SampleExam(Ch1, 2, 3)(Spring2008)

Circle your choices on this paperPart I: Multiple Choice Questions: (1 pt each) (Multiple answers allowed for this test)1. The binary value 10011 is ____a______ in hex.a. 13b. 10c. 12d. 14e. 1A#2. Hexadecimal number A1 is binary number ______e______.a. 11001001b. 10010100c. 11100001d. 01100001e. 10100001#3. Note that the Unicode for character A is 65. The expression "A" + 1 evaluates to ___a_____.a. A1b. Bc. 66d. Illegal expression#4. The expression (int)(76.0252175 * 100) / 100 evaluates to ____a_____.a. 76b. 76.02c. 76.0252175d. 76.03#5. To add a value 1 to variable x, you write a,b,da. x += 1;b. x = 1 + x;e. 1 + x = x;#6. To declare a constant MAX_LENGTH inside a method with value 99.98, you write da. final float MAX_LENGTH = 99.98;b. double MAX_LENGTH = 99.98;c. final MAX_LENGTH = 99.98;d. final double MAX_LENGTH = 99.98;#7. what is y displayed in the following code? cpublic class Test {public static void main(String[] args) {int x = 1;int y = x++ + x;System.out.println("y is " + y);}}a. y is 2.b. y is 1.c. y is 3.d. y is 4.#8. Is 'a' larger than 'A'. aa. trueb. false#9. The Unicode of 'a' is 97. What is the Unicode for 'c'? ba. 98b. 99c. 97d. 96#10. Which of the Boolean expressions below is incorrect? A,c,ea. (-10 &lt; x &lt; 0)b. !(x &gt; 0) && (x &gt; 0)c. (true) && (3 =&gt; 4)d. (x &gt; 0) || (x &lt; 0)e. (x != 0) || (x = 0)#11. Suppose x=10 and y=10 what is x after evaluating the expression (y &gt; 10) && (x++ > 10). ca. 9b. 11c. 10#12. Which of the following is the correct expression that evaluates to true if the number x is between 1 and 100 or the number is negative? da. ((x < 100) && (x > 1)) && (x < 0)b. (1 > x > 100) || (x < 0)c. 1 < x < 100 && x < 0d. ((x < 100) && (x > 1)) || (x < 0)#13. Analyze the following code:Code 1:boolean even;if (number % 2 == 0)even = true;elseeven = false;Code 2:boolean even = (number % 2 == 0); ba. Code 1 has syntax errors.b. Both Code 1 and Code 2 are correct, but Code 2 is better.c. Both Code 1 and Code 2 have syntax errors.d. Code 2 has syntax errors.#14. Assume x is 0. What is the output of the following statement? aif (x > 0)print("x is greater than 0");else if (x < 0)print("x is less than 0");elseprint("x equals 0");b. x is less than 0c. x is greater than 0d. None#15. Suppose x=10 and y=10 what is x after evaluating the expression (y &gt;=10) || (x++ > 10). ba. 9b. 10c. 11#16. Analyze the following code: bboolean even = ((231 % 2) == 0);if (even = true)System.out.println("It is even!");elseSystem.out.println("It is odd!");a. The program has a runtime errorb. The program displays "It is even!"c. The program displays "It is odd!"d. The program has a syntax error#17. What is the printout of the following switch statement? achar ch = 'b';switch (ch) {case 'a':System.out.print(ch);case 'b':System.out.print(ch);case 'c':System.out.print(ch);case 'd':System.out.print(ch);}a. bbbb. bc. bcdd. bbe. abcd#18. Analyze the following code. bint y = ((x < 100) & (x > 0)) ? 1: -1;a. The code has a syntax error because & must be &&.b. y becomes -1 after the code is executed.c. y becomes 1 after the code is executed.#19. Suppose x=0 and y=0 what is x after evaluating the expression (y > 0) &&(1 > x++). ca. -1b. 1c. 0#20. Analyze the following code fragments that assign a boolean value to the variable even. dCode 1:if (number % 2 == 0)even = true;elseeven = false;Code 2:even = (number % 2 == 0) ? true: false;Code 3:even = number % 2 == 0;a. Code 2 has a syntax error, because you cannot have true and false literals in the conditional expression.b. Code 3 has a syntax error, because you attempt to assign number to even.c. All three are correct, but Code 2 is preferred.d. All three are correct, but Code 3 is preferred.e. All three are correct, but Code 1 is preferred.#21. Which of the following code displays the area of a circle if the radius is positive. ca. if (radius != 0) System.out.println(radius * radius * Math.PI);b. if (radius >= 0) System.out.println(radius * radius * Math.PI);c. if (radius > 0) System.out.println(radius * radius * Math.PI);d. if (radius <= 0) System.out.println(radius * radius * Math.PI);#22. What is 1.0 + 1.0 + 1.0 + 1.0 + 1.0 == 5.0? aa. There is no guarantee that 1.0 + 1.0 + 1.0 + 1.0 + 1.0 == 5.0 is true.b. falsec. true#23. The statement System.out.printf("%10s", 123456) outputs _____e______. (Note: * represents a space)a. ****123456b. 123456****c. 23456*****d. 12345*****Part II: Show the output of the following code: (Write your output on the right side)(5 pts)public class Test {public static void main(String[] args) {int x1, x2, i, j, k, y, z;float f;x1 = 1;x2 = 1;y = 5 + x1--;z = 5 + ++x2;i = 6 % 4;j = 1;j += j + 3;k = 25 / 2;f = (float)((2 / 5) * k);System.out.println("x1 is " + x1); 0System.out.println("x2 is " + x2); 2System.out.println("i is " + i); 2System.out.println("j is " + j); 5System.out.println("k is " + k); 12System.out.println("y is " + y); 6System.out.println("z is " + z); 7System.out.println("f is " + f); 0.0}}Part III:A.(5 pts) Write a complete program named Exam1.java. The program reads three double numbersfrom the keyboard and displays the average of these three numbers.B. (5 pts) Write a program that prompts the user to enter an integer and checks whether the numberis divisible by both 5 and 6, or neither of them, or just one of them. Here are some sample outputs for inputs 10, 30, and 23.10 is divisible by 5 or 6, but not both30 is divisible by both 5 and 623 is not divisible by either 5 or 6KeyPart I: Multiple Choice Questions.1. The binary value 10011 is __________ in hex.a. 13b. 10c. 12d. 14e. 1AKey:a#2. Hexadecimal number A1 is binary number ____________.a. 11001001b. 10010100c. 11100001d. 01100001e. 10100001Key:e#3. Note that the Unicode for character A is 65. The expression "A" + 1 evaluates to ________.a. A1b. Bc. 66d. Illegal expressionKey:a#4. The expression (int)(76.0252175 * 100) / 100 evaluates to _________.a. 76b. 76.02c. 76.0252175d. 76.03Key:a#5. To add a value 1 to variable x, you writea. x += 1;b. x = 1 + x;c. x := 1;e. 1 + x = x;Key:abd#6. To declare a constant MAX_LENGTH inside a method with value 99.98, you writea. final float MAX_LENGTH = 99.98;b. double MAX_LENGTH = 99.98;c. final MAX_LENGTH = 99.98;d. final double MAX_LENGTH = 99.98;Key:d#7. what is y displayed in the following code?public class Test {public static void main(String[] args) {int x = 1;int y = x++ + x;System.out.println("y is " + y);}}a. y is 2.b. y is 1.c. y is 3.d. y is 4.Key:c#8. Is 'a' larger than 'A'.a. trueb. falseKey:a#9. The Unicode of 'a' is 97. What is the Unicode for 'c'?a. 98b. 99c. 97d. 96Key:b#10. Which of the Boolean expressions below is incorrect?a. (-10 &lt; x &lt; 0)b. !(x &gt; 0) && (x &gt; 0)c. (true) && (3 =&gt; 4)d. (x &gt; 0) || (x &lt; 0)e. (x != 0) || (x = 0)Key:ace#11. Suppose x=10 and y=10 what is x after evaluating the expression (y &gt; 10) && (x++ > 10).a. 9b. 11c. 10Key:c#12. Which of the following is the correct expression that evaluates to true if the number x is between 1 and 100 or the number is negative?a. ((x < 100) && (x > 1)) && (x < 0)b. (1 > x > 100) || (x < 0)c. 1 < x < 100 && x < 0d. ((x < 100) && (x > 1)) || (x < 0)Key:d#13. Analyze the following code:Code 1:boolean even;if (number % 2 == 0)even = true;elseeven = false;Code 2:boolean even = (number % 2 == 0);a. Code 1 has syntax errors.b. Both Code 1 and Code 2 are correct, but Code 2 is better.c. Both Code 1 and Code 2 have syntax errors.d. Code 2 has syntax errors.Key:b#14. Assume x is 0. What is the output of the following statement?if (x > 0)print("x is greater than 0");else if (x < 0)print("x is less than 0");elseprint("x equals 0");a. x equals 0b. x is less than 0c. x is greater than 0d. NoneKey:a#15. Suppose x=10 and y=10 what is x after evaluating the expression (y &gt;= 10) || (x++ > 10).a. 9b. 10c. 11Key:b#16. Analyze the following code:boolean even = ((231 % 2) == 0);if (even = true)System.out.println("It is even!");elseSystem.out.println("It is odd!");a. The program has a runtime errorb. The program displays "It is even!"c. The program displays "It is odd!"d. The program has a syntax errorKey:b#17. What is the printout of the following switch statement?char ch = 'b';switch (ch) {case 'a':System.out.print(ch);case 'b':System.out.print(ch);case 'c':System.out.print(ch);case 'd':System.out.print(ch);}a. bbbb. bc. bcdd. bbe. abcdKey:a#18. Analyze the following code.int x = 0;int y = ((x < 100) & (x > 0)) ? 1: -1;a. The code has a syntax error because & must be &&.b. y becomes -1 after the code is executed.c. y becomes 1 after the code is executed.Key:b#19. Suppose x=0 and y=0 what is x after evaluating the expression (y > 0) && (1 > x++).a. -1b. 1c. 0Key:c#20. Analyze the following code fragments that assign a boolean value to the variable even. Code 1:if (number % 2 == 0)even = true;elseeven = false;Code 2:even = (number % 2 == 0) ? true: false;Code 3:even = number % 2 == 0;a. Code 2 has a syntax error, because you cannot have true and false literals in the conditional expression.b. Code 3 has a syntax error, because you attempt to assign number to even.c. All three are correct, but Code 2 is preferred.d. All three are correct, but Code 3 is preferred.e. All three are correct, but Code 1 is preferred.Key:d#21. Which of the following code displays the area of a circle if the radius is positive.a. if (radius != 0) System.out.println(radius * radius * Math.PI);b. if (radius >= 0) System.out.println(radius * radius * Math.PI);c. if (radius > 0) System.out.println(radius * radius * Math.PI);d. if (radius <= 0) System.out.println(radius * radius * Math.PI);Key:c#22. What is 1.0 + 1.0 + 1.0 + 1.0 + 1.0 == 5.0?a. There is no guarantee that 1.0 + 1.0 + 1.0 + 1.0 + 1.0 == 5.0 is true.b. falsec. trueKey:a#23. The statement System.out.printf("%10s", 123456) outputs ___________. (Note: * represents a space)a. ****123456b. 123456****c. 23456*****d. 12345*****Key:aPart II: Show the output of the following code:(5 pts)public class Test {public static void main(String[] args) {int x1, x2, i, j, k, y, z;float f;x1 = 1;x2 = 1;y = 5 + x1--;z = 5 + ++x2;i = 6 % 4;j = 1;j += j + 3;k = 25 / 2;f = (float)((2 / 5) * k);System.out.println("x1 is " + x1);System.out.println("x2 is " + x2);System.out.println("i is " + i);System.out.println("j is " + j);System.out.println("k is " + k);System.out.println("y is " + y);System.out.println("z is " + z);System.out.println("f is " + f);}}x1 is 0x2 is 2i is 2j is 5k is 12y is 6z is 7f is 0.0Part III:B.(5 pts) Write a complete program named Exam1.java. The program reads three double numbersfrom the keyboard and displays the average of these three numbers.import java.util.Scanner;public class Test {/**Main method*/public static void main(String[] args) {Scanner input = new Scanner(System.in);// Prompt the user to enter an integerSystem.out.print("Enter number1:");int number1 = input.nextInt();System.out.print("Enter number2:");int number2 = input.nextInt();System.out.print("Enter number3:");int number3 = input.nextInt();// Display resultsSystem.out.println("The average is " + (number1 + number2 + number3) / 3);}}B. (5 pts) Write a program that prompts the user to enter an integer and checks whether the numberis divisible by both 5 and 6, or neither of them, or just one of them. Here are some sample outputs for inputs 10, 30, and 23.10 is divisible by 5 or 6, but not both30 is divisible by both 5 and 623 is not divisible by either 5 or 6import java.util.Scanner;public class Exercise3_12 {public static void main(String[] args) {Scanner input = new Scanner(System.in);// Prompt the user to enter an integerSystem.out.print("Enter an integer: ");int number = input.nextInt();if (number % 5 == 0 && number % 6 == 0)System.out.println(number + " is divisible by both 5 and 6");else if (number % 5 == 0 ^ number % 6 == 0)System.out.println(number + " is divisible by both 5 and 6, but not both");elseSystem.out.println(number + " is not divisible by either 5 or 6");}}。