知道电流强度等于单位时间内流过某一横截面的电量；只要计算出在时间t内流过某一横截面的电量即可计算电流值；此题难度不大，意在考查学生对基本概念的掌握程度.3.带电质点在匀强磁场中运动，某时刻速度方向如图所示，所受的重力和洛仑兹力的合力恰好与速度方向相反，不计阻力，则在此后的一小段时间内，带电质点将（）A．可能做直线运动B．可能做匀减速运动C．可能做匀速圆周运动D．一定做曲线运动【答案】D考点：洛伦兹力；曲线运动【名师点睛】此题是对洛伦兹力及曲线运动的考查；要注意质点所受洛伦兹力随速度的变化而变化，质点所受合力随之变化，当质点所受的合力与速度不共线时，质点做曲线运动。
做匀速圆周的的条件是质点受到大小不变的，方向总与速度垂直的合力作用.4.位于正方形四角上的四个等量点电荷的电场线分布如图所示，ab、cd分别是正方形两条边的中垂线，O 点为中垂线的交点，P、Q分别为cd、ab上的点．则下列说法正确的是()A．P、O两点的电势关系为φP<φOB．P、Q两点电场强度的大小关系为E P<E QC．若在O点放一正点电荷，则该正点电荷受到的电场力为零D．若将某一负电荷由P点沿着图中曲线PQ移到Q点，电场力做负功【答案】C【解析】试题分析：根据电场叠加，由图象可知ab、cd两中垂线上各点的电势都为零，所以P、O两点的电势相等．故A错误．电场线的疏密表示场强的大小，根据图象知E P＞E Q，故B错误；四个点电荷在O点产生的电场相互抵消，场强为零，故在O点放一正点电荷，则该正点电荷受到的电场力为零，故C正确．P、Q电势相等，所以a、c两点电势相等，若将某一负电荷由P点沿着图中曲线PQ移到Q点，电场力做功为零．故D错误．故选C.考点：电场强度；电势及电势能【名师点睛】本题的关键要掌握电场线的分布情况，能根据曲线的弯曲方向可知粒子的受力方向．根据电场线的方向确定场源电荷的正负．电势的高低看电场线的指向，沿着电场线电势一定降低．电场线的疏密表示场强的大小，根据电势高低判断功的正负。
【全国百强校】湖北省武汉市第二中学2015-2016学年高二上学期期末考试物理试题解析(解析版)
一、选择题：本大题共12小题，每小题4分，共48分．其中1－8是单项选择题；9－12是多项选择题，全部选对的得4分，选对但不全的得2分，有选错的得0分．1．下列说法正确的是A．物体做受迫振动时，驱动力频率越高，受迫振动的物体振幅越大B．医生利用超声波探测病人血管中血液的流速应用了多普勒效应C．两列波发生干涉，振动加强区质点的位移总比振动减弱区质点的位移大D．一列波通过小孔发生了衍射，波源频率越大，观察到的衍射现象越明显【答案】B考点：受迫振动、波的现象。
【名师点睛】物体做受迫振动的频率等于驱动力的频率，当驱动力的频率f等于物体的固有频率f0时，物体做受迫振动振幅最大，发生共振；两列波发生干涉时，振动加强区域，总是加强，两列波引起的位移方向始终相同，各质点的位移随时间做周期性变化，它的位移某时刻可能为零，也不一定比振动减弱区域的位移大；产生明显衍射的条件是障碍物或孔的尺寸比波长小或相差不多。
2．铝质薄平板的上方和下方分别有垂直于纸面的匀强磁场（图中未画出），一带电粒子从紧贴铝板上表面的A点沿图示方向射出，夹角θ= 30°，从C点穿过铝板后到达铝板上的D点，粒子的运动轨迹如图所示。
粒子从A运动到C的时间等于从C运动到D的时间。
粒子穿越铝板时速度方向不变，粒子电荷量不变，重力不计。
则铝板上方与下方的磁感应强度大小之比为A ．5B ．1CD ．0. 2 【答案】D考点：带电粒子在匀强磁场中的运动。
【名师点睛】根据题意确定带电粒子在两个磁场中做圆周运动所转过的圆心角，从而确定运动时间的表达式T t πθ2=,利用运动时间相等这个条件，求出磁感应强度之比。
3．如图所示， A 、B 是两个完全相同的灯泡，D 是理想二极管，L 是带铁芯的线圈，其直流电阻忽略不计。
下列说法正确的是A ．S 闭合瞬间，A 先亮B ．S 闭合瞬间，A 、B 同时亮C ．S 断开瞬间，B 逐渐熄灭D ．S 断开瞬间，A 闪亮一下，然后逐渐熄灭 【答案】D 【解析】试题分析：闭合瞬间线圈相当于断路，二极管为正向电流，故电流不走A 灯泡，B 逐渐亮，A 错误；B 错误；开关S 断开瞬间B 立刻熄灭，由于二极管正向导通，故自感线圈与A 形成回路，A 闪亮一下，然后逐渐熄灭，C 错误；D 正确；故选D 。
【全国百强校】湖北省武汉市第二中学2015-2016学年高二上学期期中考试化学试题解析(解析版)
试卷满分：100分可能用到的相对原子质量：H：1O:16Cl:35.5Cu: 64Fe:56第Ⅰ卷（选择题，共48分）一、选择题（每小题3分，共48分）1、下列说法正确的是（）A、Na与H2O的反应是熵增的放热反应，该反应能自发进行B、放热反应的反应速率总是大于吸热反应的反应速率C、增大压强会加快化学反应速率，其原因是增加了活化分子的百分率D、强电解质溶液导电能力一定很强，弱电解质溶液导电能力一定很弱【答案】A【考点定位】本题主要是反应自发性、反应速率、溶液导电性等有关判断【名师点晴】溶液的导电能力强弱取决于溶液中离子浓度的大小和离子所带电荷的多少，离子浓度越大，离子所带的电荷越多，溶液的导电性越强。
若强电解质溶液中离子浓度很小，而弱电解质溶液中离子浓度大，则弱电解质溶液的导电能力强，因此电解质的强弱与电解质溶液的导电性并无必然联系。
2、室温下，将0.05mol Na2CO3固体溶于水配成100mL溶液，向溶液中加入下列物质，有关结论正确的是（）【答案】C考点：考查盐类水解平衡应用。
涉及离子浓度的比较、溶液pH 的变化等 3、已知：2H 2(g )＋O 2(g )===2H 2O (l ) ΔH ＝－571.6 kJ ·mol －12CH 3OH (l )＋3O 2(g )===2CO 2(g )＋4H 2O (l ) ΔH ＝－1452 kJ ·mol －1H ＋(aq )＋OH －(aq )===H 2O (l ) ΔH ＝－57.3 kJ ·mol －1下列说法正确的是（ ）A 、H 2(g )的燃烧热为571.6 kJ ·mol －1B 、同质量的H 2(g )和CH 3OH (l )完全燃烧，H 2(g )放出的热量多C 、21H 2SO 4(aq )＋21Ba (OH )2(aq )=== 21BaSO 4(s )＋H 2O (l ) ΔH ＝－57.3 kJ ·mol －1 D 、3H 2(g )＋CO 2(g )=CH 3OH (l )＋H 2O (l ) ΔH ＝＋135.9 kJ ·mol －1 【答案】B 【解析】试题分析：A .燃烧热是1mol 的物质完全燃烧产生稳定的氧化物时所放出的热量。