湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 数学(文)
湖南省浏阳一中、攸县一中、醴陵一中14—15学年高一12月联考历史(附答案)
湖南省浏阳一中、攸县一中、醴陵一中14—15学年高一12月联考历史试题时间60分钟，满分100分第Ⅰ卷（选择题，共60分）一、选择题（每小题2.5分，共60分）1．“一国无二君，一庙无二祭主”，反映了西周宗法制的突出特点是A．嫡长子继承制B．神权色彩浓厚C．政治等级森严D．贵族拥有政治、经济特权2. 西汉察举制和隋朝科举制有利于加强中央集权的主要原因是A.自下而上的选拔方式扩大了统治基础B.通过分科考试选拔到一些德才兼备之士C.以儒家思想作为挑选人才的唯一标准D.皇帝和高官主考的形式提高了知识分子的政治地位3.唐中宗不经中书省和门下省而径自封拜官职，因心怯，故他装置诏敕的封袋，不敢照常式封发，而改用斜封，所书“敕”字也不敢用朱笔，而改用墨笔，当时称为“斜封墨敕”，这表明A．中书省和门下省的权力高于皇权B．唐朝中枢机构的行政决策具有民主性质C．唐中宗时期皇权有所弱化D．国家制度对皇权具有一定的约束力4.《宋史》卷一六二《职官志》记载：宋初，循唐、五代之制，置枢密院，与中书对持文武二柄，号为二府……中书、枢密院二府，每朝奏事，与中书先后上殿。
以上材料可看出A．枢密院使与中书分掌军政和财政B．枢密院使的设立，分割了宰相的权力C．加大各部权限，发挥官员的主动性D．充分分割军队指挥权，防止将领反叛5.明朝永乐帝设立内阁制，以内阁作为皇帝处理国政的助理机构。
英国“光荣革命”后，威廉三世逐渐以内阁代替枢密院，成为国王直辖的最高行政机关。
下面关于两国内阁制的叙述，正确的是A．内阁制的形成标志着两国的皇权（王权）得到空前强化B．内阁已经成为两国最高权力的象征C．明朝内阁长官称丞相，英国内阁长官称首相D．明朝内阁是君主专制加强的结果，英国内阁是君主立宪的象征6．关于雅典民主政治，苏格拉底说：“没有人愿意用抽签的方法去雇用一位舵手和建筑师、吹笛手或其他行业的人，而这类事若出错的话，危害还比在管理国家事务上出错轻得多。
湖南省浏阳一中、攸县一中、醴陵一中高三数学上学期12月联考试题 文
湖南省浏阳一中、攸县一中、醴陵一中2015届高三数学上学期12月联考试题 文本卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，满分150分，考试用时120分钟 一、选择题：本大题共10小题，每小题5分，共50分，在每小题给出的四个选项中，只有一项是符合题目要求的1、设全集(2),{|21},{|ln(1)}x x U R A x B x y x -==<==-，则图中阴影部分表示的集合为 A ．{}|1x x ≥ B ．{}|1x x ≤ C ．{}|01x x <≤ D ．{}21<≤x x 2、已知()3sin f x x x π=-，命题():(0,),02p x f x π∀∈<，则A ．p 是真命题，():(0,),02p x f x π⌝∀∈>B ．p 是真命题，p ┐： ()000,,02x f x π⎛⎫∃∈≥ ⎪⎝⎭C ．p 是假命题，():(0,),02p x f x π⌝∀∈≥D ．p 是假命题，p ┐： ()000,,02x f x π⎛⎫∃∈≥ ⎪⎝⎭3、定义在R 上的函数()f x 满足()()()(),22f x f x f x f x -=--=+，且(1,0)x ∈-时，()125x f x =+，则()2log 20f =A ．1B ．45C ．1-D ．45-4、某产品在某零售摊位的零售价x （单位：元）与每天的销售量y （单位：个）的统计资料如下表所示：由上表可得回归直线方程ˆˆˆybx a =+中的ˆ4b =-，据此模型预测零售价 为15元时，每天的销售量为A ．51个B ．50个C ．49个D ．48个5、设等比数列{a n }的前n 项和为S n .若S 2＝3，S 4＝15，则S 6＝( )A ．31B ．32C ．63D ．646、已知函数()322,()2,03a f x x ax cx g x ax ax c a =++=++≠，则它们的图象可能是7、已知函数()sin()(0)4f x x πωω=+>的最小正周期为π，则该函数的图象是A ．关于直线8x π=对称 B ．关于点(,0)4π对称 C ．关于直线4x π=对称 D ．关于点(,0)8π对称8、一只受伤的丹顶鹤在如图所示（直角梯形）的草原上飞过，其中2,1AD DC BC ===，它可能随机在草原上任何一 处（点），若落在扇形沼泽区域ADE 以外丹顶鹤能生还， 则该丹顶鹤生还的概率是（ ） A ．1215π- B ．110π- C ．16π- D ．3110π- 9、已知函数()y f x =对于任意的(,)22x ππ∈-满足()()cos sin 0f x x f x x '+>（其中()f x '是函数()f x 的导函数），则下列不等式不成立的是（ ）A ()()34f ππ< B ．()()34f ππ-<-C ．(0)()4f π<D ． (0)2()3f f π<10、已知函数()32(,f x x bx cx d bc d =+++均为常数)，当(0,1)x ∈时取极大值，当(1,2)x ∈时取极小值，则221()(3)2b c ++-的取值范围是A ．2B ．)C ．37(,25)4D ．()5,25二、填空题：本大题共5小题，每小题5分，共25分，把答案填在题中的横线上 11、若不等式131x x m ++-≥-恒成立，则实数m 的取值范围是12、定义行列式的运算:12122112a a ab a b b b =-，若将函数()sin cos xf x x=的图象向左平移(0)t t >个单位，所得图象对应的函数为偶函数，则t 的最小值为13、设曲线2cos sin x y x -=在点(,2)2π处切线与直线10x ay ++=垂直，则a =14、已知命题:p 函数()22lg(4)f x x x a =-+的定义域为R ；命题:q [1,1]m ∀∈-，不等式253a a --≥p q ∨“为真命题，且“p q ∧”为假命题，则实数a 的取值范围是15、已知函数()2xf x e x a =-+有零点，则a 的取值范围是三、解答题：本大题共6小题，共75分，解答应写成文字说明、证明过程或演算步骤 16、（本小题满分12分）已知幂函数223()()m m f x x m z -++=∈为偶函数，且在区间(0,)+∞上是单调增函数（1）求函数()f x 的解析式； （2）设函数3219()()()42g x f x ax x b x R =++-∈，其中,a b R ∈.若函数()g x 仅在0x =处有极值，求a 的取值范围.17. （本小题满分12分）已知函数()sin f x m x x =+,(0)m >的最大值为2． （Ⅰ）求函数()f x 在[]0,π上的值域； (Ⅱ)已知ABC ∆外接圆半径3=R，()()sin 44f A f B A B ππ-+-=，角,A B 所对的边分别是,a b ，求11+的值． 分）已知数列的前项和求的通项公式；，求数列的前项和．19. （本小题满分12分） 如图，在四棱锥P ABCD -中，90ABC ACD ∠=∠=︒,60BAC CAD ∠=∠=︒, PA ⊥平面ABCD ,E 为PD 的中点，22PA AB ==.(I ) 求证：CE ∥平面PAB ; ( II ) 求四面体PACE 的体积.20. （本小题满分13分） 已知椭圆C 的对称中心为原点O ，焦点在x 轴上，左右焦点分别为1F 和2F ，且|1F 2F |=2，点（1，23）在该椭圆上． （1）求椭圆C 的方程；（2）过1F 的直线l 与椭圆C 相交于A ，B 两点，若∆A 2F B 的面积为7212，求以2F 为圆心且与直线l 相切圆的方程．21.（本小题满分14分）.已知函数x x x f ln )(=，x e ax x x g )3()(2-+-=（a 为实数）． (Ⅰ) 当a=5时，求函数)(x g y =在1=x 处的切线方程； (Ⅱ) 求)(x f 在区间[t ，t+2]（t >0）上的最小值；(Ⅲ) 若存在两不等实根]1[，21，e ex x ∈，使方程)(2)(x f e x g x =成立，求实数a 的取值范围．浏攸醴11月高三文科数学考试答案一、选择题：本大题共10小题，每小题5分，共50分.在每小题给出的四个选项中， 只有一项是符合题目要求的.1. D【解析】因为图中阴影部分表示的集合为()U A C B ，由题意可知{}{}02,1A x x B x x =<<=<，所以()U A C B {}{}021x x x x =<<≥ {}12x x =≤<，故选.D2. B【解析】依题意得，当0,2x π⎛⎫∈ ⎪⎝⎭时，()3cos 30f x x ππ'=-<-<，函数()f x 是减函数，此时()()03sin000f x f π<=-⨯=，即有()0f x <恒成立，因此命题p 是真命题，p ┐应是“()000,,02x f x π⎛⎫∃∈≥ ⎪⎝⎭”.综上所述，应选.B3. C【解析】由()()()()224f x f x f x f x -=+⇒=+，因为24log 205<<，所以20log 2041<-<，214log 200-<-<，所以 ()()()22224log 20log 2044log 20log 15f f f f ⎛⎫=-=--=-=- ⎪⎝⎭.故选.C4. C【解析】由题意知17.5,39x y ==，代入回归直线方程得 109,a=109154-⨯49=，故选.C5. C [解析] 设等比数列{a n }的首项为a ，公比为q ，易知q ≠1，根据题意可得⎩⎪⎨⎪⎧a （1－q 2）1－q ＝3，a （1－q 4）1－q ＝15，解得q 2＝4，a 1－q ＝－1，所以S 6＝a （1－q 6）1－q ＝(－1)(1－43)＝63. 6. B【解析】因为()22f x ax ax c '=++，则函数()f x '即()g x 图象的对称轴为1x =-，故可排除,A D ；由选项C 的图象可知，当0x >时，()0f x '>，故函数()323a f x x ax cx =++在()0,+∞上单调递增，但图象中函数()f x 在()0,+∞上不具有单调性，故排除.C 本题应选.B7.A【解析】依题意得2,2T ππωω===，故()sin 24f x x π⎛⎫=+ ⎪⎝⎭，所以 sin 2sin 108842f ππππ⎛⎫⎛⎫=⨯+==≠ ⎪ ⎪⎝⎭⎝⎭，sin 2444f πππ⎛⎫⎛⎫=⨯+ ⎪ ⎪⎝⎭⎝⎭3sin4π==0≠，因此该函数的图象关于直线8x π=对称，不关于点,04π⎛⎫⎪⎝⎭和点,08π⎛⎫⎪⎝⎭对称，也不关于直线4x π=对称.故选.A8. B【解析】过点D 作DF AB ⊥于点F ，在Rt AFD ∆中，易知1,45AF A =∠= ，梯形的面积()115221122S =++⨯=,扇形ADE的面积221244S ππ=⨯⨯=，则丹顶鹤生还的概率12152415102S S P S ππ--===-，故选.B9.A 10. D【解析】因为()232f x x bx c '=++，依题意，得()()()00,1230,24120,f c f b c f b c '=>⎧⎪'=++<⎨⎪'=++>⎩则点(),b c 所满足的可行域如图所示（阴影部分，且不包括边界），其中()4.5,6A -，()3,0B -，()1.5,0D -.()22132T b c ⎛⎫=++- ⎪⎝⎭表示点(),b c 到点1,32P ⎛⎫- ⎪⎝⎭的距离的平方，因为点P到直线AD 的距离d ==，观察图形可知，22d T PA<<，又()22214.563252PA ⎛⎫=-++-= ⎪⎝⎭，所以525T <<，故选.D二、填空题：（5题，每题5分） 11. []3,5-【解析】由于()()13134x x x x ++-≥+--=，则有14m -≤，即414m -≤-≤，解得35m -≤≤，故实数m 的取值范围是[]3,5-.12.56π 【解析】()sin 2cos 6f x x x x π⎛⎫=-=+⎪⎝⎭，平移后得到函数 2cos 6y x t π⎛⎫=++ ⎪⎝⎭，则由题意得,,66t k t k k Z ππππ+==-∈，因为0t >，所以t 的最小值为56π. 13.1【解析】由题意得()()()222cos sin 2cos sin 12cos sin sin x x x x x y xx''----'==，在点,22π⎛⎫⎪⎝⎭处的切线的斜率1212cos2 1.sin 2k ππ-==又该切线与直线10x ay ++=垂直，直线10x ay ++=的斜率21k a=-， 由121k k =-，解得 1.a =14. []()2,12,6--【解析】若命题p 为真，则216402a a ∆=-<⇒>或2a <-.若命题q 为真，因为[]1,1m ∈-，⎡⎤⎣⎦.因为对于[]1,1m ∀∈-，不等式253a a --≥恒成立，只需满足2533a a --≥，解得6a ≥或1a ≤-.命题“p q ∨”为真命题，且“p q ∧”为假命题，则,p q 一真一假.①当p 真q 假时，可得22,2616a a a a ><-⎧⇒<<⎨-<<⎩或；②当p q 假真时，可得22,2116a a a a -≤≤⎧⇒-≤≤-⎨≤-≥⎩或.综合①②可得a 的取值范围是[]()2,12,6-- . 15. (],22ln 2-∞-+【解析】由()20xf x e '=-=，解得ln 2.x =当(),ln 2x ∈-∞时，()0f x '<，函数()f x 单调递减； 当()ln 2,x ∈+∞时，()0f x '>，函数()f x 单调递增. 故该函数的最小值为()ln2ln22ln222ln2.f ea a =-+=-+因为该函数有零点，所以()ln 20f ≤，即22ln 20a -+≤，解得22ln 2.a ≤-+ 故a 的取值范围是(],22ln 2-∞-+. 16.【答案】（1）4()f x x = （2）[2,2]a ∈-（1）()f x 在区间(0,)+∞上是单调增函数，2230m m ∴-++>即2230m m --<13,m ∴-<<又,0,1,2m z m ∈∴=…………………4分 而0,2m =时，3()f x x =不是偶函数，1m =时，4()f x x =是偶函数，4()f x x ∴=. …………………………………………6分（2）2'()(39),g x x x ax =++显然0x =不是方程2390x ax ++=的根.为使()g x 仅在0x =处有极值，必须2390x ax ++≥恒成立，…………………8分 即有29360a ∆=-≤，解不等式，得[]2,2a ∈-.…………………11分这时，(0)g b =-是唯一极值. ∴[]2,2a ∈-. ……………12分17.解：（1）由题意，()f x．………………………2分而0m >，于是m =π()2sin()4f x x =+．…………………………………4分在]4,0[π上递增．在 ππ4⎡⎤⎢⎥⎣⎦，递减，所以函数()f x 在[]0π，上的值域为]2,2[-；…………………………………5分（2）化简ππ()()sin 44f A f B A B -+-=得sin sin sin A B A B +=． (7)分由正弦定理，得()2R a b +=，……………………………………………9分 因为△ABC 的外接圆半径为3=R．a b +=．…………………………11分 所以211=+ba …………………………………………………………………12分 18. 解：(Ⅰ) 由 ①可得：．同时②②-①可得：．——4分从而为等比数列，首项，公比为．． ————————6分(Ⅱ) 由(Ⅰ)知，————8分故．——12分19、答案：1)法一： 取AD 得中点M ，连接EM,CM.则EM//PA 因为,,EM PAB PA PAB ⊄⊂平面平面所以，//EM PAB 平面 （2分）MEPDBA在Rt ACD 中，60,CAD CM AM ∠=︒= 所以，60ACM ∠=︒而60BAC ∠=︒,所以,MC//AB. （3分） 因为,,MC PAB AB PAB ⊄⊂平面平面 所以，//MC PAB 平面 （4分） 又因为EM MC M = 所以，//EMC PAB 平面平面因为,//EC EC PAB ⊂平面EMC 所以，平面 （6法二： 延长DC,AB,交于N 点，连接PN. 因为60,NAC DAC AC CD ∠=∠=︒⊥ 所以，C 为ND 的中点. （3分） 因为E 为PD 的中点，所以，EC//PN 因为,,EC PAB PN PAB ⊄⊂平面平面//EC PAB 所以，平面 （6分）2)法一：由已知条件有;AC=2AB=2,AD=2AC=4,CD=（7分） 因为，PA ABCD ⊥平面，所以，PA CD ⊥ （8分）又因为,CD AC AC PA A ⊥= ，所以， CD PAC ⊥平面 （10分） 因为E 是PD 的中点，所以点E 平面PAC 的距离12h CD == 12222PAC S =⨯⨯= 所以，四面体PACE 的体积112333PAC V S h =⨯=⨯=（12分） 法二：由已知条件有;AC=2AB=2,AD=2AC=4,CD=因为，PA ABCD ⊥平面，所以，112333P ACD ACD V S PA -=⨯=⨯⨯=（10分）ND因为E 是PD 的中点，所以，四面体PACE的体积12P ACD V V -== （12分） 20.（1）椭圆C 的方程为13422=+y x ……………．．（4分） （2）①当直线l ⊥x 轴时，可得A （-1，-23），B （-1，23），∆A 2F B 的面积为3，不符合题意． …………（6分） ②当直线l 与x 轴不垂直时，设直线l 的方程为y=k （x+1）．代入椭圆方程得：01248)43(2222=-+++k x k x k ，显然∆＞0成立，设A ),(11y x ，B ),(22y x ，则2221438k k x x +-=+，222143128k k x x +-=⋅，可得|AB|=2243)1(12kk ++ ……………．．（9分） 又圆2F 的半径r=21||2k k +，∴∆A 2F B 的面积=21|AB| r=22431||12k k k ++=7212，化简得：174k +2k -18=0，得k=±1，∴r =2，圆的方程为2)1(22=+-y x ……………．．（13分）21.解:(Ⅰ)当5a =时2()(53)x g x x x e =-+-⋅,(1)g e =. ………1分 2()(32)x g x x x e '=-++⋅，故切线的斜率为(1)4g e '=. ………2分 所以切线方程为:4(1)y e e x -=-,即43y ex e =-. ………4分 (Ⅱ)()ln 1f x x '=+,………6分 ①当et 1≥时,在区间(,2)t t +上()f x 为增函数,7分,(9分a分hh14分。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 化学 Word版含答案
2016届浏阳一中、攸县一中、醴陵一中十二月联考化学试卷时量：90分钟 总分：100分 命题人：王国成 审题人：黎倩用到的相对原子质量： Ag ．108第Ⅰ卷（选择题 48 分）一、选择题（本题包括16小题，每小题3分，共48分。
每小题只有一个选项符合题意）1．下列物质溶于水时会破坏水的电离平衡，且属于电解质的是（ ）A ．氢硫酸B ．二氧化碳C ．氯化钾D ．醋酸钠2．下列溶液呈中性的是（ ）A ．将水加热使K W 增大、pH<7B ．由水电离的c (H +)=10-10 mol·L －1的溶液C ．加水稀释除H +浓度增大外其它粒子浓度降低的溶液D ．非电解质溶于水得到的溶液3．A 与B 反应生成C ，其反应速率分别用υ(A)、υ(B)、υ(C)表示，且υ(A)、υ(B)、υ(C)之间有如下关系： υ(B)=3υ(A)； 3υ(C)=2υ(B)。
则此反应可表示为（ ）A ．A ＋3B 2C B ．2A+3B 2C C ．3A+B 2CD ．A ＋B Ｃ4．一定量的盐酸跟过量的锌粉反应时，为了减缓反应速率，且不影响生成氢气的总量，可向盐酸中加入适量的 ( )A ．NaNO 3 (溶液)B ．CH 3COONa(固体)C ．Na 2CO 3(溶液)D ．CuSO 4 (固体)5．下列依据热化学方程式得出的结论正确的是（ ）A ．已知C(石墨，s)＝C(金刚石，s) ΔH >0，则金刚石比石墨稳定B ．已知C(s)＋O 2(g)＝CO 2(g) ΔH 1 C(s)＋1/2O 2(g)＝CO(g)；ΔH 2，则ΔH 2>ΔH 1C ．已知2H 2(g)＋O 2(g)＝2H 2O(g) ΔH ＝－483.6 kJ/mol ，则氢气的燃烧热为241.8 kJ/molD ．已知NaOH(aq)＋HCl(aq)＝NaCl(aq)＋H 2O(l) ΔH ＝－57.3 kJ/mol ，则含20 g NaOH的稀溶液与稀盐酸完全中和，中和热为28.65 kJ/mol6．下列说法正确的是 （ ）A ．钢铁发生电化腐蚀的正极反应式：Fe －2e -= Fe 2＋B ．酸性条件下甲烷燃料电池的负极反应式：CH 4 ＋2H 2O －8e - =CO 2↑+8H +C ．粗铜精炼时，与电源正极相连的是纯铜D ．用活性电极电解饱和食盐水，阳极的电极反应式为：2Cl - －2e -=Cl 2↑7．下列叙述中正确的是( )A ．同温同压下，H 2(g)＋Cl 2(g)===2HCl(g)在光照条件下和点燃条件下的ΔH 不同B ．常温下反应2A(s)＋B(g)===2C(g)＋D(g)不能自发进行，则反应的焓变一定大于零C ．需要加热的化学反应，生成物的总能量一定高于反应物的总能量D ．等质量的硫粉分别在空气、氧气中燃烧，放出热量多的是硫粉在氧气燃烧8．某小组为研究电化学原理，设计如右图装置。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题 数学
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题 数学一、选择题：(本大题共10小题，每小题5分，共50分) 1.下列函数中,不满足f(2x)=2f(x)的是( ) A.f(x)=|x| B.f(x)=x-|x| C.f(x)=x+1D.f(x)=-x2. 设集合{}22,A x x x R =-≤∈，{}2|,12B y y x x ==--≤≤，则()R C AB 等于（ ）A ．RB ．{},0x x R x ∈≠ C ．{}0 D ．∅ 3. 9.01.17.01.1,9.0log ,8.0log ===c b a 的大小关系是 ( )A. c a b >>B. a b c >>C. b c a >>D.c b a >> 4. 已知,m n 是两条不同的直线，,αβ是两个不同的平面 ( ) A. 若//m n 且,m n αβ⊂⊂，则α与β不会垂直；B.若,m n 是异面直线，且,m n αβ⊥⊥，则α与β不会平行；C.若,m n 是相交直线且不垂直，,m n αβ⊂⊂，则α与β不会垂直；D. 若,m n 是异面直线，且//,//m n αβ，则α与β不会平行 5. 一个棱锥的三视图如图，则该棱锥的表面积为A ．．．．44侧视图8俯视图6. 设()21122x x f x =-+，若[]x 表示不超过x 的最大整数，则函数()y f x =⎡⎤⎣⎦的值域是（ ）A. {}0,1B. {}0,1-C. {}1,1-D. {}1,0,1-7. 若函数()⎪⎩⎪⎨⎧>-≤-+=1,1,2212x a a x ax x x f x在()+∞,0上是增函数,则a 的范围是 A ．](2,1 B ． )[2,1 C ．[]2,1 D ．()+∞,1 8．用一个平面去截正方体，则截面不可能是（ ） A.正三角形B.正方形C.正五边形D.正六边形9．已知异面直线a 和b 所成的角为50°，P 为空间一定点，则过点P 且与a 、b 所成角都是30°的直线有且仅有（ ）.A. 1条B. 2条C. 3条D. 4条10. 已知()f x 为偶函数，当0x ≥时，()()211f x x =--+，则满足()12f f a ⎡⎤=⎣⎦的实数a的个数为A ．2B ．4C ．6D ．8 二、填空题：（本大题共5小题，每小题5分，共25分） 11．计算：()222lg 5lg8lg 5lg 20lg 23++⋅+=___ ____ 12. 定义在R 上的函数()()()lg 4414x x f x x ⎧-≠⎪=⎨=⎪⎩，若关于的方程()()20f x bf x c ++=有5个不同的实根12345,,,,x x x x x ，则()12345f x x x x x ++++=___________ 13. 已知函数11)(2++=mx mx x f 的定义域是R ，则实数m 的取值范围是14. 如图，正方体1111ABCD A B C D -的棱长为1，,E F 分别为棱1DD ，AB上的点．下列说法正确的是__________.（填上所有正确命题的序号） ①1AC ⊥平面1B EF ； ②在平面1111A B C D 内总存在与平面1B EF平行的直线；③1B EF △在侧面11BCC B 上的正投影是面积为定值的三角形； ④当,E F 为中点时，平面1B EF 截该正方体所得的截面图形是五边形；15. 已知()f x 为R 上的偶函数，对任意x R ∈都有(6)()(3)f x f x f +=+且当[]12,0,3x x ∈，12x x ≠时，有1212()()0f x f x x x ->-成立，给出四个命题：①(3)0f =；②直线6x =-是函数()y f x =的图像的一条对称轴；③函数()y f x =在[]9,6--上为增函数；④函数()y f x =在[]9,9-上有四个零点，其中所有正确命题的序号为 ．三、解答题：（本大题共6小题，共75分） 16．（本小题满分12分）设函数()lg(23)f x x =-的定义域为集合M，函数()g x =N . 求：⑴集合M N ，；⑵集合R MN C N ，.17、（本小题满分12分）已知集合A={x ∈R|x 2+4x=0}, B={x ∈R|x 2+2(a+1)x+a 2-1=0}，如果A ∩B=B ，求实数a 的取值范围.18．（本小题满分12分）四棱锥ABCD P -中，底面ABCD 是边长为8的菱形，οBAD 60=∠，若5==PD PA ，平面PAD ⊥平面ABCD .（1）求四棱锥ABCD P -的体积； （2）求证：AD ⊥PB .19． （本小题满分13分）如图，在三棱柱111ABC A B C -中，四边形11AAC C 是边长为4的正方形，平面ABC ⊥平面11AAC C ，3,5AB BC ==．（Ⅰ）求证：1AA ⊥平面ABC ；（Ⅱ）若点D 是线段BC 的中点，请问在线段1AB 是否存在点E ，使得//DE 面11AAC C ？若存在，请说明点E 的位置，若不存在，请说明理由；（Ⅲ）求二面角111C A B C --的大小．20．（本小题满分13分）对于定义域为D 的函数)(x f y =，若同时满足下列条件：①)(x f 在D 内单调递增或单调递减；②存在区间[b a ,]D ⊆，使)(x f 在[b a ,]上的值域为[b a ,]；那么把)(x f y =（D x ∈）叫闭函数。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 数学(理)
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 数学（理）一、选择题（本大题共10小题，每小题5分，共50分，在每小题给出的四个选项中，只有一项是符合题目要求的。
）1．若0a b >>，0c d >>，则一定有( )A ．a b d c > B ． a bd c< C ． b a d c < D ． b a d c > 2．已知向量)5,3,2(-=a 与向量),,4(y x b -=平行,则,x y 的值分别是（ ） A ．–6和10B ．6和10C ．–6和-10D ． 6和-103．设n S 是等差数列{}n a 的前n 项和，已知23a =，611a =，则7S 等于（ ）A ．13B ．35C ．49D ．634．已知命题,:R x p ∈∃使;25sin =x 命题R x q ∈∀:，都有012>++x x 。
给出下列结论：①命题""q p ∧是真命题； ②命题""q p ∨⌝是真命题； ③命题""q p ⌝∨⌝是假命题； ④命题""q p ⌝∧是假命题。
其中正确的是（ ） A ．②③ B ．②④ C ．③④ D ．①②③5．已知命题265:x x p ≥-，命题2|1:|>+x q ，则p 是q 的（ ） A ．充分不必要条件 B ．必要不充分条件 C ．充要条件 D ．既不充分也不必要条件6．要制作一个容积为4 m 3，高为1 m 的无盖长方体容器．已知该容器的底面造价是每平方米20元，侧面造价是每平方米10元，则该容器的最低总造价是（ ） A ．160元B ．80元C ．240元D ．120元7. 抛物线24y x =的焦点到双曲线2213yx -=的渐近线的距离是（ ）A ．12B C ．1 D8．已知实数x ,y 满足约束条件⎪⎩⎪⎨⎧≤-≤≥021y x y x ’则y x z -=2的取值范围是（ ）A ．[0,1]B ．[1,2]C ．[1,3]D ．[0,2]9．已知数列{}n a 中,11,a =前n 项和为n S ，且点*1(,)()n n P a a n N +∈在直线10x y -+=上，则1231111nS S S S ++++= （ ） A.21n n + B. 2(1)n n + C. (1)2n n + D.2(1)n n + 10．若直线4=+ny mx 和⊙O ∶422=+y x 没有交点，则过),(n m 的直线与椭圆14922=+y x 的交点个数（ ） A ．至多一个 B ．2个 C ．1个 D ．0个二、填空题（本大题共5小题，每小题5分，共25分，将正确答案填在相应位置上。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题 英语
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题英语Part Ⅰ Listening comprehension (30 marks)Section A (22.5 marks)Directions In this section, you will hear 6 conversations between 2 speakers. For each conversation, there are several questions and each question is followed by 3 choices. Listen to the conversations carefully and then answer the questions by marking the corresponding letter (A, B or C) on the question booklet.You will hear each conversation TWICE.Conversation 11.What’s the man’s appointme nt(预约) for?A. An interviewB. An operationC. A medical examination2. What’s the time for the appointment?A. 300 p.m.B. 315 p.m.C. 330p.m.Conversation 23.What’s the woman’s present job?A. A secretaryB. A computer programmer.C. A game designer.4. Why does she want to change her job?A. To make more money.B. To have more challenges.C. To get a promotion.Conversation 35.Why didn’t the woman do well in her final exam?A. Because she didn’t work hard.B. Because she was too careless.C. Because she was late for it.6. How many courses did she take last year?A. 4B. 5C. 8Conversation 47. What’s wrong with the woman’s bag?A. It was stolen.B. It was lost.C. It was deposited（存放）overtime.8. What do we know about the bag?A. it’s small.B. It has a zip on the front.C. It has a pocket in the back.9. What’s in the bag?A. A toy.B. A pet.C. Some books.Conversation 510. What is the most possible relationship between the two speakers ?A. Professor and student.B. Boss and clerk（职员）.C. Colleagues.（同事）11. What report did the woman write?A. A news report.B. An academic report.C. An annual report .12. What is she possibly worrying about?A. The man is still angry with her.B. Her report will not pass through.C. Nobody helps with her work.Conversation 613. Why does the man want to leave early this Friday?A. To avoid the traffic jam.B. To pick up his friends.C. To catch the early bus.14. Who will have a presentation（讲座）on Monday?A. The woman.B. The man.C. A reporter.15. What does the woman ask the man to do?A. Make a cup of coffee.B. Do a survey.C. Write a report.SECTION B (1.5 x 5 = 7.5)Directions In this section, you’11 hear a short pas sage. Listen carefully and then fill in the numbered blanks with the information you’ve got. Fill in each blank withPart II Language Knowledge (45 marks)Section A (15 marks)Directions Beneath each of the following sentences there are four choices marked A, B, C and D. Choose the one answer that best completes the sentence.21. It’s a fine day. Let’s go fishing, ________?A. won’t youB. will youC. do n’t weD. shall we22. Crusoe’s dog became ill and died, ______made him very lonely.A. thisB. thatC. whichD. as23. Bob, along with several of his friends, ______to the art show, but sadly, theydidn’t sell any of their painting s.A. has invitedB. had invitedC. was invitedD. were invited24. –Why didn’t you buy that hat at last?-- ______ I liked the color of it , I did not like its shape.A. IfB. BecauseC. WhileD. Since25.--Jack , you ____computer games the whole morning. You’d better have a goodrest now.--Thank you, mum. I will.A. are playingB. were playingC. have playedD. have been playing26. –May I park here?-- No, you _____. It is an emergency exist.A. won’tB. needn’tC. couldn’tD. mustn’t27. Some teenagers like eating in fast food restaurant ______ you can see everywherein our city.A. whereB. whichC. whatD. when28. –What did our teacher say at yesterday’ meeting?--So you _______ to him carefully then.A. won’t listenB. weren’t listeningC. hadn’t listenedD. haven’t listened29. I heard my sister ________ an English song when I passed by her room last night.A. was singingB. singingC. to singD. sing30. If ___________, I will go to her birthday party.A. invited meB. invitingC. invitedD. be invited31. There is hard evidence ________ the accident was caused by his carelessdriving.A. whichB. whatC. whyD. that32.-- Jane, are you and your sister on a diet now?--- Yes, I want to lose some weight , and ______.A. neither she doesB. neither does sheC. so does sheD. so she does33. –Go and ask Mr. White for help.--- But I do n’t know _____________.A. where does he liveB. where he livesC. where is he livingD. he lives there34. Tom had no choice but to ________ an excuse to explain his being late.A. make upB. show upC. look upD. turn up35. Mr. Wang has made up his mind to devote all he could ______his oral Englishbefore going abroad.A. to improveB. improveC. to improvingD. improvingSection B （18 marks）Directions For each blank in the following passage there are 4 words or phrases marked A, B, C and D. Fill in each blank with a word or phrase that best fits the context.Once I came to the city near my hometown to find a job. I met all kinds of 36 and so I used up all my money soon.One day, I 37 a bus quietly at dusk when most people got off work. Suddenly, a 38 cried loudly, “ Someone has 39 my money!” I felt40 , because his money was in my hand. Some people suggested the bus be driven to the police station, but some were against it because they were in a hurry to go back home. The whole bus was very 41 . The driver then 42 the bus by the road and turned on the lights to search for the money. At that time, one passenger said, “Turn off the lights and give the thief a chance to take out the money.” Then the bus got 43 . When I was still struggling in mind whether to take out the money or not, the lights were on again. There was no 44 on the floor. Someone said again, “ Give him one more chance.” Then the lights were off again. My heart kept beating fast. The lights were on again but they got the same 45 . The passengers were in heated discussion again. At that time, someone said again, “ Give him the last chance !” Suddenly I felt awakened and took out all the money when the lights were off again.For many years I have felt grateful to the one who gave me three chances to 46 my mistake. When the first and second opportunities come, you may not be prepared well or don’t have enough 47 to act. When the third opportunity comes you should know clearly what you should do.36. A. danger B. strangers C. chances D. difficulties37. A. got on B. waited for C. ran for D. passed by38. A. thief B. passenger C. driver D. policeman39. A. borrowed B. received C. sent D. stolen40 A. sad B. calm C. nervous D. disappointed41. A. noisy B. dirty C. bright D. empty42. A. lost B. stopped C. missed D. found43. A. cold B. dark C. clean D. crowded44. A. money B. water C. paper D. space45. A. idea B. way C. result D. choice46. A. make B. try C. repeat D. correct47. A. strength B. skill C. courage D. experienceSection C (12 marks) Directions Complete the following passage by filling in each blank with one word that best fits the context.Some people think 48 it is better to see the film than to read the book in original (原著). The reason 49 they hold the opinion is that it takes less time to understand the whole story. Besides, the film is usually more interesting and50 is easier to follow51 , other people think differently. Their opinion is that they can get more detailed (详细的) information from the original book. At 52 same time, the language in the book is more lovely and beautiful.In my opinion, I agree 53 the second opinion. I have more reasons for it. I think I can study at home, reading quietly 54 myself. Moreover, I can understand the author’s idea better.In a word, to read the original work is better 55 to see the film based on it. Part III Reading Comprehension (30 marks)Directions Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage.AIn most parts of the world, many students help their schools make less pollution. They join “environment clubs”. In an environment club, people work together to make our environment clean.Here are some things students often do.No-garbage (垃圾) lunches. How much do you throw away after lunch? Environment clubs ask students to bring their lunches in bags that can be used again. Every week they will choose the classes that make the least garbage and report them to the whole school.No-car day. On a no-car day, nobody comes to school in a car. Not the students and not the teachers! Cars give pollution to our air, so remember work jump, bike and run. Use your legs! It’s lots of fun..Turn off the water! Did you know that some toilets can waste twenty to forty cubic(立方)meters of water an hour? In a year, that would fill a small river! In environment clubs, students mend those broken toilets. We love our environment. Let’s work together to make it clean.56. Environment clubs ask students __________.A. to run to school every dayB. to take exercise every dayC. not to forget to take carsD. to use lunch bags57.From the passage we know the students usually have lunch_________. .A. at schoolB. in shopsC. in chubsD. at home58. After students mend toilets, they save ___________.A. a small riverB. a clubC. water in cubic metersD. a toilet59. The writer wrote the passage to ask the students to ____________. .A. clean schoolB. make less pollutionC. join clubsD. help teachers60. Which of the following statements is true?A. On No-car day, only the teachers can go to school in their cars.B. In the clubs, students usually work together to make the earth less polluted.C. The water in the toilet can fill a river.D. Students can take their lunch in paper, so they can throw it after lunch.BWill it matter if you don't take your breakfast? Recently a test was given in the United States. Those tested included people of different ages, from 12 to 83. During the experiment, these people were given all kinds of breakfasts, and sometimes they got no breakfast at all. Special tests were set up to see how well their bodies worked when they had eaten a certain kind of breakfast. The results show that if a person eats a proper breakfast, he or she will work with better effect than if he or she has no breakfast. This fact appears to be especially true if a person works with his brains. If a student eats fruit, eggs, bread and milk before going to school, he will learn morequickly and listen with more attention to class.Opposite to what many people believe, if you don't eat breakfast, you will not lose weight. This is because people become so hungry at noon that they eat too much for lunch, and end up gaining weight instead of losing. You will probably lose more weight if you reduce your other meals.61. During the test, those who were tested were given ________.A. no breakfast at allB. very rich breakfastC. little food for breakfastD. different breakfast or none62. The results of the test show that ________.A. breakfast has great effect on work and studiesB. breakfast has little to do with a person’ s workC. a person will work better if he has a simple breakfastD. those working with brains should have much for breakfast63. The passage mentions that many people believe that if you don't eat breakfast, you will _________.A. lose weightB. not lose weightC. be healthierD. gain a lot of weight64. Which of the following is Not true according to the passage?A. Poor breakfasts affect those who work with brains.B. Morning diet may cause one to get fatter.C. Reducing lunch and supper is of less value in weight losing.D. Eating less in lunch and supper may help to lose weight.65. According to the passage, if a student does not eat breakfast, ___________.A. he will fall illB. he will fail to listen to his teacherC. he will not make progress in his studyD. his mind will work more slowlyCI was a medical student. To gather data for my paper, I started visiting patients at Dr Sardjito Hospital, where I would review the medical records of patients and then interview them.One evening, I was in a ward(病房), desperately “hunting” for the final three patients I needed to complete my study. Holding a patient questionnaire, I walked towards a room. A patient called Ms A was lying in bed, clearly still weak. There were no relatives or friends with her. Even the bed beside her was empty. I sat down on a chair next to her bed, and in a low voice I introduced myself and asked if I could gather some additional information from her. She agreed. After I finished, I prepared to leave. Before I could stand up, Ms A said, “ I haven’t seen you here befo re, doctor. Are you new?” “Not really, Madam. It’s just that I don’t come here every day,” I replied. Ms A started talking about herself. She shared her difficulties and sufferings, talked about her husband, who was killed in a car accident, and that she struggled to earn money. All I did was nod my head as a way of showing my sympathy.Without realizing it, I had begun holding Ms A’s hand. Finally, Ms A stopped talking. “I’m very sorry for keeping you here to listen to my problem, but I feelrelieved now. I had no one to pour out my problems to.” Tears fell from the corner of her eyes. Finally, I knew what to say. “It’s OK, Madam. It’s part of my duty.” I stood up and waved goodbye. A few days later, when I returned to the ward, I discovered Ms A had left the hospital as her condition had improved.Ms A taught me the most important lessons a doctor can learn. Sometimes patients do not need expensive medicine. They just need someone with the patience and willingness to lend an ear and spare a little of their time.66. Why did the author interview the patients at Dr Sardjito Hospital?A. Because it was the duty as a medical student.B. Because she needed medical information for her paper.C. Because she was going to get a good position there soon.D. Because she wanted to learn about the suffering of patients.67. From Paragraph 2 we can infer that Ms A was feeling________.A. relaxedB. annoyedC. nervousD. lonely68. What do we know about Ms A from the passage?A. She had lost her husband and kidsB. She got hurt in a traffic accidentC. she was living in a hard conditionD. she didn’t get on well with others69. Ms A tended to think that _________.A. the author was kind and patient enough to share her sufferingsB. other doctors treated her in a cold wayC. she shouldn’t talk about her difficulties to doctorsD. doctors ought to learn how to cure her psychological (精神上的)problems70. What conclusion did the author draw after interviewing Ms A?A. A doctor must learn how to treat each patient equally.B. Her psychological treatment made Ms A recover quickly.C. Listening is sometimes the best thing a doctor can do for a patient.D. It is the doctors’ duty to receive whatever patients say.Part 1V Writing (45 marks)Section A(10 marks) Directions Read the following passage. Fill in the numbered blanks by using the information from the passage.Write NO MORE THAN THREE WORDS for each answer.Are you afraid of math? You are not alone. A dislike of math can begin as early as first grade, and be with you for life. In fact, it becomes common as children start school.If you suffer(受苦) from math anxiety, it is not because you have no ability to study well, but because, at some point, someone or something destroyed your confidence. If you think you are bad at math, you’ll be bad at it. So you should work hard to regain （恢复）your confidence.Luckily, the fear of math can be overcome（克服）. You can learn math in different ways. For example, search the library for books or study on the Internet to master thefundamentals(基本原理) of math. Do some exercises to build up your confidence. It is also very important to understand how to use formulas（公式）to solve the problems.Though you may feel it difficult to study math well, yet don’t give up so easily. You can begin by preparing for math classes in advance. Ask questions during class. Take notes carefully and read them again after class. Do all the required homework in time. If you still need help, turn to your teachers or classmates who study math very well.In short, to study math well, you have to try hard, start early, and never give up.Section B (10 points)Directions Read the following passage. Answer the questions according to the information given in the passage and required words limit. Write your answers on your answer sheet.In 2005, a local tourist reported seeing a strange object in the Tianchi Lake. 52-year-old Zheng Changchun, his daughter and his son-in-law were enjoying the scenery in the western side of Changbai Mountain. Suddenly, in the middle of the lake, zheng saw a strange, black object showing up from the water and disturbing(搅乱) the calm surface of the lake.“I was so excited and shouted loudly that there was a monster in the lake,”said Zheng.Immediately Zheng took his camcorder（摄像录像机）and managed to record the whole process on film, but it quickly disappeared under the water.Zheng said that when they climbed to the top of the mountain above the Tianchi Lake at about 10 am, it was covered with thick fog which suddenly gave way to bright sunshine. The glassy surface of the lake was perfect for taking photos.In the one-minute film shot by Zheng, a black object could be seen appearing from the water in the same place three times. It stayed on the water for just a few seconds, before it finally disappeared.“ We were more than 1,000 meters away so it was difficult to see it clea rly, but I would say what we saw above water was the size of the head of an adult ox. And I did notice that every time it appeared form the water, there were ripples （涟漪）on the surface of the lake.”81. Where did the strange object appear? (No more than 9 words)82. How did Zheng Changchun feel at the sight of the strange object?(no more than 3 words)83. What could people see in the one-minute film shot by Zheng Changchun?(no more than 14 words)84. According to the passage, what was the object like?(no more than 7 words) Section C (25 marks)Directions Write an English composition according to the instructions given below. 下图是你对你们班上周中午休息时间内学生活动的调查结果。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题 化学
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试题化学可能用到的相对原子质量：H1 C12 O16 Al27 Cu64 S32 Cl35.5 Fe56 Na23第Ⅰ卷（选择题：共40分）一、选择题（本题包括20小题，每小题2分，共40分，每小题只有一个选项最符合题意。
）1.随着人们生活节奏的加快，方便的小包装食品已被广泛接受。
为了延长食品的保质期，防止食品受潮及富脂食品氧化变质，可用适当方法在包装袋中装入( )A．无水硫酸铜、蔗糖 B．生石灰、硫酸亚铁C．食盐、硫酸亚铁 D．生石灰、食盐2.高一学生小强的化学笔记中有如下内容：①纯净物按照组成可以分为单质和化合物②单质又可分为金属和非金属③无机化合物主要包括：酸、碱、盐和氧化物④按照分散剂粒子直径大小可将分散系分为溶液、浊液和胶体⑤水溶液能导电的化合物就是电解质⑥按照树状分类法可将化学反应分为：氧化还原反应和离子反应⑦氧化还原反应的特征是化合价升降你认为他的笔记中有几处错误( )A．三处B．四处C．五处 D．六处3.下图是某加碘食盐包装袋上的部分图表文字(I为碘元素符号)。
由此，你得到的信息和作出的推测是( )A.此食盐是纯净物B.加碘食盐中的“碘”是指碘单质C.1kg此食盐中含碘酸钾(35±15) gD.菜未烧熟不宜加入加碘盐的原因可能是碘酸钾受热不稳定4.小明家收藏了一张清末的铝制佛像，至今保存完好。
其未被锈蚀的主要原因是( )A．铝不易发生化学反应B．铝的氧化物易发生还原反应C．铝不易被氧化D．铝易被氧化为氧化铝，氧化铝膜具有保护内部铝的作用5.如图所示的实验操作中，正确的是( )6.某无色溶液中放人铝片后有氢气产生，则下列离子在该溶液中肯定可以大量存在的是( )A. Na+ B．Mg2+ C．OH- D．HCO3-7.下列反应，其产物的颜色按红色、红褐色、淡黄色、蓝色顺序排列的是( )①金属钠在纯氧中燃烧②FeSO4溶液中滴入NaOH溶液，并在空气中放置一段时间③FeCl3溶液中滴入KSCN溶液④无水硫酸铜放入医用酒精中A．②③①④B．③②①④C．③①②④D．①②③④8.用N A表示阿伏加德罗常数的值，下列说法正确的是( )A．常温常压下，32 g O2和O3的混合气体所含原子数为2N AB．1 mol·L-1 K2SO4溶液中含有的钾离子数为0.1N AC．等质量钠，在足量氧气中加热充分反应比在足量氧气(常温)中充分反应失去的电子多D．标准状况下，18g H2O的体积约为22.4L9.下列离子方程式中，正确的是( )A．氢氧化钠溶液中通入过量CO2：CO2＋2OH－= CO32-＋H2OB．金属铜与稀盐酸反应：Cu＋2H＋= Cu2＋＋H2↑C．Ca(OH)2溶液与Na2CO3溶液反应：Ca2＋＋CO2－3= CaCO3↓D．氯化铝与过量氨水反应：Al3+＋4OH－= AlO－2＋2H2O10.现有三组溶液：①汽油和氯化钠溶液②碘的CCl4溶液③氯化钠和单质溴的水溶液，分离以上各混合液的正确方法依次是( )A．萃取、蒸发、分液 B．分液、蒸馏、萃取C．分液、萃取、蒸馏 D．蒸馏、萃取、分液11.下列各组中的物质作用时，反应条件或反应物用量的改变，对生成物没有影响的是( )A．Fe和FeCl3B．Na与O2C．NaOH与CO2 D．NaOH与AlCl312.某溶液中有Fe3＋、Mg2＋、Fe2＋和Al3＋四种阳离子，若向其中加入过量的氢氧化钠溶液，搅拌后，再加入过量的盐酸，溶液中大量减少的阳离子是( )A．Fe3＋ B．Mg2＋ C．Fe2＋ D．Al3＋13.下列实验现象描述不正确的是( )14.ClO2是一种杀菌效率高、二次污染小的水处理剂。
湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高一上学期12月联考试卷 政治.pdf
，因为这会导致
A．流通中的货币量减少→居民购买力下降→社会有效需求不足→生产萎缩
B．生产资料价格下降→企业生产成本降低→企业经济效益提高→经济过热
C．生活资料价格下降→居民购买力上升→居民消费需求增加→物价上涨
D．社会投资减少→生产萎缩→失业率上升→经济衰退
9.中小企业是我国最具活力的企业群体,在GDP?中的比重约为60%,提供了约70%?的城镇就业岗位。自2011?年以来
力汽车和燃料电池汽车免征车辆购置税。对于新能源汽车消费者和生产者而言,不考虑其他因素，下图中能正确反
映这种变动的
①
②
③
④
A.?①③B.?①④C.?②③D.?②④
11.克莱斯勒汽车公司决定从2013年9月30日起，再次在华召回2639辆进口2013款克莱斯勒大捷龙汽车，召回原因是
该款汽车的气囊控制模块存在软件错误。该公司召回问题车辆
D．索要和提供餐饮发票有利于减少税收流失 ．材料一 A省GDP和财政收入情况 项目 年份GDP（亿元）财政收入（亿元 ）20087141．9916．220098345．72034．520109974．22326．0201111052．92551．2201213263．43063．8注：近年来 A省财政支出不断扩大，重点向民生领域倾斜，实施的民生工程项目从2008年12项增加到2012年的33项，投入953．8亿 ，其中2012年投入445亿，同比增长40。 材料二 近年来，A省收入差距扩大的趋势尚未得到有效遏制，初次分配和再分配中仍存在诸多不公平因素。根据国 家十二五规划提出的要求，城乡居民收入增长要超过7%，与经济发展同步。2011年，A省上调了最低工资标准。这样的 国家理念与地方选择彰显着一个基本共识科学发展不仅需要经济增长，还需要科学的财富分配。 （1）经济生活角度谈谈对材料一的认识。（分） （2）经济生活角度结合材料，A省如何实现社会公平。（1分） 近年来，越来越多的人开始选择电动轿车。微型电动轿车制造成本低廉，预计售价3万—5万元，使用成本仅为百公 里3元左右。微型电动机车虽然不能彰显身份，也受时速、续航里程的限制，但对于广大富裕进来的中等收入人群，特 别是城市中生途出行的人群来说是比较适合的。而且电动轿车是一种绿色环保交通工具，可以显著改善城市空气质量。 结合材料，分析电动轿车受到青睐的原因。 23．2013年2月份以来，全国各地羊肉价格出现持续上涨，目前全国羊肉均价为每公斤50元左右，与2012年同期相 比涨幅普遍超过20%。业内人士认为，当前羊肉价格上涨反映了我国肉羊生产能力不足，供给增长速度跟不上需求的高 涨。在当下羊产业发展基础薄弱、养殖效率不高、饲养成本上升、散户退出的速度加快、规模养殖发展缓慢的情况下 ，其供需矛盾必将日益突出。 羊肉价格上涨对人们生活与生产的影响有哪些 2017届高一浏攸醴三校联考 政治答案 总分100分 时量60分钟 命题人：攸县一中高一政治组 一、选择题（本大题共小题（1）A省地区生产总值（GDP）不断增长，财政收入也在逐年增多；A省财政支出规模不 断扩大，并重点向民生领域倾斜；经济发展是财政收入和财政支出增长的基础。 （2）坚持和完善按劳分配为主体、多种分配方式并存的分配制度，为我国实现社会公平、形成合理有序的收入分 配格局提供重要的制度保证。 居民收入在国民收入分配中占合理比重、劳动报酬在初次分配中占合理比重，实现居民收入增长和经济发展同步、 劳动报酬增长和劳动生产率提高同步这是实现社会公平的重要举措。 再分配更加注重公平是实现社会公平的另一重要举措。政府要加强对收入分配的调节，通过税收等手段，整顿分配 秩序，把收入差距控制在合理范围内。收入是消费的前提和基础。我国经济发展人民生活水平不断提高这是人们购买电 动轿车的主要原因。物价变动会影响人们的购买力。电动轿车价格低廉也使电动轿车日益受青睐。人们的消费行为受消 费心理的影响。求实的消费心理也使得人们从自己的实际出发选择经济实惠的电动轿车。电动轿车绿色环保的特点很好 地满足了人们的保护环境，绿色消费的需要。 ①价格变动会引起需求量的变动。羊肉价格上涨，会使人们减少对羊肉 的消费，会导致其替代品如鸡肉、猪肉等的需求量增加。②价格变动会促使生产者调节生产规模。羊肉价格上涨，利润 增加，会吸引养殖户扩大养殖规模，增加肉羊供应量，从而满足市场对羊肉的需求。
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湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 数学（文）一、选择题（本大题共10小题，每小题5分，共50分，每题只有一项是符合要求的）1．已知P 为椭圆192522=+y x 上一点, 12,F F 为椭圆的两个焦点，且13PF =,则2PF = ( )A. 2B. 5C. 7D. 82．在ABC ∆中，::1:2:3A B C =，则::a b c 等于 （ ） A ．1:2:3 B．2 C ．3:2:1 D．3．设n S 是等差数列{}n a 的前n 项和，已知23a =，611a =，则7S = （ ） A ．13 B ．35 C ．49 D ．634．如图，设,A B 两点在河的两岸，一测量者在A 的同侧，在所在的河岸边选定一点C ， 测出AC 的距离是50m ，∠ACB=45，∠CAB=105， 就可以计算出,A B 两点的距离为 （ ） A． B．C． D．2m 5．若抛物线的准线方程为x ＝－7，则抛物线的标准方程为 ( )A ．x 2＝－28yB ．x 2＝28yC ．y 2＝－28xD ．y 2＝28x 6．“n m =”是“方程122=+ny mx 表示圆”的 ( ) A ．充分而不必要条件B ．必要而不充分条件C ．充分必要条件D ．既不充分也不必要条件 7. 如右图所示为y =f ′(x )①f (x )在(－∞, 1)上是增函数； ②x ＝－1是f (x )的极小值点；③f (x )在(2, 4)上是减函数，在(－1, 2)上是增函数； ④x ＝2是f (x )的极小值点A ．①②③ B．①③④ C．③④ D．②③8．已知,x y 满足条件5003x y x y x -+≥⎧⎪+≥⎨⎪≤⎩，则23x yz +=的最小值为 （ ）A ．0B ．1 C．271 9．设等比数列{a n }的前n 项和为S n ，若S 2＝3，S 4＝15，则S 6＝ ( )A ．31B ．32C ．63D ．64 10．若221xy+=，则x y +的取值范围是 （ ）A ．[0,2]B ．[2,0]-C ．[)2,-+∞D ．(],2-∞- 二、填空题（本大题共5小题，每小题5分，共25分）11．等比数列{a n }的各项均为正数，且a 1a 5＝4，则log 2a 1＋log 2a 2＋log 2a 3＋log 2a 4＋log 2a 5＝ 。
12.函数ln (0)y x x =>的单调增区间为 。
13．命题p x R ∃∈，使2(1)10x a x +++<,若p ⌝为假命题，则实数a 的取值范围是 。
14．已知第一象限的点()P a b ，在直线210x y +－＝上，则11a b+的最小值为 。
15．直线y ＝a 与函数f (x )＝x 3－3x 的图像有相异的三个公共点，则a 的取值范围是_______ _。
三、解答题（本大题共6小题，满分75分,解答须写出文字说明、证明过程和演算步骤） 16．(本题满分12分)双曲线C 与椭圆x 28＋y 24＝1有相同的焦点，直线y ＝3x 为C 的一条渐近线，求双曲线C 的方程。
17．（本题满分12分）命题p ：关于x 的不等式x 2＋2ax ＋4>0，对一切x ∈R 恒成立；命题q ：指数函数f (x )＝(3－2a )x是增函数，若p 或q 为真，p 且q 为假， 求实数a 的取值范围。
18．(本题满分12分)已知函数f (x )＝ax 3＋bx ＋c 在点x ＝2处取得极值16-c 。
(1)求a ，b 的值；(2)若f(x)有极大值28，求f(x)在[－3，3]上的最小值。
19.（本题满分13分）设数列{}n a 是公比大于1的等比数列，n S 为数列{}n a 的前n 项和。
已知37S =，且13a +，23a ，34a +构成等差数列。
（1）求数列{}n a 的通项公式及前n 项和n S ； （2）令231log 12n n b a n +==，，，，求数列{}n b 的前n 项和n T 。
20．（本题满分13分）已知函数f (x )＝12x 2－a ln x (a ∈R)。
（1）求f (x )的单调区间；（2）当x > 1时，12x 2＋ln x < 23x 3是否恒成立，并说明理由。
21．（本题满分13分）已知椭圆C 的中心在坐标原点，焦点在x 轴上，它的一个顶点恰好是抛物线y ＝14x 2的焦点，离心率为255。
（1）求椭圆C 的标准方程；（2）过椭圆C 的右焦点F 作直线l 交椭圆C 于A 、B 两点，交y 轴于点M ，若MA →＝mFA →，MB →＝nFB →，求m ＋n 的值。
2016届高二浏阳一中、攸县一中、醴陵一中十二月联考文科数学试卷参考答案1-10 CBCAD BDDCD11．[解析] 在等比数列中，a 1a 5＝a 2a 4＝a 23＝4。
因为a n >0，所以a 3＝2，所以a 1a 2a 3a 4a 5＝(a 1a 5)(a 2a 4)a 3＝a 53＝25，所以log 2a 1＋log 2a 2＋log 2a 3＋log 2a 4＋log 2a 5＝log 2(a 1a 2a 3a 4a 5)＝log 225＝5。
12．[4,)+∞ ((4,)+∞也对) 13．(,3)(1,)-∞-+∞14．223+15．解析：令f ′(x )＝3x 2－3＝0，得x ＝±1，可得极大值为f (－1)＝2，极小值为f (1)＝－2，如图，观察得－2<a <2时恰有三个不同的公共点。
答案：(－2,2)16．(12分) 双曲线C 的方程为x 2－y 23＝1。
17．(12分) a 的取值范围为{a |1≤a <2或a ≤－2} 18．(12)分解：（1）因为f (x )＝ax 3＋bx ＋c ，故f ′(x )＝3ax 2＋b由于f (x )在点x ＝2处取得极值c －16，故有⎩⎪⎨⎪⎧f＝0，f＝c －16，即⎩⎪⎨⎪⎧12a ＋b ＝0，8a ＋2b ＋c ＝c －16，化简得⎩⎪⎨⎪⎧12a ＋b ＝0，4a ＋b ＝－8，解得⎩⎪⎨⎪⎧a ＝1，b ＝－12.（2）由(1)知f (x )＝x 3－12x ＋cf ′(x )＝3x 2－12＝3(x －2)(x ＋2)令f ′(x )＝0，得x 1＝－2，x 2＝2 当x ∈(－∞，－2)时，f ′(x )>0， 故f (x )在(－∞，－2)上为增函数； 当x ∈(－2,2)时，f ′(x )<0， 故f (x )在(－2,2)上为减函数； 当x ∈(2，＋∞)时，f ′(x )>0， 故f (x )在(2，＋∞)上为增函数．由此可知f (x )在x ＝－2处取得极大值f (－2)＝16＋c ，f (x )在x ＝2处取得极小值f (2)＝c －16.由题设条件知16＋c ＝28，解得c ＝12.此时f (－3)＝9＋c ＝21，f (3)＝－9＋c ＝3，f (2)＝－16＋c ＝－4， 因此f (x )在[－3,3]上的最小值为f (2)＝－4.19.（本题满分13分）解：（1）由已知得1231327:(3)(4)3.2a a a a a a ++=⎧⎪⎨+++=⎪⎩，解得22a =．设数列{}n a 的公比为q ，由22a =，可得1322a a q q==，．又37S =，可知2227q q++=，即22520q q -+=，解得12122q q ==，．由题意得12q q >∴=，．11a ∴=．故数列{}n a 的通项为12n n a -=12122112+nn n n S a a a -=++==--......； (6)分（2）由于231log 12n n b a n +==，，，，由（1）得3312n n a += 32log 23n n b n ∴==，又13n n b b +-={}n b ∴是等差数列．首项13b =，公差3d =12n n T b b b ∴=+++=1(b b )(33)3(1)222n n n n n n +++== ， 故3(1)2n n n T +=． ……13分20．（本题满分13分）解：（1）f (x )的定义域为(0，＋∞)，由题意得f ′(x )＝x －ax(x >0)，∴当a ≤0时，f (x )的单调递增区间为(0，＋∞)．当a >0时，f ′(x )＝x －a x ＝x 2－a x ＝x －a x ＋ax.∴当0<x <a 时，f ′(x )<0，当x >a 时，f ′(x )>0. ∴当a >0时，函数f (x )的单调递增区间为(a ，＋∞)， 单调递减区间为(0，a )．……………………………6分 （2）设g (x )＝23x 3－12x 2－ln x (x >1) 则g ′(x )＝2x 2－x －1x.∵当x >1时，g ′(x )＝x －x 2＋x ＋x>0，∴g (x )在(1，＋∞)上是增函数．∴g (x )>g (1)＝16>0. 即23x 3－12x 2－ln x >0，∴12x 2＋ln x <23x 3，故当x >1时，12x 2＋ln x <23x 3恒成立．………………………………7分21.（本题满分13分）解：（1）设椭圆C 的方程为x 2a 2＋y 2b2＝1 (a >b >0)．抛物线方程可化为x 2＝4y ，其焦点为(0,1)， 则椭圆C 的一个顶点为(0,1)，即b ＝1. 由e ＝c a ＝a 2－b 2a 2＝255.得a 2＝5，所以椭圆C 的标准方程为x 25＋y 2＝1. (5)分（2）易求出椭圆C 的右焦点F (2,0)，设A (x 1，y 1)，B (x 2，y 2)，M (0，y 0)，显然直线l 的斜率存在，设直线l 的方程为y ＝k (x －2)，代入方程x 25＋y 2＝1，得(1＋5k 2)x 2－20k 2x ＋20k 2－5＝0.显然△>0∴x 1＋x 2＝20k 21＋5k 2，x 1x 2＝20k 2－51＋5k2. (4)分又 MA →＝(x 1，y 1－y 0)，MB →＝(x 2，y 2－y 0)，FA →＝(x 1－2，y 1)，FB →＝(x 2－2，y 2)． ∵ MA →＝mFA →＝m ， MB →＝nFB →， ∴m ＝x 1x 1－2，n ＝x 2x 2－2， ∴m ＋n ＝2x 1x 2－x 1＋x 24－x 1＋x 2＋x 1x 2，又2x 1x 2－2(x 1＋x 2)＝40k 2－10－40k 21＋5k 2＝－101＋5k 2，4－2(x 1＋x 2)＋x 1x 2＝4－40k 21＋5k 2＋20k 2－51＋5k 2＝－11＋5k2，∴m ＋n ＝10. (4)分。