2017春季学期三月五校联考答题卡B
2017高三年级五校联考答案
2017高三年级五校联考第一部分：英语知识运用第一节：单项填空1. D 短语by all means一定，表示应允。
2. D 根据句意选择。
ambition雄心，野心，志向。
3. A 短语speed up提速，加快。
4. B It couldn't have been more boring.令人感到无聊透顶。
5. C leave…unfinished…还没有完成。
根据句意使用完成时的被动语态。
6. C 本题考查定语从句。
先行词journey在后面从句中做状元所以用关系副词where。
7. C regularly定期地，有规则地。
根据句意选择。
8. A 短语be devoted to sth./doing sth.忠诚于……;热爱……。
9. A 句意"我就是这样记住她的"。
10. B increase为抽象名词具体化，其前用冠词。
Creativity创造力，为不可数名词。
11. C previous先前的。
根据句意选择。
12. C Encouraging children to stay in touch with the nature为动名词短语作主语。
13. D 句型It will be long before…要过很久才能……。
第二空为定语从句，先行词为Mr. White, 在从句中作定语。
14. B 短语in addition to除……之外。
根据句意选择。
15. C So+情态动词/助动词/联系动词+主语，表示后者与前者相同。
第二节:完形填空16. C inform通知，有人通知我，我的父亲病得很严重。
17. A divorce离婚。
作者父母离婚后，父亲一个人住在加州的一个小房车里。
18. B 作者与父亲的距离更大了。
19. D 作者努力改变与父亲的距离。
20. C promise答应，许诺。
21. A 整个开车的路上，作者的脑海里一直闪现着儿时的记忆。
22. B 父亲教作者的第一首歌。
2017年5月2017届高三第三次全国大联考(山东卷)语文卷(答题卡)
1请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！2017年5月2017届高三第三次全国大联考【山东卷】语文答题卡第I 卷（共36分）请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！ 请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！ 姓 名：__________________________ 准考证号：贴条形码区考生禁填： 缺考标记 违纪标记以上标志由监考人员用2B 铅笔填涂选择题填涂样例： 正确填涂错误填涂1、 答题前，考生先将自己的姓名，准考证号填写清楚，并认真核准条形码上的姓名、准考证号，在规定位置贴好条形码。
2、 选择题必须用2B 铅笔填涂；填空题和解答题必须用0.5 mm 黑色签字笔答题，不得用铅笔或圆珠笔答题；字体工整、笔迹清晰。
3、 请按题号顺序在各题目的答题区域内作答，超出区域书写的答案无效；在草稿纸、试题卷上答题无效。
4、 保持卡面清洁，不要折叠、不要弄破。
注意事项×√一、二、三（36分） 1. [ A ] [ B ] [ C ] [ D ] 2. [ A ] [ B ] [ C ] [ D ] 3. [ A ] [ B ] [ C ] [ D ] 4. [ A ] [ B ] [ C ] [ D ] 5. [ A ] [ B ] [ C ] [ D ] 6. [ A ] [ B ] [ C ] [ D ] 7. [ A ] [ B ] [ C ] [ D ] 8. [ A ] [ B ] [ C ] [ D ] 9. [ A ] [ B ] [ C ] [ D ]10. [ A ] [ B ] [ C ] [ D ] 11. [ A ] [ B ] [ C ] [ D ]12. [ A ] [ B ] [ C ] [ D ]四、（24分） 13.（10分） （1）（4分）__________________________________________________________________________________________________________________________________（2）（3分） _________________________________________________________________ _________________________________________________________________（3）（3分）__________________________________________________________________________________________________________________________________请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！ 14.（8分） （1）（4分） __________________________________________________________________________________________________________________________________ （2）（4分） __________________________________________________________________________________________________________________________________ 15.（6分） （1） __________________________________________________________________________________________________________________________________ （2） __________________________________________________________________________________________________________________________________ （3） _______________________________________________________________________ __________________________________________________________ 五、（12分） 16.（4分） _____________________________________________________________________________________________________ ____________________________ 17.（4分） ______________________________________________________________________________________________________ ___________________________ 18.（4分） __________________________________________________________________________________________________________________________________ __________________________________________________________________________________________________________________________________ 六、（18分） 19.（4分） __________________________________________________________________________________________________________________________________ 20.（4分） （1）（2分） __________________________________________________________________________________________________________________________________ （2）（2分） __________________________________________________________________________________________________________________________________ 21.（4分） ______________________________________________________________________________________________________ ___________________________ 22.（6分） ______________________________________________________________________________________________________ ___________________________第Ⅱ卷（共114分）2请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！800请在各题目的答题区域内作答，超出黑色矩形边框限定区域的答案无效！七、作文（60分）23.阅读下面的材料，根据自己的感悟和联想，写一篇不少于800字的文章。
2017届高三第一次五校联考英语试题附答案
2017届高三第一次五校联考英语试题附答案第一部分听力（共两节，满分30分,不计入总分）第一节(共5小题；每小题分，满分分)听下面5段对话。
每段对话后有一个小题，从每题所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题. 每段对话仅读一遍。
1. Who will the man call?A. His wife.B. His boss.C. A taxi driver.2. What does the man suggest the woman do?A. Wait on the phone.B. Order the pizza online.C. Drive to the pizza place.3. What does the woman want to do?A. Make some coffee.B. Buy a coffee maker.C. Learn to make a video.4. What will the man do at 3 o’clock on Friday?A. Go to class.B. Meet the doctor.C. Take the woman’s shift.5. What does the man think of the lecture?A. Excellent.B. Difficult.C. Boring.第二节（共15小题；每小题分，满分分）听下面5段对话或独白。
每段对话或独白后有几个小题，从每题所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话，回答第6、7 题。
6. Who will send the file?A. Sam.B. Carol.C. Lucy.7. Where is the woman?A. At the airport.B. In the office.C. In the hotel.听下面一段对话，回答第8 至10 题。
2017学年浙江省高三五校联考答案
2017学年浙江省高三“五校联考”第二次考试答案第一部分：听力（共两节，满分30分）1-5 BACAC 6-10 ACBAB 11-15 CBABA 16-20 CACCB第二部分：阅读理解（共两节，满分35分）21-23 CAB 24-26 DDA 27-30 DCCB 31-35 BCEFA第三部分:语言运用（共两节,满分45分）第一节36-40 BDDAC 41-45 CBDAC 46-50 CBABD 51-55 ABDCA第二节56.importance 57.that 58.the 59.it 60.rising61.to breathe 62. With 63. factories 64. is getting 65.until/before第四部分：写作（共两节，满分40分）第一节：应用文写作范文：Dear parents,It is our pleasure to inform you that Xinhua School is organizing a Science Fair to be held on Saturday, 7 May, 2018. The fair is open for parents from 10:00 a.m. to 11:00 a.m. in the gym.The purpose of conducting a science fair is to promote true scientific spirit. Hands-on scientific investigation is the main focus of our fair. Our school students will present their science projects on that day. The projects are graded by our teachers and various awards will be given.Your gracious presence will be highly appreciated and encouraging for the students of our school.Sincerely yours,Li Ming第二节：读后续写Suggested Version：Ali looked up and saw the other boys rushing ahead.Refusing to give up at this point, he jumped to his feet and ran as fast as he could. He dashed across the finish line and won the fourth prize. Thinking he would let her sister down, Ali couldn’t help sobbing. Just then he suddenly heard the announcement from the broadcast that he won the third prize as the runner who collided with Ali was disqualified for breaking the rule. Holding the shoes close to his chest during the award ceremony, Ali felt overjoyed and relieved as he eventually won the shoes for his sister.Filled with delight, Ali walked home quickly. He could not wait to see his sister and share the thrilling news. On his arrival, Ali found Zahra was waiting outside. She was really nervous whether her brother had brought her what she was expecting. “Zahra, see what I have got for you.”he took the prize out of his bag with his trembling hands. The instant Zahra saw the shoes, her face lit up. So thrilled was she that she threw herself at Ali. “Thank you! Ali.” Tears of joy welled up their eyes as the brother and sister hugged tightly together.听力录音原文1M: This math puzzle is really beyond me.W: Well, if you can’t solve it, I won’t stand a chance.2M: Your computer makes such a loud noise. I guess there must be something wrong. You’d better have it checked out.W: You are right. I’ll do that later.3M: What’s the noise? It sounds as if it’s coming from next door. The Nelsons aren’t back yet, are they?W: I don’t think so. It must be the window-cleaner working upstairs.4M: I think there’s a mistake in our bill. We didn’t have dinner here last night.W: I’m sorry, sir. Here is the bill from the hotel restaurant. It’s got your signature on it.M: But that’s not my signature. I’d like to speak to the manager.5W: Good morning, Mr. Smith. I hope I’m not disturbing your work.M: Not at all, Mary. Come in and take a seat. I’m always in my office before lunch.W: I want to tell you that I have already started writing my paper and I’d like to discuss my topic with you.M: Of course. What would you like to work on?6M: This car goes from 0 to 60 in only 5 seconds. Not bad for something built in the old USA!W: Hmm, I usually don’t buy American. How do I know that this is going to be more reliable than something that’s made in Germany?M: Listen, ma’am,I’ve been driving a Ford for the past 20 years, and I mean the same Ford! These are the best in the business. I’m telling you.W: But is it safe?M: Well, that depends on how fast you want to drive!W: What?M: I’m just kidding. That was a joke! Seriously, though, the safety ratings are at the top of its class.I can show you the latest Consumer Reports if you want.W: No, that’s OK. I appreciate your time. I think I’m going to keep looking, though.M: All right. Let me know if I can help.7M: Hello, may I speak to Mr. Or Mrs. Baker, please?W: This is Mrs. Baker speaking.M: Hello, Mrs. Baker, this is Mr. Chin, Timothy’s English teacher. I’m calling because Timothy is struggling in English.W: He isn’t doing well? This is really upsetting. He must study h arder. I will talk to him about that immediately.M: Actually, I’m calling to offer my assistance. Timothy is already working hard in class, but he needs some extra help. If he could stay after class on Mondays and Wednesdays, I’d be able to help him improve. Would it be OK for him to stay after school on those days?W: Definitely. Thank you so much for offering help! I will talk to Timothy today and he’ll startstaying after school next week. Thank you for your concern!M: It’s my pleasure. I enjoy having Timothy in my class.8M: Debbie, I’m sorry to have to say this, but this lateness really can’t go on, you know?W: Oh, no, not again.M: What do you mean by that?W: Well, you’re always going on at me and I’m never more than five minutes late.M: Late is late, my girl! And if you don’t change your ways, I’m afraid I shall have to let you go. W: Let me go? Must you always put things the wrong way round? What you mean is you’ll fire me!M: Will you please stop being so aggressive and so cheeky?W: Oh, why don’t you shut up?M: Really! Debbie ... I never thought you’d... what you do you think you’re doing now?W: Doing? I’m getting my things together. That’s what I’m doing. There’s no need for you to fire me, Mr. Steiner. I resign!9W: How’s your computer c ourse going?M: Well, I’ve just had my class, actually. We have it twice a week and each one lasts two hours. W: That’s too long. Doesn’t it get boring?M: Well, you need that long to actually do a whole document. I can do all sorts of things on my computer that I never knew before.W: I can’t say the same for my cookery course.M: Oh, why not? I thought you were enjoying it.W: It’s enjoyable enough, but we just don’t seem to make much progress. We spent the whole of last week’s lesson learning how to fry an egg.M: So how often is it?W: Just once a week, for an hour and a half. It’s making cakes next week.M: Oh, that sounds fun.W: Yeah. I’m looking forward to it. I wanted to ask you something, actually. Have you learnt how to send e-mails on your cours e yet? I can’t get my computer to send them properly, and I was wondering if you’d show me how it’s done.M: Well, if you bring me one of your cakes, I suppose I could try.W: Great, well, when I’ve made them.10I don’t often lose things and I’m especiall y careful with money, so I was quite surprised when I reached for my wallet to pay for my dinner and it wasn’t there. At first, I thought it was possible that I could have left it at home. Then I remembered taking it out to pay for the taxi, so I knew I had it with me just before I walked into the restaurant. I wondered if it was possible that it could have slipped out of my pocket while I was eating dinner. Thinking about that possibility, I turned and walked back to the table where I had been sitting.Unfortunately, there were several other people sitting at the table at the time, so I called a waiter and explained to him that my wallet had fallen out of my pocket while I was sitting at the table a few minutes earlier. I had the waiter go over to the table to see if my wallet was on the floor. While the waiter was looking for it, the manager came up to me and asked me if anythingwas wrong. I didn’t want to get a lot of people involved in the problem, but I knew I had to get the wallet back. I told the manger what had happened. He had me describe the wallet to him, and then he insisted that I report it to the police. I told him that I didn’t want to set the police involved in it. Besides, I was in a hurry because I had an appointment with my doctor in just a few minutes. I explained to him that my biggest worry at the moment was how I was going to pay the check. He told me not to worry about that. He had me write down my name and address. And he said he would send me the bill.。
2017学年浙江省高三“五校联考”3技术答案
2017学年浙江省高三“五校联考”第一次考试技术参考答案第一部分信息技术13.excel(共4分)（1）________=C3-$C$14或=C3-C$14___ (1分) （4）____________不会_____________ __ (1分) （3）____B2,B6:B12,C2,C6:C12,E2,E6:E12 (1分)或B2:C2,B6:C12,E2,E6:E12（4）_________大白菜___________ (1分) 14.vb(共5分)（1）________________4_______________ (1分) （2）① ____true (1分)② ____e + 70 (1分)③ _________Chr(h)_______ (1分) （3）_________A ___________________ (1分) 15.flash(共8分)(1)__________BD____________________ (2分) （注：全部选对的得2分，选对但不全的得1分，不选或有选错的得0分）(2)_________动画补间_______________ (1分)(3) _在“五环”影片剪辑制作时最后一帧添加动作脚本stop();_ (2分)(4)on(press){ gotoAndPlay("鸣谢",1);} (2分) 或release，结构正确的1分，内部代码正确得1分，分号可以省略(5) ____________事件___________________ (1分) 16.vb加试1(共4分)①___And (Asc(Mid(a, i, 1)) <> 32)_______ (2分)②______V al(Mid(a, x, i - x))_____________ (2分)17. vb加试2(共5分)（1）__________stuinfo_________________ (1分)（2）①___________CheckCF(y) = True或CheckCF(y)_________ (1分)②______a(dd(n)) + b(dd(n))或a(dd(n)) & b(dd(n))___ ___ ___ ___ (2分)③___________p = dd(m)___________________________ (1分)第二部分通用技术（共50分）分,第17小题6分，共24分）14．每空1分（1）Ⅰ．④Ⅱ．③Ⅲ．①（2）②（3）②、③（序号顺序交换也得分）15．（1）②、④（2）（3）设计草图4分尺寸标注2分（4）②16．每条线1分，共3分17.（1）④ （2） （3）（4） ① ②。
2017年3月2017届高三第二次全国大联考（新课标Ⅲ卷）英语卷（解析版）
2017年3月2017届高三第二次全国大联考（新课标Ⅲ卷）英语卷（解析版）第一部分听力(共两节，满分30分)做题时，先将答案标在试卷上。
录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is the shirt?A.￡19.15.B.￡9.18.C.￡9.15.答案是C。
1.What does the woman want to do?A.Have her car repaired.B.Get a lift.C.Borrow a car.2.How much extra money does the man need to pay?A.$7.50.B.$1.50.C.$0.50.3.At what time will the woman arrive at the office tomorrow?A.8:00.B.8:30.C.9:00.4.How does the man feel about his test?A.Worried.B.Surprised.C.Satisfied.5.How did the boy get home from school yesterday?A.By car.B.By bus.C.By bike.第二节(共15小题；每小题1.5分，满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各个小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6、7题。
2017年三校联考数学试题文科答题卡 精品
严禁在此处作答 严禁在此处作答考 号 [0] [0] [0] [0] [0] [0] [0] [0] [0] [1] [1] [1] [1] [1] [1] [1] [1] [1][2] [2] [2] [2] [2] [2] [2] [2] [2][3] [3] [3] [3] [3] [3] [3] [3] [3][4] [4] [4] [4] [4] [4] [4] [4] [4][5] [5] [5] [5] [5] [5] [5] [5] [5] [6] [6] [6] [6] [6] [6] [6] [6] [6][7] [7] [7] [7] [7] [7] [7] [7] [7][8] [8] [8] [8] [8] [8] [8] [8] [8][9] [9] [9] [9] [9] [9] [9] [9] [9] 二、填空题（每题5分）13、 14、 15、 16、17．（1）姓名： 学校： 班级：19．（1）（2） （3） 2017年三校联考数学（文科）答题卡1 [A ] [B ] [C ] [D ]2 [A ] [B ] [C ] [D ]3 [A ] [B ] [C ] [D ]4 [A ] [B ] [C ] [D ]5 [A ] [B ] [C ] [D ]6 [A ] [B ] [C ] [D ]7 [A ] [B ] [C ] [D ]8 [A ] [B ] [C ] [D ]9 [A ] [B ] [C ] [D ] 10 [A ] [B ] [C ] [D ]（2） 11 [A ] [B ] [C ] [D ] 12 [A ] [B ] [C ] [D ] 第1页（共2页） 数学条形码粘贴处请勿贴出区域外 注意事项1.答题前，考生须准确填写自己姓名、准考证号等信息。
2.选择题必须使用2B 铅笔填涂，非选择题必须使用0.5毫米黑色签字笔书写，涂写要工整、清晰。
福建省宁德市2024-2025学年高三上学期期中五校联考数学试题及答案
福宁古五校教学联合体2024-2025学年第一学期期中质量监测高三数学试题（考试时间：120分钟，试卷总分：150分）注意事项：1．答卷前，考生务必将自己的姓名、准考证号填写在答题卡上．并将准考证号条形码粘贴在答题卡上的指定位置．2．选择题的作答：每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑．写在试卷、草稿纸和答题卡上的非答题区域均无效．3．填空题和解答题的作答：用黑色签字笔直接答在答题卡上对应的答题区域内．写在试卷、草稿纸和答题卡上的非答题区域均无效．一、单选题：本题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一个选项是正确的．1. 已知集合{}30,21x M x Q x x x −=≤=∈≤ + N ，则M Q ∩=（ ）A. {}0,1,2B. []0,2C. (]2,2−D. {}1,22. 某一物质在特殊环境下的温度变化满足：1015ln w w T w w −=−（T 为时间，单位为0min,w 为特殊环境温度，1w 为该物质在特殊环境下的初始温度，w 为该物质在特殊环境下冷却后的温度），假设一开始该物质初始温度为100℃，特殊环境温度是20℃，则经过15min ，该物质的温度最接近（参考数据：e 2.72≈）（ ） A. 54℃B. 52℃C. 50℃D. 48℃3. 在ABC 中，已知tan tan A,B 是关于x 方程2670x x −+=的两个实根，则角C 的大小为（ ） A.3π4B.2π3C.π3D.π44. 对任意实数()2,x ∈+∞,“4a x x<+”是“4a ≤”的（ ） A 充分不必要条件 B. 必要不充分条件 C 充要条件D. 既不充分也不必要条件的..5. 函数221sin ln x y x x+=−⋅的大致图象是（ ） AB.C. D.6. 已知函数()332e e 1x xf x x x −=−+−+，若()()2232f a f a−+≥，则实数a 的取值范围为（ ）A. (],1−∞B. []3,1−C. (][),13,−∞−+∞D. (][),31,−∞−∪+∞7. 已知1215sin ,ln ,223a b c −===，则（ ）A. c b a <<B. a b c <<C. a c b <<D. b a c <<8. 已知函数()2e ln xf x x x x a x =−−−，若对任意的0x >，都有()1f x ≥恒成立，则实数a 的取值范围为（ ） A. []4,4− B. []3,3− C. []22−,D. []1,1−二、多选题：本题共3小题，每小题6分，共18分．在每小题给出的选项中，有多项符合题目要求．全部选对得6分，选对但不全的得部分分，有选错的得0分．9. 已知三次函数()f x 的图象如图，则下列说法正确的是（ ）.A. ()()()Δ01Δ1lim 1Δx f x f f x→+−=−′B. ()()23f f ′′<C. 0f=D. ()0xf x ′>的解集为()(),10,1−∞−∪10. 已知函数()()ππ2cos 2,2sin 236f x x g x x =+=−，则（ ） A. ()f x 与()g x 的图象有相同的对称中心 B. ()f x 与()g x 图象关于x 轴对称 C. ()f x 与()g x 的图象关于y 轴对称 D. ()()f x g x ≥的解集为()5πππ,π1212k k k−++∈Z11. 已知函数()f x 的定义域为R ，且()10f ≠，若()()()f x y f x f y xy +−=−，则（ ） A. ()00f = B. ()f x 关于()1,0−中心对称 C. e xx >ff (xx )D. 函数()y xf x =−有最大值三、填空题：本题共4小题，每小题5分，共15分12. 已知复数z 满足()34i 5i z −=，则z =______． 13. 已知,,20,1a b a b a b ∈>>+=R ，则112a b b+−的最小值为______．14. 已知()()()eln e ,xxf x ax ag x x=−∈=R ，若函数()()y f g x a =−恰有三个零点，则a 的取值范围为______．四、解答题：本题共5小题，共77分．解答应写出文字说明、证明过程或演算步骤．15. 已知函数()1e 1xf x a =++为R 上的奇函数． （1）求a ；（2）若函数()()()2e 12xg x f x x =++，讨论()g x 的极值．16. 在锐角ABC 中，内角,,A B C 的对边分别为,,a b c，且tan tan A B +=. （1）求角A 的大小；的（2）若BC =，点D 是线段BC 的中点，求线段AD 长的取值范围．17. 在三棱锥P ABC −中，PM ⊥底面ABC ，AB AC ⊥，1AB =，AC =，,M N 分别为,BC AC的中点，E 为线段AP 上一点．（1）求证：BN ⊥平面APM ； （2）若平面EBN ⊥底面ABC 且12PM =，求二面角A EN B −−的正弦值． 18. 已知函数()()2311ex x f x a x b −=−−−−，其中,a b 是实数． （1）若1a =，求()f x 的单调区间；（2）若函数()f x 在定义域上是单调函数，求实数a 的取值范围； （3）若()0f x ≤恒成立，求5a b +的最小值． 19. 已知函数()(πsin ,0,2f x x ωϕωϕ =+><图象的相邻两条对称轴间的距离为π2，且函数()f x 图象过点 ． （1）若函数()y f x m =+是偶函数，求m 的最小值； （2）令()()41g x f x =+，记函数()g x 在17π31π,1212x∈−上的零点从小到大依次为12,,,n x x x ，求1231222n n x x x x x −+++++ 的值；（3）设函数(),y x x D ϕ=∈，如果对于定义域D 内的任意实数x ，对于给定的非零常数P ，总存在非零常数T ，恒有()()x T P x ϕϕ+=⋅成立，则称函数()x ϕ是D 上的“P 级周期函数”，周期为T ．请探究是否存在非零实数λ，使函数()1π26xh x f x λ =−是R 上的周期为T 的T 级周期函数，并证明你的结论．福宁古五校教学联合体2024-2025学年第一学期期中质量监测高三数学参考答案一、单选题：1 【答案】A【详解】不等式301x x −≤+的解集等价于不等式组()()31010x x x −+≤ +≠的解集， 即131x x −≤≤≠−，得13x −<≤，又2x ≤，解得22x −≤≤， 于是{}30131x M xx x x−=≤=−<≤ +，{}{}{}2220,1,2Q x x x x =∈≤=∈−≤≤=N N ，则{}0,1,2M Q ∩=. 故选：A 2.【答案】C【详解】由初始温度为100℃，特殊环境温度是20℃，时间15min 代入题中式子得：100201515ln20w −=−，即80e 20w =−，即8080202049.41e 2.72w =+≈+≈. 故选：C.3. 【答案】D【详解】由题意，tan tan 6,tan tan 7A B A B +=⋅=， 所以()tan tan 6tan 11tan tan 17A B A B A B ++===−−⋅−，由()()tan tan πtan A B C C +=−=−，故tan 1C =， 又0πC <<，所以π4C =. 故选：D 4. 【答案】C.【详解】对于函数4y x x=+，根据均值不等式a b +≥（当且仅当a b =时取等号），则44y x x =+≥=. 当4x x =即2x =时取等号，但是(2,)x ∈+∞，所以44y x x=+> 判断充分性: 若4a x x <+，因为(2,)x ∈+∞时44x x+>，那么4a ≤，所以充分性成立. 判断必要性:若4a ≤，当(2,)x ∈+∞时44x x+>，显然4a x x <+，所以必要性成立.所以“4a x x<+”是“4a ≤”的充要条件. 故选：C. 5. 【答案】C【详解】函数221sin ln x y x x +=−⋅的定义域为()(),00,∞∞−∪+， ()()()()()222211sin ln ln x x f x x x f x x x −++−=−−⋅=⋅=−−， 则函数为奇函数，排除选项A 和B ； 当πx =时，函数值为0，取2π4ln 102πf =−+<，排除选项D , 故选：C . 6. 【答案】D【详解】由已知222()92e e 9290x x f x x x x −′=−++≥−+=≥，当且仅当0x =时等号成立，所以()f x 是R 上的增函数，又2()33e e 1x x f x x x −−=−++−+2()f x =−， 所以不等式()()2232f a f a−+≥化为2()2(23)(32)f a f a f a ≥−−=−，所以232a a ≥−，解得1a ≥或3a ≤−． 故选：D ． 7. 【答案】B【详解】令ff (xx )=xx −sin xx (xx >0),gg (xx )=xx −1−ln xx ,ℎ(xx )=ln xx −2(xx−1)xx+1，则()()()()()()22211141cos 0,,011x x f x x g x h x x x x x x −−′=−≥==−=+′′≥+，显然01x <<时()0g x ′<，1x >时()0g x ′>， 所以()(),f x h x 在(0,+∞)上单调递增，()g x 在(0,1)上单调递减，在(1,+∞)上单调递增，所以ff (xx )>ff (0)⇒sin xx <xx ,gg (xx )≥gg (1)=0⇒xx −1≥ln xx （1x =时取得等号）， ()()()()21101ln 1x h x h x x x −≥=≥⇒≥+（1x =时取得等号），故52111523sin ln 5223313−<=<<<+a b c <<. 故选：B 8. 【答案】D【详解】()()2ln 1,e2ln 1x xf x x x x a x +≥∴−++−≥ ，即()2ln e 2ln 11x x x x a x+−+−−≤，令()()e 1e 1xxg x x g x =−−⇒=−′， 显然0x >时()0g x ′>，0x <时()0g x ′<，即()g x 在(0,+∞)上单调递增，在(),0∞−上单调递减，所以()()00g x g ≥=， 则()2ln e 1,e 2ln 10xx xx x x +≥+∴−+−≥，又∵xx >0,∴ee 2xx+ln xx −(2xx+ln xx )−1xx≥0，当且仅当2ln 0x x +=时，等号成立．()2ln min2ln 10,10,11x x e x x a a x + −+−∴=∴−≤∴−≤≤ ． 故选：D ．二、多选题：9. 【答案】ACD【详解】由图可知，三次函数()f x 为奇函数，且()f x 的极值点为1、1−， 设()32f x bx cx dx e =+++，则()00f e ==，可得()32f x bx cx dx =++，由奇函数的定义可得ff (−xx )=−ff (xx )，即()()()3232b x c x d x bx cx dx ⋅−+⋅−+⋅−=−−−， 所以0c =，可得()3f x bx dx =+，则()23f x bx d ′=+，由题意可得()130f b d ′=+=，可得3d b =−，则()233f x bx b ′=−，由图可知，函数()f x 的单调递增区间为(−1,1)，故不等式ff ′(xx )=3bbxx 2−3bb >0解集为(−1,1)，所以0b <， 对于A 选项，由题意可知，()()110f f ′−′==，由导数的定义可得()()()()Δ01Δ1lim11Δx f x f f f x→+−=′′=−，故A 正确；对于B 选项，()21239f b b b −′==，()327324f b b b =−=′， 由0b <，924b b >，所以()()23f f ′>′，故B 错误； 对于C 选项，()33f x bx bx =−，所以0f=−=，故C 正确；对于D 选项，由xxff ′(xx )=xx ⋅3bb (xx 2−1)=3bbxx (xx −1)(xx +1)>0， 可得()()110x x x −+<，解得1x <−或01x <<，因此，不等式()0xf x ′>的解集为()(),10,1∞−−∪，故D 正确. 故选：ACD 10. 【答案】ABD【详解】()()πππ2sin 22cos 2323g x x x f x =+−=−+=−， 即()f x 与()g x 的图象关于x 轴对称， 令ππππ2π32122k x k x +=+⇒=+， 的且有相同的对称中心()ππ,0Z 122k k+∈，故A 、B 正确，C 错误； 由不等式()()()π20cos 203f x g x f x x≥⇒≥⇒+≥， 令()πππ5ππ2π22ππ,πZ 2321212k x k x k k k+≥+≥−+⇒∈−++∈，故D 正确. 故选：ABD 11.【答案】BD【详解】令0,1x y ==，则()()()1010f f f −⋅=， 又()()10,01f f ≠∴=，故A 错误；令1,1x y ==−，则()()()()()0111,110f f f f f −⋅−=∴⋅−=， 又()10f ≠，()10f ∴−=，再令()()()()1,11,1y f x f x f x f x x =−−−⋅−=∴−=，()()1,f x x f x ∴=+∴的图象关于()1,0−中心对称，故B 正确；由B 得()1f x x =+，当0x =时，1x e x =+，故C 错误；由B 得()()21,f x x y xf x x x =+=−=−−，在12x =−时取到最大值，故D 正确．三、填空题：12. 【答案】1【详解】由()()()()5i 34i 5i 3434i 5i i 34i 34i 34i 55z z +−=⇒===−−−+，则1z z ===. 故答案为：113.【答案】4+；【详解】因为20a b >>，1a b +=，所以111132()(23)44222b a ba b b a b b a b b a b b−+=+−+=++≥+−−−，当且仅当322b a b a b b −=−，即a b ==时等号成立， 故答案：4+． 14. 【答案】e 1,2【详解】设()g x t =，则()f t a =，()21ln e 0xg x x−′=⋅=，得e x =， 当()()()0,e ,0,x g x g x >′∈单调递增，当()()()e,0,x g x g x ′∈+∞<,单调递减， 当e x =时，函数()g x 取得最大值1， 如图1，画出函数()t x g =的图象，由()f t a =，即e t at a −=，则()()e 1,1a t y a t =+=+恒过点()1,0−，如图，画出函数e t y =的图象，设过点()1,0−的切线与e t y =相切于点()00,e tt ，则00e e 1t t t =+，得00t =，即切点()0,1，所以切线方程为1y x =+， 如图2，则()1y a t =+与e t y =有2个交点，1a >，如图可知，若函数()()y f g x a =+恰有三个零点，则110t −<<，201t <<，则()le 11a >+，所以e 2a <，为综上可知，e 12a <<． 故答案为：e 1,2四、解答题：15.【答案】（1）12a =− （2）极大值为2ln21−；无极小值.【解析】【小问1详解】因为函数()1e 1x f x a =++为RR 上的奇函数， 由()100,2f a =∴=−， 此时()()1e 2e 1xx f x −=+， 则()()111e e 1e e 11e e ()1e 2(e 1)2(e 1)2(e 1)2e 121e x x x x xxx x x x x x f x f x −−−−−−−−===×==−=−+++ ++ ， 所以()f x 为奇函数．所以12a =−； 【小问2详解】由（1）得：()()()()2e 122e 1,x x g x f x x x g x =++=−+定义域为RR ， ()2e x g x ∴=−′，由()0g x ′>，得ln2x <；由()0g x ′<，得ln2x >，()g x ∴在(),ln2∞−上单调递增，()g x 在()ln2,∞+上单调递减，所以()g x 在ln2x =处取得极大值，()g x 极大值()ln22ln21f ==−；无极小值.16. 【答案】（1）π3A =；（2）32.【解析】【小问1详解】因为tan tan A B +=，所以由正余弦定理得tan tan A B +===， 又()sin sin sin sin cos sin cos sin tan tan cos cos cos cos cos cos cos cos A B A B A B B A C A B A B A B A B A B +++=+===，sin cos cos C A B=，又ABC 是锐角三角形，所以sin 0,cos 0C B >>，所以sin A A =，所以tan A =又π0,2A∈ ，所以π3A =. 【小问2详解】由余弦定理可得222222cos 3a c b cb A c b cb =+−=+−=，即223c b cb +=+， 又()12AD AB AC =+ ， 所以()()222222111()2444AD AB AC AB AC AB AC c b bc =+=++⋅=++ ()13132442bc bc =+=+， 又由正弦定理可得2sin sin sin a b c A B C===，所以2sin b B =，2π12sin 2sin 2sin 32c C B B B ==−=+，所以2111cos24cos sin 4222B bc B B B B −=+=+⋅111π4cos22cos212sin 214426B B B B B =−+=−+=−+，由题意得π0,22ππ0,32B B << <−< 解得ππ62B <<，则ππ5π2,666B −∈ ， 所以π1sin 2,162B−∈，所以(]2,3bc ∈， 所以279,44AD ∈ ，所以线段AD长的取值范围为32 . 17. 【答案】（1）证明见解析（2【解析】【小问1详解】解法一：连接AM 交BN 与点O ，则MAC MCA ∠=∠，tan AB MCA AC ∠==，tan AN ABN AB ∠==， 故ABN MCA MAC ∠=∠=∠，从而90MAB ABN MAB MAC ∠+∠=∠+∠=°，从而AM BN ⊥， PM ⊥ 底面ABC ，BN ⊂ABC ，∴PM BN ⊥， 又AM PM M = ，AM PM ⊂，平面APM ，故BN ⊥平面APM 解法二：连接AM ，由,M N 分别为BC ，AC 的中点，所以1122AM AB AC =+ ， 12BN AB AC =−+ ， 又因为AB AC ⊥，1AB =，AC = 所以1110222AM BN AB AC AB AC ⋅=+⋅−+= ，故AM BN ⊥ ，从而AM BN ⊥， ∵PM ⊥底面ABC ，BN ⊂底面ABC ，∴PM BN ⊥， 又AM PM M = ，AM PM ⊂，平面APM ，故BN ⊥平面APM【小问2详解】因为AB AC ⊥，故以点A 为坐标原点，,AB AC 所在直线分别为,x y 轴，过点A 作垂直于平面ABC 的直线为z 轴建立如图所示的空间直角坐标系，则()0,0,0A，()C ,()1,0,0B,1122P,N,12M ，则()AC =，BN =−，1122AP = ,因为平面EBN ⊥底面ABC ，且AM BN ⊥，则AM ⊥平面EBN，则12AM =,易得平面EBN的一个法向量为()1n = ，设平面PAC 的一个法向量为()2,,n x y z = ， 则2200AP n AC n ⋅= ⋅=，可得110220x y z = =，令1x =可得()21,0,1n =− ， 设二面角A EN B −−为θ，则12cos cos ,n n θ=〉〈== 故二面角A EN B −−18. 【答案】（1）()f x 在(),0−∞单调递增，()0,∞+单调递减； （2）413ea ≤−（3）1−．【解析】【小问1详解】 当1a =时，()()2311e x x f x x b −=−−−−，则()33e exx x f x −′−=，易知33e x y x =−−单调递减，且0x =时，0y =， 所以令ff ′(xx )>0，解得0x <，令ff ′(xx )<0，解得0x >， 所以()f x 在(),0∞−单调递增，(0,+∞)单调递减；【小问2详解】函数()f x 的图象是连续的，且在定义域上是单调函数，()330ex x f x a −∴=−≥′在定义域内恒成立， 或()330ex x f x a −=−≤′，在定义域内恒成立． 令()()()4ex x g x f x g x =′−⇒′=，显然()g x ′在(),4∞−为负，()4,∞+为正， 所以()33ex x f x a −′=−在(),4∞−单调递减，()4,∞+单调递增， ①若()330ex x f x a −=−≥′在定义域内恒成立， 只需()min 41()430e f x f a ==−−′≥′，即413ea ≤−， ②若()330e x x f x a −=−≤′在定义域内恒成立， x →−∞ 时，()f x ∞′→+，故该情况a 无解． 综上：413e a ≤−； 【小问3详解】 若()0f x ≤恒成立，则()23110ex x a x b −−−−−≤， 当2x =时，510a b −−−≤，即51a b +≥−， 下证51a b +=−成立，由51a b +=−得，()23150e x x a x a −−−+≤恒成立， 即()()2136230e e x x x a x x a − −−=−−≤， 易知12,3ex y x y a =−=−在R 上分别单调递增、单调递减， 又记()20F =，要满足题意需12,3e x y x y a =−=−零点相同， 即2130e a −=，解得213ea =， 即只需证()()221360e 3ex x F x x −=−−≤恒成立，()231e ex x F x ′−=−，由（2）得()F x ′在(),4∞−上单调递减，在()4,∞+上单调递增， 又()()20,F F x =′∴′在(),2∞−上为正，在()2,4上为负，在()4,∞+上为负， ()F x ∴在(),2∞−上单调递增，在()2,∞+上单调递减，()max ()20F x F ∴==， 即()0F x ≤恒成立，5a b ∴+最小值为1−．19. 【答案】（1）π12． （2）49π6（3）存在，证明见解析【解析】【小问1详解】()f x 图象的相邻的两条对称轴间的距离为π2()f x ∴的最小正周期为π2π2T =×=， 2π0,2Tωω>∴== ()()sin 2f x x ϕ∴=+，又()f x 的图象过点(),0sin f ϕ ∴== ． ()πππ,,sin 2233f x x ϕϕ <∴==+， 因为函数()πsin 223y f x m x m=+=++是偶函数， ()()ππππ2π,32122k m k k m k ∴+=+∈∴=+∈Z Z ． m ∴的最小值π12． 【小问2详解】由()()π414sin 2103g x f x x=+=++= 可得π1sin 234x +=−， 17π31ππ5π11π,,2,1212322x x ∈−∴+∈−， 设π23i i x t +=，由sin y t =与14y =−图象可知在5π11π,22 −共有8个交点．182736453πt t t t t t t t +=+=+=+=，1818ππ7π223π,336x x x x ∴+++=∴+=，同理2345672222227πx x x x x x +++++=， 1234567849π2222226x x x x x x x x ∴+++++++=． 【小问3详解】()()()π1π1sin 2,sin 23262x xf x x h x f x x λλ =+∴−=假设存在非零实数λ，使得函数()()1sin 22x h x x λ =是R 上的周期为T 的T 级周期函数，即x ∀∈R ，恒有()()h x T T h x +=⋅， 则x ∀∈R ，恒有()()11sin 22sin 222x T x x T T x λλλ+ +=⋅成立，则x ∀∈R ，恒有()()sin 222sin 2T x T T x λλλ+=⋅成立，当0λ≠时，x ∀∈R ，则2,22x x T λλλ∈+∈R R ， 所以()1sin21,1sin 221x x T λλλ−≤≤−≤+≤，要使得()sin 222sin2T x T T x λλλ+=⋅恒成立，则有21T T ⋅=±①当21T T ⋅=时，则0T >，即12T T =，令()12x p x x=−，其中0x >，则()120,121102p p =−<=−=>， 且函数()p x 在()0,∞+上的图象是连续的，由零点存在定理可知，函数()p x 在()0,∞+上有唯一的零点， 此时，()sin 22sin2x T x λλλ+=恒成立，则()22T m m λπ=∈Z ，即()m m Tπλ=∈Z ； ②当21T T ⋅=−时，则0T <，即2T T −−=，作出函数y x =−、2x y −=的图象如下图所示：由图可知，函数2x y x y −=−=、的图象没有公共点， 故方程21T T ⋅=−无实数解． 综上所述，存在()πm m Tλ=∈Z 满足题意，其中T 满足21T T ⋅=。
2017届高三第一次五校联考-英语答题卡
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2017 届-广东省五校协作体-第一次联考-英语答题卡 第 1 页/共 2 页 请勿在框线外
Last month, I, as well as my parents, were invited to my uncle’s home in the United States. My uncle, moved to America when I was five, has been living there for nearly ten years. She met us in the airport. I was exciting when I set my foot on the land of America. In the followed days, we visited some places of interest and took photos in the front of the Statue of Liberty. We all enjoyed visiting the Museum of Natural History so it enriched our knowledge great. For me, this is one of the most rewarding trips which I have ever made in my life and I look forward to go there again.
作文（25 分）
Dear Mr./Ms. Wang,
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2017学年浙江省高中三年级“五校联考”第一次考试
2017学年浙江省高三“五校联考”第一次考试英语试题卷命题学校：杭州高级中学第二部 4分：阅读理解（共两节，满分35分）第一节（共10个小题：每小题2.5分，满分25分）阅读下列短文，从每题所给的A，B，C，D四个选项中，选出最佳选项，并在答题卷上将该选项涂黑。
AAt 27, after serving in World War II, I dreamed of owning a piece of land. So I moved from central Illinois to Shelbina, Missouri, and bought 236 acres for $6,000. The plot of land was situated on a dirt road and was half farmland and half trees, with an old house that had no running water or electricity. Obviously, it was not what you’d call prime real estate. But it was mine.I was alone for the first time in my life, and I found it liberating. My days were filled from dawn until dusk with plowing and planting corn. Dinnertime came and went, and I barely remembered to eat.I wouldn’t say I was a great success at farmi ng in Missouri. However, when I went to the store to buy some plowshares, I met a nice woman named Claudette working behind the counter. I also ran into her at St. Mary’s Catholic Church in Shelbina each week. I found out later that her manager kept asking her about “that tall boy (and eligible bachelor) from Illinois living out in the country in an old house with no water, no electricity and no housekeeper.”Claudette and her sister soon visited my farm and put up some curtains. To show my appreciation, I took Claudette out for a ride in my 2 ⅟2-ton Studebaker truck. We married in 1954 and have now been together for more than 62 years!I later sold the Missouri farm for a $3,500 profit and bought 40 acres in Illinois. For many reasons, buying the Missouri farm was a good idea. I will always cherish memories of owning the farm and meeting my beloved.1. When the author bought the plot of land in Shelbina, ________.A. it was well equippedB. he was unsatisfied with itC. it was not a real estateD. he worked very hard on it2. The underlined word “liberating” in paragraph 2 can be replaced by the word ________.A. upsetB. interestingC. freeD. boring3. The author regards buying the Missouri farm as a good idea because _______.A. he was able to sell it at the price of $3,500B. he could recall plenty of experiences in his own farmC. he got the chance to meet his wife working at a church in Shelbina thenD. he could purchase another house in Illinois as a result of successful farming 【答案】1.D 2.C 3.BBNinety percent of Americans drive to work every day although working from home is on the rise. If you’re lacking for topics of conversation at a party, chatting about your commute is a pretty safe bet.According to a recent study, driving for more than two hours each day can steadily decrease the IQ of middle aged drivers. The Sunday Times of London detailed the study, which looked into the lifestyle choices of over 500,000 Britons between the ages of 37 and 73.When looking at the data of the 93,000 participants who drove more than two to three hours per day, the study found a noticeable dropoff in brainpower, measured by intelligence and memory tests. The study found similar results with participants who took part in several hours similarly sedentary (久坐的) activity, like television watching.As it turns out, stimulating activity stimulates your brain, whilenon-stimulating activity, well, doesn’t stimulate your brain.“Cognitive (认知的) decline is measurable over five years because it can happen fast in middle-aged and older people. This is associated with lifestyle factors such as smoking and bad diet —and now with time spent driving,” Kishran Bakrania, a medical epidemiologist at the University of Leicester told the Times.Fortunately for most Americans, the average commute time was recorded at approximately 26.5 minutes according to the 2015 United States Census.And if you think that the way to pump up your IQ is through brain games, think again. Just try and avoid those long hours on the road if possible, and if you happen to have free time on your commute, be sure to use it wisely.1. According to the passage, which of the following may be of help to our brainpower?A. Watching TV.B. Having sports.C. Driving long timeD. Sleeping.2. Why does the writer mention “results with people participating in similarly sedentary activities” in para3?A. To make a contrast.B. To give an example.C. To make a description.D. To give more evidence.3. We can infer from the passage that ________.A. long time drive may decrease the driver’s IQB. smoking and bad diet can cause cognitive declineC. people should participate in more stimulating activitiesD. an increasing number of Americans drive to work every day【答案】1.B 2.D 3.CCIt used to be a matter of fact when Peter Pan —a character from James Matthew Barrie’s 1911 book —said: “All children, except one, grow up.”But this “fact” doesn’t seem to apply to today’s world anymore.According to the NPD Group, a US market research company, sales of toys to adults in the UK increased by more than 20 percent in 2016, three times the pace of the children’s toy market itself. These toys ranged from puzzles and Lego building sets to vehicle models and action figures. And more than half of the sales came from millennials — people born between the 1980s and 2000s.“Adults of the 21st century are channeling their inner child, one toy at a time,” commented website Koreaboo. This is also why these adults are sometimes refer red to as “kidults”.According to Frederique Tutt, an analyst at NPD, the motivation of these grown-ups is to escape the stress of today’s fast-paced world. They are driven toward the more immediate pleasures brought by toys than those brought by, say, getting a promotion, which is far less easy to achieve.“It reminds me of the playful side of life,” Rob Willner, a 25-year-old PhD student in the UK, told The Telegraph when talking about his love for Lego, which he said brings him both comfort and entertainment.Despite this, some social scientists see the trend as disturbing. To Frank Furendi, a professor at the University of Kent in the UK, the fact that so many adults are pursuing “the thrills of youth” is the evidence that “adulthood has got nothing attr active about it anymore”, he told The New York Times. “That’s actually quite sad.”But scientists are probably just worrying too much. According to Canadian comic book artist Todd McFarlane, collecting toys could simply be a way for people to express their individuality. “It’s just pop culture stuff. It’s stuff that says, ‘I like a little of this and I like a little of that’,” he told ABC News. “It’s no big deal.”So now that over 100 years have passed since Peter Pan, perhaps it’s time to introduce a new “fact”, as stated in the tagline (标语) of the UK fashion brand KIDULT: “Growing old is mandatory (被迫的), but growing up is optional.”1. What does the underlined sentence in paragraph 2 imply?A. Something old is not suitable for a new world.B. Many adults still have some childlike features.C. All children grow up as they become adults.D. It’s difficult for some children to grow up in today’s world.2. Which of the following statements is true?A. Frederique Tutt believes that some adults enjoy playing with children’s toys to escape the stress.B. Rob Willner believes that the pleasure brought by toys is easier to achieve.C. Frank Furendi believes that the thrill of youth does not attract adults.D. Todd McFarlane is worrying too much about collecting toys.3. What is the writer’s attitude towards the trend of growing kidults?A. SupportiveB. DoubtfulC. CriticalD. Indifferent4. What can be the best title for the passage?A. Growing Old Or Growing UpB. Toys Sales On The RiseC. Staying Young ForeverD. Kidults In Fashion Again【答案】1.B 2.A 3.A 4.C第二节（共5个小题，每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，选项中有两项为多余部分。