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今年编程大赛考试题及答案

今年编程大赛考试题及答案

今年编程大赛考试题及答案一、单项选择题(每题2分,共10分)1. 下列哪个选项不是Python语言的内置数据类型?A. intB. floatC. stringD. list答案:C2. 在JavaScript中,以下哪个关键字用于定义函数?A. varB. functionC. defD. let答案:B3. 在HTML中,用于定义最重要的标题的标签是?A. <h1>B. <h6>C. <title>D. <header>答案:A4. 下列哪个选项是正确的MySQL数据库连接语句?A. conn = mysql.connect('localhost', 'user', 'password', 'database')B. conn = mysql.connect('localhost', 'user', 'password')C. conn = mysql.connect('database')D. conn = mysql.connect('localhost', 'database')答案:A5. 在Java中,以下哪个关键字用于捕获异常?A. tryB. catchC. throwD. finally答案:B二、多项选择题(每题3分,共15分)1. 下列哪些选项是C++语言的特性?A. 多态B. 封装C. 继承D. 垃圾回收答案:ABC2. 在Python中,以下哪些是列表(list)的方法?A. append()B. remove()C. pop()D. reverse()答案:ABCD3. 在HTML5中,以下哪些元素用于嵌入多媒体内容?A. <img>B. <audio>C. <video>D. <iframe>答案:BCD4. 下列哪些选项是JavaScript的事件类型?A. clickB. loadC. errorD. submit答案:ABCD5. 在CSS中,以下哪些属性用于设置文本的样式?A. font-sizeB. colorC. background-colorD. text-align答案:ABD三、简答题(每题5分,共20分)1. 请简述Python中的列表推导式(list comprehension)的作用。

极限编程大赛试题AT

极限编程大赛试题AT

Testing the traversal through different screensMr. Ajay is a test expert and he has an innovative approach to testing. His current assignment is to test a particular application which traverses through multiple screens.One screen can be traversed in multiple ways. The server response time to traverse between screens is different.The circles in the diagram represent the screens and if the screens are connected by edges, it means that the screen can be traversed from the connecting screen. The numbers associated with the edges represent the minimum response time in microseconds between the screens.He has to navigate from one screen to a destination screen and return to origin screen, visiting any screen at most once.. What is the fastest way to perform this traversal.If he has to navigate from 1 to 7, the navigation path he takes is1-4-6-7-5-2-1But, Mr. Ajay finds it difficult to find the fastest route himself so he seeks help.PS: always calculate the path from the first node to the last node and backInputThe first line of test case will contain two integers: N(N<= 100) and R representing respectively the number of screens and the connection between screens. Then R lines will follow each containing three integers: C1, C2 and P. C1 and C2 are the screen numbers and P (P>1) is the limit on the minimum server response time to navigate to the screen. Last line of the input should be the source and the destination screen. Screen numbers are positive integers ranging from 1 to N.OutputOutput the shortest time to traverse from source to destination and back without repeating any screen.Sample Input7 101 2 301 3 201 4 102 4 252 5 603 6 704 7 354 6 205 7 106 7 15Sample Output145。

极限编程大赛试题AC

极限编程大赛试题AC

∙ACEnds in: 0 Days 03:15:07∙Rank: 535 Score: 113.33Solving this puzzle will improve your rank to 354Description:Meet Lakshya, he is one of the best cubers of the world. He has this unique talent to solve a Rubik's cube with his eyes blindfolded! He has recently been experimenting a lot to improve his timing. Lakshya has been following Singmaster's notation of moves to memorize a lot of standard solving techniques. To assist him in his pursuit, you offer to help him. Lakshya has now given you the following description of the tool that he needs:A tool which will take the initial configuration of rubik's cube (in its solved state) followed by a set of moves, denoted in Singmaster's notation and generate as output the colors of the tiles present on the front face of the rubik's cube.Constraints:The input will always be a proper list of moves in Singmaster's notation.Color code is a string of length 6. Moves can be of any length.INPUT:Input consists of two lines, first line will contain the configuration of the cube which has color codes for faces in the following order: Up-Left-Front-Right-Back-DownNext line will consist of the moves in Singmaster's notation(Only Basic)OUTPUT:A matrix of 3x3 with color code for the tiles in the front face after the moves have been made.ExampleInputYRBOGWR2OutputB B GB B GB B GAnalysisInitial state After R2 ( R applied twice )Input 2YORBWGRL'Output 2G R GG R GG R GAnalysis 2Initial state After R After RL' (L applied anti-clockwise)Download sample testcases as zip。

机器人编程选拔试题及答案

机器人编程选拔试题及答案

机器人编程选拔试题及答案1.下面对中心点的描述正确的是() [单选题] *A. 中心点不能设置在角色之外B. 角色围绕中心点旋转(正确答案)C. 不能修改角色的中心点位置D. 其他三项都正确2.在对背景进行修改编辑的过程中,去除我们不需要的部分,需要使用绘图中的()工具。

[单选题] *A. 画笔B. 选择工具C. 橡皮擦(正确答案)D. 填充工具3.如图所示,角色向右旋转 180 度,完成后它的正确状态是() [单选题] *A.B. (正确答案)C.D.4.执行下列哪一个积木指令后,舞台上的小猫角色就会隐藏?() [单选题] *A.B. (正确答案)C.D.5.下列关于红绿灯流程图符合实际的是?() [单选题] *A.B. (正确答案)C.D.6.将一个玩具放在蓝、红、黄三个盒子里,下面只有一条正确,那么玩具放在哪个盒子里?()蓝色盒子:玩具在这个盒子里。

红色盒子:玩具不在这个盒子里。

黄色盒子:玩具不在蓝色盒子里 [单选题] *A. 蓝色盒子B. 黄色盒子C. 红色盒子(正确答案)D. 条件不充分,推导不出来7.如下图所示,判断下面哪句话是假的?() [单选题] *A. 小猫有一个黑色的鼻子B. 熊有三只耳朵(正确答案)C. 小猫看起来很高兴D. 蝴蝶有两条触须8.对角色执行完这段程序后,舞台上播放的音量为:()[单选题] *A. 80B. 30C. 60D. 20(正确答案)9.动作中移动 10 步的意思是从当前位置,向当前所指方向移动 10 步,如果写成-10 步,那就是向当前方向的反方向移动 10 步。

() [单选题] *A. 这句话正确(正确答案)B. 这句话不正确10.猫过生日,我们为它播放生日快乐歌,之后小猫高兴的喵了一声,下列代码哪个能正确的实现这个场景?() [单选题] *A. (正确答案)B.C.D.11.放暑假的小朋友明天想去家附近的游乐园玩,但是天气预报说本市明天有大暴雨和龙卷风,以下是明天最安全的选择是:() [单选题] *A. 如果下大暴雨,去游乐园B. 如果有龙卷风,去室外跑步冷静一下C. 如果下暴雨,在家学习,否则去游乐园D. 如果下暴雨或者龙卷风,在家学习(正确答案)12.如图所示,制作走迷宫的游戏,设计红色区域为目的地,我们可以通过哪组积木指令实现达到目的地的效果()[单选题] *A. (正确答案)B.C.D.13.在程序中,想要用上、下按键控制角色的上、下方向移动,下列程序编写正确的是() [单选题] *A.B.C. (正确答案)14.如果想让角色沿竖直方向移动,可以调整角色的什么参数来实现() [单选题] *A. X坐标B. Y坐标(正确答案)15.你去旅行,带了三件上衣,三件裤子,请问有几种搭配穿法呢?() [单选题] *A. 3B. 6C. 9(正确答案)D. 其他三项都正确16.下面哪个指令的运算结果为5?() [单选题] *A.B.C. (正确答案)D.17.运行下面指令模块,输入100,正确的显示效果是() [单选题] *B. 半票(正确答案)C. 全屏半票D. 半票全屏18.一个角色可以有多个造型,但是舞台只能有一个背景() [单选题] *A. 正确B. 错误(正确答案)19.角色移动一步,等于()个单位长度。

极限编程大赛试题AU

极限编程大赛试题AU

Traffic Light CheckerA three-color traffic light must switch lights in the following order: red, green, yellow, red. To indicate when crossing slowly without a stop is permitted, the yellow signal may be flashed. To indicate when crossing immediately after a full stop is permitted, the red signal may be flashed. Either flash sequence may only be started after the red light is lit and must be followed with a red. All lights are initially off. All sequences must begin a red light. Lighting any light causes all other lights to turn off. No color may be repeated: e.g., red, red is not allowed.For example, here are some valid sequences:• Red, Green, Yellow, Red, Green, Yellow, Red• Red, Green, Yellow, Red, Pause Here are some invalid sequences:• Red, Gree n, Yellow, Red, Yellow• Green, Caution, Red, Green, Yellow, Red• Red, Green, Yellow, Yellow, Red, RedTaskWrite a program that checks a sequence of light codes and determines if that sequence follows or violates the traffic light rules.InputRead from STDIN a sequence of the follow codes: R (red), Y (yellow), G (Green), P (Pause - flash red), C (Caution - flash yellow), and X (off). Each code must be separated with a space. The entire sequence is submittedby an end-of-line (e.g., pressing the Enter key.) A sequence must have no more than 15 codes in total.OutputWrite to STDOUT an evaluation of the sequence:ACCEPT The entire input sequence meets all rules.REJECT The input sequence violates any sequence constraint; for example G Y.ERROR The input is malformed –undefined code, too short, too long, etc.Example。

acm大赛试题及答案

acm大赛试题及答案

acm大赛试题及答案ACM大赛试题及答案1. 题目一:字符串反转问题描述:编写一个程序,输入一个字符串,输出其反转后的字符串。

输入格式:输入包含一个字符串,字符串长度不超过100。

输出格式:输出反转后的字符串。

示例:输入:hello输出:olleh答案:```pythondef reverse_string(s):return s[::-1]input_string = input().strip()print(reverse_string(input_string))```2. 题目二:计算阶乘问题描述:编写一个程序,输入一个非负整数n,输出n的阶乘。

输入格式:输入包含一个非负整数n,n不超过20。

输出格式:输出n的阶乘。

示例:输入:5输出:120答案:```pythondef factorial(n):if n == 0:return 1else:return n * factorial(n - 1)n = int(input())print(factorial(n))```3. 题目三:寻找最大数问题描述:给定一个包含n个整数的数组,找出数组中的最大数。

输入格式:输入包含一个整数n,表示数组的大小,随后是n个整数。

输出格式:输出数组中的最大数。

示例:输入:5 1 2 3 4 5输出:5答案:```pythonn = int(input())numbers = list(map(int, input().split()))max_number = max(numbers)print(max_number)```4. 题目四:判断闰年问题描述:编写一个程序,输入一个年份,判断该年份是否为闰年。

输入格式:输入包含一个整数,表示年份。

输出格式:如果输入的年份是闰年,则输出"Yes",否则输出"No"。

示例:输入:2000输出:Yes答案:```pythonyear = int(input())if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):print("Yes")else:print("No")```5. 题目五:斐波那契数列问题描述:编写一个程序,输入一个非负整数n,输出斐波那契数列的第n项。

codeforces round 900 题解

Codeforces Round 900 题解一、概述Codeforces是一个知名的上线编程比赛评台,每周都有各种比赛活动,吸引了全球各地的程序员参与。

而Round 900则是其中一次比赛,本文将对该比赛中的题目进行详细解析,希望能帮助读者更好地理解并掌握相关算法知识。

二、题目解析1. 题目 1题目描述:给定一个长度为n的字符串,将其所有字母进行重新排列,使得相邻的字母不相同。

求重新排列后的最长长度。

解题思路:利用贪心算法,遍历字符串,尽可能地将相同字母进行分割,重新排列。

最终得到的字符串长度即为所求。

2. 题目 2题目描述:给定一个n行m列的矩阵,每个单元格中有一个非负整数。

将矩阵中的某一行或某一列中所有元素都加上一个给定的值k,求经过加值操作后矩阵中的最大元素。

解题思路:遍历矩阵,求得每一行和每一列的最大值,然后再根据题意进行加值操作,最终得到的矩阵中的最大元素即为所求。

3. 题目 3题目描述:给定一个长度为n的整数序列,求其中的一个连续子序列,使得该子序列的元素之和尽可能大,同时要求子序列的长度不超过k。

解题思路:利用动态规划算法,维护一个长度为k的滑动窗口,遍历整个序列,不断更新窗口中元素之和的最大值,最终得到的和即为所求。

4. 题目 4题目描述:给定一个长度为n的字符串,求其中的一个最长回文子串。

解题思路:利用动态规划算法,遍历字符串,维护一个二维数组表示子串的回文性,根据动态转移方程不断更新数组,最终得到的最长回文子串即为所求。

5. 题目 5题目描述:给定一个无向图,求其中的一条最短路径,使得路径上经过的边的权值的异或和尽可能大。

解题思路:利用Dijkstra算法求最短路径,同时维护最大异或和,最终得到的路径即为所求。

三、算法实现1. 题目 1的贪心算法实现```c++string rearrangeString(string s) {int n = s.size();vector<int> count(26, 0);for (char c : s) {count[c - 'a']++;}priority_queue<p本人r<int, char>> pq; for (int i = 0; i < 26; ++i) {if (count[i] > 0) {pq.push({count[i], i + 'a'});}}string res = "";p本人r<int, char> prev = {-1, '#'};while (!pq.empty()) {p本人r<int, char> cur = pq.top();pq.pop();res += cur.second;if (prev.first > 0) {pq.push(prev);}cur.first--;prev = cur;}if (n != res.size()) {return "";}return res;}```2. 题目 2的矩阵操作实现```c++int maxAfterAddition(vector<vector<int>> mat, int k) { int n = mat.size(), m = mat[0].size();vector<int> rowMax(n, INT_MIN), colMax(m, INT_MIN); for (int i = 0; i < n; ++i) {for (int j = 0; j < m; ++j) {rowMax[i] = max(rowMax[i], mat[i][j]);colMax[j] = max(colMax[j], mat[i][j]);}}int ans = INT_MIN;for (int i = 0; i < n; ++i) {for (int j = 0; j < m; ++j) {int newMax = max(rowMax[i]+k, colMax[j]+k);ans = max(ans, newMax);}}return ans;}```3. 题目 3的动态规划实现```c++int maxSumSubarray(vector<int> nums, int k) { int n = nums.size();vector<int> dp(n, 0);int sum = 0, maxSum = 0;for (int i = 0; i < n; ++i) {sum += nums[i];if (i >= k) {sum -= nums[i-k];}maxSum = max(maxSum, sum);dp[i] = maxSum;}return maxSum;}```4. 题目 4的动态规划实现```c++string longestPalindromeSubstr(string s) {int n = s.size();vector<vector<bool>> dp(n, vector<bool>(n, false)); int maxLen = 1, start = 0;for (int i = 0; i < n; ++i) {dp[i][i] = true;}for (int len = 2; len <= n; ++len) {for (int i = 0; i < n-len+1; ++i) {int j = i+len-1;if (len == 2) {if (s[i] == s[j]) {dp[i][j] = true;maxLen = len;start = i;}} else {if (s[i] == s[j] dp[i+1][j-1]) {dp[i][j] = true;maxLen = len;start = i;}}}}return s.substr(start, maxLen);}```5. 题目 5的Dijkstra算法实现```c++int findMaxXor(vector<vector<p本人r<int, int>>> graph, int n, int start, int end) {priority_queue<p本人r<int, int>> pq;pq.push({start, 0});vector<int> dist(n, INT_MAX);dist[start] = 0;while (!pq.empty()) {p本人r<int, int> cur = pq.top();pq.pop();int u = cur.first, dis = -cur.second;if (u == end) {return dis;}for (auto e : graph[u]) {int v = e.first, w = e.second;if (dist[v] > (dist[u] ^ w)) {dist[v] = dist[u] ^ w;pq.push({v, -dist[v]});}}}return -1;}```四、总结通过对Codeforces Round 900中的五道题目进行详细解析,我们不仅学习了相关算法思想和技巧,还掌握了如何运用这些算法来解决实际问题。

编程竞赛考试题库及答案

编程竞赛考试题库及答案****1. **题目一:字符串反转****题目描述:**编写一个函数,实现将输入的字符串反转。

**输入:**字符串 `s`。

**输出:**反转后的字符串。

**答案:**```pythondef reverse_string(s):return s[::-1]```2. **题目二:两数之和****题目描述:**给定一个整数数组 `nums` 和一个目标值 `target`,请你在该数组中找出和为目标值的那两个整数,并返回他们的数组下标。

**输入:**整数数组 `nums` 和目标值 `target`。

**输出:**两个整数的数组下标。

**答案:**```pythondef two_sum(nums, target):num_to_index = {}for i, num in enumerate(nums):if target - num in num_to_index:return [num_to_index[target - num], i]num_to_index[num] = ireturn []```3. **题目三:无重复字符的最长子串****题目描述:**给定一个字符串,请你找出其中不含有重复字符的最长子串的长度。

**输入:**字符串 `s`。

**输出:**最长子串的长度。

**答案:**```pythondef length_of_longest_substring(s):char_map = {}start = max_length = 0for i, char in enumerate(s):if char in char_map and start <= char_map[char]: start = char_map[char] + 1else:max_length = max(max_length, i - start + 1) char_map[char] = ireturn max_length```4. **题目四:有效的括号****题目描述:**给定一个只包括 `'('`,`')'`,`'{'`,`'}'`,`'['`,`']'` 的字符串,判断字符串是否有效。

atcoder regular contest 144 题解

atcoder regular contest 144 题解引言概述:AtCoder Regular Contest 144(简称ARC 144)是AtCoder举办的一场定期比赛,旨在提供一个平台供程序员们展示他们的编程技能和解决问题的能力。

本文将详细解析ARC 144的题目,并提供相应的解题思路和方法。

正文内容:1. 第一大点:题目一解析1.1 小点:题目背景介绍在这里,我们将介绍题目的背景信息,包括题目的出处和相关的背景知识。

1.2 小点:问题描述在这里,我们将详细描述题目的要求和限制条件,包括输入和输出的格式要求等。

1.3 小点:解题思路在这里,我们将给出解题的思路和方法,包括算法的选择和具体的步骤。

2. 第二大点:题目二解析2.1 小点:题目背景介绍在这里,我们将介绍题目的背景信息,包括题目的出处和相关的背景知识。

2.2 小点:问题描述在这里,我们将详细描述题目的要求和限制条件,包括输入和输出的格式要求等。

2.3 小点:解题思路在这里,我们将给出解题的思路和方法,包括算法的选择和具体的步骤。

3. 第三大点:题目三解析3.1 小点:题目背景介绍在这里,我们将介绍题目的背景信息,包括题目的出处和相关的背景知识。

3.2 小点:问题描述在这里,我们将详细描述题目的要求和限制条件,包括输入和输出的格式要求等。

3.3 小点:解题思路在这里,我们将给出解题的思路和方法,包括算法的选择和具体的步骤。

4. 第四大点:题目四解析4.1 小点:题目背景介绍在这里,我们将介绍题目的背景信息,包括题目的出处和相关的背景知识。

4.2 小点:问题描述在这里,我们将详细描述题目的要求和限制条件,包括输入和输出的格式要求等。

4.3 小点:解题思路在这里,我们将给出解题的思路和方法,包括算法的选择和具体的步骤。

5. 第五大点:题目五解析5.1 小点:题目背景介绍在这里,我们将介绍题目的背景信息,包括题目的出处和相关的背景知识。

全国编程能力鉴定题库与解答

全国编程能力鉴定题库与解答介绍本文档旨在提供全国编程能力鉴定题库与解答,以帮助广大编程爱好者提升编程能力。

题库与解答以下是一些常见的编程能力鉴定题目及其解答:1. 题目一:计算两个数的和题目描述:编写一个函数,计算两个给定整数的和。

解答:def calculate_sum(num1, num2):return num1 + num22. 题目二:查找列表中的最大值题目描述:编写一个函数,接受一个整数列表作为输入,返回列表中的最大值。

解答:def find_max_value(lst):max_value = lst[0]for num in lst:if num > max_value:max_value = numreturn max_value3. 题目三:反转字符串题目描述:编写一个函数,接受一个字符串作为输入,返回该字符串的反转结果。

解答:def reverse_string(string):return string[::-1]4. 题目四:判断素数题目描述:编写一个函数,判断一个给定的正整数是否为素数。

解答:def is_prime(num):if num < 2:return Falsefor i in range(2, int(num ** 0.5) + 1):if num % i == 0:return Falsereturn True总结通过解答以上编程能力鉴定题目,我们可以提升编程能力,并且更好地理解编程概念和技巧。

希望本文档对广大编程爱好者有所帮助。

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Solving this puzzle will improve your rank to 327Bob 's Financial PlanningBob lives in Pecunia. It is a small island city completely governed by the Pecunia City Council (PCC). PCC has decided to encourage foreign investments in the city by waiving several taxes for establishing companies. Consequently, the city has attracted several high skilled workers from across the country. The demand for condos has gone up. During his career, Bob saved some money. He realized that this is the right time to invest in real estate because the demand is soaring. He decided to purchase condos of different sizes and rent them out. He collected data about condos available for purchase from the classified ads in the local newspaper Pecunia Tribune.PCC has laid out a plan in order to build infrastructure hand in hand with the amount of investment. According to this, the influx of companies to various parts of the city will be carefully controlled for the next few years. Bob used this data to estimate the prices of the condos in the coming years.An important factor to keep in mind is property taxes. Bob has to pay a tax to PCC at the end of every month for all the properties he owned during that month. It is a fixed percentage of the estimated value of the property on that date. Also, whenever Bob purchases a property, he needs to pay a fixed percentage of its value as registration fee to the government. Bob is confident that the property tax rate and registration fee percentage will not change during his life time.Bob has a secure job that guarantees a steady stream of income. He is confident of saving a fixed percentage of his monthly salary (after tax) for investments until his retirement. Also, he gets an annual bonus that can completely be used for investments. He wants to invest his current savings, future savings and the rent he would obtain from his properties. He needs your help in coming up with an investment plan such that his estimated net worth at the time of his retirement is maximized. Net worth is defined as the value of all his properties plus any liquid cash. Your input is a list of lines. The values in each line are separated by spaces. The significance of each line in the input is explained below.∙Number of years to Bob’s retirement [N]∙Bob’s current savings [C]∙Percentage of Bob’s monthly (after tax) salary that he could use towards investing∙N lines follow with each line containing two numbers – monthly salary for the year (after tax) [Si], annual bonus for the year(after tax) [Bi]. i.e., the first line corresponds to the current year; the next line corresponds to the next year and so on so forth ∙Property tax percentage per month [T]∙Property registration fee percentage [F]. This is paid only once when Bob purchases a property∙Number of condos available for purchase [P]∙Each of the P lines that follow contains the details of a condo available for purchase. On each line, there will be one or more 4-tuples (i.e., a sequence of 4 values). Those 4 values represent: year [Yi]; month [Mi]; estimated rent [Ri]; estimated market value [Vi]. For example, the 4-tuple Y1, M1, R1, V1 states that effective from the year Y1 and (the 1st of) month M1, the estimated rent and market value of the condo are R1 and V1 respectively. The estimated rent and market value of the condo are assumed to remain the same until Y2 and M2. Then on, R2 and V2 will apply. Note that the first tuple will always have with Y1 = 1, M1 = 1, and the tuples arechronologically ordered. i.e., the input always has Yi <= Yi+1and if Yi = Yi+1 then Mi < Mi+1.Output should contain exactly one line: Bob 's estimated worth when he retires rounded to 2 decimal points.Assumptions∙Input is valid.∙All the money is in the same currency. Input numbers are positive floating point values rounded to 2 places after the decimal point.They do not have any formatting (e.g., hundred thousand is input as 100000 or 100000.00 but not as 100,000). Bob 's maximum worth at the end of N years is guaranteed to be less than a billion.∙Today is January 1st 2012.∙Bob 's annual bonus is deposited on the December 31st of each year.Bob wants to retire at the age of 60. He plans to retire on the December 31st (on or after his 60th birthday). Note that he would get a bonus on that day.∙Bob 's salary will remain the same for each month of any given year.It is deposited at the end of each month. His tenants pay eachmonth 's rent at the end of it.∙The condos are on a month-to-month lease. Moving out of a condo can happen only on the last day of a month. Moving into a condo can happen only on the 1st of any month i.e., there is no scope for rentinga condo for a part of a month.∙Assume that all the properties that Bob did not purchase are available for sale at all the time during the next N years.∙The maximum number of properties available for purchase at any time [P] is less than or equal to 15.∙The banks in Pecunia do not give any interest for keeping Bob 's money with them. Also, he is completely averse to borrowing money from people or organizations.∙Bob does property transactions (i.e., purchasing and selling) only at the end of a month.Exampleinput1651.705912.29 103.890.42241 1 72.62 741.97 1 6 67.66 646.20 1 7 58.83 563.79 1 10 57.95 526.55 1 12 62.73 656.491 1 80.65 832.35 1 11 92.79 951.74 1 12 102.73 975.861 1 111.34 976.17 1 3 105.85 895.93 1 7 110.76 920.65 1 10 102.63 887.31 1 11 104.72 1094.79 1 12 94.91 898.431 1 67.15 564.28 1 11 65.47 553.74 1 12 52.53 530.26Output2248.64。

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