计算机二级C语言教程第14章课后编程题
二级C语言课后编程答案的整理版
3.16main(){ float a,b,c,s,v;printf("input a,b,c:");scanf("%f %f %f:",&a,&b,&c);s=a*b;v=a*b*c;printf("a=%f,b=%f,c=%f\n",a,b,c); printf("s=%f,v=%f\n",s,v);}3.17main(){ int h,m;h=560/60;m=560%60;3.18main(){ int m,n;printf("input m & n:");scanf("%d%d",&m,&n);printf("\n%d,%d\n",m/n,m%n);getch();}3.19main(){ double x,y,z,s;printf("input x,y,z: ");scanf("%lf%lf%lf",&x,&y,&z);s=(x+y+z)/3.0;printf("\nAverage=%6.1lf\n",s);getch();}3.20main(){ int a,b,c,t;printf("Input a,b,c: ");scanf("%d%d%d",&a,&b,&c);t=c;c=b;b=a;a=t;printf("\na,b,c=%d,%d,%d\n",a,b,c); getch();}【4-21】main(){ int a,m;printf("input a: ");scanf("%d",&a);switch(a/10){ case 0:case 1:case 2: m=1 ;break;case 3: m=2 ;break;case 4: m=3 ;break;case 5: m=4 ;break;default: m=5;}printf("a,m=%d, %d",a,m );getch();}【4-22】main(){ int age,y0,m0,d0,y1,m1,d1;printf("\ninput a stedent\' birthday (yy-mm-dd): ");scanf("%d-%d-%d",&y0,&m0,&d0);printf("\ninput today\' date(yy-mm-dd): ");scanf("%d-%d-%d",&y1,&m1,&d1);if ((m1>m0)||(m1==m0)&&(d1>=d0)) age=y1-y0;else age=y1-y0-1;printf("\nThe student\' ageis %d",age);getch();}【4-23】main(){ int m;printf("\ninput a integer: ");scanf("%d",&m);if (m%2==0) printf("\n%d is event.",m);else printf("\n%d is ord.",m);getch();}【4-24】main(){ int a,b,c,max;printf("\ninput a,b,c: ");scanf("%d%d%d",&a,&b,&c);max=a;if (b>max) max=b;if (c>max) max=c;printf("max is %d",max);getch();}【4-25-1】main(){ int x,y;printf("\ninput x: ");scanf("%d",&x);if((x>-5)&&(x<0)) y=x;if (x==0) y=x-1;if ((x>0)&&(x<10)) y=x+1;printf("\nx is %d , y is %d",x,y); getch();}【4-25-2】main(){ int x,y;printf("\ninput x: ");scanf("%d",&x);if((x>-5)&&(x<10)){ if (x<0) y=x;if (x==0) y=x-1;if (x>0) y=x+1;printf("\nx is %d , y is %d",x,y); }else printf("input x iserror ! %c",'\007');getch();}【4-25-3】main(){ int x,y;printf("\ninput x: ");scanf("%d",&x);if ((x>-5)&&(x<0)) y=x;else if (x==0) y=x-1;else if ((x>0)&&(x<10)) y=x+1; printf("\nx is %d , y is %d",x,y); getch();}【4-25-4】main(){ int x,y;printf("\ninput x: ");scanf("%d",&x);switch(x){ case -4:case -3:case -2:case -1: y=x;break;case 0 : y=x-1;break;case 1 :case 2 :case 3 :case 4 :case 5 :case 6 :case 7 :case 8 :case 9 : y=x+1;break;default : printf("Input xerror ! %c",7);}printf("\nx is %d , y is %d",x,y); getch();}【5-17】main(){ int i,s=1,k=-1;for (i=1;i<=50;i++){ s=s+k*(2*i+1);k=-k;}printf("s=%d",s);getch();}【5-18-1】main(){ int i=1;double e=1.0,s=1.0;for(i=1;i<=50;i++){s=s*i;e=e+1/s;}printf("e=%lf",e);getch();}【5-18-2】main(){ int i=1;float e=1.0,s=1.0;while (1/s>=1e-04) /* 8 times */ {s=s*i;i++;e=e+1/s;}printf("e=%10.6f",e);getch();}【5-19】main(){ int y,k=0;for(y=1000;y<=2000;y++){ if (y%4==0&&y%100!=0||y%400==0) {printf("%10d",y);k++;}if (k%3==0) printf("\n");}getch();}【5-20】#include <stdio.h>main(){int i,j,n;printf("Input n (1--10):"); do scanf("%d",&n);while (n<1||n>10);for (i=1;i<=n;i++){for (j=1;j<=40-i;j++)printf(" ");for (j=1;j<=2*i-1;j++)printf("*");printf("\n");}for (i=n+1;i<=2*n-1;i++){ for (j=1;j<=40-2*n+i;j++) printf(" ");for (j=1;j<=4*n-1-2*i;j++) printf("*");printf("\n");}getch();}【6-20】#include <stdio.h>main(){ int k=0; char ch;while((ch=getchar())!=10) { k++;printf("%4c%4d",ch,ch); if(k%3==0) printf("\n"); }getch();}【6-21】#include <stdio.h>main(){ long k=0; char ch;while((ch=getchar())!=EOF) { if (ch>='0'&&ch<='9'){ ch=ch-'0';k=k*10+ch;}}printf("%ld",k);getch();}【6-22】#include <stdio.h>main(){ int flag,k=0; char ch;while((ch=getchar())!=EOF){ if (ch==10) { k++; flag=0; }else flag=1;}if (flag==1) k++;printf("\n The line numberis %d\n",k);getch();}【6-23】#include <stdio.h>main(){ int k=0; char ch;while((ch=getchar())!=10)if (ch>='a'&&ch<='z') k++;printf("\n The lower letter number is %d\n",k);getch();}【6-24】#include <stdio.h>main(){ int i,j,n;printf("Input line number : ");scanf("%d",&n);for(i=1;i<=n;i++){ for (j=1;j<=40-i;j++)printf(" ");for(j=1;j<=2*i-1;j++)printf("%c",64+i);printf("\n");}getch();}【7-15】main(){int a,b;printf("Input a & b:"); scanf("%d%d",&a,&b);printf("\n%d%%%d=%d",a,b,mymod(a,b)); getch();}mymod(int a, int b){int z;z=a%b;return z;}【7-16】float fun(int n){return (1.0/n);}main(){int i,n,k=1;float s=0.0;printf("Input n:");scanf("%d",&n);for(i=1;i<=n;i++){s+=k*fun(i);k=-k;}printf("\ns=%8.6f",s);getch();}【7-17】float f(int m){ float t=1.0;int i;for (i=2;i<=m;i++)t-=1.0/(i*i);return t;}main(){int n;printf("Input n:");scanf("%d",&n);printf("\nt=%8.6f",f(n));getch();}【7-18】#include <math.h>float f(float x){ float z;z=x*x-5*x+4;return z;}main(){float x,y1,y2,y3;printf("Input x: ");scanf("%f",&x);y1=f(2);y2=f(x+15);y3=f(sin(x));printf("y1=%10.4f\n",y1);printf("y2=%10.4f\n",y2);printf("y3=%10.4f\n",y3);printf("\n**** END ****");getch();}【8-17-1】fun(x,y)int *x,*y;{int z1,z2;z1=*x+*y;z2=*x-*y;*x=z1; *y=z2;}main(){int *a,*b,A,B;a=&A,b=&B;printf("input two numbers: ");scanf("%d%d",a,b);printf("a,b=%d,%d\n",*a,*b);printf("before call function:\n"); printf("a=%d b=%d\n",*a,*b);fun(a,b);printf("after call function:\n"); printf("a=%d b=%d\n",*a,*b); getch();}【8-17-2】fun(x,y) float *x,*y;{float z1,z2;z1=*x+*y;z2=*x-*y;*x=z1; *y=z2;}main(){float *a,*b,A,B;a=&A;b=&B;printf("input two real numbers: "); scanf("%f%f",a,b);printf("a,b=%f, %f\n",*a,*b);printf("before call function:\n"); printf("a=%f b=%f\n",*a,*b);fun(a,b);printf("after call function:\n"); printf("a=%f b=%f\n",*a,*b);getch();}【8-18】fun(int *a,int *b,int *c){ int max,min;max=*a;min=*a;if (*b>*a) max=*b;if (*b<*a) min=*b;if (*c>max) max=*c;if (*c<min) min=*c;*a=max;*c=min;}main(){int a,b,c;printf("Input a,b,c: ");scanf("%d%d%d",&a,&b,&c);printf("before call function:\n"); printf("a=%d b=%dc=%d\n",a,b,c);fun(&a,&b,&c);printf("after call function:\n"); printf("max=%d min=%d\n",a,c);getch();}【9-27】#include <ctype.h>main(){ char *s,a[100];int i,k=0,num[10]={0};s=a;printf("Input an number string: "); scanf("%s",s);while(*s!='\0'){ if (isdigit(*s)&&(*s>'0'))num[*s-49]++;if (*s==48) num[9]++;s++;}for (i=0;i<9;i++)printf("%2d-->%3d\n",i+1,num[i]); printf(" 0-->%3d\n",num[9]);printf("***** TOTAL *****\n");for (i=0;i<=9;i++) k+=num[i];printf(" %d ",k);getch();}【9-28】move(int a[10],int n){int i;for (i=n;i<10;i++)a[i-1]=a[i];a[9]=0;}main(){int x[10],i,n;printf("input 10 number:");for(i=0;i<10;i++)scanf("%d",&x[i]);printf("\ninput the N:");scanf("%d",&n);move(x,n);printf("\nAfter move tne member list is :\n");for (i=0;i<10;i++)printf("%d ",x[i]);getch();} 【9-29】main(){int a[100]={0},b[100]={0},i,j;printf("\nInput the number list (end with 32767) :\n ");for(i=0;i<100;i++){scanf("%d",&a[i]);if ( a[i]==32767) break;}i--;odd(a,b,i);printf("\narray B :\n");for (i=0;i<100;i++)if (b[i]!=0) printf("%d ",b[i]); else break;getch();}odd(int a[100],int b[100],int n){ int i,j=0;for(i=0;i<=n;i++)if(a[i]%2!=0) b[j++]=a[i];}【9-30】#include <string.h>sort(char s[],int n){int i,j,p,t;for(j=0;j<(n-1);j++){p=j;for(i=j+1;i<n;i++)if(s[p]<s[i]) p=i;if(p!=j) { t=s[j]; s[j]=s[p];s[p]=t; }}}main(){char *s;int n;printf("\nInput s:");scanf("%s",s);n=strlen(s);sort(s,n);printf("\nthe sorted string is %s\n",s);getch();}【9-31】main(){int a[100],n,*p,i=1;a[0]=-32768; p=a+1;printf("\nInput an number list (end with 32767) :\n");do{scanf("%d",&a[i]);if (a[i]>=a[i-1]) i++;}while(a[i-1]!=32767);printf("\nInput inserted number: "); scanf("%d",&n);p=a;insert(p,n);p=a+1;printf("\nOutput array a:\n");doif (*p!=32767) printf("%d ",*p++); while (*p!=32767);getch();}insert( int *q, int n){ int *k;k=q;while (*q!=32767) q++;*(q+1)=*q;while(q>k){ if (n>*(q-1)) { *q=n; break; }else {q--; *(q+1)=*q; }}}【9-32】main(){int n,a[16]={0},*p;printf("\nInput an number:"); scanf("%d",&n);p=a;change(a,n,p);printf("n=%d\n",n);while(p<=a+15)printf("%d",*p++);}change(x,n,p)int x[16],n,*p;{p=x+15; *p=0;if(n==0) return(0);while(n!=0){*p=n%2;p--;n/=2;}}【9-33】#include <stdio.h>main(){int a[15],*p,i;p=a;frandm(a);printf("\nThe array a is: "); for(i=0;i<15;i++)printf("%d ",*p++);}frandm( a[]);{int k=0,i,x,*q;for (i=0;i<15;i++) a[i]=20; while(k<15){x=rand()%20;for (i=0;i<15;i++)if (a[i]==x ) continue;else a[k++]=x;}}【9-34】#define N 20main(){inta[N][N],x[N]={0},y[N]={0},i,j,m,sum=0 ;printf("\n Input N (<20) :");scanf("%d",&m);printf("\n Input arraya[%d][%d]:\n",m,m);for(i=0;i<m;i++)for(j=0;j<m;j++){ scanf("%d",&a[i][j]);x[i]+=a[i][j]; y[j]+=a[i][j];if (i==j ) sum+=a[i][i];}printf("\n After compute : \n");for (i=0;i<m;i++){ for (j=0;j<m;j++)printf("%5d",a[i][j]);printf("%5d\n",x[i]);}for (i=0;i<m;i++)printf("%5d",y[i]);printf("\n\nSum=%d\n",sum);getch();}【9-35】#define N 20main(){int a[N][N],b[N][N],c[N][N],m,n,i,j; printf("\n Input m,n (<20) :");scanf("%d%d",&m,&n);printf("\n Input arrayA[%d][%d]:\n",m,n);for(i=0;i<m;i++)for(j=0;j<n;j++){ scanf("%d",&a[i][j]);}printf("\n Input arrayB[%d][%d]:\n",m,n);for(i=0;i<m;i++)for(j=0;j<n;j++) { scanf("%d",&b[i][j]);c[i][j]=a[i][j]+b[i][j];}printf("\n After compute array C: \n"); for (i=0;i<m;i++){ for (j=0;j<n;j++)printf("%5d",c[i][j]);printf("\n");}getch();}【9-36】main(){int i,j,k;printf("\n ** A MULTIPLICATION TABLE **\n");printf(" ");for(i=1;i<10;i++)printf("(%3d)",i);printf("\n--------------------------------------------\n");for(i=1;i<10;i++){ for(j=0;j<10;j++)if(j==0) printf("( %d)",i);else printf("%5d",i*j);printf("\n");}printf("\n--------------------------------------------\n");getch();}【9-37】#include "stdio.h"#include "stdlib.h"main(){static int m[5][5]={0},i,j;int k=0;printf("\nBefore :\n");for (i=0;i<5;i++)for(j=0;j<5;j++){ m[i][j]=rand()%100;printf("%4d",m[i][j]);if ((++k)%5==0)printf("\n"); }printf("\nAfter:\n");for (i=0;i<5;i++)for(j=0;j<i;j++){ k=m[i][j]; m[i][j]=m[j][i]; m[j][i]=k; }k=0;for (i=0;i<5;i++)for(j=0;j<5;j++){ printf("%4d",m[i][j]);if ((++k)%5==0)printf("\n"); }printf("\n Program end ! \n");}【9-38】#include "stdio.h"main(){ int m[5][5]={0},i,j;int k=0;printf("\nBefore :\n");for (i=0;i<5;i++)for(j=0;j<5;j++){ m[i][j]=rand()%100;printf("%4d",m[i][j]);if ((++k)%5==0)printf("\n"); }printf("\nAfter:\n");for (i=0;i<5;i++)for(j=0;j<i;j++){ k=m[i][j]; m[i][j]=m[j][i]; m[j][i]=k; }printf("%4d",m[i][j]);if ((++k)%5==0)printf("\n"); }k=0;for (i=0;i<5;i++)for(j=0;j<5;j++) { printf("%4d",m[i][j]);if ((++k)%5==0)printf("\n"); }printf("\n Program end ! \n"); getch();}【10-10】#include <string.h>main(){ char str1[]="string",str2[8],*str3,*str4="string";strcpy(str1,"HELLO1");strcpy(str2,"HELLO2");strcpy(str3,"HELLO3");strcpy(str4,"HELLO4");printf("%s\n%s\n%s\n%s\n",str1,str2,s tr3,str4);getch();}【10-13】main(){char *p[]={"BOOL","OPK","H","SP"}; int i;for(i=3;i>=0;i--,i--)printf("%c",*p[i]);printf("\n");getch();}【10-19】#include <stdio.h>#include <string.h>mygets(s)char *s;{ char ch;ch=getchar();while (ch!=10){*s=ch; s++;ch=getchar();}*s='\0';}myputs(s)char *s;{ int i,n;n=strlen(s);for(i=0;i<n;i++)putchar(*s++);}main(){char *str,s[80];str=s;printf("Input a string:");mygets(str);printf("\nOutput the string:\n"); myputs(str);printf("\n");getch();}【10-20】#include <string.h>main(){ char *str ;str=(char*)malloc(1);printf("Input a string:\n" );gets(str);if (fun(str)) printf("\nThis is back-round-text\n");else printf("\nThis is not back-round-text\n");getch();}fun(char *s){int n,i,j, flag=1;n=strlen(s);for (i=0,j=n-1;i<j;i++,j--)if(*(s+i)!=*(s+j)) flag=0;return(flag);}【10-21】#include <string.h>#include <stdio.h>char deltet(s,n)char *s; int n;{ char ch; if (n>strlen(s)) {printf("\nCANNOT DELETE IT !!! %c",007);return('\0'); }else{ ch=*(s+n);do{ *(s+n)=*(s+n+1); n++; }while(*(s+n-1)!='\0');return(ch);}}main(){char str[80],*p,ch;int n;printf("\nInput a string:\n");p=str+1;gets(p);printf("\nDelete the n'th character: ");scanf("%d",&n);ch=deltet(str,n);printf("\nAfter delete thestring :(ch=%c)\n",ch);for(n=1;n<strlen(str);n++)putchar(*p++);getch();。
《全国计算机等级考试二级教程——C语言程序设计》课后题及参考答案
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《全国计算机等级考试二级教程——Ｃ 语言程序设计》课后题及参考答案 目 录 第一章、第二章、第三章、第四章、第五章、第六章、第七章、第八章、第九章、 第十章、第十一章、第十二章、第十三章、第十四章、第十五章、第十六章 第一章 程序设计基本概念 １．１ 在 ＴＲＵＢＯ Ｃ 环境中用 ＲＵＮ 命令运行一个 Ｃ 程序时，所运行的程序的后缀是。
答案：．ｅｘｅ １．２ Ｃ 语言源程序文件的后缀是，经过编译后，生成文件的后缀是，经过连接后， 生成文件的后缀是。
答案：．ｃ ．ｏｂｊ ．ｅｘｅ １．３ 结构化程序由、、三种基本结构组成。
答案：顺序、选择、循环 第二章 Ｃ 程序设计的初步知识 一、选择题 ２．１ 以下选项中正确的整型常量是 Ａ）１２． Ｂ）－２０ Ｃ）１，０００ Ｄ）４ ５ ６ 答案：Ｂ ２．２ 以下选项中正确的实型常量是 Ａ）０ Ｂ）３． １４１５ Ｃ）０．３２９×１０（２）（１０ 的 ２ 次方） Ｄ）．８７１ 答案：Ｄ ２．３ 以下选项中不正确的实型常量是 Ａ）２．６０７Ｅ－１ Ｂ）０．８１０３ｅ ２ Ｃ）－７７．７７ Ｄ）４５６ｅ－２ 答案：Ｂ ２．４ 以下选项中不合法的用户标识符是 Ａ）ａｂｃ．ｃ Ｂ）ｆｉｌｅ Ｃ）Ｍａｉｎ Ｄ）ＰＲＩＮＴＦ 答案：Ａ ２．５ 以下选项中不合法的用户标识符是 Ａ）＿１２３ Ｂ）ｐｒｉｎｔｆ Ｃ）Ａ￥ Ｄ）Ｄｉｍ 答案：Ｃ ２．６ Ｃ 语言中运算对象必需是整型的运算符是 Ａ）％ Ｂ）／ Ｃ）！ Ｄ）＊＊ 答案：Ａ ２．７ 可在 Ｃ 程序中用作用户标识符的一组标识符是 Ａ）ｖｏｉｄ ｄｅｆｉｎｅ ＷＯＲＤ Ｂ）ａｓ＿ｂ３ ＿１２３ Ｉｆ Ｃ）Ｆｏｒ －ａｂｃ ｃａｓｅ Ｄ）２ｃ ＤＯ ＳＩＧ 答案：Ｂ ２．８ 若变量已正确定义并赋值，符合 Ｃ 语言语法的表达式是 Ａ）ａ＝ａ＋７； Ｂ）ａ＝７＋ｂ＋ｃ，ａ＋＋ Ｃ）ｉｎｔ（１２．３％４） Ｄ）ａ＝ａ＋７＝ｃ＋ｂ 答案：Ｂ ２．９ 以下叙述中正确的是 Ａ）ａ 是实型变量，Ｃ 允许进行以下赋值 ａ＝１０，因此可以这样说：实型变量中允许存放整 型值。
全国计算机等级考试二级教程--C语言程序设计课后习题答案范文
《全国计算机等级考试二级教程--C语言程序设计》课后习题答案第一章1.1 EXE1.2 C OBJ EXE1.3 顺序选择循环第二章一. 选择题2.1 B 2.2 D 2.3 B 2.4 A 2.5 C 2.6 A 2.7 B2.8 B 2.9 D 2.10 C 2.11 B 2.12 B 2.13 A二. 填空题2.14 11 122.15 4.2 4.22.16 { } 定义执行语句2.17 关键字用户标识符2.18 int float double2.19 float a1=1; float a2=1;2.20 存储单元2.213.52.22 (a*b)/c a*b/c a/c*b2.23 把常量10赋给变量s2.24 位1或02.25 8 127 -1282.26 32767 -32768 000002.27 10 8 16三. 上机改错题2.28#include "stdio.h"; 删除行尾的";"main(); / * main function * / 删除")"后的";",注释中的*要紧靠“/”,即应为“/*”和“*/”函数开始处遗失了一个“{”float r,s ; /*/*r is radius*/,/* s is area of circuilar*/*/ 注释符号不可嵌套使用r = 5.0 ;s = 3.14159 * r * r ;printf("%f\n",s) 行尾遗失了“;”函数结束处遗失了一个“}”2.29#include "stdio.h"main /* main function */ main后遗失了“()”{float a,b,c,v; /*a,b,c are sides, v is volume of cube */a=2.0; b=3.0; c=4.0 行尾遗失了“;”printf("%f\n", v) 行尾遗失了“;”}第三章一. 选择题3.1 C 3.2 C 3.3 D 3.4 C 3.5 D 3.6 B 3.7 C 3.8 D 3.9 A 3.10 B3.11 C 3.12 D 3.13 D 3.14 A 3.15 C 3.16 C 3.17 C 3.18 无答案3.19 C 3.20 B二. 填空题3.21 (1)-(2)i=-200,j=2500(3)i=-200j=25003.22 12 0 03.23 一条语句;3.24 ;3.25 100,25.81,1.89234 100 25.81 1.89234 100 25.81 1.892343.26 x=127,x= 127,x= 177,x= 7f,x= 1273.27 x=127,x=127 ,x=$127 ,x=$,x=%06d3.28 a=513.,a= 513.79,a= 513.,a= 513.三. 编程题和改错题3.29 修改后的程序如下：main(){double a,b,c,s,v;printf("input a,b,c:");scanf("%lf%lf%lf",&a,&b,&c);s =a*b;v=a*b*c;printf("a=%f,b=%f,c=%f\n", a,b,c);printf("s=%f,v=%f\n",s,v);}3.30#includemain(){int a=560,b=60;printf("560 minute is %d hour and %d minute.\n",a/b,a%b);}3.31#includemain(){a=1500;b=350;printf("a div b is : %d\n",a/b);printf("a mod b is : %d\n",a%b);}3.32#includemain(){double a,b,c,ave;printf ("input 3 double number : \n");scanf ("%lf%lf%lf",&a,&b,&c);printf ("%.1f\n",(a+b+c)/3);}3.33#includevoid main(){int a,b,c,t;printf("请依次输入整数a,b,c:");scanf("%d%d%d",&a,&b,&c);printf("\n你输入的值是: a=%d,b=%d,c=%d\n",a,b,c);t=b;b=a;a=c;c=t;printf("交换之后的值是:a=%d,b=%d,c=%d\n",a,b,c);}第四章一. 选择题4.1 A 4.2 A 4.3 A 4.4 D 4.5 C 4.6 A 4.7 B 4.8 C 4.9 D 4.10 C二. 填空题4.11 非0 04.12 < > >= <=同级== ！=同级4.13 ! && ||4.15 !4.16 a == b || a < c x > 4 || x < -44.17 14.18 x <= 0 1 > 04.19 3 2 24.20 *#三. 编程题4.21 略4.22/* 检查日期的合法性*/int checkdate(int year, int month, int day){if(year < 1900 || year > 2005){printf("输入的年份无效!\n");return 0;}else if(month < 0 && month > 12){printf("输入的月份无效!\n");return 0;}else if(day <= 0 && day > 31){printf("输入的日期无效!\n");return 0;}else{switch(month){case 4:case 6:case 9:case 11:if(day > 30){printf("输入的日期无效!\n");return 0;}break;case 2:if((year%4 == 0 && year%100 != 0) || year%400 == 0) {if(day > 29){printf("输入的日期无效!\n");return 0;}}elseif(day > 28){printf("输入的出生日期无效!\n"); return 0;}}break;}/* end of switch(m0)*/}return 1;}void main(){int y0, m0, d0; /* 生日*/int y1, m1, d1; /* 当前日期*/int years, months, days; /* 实足年龄*/printf("请输入学生的生日:");scanf("%d%d%d", &y0,&m0,&d0);if(checkdate(y0, m0, d0)){printf("请输入当前日期:");scanf("%d%d%d", &y1,&m1,&d1);/*当前日期合法性检查*/if(!checkdate(y1, m1, d1)){return;}else if(y0 > y1){printf("出生年份比当前年份晚!\n"); return;}else if(y0 == y1){if(m0 > m1){printf("出生年月比当前年月晚!\n"); return;}else if(m0 == m1)if(d0 > d1){printf("出生年月日比当前年月日晚!\n");return;}}}}/* 计算实足年龄*/years = y1 - y0;months = m1 - m0;days = d1 - d0;/* 修正实足年龄天数*/if(days < 0){months--;switch(m1){case 1:case 5:case 7:case 10:case 12:days += 30;break;case 2:case 4:case 6:case 8:case 9:case 11:days += 31;break;case 3:if((y1%4 == 0 && y1%100 != 0) || y1%400 == 0) {days += 29;}else{days += 28;break;}/* end of switch(m1) */}/* end of if(days < 0) *//* 修正实足年龄月数*/if(months < 0){months += 12;years--;}/* end of if(months < 0) */printf("出生日期: %d年%d月%d日\n", y0, m0, d0);printf("当前日期: %d年%d月%d日\n", y1, m1, d1);printf("实足年龄: %d年%d月%d日\n", years, months, days);return;}4.23#includevoid main(){int a;printf ("请输入一个整数:");scanf ("%d",&a);if (a%2==0){printf ("%d 是偶数\n", a);}else{printf ("%d 是奇数\n", a);}}4.24#includevoid main(){int a,b,c,temp,max;printf ("请输入三个整数:");scanf ("%d %d %d",&a,&b,&c);temp=(a>b)? a:b;max=(temp>c)? temp:c;printf ("\n");printf ("你输入的数中最大的是%d.\n",max); }4.25(1)不嵌套的if语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);if ( x>-5 && x<0 ){printf("y is %d\n",y=x);}if ( x==0 ){printf("y is %d\n",y=x-1);}if ( x>0 && x<10 ){printf("y is %d\n",y=x+1);}if ( x>=10 || x<=-5){printf("error\n");}}(2)嵌套的if语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);printf("\n");if(x < 0){if(x > -5){printf("y is %d.\n",y=x); }else{printf("error!\n");}}if(0 == x){printf("y is %d.\n",y=x-1); }if(x > 0){if(x < 10){printf("y is %d.\n",y=x+1); }else{printf("error!\n");}}}(3)if_else语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);if( x>-5 && x<0 ){printf("y is %d.\n",y=x); }else if( x==0 ){printf("y is %d.\n",y=x-1); }else if( x>0 && x<10 ) {printf("y is %d.\n",y=x+1); }else{printf("error!\n");}}(4)switch语句#includevoid main(){int x,y;printf("input x : ");scanf("%d",&x);switch (x){case -4:case -3:case -2:case -1:printf("y is %d.\n",y=x); break;case 0:printf("y is %d.\n",y=x-1); break;case 1:case 2:case 3:case 4:case 5:case 6:case 7:case 8:case 9:printf("y is %d.\n",y=x+1); break;default:printf("error!\n");}}第五章一. 选择题5.1 D 5.2 C 5.3 B 5.4 C 5.5 C 5.6 B 5.7 D 5.8 A 5.9 D 5.10 D二. 填空题5.11 5 4 65.12 死循环5.13 -15.14 115.15 d=1.0 k++ k<=n5.16 x>=0 x三. 编程题5.17#includevoid main(){int i;int sig = 1;int sum = 0;for(i=1; i<=101; i++,i++){sum += sig*i;sig *= -1;}printf("sum=%d\n", sum);}5.18(1)#includevoid main(){int i;double m=1.0;double e = 1.0;for(i=1; i<50; i++){m *= i;e += 1/m;}printf("e=%f\n",e);}(2)#includevoid main(){int i=1;double m=1.0;double e = 1.0;while(1/m >= 0.0004){m *= i;e += 1/m;i++;}printf("e=%f\n",e);}5.19#includevoid main(){int year;int col = 0;for(year=1600; year<=2000; year++){if((year%4 == 0 && year%100 != 0) || year%400 == 0) {printf("%d\t", year);col++;if(col%5 == 0){printf("\n");}}}printf("\n");}5.20#include#define N 7void main(){int i;int j;int m;int k = N/2;for(i=0; i {m = i-k;if(m < 0){m *= -1;}for(j=0; j {printf(" ");}for(j=0; j<2*(k-m)+1; j++){printf("*");}printf("\n");}}第六章一. 选择题6.1 B 6.2 D 6.3 A 6.4 A 6.5 B 6.6 D 6.7 D 6.8 B 6.9 A 6.10 A 6.11 C二. 填空题6.12 -16.13 16.14 ctype.h6.15 16.16 10A 20B 30C 40D6.177.29 101.298AB6.18 A7.29B101.2986.19 A B C (每个字符后有三个空格)三. 编程题6.20#include#define N 80void main(){int iLoop = 0;gets(str);while(str[iLoop]){printf("%c-%d\t", str[iLoop],str[iLoop]); iLoop++;if(iLoop%3 == 0){printf("\n");}}printf("\n");}6.21#include#define N 80void main(){char str[N];int num = 0;int iLoop = 0;gets(str);while(str[iLoop]){if(str[iLoop] >= '0' && str[iLoop] <= '9') {num = 10*num + (str[iLoop] - '0');}iLoop++;}printf("%d\n",num);}6.22#include#include#define N 80void main(){char str[N];do{gets(str);num++;}while(strcmp(str, "EOF"));printf("您输入了%d行字符！\n",num);}6.23#include#define N 80void main(){char str[N];int iLoop = 0;int num = 0;gets(str);while(str[iLoop] && iLoop < N){if(str[iLoop] >= 'a' && str[iLoop] <= 'z'){num++;}iLoop++;}printf("您输入了字符中有%d个小写字母！\n",num); }6.24#includevoid main(){int line;int iLoop1;int iLoop2;printf("请输入图案的行数(不大于26):");scanf("%d", &line);for(iLoop1 = 0; iLoop1 < line; iLoop1++){for(iLoop2 = 0; iLoop2 < line - iLoop1; iLoop2++){printf(" ");}for(iLoop2 = 0; iLoop2 < 2*iLoop1+1; iLoop2++) {printf("%c",iLoop1 + 'A');}printf("\n");}}第七章一. 选择题7.1 C 7.2 C 7.3 B 7.4 C 7.5 A 7.6 D 7.7 A二. 填空题7.8 127.9 9.7.10 47.11 n=1 s7.12 <=y z*x7.13 1 s*i 0 f(k)三. 程序调试和编程题7.14fun(int n){ int k,yes;for(k=2; k<=n/2; k++){if(n%k == 0) { yes = 0; break;}else yes = 1;}return yes;}7.15int mymod(int a, int b){return a%b;}7.16double fun(int n){double sum = 0;int iLoop;int sig = -1;for(iLoop=1; iLoop<=n; iLoop++){sig *= -1;sum += sig*1.0/iLoop;}return sum;}7.17double fun(int n){double t = 1.0;int iLoop;long tmp;for(iLoop=2; iLoop<=n; iLoop++){tmp = iLoop*iLoop;t -= 1.0/tmp;}return t;}7.18#include#includedouble fun(double x){return x*x + 5*x + 4;}void main(){int x = 2;printf("y1=%f\n", fun(x));printf("y2=%f\n", fun(x+15));printf("y3=%f\n", fun(sin(x)));}第八章一. 选择题8.1 A 8.2 B 8.3 B 8.4 C 8.5 B 8.6 B 8.7 C 8.8 D 8.9 B 8.10 C 8.11 C 8.12 C8.13 1108.14 7 18.15 (1)char *p=&ch; (2) p=&ch; (3)scanf("%c",p); (4)*p='A'; (5)printf("%c",*p);8.16 (1)s=p+3; (2)s=s-2 (3)50 (4)*(s+1) (5)2 (6)10 20 30 40 50三. 编程题8.17void fun(double x, double y, double *sum, double *div){*sum = x + y;*div = x - y;return;}8.18void fun(double x, double y, double z, double *max, double *min){*max = x;*min = x;if(*max < y){*max = y;}if(*max < z){*max = z;}if(*min > y){*min = y;}if(*min > z){*min = z;}return;}第九章一. 选择题9.1 D 9.2 A 9.3 A 9.4 C 9.5 C 9.6 A 9.7 B 9.8 D 9.9 C 9.10 C9.11 C 9.12 D 9.13 D 9.14 A 9.15 A 9.16 A 9.17 C 9.18 C二. 填空题9.20 69.21 129.22 39.23 27219.24 -850,2,09.25 k=p k9.26 (c=getchar()) c-'A'三. 编程题9.27#include#define N 81int main(){int counter[10] = {0};int iLoop = 0;char str[N];gets(str);while(str[iLoop]){if(str[iLoop] >= '0' && str[iLoop] <= '9') {counter[str[iLoop] - '0']++;}iLoop++;}for(iLoop=0; iLoop < 10; iLoop++){printf("%d - %d\n", iLoop, counter[iLoop]); }return 0;}9.28void fun(int array[], int arraysize, int start) {int iLoop;if(start < arraysize-1){if(start <=0){start = 1;}for(iLoop = start; iLoop < arraysize; iLoop++){array[iLoop-1] = array[iLoop];}}for(iLoop = 0; iLoop < arraysize; iLoop++){printf("No.%d = %d\n", iLoop, array[iLoop]);}}9.29int fun(int arry1[], int arry2[], int arrysize){int iLoop;int counter = 0;for(iLoop = 0; iLoop < arrysize; iLoop++){if(arry1[iLoop] % 2){arry2[counter++] = arry1[iLoop];}}return counter;}9.30void fun(char array[], int arraysize){int iLoop1;int iLoop2;char temp;/* 冒泡排序*/for(iLoop1 = 0; iLoop1 < arraysize - 1; iLoop1++){for(iLoop2 = 0; iLoop2 < arraysize - 1 - iLoop1; iLoop2++) {if(array[iLoop2] < array[iLoop2 + 1]){temp = array[iLoop2];array[iLoop2] = array[iLoop2 + 1];array[iLoop2 + 1] = temp;}}}}#includevoid fun(int array[], int arraysize, int inertNumber) {int iLoop;int iLoop2;if(array[0] < array[arraysize-1]){for(iLoop = 0; iLoop< arraysize; iLoop++){if(array[iLoop] > inertNumber){for(iLoop2 = arraysize - 1; iLoop2 >= iLoop; iLoop2--) {array[iLoop2 + 1] = array[iLoop2];}array[iLoop] = inertNumber;break;}}if(iLoop >= arraysize){array[arraysize] = inertNumber;}}else{for(iLoop = 0; iLoop< arraysize; iLoop++){if(array[iLoop] < inertNumber){for(iLoop2 = arraysize - 1; iLoop2 >= iLoop; iLoop2--) {array[iLoop2 + 1] = array[iLoop2];}array[iLoop] = inertNumber;break;}}if(iLoop >= arraysize){array[arraysize] = inertNumber;}}int main(){int iLoop;int a[20] = {7,6,5,3,2,1};for(iLoop = 0; iLoop < 6; iLoop++) {printf("%d ", a[iLoop]);}printf("\n");fun(a, 6, 0);for(iLoop = 0; iLoop < 7; iLoop++) {printf("%d ", a[iLoop]);}printf("\n");fun(a, 7, 4);for(iLoop = 0; iLoop < 8; iLoop++) {printf("%d ", a[iLoop]);}printf("\n");fun(a, 8, 8);for(iLoop = 0; iLoop < 9; iLoop++) {printf("%d ", a[iLoop]);}printf("\n");return 0;}9.32int fun(int number, int array[]) {int iLoop = 0;int iLoop2;int binLen;int midNumber;int div;int remain;midNumber = number;dodiv = midNumber/2;remain = midNumber%2;midNumber = div;array[iLoop++] = remain;}while(midNumber);binLen = iLoop;for(iLoop2 = 0, iLoop = binLen - 1; iLoop2 < iLoop; iLoop2++, iLoop--) {midNumber = array[iLoop2];array[iLoop2] = array[iLoop];array[iLoop] = midNumber;}return binLen;}9.33#include#include#define N 15void fun(int array[], int arraysize){int x;int iLoop;int iLoop2;for(iLoop = 0; iLoop < arraysize; iLoop++){iLoop2 = 0;x = rand()%20;do{if(x == array[iLoop2] && iLoop > 0){x = rand()%20;iLoop2 = 0;}iLoop2++;}while(iLoop2 < iLoop);array[iLoop] = x;}}int main(){int a[N];int iLoop;fun(a, N);for(iLoop = 0; iLoop < N; iLoop++){printf("%d\n", a[iLoop]);}return 0;}第十章一. 选择题10.1 C 10.2 B 10.3 C 10.4 B 10.5 C 10.6 A 10.7 C 10.8 A 10.9 C 10.10 C二. 填空题10.11 GFEDCB10.12 XYZ10.13 SO10.14 1010.15 Itis10.16 strlen(str)-1 j--10.17 310.18 goodgood！三. 编程题10.19char* mygets(char *str){int iLoop = 0;char ch;while((ch=getchar()) != '\n'){str[iLoop++] = ch;}str[iLoop] = '\0';return str;}char * myputs(char *str)int iLoop = 0;while(str[iLoop]){putchar(str[iLoop++]);}putchar('\n');return str;}10.20#include#includeint fun(char *str){int len;int iLoop1;int iLoop2;int result = 1;len = strlen(str);for(iLoop1 = 0, iLoop2 = len - 1; iLoop1 < iLoop2; iLoop1++, iLoop2--) {if(str[iLoop1] != str[iLoop2]){result = 0;break;}}return result;}int main(){char a[20] = "ABCDCBA";char b[20] = "ABCDEBA";printf("%d\n", fun(a));printf("%d\n", fun(b));return 0;}10.21char fun(char *str, int pos){int len;int iLoop;char ch;len = strlen(str);if(pos > len){return NULL;}ch = str[pos];for(iLoop = pos; iLoop < len - 1; iLoop++) {str[iLoop] = str[iLoop + 1];}str[len-1] = '\0';return ch;}第十一章一. 选择题11.1 D 11.2 B 11.3 A 11.4 C二. 填空题11.5 IJKLEFGHABCD11.6 711.7 811.8 *(s+j) i+1 i11.9 1711.10 (*fun)() (*fun)(a+i*h)/h mypoly三. 编程题11.11#include#include#define N 81int main(int argc, char **argv){char sig;int dig;int pos;char str[N] = {'\0'};char outStr[N] = {'\0'};if(argc < 2){sig = '-';dig = 10;}else{sig = argv[1][0];dig = argv[1][1] - '0';}printf("请输入一个字符串："); gets(str);if(sig == '-'){pos = strlen(str) - dig;if(pos <= 0){pos = 0;}strcpy(outStr, str + pos);}else if(sig == '+'){strcpy(outStr, str);pos = strlen(outStr);if(pos > dig){pos = dig;}outStr[pos] = '\0';}printf("处理后的字串为："); printf("%s\n", outStr);return 0;}11.12#include#includevoid movebin(char *bin){int len;int iLoop;len = strlen(bin);for(iLoop = len; iLoop > 0; iLoop--) {bin[iLoop] = bin[iLoop - 1];}return;}void fun(int n, char *bin){int pos;pos = strlen(bin);if(n == 0){return;}if(n == 1){movebin(bin);bin[0] = '1';return;}movebin(bin);bin[0] = (n%2) + '0';n /= 2;fun(n, bin);return;}int main(){int a = 4;char bin[50] = {""};fun(a, bin);printf("%s\n", bin);return 0;}11.13long fun(int n){if(n == 1){return n;}else{return fun(n-1) + n;}}int main(){int num;int sum;printf("请输入一个自然数："); scanf("%d", &num);sum = fun(num);printf("结果是：%d\n", sum);return 0;}11.14#includeint fun(int n){if(n == 0 || n == 1){return 1;}else{return fun(n-1) + fun(n-2); }}int main(){int result;printf("请输入一个自然数：");scanf("%d", &num);result = fun(num);printf("斐波拉契级数为：%d\n", result);return 0;}第十二章一. 选择题12.1 B 12.2 B 12.3 A 12.4 C 12.5 D 12.6 B 12.7 A 12.8 A二. 填空题12.9 2,5,1,2,3,-212.10 2468第十三章一. 选择题13.1 A 13.2 C 13.3 B 13.4 C 13.5 D 13.6 D 13.7 D二. 填空题13.8 ar=9 ar=9 ar=1113.9 int* s *b三. 编程题13.10#define MYALPHA(C) ((C>='A' && C<='Z') || (C>='a' && C<='z')) ? 1 : 0 13.11#define SWAP(t,x,y) {t tmp; tmp=x; x=y; y=tmp;}13.12#include#includeint main(){int *p;int tmp;int iLoop;int iLoop2;p = (int *)malloc(sizeof(int)*3);scanf("%d%d%d", p,p+1,p+2);for(iLoop = 0; iLoop < 2; iLoop++){for(iLoop2 = 0; iLoop2 < 2 - iLoop; iLoop2++){if(*(p + iLoop2) > *(p + iLoop2 + 1)){tmp = *(p + iLoop2);*(p + iLoop2) = *(p + iLoop2 + 1);*(p + iLoop2 + 1) = tmp;}}}printf("%d %d %d\n", *p, *(p+1), *(p+2));free(p);p = NULL;return 0;}第十四章一. 选择题14.1 D 14.2 D 14.3 D 14.4 A 14.5 C 14.6 C 14.7 C 14.8 B二. 填空题14.9 struct link *next14.10 p->next m>p->data14.11 (struct list*) struct list struct list* struct list return h三. 编程题14.12#include#define N 3struct stud{char num[5], name[10];int s[4];double ave;};void readrec(struct stud array[], int size)int iLoop;for(iLoop=0; iLoop {scanf("%s%s%d%d%d%d", array[iLoop].num, array[iLoop].name, &array[iLoop].s[0], &array[iLoop].s[1],&array[iLoop].s[2], &array[iLoop].s[3]);array[iLoop].ave = (array[iLoop].s[0] + array[iLoop].s[1] +array[iLoop].s[2] + array[iLoop].s[3])/4.0;}return;}void writerec(struct stud array[], int size){int iLoop;for(iLoop=0; iLoop{printf("%s\t%s\t%d\t%d\t%d\t%d\t%f\n",array[iLoop].num,array[iLoop].name,array[iLoop].s[0],array[iLoop].s[1],array[iLoop].s[2],array[iLoop].s[3],array[iLoop].ave);}return;}int main(){struct stud stu[N];readrec(stu, N);writerec(stu, N);return 0;}14.13#include#include#define N 100struct node{int data;struct node* next;int seekMaxValue(struct node *pNode){int max;struct node* pMove;pMove = pNode;max = pMove->data;pMove = pMove->next;while(pMove){if(max < pMove->data){max = pMove->data;}pMove = pMove->next;}return max;}struct node* seekMaxValueAddress(struct node *pNode) {int max;struct node* maxAddress;struct node* pMove;pMove = pNode;max = pMove->data;maxAddress = pMove;pMove = pMove->next;while(pMove){if(max < pMove->data){max = pMove->data;maxAddress = pMove;}pMove = pMove->next;}return maxAddress;}int main()struct node* head;struct node* pNode;int iLoop;head = (struct node*)malloc(sizeof(struct node)); pNode = head;pNode->next = NULL;for(iLoop=0; iLoop {pNode->next = (struct node*)malloc(sizeof(struct node)); pNode = pNode->next;pNode->next = NULL;pNode->data = iLoop;}printf("%d\n", seekMaxValue(head->next));printf("%d\n", seekMaxValueAddress(head->next));return 0;}第十五章一. 选择题15.1 D 15.2 A 15.3 B 15.4 A二. 填空题15.515.6 a^a15.7 a|0xffff15.8 x|0xff0015.9 a=(>>2)15.10 ch|0x20第十六章一. 选择题16.1 B 16.2 C二. 填空题16.3 3 !feof(f1) f2 fclose(f1) fclose(f2)16.4 fopen(fname,"w") ch16.5 "r" !feof(fp) fgetc(fp)16.6 CCCCBBBBAAAA三. 编程题16.7#include#define N 10#define LEN 81int main(){char *str[N] = {"AAAAAAAAA", "BBBBBBBBB", "CCCCCCCCC", "DDDDDDDDD", "EEEEEEEEE", "FFFFFFFFF", "GGGGGGGGG", "HHHHHHHHH","IIIIIIIII","JJJJJJJJJ"};char str2[N][LEN];FILE *fp;int iLoop;fp = fopen("str.txt", "w");if(fp == NULL){printf("创建文件失败！\n"); return 1;}else{for(iLoop = 0; iLoop < N; iLoop++) {fputs(str[iLoop], fp);fputs("\n",fp);}}fclose(fp);fp = fopen("str.txt", "r");if(fp == NULL){printf("打开文件失败！\n"); return 1;}else{for(iLoop = 0; iLoop < N; iLoop++) {fgets(str2[iLoop], LEN - 1, fp);}}fclose(fp);for(iLoop = 0; iLoop < N; iLoop++) {printf("%s", str2[iLoop]);}return 0;}16.8#include#define N 10int main(){float num;int iLoop;FILE *fp;fp = fopen("num.bin", "wb+");if(fp == NULL){printf("创建文件失败！\n"); return 1;}/* 从键盘读入10个数并写文件*/ printf("请输入%d个数：", N);for(iLoop = 0; iLoop < N; iLoop++) {scanf("%f", &num);fwrite(&num, sizeof(num), 1, fp); }/* 文件指针回到开始处*/ rewind(fp);/* 从文件读出10个数并显示*/ for(iLoop = 0; iLoop < N; iLoop++) {fread(&num, sizeof(num), 1, fp); printf("%f\n", num);}/* 移文件指针到第四个数开始处*/ fseek(fp, 3L*sizeof(num), SEEK_SET); /* 读入一个新数据*/printf("请输入一个新数据：");scanf("%f", &num);fwrite(&num, sizeof(num), 1, fp);/* 文件指针回到开始处*/rewind(fp);/* 从文件读出10个数并显示*/for(iLoop = 0; iLoop < N; iLoop++) {fread(&num, sizeof(num), 1, fp); printf("%f\n", num);}/* 关闭文件*/fclose(fp);return 0;}。
二级VISUAL+BASIC-14-1
二级VISUAL BASIC-14-1(总分：66.00，做题时间：90分钟)一、{{B}}选择题{{/B}}(总题数：35，分数：59.00)1.按照“后进先出”原则组织数据的数据结构是{{U}} {{/U}}。
∙ A.队列∙ B.栈∙ C.双向链表∙ D.二叉树（分数：2.00）A.B. √C.D.解析：2.下列叙述中正确的是______。
∙ A. 在窗体的Form_Load事件过程中定义的变量是全局变量∙ B. 局部变量的作用域可以超出所定义的过程∙ C. 在某个Sub过程中定义的局部变量可以与其他事件过程中定义的局部变量同名，但其作用域只限于该过程∙ D. 在调用过程时，所有局部变量被系统初始化为0或空字符串（分数：2.00）A.B.C. √D.解析：[解析] 对于选项A，变量的作用域来讲，Form_Load事件过程和Sub过程是一样的；对于选项B，局部变量的作用域只是它所在的过程中；对于选项D，如果使用Static定义的过程，则过程中的局部变量就是“static”型的，即在每次调用过程时，局部变量的值保持不变。
3.改变驱动器列表框的Drive属性值将激活______事件。
∙ A. Change∙ B. Scroll∙ C. KeyDown∙ D. KeyUp（分数：2.00）A. √B.C.解析：[解析] 驱动器列表框控件的相关属性和事件驱动器列表框的Drive属性，用来设置或返回程序运行时所选择的驱动器名。
当驱动器列表框的Drive属性值发生变化时，会触发驱动器列表框的Change事件。
当驱动器列表框的滚动框被重新定位或沿水平或垂直方向滚动时，会触发驱动器列表框的Scroll事件。
在驱动器列表框获得焦点时，按下或松开键盘上的按键，会触发驱动器列表框的KeyDown或KeyUp事件。
4.能够将组合框Combo1中最后一个数据项删除的语句为______。
∙ bo1.RemoveItem Combo1.ListCount∙ bo1.RemoveItem Combo1.ListCount-1∙ bo1.RemoveItem Combo1.ListIndex∙ bo1.RemoveItem Combo1.ListIndex-1（分数：1.00）A.B. √C.D.解析：[解析] 组合框的RemoveItem方法与列表框删除指定项目的方法相同，格式为：RemoveItem(索引值)，而列表中的项目索引值从0开始，因此最后一项的索引值为ListCount-1。
计算机二级C语言第14章 文件
若文件指针fp已正确指向文件，ch为字符型变量，以下不能把字符输出到文件中的语句是( ) A.fget( fp,ch ); B.fputc(ch,fp); C.fprintf( fp, "%c",ch ); D.fwrite( &ch,sizeof(ch),1,fp);
正确答案：A 【解析】fgetc()从文件读入一个字符到指定变量。fputc()将指定字符写入fp文件中，fprintf(),fwrite()均是写入 文件操作函数。因此选项B,C,D错误。答案为A选项。
到fout所指文件中，但函数不完整：
有以下文件打开语句：
fp=fopen("person.dat",__________ );
要求文本文件person.dat可以进行信息查找和信息的补充录入，若文件不存在还可以建立同名新
文件，则下划线处应填入的是（）。
A."a+" B."w" C."w+" D."wb"
正确答案：A 【解析】选项A中，"a+"表示在文件后面添加数据，如果指定的文件不存在， 系统将用在fopen调用中指定的文件名建立新文件，正确；选项B中，"w" 表示以写的方式打开文本文件，如果指定的文件不存在，系统将用fopen调
目录页
CONTENTS PAGE
计算机二级C语言 第14章 文件
以下关于C语言文件的叙述中正确的是（） A.文件由数据序列组成，其类型可以为二进制文件或文本文件 B.文件由记录序列组成，其类型可以为二进制文件或文本文件 C.文件由字符序列组成，其类型可以为二进制文件或文本文件 D.文件由数据序列组成，其类型只能是二进制文件
《全国计算机等级考试二级教程——C语言程序设计》课后习题详细解答及答案
《全国计算机等级考试二级教程——C语言程序设计》习题分析与详细解答第一章程序设计基本概念习题分析与解答1．1 【参考答案】EXE1．2 【参考答案】［1］.C ［2］.OBJ ［3］.EXE1．3 【参考答案】［1］顺序结构［2］选择结构［3］循环结构第二章C程序设计的初步知识习题分析与解答一、选择题2．1 【参考答案】B)2．2 【参考答案】D)2．3 【参考答案】B)2．4 【参考答案】A)2．5 【参考答案】C)2．6 【参考答案】A)2．7 【参考答案】B)2．8 【参考答案】B)2．9 【参考答案】D)2．10 【参考答案】C)2．11 【参考答案】B)2．12 【参考答案】B)2．13 【参考答案】A)二、填空题2．14 【参考答案】［1］11 ［2］122．15 【参考答案】［1］4.2 ［2］4.22．16 【参考答案】［1］{ ［2］} ［3］定义［4］执行2．17 【参考答案】［1］关键字［2］用户标识符2．18 【参考答案】［1］int ［2］float ［3］double2．19 【参考答案】float a1=1.0, a2=1.0；或float a1=1, a2=1;(系统将自动把1转换为1.0)2．20 【参考答案】存储单元2．21 【参考答案】 3.52．22 【参考答案】［1］a*b/c ［2］a/c*b ［3］b/c*a2．23 【参考答案】把10赋给变量s2．24 【参考答案】［1］位［2］1位二进制数据(0或1)2．25 【参考答案】［1］8 ［2］127 ［3］01111111 ［4］-128 [ 5 ] 100000002．26 【参考答案】［1］32767 ［2］-32768 ［3］10000000000000002．27 【参考答案】［1］十［2］八［3］十六三、上机改错题2．28 【分析与解答】第1行的错误：(1) include是一个程序行，因此在此行的最后不应当有分号(;)。
全国计算机二级c语言学习指南课件与历年真题精讲精析 第14章
二级C语言程序设计 学习指南与历年真题精讲精析
第14章 结构体、共用体和用户定义 类型
C语言中可由用户构造的两种数据类型：
1、结构体（struct）
2、共用体（union）
14.1 用typedef说明一种新类型名 1、C语言允许用typedef说明一种新类型名： typedef 类型名 标识符; 2、“类型名”必须是在此语句之前已有定义的类型标 识符，“标识符”是一个用户定义标识符，用作新的 类型名。typedef语句的作用仅仅是用“标识符”来
struct dent*s=&s[0]
则以下表达式中值为2的是_____。 (&s[0])->m s[0].m
B）*(p++)->m
C）(*p).m
*(&s[0])->m
s[0].m
*s[0].m
*&a
a
√
D）*((++p)->m)
*((&s[1])->m)
*s[1].m
*&b
五、函数之间结构体变量的数据传递 1、向函数传递结构体变量的成员 结构体变量中的每个成员可以是简单变量、数组或指针变量 等，作为成员变量，它们可以参与所属类型允许的任何操作。 2、向函数传递结构体变量 结构体变量作实参时，传递给函数对应形参的是它的值，函
}std,pers[3],* pstd; name sex birthday year month day sc[0] sc[1] sc[2] sc[3]
方法2：在说明一个无名结构体类型的同时，直接进行定义： 如：struct { char name[12]; char sex; struct date birthday; float sc[4];
全国计算机等级测验二级教程C语言程序设计课后习题答案
ｍaiｎ(）ﻫ｛ﻫｉnt a，b; ﻫａ=150０；b＝35０;ﻫprintf(＂a diｖb is: %d\n",ａ／b);
ｐrintf("a mod bis :％d\n",a%ｂ)；ﻫ}
3.32
#inｃlｕde
main（)
{ ﻫdｏublｅａ,b,c,ａve；ﻫpriｎtf("input 3 dｏｕbｌe numｂｅｒ：＼n"); ﻫsｃanf (＂％lf%lｆ%lf",&a,&ｂ,&c)；ﻫpｒｉntf (＂％.1f\n＂,(a＋b+c）/3); ﻫ}ﻫ3.３3 ﻫ＃incｌｕｄe
｝
ﻫ第四章ﻫ一.选择题ﻫ4．1 A4.2 A 4.3 A4.4Ｄ ４.５C４.6Ａ４.7 B 4.８C4.9 D４.10 C
二．填空题
4．1１非00ﻫ4.12 <> >=＜=同级== !＝同级ﻫ４.1３! && ||
4．15 ! ﻫ４.16a =＝b |｜ａ＜cｘ＞4｜| x <－4 ﻫ４．171 ﻫ４.18x<=01＞０ﻫ4.193 22
函数结束处遗失了一个“}”
ﻫ2．2９ﻫ#includｅ"stdｉｏ.h＂
maｉｎ/＊maiｎfunｃtioｎ＊／maｉｎ后遗失了“（)”
｛
floata,b,c，v; /*a,b,c aresides, v isvoluｍe ofｃube */ ﻫa=2．0; b=３.0; c=4.0行尾遗失了“;”ﻫv＝a＊b*c;
1.3顺序 选择 循环
ﻫ第二章ﻫ一.选择题ﻫ2.1 B 2.2 D 2.3 B 2.4Ａ ２.5 C２．6Ａ2.7 B