2019届秋季上学期高二语文8月月考试题(含解析) (936)
2019届秋季上学期高二语文8月月考试题(含解析) (805)
专题十四英语标识语的使用1.[2019原创]Which of the following public signs is correct in English?A. B.C. D.2.[2019原创]Which of the following public signs is correct in English?A. B.C. D.3.[2019原创]Which of the following public signs is correct in English?A. B.C. D.4.[2019原创]Which of the following public signs is correct in English?A. B.C. D.5.[2019原创]Which of the following public signs is correct in English?A. B.C. D.6.[2019原创]Which of the following public signs is correct in English?A. B.C. D.7.[2019原创]Which of the following public signs is correct in English?A. B.C. D.8.[2019原创]Which of the following public signs is correct in English?A. B.C. D.9.[2019原创]Which of the following public signs is correct in English?A. B.C. D.10.[2019原创]Which of the following public signs is correct in English?A. B.C. D.【参考答案】1.D 【解析】本题考查公共标识。
2019届秋季上学期高二语文8月月考试题(含解析) (1138)
9大语法难点（1）一、宾语从句1.宾语从句的含义充当主句宾语的从句叫做宾语从句。
如：She knew that the teacher had se en the film.她知道这位老师看过这部电影。
“that the teacher had seen the film”做 knew 的宾语，同时又是由连接词 that 引导的从句，所以它叫做宾语从句。
2. 宾语从句的分类（1）动词宾语从句：顾名思义，它是位于动词后面的宾语从句。
如：He asked whose handwriting was the best in our class．他问我们班上谁的书法最好。
（2）介词宾语从句：顾名思义，它是位于介词后面的宾语从句。
如：I agree with what you said just now.我同意你刚才说的话。
（3）形容词宾语从句：顾名思义，它是位于形容词后面的宾语从句。
如：I am afraid that I will be late. 恐怕我要迟到了。
3. 引导宾语从句的连接词（1）that：没有含义，在宾语从句中不做成分（2）whether/if：表示是否，在宾语从句中不做成分。
I don't know if /whether he still lives h ere after so many years. 我不知道这么多年后，他是否还住在这里。
（3）连接代词：what, which, who, whom, whose（在宾语从句中做主、宾、表和定语）连接副词：where, when, how, why（在宾语从句中做状语）The small children don't know what is in their stockings．（what 在宾语从句中做主语）这些小孩子不知道什么在他们的长筒袜里。
Could you tell me why you were late for the meeting this morning？（why 在宾语从句中做原因状语）你能告诉我为什么你今天早上开会迟到吗？4. 在做宾语从句的题目时应注意两点（1）时态：①当主句是现在时态时，宾语从句可以根据需要使用任何时态。
2019届秋季上学期高二语文8月月考试题(含解析) (308)
河北武邑中学2018-2019学年上学期高二年级第一次月考历史试题一、选择题（本大题共25小题，每小题2分，共50分）1.“商人们通过电报和海底电缆追踪明尼阿波利斯、利物浦、布宜诺斯艾利斯和格但斯克的小麦价格，他们到最便宜的地方去买，到最贵的地方去卖。
这样，世界小麦的供应大体上就按照需求和支付能力来进行供应。
”这一现象说明A. 科技进步促进农产品价格明显下降B. 垄断产生克服了生产的无计划性C. 通讯革新推动了世界市场形成D. 农产品成为世界市场主要商品【答案】C【解析】“电报和海底电缆”是第二次工业革命时期发明，“到最便宜的地方去买，到最贵的地方去卖”说明通讯工具的革新导致世界市场的最终形成，故C项正确；材料说明是世界市场发展问题，农产品价格上升和下降与市场需求有关，故A项错误；垄断组织不是材料体现的主要信息，故B项错误；材料中农产品只是举例子，不能说明农产品成为世界市场主要商品，故D项错误。
2.老舍的著名话剧《茶馆》中有一位秦二爷，他在19世纪末致力于投资近代工业，他的理想是要“顶大顶大的工厂！那才救得了穷人，那才能抵制外货，那才能救国！”他也确实创办了一些实业，1916年前后，他创办的企业最为红火，其原因不包括A. 清政府放宽了对民间设厂的严格限制B. 辛亥革命后为资本主义扫除一些障碍C. 一战期间列强放松了对中国的经济侵略D. 实业救国思潮及反帝爱国运动的推动【答案】A【解析】1916年，清政府已被推翻，民国建立，中国民族工业处于发展的黄金时期，A项说法错误，符合题意。
其他三项均符合本阶段民族资本主义发展的原因。
故答案选A。
3.有西方学者认为：“近代世界赖以建立的种种发明与发现可能有一半来源于中国”。
传入欧洲并对“近代世界”的到来产生了重大影响的中国科技成就是A. 地动仪B. 造纸术C. 雕版印刷术D. 罗盘针【答案】D【解析】【详解】根据材料可知，宋朝时指南针用于航海，它传入欧洲以后，促进新航路开辟，加强了世界各地之间的联系，D项正确。
2019届秋季上学期高二语文8月月考试题(含解析) (800)
词语运用
74
year→years
I've been buying the lottery (彩票) for almost twentyyears...
2010
词语运用
72
lesson
...you have learned a valuable(有价值的)lessontoday.
词语运用
73
time→times
词语运用
75
way
In the Republic of Korea,the"hand heart"has been popular for a long time,but in a differentway.
2014
词语运用
68
rest
After the students get paid, therestof the money goes to a local youth project.
词语运用
75
people
However, I knew that as soon as I got my smartphone back I would be one of thosepeopleonce again.
2015
词语运用
67
star→stars
Many young popstarsin theUShave done the move in recent photos.
词语运用
74
soup
Nasreddin's wife brought somesoupto the table and the visitor tasted it.
2019届秋季上学期高二语文8月月考试题(含解析) (1066)
Unit 1 Where did you go on vacation? Section AI.用所给词的适当形式填空(每小题1分)1.I think you are old enough (足够)to dress (you),Rick.2. If anyone (ask)me the way to somewhere, I will say, “Sorry, I am a stranger here.”3.Do you read Lei Feng’s (diary)? I learn a lot from them.4.Linyi People’s Park is a (wonder)place to have fun at.5.He doesn’t have a job. So he has nothing (do)every day.6.Her son seems (be)asleep.7.The football match was ______ (wonder)last week.8.You must look after ___ (your)because no one can help you.9.Why do you keep ___ (talk)about that?10.Something __ (be)wrong with your watch.11.—When did you go (shop)? —At 8:00 p.m. yesterday evening.12.He seemed (be)tired in class.13.I felt very nervous(紧张的) in the classroom, because I didn’t know (someone).14.The weekend was boring. She seemed to be (boring).15.Help (you)to some fish, boys and girls.16．Can you find a ______________(different) between the two pictures?17．Alice always _____________(try) to help me to learn English well.18．Are there any_______________ (bird) in the tree?19．Living in the village is boring，so she ____________(like) it.20．Students should be careful when they are taking some of the outdoor ______________(activity)．Ⅱ.单项填空11.—The weather was really cold yesterday. —Yes. It was five ________ zero last night.A．under B．below C．down D．betweenst Sunday we didn't go out ________ the rain.A．because of B．because C．in front of D．before13.—Why didn't you get to the top of the mountain? —Because we didn't have________ time.A．free B．right C．natural D．enough14.Mike decided ________ the museum this Sunday.A．visit B．visits C．visiting D．to visit15.Please turn on the TV.I________ what the weather will be like tomorrow.A．wonder B．feed C．know D．wait16.My host family tried to cook for me when I studied in New Zealand.A. different somethingB. different anythingC. something differentD. anything different17.You may take of these books, but you must return(归还) it on time.A. someoneB. everyone C .anyone D. any one18.I tennis with my cousin every day when I was in America.A. playB. playedC. had playedD. has played19.What a surprise to see you here! When you back?A. do, getB. did, getC. do, gotD. will, get20.The only problem was that there was to do but read.A. much somethingB. anything muchC. much nothingD. nothing much21.We some hens and some baby pigs last vacation.A. feed, seeB. fed, seeC. feed, saw D .fed, saw22.—Let’s buy some cards our teachers on Teachers’ Day.—Why not make some by hand? It’s much more interesting.A. forB.toC.atD. with23.—How was your trip? —.I hope I can go there again.A. Just so-soB. Not very goodC. Nothing specialD. Wonderful24.—Did you buy anything during the vacation? —.I bought a pair of new shoes anda T-shirt.A. Sounds goodB. Of courseC. Not reallyD. Oh, no25.Yesterday,I forgot an umbrella with me,so I was all wet.A. bringB. bringingC.to bringD. brought26.—Is here? —No. Kate is ill in hospital.A. someoneB. anyoneC. everyoneD.no one27.In our school students like English, but of them can speak English smoothly(流畅地).A. a little, a fewB. a few, few C .a few, little D .a little, few28.I think it’s important to there on time. A .go B. going C.t o goD. goes29.When summ er comes, a lot of people feel like in the pool.A.to swimB. swimC. swimmingD. have swum30.The new kind of ring is expensive. I don’t have money.A. too much, much tooB. much too, too much C .too many, too much D. much too, much too31.Two Chinese pandas, Tiantian and Yangguang, England the afternoon of December 4th,2011.A. arrived in, onB. arrived at, inC. arrive in, onD. got to, in32.The pizza good. I’d like some more. A. turns B. sounds C. feels D. tastes33.He didn’t go to school yesterday he was ill. A. because B .because ofC. ifD.so34.When you move somewhere new, the first thing for you is to find a place .A.to liveB. living inC.to live inD. live35.—What do you think of the lecture of Li Yang’s Crazy English?—I think it’s ,but someone t hinks it’s much too . A. wonderful enough, bored B. enough wonderful, boring C. enough wonderful, bored D. wonderful enough, boring36.She is new here，so she has_____ friends at school. A．much B．few C．little D．a litt le37.—Can you help me work out the problem？It's so difficult.—OK. Let me ________.A．grow B．try C．pick D．blow38.I don't want to go to the museum，because it's too________.A．relaxing B．boring C．bored D．beautifulⅥ.完形填空(每小题1分,共10分)Mr.and Mrs.Smith always spent their summer holidays in a small hotel at the seaside near their hometown. One year, however, Mr.Smith made a lot of 36 in his business, so they decided 37 to a foreign country and stay at a really good 38 .They flew to London and 39 at a 5-star hotel late in the evening. Although they were hungry, they thought they would have to go to bed, because in that 40 hotel where they had been used to (过去常常)stay in the past, no meals were served(供应) 41 seven in the evening. They 42 surprised to be told that the hotel served dinner until ten. “Then what is the time 43 meals?” asked Mrs.Smith.“Well, madam, we serve breakfast from seven to eleven, lunch from twelve to three, 44 from four to five, and dinner from six to ten.”“But that hardly leaves any time for us to see the city!” said Mrs.Smith.When the waitress 45 this, she smiled and said, “You can choose (选择)any time to come here for a meal.”36.A.mistakes B. time C. friends D. money 37.A.went B.to go C. go D. going38.A.hotel B. place C. city D. restaurant 39.A.stayed B. got C. arrived D. reached40.A.small B. big C. foreign D. good 41.A.on B. after C. during D.until42.A.are B.is C. were D.be 43.A.with B. on C.at D. of 44.A.drink B. tea C .beer D. food 45.A.hear B .heard C. listen D. heardⅦ.阅读理解(每小题2分,共30分)AQingdao is famous for its sunshine, white sandy beaches and clear water. You can relax here, walking along the beaches and breathing the fresh air! On July 18th,2014,Frank and his parents went to Qingdao.T hey were on vacation. Qingdao is a beautiful city beside the sea. It was about 12:00 when they arrived there on the first day. They found a hotel and had a short rest. It was really hot and they decided to go to the beach. At about 3:30 pm, th eygot to the beach. There were many people there. Some were lying on the beach and many children were playing in the water. Frank was playing with them and he was very happy. His parents also felt relaxed. About two hours later, they went back to the hotel.On the second day, it rained all day. Frank played computer games in the hotel with his father and his mother went shopping. On July 20th,they went to Laoshan Mountain in the morning and took a bus home in the afternoon. They were tired but very happy.46.Where did Frank’s family go on vacation?A. To Shanghai.B. To Tianjin.C. To Qingdao.D. To Shanxi.47.What did Frank’s fa ther do on July 19th? A. He swam in the sea. B. He played computer games in the hotel. C. He went shopping with Frank’s mother.D. He visited Laoshan Mountain.48.How long was their vacation? A. One day. B. Two days. C. Three days. D. Four days.49.How did they go back home? A. By train. B. By bus. C. By bike. D. By taxi.50.Which of the following is TRUE?A. They stayed on the beach for about an hour.B. They went shopping on July 20th.C. Frank didn’t play in the water on the first day.D. It rained on July 19th.BThe summer vacation is over. It’s tru e that time flies. During the vacation, the weather was hot and I could not do much work, but I was happy.As the afternoons were hot, I did my work in the morning. I got up at 6:30 and took a walk in the garden for half an hour. After breakfast, I did some exercises in math. I spent three hours or more doing this. I worked quite hard and made good progress(取得进步).In the afternoon I went swimming. It was fun. I did not go home until about five or six o’clock. Sometimes in the evening a friend of mine would come to see me and we would spend some time listening to music.In this way I spent my vacation happily. I not only studied well but also became a good swimmer. Now I am in good health and high spirits(精神).51.What does the text mainly tell us?A. How the writer spent his summer vacation.B. What the weather was like that summer.C. When the writer got up in the morning.D. Where the writer took a walk.52.How long did the writer spend doing his exercises?A. Half an hour.B. Three hours or more.C. Only one hour.D. Two hours and a half.53.The writer spent most of the afternoons .A. listening to musicB. visiting his friendsC. walking in the garden D .swimming54.The writer had a very good summer vacation because he .A. worked very hard and made good progressB. went to swim and made good progress in mathC. got up early and went home lateD. liked swimming better than studying55.Which of the following is NOT true?A. The writer made progress in math.B. The writer took a walk for half an hour before breakfast.C. The writer began studying as soon as she got up.D. The writer spent more time swimming than listening to music.Ⅴ.词语运用。
2019届秋季上学期高二语文8月月考试题(含解析) (502)
河南省滑县2019届高三数学第二次联考试题文（扫描版）2018—2019学年高三年级调研考试（二）数学（文科）参考答案1.【答案】B【解析】依题意，{}{}232,1,0,1,2Z A x x =∈-≤<=--，故{}0,2A B =，故选B.2.【答案】A 【解析】依题意，()()()()24i 13i 24i 26i 4i 121010i1i 13i 13i 13i 1010--------====--++-，故选A. 3.【答案】D【解析】依题意，131********n n ⎡⎤⎛⎫-⎢⎥⎪⎝⎭-⎢⎥⎣⎦=--，化简可得2log 6n =，故[]2n =，则第2日蒲生长的长度为D. 4.【答案】C【解析】运行该程序，第一次，999,2S k ==；第二次，995,4S k ==；第三次，979,6S k ==；第四次，915,8S k ==；第五次，659,10S k ==，第六次365,12S k =-=，此时0S <，故输出的k 的值为12，故选C. 5.【答案】B【解析】A 班学生的分数多集中在[70,80]之间，B 班学生的分数集中在[50,70]之间，故A B x x >；相对两个班级的成绩分布来说，A 班学生的分数更加集中，B 班学生的分数更加离散，故22A B s s <，故选B.6.【答案】A【解析】依题意，()()()()55255550550mn m n m n n m n ->-⇔--->⇔-->5,5,5,5,m m n n ><⎧⎧⇔⎨⎨><⎩⎩或故“2216m n +<”⇒“5525mn m n ->-”，反之不成立，例如6m n ==；故“2216m n +<”是“5525mn m n ->-”的充分不必要条件，故选A. 7.【答案】C【解析】作出该几何体1111ABCD A B C D -的直观图，旋转一定的角度后，得到的图形如下图所示，观察可知，1CA =1A D =，1A B = C.8.【答案】B【解析】依题意，不妨设点M （x,y ）在第一象限，联立225,,x y by x a ⎧+=⎪⎨=⎪⎩解得,x c y ⎧=⎪⎪⎨⎪=⎪⎩（其中222b a c +=），可知四边形MNPQ为矩形，且根据双曲线的对称性，2c c ⋅=，即225c ab =，解得12b a =（2b a=舍去），故所求渐近线方程为12y x =±，故选B. 9.【答案】D【解析】依题意，函数()f x 为偶函数，故1k =-，则()()320g k x g x ++-+=即为()()132g x g x -++-=-，故函数()g x 的图象的对称中心为()1,1-，故选D.10.【答案】A【解析】依题意，()()()3sin 32sin 33f x x x x πϕϕϕ⎛⎫=-+-=-+ ⎪⎝⎭，则()333Z k k ππϕπ⨯-+=∈，则()43Z k k πϕπ=-∈；因为2πϕ<，故3πϕ=，故()2sin 3f x x =，则将函数()f x 的图象向右平移6π个单位长度 后得到函数()2cos3g x x =-的图象，故选A. 11.【答案】B【解析】依题意，当0x ≥时，()()2'1212121f x x x x x =-=-，故当()0,1x ∈时，()'0f x <，当()1,x ∈+∞时，()'0f x >，且()11f =-，作出函数()f x 的大致图象如下所示；令()()()22320g x f x f x =--=⎡⎤⎣⎦，解得()()122f x f x ==-或，观察可知，函数()g x 共有3个零点，故选B.12.【答案】A【解析】设()00,M x y ，()11,N x y ，则直线MA 1的斜率为1003MA y k x -=，由11NA MA ⊥，所以直线NA 1的斜率为1003NA x k y =--．于是直线NA 1的方程为：0033x y x y =-+-．同理，NA 2的方程为：0033x y x y =--+．联立两直线方程，消去y ，得20109y x x -=． 因为()00,M x y 在椭圆221189y x +=上，所以22001189x y +=，从而2292x y -=-．所以012x x =-． 所以1212012MA A NA A S x S x ∆∆==，故选A. 13.【答案】322-或【解析】依题意，()4212m m +⋅=，解得322m =-或. 14.【答案】5【解析】作出不等式组所表示的平面区域如下图阴影部分所示，观察可知，当直线2z x y =-过点55,33A ⎛⎫- ⎪⎝⎭时，2z x y =-取最大值，最大值为5.15.【答案】108【解析】依题意，不妨设2AB =，故所求概率22224P ππ⨯⨯+⨯⨯==.16.【解析】因为()sin sin 4sin sin ABC b a A b B B S bc C ∆+=⋅+，故2sin sin 4sin sin ABC ab A b B B S bc C ∆+=⋅+，即222sin sin 4sin sin ABC a B b B B S c B ∆+=⋅+，即2224ABC a b c S ∆+-=，故cos sin ab C ab C =，故4C π=，则△ABC的外接圆半径为2sin c C ==.17.【解析】（1）依题意，设BD x =，则AD =，3BC x =,又,43B AB π==.在△ABD 中，由余弦定理得3cos4216322π⋅⋅-+=x x x ，即2280x x +-=，解得2x =，或4-=x （舍去）. 则36BC x ==；（5分）（2） 在△ ABC 中，设A,B,C 所对的边分别为a,b,c ， 由正弦定理sin sin b c B C=，得sin sin c B C b ==又AC b AB c =>=，所以B C >，则C为锐角，所以cos 3C =则()1sin sin sin cos cos sin 2BAC B C B C B C ∠=+=++=.（10分） 18.【解析】（1）依题意，设等差数列{}n a 的公差为d ，则4224d a a =-=，解得2d =，故11a =，21n a n =-，而236m mS S +=+，则214436m m a a m +++=+=，解得8m =，故32424232425762m S S ⨯==+⨯=；（6分）（2）因为21n a n =-，故()()+1211111212322123n n a a n n n n +⎛⎫==- ⎪++++⎝⎭，故()111111111...23557792123323n nT n n n ⎛⎫=-+-+-++-= ⎪+++⎝⎭.（12分） 19.【解析】（1）依题意 ，所求平均数为20.260.36100.28140.12180.04⨯+⨯+⨯+⨯+⨯ 0.4 2.16 2.8 1.680.727.76=++++=；（3分） （2）依题意，完善表中的数据如下所示：故()222000800600200400333.3310.828100010001200800K ⨯⨯-⨯=≈>⨯⨯⨯；故有99.9%的把握认为“愿意购买该款电视机”与“市民的年龄”有关；（7分）（3）依题意，使用时间在[)0,4内的有1台，记为A ，使用时间在[]4,20内的有4台，记为a,b,c,d ，则随机抽取2台，所有的情况为（A ，a ），（A ，b ），（A ，c ），（A ，d ），（a ，b ），（a ，c ），（a ，d ），（b ，c ），（b ，d ），（c ，d ），共10种，其中满足条件的为（a ，b ），（a ，c ），（a ，d ），（b ，c ），（b ，d ），（c ，d ），共6种，故所求概率63105P==.（12分）20.【解析】（1）作出平面EFG 的图形如下所示，点G 为线段SB 上靠近B 点的三等分点；C（5分）（2）依题意， 因为0090,45SDA SAD ∠=∠=，故SD AD ==而2SA SB ==，所以222SB SD BD =+， 所以SD BD ⊥，又因为DADB D =，所以SD ABCD ⊥平面；因为SD ⊂平面SCD，所以平面SCD ABCD ⊥平面． 作'EE CD ⊥于'E ，因为平面=SCDABCD CD 平面，所以'EE ⊥平面SCD ；又因为//EF SCD 平面，所以'EE 即为F 到平面SCD 的距离．在△ABD 中，设AB 边上的高为h ，则h =，因为23ED EC BD AC ==，所以2'3EE h ==，即F 到平面SCD（12分）21.【解析】（1）依题意，直线l ：28y x =+，联立22,28,x y y x ⎧=⎨=+⎩故24160x x --=，设11(,)M x y ，22(,)N x y ，则124x x +=，1216x x =-，故1220MN x =-==；（5分）（2）联立0,40,x y x y -=⎧⎨+-=⎩解得2x y ==，故()2,2A ，设直线l 的方程为：4(2)y k x -=+，11(,)M x y ，22(,)N x y ， 则11112(2)222AM y k x k x x -++==--，22222(2)222AN y k x k x x -++==--， 212121212121212[(2)2][(2)2][2()4]2(4)4(2)(2)2()4AM ANk x k x k x x x x k x x k k x x x x x x +++++++++++==---++， 联立抛物线22x y =与直线4(2)y k x -=+的方程消去y 得22480x kx k ---=，可得122x x k +=，1248x x k =--，代入AM AN k k ⋅可得1AM AN k k ⋅=-.（12分）22.【解析】（1）依题意，()0,x ∈+∞，()221'222x mx f x x m x x++=++=⋅，若22m -≤≤，则210x mx ++≥，故()'0f x ≥，故函数()f x 在()0,+∞上单调递增；当22m m <->或时，令210x mx ++=，解得12xx ； 若2m >0<0<，故函数()f x 在()0,+∞上单调递增； 若2m <-，则当x ⎛∈⎝⎭时，()'0f x >，当x ∈⎝⎭时，()'0f x <，经典资料经典资料（一）当x ⎫∈+∞⎪⎝⎭时，()'0f x >； 综上所述；当2m ≥-时，函数()f x 在()0,+∞上单调递增；当2m <-时，函数()f x在⎛ ⎝⎭和⎫+∞⎪⎝⎭上单调递增，在⎝⎭上单调递减；（6分） （2）题中不等式等价于2222ln 2e 3x x mx x x ++≤+，即2e ln x x x mx -+≥， 因此2e ln x x x m x -+≥，设()2e ln x x x h x x-+=，∴ ()'10h =，当)1,0(∈x 时，()2e 1ln 10x x x x -++-<，即0)('<x h ，)(x h 单调递减； 当),1(+∞∈x 时，()2e 1ln 10x x x x -++->，即0)('>x h ，)(x h 单调递增； 因此1=x 为)(x h 的极小值点，即1)1()(+=≥e h x h ，故e 1m ≤+， 故实数m 的取值范围为(],e 1-∞+.（12分）。
2019届秋季上学期高二语文8月月考试题(含解析) (163)
13.3 全等三角形的判定（3）【学习目标】探索并掌握两个三角形全等的角边角（ASA ）和角角边（AAS ）的条件，在与他人合作交流等活动过程中，发展合情推理，进一步学习有条理的思考与表达. 【学习重点】探索并掌握两个三角形全等的角边角（ASA ）和角角边（AAS ）条件，并能灵活运用. 【学习难点】在观察、实验、分析中探究两个三角形全等的条件. 【预习自测】 知识链接已经学过的三角形全等的判定方法有哪些？【合作探究】 探究活动一课本“一起探究”的学习与认识．探究活动二如图，M 是AB 的中点，MC=MD ，∠1=∠2， 请说明△AMC ≌△BMD 的理由．归纳: 三角形全等判定依据有角边角（ASA ），推论角角边（AAS ） 【精讲答疑】 例题:如图，已知点D 是△ABC 的边AB 上一点，DF 交AC 于E ，DE=EF ，C F∥AB ，AE 与CE 是否相等？试说明理由.ACDM 121.课本练习.2.如图，AD⊥BC于D，BD=CD．△ABD和△ACD全等吗？为什么？【反馈拓展】1.如图，∠C =∠D，AC = BD. 则△AOC≌△BOD吗？为什么？AB C2．如图，已知：AB = CD ，DE ⊥AC ，BF ⊥AC ，垂足分别为E 、F ，∠B=∠D ，则AF = CE 吗？为什么？3. 如图，△ABC ≌△A ′B ′C ′，AD 、A ′D ′分别是△ABC 和△A ′B ′C ′的中线，你能得出AD=A ′D ′吗？变式一：若AD 、A ′D ′分别是△ABC 和△A ′B ′C ′的角平分线，AD=A ′D ′吗？变式二：若AD 、A ′D ′分别是△ABC 和△A ′B ′C ′的高线，AD=A ′D ′吗？B C ′D ′【总结反思】1.本节课我学会了：还有些疑惑：2.做错的题目有：原因：。
2019届秋季上学期高二语文8月月考试题(含解析) (1115)
化学部分A卷：7．C 8．D 9．D 10．A 11．B 12． C 13．BB卷：7．B 8．D 9．B 10．A 11．C 12．C 13．B26. (15分)(1)D→B→C→B (2分)(2)硬质玻璃管 (2分)(3) 5NO+3MnO4－+4H+=5NO3－+3Mn2++2H2O (2分)(4)60% (2分)(5)②淀粉溶液 (1分)加入最后一滴液体时，锥形瓶内溶液恰好从蓝色变为无色，且维持半分钟不变色(2分) ③56.6% (2分) ④BD(2分)27．(14分)(1)Bi2S3+6Fe3＋=2Bi3＋+6Fe2＋+3S (2分)抑制溶液中Bi3＋的水解(2分) SiO2(2分)(2)过滤、洗涤、干燥(2分)28. (14分)(1)CO2(g)+3H2(g)=== 1/2C2H4(g)+2H2O ΔH=－(b－a) kJ/mol(2分)(其它合理答案均得分)(2)负 (1分) 4OH――4e－=O2↑+2H2O或2H2O―4e－=O2↑+4H+(2分)(3)①Ir (1分) ②d和e(2分)，＜(2分)③状态a和c均未达到平衡，状态c温度高反应速率快，CO2的转化量大，转化率高；(2分)④62527（或23.15）(2分)35．【化学－物质结构与性质】 (15分)3d4s分) d (1分)(2)①具有孤电子对(或孤对电子) (2分)②sp 3(1分) 8N A (2分) ③CN －或C 22－或NO +(2分)(3)从锰到铼原子序数增大，核对外层电子引力增大，电子层数增多，核对外层电子引力减小，但前者占主导，所以铼中的金属键更强，熔点更高 (2分) (4)6 (1分) 234(3.74×10－8)3×N A(2分)36．【化学——选修5：有机化学基础】(15分) (1)－ CH 3(2分)(2)取代反应(1分) －CHO(1分) (3)乙醛(2分)(4)O － CCH 2CHHOCHCH 222C －OO+ 2H 2O(2分)(5)10 (2分)CHC H 2CHO OH或或HOCH 2CHCHOOHCHCHOHOCH 2 (2分)HCHOH 2Cu/O 2ΔΔ3CH 2OHCH 3CH 3CH 2ClNaOH/H 2 OCH 2－CH 2－CH 2OHOHHOCH 2CH 2 CHO（3分）（6）。
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高一级部2017——2018学年度第一学期期末物理学科第6次假期作业
1、如图所示，物体A 靠在竖直墙面上，在力F 作用下，A 、B 保持静.物体B 的受力个数为（ ） A ．2 B ．3
C ．4
D ．5
2、（多选）如图所示，在水平力F 作用下，木块A 、B 保持静止．若木块A 与B 的接
触面是水平的，且F ≠0.则关于木块B 的受力个数可能是( ) A ．3个 B ．4个 C ．5个 D ．6个
3.如图所示，一串红灯笼在水平风力的吹动下发生倾斜，悬挂绳与竖直方向的夹角为30°.设每个红灯笼的质量均为m ，绳子质量不计．则自上往下数第一个红灯笼对第二个红灯笼的拉力大小为 ( )
A.33
mg B ．2mg C ．4mg
D.33mg
4．如图所示，质量m A >m B 的两物体A 、B 叠放在一起，靠着竖直墙面．让它们由静止释放，在沿粗糙面下落过程中，物体B 的受力示意图是( )．
5.如图所示,在光滑水平面上叠放着A 、B 两物体,已知m A =6 kg 、m B =2 kg,A 、B 间动摩擦因数μ=0.2,现水平向右拉物体A,g 取10 m/s 2
,则 ( )
A.当拉力F<12 N 时,A 静止不动
B.当拉力F>12 N 时,A 相对B 滑动
C.当拉力F=16 N 时,B 受A 的摩擦力等于4 N
D.无论拉力F 多大,A 相对B 始终静止
6．如图所示，物体P 静止于固定的斜面上，P 的上表面水
平，现把物体Q 轻轻地叠放在P 上，则( ) A ．P 向下滑动 B ．P 静止不动
C ．P 所受的合外力增大
D ．P 与斜面间的静摩擦力不变
7、 如图所示，一固定斜面上两个质量相同的小物块A 和B 紧挨
着匀速下滑，A 与B 的接触面光滑．已知A 与斜面之间的动摩擦因数是B 与斜面之间动摩擦因数的2倍，斜面倾角为α，B 与斜
面之间的动摩擦因数是 ( )
A.32tan α
B.32
cot α C ．tan α D ．cot α
8．如图所示，桌面上固定一个光滑的竖直挡板，现将一个质量一定的重球A 与截面为三角形的垫块B 叠放在一起，用水平外力F 可以缓缓向左推动B ，使球慢慢
升高，设各接触面均光滑，则该过程中( ) A ．A 和B 均受三个力作用而平衡 B ．B 对桌面的压力越来越大 C ．A 对B 的压力越来越小 D ．推力F 的大小恒定不变
9、（多选）如图所示，质量分别为mA 、mB 的两物块A 、B 叠放在一起，若它们共同沿固定在水平地面上倾角为α的斜面匀速下滑．则 ( ) A ．A 、B 间无摩擦力
B ．A 、B 间有摩擦力，且A 对B 的摩擦力对B 做正功
C ．B 与斜面间的动摩擦因数μ=tan α
D ．B 对斜面的摩擦力方向沿斜面向下
10．(多选)如图所示，木块m 和M 叠放在一固定在地面不动的斜面上，它们一起沿斜面匀速下滑，则m 、M 间的动摩擦因数μ
1和M 、斜面间的动摩擦因数μ2可能
正确的有( )．
A ．μ1＝0，μ2＝0
B ．μ1＝0，μ2≠0
C ．μ1≠0，μ2＝0
D ．μ1≠0，μ2≠0 11. 如图所示，A 物体的上表面水平，它与B 物体保持相对静
止，一起沿着斜面匀速下滑，试分析A 的受力情况.
12、如图所示，质量M等于2kg的木块套在水平固定杆上，并用轻绳与质量m=1kg的小球相连。
今用跟水平方向成60°角的力F=10 N拉着球并带动
木块一起向右匀速运动，运动中M、m相对位置保持不变，g取10ms2。
求：
（1）轻绳与水平方向夹角θ；
（2）木块M与水平杆间的动摩擦因数μ。
13.如图所示，质量为M的直角三棱柱A放在水平地面上，三棱柱的斜面是光滑的，且斜面倾角为θ.质量为m的光滑球放在三棱柱和光滑竖直墙壁之
间，A和B都处于静止状态，求地面对三棱柱的支持力和摩
擦力各为多少？
14．如图所示，质量M＝2 kg的木块套在水平杆上，并用轻绳与质量m＝ kg的小球相连．今用跟水平方向成α＝30°角的力F＝10 N拉着球带动木块一起向右匀速运动，运动中M、m的相对位置保持不变，g＝10 m/s2，求运动过程中轻绳与水平方向的夹角θ及木块M与水平杆
间的动摩擦因数．
第6次假期作业参考答案
1、C
2、BC
3、D
4、A
5、C
6、B
7、 A
8、D
9、BCD 10、BD 11、【答案】
12、【答案】（1）30° （2）μ＝33 【解析】
（1）（7分）m 处于静止状态，其合力为零。
（1分） 以m 为研究对象，由平衡条件得：
水平方向F cos60°－F T cos θ＝0 ①（2分） 竖直方向F sin60°＋F T sin θ－mg ＝0 ②（2分） 由③④得θ＝30°（2分）
（2）（7分）M 、m 整体处于静止状态，可看做整体，系统所受合力为零。
（1分） 以M 、m 整体为研究对象。
由平衡条件得
水平方向F cos60°－μF N ＝0 ③（2分） 竖直方向F N ＋F sin60°－Mg －mg ＝0 ④（2分） 由①②得μ＝33
（2分） 13、答案：(M ＋m )g mg tan θ
解析：选取A 和B 整体为研究对象，它受到重力(M ＋m )g ，地面支持力F N ，墙壁的弹力F 和地面的摩擦力F f 的作用(如图所示)而处于平衡状态．根据平衡条件有：
F N －(M ＋m )g ＝0，F ＝F f
可得F N ＝(M ＋m )g
再以B 为研究对象，它受到重力mg ，三棱柱对它的支持力F AB ，
墙壁对它的弹力F 的作用(如图所示)，处于平衡状态，根据平
衡条件有：
经典资料
竖直方向上：F AB cos θ＝mg
水平方向上：F AB sin θ＝F
解得F＝mg tan θ，所以F f＝F＝mg tan θ.
3
14【答案】30° 5
【详解】以M、m整体为研究对象
由平衡条件得：
水平方向：Fcos30°－μFN＝0 ①
竖直方向：FN＋Fsin30°－Mg－mg＝0 ②
3
由①②得：μ＝5
以m为研究对象，由平衡条件得：
Fcos30°－FTcosθ＝0 ③
Fsin30°＋FTsinθ－mg＝0 ④
由③④得：θ＝30°。