(完整版)士兵军考试题：2017年军队院校招生文化科目统一考试——士兵高中数学模拟试题1(含答案),推荐文档
2017年军队院校生长军官招生文化科目统一考试——士兵高中英语试题及答案
2017 年士兵高中军考英语真题一、选择填空（共15 分，每小题 1 分）1. —We could invite John and Barbara to the Friday night party.—Yes, ____ ? I’ll give them a call right now.A.why notB. what forC. whyD. what2. Try ____ she might, Sue couldn’t get the door open.A. ifB. whenC. sinceD. as3. Planning so far ahead ____ no sense-so many things will have changed by next year.A. madeB. is makingC. makesD. has made4. I wasn’t sure if he was really interested or if he ____ polite.A. was just beingB. will just beC. had just beenD. would just be5. The lawyer rarely wears anything other than jeans and a T-shirt ____ the season.A. whateverB. whereverC. wheneverD. however6. I like getting up very early in summer. The morning air is so good ____.A. to be breathedB. to breatheC. breathingD. being breathed7. —Have you known Dr. Jackson for a long time?—Yes, since she ____ the Chinese Society.A.has joinedB. joinsC. had joinedD. joined8. We all know that, ____, the situation will get worse.A. not if dealt carefully withB. if not carefully dealt withC. if dealt not carefully withD. not if carefully dealt with9. I smell something ____ in the kitchen. Can I call you back in a minute?A. burningB. burntC. being burntD. to be burnt10. Does this meal cost $50? I ____ something far better than this!A. preferB. expectC. suggestD. suppose11. The prize will go to the writer ____ story shows the most imagination.A. thatB. whichC. whoseD. what12. They ____ have arrived at lunchtime but their flight was delayed.A. willB. canC. mustD. should13. It is generally accepted that ____ boy must learn to stand up and fight like ____man.A. a; aB. a; theC. the; theD. a; /14. It is important to pay your electricity bill on time, as late payments may affect your ____.A. conditionB. incomeC. creditD. status15. —It was a wonderful trip. So, which city did you like better, Paris or Rome?—____. There were good things and bad things about them.A. It’s hard to sayB. I didn’t get itC. You must be kiddingD. Couldn’t be better二、阅读理解（共40 分，每小题2 分）Passage 1How can you remember a song from your childhood to this day? Why do your teachers use songs to teach you English? It seems there is a scientific reason for this.Researchers are now studying the relationship between music and remembering a foreign language. They find that remembering words in a song is the best way to remember even the most difficult language.“Singing could be a new way of learning a foreign langu age. The brain likes to remember things when they are used in a catchy and meaningful way”, said Dr, Karen Ludke. The findings may help those who have difficulties learning foreign languages. On his blog, Dr. Ludke writes, “A listen-and-repeat singing method can support foreign language learning, and opens the door for future research in this area.”Many language teachers know the value of using music and singing. Hua Zhuying, a teacher at a Chinese language school in Washington, D.C. depends heavily on songs in teaching Chinese. She says, “I use music all the time to teach children Chinese. For little kids usually we use the music. Not only does it work, but it is fun for kids.”“Sometimes, I think if I were taught English that way, maybe I could speak mu ch better English than now,” Hua Zhuying adds.Our brain likes music, especially for remembering. So, if you’re still struggling in learning a language, why not try singing it out ?16. According to the passage, the best way to remember a foreign language is to .A. listen to the teacher carefullyB. copy the words many times.C. remember words in a songD. read and write more17.The underlined word “catchy” probably means “____”A.infamousB. boringC. impressiveD.emotional18.Dr. Ludke believes that foreign language learning can be supported by .A. writing songs with the languageB. listening to all kinds of famous musicC. using the listen-and-repeat singing methodD. reading the lyrics again and again19.From the passage, we know that Hua Zhuying .A. is interested in writing English songsB. teaches Chinese in an American schoolC. teaches children English by using musicD. is a researcher in a language school20.The passage mainly tells us that .A. many researchers realize the importance of language studyingB. many language teachers know the value of famous musicC. your brain remembers a language better if you sing it.D. you will never learn a language well unless you can singPassage 2Mass media are tools of communication. Mass media can be divided into two groups: print media and electronic media. By print media, we mean books, newspapers and magazines. Electronic media include television, computer, radio and movie. Mass media allow us to record and pass information rapidly to a large, scattered audience.They extend our ability to talk to each other by helping us overcome barriers caused by time and space. There are various ways in which mass media make daily life easier for us. Firstly, they inform and help us keep a watch on our world. They gather and pass on information we would be unlikely or unable to obtain on their own.Secondly, mass media help us to arrange our time and life. What we talk about and what wethink about are greatly influenced by the media. When people get together, they tend to talk about certain happenings in newspapers or on TV. Because we are exposed to different points of view through different kinds of media every day, we are able to evaluate all sides of a certain issue.Thirdly, the media are used to persuade people. A good example is advertisements through the media. Newspapers, magazines and TV are filled with all kinds of colorful, persuasive advertisements. Though many advertisements may not say openly that they want you to buy a certain product, they describe their products in such a way that you may want to buy them.Fourthly, the media also entertain. All of the media make efforts to try to entertain their audience. For instance, even though the newspaper is a prime medium of information, it also contains entertainment features. Television, motion pictures, fiction books and some radio stations and magazines are devoted mainly to entertainment. It is estimated that in the future, the entertainment function of mass media will become even more important than it is now.21. What makes it possible for people living in different places to communicate with each other?A. Printed mediaB. Mass mediaC. Electronic mediaD. Computers22. Which of the following functions of mass media is Not mentioned?A. To make people well informed about the worldB. To amuse and entertain peopleC. To help people arrange their time and lifeD. To give people a sense of honor23. Certain matters in newspapers or on TV tend to be talked about when people get together because ____.A. people are curious about themB. people are influenced by those mass mediaC. it is fashionable for people to do soD. it is easy for people to communicate in this way24. How does advertisement make people purchase certain goods according to the passage?A. By giving an attractive account of the goods.B. By asking people to buy them.C. By forcing people to buy them.D. By giving people something extra.25. Which of the following media is mainly devoted to information according to the passage?A. TVB. MagazinesC. Motion PicturesD. NewspapersPassage 3When international aid is given, steps must be taken to ensure (确保)that the aid reaches the people for whom it is intended. The way to achieve this may not be simple. It is very difficult for a nation to give help directly to people in another nation. The United Nations Organization (UNO) could undertake to direct the distribution of aid. Here however rises the problem of costs. Also tied with this is time. Perhaps the UNO could set up a body of devoted men and women in every country who can speedily distribute aid to victims of floods and earthquakes.More than the help that one nation can give to another during a disaster; it would be more effective to give other forms of help during normal times. A common proverb says, “Give me afish and I eat for day, teach me to fish and I eat for a lifetime.” If we follow this wise saying, it would be right to teach people from less developed nations to take care of themselves. For example, a country could share its technology with another. This could be in simple areas like agriculture or in more complex areas like medical and health care or even in building satellites. Even small country is able to help less developed nations. Sometimes what is take for granted, like the setting up of a water purification plant or the administration of a school, could be useful for countries which are looking about to solve common problems. It does not cost much to share such simple things. Exchange students could be attached for a number of months or years and learn the required craft while on the site. They can then take their knowledge back to their homelands and if necessary come back from time to time to clear doubts or to update themselves. Such aid will be truly helpful and there is no chance of it being temporary or of it falling into the wrong hands.Many countries run extensive courses in all sorts of skills. It will not cost much to include deserving foreigners in these courses. Besides giving effective help to the countries concerned, there is also the build-up of friendships to consider. Giving direct help by giving materials may be effective in the short run and must continue to be given in the event of emergencies. However, in the long run what is really effective would be the sharing of knowledge.26. According to the author, how could international aid reach the victims in time?A. By solving the cost problemsB. By solving the transportation problemsC. By relying on the direct distribution of the UNO.D. By setting up a body of devoted people in every country.27. What does the author try to express in the underlined sentence?A. Providing food is vital. Learning to fish is helpfulC. Teaching skills is essentialD. Looking after others is important.28. The second paragraph is developed mainly ____.A.by contrastB.by processC.by comparisonD.by example29. Which aid is likely to fall into the wrong hands?A. A medical team.B. An exchange program.C. Financial support.D. A water plant.30. What can we infer about international aid from the passage?A. It is facing difficultiesB. It is unnecessary during normal timesC. It should be given in the form of materialsD. It has gained support from developed countriesPassage 4Human needs seem endless. When a hungry man gets a meal, he begins to think about an overcoat; when a manager gets a new sports car, a big house and pleasure boats dance into view.The many needs of mankind might be made up of several levels. When there is moneyenough to satisfy one level of needs, another level appears.The first and most basic level of needs involves food. Once this level is satisfied, the second level of needs, clothing and some sort of shelter, appears. By the end of World WarⅡ, these needs were satisfied for a great majority of Americans. Then a third level appeared. It included such items as automobiles and new houses.By 1957 or 1958 this third level of needs was fairly well satisfied. Then, in the late 1950s, a fourth level of needs appeared: the “life-enriching” level. While the other levels involve physical satisfaction, that is, the feed in comfort, safety, and transportation, this level stresses mental needs for recognition, achievement, and happiness. It includes a variety of goods and services, many of which could be called “luxury” items. Among them are vacation trips, the best medical and dental care, and recreation. Also included here are fancy goods and the latest fashions.On the fourth level, a lot of money is spent on services, while on the first three levels more is spent on goods. Will consumers raise their sights to a fifth level of needs as their income increases, or will they continue to demand luxuries and personal services on the fourth level?A fifth level would probably involve needs that can be achieved best by community action. Consumers may be spending more on taxes to pay for government action against disease, ignorance, crime, and prejudice. After filling our stomachs, our clothes closets, our garages, our teeth and our minds, we now may seek to ensure the health, safety, and leisure to enjoy more fully the good things on the first four levels.31. According to the passage, man will begin to think about such needs as housing and clothing only when _____.A. he has saved up enough moneyB. he has grown dissatisfied with his simple shelterC. he has satisfied his hungerD. he has learned to build houses32. It can be inferred from the passage that by the end of World War Ⅱ, most Americans _____.A. were very richB. lived in povertyC. had the good things on the first three levelsD. did not own automobiles33. Which of the following is NOT related to "physical satisfaction"?A. A successful career.B. A comfortable home.C. A good meal.D. A family car.34. What is the main concern of man on the fourth level?A. The more goods, the better.B. The more mental satisfaction, the better.C. The more "luxury" items, the better.D. The more earnings, the better.35. The author tends to think that the fifth level .A．would be little better than the fourth levelB．may be a lot more desirable than the first fourC．may ask consumers to spend less on taxesD．would be attainable before the government takes actions三、完形填空（共15 分，每小题 1 分）Eco-tourism involves people traveling to beautiful but environmental sensitive places. Such trips are 36 carried out with an experienced guide. Over recent years, this type of travel has been steadily gaining 37 as more people search for new travel experiences.Eco-tourism has many benefits. First, all the money spent by the tourists is used to protect the important environmental spots they visit. Second, it helps visitors to better understand the environment, thereby 38 their knowledge of the world. Furthermore, this style of travel is also more 39 of the local culture.Compared to 40 tourists, eco-tourists use energy more efficiently, save water and produce less rubbish by finding ways to 41 it. These behaviors have a 42 and lasting effect on the local environment.Two things are needed to make eco-tourism a/an 43 . First, it should be done in small groups. And second, because it requires considerable effort, both eco-tourists and locals must be 44 in their commitment to improving the environment.Green travel provides local people with jobs in parks, 45 and shops. One great achievement of eco-tourism has been the 46 of illegal hunting. Former hunters can now work as guides to help keep the animals 47 in their natural surroundings. Green travel also 48 local people's quality of life, especially children's. Peru is one country using eco-tourism to promote respect for the 49 . It's now able to take better care of its rainforests because of a focus on more sustainable(不破坏生态环境的，可持续的)travel. 50 this, local people's living-standards have improved. Many others are now following Peru's example and using eco -tourism to preserve their environment for the future generations.36. A. finally B. usually C. suddenly D. roughly37. A. pleasure B. satisfaction C. popularity D. freedom38. A. approving B. confirming C. enriching D. supporting39. A. respectful B. aware C. uncertain D. independent40. A. rich B. curious C. lazy D. normal41. A. use B. recycle C. copy D. restrict42. A. challenging B. disappointing C. positive D. risky43. A. success B. adventure C. tool D. symbol44. A. polite B. sincere C. doubtful D. grateful45. A. mines B. factories C. schools D. hotels46. A. ban B. result C. decline D. appearance47. A. close B. safe C. friendly D. active48. A. influences B. examines C. balances D. improves49. A. environment B. law C. economy D. hosts50. A. But for B. According to C. In spite of D. In addition to四、翻译（共 20 分，汉译英每小题 3 分，英译汉每小题 2 分）51.每个人都能做与他体力和脑力相适应的工作。
(word完整版)士兵军考试题：2017年军队院校招生文化科目统一考试——士兵高中数学模拟试题1(含
阶段性检测试题一、选择题(共9小题，每题4分)1、 已知全集 U = R ，集合 A = {x|lg x < 0}, B = {x|2x< 32}，则 AU B = ( D )1 1A . ?B . (0, 3]C . [3, 1]D •(—汽 1] 1(1)由题意知，A = (0, 1], B = (— ^, 3]，二 AU B =(—汽 1].故选 D. 2.已知等比数列{an}的公比为正数，且a s a s = 2毛2,2,则印=(C )A1口 2A.qB ^2_C . 2D . 2解析：选c.由等比数列的性质得， Tq>0,a^^ _ a2 .a6= 2a5, q =話=2, a1 = ~q = 2,故选 C.n3. 已知 f(x) = 3sin x —n x ,命题 p ： ? x € 0,刁，f(x)<0，则(D ) nA . p 是假命题，p ： ? x € 0,兀,f(x) >0nB.p 是假命题， p ： ? x0€ 0, ，f(x0) >0nC. p 是真命题，p ： ? x € 0,刁，f(x)>0 nD. p 是真命题， p ： ? x0€ 0, "2，f(x0) >0n解析：选D.因为f ' (x)3cos x —n,所以当x € 0,—时，f ‘(x)<0,函数f(x)单调递减,n所以？ x € 0,刁，f(x)<f(0) = 0,所以p 是真命题，又全称命题的否定是特称命题，所 以答案选D.4. 已知向量a , n2 nb 满足|a|= 3, |b|= 23 且a € (升b),贝S a 与b 的夹角为(D )3 n 5 n C.4D.6A. 2B. 3解析：选 D.a € (a+ b)? a •(令b)= a2+ a •扣|a|2+ |a||b|cos0,故cos 〈 a, b> 〈a, b>宁，故所求夹角为詈.5.下列函数中，既是偶函数又在区间(一^, 0)上单调递增的是(A )A . f(x) = 4rB . f(x) = x 2+ 1 xC . f(x) = x 3D . f(x) = 2-x1解析：选A.A 中f(x)=辺是偶函数，且在(-汽0)上是增函数，故A 满足题意.B 中 f(x) = x2 + 1是偶函数，但在(—汽0)上是减函数.C 中f(x) = x3是奇函数.D 中f(x) =2 — x 是非奇非偶函数.故B , C , D 都不满足题意.6.已知lg a + lg b = 0,则函数f(x)=才与函数g(x) = — log b x 的图象可能是( B) 解析：选 B.Tlg a + lg b = 0,二 ab = 1,T g(x) = — logbx 的定义域是(0,+ ^)故排除A . 若 a > 1,则 0v bv 1, 此时f(x) = ax 是增函数， g(x) = — logbx 是增函数， 结合图象知选B.7、已知数列｛an ｝的前n 项和为Sn ,a 1 =1, S n = 2a n +1，则S n =( B )3 n — 1 B.2D .2~H2n — 1A . 2n — 12 n — 1 C.3［解析］(1)由已知 Sn =2an +1,得 Sn = 2(Sn + 1 — Sn),即 2Sn + 1 = 3Sn,Sn + 1 = 3 Sn = 2,3 n — 1而 S1 = a1 = 1,所以 Sn = 2 ［答案］B8•设正实数x , y , z 满足x 2 — 3xy + 4? — z = 0.则当2Z 取得最大值时，三—f 的最大值为厶 入 y 厶(B )…z — x 2— 3xy + 4y 2_x 4y W4— 3— 1.一十 一3 y x当且仅当y =皱，即x = 2y 时等号成立，此时z = x 2— 3xy + 4y 2= 4y 2 — 6y 2 + 4y 2= 2y 2, y x2 12 2 1 2 1 2 1 …x 十 y — z _ 2y 十 y — 2y 2_ — y 2 十 y _—y1.20 (a 1 + a 20) 小 10 (a 1+ a 10)解析：选 C.S 20 — 2S 10=2— 2 X=10(a 20 — a 10) = 100d. 又 a 10= a 2 + 8d ,••• 33= 1 + 8d , ••• d= 4.• S 20— 2S 10= 400.二、填空题(共8小题，每题4分)1、 函数E l%2的定义域为()lg (x — 1)解析：要使函数有意义，10 + 9x — x 2> 0,则x 需满足x —1>0,lg (x — 1)工 0,解①得—1< x < 10.所以不等式组的解集为(1, 2)U (2, 10].2、 函数y = cos(— 2x)的单调减区间为 ____4⑶由 y = cos 才一2x = cos2x —亍，得n2k nW 2x ——"4 W 2k n + n (k € Z) n , 5 n故 k n + "8 W x W k n+ g (k € Z)n 5 n所以函数的单调减区间为 k n+§, kn+石(k € Z)C.9解析：选 B.z = x 2 — 3xy + 4y 2(x>0, y>0, z>0), .xy xy 1 一 12 2 1 2—1 + 1,二当y = 1时，£+1—2的最大值为y 9.已知｛a n ｝为等差数列，a i0= 33, a 2= 1, (C )A . 40B . 200S.为数列｛a n ｝的前n 项和，则S 20 — 2Sw 等于C . 400D . 20(x+ 1)(x — 10) <0,① x>1, XM 2,3、函 数 f(x)=3x 3x 2 3 3x 4 在［0 , 2］上的最小值是( )17 B .-10 A .— 3-364 C .— 4D .-飞解析: 选 A.f ' (x) = x2+ 2x — 3, 令f (=0,得 x = 1(x = — 3 舍17 10又 f(0) = - 4, f(1) = --3-, f(2)=-亍,17故f(x)在［0, 2］上的最小值是f(1) = -j.4、某三棱锥的三视图如图所示，则该三棱锥最长棱的棱长为 6、若命题“ ？ x °€ R , 2x 0 — 3ax o + 9<0”为假命题，贝卩实数a 的取值范围是______________________________________________________________________________ .因为 “？ x o € R , 2x 2 — 3ax °+ 9<0” 为假命题，则 “？ x € R , 2x 2— 3ax + 9>0” 为 真命题.因此△= 9a 2 — 4X2X9<0,故一2 2<a <2 2.7、若函数f(x)(x € R)是周期为4的奇函数，且在［0 , 2］上的解析式为f(x)= x (1 — x ), 0< x < 1,29 41贝 S f 丁 + f 7" = _______sin n x, 1<x< 2, 4 5 629 3 341 7T f(x)是以 4 为周期的奇函数，二 f = f 8 — 3 = f — 4 , f ~6 = f 8— 7rr3 3 3 3T 当 0<x< 1时,f(x) = x(1 — x), /. f 4 = 4X 1— 4 = 16. T 当 1<x<2 时，f(x)= sin n解析：根据三视图还原几何体，得如图所示的三棱锥 P-ABC.由 三视图的形状特征及数据，可推知 PA €平面ABC ，且PA = 2. 底面为等腰三角形，AB = BC ,设D 为AC 中点，AC = 2,则 AD = DC = 1,且 BD = 1,易得 AB = BC = ：2,所以最长的棱为 PC , PC = d PA2 + AC2 =2 2. 答案：2 2 5、若数列｛a n ｝满足 a 1 = 15,且 3a *+1= 3a * — 4,则 a n =4 解析：由 3a n +1 = 3a n — 4,得 a n +1 — a n= — 3,4所以｛a n ｝是等差数列，首项a 1= 15,公差d =-3,4 49— 4n所以 an = 15-3(n —1)= 3 —.答案: 49 —4n312•又Tf(X)是奇函数，-3 f -7 =_f 7 = 1 16， 6 — 6 — 2'3 _ 5 16= 16-8. _____________ 设函数f(x) = ax 3— 3x + 1(x € R ,若对于任意x € [- 1, 1],都有f(x)》成立，则实数 a 的值为 .解析：(构造法)若x = 0,则不论a 取何值，f(x)》显然成立；“ ， 3 (1 — 2x )则 g ‘ (x) (x4,1 1 所以g(x)在区间0, 1上单调递增，在区间2, 1上单调递减,1因此 g(x)max = g 2 = 4,从而 a >4.3 1当x<0时，即x € — 1, 0)时，同理a 戈2 — x3.g(x)在区间[—1, 0)上单调递增， 二 g(x)min = g( —1)= 4,从而a<4综上可知a =4. 答案：4 三.计算下列各题：(18分)1 32 4 — __ (1)』g 49— 3© 8 + lg 245；解: (1)如 49— 4lg 8 + lg 2451 4 3 1=2 x (5lg 2 — 2lg 7) — 3 X 西 2 + 2(lg 5 + 2lg 7) 5 1=2© 2 — lg 7 — 2lg 2 + qlg 5 + lg 7 1 1 1 1=^lg 2+2lg 5=］g(2 x=)夕(2)在€ ABC 中，a, b , c 分别为内角 A , B , C 的对边，且 2asin A = (2b + c)sin B + (2c + b)sin C.求角A 的大小； ［解］(1)由题意知，x ,7_ 6当x>0时，即x € (0, 1］时，f(x)=ax3 — 3x +1》0可化为 a >x2 — x3 设 g(x) 3 —丄x2 — ,根据正弦定理得2a2= (2b + c)b + (2c + b)c , 即 a2= b2 + c2 + bc. €由余弦定理得a2= b2 + c2 — 2bccos A ,1故 cos A = — 2, A = 120° . 四、(12分)已知p ：1冨2,q:x 22x1 m2 0(m 0)，若P 是q的必要不充分条件, 求实数m 的取值范围。
2017年解放军军考语文真题及参考答案
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一、单项选择题。
（共15分）1．加线字的注音，完全正确的是（ ） A ．滂沱p āng 诤友zhèng 蓓蕾bèi 量体裁衣liángB ．处分chù 糜烂mí 场院cháng 风驰电掣zhìC ．漱口sù 重创chuāng 内疚jiù 谆谆教导zhūnD ．渣滓zǐ 痉挛jìng 绮丽q ǐ 装模作样mú2．没有错别字的是（ ）A ．甄别 腥红 亲和力 声名鹊起B ．迂腐 乔迁 舶来品 两全齐美C ．福址 喝彩 挖墙脚 甘之如饴D ．真谛 整饬 明信片 共商国是3．加线的成语，使用恰当的是（ ）A ．四月的瘦西湖，碧波荡漾，柳风拂面，花团锦簇，游客们无不感到如沐春风。
B ．围场县营造了世界最大的人工林，拥有华北最大的林海。
大片的草原和林海，构成了名副其实的“华北之肺”。
C ．这位已故知名作家的作品，由于各种原因一直没有发表，这次出版对于编辑来说，有点敝帚自珍的意味。
D ．对于房价在全国略胜一筹的北京来说，经济适用房的低价位无疑对工薪阶层具有巨大的吸引力。
4．下列各句没有语病、语意明确的一项是（ ）A ．青少年只要树立了远大的理想和正确的人生观，有了明确的生活目标，生活才会变得充实而富有意义。
B ．由于受到人类的活动影响较小，使山地旅游资源较好地保持了原始自然风貌。
【精品】解放军军考化学5年真题及答案德方军考汇编(2013-2017)
（2013-2017）解放军军考化学真题，解放军士兵考军校，解放军军考化学，德方军考，解放军军考历年真题，解放军军考资料目录2013年军队院校招生士兵高中化学真题 (2)2014年军队院校招生士兵高中化学真题 (4)2015年军队院校招生士兵高中化学真题 (6)2016年军队院校招生士兵高中化学真题 (8)2017年军队院校招生士兵高中化学真题 (10)2013年军队院校招生士兵高中化学真题答案 (12)2014年军队院校招生士兵高中化学真题答案 (13)2015年军队院校招生士兵高中化学真题答案 (14)2016年军队院校招生士兵高中化学真题答案 (15)2017年军队院校招生士兵高中化学真题答案 (16)2013年军队院校招生士兵高中化学真题可能用到的相对原子质量H:1 C:12 O:16 Na:23 S:32 I:127 K:39 Fe:56 Al:27 Ba:137一、选择题（每小题3分，共18分。
每小题只有一项正确答案）1、下列电子式书写错误的是（）A. B. C. D.2、在pH=13的无色溶液中，可以大量共存的一组离子是（）A. Na+、ClO-、AlO2-、NO3-B. CrO42-、K+、Na+、SO42-C. NH4+、NO3-、K+、SO42-D. CO32-、NO3-、HCO3-、Na+3、实验室用铜和稀硝酸制取NO时，为了加快反应速率可以采取的措施是（）A. 加热B. 增加压强C. 改用浓硝酸D. 减小稀硝酸浓度4、下列实验中需用温度计，且温度计水银球的位置需伸入反应液液面以下的是（）A. 石油分馏B. 实验室制溴苯C. 实验室蒸馏酒精D. 实验室用乙醇制乙烯5、将含有浓度相同的CuSO4、Zn(NO3)2、AgNO3的水溶液水解，在阴极上首先得到的物质是（）A. CuB. AgC. ZnD. H26、经检测，某品牌白酒中含有塑化剂的主要成分为邻苯二甲酸二丁酯，其结构简式为COOCH2CH2CH2CH3COOCH2CH2CH2CH3，下列有关说法正确的是（）A. 该酯可以增加白酒香味，对人体无害B. 该酯的分子式为C16H21O4C. 用邻苯二甲酸与丁醇反应可以合成邻苯二甲酸二丁酯D. 该酯不能发生加成反应二、填空题（每空3分，共36分）1. 蛋白质是由组成的结构复杂的高分子化合物。
军考真题数学【完整版】
2017年军考真题士兵高中数学试题关键词：军考真题，德方军考，大学生士兵考军校，军考数学，军考资料 一、单项选择（每小题4分，共36分）．1. 设集合A={y|y=2x ，x ∈R}，B={x|x 2﹣1＜0}，则A ∪B=（ ）A ．（﹣1，1）B ．（0，1）C ．（﹣1，+∞）D ．（0，+∞）2. 已知函数f （x ）=a x +log a x （a ＞0且a ≠1）在[1，2]上的最大值与最小值之和为（log a 2）+6，则a 的值为（ ）A ．B ．C ．2D ．43. 设a b 、是向量，则||=||a b 是|+|=|-|a b a b 的（ ） A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件 4．已知421353=2,4,25a b c ==，则（ ）A ．b<a<cB ．a<b<cC ．b<c<aD ． c<a<b 5. 设F 为抛物线C ：y 2=3x 的焦点，过F 且倾斜角为30°的直线交C 于A ，B 两点，O 为坐标原点，则△OAB 的面积为（ ）A ．B ．C ．D ．6. 设数列{a n }是首项为a 1、公差为-1的等差数列，S n 为其前n 项和，若S 1，S 2，S 4成等比数列，则a 1=（ ）A ．2B ．C ．﹣2D ．﹣7. 袋中共有15个除了颜色外完全相同的球，其中有10个白球，5个红球．从袋中任取2个球，所取的2个球中恰有1个白球，1个红球的概率为（ ）A ．B ．C ．D ．18. 已知A ，B ，C 点在球O 的球面上，∠BAC=90°，AB=AC=2．球心O 到平面ABC 的距离为1，则球O 的表面积为（ ）A ．12πB ．16πC ．36πD ．20π9. 已知2017ln f x x x =+（）（），0'2018f x =（），则0x =（ ） A. 2e B.1 C. ln 2 D. e二、填空题（每小题4分，共32分）10. 设向量，，且，则m=．12. 已知A、B为双曲线E的左右顶点，点M在E上，△ABM为等腰三角形，且顶角为120°，则E的离心率为．13. 已知函数f（x）=，则f（f（））= ．14. 在的展开式中x7的项的系数是．15. 我国第一艘航母“辽宁舰”在某次舰载机起降飞行训练中，有5架“歼﹣15”飞机准备着舰，如果甲、乙两机必须相邻着舰，而丙、丁两机不能相邻着舰，那么不同的着舰方法数是_______。
【精品】解放军军考数学5年真题及答案德方军考汇编(2013-2017)
寄 讲、教材习题精讲和专项突破视频课程，相信对你的军考备考会很有帮助，现在军考通 APP 视频课免费公开 语 了 20%！
一． （36 分）选择题，本题共有 9 个小题，每个小题都给出代号为 A, B. C,D 的四个结论，其中只有一个结论是正 确的，将正确的结论代号写在答题纸指定位置上，选对得 4 分，选错、不选或多选一律得 0 分． 1．已知集合 P={-1，0，1}，Q={x│x=ab，a，b∈P 且 a≠b） ，则 P∪Q= A．{0,1} B．{ -1,0} C．{-1,0,1} ．
目录
2013 年军队院校招生士兵高中数学真题 .............................................................................................................................. 2 2014 年军队院校招生士兵高中数学真题 .............................................................................................................................. 6 2015 年军队院校招生士兵高中数学真题 ............................................................................................................................ 10 2016 年军队院校招生士兵高中数学真题 ............................................................................................................................ 14 2017 年军队院校招生士兵高中数学真题 ............................................................................................................................ 20 2013 年军队院校招生士兵高中数学真题答案 ....................................................................................... 25 2014 年军队院校招生士兵高中数学真题答案 .................................................................................................................... 28 2015 年军队院校招生士兵高中数学真题答案 .................................................................................................................... 31 2016 年军队院校招生士兵高中数学真题答案 .................................................................................................................... 36 2017 年军队院校招生士兵高中数学真题答案 .................................................................................................................... 40
【精品】2017年边消防军考全科真题及答案详解德方军考汇编
2017年军考真题，边消防军考真题汇编，军考数学，军考语文，军考英语，军考政治，军考物理，军考化学，边消防士兵考军校资料，德方军考，边消防军考资料目录2017年边消防军考语文真题 (2)2017年边消防军考数学真题 (7)2017年边消防军考英语真题 (11)2017年边消防军考综合真题 (17)2017年边消防军考语文真题参考答案 (29)2017年边消防军考数学真题参考答案 (31)2017年边消防军考英语真题参考答案 (34)2017年边消防军考综合真题参考答案 (35)边消防军考语文真题，边消防士兵考军校资料，边消防军考语文，德方军考，边消防军考真题，边消防军考资料一、单项选择题。
（每题2分，共30分）1．下面加线字读音全部相同的一项是（）A．烟火绿茵咽喉要塞B．消防逍遥销声匿迹C．沾光玷污拈轻怕重D．敦厚淳朴谆谆教导2．下列各组词语中，没有错别字的一项是（）A．浇筑干金顶旗织鲜明B．缜秘核幅射防微杜渐C．荟萃迷彩服集思广益D．商确福利院责无旁代3．下列句子中“靠边”一词，意思相同的一组是（）①机动车在行驶中出现故障，要及时靠边站。
②谁工作不得力，就让谁靠边站。
③把桌子靠边摆，腾出点空间。
④别说，你刚才的话还挺靠边。
A．①③B．①④C．②⑨D．②④4．下列文字横线处依次填入词语，最恰当的一组是（）东水门有一段城墙，城门洞还在，像一个的老人豁开的嘴，城外杂乱无序的吊脚楼依山崖、依陡坡而建，看上去，仿佛一跺脚就会。
A．饱经沧桑岌岌可危塌陷B．曾经沧海岌岌可危垮塌C．饱经沧桑摇摇欲坠垮塌D．曾经沧海摇摇欲坠坍塌5．下列句子中加线成语适用恰当的一项是（）A．公安英模事迹报告会上，听众用振聋发聩的掌声表达对英模的崇敬。
B．只有发扬无微不至的精神，才能不遗漏任何线索，把一疑案办成铁案。
C．近几年来，网络诈骗案件层出不穷，手段也独具匠心，使人防不胜防。
D．指导员提纲挈领的几句话，为我们接下来的工作指明了方向。
2017年士兵高中军校数学模拟卷
军校模拟试卷（六）一、选择题：本大题共9小题，每小题4分，共36分，在每个小题给出的四个选项中，只有一项是符合题目要求的．1．函数1y x x =+-的值域为（ ）．A ．[0,)+∞B ．[0,2]C ．[2,)+∞D ．[1,2]2．已知{(,)|2},{(,)|4}M x y x y N x y x y =+==-=，则M N = （ ）．A ．3,1x y ==-B ．(3,1)-C ．{3,1}-D ．{(3,1)}-3．若ln 2ln 3ln 5,,235a b c ===，则（ ）．A ．a b c <<B ．c b a <<C ．c a b <<D ．b a c <<4．设n S 是等差数列{}n a 的前n 项和，若5359a a =,则95S S 的值等于（ ）．A ．1B ．1-C ．2D ．215．等边△ABC 中的边长为2，则AB ·BC 的值为 ( ) ． A ．4 B ．4- C ．2 D ．2-6．某学校召开学生代表大会，6个代表名额分配到高二年级的3个班，要求每班至少1名，则代表名额分配方案种数是（ ）．A ．64B ．36C ．24D ．107．已知点M (a ，b )在圆O ：x 2＋y 2＝1外， 则直线ax ＋by ＝1与圆O 的位置关系是( )A ．相切B ．相交C ．相离D ．不确定8．已知函数f (x )是定义域为R 的偶函数，且f (x ＋1)＝1f （x ），若f (x )在[－1，0]上是减函数，那么f (x )在[2，3]上是( ) A ．增函数B ．减函数C ．先增后减的函数D ．先减后增的函数9．若锐角α的终边上有一点(2sin3,2cos3)-，则锐角α的弧度数是（ ）．A ．3B ．3-C ．32π-D ．32π-二、填空题：本大题共8小题，每小题4分，共32分，把答案填在题中横线上．1．若实数0,0x y >>，且3412x y +=，则lg lg x y +的最大值是_______________．2．函数2()2sin sin 1f x x x =+-的定义域是_______________． 3．若sin sin sin 0,cos cos cos 0,αβγαβγ++=++=则cos()βγ-的值是 ．4．在21(2)2n x x +的展开式中，2x 的系数是224，则21x 的系数是_______________．5．已知椭圆的焦点12(1,0),(1,0)F F -，P 是椭圆上一点，且12||F F 是 1||PF ，2||PF 的等差中项，则椭圆的标准方程是_______________．6．抛物线x y 62=的准线方程为_______________． 7．点,A B 到平面α的距离分别为4cm 和6cm ，则线段AB 的中点M 到α平面的距离为_______________． 8. =++++∞→)2121211(lim 2n x 。
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[ ] π
5π
kπ＋ ，kπ＋
所以函数的单调减区间为
8
8 (k∈Z)．
3、函数
f(x)＝
x3 3
x2
3x
4
在[0，2]上的最小值是( )
17 A．－ 3
C．－4
10 B．－ 3
64 D．－ 3
解析：选 A.f′(x)＝x2＋2x－3，
令 f′(x)＝0，得 x＝1(x＝－3 舍去)，
( )π
0， 减，所以∀x∈ 2 ，f(x)<f(0)＝0，所以 p 是真命题，又全称命题的否定是特称命题， 所以答案选 D.
4．已知向量 a，b 满足|a|＝3，|b|＝2 3，且 a⊥(a＋b)，则 a 与 b 的夹角为(D )
π
2π
3π
A. 2
B. 3
C. 4
5π D. 6
解析：选 D.a⊥(a＋b)⇒a·(a＋b)＝a2＋a·b＝|a|2＋|a||b|cos〈a，b〉＝0，故 cos〈a，b〉
∴33＝1＋8d，
∴d＝4.
∴S20－2S10＝400.
二、填空题（共 8 小题，每题 4 分）
10＋9x－x2 1、函数 f(x)＝ lg（x－1） 的定义域为( )
解析：要使函数有意义，
{ ) { ) 10＋9x－x2 ≥ 0， （x＋1）（x－10） ≤ 0，①
x－1 > 0，
x > 1，
则 x 需满足 lg（x－1） ≠ 0， 即
1
＋ －3
∴ z ＝x2－3xy＋4y2＝y x ≤4－3＝1.
x 4y 当且仅当y＝ x ，即 x＝2y 时等号成立，此时
( ) 2 1 2 2 1 2
12
1 －1
2
z＝x2－3xy＋4y2＝4y2－6y2＋4y2＝2y2，∴x＋y－z＝2y＋y－2y2＝－y2＋y＝－ y
212
＋1，∴当 y＝1 时，x＋y－z的最大值为 1.
7、已知数列{an}的前 n 项和为 Sn，a1＝1，Sn＝2an＋1，则 Sn＝( B )
( )3 n－1
A．2n－1 B. 2
( )2 n－1
C. 3
1 D.2n－1
Sn＋1 3
[解析] (1)由已知 Sn＝2an＋1，得 Sn＝2(Sn＋1－Sn)，即 2Sn＋1＝3Sn， Sn ＝2，
9.已知{an}为等差数列，a10＝33，a2＝1，Sn 为数列{an}的前 n 项和，则 S20－2S10 等于( C )
A．40
B．200
C．400
D．20
20（a1＋a20） 10（a1＋a10）
解析：选 C.S20－2S10＝
2
－2×
2
＝10(a20－a10)＝100d.
又 a10＝a2＋8d，
( )3 n－1
而 S1＝a1＝1，所以 Sn＝ 2 .
[答案] B
xy
212
8.设正实数 x，y，z 满足 x2－3xy＋4y2－z＝0.则当 z 取得最大值时，x＋y－z的最大值
为( B )
A．0
9
Hale Waihona Puke B．1C. 4D．3
解析：选 B.z＝x2－3xy＋4y2(x>0，y>0，z>0)，
1
xy
xy
x 4y
17
10
又 f(0)＝－4，f(1)＝－ 3 ，f(2)＝－ 3 ，
17 故 f(x)在[0，2]上的最小值是 f(1)＝－ 3 .
4、某三棱锥的三视图如图所示，则该三棱锥最长棱的棱长为 ________．
解析：根据三视图还原几何体，得如图所示的三棱锥 PABC.由 三视图的形状特征及数据，可推知 PA⊥平面 ABC，且 PA＝2. 底面为等腰三角形，AB＝BC，设 D 为 AC 中点，AC＝2，则 AD＝DC＝1，且 BD＝1，易得 AB＝BC＝ 2，所以最长的棱为 PC，PC＝ PA2＋AC2＝2 2.
3
5π
＝－ 2 ，故所求夹角为 6 .
5．下列函数中，既是偶函数又在区间(－∞，0)上单调递增的是( A )
A．f(x)＝ 1 B．f(x)＝x2＋1
x2
C．f(x)＝x3
D．f(x)＝2－x
1 解析：选 A.A 中 f(x)＝x2是偶函数，且在(－∞，0)上是增函数，故 A 满足题意．B 中 f(x)＝x2＋1 是偶函数，但在(－∞，0)上是减函数．C 中 f(x)＝x3 是奇函数．D 中 f(x) ＝2－x 是非奇非偶函数．故 B，C，D 都不满足题意．
6．已知 lg a＋lg b＝0，则函数 f(x)＝ax 与函数 g(x)＝－logbx 的图象可能是( B)
解析：选 B.∵lg a＋lg b＝0，∴ab＝1， ∵g(x)＝－logbx 的定义域是(0，＋∞)，故排除 A.
若 a＞1，则 0＜b＜1， 此时 f(x)＝ax 是增函数， g(x)＝－logbx 是增函数， 结合图象知选 B.
阶段性检测试题
一、选择题（共 9 小题，每题 4 分）
1、已知全集 U＝R，集合 A＝{x|lg x≤0}，B＝{x|2x≤3 2}，则 A∪B＝( D )
A．∅
1 B．(0，3]
1 C．[3，1]
D．(－∞，1]
1 (1)由题意知，A＝(0，1]，B＝(－∞，3]，∴A∪B＝(－∞，1]．故选 D.
2．已知等比数列{an}的公比为正数，且 a3a9＝2a52，a2＝2，则 a1＝( C )
1
2
A.2
B. 2
C. 2
D．2
解析：选 C.由等比数列的性质得 ，
∵q>0，
a6
a2
∴a6＝ 2a5，q＝a5＝ 2，a1＝ q ＝ 2，故选 C.
( )π
0， 3．已知 f(x)＝3sin x－πx，命题 p：∀x∈ 2 ，f(x)<0，则( D )
( )π
0， A．p 是假命题， p：∀x∈ 2 ，f(x)≥0
( )π
0， B．p 是假命题， p：∃x0∈ 2 ，f(x0)≥0
( )π
0， C．p 是真命题， p：∀x∈ 2 ，f(x)>0
( )π
0， D．p 是真命题， p：∃x0∈ 2 ，f(x0)≥0
( )π
0， 解析：选 D.因为 f′(x)＝3cos x－π，所以当 x∈ 2 时，f′(x)<0，函数 f(x)单调递
x ≠ 2，
解①得－1≤x≤10.
所以不等式组的解集为(1，2)∪(2，10]．
2、函数
y＝
cos(
2x) 的单调减区间为________．
4
( ) ( ) π
π
－2x
2x－
(3)由 y＝cos 4 ＝cos
4 ，得
π 2kπ≤2x－ 4 ≤2kπ＋π(k∈Z)，
π
5π
故 kπ＋ 8 ≤x≤kπ＋ 8 (k∈Z)．