学易金卷：段考模拟君之2017年高考理综原创模拟卷03(考试版).doc
2017届高三普通高等学校招生全国统一考试能力测试(三)理综物理试题 含解析
二、选择题:本题共8小题,每小题6分。
在每小题给出的四个选项中，第14～17题只有一项符合题目要求，第18～21题有多项符合题目要求。
全部选对的得6分，选对但不全的得3分，有选错的得0分.1. 用比值定义法定义物理量是物理学中一种很重要的思想方法，下列表达式中属于用比值法定义的物理量是()A。
磁场的磁感应强度B=(B⊥L）B。
点电荷电场的电场强度E=kC。
金属导体的电阻R=ρD。
平行板电容器的电容C=【答案】A【解析】磁场的磁感应强度与直导线所受的安培力F和电流大小I 以及金属棒的长度L都无关，故用的是比值定义法，选项A正确；电场强度，E随场源电荷q的增大而增大，随r增大而减小,该表达式不是比值定义法，故B错误；导体的电阻与电阻率、长度成正比，与横截面积成反比，故R=ρ用的不是比值定义法，选项C错误；电容器的电容的决定式：C=与极板之间的正对面积成正比，与极板之间的距离成反比，不属于比值定义，选项D错误；故选A.点睛:中学物理中,有相当数量的物理量是采用“比值法”定义的．应用比值法定义物理量，往往需要一定的条件；一是客观上需要，二是间接反映特征属性的两个物理量可测,三是两个物理量的比值必须是一个定值．2. 右图为飞船发射过程中某个阶段的示意图,飞船先沿实线椭圆轨道飞行，然后在A处点火加速变轨,由实线椭圆轨道变成虚线圆轨道，在虚线圆轨道上飞船运行周期约为100 min.下列判断正确的是()A. 全过程中飞船内的物体一直处于超重状态B. 飞船在椭圆轨道上的运行周期大于100 minC. 在圆轨道上运行时飞船的角速度大于同步卫星运动的角速度D。
飞船沿椭圆轨道通过A点时的加速度大于沿圆轨道通过A点时的加速度【答案】C【解析】全过程中飞船内的物体一直处于失重状态，选项A错误;因飞船沿椭圆轨道飞行时的半长轴小于沿虚线圆周的半径，根据开普勒第三定律可知，飞船在椭圆轨道上的运行周期小于100 min,选项B错误；根据，可知可知,因同步卫星的高度比飞船的高度大的多，故飞船在圆轨道上运行时的角速度大于同步卫星运动的角速度，选项C正确;飞船沿椭圆轨道通过A点时所受的万有引力等于沿圆轨道通过A点时的万有引力,则根据可知,飞船沿椭圆轨道通过A点时的加速度等于沿圆轨道通过A点时的加速度,选项D 错误;故选C。
学易金卷：段考模拟君之2017-2018学年高二物理下学期期末考试原创模拟卷01(考试版)
绝密★启用前|1考试研究中心命制2019-2019学年下学期期末原创卷01高二物理（考试时间：90分钟试卷满分：100分）注意事项：1．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2．回答第Ⅰ卷时，选出每小题答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3．回答第Ⅱ卷时，将答案写在答题卡上。
写在本试卷上无效。
4．测试范围：选修3-1+选修3-2+选修3-5。
5．考试结束后，将本试卷和答题卡一并交回。
第Ⅰ卷一、选择题：本题共12小题，每小题4分，共48分。
在每小题给出的四个选项中，第1~8题只有一项符合题目要求，第9~12题有多项符合题目要求。
全部选对的得4分，选对但不全的得2分，有选错的得0分。
1．两个可以自由移动的点电荷分别放在A、B两处，如图所示，A处电荷带正电Q1，B处电荷带负电Q2，且Q2=4Q1。
另取一个可以自由移动的点电荷Q3，放在直线AB上某处，欲使整个系统处于平衡状态，下列说法中正确的是A．Q3带负电，且放于A、B之间B．Q3带正电，且放于B右侧C．Q3带负电，且放于A左侧D．Q3带正电，且放于A、B之间2．静止在湖面的小船上有两个人分别向相反方向抛出质量相同的小球，甲向左抛，乙向右抛，如图所示，甲先抛乙后抛，抛出后两小球相对岸的速率相等，不计水的阻力，下列说法中正确的是A．两球抛出后，船往左以一定速度运动，乙球受到的冲量大一些B．两球抛出后，船往右以一定速度运动，甲球受到的冲量大一些C．两球抛出后，船的速度为零，甲球受到的冲量大一些D．两球抛出后，船的速度为零，两球所受到的冲量相等3．用一束绿光照射某金属，能产生光电效应，现在把人射光的条件改变，再照射这种金属。
下列说法正确的是A．把这束绿光遮住一半，则可能不产生光电效应B．把这束绿光遮住一半，则逸出的光电子最大初动能将减小C．若改用一束红光照射，则不产生光电效应D．若改用一束蓝光照射，则逸出光电子的最大初动能将增大4．图中a、b是两个点电荷，它们的电荷量分别为Q1、Q2，MN是ab连线的中垂线，P是中垂线上的一点。
学易金卷：段考模拟君之2024-2025学年高二英语上学期期中原创卷03(考试版)
绝密★启用前|1试题命制中心2024-2025学年上学期期中原创卷03高二英语（考试时间：90分钟试卷满分：120分）留意事项：1. 本试卷由三个部分组成。
其中，第一和其次部分的第一节为选择题。
其次部分的其次节和第三部分为非选择题。
2. 答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
3. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
回答非选择题时，将答案写在答题卡上，写在本试卷上无效。
4．测试范围：人教必修5 。
5．考试结束后，将本试卷和答题卡一并交回。
第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项。
AWelcome to Holker Hall & GardensVisitor InformationHow to Get to HolkerBy Car: Follow brown signs on A590 from J36, M6. Approximate travel times: Windermere-20 minutes, Kendal-25 minutes, Lancaster-45 minutes, Manchester-1 hour 30 minutes.By Rail: The nearest station is Cark-in-Cartmel with trains to Carnforth, Lancaster and Preston for connections to major cities & airports.Opening TimesSunday-Friday (closed on Saturday)11:00 am-4:00pm, 30th March-2nd November.Admission ChargesHall & Gardens GardensAdults: £12.00 £8.00Groups: £9.00 £5.50Special EventsProducers’ Market 13th AprilJoin us to taste a variety of fresh local food and drinks. Meet the producers and get some excellent recipe ideas.Holker Garden Festival 30th MayThe event celebrates its 22nd anniversary with a great show of the very best of gardening, making it one of the most popular events in gardening.National Garden Day 28th AugustHolker once again opens its gardens in aid of the disadvantaged. For just a small donation you can take a tour with our garden guide.Winter Market 8th NovemberThis is an event for all the family. Wander among a variety of shops selling gifs while enjoying a live music show and nice street entertainment.1. How long does it probably take a tourist to drive to Holker from Manchester?A.20 minutes.B.25 minutes.C.45 minutes.D.90 minutes.2.How much should a member of a tour group pay to visit to Hall & Gardens?A.£l2.00.B. £9.00.C. £8.00.D. £5.50.3.Which event will you go to if you want to see a live music show?A. Producers’ Market.B. Holker Garden Festival.C. National Garden Day.D. Winter Market.BMy First Marathon（马拉松）A month before my first marathon, one of my ankles was injured and this meant not running for two weeks, leaving me only two weeks to train. Yet, I was determined to go ahead.I remember back to my 7th year in school. In my first P.E. class, the teacher required us to run laps and then hita softball. I didn’t do either well. He later informed me that I was ＂not athletic＂.The idea that I was ＂not athletic＂stuck with me for years. When I started running in my 30s, I realized running was a battle against myself, not about competition or whether or not I was athletic. It was all about the battle against my own body and mind. A test of wills!The night before my marathon, I dreamt that I couldn’t even fin d the finish line. I woke up sweating and nervous, but ready to prove something to myself.Shortly after crossing the start line, my shoe laces(鞋带) became untied. So I stopped to readjust. Not the start I wanted!At mile 3, I passed a sign: ＂GO FOR IT, RUNNERS!＂By mile 17, I became out of breath and the once injured ankle hurt badly. Despite the pain, I stayed the course walking a bit and then running again.By mile 21, I was starving!第 1 页As I approached mile 23, I could see my wife waving a sign. She is my biggest fan. She never minded the alarm clock sounding at 4 a.m. or questioned my expenses on running.I was one of the final runners to finish. But I finished! And I got a medal. In fact, I got the same medal as the one that the guy who came in first place had.Determined to be myself, move forward, free of shame and worldly labels(世俗标签), I can now call myselfa ＂marathon winner＂.4. A month before the marathon, the author ____________.A. was well trainedB. felt scaredC. made up his mind to runD. lost hope5. Why did the author mention the P.E. class in his 7th year?A. To acknowledge the support of his teacher.B. To amuse the readers with a funny story.C. To show he was not talented in sports.D. To share a precious memory.6. How was the author’s first marathon?A. He made it.B. He quit halfway.C. He got the first prize.D. He walked to the end.7. What does the story mainly tell us?A. A man owes his success to his family support.B. A winner is one with a great effort of will.C. Failure is the mother of success.D. One is never too old to learn.CThe most important lessons in life that we need to learn are the results of our poor decisions. Although time and experience are the best teachers, we also suffer from experiences such as our sacrifices, suffering and the hardships. Good judgment develops only when we truly learn from our mistakes. However, many people keep repeating the same mistakes before learning their lessons because as they say, they are just humans who are subject to making mistakes.Our weaknesses in life can be turned into our strengths if we immediately acknowledge and recognize the fact that we mess up and learn from them. Our good or bad experiences help us learn better judgment in life. Yet, too many people are in denial (拒绝承认) and place the blame on others without realizing that the minute they take responsibility for their action is when the learning process begins. Aside from learning from our own experience, we can also learn valuable lessons from the experience of others. It allows us to observe our behavior from another angle. When we recognize our mistakes and prevent them from happening again, we are, therefore, learning.Quickly identifying our mistakes and changing behavior accordingly requires less time and energy than denying mistakes. However, acknowledgement of mistakes requires belief in the idea that perfection is not possible.It is easier to analyze our mistakes especially when we talk to others, which can help people to sort out comments or criticisms after a mistake is made. Despite our tendency to avoid mistakes, timely acknowledgement is one of the best ways to prevent them from repeating.8. What does learning from the experience of others help us do?A. Realize that mistakes are part of life.B. Re-evaluate our behavior differently.C. Recognize the results of mistakes.D. Learn better judgment in life.9. What should we keep in mind to admit our mistakes?A. Every man has his faults.B. Mistakes are great teachers.C. Behind bad luck comes good luck.D. As you make your bed, so you must lie in it.10. How should we avoid repeating mistakes, according to the author?A. Think twice before acting.B. Learn carefully from others’ comments.C. Have a timely talk with others for advice.D. Admit the existence of mistakes in time.11. What may be the best title for the passage?A. Never Be Afraid of Making MistakesB. Learn Wisdom from Our MistakesC. Learn from Others to See Our MistakesD. Stop Being Ashamed of Making MistakesDIllegally traded endangered species that escape, forming secondary populations, offer hope to their long-term survival, a study suggests. "This first came to my attention when I read a news story about the seizure of an illegal shipment of 23 yellow-crested cockatoos," said Luke Gibson, a college teacher. He learned that the species was critically endangered, which surprised him.This encouraged Dr. Gibson and his colleague to investigate(调查) how a critically endangered species hadbecome self-sustaining outside of its natural range. They discovered 49 cases of a globally threatened species becoming established as a separate population, including the yellow-crested cockatoo in their city."This is a species which is primarily threatened by wildlife trade," he told BBC News. "Poachers(偷猎者) go out into the forest in its native range in eastern Indonesia and capture the birds and then ship them off, usually up to our city where there is a strong demand for pet birds. This is what has fueled the decline of this species in its native range. But it’s really interesting because that same cause also had another effect: some of the people who were keeping this species here accidentally or intentionally released them." As a result of enough of the birds being set free, it allowed a new self-sustaining population to be established in this city.The government of Dr. Gibson’s city has made it illegal to capture the species, even though it is a non-native species. Because the city is affluent and relatively well educated, the cases of people breaking the law are extremely rare, explained Dr. Gibson. Unlike in its native range in Indonesia where capturing birds forms a major source of income.However, there can be downsides(缺点) to the newly established population of endangered species, such as a limited genetic pool, and suffering from novel diseases. It did also present a possible "very interesting" opportunity for conservationists, Dr. Gibson suggested. This would involve "harvesting" some of the newly established secondary population, which may provide a way to help slow global biodiversity loss.12. What was beyond Gibson’s expectations according to the first paragraph?A. The high rate of wildlife trade.B. The preciousness of the birds.C. The fact that the birds nearly disappear.D. The news that the birds were poached.13. What happened unexpectedly when the birds were shipped abroad?A. They formed a separate population.B. They were kept as pet birds.C. They were traded illegally.D. They were killed for research.14. Which can replace the underlined word "affluent"?A. Peace-loving.B. Rich.C. Free.D. Environment-friendly.15. For what purpose did the author write the passage?A. To appeal to everyone to stop the wildlife trade.B. To explain the challenge the wild birds are facing.C. To introduce a creative approach to wildlife conservation.D. To raise people’s awareness of protecting endangered species.其次节（共5小题；每小题2分，满分10分）依据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
学易金卷：段考模拟君之2017年高考化学原创模拟卷01(考试版)
【学易金卷】2017年高考第一次原创模拟卷理科综合化学（考试时间：50分钟试卷满分：100分）注意事项：1．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2．回答第Ⅰ卷时，选出每小题答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3．回答第Ⅱ卷时，将答案写在答题卡上。
写在本试卷上无效。
4．考试结束后，将本试卷和答题卡一并交回。
可能用到的相对原子质量：H—1 C—12 N—14 O—16 Na—23 Cl—35.5 Cu—64 Zn—65第Ⅰ卷一、选择题：本题共7个小题，每小题6分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
7．生产生活中处处有化学，下列表述错误的是A．低碳生活的核心就是节约能源，减少温室气体的排放B．硅酸钠的水溶液俗称水玻璃，是制备硅胶和木材防火剂的原料C．用活性炭为糖浆脱色和用臭氧漂白纸浆，原理相似D．变质的植物油有难闻的特殊气味，是由于植物油发生了氧化反应8．分子式为C9H12的所有带苯环结构的异构体中，在催化剂条件下与液溴发生取代反应，其一溴代物为三种的结构有A．1种B．2种C．3种D．4种9．设N A为阿伏加德罗常数的值，下列说法中正确的是A．1 L 2 mol·L−1 K2S溶液中S2−和HS−的总数为2N AB．电解精炼铜时，若阴极得电子数为2N A，则阳极质量减少64 gC．1 mol 聚苯乙烯分子有碳碳双键的数目为N AD．1 mol Mg 在空气中燃烧生成MgO(含少量Mg3N2)失去电子数为2N A10．X、Y、Z、W均为短周期元素，且Y、Z、W在周期表的位置关系如下。
已知X与理科综合化学试题第1页（共14页）理科综合化学试题第2页（共14页）W能形成最简单的有机物，则下列有关说法正确的是A．X能分别与Y、W形成化合物，且所含化学键类型完全相同B．W有多种同素异形体，且均具有高熔点、高沸点的性质C．X的离子半径一定小于与Y同族的短周期元素的离子半径D．Y、Z与X的常见稳定液态氧化物反应的剧烈程度Y大于Z11．下列图中的实验方案，能达到实验目的的是并能较长时间观察其颜色12．如图甲是一种利用微生物将废水中的尿素(H2NCONH2，氮元素显−3价)的化学能直接转化为电能，并生成对环境无害物质的装置，同时利用此装置的电能在铁上镀铜，下列说法中不正确的是理科综合化学试题第3页（共14页）理科综合化学试题第4页（共14页）理科综合化学试题 第5页（共14页）理科综合化学试题 第6页（共14页）A ．H +透过质子交换膜由左向右移动B ．铜电极应与Y 相连接C ．M 电极反应式：H 2NCONH 2+H 2O −6e −CO 2↑+N 2↑+6H +D ．当N 电极消耗0.25 mol 气体时，则铁电极增重16 g13．常温下，向20 mL 某盐酸溶液中逐滴加入0.1 mol·L −1的氨水，溶液pH 的变化与加入氨水的体积关系如图所示，下列叙述正确的是A ．盐酸的物质的量浓度为1 mol·L −1B ．在①、②之间的任意一点：c (Cl −)>c (+4NH )，c (H +)>c (OH −) C ．在点②所示溶液中：c (+4NH )=c (Cl −)>c (OH −)=c (H +)，且V <20 D ．在点③所示溶液中：由水电离出的c (OH −)>10−7 mol·L −1理科综合化学试题 第7页（共14页）理科综合化学试题 第8页（共14页）第Ⅱ卷二、非选择题：本卷包括必考题和选考题两部分。
学易金卷：段考模拟君之2017-2018学年高一物理下学期期中考试原创模拟卷03(考试版)
学易金卷：段考模拟君之2017-2018学年高一物理下学期期中考试原创模拟卷03（考试版）绝密★启用前|1试题命制中心2019-2019学年下学期期中原创卷03高一物理（考试时间：90分钟试卷满分：100分）注意事项：1．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2．回答第Ⅰ卷时，选出每小题答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3．回答第Ⅱ卷时，将答案写在答题卡上。
写在本试卷上无效。
4．测试范围：必修2第5、第6章、第7章前三节。
5．考试结束后，将本试卷和答题卡一并交回。
第Ⅰ卷一、选择题：本题共12小题，每小题4分，共48分。
在每小题给出的四个选项中，第1~8题只有一项符合题目要求，第9~12题有多项符合题目要求。
全部选对的得4分，选对但不全的得2分，有选错的得0分。
1．图甲为一女士站在煌华的台阶式自动扶梯上匀速上楼（忽略扶梯对手的作用），图乙为一男士站在家乐福履带式自动扶梯上匀速上楼，两人相对扶梯均静止，下列关于力做功的判断正确的是A．甲图中支持力对人不做功B．甲图中摩擦力对人做负功C．乙图中支持力对人做正功D．乙图中摩擦力对人做正功2．假设宇宙中有两颗相距无限远的行量A和B，白身球体半径分别为A R和B R两颗行星各自周围的卫星的轨道半径的三次方（3r）与运行公转周期的平方（2T）的关系如图所示；0T为卫星环绕各自行星表面运行的周期，忽略行星自转的影响A．行星A的质量小于行星B的质量B．行星A的密度大于行星B的密度C．行星A的第一宇宙速度小于行星B的第一字宙速度D．行星A表面的重力加遠度大于行星B表面的重力加速度3．如图所示，A、B、C三颗人造地球卫星绕地球做匀速圆周运动，已知三颗卫星的质量关系为A B Cm m m=<，轨道半径将完成。
“嫦娥五号”探测器在月球表面着陆的过程可以简化如下，探测器从圆轨道1上A点减速后变轨到椭圆轨道2，之后又在轨道2上的B点变轨到近月圆轨道3。
精品解析：湖南省2017届高三普通高等学校招生全国统一考试考前演练卷(三)理科综合化学试题(解析版)
1. 化学与生活、社会发展息息相关，下列说法错误的是A. “霾尘积聚难见路人”，雾霾所形成的气溶胶有丁达尔效应B. “熬胆矾铁釜，久之亦化为铜”，该过程发生了置换反应C. “青蒿一握，以水二升渍，绞取汁”，屠呦呦对青蒿素的提取属于化学变化D. 古剑“湛泸”“以剂钢为刃，柔铁为茎干，不尔则多断折”，剂钢指的是铁的合金【答案】C【解析】【详解】A．雾霾所形成的气溶胶属于胶体，具有丁达尔效应，故A正确；B．铁置换铜属于湿法炼铜，该过程发生了置换反应，故B正确；C．对青蒿素的提取利用的是萃取原理，萃取过程中没有新物质生成，属于物理变化，故C错误；D．剑刃硬度要大，所以用铁碳合金，故D正确；故选C。
2. 下列关于有机物的叙述正确的是( )A. 乙烯和苯都能使溴水褪色，褪色的原因相同B. 分子式为C2H4O2且能与NaOH溶液反应的有机物一定是乙酸C. 油脂和纤维素都是能发生水解反应的高分子化合物D. 甲烷、苯、乙醇、乙酸和酯类都可以发生取代反应【答案】D【解析】【详解】A、乙烯结构简式为CH2=CH2，含有碳碳双键，和溴水发生加成反应，苯使溴水褪色，利用溴单质易溶于有机溶剂，属于萃取，因此原理不同，故错误；B、C2H4O2可以是CH3COOH，也可以是HCOOCH3，羧酸与NaOH发生中和反应，酯在NaOH溶液发生水解，故错误；C、油脂不是高分子化合物，纤维素属于高分子化合物，故错误；D、甲烷和氯气在光照条件下发生取代反应，苯和液溴在铁作催化剂作用下发生取代反应，乙醇和乙酸发生酯化反应，即取代反应，酯类发生水解，即取代反应，故正确。
3. 利用下列实验装置进行相应的实验，不能达到实验目的的是A. 利用图甲装置，可快速制取氨气B. 利用图乙装置，用饱和碳酸钠溶液分离CH3CH2OH和CH3COOC2H5混合液C. 利用图丙装置，可制取乙烯并验证其易被酸性KMnO4溶液氧化D. 利用图丁装置，可说明浓H2SO4具有脱水性、强氧化性，SO2具有漂白性、还原性【答案】C【解析】【详解】A.生石灰与水反应放出大量的热，浓氨水受热发生分解生成氨气，所以利用图甲装置可快速制取氨气，故A正确；B.乙醇易溶于水，乙酸乙酯不溶于饱和碳酸钠溶液，所以可以利用图乙装置，乙醇用饱和碳酸钠溶液分离CH3CH2OH和CH3COOC2H5混合液，故B正确；C.乙醇和浓硫酸混合加热到170℃时发生反应，生成乙烯，但是如果加热到140℃，生成的是乙醚。
学易金卷：段考模拟君之2017年高考化学原创密卷03(考试版)
理科综合化学试题 第1页（共8页） 理科综合化学试题 第2页（共8页）绝密★启用前|试题命制中心【学易金卷】2017年高考考前原创密卷03理科综合化学（考试时间：50分钟 试卷满分：100分）注意事项：1．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2．回答第Ⅰ卷时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3．回答第Ⅱ卷时，将答案写在答题卡上。
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4．考试结束后，将本试卷和答题卡一并交回。
可能用到的相对原子质量：H 1 C 12 N 14 O 16 Na 23 Al 27 S 32 Cl 35.5第Ⅰ卷一、选择题：本题共7个小题，每小题6分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
7．《本草图经》中关于绿矾的分解有如下描述：“绿矾形似朴消（Na 2SO 4·10H 2O ）而绿色，取此物置于铁板上，聚炭，封之囊袋，吹令火炽，其矾即沸，流出，色赤如融金汁者是真也。
”对此段话的说明中肯定错误的是A ．绿矾的化学式为FeSO 4·7H 2OB ．绿矾分解过程中没有发生电子的转移C ．“色赤”物质可能是Fe 2O 3D ．流出的液体中可能含有硫酸8．设N A 为阿伏加德罗常数的值，下列说法正确的是 A ．100 g 98%的浓硫酸中含有的氢原子数目为2N AB ．常温下，2.7 g Al 与足量浓度为18 mo1/L 的浓硫酸反应时，转移的电子数为0.3N AC ．标准状况下，22.4 L 的CCl 4含有的CCl 4分子数大于N AD ．1 mol 苯完全转化为环己烷，参与反应的碳碳双键数为3N A 9．下列关于有机物的说法不正确的是A ．用碳酸钠溶液可一次性鉴别乙酸、苯和乙醇三种无色液体B ．中所有原子可能共平面C ．1 mol 苹果酸(HOOCCHOHCH 2COOH)可与3 mol NaHCO 3发生反应D ．—C 3H 7和—C 2H 5O 各取代苯分子中的一个氢原子形成的二元取代物的同分异构体有24种 10．下列有关溶液中离子存在和转化的表达合理的是A ．中性溶液中可能大量存在Fe 3+、K +、Cl −、24SO -B ．离子方程式2Ca 2++33HCO -+3OH−2CaCO 3↓+23CO -+3H 2O 可以表示NH 4HCO 3与澄清石灰水反应C ．由水电离出的c (H +)=1×10−12 mol/L 的溶液中可能大量存在K +、I −、Mg 2+、3NO -D ．n [NH 4AlSO 4)2]∶n [Ba(OH)2] =2∶5时发生的反应为：+4NH +Al 3++224SO -+2Ba 2++5OH−NH 3·H 2O+2AlO -+2H 2O+2BaSO 4↓11．利用如图装置进行“氨的催化氧化”实验（固定装置略去）。
学易金卷：段考模拟君之2017年高考理数原创模拟卷03(考试版).doc
a b1 22.定义运算 c d=ad - be z =i t 2（i 为虚数单位），则复数歹在复平面上对应的点位于A.第一象限C.第三象限B.第二象限D.第四象限3. 如图，一铜钱的直径为32毫米，穿径（即铜钱内的正方形小孔边长）为8毫米，现向该铜钱内随机地投入 【学易金卷】2017年高考第三次原创模拟卷理科数学（考试nt 间：120分钟 试卷满分：150分）注意事项：1. 本试卷分第I 卷（选择题）和第II 卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考 证号填写在答题卡上。
2. 回答第I 卷时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动， 用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3. 回答第］I 卷时，将答案写在答题卡上。
写在本试卷上无效。
4. 考试结束后，将本试卷和答题卡一并交回。
5. 考试范围：高考全部内容。
第I 卷一、选择题（本题共12小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的）11 21.己知集合M ={m\-<（-y n<4jnE Z},N = {x\ ——21},则MC\N =4 2 x-l A. 0 B. {2}C. {x|l<x<2}D. {—2,—1,0,1,2}-粒米（米的大小忽略不计），则该粒米未落在铜钱的正方形小孔内的概率为1A.-216C.—31B.D.16298B. b>c> aD. c> a>b1 I 1A. —B. 1 --------4兀4兀1 1 1C. —D. 1 --------2 K 6 7t4.《九章算术》之后，人们学会了用等差数列的知识来解决问题，《张丘建算经》卷上第22题为:“今有女善织，日益功疾（注:从第2天开始，每天比前一天多织相同量的布），第一天织5尺布，现在一月（按30天计）共织390尺布”，则从第2天起每天比前一天多织多少尺布5.己知a = log30.5,/? = log030.2,c = O.50,3，贝【JA. a>c>bC. b> a>c6.执行如下程序框图，若输出的结果为170,则判断框内应补充的条件为A. z>5?7.某几何体的三视图如图所示，则该几何体的体积为，孕8.抛物线C: y2=4x的焦点为F,斜率为上的直线/与抛物线。
学易金卷：段考模拟君之2017年高考英语原创模拟卷01(考试版)
英语试题 第1页（共8页） 英语试题 第2页（共8页）绝密★启用前|学易教育教学研究院命制【学易金卷】2017年高考第一次原创模拟卷英 语(考试时间：90分钟 试卷满分：120分)注意事项：1.本试卷由三个部分组成。
其中，第一和第二部分的第一节为选择题。
第二部分的第二节和第三部分为非选择题。
2.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
3.回答选择题时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑；回答非选择题时，将答案写在答题卡上，写在本试卷上无效。
4.考试结束后，将本试卷和答题卡一并交回。
第一部分 阅读理解(共两节，满分40分) 第一节 (共15小题；每小题2分，满分30分)阅读下列短文，从每题所给的A 、B 、C 和D 四个选项中，选出最佳选项，并在答题卡上将该项涂黑。
AEnter for a chance to win a Montana adventureImagine yourself hiking on the same route that Lewis and Clark once explored, fly fishing and whitewater rafting (激浪漂流) in beautiful lakes and rivers, learning how to speak Blackfeet, digging for ancient dinosaur remains, and standing at the edge of a 6,000-year-old glacier (冰川) in Glacier National Park. You have the chance to do all of this and much more with the National Geographic Kids Hands-On Explorer Challenge Expedition Team. The Hands-On Explorer Challenge is heading west in 2016 to Montana. HIKE!Montana is home to many species of plants and animals. Follow in the footsteps of legendary explorers and get a close-up view of waterfalls, wildflowers, and wildlife. DIG!Some of the most important dinosaur discoveries have been found in Montana. You’ll discover treasures yourself as you dig for ancient dinosaur remains in Montana’s High Plains. CULTURE!Montana has eleven Nat ive American tribes―each one filled with a unique heritage and lots of rich traditions. View the world as they see it through their dances, songs, food, games, and languages. HOW TO ENTER1. Write an original, personal essay in English of no more than 300 words telling us how you explore your world and what it is about exploration that inspires and excites you.2. Take a photograph of what, where, or how you explored the subject of your essay.3. Enter by January 7, 2016. Open to kids who will be ages 9—14 as of July 1, 2016.4. Send your entry form, essay, and photo (as described in the Official Rules) to: NG Kids Hands-On ExplorerChallenge, National Geographic Kids magazine/CDH, 1145 17th Street NW, Washington, DC 20036. FOR MORE INFORMA TION, GO TO /KIDS/CONTESTS/EXPLORER- TRIP-2016. 1. What is true about Montana?A. It is home to many species of plants and animals.B. It is Lewis and Clark’s hometown.C. Its Native American tribes share the same culture.D. It has many elephant discoveries.2. What must you do if you want to enter the contest? A. Be over 14 years old. B. Send a photo with your essay.C. Have rich exploration experience.D. Write an English article over 300 words.3. What is the purpose of the passage?A. To provide travel information.B. To describe Montana’s scenery.C. To announce a kid competition.D. To suggest some outdoor activities. BIn this season for thanks and giving, even the most thoughtful children may not offer much gratitude for what they receive. And you’d be wise not to expect it. All the research I’ve done has convinced me that it’s not going to happen.As parents, we don’t consider our holiday gifts an “exchange relationship” since we know the time, money, and effort we put in to buy them. But kids have a different view. One mom told me that when she asked her 16-year-old son to thank her for buying him a cellphone, he said, “But tha t ’s what moms should do, isn’t it?” From a teenager’s view , it’s a parent’s responsibility to take care of the family, and playing Santa is part of the job. According to Yarrow Dunham, Yale’s assistant professor of P sychology, “When teenagers code it that way, a gift is no longer something given freely and voluntarily — it ’s just mom and dad’s living up to their obligation .”Kids can’t know how blessed they are unless they have a basis for comparison. We need to give our children the gift of a wider world view. Take them to a soup kitchen instead of to the mall. Become the secret Santa for a needy family. Show by example that gratitude isn’t about stuff — which ultimately can’t make any of us happy anyway. It’s about realizing how lucky you are.Set up a family ritual at bedtime where kids describe three things that made them grateful. When kids go off to college, you can text them a picture of something that inspires your appreciation each week. Whether it’s a friend, a snowflake, or a sunset, the spirit of the photos will help you and them see the world differently.Teaching children to focus on the positive and appreciate the goodness in their lives is perhaps the greatest gift we can give them. And we can all learn together that the things that really matter aren’t on sale at a department英语试题第3页（共8页）英语试题第4页（共8页）4. Why don’t children express thanks for gifts ?A. Because they regard them as an “exchange relationship”.B. Because they think badly of the gifts.C. Because children are not as considerate as adults.D. Because gifts are not what they expect.5. Parents should make the kids know how blessed they are by _______.A. buying them a cellphoneB. becoming the secret Santa for a needy familyC. taking them to a soap factory instead of to the mallD. texting them a picture of something that inspires your appreciation each week6. What should parents do to make children grateful for what they have?A. Set an example to childrenB. Teach them not to care about giftsC. Ask children to cook themselvesD. Describe things they are grateful for7. As far as the author is concerned, no gifts are greater than _______.A. helping kids see the world differentlyB. learning together things that matterC. teaching kids to think positivelyD. making kids realize they are luckyCOne day, a poor boy who was selling goods from door to door, found he had only one coin left, and he was hungry. He decided he would ask for a meal at the next house. However, he lost his courage when a lovely young woman opened the door. Instead of a meal he asked for a drink of water. She thought he looked hungry so she brought him a large glass of milk. He drank it slowly, and then asked, “How much do I owe you?”You don’t owe me anything, she replied. Mother has taught me never to accept pay for a kindness. He said, “then I thank you from the bottom of my heart.” As he left that house, he not only felt stronger physically, but it also increased his faith in the human race. He was about to give up and quit before this point.Years later the young woman became badly ill. When a doctor heard the name of the town she came from, a strange light filled his eyes.Dressed in his doctor’s gown(长外衣), he went in to see her. He recognized her at once. He determined to do his best to save her life. From that day on, he gave special attention to her case.After a long struggle, the battle won. He requested the office to pass the final bill to him. He looked at it and then wrote something on the side. The bill was sent to her room. She was afraid to open it because she was positive that it would take the rest of her life to pay it off. Finally she looked, and the note on the side of the bill caught her attention. She read these words...“Paid in full with a glass of milk.”Signed Dr. Howard Kelly.8. What can we infer from the passage?A. The doctor can’t save the woman.C. Dr. Howard Kelly doesn’t know the woman.D. The woman paid for the treatment by herself finally.9. What does the word “battle” truly mean?A. Fight.B. Treatment.C. Conflict.D. Survey.10. Which statement can be used to describe the passage? .A. Practice makes perfect.B. Well begun is half done.C. Good will be rewarded with good.D. Nothing is impossible to a willing heart.11. What does the poor boy get from the woman?A. A cup of water.B. A glass of milk.C. A meal.D. A piece of bread.DResearchers have long attributed the evolution of human intelligence to the size of the brain. It turns out that while a larger skull certainly helped, it was the extra blood sucked in by the brain that transformed humans into one of Earth’s smartes t species. The surprising discovery that overturns the previous, long-standing theory comes from a team of scientists at the University of Witwatersrand in South Africa and the University of Adelaide in Australia.Led by Professor Roger Seymour from University of Adelaide, the group examined several different fossil hominin(古人类) skulls ranging from the 3 million-year-old Australopithecus(南方古猿) to those of modern humans. However, they did not focus on the size of the head. Instead, the scientists carefully measured and documented the diameter of the holes at the base of each skull that accommodate the blood-delivering arteries(动脉).The researchers discovered that the size of the holes increased rapidly over time, indicating that additional blood was being pum ped into the brain. According to the team’s calculations, over the course of human evolution, the amount of blood supply increased by 600%, while the size of the human brain grew by only 350%.The researchers said that as humans evolved, the brain required more oxygen and nutrients to finish tasks that required increased learning and problem solving. So the amount of blood flowing into the brain had to increase. This in turn, meant that the arteries transporting them had to grow as well, leading to the need for bigger holes. Therefore, the scientists, who published their findings in the journal Open Science on August 31, concluded that it was not the skull size but the more blood sucked in by the brain that helped with human intelligence.12. What makes a great contribution to human intelligence?A. The size of the brain.B. The amount of blood flowing into the brain.C. The health of the blood-delivering arteries.D. The requirements of learning and problem solving.英语试题 第5页（共8页） 英语试题 第6页（共8页）13. What did the researchers concentrate on in the study? A. The size of the head. B. The blood-delivering arteries. C. The size of the holes of each skull. D. The quality of blood flowing into the brain. 14. How did the researchers draw the conclusion? A. By doing experiments.B. By telling stories.C. By calculating and comparing.D. By giving examples and classifying. 15. Which of the following is the right order of the factors given in the passage? a. Humans had bigger holes of skull. b. The arteries transporting blood had to grow. c. Humans took on more complex tasks. d. The brain increased the need for blood. e. The brain needs more oxygen and nutrients. A. c →e →d →b →aB. c →a →d →e →bC. b →a →e →b →cD. a →c →d →e →b第二节 (共5小题；每小题2分，满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。
学易金卷：段考模拟君之2017年高考物理原创模拟卷02(考试版)
理科综合物理试题 第1页（共6页） 理科综合物理试题 第2页（共6页）绝密★启用前2017年高考第二次原创模拟卷理科综合物理（考试时间：150分钟 试卷满分：300分）注意事项：1．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。
2．回答第Ⅰ卷时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动，用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3．回答第Ⅱ卷时，将答案写在答题卡上。
写在本试卷上无效。
4．考试结束后，将本试卷和答题卡一并交回。
第Ⅰ卷二、选择题：本题共8小题，每小题6分。
在每小题给出的四个选项中，第14~17题只有一项符合题目要求，第18~21题有多项符合题目要求。
全部选对的得6分，选对但不全的得3分，有选错的得0分。
14．如图所示为甲、乙两个物体在同一条直线上运动的v –t 图象，t =0时两物体相距3x 0，在t =1 s 时两物体相遇，则下列说法正确的是A ．t =0时，甲物体在前，乙物体在后B ．t =2 s 时，两物体相距最远C ．t =3 s 时，两物体再次相遇D ．t =4 s 时，甲物体在乙物体后2x 0处15．质量均为1 kg 的木块M 和N 叠放在水平地面上，用一根细线分别拴接在M 和N 右侧，在绳子中点用水平向右的力F =5 N 拉动M 和N 一起沿水平面匀速滑动，细线与竖直方向夹角θ=60°，g =10 m/s 2，则下列说法正确的是A ．木块N 和地面之间的动摩擦因数μ=0.35B ．木块M 和N 之间的摩擦力f =2.5 NC ．木块M对木块N 的压力大小为10 ND ．若θ变小，拉动M 、N 一起匀速运动所需拉力应大于5 N16．如图为湖边一倾角为30°的大坝的横截面示意图，水面与大坝的交点为O 。
一人站在A 点处以速度v 0沿水平方向扔小石子，已知AO =40 m ，g 取10 m/s 2。
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2017年高考第三次原创模拟卷理科综合（考试时间：150分钟 试卷满分：300分）注意事项：1. 本试卷分第【卷（选择题）和第II 卷（非选择题）两部分。
答卷前，考生务必将自己的姓名、准考 证号填写在答题卡上。
2. 回答第I 卷时，选出每小题答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动， 用橡皮擦干净后，再选涂其他答案标号。
写在本试卷上无效。
3. 回答第II 卷时，将答案写在答题卡上。
写在本试卷上无效。
4. 考试结束后，将本试卷和答题卡一并交回。
可能用到的相对原子质量：H —1 C —12 N —14 0—16 Na —23 Al —27 Cu —64第I 卷一、选择题：本题共13个小题，每小题6分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1. 下列有关细胞结构和功能的叙述，正确的是A. S 型肺炎双球菌通过核孔能实现核质之间频繁的物质交换和信息交流B. 洋葱根尖分生区细胞中含有遗传物质的结构有细胞核、线粒体和叶绿体C. 性腺细胞膜上运输性激素的载体蛋白数量通常青春期时比幼年和老年时期多D. 人体肝细胞中线粒体是产生二氧化碳的场所，抑制其功能会影响蛋白质的合成2. 蜂毒素是蜂毒腺分泌的多肽，体外研究蜂毒素对胃癌细胞的作用，结果如图1和图2。
下列相关叙述正确的是A. 蜂毒素的合成场所是核糖体，其分泌过程不消耗ATPB. 图1表明蜂毒素能将胃癌细胞阻断在有丝分裂前期C. 图2表明一定浓度范围内的蜂毒素能诱导胃癌细胞凋亡，且随浓度增大诱导效应增强数示空示空表的衰的加白 图-2・■■注度（陌mL ）D.该实验表明蜂毒素的作用机理是使胃癌细胞表面糖蛋白减少而使胃癌细胞凋亡数年后这些野马将3. 寨卡病毒的遗传物质是一条单链RNA,可以作为模板翻译出衣壳蛋白等（如图所示）。
下列有关说法错误的是A. 物质M 的合成过程还需要其他RNA 参与B. ①②③过程都遵循碱基互补配对原则C. 物质N 能降低化学反应的活化能D. 全部过程受细胞核DNA 分子的控制4. 濒危动物研究中心精心挑选出了两个家族的25匹普氏野马，将其放归到保护区中。
发展成为一个野生种群。
下列叙述正确的是 A. 野外的普氏野马的基因突变频率将不断增加 B. 野外的普氏野马有助于增强保护区的恢复力稳定性 C. 野外的普氏野马种群中某些基因的频率会发生定向改变 D. 野外的普氏野马与圈养的普氏野马因环境不同而产生生殖隔离5. 下列关于人体内环境稳态的叙述，不正确的是 A. 血浆渗透压与Na\ K+、血红蛋白等的含量有关 B. H 2CO 3./NaHCO 3是维持细胞外液pH 稳定的缓冲物质C. 细胞内、外Na\ K+分布不平衡的状态是通过消耗能量来维持的D. 细胞中有机物的氧化放能是人体热量的主要来源 6. 下列以洋葱为材料所进行的实验，其操作或分析合理的是A. 观察洋葱根尖分生区细胞减数分裂时可以用改良的苯酚品红染液染色B. 观察紫色洋葱鳞片外表皮细胞质壁分离时看不到线粒体和细胞核C. 紫色洋葱鳞片叶内表皮细胞被甲基绿毗罗红染色后细胞质呈绿色D. 将洋葱放在4 °C 的冰箱中培养3天，所有体细胞中染色体数日均加倍 7. 化学与生产、生活相关，下列有关说法正确的是A. 用二氧化硫漂白后的食品显得白亮，二氧化硫可作食品漂白剂B. 油脂在人体内水解为氨基酸和甘油等小分子物质后才能被吸收C.“天宫二号”中使用的碳纤维是一种新型无机非金属材料13.14.15.D. 向牛奶中加入果汁会产生沉淀，这是因为酸碱发生了中和反应 8. 分子式为C5H3O2且能与NaOH 溶液反应的有机物有（不含立体异构） A. 13 种B. 4 种C. 9 种D. 16 种9. 设N A 为阿伏加德罗常数的值，N 表示粒子数。
下列说法正确的是 A. 0.1 mo 1苯乙烯中含有碳碳双键的数目为0.4N AB. 将 1 mol Cl 2通入到水中，则 A T（HC1O ）+MC 「）+N （C1O 「）=2LV A TV （C12）］C. 一定条件下，O.lmolSCh 与足量氧气反应生成SO3，转移电子数为（）.2N AD. 电解精炼铜，当电路中通过的电子数目为0.2N A 时，阳极质量减少6.4g10. 在周期表中，X 元素与Y 、Z 、W 三种元素相邻，X 、Y 的原子序数之和等于Z 的原子序数，这四种短周期元素原子的最外层电子数之和为20,下列判断正确的是 A. 原子半径：冲*＜八，B. 四种元素形成的单质最多有6种C. 四种元素均可与氢元素形成18电子分子D. 四种元素中，Z 的最高价氧化物对应的水化物的酸性最强 11-下列实验操作和现象对应所得到的结论均正确的是12. H 3BO 3可以通过电解NaB （OH ）4溶液的方法制备，其工作原理如图，下列叙述错误的是------ 电源-------- 1I费b萨管，石r醐岫H BO' '匚枷溶制|浓溶液「］二~ M室产品童原料室N空b%NaOH 溶液a%NaOH 溶液M室发生的电极反应式为：2H2O-4e-^=O2?+4H+N 室中：a%vb%b膜为阴膜，产品室发生反应的化学原理为强酸制弱酸D.理论上每生成1 mol产品，阴极室可生成标准状况下5.6 L气体25°C时，向100 mL 0.1 mol L NH4HSO4溶液中滴加0.1 mol L-1 NaOH溶液，得到的溶液pH与NaOH溶液体积的关系曲线如图（H2SO4视为二元强酸）。
下列说法错误的是A.。
点时溶液的pHvlB.〃点到人点的过程中，溶液的导电能力减弱C.湖段上的点（不包括。
点）均满足关系式：c（NH：）+c（Na+）v2c（SO：）D.方点时离子浓度大小顺序为：c（Na+）＞c（SO；-）X（NH：）＞c（HAc（OH—）选择题：本题共8小题，每小题6分。
在每小题给出的四个选项中，第14〜17题只有一项符合题目要求，第18〜21题有多项符合题目要求。
全部选对的得6分，选对但不全的得3分，有选错的得（）分。
下列说法正确的是A.铀核裂变时释放的能量等于它俘获中子时得到的能量B.发生光电效应时，入射光越强，则光子的能量就越大，光电子的最大初动能就越大C.用a粒子轰击氮、氟、钠、铝等元素的原子核，都可以打出质子，因此人们断定质子是原子核的组成部分D.用能量为ll.OeV的光子照射处于基态的氢原子，可使其跃迁到激发态将一小球以一定的初速度竖直向上抛出并开始计时，小球所受空气阻力的大小与小球的速率成正比，己知色时刻小球落回抛出点，其运动的VT图象如图所示，则在此过程中A.r=o时，小球的加速度最大B.当小球运动到最高点时，小球的加速度大于重力加速度gC.(2=2/1D.小球的速度大小先减小后增大，加速度大小先增大后减小16.如图所示，斜面体。
放置于水平地面上，小物块B置于斜面上，通过细绳跨过光滑的定滑轮与沙漏』连接，连接B的一段细绳与斜面平行。
在刀中的沙子缓慢流出的过程中，A. 8、C都处于静止状态, 则在此过程中4A.3对。
的摩擦力大小一定减小B.C对8的作用力大小一定先减小后增大C.地面对C的摩擦力大小一定减小D.C对地面的摩擦力方向始终水平向左17.2016年11月14日“超级月亮”现身合肥市夜空，某时刻月亮看起来比平常大14%、亮度提高了30%,这是因为月球沿椭圆轨道绕地球运动到近地点的缘故，则下列说法中正确的是A.此时月球的速度最小B.此时月球的加速度最大C.月球由远地点向近地点运动的过程，地球对月球的万有引力做负功D.月球由远地点向近地点运动的过程，月球的机械能减小18.如图所示，两相同的斜面倾角均为45。
，高度为力，从左侧斜面顶端以一定初速度水平抛出一个小球,已知重力加速度为g,则下列说法正确的是A.小球落在斜面上时运动时间与初速度成正比/B.小球落在斜面上时水平位移与初速度的平方成正比I \c.小球下落到斜面上高度为?处时，初速度可能为头®2 2D.小球可能垂直落在斜面上19.如图所示，有一矩形线圈的面积为S,匝数为N,电阻不计，绕OO,轴在水平方向的磁感应强度为B 的匀强磁场中以角速度s做匀速转动，从图示位置开始计时。
矩形线圈通过铜滑环接理想变压器的原线圈，副线圈接固定电阻&和滑动变阻器A,下列判断正确的是矩形线圈产生的感应电动势的瞬时值表达式为e=NBScocos cot兀矩形线圈从图示位置经过——时间内，通过电流表A］的电荷量为02coC.当滑动变阻器的滑片向上滑动过程中，电流表A1和A2示数都变小D.当滑动变阻器的滑片向上滑动过程中，电压表Vi示数不变，V2和V3的示数都变小20.如图所示电路中，A. 3是构成平行板电容器的两金属极板，户为其中的一个定点。
将开关S闭合，电路稳定后将力板向上平移一小段距离，则下列说法正确的是A.电容器的电容增加B.在刀板上移过程中，电阻R中有向上的电流C. A. B两板间的电场强度增大D.P点电势降低21.如图所示，直角坐标系xOy位于竖直平面内，.y轴竖直向上，第III象限内存在电场强度大小未知，方向沿x轴负方向的匀强电场，第IV象限内同时存在垂直纸面的匀强磁场和方向平行于*轴的匀强电场（图中未画出）。
一带电小球从x轴上的财点由静止释放，沿着直线运动，图中1=30。
，经过P 点后小球进入第IV象限，然后做圆周运动，从N点垂直于x轴进入第I象限，N点距O点的距离为d, 重力加速度为g,根据以上信息，可以求出的物理量有A.第IV象限内电场强度的大小和方向B.圆周运动的速度大小C.小球在第IV象限运动的时间D.磁感应强度的大小和方向第II卷三、非选择题：本卷包括必考题和选考题两部分。
第22〜32题为必考题，每个试题考生都必须作答。
第33〜38 题为选考题，考生根据要求作答。
（一）必考题（共129分）22.（6分）如图1所示是某同学用水平气垫导轨探究“加速度与力的关系”的实验装置，他将光电门固定在导轨上的8点，吊盘（含金属片）通过细线与滑块相连，滑块上固定一遮光条并放有若干金属片，实验中每次滑块都从导轨上的同一位置刀由静止释放。
（1）用游标卡尺测量遮光条的宽度d（沿滑块运动方向的长度）如图2所示,则d=mm；用螺旋测微器测量遮光条的厚度力如图3所示，则力=mm。
若光电计时器记录遮光条通过光电门的时间为也，则滑块经过光电门时的速度v= （用所测物理量的符号表示）。
（2）若滑块（含遮光条和金属片）和吊盘（含金属片）组成的系统的总质量为吊盘及其中的金属片的质量为则滑块从力处释放后系统的加速度大小为。
=（己知重力加速度为g）；（3）现保持系统的总质量不变，通过,改变测出多组齿、v数据，在坐标纸上以m为横轴，以纵轴描点作出图象，若图线是一条过坐标原点的直线，则系统的加速度大小与所受合力大小成正比。