高三阶段性检测(17)
2017届高三理科综合三诊考试卷(含答案)

2017届高三理科综合三诊考试卷(含答案)遂宁市高中2017届三诊考试理科综合能力测试本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
全卷满分300分,考试时间10分钟。
注意事项:1.答题前,考生务必将自己的姓名、班级、考号用0毫米的黑色墨水签字笔填写在答题卡上。
并检查条形码粘贴是否正确。
2.选择题使用2B铅笔填涂在答题卡对应题目标号的位置上,非选择题用0毫米黑色墨水签字笔书写在答题卡对应框内,超出答题区域书写的答案无效;在草稿纸、试题卷上答题无效。
3.考试结束后,将答题卡收回。
可能用到的相对原子质量:H-1 -12 -16 l-3 Na-23 Al-27 u-64 Zn-6第Ⅰ卷(选择题,共126分)一、选择题(本题共13小题,每小题6分。
在每小题给出的四个选项中,只有一项符合题目要求)1.关于最基本的生命系统相同点的叙述,错误的是A 生命活动的主要承担者是蛋白质B 遗传信息的翻译场所是核糖体遗传物质主是要DNA或RNA D 系统边界的基本支架具有流动性2.滤泡性淋巴瘤起于正常的滤泡生发中心B细胞。
在滤泡生发中心B细胞向滤泡性淋巴瘤细胞发展转化的过程中常发生多个基因突变。
关于这两种细胞的比较,分析正确的是A.细胞周期的长短不相同B.均具有无限增殖能力.凋亡和衰老的时间相同D.糖蛋白种类和含量相同3.Aita小鼠是一种糖尿病模型小鼠,该小鼠由于胰岛素基因突变干扰了胰岛素二硫键的形成,大量错误折叠的蛋白质累积在内质网中,导致相关细胞的内质网功能紊乱,最终启动对该细胞的凋亡程序。
与此有关叙述错误的是A.胰岛素空间结构的形成离不开内质网的加工B.内质网功能紊乱会诱发某些特定基因的表达.Aita小鼠胰岛A细胞和胰岛B细胞大量凋亡D.Aita小鼠体内肝细胞合成糖原的速率减慢4.正常的受精卵在早期有丝分裂的过程中染色体不分离也会导致21三体综合征,与此有关叙述正确的是A.患者含有三体综合征的相关致病基因B.患者有可能形成正常的成熟生殖细胞.患者病因与染色体的联会紊乱有关系D.患者体内的细胞中含有三个染色体组.下列实验中都有前后对照的是A.鲁宾和卡门证明了光合作用释放的氧全部自水B.探究PH对过氧化氢酶活性的影响.探究酵母菌细胞呼吸的方式D.洋葱表皮细胞的质壁分离与复原6.白花三叶草有两个稳定遗传的品种,叶片内含氰(有剧毒)和不含氰的。
山西省吕梁市2022至2023学年高三11月阶段性测试化学试题附参考答案

吕梁市2022~2023学年度高三年级阶段性测试化学试题(本试题满分100分,考试时间90分钟。
答案一律写在答题卡上)可能用到的相对原子质量:H :1 C :12 N :14 O :16 Na :23 Mg :24 Al :27 S :32 Cl :35.5 K :39 Fe :56 Cu :64 Br :80 Ag :108 Mn :55注意事项:1.本试卷分第Ⅰ(选择题)和第Ⅱ卷(非选择题)两部分。
2.答题前,考生务必用0.5毫米黑色签字笔填写好自己的姓名、班级、考号等信息。
3.考试作答时,肘将答案正确地填写在答题卡上,答在本试卷上无效。
4.考试结束后将答题卡交回。
第Ⅰ卷 选择题(共48分)一、选择题(本题包括16小题,每小题3分,共48分。
每小题只有一个选项符合题意)1.中华古诗词精深唯美,下列有关说法错误的是( )A .“白云深处有人家”:“白云”是一种胶体B .“松阁静临龙虎窟,瀑布寒挂水晶帘”:生活中常见水晶挂件的主要成分为硅酸盐C .“粉骨碎身全不怕,要留清白在人间”:有化学能和热能的相互转化D .“墙角数枝梅,凌寒独自开。
遥知不是雪,为有暗香来”中“暗香”是分子运动的结果2.化学创造美好生活。
下列对生产活动的知识解读错误的是( )选项生产活动知识解读A 用干冰进行人工降雨干冰升华吸热B 用生石灰作食品干燥剂生石灰吸水,易与水反应C 向葡萄酒中通入少量进行防腐,起到保质作用2SO 具有氧化性2SO D 利用氢氟酸刻蚀石英制作艺术品氢氟酸可与反应2SiO A .AB .BC .CD .D3.下列示意图表述内容不相符的是()ABCD熔融氯化钠导电合金内原子层之间的相对滑动变得困难,导致合金的硬度变大标准状况下,气体所占体积1mol 聚乙烯的部分分子结构模型A .AB .BC .CD .D4.设为阿伏加德罗常数的值。
下列说法正确的是( )A N A .常温下,的硫酸中所含的数目为100g 98%H +A2N B .标准状况下,体积均为的和中所含分子数都约为1.12L HCl HF A 0.05N C .和的混合物中含有的电子数为1622.0g D O 143ND A N D .溶液中,数目为31mol /L AlCl Cl -A3N 5.宏观辨识和微观探析是化学学科的核心素养之一,下列指定反应的离子方程式书写正确的是()A .向溶液中加入过量稀盐酸:2NaAlO 223AlO H H O Al(OH)-+++↓B .向溶液中通入:2CaCl 2CO 2223Ca H O CO CaCO 2H ++++↓+C .溶液久置空气中变黄色:KI 2224I O 2H O 2I 4OH --+++D .明矾溶液中加入过量溶液:()()422KAl SO 12H O ⋅2Ba(OH)322434Al SO Ba 3OH Al(OH)BaSO +-+-+++↓+↓6.用下列仪器或装置(图中夹持略)进行相应实验,能达到实验目的的是()A B C D配制浓度为的10.010mol L-⋅溶液4KMnO铜和稀硝酸制取、净化、收集一氧化氮测定醋酸浓度验证干燥的氯气是否有漂白性A.A B.B C.C D.D7.科研人员提出了雾霾微粒中硫酸盐生成的三个阶段的转化机理,其主要过程示意图如下。
山东省名校考试联盟2024-2025学年高三上学期10月阶段性检测数学试题(解析版)

山东名校考试联盟2024年10月高三年级阶段性检测数学试题注意事项:1.答卷前,考生务必将自己的考生号、姓名、考场号及座位号填写在答题卡上.2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑.如需要改动,用橡皮擦干净后,再选涂其他答案标号.回答非选择题时,将答案写在答题卡上.写在本试卷上无效.3全卷满分150分.考试用时120分钟..考试结束后,将本试卷和答题卡一并交回.一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 已知()(){}23230,02x A x x x B x x +=∈−−==∈≤ − Q R∣,则A B = ( )A. {}2B. {C. {}2D. ∅【答案】D 【解析】【分析】解方程与不等式求得集合,A B ,进而可求A B ∩.【详解】由2(2)(3)0x x −−=,可得2x =或x =,又Q x ∈,所以2x =,所以{2}A =;由302x x +≤−,可得(3)(2)020x x x +−≤ −≠,解得32x −≤<,所以{|32}Bx x =−≤<, 所以{2}{|32}A B x x =−≤<=∅ . 故选:D.2. 幂函数()23f x x =的图象大致为( )A. B.C. D.【答案】B 【解析】【分析】根据题意,利用函数奇偶性的判定方法,得到函数()f x 为偶函数,再由幂函数的性质,结合选项,即可求解.【详解】由函数()23f x x ==,可得函数的定义域为R ,关于原点对称,且()()f x f x −===,所以函数()f x 为偶函数,所以函数()f x 的图象关于y 轴对称,又由幂函数的性质得,当0x ≥时,函数()f x 单调递增, 结合选项,选项B 符合题意. 故选:B.3. 把物体放在冷空气中冷却,如果物体原来的温度是1C θ ,空气的温度是0C θ,那么min t 后物体的温度θ(单位:C )可由公式)01010ktθθθθ−=+−⋅求得,其中k 是一个随物体与空气的接触情况而定的正常数.现有65C 的物体,放到15C 的空气中冷却,1min 后物体的温度是35C ,已知lg20.3≈,则k 的值大约为( ) A. 0.2 B. 0.3 C. 0.4 D. 0.5【答案】C 【解析】【分析】根据题意列出等式()3515651510k−=+−⋅,化简后即可求解.【详解】由题意知015C θ= ,165C θ=, 代入公式()01010ktθθθθ−=+−⋅,可得()3515651510k−=+−⋅,则2105k−=,两边同时取对数得2lg10lg 5k−=, 即lg2lg 50.30.70.4k −=−≈−=−,则0.4k =,故C 正确. 是故选:C.4. 如图所示,一个组合体的上面部分是一个高为0.5m 长方体,下面部分是一个正四棱锥,公共面是边长为1m 的正方形,已知该组合体的体积为32m 3,则其表面积为( )A. (22m +B. (23m +C. (22m +D. (23m +【答案】B 【解析】【分析】由题意先利用棱锥体积公式求出正四棱锥的高,然后再求出其斜面上的高,即可求解. 【详解】由题意知该组合体由长方体和正四棱锥组成,且该组合体的体积为32m 3, 长方体的体积为31110.5m 2××=,则正四棱锥体积为3211m 326−=, 所以正四棱锥的高为1316m 112×=×,2112×, 所以组合体的表面积为()(210.541143m ××+×=+,故B 正确.故选:B.5. 若12,x x 是一元二次方程()()220x m x m m −++=∈R 的两个正实数根,则1221x x x x +的最小值为( ) A. 2 B. 4C. 6D. 8【答案】C 【解析】【分析】由题意及韦达定理可得122x x m +=+,12x x m =,从而得()2221212211222m mx x x x x x x x m+−++==,再结合基本不等式即可求解.【详解】由若12,x x 是一元二次方程()()220x m x m m −++=∈R 的两个正实数根, 所以122x x m +=+,12x x m =,则mm >0所以()()222212121212211212222x x x x m mx x x x x x x x x x m+−+−++===2244226m m m m m ++==++≥+=,当且仅当2m =时取等号,故C 正确. 故选:C.6. 已知等差数列{}n a 和等比数列{}n b 的前n 项和分别为n S 和n T ,且21nn S n T =+,则35=a b ( ) A. 9 B. 10 C. 11 D. 12【答案】C 【解析】【分析】分别设出为n S 和n T 的二次形式,由此求得35,a b ,即可化简后得到结果. 【详解】由等差数列{aa nn }和等比数列{bb nn }的前n 项和分别为n S 和n T ,所以可设()21n S kn n =+,n T kn =,0k ≠, 所以可得33255421101154a S S k k b T T k k−−===−−,故C 正确. 故选:C.7. 若2x =是函数()222exax x f x +−=的极小值点,则实数a 的取值范围是( ) A. (),1∞−− B. (),1−∞C. ()1,−+∞D. ()1,+∞【答案】A 【解析】【分析】求导,利用导数,分0a =,0a >,0a <三种情况讨论可求实数a 的取值范围.【详解】由()222exax x f x +−=,可得()222(22)e (22)e (22)4(2)(2)(e e e)x x x x xax ax x ax a x ax x f x +−+−−+−+−−−′===, 若0a =,当2x <时,()0f x ′>,当2x >时,()0f x ′<,故2x =是()222exax x f x +−=的极大值点,不符合题意,若0a ≠时,令()0f x ′=,可得(2)(2)0ax x −−−=,可得2x =或2x a=−, 若0a >时,则20a−<,当22x a −<<时,()0f x ′>,当2x >时,()0f x ′<,故2x =是()222exax x f x +−=的极大值点,不符合题意, 若0a <时,则20a−>,由二次函数的(2)(2)y ax x =−−−图象可知, 要使2x =是函数()222exax x f x +−=的极小值点, 需22a−<,解得1a <−, 所以实数a 的取值范围是(,1)∞−−. 故选:A.8. 已知函数()()6sin cos 10f x x x ωωω=+−>在π0,3上有且仅有3个零点,则ω的取值范围是( ) A. 3,32B. 3,32C. 93,2D. 93,2【答案】D 【解析】【分析】化简得23()sin 24f x x ω=−,由题意可得2π2π3π3ω<≤,求解即可. 详解】()()()66224224sin cos 1sin cos sin sin ?cos cos 1f x x x x x x x x x ωωωωωωωω=+−=+−+−()242242222sin sin ?cos cos 1sin cos 3sin ?cos 1x x x x x x x x ωωωωωωωω−+−=+−−22222313sin cos 13sin cos sin 24x x x x x ωωωωω=−−=−=− ,因为π0,3x ∈,2π20,3x ωω ∈ , 【由函数()()66sin cos 10f x x x ωωω=+−>在π0,3上有且仅有3个零点,可得2π2π3π3ω<≤,解得932ω<≤,所以ω的取值范围是9(3,]2.故选:D.二、多选题:本题共3小题,每小题6分,共18分.在每个小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分. 9. 已知n S 为数列{}n a 的前n 项和,若3n n S a n =+,则( ) A. 112a =B. 数列{}1n a −为等比数列C. 312nn a =−D. 3332nn S n =−⋅+【答案】BCD 【解析】【分析】当1n =时,1131S a =+,解得112a =−;根据3n n S a n =+,可得当2n ≥时,1131n n S a n −−=+−,从而得13122n n a a −=−,即()13112n n a a −−=−;根据B 可求得312nn a−=−;从而可求出333?2nn S n =−+.【详解】A :当1n =时,1131S a =+,解得112a =−,故A 错误; B :因为3n n S a n =+,当2n ≥时,1131n n S a n −−=+−, 将两式相减可得1331n n n a a a −=−+,即13122n n a a −=−, 则()13112n n a a −−=−,因112a =−,则1312a −=−,数列{}1n a −为首项为32−,公比为32的等比数列,故B 正确;C :由B 可得13331?222n n n a −−=−=−,所以312nn a =− ,故C 正确;D :3333?2nn n S a n n =+=−+,故D 正确.故选:BCD.10. 已知幂函数()()293m f x m x =−的图象过点1,n m−,则( )A. 23m =−B. ()f x 为偶函数C. n =D. 不等式()()13f a f a +>−的解集为(),1−∞ 【答案】ABC 【解析】【分析】利用幂函数的定义结合过点1,n m−,可求,m n 判断AC ;进而可得函数的奇偶性判断B ;解不等式可求解集判断D.【详解】因为函数()()293m f x mx =−为幂函数,所以2931m −=,解得23m =±,当23m =时,幂函数()23f x x =的图象不可能过点3,2n − ,故23m ≠,当23m =−,幂函数()23f x x −=的图象过点2,3n,则2332n =,解得32()32n ==,故AC 正确; ()23f x x −=的定义域为{|0}x x ≠,且()2233()()f x x xf x −−−=−==,故()f x 为偶函数,故B 正确;函数()23f x x−=在(0,)+∞上单调递减,由()()13f a f a +>−,可得()()|1||3|f a f a +>−,所以1310a a a +<− +≠,解得1a <且1a ≠−,故D 错误.故选:ABC.11. 已知函数()f x 及其导函数()f x ′的定义域均为R ,记()()g x f x ′=,若()2g x +的图象关于直线2x =−对称,且()()()111f x f x f x −++=+−,则( )A. ()g x 是偶函数B. ()f x 是奇函数C. 3为()y f x =的一个周期D.20251()0i g i ==∑【答案】ACD 【解析】【分析】由()2g x +的图象关于直线2x =−对称,则可得()g x 关于xx =0对称,可对A 判断;由gg (xx )=ff ′(xx ),从而可得ff (xx )关于()0,1对称,可对B 判断;由ff (xx )关于()0,1对称,可得()()()113f x f x f x −+++=,故()()()213f x f x f x −+−+=,从而得()()12f x f x +=−,即()()3f x f x +=,可对C 判断;由()()()113f x f x f x −+++=,两边求导得()()()110g x g x g x −+++=,可对D 判断.【详解】A :因为()2g x +的图象关于直线2x =−对称,故将()2g x +的图象向右平移2个单位后变为()g x 的图象,此时()g x 关于xx =0对称,所以()g x 是偶函数,故A 正确;B :因为()g x 是偶函数,所以ff (xx )关于()0,c 对称且c 为常数,当xx =0时,()()()1110f f f −+=+,又因为()()112f f c −+=,()0f c =,所以1c =,所以ff (xx )关于()0,1对称,故B 错误; C :因为ff (xx )关于()0,1对称,所以()()2f x f x −=−+,所以()()()()1113f x f x f x f x −++=+−=−,所以()()()113f x f x f x −+++=①,故()()()213f x f x f x −+−+=②,则①②两式相减得()()12f x f x +=−,即()()3f x f x +=,所以3是()y f x =的一个周期,故C 正确; D :因为()()()113f x f x f x −+++=,两边求导得()()()110g x g x g x −+++=,且()g x 的周期为3,又因为20256753=×,所以()202510i g i ==∑,故D 正确.故选:ACD.【点睛】关键点点睛:B 中因为()g x 是偶函数,所以可得ff (xx )关于()0,c 对称,从而可求出1c =;D 中可有()()()113f x f x f x −+++=,两边求导得()()()110g x g x g x −+++=,从而可知()g x 中连续3项之和为零.三、填空题:本题共3小题,每小题5分,共15分.12. 已知函数()ln f x x x =,则曲线()y f x =在1x =处的切线方程是 _____.【答案】10x y −−=【解析】【分析】求出导函数,根据导数的几何意义得出斜率,求出切点坐标,代入点斜式方程,即可得出答案.【详解】因为()ln 1f x x ′=+,所以()11f ′=. 根据导数的几何意义可知,曲线()y f x =在1x =处的切线的斜率()11k f ′==. 又()10f =,所以,切线方程为1y x =−,即10x y −−=. 故答案为:10x y −−=. 13. 已知0a >且1a ≠,函数()2,1,1x x x f x a x ≥= <,若关于x 的方程()()2560f x f x −+=恰有3个不相等的实数解,则实数a 的取值范围是______. 【答案】(]2,3 【解析】【分析】当1x ≥时,()2xf x =,方程()()2560fx f x −+=有2个不相等实数解,则当1x <时,()x f x a =,此时方程()()2560f x f x −+=只有1个实数解,对a 分类讨论,由()x f x a =的值域求实数a 的取值范围. 【详解】方程()()2560fx f x −+=,即()2f x =或()3f x =, 当1x ≥时,()2xf x =,由()2f x =解得1x =,由()3f x =解得2log 3x =; 当1x <时,()xf x a =,此时方程()()2560fx f x −+=只有1个实数解, 若01a <<,则()xf x a =在(),1∞−上单调递减,()(),f x a ∞∈+,的此时()2f x =和()3f x =都有解,不合题意,若1a >,则()xf x a =在(),1∞−上单调递增,()()0,f x a ∈,则23a <≤.所以实数a 的取值范围是(]2,3. 故答案为:(]2,314. 已知三棱锥A BCD −的四个顶点都在球O 的球面上,若AB CD =O 的半径为,则三棱锥A BCD −体积的最大值为__________.【答案】 【解析】【分析】设,AB CD 的中点为,M N ,球心为O ,由题意可得,,O M N 在同一直线上时,ABN 的面积最大,CD ⊥平面ABN ,三棱锥A BCD −体积的最大值,求解即可. 【详解】设,AB CD 的中点为,M N ,球心为O ,由题意可得,OM AB ON CD ⊥⊥,由题意可得1,2OM ON ==,当,,O M N 在同一直线上时,ABN 的面积最大,最大面积为1(12)2×+, 设C 到平面ABN 的距离为d ,由题意可得D 到平面ABN 的距离也为d ,当CD ⊥平面ABN 时,d 取最大值12CD =所以三棱锥A BCD −体积的最大值为112233ABN S d ××=×=故答案为:四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15. 已知函数()2π2sin 4f x x x=+.(1)求()f x 在π0,2上的单调递增区间;(2)已知ABC 的内角,,A B C 的对边长分别是,,a b c,若π1212C f−,2c =,求ABC 面积的最大值. 【答案】(1)5π[0,]12(2)2 【解析】【分析】(1)化简π()12sin(2)3f x x =+−,利用πππ2π22π,Z 232k x k k −+≤−≤+∈,可求单调区间;(2)由余弦定理可得22242cos 2c a b ab C ab ==+−≥,可求ab 的最大值,进而可求ABC 面积的最大值. 【小问1详解】()2π1cos 2π22sin 21sin 242x f x x x x x x−+=+=×−=+−πππ12(sin 2cos cos2sin 12sin(2)333x x x =+−=+−, 由πππ2π22π,Z 232k x k k −+≤−≤+∈,得π5πππ,Z 1212k x k k −+≤≤+∈, 又π0,2∈ x ,所以函数()f x 在π0,2上的单调递增区间为5π[0,]12;【小问2详解】由π1212C f−=−,得ππ12sin[2()]12123C +×−−,所以πsin()2C −,所以cos C =,因为0πC <<,所以π6C =,又2c =,在ABC中,由余弦定理可得22242cos 2c a b ab C ab ==+−≥−,所以4(2ab ≤=,当且仅当a b ==时取等号,所以111sin 4(22222ABC S ab C =≤×+×=+所以ABC 面积的最大值为2. 16. 已知函数()()ln R mf x x m x=+∈. (1)讨论函数()f x 的单调性;(2)当1m =时,证明:当1x ≥时,()e e 0xxf x x −−+≤.【答案】(1)答案见解析 (2)证明见解析 【解析】【分析】(1)利用导数与函数单调性的关系,分类讨论即可得解;(2)构造函数()()e e xg x xf x x =−−+,利用二次导数,结合函数的最值情况,证得()0g x ≤,从而得证.【小问1详解】因为()ln mf x x x=+的定义域为()0,∞+, 所以()221m x mf x x x x −′=−=,当0m ≤时,()0f x ′>恒成立,所以()f x 在()0,∞+上单调递增; 当0m >时,令()0f x ′=,得x m =, 当()0,x m ∈时,()()0,f x f x ′<单调递减, 当(),x m ∈+∞时,()()0,f x f x ′>单调递增, 综上,当0m ≤时,()f x 在()0,∞+上单调递增;当0m >时,()f x 在()0,m 上单调递减,在(),m +∞上单调递增. 【小问2详解】当1m =时,()1ln f x x x=+, 令()()e e ln e e 1xxg x xf x x x x x =−−+=−−++,则()ln e xg x x =−′, 令()()ln e xh x g x x ′==−,则()1e xh x x=′−,因为1x ≥,所以11,e e 1x x≤≥>, 所以当1x ≥时,()h x ′1e 0xx=−<恒成立,所以()h x 在[)1,+∞上单调递减,即()ln e x g x x =−′在[)1,+∞上单调递减,所以()()1e 0g x g ′≤−′=<, 所以()g x 在[)1,+∞上单调递减,所以()()10g x g ≤=,即()e e 0xxf x x −−+≤. 【点睛】结论点睛:恒成立问题:(1)()0f x >恒成立()min 0f x ⇔>;()0f x <恒成立()max 0f x ⇔<. (2)()f x a >恒成立()min f x a ⇔>;()f x a <恒成立()max f x a ⇔<.(3)()()f x g x >恒成立()()min 0f x g x ⇔−> ;()()f x g x <恒成立()()max 0f x g x ⇔−< ; (4)1x M ∀∈,2x N ∀∈,()()()()1212min max f x g x f x g x >⇔>.17. 已知函数()33x x af x a+=−.(1)若()f x 为奇函数,求a 的值;(2)当0a <时,函数()f x 在[],m n 上的值域为11,33m n −− ,求a 的取值范围.【答案】(1)1或1−(2)(,3−∞−− 【解析】【分析】(1)由ff (xx )为奇函数,可得()()0f x f x +−=,从而可求解; (2)当0a <时,可得()y f x =是单调增函数,从而可得即,m n 是函数3133x x x a a +=−−的两个解,参数分离可得23313x x xa +=−,利用换元法设13xt =−,可得23a t t =+−,且1t <,再结合对勾函数性质从而可求解.【小问1详解】由()32133x xx a af x a a+==+−−,所以()22?31131?3x x x a a f x a a −−=+=+−−, 因为ff (xx )为定义域上的奇函数,所以()()0f x f x +−=, 即22?311031?3xx xa a a a +++=−−,化简得·3131?3x xx a a a a +=−−−, 则22222·3?3?33?3?30x x x x x x a a a a a a a −+−+−−+=,则得21a =, 所以aa =−1或1a =. 【小问2详解】当0a <时,()32133x x xa af x a a+==+−−,所以()y f x =是单调增函数, 由函数()f x 在[],m n 上的值域为11,33m n −−, 所以()3133m m m a f m a +==−−,()3133n n n a f n a +==−−,即,m n 是函数3133x x x a a +=−−的两个解,则得23313x x xa +=−,设130xt =−<,则22332313x xxa t t +==+−−,0t <,根据对勾函数性质可得23y t t=+−在()上单调递减,(,−∞上单调递增,其中23y t t=+−在(),0−∞上的值域为(,3 −∞− ,当t =时取最大值,综上可得3a <−,所以a 的取值范围为(),3−∞−−. 18. 已知函数()()28ln 1exf x axbx =+++.(1)若()f x ′在R 上单调递减,求a 的最大值; (2)证明:曲线()y f x ′=是中心对称图形; (3)若()8ln2f x ,求a 的取值范围. 【答案】(1)1− (2)证明见解析 (3)(],1−∞−【解析】【分析】(1)对ff (xx )求导得()8e 21e x x f x ax b =+++′,令()8e 21exxg x ax b =+++,再结合基本不等式从而可得()8201e 2ex x g x a =++′≤+,即可求解. (2)由()()28f x f x b ′′−+=+,从而曲线yy =ff ′(xx )关于点()0,4b +对称,即可求解. (3)分情况讨论求出0a <,4b =−,然后再利用导数讨论1a ≤−,10a −<<情况下,从而可求出a 的取值范围是(],1−∞−. 【小问1详解】由函数()()28ln 1e xf x ax bx =+++,所以()8e 21exxf x ax b =+++′, 令()8e 21e xxg x ax b =+++,因若ff ′(xx )在RR 上单调递减,则()()28e 822011e e 2exxxx g x a a =+=+++′≤+恒成立,因为1e 224e x x ++≥=,当且仅当xx =0时取等号, 则821e 2e x x −≥−++,所以821e 2ex x a ≤−++,即22a ≤−,得1a ≤−. 故a 的最大值为1−. 【小问2详解】证明:由(1)知()8e 21e x x f x ax b =+++′,则()8e 21exxf x ax b −−−=−++′, 则()()8e 8e 8e 8222281e 1e 1e 1ex x x x x x xf x f x ax b ax b b b −−−+=−++++=++=+′+′+++, 所以曲线yy =ff ′(xx )关于点()0,4b +对称,是中心对称图形.【小问3详解】当aa >0时,则当x →+∞时,()f x →+∞,与()8ln2f x ≤矛盾,所以0a ≤;为当0a =,0b ≥时,则当x →+∞时,()f x →+∞,与()8ln2f x ≤矛盾; 当0a =,0b <时,则当x →−∞时,()f x →+∞,与()8ln2f x ≤矛盾; 所以0a <.当4b >−,则当402b x a +<<−时,()8e 24201exxf x ax b ax b =++>++>+′, 此时()()08ln 2f x f >=,矛盾; 当4b <−,则当402b x a +−<<时,()8e 24201ex x f x ax b ax b =++<++<+′, 此时()()08ln 2f x f >=,矛盾; 因此4b =−,所以()8e 241exxf x ax =+−+′, 当1a ≤−,由(1)可知ff ′(xx )在RR 上单调递减,又()00f ′=,所以当0x ≤时,()0f x ′≥,ff (xx )在区间(],0−∞上单调递增; 当xx >0时,()0f x ′<,ff (xx )在区间(0,+∞)上单调递减; 此时()()08ln 2f x f ≤=,符合题意; 当10a −<<,则当0ln 1x <<−时,()()()228e 82201e 1e xxxg x a a =+>+′>++,此时()()()00f x g x g >′==,则()()08ln 2f x f >=,不合题意. 综上所述:a 的取值范围是(],1−∞−.【点睛】方法点睛:(1)导函数中常用的两种常用的转化方法:一是利用导数研究含参函数的单调性,常化为不等式恒成立问题.注意分类讨论与数形结合思想的应用;二是函数的零点、不等式证明常转化为函数的单调性、极(最)值问题处理;(2)利用导数解决含参函数的单调性问题时,一般将其转化为不等式恒成立问题,解题过程中要注意分类讨论和数形结合思想的应用;(3)证明不等式,构造一个适当的函数,利用它的单调性进行解题,是一种常用技巧.许多问题,如果运用这种思想去解决,往往能获得简洁明快的思路,有着非凡的功效.19. 若存在1,1,2,2,,,n n 的一个排列n A ,满足每两个相同的正整数()1,2,,k k n = 之间恰有k 个正整数,则称数列n A 为“有趣数列”,称这样的n 为“有趣数”.例如,数列7:4,6,1,7,1,4,3,5,6,2,3,7,2,5A 为“有趣数列”,7为“有趣数”.(1)判断下列数列是否为“有趣数列”,不需要说明理由; ①2:1,2,1,2A ;②3:3,1,2,1,3,2A . (2)请写出“有趣数列”4A 的所有可能情形;(3)从1,2,,4n 中任取两个数i 和()j i j <,记i 和j 均为“有趣数”的概率为n P ,证明:14n P <. 【答案】(1)①不是;②是(2)4,1,3,1,2,4,3,2或2,3,4,2,1,3,1,4 (3)证明见解析 【解析】【分析】(1)根据“有趣数列”定义逐项判断即可求解.(2)分当两个1中间为2,当两个1中间为3,当两个1中间为4,共3种情况从而可找到符合题意的“有趣数列”,即可求解.(3)先设“有趣数列”n A 中数字()1,2,3,k k n = 第一次出现的项记作k a 项,从而可得()21111n n n k k k k k k a a a k k === +++=∑∑∑,可求得()1314nk k n n a =−=∑,再分情况讨论当()*43,42n m m m =−−∈N ,()*41n m m =−∈N ,()*4nm m ∈N 时符合“有趣数列”的情况,从而可得224C 1C 4nn nP =<,即可求解.【小问1详解】①2:1,2,1,2A 中两个2之间间隔数只有一个,故不是“有趣数列”, ②3:3,1,2,1,3,2A 中两个1之间间隔数有1个,两个2之间间隔数有2个, 两个3之间间隔数有3个,故是“有趣数列”.小问2详解】当两个1中间为2,不妨设1,2,1右边两个2中间可能为1,3或1,4, 则4A 可能为4,3,1,2,1,3,2,4或4,3,1,2,1,4,2,3,不符合题意; 当两个1中间为3,两个2中间可能为3,4或4,3,则4A 可能为4,1,3,1,2,4,3,2或2,3,4,2,1,3,1,4,符合题意;【当两个1中间为4,不妨设1,4,1右边两个2中间可能为3,4或4,3, 则4A 可能为1,4,1,2,3,4,2,3或1,4,1,2,4,3,2,3,不符合题意; 综上所述:“有趣数列”4A 可能为4,1,3,1,2,4,3,2或2,3,4,2,1,3,1,4. 【小问3详解】将“有趣数列”n A 中数字()1,2,3,k k n = 第一次出现的项记作k a 项, 由题意可知数字k 第二次出现的项为()1k a k ++项, 于是()21111n nn k kk k k k a aa k k === +++=∑∑∑,则()()13221222nk k n n n n a =+++=∑,即()1314nk k n n a =−=∑,又因为1nk k a =∑为整数,故必有()314n n −为整数,当()*43,42n m m m =−−∈N时,()314n n −不可能为整数,不符合题意; 当()*41n m m =−∈N时,()314n n −为整数,构造“有趣数列”41m A −为44,,2,42,23,1,41,1,23,m m m m m m −−−−− 2,,44,21,43,,21,42,m m m m m −−−+−22,,2,21,41,2,,22,21,,43m m m m m m −−−−+− ,符合题意; 当()*4nm m ∈N 时,()314n n −为整数,构造“有趣数列”4m A 为44,,2,42,23,1,41,1,23,m m m m m m −−−−− 2,,44,4,43,,21,42,m m m m m m −−+−22,,2,21,41,2,,22,21,,43,21,4m m m m m m m m −−−−+−− ,符合题意;这里44,,2m m − 是指将44m −一直到2m 的偶数按从大到小的顺序进行排列,23,,1m − 是指将23m −一直到1的奇数按从大到小的顺序进行排列,故1,2,,4n 中的“有趣数列”为3,4,7,8,,41,4n n − 共2n 个,则所求概率为()224C 211C 2414nn nn P n −==<−. 【点睛】方法点睛:本题主要是根据“有趣数列”定义,理解并应用,对于(3)中主要巧妙设出“有趣数列”n A 中数字()1,2,3,k k n = 第一次出现的项记作k a 项,由题意可知数字k 第二次出现的项为()1k a k ++项,从而求出()1314nk k n n a =−=∑,从而可求解.。
山东名校考试联盟2024年10月高三年级阶段性检测语文试题及参考答案

山东名校考试联盟2024年10月高三年级阶段性检测语文试题一、现代文阅读(35分)(一)现代文阅读I(本题共5小题,19分) 阅读下面的文字,完成1~5题。
材料一:《红楼梦》中有一个聚讼纷纭的案例,学界产生了多篇专论之文,但仍有可深入探讨之处。
在第四十回中,贾母带领众人去蘅芜苑,从荇叶渚上船。
宝玉道:“这些破荷叶可恨,怎么还不叫人来拔去。
”宝钗笑道:“今年这几日,何曾饶了这园子闲了,天天逛,那里还有叫人来收拾的工夫。
”林黛玉道:“我最不喜欢李义山的诗,只喜他这一句:‘留得残荷听雨声’。
偏你们不留着残荷了。
”宝玉道:“果然好句,以后咱们就别叫人拔去了。
”首先,探讨一下林黛玉引用时的改字问题。
其实,这是一种“随文立训”式的改动。
据文本内容来推,本回故事当发生在八月二十五日。
因为巧姐发热,彩明念《玉匣记》云“八月二十五日,病者在东南方得遇花神”,此时之荷尚未枯,用“残”字更贴切。
关于此,《红楼梦》中恰有可以援证之文,第六十七回袭人“刚来到沁芳桥畔,那时正是夏末秋初,池中莲藕新残相间,红绿离披”,这个夏末秋初大概是何时,书中并未明言,但亦可推知,第六十六回中柳湘莲对贾琏说“不过月中就进京的”,后又说“八月内湘莲方进了京”,然后是尤三姐自刎、柳湘莲出家等,则应该是八月下旬。
黛玉为了加强说服力,把形容此时秋景本不特别贴切的诗句改了一个字,这一改动在她引用之后的语言中也有非常清楚的显示。
事实上,这种引用时的随文改动正是古人常有之例。
因此,虽然可以确定李商隐的原文与曹雪芹的引文有一字之不同,但这却绝非一个校勘学上的“他校”问题。
接下来,我们从情节前后的脉络出发,来讨论黛玉引此诗的背后逻辑。
理解这一段对话的关键就藏在上引的原文之中,或者说,存在于作者对宝、黛、钗三人关系的设定之中。
在这三人的关系中,黛玉一直是最为警惕的那一个,面对来自宝钗的威胁,她总是下意识地防范,甚至会主动出击。
仔细看一下原文。
先是宝玉说“这些破荷叶可恨,怎么还不叫人来拔去”,这时,如果宝钗未接话,黛玉或许也可能赞同宝玉的意见,然而心思细密又喜欢给人讲道理的宝姐姐这时肯定会有所表现,所以她立刻就接着说:“今年这几日,何曾饶了这园子闲了,天天逛,那里还有叫人来收拾的工夫。
山东省济南市2021年4月高三阶段性检测语文试题含答案

山东省济南市2021年4月高三阶段性检测语文试题注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、现代文阅读(35分)(一)现代文阅读(本题共5小题,19分)阅读下面的文字,完成1~5题。
材料一时隔8年,那个写《活着》的余华又活了!他的长篇新作《文城》将由新经典·北京十月文艺出版社出版。
《文城》继续在人生、命运、时代等余华曾深刻挖掘的主题上求索,书写一个人在命运浪涛里的寻找,以及一群人在时代洪流中的选择。
在溪镇人最初的印象里,林祥福是一个身上披戴雪花,头发和胡子遮住脸庞的男人,有着垂柳似的谦卑和田地般的沉默寡言。
哪怕后来成了万亩荡和木器社的主人,他身上的谦卑和沉默依旧没有变。
他的过去和一座谜一样的城联系在了一起,没人知道他为什么要找一个不存在的地方。
他原本不属于这里,他的家乡在遥远的北方。
为了一个承诺他将自己连根拔起,漂泊至此。
往后的日子,他见识过温暖赤诚的心,也见识过冰冷无情的血。
最终他徒劳无获,但许多人的牵挂和眼泪都留在了他身上。
自1990年代《活着》出版以来,从张艺谋改编同名电影,将福贵的经历搬上荧幕,到易烊千玺手写读后感,“随着福贵走在洒满盐的路上”,一代代读者,不分老幼,不分城乡,一遍遍读他的作品,从小说中看到现实,在感动中获得力量。
《活着》让每个读过福贵故事的人都相信,生活是属于每个人自己的感受,不属于任何别人的看法。
透过《文城》,读者也将在那个熟悉的余华身上,窥见他令人耳目一新的一面。
余华曾这样谈写作:“一个梦,让一个记忆回来了,然后一切都变了。
”也许正是因此,他的许多小说都在书写记忆,不管是个人的,还是集体的。
在《文城》中,余华继续追寻一段被历史记忆封存的时光,同时,他也突破以往的创作,把故事背景上溯至《活着》之前那个更残酷的清末时代。
山东名校考试联盟2024届高三上学期12月阶段性检测试题 地理含答案

试卷类型A山东名校考试联盟2023年12月高三年级阶段性检测地理试题(答案在最后)本试卷总分100分,考试时间90分钟。
注意事项:1.答卷前,考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
回答非选择题时,将答案写在答题卡上。
写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、选择题:本题共15小题,每小题3分,共45分。
每小题只有一个选项符合题目要求。
位于贵阳市的某县域企业成立时是传统的磷化工企业。
随着新能源汽车产业的发展,该企业主动寻求转型,着力布局磷酸铁锂正极材料(电池材料)的研发。
目前,企业已获得专利66项,经济效益明显。
2021年,该企业获国家“专精特新‘小巨人’企业”称号。
据此完成1~2题。
1.该企业研发的专利多属于①设备研发领域;②销售模式标准;③品牌创意设计;④生产工艺优化A.①②B.①④C.②③D.③④2.自建厂以来,企业加工厂的位置一直保持不变,主要是因为该地区A.市场需求广阔B.政策支持力度大C.原料量大质优D.劳动力丰富廉价祁连山黑河发源地区(图1)冻融作用发育普遍而强烈。
随着气候变暖,该地区因冻土层融化导致地表土体的滑塌现象(热融滑塌)多发,这对地区生态环境造成了较大的影响。
据此完成3~5题。
3.下列四地易发热融滑塌的是A.甲B.乙C.丙D.丁4.黑河源地的热融滑塌多发在阴坡区域,主要是由于阴坡区域A.降水频率大B.土体湿度大C.土体厚度大D.温差变化小5.随着气候变暖,热融滑塌的面积增大会造成黑河源地A.河流补给类型增多B.高寒草甸面积扩大C.生物多样性增加D.土壤碳排放量增大历次人口骨查结果可以反映人口迁移状况,人口迁移给区域发展带来较大影响,下图为东北三省四次人口普查的人口迁移状况表,据此完成6~7题。
6.关于东北三省人口迁移特点下列说法正确的是A.“五普”相较“四普”,东北地区开始呈现净迁出趋势B.“七普”相较“六普”,黑龙江省人口迁移变率最大C.“四普”至“六普”,吉林省人口净迁出总量最少D.“四普”至“七普”,东北地区净迁出趋势持续加速7.人口迁移状况给东北地区发展带来的影响是①阻碍劳动密集型制造业的发展;②限制生产性服务业的发展;③阻碍制造业的转型;④缓解人口老龄化问题。
成都17届高三理科语文三诊模拟考试试卷

成都七中2016—2017学年下期高2017届“三诊”模拟语文试卷本试卷分第I卷(阅读题)和第Ⅱ卷(表达题)两部分,共150分。
考试时间150分钟。
两卷答案均应写在答题卡上。
第I卷阅读题(70分)一、现代文阅读(35分)(一)阅读下面的文字,完成1~3题。
(9分,每小题3分)网络用语拉低了社会格调吗?《别让粗鄙网语拉低文化品位》一文提出,当前网络热词“不乏‘尼玛’‘撕逼’之类格调低下、有伤风化的粗鄙化网语”“低俗、粗鄙的网语大行其道,对汉语的纯净和美感造成伤害的同时也拉低了社会的文化品位”。
因此,必须“捍卫汉语言文化的圣洁,对网语要甄别与规范”。
这种“原则性”的指导隔段时间就有人重提,这次是把严重性上升为维护“汉语言文化的圣洁”。
去年一篇文章《媒体用语要有“三条线”》则把这个问题提高到了捍卫“五千年灿烂文明的文化”的高度。
然而,这种高屋建瓴的批判似乎注定解决不了问题,因为它没有弄清楚造成这种“污染”的到底是新词还是运用新词的人。
如果造成污染的是新词,在网上对之进行审查、过滤和删除,便能起到禁止的效果。
如果造成污染的是运用新词的人,那么事情另当别论了。
问题的关键是如何以理服人,让他们打心底自觉避免使用。
语言是出于表意和传情的需要,并为之服务的工具。
需要是发明之母,强行禁止一些新词,就会有别的新词创造出来。
主张对语言进行审查和管控的人们对语言的基本特点缺乏认识,那就是语言来自于人,除了表意和传情,日常用语还是一种社会行为。
使用没格调热词的人并不是不知道没格调,而是根本就不在乎那个,或是有意要反抗。
这就像“文革”时,许多人开口就用“大老粗”的语言,这是一种对资产阶级及其文化的“造反”行为。
社会上的“哥们语言”也是一样,那些油里油气、流氓气十足的语言会让“文明人”听着觉得不顺耳,甚至反感。
但又如何?这些语言可以看作是社会边缘人、受漠视者用来当作一种逆反行为,你能用“汉语言文化的圣洁”或“五千灿烂文化”去教化他?人类学家马林诺斯基最早从社会行为角度来看待语言运用。
阶段性检测分析

阶段性检测质量分析一、存在问题1. 听力完成情况不理想。
集中反映出学生不会做听力,不能很好地掌握答题技巧。
如听力部分最后一题都是“听课文,填入所缺单词”,出错率较高,有些学生是听一个写一个,结果发现根本赶不上录音的节奏,导致有些单词瞎写。
还有就是不能很好地联系上下文去分析所填单词的时态或形式,只是结合快速的录音凭自己的感觉随便写个答案,最后导致出错。
2. 词汇教学不到位。
例如笔试部分的第六题(用所给词的适当形式填空)失分比较严重。
教者在日常教学过程中要让学生在具体的语境中去理解词义,如果仅是孤立地集中讲解词义,效果肯定好不了。
还有就是要不断重复,次数出现多了学生自然而然地就掌握了。
3. 基础知识掌握不扎实。
六年级试卷笔试部分的第七题(句子配对)都属于基础题,对于那些在及格边缘徘徊的学生,成绩要想有所突破就应该从这些最基本的题目入手,如果在这些题目上再不能保证得分的话,其它更是无从谈起。
4. 学生的阅读理解能力不强。
学生做完阅读理解题后,对自己的答案毫无把握,感觉像是在赌博一样,运气好就多拿点分,运气不好就少点,关键还是不得法。
二、改进措施本次期中测试留给我们思考的问题很多,现对如何进一步加强小学英语教学,提高小学英语教学质量提出以下几点建议:1. 加强答题技巧的指导和训练。
在教学中,一方面要规范答题要求,另一方面要加强思维方法的训练和答题技巧的训练,使学生在不断的实践中掌握正确的方法。
如听力题,每一份英语试卷听力部分都是安排在试卷的开头,因此听力部分完成情况的好坏与否将直接影响学生对整个试卷的发挥。
听力完成得比较理想,下面答题时就会信心倍增,轻松很多。
如果听力部分一团糟,下面心情自然好不了。
例如:在完成“听对话,把句子补充完整”这种题目时,就要指导学生播放第一遍时只要听,不要写,力争把每道题听个大概轮廓;第二遍时边听边写,但写时又要注意不是完整地写,速写、简写,总之只要自己能看懂就行,不要一味地追求完美,在某一个单词或词组上花费过多的时间,捡了芝麻,丢了西瓜,因小失大。
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高三英语阶段性周练检测试题(17)一.单项选择1. —Why do you look worried?—There are so many problems .A. remaining to settleB. remained settlingC. remaining to be settledD. remained to be settled2. ---_______ leave at the end of this month.--- I don’t think y ou should do that until ____ another job.A. I’m going to; you’d foundB. I’m going to; you’ve foundC. I’ll; you’ll findD. I’ll; you’d find3. I’ve won a holiday for two days to Florida. I _________ my mum.A. am takingB. have takenC. takeD. will have taken4. Though he is ill, he has not quit ___________.A. smokeB. to smokeC. smokedD. smoking5. __________ the man’s rude behavior cost him his job, he was still in high spirits.A. AsB. DespiteC. BecauseD. While6. We can make some adjustments __________ the reactions of the customers.A. in answer toB. in response toC. in reply toD. A,B and C7. After graduation, he _____ the challenge, which _____ all his spare time.A. took up; took upB. took on; took onC. took in; took overD. took on; took in8. All those __________ about the poor children should be __________.A. concerned; thankedB. are concerned; thankedC. who are concerned; thanked forD. are concerned; thanked for9. Chinese economy suffered a great loss from the May12 earthquake _________ the snow and ice storm in February, 2008. Which of the following is NOT true?A. as well asB. in additionC. besidesD. apart from10. She tried her best to __________ the life there, but failed to make any __________.A. adjust to; senseB. adapt to; troubleC. adapt to; effortD. adjust to; difference11. —The telephone is ringing.—I answer it.A. am going toB. am toC. willD. am about to12. While crossing the road, an old man was knocked down by a car and badly ________.A. woundedB. ruinedC. injuredD. harmed13. There is still a long way to go to solve all the problems ____ conservation of natural resources.A. concerningB. concernedC. concerning aboutD. concerned about14. Although my grandfather is in his eighties, he is still as ______ as a young man and hatessitting around doing nothing all day.A. enthusiasticB. automaticC. energeticD. innocent15.The crazy fans patiently for two hours, and they would wait till YaoMing, the basketballstar, arrived.A. were waitingB. had been waitingC. had waitedD. would wait16.What lessons China can draw from ______ global financial crisis has become _____ hot topicamong us students.A. a; theB. /; aC. the; aD. /; the17.——Have you finished the book?——No. I’ve read up to the children discover the secret cave.A. whichB. whatC. thatD. where18. ——The weather has been very hot and dry.—— Yes. If it had rained even a drop, things would be much better now. And my vegetables .A. wouldn’t dieB. didn’t dieC. hadn’t dieD. wouldn’t have died.19. _________along the quiet road at forty miles an hour, and then an old man suddenly started tocross the road in front of me.A. DrivingB. when I was drivingC. I was drivingD. Having driven20. In all kinds of competitions, Jackie ________ a most excellent athlete. He has won so manygold medals.A. practisesB. conductsC. behavesD. proves21. ——How did you like Nick’s performance last night?—— To be honest, his singing didn’t to me much?A. appealB. belongC. referD. occur22. The girl had hardly rung the bell the door was opened suddenly, and her friendrushed out to greet her.A. beforeB. untilC. asD. since23. Don’t worry ab out the child. Next to him _____ a lady, _____ he can turn when he is in trouble.A. sits; whomB. sits; to whomC. is sitting; with whomD. was sitting; to whom24. Vitamin D helps our bodies make a special chemical, and this special chemical, ________,affects our brains, making us feel happy.A. in turnB. in particularC. in advanceD. in short25. Helping others is a habit, you can learn even at an early age.A. itB. thatC. whatD. one26. Mr. Lee, who as a carpenter for over 10 years, is now a very famous statesman inthis country.A. has workedB. had workedC. workedD. works27. ——I can’t get on with some of my classmates. They just leave me in the cold.——. But what’s the reason?A. Sorry to hear that.B. How about that?C. Don’t mention it.D. Never give up.28. He doesn’t spend any more money on clothing than I do, but he manages to look so stylish.A. thereforeB. somehow C furthermore D. otherwise29. abroad for a tour can be a great honor for an ordinary person like me.A. TakenB. TakingC. Having been takenD. Being taken30. Three criminals were caught and asked to aid in the .A. interviewB. investigationC. questionD. request二.完型填空God’s coffeeA group of class friends, highly established in their careers, got together to visit their old university professor. Conversation soon 31 into complaints about stress in work and life.Offering his guests coffee, the professor went to the 32 and returned with a large pot of coffee and a couple of 33 ---porcelain, plastic, glass, crystal, some 34 looking, some expensive, some delicate --- telling them to 35 themselves to the coffee.When all the students had a cup of coffee in 36 , the professor said :“ If you noticed, all the nice looking expensive cups were taken up, 37 behind the plain and cheap ones. Whiles it is normal for you to 38 only the best for yourselves, that is the 39 of your problems and stress. Be assured that the cup itself 40 no quality to the coffee. In most cases it is just more expensive and in some cases even hides what we drink. 41 all of you really wanted was coffee, not the cup, but you 42 went for th e best cups… And then you began 43 each other’s cups. Now consider this: Life is the 44 ; the jobs, money and position in society are the cups. They are just tools to hold and contain life, and the type of cup we have does not 45 , nor change the quality of life we 46 . Sometimes, by concentrating only on the cup, we 47 to enjoy the coffee God has 48 us. God brews the coffee, not the cups… Enjoy the coffee!”The happiest people don’t have the best of everything. They just 49 the best of everything.Live simply. Love generously. Care deeply. Speak kindly. Leave the 50 to God.31. A. stopped B. looked C. grew D. turned32. A. living-room B. waiting-room C. bedroom D. kitchen33. A. cups B. pans C. bowls D. bottles34. A. plain B. clean C. ugly D. fine35. A. devote B. help C. dedicate D. enjoy36. A. stomach B. hand C. mind D. mouth37. A. falling B. leaving C. hiding D. keeping38. A. hope B. wish C. need D. want39. A. source B. resource C. energy D. reason40. A. adapts B. puts C. adds D. applies41. A. As B. What C. That D. Which42. A. consciously B. cheerfully C. deliberately D. bravely43. A. looking B. glaring C. eyeing D. glancing44. A. tea B. water C. wine D. coffee45. A. sign B. mean C. define D. signal46. A. spend B. live C. hate D. love47. A. fail B. succeed C. tend D. manage48. A. shown B. taken C. sent D. provided49. A. keep B. take C. make D. hold50. A. complex B. remains C. rest D. complaints 三.阅读理解AMIANYANG—At a corner of the city’s Jiuzhou Stadium, one of the biggest camps set up for those left homeless in the earthquake, 62-year-old Liu Yaorong was leaning against a window on Thursday.Pointing to a quilt and clothes he received from the local government, he said: “These are all I have. My home collapsed in the quake, and everything in the town was flooded.”He used to live in Xuanping town of Beichuan county which was destroyed by the quake. Adding to his misery, rivers blocked by landslides(山崩) led to flooding in the town.But Liu said he was lucky because he was healthy, otherwise he would not have the energy to walk 10 hours on damaged and dangerous mountainous roads to escape the flood on Monday. He said the trip used to take him about 90 minutes when the roads were in good condition.The journey was difficult and “rocks kept falling,” he said, showing injured legs and black, split toenails.Liu said his three sons were working in eastern cities as migrant workers.“I’ve been living alone in the mountains for more than 20 years. My wife died 30 years ago,” he said in a low voice.During his journey to Mianyang, Liu said he saw many elderly people who chose to stay.“Soldiers were persuading them to leave for fear of floods,” he said.Talking a bout his home before the quake struck, Liu’s mood lifted. “I raised pigs and chickens, and grew vegetables. I could have rice, meat and greens almost every day,” he said.“But now, I have only biscuits and instant noodles.”Liu said one of his sons returned home from Wenzhou, Zhejiang Province, after the quake, but left because the father refused to go with him.“I don’t want to leave home. And I know it is difficult for them out there. How could I add to their burden?” he asked, his eyes red.“I still want to go back to my home. Given a small piece of land, I could live by myself.”It is learnt that resettlement plans for displaced people have not been finalized.However, not every elderly person is as strong-willed as Liu.Psychologists said the elderly need as much comfort as children. Lu Jianguo, a psychologist from Chengdu Medical College, said “We will first let them cry and tell their stories, and then help them regain confidence.”51. Which of the following is TRUE according to the passage?A. Liu Yaorong spent 8.5 hours more than usual covering the roads in escaping the flood.B. The flood was followed by an earthquake in Xuanping in the same day.C. Liu Yaorong was in time to escape the quake without being hurt.D. Being healthy, Liu Yaorong was the only old man to escape the flood.52. The underlined word “ misery ”in the third paragraph most probably means “”.A. happinessB. fortuneC. puzzleD. suffering53. What’s Liu Yaorong’s attitude towards self-relief after the earthquake?A. Positive.B. Negative.C. Aggressive.D. Dependent.54. What would be the best title for the news report?A. Elderly react more quickly to flood disasterB. Elderly try hard to deal with quake disasterC. Elderly prefer to stay at their own homeD. Elderly are well cared for by governmentBIn all one’s lifetime it is oneself that one spends the most time being with or dealing with. But it is exactly oneself that one has the least understanding of.When you are going upwards in life you tend to overestimate yourself. It seems that everything you seek for is within your reach. When you are going downhill you tend to underestimate yourself, mistaking difficulties for your own incompetence.To get a thorough understanding of oneself is to gain a correct view of oneself-aware of both one’s strengths and shortages. You may look forward hopefully to the future but be sure not to expect too much, for ideals can never be fully realized. You may be courageous to meet challenges but it should be clear to you where to direct your efforts. That’s to say so long as you have a perfect knowledge of yourself there won’t be difficulties you can’t overcome.To get a thorough understanding of oneself needs self-appreciation. Whether you think you are a towering tree or a blade of grass, a high mountain or a small stone, you represent a state of nature that has its own value. If you earnestly admire yourself you’ll have a real sense of self-appreciation, which will give you confidence. A s soon as you gain full confidence in yourself, you’ll be enabled to fight and overcome any adversity.To get a thorough understanding of oneself also requires doing oneself a favor when it’s needed. In time of sadness, do yourself a favor by sharing it with your friends so as to change a gloomy mood into a cheerful one; in time of tiredness, do yourself a favor by getting a good sleep. As you are aware, what a person physically has is but a human body that’s vulnerable when exposed to the elements. So if y ou fall ill, it’s up to you to take a good care of yourself.In a word, to get a thorough understanding of oneself is to get a full control of one’s life. Then one will find one’s life full of color and flavor.55. What is described in Paragraph 2 is to show that .A. a person is easy to estimate himself too high when succeedingB. it is difficult for one to have a perfect knowledge of oneselfC. you should keep up high spirits whatever difficulties you meetD. it is essential that a person get a thorough understanding of himself56. Remember not to expect too much of yourself when looking forward to the future because .A. your shortages might stop you succeedingB. ideals can never be turned into realitiesC. you are likely to lack enough courageD. you haven’t understood yourself quite well57. Having a real sense of self-appreciation can enable one .A. to realize one’s shortagesB. not to be too proudC. to gain enough self-confidenceD. not to go downhill58. If this passage is divided into three parts, the second part should consist of .A. Paragraph 2 and Paragraph 3B. Paragraph 2 to Paragraph 5C. Paragraph 3 to Paragraph 5D. Paragraph 4 and Paragraph 5CScientists studying the impact of climate change on the Arctic need to consider ways to reduce their own carbon footprints(碳排放量), says Ryan Brook, a researcher who regularly flies north to study the health of caribous(驯鹿).He calls on scientists to show leadership by examining and sharing ways to reduce the impact of working in polar regions.“The importance of the research is not at question here. It is important to our understanding of and adapting to climate change. But we need to think about better approaches,” says Brook.“This is a n issue for all scientists, though polar researchers often travel particularly long distances using commercial air travel. We also rely extensively on small aircraft, icebreakers, and snowmobiles, all of which produce large amounts of carbon.”Brook studies the health of caribou herds in Nunavut and Northwest Territories. He works with northern wildlife managers. This work typically takes him north five or six times per year and when he calculated his own carbon footprint, he was not happy with the result.“My research footprints are about the same as the annual footprints of an average Toronto resident. Basically, I have two footprints —my own personal life, which is moderate, and my research footprint.”Climate scientists can rightly argue that Arctic research is a specialized field and the community of scientists who travel north is relatively small. Even if all scientists working in the north reduced their carbon emissions, it would not make a big impact on the global scale. For Brook, it’s the option th at matters.There are ways researchers can reduce the amount of carbon they use. Some helicopters use less fuel than others. Solar and wind power are alternatives to gas-fired generators. And while carbon offsets(抵消) don’t reduce the amount of carbon emitted, they are an easy first step.“There aren’t necessarily any easy answers, but we need to start talking about it,” says Brook. “This is particularly important for the next generation of scientists being trained and I hope to see them become leaders in this issue.”59. What did Brook find when he calculated his own carbon footprints?A. His carbon footprints are more than the annual footprints of a Toronto resident.B. His personal life footprints are more than the annual footprints of a Toronto resident.C. His research footprints are about the same as his personal life footprints.D. His personal life footprints are more than his research footprints.60. Brook’s opinion is challenged by the statement that .A. arctic research is very importantB. the Arctic is a special environmentC. the footprints of Arctic scientists are smallD. Brook’s situation is a common phenomenon61. We can infer from the last paragraph that .A. we should take actions immediately instead of just talkingB. it’s easy to start talking about the problem of carbon emissionsC. it’s necessary now to pay attention to the problem of research footprintsD. the next generation of scientists are more interested in research footprints62. What’s the main idea of the text?A. The importance of arctic research is not at question.B. Climate change becomes worse because of arctic research.C. Brook suggests ways of reducing the use of carbon.D. Scientists must look at their own carbon footprints.四.单词复习1. The salesman g_________ the walkman for at least six years, but it went wrong only one month after I bought it2. The citizens find the noise from the worksite u_________ and they hope the project being built will be completed as soon as possible.3. Every household should have some type of first aid kit in case an e__________ occurs.4. The m__________ load for the bus is limited to 30 passengers, so picking up more is against the traffic rules.5. As the s__________ goes, all work and no play will make Jack a dull boy.6. Dr Brain ____________(克服)the hardships in his research and succeeded in finding the practical ways to solve the scientific problem.7. I have no _______(同情)for students who get caught cheating in exams.8. It is _______(值得的)visiting such glorious and ancient buildings, beside s it’s free of charge.9. As is known to millions of audience, Li Xuejian is one of the most ___________(杰出的)film stars, who plays many chief roles in scores of movies.10. To the __________(残疾人),happiness means getting love and concerns from their family andthat they can do things for society as the common people do.五.任务型阅读The United States is facing a growing concern: rising obesity(肥胖) rates. A new report says adult obesity rates rose last year in 23 of the 50 states. And, the percentage of obese children was at or above 30% in 30 states. Mississippi had the highest rate of adult obesity in the new study. 32.5% of the state’s adults were obese. Mississippi also had the highest rate of obese and overweight children. 44.4% of all children between the ages of ten and seventeen years were obese or overweight.The study used a system of measurement called the Body Mass Index(B-M-I) to define words like obese and overweight. To find your B-M-I, divide your weight in kilograms by height in meters squared. A normal B-M-I is between 18.5 and 24.9. The B-M-I of someone overweight is between 25 and 29.5. And, an obese person has a B-M-I above 30.The new report says widespread obesity is increasing the rates of long-lasting diseases, such asheart disease. Obesity is also responsible for an increasing part of health care costs in the United States. Health care costs have grown while many Americans are getting fatter. A lack of physical exercise, watching TV too much and eating junk food contribute to the rising obesity rate. The report says the current economic recession(经济衰退) could worsen obesity rates by increasing food prices. This would make healthy foods cost more. The report blames the recession for rising rates of depression, anxiety and stress, which are closely linked to obesity in many cases.The report offers some ideas for dealing with obesity within government health care reforms. They include making sure that every adult and child has a right to preventive medical services. Also, people should do more physical exercise, drive less and eat less junk food to fight obesity.Widespread obesity in the US高三英语阶段性周练检测试题(17)参考答案:一.单项选择CBADD BACBD CCACBC D D C D A A B A D C A B D B二.完型填空D D A A B B B D A C B A C D C B A D C C三.阅读理解ADAB DACC ACCD四.单词复习76. guaranteed 77. unbearable 78. emergency 79. maximum 80. saying81. overcame 82. sympathy 83. worthwhile 84. outstanding 85. disabled五.任务型阅读71. Problem 72. Adult73. diseases 74. costs75. Causes 76. lacking77. Solutions 78. Government79. offering 80. driving教后记:。