医用物理学课后习题参考答案解析

医用物理学课后习题参

考答案解析

-CAL-FENGHAI-(2020YEAR-YICAI)_JINGBIAN

医用物理学课后习题参考答案

第一章

1-1 ① 1rad/s ② 6.42m/s

1-2 ① 3.14rad/s - ② 31250(3.9310)rad π⨯ 1-3 3g =

2l β 1-4 1

W=g 2

m l 1-5 ① 22

k E 10.8(1.0710)J π=⨯ ② -2M=-4.2410N m ⨯⋅

③ 22

W 10.8(1.0710)J π=-⨯

1-6 ① 26.28rad/s ② 314rad ③ 394J ④ 6.28N

1-7 ① ω ② 1

g 2

m l 1-8 ① =21rad/s ω ② 10.5m/s

1-9 ① =20rad/s ω ② 36J ③ 2

3.6kg m /s ⋅

1-10 ① 211=

2ωω ②1

=-2

k k1E E ∆ 1-11 =6rad/s ω 1-12 12F =398F 239N

N =

1-13 ① 51.0210N ⨯ ② 1.9%

1-14 ① 42210/N m ⨯ ② 52410/N m ⨯

1-15 ① -6

5m(510)m μ⨯ ② -31.2510J ⨯

第三章

3-1 -33V=5.0310m ⨯

3-2 ① 12m/s ② 5

1.2610a P ⨯

3-3 ① 9.9m/s ② 36.0m

3-4 ①-221.510;3.0/m m s ⨯ ② 4

2.7510a P ⨯ ③粗处的压强大于

51.2910a P ⨯时，细处小于P 0时有空吸作用。

3-5 主动脉内Re 为762～3558，Re<1000为层流，Re>1500为湍流， 1000< Re<1500为过渡流。 3-6 71.210J ⨯ 3-7 0.77m/s

3-8 ①3=5.610a P P ∆⨯ ②173

=1.3810a P s m β-⨯⋅⋅③-143Q=4.0610/m s ⨯

3-9 0.34m/s 3-10 431.5210/J m ⨯

第四章

4-1 -2

3

S=810cos(4t )m 2

ππ⨯+

或-2

-2S=810cos(4t-

)m=810sin 4t 2

π

ππ⨯⨯

4-2 ① ϕπ∆= ② 12t=1s S 0,S 0==当时，

4-3 ① S=0.1cos(t-

)m 3

π

π ②5

t (0.833)6

s s ∆=

4-4 ①-2

S=810cos(2t-

)m 2

π

π⨯ ② -2=-1610s in(2t-

)m/s 2

v π

ππ⨯;

2-22a=-3210cos(2t-

)m/s 2

π

ππ⨯③k E =0.126J 0.13J;

F=0≈.

4-5 ①max =20(62.8)m/s v π ②242

max a =4000 3.9410m/s π=⨯

③22321

E=

m A =1.9710J=200J 2

ωπ⨯ 4-6 ①2

A 5.010,=4,T=0.25,

=1.25m Hz s m νλ-=⨯

② -2

S=5.010cos8(t-

)0.5

x

m π⨯ 4-7 ①S=0.10cos

(-)0.10cos 0.2(-)522

x x

t m t m π

π= ②S=-0.10m

4-8 ①=60,=1.0Hz m νλ ② -2S=5.010cos120(-

)60

x

t m π⨯ 4-9 ①1s ϕπ-=②2A 6.010,=20,T=0.1,=0.2,c 2.m s m m/s ωπλ-=⨯= 4-10 ①22-31

=

A =25.44J m 2

ερω⋅ ②328.4210W m -⨯⋅ 4-11 ① 0 ② 2A

4-12 ①-3

9.1210a P ⨯ ②-9E=1.6510J ⨯

4-13 ① 889.9 ② 0.5

4-14 ① -621.010W m -⨯⋅ ② -61.010W ⨯ 4-15 2=0.054 5.410v m/s m/s -=⨯

第五章

5-1 ①71.110a P ⨯ ②6

7.0810a P ⨯

5-2 ① 2534.8310m -⨯ ② -9

=2.7310;

9d m ⨯倍。

5-3 p =389v m/s =441v m/s m/s

5-4 ①31.5610J ⨯ ；氧分子的-21-21t r =6.2110J;=4.1410J;εε⨯⨯

（8g 氧气的总平均平动动能t =935J;ε总转动动能r =623J ε） ② 26J ③ 32.510J ⨯ 5-5 -21t =6.2110J ε⨯

5-6 ①T=1.6k ∆ ②4

P=1.6610a P ∆⨯

5-7 P=0.126(0.13)a P 或 5-8 3=6.110h m ⨯ 5-9 ①-8=5.810m λ⨯ ② =455v m/s ;91Z=7.810s -⨯ 5-10 -32D=1.910/m s ⨯;=426v m/s ;-5=1.3410m λ⨯

第六章

6-1 ①-367.610N/m ⨯ ②-31.2710N ⨯