On finite sequences satisfying linear recursions
Tektronix MDO3000 Series 数字多功能作业仪用户指南说明书

19StandardMath ToolsDisplay up to four math function traces (F1-F4). The easy-to-use graphical interface simplifies setup of up to two operations on each function trace;and function traces can be chained together to perform math-on-math.absolute value integralaverage (summed)invert (negate)average (continuous)log (base e)custom (MATLAB) – limited points product (x)derivativeratio (/)deskew (resample)reciprocaldifference (–)rescale (with units)enhanced resolution (to 11 bits vertical)roof envelope (sinx)/x exp (base e)square exp (base 10)square root fft (power spectrum, magnitude, phase,sum (+)up to 50 kpts) trend (datalog) of 1000 events floorzoom (identity)histogram of 1000 eventsMeasure ToolsDisplay any 6 parameters together with statistics, including their average,high, low, and standard deviations. Histicons provide a fast, dynamic view of parameters and wave-shape characteristics.Pass/Fail TestingSimultaneously test multiple parameters against selectable parameter limits or pre-defined masks. Pass or fail conditions can initiate actions including document to local or networked files, e-mail the image of the failure, save waveforms, send a pulse out at the rear panel auxiliary BNC output, or (with the GPIB option) send a GPIB SRQ.Jitter and Timing Analysis Software Package (WRXi-JTA2)(Standard with MXi-A model oscilloscopes)•Jitter and timing parameters, with “Track”graphs of •Edge@lv parameter (counts edges)• Persistence histogram, persistence trace (mean, range, sigma)Software Options –Advanced Math and WaveShape AnalysisStatistics Package (WRXi-STAT)This package provides additional capability to statistically display measurement information and to analyze results:• Histograms expanded with 19 histogram parameters/up to 2 billion events.• Persistence Histogram• Persistence Trace (mean, range, sigma)Master Analysis Software Package (WRXi-XMAP)(Standard with MXi-A model oscilloscopes)This package provides maximum capability and flexibility, and includes all the functionality present in XMATH, XDEV, and JTA2.Advanced Math Software Package (WRXi-XMATH)(Standard with MXi-A model oscilloscopes)This package provides a comprehensive set of WaveShape Analysis tools providing insight into the wave shape of complex signals. Includes:•Parameter math – add, subtract, multiply, or divide two different parameters.Invert a parameter and rescale parameter values.•Histograms expanded with 19 histogram parameters/up to 2 billion events.•Trend (datalog) of up to 1 million events•Track graphs of any measurement parameter•FFT capability includes: power averaging, power density, real and imaginary components, frequency domain parameters, and FFT on up to 24 Mpts.•Narrow-band power measurements •Auto-correlation function •Sparse function• Cubic interpolation functionAdvanced Customization Software Package (WRXi-XDEV)(Standard with MXi-A model oscilloscopes)This package provides a set of tools to modify the scope and customize it to meet your unique needs. Additional capability provided by XDEV includes:•Creation of your own measurement parameter or math function, using third-party software packages, and display of the result in the scope. Supported third-party software packages include:– VBScript – MATLAB – Excel•CustomDSO – create your own user interface in a scope dialog box.• Addition of macro keys to run VBScript files •Support for plug-insValue Analysis Software Package (WRXi-XVAP)(Standard with MXi-A model oscilloscopes)Measurements:•Jitter and Timing parameters (period@level,width@level, edge@level,duty@level, time interval error@level, frequency@level, half period, setup, skew, Δ period@level, Δ width@level).Math:•Persistence histogram •Persistence trace (mean, sigma, range)•1 Mpts FFTs with power spectrum density, power averaging, real, imaginary, and real+imaginary settings)Statistical and Graphical Analysis•1 Mpts Trends and Histograms •19 histogram parameters •Track graphs of any measurement parameterIntermediate Math Software Package (WRXi-XWAV)Math:•1 Mpts FFTs with power spectrum density, power averaging, real, and imaginary componentsStatistical and Graphical Analysis •1 Mpts Trends and Histograms •19 histogram parameters•Track graphs of any measurement parameteramplitude area base cyclescustom (MATLAB,VBScript) –limited points delay Δdelay duration duty cyclefalltime (90–10%, 80–20%, @ level)firstfrequency lastlevel @ x maximum mean median minimumnumber of points +overshoot –overshoot peak-to-peak period phaserisetime (10–90%, 20–80%, @ level)rmsstd. deviation time @ level topΔ time @ levelΔ time @ level from triggerwidth (positive + negative)x@ max.x@ min.– Cycle-Cycle Jitter – N-Cycle– N-Cycle with start selection – Frequency– Period – Half Period – Width– Time Interval Error – Setup– Hold – Skew– Duty Cycle– Duty Cycle Error20WaveRunner WaveRunner WaveRunner WaveRunner WaveRunner 44Xi-A64Xi-A62Xi-A104Xi-A204Xi-AVertical System44MXi-A64MXi-A104MXi-A204MXi-ANominal Analog Bandwidth 400 MHz600 MHz600 MHz 1 GHz 2 GHz@ 50 Ω, 10 mV–1 V/divRise Time (Typical)875 ps500 ps500 ps300 ps180 psInput Channels44244Bandwidth Limiters20 MHz; 200 MHzInput Impedance 1 MΩ||16 pF or 50 Ω 1 MΩ||20 pF or 50 ΩInput Coupling50 Ω: DC, 1 MΩ: AC, DC, GNDMaximum Input Voltage50 Ω: 5 V rms, 1 MΩ: 400 V max.50 Ω: 5 V rms, 1 MΩ: 250 V max.(DC + Peak AC ≤ 5 kHz)(DC + Peak AC ≤ 10 kHz)Vertical Resolution8 bits; up to 11 with enhanced resolution (ERES)Sensitivity50 Ω: 2 mV/div–1 V/div fully variable; 1 MΩ: 2 mV–10 V/div fully variableDC Gain Accuracy±1.0% of full scale (typical); ±1.5% of full scale, ≥ 10 mV/div (warranted)Offset Range50 Ω: ±1 V @ 2–98 mV/div, ±10 V @ 100 mV/div–1 V/div; 50Ω:±400mV@2–4.95mV/div,±1V@5–99mv/div,1 M Ω: ±1 V @ 2–98 mV/div, ±10 V @ 100 mV/div–1 V/div,±10 V @ 100 mV–1 V/div±**********/div–10V/div 1 M Ω: ±400 mV @ 2–4.95 mV/div, ±1 V @5–99 mV/div, ±10 V @ 100 mV–1 V/div,±*********–10V/divInput Connector ProBus/BNCTimebase SystemTimebases Internal timebase common to all input channels; an external clock may be applied at the auxiliary inputTime/Division Range Real time: 200 ps/div–10 s/div, RIS mode: 200 ps/div to 10 ns/div, Roll mode: up to 1,000 s/divClock Accuracy≤ 5 ppm @ 25 °C (typical) (≤ 10 ppm @ 5–40 °C)Sample Rate and Delay Time Accuracy Equal to Clock AccuracyChannel to Channel Deskew Range±9 x time/div setting, 100 ms max., each channelExternal Sample Clock DC to 600 MHz; (DC to 1 GHz for 104Xi-A/104MXi-A and 204Xi-A/204MXi-A) 50 Ω, (limited BW in 1 MΩ),BNC input, limited to 2 Ch operation (1 Ch in 62Xi-A), (minimum rise time and amplitude requirements applyat low frequencies)Roll Mode User selectable at ≥ 500 ms/div and ≤100 kS/s44Xi-A64Xi-A62Xi-A104Xi-A204Xi-A Acquisition System44MXi-A64MXi-A104MXi-A204MXi-ASingle-Shot Sample Rate/Ch 5 GS/sInterleaved Sample Rate (2 Ch) 5 GS/s10 GS/s10 GS/s10 GS/s10 GS/sRandom Interleaved Sampling (RIS)200 GS/sRIS Mode User selectable from 200 ps/div to 10 ns/div User selectable from 100 ps/div to 10 ns/div Trigger Rate (Maximum) 1,250,000 waveforms/secondSequence Time Stamp Resolution 1 nsMinimum Time Between 800 nsSequential SegmentsAcquisition Memory Options Max. Acquisition Points (4 Ch/2 Ch, 2 Ch/1 Ch in 62Xi-A)Segments (Sequence Mode)Standard12.5M/25M10,00044Xi-A64Xi-A62Xi-A104Xi-A204Xi-A Acquisition Processing44MXi-A64MXi-A104MXi-A204MXi-ATime Resolution (min, Single-shot)200 ps (5 GS/s)100 ps (10 GS/s)100 ps (10 GS/s)100 ps (10 GS/s)100 ps (10 GS/s) Averaging Summed and continuous averaging to 1 million sweepsERES From 8.5 to 11 bits vertical resolutionEnvelope (Extrema)Envelope, floor, or roof for up to 1 million sweepsInterpolation Linear or (Sinx)/xTrigger SystemTrigger Modes Normal, Auto, Single, StopSources Any input channel, External, Ext/10, or Line; slope and level unique to each source, except LineTrigger Coupling DC, AC (typically 7.5 Hz), HF Reject, LF RejectPre-trigger Delay 0–100% of memory size (adjustable in 1% increments, or 100 ns)Post-trigger Delay Up to 10,000 divisions in real time mode, limited at slower time/div settings in roll modeHold-off 1 ns to 20 s or 1 to 1,000,000,000 events21WaveRunner WaveRunner WaveRunner WaveRunner WaveRunner 44Xi-A 64Xi-A 62Xi-A104Xi-A 204Xi-A Trigger System (cont’d)44MXi-A64MXi-A104MXi-A204MXi-AInternal Trigger Level Range ±4.1 div from center (typical)Trigger and Interpolator Jitter≤ 3 ps rms (typical)Trigger Sensitivity with Edge Trigger 2 div @ < 400 MHz 2 div @ < 600 MHz 2 div @ < 600 MHz 2 div @ < 1 GHz 2 div @ < 2 GHz (Ch 1–4 + external, DC, AC, and 1 div @ < 200 MHz 1 div @ < 200 MHz 1 div @ < 200 MHz 1 div @ < 200 MHz 1 div @ < 200 MHz LFrej coupling)Max. Trigger Frequency with400 MHz 600 MHz 600 MHz 1 GHz2 GHzSMART Trigger™ (Ch 1–4 + external)@ ≥ 10 mV@ ≥ 10 mV@ ≥ 10 mV@ ≥ 10 mV@ ≥ 10 mVExternal Trigger RangeEXT/10 ±4 V; EXT ±400 mVBasic TriggersEdgeTriggers when signal meets slope (positive, negative, either, or Window) and level conditionTV-Composite VideoT riggers NTSC or PAL with selectable line and field; HDTV (720p, 1080i, 1080p) with selectable frame rate (50 or 60 Hz)and Line; or CUSTOM with selectable Fields (1–8), Lines (up to 2000), Frame Rates (25, 30, 50, or 60 Hz), Interlacing (1:1, 2:1, 4:1, 8:1), or Synch Pulse Slope (Positive or Negative)SMART TriggersState or Edge Qualified Triggers on any input source only if a defined state or edge occurred on another input source.Delay between sources is selectable by time or eventsQualified First In Sequence acquisition mode, triggers repeatedly on event B only if a defined pattern, state, or edge (event A) is satisfied in the first segment of the acquisition. Delay between sources is selectable by time or events Dropout Triggers if signal drops out for longer than selected time between 1 ns and 20 s.PatternLogic combination (AND, NAND, OR, NOR) of 5 inputs (4 channels and external trigger input – 2 Ch+EXT on WaveRunner 62Xi-A). Each source can be high, low, or don’t care. The High and Low level can be selected independently. Triggers at start or end of the patternSMART Triggers with Exclusion TechnologyGlitch and Pulse Width Triggers on positive or negative glitches with widths selectable from 500 ps to 20 s or on intermittent faults (subject to bandwidth limit of oscilloscope)Signal or Pattern IntervalTriggers on intervals selectable between 1 ns and 20 sTimeout (State/Edge Qualified)Triggers on any source if a given state (or transition edge) has occurred on another source.Delay between sources is 1 ns to 20 s, or 1 to 99,999,999 eventsRuntTrigger on positive or negative runts defined by two voltage limits and two time limits. Select between 1 ns and 20 sSlew RateTrigger on edge rates. Select limits for dV, dt, and slope. Select edge limits between 1 ns and 20 s Exclusion TriggeringTrigger on intermittent faults by specifying the normal width or periodLeCroy WaveStream Fast Viewing ModeIntensity256 Intensity Levels, 1–100% adjustable via front panel control Number of Channels up to 4 simultaneouslyMax Sampling Rate5 GS/s (10 GS/s for WR 62Xi-A, 64Xi-A/64MXi-A,104Xi-A/104MXi-A, 204Xi-A/204MXi-A in interleaved mode)Waveforms/second (continuous)Up to 20,000 waveforms/secondOperationFront panel toggle between normal real-time mode and LeCroy WaveStream Fast Viewing modeAutomatic SetupAuto SetupAutomatically sets timebase, trigger, and sensitivity to display a wide range of repetitive signalsVertical Find ScaleAutomatically sets the vertical sensitivity and offset for the selected channels to display a waveform with maximum dynamic range44Xi-A 64Xi-A 62Xi-A104Xi-A 204Xi-A Probes44MXi-A 64MXi-A104MXi-A 204MXi-AProbesOne Passive probe per channel; Optional passive and active probes available Probe System; ProBus Automatically detects and supports a variety of compatible probes Scale FactorsAutomatically or manually selected, depending on probe usedColor Waveform DisplayTypeColor 10.4" flat-panel TFT-LCD with high resolution touch screenResolutionSVGA; 800 x 600 pixels; maximum external monitor output resolution of 2048 x 1536 pixelsNumber of Traces Display a maximum of 8 traces. Simultaneously display channel, zoom, memory, and math traces Grid StylesAuto, Single, Dual, Quad, Octal, XY , Single + XY , Dual + XY Waveform StylesSample dots joined or dots only in real-time mode22Zoom Expansion TracesDisplay up to 4 Zoom/Math traces with 16 bits/data pointInternal Waveform MemoryM1, M2, M3, M4 Internal Waveform Memory (store full-length waveform with 16 bits/data point) or store to any number of files limited only by data storage mediaSetup StorageFront Panel and Instrument StatusStore to the internal hard drive, over the network, or to a USB-connected peripheral deviceInterfaceRemote ControlVia Windows Automation, or via LeCroy Remote Command Set Network Communication Standard VXI-11 or VICP , LXI Class C Compliant GPIB Port (Accessory)Supports IEEE – 488.2Ethernet Port 10/100/1000Base-T Ethernet interface (RJ-45 connector)USB Ports5 USB 2.0 ports (one on front of instrument) supports Windows-compatible devices External Monitor Port Standard 15-pin D-Type SVGA-compatible DB-15; connect a second monitor to use extended desktop display mode with XGA resolution Serial PortDB-9 RS-232 port (not for remote oscilloscope control)44Xi-A 64Xi-A 62Xi-A104Xi-A 204Xi-A Auxiliary Input44MXi-A 64MXi-A104MXi-A 204MXi-ASignal Types Selected from External Trigger or External Clock input on front panel Coupling50 Ω: DC, 1 M Ω: AC, DC, GND Maximum Input Voltage50 Ω: 5 V rms , 1 M Ω: 400 V max.50 Ω: 5 V rms , 1 M Ω: 250 V max. (DC + Peak AC ≤ 5 kHz)(DC + Peak AC ≤ 10 kHz)Auxiliary OutputSignal TypeTrigger Enabled, Trigger Output. Pass/Fail, or Off Output Level TTL, ≈3.3 VConnector TypeBNC, located on rear panelGeneralAuto Calibration Ensures specified DC and timing accuracy is maintained for 1 year minimumCalibratorOutput available on front panel connector provides a variety of signals for probe calibration and compensationPower Requirements90–264 V rms at 50/60 Hz; 115 V rms (±10%) at 400 Hz, Automatic AC Voltage SelectionInstallation Category: 300 V CAT II; Max. Power Consumption: 340 VA/340 W; 290 VA/290 W for WaveRunner 62Xi-AEnvironmentalTemperature: Operating+5 °C to +40 °C Temperature: Non-Operating -20 °C to +60 °CHumidity: Operating Maximum relative humidity 80% for temperatures up to 31 °C decreasing linearly to 50% relative humidity at 40 °CHumidity: Non-Operating 5% to 95% RH (non-condensing) as tested per MIL-PRF-28800F Altitude: OperatingUp to 3,048 m (10,000 ft.) @ ≤ 25 °C Altitude: Non-OperatingUp to 12,190 m (40,000 ft.)PhysicalDimensions (HWD)260 mm x 340 mm x 152 mm Excluding accessories and projections (10.25" x 13.4" x 6")Net Weight7.26kg. (16.0lbs.)CertificationsCE Compliant, UL and cUL listed; Conforms to EN 61326, EN 61010-1, UL 61010-1 2nd Edition, and CSA C22.2 No. 61010-1-04Warranty and Service3-year warranty; calibration recommended annually. Optional service programs include extended warranty, upgrades, calibration, and customization services23Product DescriptionProduct CodeWaveRunner Xi-A Series Oscilloscopes2 GHz, 4 Ch, 5 GS/s, 12.5 Mpts/ChWaveRunner 204Xi-A(10 GS/s, 25 Mpts/Ch in interleaved mode)with 10.4" Color Touch Screen Display 1 GHz, 4 Ch, 5 GS/s, 12.5 Mpts/ChWaveRunner 104Xi-A(10 GS/s, 25 Mpts/Ch in interleaved mode)with 10.4" Color Touch Screen Display 600 MHz, 4 Ch, 5 GS/s, 12.5 Mpts/Ch WaveRunner 64Xi-A(10 GS/s, 25 Mpts/Ch in interleaved mode)with 10.4" Color Touch Screen Display 600 MHz, 2 Ch, 5 GS/s, 12.5 Mpts/Ch WaveRunner 62Xi-A(10 GS/s, 25 Mpts/Ch in interleaved mode)with 10.4" Color Touch Screen Display 400 MHz, 4 Ch, 5 GS/s, 12.5 Mpts/Ch WaveRunner 44Xi-A(25 Mpts/Ch in interleaved mode)with 10.4" Color Touch Screen DisplayWaveRunner MXi-A Series Oscilloscopes2 GHz, 4 Ch, 5 GS/s, 12.5 Mpts/ChWaveRunner 204MXi-A(10 GS/s, 25 Mpts/Ch in Interleaved Mode)with 10.4" Color Touch Screen Display 1 GHz, 4 Ch, 5 GS/s, 12.5 Mpts/ChWaveRunner 104MXi-A(10 GS/s, 25 Mpts/Ch in Interleaved Mode)with 10.4" Color Touch Screen Display 600 MHz, 4 Ch, 5 GS/s, 12.5 Mpts/Ch WaveRunner 64MXi-A(10 GS/s, 25 Mpts/Ch in Interleaved Mode)with 10.4" Color Touch Screen Display 400 MHz, 4 Ch, 5 GS/s, 12.5 Mpts/Ch WaveRunner 44MXi-A(25 Mpts/Ch in Interleaved Mode)with 10.4" Color Touch Screen DisplayIncluded with Standard Configuration÷10, 500 MHz, 10 M Ω Passive Probe (Total of 1 Per Channel)Standard Ports; 10/100/1000Base-T Ethernet, USB 2.0 (5), SVGA Video out, Audio in/out, RS-232Optical 3-button Wheel Mouse – USB 2.0Protective Front Cover Accessory PouchGetting Started Manual Quick Reference GuideAnti-virus Software (Trial Version)Commercial NIST Traceable Calibration with Certificate 3-year WarrantyGeneral Purpose Software OptionsStatistics Software Package WRXi-STAT Master Analysis Software Package WRXi-XMAP (Standard with MXi-A model oscilloscopes)Advanced Math Software Package WRXi-XMATH (Standard with MXi-A model oscilloscopes)Intermediate Math Software Package WRXi-XWAV (Standard with MXi-A model oscilloscopes)Value Analysis Software Package (Includes XWAV and JTA2) WRXi-XVAP (Standard with MXi-A model oscilloscopes)Advanced Customization Software Package WRXi-XDEV (Standard with MXi-A model oscilloscopes)Spectrum Analyzer and Advanced FFT Option WRXi-SPECTRUM Processing Web Editor Software Package WRXi-XWEBProduct Description Product CodeApplication Specific Software OptionsJitter and Timing Analysis Software Package WRXi-JTA2(Standard with MXi-A model oscilloscopes)Digital Filter Software PackageWRXi-DFP2Disk Drive Measurement Software Package WRXi-DDM2PowerMeasure Analysis Software Package WRXi-PMA2Serial Data Mask Software PackageWRXi-SDM QualiPHY Enabled Ethernet Software Option QPHY-ENET*QualiPHY Enabled USB 2.0 Software Option QPHY-USB †EMC Pulse Parameter Software Package WRXi-EMC Electrical Telecom Mask Test PackageET-PMT* TF-ENET-B required. †TF-USB-B required.Serial Data OptionsI 2C Trigger and Decode Option WRXi-I2Cbus TD SPI Trigger and Decode Option WRXi-SPIbus TD UART and RS-232 Trigger and Decode Option WRXi-UART-RS232bus TD LIN Trigger and Decode Option WRXi-LINbus TD CANbus TD Trigger and Decode Option CANbus TD CANbus TDM Trigger, Decode, and Measure/Graph Option CANbus TDM FlexRay Trigger and Decode Option WRXi-FlexRaybus TD FlexRay Trigger and Decode Physical Layer WRXi-FlexRaybus TDP Test OptionAudiobus Trigger and Decode Option WRXi-Audiobus TDfor I 2S , LJ, RJ, and TDMAudiobus Trigger, Decode, and Graph Option WRXi-Audiobus TDGfor I 2S LJ, RJ, and TDMMIL-STD-1553 Trigger and Decode Option WRXi-1553 TDA variety of Vehicle Bus Analyzers based on the WaveRunner Xi-A platform are available.These units are equipped with a Symbolic CAN trigger and decode.Mixed Signal Oscilloscope Options500 MHz, 18 Ch, 2 GS/s, 50 Mpts/Ch MS-500Mixed Signal Oscilloscope Option 250 MHz, 36 Ch, 1 GS/s, 25 Mpts/ChMS-500-36(500 MHz, 18 Ch, 2 GS/s, 50 Mpts/Ch Interleaved) Mixed Signal Oscilloscope Option 250 MHz, 18 Ch, 1 GS/s, 10 Mpts/Ch MS-250Mixed Signal Oscilloscope OptionProbes and Amplifiers*Set of 4 ZS1500, 1.5 GHz, 0.9 pF , 1 M ΩZS1500-QUADPAK High Impedance Active ProbeSet of 4 ZS1000, 1 GHz, 0.9 pF , 1 M ΩZS1000-QUADPAK High Impedance Active Probe 2.5 GHz, 0.7 pF Active Probe HFP25001 GHz Active Differential Probe (÷1, ÷10, ÷20)AP034500 MHz Active Differential Probe (x10, ÷1, ÷10, ÷100)AP03330 A; 100 MHz Current Probe – AC/DC; 30 A rms ; 50 A rms Pulse CP03130 A; 50 MHz Current Probe – AC/DC; 30 A rms ; 50 A rms Pulse CP03030 A; 50 MHz Current Probe – AC/DC; 30 A rms ; 50 A peak Pulse AP015150 A; 10 MHz Current Probe – AC/DC; 150 A rms ; 500 A peak Pulse CP150500 A; 2 MHz Current Probe – AC/DC; 500 A rms ; 700 A peak Pulse CP5001,400 V, 100 MHz High-Voltage Differential Probe ADP3051,400 V, 20 MHz High-Voltage Differential Probe ADP3001 Ch, 100 MHz Differential Amplifier DA1855A*A wide variety of other passive, active, and differential probes are also available.Consult LeCroy for more information.Product Description Product CodeHardware Accessories*10/100/1000Base-T Compliance Test Fixture TF-ENET-B †USB 2.0 Compliance Test Fixture TF-USB-B External GPIB Interface WS-GPIBSoft Carrying Case WRXi-SOFTCASE Hard Transit CaseWRXi-HARDCASE Mounting Stand – Desktop Clamp Style WRXi-MS-CLAMPRackmount Kit WRXi-RACK Mini KeyboardWRXi-KYBD Removable Hard Drive Package (Includes removeable WRXi-A-RHD hard drive kit and two hard drives)Additional Removable Hard DriveWRXi-A-RHD-02* A variety of local language front panel overlays are also available .† Includes ENET-2CAB-SMA018 and ENET-2ADA-BNCSMA.Customer ServiceLeCroy oscilloscopes and probes are designed, built, and tested to ensure high reliability. In the unlikely event you experience difficulties, our digital oscilloscopes are fully warranted for three years, and our probes are warranted for one year.This warranty includes:• No charge for return shipping • Long-term 7-year support• Upgrade to latest software at no chargeLocal sales offices are located throughout the world. Visit our website to find the most convenient location.© 2010 by LeCroy Corporation. All rights reserved. Specifications, prices, availability, and delivery subject to change without notice. Product or brand names are trademarks or requested trademarks of their respective holders.1-800-5-LeCroy WRXi-ADS-14Apr10PDF。
Vol.1, No.2, March–April 1990 Université Catholique de Louvain Introduction to Trees

FORMALIZED MATHEMATICSVol.1,No.2,March–April1990Universit´e Catholique de LouvainIntroduction to TreesGrzegorz Bancerek1Warsaw UniversityBia l ystokSummary.The article consists of two parts:thefirst one deals with the concept of the prefixes of afinite sequence,the second one introducesand deals with the concept of tree.Besides some auxiliary propositionsconcerningfinite sequences are presented.The trees are introduced asnon-empty sets offinite sequences of natural numbers which are closed onprefixes and on sequences of less numbers(i.e.if n1,n2,...,n k is avertex(element)of a tree and m i≤n i for i=1,2,...,k,then m1,m2,...,m k also is).Finite trees,elementary trees with n leaves,the leavesand the subtrees of a tree,the inserting of a tree into another tree,with anode used for detemining the place of insertion,antichains of prefixes,andheight and width offinite trees are introduced.MML Identifier:TREES1Partially supported by Le Hodey Foundation.The part of this work had been done on Mizar Workshop’89(Fourdrain,France)in Summer’89.421c 1990Fondation Philippe le HodeyISSN0777–4028422Grzegorz BancerekLet p,q befinite sequences.The predicate p q is defined by:there exists n such that p=q Seg n.We now state a number of propositions:(7)For allfinite sequences p,q holds p q if and only if there exists n suchthat p=q Seg n.(8)For allfinite sequences p,q holds p q if and only if there exists r beingafinite sequence such that q=p r.(9)For allfinite sequences p,q such that p q holds len p≤len q.(10)For everyfinite sequence p holdsε p andεD p.(11)For everyfinite sequence p such that p εholds p=ε.(12)For everyfinite sequence p holds p p.(13)For allfinite sequences p,q such that p q and q p holds p=q.(14)For allfinite sequences p,q,r such that p q and q r holds p r.(15)For allfinite sequences p,q such that p q and len p=len q holds p=q.(16) x y if and only if x=y.We now define two new predicates.Let p,q befinite sequences.The predicate p and q are comparable is defined by:p q or q p.The predicate p≺q is defined by:p q and p=q.One can prove the following propositions:(17)For allfinite sequences p,q holds p and q are comparable if and only ifp q or q p.(18)For allfinite sequences p,q holds p≺q if and only if p q and p=q.(19)For allfinite sequences p,q such that p and q are comparable and len p=len q holds p=q.(20)For allfinite sequences p,q holds p≺q or p=q or q≺p if and only if pand q are comparable.(21)For everyfinite sequence p holds p and p are comparable.In the sequel p1,p2will befinite sequences.Next we state a number of propositions:(22)If p1and p2are comparable,then p2and p1are comparable.(23) x and y are comparable if and only if x=y.(24)For allfinite sequences p,q such that p≺q holds len p<len q.(25)For nofinite sequence p holds p≺εor p≺εD.(26)For nofinite sequences p,q holds p≺q and q≺p.(27)For allfinite sequences p,q,r such that p≺q and q≺r or p≺q andq r or p q and q≺r holds p≺r.(28)If p1 p2,then p2p1.(29)If p1≺p2,then p2p1.(30)If p1 x p2,then p1≺p2.Introduction to Trees423(31)If p1 p2,then p1≺p2 x .(32)If p1≺p2 x ,then p1 p2.(33)Ifε≺p2orε=p2,then p1≺p1p2.Let p be afinite sequence.The functor Seg (p)yielding a set,is defined by: x∈Seg (p)if and only if there exists q being afinite sequence such thatx=q and q≺p.The following propositions are true:(34)For everyfinite sequence p holds X=Seg (p)if and only if for every xholds x∈X if and only if there exists q being afinite sequence such thatx=q and q≺p.(35)For everyfinite sequence p such that x∈Seg (p)holds x is afinitesequence.(36)For allfinite sequences p,q holds p∈Seg (q)if and only if p≺q.(37)For allfinite sequences p,q such that p∈Seg (q)holds len p<len q.(38)For allfinite sequences p,q,r such that q r∈Seg (p)holds q∈Seg (p).(39)Seg (ε)=∅.(40)Seg ( x )={ε}.(41)For allfinite sequences p,q such that p q holds Seg (p)⊆Seg (q).(42)For allfinite sequences p,q,r such that q∈Seg (p)and r∈Seg (p)holds q and r are comparable.The mode tree,which widens to the type a non-empty set,is defined by:it⊆∗and for every p such that p∈it holds Seg (p)⊆it and for all p,k,n such that p k ∈it and n≤k holds p n ∈it.Next we state a proposition(43)D is a tree if and only if D⊆∗and for every p such that p∈D holdsSeg (p)⊆D and for all p,k,n such that p k ∈D and n≤k holdsp n ∈D.In the sequel T,T1denote trees.The following proposition is true(44)If x∈T,then x is afinite sequence of elements of.Let us consider T.We see that it makes sense to consider the following mode for restricted scopes of arguments.Then all the objests of the mode element ofT are afinite sequence of elements of.The following propositions are true:(45)For allfinite sequences p,q such that p∈T and q p holds q∈T.(46)For everyfinite sequence r such that q r∈T holds q∈T.(47)ε∈T andε∈T.(48){ε}is a tree.(49)T∪T1is a tree.(50)T∩T1is a tree.The modefinite tree,which widens to the type a tree,is defined by:it isfinite.424Grzegorz BancerekThe following proposition is true(51)T is afinite tree if and only if T isfinite.In the sequel fT,fT1will befinite trees.Next we state two propositions:(52)fT∪fT1is afinite tree.(53)fT∩T is afinite tree and T∩fT is afinite tree.Let us consider n.The functor elementary tree of n yielding afinite tree,is defined by:elementary tree of n={ k :k<n}∪{ε}.The following propositions are true:(54)fT=elementary tree of n if and only if fT={ k :k<n}∪{ε}.(55)If k<n,then k ∈elementary tree of n.(56)elementary tree of0={ε}.(57)If p∈elementary tree of n,then p=εor there exists k such that k<nand p= k .We now define two new functors.Let us consider T.The functor Leaves T yields a subset of T and is defined by:p∈Leaves T if and only if p∈T and for no q holds q∈T and p≺q.Let us consider p.Let us assume that p∈T.The functor T p yields a tree and is defined by:q∈T p if and only if p q∈T.We now state three propositions:(58)For every subset X of T holds X=Leaves T if and only if for every pholds p∈X if and only if p∈T and for no q holds q∈T and p≺q.(59)If p∈T,then T1=T p if and only if for every q holds q∈T1if andonly if p q∈T.(60)Tε=T.The arguments of the notions defined below are the following:T which is a finite tree;p which is an element of T.Then T p is afinite tree.Let us consider T.Let us assume that Leaves T=∅.The mode leaf of T, which widens to the type an element of T,is defined by:it∈Leaves T.We now state a proposition(61)If Leaves T=∅,then for every element p of T holds p is a leaf of T ifand only if p∈Leaves T.Let us consider T.The mode subtree of T,which widens to the type a tree, is defined by:there exists p being an element of T such that it=T p.One can prove the following proposition(62)T1is a subtree of T if and only if there exists p being an element of Tsuch that T1=T p.In the sequel t is an element of T.Let us consider T,p,T1.Let us assume that p∈T.The functor T(p/T1)yields a tree and is defined by:Introduction to Trees425 q∈T(p/T1)if and only if q∈T and p q or there exists r such that r∈T1 and q=p r.In the sequel T2is a tree.Next we state four propositions:(63)If p∈T1,then T=T1(p/T2)if and only if for every q holds q∈T if andonly if q∈T1and p q or there exists r such that r∈T2and q=p r.(64)If p∈T,then T(p/T1)={t1:p t1}∪{p s:s=s}.(65)If p∈T and q∈T1,then p q∈T(p/T1).(66)If p∈T,then T1=(T(p/T1))p.The arguments of the notions defined below are the following:T which is afinite tree;t which is an element of T;T1which is afinite tree.Then T(t/T1)isafinite tree.In the sequel w will denote afinite sequence.The following two propositions are true:(67)For everyfinite sequence p holds Seg (p)≈Seg(len p).(68)For everyfinite sequence p holds card(Seg (p))=len p.The mode antichain of prefixes,which widens to the type a set,is defined by: for every x such that x∈it holds x is afinite sequence and for all p1,p2such that p1∈it and p2∈it and p1=p2holds p1and p2are not comparable.Next we state three propositions:(69)X is an antichain of prefixes if and only if for every x such that x∈Xholds x is afinite sequence and for all p1,p2such that p1∈X and p2∈Xand p1=p2holds p1and p2are not comparable.(70){w}is an antichain of prefixes.(71)If p1and p2are not comparable,then{p1,p2}is an antichain of prefixes.Let us consider T.The mode antichain of prefixes of T,which widens to the type an antichain of prefixes,is defined by:it⊆T.We now state a proposition(72)For every antichain S of prefixes holds S is an antichain of prefixes of Tif and only if S⊆T.In the sequel t1,t2will be elements of T.The following three propositions are true:(73)∅is an antichain of prefixes of T and{ε}is an antichain of prefixes of T.(74){t}is an antichain of prefixes of T.(75)If t1and t2are not comparable,then{t1,t2}is an antichain of prefixesof T.We now define two new functors.Let T be afinite tree.The functor height T yields a natural number and is defined by:there exists p such that p∈T and len p=height T and for every p such thatp∈T holds len p≤height T.The functor width T yielding a natural number,is defined by:426Grzegorz Bancerekthere exists X being an antichain of prefixes of T such that width T=card X and for every antichain Y of prefixes of T holds card Y≤card X.We now state three propositions:(76)For everyfinite tree T for every n holds n=height T if and only if thereexists p such that p∈T and len p=n and for every p such that p∈Tholds len p≤n.(77)For everyfinite tree T for every n holds n=width T if and only if thereexists X being an antichain of prefixes of T such that n=card X and forevery antichain Y of prefixes of T holds card Y≤card X.(78)1≤width fT.The following propositions are true:(79)height(elementary tree of0)=0.(80)If height fT=0,then fT=elementary tree of0.(81)height(elementary tree of(n+1))=1.(82)width(elementary tree of0)=1.(83)width(elementary tree of(n+1))=n+1.(84)For every element t of fT holds height(fT t)≤height fT.(85)For every element t of fT such that t=εholds height(fT t)<height fT.The scheme TreeIntroduction to Trees427 [7]Krzysztof Hryniewiecki.Basic properties of real numbers.Formalized Math-ematics,1(1):35–40,1990.[8]Andrzej Trybulec.Tarski Grothendieck set theory.Formalized Mathematics,1(1):9–11,1990.Received October25,1989。
Randomness

a rX iv:mat h /1186v2[mat h.PR]1Oct21Randomness Paul Vit´a nyi ∗CWI and Universiteit van Amsterdam Abstract Here we present in a single essay a combination and completion of the several aspects of the problem of randomness of individual objects which of necessity occur scattered in our text [10].The reader can consult different arrangements of parts of the material in [7,20].Contents 1Introduction 21.1Occam’s Razor Revisited .......................31.2Lacuna of Classical Probability Theory ...............41.3Lacuna of Information Theory ....................42Randomness as Unpredictability 62.1Von Mises’Collectives ........................82.2Wald-Church Place Selection ....................113Randomness as Incompressibility 123.1Kolmogorov Complexity .......................143.2Complexity Oscillations .......................163.3Relation with Unpredictability ...................193.4Kolmogorov-Loveland Place Selection ...............204Randomness as Membership of All Large Majorities214.1Typicality ...............................214.2Randomness in Martin-L¨o f’s Sense .................244.3Random Finite Sequences ......................254.4Random Infinite Sequences .....................284.5Randomness of Individual Sequences Resolved (37)5Applications375.1Prediction (37)5.2G¨o del’s incompleteness result (38)5.3Lower bounds (39)5.4Statistical Properties of Finite Sequences (41)5.5Chaos and Predictability (45)1IntroductionPierre-Simon Laplace(1749—1827)has pointed out the following reason why intuitively a regular outcome of a random event is unlikely.“We arrange in our thought all possible events in various classes;andwe regard as extraordinary those classes which include a very smallnumber.In the game of heads and tails,if head comes up a hundredtimes in a row then this appears to us extraordinary,because thealmost infinite number of combinations that can arise in a hundredthrows are divided in regular sequences,or those in which we ob-serve a rule that is easy to grasp,and in irregular sequences,thatare incomparably more numerous”.[place,A PhilosophicalEssay on Probabilities,,Dover,1952.Originally published in1819.Translated from6th French edition.Pages16-17.]If by‘regularity’we mean that the complexity is significantly less than maximal, then the number of all regular events is small(because by simple counting the number of different objects of low complexity is small).Therefore,the event that anyone of them occurs has small probability(in the uniform distribution). Yet,the classical calculus of probabilities tells us that100heads are just as probable as any other sequence of heads and tails,even though our intuition tells us that it is less‘random’than some others.Listen to the redoubtable Dr. Samuel Johnson(1709—1784):“Dr.Beattie observed,as something remarkable which had hap-pened to him,that he chanced to see both the No.1and the No.1000,of the hackney-coaches,thefirst and the last;‘Why,Sir’,saidJohnson,‘there is an equal chance for one’s seeing those two num-bers as any other two.’He was clearly right;yet the seeing of twoextremes,each of which is in some degree more conspicuous than therest,could not but strike one in a stronger manner than the sightof any other two numbers.”[James Boswell(1740—1795),Life ofJohnson,Oxford University Press,Oxford,UK,1970.(Edited byR.W.Chapman,1904Oxford edition,as corrected by J.D.Fleeman,third edition.Originally published in1791.)Pages1319-1320.]Laplace distinguishes between the object itself and a cause of the object.2“The regular combinations occur more rarely only because they areless numerous.If we seek a cause wherever we perceive symmetry,itis not that we regard the symmetrical event as less possible than theothers,but,since this event ought to be the effect of a regular causeor that of chance,thefirst of these suppositions is more probablethan the second.On a table we see letters arranged in this order Co n s t a n t i n o p l e,and we judge that this arrangementis not the result of chance,not because it is less possible than others,for if this word were not employed in any language we would notsuspect it came from any particular cause,but this word being inuse among us,it is incomparably more probable that some personhas thus arranged the aforesaid letters than that this arrangementis due to chance.”[place,Ibid.]Let us try to turn Laplace’s argument into a formal one.First we introduce some notation.If x is afinite binary sequence,then l(x)denotes the length (number of occurrences of binary digits)in x.For example,l(010)=3.1.1Occam’s Razor RevisitedSuppose we observe a binary string x of length l(x)=n and want to know whether we must attribute the occurrence of x to pure chance or to a cause. To put things in a mathematical framework,we define chance to mean that the literal x is produced by independent tosses of a fair coin.More subtle is the interpretation of cause as meaning that the computer on our desk computes x from a program provided by independent tosses of a fair coin.The chance of generating x literally is about2−n.But the chance of generating x in the form of a short program x∗,the cause from which our computer computes x,is at least2−l(x∗).In other words,if x is regular,then l(x∗)≪n,and it is about 2n−l(x∗)times more likely that x arose as the result of computation from some simple cause(like a short program x∗)than literally by a random process.This approach will lead to an objective and absolute version of the classic maxim of William of Ockham(1290?–1349?),known as Occam’s razor:“if there are alternative explanations for a phenomenon,then,all other things being equal,we should select the simplest one”.One identifies‘simplicity of an object’with‘an object having a short effective description’.In other words,a priori we consider objects with short descriptions more likely than objects with only long descriptions.That is,objects with low complexity have high probability while objects with high complexity have low probability.This principle is intimately related with problems in both probability theory and information theory.These problems as outlined below can be interpreted as saying that the related disciplines are not‘tight’enough;they leave things unspecified which our intuition tells us should be dealt with.31.2Lacuna of Classical Probability TheoryAn adversary claims to have a true random coin and invites us to bet on the outcome.The coin produces a hundred heads in a row.We say that the coin cannot be fair.The adversary,however,appeals to probabity theory which says that each sequence of outcomes of a hundred coinflips is equally likely,1/2100, and one sequence had to come up.Probability theory gives us no basis to challenge an outcome after it has happened.We could only exclude unfairness in advance by putting a penalty side-bet on an outcome of100heads.But what about1010...?What about an initial segment of the binary expansion ofπ?Regular sequence1Pr(00000000000000000000000000)=226Random sequence1Pr(10010011011000111011010000)=being equally probable,this quantity is the number of bits needed to count all possibilities.This expresses the fact that each message in the ensemble can be communi-cated using this number of bits.However,it does not say anything about the number of bits needed to convey any individual message in the ensemble.To illustrate this,consider the ensemble consisting of all binary strings of length 9999999999999999.By Shannon’s measure,we require9999999999999999bits on the average to encode a string in such an ensemble.However,the string consisting of 99999999999999991’s can be encoded in about55bits by expressing9999999999 999999in binary and adding the repeated pattern‘1’.A requirement for this to work is that we have agreed on an algorithm that decodes the encoded string. We can compress the string still further when we note that9999999999999999 equals32×1111111111111111,and that1111111111111111consists of241’s.Thus,we have discovered an interesting phenomenon:the description of some strings can be compressed considerably,provided they exhibit enough regularity.This observation,of course,is the basis of all systems to express very large numbers and was exploited early on by Archimedes(287BC—212BC)in his treatise The Sand-Reckoner,in which he proposes a system to name very large numbers:“There are some,King Golon,who think that the number of sandis infinite in multitude[...or]that no number has been named whichis great enough to exceed its multitude.[...]But I will try to showyou,by geometrical proofs,which you will be able to follow,that,of the numbers named by me[...]some exceed not only the massof sand equal in magnitude to the earthfilled up in the way de-scribed,but also that of a mass equal in magnitude to the universe.”[Archimedes,The Sand-Reckoner,pp.420-429in:The World ofMathematics,Vol.1,J.R.Newman,Ed.,Simon and Schuster,NewYork,1956.Page420.]However,if regularity is lacking,it becomes more cumbersome to express large numbers.For instance,it seems easier to compress the number‘one billion,’than the number‘one billion seven hundred thirty-five million two hundred sixty-eight thousand and three hundred ninety-four,’even though they are of the same order of magnitude.The above example shows that we need too many bits to transmit regular objects.The converse problem,too little bits,arises as well since Shannon’s theory of information and communication deals with the specific technology problem of data transmission.That is,with the information that needs to be transmitted in order to select an object from a previously agreed upon set of alternatives;agreed upon by both the sender and the receiver of the message. If we have an ensemble consisting of the Odyssey and the sentence“let’s go drink a beer”then we can transmit the Odyssey using only one bit.Yet Greeks5feel that Homer’s book has more information contents.Our task is to widen the limited set of alternatives until it is universal.We aim at a notion of ‘absolute’information of individual objects,which is the information which by itself describes the object completely.Formulation of these considerations in an objective manner leads again to the notion of shortest programs and Kolmogorov complexity.2Randomness as UnpredictabilityWhat is the proper definition of a random sequence,the‘lacuna in probability theory’we have identified above?Let us consider how mathematicians test ran-domness of individual sequences.To measure randomness,criteria have been developed which certify this quality.Yet,in recognition that they do not mea-sure‘true’randomness,we call these criteria‘pseudo’randomness tests.For instance,statistical survey of initial segments of the sequence of decimal dig-its ofπhave failed to disclose any significant deviations of randomness.But clearly,this sequence is so regular that it can be described by a simple program to compute it,and this program can be expressed in a few bits.“Any one who considers arithmetical methods of producing randomdigits is,of course,in a state of sin.For,as has been pointed outseveral times,there is no such thing as a random number—there areonly methods to produce random numbers,and a strict arithmeticalprocedure is of course not such a method.(It is true that a problemwe suspect of being solvable by random methods may be solvable bysome rigorously defined sequence,but this is a deeper mathematicalquestion than we can go into now.)”[John Louis von Neumann(1903—1957),Various techniques used in connection with randomdigits,J.Res.Nat.Bur.Stand.Appl.Math.Series,3(1951),pp.36-38.Page36.Also,Collected Works,Vol.1,A.H.Taub,Ed.,Pergamon Press,Oxford,1963,pp.768-770.Page768.]This fact prompts more sophisticated definitions of randomness.In his famous address to the International Congress of Mathematicians in1900,David Hilbert (1862—1943)proposed twenty-three mathematical problems as a program to direct the mathematical efforts in the twentieth century.The6th problem asks for”To treat(in the same manner as geometry)by means of axioms,those physical sciences in which mathematics plays an important part;in thefirst rank are the theory of probability..”.Thus,Hilbert views probability theory as a physical applied theory.This raises the question about the properties one can expect from typical outcomes of physical random sources,which a priori has no relation whatsoever with an axiomatic mathematical theory of probabilities. That is,a mathematical system has no direct relation with physical reality.To6obtain a mathematical system that is an appropriate model of physical phe-nomena one needs to identify and codify essential properties of the phenomena under consideration by empirical observations.Notably Richard von Mises(1883—1953)proposed notions that approach the very essence of true randomness of physical phenomena.This is related with the construction of a formal mathematical theory of probability,to form a basis for real applications,in the early part of this century.While von Mises’objective was to justify the applications to the real phenomena,Andrei Niko-laevitch Kolmogorov’s(1903—1987)classic1933treatment constructs a purely axiomatic theory of probability on the basis of set theoretic axioms.“This theory was so successful,that the problem offinding the basisof real applications of the results of the mathematical theory of prob-ability became rather secondary to many investigators....[however]the basis for the applicability of the results of the mathematical the-ory of probability to real‘random phenomena’must depend in someform on the frequency concept of probability,the unavoidable natureof which has been established by von Mises in a spirited manner.”[A.N.Kolmogorov,On tables of random numbers,Sankhy¯a,SeriesA,25(1963),369-376.Page369.]The point made is that the axioms of probability theory are designed so that abstract probabilities can be computed,but nothing is said about what prob-ability really means,or how the concept can be applied meaningfully to the actual world.Von Mises analyzed this issue in detail,and suggested that a proper definition of probability depends on obtaining a proper definition of a random sequence.This makes him a‘frequentist’—a supporter of the frequency theory.The following interpretation and formulation of this theory is due to John Edensor Littlewood(1885—1977),The dilemma of probability theory,Little-wood’s Miscellany,Revised Edition,B.Bollob´a s,Ed.,Cambridge University Press,1986,pp.71-73.The frequency theory to interpret probability says, roughly,that if we perform an experiment many times,then the ratio of favor-able outcomes to the total number n of experiments will,with certainty,tend to a limit,p say,as n→∞.This tells us something about the meaning of probability,namely,the measure of the positive outcomes is p.But suppose we throw a coin1000times and wish to know what to expect.Is1000enough for convergence to happen?The statement above does not say.So we have to add something about the rate of convergence.But we cannot assert a certainty about a particular number of n throws,such as‘the proportion of heads will be p±ǫfor large enough n(withǫdepending on n)’.We can at best say‘the proportion will lie between p±ǫwith at least such and such probability(de-pending onǫand n0)whenever n>n0’.But now we defined probability in an obviously circular fashion.72.1Von Mises’CollectivesIn1919von Mises proposed to eliminate the problem by simply dividing all infi-nite sequences into special random sequences(called collectives),having relative frequency limits,which are the proper subject of the calculus of probabilities and other sequences.He postulates the existence of random sequences(thereby circumventing circularity)as certified by abundant empirical evidence,in the manner of physical laws and derives mathematical laws of probability as a con-sequence.In his view a naturally occurring sequence can be nonrandom or unlawful in the sense that it is not a proper collective.Von Mises views the theory of probabilities insofar as they are nu-merically representable as a physical theory of definitely observ-able phenomena,repetitive or mass events,for instance,as foundin games of chance,population statistics,Brownian motion.‘Prob-ability’is a primitive notion of the theory comparable to those of‘energy’or‘mass’in other physical theories.Whereas energy or mass exist infields or material objects,proba-bilities exist only in the similarly mathematical idealization of collec-tives(random sequences).All problems of the theory of probabilityconsist of deriving,according to certain rules,new collectives fromgiven ones and calculating the distributions of these new collectives.The exact formulation of the properties of the collectives is secondaryand must be based on empirical evidence.These properties are theexistence of a limiting relative frequency and randomness.The property of randomness is a generalization of the abundant experience in gambling houses,namely,the impossibility of a suc-cessful gambling system.Including this principle in the foundationof probability,von Mises argues,we proceed in the same way as thephysicists did in the case of the energy principle.Here too,the ex-perience of hunters of fortune is complemented by solid experienceof insurance companies and so forth.A fundamentally different approach is to justify a posteriori theapplication of a purely mathematically constructed theory of prob-ability,such as the theory resulting from the Kolmogorov axioms.Suppose,we can show that the appropriately defined random se-quences form a set of measure one,and without exception satisfyall laws of a given axiomatic theory of probability.Then it appearspractically justifiable to assume that as a result of an(infinite)ex-periment only random sequences appear.Von Mises’notion of infinite random sequence of0’s and1’s(collective)essen-tially appeals to the idea that no gambler,making afixed number of wagers of ‘heads’,atfixed odds[say p versus1−p]and infixed amounts,on theflips of a coin[with bias p versus1−p],can have profit in the long run from betting ac-8cording to a system instead of betting at random.Says Alonzo Church(1903—):“this definition[below]...while clear as to general intent,is too inexact in form to serve satisfactorily as the basis of a mathematical theory.”[A.Church, On the concept of a random sequence,Bull.Amer.Math.Soc.,46(1940),pp. 130-135.Page130.]Definition1An infinite sequence a1,a2,...of0’s and1’s is a random sequence in the special meaning of collective if the following two conditions are satisfied.1.Let f n is the number of1’s among thefirst n terms of the sequence.Thenf nlimn→∞we should distinguish between randomness proper(as absence of anyregularity)and stochastic randomness(which is the subject of prob-ability theory).There emerges the problem offinding reasons forthe applicability of the mathematical theory of probability to thereal world.”[A.N.Kolmogorov,On logical foundations of probabil-ity theory,Probability Theory and Mathematical Statistics,LectureNotes in Mathematics,Vol.1021,K.Itˆo and J.V.Prokhorov,Eds.,Springer-Verlag,Heidelberg,1983,pp.1-5.Page1.]Intuitively,we can distinguish between sequences that are irregular and do not satisfy the regularity implicit in stochastic randomness,and sequences that are irregular but do satisfy the regularities associated with stochastic randomness. Formally,we will distinguish the second type from thefirst type by whether or not a certain complexity measure of the initial segments goes to a definite limit. The complexity measure referred to is the length of the shortest description of the prefix(in the precise sense of Kolmogorov complexity)divided by its length. It will turn out that almost all infinite strings are irregular of the second type and satisfy all regularities of stochastic randomness.“In applying probability theory we do not confine ourselves to negat-ing regularity,but from the hypothesis of randomness of the ob-served phenomena we draw definite positive conclusions.”[A.N.Kol-mogorov,Combinatorial foundations of information theory and thecalculus of probabilities,Russian Mathematical Surveys,,38:4(1983),pp.29-40.Page34.]Considering the sequence as fair coin tosses with p=1/2,the second condition in Definition1says there is no strategyφ(principle of excluded gambling system) which assures a player betting atfixed odds and infixed amounts,on the tosses of the coin,to make infinite gain.That is,no advantage is gained in the long run by following some system,such as betting‘head’after each run of seven consecutive tails,or(more plausibly)by placing the n th bet‘head’after the appearance of n+7tails in succession.According to von Mises,the above conditions are sufficiently familiar and a uncontroverted empirical generalization to serve as the basis of an applicable calculus of probabilities.Example1It turns out that the naive mathematical approach to a concrete formulation,admitting simply all partial functions,comes to grief as follows. Let a=a1a2...be any collective.Defineφ1asφ1(a1...a i−1)=1if a i=1, and undefined otherwise.But then p=1.Definingφ0byφ0(a1...a i−1)=b i, with b i the complement of a i,for all i,we obtain by the second condition of Definition1that p=0.Consequently,if we allow functions likeφ1andφ0as strategy,then von Mises’definition cannot be satisfied at all.3102.2Wald-Church Place SelectionIn the thirties,Abraham Wald(1902—1950)proposed to restrict the a priori admissibleφto anyfixed countable set of functions.Then collectives do exist. But which countable set?In1940,Alonzo Church proposed to choose a set of functions representing‘computable’strategies.According to Church’s Thesis, this is precisely the set of recursive functions.With recursiveφ,not only is the definition completely rigorous,and random infinite sequences do exist,but moreover they are abundant since the infinite random sequences with p=1/2 form a set of measure one.From the existence of random sequences with proba-bility1/2,the existence of random sequences associated with other probabilities can be derived.Let us call sequences satisfying Definition1with recursiveφMises-Wald-Church random.That is,the involved Mises-Wald-Church place-selection rules consist of the partial recursive functions.Appeal to a theorem by Wald yields as a corollary that the set of Mises-Wald-Church random sequences associated with anyfixed probability has the cardinality of the continuum.Moreover,each Mises-Wald-Church random se-quence qualifies as a normal number.(A number is normal in the sense of´Emile F´e lix´Edouard Justin Borel(1871—1956)if each digit of the base,and each block of digits of any length,occurs with equal asymptotic frequency.)Note however, that not every normal number is Mises-Wald-Church random.This follows,for instance,from Champernowne’s sequence(or number),0.1234567891011121314151617181920...due to David G.Champernowne(1912—),which is normal in the scale of10 and where the i th digit is easily calculated from i.The definition of a Mises-Wald-Church random sequence implies that its consecutive digits cannot be effectively computed.Thus,an existence proof for Mises-Wald-Church random sequences is necessarily nonconstructive.Unfortunately,the von Mises-Wald-Church definition is not yet good enough, as was shown by Jean Ville in1939.There exist sequences that satisfy the Mises-Wald-Church definition of randomness,with limiting relative frequency of ones of1/2,but nonetheless have the property thatf nfor all n.2The probability of such a sequence of outcomes in randomflips of a fair coin is zero.Intuition:if you bet‘1’all the time against such a sequence of outcomes, then your accumulated gain is always positive!Similarly,other properties of randomness in probability theory such as the Law of the Iterated Logarithm do not follow from the Mises-Wald-Church definition.An extensive survey on these issues(and parts of the sequel)is given in[8].113Randomness as IncompressibilityAbove it turned out that describing‘randomness’in terms of‘unpredictability’is problematic and possibly unsatisfactory.Therefore,Kolmogorov tried another approach.The antithesis of‘randomness’is‘regularity’,and afinite string which is regular can be described more shortly than giving it literally.Consequently,a string which is‘incompressible’is‘random’in this sense.With respect to infinite binary sequences it is seductive to call an infinite sequence‘random’if all of its initial segments are‘random’in the above sense of being‘incompressible’.Let us see how this intuition can be made formal,and whether leads to a satisfactory solution.Intuitively,the amount of effectively usable information in afinite string is the size(number of binary digits or bits)of the shortest program that,without additional data,computes the string and terminates.A similar definition can be given for infinite strings,but in this case the program produces element after element forever.Thus,a long sequence of1’s such as10,000times11111 (1)contains little information because a program of size about log10,000bits out-puts it:for i:=1to10,000print1Likewise,the transcendental numberπ=3.1415...,an infinite sequence of seemingly‘random’decimal digits,contains but a few bits of information.(There is a short program that produces the consecutive digits ofπforever.)Such a definition would appear to make the amount of information in a string(or other object)depend on the particular programming language used.Fortunately,it can be shown that all reasonable choices of programming languages lead to quantification of the amount of‘absolute’information in indi-vidual objects that is invariant up to an additive constant.We call this quantity the‘Kolmogorov complexity’of the object.If an object is regular,then it has a shorter description than itself.We call such an object‘compressible’.More precisely,suppose we want to describe a given object by afinite binary string.We do not care whether the object has many descriptions;however,each description should describe but one object.From among all descriptions of an object we can take the length of the shortest description as a measure of the object’s complexity.It is natural to call an object‘simple’if it has at least one short description,and to call it‘complex’if all of its descriptions are long.But now we are in danger of falling in the trap so eloquently described in the Richard-Berry paradox,where we define a natural number as“the least natural number that cannot be described in less than twenty words”.If this number12does exist,we have just described it in thirteen words,contradicting its defini-tional statement.If such a number does not exist,then all natural numbers can be described in less than twenty words.(This paradox is described in[Bertrand Russell(1872—1970)and Alfred North Whitehead,Principia Mathematica,Ox-ford,1917].In a footnote they state that it“was suggested to us by Mr.G.G. Berry of the Bodleian Library”.)We need to look very carefully at the notion of‘description’.Assume that each description describes at most one object.That is,there is a specification method D which associates at most one object x with a description y.This means that D is a function from the set of descriptions,say Y,into the set of objects,say X.It seems also reasonable to require that,for each object x in X,there is a description y in Y such that D(y)=x.(Each object has a description.)To make descriptions useful we like them to befinite.This means that there are only countably many descriptions.Since there is a description for each object,there are also only countably many describable objects.How do we measure the complexity of descriptions?Taking our cue from the theory of computation,we express descriptions as finite sequences of0’s and1’s.In communication technology,if the specification method D is known to both a sender and a receiver,then a message x can be transmitted from sender to receiver by transmitting the sequence of0’s and1’s of a description y with D(y)=x.The cost of this transmission is measured by the number of occurrences of0’s and1’s in y,that is,by the length of y. The least cost of transmission of x is given by the length of a shortest y such that D(y)=x.We choose this least cost of transmission as the‘descriptional’complexity of x under specification method D.Obviously,this descriptional complexity of x depends crucially on D.The general principle involved is that the syntactic framework of the description language determines the succinctness of description.In order to objectively compare descriptional complexities of objects,to be able to say“x is more complex than z”,the descriptional complexity of x should depend on x alone.This complexity can be viewed as related to a universal description method which is a priori assumed by all senders and receivers.This complexity is optimal if no other description method assigns a lower complexity to any object.We are not really interested in optimality with respect to all description methods.For specifications to be useful at all it is necessary that the mapping from y to D(y)can be executed in an effective manner.That is,it can at least in principle be performed by humans or machines.This notion has been formalized as‘partial recursive functions’.According to generally accepted mathematical viewpoints it coincides with the intuitive notion of effective computation.The set of partial recursive functions contains an optimal function which minimizes description length of every other such function.We denote this func-tion by ly,for any other recursive function D,for all objects x,there is a description y of x under D0which is shorter than any description z of x13。
浙江省宁波市英语初三上学期期中试卷及答案指导(2024年)

2024年浙江省宁波市英语初三上学期期中复习试卷及答案指导一、听力部分(本大题有20小题,每小题1分,共20分)1、What does the girl want to do?a) Play basketball.b) Watch TV.c) Go shopping.Recording: (Boy) “Hey, do you want to play some basketball after school?” (Girl) “Not really, I was thinking about going shopping instead.”Answer: c) Go shopping.Explanation: The girl responds to the boy’s suggestion by saying she’d rather go shopping than play basketball, making ‘Go shopping’ the correct answer.2、Where are the speakers?a) At a restaurant.b) In a library.c) At a movie theater.Recording: (Woman) “Excuse me, could you please keep it down? We’re trying to study over here.” (Man) “Oh, sorry, we didn’t realize it was so quiet aroundhere.”Answer: b) In a library.Explanation: The woman asks the man to keep his voice down because people are studying, indicating they are in a quiet place such as a library, not a restaurant or movie theater where noise levels are typically higher.3、What is the weather like in the city where the woman is visiting?A. Sunny.B. Rainy.C. Cloudy.D. Windy.Answer: BExplanation: In the conversation, the woman mentions that it’s been raining all day in the city she is visiting, so the correct answer is “Rainy.”4、Why does the man think it’s important to learn a second language?A. To improve his grades.B. To travel abroad easily.C. To understand different cultures.D. To find a good job.Answer: CExplanation: The man in the conversation states that learning a second language helps him understand and appreciate different cultures, making option C the correct answer.5、What does the boy want to drink?A. Coffee.B. Tea.Audio: (The audio clip would play here.)Answer: B. Tea.Explanation: In the conversation, the boy says, “I’m not a fan of caffeine;I think I’ll have some tea instead.” This clearly indicates that he prefers tea over coffee because he doesn’t like caffeine.6、Where does the dialogue take place?A. At a restaurant.B. At a clothing store.Audio: (The audio clip would play here.)Answer: A. At a restaurant.Explanation: The dialogue includes phrases such as “Can I get the check, please?” and “I’ll have the steak,” which suggest that the conversation is happening in a restaurant setting rather than a clothing store.7、Question: What is the weather like today according to the conversation?A) It’s sunny.B) It’s cloudy.C) It’s raining.D) It’s windy.Answer: BExplanation: The conversation mentions that it’s a bit cloudy today, so the correct answer is B) It’s cl oudy.8、Question: How does the man feel about the movie he just watched?A) He enjoyed it very much.B) He thinks it’s boring.C) He didn’t like it at all.D) He needs to see it again.Answer: AExplanation: The man says, “It was an amazing movie! I really enjoyed it,” which indicates that he enjoyed it very much, so the correct answer is A) He enjoyed it very much.9、(Listen to a dialogue about a school trip planning)Question: What activity does the boy suggest adding to the school trip itinerary?A. Visiting a museumB. Going to the beachC. Watching a play at the local theaterAnswer: C. Watching a play at the local theaterExplanation: In the dialogue, the boy mentions that he thinks it would be enriching for everyone to experience the culture of the destination by watchinga local performance at the theater, which isn’t part of the initial plan.10、(Follow-up question based on the same dialogue)Question: How does the girl respond to the boy’s suggestion?A. She agrees but suggests doing it another day.B. She disagrees because she thinks it will be boring.C. She likes the idea and proposes they combine it with visiting a museum.Answer: A. She agrees but suggests doing it another day.Explanation: The girl responds positively to the idea but mentions that the current schedule is already tight, so she proposes postponing the theater visit to another less busy day during the trip.11.You are listening to a conversation between a student and a teacher ina classroom.Student: “Mr.Smith, can you explain how the quadratic formula works again?”Teacher: “Certainly, the quadratic formula is used to solve quadratic equations of the form ax^2 + bx + c = 0. It is derived from the completing the square method. The formula is x = (-b ± √(b^2 - 4ac)) / (2a). Do you understand that?”Question: What does the teacher say about the quadratic formula?A) It’s a method to find the roots of any equation.B) It’s a formula to solve quadratic equations.C) It’s a technique for completing the square.D) It’s a shortcut for fin ding the sum of roots.Answer: B) It’s a formula to solve quadratic equations.Explanation: The teacher explicitly states that the quadratic formula isused to solve quadratic equations.12.You are listening to a news report about a new environmental initiative.News Anchor: “In a bid to combat climate change, the city government has announced the introduction of a new recycling program. This program will require all residents to separate their waste into recyclable and non-recyclable materials. The goal is to reduce the amount of waste sent to landfills by 50% within the next five years. How do you think this initiative will impact the environment?”Question: What is the main goal of the new recycling program?A) To encourage people to use more plastic products.B) To increase the number of parks in the city.C) To reduce the amount of waste in landfills.D) To provide jobs for recycling workers.Answer: C) To reduce the amount of waste in landfills.Explanation: The news report clearly states that the aim of the recycling program is to reduce waste sent to landfills by 50%.13.W: Have you finished your science homework yet?M: No, I haven’t. I’m going to the library to get some books on phy sics.Question: Where is the boy going?A) To the classroomB) To the libraryC) To the science labD) To the teacher’s officeAnswer: B) To the libraryExplanation: The boy says he is going to the library to get some books on physics, which indicates that he is going to the library for his homework.14.W: How was your weekend, Tom?M: It was quite busy. I had to help my father with the gardening. But on Sunday, we went to the beach and had a great time.Question: What did the boy do on Sunday?A) He went to the beachB) He helped his father with gardeningC) He studied for examsD) He went to the libraryAnswer: A) He went to the beachExplanation: The boy mentions that on Sunday, he went to the beach and had a great time, which is the correct answer. The other activities were mentioned but not on Sunday.15.You are listening to a conversation between two friends, Alice and Bob.A: Hey Bob, how was your weekend?B: It was pretty good, Alice. I went hiking with my friends on Sunday. We climbed up a mountain and had a great view at the top.A: That sounds amazing! Do you often go hiking?B: Yes, I love outdoor activities. We usually go hiking once a month.Question: How often does Bob go hiking?Answer: B) Once a month.Explanation: Bob mentions that he and his friends usually go hiking oncea month, so the correct answer is B) Once a month.16.You are listening to a news report about a new study.News Anchor: According to a recent study, eating a healthy diet can help improve cognitive function in older adults. Researchers found that individuals who consumed a balanced diet rich in fruits, vegetables, and whole grains showed better memory and concentration.Question: What did the study find about a healthy diet?Answer: A) It improves memory and concentration in older adults.Explanation: The news report directly states that the study found that a healthy diet, rich in fruits, vegetables, and whole grains, can help improve memory and concentration in older adults. Therefore, the correct answer is A) It improves memory and concentration in older adults.17.What are the speakers mainly discussing?A. The weather forecast for the next weekB. The importance of wearing a coat in cold weatherC. Their favorite winter activitiesD. The need for an extra blanket in the dormitoryAnswer: CExplanation: The speakers are discussing their favorite winter activities,which is indicated by the words “fun” and “exciting” in the conversation.18.Why does the man decide not to go for a walk in the park?A. He is worried about his health.B. The weather is too cold.C. He doesn’t have enough time.D. He is not interested in walking.Answer: BExplanation: The man mentions that it is freezing outside, which implies that the weather is too cold for him to go for a walk in the park.19.You hear a conversation between two students discussing their favorite subject.A)Math is their favorite subject because it’s challenging.B)English is their favorite subject because it’s interesting.C)Science is their favorite subject because it’s engaging.Answer: BExplanation: The conversation indicates that the students find English engaging and enjoyable, making it their favorite subject.20.You hear a weather forecast for a city in China.A)The weather will be sunny and warm with a high of 28°C.B)The weather will be cloudy with a chance of rain and a high of 22°C.C)The weather will be windy with a low of 10°C and a high of 15°C.Answer: BExplanation: The weather forecast mentions that it will be cloudy with a chance of rain and ahigher temperature during the day, which corresponds to option B.二、阅读理解(30分)Reading Passage:The following passage is about the importance of exercise for students.Exercise is not only beneficial for our physical health, but it also has a significant impact on our mental well-being. In recent years, more and more studies have shown that regular exercise can improve students’ academic performance, reduce stress, and increase their overall happiness.One study conducted by the University of California, Berkeley, found that students who engaged in moderate exercise for at least 30 minutes a day showed better cognitive function and memory retention compared to those who did not exercise. The study also suggested that physical activity can help students focus better and reduce the symptoms of ADHD.Moreover, exercise is a great way to relieve stress. A study published in the Journal of Physical Activity and Health revealed that students who exercised regularly had lower levels of cortisol, the stress hormone, in their bloodstream. This, in turn, helped them to handle stress more effectively and improve their emotional well-being.In addition to its mental health benefits, exercise also contributes to better academic performance. A survey conducted by the American Council on Exercise showed that students who participated in sports or physical activitiesscored higher on standardized tests than their non-athletic peers. This is because exercise improves blood circulation, which in turn enhances the delivery of oxygen and nutrients to the brain, leading to better cognitive function.With all these benefits, it is essential for students to incorporate regular exercise into their daily routines. However, many students struggle to find the time to exercise. To help them, schools can offer physical education classes, organize extracurricular sports activities, and encourage students to participate in community sports programs.Questions:1.According to the passage, what is one of the benefits of exercise for students’ academic performance?A) Improved physical healthB) Enhanced cognitive function and memory retentionC) Lower stress levelsD) Better emotional well-being2.What is the main idea of the second paragraph?A) Exercise is a great way to relieve stress.B) Regular exercise can improve students’ academic performance.C) Students with ADHD can benefit from exercise.D) Physical activity can help students focus better.3.Which of the following statements is NOT supported by the passage?A) Exercise can help students with ADHD.B) Regular exercise can improve students’ academic performance.C) Students who do not exercise have lower levels of cortisol.D) Physical activity enhances the delivery of oxygen and nutrients to the brain.Answers:1.B) Enhanced cognitive function and memory retention2.A) Exercise is a great way to relieve stress.3.C) Students who do not exercise have lower levels of cortisol.三、完型填空(15分)Section III: Reading ComprehensionDirections: There are 10 blanks in the following passage. For each blank, there are four choices marked A, B, C, and D. Choose the one that best fits into the passage. Then mark the corresponding letter on Answer Sheet 2 with a single line through the centre.The following is a story about a young girl named Lily who discovered the beauty of nature.One sunny morning, Lily decided to take a walk in the nearby forest. She had always been fascinated by nature and loved to explore the wonders of the world around her. As she walked deeper into the forest, she noticed a small, clear stream that flowed gently over the rocks.1.The story begins by describing a__________morning.A. cloudyB. sunnyC. rainyD. windyLily followed the stream and came across a beautiful flower that she had never seen before. It had petals of various colors, and its scent was so sweet that it made her stop in her tracks.2.Lily felt__________when she saw the flower.A. boredB. excitedC. scaredD. hungryContinuing her journey, Lily came upon a small, serene lake. The water was so clear that she could see the fish swimming below. She sat by the lake and took in the peacefulness of the scene.3.The lake was described as __________.A. dirtyB. sereneC. loudD. darkAs the afternoon sun began to set, Lily realized she had walked quite far. She needed to find her way back home. However, she was not worried, as she had learned the basics of navigation from her father.4.Lily was not worried about finding her way back because she __________.A. had a mapB. had a phoneC. knew the wayD. was too tiredAs she walked back, Lily reflected on her adventure. She realized that nature had a way of teaching her valuable lessons about life and the world around her.5.Lily’s adventure taught her about __________.A. the importance of technologyB. the beauty of natureC. the dangers of the forestD. the need for exerciseAnswer Key:1.B2.B3.B4.C5.B四、语法填空题(本大题有10小题,每小题1分,共10分)1、The students are going to the library_____________we_____________need some new books.A. because / areB. since / doC. if / willD. when / willAnswer: BExplanation: The correct answer is “since / do” because “since” is used to introduce a reason or cause, and “do” is used to agree with the present need expressed in the second clause. The sentence means “The students are going to the library because we need some new books.”2、In the_____________days, people used to travel by horseback, which was_____________than traveling by car.A. past, much slowerB. old, fasterC. present, as fastD. future, much fasterAnswer: AExplanation: The correct answer is “past, much slower” because “past” refers to a time that is in the past, and “much slower” correctly contrasts the speed of travel by horseback in the past with the speed of travel by car, which is generally faster.3、In the___________of the park, there is a beautiful lake that reflects the___________of the sky.A. middle, colorsB. center, blueC. middle, colors of the skyD. center, blue skyAnswer: CExplanation: The correct phrase to describe the location within the park is “in the middle of the park.” Additionally, the sentence is referring to the colors of the sky reflected in the lake, so “colors of the sky” is the correct choice.4、She___________her homework yesterday, but now she has finished it.A. didn’t doB. ha sn’t doneC. doesn’t doD. didn’t have doneAnswer: AExplanation: The sentence describes an action that happened in the past, which is a completed action. The correct past simple negative form to use is “didn’t do,” indicating that she did not do her home work yesterday. The other options are incorrect because they suggest actions in the present perfect or future perfect, which do not match the context of the sentence.5.The teacher,____________was very strict with us, retired last month.A. whoseB. whoC. thatD. whichAnswer: BExplanation: The correct answer is “who” because it is used as a relative pronoun to refer to “The teacher” in the non-restrictive relative clause “who was very strict with us.”6.It was not until yesterday that he____________the truth of the matter.A. realizedB. had realizedC. was realizingD. have realizedAnswer: AExplanation: The correct answer is “realized” because the sentence is using the structure “It was not until + past time + that + past simple,” indicating that the realization of the truth occurred in the past.7.In the 7 morning, I 8 up early and decided to go for a run in the park.A. last / gotB. first / gotC. next / gotD. early / gotAnswer: B. first / gotExplanation: The correct answer is “first” because it indicates the first morning in a sequence, which is the context given. “Got up” is the correct phrasal verb to use here, meaning to wake up.8.She 9 her homework last night and now she feels 10 to take a break.A. finished / tiredB. finishes / tiredC. finishing / tiredD. finished / tiredlyAnswer: A. finished / tiredExplanation: The correct answer is “finished” because the sentence is referring to an action that was completed in the past. “Tired” is the correct adjective to describe how she f eels after finishing her homework. “Finishes” would be incorrect because it is in the present tense, not past tense. “Finishing” would also be incorrect as it is the present participle, not the past simple form. “Tiredly” is an adverb and does not fit the context of describing her feeling after finishing her homework.9.I______(be) reading a book when you______(call) me yesterday.A. was, calledB. were, calledC. was, were calledD. were, was calledAnswer: AExplanation: In the first part of the sentence, “I” is the subject, and “was” is the past continuous tense of “be,” indicating that the action was in progress at a specific past time. In the second part, “you” is the subject, and “called” is the past simple tense of “call,” indicating that the action w as completed at a specific past time. Therefore, the correct answer is “was, called.”10.If I______(have) more time, I______(do) my homework yesterday.A. had, would have doneB. have, would doC. had, would doD. have, would have doneAnswer: AExplanation: This sentence is a conditional sentence with a past perfect tense in the first clause and a past perfect tense in the second clause. The first clause uses “If I had more time” to express a hypothetical situation in the past, and the second clause uses “I would have done” to express the result of that hypothetical situation. Therefore, the correct answer is “had, would have done.”五、简答题(本大题有5小题,每小题2分,共10分)1、What are the main differences between a novel and a play in terms of narrative structure and audience engagement?答案:1.Narrative Structure:a.A novel typically follows a linear narrative, with a clear beginning,middle, and end, allowing readers to follow the story sequentially.b.A play, on the other hand, uses a non-linear structure, often with scenesand acts that can be experienced out of chronological order, depending on the performance.2.Audience Engagement:a.In a novel, the audience engages with the story through reading andimagination, creating their own mental images of the characters andsettings.b.In a play, the audience engages through live performance, experiencingthe story through the actors’ performan ces and the physical setting of the stage.解析:This question requires an understanding of the basic differences between a novel and a play. The answer outlines the distinct narrative structures and the ways in which audiences engage with each form of literature. It highlights the linear nature of novels versus the more flexible and non-linear structure of plays, as well as the different methods of audience engagement, such as imagination in novels and live performance in plays.3、What are the main differences between the past simple tense and the present perfect tense in English grammar?答案:1.The past simple tense is used to describe actions or states that happened at a specific time in the past, without any reference to the present.2.The present perfect tense is used to describe actions or states that have happened at an unspecified time in the past and have a present result.解析:This question tests the understanding of the past simple and present perfecttenses in English. The past simple tense is typically used for past events without a clear connection to the present, while the present perfect tense is used to show a connection between the past and the present, often emphasizing the result or outcome of the action. For example, “I visited the museum yest erday” (past simple) vs.“I have visited the museum before” (present perfect).4、How do you form the future continuous tense in English?答案:1.The future continuous tense is formed by combining the word “will” with the base form of the verb plus “ing.”2.It is used to express actions or states that will be in progress at a specific time in the future.解析:This question focuses on the formation of the future continuous tense, which is used to describe actions that will be ongoing at a particular time in the future. It is important to note that the future continuous tense is not as common as the simple present tense for future actions. For example, “I will be reading a book at 6 PM tomorrow” or “They will be watching a movie tonight.” This tense emphasizes the ongoing nature of the action at the specified future time.5、After reading the passage about environmental protection, list three ways in which individuals can contribute to reducing pollution in their daily lives. Then, explain why you think one of these methods is the most effective.Answer:•Reduce, Reuse, and Recycle (the 3Rs)•Use public transportation, carpool, bike, or walk instead of driving alone •Conserve water and energy at homeExplanation for the most effective method:I believe that using public transportation, carpooling, biking, or walking instead of driving alone is the most effective way to reduce pollution. This is because the transportation sector is a major source of greenhouse gas emissions, contributing significantly to air pollution and climate change. By choosing more sustainable transport options, we can drastically cut down on the number of vehicles on the road, leading to less carbon dioxide and other pollutants being released into the atmosphere. Additionally, it helps to reduce traffic congestion, which not only lowers emissions but also improves the overall quality of life in urban areas by decreasing noise and travel time.解析:本题考查学生对环保知识的理解以及他们将这些知识应用到日常生活中的能力。
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FORMALIZED MATHEMATICSVolume12,Number2,2004University of BiałystokConcatenation of Finite Sequences Reducing Overlapping Part and an Argumentof Separators of Sequential FilesHirofumi Fukura Shinshu UniversityNagano Yatsuka Nakamura Shinshu UniversityNaganoSummary.For twofinite sequences,we present a notion of their concate-nation,reducing overlapping part of the tail of the former and the head of thelatter.At the same time,we also give a notion of common part of twofinitesequences,which relates to the concatenation given here.Afinite sequence is se-parated by anotherfinite sequence(separator).We examined the condition thata separator separates uniquely anyfinite sequence.This will become a model ofa separator of sequentialfiles.MML Identifier:FINSEQ8.The terminology and notation used here are introduced in the following articles: [14],[15],[9],[1],[12],[16],[3],[10],[2],[4],[5],[8],[13],[7],[11],and[6].The following propositions are true:(1)For every set D and for everyfinite sequence f of elements of D holdsf↾0=∅.(2)For every set D and for everyfinite sequence f of elements of D holdsf⇂0=f.Let D be a set and let f,g befinite sequences of elements of D.Then f g is afinite sequence of elements of D.Next we state three propositions:(3)For every non empty set D and for allfinite sequences f,g of elementsof D such that len f 1holds mid(f g,1,len f)=f.(4)Let D be a set,f be afinite sequence of elements of D,and i be a naturalnumber.If i len f,then f⇂i=εD.219c 2004University of BiałystokISSN1426–2630220hirofumi fukura and yatsuka nakamura(5)For every non empty set D and for all natural numbers k1,k2holdsmid(εD,k1,k2)=εD.Let D be a set,let f be afinite sequence of elements of D,and let k1,k2be natural numbers.The functor smid(f,k1,k2)yields afinite sequence of elements of D and is defined as follows:↾((k2+1)−′k1).(Def.1)smid(f,k1,k2)=f⇂k1−′1One can prove the following propositions:(6)Let D be a non empty set,f be afinite sequence of elements of D,andk1,k2be natural numbers.If k1 k2,then smid(f,k1,k2)=mid(f,k1,k2).(7)Let D be a non empty set,f be afinite sequence of elements of D,andk2be a natural number.Then smid(f,1,k2)=f↾k2.(8)Let D be a non empty set,f be afinite sequence of elements of D,andk2be a natural number.If len f k2,then smid(f,1,k2)=f.(9)Let D be a set,f be afinite sequence of elements of D,and k1,k2benatural numbers.If k1>k2,then smid(f,k1,k2)=∅and smid(f,k1,k2)=εD.(10)For every set D and for everyfinite sequence f of elements of D and forevery natural number k2holds smid(f,0,k2)=smid(f,1,k2+1).(11)For every non empty set D and for allfinite sequences f,g of elementsof D holds smid(f g,len f+1,len f+len g)=g.Let D be a non empty set and let f,g befinite sequences of elements of D.The functor ovlpart(f,g)yielding afinite sequence of elements of D is defined by the conditions(Def.2).(Def.2)(i)len ovlpart(f,g) len g,(ii)ovlpart(f,g)=smid(g,1,len ovlpart(f,g)),(iii)ovlpart(f,g)=smid(f,(len f−′len ovlpart(f,g))+1,len f),and(iv)for every natural number j such that j len g and smid(g,1,j)= smid(f,(len f−′j)+1,len f)holds j len ovlpart(f,g).Next we state the proposition(12)For every non empty set D and for allfinite sequences f,g of elementsof D holds len ovlpart(f,g) len f.Let D be a non empty set and let f,g befinite sequences of elements of D.The functor ovlcon(f,g)yielding afinite sequence of elements of D is defined as follows:(Def.3)ovlcon(f,g)=f (g⇂len ovlpart(f,g)).One can prove the following proposition(13)For every non empty set D and for allfinite sequences f,g of elementsof D holds ovlcon(f,g)=(f↾(len f−′len ovlpart(f,g))) g.concatenation of finite sequences reducing (221)Let D be a non empty set and let f,g befinite sequences of elements of D.The functor ovlldiff(f,g)yields afinite sequence of elements of D and is defined as follows:(Def.4)ovlldiff(f,g)=f↾(len f−′len ovlpart(f,g)).Let D be a non empty set and let f,g befinite sequences of elements of D.The functor ovlrdiff(f,g)yields afinite sequence of elements of D and is defined by:(Def.5)ovlrdiff(f,g)=g⇂len ovlpart(f,g).One can prove the following propositions:(14)Let D be a non empty set and f,g befinite sequences of elements ofD.Then ovlcon(f,g)=(ovlldiff(f,g)) ovlpart(f,g) ovlrdiff(f,g)andovlcon(f,g)=(ovlldiff(f,g)) ((ovlpart(f,g)) ovlrdiff(f,g)).(15)Let D be a non empty set and f be afinite sequence of elements of D.Then ovlcon(f,f)=f and ovlpart(f,f)=f and ovlldiff(f,f)=∅andovlrdiff(f,f)=∅.(16)For every non empty set D and for allfinite sequences f,g of elementsof D holds ovlpart(f g,g)=g and ovlpart(f,f g)=f.(17)Let D be a non empty set and f,g befinite sequences of elementsof D.Then len ovlcon(f,g)=(len f+len g)−len ovlpart(f,g)andlen ovlcon(f,g)=(len f+len g)−′len ovlpart(f,g)and len ovlcon(f,g)=len f+(len g−′len ovlpart(f,g)).(18)For every non empty set D and for allfinite sequences f,g of elementsof D holds len ovlpart(f,g) len f and len ovlpart(f,g) len g.Let D be a non empty set and let C1be afinite sequence of elements ofD.We say that C1separates uniquely if and only if the condition(Def.6)issatisfied.(Def.6)Let f be afinite sequence of elements of D and i,j be natural numbers.Suppose1 i and i<j and(j+len C1)−′1 len f and smid(f,i,(i+len C1)−′1)=smid(f,j,(j+len C1)−′1)and smid(f,i,(i+len C1)−′1)=C1.Then j−′i len C1.The following proposition is true(19)Let D be a non empty set and C1be afinite sequence of elements of D.Then C1separates uniquely if and only if len ovlpart((C1)⇂1,C1)=0.Let D be a non empty set,let f,g befinite sequences of elements of D,and let n be a natural number.We say that g is a substring of f if and only if: (Def.7)If len g>0,then there exists a natural number i such that n i andi len f and mid(f,i,(i−′1)+len g)=g.We now state four propositions:222hirofumi fukura and yatsuka nakamura(20)Let D be a non empty set,f,g befinite sequences of elements of D,andn be a natural number.If len g=0,then g is a substring of f.(21)Let D be a non empty set,f,g befinite sequences of elements of D,andn,m be natural numbers.If m n and g is a substring of f,then g is asubstring of f.(22)For every non empty set D and for everyfinite sequence f of elementsof D such that1 len f holds f is a substring of f.(23)Let D be a non empty set and f,g befinite sequences of elements of D.If g is a substring of f,then g is a substring of f.Let D be a non empty set and let f,g befinite sequences of elements of D.We say that g is a preposition of f if and only if:(Def.8)If len g>0,then1 len f and mid(f,1,len g)=g.One can prove the following four propositions:(24)Let D be a non empty set and f,g befinite sequences of elements of D.If len g=0,then g is a preposition of f.(25)For every non empty set D holds everyfinite sequence f of elements ofD is a preposition of f.(26)Let D be a non empty set and f,g befinite sequences of elements of D.If g is a preposition of f,then len g len f.(27)Let D be a non empty set and f,g befinite sequences of elements of D.If len g>0and g is a preposition of f,then g(1)=f(1).Let D be a non empty set and let f,g befinite sequences of elements of D.We say that g is a postposition of f if and only if:(Def.9)Rev(g)is a preposition of Rev(f).Next we state several propositions:(28)Let D be a non empty set and f,g befinite sequences of elements of D.If len g=0,then g is a postposition of f.(29)Let D be a non empty set and f,g befinite sequences of elements of D.If g is a postposition of f,then len g len f.(30)Let D be a non empty set,f,g befinite sequences of elements of D,andn be a natural number.Suppose g is a postposition of f.If len g>0,thenlen g len f and mid(f,(len f+1)−′len g,len f)=g.(31)Let D be a non empty set,f,g befinite sequences of elements of D,and n be a natural number such that if len g>0,then len g len f andmid(f,(len f+1)−′len g,len f)=g.Then g is a postposition of f.(32)Let D be a non empty set,f,g befinite sequences of elements of D,andn be a natural number.If len g=0,then g is a preposition of f.(33)Let D be a non empty set,f,g befinite sequences of elements of D,andn be a natural number.If1 len f and g is a preposition of f,then g isconcatenation of finite sequences reducing (223)a substring of f.(34)Let D be a non empty set,f,g befinite sequences of elements of D,and n be a natural number.Suppose g is not a substring of f.Let i be anatural number.If n i and0<i,then mid(f,i,(i−′1)+len g)=g.Let D be a non empty set,let f,g befinite sequences of elements of D,and let n be a natural number.The functor instr(n,f)yielding a natural number is defined by the conditions(Def.10).(Def.10)(i)If instr(n,f)=0,then n instr(n,f)and g is a preposition of f⇂instr(n,f)−′1and for every natural number j such that j n and j>0and g is a preposition of f⇂j−′1holds j instr(n,f),and(ii)if instr(n,f)=0,then g is not a substring of f.Let D be a non empty set and let f,C1befinite sequences of elements of D.The functor addcr(f,C1)yields afinite sequence of elements of D and is defined by:(Def.11)addcr(f,C1)=ovlcon(f,C1).Let D be a non empty set and let r,C1befinite sequences of elements ofD.We say that r is terminated by C1if and only if:(Def.12)If len C1>0,then len r len C1and instr(1,r)=(len r+1)−′len C1.The following proposition is true(35)For every non empty set D holds everyfinite sequence f of elements ofD is terminated by f.References[1]Grzegorz Bancerek.The fundamental properties of natural numbers.Formalized Mathe-matics,1(1):41–46,1990.[2]Grzegorz Bancerek and Krzysztof Hryniewiecki.Segments of natural numbers andfinitesequences.Formalized Mathematics,1(1):107–114,1990.[3]Czesław Byliński.Finite sequences and tuples of elements of a non-empty sets.FormalizedMathematics,1(3):529–536,1990.[4]Czesław Byliński.Functions and their basic properties.Formalized Mathematics,1(1):55–65,1990.[5]Czesław Byliński.Functions from a set to a set.Formalized Mathematics,1(1):153–164,1990.[6]Czesław Byliński.Some properties of restrictions offinite sequences.Formalized Mathe-matics,5(2):241–245,1996.[7]Agata Darmochwał.The Euclidean space.Formalized Mathematics,2(4):599–603,1991.[8]Agata Darmochwałand Yatsuka Nakamura.The topological space E2T.Arcs,line segmentsand special polygonal arcs.Formalized Mathematics,2(5):617–621,1991.[9]Krzysztof Hryniewiecki.Basic properties of real numbers.Formalized Mathematics,1(1):35–40,1990.[10]Jarosław Kotowicz.Functions andfinite sequences of real numbers.Formalized Mathe-matics,3(2):275–278,1992.[11]Yatsuka Nakamura and Roman Matuszewski.Reconstructions of special sequences.For-malized Mathematics,6(2):255–263,1997.[12]Takaya Nishiyama and Yasuho Mizuhara.Binary arithmetics.Formalized Mathematics,4(1):83–86,1993.224hirofumi fukura and yatsuka nakamura[13]Beata Padlewska and Agata Darmochwał.Topological spaces and continuous functions.Formalized Mathematics,1(1):223–230,1990.[14]Andrzej Trybulec.Tarski Grothendieck set theory.Formalized Mathematics,1(1):9–11,1990.[15]Zinaida Trybulec.Properties of subsets.Formalized Mathematics,1(1):67–71,1990.[16]Edmund Woronowicz.Relations and their basic properties.Formalized Mathematics,1(1):73–83,1990.Received March18,2004。
Properties of First and Second Order Cutting of Binary Relations

MATHEMATICS
13, Number 3, Pages 361–365
of Bialystok, 2005
University
Properties of First and Second Order Cuttrzysztof Retel School of Mathematical and Computer Sciences Heriot-Watt University Riccarton, Edinburgh EH14 4AS, Scotland
c
2005 University of Bialystok ISSN 1426–2630
362
krzysztof retel
(1) y ∈ {{∗} : ∗ ∈ X } iff there exists x such that y = {x} and x ∈ X. (2) X = ∅ iff {{∗} : ∗ ∈ X } = ∅. (3) {{∗} : ∗ ∈ X ∪ Y } = {{∗} : ∗ ∈ X } ∪ {{∗} : ∗ ∈ Y }. (4) {{∗} : ∗ ∈ X ∩ Y } = {{∗} : ∗ ∈ X } ∩ {{∗} : ∗ ∈ Y }. (5) {{∗} : ∗ ∈ X \ Y } = {{∗} : ∗ ∈ X } \ {{∗} : ∗ ∈ Y }. (6) X ⊆ Y iff {{∗} : ∗ ∈ X } ⊆ {{∗} : ∗ ∈ Y }. Let M be a set and let X , Y be families of subsets of M . Then X ∩ Y is a family of subsets of M . We now state two propositions: (7) For all families B1 , B2 of subsets of M holds Intersect(B1 ) ∩ Intersect(B2 ) ⊆ Intersect(B1 ∩ B2 ). (8) (P ∩ Q) · R ⊆ (P · R) ∩ (Q · R).
3-fold log flips according to V.V.Shokurov
arXiv:math/9803145v1 [math.AG] 29 Mar 1998
Hiromichi Takagi∗
Abstract. We review §8 of V. V. Shokurov’s paper ”3-fold log flips”.
2
0
HIROMICHI TAKAGI
0
Definition (0.3) (S n (local)). We denote by S n (local) the set of sequences (b1 , b2 , . . . bm ) such that there is a Q-factorial variety X of dimension at most n, a subset Z ⊂ X and a divisor B0 + bi Bi (B0 = φ is reduced but possibly reducible) such that every Bi intersects Z , Z ⊂ B0 , KX + B0 is PLT and KX + B0 + bi Bi is maximally log canonical near Z . Shokurov proved the following Reduction Theorem: Theorem (0.4) (Reduction Theorem). Let X be a n-dimensional normal variety and B a boundary such that KX + B is KLT. Let f : X → Y be a small contraction such that −(KX + B ) is f -ample. Then the flip of f exists if the following three hold: (1) (Existence of Special flips) there exists the flip for any special flipping contraction of dimension n; (2) (Special termination) The special termination holds in dimension n; 0 (3) (A.C.C for S n (local)) 0 The ascending chain condition holds for the set S n (local). Proof. See [S,Theorem 6.4] or [FA, §18]. In dimension 3, the special termination holds by [S, Theorem 4.1] or [FA, Theorem 7.1]. 0 Furthermore the A.C.C holds for S 3 (local) by [S, Chicago Lemma 4.9] or [FA,Proposition 18.19 and Corollary 18.25.1]. Hence in dimension 3, it suffices to prove the existence of the special flip. So we consider only the special flipping contraction in the below and we use the notation in Definition 0.1 for explanation. First we can easily prove the existence in case S is reducible (See [FA, Proposition 21.2].) Hence we may assume that S is irreducible in the below. To flip in this case, Shokurov introduced the concept of the complement and divided special flipping contractions into cases using it: Definition (0.5) (Complement) (See [S, §5] or [FA, §19]). Let X be a normal variety and B a subboundary on X . Let S be the smallest effective Weil divisor on X such that B − S ≤ 0, and let B0 := B − S . An n-complement of KX + B is a divisor B ∈ | − nKX − nS − (n + 1)B0 | 1 ( (n + 1)B0 + B ). We say KX + B is nsuch that KX + B + is LC, where B + := S + n complemented if an n-complement exists. The definition is arranged so that the vanishing theorem can be applied. But in the explanation below, we consider only the case B is a reduced boundary. So we restate the definition for this case. Definition (0.5’) (Complement). Let X be a normal variety and S a reduced boundary. An n-complement of KX + S is a divisor B ∈ | − nKX − nS | such that KX + S + B is LC, 1 B . We say KX + B is n-complemented if an n-complement exists. where B := n Then the following theorem holds: Theorem (0.6). Let f : X → Y be a 3-dimensional special flipping contraction such that S is irreducible. Then KX + S is n-complemented, where n ∈ {1, 2, 3, 4, 6}. Proof. See [S, Theorem 5.12] or [FA, Theorem 19.6 and Theorem 19.8]. We call the minimum of n as in Theorem 0.6 the index of f . In case the index is 1, it is easy to show the existence of the flip. (See [S, Proposition 6.8] or [FA, Proposition 21.4].)
Linear algorithms with finite deviation H. Brass
To exclude trivialities, we assume from now on that I is not of the form
I f] =
n X
=1
a f (x ) :
Theorem 1. In the case of the co-observation (3) we have
M should be interpreted
sup sup fI g ? g ] : g ; g 2 Info (f )g < 1 :
f 2K
1 2 1 2
(5)
If n r then we use a suitable expression for the error of polynomial interpolation at the nodes x ; : : : ; xr and obtain jg (x) ? g (x)j M const
f 2K
and assume
(1)
Because of the convexity of K, the set I Info (f )] is an interval (and we assume that our information is not contradictory, so it is nonvoid), because of (1) it is bounded. We de ne further the \strongly optimal" (or \central") algorithm 1 ^ Qso f ] := 2 (Q f ] + Q f ]) and its error 1 ^ f ] := 2 (Q f ] ? Q f ]) : Although this a simple and natural concept (the idea goes back at least as far as v. Mises 1933]), there are very few explicity known examples of strongly optimal algorithms. Our purpose is to identify a source of the di culties by showing that in many cases of practical interest the strongly optimal algorithms are nonlinear. Here we call Qso linear if it has the form n X so f ] = Q a f (x ) ; f 2 K (2) with (a independent of f . So we may look for other algorithms which combine simplicity with small error. An algorithm is in our context a real function Q de ned on f(f (x ); : : : ; f (xn)) : f 2 Kg. As a measure of the quality of Q we de ne the \deviation" dev Q := sup jI f ] ? Q f ]j (f ) f 2K
Generating Sequences With Recurrent Neural Networks
3 hidden Layers, 400 LSTM cells in each 3.6M weights total Trained with RMSprop, learn rate 0.0001, momentum 0.9 Error clipped during backward pass (lots of numerical problems) Trained overnight on fast multicore CPU
Input gate: scales input to cell (write) Output gate: scales output from cell (read) Forget gate: scales old cell value (reset)
• S. Hochreiter and J. Schmidhuber, “Long Short-‐term Memory” Neural Computa:on 1997
Samples
Samples
Output Density
Handwriting Synthesis
• • • •
Want to tell the network what to write without losing the distribution over how it writes Can do this by conditioning the predictions on a text sequence Problem: alignment between text and writing unknown Solution: before each prediction, let the network decide where it is in the text sequence
A new result on the distinctness of primitive sequences over Z(pq) modulo 2(FFA-2011)
doi:10.1016/j.ffa.2010.12.004
Q.-X. Zheng, W.-F. Qi / Finite Fields and Their Applications 17 (2011) 254–274
A new result on the distinctness of primitive sequences over
Z/(pq) modulo 2 ✩
Qun-Xiong Zheng a, Wen-Feng Qi a,b,∗
a Department of Applied Mathematics, Zhengzhou Information Science and Technology Institute, Zhengzhou, PR China b State Key Laboratory of Information Security, Institute of Software, Chinese Academy of Sciences, Beijing, PR China
sequences generated by f (x) are pairwise distinct, then there is a one-to-one correspondence between
compressing sequences and primitive sequences, which implies that every compressing sequence pre-
If a sequence a = (a(t))t 0 over Z/(N) satisfies
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Introduction
Fix a field k . For any integers m, n with 0 2m n + 1, let Wn be the k -vector space of sequences (x0 , . . . , xn ), and let Hm ⊆ Wn be the subset of sequences satisfying a degree-m linear recursion, that is, for which there exist a0 , . . . , am ∈ k , not all zero, such that
On finite sequences satisfying linear recursions
Noam D. Elkies1 May, 2001
corrected April, 2002 per referee’s report
arXiv:math/0105007v2 [math.CO] 12 Jun 2002
m
ai xi+j = 0
i=0
holds for each j = 0, 1, . . . , n − m. Equivalently, Hm is the set of (x0 , . . . , xn ) such that the (m + 1) × (n − m + 1) matrix with (i, j ) entry xi+j (0 i m, 0 j n − m) has rank at most m. We use elementary linear and polynomial algebra to study these sets Hm . In particular, when k is a finite field of q elements, we write the characteristic function of Hm as a linear combination of characteristic functions of linear subspaces of dimensions m and m + 1 in Wn . We deduce a formula for the discrete Fourier transform of this characteristic function, and obtain some consequences. For instance, if the 2m + 1 entries of a square Hankel matrix of order m + 1 are chosen independently from a fixed but not necessarily uniform distribution µ on k , then as m → ∞ the matrix is singular with probability approaching 1/q provided µ 1 < q 1/2 . This bound q 1/2 is best possible if q is a square.
1
has rank at most m.3 Now linear recursions on infinite sequences {xi }i∈Z are known to correspond to polynomials in the shift operators T ±1 : {xi } → {xi±1 }, modulo multiplication by powers of T . This approach does not work so nicely for finite sequences, because T and T −1 push x0 and xn off the edge. We propose to remedy this problem at T = 0, ∞ by homogenizing: instead of polynomials in T ±1 , use homogeneous polynomials in two variables Y and Z that act on Wn as the right and left truncation maps to Wn−1 . We shall see that this approach yields a clean account of linear recursions and the subsets Hm in the space Wn , which itself will be identified with the dual of the space Vn of homogeneous polynomials of degree n in Y and Z .4 In the present paper we develop this account using elementary linear and polynomial algebra. When k is a finite field of q elements, we also write the characteristic function of Hm as a linear combination of characteristic functions of linear subspaces of dimensions m and m + 1 in Wn . We deduce a formula for the discrete Fourier transform of this characteristic function, and obtain some consequences. For instance we obtain a new proof that #Hm = q 2m . We further show that if the 2m + 1 entries x0 , . . . , x2m of a square Hankel matrix x0 x1 ··· xm x1 x2 · · · xm+1 (3) . . . . . . . . . xm xm+1 · · · x2m of order m +1 are chosen independently from a fixed but not necessarily uniform distribution µ on k , then as m → ∞ the the matrix is singular with probability approaching 1/q provided the Fourier transform of µ has l1 norm less than q 1/2 . This bound is best possible if q is a square: if µ is the uniform distribution
m
ai xi+j = 0
i=0
(1)
holds for each j = 0, 1, . . . , n − m. Equivalently, Hm is the set of (x0 , . . . , xn )