数据库实验报告

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实验内容与要求

请有选择地实践以下各题。

(1)基于“教学管理”数据库jxgl,使用SQL的查询语句表达下列查询:①检索年龄大于23岁的男学生的学号和姓名;

SELECT Sno,Sname

FROM Student

WHERE Ssex=’男’AND

Sage>23;

②检索至少选修一门课程的女生姓名;

SELECT Sname

FROM Student

WHERE Ssex=’女’AND Sno IN

( SELECT Sno

FROM SC

GROUP BY Sno

HAVING count(*)>=1;

);

③检索王同学不学的课程的课程号;

SELECT Cno;

FROM Course

WHERE Cno NOT IN

( SELECT Cno

FROM Student,SC

WHERE Sname like ’王%’AND Student.Sno=SC.Sno );

④检索至少选修两门课程的学生学号;

SELECT DISTINCT Sno

FROM SC

GROUP BY Sno

HAVING count(*)>=2;

⑤检索全部学生都选修的课程的课程号与课程名;

SELECT Cno,Cname

FROM Course

WHERE NOT EXISTS

( SELECT *

FROM Student

WHERE NOT EXISTS

( SELECT *

FROM SC

WHERE SC.Sno=Student.Sno AND o=o )

);

⑥检索选修了所有3学分课程的学生学号;

SELECT DISTINCT Sno

FROM SC X

WHERE NOT EXISTS

( SELECT *

FROM Course

WHERE Ccredit=3 AND NOT EXISTS

( SELECT *

FROM SC Y

WHERE X.Sno=Y.Sno AND o=o

)

);

(2)基于“教学管理”数据库jxgl,使用SQL的查询语句表达下列查询:

①统计有学生选修的课程门数;

SELECT count(DISTINCT Cno)

FROM SC;

②求选修4号课程的学生的平均年龄;

SELECT AVG(Sage)

FROM Student,SC

WHERE Cno=4 AND Student.Sno=SC.Sno;

③求学分为3的每门课程的学生平均成绩;

SELECT AVG(Grade)

FROM Course,SC

WHERE Ccredit=3 AND o=o

GROUP BY o;

④统计每门课程的学生选修人数,要求超过3人的课程才统计,要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列;

SELECT Cno,count(Sno)

FROM SC

GROUP BY Cno

HAVING count(Sno)>3

ORDER BY count(Sno) DESC,Cno ASC;

⑤检索学号比“王菲”同学大而年龄比他小的学生姓名;

SELECT Sname

FROM Student X

WHERE Sno>

( SELECT Sno

FROM Student Y

WHERE Sname=’王菲’AND Sage>

( SELECT Sage

FROM Student Z

WHERE Sname=’王菲’AND X.Sno=Z.Sno AND Y.Sno=Z.Sno

)

);

⑥检索姓名以“王”打头的所有学生的姓名和年龄;

SELECT Sname,Sage

FROM Student

WHERE Sname LIKE ‘王%’;

⑦在SC中检索成绩为空置的学生学号和课程号;

SELECT Sno,Cno

FROM SC

WHERE Grade is NULL;

⑧求年龄大于女同学平均年龄的男学生姓名和年龄;

SELECT Sname,Sage

FROM Student X

WHERE Ssex=’男’AND Sage>

( SELECT AVG(Sage)

FROM Student

WHERE Ssex=’女’AND X.Sno=Y.Sno

);

⑨求年龄大于所有女同学年龄的男同学姓名和年龄;

SELECT Sname,Sage

FROM Student X

WHERE Ssex=’男’AND Sage>

( SELECT MAX(Sage)

FROM Student Y

WHERE Ssex=’女’AND X.Sno=Y.Sno

);

⑩检索所有比“王华”年龄大的学生姓名,年龄和性别;

SELECT Sname,Sage,Ssex

FROM Student X

WHERE Sage>

( SELECT Sage

FROM Student Y

WHERE Sname=’王华’AND X.Sno=Y.Sno

);

①检索选修“2”课程的学生中成绩最高的学生和学号;

SELECT Sname,SC.Sno

FROM Student,SC

WHERE Cno=2 AND Student.Sno=SC.Sno;

②检索学生姓名和其所选修课程的课程号和成绩;

SELECT Sname,Cno,Grade

FROM Student,SC

WHERE Student.Sno=SC.Sno

GROUP BY Sname;

③检索选修4门以上课程的学生总成绩(不统计不及格的课程),并要求按总成绩的降序排列出来;

SELECT Sno,SUM(Grade)

FROM SC X

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