高三第三次月考试题

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湖南省永州市第一中学2022-2023学年高三上学期第三次月考地理试题(解析版)

湖南省永州市第一中学2022-2023学年高三上学期第三次月考地理试题(解析版)
【点睛】泥沙淤积会导致湖泊萎缩,使得湖泊容水量不断降低。
二、非选择题
17.阅读图文资料,完成下列要求。
材料一 距今20~200万年前,青海湖(图6)还是一个外流湖,湖水通过东南部的倒淌河泄入黄河。后经构造运动,青海湖逐渐演变成闭塞湖,湖水也逐渐变咸。据科学家推测,明朝时期,青海湖面积为5000平方千米,上世纪50年代以后面积逐渐缩小,到2004年达最小,仅为4186平方千米。此后,青海湖面积持续增大,2017年达到4425平方千米。
(3)本题主要考查农业的区位因素。蜂农从甘肃定西来到青海湖追花采蜜的原因:1、定西的花期已经结束;2、定西离青海湖距离较近;3、“四周满是金黄的油菜花,如地毯一样铺开,一直延伸到湖边”说明青海湖周边油菜花盛开,蜜粉源充足;4、当地位于青藏高原东北部,降水少,天气晴好,利于蜜蜂采集花蜜;5、当地正处于旅游旺季,利于销售蜂蜜。
【5题详解】
湖泊空间大小不是影响生物种类的主要因素,故A错误。班公错位于青藏高原西部,降水少,且克什米尔湖区没有淡水注入,所以湖水盐度较高,导致生物匮乏,故B正确。附近区域为山地地形,植被覆盖较好,水流清澈,湖水透明度较高,故C错误。该区域位于青藏高原西部,人口稀少,不会存在过度捕捞的情况,故D错误。所以本题正确答案为B。
A.向南、13米B.向北、13米
C.向东、23米D.向西、13米
13.图中四地,最需要植树造林增加植被覆盖率的地点是( )
A.甲B.乙C.丙D.丁
【答案】12. B 13. D
【解析】
【12题详解】
水往低处流,结合材料“黄土底层为流动性地下含水层”和“虚线是基岩表面(黄土底面)等高线”可知,地下水径流方向应垂直基岩表面等高线(虚线)由高处流向低处,结合乙处附近虚线数值变化规律和指向标,可判断出乙地地下水应向北流动;由等高线可知,乙处黄土表面高度在825~830m之间,乙处基岩表面高度在815~820m之间,故黄土层的厚度应在5~15m之间;综上分析,可知B选项“向北、13米”符合题意,B正确,ACD错误。故选B。

河南省南阳市第一中学校2023-2024学年高三上学期第三次月考地理试题(解析版)

河南省南阳市第一中学校2023-2024学年高三上学期第三次月考地理试题(解析版)

南阳一中2023年秋期高三年级第三次月考地理试题一、选择题组(每小题1.5分,共40题)城市土地出让是指城市政府土地主管部门依法将城市土地的使用权出让给用地单位,是联系城市产业结构与空间结构的纽带。

土地出让空间区位选择与诸多社会经济因素有关,其中人口规模、经济发展水平对土地出让具有重要影响。

下图示意黄山市城市土地出让区位模式。

据此完成下面小题。

1.V区虽位于城市外围,但商业用地和住宅用地规模大,主要原因是()A.位于城市外围,土地租金廉价B.人口规模较市中心大,商业服务需求高C.中心城区环境差,商业服务外迁D.位于旅游景区,经济发展水平高2.黄山市城市用地的分布特点是()A.分布均衡,集聚程度较低B.住宅用地分布在近郊和旅游区C.集中度高,成多中心状态D.中心城区土地利用率较外围低【答案】1.D 2.C【解析】【1题详解】黄山市为旅游业发达的城市,V区可能为旅游区,虽然与市中心距离较远,但旅游业的发展使其土地租金并不廉价,A错误;V区位于城市外围,人口规模并不如市中心大,B错误;没有信息说明中心城区环境质量差,C错误;旅游业的发展带动了经济发展,该地经济发展水平高,商业和度假旅居型、疗养等服务业的发展,使得V区商业用地和住宅用地规模较大,D正确。

故选D。

【2题详解】据图及上题可知,黄山市三类用地区域位置差异较大,A错误;住宅用地主要集中于中心城区、重要旅游区附近,B错误;商业服务用地分布的热点区域主要集中于城市商业集聚区、大型公共设施和旅游景区周围、重要交通设施附近,因此,黄山市各类用地集中程度高,成多中心状态,C正确;中心城区土地利用率较外围高,D错误。

故选C。

【点睛】影响城市土地租金的因素有距离市中心的远近和交通通达度。

波兰首都华沙的工业园区逐步转型成为次级商务区(SBD),其与西南运输走廊(IBD)和主城区的中央商务区(CBD)共同构成华沙的经济增长极。

下图示意华沙经济增长极的空间分布读图,完成下面小题。

长沙市长郡中学2023届高三上学期第三次月考数学试题(含答案)

长沙市长郡中学2023届高三上学期第三次月考数学试题(含答案)
A. B. C. D.
【答案】D
【解析】
【分析】先作出 关于 的对称点 ,再作 关于 的对称点 ,因为光线从 点出发射到 上的 点经 反射后,入射光线和反射光线都经过 关于直线 的对称点 点,又因为再经 反射,反射光线经过 关于直线 的对称点,所以只需连接 、 交 与点 ,连接 、 分别交 为点 、 ,则 , 之间即为点 的变动范围.再求出直线 , 的斜率即可.
A. B.
C. D.
【答案】ABD
【解析】
【分析】观察图形,分析剪掉的半圆的变化,纸板 相较于纸板 剪掉了半径为 的半圆,再分别写出 和 的递推公式,从而累加得到通项公式再逐个判断即可
【详解】根据题意可得纸板 相较于纸板 剪掉了半径为 的半圆,故 ,即 ,故 , , , … ,累加可得 ,所以 ,故A正确,C错误;
6.设 ,则()
A. B.
C. D.
【答案】D
【解析】
【分析】分别判断出 , , ,即可得到答案.
【详解】 .
因为 ,所以 .
所以 ;
因为 在R上为增函数,所以 ;
因为 在 上为增函数,且 所以 ,即 ;
所以 .
故选:D
7.将函数 的图象上所有点向右平移 个单位长度,得到如图所示的函数 的图象,则 ()
10.设 ,函数 在区间 上有零点,则 的值可以是()
A. B. C. 解不等式 得解.
【详解】由题得 ,
令 ,解得 ,取k=0,
,即 .
故选:BCD
11.如图, 是一块半径为1的圆形纸板,在 的左下端前去一个半径为 的半圆后得到图形 ,然后依次剪去一个更小半圆(其直径为前一个前掉半圆的半径)得图形 , ,记纸板 的周长为 ,面积为 ,则下列说法正确的是()

2024学年宝坻区第一中学高三下第三次月考英语试题含解析

2024学年宝坻区第一中学高三下第三次月考英语试题含解析

2024学年宝坻区第一中学高三下第三次月考英语试题注意事项1.考生要认真填写考场号和座位序号。

2.试题所有答案必须填涂或书写在答题卡上,在试卷上作答无效。

第一部分必须用2B 铅笔作答;第二部分必须用黑色字迹的签字笔作答。

3.考试结束后,考生须将试卷和答题卡放在桌面上,待监考员收回。

第一部分(共20小题,每小题1.5分,满分30分)1.— Can you do me a favour, Mr. Smith? My car ______ start.— No problem. Y ou can count on it.A.won’t B.mustn’tC.needn’t D.shouldn’t2.Is it common practice that salesmen receive a _______ of 10 percent on all sales made?A.deposit B.receiptC.pension D.commission3.The old couple, ________ country life, were unwilling to move to the city to live with his son.A.accustomed to B.buried inC.addicted to D.exposed to4."They didn’t take measures in time, otherwise the explosions ____."some experts said.A.wouldn’t happen B.didn’t happenC.wouldn’t have happened D.mustn’t have happened5.If the traffic so heavy, I could have been back by 6 o’clock.A.hadn’t been B.wasn’tC.couldn’t be D.hasn’t been6.--- Did you watch the final match of China Open yesterday?---Sure. I it so attentively that I forgot to cook supper.A.watched B.had watchedC.was watching D.was to watch7.Whether the buildings in this area should be pulled down has remained ____;people are still looking for other possible solutions.A.unchallenged B.relevantC.controversial D.contradictory8.-----My room gets very cold at night.-----_________________.A.So is mine B.So mine is C.So does mine D.So mine does9.Don't give up half way, and you will find the scenery is more beautiful when you reach the destination than when you_______.A.start off B.have started offC.started off D.will start off10.Never in my life ________ such a beautiful sunrise!A.have I seen B.I have seenC.did I see D.I saw11.With WeChat Pay coming into widespread use, our household bills are convenient ____.A.paying B.paid C.to pay D.to be paid12.—What’s the recent progress in Xiong’an New Area, first announced two years ago?—It _____ increasing attention from foreign companies given its huge development potential.A.has been attracting B.had attracted C.would be attracting D.was attracting13.His children were his pride, and being a devoted father became a top ______ in his life.A.capacity B.anxiety C.priority D.opportunity14.Where was it ______ the road accident happened the other day?A.that B.whenC.how D.which15.—Sometimes I am even sleepy in class.—It’s terrible. You _____ as well go to bed earlier.A.should B.willC.might D.can16.—________! Somebody has broken the vase!—Don’t look at me.A.Come on B.Hi,thereC.Thank goodness D.Dear me17.The news came as no surprise to me. I ______ for some time that the factory was going to shut down. A.had known B.knewC.have known D.know18.My mother opened the drawer to ______ the knives and spoons.A.put away B.put up C.put on D.put together19._____ every year, many people do not hold a high opinion of the CCTV Spring Festival Gala, it has become a somewhat necessary part of the festival.A.As B.Therefore C.While D.Since20.Due to a terrible flu that ________ on, many students don’t show up to school today.A.goes B.was going C.is going D.has gone第二部分阅读理解(满分40分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳选项。

邵阳县一中高三第三次月考语文试题(含答案)

邵阳县一中高三第三次月考语文试题(含答案)

邵阳县一中高三第三次月考语文试题命题者:邵阳县一中高三语文备课组一、语言文字运用(12分,每小题3分)1.下列词语中加点的字,读音全都正确的一组是:(C)A.悭吝qiān 绾结wǎn 引擎 qíng 焚膏继晷 jiùB.稽首 qǐ踝骨 huái 铣床 xiǎn 含英咀华 jǔC.戏谑 xuè抨击 pēng 宽宥 yòu 暴虎冯河 píngD.红杉 shā月晕 yùn 楔子 qiè飞来横祸 hèng2.下列词语中,没有错别字的一组是:(B)A. 泄露协从作案同仇敌忾萎靡B. 骁勇严惩不贷明火执仗熏陶C. 福祉平白无故严正申明浩渺D. 磋商坂上走丸留芳百世歉收3.下列各句中,加点成语使用不恰当的一句是:(C)A.手捧方便面,校友们随意入座,没有传统宴席上身份尊卑,地位高低,清贫富有之别。

校庆活动中的这种“返璞归真....”之举,有令人意外的效果。

B.中国的所谓“大局为重”,在日本看来其实就是能忍则忍,即“小不忍则乱大谋”;至于“斗而不破”,则被他们解读为隔靴搔痒....,“坏不到哪里去”的理论依据。

C.实践与探讨新课程背景下高中语文“人本课堂”,就要把死气沉沉的语文课变成栩栩..如生..的“活语文”,就是要构建高效语文课堂。

D.近年来,学校开展了丰富多样的活动,大大提高了学生的综合素质,纷至沓来....的获奖喜讯报告着这所百年名校在新时代里教育的成功。

4.下列各句中,没有语病的一句是:(B)A.前不久,上海率先提交市人大审议并制订的《上海市商品包装物减量若干规定(草案)》,首次对销售过度包装商品设立了惩罚性规则,最高罚款5万元。

B.新近发布的《新媒体蓝皮书:中国新媒体发展报告(2012)》认为,微博用户数量的持续增加,以及“思想表达和参政议政的移动化传播”的强化,将改变中国的舆论生态,进而会影响和改变中国的社会政治生态。

高三物理月考题(含答案)

高三物理月考题(含答案)

高三物理第三次月考试题一、选择题(本大题13小题,每小题4分,共42分。

在每小题给出的四个选项中,有的小题只有一个选项正确,有的小题有多个选项正确。

全部选对的得4分,选不全的得2分,有错选或不答的得0分。

)1、某班同学从山脚下某一水平线上同时开始沿不同路线爬山,最后所有同学都陆续到达山顶上的平台。

则下列结论正确的是()A、体重相等的同学,克服重力做的功一定相等B、体重相同的同学,若爬山路径不同,重力对它们做的功不相等C、最后到达山顶的同学,克服重力做功的平均功率最小D、先到达山顶的同学,克服重力做功的平均功率最大1.A解析:所有同学爬山过程中,初末位置的高度差相等,都是由低处到高处,重力都做负功,即克服重力做功。

有与重力的功与路径无关,体重相等的同学,重力的功相等,克服重力的功相等。

选项A正确B错误;最先到达山顶的同学所用时间最短,但克服重力的功可能较小,平均功率不一定最大。

最后到达山顶的同学所用时间最长,但克服重力的功可能较大,平均功率不一定最小。

2、一蹦极运动员身系弹性蹦极绳从水面上方的高台下落,到最低点时距水面还有数米距离。

假定空气阻力可忽略,运动员可视为质点,下列说法正确的是()A、运动员到达最低点前重力势能始终减小B、蹦极绳张紧后的下落过程中,弹性力做负功,弹性势能增加C、蹦极过程中,运动员、地球和蹦极绳所组成的系统机械能守恒D、蹦极过程中,重力势能的改变与重力势能零点的选取有关2.ABC。

解析:不管选那个位置为重力势能参考面,运动员到达最低位置前高度总是减小的,因此重力势能一直是减小的。

绳紧张后,随着运动员的下降,绳伸长,对运动员作用向上的弹力,此力做负功,同时伸长量增大,弹性势能增加。

由于空气阻力可以忽略,蹦极过程中,对于运动员、地球、绳系统来说,只有重力与弹力做功,系统的机械能守恒。

重力势能与重力势能参考平面的选取有关,而重力势能的变化量则与此无关。

3、如图所示,质量不同的两物体通过轻绳相连,M >m,滑轮光滑且质量不计,轻绳的伸长不计,空气阻力不计。

长郡中学2023届高三第三次月考语文试题

长郡中学2023届高三第三次月考语文试题

长郡中学2023届高三第三次月考语文试题
一、单项选择(每小题2分,共30分)1.今天,他站在角落里,模
样憔悴得好像一把()。

A.老针B.旧磨刀C.衰草D.凋零的花2.就在我们
展望未来的同时,也要记住在一切的发展中不可忽视的是()。

A.社会义
务B.历史传承C.民族文化D.个人能力3.天下危在旦夕,()变化着中国
的命运。

A.动荡的潮流B.空前的绝后C.稳定的现状D.日新月异的4.在我
们这里,家长们都希望自己的孩子能够立足于()。

A.心灵B.社会C.母
校 D.大众5.为生活寻求一个发挥自我体验自由的更宽阔的容器,这是()的不可抹去的宿命。

A.人间B.世界C.上帝D.社会二、短文填空(每小题
1分,共15分)请根据下文内容,在空格处填入一个最恰当的词语。


明的发展,变革的实践,可以从人类尊重自然开始,开始依靠自然,以自
然为伴,这种共生共存的思想,就是一种文明发展的思想,就是一种文明()。

关爱自然和传承文化,这两者本来就相连,而传承文化,就是要用
文化把历史上积淀下来的经验,传递给后代,形成一种智慧的()。

答案:观念,守护。

湖南省长沙市湖南师大附中2024-2025学年高三上学期第三次月考数学试题(含解析)

湖南省长沙市湖南师大附中2024-2025学年高三上学期第三次月考数学试题(含解析)

湖南师大附中2025届高三月考试卷(三)数学时量:120分钟满分:150分得分:________________一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.集合的真子集个数是( )A.7B.8C.15D.162.“”是“”的( )A.充分不必要条件 B.必要不充分条件C.充要条件D.既不充分也不必要条件3.已知角的终边上有一点的坐标是,其中,则( )A.B.C.D.4.设向量,满足,等于( )A. B.2C.5D.85.若无论为何值,直线与双曲线总有公共点,则的取值范围是( )A. B.C.,且 D.,且6.已知函数的图象关于原点对称,且满足,且当时,,若,则等于( )A.B.C. D.7.已知正三棱台所有顶点均在半径为5的半球球面上,且棱台的高为( )A.1B.4C.7D.1或78.北宋数学家沈括博学多才、善于观察.据说有一天,他走进一家酒馆,看见一层层垒起的酒坛,不禁想到:{}0,1,2,311x -<240x x -<αP ()3,4a a 0a ≠sin2α=4372524252425-a b a b += a b -=a b ⋅ θsin cos 10y x θθ⋅+⋅+=2215x y m -=m 1m ≥01m <≤05m <<1m ≠1m ≥5m ≠()2f x ()()130f x f x ++-=()2,4x ∈()()12log 2f x x m =--+()()2025112f f -=-m 132323-13-111ABC A B C -AB =11A B =“怎么求这些酒坛的总数呢?”经过反复尝试,沈括提出对于上底有个,下底有个,共层的堆积物(如图所示),可以用公式求出物体的总数,这就是所谓的“隙积术”,相当于求数列,的和.若由小球堆成的上述垛积共7层,小球总个数为238,则该垛积最上层的小球个数为()A.2B.6C.12D.20二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.9.若,则下列正确的是()A. B.C. D.10.对于函数和,下列说法中正确的有()A.与有相同的零点B.与有相同的最大值点C.与有相同的最小正周期D.与的图象有相同的对称轴11.过点的直线与抛物线交于,两点,抛物线在点处的切线与直线交于点,作交于点,则()A.B.直线恒过定点C.点的轨迹方程是D.的最小值为选择题答题卡题号1234567891011得分ab cd n()()()2266n nS b d a b d c c a⎡⎤=++++-⎣⎦ab()()()()()()11,22,,11a b a b a n b n cd+++⋅++-+-=2024220240122024(12)x a a x a x a x+=++++2024a=20240120243a a a+++=012320241a a a a a-+-++=12320242320242024a a a a-+--=-()sin cosf x x x=+()sin cos22g x x xππ⎛⎫⎛⎫=---⎪ ⎪⎝⎭⎝⎭()f x()g x()f x()g x()f x()g x()f x()g x()0,2P2:4C x y=()11,A x y()22,B x yC A2y=-N NM AP⊥AB M5OA OB⋅=-MNM()22(1)10y x y-+=≠ABMN答案三、填空题:本题共3小题,每小题5分,共15分.12.已知复数,的模长为1,且,则________.13.在中,角,,所对的边分别为,,已知,,,则________.14.若正实数是函数的一个零点,是函数的一个大于e 的零点,则的值为________.四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15.(本小题满分13分)现有某企业计划用10年的时间进行技术革新,有两种方案:贷款利润A 方案一次性向银行贷款10万元第1年利润1万元,以后每年比前一年增加的利润B 方案每年初向银行贷款1万元第1年利润1万元,以后每年比前一年增加利润3000元两方案使用期都是10年,贷款10年后一次性还本付息(年末结息),若银行贷款利息均按的复利计算.(1)计算10年后,A 方案到期一次性需要付银行多少本息?(2)试比较A 、B 两方案的优劣.(结果精确到万元,参考数据:,)16.(本小题满分15分)如图,四棱锥中,底面为等腰梯形,.点在底面的射影点在线段上.(1)在图中过作平面的垂线段,为垂足,并给出严谨的作图过程;(2)若.求平面与平面所成锐二面角的余弦值.17.(本小题满分15分)1z 2z 21111z z +=12z z +=ABC ∆A B C a b c 5a =4b =()31cos 32A B -=sin B =1x ()2e e xf x x x =--2x ()()()3e ln 1e g x x x =---()122e ex x -25%10%101.12.594≈101.259.313≈P ABCD -ABCD 222AD AB BC ===P Q AC A PCD H 2PA PD ==PAB PCD已知函数,为的导数.(1)证明:当时,;(2)设,证明:有且仅有2个零点.18.(本小题满分17分)在平面直角坐标系中,已知椭圆的两个焦点为、,为椭圆上一动点,设,当时,.(1)求椭圆的标准方程.(2)过点的直线与椭圆交于不同的两点、(在,之间),若为椭圆上一点,且,①求的取值范围;②求四边形的面积.19.(本小题满分17分)飞行棋是大家熟悉的棋类游戏,玩家通过投掷骰子来决定飞机起飞与飞行的步数.当且仅当玩家投郑出6点时,飞机才能起飞.并且掷得6点的游戏者可以连续投掷骰子,直至显示点数不是6点.飞机起飞后,飞行步数即骰子向上的点数.(1)求甲玩家第一轮投掷中,投郑次数的均值)(2)对于两个离散型随机变量,,我们将其可能出现的结果作为一个有序数对,类似于离散型随机变量的分布列,我们可以用如下表格来表示这个有序数对的概率分布:(记,)()e sin cos x f x x x =+-()f x '()f x 0x ≥()2f x '≥()()21g x f x x =--()g x xOy 2222:1(0)x y C a b a b+=>>1F 2F P C 12F PF θ∠=23πθ=12F PF ∆C ()0,2B l M N M B N Q C OQ OM ON =+ OBMOBNS S OMQN X 11()()lim ()n n k k E X kP k kP k ∞→∞==⎛⎫== ⎪⎝⎭∑∑ξη()()()11,m i i ijj p x p x p x y ξ====∑()()()21,njjiji p y p y p x y η====∑ξη1x 2x ⋯nx 1y ()11,p x y ()21,p x y ⋯()1,n p x y ()21p y 2y ()12,p x y ()22,p x y()2,n p x y ()22p y1若已知,则事件的条件概率为.可以发现依然是一个随机变量,可以对其求期望.(ⅰ)上述期望依旧是一个随机变量(取值不同时,期望也不同),不妨记为,求;(ⅱ)若修改游戏规则,需连续掷出两次6点飞机才能起飞,记表示“甲第一次未能掷出6点”表示“甲第一次掷出6点且第二次未能掷出6点”,表示“甲第一次第二次均掷出6点”,为甲首次使得飞机起飞时抛掷骰子的次数,求.⋯⋯⋯⋯⋯⋯my ()1,m p x y ()2,m p x y ⋯(),n m p x y ()2m p y ()11p x ()12p x()1n p x i x ξ={}j y η={}{}{}()()1,,j i i j jii i P y x p x y Py x P x p x ηξηξξ=======∣i x ηξ=∣{}{}1mi j j i j E x y P y x ηξηξ===⋅==∑∣∣()()111,mj i j i i y p x y p x ==⋅∑ξ{}E ηξ∣{}E E ηξ⎡⎤⎣⎦∣0ξ=1ξ=2ξ=ηE η湖南师大附中2025届高三月考试卷(三)数学参考答案题号1234567891011答案CACBBDABBCACDBC一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.C 【解析】集合共有(个)真子集.故选C.2.A 【解析】解不等式,得,解不等式,得,所以“”是“”的充分不必要条件.3.C 【解析】根据三角函数的概念,,,故选C.4.B 【解析】.5.B 【解析】易得原点到直线的距离,故直线为单位圆的切线,由于直线与双曲线总有公共点,所以点必在双曲线内或双曲线上,则.6.D 【解析】依题意函数的图象关于原点对称,所以为奇函数,因为,故函数的周期为4,则,而,所以由可得,而,所以,解得.7.A 【解析】上下底面所在外接圆的半径分别为,,过点,,,的截面如图:{}0,1,2,342115-=240x x -<04x <<11x -<02x <<11x -<240x x -<44tan 33y a x a α===22sin cos 2tan 24sin211tan 25ααααα===+()2211()()1911244a b a b a b ⎡⎤⋅=+--=⨯-=⎣⎦ 1d ==2215x y m -=()1,0±01m <≤()f x ()f x ()()()133f x f x f x +=--=-()f x ()()20251f f =()()11f f -=-()()2025112f f -=-()113f =()()13f f =-()121log 323m --=13m =-13r =24r =A 1A 1O 2O,,,故选A.8.B 【解析】由题意,得,,则由得,整理得,所以.因为,为正整数,所以或6.因此有或而无整数解,因此.故选B.二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.9.BC 【解析】对于A :令,则,故A 错误;对于B :令,则,故B 正确;对于C :令,则,故C 正确;对于D ,由,两边同时求导得,令,则,故D 错误.故选BC.10.ACD 【解析】,.令,则,;令,则,,两个函数的零点是相同的,故选项A 正确.的最大值点是,,的最大值点是,,两个函数的最大值虽然是相同的,但最大值点是不同的,故选项B 不正确.由正弦型函数的最小正周期为可知与有相同的最小正周期,故选项C 正确.曲线的对称轴为,,曲线的对称轴为,,两个函数的图象有相同的对称轴,故选项D 正确.故选ACD.11.BC 【解析】作图如下:24OO ==13OO ==211h OO OO ∴=-=6c a =+6d b =+()()()772223866b d a b dc c a ⎡⎤++++-=⎣⎦()()()()77262126623866b b a b b a a a ⎡⎤++++++++-=⎣⎦()321ab a b ++=773aba b +=-<a b 3ab =6,3a b ab +=⎧⎨=⎩5,6.a b ab +=⎧⎨=⎩63a b ab +=⎧⎨=⎩6ab =0x =01a =1x =20240120243a a a +++= 1x =-012320241a a a a a -+-++= 2024220240122024(12)x a a x a x a x +=++++ 202322023123202420242(12)232024x a a x a x a x ⨯⨯+=++++ 1x =-12320242320244048a a a a -++-=- ()4f x x π⎛⎫=+ ⎪⎝⎭()3244g x x x πππ⎛⎫⎛⎫=--=-⎪ ⎪⎝⎭⎝⎭()0f x =4x k ππ=-+k ∈Z ()0g x =34x k ππ=+k ∈Z ()f x 24k ππ+k ∈Z ()g x 324k ππ-+k ∈Z 2πω()f x ()g x 2π()y f x =4x k ππ=+k ∈Z ()y g x =54x k ππ=+k ∈Z设直线的方程为(斜率显然存在),,,联立消去整理可得,由韦达定理得,,A.,,故A 错误;B.抛物线在点处的切线为,当时,,即,直线的方程为,整理得,直线恒过定点,故B 正确;C.由选项B 可得点在以线段为直径的圆上,点除外,故点的轨迹方程是,故C 正确;D.,则,,,则,设,,当单调递增,所以,故D 错误.故选BC.三、填空题:本题共3小题,每小题5分,共15分.AB 2y tx =+211,4x A x ⎛⎫ ⎪⎝⎭222,4x B x ⎛⎫ ⎪⎝⎭22,4,y tx x y =+⎧⎨=⎩x 2480x tx --=124x x t +=128x x =-221212444x x y y =⋅=1212844OA OB x x y y ⋅=+=-+=- C A 21124x x x y ⎛⎫=+ ⎪⎝⎭2y =-11121244282222x x x x x t x x =-=-=+=-()2,2N t -MN ()122y x t t +=--xy t=-MN ()0,0M OP O M ()22(1)10y x y -+=≠2MN AB ===22ABMN ===m =m ≥12ABm MN m ⎛⎫=- ⎪⎝⎭()1f m m m =-m ≥()2110f m m=+>'m ≥()f m min ()f m f==12.1【解析】设,,因为,所以.因为,,所以,所以,所以,,所以.【解析】在中,因为,所以.又,可知为锐角且.由正弦定理,,于是.将及的值代入可得,平方得,故.14.e 【解析】依题意得,,即,,,即,,,,,又,,同构函数:,则,又,,,,又,,单调递增,,.四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15.【解析】(1)A 方案到期时银行贷款本息为(万元).……(3分)()1i ,z a b a b =+∈R ()2i ,z c d cd =+∈R 21111z z +=1222111z z z z z z +=111z z =221z z =121z z +=()()i i i 1a b c d a c b d -+-=+-+=1a c +=0b d +=()()12i 1z z a c b d +=+++=ABC ∆a b >A B >()31cos 32A B -=A B -()sin A B -=sin 5sin 4A aB b ==()()()5sin sin sin sin cos cos sin 4B A A B B A B B A B B ⎡⎤==-+=-+-⎣⎦()cos A B -()sin A B -3sin B B =2229sin 7cos 77sin B B B ==-sin B =1211e e 0xx x --=1211e e xx x -=10x >()()322e ln 1e 0x x ---=()()322e ln 1e x x --=2e x >()()()131122e e e e ln 1x x x x x ∴-==--()()()11122e e ln 1e x x x x +∴-=--()()()21ln 11112e e ln 1e e x x x x -++⎡⎤∴-=--⎣⎦2ln 1x > 2ln 10x ->∴()()1e e ,0x F x x x +=->()()312ln 1e F x F x =-=()()111e e e e e 1e x x x x F x x x +++=-+'=-+0x > 0e e 1x ∴>=e 10x ∴->1e 0x x +>()0F x ∴'>()F x 12ln 1x x ∴=-()()()31222222e ln 1e e e eeex x x x ---∴===()1010110%26⨯+≈(2)A 方案10年共获利:(万元),……(5分)到期时银行贷款本息为(万元),所以A 方案净收益为:(万元),……(7分)B 方案10年共获利:(万元),……(9分)到期时银行贷款本息为(万元),……(11分)所以B 方案净收益为:(万元),……(12分)由比较知A 方案比B 方案更优.……(13分)16.【解析】(1)连接,有平面,所以.在中,.同理,在中,有.又因为,所以,,所以,,故,即.又因为,,平面,所以平面.平面,所以平面平面.……(5分)过作垂直于点,因为平面平面,平面平面,且平面,有平面.……(7分)(2)依题意,.故为,的交点,且.所以过作直线的平行线,则,,,两两垂直,以为原点建立如图所示空间直角坐标系,()1091.2511125%(125%)33.31.251-+++++=≈- 1010(110%)25.9⨯+≈33.325.97-≈()()101010.31 1.3190.310123.52⨯-⨯++++⨯=⨯+= ()()10109 1.11.11(110%)(110%)110%17.51.11-++++++=≈- 23.517.56-≈PQ PQ ⊥ABCD PQ CD ⊥ACD ∆2222cos 54cos AC AD CD AD CD ADC ADC =+-⋅⋅∠=-∠ABC ∆222cos AC ABC =-∠180ABC ADC ∠+∠= 1cos 2ADC ∠=()0,180ADC ∠∈ 60ADC ∠=AC =222AC CD AD +=AC CD ⊥PQ AC Q = PQ AC ⊂PAC CD ⊥PAC CD ⊂PCD PCD ⊥PAC A AH PC H PCD ⊥PAC PCD PAC PC =AH ⊂PAC AH ⊥PCD AQ DQ ==Q AC BD 2AQ ADCQ BC==23AQ AC ==PQ ==C PQ l l AC CD C则:,,,,所以,,,.设平面的法向量为,则取.同理,平面的法向量,,……(14分)故所求锐二面角余弦值为.……(15分)17.【解析】(1)由,设,则,当时,设,,,,和在上单调递增,,,当时,,,则,函数在上单调递增,,即当时,.()1,0,0D P ⎛ ⎝()A 12B ⎛⎫- ⎪ ⎪⎝⎭()1,0,0CD = CP ⎛= ⎝ 0,AP ⎛= ⎝ 1,2BP ⎛= ⎝ PCD (),,m x y z =)0,0,m CD x m CP y ⎧⋅==⎪⎨⋅=+=⎪⎩()0,m =- PAB )1n =-1cos ,3m n m n m n ⋅==13()e cos sin xf x x x =+'+()e cos sin xh x x x =++()e sin cos xh x x x =+'-0x ≥()e 1x p x x =--()sin q x x x =-()e 10x p x ='-≥ ()1cos 0q x x ='-≥()p x ∴()q x [)0,+∞()()00p x p ∴≥=()()00q x q ≥=∴0x ≥e 1x x ≥+sin x x ≥()()()e sin cos 1sin cos sin 1cos 0xh x x x x x x x x x =-+≥+-+=-++≥'∴()e cos sin x h x x x =++[)0,+∞()()02h x h ∴≥=0x ≥()2f x '≥(2)由已知得.①当时,,在上单调递增,又,,由零点存在定理可知,在上仅有一个零点.……(10分)②当时,设,则,在上单调递减,,,,在上单调递减,又,,由零点存在定理可知在上仅有一个零点,综上所述,有且仅有2个零点.……(15分)18.【解析】(1)设,为椭圆的焦半距,,,当时,最大,此时或,不妨设,当时,得,所以,又因为,所以,.从,而椭圆的标准方程为.……(3分)(2)由题意,直线的斜率显然存在.设,.……(4分),同理,..……(6分)联立,……(8分)()e sin cos 21xg x x x x =+---0x ≥()()e cos sin 220x g x x x f x =+='+--'≥ ()g x ∴[)0,+∞()010g =-< ()e 20g πππ=->∴()g x [)0,+∞0x <()2sin cos (0)e x x xm x x --=<()()2sin 10exx m x -=≤'()m x ∴(),0-∞()()01m x m ∴>=e cos sin 20x x x ∴++-<()e cos sin 20x g x x x ∴=++-<'()g x ∴(),0-∞()010g =-< ()e 20g πππ--=+>∴()g x (),0-∞()g x ()00,P x y c C 12122F PF p S c y ∆=⋅⋅00y b <≤ 0y b =12F PF S ∆()0,P b ()0,P b -()0,P b 23πθ=213OPF OPF π∠=∠=c =12F PF S bc ∆==1b =c =2a =∴C 2214x y +=l ()11: 2.,l y kx M x y =+()22,N x y 1112OBM S OB x x ∆∴=⋅=2OBN S x ∆=12OBM OBN S xS x ∆∆∴=()22222,141612044y kx k x kx x y =+⎧⇒+++=⎨+=⎩,.……(9分)又,,,同号..,,.令,则,解得,.……(12分)(3),.且四边形为平行四边形.由(2)知,,.而在椭圆上,.化简得.……(14分)线段,……(15分)到直线的距离……(16分).……(17分)()()222Δ(16)4121416430k k k∴=-⨯⨯+=->234k ∴>1221614k x x k -+=+ 12212014x x k=>+1x ∴2x ()()2222122121212216641421231414k x x x x k k x x x x k k -⎛⎫ ⎪++⎝⎭∴===++++234k > ()2226464164,1331434k k k ⎛⎫∴=∈ ⎪⎛⎫+⎝⎭+ ⎪⎝⎭211216423x x x x ∴<++<()120x x λλ=≠116423λλ<++<()1,11,33λ⎛⎫∈ ⎪⎝⎭()1,11,33OBM OBN S S ∆∆⎛⎫∴∈ ⎪⎝⎭ OQ OM ON =+()1212,Q x x y y ∴++OMQN 1221614k x x k -+=+()121224414y y k x x k ∴+=++=+22164,1414k Q k k -⎛⎫∴ ⎪++⎝⎭Q C 2222164441414k k k -⎛⎫⎛⎫∴+⨯= ⎪ ⎪++⎝⎭⎝⎭2154k =∴MN ====O MN d ==OMQN S MN d ∴=⋅==四边形19.【解析】(1),,2,3,…,所以,,2,3,…,记,则.作差得:,所以,.故.……(6分)(2)(ⅰ)所有可能的取值为:,.且对应的概率,.所以,又,所以.……(12分)(ⅱ),;,;,,,故.……(17分)()11566k P X k -⎛⎫==⨯ ⎪⎝⎭1k =()56k k k P X k ⋅==1k =()21111512666nn k kP k n =⎛⎫=⨯+⨯++⨯ ⎪⎝⎭∑ 211112666n n S n =⨯+⨯++⨯ 2311111126666n n S n +=⨯+⨯++⨯ 1211111511111111661666666556616n n n n n n n S n n ++⎛⎫- ⎪⎛⎫⎛⎫⎝⎭=+++-⨯=-⨯=-+ ⎪⎪⎝⎭⎝⎭- 611155566n n n S ⎡⎤⎛⎫⎛⎫=⋅-+⎢⎥ ⎪⎪⎝⎭⎝⎭⎢⎥⎣⎦()16615556n nn k kP k S n =⎛⎫⎛⎫==-+ ⎪⎪⎝⎭⎝⎭∑116616()()lim ()lim 5565nn n n k k E X kP k kP k n ∞→∞→∞==⎡⎤⎛⎫⎛⎫⎛⎫===-+=⎢⎥ ⎪⎪ ⎪⎝⎭⎝⎭⎝⎭⎢⎥⎣⎦∑∑{}E ηξ∣{}i E x ηξ=∣1,2,,i n = {}{}()()()1ii i p E E x p x p x ηξηξξ=====∣∣1,2,,i n = {}()()()()()111111111[{}],,nnm n m i i j i j i j i j i i j i j i E E E x p x y p x y p x y p x y p x ηξηξ=====⎛⎫==⋅=⋅= ⎪ ⎪⎝⎭∑∑∑∑∑∣∣()()()()21111111,,,n m m n mn mj i j j i j j i j j j i j j i j i j y p x y y p x y y p x y y p y E η=======⎛⎫⋅=⋅==⋅= ⎪⎝⎭∑∑∑∑∑∑∑{}E E E ηξη⎡⎤=⎣⎦∣{}01E E ηξη==+∣156p ={}12E E ηξη==+∣2536p ={}22E η==3136p ={}()()5513542122636363636E E E E E E ηηηηηξ⎡⎤==++++⨯=+⎣⎦∣42E η=。

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2014-2015学年度上学期第三次月考高三英语试题考试时间:11月30日本试卷满分150分,考试时间120分钟。

(注意:36-40题,61-70题写到答题页上)第一卷(共100分)第一卷共分三部分,第一部分听力在笔试结束后,剩余20分钟进行,请同学们先答笔试部分,涂卡时注意序号。

第二部分:阅读理解(共两节,满分40分)第一节:阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。

(共15小题, 每小题2分,满分30分)AThere once was a very wealthy man who had made great achievement. He had more money than he could ever spend, and he was admired and looked up to by his neighbors. Still,he knew that something was missing in his life. He wasn't happy. All his life he had been striving(奋斗)for happiness, but he had never been able to find it.Then one day, he heard about a hidden temple in Nepal that had a special room that contained the secret of happiness. He immediately sold all that he owned and set out to find this hidden temple. After many years of searching and countless hardships he arrived there. He was tired and penniless, but he knew that none of that was important now because he had found the temple. He asked a wise, smiling monk(僧侣)if he could enter the special room. The monk agreed and showed him the stairs leading to the room. He climbed them with legs shaking with expectation and slowly opened the door. He stared into the room with sunlight streaming through the window and saw what he had come so far to find. There hanging on the wall was the secret of happiness. The man gazed at himself in the mirror and laughed.It is time that we all realized that we were the secret of our own happiness. Happiness is a choice that we can make. Don't spend the rest of your life searching the world for happiness then. Just look in the mirror and laugh. Just let the happiness flow from your heart, mind, and soul until it fills your life and the lives of all those around you.21. According to the text, the man .A. was not happy because of his wealth and successB. wasn't popular with people of his neighborsC. found the secret of happiness at lastD. would regret for what he had done22. What can we infer from the text?A. Getting wealth means losing happiness.B. There should be a wise monk in the temple.C. People can learn what happiness is from the mirror.D. It was difficult to find the temple in Nepal.23. Which of the following statements is not true?A. On the way to seeking happiness, the man spent all his moneyB. With a lot of money, the man lived a happy life.C. Happiness is a choice that depends on ourselves.D. The man was very happy when he found the secret of happiness24. The purpose of the author's writing the text is to .A. show the relationship between wealth and happinessB. tell the story about a wealthy manC. tell us what is the real secret of happinessD. introduce the process of a man's finding his happinessBAsk runners why they run and you'll get a variety of answers: to stay healthy or to feel better. Some have an even bigger reason一to stay calm or out of prison. But Back on My Feet puts recovering addicts and the homeless on the road to a brighter future, starting with a simple step; attending group runs three tunes a week.At 5:30 a.m. on a hot July day, Back on My Feet's Team Brooklyn gathered in a parking lot. After a round of hugs and some warm-up, the group of eight volunteers and seven residents(居民)set out on a run to nearby Prospect Park. Some ran three miles, some longer, but the goal for all was to finish as a team"It's helping me put my life back together," said Jimmy, a 58-year-old cancer survivor who was homeless and a former alcohol addic t. “It’s healthy. It makes me feel good inside,” adds Jimmy.Many are skeptical(怀疑的)about the idea of homeless runners, according to Anne Mahlum, who founded Back on My Feet in 2007 after starting a running club for men at a shelter near her Philadelphia home. They did want to run, and in just six years, Mahlum's small running club has expanded to 10 cities around the country, and 388 active members.The only requirement for joining, besides wanting to, is insisting on at least 30 days."The first day we giv e them new shoes and Back on My Feet shirts," Mahlum says. “Then they run a mile the first day. And then gradually we'll encourage them to build goals. “After 30 days,residents gain access to services like financial aid,housing assistance and employment opportunities through Back on My Feet's partners. In its first year, the New York chapter has seen 41 members obtain employment, 34 gain housing and 50 work in job-training programs.That's not to say it's always easy. “I wanted to quit. But then I started to push myself,”said Adel, 39, who began running in March. “Now I would love to run a 10-mile run. Or maybe a marathon one day, who knows. I ran this far, so why not?”25. Back on My Feet aims to help .A. the addicts quit their bad habitsB. the homeless remain healthyC. people build a better futureD. the prisoners get out of prison26. Members of Back on My Feet must .A. attend group runsB. run the same distanceC. run on weekendsD. keep the same speed27. What great change happened to Adel after a period of running?A. He was more grateful.B. He was much prouder.C. He was more addictive.D. He was more confident.28. According to the author, Back on My Feet is .A. making progressB. well-known around the worldC. meeting difficultyD. in need of moneyCRecently, the documentary(纪录片)“A Bite of China", which takes the fine foods as the theme, has beaten many TV series, becoming extremely popular on the microblog(微博)and turning into the hottest topic. Chinese people are proud of the great food culture of China and some even praise the documentary by saying that “it is a best video that arouses our great love of our country”.Produced by Chen Xiaoqing, an award-winning documentar y maker, “A Bite of China” is filled with mouthwatering images of food ranging from royal cooking to local specialties. It focuses on the beautiful and simplified process of food making and attracts food lovers and ordinary audiences.“Television is filled with food these days, especially introductions by some professionalcooks, even famous TV hosts. We also have some scenes of food-making, but how to create dishes is only one aspect of food culture,” Chen says.“The program tries to bring something new b y presenting more cultural elements related to dishes, such as eating habits and eating principles,” he adds.Each series lasts 50 minutes. Every series will focus on different people, who will tell stories about their adventures with food. “A Bite of China” also focuses on social changes while presenting food cultures, such as the dispersion of families that leave the elderly in their hometowns while other members work outside. In such cases food serves as reminders of happy times and expectations of reunions.29. Which of the following statements is NOT true according to the passage?A. The documentary has many different characteristics.B. The documentary is not only about food making.C. The documentary usually lasts fifty minutes.D. The documentary also involves social problems.30.What does the underlined word “dispersion” probably mean?A.connectionB. ImmigrationmunicationD. separation31. The purpose of the passage is to ·A. attract more people to enjoy Chinese foodB. introduce a popular TV programC. make people know more about Chinese foodD. deal with some social problemsDAbout 6 percent of luxury hotels in three major Chinese cities have stopped serving shark fin(鱼翅),a survey has found. Although the controversial(有争议的)dish remains on the menu at most hotels, Green Beagle Environment Institute, a Beijing-based non-government organization that was the main sponsor of the survey, said the results are encouraging and reflect increased awareness.The survey was carried out in Beijing, Shenzhen and Fuzhou, which were selected as representative cities to collect basic data on shark fin consumption nationwide. In Beijing, 132 hotels completed the phone questionnaire between Nov. 20 and Dec. 12. Only 12 hotels, 9 percent, said they do not serve shark fin. A similar survey of 131 Beijing hotels conducted a year ago found only one hotel that did not serve shark fin, Wang Xue, chief coordinator(协调人)of the survey, said on Saturday.In Shenzhen, four out of the 85 four and five star hotelssurveyed had stopped serving shark fin, accounting for about 5 percent. In Fuzhou, only one of the 40 hotels surveyed did not serve shark fin. On average, about 6. 61 percent of the hotels in the three cities did not serve the food.“The survey reminded us there is still a long way to go to remove shark fins from Chinese hotels and restaurants, but the improved situation in Beijing is encouraging,” said Wang. “We found more hotels and restaurants were willing to take action over the past year.” International hotels are more active in the “shark-fin-free” project, she noted. China is the world's biggest importer and consumer of shark fin, which has been used in luxurious Chinese dishes for 500 years. Dishes made from shark fin are still regarded as a symbol of honor and respect,especially at business dinners, according to Wang.Research has also found that shark fin contains poisonous elements, but the nutritious value is less than that of chicken or pork. “We hope hotels and restaurants remove shark fin products from their menus,” Wang added.32. Why do Chinese people are fond of eating shark fin?A. Shark fin is rich in a variety of nutritionB. Shark fin stands for honor and respect in ChinaC. The living standard of Chinese is much better than before.D. Shark fin can make people live longer.33. In which way was the survey carried out?A . Phone questionnaire. B. Interviewing on the spot.C. Filling the forms.D. Talk show.34. According to the text, which city did the best this year?A. ShanghaiB. ShenzhenC. BeijingD. Fuzhou35. The author wants to tell us .A. the opinions divided on consuming shark finB. Chinese people' taste of shark finC. the world's biggest importer and consumer of shark finD. the appeal to hotels and restaurants for stopping serving shark fin第二节(共5小题; 每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

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