【2014潍坊二模】山东省潍坊市2014届高三4月模拟考试 理科4份(语数英理综)Word版含答案
2014年潍坊市二模英语试题含word版答案
2014年潍坊市高三第二次模拟考试2014.4第I卷（共105分）第一部分英语知识运用（共两节，满分55分）第一节单项填空（共10小题；每小题1.5分，满分15分）1. If you want to speak English without ______ foreigner’s accent, you have to learn ______ correct pronunciation of those words.A. the; aB. a; theC. a; 不填D. the; 不填2. The MH370 from Malaysia crashed in the southern Indian Ocean, ____ global concern about flight safety. A. to cause B. caused C. causing D. having caused3. A1l the candidates are required to be at the Conference Hall at 2:00 pm ______ otherwise informed.A. unlessB. if .C. whileD. though4. Although faced with stress from constant exams, she lost________ of her enthusiasm for study.A. someB. neitherC. noneD. all5. —________you go to the movies with me tonight? —I’d love to.A. WillB. MustC. MightD. Shall6. It is not quite clear_______ our local government will do with air pollution.A. whetherB. howC. whatD. that7. —How long have you been here , Alice? —Only a few minutes. Susan_______ me here.A. walksB. walkedC. has walkedD. had walked8. Left_______ in the reading room alone quite by accident, the boy felt nervous.A. lockingB. having lockedC. to lockD. locked9. I'd like to place things__________ it is convenient to get them.A. in whichB. whatC. whereD. that10.—I guess you find the speech boring. —_______. I like it.A. Not in the leastB. Don't mention itC. No doubtD. I couldn't agree more第二节完形填空(共30小题;11-20题每小题1分, 21-40小题 1.5分, 满分40分)AA few weeks ago, I was taking a quiet walk in my backyard 11 I saw a baby bird lying in the grass. It must have fallen off the nest high in the branches. I was sure it was dead. But as I tried to pick it up, 12 it moved.To put it back, I placed a ladder 13 the tree and tried to get it near the 14 with the nest. It was then that I saw a neighborhood cat in the leaves. Immediately it came to me that he must have 15 the bird out of the nest when climbing up along the branches and 16 himself up in the tree as well. Climbing up through the branches, I seized him, gave him a 17 “ Hiss!” and dropped him softly tothe ground. He ran off as fast as he could.I gently 18 the baby bird, climbed up the ladder and, stretching my arm out as far as I could,19 it in the nest. Then I said a little prayer for it.In the weeks that followed I looked up at the nest several times ,but only saw the mother bird. I may never know whether my efforts have made a 20 or not. But trying was enough. Sometimes love has to be its own reward.11. A. while B. as C. after D. when12. A. suddenly B. finally C. nearly D. actually13. A. off B. against C. on D. beside14. A. tree B. leaves C. wall D. branch15. A. led B. shaken C. tricked D. blown16. A. trapped B. wounded C. seized D. stored17. A. worrying B. puzzling C. scolding D. surprising18. A. tried on B. picked up C. took out D. turned over19. A. placed B. caught C. fed D. threw20. A. choice B. decision C. difference D. conclusionBA 58-year-old man was sharing his memories of his father. He said his father had been a workaholic who was always busy with his 21 . He 22 came to his son's sports games or activities. 23 , the son said his dad almost never spoke to him. 24 the time the son was 18 years old, in his last year of school, he’d become a very good football player. When his team qualified for the championship, he 25 his father to finally come to see him play this one time; so his dad 26 he'd be there.On the day of the 27 , the son was on the field warming up just 28 the game when he saw his dad come into the stadium with two other men. Then shortly after the game started, his dad 29 with his friends and never returned. It's now been 40 years 30 that day, yet this 58-year-old son says the painful 31 he felt as a teenager is still very real. When his father recently died at age 83, he stood alone next to his dad's coffin at the funeral home and said: “Dad, we could have 32 so much love and good times together, 33 I never knew you.”A father has great power and 34 in the lives of his children. Studies have shown that the No. 135 of troubled boys and young men is that they had fathers who didn’t 36 care. They didn't spend time with their sons so they weren’t 37 to them. There are millions of invisible 38 like this. But “No man stands as tall as when he bends down to help his son.” How about you? Do you need to give more time and 39 to your children? It's never too late to 40 .21. A. family B. work C. hobby D. housework22. A. often B. ever C. even D. never23. A. In fact B. As a result C. Of course D. Above all24. A. At B. In C. By D. For25. A. begged B. advised C. permitted D. ordered26. A. admitted B. pretended C. suspected D. promised27. A. ceremony B. graduation C. championship D. concert28. A. after B. on C. before D. during29. A. stood B. left C. chatted D. sat30. A. since B. until C. after D. before31. A. relief B. disappointment C. fear D. anxiety32. A. lacked B. shared C. received D. mixed33. A. and B. but C. so D. then34. A. trust B. favor C. influence D. courage35. A. reason B. case C. cause D. concern36. A. simply B. only C. initially D. really37. A. close B. similar C. polite D. known38. A. mothers B. sons C. fathers D. players39. A. money B. freedom C. attention D. award40. A. learn B. change C. develop D. adapt第二部分阅读理解（共25小题；每小题2分，满分50分）AIf you didn’t look at them, they weren’t there, right? On seeing those in rags on the corner, I only wanted the light to turn green fast enough so that I wouldn't have to keep pretending not to see them.Then, one day, as I was holding the hand of my best friend Jane who was young but dying of breast cancer, she told me that she made every moment count by slowing down and by seeing everything. I held her hand for five years and then she passed away. She did teach me something. It took a while for her words to really sink in. I can be a slow learner.I started by seeing everything, and focused on their presence. One day I saw a Vietnam veteran(老兵). I asked him what would make his day.“A hot cup of coffee,” he told me.I bought him a cup of coffee a stack of pancakes, some eggs, and so on. After our meal together, I asked him if there was anything else that would make his life a bit easier.“A new pair of socks,” he said.Socks, really? I actually happened to be wearing a nice pair of wool hiking socks at that very moment. I told him that I wanted to give him the pair I was wearing, if he would accept it. Finally, he agreed. We sat down on a bench, and he started to first take off his boots, then remove the black socks that had once been white off his feet. I think a layer or two of skin might have come off with them. Taking his new pair of socks, he held the socks up to his cheeks and said they were warm and smelled as good as me, pools of tears in his eyes.Such a simple luxury I used to take for granted. Now, I always have an extra pair with me in my car. They are always my best pair, just waiting to be given away.41. On seeing the homeless, the author used to_______.A. hide in the cornerB. show mercy to themC. act as if they were not thereD. make fun of them42. What can we learn about the author from Paragraph 2?A. He was slow in learning things.B. His best friend was once a teacher.C. He was sad that his friend was dying.D. He didn't understand Jane's words at first.43. What does the underlined word “them” in the last paragraph but one refer to?A. The veteran's boots.B. The veteran’s feet.C. The wool hiking socks.D. The veteran's old socks.44. Why does the author always have an extra pair of socks in his car?A. To decorate his car.B. To sell it to others.C. To keep it for a change.D. To donate it to a needy person.45. What does the author want to convey to us?A. All men are born equal.B. A beggar’s purse is bottomless.C. Don’t miss doing any good thing.D. Don’t trouble until trouble troubles you.BAmerican high school students are terrible writers, and one education reform group thinks it has an answer: robots. Or, more accurately, robot-readers-computers programmed to scan student essays and spit out a grade.Mark Shermis, professor of the College of Education at the University of Akron, is helping to hold a contest, set up by the William and Flora Hewlett Foundation ( WFHF), that promises $ 100,000 in prize money to programmers who write the best automated grading software. “If you’re a high school teacher and you give a writing task, you're walking home with 150 essays,” Shermis said. “You're going to need some help.”Automated essay grading was first proposed in the 1960s, but computers back then were not up to the task. In the late 1990s, as technology improved, several textbook and testing companies jumpedinto the field. Today, computers are used to grade essays on South Dakota’s student writing assessments and a handful of other exams, including the TOEFL test of English fluency, taken by foreign students.The Hewlett contest aims to show that computers can grade as well as English teachers- only much more quickly and without all that depressing red ink. Automated essay scoring is “objective,”Shermis said. “And it can be done immediately. If students finish an essay at l0 pm, they get a result at 10:0l pm.”Take, for instance, the Intelligent Essay Assessor, a web-based tool marketed by Pearson Education, Inc. Within seconds it can analyze an essay for spelling, grammar, organization, and help students to make revisions. The program scans for key words and analyzes semantic(语义的) patterns, and Pearson claims that it can understand the meaning of text much the same as a human reader.46. The text is written to introduce________.A. robot-readersB. education reform in AmericaC. Hewlett contestD. William and Flora Hewlett Foundation47. What does the underlined phrase "spit out "in Paragraph I probably mean?A. Give.B. Organize.C. Analyze.D. Check.48. From Paragraph 3, we know that in the 1960s _______.A. computers were not easy to getB. automated grading software was popularC. people refused automated essay gradingD. computers couldn't grade essays automatically49. What does Paragraph 4 focus on?A. The prize of Hewlett contest.B. The advantages of automated essay scoring.C. The application of automated essay scoring.D. Teachers' opinions about Hewlett contest.50. The Intelligent Essay Assessor can________.A. rewrite essaysB. underline the mistakes in red inkC. understand the meaning of textD. correct key words and patternsCIn order to increase their job chances after college, Chinese students are turning to a special practice —Eiffel Tower nose jobs (鼻整形术). The latest trend in plastic surgery promises to create a nose that is classic, slim and sloping, similar to the sweeping curve of the Eiffel Tower.Surgeon Wang Xuming said: “We are influenced by the beauty of the Eiffel Tower, we are not content to just add something to the nose, we reconstruct it.” The surgery costs about US $ 10,000 and involves the enlarging of the nose using tissue from the forehead.Hundreds of posters advertising the procedure are put up all over Chongqing city, where surgeon Xuming runs his practice. They show a Western-looking woman with an almost-too- perfect nose, against an outline of the Eiffel Tower.Interestingly, many young women in China are eager to achieve a western appearance, as theybelieve it will give them an advantage in the highly competitive job market. “Some students face a lot of employment pressure after graduation. If their facial features are good, they’ll have more chances of finding a job,”said surgeon Xuming. “We've had students getting the Eiffel Tower nose; it’s helped them a lot.”Apparently, Chinese employers are quite particular about appearances and prefer attractive candidates. Some of them even go as far as putting height and weight requirements in their employment ads. Plastic surgeons across the country are reporting an increase in the number of students choosing beauty “improvement”.According to a Mr. Li, hospital manager at surgeon Xuming’s clinic, most of their customers are female and the bill is taken care of by the family. “They usually come in with their mothers, and tend to be from well-off backgrounds,” he said.51. Chinese college students choose to have a nose operation to_______.A. marry wellB. look coolC. have a good jobD. look like westerners52. What is mainly talked about in Paragraph 3?A. The posters.B. A nose job.C. The Eiffel Tower.D. A plastic surgery procedure.53. It can be inferred from Paragraph 5 that________.A. employers are potential customersB. ads promote the plastic surgeryC. appearance is as important as height and weightD. attractive appearance seems to increase job chances54. From what Mr. Li said we can learn that ________.A. most families can't afford the surgeonB. the number of plastic surgeons is increasingC. patients can be well looked after at the clinicD. their customers are usually from wealthy families55.What’s the author's attitude towards Eiffel Tower nose jobs?A. Skeptical.B. Objective.C. Critical.D. Worried.DLaw enforcement agencies across the United States are using cameras to take pictures of automobile license plates. The idea is to build a computerized collection of information detailing the daily travel of millions of Americans.Detective Mohammed Tabibi uses a license plate reader, also known as a LPR to look for stolen vehicles. “It has somewhat paid. We have caught some people involved in some serious crimes because of the LPR,” said Tabibi.The use of LPRs is growing across the United States. Some are fixed to poles along Roadsides, others are placed in law-enforcement vehicles. Privacy groups are concerned about the growing use ofthese devices. Jay Stanley is with the American Civil Liberties Union (ACLU). “What they are also doing is storing everybody's time, place, and location. And many police departments are holding that information indefinitely. You know in our society, the government doesn’t follow you and invade your privacy and track you unless it has a specific reason that you are involved in wrongdoing,” said Stanley.Kevin Rearden served as Captain of the Arlington county Police, who also headed the county’s Homeland Security Department before he retired. He said county policy called for the LPR information to be kept for six months. “We originally had a two-month period, and the detectives requested the chief extend it to six months because they found in so many investigations, keeping it for two months wasn't long enough,” said Rearden, “but other law enforcement agencies that use the information may store it for unlimited periods of time.”Supporters of privacy rights say they have no problem with police departments taking pictures of license plates to investigate crimes. But Jay Stanley says they're against storing the information for long periods of time.However, Captain Rearden disagrees, “They keep saying the word ‘tracking’. I would be lucky if I could find you in a few places in Arlington at a particular time. By no stretch of the imagination wouldI be able to track you.”56. What does the text mainly tell us?A. The use of LPRs is controversial.B. Privacy protection is important.C. LPRs help investigate crimes.D. ACLU is involved in wrongdoing.57. The function of a LPR itself is to_______.A. give directionsB. take picturesC. identify locationD. analyze information58. Jay Stanley agrees that________.A. tracking people all the time costs too muchB. using LPRs is likely to invade one's privacyC. police are not allowed to store private informationD. every citizen is supposed to support the government59. How long was the LPR information kept in the beginning?A. Two months.B. Six months.C. Two years.D. Unlimited periods of time.60. According to the last paragraph, Kevin Rearden thinks that_______.A. tracking is almost impossibleB. imagination never endsC. he is lucky to live in ArlingtonD. time and place are both important in trackingEItalians were reminded to slow down and relax on World Slow Day, an annual event celebrating life's simple pleasures.“Let’s take this day to stop and think about all the things we miss while we're rushing through our lives,” said Bruno Contigiani, the President of the Art of Living Slowly Association. Contigiani, 62, aone-time high-powered manager, is now an ambassador for the slow life movement around the world. He started the first World Slow Day in 2007 to encourage the values of living and working at a more natural pace, and to make people rethink their daily lifestyle.Contigiani’s association suggests “14 commandments (诫条)” for living better, such as waking up five minutes earlier to enjoy breakfast without rushing. Others include walking whenever possible, and reading in the evenings instead of watching television.This year, Contigiani left Italy where the event has spread around the country for Shanghai, one of the fastest moving cities in the world. The slow-living supporter said he wandered around the busiest streets of the commercial center for an entire afternoon, inviting people to “slow down”. “Among the 14 commandments, the one about waking up five minutes earlier was the most popular by far,”Contigiani said.Back in Italy, the now well-known event hosts a lot of activities, such as reminding people to stop and smell the roses. In central Milan: you would probably be fined if you walk too fast. In parks and public spaces, free yoga and Tai Chi (太极拳) lessons are important parts of the events.Italian farmers' union noted that Italians spent less and less time preparing meals, a habit connected to rising levels of obesity. Therefore, the group said World Slow Day was a good opportunity to remind Italians to take extra time at meals in particular.World Slow Day is by now an international event. A total of 90 “Slow Cities”in 11 countries inspired by the “live well” philosophy are supporting the day.61. What's the best title of the text?A. Slow Life SupportersB. Lifestyle of ItalyC. World Slow DayD. Living Well62. World Slow Day is intended to__________.A. tell people to walk slowlyB. encourage people to enjoy pleasant thingsC. advise people to adjust to modern lifestyleD. remind people to live and work at a natural pace63. Which of the following goes against the “commandments”?A. Walking whenever possible.B. Slowing down to smell flowers.C. Watching TV in the evenings instead of reading.D. Waking up five minutes earlier to enjoy breakfast.64. We know from Paragraph 6 that .A. obesity had little to do with eating quicklyB. free yoga in particular is popular with ItaliansC. Italian farmers' union supported World Slow DayD. Italians spent more and more time preparing meals65. In which section of a newspaper is the text probably put?A. Advertisement.B. Culture.C. Business.D. Entertainment.第Ⅱ卷（共45分）第一节阅读表达（共5小题；每小题3分，满分15分）阅读下面短文并回答问题，然后将答案写到答案纸相应的位置上（请注意题后的词数要求）[1] Calling a taxi is easy ---- you stand in the street and stretch out your hand. But have you tried to call a taxi using a mobile application (软件)? It’s not hard ---- you download a taxi-calling application, input your location and destination, click “calli ng” and wait for a taxi to pick you up. Didi taxi and Kuaidi Taxi are two of the most popular taxi apps.[2] However, what appeals to people about the apps is not only convenience but also potential prizes. In early January, Didi announced that for each successful ride arranged over the app, both passengers and drivers get 10 yuan subsidies (补贴). A few days later, Kuaidi decided to offer 10 yuan for passengers and 15 yuan for drivers per ride.[3] However popular the taxi-calling apps may be, questions have arisen. One big concern is safety. In order to claim as many subsidies as possible, some drivers constantly check the apps to grab more taxi call s, even while they're driving. “It greatly distracts drivers’ attention, thus causing a threat to road safety,” Beijing Review commented. Meanwhile, like many other digital devices, apps may be quite handy for tech-savvy young people, but it could bring a challenge for senior citizens who don't know how to use them, commented China Daily. “As drivers prefer taking taxi orders from apps, they will overlook those p eople standing on the street,” Beijing Review continued.[4] “Taxi-calling apps are a new thing and we should observe them carefully,” said Liu Xiaohua, deputy director of Guangdong Transport Department. “Authorities are expected to regulate the market when they cause saf ety issues or market disorder.”[5] Some cities________________________. Beijing said last month that each taxi is only allowed to be linked with one taxi-calling app, China Daily reported. In Shanghai, drivers will be banned from using these apps during rush hour starting on March l. The city also decided to include these taxi apps in its own taxi-calling service platform.66. What's the main idea of the text? ( no more than 15 words)67. Complete the following sentence using a proper word from Paragraph 2.Apart from saving us money, calling a taxi using a mobile app also brings us__________________. 68. What is Paragraph 3 mainly about? ( no more than 5 words)69. What does the underlined word "they" in Paragraph 4 refer to?70. Fill in the blank in Paragraph 5 with proper words. ( no more than 5 words)第二节写作（满分30分）假设你是李华，你的英国笔友Mike即将完成学业，不久前来信就是否到中国工作询问你的意见。
2014年山东省潍坊市高三考点回扣即高考模拟训练(四)英语试题
2014年山东省潍坊市高三考点回扣即高考模拟训练（四）英语试题第I卷(共105分)第一部分英语知识应用(共两节，满分55分)第一节单项填空(共10小题；每小题1．5分，满分15分)从A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
1．—Oh，my God! I've just broken the vase that my mother likes best．—______________．It can’t be helped．A．That’s fine B．All right C．Never mind D．Not at all2．Paul fell down and broke his wrist，____________ was a pity．A．which B．what C．that D．it3. I must admit you _____________ but I'm afraid the answer is still no．A．will try B．try C．have tried D．had tried4．Lora，you ____________ leave all your books on the floor like this!A．wouldn’t B．mustn’t C．needn’t D．may not5．Mr．Black is willing to do ______________ Mrs．Black tells him to do．A．whichever B．however C．whatever D．whenever6．While reading an interesting story book in my room，______________.A．the light suddenly went out B．the doorbell rangC．someone was shouting outside D．I heard someone shouting outside7．—Is Tom still smoking?—No．By next Saturday he _____________ for a whole month without smoking a single cigarette.A．will go B．will have gone C．goes D．has been going8．Shanghai is the first city in the world _____________ a high-speed maglev train，from the city to Pudong Airport．A．building B．having built C．to have built D. built9．Mother was busy washing dishes ________________ Father was watching TV．A．until B．if C．since D．while10．—I was worried about my math，but Mr．Brown gave me an A.A．Don’t worry about it． B．Congratulations! That’s a difficult course．C．Mr．Brown is very good．D．Good luck to you!第二节完形填空(共两篇，满分40分)阅读下面短文，从短文后各题所给的四个选项(A、B、C和D)中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
山东省潍坊市2014届高三考点回扣即高考模拟训练(四)数学(理)试卷
第I 卷(选择题，共50分)一、选择题：本大题共10小题．每小题5分。
共50分．把正确答案涂在答题卡上.1.已知集合{}{}(){}*2,4124,,,,log x A B C x y x A y B y N ===∈∈∈，，，且，则C 元素个数是A.2B.3C.4D.5 2.已知()():230p x a x x p q -<4;-->⌝⌝，若是的充分不必要条件，则实数a 的取值范围A. 16a a <->或B. 16a a <-≥或C. 16a -≤≤D. 16a -<<3.已知向量()()cos ,2,sin ,1//tan 4a b a b πααα⎛⎫=-=-⎪⎝⎭，且，则等于A.3B. 3-C. 13D. 13- 4.执行右图的程序框图，任意输入一次()()0101x x y y ≤≤≤≤与，则能输出数对(),x y 的概率为 A. 14B.13 C. 23 D. 345.下列说法正确的个数是①“在ABC ∆中，若sin sin A B >>，则A B ”的逆命题是真命题；②“1m =-”是“直线()2110mx m y +-+=和直线320x my ++=垂直”的充要条件；③“三个数,,a b c 成等比数列”是“b =④命题“32,10x R x x ∀∈-+≤”的否定是“33000,10x R x x ∃∈-+>”A.1B.2C.3D.46.已知各项均不为零的数列{}n a ，定义向量()()*1,,,1,n n n n c a a b n n n N +==+∈，则下列命题中是真命题的是A.若对任意的*n N ∈，都有//n n c b 成立，则数列{}n a 是等差数列B.若对任意的*n N ∈，都有//n n c b 成立，则数列{}n a 是等差数列C.若对任意的*n N ∈，都有n n c b ⊥成立，则数列{}n a 是等差数列D.若对任意的*n N ∈，都有n n c b ⊥成立，则数列{}n a 是等比数列7.已知非零向量AB AC与满足102AB AC AB AC BC AB AC AB AC ⎛⎫ ⎪+⋅=⋅= ⎪⎝⎭，且，则ABC ∆为 A.等腰非等边三角形 B.等边三角形C.三边均不相等的三角形D.直角三角形 8.一个篮球运动员投篮一次得3分的概率为a ，得2分的概率为b ，不得分的概率为(),,0,1c a b c ∈⎡⎤⎣⎦，，已知他投篮一次得分的期望是2，则213a b+的最小值为 A. 323 B. 283 C. 143 D. 1639.设不等式组4,010x y x x y +≤⎧⎪-≥⎨⎪-≥⎩表示的平面区域为 D.若圆()()()222:110C x y r r +++=>经过区域D 上的点，则r的取值范围是A. ⎡⎣B.⎡⎣ C. (0, D. ( 10.设()f x 是定义在R 上的偶函数，对x R ∈，都有()()[]22,2,0f x f x x -=+∈-且当时，()112x f x ⎛⎫=- ⎪⎝⎭，若在区间(]2,6-内关于x 的方程()()()log 201a f x xa -+=>恰有3个不同的实数根，则a 的取值范围是A. ()1,2B. ()2,+∞C. (D. )2 第II 卷（非选择题，共100分）二、填空题：本大题共5小题，每小题5分，共25分.把正确答案填在答题卡相应的位置上.11.复数2a i i+-在复平面内所对应的点在实轴上，那么实数a =___________.12.若()5224100125321x a a x a x a x a +=+++⋅⋅⋅+，则的值为____________.13.函数()tan 0y x y a ωω=>=与直线相交于A ，B 两点，且AB 最小值为π，则函数()cos f x x x ωω=-的单调增区间是___________.14.如图，12,F F 是椭圆221:14x C y +=与双曲线2C 的公共焦点，A ，B 分别是12,C C 在第二、四象限的公共点.若四边形12AF BF 为矩形，则2C 的离心率是_________.15.关于函数()()21lg 0x f x x x+=≠，有下列命题： ①其图象关于y 轴对称；②当()0x f x >时，是增函数；当()0x f x <时，是减函数；③()f x 的最小值是lg 2；④()f x 在区间()()1,02,-+∞、上是增函数；⑤()f x 无最大值，也无最小值.其中所有正确结论的序号是_____________.三、解答题：本大题共6小题，共75分.解答应写出必要的文字说明、证明过程或演算步骤.16.（本小题满分12分）已知锐角ABC ∆中内角A 、B 、C 的对边分别为2226cos ,sin 2sin sin a b c a b ab C C A B +==、、，且.（I ）求角C 的值；（II ）设函数()()sin cos 06f x x x πωωω⎛⎫=--> ⎪⎝⎭，且()f x 图象上相邻两最高点间的距离为π，求()f A 的取值范围.17.（本小题满分12分）李先生家住H 小区，他工作在C 科技园区，从家开车到公司上班路上有12L L 、两条路线（如图），1L 路线上有123A A A 、、三个路口，各路口遇到红灯的概率均为12；2L 路线上有12B B 、两个路口，各路口遇到红灯的概率依次为3345，.（I ）若走1L 路线，求最多遇到1次红灯的概率；（II ）若走2L 路线，求遇到红灯次数的X 的数学期望；（III ）按照“平均遇到红灯次数最少”的要求，请你帮助李先生从上述两条路线中选择一条最好的上班路线，并说明理由.18.（本小题满分12分）如图，在底面是正方形的四棱锥P ABCD PA -⊥中，面ABCD ，BD 交AC 于点E ，F 是PC 中点，G 为AC 上一点.（I ）求证：BD FG ⊥；（II ）确定点G 在线段AC 上的位置，使FG//平面PBD ，并说明理由；（III ）当二面角B PC D --的大小为23π时，求PC 与底面ABCD 所成角的正切值.19.（本小题满分12分）已知数列{}n a 是首项为111,44a q ==公比的等比数列，设()*1423log n n b a n N +=∈，数列{}n c 满足n n n c a b =⋅.（I ）求数列{}n c 的前n 项和n S ；（II ）若2114n c m m ≤+-对一切正整数n 恒成立，求实数m 的取值范围. 20.（本小题满分12分）以椭圆()2222:10x y C a b a b+=>>的中心O 为半径的圆称为该椭圆的“准圆”.设椭圆C 的左顶点为P ，左焦点为F ，上顶点为Q ，且满足2,OFQ PQ S OPQ S ∆∆==. （I ）求椭圆C 及其“准圆”的方程；（II ）若椭圆C 的“准圆”的一个弦ED （不与坐标轴垂直）与椭圆C 交于M 、N 两点，试证明：当0OM ON ⋅=时，试问弦ED 的长是否为定值，若是，求出该定值；若不是，请说明理由.21.（本小题满分12分）已知函数()()()211,ln .f x a x x g x x =-+-=（I ）若()()()()1,0a F x g x f x ==-+∞求在，上的最大值； （II ）证明：对任意的正整数n ，不等式()23412ln 149n n n ++++⋅⋅⋅+>+都成立； （III ）是否存在实数()0a a >，使得方程()()()21141,g x f x a e x e ⎛⎫'=+-- ⎪⎝⎭在区间内有且只有两个不相等的实数根？若存在，请求出a 的取值范围；若不存在，请说明理由.。
潍坊2014二模数学试题文科及理科
高三数学(文)2014．04本试卷共5页，分第I 卷(选择题)和第Ⅱ卷(非选择题)两部分．共150分．考试时间120分钟．第I 卷(选择题 共50分)注意事项：1．答卷前，考生务必用0．5毫米黑色签字笔将自己的、号、考试科目填写在规定的位置上。
2．第I 卷每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。
3．第Ⅱ卷必须用0．5毫米黑色签字笔作答，答案必须写在答题卡各题目指定区域相应的位置；如需改动，先划掉原来的答案，然后再写上新的答案，不得使用涂改液，胶带纸、修正带和其他笔。
4．不按以上要求作答以及将答案写在试题卷上的，答案无效。
一、选择题：本大题共10小题。
每小题5分，共50分．在每小题给出的四个选项中，只有一项是符合题目要求的．1.若复数z 满足()1i z i z +=，则的虚部为 A.2i - B.12- C.2i D.122.已知集合{}(){}2210,l 10,A x x B x ox A B g =-≤=-≤⋂=则 A.[]0,2 B.(]0,2 C.(]1,2D.()1,2 3.下列结论正确的是A.若向量a//b ，则存在唯一的实数a b λλ=使B.已知向量,a b 为非零向量，则“,a b 的夹角为钝角”的充要条件是“0a b •<”C.“若3πθ=，则1cos 2θ=”的否命题为“若132πθθ≠≠，则cos ” D.若命题22:,10:,10p x R x x p x R x x ∃∈-+<⌝∀∈-+>，则4.为了调查学生携带手机的情况，学校对高一、高二、高三三个年级的学生进行分层抽样调查.已知高一有学生1000人、高二有1200人；三个年级总共抽取了66人，其中高一抽取了20人，则高三年级的全部学生数为A.1000B.1100C.1200D.13004.已知()()()21sin ,42f x x x f x f x π⎛⎫'=++ ⎪⎝⎭为的导函数，则()'y f x =图象大致是6.已知,αβ表示平面，,m n 表示直线，,m βαβ⊥⊥，给出下列四个结论；①,n n αβ∀⊂⊥；②,n m n β∀⊂⊥；③,//n m n α∀⊂；④,n m n α∃⊂⊥. 则上述结论中正确的个数为A.1B.2C.3D.47.已知函数()2f x x x =+，执行右边的程序框图，若输出的结果是3132，则判断框中的条件应是A. 30n ≤B. 31n ≤C. 32n ≤D. 33n ≤ 8.已知双曲线()2222:10x y C a b a b-=>0,>的左、右焦点分别是12F F 、，过2F 垂直x 轴的直线与双曲线C 的两渐近线的交点分别是M 、N ，若1MF ∆N 为正三角形，则该双曲线的离心率为A.21B.3C.13D.23+9.某几何体的三视图如图所示，则该几何体外接球的表面积为A.43π B.323π C.4π D.16π10.已知定义在R 上的函数()y f x =对任意的x 满足()()1,11f x f x x +=--≤<当时，()3f x x =.函数()1,0,1,0a og x x g x x x⎧>⎪=⎨-<⎪⎩，若函数()()()[)6h x f x g x =--+∞在，上有6个零点，则实数a 的取值围是A.()1077⎛⎫⋃+∞ ⎪⎝⎭，，B.(]117997⎡⎫⋃⎪⎢⎣⎭，，C.(]11199⎡⎫⋃⎪⎢⎣⎭，，D.[)117997⎛⎤⋃ ⎥⎝⎦，， 第II 卷（非选择题 共100分）注意事项：将第II 卷答案用0.5mm 的黑色签字笔答在答题卡的相应位置上.二、填空题：本大题共5小题，每小题5分，共25分.11.已知12,e e 是夹角为60的两个单位向量.若向量1232a e e =+，则a =________。
山东省潍坊市2014届高三数学考点回扣即模拟训练试题 理(四)
山东省潍坊市2014届高三数学考点回扣即模拟训练试题 理〔四〕第I 卷(选择题，共50分)一、选择题：本大题共10小题．每一小题5分。
共50分．把正确答案涂在答题卡上. 1.集合{}{}(){}*2,4124,,,,logxA B C x y x A y B y N ===∈∈∈，，，且，如此C 元素个数是A.2B.3C.4D.52.()():230p x a x x p q -<4;-->⌝⌝，若是的充分不必要条件，如此实数a 的取值范围 A.16a a <->或 B.16a a <-≥或 C.16a -≤≤ D.16a -<<3.向量()()cos ,2,sin ,1//tan 4a b a b πααα⎛⎫=-=- ⎪⎝⎭，且，则等于 A.3B.3-C.13D.13- 4.执行右图的程序框图，任意输入一次()()0101x x y y ≤≤≤≤与，如此能输出数对(),x y 的概率为A.14B.13 C.23D.345.如下说法正确的个数是①“在ABC ∆中，假设sin sin A B >>，则A B 〞的逆命题是真命题；②“1m =-〞是“直线()2110mx m y +-+=和直线320x my ++=垂直〞的充要条件； ③“三个数,,a b c 成等比数列〞是“b ac =〞的既不充分也不必要条件；④命题“32,10x R x x ∀∈-+≤〞的否认是“33000,10x R x x ∃∈-+>〞A.1B.2C.3D.46.各项均不为零的数列{}n a ，定义向量()()*1,,,1,n n n n c a a b n n n N +==+∈，如此如下命题中是真命题的是A.假设对任意的*n N ∈，都有//n n c b 成立，如此数列{}n a 是等差数列 B.假设对任意的*n N ∈，都有//n n c b 成立，如此数列{}n a 是等差数列C.假设对任意的*n N ∈，都有n n c b ⊥成立，如此数列{}n a 是等差数列 D.假设对任意的*n N ∈，都有n n c b ⊥成立，如此数列{}n a 是等比数列7.非零向量AB AC 与满足102AB AC AB AC BC AB AC AB AC ⎛⎫ ⎪+⋅=⋅= ⎪⎝⎭，且，如此ABC ∆为A.等腰非等边三角形B.等边三角形C.三边均不相等的三角形D.直角三角形8.一个篮球运动员投篮一次得3分的概率为a ，得2分的概率为b ，不得分的概率为(),,0,1c a b c ∈⎡⎤⎣⎦，，他投篮一次得分的期望是2，如此213a b+的最小值为 A.323 B.283 C.143D.1639.设不等式组4,010x y x x y +≤⎧⎪-≥⎨⎪-≥⎩表示的平面区域为D.假设圆()()()222:110C xy r r +++=>经过区域D 上的点，如此r 的取值范围是A.⎡⎣B.⎡⎣C.(0, D. (10.设()f x 是定义在R 上的偶函数，对x R ∈，都有()()[]22,2,0f x f x x -=+∈-且当时，()112xf x ⎛⎫=- ⎪⎝⎭，假设在区间(]2,6-内关于x 的方程()()()log 201a f x x a-+=>恰有3个不同的实数根，如此a 的取值范围是 A.()1,2 B.()2,+∞ C.( D.)2第II 卷〔非选择题，共100分〕二、填空题：本大题共5小题，每一小题5分，共25分.把正确答案填在答题卡相应的位置上. 11.复数2a ii+-在复平面内所对应的点在实轴上，那么实数a =___________. 12.假设()5224100125321x a a x a x a x a +=+++⋅⋅⋅+，则的值为____________.13.函数()tan 0y x y a ωω=>=与直线相交于A ，B 两点，且AB 最小值为π，如此函数()3sin cos f x x x ωω=-的单调增区间是___________.14.如图，12,F F 是椭圆221:14x C y +=与双曲线2C 的公共焦点，A ，B 分别是12,C C 在第二、四象限的公共点.假设四边形12AF BF 为矩形，如此2C 的离心率是_________.15.关于函数()()21lg 0x f x x x+=≠，有如下命题：①其图象关于y 轴对称；②当()0x f x >时，是增函数；当()0x f x <时，是减函数； ③()f x 的最小值是lg 2；④()f x 在区间()()1,02,-+∞、上是增函数； ⑤()f x 无最大值，也无最小值.其中所有正确结论的序号是_____________.三、解答题：本大题共6小题，共75分.解答应写出必要的文字说明、证明过程或演算步骤. 16.〔本小题总分为12分〕锐角ABC ∆中内角A 、B 、C 的对边分别为2226cos ,sin 2sin sin a b c a b ab C C A B +==、、，且. 〔I 〕求角C 的值；〔II 〕设函数()()sin cos 06f x x x πωωω⎛⎫=--> ⎪⎝⎭，且()f x 图象上相邻两最高点间的距离为π，求()f A 的取值范围.17.〔本小题总分为12分〕李先生家住H 小区，他工作在C 科技园区，从家开车到公司上班路上有12L L 、两条路线〔如图〕，1L 路线上有123A A A 、、三个路口，各路口遇到红灯的概率均为12；2L 路线上有12B B 、两个路口，各路口遇到红灯的概率依次为3345，.〔I 〕假设走1L 路线，求最多遇到1次红灯的概率； 〔II 〕假设走2L 路线，求遇到红灯次数的X 的数学期望；〔III 〕按照“平均遇到红灯次数最少〞的要求，请你帮助李先生从上述两条路线中选择一条最好的上班路线，并说明理由.18.〔本小题总分为12分〕如图，在底面是正方形的四棱锥P ABCD PA -⊥中，面ABCD ，BD 交AC 于点E ，F 是PC 中点，G 为AC 上一点.〔I 〕求证：BD FG ⊥；〔II 〕确定点G 在线段AC 上的位置，使FG//平面PBD ，并说明理由； 〔III 〕当二面角B PC D --的大小为23π时，求PC 与底面ABCD 所成角的正切值. 19.〔本小题总分为12分〕 数列{}n a 是首项为111,44a q ==公比的等比数列，设()*1423log n n b a n N +=∈，数列{}n c 满足n n n c a b =⋅.〔I 〕求数列{}n c 的前n 项和n S ； 〔II 〕假设2114n c m m ≤+-对一切正整数n 恒成立，求实数m 的取值范围. 20.〔本小题总分为12分〕以椭圆()2222:10x y C a b a b+=>>的中心O .设椭圆C 的左顶点为P ，左焦点为F ，上顶点为Q ，且满足2,OFQ PQ S OPQ ∆∆==. 〔I 〕求椭圆C 与其“准圆〞的方程；〔II 〕假设椭圆C 的“准圆〞的一个弦ED 〔不与坐标轴垂直〕与椭圆C 交于M 、N 两点，试证明：当0OM ON ⋅=时，试问弦ED 的长是否为定值，假设是，求出该定值；假设不是，请说明理由.21.〔本小题总分为12分〕函数()()()211,ln .f x a x x g x x =-+-=〔I 〕假设()()()()1,0a F x g x f x ==-+∞求在，上的最大值； 〔II 〕证明：对任意的正整数n ，不等式()23412ln 149n n n++++⋅⋅⋅+>+都成立； 〔III 〕是否存在实数()0a a >，使得方程()()()21141,g x f x a e x e ⎛⎫'=+-- ⎪⎝⎭在区间内有且只有两个不相等的实数根？假设存在，请求出a 的取值范围；假设不存在，请说明理由.。
山东省潍坊高密市2014届高三4月月考理科综合试题(扫描版).pdf
理综化学参考答案选择题（本题包括7小题，每小题分，共分。
每小题只有一个选项符合题意。
） 7．B 8．9．B 10． 11．C 12． 13．C 28．（1分）（1）2Al +2OH－+6H2O=2 [Al(OH)4]－ + 3H2↑（2分）（）（2分）（）4Al (s)+ 3MnO2 (s) ＝3Mn(s) +2Al2O3(s) ΔH＝1789 kJ/mol（3分）（）Si3N4 +16HF=3SiF4 + 4NH4F （2分） （）0.024 （3分） 减小（2分） （）c(Ce4+)?[c(OH－)]4 （分） ；8 （2分） 29．（1分）（1） 氧化（2分） CO2 + 2e-==CO+O2-（2分） （2）SiO2、Cu（各1分）Fe2+ （2分） 2Fe3+ + Cu=Cu2+ + 2Fe2+（2分） 5.2≤pH＜5.4 （2分） b （2分） 5：11 （3分） ．（1分）．（）CO2在水中存在平衡：CO2+H2OH2CO3HCO3－+H+，有H2SO4存在时，可使上述平衡向左移动，从而减少CO2在水中的溶解，同时吸收挥发出来的HCl气体（分）HCl气体CO2在水中的溶解H2SO4电离出的H+使平衡左移 （）2HCO3－+Ba2+=BaCO3↓+ CO2↑+H2O（分）．（1）碱石灰或生石灰或氢氧化钠固体（任意填一种）（2分） （2）Cu和Cu2O（3分）（）偏小（2分）（）、（分） （）防止F中水蒸气进入D中，并吸收氨气（2分） . （1分）（1）醛基 （1分） （2）（分）（3）G：CH2＝CHOOCCH3 （分） M： （分） （4） +3NaOHCH3COONa++NaBr+ H2O（3分） （5）（分） 24．（12分）（1） RNA聚合酶、DNA解旋酶 核孔 从a到b TCAGCC （2）与蛋白质的加工与运输有关 D （2分） （3） 阻止GA-MYB基因的转录（2分） 启动a-淀粉酶基因的转录（2分） （4）催化大麦种子中储藏的淀粉水解，为种子萌发提供可利用的小分子物质 25．（13分） （1）叶绿体 叶绿素a （2）逐渐下降 28 （3）淀粉和蔗糖的含量 （4）减少（降低） 在叶片中积累 （5）a、c和e （2分） （6）150（2分） C（2分） 26．（9分）（1）光合作用 同化作用 （2）三个 捕食和竞争（2分） （3）次生演替 （4）调节种间关系，维持生态系统相对稳定 （5）y=25x-20ax（2分） 27．（14分） （1）12 （2）紫花腋生 紫花腋生：蓝花腋生：白花腋生=12：3：1（2分）（3）Aabb和aaBb（2分） （4）3：0：1（2分） （5）实验一：出现紫花腋生：紫花顶生：白花腋生：白花顶生=9：3：3：1（或出现四种表现型） 出现紫花顶生：紫花腋生：白花腋生=1：2：1（或出现三种表现型） 实验二：aaBbEe（2分） 出现蓝花腋生：蓝花顶生：白花腋生：白花顶生=9：3：3：1（或出现四种表现型）蓝花腋生：白花顶生=3：1（或出现两种表现型） 35．（12分）（1）促性腺 同期发情 （2）获能 减数第二次分裂中（2分） （3）显微注射 抗凝血酶（2分） （4）桑椹胚或囊胚 胚胎分割 （5）早期胚胎在相同生理环境条件下空间位置的转移（2分） ： ：。
数学_2014年山东省潍坊市高考数学模拟试卷(四)(理科)_(含答案)
2014年山东省潍坊市高考数学模拟试卷（四）（理科）一、选择题：本大题共10小题．每小题5分．共50分．把正确答案涂在答题卡上. 1. 已知集合A ={2, 4}，B ={1, 2, 4}，C ={(x, y)|x ∈A, y ∈B, 且log x y ∈N ∗}，则C 元素个数是（ ）A 2B 3C 4D 52. 已知：p:|x −a|<4，q ：(x −2)(3−x)>0，若￢p 是￢q 的充分不必要条件，则实数a 的取值范围是（ ）A a <−1或a >6B a ≤−1或a ≥6C −1≤a ≤6D −1<a <6 3. 已知向量a →=(cosα, −2)，b →=(sinα, 1)，且a → // b →，则tan(α−π4)等于( ) A 3 B −3 C 13D −134.如图，阅读程序框图，任意输入一次x(0≤x ≤1)与y(0≤y ≤1)，则能输出数对(x, y)的概率为（ ） A 13B 23C 14D 345. 下列说法正确的个数是①“在△ABC 中，若sinA >sinB ，则A >B”的逆命题是真命题；②“m =−1”是“直线mx +(2m −1)y +1=0和直线3x +my +2=0垂直”的充要条件； ③“三个数a ，b ，c 成等比数列”是“b =√ac”的既不充分也不必要条件；④命题“∀x ∈R ，x 3−x 2+1≤0”的否定是“∃x 0∈R ，x 03−x 03+1>0”（ ） A 1 B 2 C 3 D 46. 已知各项均不为零的数列{a n }，定义向量c n→=(a n ,a n+1)，b n →=(n,n +1)，n ∈N ∗．下列命题中真命题是（ ） A 若∀n ∈N∗总有c n → // b n →成立，则数列{a n }是等差数列 B 若∀n∈N∗总有c n → // b n →成立，则数列{a n }是等比数列 C 若∀n ∈N ∗总有c n →⊥b n →成立，则数列{a n }是等差数列 D 若∀n ∈N∗总有c n→⊥b n →成立，则数列{a n }是等比数列7. 已知非零向量AB →与AC →满足(AB →|AB|→+AC →|AC|→)⋅BC →=0，且AB →|AB|→⋅AC →|AC|→=−12，则△ABC 为（ ）A 等腰非等边三角形B 等边三角形C 三边均不相等的三角形D 直角三角形 8. 一个篮球运动员投篮一次得3分的概率为a ，得2分的概率为b ，不得分的概率为c（a, b, c ∈(0, 1)），已知他投篮一次得分的均值为2，2a+13b的最小值为（ ）A 323B 283C 143D 1639. 设不等式组{x +y ≤4y −x ≥0x −1≥0，表示的平面区域为D ，若圆C ：(x +1)2+(y +1)2=r 2(r >0)经过区域D 上的点，则r 的取值范围是（ ）A [2√2, 2√5]B (2√2, 3√2]C (3√2, 2√5]D (0, 2√2)∪(2√5, +∞)10. 设f(x)是定义在R 上的偶函数，对于任意的x ∈R ，都有f(x −2)＝f(2+x)，且当x ∈[−2, 0]时，f(x)=(12)x −1，若在区间(−2, 6]内关于x 的方程f(x)−log a (x +2)＝0恰有3个不同的实数解，则a 的取值范围是（ ）A (1, 2)B (2, +∞)C (1, √43) D (√43, 2)二、填空题：本大题共5小题，每小题5分，共25分.把正确答案填在答题卡相应的位置上. 11. 复数a+i 2−i在复平面内所对应的点在实轴上，那么实数a =________．12. 若(2x 2+1)5=a 0+a 1x 2+a 2x 4+...+a 5x 10，则a 3的值为________．13. 已知函数y =tanωx(ω>0)与直线y =a 相交于A 、B 两点，且|AB|最小值为π，则函数f(x)=√3sinωx −cosωx 的单调增区间是________．14.如图，F 1，F 2是椭圆C 1:x 24+y 2=1与双曲线C 2的公共焦点，A ，B 分别是C 1，C 2在第二、四象限的公共点．若四边形AF 1BF 2为矩形，则C 2的离心率是________．15. 关于函数f(x)=lgx 2+1|x|(x ≠0)，有下列命题①其图象关于y 轴对称；②当x >0时，f(x)是增函数；当x <0时，f(x)是减函数； ③f(x)的最小值是lg2；④f(x)在区间(−1, 0)、(2, +∞)上是增函数； ⑤f(x)无最大值，也无最小值其中所有正确结论的序号是________．三、解答题：本大题共6小题，共75分.解答应写出必要的文字说明、证明过程或演算步骤.16. 已知锐角三角形ABC 中内角A 、B 、C 的对边分别为a ，b ，c ，a 2+b 2=6abcosC ，且sin 2C =2sinAsinB ．（1）求角C 的值；（2）设函数f(x)=sin(ωx −π6)−cosωx(ω>0)，且f(x)图象上相邻两最高点间的距离为π，求f(A)的取值范围．17. 如图，李先生家住H 小区，他工作在C 科技园区，从家开车到公司上班路上有L 1、L 2两条路线，L 1路线上有A 1、A 2、A 3三个路口，各路口遇到红灯的概率均为12；L 2路线上有B 1、B 2两个路口，各路口遇到红灯的概率依次为34，35．（1）若走L 1路线，求最多遇到1次红灯的概率； （2）若走L 2路线，求遇到红灯次数X 的数学期望；（3）按照“平均遇到红灯次数最少”的要求，请你帮助李先生从上述两条路线中选择一条最好的上班路线，并说明理由．18. 如图，在底面是正方形的四棱锥P −ABCD 中，PA ⊥面ABCD ，BD 交AC 于点E ，F 是PC 中点，G 为AC 上一点． （1）求证：BD ⊥FG ；（2）确定点G 在线段AC 上的位置，使FG // 平面PBD ，并说明理由；（3）当二面角B −PC −D 的大小为2π3时，求PC 与底面ABCD 所成角的正切值．19. 已知数列{a n }是首项为a 1=14，公比q =14的等比数列，设b n +2=3log 14a n (n ∈N ∗)，数列{c n }满足c n =a n ⋅b n ． （1）求{b n }的通项公式；（2）若c n ≤14m 2+m −1对一切正整数n 恒成立，求实数m 的取值范围． 20. 以椭圆C:x 2a 2+y 2b 2=1(a >b >0)的中心O 为圆心，√a 2+b 2为半径的圆称为该椭圆的“准圆”．设椭圆C 的左顶点为P ，左焦点为F ，上顶点为Q ，且满足|PQ|=2，S △OPQ =√62S △OFQ． （1）求椭圆C 及其“准圆”的方程；（2）若椭圆C 的“准圆”的一个弦ED （不与坐标轴垂直）与椭圆C 交于M 、N 两点，试证明：当OM →⋅ON →=0时，试问弦ED 的长是否为定值，若是，求出该定值；若不是，请说明理由． 21. 已知函数f(x)=a(x −1)2+x −1，g(x)=lnx ．（1）若a =1，求F(x)=g(x)−f(x)在(0, +∞)上的最小值；（2）证明：对任意的正整数n，不等式2+34+49+...+n+1n>ln(n+1)都成立；（3）是否存在实数a(a>0)，使得方程2g(x)x =f′(x+1)−(4a−1)在区间(1e, e)内有且只有两个不相等的实数根？若存在，请求出a的取值范围；若不存在，请说明理由．2014年山东省潍坊市高考数学模拟试卷（四）（理科）答案1. B2. C3. B4. A5. C6. A7. A8. D9. A10. D11. −212. 8013. [−π3+2kπ,2π3+2kπ](k∈Z)14. √6215. ①③④16. 解：（1）∵ sin2C=2sinAsinB，∴ 由正弦定理有：c2=2ab，由余弦定理有：a2+b2=c2+2abcosC=c2(1+cosC)①又a2+b2=6abcosC=3c2cosC②由①②得1+cosC=3cosC，∴ cosC=12，又0<C<π，∴ C=π3；（2）f(x)=sin(ωx−π6)−cosωx=√3sin(ωx−π3)∵ f(x)图象上相邻两最高点间的距离为π，∴ T=π∴ 2πω=π∴ ω=2∴ f(x)=√3sin(2x−π3)∴ f(A)=√3sin(2A−π3)∵ π6<A <π2，∴ 0<2A −π3<2π3∴ 0<sin(2A −π3)≤1∴ 0<f(A)≤√3．17. 设“走L 1路线最多遇到1次红灯”为事件A ，包括没有遇到红灯和只遇到红灯一次两种情况．则P(A)=C 30×(12)3+C 31×12×(12)2=12，所以走L 1路线，最多遇到1次红灯的概率为12． 依题意，X 的可能取值为0，1，2． P(X =0)=(1−34)×(1−35)=110，P(X =1)=34×(1−35)+(1−34)×35=920，P(X =2)=34×35=920．随机变量X 的分布列为：所以EX =110×0+920×1+920×2=2720．设选择L 1路线遇到红灯次数为Y ，随机变量Y 服从二项分布Y ∼B(3,12)，所以EY =3×12=32．因为EX <EY ， 18. 证明：（1）∵ PA ⊥面ABCD ，四边形ABCD 是正方形，其对角线BD ，AC 交于点E ， ∴ PA ⊥BD ，AC ⊥BD ， ∴ BD ⊥平面PAC ， ∵ FG ⊂平面PAC ， ∴ BD ⊥FG 解（2）：当G 为EC 中点，即AG =34AC 时，FG // 平面PBD ， 理由如下：连接PE ，由F 为PC 中点，G 为EC 中点，知FG // PE ， 而FG Ë平面PBD ，PE ⊂平面PBD ， 故FG // 平面PBD ．解（3）：作BH ⊥PC 于H ，连接DH ，∵ PA ⊥面ABCD ，四边形ABCD 是正方形， ∴ PB =PD ，又∵ BC =DC ，PC =PC ， ∴ △PCB ≅△PCD ，∴ DH ⊥PC ，且DH =BH ，∴ ∠BHD 就是二面角B −PC −D 的平面角， 即∠BHD =2π3，∵ PA ⊥面ABCD ，∴ ∠PCA 就是PC 与底面ABCD 所成的角 连接EH ，则EH ⊥BD ，∠BHE =π3，EH ⊥PC ， ∴ tan∠BHE =BE EH=√3，而BE =EC ，∴EC EH=√3，∴ sin∠PCA =EH EC=√33，∴ tan∠PCA =√22， ∴ PC 与底面ABCD 所成角的正切值是√22或用向量方法：解：以A 为原点，AB ，AD ，AP 所在的直线分别为x ，y ，z 轴建立空间直角坐标系如图所示，设正方形ABCD 的边长为1，则A(0, 0, 0)，B(1, 0, 0)，C(1, 1, 0)，D(0, 1, 0)，P(0, 0, a)(a >0)，E(12,12,0)，F(12,12,a2)，G(m, m, 0)(0<m <√2)(1)BD →=(−1, 1, 0)，FG →=(m −12,m −12,−a2)，BD →×FG →=−m +12+m −12+0=0， ∴ BD ⊥FG（2）要使FG // 平面PBD ，只需FG // EP ，而EP →=(12,12,−a)，由FG →=12EP →可得{m −12=12λ−a2=−aλ，解得l =1，m =34，∴ G(34, 34, 0)，∴ AG →=34AC →， 故当AG =34AC 时，FG // 平面PBD（3）设平面PBC 的一个法向量为u →=(x, y, z)，则{u →⋅BC →=0˙，而PC →=(1,1,−a)，BC →=(0,1,0)，∴ {x +y −az =0y =0，取z =1，得u →=(a, 0, 1)，同理可得平面PDC 的一个法向量为v →=(0, a, 1)，设u →，v →所成的角为β，则|cosβ|=|cos2π3|=12，即|u →||v →|˙=12，∴√a 2+1⋅√a 2+1=12，∴ a =1∵ PA ⊥面ABCD ，∴ ∠PCA 就是PC 与底面ABCD 所成的角， ∴ tan∠PCA =PA AC=√2=√2219. 解：（1）由题意知，a n =(14)n (n ∈N ∗)， 易得b n =3log 14a n −2=3n −2；（2）c n =a n ⋅b n =(3n −2)⋅(14)n ，∴ c n+1−c n =(3n +1)⋅(14)n+1−(3n −2)⋅(14)n =9(1−n)⋅(14)n+1(n ∈N ∗)， ∴ 当n =1时，c 2=c 1=14，当n ≥2时，c n+1<c n ，即c 1=c 2>c 3>c 4>...>c n ，∴ 当n =1时，c n 取最大值是14，又c n ≤14m 2+m −1对一切正整数n 恒成立， ∴ 14m 2+m −1≥14，即m 2+4m −5≥0，解得：m ≥1或m ≤−5． 20. 解：（1）设椭圆的左焦点F(−c, 0)(c >0)， 由S △OPQ =√62S △OFQ 得12ab =√62⋅12bc ，化为a =√62c ． 由|PQ|=2可得√a 2+b 2=2，联立{a =√62c √a 2+b 2=2a 2=b 2+c 2，解得a 2=3，b 2=1，c 2=2．∴ 椭圆C 的标准方程为x 23+y 2=1，椭圆C 的“准圆”的方程为x 2+y 2=4．（2）设直线ED 的方程为y =kx +t ，与椭圆的交点为M(x 1, y 1)，N(x 2, y 2)， 联立{y =kx +tx 23+y 2=1，化为(1+3k 2)x 2+6ktx +3t 2−3=0，∴ x 1+x 2=−6kt1+3k 2，x 1x 2=3t 2−31+3k 2，可得y 1y 2=(kx 1+t)(kx 2+t)=t 2−3k 21+3k 2，由OM →⋅ON →=0，得x 1x 2+y 1y 2=0，即3t 2−31+3k 2+t 2−3k 21+3k 2=4t 2−3k 2−31+3k 2=0，∴ t 2=34(k 2+1)，此时满足△=36k 2t 2−4(1+3k 2)(3t 2−3)=27k 2+3>0成立．则点O 到弦ED 的距离d =2=√t 21+k 2=√34=√32， ∴ |ED|=2√4−34=√13是定值． 21. （1）解：a =1时，f(x)=x 2−x ， F(x)=lnx −x 2+x ，F′(x)=−(2x+1)(x−1)x，由F′(x)=0得x 1=−12，x 2=1，∵ x ∈(0, +∞)，∴ x ∈(0, 1)时，F(x)递减，x ∈(1, +∞)时，F(x)递增， 则x =1为极小值点，也为最小值点， 故F(x)min =F(1)=0．（2）证明：由（1）知lnx ≤x 2−x ，令x =i+1i>1，lni+1i<(i+1i)2−i+1i=i+1i 2，即ln(i +1)−lni <i+1i 2，故∑[n i=1ln(i +1)−lni]<2+34+49+...+n+1n ，即有不等式2+34+49+...+n+1n>ln(n +1)恒成立；（3）解：假设存在实数a(a >0)，使得方程2g(x)x=f′(x +1)−(4a −1)在区间(1e , e)内有且只有两个不相等的实数根． 将方程2g(x)x=f′(x +1)−(4a −1)整理得ax 2+(1−2a)x −lnx =0，设H(x)=ax 2+(1−2a)x −lnx ，由已知可转化为H(x)在(1e , e)内有且只有两个零点， 所以H′(x)=2ax +1−2a −1x =(2ax+1)(x−1)x令H′(x)=0，a >0，解得x 1=1，x 2=−12a（舍去），当x ∈(0, 1)，H′(x)<0，H(x)单调递减，x ∈(1, +∞)，H(x)单调递增． 故H(x)在(1e , e)内有且只有两个零点，只需{H(1e )>0H(1)<0H(e)>0即{a e 2+1−2ae +1>0a +1−2a <0ae 2+(1−2a)e −1>0 则{a <e 2+e2e−1a >1a >1−ee −2e解得1<a <e 2+e 2e−1，即存在a >0，且a 的取值范围是(1, e 2+e2e−1)．。
英语高考模拟卷-潍坊市届高三第二次模拟考试英语试题及答案
山东省潍坊市2014届高三第二次模拟考试英语试题本试卷分第1卷（选择题）和第Ⅱ卷（非选择题）两部分。
第1卷1至10页，第Ⅱ卷11至12页。
满分为150分。
考试用时为120分钟。
第I卷（共105分）注意事项：1．答第1卷前，考生务必将自己的姓名、准考证号、考试科目涂写在答题卡上。
2．每小题选出答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
不能答在试卷上。
第一部分英语知识运用（共两节，满分55分）第一节单项填空（共10小题；每小题1.5分，满分15分）从每题所给的A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
1. If you want to speak English without _______foreigner's accent, you have to learn ________correct pronunciation of those words.A．the；a B．a；the C．a；不填D．the；不填2.The MH370 from Malaysia crashed in the southern Indian Ocean,________global concern about flight safety.A. to causeB.causedC.causingD.having caused3. A1l the candidates are required to be at the Conference Hall at 2:00 pm________ otherwiseinformed．A. unlessB.ifC.whileD.though4. Although faced with stress from constant exams, she lost________ of her enthusiasmforstudy.A. someB.neitherC.noneD.all5. -________you go to the movies with me tonight?- I'd love to．A. WillB.MustC.MightD.Shall6. It is not quite clear_______our local government will do with air pollution.A. whetherB. howC. whatD. that7. - How long have you been here , Alice?- Only a few minutes. Susan_______me here.A. walksB. walkedC. has walkedD. had walked8. Left_______in the reading room alone quite by accident ,the boy felt nervous.A. lockingB. having lockedC. to lockD. locked9. I'd like to place things_______it is convenient to get them.A. in whichB. whatC. whereD. that10.- I guess you find the speech boring.- _______. I like it.A. Not in the leastB. Don't mention itC. No doubtD. I couldn't agree more .第二节完形填空 (共 30小题;11-20题每小题1分,21-40小题 1.5分, 满分40分) 阅列短文 ,掌握其大意，从每题所给的 A .B .C .D四个选项中 ,选出最佳项,并在答题卡上将该项涂黑。
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高三语文注意事项：1．本试题分为选择题和非选择题两部分，共8页。
时间150分钟，满分150分。
2．务必将自己的班级、姓名、座号、考号填涂在答题卡的相应位置。
第1卷（共3 6分）一、（15分，每小题3分）1．下列词语中加点的字，读音全都正确的一项是A．懵．懂měng 混．浊hùn 双曲．线qū削．足适履xuēB．卸载．zǎi 襁．褓qiǎng 压轴．戏zhòu 徇私．舞弊xùnC．症．结zhēng 电荷．hé潜．意识qián 叱．咤风云zhàD．尽．管jìn 强．迫qiǎng 冠．心病guān 龇牙．咧嘴zī2．下列各句中，没有错别字的一句是A．组织跳广场舞成了少数人牟利的手段，为争夺“客源”，她们竞相放大各自的音响音量，吸引人们参加自己的跳舞团队。
B．开出“一毛钱处方”的徐医生说：“根据病情开药，多开药不见得就能把病看好。
”小小处方，映射出了医者的赤诚之心。
C．自称“大师”的刘某伙同他人在养生会所内，利用艾灸故弄悬虚，迷惑顾客，谎称为病人“发功”治病而骗取钱财。
D．火车站周边大量制办、贩卖假证的小广告令人防不胜防。
脚下踩着“牛皮癣”，眼前晃着“小广告”，让人不胜其繁。
3．下列语句中，加点词语使用恰当的一项是A．《南方周末》是“跨地区监督”的典范，其舆论监督的触角伸向全国各地，这种模式已为国内一些新闻媒体所效尤．．。
B．作为一名硕士村官，她最近在捉摸．．如何在信息极其闭塞的村子里通过电子商务把农产品销售出去，增加农民的收入。
C．当看到留守儿童因不敢说话、孤独、交往能力低而卓尔不群．．．．时，我知道，让孩子快乐成长已经成为一种责任。
D．他因一场大病感受到了身体健康的重要，随后跟随体校的老师练起了健美，从此一发．．而不可收．．．．，最终竟练成了健美冠军。
4．下列各句中，标点符号使用正确的一句是A．我们曾经传奇般地翻译、写作、生活。
虽然有些人已经死去了，但他们所经历的生活的幸福是永恒的。
B．房地产开发商在新楼盘售房之初往往采取这样的办法：先将不太好的楼层介绍给客户，却将三四层等好楼层雪藏，声称好楼层已经售罄。
C．我们要和“中国梦”主题系列丛书的主编王先生协商，提出选题计划，再请懂外文的资深编辑对译本做出评估。
D．诗歌既要讲“奇”，又要讲“通”。
所谓“奇”，就是俄国形式主义所说的“陌生化”，而“通”，按我的理解，则是一种诗意的合理性。
5.下列各句中，没有语病、句意明确的一句是A．在马航客机失联第31天，交通运输部召开马航失联客机应急反应领导小组第27次工作会，要求集中舰船加大水下扫测搜寻。
B．今年是焦裕禄逝世第50个年头，清明期间，全国各地群众自发来到位于河南兰考的焦裕禄陵墓前，纪念这位共产党人的楷模。
C．山东省首套扬尘在线监控系统正式启用，现场视频、图像、数据通过3G网络就能传输到智能移动平台、桌面PC机等终端设备进行访问。
D．两会期间，在广场负责安检工作的警犬首次穿上了“小军靴”，给警犬穿鞋主要是为了保护它们的脚爪被路面的碎石、碎玻璃划伤。
二、（9分．每小题3分）阅读下面的文字，完成6～8题。
中国美学的基本精神祝东力尽管中国古代没有西方式的学科分类，因而也就不存在美学学科，但其处理感性领域以及感性与理性之关系的实践和方法却是极其丰富而又独特的，其核心内涵我们称之为“中国美学的基本精神”。
就中国古代艺术而言，其突出的特征之一是对物质媒介的简省，其极端的情况就是所谓“不著一字，尽得风流”。
从诗词、水墨画到戏曲，其形式的平淡、简易甚至枯涩，与西方近代艺术对于物质媒介的高度依赖形成鲜明对照。
西方艺术遵循了一条物质主义的路线，从古典主义艺术到巴洛克艺术再到今天的好莱坞大片，‘感官的盛宴已近于巅峰。
相反，中国艺术则走了一条反物质主义的路线，其要旨在于通过平淡、简易甚至枯涩的形式完成对感性欲望和冲动的节制与升华，从而范导、提升这种感性力量，使它们成为情操、意志和人格的有力支撑，完成从美学向伦理学的过渡。
可以说，这种对感性领域以及感性与理性之关系的应对方式，就是中国美学的基本精神。
文艺复兴以来，西方社会中人的欲望、个性不断释放和张扬，到今天已接近极限；而中国美学精神得以形成的社会基础则在于：由于古代技术条件的限制，中国很早便面临人口规模与资源环境的结构性矛盾，因此对商品生产、消费和物欲自觉地采取了抑制和约束的政策。
由此，也形成了中国美学的基本精神。
说到底，不同的美学精神反映的是不同的文明取向。
自从19世纪中叶以来，西方的学术、文化如潮水一般涌入中国，但我们不能直接把“美”和“艺术”这两个西方美学的中心概念不加批判地移植过来，那样只能把中国美学变成西方美学的中文注释本。
中国美学应具有一种普遍的真正的“美学”品质，也要具有内在的属于中国学术的质的规定性。
王国维的《人间词话》据国学而熔铸叔本华、康德、尼采等人的学说，把“境界”这一概念，从古典过渡到现代，由诗歌拓展到人生，经诗学而沟通哲学，从而使之最后告别传统诗话，提炼为现代中国美学的一个重要范畴。
宗白华通过对艺术作品的分析来寻找中国的美学特征。
他不仅发现了中国传统艺术美的两大类型，即“错彩镂金’’的美与“芙蓉出水”的美，而后者是中国古典艺术所追求的最高的美的境界；他还重新发现了中国传统艺术中的时空意识，由此对中国艺术意境作了精彩绝伦的阐发，揭示了中国艺术独特的意蕴、内涵和精神，找到真正的中国人的美感形态，由此建立中国人自己的美学理论体系。
宗白华的美学研究，无疑具有一种典范的意义。
（选自《社会科学报》，有删改）6．下列对于“中国美学的基本精神”的理解，正确的一项是A．它是中国古代处理感性领域以及感性与理性之关系的极其丰富的实践和方法。
B．它的特征之一是物质媒介十分简省，走的是反物质主义路线，与西方近代艺术相近。
C．它成为情操、意志和人格的有力支撑，能对感性欲望和冲动节制、升华并规范提升。
D．它是对感性领域以及感性与理性之关系的应对方式，即采用的平淡、简易甚至枯涩的形式。
7．下列理解和分析，不符合原文意思的一项是A．中国美学基本精神形成的社会基础是对商品生产、消费和物欲自觉地采取了抑制和约束的政策。
B．中国美学不能移植西方美学的中心概念，那样只能把中国美学变成西方美学的中文注释本。
C．王国维的《人间词话》根据国学熔铸西方学说，把“境界”提炼为现代中国美学的一个重要范畴。
D．宗白华发现的中国传统艺术美类型之一“芙蓉出水”的美，是中国古典艺术所追求的最高的美的境界。
8．根据原文内容，下列理解和分析不正确的一项是A．中国古代没有美学学科，但美学的基本精神能够通过诗词、水墨画和戏曲等艺术形式体现出来。
B．中国古代艺术和西方近代艺术遵循的不同的路线，反映了东西方不同的文明取向。
C．宗白华发现的传统艺术中美的两种类型和时空意识，都揭示了中国艺术独特的意蕴、内涵和精神。
D．王国维和宗白华的美学研究，证明中国美学具有了内在的属于中国学术的质的规定性。
三、（12分，每小题3分）阅读下面的文言文，完成9～12题。
炀皇帝，讳广，高祖第二子也。
上美姿仪，少敏慧，高祖及后于诸子中特所钟爱。
上好学，善属文，沉深严重，朝野属望。
既而高祖幸上所居第，见乐器弦多断绝，又有尘埃，若不用者，以为不好声妓，善之。
上尤自矫饰，当时称为仁孝。
尝观猎遇雨，左右进油衣，上日：“士卒皆沾湿，我独衣此乎！”乃令持去。
八年冬，大举伐陈，以上为行军元帅。
及陈平，执尚书都令史暨慧，以其邪佞，有害于民，斩之右阙下，以谢三吴。
于是封府库，资财无所取，天下称贤。
及太子勇废，立上为皇太子。
初，上自以藩王，次不当立，每矫情饰行，以钓虚名，阴有夺宗之计。
时高祖雅信文献皇后，而性忌妾媵。
皇太子勇内多嬖幸，以此失爱。
帝后庭有子，皆不育之，示无私宠，取媚于后。
大臣用事者，倾心与交。
中使至第，无贵贱，皆曲承颜色，申以厚礼。
婢仆往来者，无不称其仁孝。
又常私入宫掖，密谋于献后，杨素等因机构扇，遂成废立。
四年七月，高祖崩，上即皇帝位于仁寿宫。
以天下承平日久，士马全盛，慨然慕秦皇、汉武之事，乃盛治宫室，穷极侈靡，召募行人，分使绝域。
诸蕃至者，厚加礼赐，有不恭命，以兵击之。
课天下富室，益市武马，匹直十余万，富强坐是冻馁者十家而九。
帝性多诡谲，所幸之处，不欲人知。
每之一所，郡县官人，竞为献食，丰厚者进擢，疏俭者获罪。
奸吏侵渔，人不聊生，人饥相食，邑落为墟，上不之恤也。
东西游幸，靡有定居，每以供费不给，逆收数年之赋。
区宇之内，盗贼蜂起，近臣互相掩蔽，隐贼数不以实对。
或有言贼多者，辄大被诘责。
各求苟免，上下相蒙，每出师徒，败亡相继。
黎庶愤怨，天下土崩，至于就擒，而犹未之寤也。
史臣日：炀帝爰在弱龄，早有令闻，南平吴会，北却匈奴，昆弟之中，独著声绩。
于是矫情饰貌，遂践峻极之崇基。
负其富强之资，思逞无厌之欲。
内怀险躁，外示凝简，盛冠服以饰其奸，除谏官以掩其过。
《书》日：“天作孽，犹可违，自作孽，不可逭注。
”观隋室之存亡，斯言信而有征矣！（节选自《隋书》，有删减》[注释]逭：逃避9．对下列句子中加点词的解释，不正确的一项是A．上好学，善属．文属：写作B．杨素等因机构．扇构：构成C．逆．收数年之赋逆：预先D．思逞无厌．之欲厌：满足10．下列各组句子中，加点词的意义和用法相同的一组是11．以下六句话分别编为四组，全都体现炀帝“矫情饰行”的一组是①乐器弦多断绝，又有尘埃②士卒皆沾湿，我独衣此乎③大举伐陈，以上为行军元帅④帝后庭有子，皆不育之⑤中使至第，无贵贱，皆由承颜色，中以厚礼⑥所幸之处，不欲人知A．①③⑤B．①④⑥C．②③⑥D．②④⑤12．对原文有关内容的理解和分析，下列表述不正确的一项是A．隋炀帝年少时就深得高祖喜爱。
后来高祖到他住处，见到乐器好像很久没有用过，由此认为他不好声妓。
B．太子杨勇因宠爱妃妾而失宠，杨广为显示自己不宠爱妃妾，就对妃妾生的孩子不管不问，以此讨好皇后。
C．隋炀帝性情诡谲，因此，他每到一处，当地官员都会争着供奉美食讨好他，而隋炀帝也会视进奉多少予以奖惩。
D．隋炀帝为满足个人私欲而不顾百姓死活，他的覆灭正好验证了“天作孽，犹可违，自作孽，不可逭”这句话。
第Ⅱ卷（共1 1 4分）四、（24分）13．把文言文阅读材料中加横线的句子翻译成现代汉语。
（10分）(1)每矫情饰行，以钓虚名，阴有夺宗之计。
（3分）(2)课天下富室，益市武马，匹直十余万，富强坐是冻馁者十家而九。
（4分）(3)黎庶愤怨，天下土崩，至于就擒，而犹未之寤也。
（3分）14．阅读下面一首元曲，完成后面的问题。
（8分）[越调]天净沙鲁卿庵中张可久青苔古木萧萧，苍云秋水迢迢。
红叶山斋小小。
有谁曾到？探梅人过溪桥。
[注]此曲为作者访友之作。
鲁卿，隐士。
(1)该元曲前三句描绘了什么样的景色？营造了怎样的意境？（4分）(2)深秋本无梅可赏，作者却自称“探梅人”，如何理解？表达了作者什么样的思想感情？（4分）15．补写出下列名句名篇的空缺部分（6分，每空1分）(1)仰观宇宙之大，____________，_____________，足以极视听之娱，信可乐也。