(完整word版)C语言源代码

剪刀石头布源代码#include<stdio.h>#include<stdlib.h>main(){int d,x;{printf(" 请输入:1 是剪刀,2 是石头,3是布");scanf("%d",&d);x=rand()%3;if(d==x)printf(" 双方平局");else if((d==1&&x==2)||(d==2&&x==3)||(d==3&&x==1)) printf("你赢了");elseprintf(" 电脑赢了");}}简单计算器#include<stdio.h>main(){int a,b,d=0;char c;while(d==0){printf(" 请开始计算,请输入需要运算的数字和运算法则,数字符号数字:"); scanf("%d%c%d",&a,&c,&b);switch(c){case'+': printf("%d+%d=%d\n",a,b,a+b); break;case'-':printf("%d-%d=%d\n",a,b,a-b); break;case'*':printf("%d*%d=%d\n",a,b,a*b);break;case'/':if(0==b)printf(" 除法被除数不能为零!\n") ; elseprintf("%d/%d=%d\n",a,b,a/b); break;}}}加油站加油问题#include<stdio.h>int main(){double a = 3.25, b = 3.00, c= 2.75;double d = 0.05, e = 0.10, m;int x,y,z;printf(" 请输入您要的加油量:");scanf("%d",&x);printf(”请输入您要的汽油种类,1-a型汽油售价3.25元/千克,2-b型汽油售价3.00元/千克, 3-c型汽油售价2.75元/千克:”);scanf("%d",&y);printf(" 请输入您要的服务类型,1-自己加服务优惠0.05,2-协助加服务优惠0.10:");scanf("%d",&z);switch(y){case 1:y = a;break;case 2:y = b;break;case 3:y = c;break;}if(z == 1)m = (1 - d) * y * x; else if(z == 2)m = (1 - e) * y * x;",m);printf(" 您需要支付:%f 元,谢谢惠顾,欢迎下次再来return 0;}猜数字游戏#include<stdio.h>#include<stdlib.h>int main(){int d=1,e=0;int a,b,t;printf (" 请输入1-10 以内的整数,\n ");while(d==1){printf(" 玩家的选择: ");scanf("%d",&a);do{if((a>=0)&&(a<11))break; else{printf(" 错误");scanf("%d",&a);}}while(e==0);b=rand()%10+1;printf("npc:%d",b);t=a-b;if(t==0)printf("\nRight!\n");else if(t<0)printf("\n Wrong ! 太小了\ n");else if(t>0)printf("\n Wrong ! 太大了\ n");}return 0;}万年历#include<stdio.h>#include<stdlib.h> void setmonth(int r);void main(void){int year,month,day,a,b,i,j,d,x,mon,k;do{printf(" --------------------------------------------------- \n");printf(" 查全年,输入1!\n");printf(" 查月份,输入2!\n");printf(" 查日期,输入3!\n"); printf(" 继续?输入4!\n");printf(" 退出,输入5!\n"); printf(" ----------------- \n");printf(" 请输入:");scanf("%d",&x);if(x==1){ month=12; printf(" 输入年份:"); scanf("%d",&year);} if(x==2){printf(" 输入年份:"); scanf("%d",&year); printf(" 输入月份:"); scanf("%d",&month);} if(x==3){printf(" 输入年份:"); scanf("%d",&year); printf(" 输入月份:"); scanf("%d",&mon);printf(" 输入日期:"); scanf("%d",&day); month=mon-1;}}if(x==5) exit(100); a=((year-1)*365+(year-1)/4-(year-1)/100+(year-1)/400)%7;for(i=1,d=0;i<=month;i++){ switch(i) { case 1: case 3: case 5: case 7: case 8: case 10: case 12:d=31;break;case 2:if(!(year%4)&&(year%100)||!(year%400)) d=29;elsed=28; break; case 4: case 6: case 9: case 11:d=30;} b=a%7; a+=d; if(x==1){printf("setmonth(i);**\n"); printf("========================================================\n"); printf(" 星期一 星期二 星期三 星期四 星期五 星期天 \n");for(j=1;j<=b;j++) printf("%8c",' '); for(j=1;j<=d;j++) {printf("%8d",j);if((j+b)%7==0) printf("\n");\n");printf( 星期六**\n");printf("========================================================\n");printf(" 星期一 星期二 星期三 星期四 星期五 星期天 \n");for(j=1;j<=b;j++)printf("%8c",' '); for(j=1;j<=d;j++) {printf("%8d",j); if((j+b)%7==0) printf("\n");}printf("\n");}if(x==3){a+=day; a%=7;printf (" 是否继续?输入 4继续,输入 5退出: ");scanf("%d",&k);while(k==4);printf(" }if(x==1)printf("\n");if(x==2)\n");setmonth(i-1);printf( 星期六switch(a){case 0:printf("%d.%d.%d case 1:printf("%d.%d.%d case 2:printf("%d.%d.%d case 3:printf("%d.%d.%d case 4:printf("%d.%d.%d case 5:printf("%d.%d.%d default:printf("%d.%d.%d } printf("\n");}星期一 !",year,mon,day);break;星期二 !",year,mon,day);break;星期三 !",year,mon,day);break;星期四 !",year,mon,day);break;星期五 !",year,mon,day);break;星期六 !",year,mon,day);break;星期天 !",year,mon,day);if(k==5)三 (- --=e H 川。

寸 %==l u _」d o ① SB 。

三 e p fi - --=eHIZ 。

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C语言程序设计 入门源代码代码集合【精选文档】

C语言程序设计 入门源代码代码集合【精选文档】

#include 〈stdio.h〉void print_star(void){printf("*****************\n"); }void print_welcome(void){printf(”C language,welcome!\n");}void main(){print_star();print_welcome();print_star();getchar();}演示2#include "stdio。

h"int sum(int i,int j){return(i + j);}void main(){int n1,n2;printf("input 2 numbers:\n”);scanf("%d%d”,&n1,&n2);printf("the sum = %d\n",sum(n1,n2));getchar();}演示3#include "stdio。

h"int maxnum(int,int,int);main(){int a,b,c;printf("Please enter 3 numbers:\n");scanf(”%d,%d,%d”,&a,&b,&c);printf(”Maxnum is %d\n",maxnum(a,b,c));}int maxnum(int x,int y,int z){int max=x;if(y>max)max = y;if(z>max)max = z;return max;}演示4#include 〈stdio。

h〉int s1(int n){int j,s;s=0;for(j=1;j<=n;j++)s=s+j;return s;}int sum(int n){int i,s=0;for(i=1;i<=n;i++)s=s+s1(i);return s;}void main(){int n;printf(”n:”);scanf(”%d",&n);printf("s=%d\n”,sum(n));}演示5#include <stdio.h〉void func(int n){int i;for(i=n-1;i〉=1;i--)n=n+i;printf("n=%d\n",n);}void main(){int n;printf("Input n:");scanf("%d”,&n);func(n);printf(”n=%d\n",n);}演示6#include <stdio。

(完整word版)进程管理实验报告源代码

(完整word版)进程管理实验报告源代码

实验一进程管理1.目的和要求通过实验理解进程的概念,进程的组成(PCB结构),进程的并发执行和操作系统进行进程管理的相关原语(主要是进程的创建、执行、撤消)。

2.实验内容用C语言编程模拟进程管理,至少要有:创建新的进程;查看运行进程;换出某个进程;杀死运行进程以及进程之间通信等功能。

3.实验环境Windows操作系统、VC++6.0C语言4.实验提示PCB结构通常包括以下信息:进程名,进程优先数,轮转时间片,进程所占用的CPU时间,进程的状态,当前队列指针等。

可根据实验的不同,PCB结构的内容可以作适当的增删。

主体程序#include "conio.h"#include "stdio.h"#include "stdlib.h"struct jincheng_type{int pid;int youxian;int daxiao;int msg;int live;};struct jincheng_type neicun[20],waicun[20];int shumu=0,pid_l;main(){int n,m,i;char a;n=1;while(n==1){system("cls");printf("\n********************************************");printf("\n* 进程演示系统*");printf("\n********************************************");printf("\n 1.创建新的进程 2.查看运行进程");printf("\n 3.换出某个进程 4.杀死运行进程");printf("\n 5.进程之间通信 6.退出");printf("\n********************************************");printf("\n请选择(1~6) ");a=getch();switch(a){case'1':create( );break;case'2':viewrun( );break;case'3':huanchu();break;case'4':kill( );break;case'5':tongxun( );break;case'6': exit(0);default: n=0;}}}create( ) /* 创建一个进程的示例(不完整的程序)*/ {if(shumu>=20){printf("\n内存已满,请先结束或换出进程\n");}else{printf("\n请输入新进程的pid\n");scanf("%d",&neicun[shumu+1].pid);printf("\n请输入新进程的优先级\n");scanf("%d",&neicun[shumu+1].youxian);printf("\n请输入新进程的大小\n");scanf("%d",&neicun[shumu+1].daxiao);printf("\n请输入新进程的消息\n");scanf("%d",&neicun[shumu+1].msg);neicun[shumu+1].live=1;shumu++;}return neicun[shumu-1].live;}viewrun( )/*查看运行进程*/{int vpid;printf("\n请输入进程的pid\n");scanf("%d",&vpid);if(vpid>0&&vpid<=20&&neicun[vpid].live==1){printf("\n进程的pid是: %d\n",neicun[vpid].pid);printf("进程的优先级是: %d\n",neicun[vpid].youxian);printf("进程的大小是:%d\n",neicun[vpid].daxiao);printf("进程的消息是:%d\n",neicun[vpid].msg);}else{printf("\n所查看运行进程不存在\n");}printf("请按回车退出查看\n");vpid=getch();}huanchu()/*换出某个进程*/{int pid1,pid2;char c;printf("\n请输入第一个替换进程的pid\n");scanf("%d",&pid1);printf("\n请输入第二个替换进程的pid\n");scanf("%d",&pid2);if(pid1>0&&pid1<=20&&neicun[pid1].live==1){if(neicun[pid1].youxian>neicun[pid2].youxian){waicun[20].pid=neicun[pid1].pid;waicun[20].youxian=neicun[pid1].youxian;waicun[20].daxiao=neicun[pid1].daxiao;waicun[20].msg=neicun[pid1].msg;neicun[pid1].pid=neicun[pid2].pid;neicun[pid1].youxian=neicun[pid2].youxian;neicun[pid1].daxiao=neicun[pid2].daxiao;neicun[pid1].msg=neicun[pid2].msg;neicun[pid2].pid=waicun[20].pid;neicun[pid2].youxian=waicun[20].youxian;neicun[pid2].daxiao=waicun[20].daxiao;neicun[pid2].msg=waicun[20].msg;printf("\n替换完成\n");printf("\n被替换进程的pid是: %d\n",waicun[20].pid); printf("被替换进程的优先级是: %d\n",waicun[20].youxian); printf("被替换进程的大小是:%d\n",waicun[20].daxiao); printf("被替换进程的消息是:%d\n",waicun[20].msg);}else{printf("\n进程优先级不够大");}}else{printf("所查看运行进程不存在");}printf("请按回车退出换出进程\n");c=getche();return;}kill()/*杀死运行进程*/{int kpid;printf("\n请输入进程的pid\n");scanf("%d",&kpid);if(kpid>0&&kpid<20&&neicun[kpid].live==1){neicun[kpid].live=0;}return;}tongxun( )/*进程之间通信*/{int tpid1,tpid2;int buffer;char d;printf("\n请输入通信源进程pid\n");scanf("%d",&tpid1);printf("\n请输入通信目的进程pid\n");scanf("%d",&tpid2);if(tpid1>0&&tpid1<20&&neicun[tpid1].live==1){buffer=neicun[tpid1].msg;neicun[tpid1].msg=neicun[tpid2].msg;neicun[tpid2].msg=buffer;printf("\n源进程的消息是: %d\n",neicun[tpid1].msg);printf("\n目的进程的消息是: %d\n",neicun[tpid2].msg);}else{printf("\n所查看运行进程不存在\n");}printf("\n请按回车退出进程通信\n");d=getch();return;}5.实验运行结果******************************************** * 进程演示系统* ********************************************1.创建新的进程2.查看运行进程3.换出某个进程4.杀死运行进程5.进程之间通信6.退出系统******************************************** 请选择(1~6)然后根据你选择的不同,出现不同的结果。

C语言游戏源代码

C语言游戏源代码

C语言游戏源代码1、简单的开机密码程序#include "conio.h"#include "string.h"#include "stdio.h"void error(){window(12,10,68,10);textbackground(15);textcolor(132);clrscr();cprintf("file or system error! you can't enter thesystem!!!"); while(1); /* 若有错误不能通过程序 */}void look(){FILE *fauto,*fbak;char *pass="c:\\windows\\password.exe"; /* 本程序的位置 */char a[25],ch;char *au="autoexec.bat",*bname="hecfback.^^^"; /*bname 是autoexec.bat 的备份 */setdisk(2); /*set currently disk c:*/chdir("\\"); /*set currently directory \*/fauto=fopen(au,"r+");if (fauto==NULL){fauto=fopen(au,"w+");if (fauto==NULL) error();}fread(a,23,1,fauto); /* 读取 autoexec.bat 前 23 各字符 */a[23]='\0';if (strcmp(a,pass)==0) /* 若读取的和 pass 指针一样就关闭文件,不然就添加 */fclose(fauto);else{fbak=fopen(bname,"w+");if (fbak==NULL) error();fwrite(pass,23,1,fbak);fputc('\n',fbak);rewind(fauto);while(!feof(fauto)){ch=fgetc(fauto);fputc(ch,fbak);}rewind(fauto);rewind(fbak);while(!feof(fbak)){ch=fgetc(fbak);fputc(ch,fauto);}fclose(fauto);fclose(fbak);remove(bname); /*del bname file*/}}void pass(){char *password="88888888";char input[60];int n;while(1){window(1,1,80,25);textbackground(0);textcolor(15);clrscr();n=0;window(20,12,60,12);textbackground(1);textcolor(15);clrscr();cprintf("password:");while(1){input[n]=getch();if (n>58) {putchar(7); break;} /* 若字符多于 58 个字符就结束本次输入 */if (input[n]==13) break;if (input[n]>=32 && input[n]<=122) /* 若字符是数字或字母才算数*/ {putchar('*');n++;}if (input[n]==8) /* 删除键 */if (n>0){cprintf("\b \b");input[n]='\0';n--;}}input[n]='\0';if (strcmp(password,input)==0)break;else{putchar(7);window(30,14,50,14);textbackground(15);textcolor(132);clrscr();cprintf("password error!");getch();}}}main(){look();pass();}2、彩色贪吃蛇#include <graphics.h>#include <stdlib.h>#define N 200#define up 0x4800#define down 0x5000#define left 0x4b00#define right 0x4d00#define esc 0x011b#define Y 0x1579#define n 0x316eint gamespeed; /* 游戏速度 */int i, key, color;int score = 0; /* 游戏分数 */char cai48H[] ={0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x04, 0x00, 0x18, 0x00, 0x00, 0x00, 0x0E, 0x00,0x1C, 0x00, 0x00, 0x00, 0x1C, 0x00, 0x1C, 0x00,0x00, 0x00, 0x20, 0x00, 0x38, 0x00, 0x00, 0x00,0x40, 0x00, 0x78, 0x00, 0x00, 0x01, 0x80, 0x40,0x70, 0x00, 0x00, 0x03, 0x80, 0xC0, 0xE0, 0x00,0x00, 0x07, 0x80, 0x80, 0xC0, 0x00, 0x00, 0x0E,0x11, 0x81, 0xC0, 0x00, 0x00, 0x08, 0x61, 0x01,0x80, 0x00, 0x00, 0x00, 0x23, 0x03, 0x04, 0x00,0x00, 0x02, 0x02, 0x00, 0x06, 0x00, 0x00, 0x1E,0x04, 0x00, 0x0F, 0x00, 0x00, 0x1C, 0x1F, 0x80,0xF0, 0x00, 0x00, 0x7F, 0xF0, 0x00, 0xE0, 0x00, 文档大全实用标准0x03, 0xFF, 0xFC, 0x01, 0x80, 0x00, 0x03, 0xC0,0xFF, 0x01, 0x03, 0x80, 0x01, 0x01, 0xFF, 0x00,0x03, 0x80, 0x00, 0x01, 0x3F, 0x00, 0x07, 0x80,0x00, 0x02, 0x11, 0x00, 0x07, 0x00, 0x00, 0x00,0x10, 0x00, 0x07, 0x00, 0x00, 0x00, 0x10, 0x00,0x0E, 0x00, 0x00, 0x08, 0x10, 0x00, 0x1C, 0x00,0x00, 0x30, 0x10, 0x00, 0x18, 0x00, 0x00, 0x70,0x10, 0x00, 0x30, 0x00, 0x01, 0xE0, 0x10, 0x00,0x70, 0x00, 0x03, 0x80, 0x10, 0x00, 0x60, 0x00,0x00, 0x00, 0x30, 0x00, 0xE0, 0x00, 0x00, 0x00,0xF0, 0x01, 0xC0, 0x00, 0x00, 0x00, 0x70, 0x03,0xC0, 0x00, 0x00, 0x00, 0x10, 0x07, 0x80, 0x00,0x00, 0x00, 0x00, 0x0F, 0x00, 0x00, 0x00, 0x00,0x00, 0x1E, 0x00, 0x00, 0x00, 0x00, 0x00, 0x3C,0x00, 0x00, 0x00, 0x00, 0x00, 0x70, 0x00, 0x00,0x00, 0x00, 0x01, 0xC0, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, };char she48H[] ={0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x04,0x00, 0x00, 0x00, 0x00, 0x00, 0x0C, 0x00, 0x00,0x00, 0x00, 0x00, 0x0E, 0x00, 0x00, 0x00, 0x00,0x00, 0x0E, 0x00, 0x00, 0x00, 0x03, 0x00, 0x07,0x00, 0x00, 0x00, 0x02, 0x00, 0x03, 0x00, 0x00,0x00, 0x02, 0x00, 0x00, 0x00, 0x00, 0x00, 0x02,0x00, 0x00, 0xF8, 0x00, 0x00, 0x02, 0x00, 0x07,0x86, 0x00, 0x00, 0x02, 0x00, 0x18, 0x03, 0x00,0x00, 0x02, 0x00, 0x00, 0x07, 0x80, 0x00, 0x03,0xF0, 0x00, 0x07, 0x80, 0x00, 0x0F, 0xFC, 0x00,0x0C, 0x00, 0x00, 0x7E, 0x3F, 0x80, 0x00, 0x00,0x01, 0xFE, 0x1F, 0x80, 0x00, 0x00, 0x01, 0xE2,0x39, 0x8C, 0x00, 0x00, 0x00, 0xC2, 0x30, 0x08,0xE0, 0x01, 0xE0, 0x00, 0x00, 0x3F, 0x80, 0x1F,0xE0, 0x00, 0x00, 0x1E, 0x00, 0x1F, 0x80, 0x00,0x00, 0x1E, 0x00, 0x1F, 0x00, 0x00, 0x00, 0x02, 文档大全实用标准0x38, 0x1E, 0x00, 0x00, 0x00, 0x07, 0xFC, 0x1C,0x00, 0x20, 0x00, 0x07, 0xFC, 0x18, 0x00, 0x20,0x00, 0x1F, 0x0C, 0x10, 0x00, 0x20, 0x00, 0x7C,0x04, 0x10, 0x00, 0x60, 0x01, 0xF0, 0x00, 0x10,0x00, 0x60, 0x01, 0xE0, 0x00, 0x08, 0x00, 0xF0,0x00, 0x80, 0x00, 0x08, 0x03, 0xF0, 0x00, 0x00,0x00, 0x07, 0xFF, 0xF0, 0x00, 0x00, 0x00, 0x07,0xFF, 0xF0, 0x00, 0x00, 0x00, 0x03, 0xFF, 0xE0,0x00, 0x00, 0x00, 0x01, 0xFF, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, };char tun48H[] ={0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x0E, 0x00, 0x00, 0x00, 0x00, 0x00, 0x3E,0x00, 0x00, 0x00, 0x00, 0x00, 0x7F, 0x00, 0x00,0x00, 0x00, 0x00, 0xE0, 0x00, 0x00, 0x00, 0x00,0x03, 0xC0, 0x00, 0x00, 0x00, 0x00, 0x1F, 0x00,0x00, 0x00, 0x00, 0x00, 0x7C, 0x00, 0x00, 0x00,0x00, 0x01, 0xF8, 0x00, 0x00, 0x00, 0x00, 0x03,0xF8, 0x00, 0x40, 0x00, 0x00, 0x00, 0x06, 0x07,0xC0, 0x00, 0x00, 0x00, 0x07, 0xFF, 0xE0, 0x00,0x00, 0x00, 0x07, 0xFF, 0xE0, 0x00, 0x00, 0x00,0x0F, 0xFF, 0x80, 0x00, 0x00, 0x00, 0x7F, 0xF8,0x00, 0x00, 0x00, 0x1F, 0xFF, 0xF8, 0x00, 0x00,0x00, 0x1F, 0xFF, 0xF8, 0x00, 0x00, 0x00, 0x1F,0xFC, 0x3C, 0x00, 0x00, 0x00, 0x0F, 0xF8, 0x0E,0x00, 0x00, 0x00, 0x04, 0x70, 0x07, 0x00, 0x00,0x00, 0x00, 0x60, 0x03, 0x80, 0x00, 0x00, 0x00,0xC0, 0x00, 0xC0, 0x00, 0x00, 0x01, 0x80, 0x00,0x30, 0x00, 0x00, 0x01, 0x00, 0x3C, 0x18, 0x00,0x00, 0x02, 0x03, 0xFF, 0x0C, 0x00, 0x00, 0x0C,0x01, 0xF0, 0x70, 0x07, 0x03, 0xF8, 0x07, 0xE0,0x70, 0x0E, 0x03, 0xFE, 0x00, 0x00, 0x38, 0x1E,0x01, 0xFE, 0x00, 0x00, 0x3F, 0xFE, 0x00, 0x0C, 文档大全实用标准0x00, 0x00, 0x1F, 0xFE, 0x00, 0x00, 0x00, 0x00,0x1F, 0xFE, 0x00, 0x00, 0x00, 0x00, 0x0F, 0xFE,0x00, 0x00, 0x00, 0x00, 0x04, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, };char dan48H[] ={0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0xFC, 0x00, 0x00, 0x00, 0x00, 0x07, 0xFF,0x00, 0x00, 0x00, 0x00, 0x7F, 0xC0, 0x80, 0x00,0x00, 0x03, 0xFF, 0x80, 0x40, 0x00, 0x00, 0x01,0xF1, 0x80, 0x40, 0x00, 0x00, 0x01, 0x81, 0x80,0xE0, 0x00, 0x00, 0x00, 0x01, 0x93, 0xF0, 0x00,0x00, 0x00, 0x01, 0xFF, 0xF0, 0x00, 0x00, 0x00,0x21, 0xFF, 0xF0, 0x00, 0x00, 0x00, 0x21, 0xF8,0x00, 0x00, 0x00, 0x00, 0x61, 0xC0, 0x00, 0x00,0x00, 0x00, 0x61, 0x80, 0x00, 0x00, 0x00, 0x00,0xF3, 0x00, 0x00, 0x00, 0x00, 0x00, 0xFF, 0x00,0x00, 0x00, 0x00, 0x01, 0xFF, 0xC0, 0x00, 0x00,0x00, 0x03, 0xFF, 0xF8, 0x00, 0x00, 0x00, 0x02,0x00, 0xFC, 0x00, 0x00, 0x00, 0x04, 0x02, 0x1F,0x00, 0x00, 0x00, 0x08, 0x03, 0x01, 0xC0, 0x00,0x00, 0x38, 0x03, 0x00, 0x7C, 0x00, 0x00, 0xF8,0x07, 0xF8, 0x3F, 0xC0, 0x01, 0xF0, 0x3F, 0xFE,0x3F, 0xF8, 0x03, 0xC1, 0xFF, 0x0F, 0x1F, 0xF8,0x00, 0x01, 0xE3, 0x0F, 0x0F, 0xF0, 0x00, 0x01,0xC3, 0x0E, 0x00, 0x00, 0x00, 0x01, 0x83, 0xFC,0x00, 0x00, 0x00, 0x00, 0xC7, 0xF8, 0x00, 0x00,0x00, 0x00, 0xFF, 0xF8, 0x00, 0x00, 0x00, 0x00,0x7F, 0xF0, 0x00, 0x00, 0x00, 0x00, 0x3F, 0x03,0x80, 0x00, 0x00, 0x00, 0x03, 0x04, 0x00, 0x00,0xE0, 0x00, 0x00, 0x07, 0xFF, 0x81, 0xE0, 0x00,0x00, 0x07, 0xE0, 0x00, 0xE0, 0x00, 0x00, 0x03,0x00, 0x00, 0x60, 0x00, 0x00, 0x00, 0x00, 0x00, 文档大全实用标准0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, };char zuo16H[] ={0x18, 0xC0, 0x18, 0xC0, 0x19, 0x80, 0x31, 0xFE,0x33, 0xFE, 0x76, 0xC0, 0xF0, 0xFC, 0xB0, 0xFC,0x30, 0xC0, 0x30, 0xC0, 0x30, 0xFE, 0x30, 0xFE,0x30, 0xC0, 0x30, 0xC0, 0x30, 0xC0, 0x00, 0x00, };char zhe16H[] ={0x03, 0x00, 0x03, 0x0C, 0x1F, 0xCC, 0x1F, 0xD8,0x03, 0x30, 0xFF, 0xFE, 0xFF, 0xFE, 0x03, 0x00,0x0F, 0xF8, 0x3F, 0xF8, 0xEC, 0x18, 0xCF, 0xF8,0x0C, 0x18, 0x0F, 0xF8, 0x0F, 0xF8, 0x00, 0x00, };char tian16H[] ={0x00, 0x00, 0x3F, 0xFC, 0x3F, 0xFC, 0x31, 0x8C,0x31, 0x8C, 0x31, 0x8C, 0x3F, 0xFC, 0x3F, 0xFC,0x31, 0x8C, 0x31, 0x8C, 0x31, 0x8C, 0x3F, 0xFC,0x3F, 0xFC, 0x30, 0x0C, 0x00, 0x00, 0x00, 0x00, };char xue16H[] ={0x33, 0x18, 0x19, 0x98, 0x08, 0xB0, 0x7F, 0xFC,0x7F, 0xFC, 0x60, 0x0C, 0x1F, 0xF0, 0x1F, 0xF0,0x00, 0xC0, 0x7F, 0xFC, 0x7F, 0xFC, 0x01, 0x80,0x01, 0x80, 0x07, 0x80, 0x03, 0x00, 0x00, 0x00, };char ke16H[] ={0x00, 0x00, 0x0C, 0x18, 0xFD, 0x98, 0xF8, 0xD8,0x18, 0x58, 0xFE, 0x18, 0xFE, 0x98, 0x18, 0xD8,0x3C, 0x58, 0x7E, 0x1E, 0xDB, 0xFE, 0x9B, 0xF8,0x18, 0x18, 0x18, 0x18, 0x18, 0x18, 0x00, 0x00, };文档大全实用标准struct Food/* 定义结构体存储食物的属性*/{int x; /* 食物的坐标 */int y;int yes; /* 值为 0 表示屏幕上没有食物,值为 1 表示屏幕上有食物 */int color; /* 食物颜色 */} food;struct Snake/* 定义结构体存储蛇的属性*/{int x[N]; /* 每一节蛇的坐标*/int y[N];int color[N];/* 存储每一节蛇的颜色 */int node; /* 蛇的节数 */int direction; /* 蛇移动的方向 */int life; /* 蛇的生命,如果为1,蛇死,游戏结束*/} snake;void init(void)/* 图形驱动 */{int driver = DETECT, mode = 0;registerbgidriver(EGAVGA_driver);initgraph(&driver, &mode, "");}void drawmat(char *mat, int matsize, int x, int y, int color) /* 汉字点阵*/{int i, j, k, m;m = (matsize - 1) / 8 + 1;for(j = 0; j < matsize; j++)for(i = 0; i < m; i++)for(k = 0; k < 8; k++)if(mat[j*m+i]&(0x80 >> k))putpixel(x + i * 8 + k, y + j, color); }void showword(void){/* 调用汉字点阵输出程序,显示标题和作者信息*/drawmat(cai48H, 48, 249, -4, 7);drawmat(she48H, 48, 329, -4, 7);drawmat(tun48H, 48, 409, -4, 7); 文档大全实用标准drawmat(dan48H, 48, 489, -4, 7);drawmat(cai48H, 48, 250, -5, 4);drawmat(she48H, 48, 330, -5, 4);drawmat(tun48H, 48, 410, -5, 4);drawmat(dan48H, 48, 490, -5, 4);/* 作者田学科 */drawmat(zuo16H, 16, 515, 465, 7);drawmat(zhe16H, 16, 530, 465, 7);drawmat(tian16H, 16, 550, 465, 7);drawmat(xue16H, 16, 565, 465, 7);drawmat(ke16H, 16, 580, 465, 7);}void draw(void)/* 画出四周的墙*/{if(color == 15)color = 0;setcolor(++color);setlinestyle(SOLID_LINE, 0, 1);for(i = 30; i <= 600; i += 10){rectangle(i, 40, i + 10, 49);rectangle(i, 451, i + 10, 460);}for(i = 40; i < 450; i += 10){rectangle(30, i, 39, i + 10);rectangle(601, i, 610, i + 10);}}void prscore(void){/* 打印游戏分数*/char str[10];setfillstyle(SOLID_FILL, YELLOW);bar(50, 10, 200, 30);setcolor(6);settextstyle(0, 0, 2);sprintf(str, "score:%d", score);outtextxy(55, 15, str);文档大全实用标准}void gameover(void){cleardevice(); /* 清屏函数 */for(i = 0; i < snake.node; i++) /* 画出蛇死时的位置*/{setcolor(snake.color[i]);rectangle(snake.x[i], snake.y[i], snake.x[i] + 10, snake.y[i] + 10);}prscore(); /* 显示分数 */draw();showword();settextstyle(0, 0, 6);setcolor(7);outtextxy(103, 203, "GAME OVER");setcolor(RED);outtextxy(100, 200, "GAME OVER");}void gameplay(void)/* 玩游戏的具体过程*/{int flag, flag1;randomize();prscore();gamespeed = 50000;food.yes = 0; /* food.yes=0 表示屏幕上没有食物*/snake.life = 1; /* snake.life=1 表示蛇是活着的*/snake.direction = 4; /* 表示蛇的初始方向为向右*/snake.node = 2; /* 蛇的初始化为两节*/snake.color[0] = 2; /* 两节蛇头初始化为绿色 */snake.color[1] = 2;snake.x[0] = 100;snake.y[0] = 100;snake.x[1] = 110;snake.y[1] = 100;food.color = random(15) + 1;while(1){while(1){if(food.yes == 0) /* 如果蛇活着 */{ 文档大全实用标准while(1){flag = 1;food.yes = 1;food.x = random(56) * 10 + 40;food.y = random(40) * 10 + 50;for(i = 0; i < snake.node; i++){if(food.x == snake.x[i] && food.y == snake.y[i])flag = 0;}if(flag)break;}}if(food.yes){setcolor(food.color);rectangle(food.x, food.y, food.x + 10, food.y + 10);}for(i = snake.node - 1; i > 0; i--){snake.x[i] = snake.x[i-1];snake.y[i] = snake.y[i-1];}switch(snake.direction){case 1:snake.y[0] -= 10;break;case 2:snake.y[0] += 10;break;case 3:snake.x[0] -= 10;break;case 4:snake.x[0] += 10;break;}文档大全实用标准for(i = 3; i < snake.node; i++){if(snake.x[i] == snake.x[0] && snake.y[i]== snake.y[0]){gameover();snake.life = 0;break;}}if(snake.x[0] < 40 || snake.x[0] > 590 || snake.y[0] < 50 || snake.y[0] > 440){gameover();snake.life = 0;}if(snake.life == 0)break;if(snake.x[0] == food.x && snake.y[0] == food.y) /* 蛇吃掉食物 */{setcolor(0);rectangle(food.x, food.y, food.x + 10, food.y + 10);snake.x[snake.node] = -20;snake.y[snake.node] = -20;snake.color[snake.node] = food.color;snake.node++;food.yes = 0;food.color = random(15) + 1;score += 10;prscore();if(score % 100 == 0 && score != 0){for(i = 0; i < snake.node; i++) /* 画出蛇 */{setcolor(snake.color[i]);rectangle(snake.x[i], snake.y[i], snake.x[i] + 10, snake.y[i] + 10);}文档大全实用标准sound(200);delay(50000);delay(50000);delay(50000);delay(50000);delay(50000);delay(50000);nosound();gamespeed -= 5000;draw();}else{sound(500);delay(500);nosound();}}for(i = 0; i < snake.node; i++) /* 画出蛇 */{setcolor(snake.color[i]);rectangle(snake.x[i], snake.y[i], snake.x[i] + 10, snake.y[i] + 10);}delay(gamespeed);delay(gamespeed);flag1 = 1;setcolor(0);rectangle(snake.x[snake.node-1], snake.y[snake.node-1],snake.x[snake.node-1] + 10, snake.y[snake.node-1] + 10);if(kbhit() && flag1 == 1) /* 如果没按有效键就重新开始循环 */{flag1 = 0;key = bioskey(0);if(key == esc)exit(0);else if(key == up && snake.direction != 2)snake.direction = 1;文档大全实用标准else if(key== down &&snake.direction != 1) snake.direction = 2;else if(key== left &&snake.direction != 4) snake.direction = 3;else if(key == right &&snake.direction !=3)snake.direction = 4;}}if(snake.life == 0) /* 如果蛇死了就退出循环*/break;}}void main(void){while(1){color = 0;init();cleardevice();showword();draw();gameplay();setcolor(15);settextstyle(0, 0, 2);outtextxy(200, 400, "CONTINUE(Y/N)?");while(1){key = bioskey(0);if(key == Y || key == n || key == esc)break;}if(key == n || key == esc)break;}closegraph();}3、 c 语言实现移动电话系统#include <stdio.h>#define GRID-SIZE 5#define SELECTED -1 /* 低于矩阵中所有元素*/ 文档大全实用标准#define TRAFFIC-FILE “ traffic.dat ” /* 关于交通数据的文件*/#define NUM-TRANSMITTERS 10 /* 可用的发射器数量 */void get-traffic-data(int commuters[GRID-SIZE][GRID-SIZE],int salesforce[GRID-SIZE][GRID-SIZE],int weekends [GRID-SIZE][GRID-SIZE];voide print-matrix[GRID-SIZE][GRID-SIZE];intmain(void){int commuters[GRID-SIZE][GRID-SIZE];/* 上午 8: 30 的交通数据 */int salesforce[GRID-SIZE][GRID-SIZE]; /* 上午 11: 00 的交通数据*/int weekend[GRID-SIZE][GRID-SIZE];/* 周末交通数据 */int commuter-weight, /* 通勤人员数据的权重因子 */sale-weight,/* 营销人员数据的权重因子*/weekend-weight ;/* 周末数据的权重因子 */int location-i ,/* 每个发射器的位置 */location-j ;int current-max ;/* 和数据中当前的最大值 */int i , j ,/* 矩阵的循环计数器 */tr ;/* 发射器的循环计数器 *//* 填入并显示交通数据*/Get-traffic-data ( commuters , salesforce ,weekend);Printf (“ 8: 30 A.M.WEEKDAY TRAFFIC DATA 、 \n\n ”)print-matrix(commuters);printf( “ \n\n WEEKEND TRAFFIC DATA\n\n ” );print-matrix(salesforce);printf( “ \n\n WEEKEND TRAFFIC DATA\n\n ” );printf_matrix(weekeng);/* 请用户输入权重因子*/printf( “ \n\nPlease input the following value:\n ”);printf( “ Weight (an interger>=0) for the 8:30 muter data> ”)scanf( “ %d” ,&commuter_weight);printf( “ weight(an integer>=0) for the weekeng data> ” );scanf( “ %d” ,&weekend_weight);scanf( “ %d” ,&weekend_weight);/* 计算并显示加权后求和的数据*/for (i=0;i<GRID_SIZE;++i)for (j=0;j<GRID_SIZE;++j)summed_data[i][j]=commuter_weight*commuter[i][j]+文档大全实用标准salesforce_weight*salesforce[i][j]+weekend_weight*weekend[i][j]; printf( “ \n\nThe weighted,summed data is :\n\n ” );printf_matrix(summed_data);/* 在 summed_data 矩阵中找出 NUM_TRANSMITTERS个最大值,将坐标临时存储在location_i 和 location_j 中,然后把最后的结果坐标输出*/printf( “ \n\nLocations of the %d transmitters:\n\n ” ,NUM_TRANSMITTERS);for (tr=1;tr<=NUM_TRANSMITTERS;++tr){current_max=SELECTED ; /* 以一个过低的值为起点开始查找*/for (i=0;i<GRID_SIZE;++i){for(j=0;j<GRID_SIZE;++j){if(current_max<summed_data[i][j]){current_max=summed_data[i][j]){location_i=i;location_j=j;}}}/* 将选中的单元赋一较低的值以避免下次再选中这一元素,显示查找结果*/ summed_data[location_i][location_j]=SELECTED;printf( “ Transmitter %3d:at location %3d %3d\n ” ,tr,location_i,location_j);}return (0);}/** 把 TRAFFIC_FILE 中的交通数据填充到3 个 GRID_SIZE×GRID_SIZE数组中*/voidget_traffic_data(int commuters[GRID_SIZE] ,/* 输出 */int salesforce[GRID_SIZE][GRID_SIZE],/*输出 */int weekend[GRID_SIZE][GRID_SIZE] , /* 输出*/{int i,j; /* 循环计数器 */FILE *fp; /* 文件指针 */fq=fopen(TRAFFIC_FILE, “ r ” );for(i=0 ; i<GRID_SIZE;++i)for(j=0;j<GRID_SIZE;++j)fscanf(fp, “ %d” ,&commnters[i][j]; 文档大全实用标准for(i=0;i<GRID_SIZE;++j)for(j=0;j<GRID_SIZE;++j)fscanf(fq, “ %d”, &weekend[i][j]);fclose(fq);}/** 显示一个GRID_SIZE× GRID_SIZE整数矩阵的内容*/voidprint_matrix(int matrix[GRID_SIZE][GRID_SIZE]){int i,j; /* 循环计数器 */for(i=0;i<GRID_SIZE;++j){for(j=0;j<GRID_SIZE;++J)printf( “ %3d” ,matrix[i][j]);printf( “ \n ” );}}4、扑克牌游戏/*************************************Copyright(C) 2004-2005 vision,math,NJU .File Name: guess_card.cppAuthor: vision Version: 1.0 Data: 23-2-2004Description:给你 9张牌 , 然后让你在心中记住那张牌, 然后电脑分组让你猜你记住的牌在第几组 , 然后猜出你记住的那张牌 .Other: 出自儿童时的一个小魔术History: 修改历史**************************************/ #include <stdio.h>#include <stdlib.h>#include <string.h>#include <time.h>#include <assert.h>#define CARDSIZE 52 /* 牌的总张数*/#define SUITSIZE 13 /* 一色牌的张数*//* 扑克牌结构 */typedef struct Card{char val;/* 扑克牌面上的大小 */int kind :4; /* 扑克牌的花色*/}Card;文档大全实用标准/*************************************************Function: // riffleDescription: // 洗牌 , 然后随机的得到 9 张牌 , 要求九张牌不能有重复.Calls: //Called By: // main()Table Accessed: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Table Updated: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Input: //Card card[] 牌结构 , int size 结构数组的大小Output: //Return: // voidOthers: // 此函数修改 card[] 的值 , 希望得到九张随机牌Bug: // 此函数有bug,有时会产生两个相同的牌,有待修订*************************************************/void riffle(Card *cards, int size);/*************************************************Function: // showDescription: // 显示数组的内容Calls: //Called By: // main()Table Accessed: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Table Updated: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Input: //Card *card 牌结构指针 , int size 结构数组的大小Output: //Return: // voidOthers: //*************************************************/void show(const Card *cards, int size);/*************************************************Function: // groupingDescription: // 把9 张牌分别放到 3 个数组中, 每组3 张 ,a.e 分组Calls: //Called By: // main()Table Accessed: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Table Updated: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Input: //Card *card 牌结构指针 , int size 结构数组的大小Output: //Return: // voidOthers: // 此函数修改 *carr1,*carr2,* carr3 的值文档大全实用标准*************************************************/void grouping(const Card *cards, Card *carr1, Card *carr2, Card *carr3);/*************************************************Function: // result_processDescription: // 用递归计算, 所选的牌Calls: // rshiftCalled By: // main()Table Accessed: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Table Updated: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Input: //Card *carr1, Card *carr2, Card *carr3Output: //Return: // voidOthers: // 此函数修改 *carr1,*carr2,* carr3 的值*************************************************/Card* result_process(Card *carr1, Card *carr2, Card *carr3, int counter);/*************************************************Function: // rshiftDescription: // 右移操作Calls: //Called By: // result_processTable Accessed: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Table Updated: // 被修改的表(此项仅对于牵扯到数据库操作的程序)Input: //Card *carr1, Card *carr2, Card *carr3 ,int counterOutput: //Return: // Card*Others: // 此函数修改 *carr1,*carr2,* carr3 的值*************************************************/void rshift(Card *carr1, Card *carr2, Card *carr3, int counter);void main(){Card cards[9]; /* 存放九张牌 */Card carr1[3]; /* 第一组牌 ,cards array 1*/Card carr2[3]; /* 第二组牌 ,cards array 2*/Card carr3[3]; /* 第三组牌 ,cards array 3*/int select = 0; /* 玩家的选择 */Card *selected_card;/* 存放玩家所记住( 选 ) 的牌 */int counter = 0;riffle(cards, 9); /* 洗牌 , 得到九张牌 */puts(" 请记住一张牌千万别告诉我! 最多经过下面三次我与你的对话, 我就会知道你所记的那张牌 !");puts(" 如果想继续玩 , 请准确的回答我问你的问题, 根据提示回答!"); 文档大全实用标准puts(" 请放心 , 我不会问你你选了哪张牌的!");grouping(cards, carr1, carr2, carr3); /* 把 9 张牌分别放到3 个数组中 , 每组 3 张,a.e 分组 */show(carr1, 3);show(carr2, 3);show(carr3, 3);puts(" 请告诉我你记住的那张牌所在行数");select = getchar();switch(select)/* 分支猜你玩家记住的牌 */{case '1':selected_card = result_process(carr1, carr2, carr3, counter);break;case '2':selected_card = result_process(carr2, carr3, carr1, counter);break;case '3':selected_card = result_process(carr3, carr1, carr2, counter);break;default:puts(" 你在撒谎!不和你玩了! ");fflush(stdin);getchar();exit(0);}if( selected_card ==NULL){fflush(stdin);getchar();exit(0);}puts(" 你猜的牌为 :");show(selected_card, 1);puts(" 我猜的对吧 , 哈哈 ~~~~");fflush(stdin);getchar();}/*riffle 的原代码 */void riffle(Card *cards, int size){char deck[CARDSIZE];/* 临时数组,用于存储牌 */unsigned int seed;/* 最为产生随机数的种的 */int deckp = 0; /* 在牌的产生中起着指示作用*/文档大全实用标准seed = (unsigned int)time(NULL);srand(seed);/* 洗牌 */while (deckp < CARDSIZE){char num = rand() % CARDSIZE;if ((memchr(deck, num, deckp)) == 0){assert(!memchr(deck,num,deckp));deck[deckp] = num;deckp++;}}/* 找 9 张牌给 card*/for (deckp = 0; deckp < size; deckp++){div_t card = div(deck[deckp], SUITSIZE);cards[deckp].val = "A23456789TJQK"[card.rem]; /* 把余数给 card.val*/ cards[deckp].kind = "3456"[card.quot]; /* 把商给 card.kind*/}}/*show 的原代码,将会自动换行*/void show(const Card *cards, int size){for(int i = 0; i < size; i++){printf("%c%c ",cards[i].kind,cards[i].val);if( (i !=0) && (((i+1 ) % 3) == 0))puts("");}puts(""); /* 自动换行 */}/*grouping 的原代码 */void grouping(const Card *cards, Card *carr1, Card *carr2, Card *carr3) {int i = 0;/* 循环参数 *//* 分给 carr1 三个数 */while (i < 3){carr1[i].val = cards[i].val;carr1[i].kind = cards[i].kind; 文档大全实用标准i++;}/* 分给 carr2 接下来的三个数 */while (i < 6){carr2[i-3].val = cards[i].val;carr2[i-3].kind = cards[i].kind;i++;}/* 分给 carr3 接下来的三个数*/while (i < 9){carr3[i-6].val = cards[i].val;carr3[i-6].kind = cards[i].kind;i++;}}/*rshift 的实现 */void rshift(Card *carr1, Card *carr2, Card *carr3, int counter) {Card temp2;/* 用于存放 carr2[counter]*/Card temp3;/* 用于存放 carr3[counter]*//*temp = carr2*/temp2.val = carr2[counter].val;temp2.kind = carr2[counter].kind;/*carr2 = carr1*/carr2[counter].val = carr1[counter].val;carr2[counter].kind = carr1[counter].kind;/*temp3 = carr3*/temp3.val = carr3[counter].val;temp3.kind = carr3[counter].kind;/*carr3 = carr2*/carr3[counter].val = temp2.val;carr3[counter].kind = temp2.kind;/*carr1 = carr3*/carr1[counter].val = temp3.val;carr1[counter].kind = temp3.kind;}rshift(carr1, carr2, carr3, counter); /* 把数组的第一个元素依次右移 */ if(counter == 2)文档大全实用标准{return(&carr2[2]);}show(carr1, 3);show(carr2, 3);show(carr3, 3);puts(" 请给出你记住的牌所在行数:");fflush(stdin);int input = 1;input = getchar(); /* 获取你选的组 */switch(input){case '1':return(result_process(carr1, carr2, carr3, ++counter));break;case '2':return(&carr2[counter]);break;default:puts(" 你在撒谎!不和你玩了!");return NULL;}}5、 C 语言实现打字游戏#include "stdio.h"#include "time.h"#include "stdlib.h"#include "conio.h"#include "dos.h"#define xLine 70#define yLine 20#define full 100#define true 1#define false 0/*---------------------------------------------------------------------*/void printScreen(int level,int right,int sum,char p[yLine][xLine])/* 刷新屏幕的输出图像 */{int i,j;文档大全printf("level:%d Press 0 to exit;1 topause score:%d/%d\n",level,right,sum);/* 输出现在的等级,击中数和现在已下落总数*/printf("----------------------------------------------------------------------\n");for (i=0;i<yLine;i++){for(j=0;j<xLine;j++)printf ("%c",p[i][j]);printf("\n");}/* for (i) */printf("----------------------------------------------------------------------\n");}/* printScreen *//*---------------------------------------------------------------------*/void leave()/* 离开程序时,调用该函数结束程序。

(完整版)c语言初学必背代码

(完整版)c语言初学必背代码

//1.成绩判断#include <stdio.h>int main(){//成绩int score;printf("请输入你的成绩:\n");scanf("%d", &score);//判断if(score >=0 && score < 60){printf("不及格\n");}else if(60 <= score && score < 80){printf("中等\n");}else if(80 <= score && score < 100){printf("优秀\n");}else{printf("输入错误!\n");}}//2.计算1到100的和#include <stdio.h>int main(){int sum = 0;//存结果变量int i;for(i=1;i <= 100;i++){sum = sum + i;}printf("sum=%d\n", sum);}//3.最大公约数#include <stdio.h>//求m,n的最大公约数int main(){int m, n;int i, k;printf("请输入两个数:");scanf("%d %d", &m, &n);//三元运算符找较小的那个k = m < n ? m : n;//从较小的那个数倒着往前找for(i=k; i>=1; i--){//这是公约数if((m % i == 0) && (n % i ==0)){printf("最大公约数是%d\n", i);break;//跳出for循环}}}//4.最小公倍数#include <stdio.h>//求m,n的最小公倍数int main(){int m, n;int max, min;//m,n中较大,较小的那个int k;//max, 2*max, 3*max, .....printf("请输入两个数:");scanf("%d %d", &m, &n);//也可以交换m,n,保证m小n大max = m > n ? m : n;min = m < n ? m : n;k = max;//从max开始while(k % min != 0){k += max;//每次倍增}printf("最小公倍数是%d\n", k); }//5.金字塔#include <stdio.h>//金字塔int main(){int i;//外层int j;//内层for(i=1;i<=10;i++){//当前是在第i行//先补空格10-i个for(j=1;j<=10-i;j++){printf(" ");}//再打2i-1个*for(j=1;j<=2*i-1;j++){printf("*");}printf("\n");}}//6.九九乘法表#include <stdio.h>//打印九九乘法表int main(){int i,j;for(i=1;i<=9;i++)//外层一定是9行{for(j=1; j<=i; j++)//内层第几行走几遍{printf("%d*%d=%d ", i, j, i*j);}printf("\n");}}//7.百钱买百鸡#include <stdio.h>/**百钱买百鸡,类似1,2,5凑100银币问题*/int main2(){int i,j;//公鸡,母鸡个数for(i=0; i<=20; i++)//公鸡{for(j=0; j<=33; j++)//母鸡{if( (15*i + 9*j + (100-i-j)) == 300){printf("公鸡%d,母鸡%d,小鸡%d\n", i, j, 100-i-j);}}}}//1,2,5凑100银币问题int main3(){int count = 0;//情况数int i,j;//5分个数,2分个数for(i=0; i<=20; i++)//5分个数{for(j=0; j<=50; j++)//2分个数{if( ( 5*i + 2*j ) <= 100 ){count++;printf("%d: 5分%d个,2分%d 个,1分%d个\n", count, i, j, 100-5*i-2*j);}}}}//8.一维数组的最大值、最小值、平均值#include <stdio.h>#define N 10//宏定义常量int main(){int i;//下标索引int max, min;double sum = 0;//累加和int a[N] = {58, 58, 96, 100, 25, 55, 66, 88, 99, 77};max = a[0];//假设第一个最大min = a[0];//假设第一个最小for(i=1; i<N; i++){if(a[i] > max)//比最大值还大max = a[i];//你才是最大if(a[i] < min)//比最小值还小min = a[i];//你才是最小sum += a[i];}printf("max=%d, min=%d\n", max, min);printf("average = %.2lf\n", sum/N);}//9.二维数组的最大值、最小值、平均值#include <stdio.h>int main(){int i; //第几行int j; //第几列int a[3][4] = { {1,2,3,4}, {5,-6,7,8}, {9,19,39,0}};int max = a[0][0];//假设你最大int min = a[0][0];//假设你最小double average;//平均值double sum = 0; //总和for(i=0; i<3; i++)//必定3行{for(j=0; j<4; j++)//必定4列{printf("%5d ", a[i][j]);sum += a[i][j];if(a[i][j] > max)max = a[i][j];if(a[i][j] < min)min = a[i][j];}printf("\n");}average = sum / (3*4);printf("max=%d, min=%d, avg=%.2lf\n", max, min, average);}//10.二维数组转置#include <stdio.h>//二维数组转置:行变列,列变行int main(){int i; //第几行int j; //第几列int a[3][4] = { {1,2,3,4}, {5,-6,7,8}, {9,19,39,0}};int b[4][3];for(i=0; i<3; i++){for(j=0; j<4; j++){printf("%5d", a[i][j]);}printf("\n");}//矩阵转置for(i=0; i<3; i++){for(j=0; j<4; j++){b[j][i] = a[i][j];}}for(i=0; i<4; i++){for(j=0; j<3; j++){printf("%5d", b[i][j]);}printf("\n");}}//11.冒泡排序#include <stdio.h>#define N 10//宏定义常量int main(){int i;//下标索引int j;int tmp;//临时交换用int a[N] = {58, 58, 96, 100, 25, 55, 66, 88, 99, 77};//外层循环一定是N-1for(i=0; i<N-1; i++){//两两交换,大的往后走for(j=0; j<N-i-1; j++){//交换if(a[j] > a[j+1]){tmp = a[j];a[j] = a[j+1];a[j+1] = tmp;}}}for(i=0; i<N; i++){printf("%d ", a[i]);;}printf("\n");}//12.结构冒泡排序#include <stdio.h>//结构定义,用户自定义类型typedef struct student{char sno[20];//学号char name[20];//姓名int age;//年龄char gender;//性别char tel[20];//电话};int main(){int i;int j;double sum = 0;struct student tmp;//两两交换临时用;//结构数组struct student team[5];for(i=0; i<5; i++){printf("请输入第%d个队员的信息:\n", i+1);scanf("%s %s %d %c %s", team[i].sno, team[i].name, &team[i].age, &team[i].gender, team[i].tel);}//按年龄冒泡排序for(i=0; i<5; i++){for(j=0; j<5-i-1; j++){//两两交换if(team[j].age > team[j+1].age){tmp = team[j];team[j] = team[j+1];team[j+1] = tmp;}}}//取值printf("%-12s %-10s %-5s %-5s %-15s\n", "学号", "姓名", "年龄", "性别", "电话");for(i=0; i<5; i++){printf("%-12s %-10s %-5d %-5c %-15s\n", team[i].sno, team[i].name, team[i].age, team[i].gender, team[i].tel);}}//13.结构数组找年龄最大值#include <stdio.h>//结构定义,用户自定义类型typedef struct student{char sno[20];//学号char name[20];//姓名int age;//年龄char gender;//性别char tel[20];//电话};int main(){int i;struct student tmp;//找最大临时用//结构数组struct student team[5];for(i=0; i<5; i++){printf("请输入第%d个队员的信息:\n", i+1);scanf("%s %s %d %c %s", team[i].sno, team[i].name, &team[i].age, &team[i].gender, team[i].tel);}//取值printf("%-12s %-10s %-5s %-5s %-15s\n ", "学号", "姓名", "年龄", "性别", "电话");for(i=0; i<5; i++){printf("%-12s %-10s %-5d %-5c %-15s\ n", team[i].sno, team[i].name, team[i].age, team[i].gender, team[i].tel);}//找学号最大的那一个tmp = team[0];for(i=1; i<5; i++){if(strcmp(team[i].sno,tmp.sno) >0 ){tmp = team[i];}}printf("学号最大的队员如下:\n");printf("%-12s %-10s %-5d %-5c %-15s\ n", tmp.sno, , tmp.age, tmp.gender, tmp.tel);}//14.文件读写#include <stdio.h>#include <stdlib.h>//结构定义,用户自定义类型typedef struct student{char sno[20];//学号char name[20];//姓名int age;//年龄char gender;//性别char tel[20];//电话};//文件读写int main(){struct student * s, * p1;//个数未知FILE * fp;int i, n = 0;char buf[1024];//fgets缓冲区//打开文件fp = fopen("e:\\test.txt", "r");while(fgets(buf, 1024, fp) != NULL)n++;fclose(fp);//指向一个可以存储n个student结构的内存空间s = (struct student *)malloc(sizeof(struct student) * n);p1 = s;//不要动头位置s的值//打开文件fp = fopen("e:\\test.txt", "r");for(i=0; i<n; i++){//从文件中读入一行fscanf(fp, "%s %s %d %c %s", p1->sno, p1->name, &p1->age, &p1->gender, p1->tel);p1++;}fclose(fp);p1 = s;for(i=0; i<3; i++){printf("%s %s %d %c %s\n", p1->sno, p1->name, p1->age, p1->gender, p1->tel);}free(s);}//15.输入三角形三边长计算周长和面积#include<stdio.h>#include<math.h>int main(){double area,perimeter,s,a,b,c;printf("请输入三边长a b c:");scanf("%lf%lf%lf",&a,&b,&c);if((a+b>c) && (a+c>b) && (b+c>a)){s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c));perimeter=a+b+c;printf("area=%.2f,perimeter=%.2f\ n",area,perimeter);}else{printf("三边长无法构成三角形。

经典C语言程序100例(word文档版)

经典C语言程序100例(word文档版)

【程序1】题目:有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。

组成所有的排列后再去掉不满足条件的排列。

2.程序源代码:main(){int i,j,k;printf("\n");for(i=1;i<5;i++) /*以下为三重循环*/for(j=1;j<5;j++)for (k=1;k<5;k++){if (i!=k&&i!=j&&j!=k) /*确保i、j、k三位互不相同*/printf("%d,%d,%d\n",i,j,k);}}=========================================================== 【程序2】题目:企业发放的奖金根据利润提成。

利润(I)低于或等于10万元时,奖金可提10%;利润高于10万元,低于20万元时,低于10万元的部分按10%提成,高于10万元的部分,可可提成7.5%;20万到40万之间时,高于20万元的部分,可提成5%;40万到60万之间时高于40万元的部分,可提成3%;60万到100万之间时,高于60万元的部分,可提成1.5%,高于100万元时,超过100万元的部分按1%提成,从键盘输入当月利润I,求应发放奖金总数?1.程序分析:请利用数轴来分界,定位。

注意定义时需把奖金定义成长整型。

2.程序源代码:main(){long int i;int bonus1,bonus2,bonus4,bonus6,bonus10,bonus;scanf("%ld",&i);bonus1=*0.1;bonus2=bonus1+*0.75;bonus4=bonus2+*0.5;bonus6=bonus4+*0.3;bonus10=bonus6+*0.15;if(i<=)bonus=i*0.1;else if(i<=)bonus=bonus1+(i-)*0.075;else if(i<=)bonus=bonus2+(i-)*0.05;else if(i<=)bonus=bonus4+(i-)*0.03;else if(i<=)bonus=bonus6+(i-)*0.015;elsebonus=bonus10+(i-)*0.01;printf("bonus=%d",bonus);}=========================================================== 【程序3】题目:一个整数,它加上100后是一个完全平方数,再加上168又是一个完全平方数,请问该数是多少?1.程序分析:在10万以内判断,先将该数加上100后再开方,再将该数加上268后再开方,如果开方后的结果满足如下条件,即是结果。

(完整word版)增量式PID控制C语言代码

(完整word版)增量式PID控制C语言代码
// Integral=0
// LastError=0
//Input: PID的P、I控制常数和之前的误差量(PID *pp)
//Return:
//////////////////////////////////////////////////////////////////////
void PIDInit (PID *pp) //PID参数初始化,都置0
//增量式PID算法(需要控制的不是控制量的绝对值,而是控制量的增量)
int pError,dError,iError;
long templ;
pError = ThisError-pp->LastError;
iError = ThisError;
dError = ThisError-2*(pp->LastError)+pp->PreError;
增量式PID控制C语言代码
增量式PID控制公式:
上面△u(k)是控制量增量,“增量式PID”就是直接以这个增量进行控制。
至于参数的整定,根据响应的情况调,比如,响应慢了,我就增大kp,或者减小kd,超调大了就减小kp或增大点kd,这个规律你可以看看PID三个参数的作用:)
////////////////////////////////////////////////////////////////
{
memset ( pp,0,sizeof(PID));
//memset()的函数,它可以一字节一字节地把整个数组设置为一个指定的值。
// memset()函数在mem.h头文件中声明,它把数组的起始地址作为其第一个参数,
//第二个参数是设置数组每个字节的值,第三个参数是数组的长度(字节数,不是元素个数)。

(完整word版)纯C语言写的一个小型游戏源代码

/* A simple game*//*CopyRight: Guanlin*/ #include<stdio。

h〉#include〈stdlib。

h〉#include<string.h〉#include〈time。

h>#include〈conio。

h>#include<process.h〉struct object_fix{char name[20];char id[5];char desc[500];char action[30];char im[5];};struct object_move{char name[20];char id[5];char desc[500];int loc;int pwr;int strg;char im[5];};struct rover{char name[20];char id[5];char desc[500];int pwr;int strg;int location[2];char im[5];};struct map /* this is the map structure*/{char data[20];char add_data[20];int amount;int x; /* this were the successor keeps it's x & y values*/int y;};struct location /*this structure is for the successor lister*/{float height;char obj;};void stats_update(int selected, struct rover *p_rover){switch (selected){case 1:if(p_rover->pwr 〈 7)printf("\n\nYou do not have enough power to perform this action!\n\n”);else{(p_rover—〉pwr)—= 7;printf("You have destroyed the object!\n\n");}break;case 2:if(p_rover->pwr 〈 3)printf(”\n\nYou do not have enough power to perform this action!\n\n"); else if(p_rover—〉strg > 90)printf("\n\nYou do not have enough storage space for this object!\n\n");{(p_rover-〉pwr) —= 3;(p_rover—>strg) += 10;printf("You have collected a sample of the object!\n\n");}break;case 3:p_rover->pwr -= 10; /*Distance around object— value gained from mapper module. 1 square = -1 power*/printf(”You have avoided the object!\n\n”);break;case 4:p_rover—>pwr —= 2;printf("You have driven through the obstacle!\n\n”);break;case 5:if(p_rover—〉pwr == 100)printf(”\n\nYou do not need to charge up!\n\n");else{p_rover—〉pwr = 100;printf(”You have charged up your rover!\n\n”);}break;default:printf("\n\n*****ERROR*****\nInvalid Selection\n\n”);break;}}void action(char object, struct rover *p_rover){int selection;switch(object)case 1:printf(”\nYou have encountered: A Sandy Rock\n\n");printf(”This object can be:\n1.\tDestroyed\n2.\tCollected\nPlease choose action 1 or 2:\t"); scanf("%d”, &selection);stats_update(selection, p_rover);break;case 2:printf(”\nYou have encountered: A Solid Rock\n\n");printf(”This object can be:\n1。

CRC16校验C语言程序源码(附完整的可执行的C语言代码)

CRC16校验C 语言程序源码 (附完整的可执行的 C 语言代码)//CRC16校验在通讯中应用广泛,这里不对其理论进行讨论,只对常见的 2种//实现方法进行测试。

方法一:查表法(256长度的校验表)速度快,准确,但是对于单片机设备存储占用大,且校验表长度大,输入时容易岀现错误 // .................. --POPULAR POLYNOMIALS ....................// CCITT: x A 16 + x A 12 + x A 5 + x A 0(0x1021) // CRC-16: x A 16 + xA15 + xA2 + xA0(0x8005)#defi neCRC_16_POLYNOMIALS0x8005const BYTE chCRCHTalbe[]=// CRC 高位字节值表{0x00, 0xC1, 0x81, 0x40, 0x01, OxCO, 0x80, 0x41, 0x01, OxCO, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x00, 0xC1,0x81,0x40, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x00, 0xC1, 0x81, 0x40, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x00, 0xC1,0x81,0x40, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41,0x00, 0xC1,0x81,0x40,0x01, 0xC0, 0x80, 0x41,0x01,0xC0, 0x80, 0x41, 0x00, 0xC1,0x81,0x40, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x00, 0xC1,0x81,0x40, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x00, 0xC1, 0x81, 0x40, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x00, 0xC1, 0x81, 0x40,0x01,0xC0, 0x80, 0x41,0x01, 0xC0, 0x80, 0x41,0x00, 0xC1, 0x81, 0x40, 0x01, 0xC0,0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x00, 0xC1, 0x81, 0x40, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01,0xC0, 0x80, 0x41,0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x00, 0xC1,0x81,0x40, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x00, 0xC1, 0x81, 0x40, 0x01, 0xC0, 0x80, 0x41, 0x00, 0xC1, 0x81, 0x40, 0x01,0xC0, 0x80, 0x41, 0x01,0xC0, 0x80, 0x41,0x00, 0xC1, 0x81, 0x40 };con st BYTE chCRCLTalbe[] = // CRC 低位字节值表 {0x00, 0xC0, 0xC1,0x01,0xC3, 0x03, 0x02, 0xC2, 0xC6, 0x06, 0x07, 0xC7,0x05, 0xC5, 0xC4, 0x04, 0xCC, 0x0C, 0x0D, 0xCD, 0x0F, 0xCF, 0xCE, 0x0E, 0x0A, 0xCA, 0xCB, 0x0B, 0xC9, 0x09, 0x08, 0xC8, 0xD8, 0x18, 0x19, 0xD9, 0x1B, 0xDB, 0xDA, 0x1代 0x1E, 0xDE, 0xDF, 0x1F, 0xDD, 0x1D, 0x1C, 0xDC, 0x14, 0xD4, 0xD5, 0x15, 0xD7, 0x17, 0x16, 0xD6, 0xD2, 0x12, 0x13, 0xD3, 0x11, OxD1, OxDO, 0x10, OxFO, 0x30, 0x31, OxF1,0x33, 0xF3, 0xF2, 0x32, 0x36, 0xF6, 0xF7, 0x37, 0xF5, 0x35, 0x34, 0xF4, 0x3C, 0xFC, 0xFD, 0x3D,0xFF, 0x3F, 0x3E, 0xFE, 0xFA, 0x3A, 0x3B, 0xFB, 0x39, 0xF9, 0xF8, 0x38,0x28, 0xE8, 0xE9, 0x29, 0xEB, 0x2B, 0x2A, 0xEA, 0xEE, 0x2E, 0x2F, 0xEF,0x2D, 0xED, 0xEC, 0x2C, 0xE4, 0x24, 0x25, 0xE5, 0x27, 0xE7, 0xE6, 0x26,0x22, 0xE2, 0xE3, 0x23, 0xE1, 0x21, 0x20, 0xE0, 0xA0, 0x60, 0x61,0xA1,0x63, 0xA3, 0xA2, 0x62, 0x66, 0xA6, 0xA7, 0x67, 0xA5, 0x65, 0x64, 0xA4,0x6C, 0xAC, 0xAD, 0x6D, 0xAF, 0x6F, 0x6E, 0xAE, 0xAA, 0x6A, 0x6B, 0xAB,0x69, 0xA9, 0xA8, 0x68, 0x78, 0xB8, 0xB9, 0x79, 0xBB, 0x7B, 0x7A, 0xBA,0xBE, 0x7E, 0x7F, 0xBF, 0x7D, 0xBD, 0xBC, 0x7C, 0xB4, 0x74, 0x75, 0xB5,0x77, 0xB7, 0xB6, 0x76, 0x72, 0xB2, 0xB3, 0x73, 0xB1, 0x71, 0x70, 0xB0,0x50, 0x90, 0x91, 0x51, 0x93, 0x53, 0x52, 0x92, 0x96, 0x56, 0x57, 0x97,0x55, 0x95, 0x94, 0x54, 0x9C, 0x5C, 0x5D, 0x9D, 0x5F, 0x9F, 0x9E, 0x5E,0x5A, 0x9A, 0x9B, 0x5B, 0x99, 0x59, 0x58, 0x98, 0x88, 0x48, 0x49, 0x89,0x4B, 0x8B, 0x8A, 0x4A, 0x4E, 0x8E, 0x8F, 0x4F, 0x8D, 0x4D, 0x4C, 0x8C,0x44, 0x84, 0x85, 0x45, 0x87, 0x47, 0x46, 0x86, 0x82, 0x42, 0x43, 0x83,0x41, 0x81, 0x80, 0x40};WORD CRC16_1(BYTE* pchMsg, WORD wDataLe n){BYTE chCRCHi = 0xFF; // 高CRC字节初始化BYTE chCRCLo = 0xFF; // 低CRC字节初始化WORD win dex; // CRC 循环中的索引while (wDataLe n--){// 计算CRCwin dex = chCRCLo A *pchMsg++ ;chCRCLo = chCRCHi A chCRCHTalbe[wl ndex]; chCRCHi =chCRCLTalbe[wi ndex];}return ((chCRCHi << 8) | chCRCLo);}方法一:列表法(简单表)con st WORD wCRCTalbeAbs[]={0x0000, 0xCC01, 0xD801, 0x1400, 0xF001, 0x3C00, 0x2800, 0xE401, 0xA001, 0x6C00, 0x7800,0xB401,0x5000, 0x9C01,0x8801,0x4400,};WORD CRC16_2(BYTE* pchMsg, WORD wDataLe n){WORD wCRC = OxFFFF;WORD i;BYTE chChar;for (i = 0; i < wDataLe n; i++){chChar = *pchMsg++;wCRC = wCRCTalbeAbs[(chChar A wCRC)& 15] A (wCRC>> 4);wCRC = wCRCTalbeAbs[((chChar >> 4) A wCRC) & 15] A (wCRC >> 4);}return wCRC;}方法二:定义法根据CRC16/MODBUS理直接计算,算法简单但对单片机计算压力大。

(完整word版)C语言课程设计----运动会分数统计系统源代码

源代码:#include<stdio.h>#include<math.h>#include <conio.h>#include <process.h>#define n 2//学校数目#define m 1//男子项目数目#define w 1//女子项目数目#define null 0typedef struct{int itemnum; //项目编号int top; //取名次的数目int range[5]; //名次int mark[5]; //分数}itemnode; //定义项目结点的类型typedef struct{int schoolnum; //学校编号int score; //学校总分int mscore; //男团体总分int wscore; //女团体总分itemnode c[m+w]; //项目数组}headnode;//定义头结点类型headnode h[n];//定义一个头结点数组void inputinformation() //输入信息,建立系统{int i,j,k,s;for(i=0;i<n;i++){h[i].score=0;h[i].mscore=0;h[i].wscore=0;} //初始化头结点for(i=0;i<n;i++){printf("*****学校编号:");scanf("%d",&h[i].schoolnum); //输入头结点信息for(j=0;j<m+w;j++){printf("*****项目编号:");scanf("%d",&h[i].c[j].itemnum);printf("*****取前3名or前5名:");scanf("%d",&h[i].c[j].top);printf("*****获得几个名次:");scanf("%d",&k); //输入项目信息for(s=0;s<5;s++)h[i].c[j].range[s]=0, h[i].c[j].mark[s]=0; //初始化排名和分数for(s=0;s<k;s++){printf("*****名次:");scanf("%d",&h[i].c[j].range[s]); //输入所获名次信息if(h[i].c[j].top==3)switch(h[i].c[j].range[s]){case 0: h[i].c[j].mark[s]=0; break;case 1: h[i].c[j].mark[s]=5; break;case 2: h[i].c[j].mark[s]=3; break;case 3: h[i].c[j].mark[s]=2; break;}elseswitch(h[i].c[j].range[s]){case 0: h[i].c[j].mark[s]=0; break;case 1: h[i].c[j].mark[s]=7; break;case 2: h[i].c[j].mark[s]=5; break;case 3: h[i].c[j].mark[s]=3; break;case 4: h[i].c[j].mark[s]=2; break;case 5: h[i].c[j].mark[s]=1; break;}h[i].score=h[i].score+h[i].c[j].mark[s];//按取前三名还是取前五名分别记分if(j<=m-1)h[i].mscore=h[i].mscore+h[i].c[j].mark[s];//是男子项目则记到男子分数里面去elseh[i].wscore=h[i].wscore+h[i].c[j].mark[s];//是女子项目则记到女子项目里面去}printf("\n");}}}void output() //输出函数{int choice,i,j,k;int remember[n];int sign;do{printf("*******************1.按学校编号输出.*******************\n");printf("*******************2.按学校总分输出.*******************\n");printf("*******************3.按男团总分输出.*******************\n");printf("*******************4.按女团总分输出.*******************\n");printf("\n\n******************* 请选择编号*************************\n\n:");scanf("%d",&choice);switch(choice){case 1:for(i=0;i<n;i++){printf("\n\n*****学校编号:%d\n",h[i].schoolnum);printf("*****学校总分:%d\n" ,h[i].score);printf("*****男团总分:%d\n",h[i].mscore);printf("*****女团总分: %d\n\n\n",h[i].wscore);} //按编号顺序输出break;case 2:for(i=0;i<n;i++)remember[i]=i;for(i=0;i<n;i++){for(j=i+1;j<n;j++)if(h[remember[i]].score<h[j].score)k=remember[i];remember[i]=remember[j],remember[j]=k;} // 用冒泡排序方法,用辅助数组记住头结点下标for(i=0;i<n;i++){printf("\n\n*****学校编号:%d\n",h[remember[i]].schoolnum);printf("*****学校总分:%d\n" ,h[remember[i]].score);printf("*****男团总分:%d\n",h[remember[i]].mscore);printf("*****女团总分: %d\n\n\n",h[remember[i]].wscore);//按所记下标顺序输出} //按学校总分输出break;case 3:for(i=0;i<n;i++)remember[i]=i;for(i=0;i<n;i++){for(j=i+1;j<n;j++)if(h[remember[i]].mscore<h[j].mscore)k=remember[i];remember[i]=remember[j];remember[j]=k;}for(i=0;i<n;i++){printf("\n\n*****学校编号:%d\n",h[remember[i]].schoolnum);printf("*****学校总分:%d\n" ,h[remember[i]].score);printf("*****男团总分:%d\n",h[remember[i]].mscore);printf("*****女团总分: %d\n\n\n",h[remember[i]].wscore);} //按男团总分输出break;case 4:for(i=0;i<n;i++)remember[i]=i;for(i=0;i<n;i++){for(j=i+1;j<n;j++)if(h[remember[i]].wscore<h[j].wscore)k=remember[i];remember[i]=remember[j];remember[j]=k;}for(i=0;i<n;i++){printf("\n\n*****学校编号:%d\n",h[remember[i]].schoolnum);printf("*****学校总分:%d\n" ,h[remember[i]].score);printf("*****男团总分:%d\n",h[remember[i]].mscore);printf("*****女团总分: %d\n\n\n",h[remember[i]].wscore);}break; //按女团总分输出}printf("请选择 2 继续,0 跳出\n");scanf("%d",&sign);}while(sign==2); //循环执行输出语句}void inquiry() //查询函数{int choice;int i,j,k,s;printf("\n*****1:按学校编号查询\n");printf("\n*****2:按项目编号查询\n");printf("\n\n*****请选择查询方式:"); //提供两种查询方式scanf("%d",&choice);switch(choice){case 1:do{printf("要查询的学校编号:");scanf("%d",&i);if(i>n)printf("错误:这个学校没有参加此次运动会!\n\n\n");else{printf("要查询的项目编号:");scanf("%d",&j);if(j>m+w||j==0)printf("此次运动会没有这个项目\n\n\n");//学校编号超出范围,则输出警告else{printf("这个项目取前%d名,该学校的成绩如下:\n", h[0].c[j-1].top);for(k=0;k<5;k++)if(h[i-1].c[j-1].range[k]!=0)printf("名次:%d\n",h[i-1].c[j-1].range[k]);//输出要查询学校项目的成绩}}printf("请选择2 继续, 0 跳出\n");scanf("%d",&s);printf("\n\n\n");}while(s==2); //循环执行输出语句break;case 2:do{printf("要查询的项目编号:");scanf("%d",&s);if(s>m+w||s==0)printf("此次运动会不包括这个项目.\n\n\n");//项目编号超出范围则输出警告else{printf("该项目取前%d名,取得名次的学校\n",h[0].c[s-1].top);for(i=0; i<n;i++)for(j=0;j<5;j++)if(h[i].c[s-1].range[j]!=0)printf("学校编号:%d,名次:%d\n",h[i].schoolnum,h[i].c[s-1].range[j]);} //输出该项目取得名次学校的成绩printf("\n\n\n继续2,跳出0\n");scanf("%d",&i);printf("\n\n\n");}while(i==2);break;}}void writedata() //把数据存储在文件中{FILE *report;int i;if((report=fopen("sportsdata.txt","w"))==null){printf("不能打开文件\n");exit(1);}for(i=0;i<n;i++)fwrite(&h[i],sizeof(headnode),1,report);fclose(report);} //按头结点块写入void readdata() //读出文件中数据的函数{FILE *report;int i,j,k,s;if((report=fopen("sportsdata.txt","r"))==null){printf("file can not be opened\n");exit(1);}for(i=0;i<n;i++){printf("******学校编号:");fread(&k,sizeof(int),1,report);printf("%d\n",k);printf("******学校总分:");fread(&k,sizeof(int),1,report);printf("%d\n",k);printf("******男团总分:");fread(&k,sizeof(int),1,report);printf("%d\n",k);printf("******女团总分:");fread(&k,sizeof(int),1,report);printf("%d\n",k);printf("\n\n\n");getch();for(j=0;j<m+w;j++){printf("******项目编号:");fread(&k,sizeof(int),1,report);printf("%d\n",k);printf("******所取名次数量:");fread(&k,sizeof(int),1,report);printf("%d\n",k);for(s=0;s<5;s++){fread(&k,sizeof(int),1,report);if(k!=0)printf("******名次:"),printf("%d\n",k);}for(s=0;s<5;s++){fread(&k,sizeof(int),1,report);if(k!=0) printf("******分数:"),printf("%d\n",k);}}printf("\n\n\n");getch();}fclose(report); //关闭文件} //按照读一个数据就输出一个数据的方式显示数据内容void main(){int choice;printf("======================欢迎使用======================\n"); printf("\n\n*****************运动会分数统计系统********************\n");printf("\n\n********************1.输入信息*************************\n");printf("********************2.输出信息*************************\n");printf("********************3.查询信息*************************\n");printf("********************4.调用信息*************************\n");printf("********************5.退出系统*************************\n\n\n");printf("================================================\n\n");printf("********请选择要实现步骤的编号:\n\n");scanf("%d",&choice);switch(choice){case 1:inputinformation();writedata();readdata();main();case 2:output();main();case 3:inquiry();main();case 4:readdata();main();case 5:exit(0);default:exit(0);}}。

(完整word版)增量式PID控制C语言代码

LASERH=laser.Num[0];
LASERL=laser.Num[1];
}
}
///////////////////////////////////////////////////////////////////////
//rtion="0"
vPID. SetPoint = //根据实际情况设定
while(1)
{
Verror=Measure(); //得到AD的输出值
Error =vPID. SetPoint- Verror; //与设定值比较,得到误差值
tempi=PIDCal(&vPID, Error;
laser.Value+=tempi; // Value与Num[2]为共同体,共同体名laser
//增量式PID算法(需要控制的不是控制量的绝对值,而是控制量的增量)
int pError,dError,iError;
long templ;
pError = ThisError-pp->LastError;
iError = ThisError;
dError = ThisError-2*(pp->LastError)+pp->PreError;
int Integral; // Integral积分系数
int Derivative; // Derivative微分系数
int LastError; // Error[-1]前一拍误差
int PreError; // Error[-2]前两拍误差
} PID;
main()
{
PID vPID; //定义结构变量名
//Input: PID的P、I控制常数和之前的误差量(PID *pp)&当前误差量(ThisError)
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