高二月考试题
贵州省六盘水市水城区2023-2024学年高二上学期12月月考试题 数学含解析
2023-2024学年第一学期高二质量监测数学（答案在最后）注意事项：1．答题前，考生务必将自己的姓名､考生号､考场号､座位号填写在答题卡上．2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑．如需改动，用橡皮擦干净后，再选涂其他答案标号．回答非选择题时，将答案写在答题卡上．写在本试卷上无效．3．考试结束后，将本试卷和答题卡一并交回．4．本试卷主要考试内容：人教A 版必修第一册至选择性必修第一册第三章3.1．一､选择题：本题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一项是符合题目要求的．1.若集合{}{}2,4,1,3,4A B =-=-，则A B ⋃=（）A.{}4 B.{}2,1-- C.{}2,1,3-- D.{}2,1,3,4--2.在空间直角坐标系中，点B 是点()2,1,5A -在坐标平面Oyz 内的射影，则B 的坐标为（）A.()0,1,5- B.()2,0,5- C.()2,1,0 D.()2,1,5--3.直线270y --=的倾斜角为（）A.150B.30C.120D.604.若()()275f x x a x =+--为偶函数，则=a （）A.0B.5C.7D.95.已知椭圆22:1131x y M m +=-，则m 的取值范围为（）A.()1,+∞ B.()()1,1414∞⋃+ C.()0,∞+ D.()()1,1313∞⋃+6.已知直线0x y -=与圆22:(2)6M x y +-=交于,A B 两点，则AB =（）A.1 B.2 C.4D.7.有编号互不相同的五个砝码，其中3克、1克的砝码各两个，2克的砝码一个，从中随机选取两个砝码，则这两个砝码的总重量超过4克的概率为（）A.310B.15C.25D.128.已知椭圆22:153x y M +=，过点()1,P m ，斜率为35的直线l 与M 交于,A B 两点，且P 为AB 的中点，则m =（）A.1B.1- C.12D.12-二､多选题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求．全部选对的得5分，部分选对的得2分，有选错的得0分．9.已知1F ，2F 分别是椭圆22:186y x M +=的上、下焦点，点P 在椭圆M 上，则（）A.M 的长轴长为B.M 的短轴长为C.1F 的坐标为()D.2PF 10.已知向量(),,2a m n =，()2,2,1b =- ，则下列结论正确的是（）A .若a b，则4,4m n ==- B.若a b，则4,4m n =-=C.若a b ⊥，则10-+=m n D.若a b ⊥，则10n m -+=11.若函数()πsin 28f x x ⎛⎫=- ⎪⎝⎭的图象向左平移π8个单位长度后得到函数()g x 的图象，则（）A.()g x 的最小正周期为πB.()g x 是奇函数C.()g x 的图象关于直线3π16x =对称D.()g x 在π0,8⎡⎤⎢⎥⎣⎦上单调递增12.在如图所示的直角坐标系中，五个大小相同的圆环排成两排从左到右环环相扣，若每个圆环的大圆半径为1.2，小圆半径为1，其中圆心135,,O O O 在x 轴上，且15O O 24O O ，133524 2.6O O O O O O ===，圆2O 与圆4O 关于y 轴对称，直线1524,O O O O 之间的距离为1.1，则给出的结论中正确的是（）A.设,M N 是图中五个圆环组成的图形上任意的两点，则,M N 两点间的距离的最大值为7.6B.小圆2O 的标准方程为22( 1.3)( 1.1)1x y +++=C.图中五个圆环覆盖的区域的面积为2.2πD.小圆1O 与小圆2O 的公共弦所在的直线方程为1301101930x y -+=三､填空题：本题共4小题，每小题5分，共20分．13.()i 59i +的虚部为__________．14.已知方程2222660x y x y m ++-++=表示一个圆，则m 的取值范围为__________，该圆的半径的最大值为__________．15.已知正方体的外接球的体积为92π，则该正方体的棱长为__________．16.已知椭圆2222:1(0)x y C a b a b +=>>的左､右焦点分别为12,F F ，其离心率12e =，P 和M 是椭圆C 上的点，且1260F PF ∠=，12F PF △的面积为3，O 是坐标原点，则1MF MO ⋅的最小值为__________．四､解答题：本题共6小题，共70分．解答应写出必要的文字说明､证明过程或演算步骤．17.已知直线l 经过点(2,4)A --．（1）若l 经过点(1,1)B -，求l 的斜截式方程；（2）若l 在x 轴上的截距为4-，求l 在y 轴上的截距．18.已知圆M 的圆心的坐标为()1,2-，且经过点()2,1．（1）求圆M 的标准方程；（2）若P 为圆M 上的一个动点，求点P 到直线3150x y +-=的距离的最小值．19.已知,A B 分别是椭圆222:1(0)4y xM m m+=>的左顶点､上顶点，且5AB =（1）求点,A B 的坐标；（2）若直线l 与AB 平行，且l 与M 相切，求l 的一般式方程．20.如图，在直三柱111A B C ABC -中，1,2,4,6AC AB AC AB AA ⊥===，,E F 分别为1CA ，AB 的中点．（1）若11111EF xB B yB C zB A =++，求,,x y z 的值；（2）求1B C 与平面AEF 所成角的正弦值．21.已知ABC 的内角,,A B C 的对边分别为,,a b c ，且πsin cos cos 4A b A B ⎛⎫+= ⎪⎝⎭．（1）求B ；（2）若b =，求ABC 面积的最大值．22.已知椭圆2222:1(0)x y E a b a b +=>>的左､右焦点分别为()()121,0,1,0F F -，其离心率为33，M 是E上的一点．（1）求椭圆E 的方程；（2）过右焦点2F 的直线l 与椭圆E 交于,A B 两点，线段AB 的垂直平分线交直线l 于点P ，交直线2x =-于点Q ，求PQ AB的最小值．2023-2024学年第一学期高二质量监测数学注意事项：1．答题前，考生务必将自己的姓名､考生号､考场号､座位号填写在答题卡上．2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑．如需改动，用橡皮擦干净后，再选涂其他答案标号．回答非选择题时，将答案写在答题卡上．写在本试卷上无效．3．考试结束后，将本试卷和答题卡一并交回．4．本试卷主要考试内容：人教A 版必修第一册至选择性必修第一册第三章3.1．一､选择题：本题共8小题，每小题5分，共40分．在每小题给出的四个选项中，只有一项是符合题目要求的．1.若集合{}{}2,4,1,3,4A B =-=-，则A B ⋃=（）A.{}4 B.{}2,1-- C.{}2,1,3-- D.{}2,1,3,4--【答案】D 【解析】【分析】由并集的定义求解.【详解】集合{}{}2,4,1,3,4A B =-=-，则{}2,1,3,4A B ⋃=--．故选：D2.在空间直角坐标系中，点B 是点()2,1,5A -在坐标平面Oyz 内的射影，则B 的坐标为（）A.()0,1,5- B.()2,0,5- C.()2,1,0 D.()2,1,5--【答案】A 【解析】【分析】根据已知条件可得出点B 的坐标.【详解】在空间直角坐标系中，点B 是点()2,1,5A -在坐标平面Oyz 内的射影，则点B 的坐标为()0,1,5-.故选：A.3.直线270y --=的倾斜角为（）A.150B.30C.120D.60【答案】D 【解析】【分析】设直线的倾斜角为α，根据题意，得到tan α=，即可求解.【详解】由题意，该直线270y --=的斜率为k =设直线270y --=的倾斜角为α，可得tan α=，因为0180α≤< ，所以所求的倾斜角为60α= ．故选：D.4.若()()275f x x a x =+--为偶函数，则=a （）A.0 B.5C.7D.9【答案】C 【解析】【分析】求出()f x -的表达式，根据偶函数定义即可求出a 的值.【详解】由题意，()()275f x x a x =+--为偶函数，∴()()()()227575f x x a x x a x -=-----=--，()()=f x f x -，∴()77a a -=--，解得：7a =，故选：C.5.已知椭圆22:1131x y M m +=-，则m 的取值范围为（）A.()1,+∞ B.()()1,1414∞⋃+ C.()0,∞+ D.()()1,1313∞⋃+【答案】B 【解析】【分析】根据题意，由椭圆的标准方程，列出不等式代入计算，即可得到结果.【详解】由题意得10,113,m m ->⎧⎨-≠⎩得1m >且14m ≠．故选：B6.已知直线0x y -=与圆22:(2)6M x y +-=交于,A B 两点，则AB =（）A.1 B.2C.4D.【答案】C 【解析】【分析】根据题意圆心M 为(0,2)，半径r =，圆心M (0,2)到直线0x y -=，利用垂径定理即可求得弦长.【详解】圆心M (0,2)到直线0x y -==又圆的半径r =4AB ==．故选：C7.有编号互不相同的五个砝码，其中3克、1克的砝码各两个，2克的砝码一个，从中随机选取两个砝码，则这两个砝码的总重量超过4克的概率为（）A.310B.15 C.25D.12【答案】A 【解析】【分析】用列举法列举出样本空间，结合古典概型概率计算公式即可求解.【详解】记3克的砝码为1A ，2A ，1克的砝码为1C ，2C ，2克的砝码为B ，从中随机选取两个砝码，样本空间()()()()()()()()()(){}1211112221221212,,,,,,,,,,,,,,,,,,,A A A B A C A C A B A C A C B C B C C C Ω=，共有10个样本点，其中事件“这两个砝码的总重量超过4克”包含3个样本点，故所求的概率为310．故选：A.8.已知椭圆22:153x y M +=，过点()1,P m ，斜率为35的直线l 与M 交于,A B 两点，且P 为AB 的中点，则m =（）A.1B.1- C.12D.12-【答案】B 【解析】【分析】设()()1122,,,A x y B x y ，因为()1,P m 为,A B 的中点，可得12122,2x x y y m +=+=，代入椭圆的方程，两式相减，得出关于m 的方程，即可求解.【详解】设()()1122,,,A x y B x y ，因为()1,P m 为,A B 的中点，可得12122,2x x y y m+=+=又由22112222153153x y x y ⎧+=⎪⎪⎨⎪+=⎪⎩，两式相减得()()()()22221212121212125353x x x x y y y y x x y y -+-+--+=+()()121222053x x m y y --=+=，则()()1212113053535m y y m x x -+=+⨯=-，得1m =-．故选：B.二､多选题：本题共4小题，每小题5分，共20分．在每小题给出的选项中，有多项符合题目要求．全部选对的得5分，部分选对的得2分，有选错的得0分．9.已知1F ，2F 分别是椭圆22:186y x M +=的上、下焦点，点P 在椭圆M 上，则（）A.M的长轴长为 B.M的短轴长为C.1F的坐标为()D.2PF【答案】ABD 【解析】【分析】根据题意，结合椭圆的几何性质，即可求解.【详解】由椭圆22:186y x M +=，可得a =，b，则c ==，所以，椭圆M的长轴长为M的短轴长为1F的坐标为(，根据椭圆的几何性质，得到2PF的最小值为a c -=故选：ABD.10.已知向量(),,2a m n =，()2,2,1b =- ，则下列结论正确的是（）A.若ab，则4,4m n ==- B.若ab，则4,4m n =-=C.若a b ⊥，则10-+=m n D.若a b ⊥，则10n m -+=【答案】AC 【解析】【分析】根据向量平行的坐标表示计算得出,m n 的值判断A ，B ；根据向量垂直的坐标表示计算得出,m n 的关系判断C ，D.【详解】若a b，则2221m n ==-，得4,4m n ==-，故A 正确，B 错误；若a b ⊥ ，则2220a b m n ⋅=-+= ，即10-+=m n ，故C 正确，D 错误；故选：AC.11.若函数()πsin 28f x x ⎛⎫=- ⎪⎝⎭的图象向左平移π8个单位长度后得到函数()g x 的图象，则（）A.()g x 的最小正周期为πB.()g x 是奇函数C.()g x 的图象关于直线3π16x =对称D.()g x 在π0,8⎡⎤⎢⎥⎣⎦上单调递增【答案】ACD 【解析】【分析】根据题意，利用三角函数的图象变换，求得()πsin 28g x x ⎛⎫=+ ⎪⎝⎭，结合三角函数的图象与性质，逐项判定，即可求解.【详解】由题意，可得()πππsin 2sin 2888g x x x ⎡⎤⎛⎫⎛⎫=+-=+ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦，则()g x 的最小正周期为π，且()g x 不是奇函数，所以A 正确，B 不正确；当3π16x =时，可得()3πππsin(2sin 11682g x =⨯+==，所以()g x 的图象关于直线3π16x =对称，所以C 正确；由π0,8x ⎡⎤∈⎢⎥⎣⎦，得ππ3π2,888x ⎡⎤+∈⎢⎣⎦，所以()g x 在π0,8⎡⎤⎢⎥⎣⎦上单调递增，所以D 正确．故选：ACD.12.在如图所示的直角坐标系中，五个大小相同的圆环排成两排从左到右环环相扣，若每个圆环的大圆半径为1.2，小圆半径为1，其中圆心135,,O O O 在x 轴上，且15O O 24O O ，133524 2.6O O O O O O ===，圆2O 与圆4O 关于y 轴对称，直线1524,O O O O 之间的距离为1.1，则给出的结论中正确的是（）A.设,M N 是图中五个圆环组成的图形上任意的两点，则,M N 两点间的距离的最大值为7.6B.小圆2O 的标准方程为22( 1.3)( 1.1)1x y +++=C.图中五个圆环覆盖的区域的面积为2.2πD.小圆1O 与小圆2O 的公共弦所在的直线方程为1301101930x y -+=【答案】ABD 【解析】【分析】根据五圆的位置，求,M N 两点间的距离的最大值判断选项A ；由圆心坐标和半径求小圆2O 的标准方程判断选项B ；求每个圆环的面积判断选项C ；作差法求两圆公共弦所在的直线方程判断选项D.【详解】设每个大圆的半径为R ，每个小圆的半径为r ．因为152 2.6 5.2O O =⨯=，所以M ，N 两点间距离的最大值应为2.622 5.22 1.27.6R ⨯+=+⨯=，A 选项正确．依题意可得小圆2O 的圆心为()1.3, 1.1--，半径1r =，所以小圆2O 的标准方程为22( 1.3)( 1.1)x y +++=1，B 选项正确．因为每个圆环的面积为()22π0.44πR r-=，即0.44π5 2.2π⨯=，而五个圆环有重合的部分，所以图中五个圆环覆盖的区域的面积小于2.2π，C 选项错误．又小圆1O 的方程为22( 2.6)1x y ++=，所以小圆1O 和小圆2O 两圆方程相减，可得公共弦所在直线方程2.6 2.2 3.860x y -+=，化简得1301101930x y -+=，D 选项正确．故选：ABD三､填空题：本题共4小题，每小题5分，共20分．13.()i 59i +的虚部为__________．【答案】5【解析】【分析】由复数的乘法和复数虚部的定义求解.【详解】由题意得()i 59i 95i +=-+，所以()i 59i +的虚部为5．故答案为：514.已知方程2222660x y x y m ++-++=表示一个圆，则m 的取值范围为__________，该圆的半径的最大值为__________．【答案】①.()2,2-②.2【解析】【分析】将圆的一般方程化为标准方程，得到240m -+>，求出m 的取值范围，并根据244m -+≤求出半径的最大值.【详解】该方程可化为圆的标准方程222(1)(3)4x y m ++-=-+．由240m -+>，得22m -<<．因为244m -+≤，2=．故答案为：()2,2-，215.已知正方体的外接球的体积为，则该正方体的棱长为__________．【答案】【解析】【分析】设该正方体的棱长为a ，由正方体的性质得得到对角线，也就是外接球的直径，进而得到半径，然后利用球的体积公式得到关于a 的方程，求解即得.【详解】设该正方体的棱长为a，则该正方体的外接球的半径为22=.由4π332⎛⎫= ⎪ ⎪⎝⎭，得a =.16.已知椭圆2222:1(0)x y C a b a b +=>>的左､右焦点分别为12,F F ，其离心率12e =，P 和M 是椭圆C 上的点，且1260F PF ∠=，12F PF △的面积为，O 是坐标原点，则1MF MO ⋅的最小值为__________．【答案】8【解析】【分析】设12,PF m PF n ==，由12F PF △的面积，解出mn ，在12F PF △中利用余弦定理，结合离心率12e =，求出,a c ，得椭圆方程，设()00,M x y ，表示出1MF MO ⋅ ，利用二次函数的性质求最小值.【详解】由12e =，得2a c =．设12,PF m PF n ==，则2m n a +=，121sin602F PF S mn == ，解得16mn =．在12F PF △中，()22222(2)2cos60343c m n mn m n mn a mn =+-=+-=- ，解得22212a c b -==，从而4,2a c ==，椭圆方程为2211612x y+=，()12,0F -，设()()-≤≤000,44M x y x ，则()2221000012484MF MO x x y x ⋅=++=++ ，当04x =-时，1MF MO ⋅的最小值是8．故答案为：8四､解答题：本题共6小题，共70分．解答应写出必要的文字说明､证明过程或演算步骤．17.已知直线l 经过点(2,4)A --．（1）若l 经过点(1,1)B -，求l 的斜截式方程；（2）若l 在x 轴上的截距为4-，求l 在y 轴上的截距．【答案】（1）2y x =-（2）8-【解析】【分析】（1）根据斜率公式求解斜率，即可由点斜式求解；（2）根据截距式代入即可求解.【小问1详解】由题意得41121AB k -+==--，则l 的方程为11y x +=-，其斜截式方程为2y x =-．【小问2详解】设l 的截距式方程为1x ya b+=，由题意得241,4,a ba --⎧+=⎪⎨⎪=-⎩得8b =-，所以l 在y 轴上的截距为8-．18.已知圆M 的圆心的坐标为()1,2-，且经过点()2,1．（1）求圆M 的标准方程；（2）若P 为圆M 上的一个动点，求点P 到直线3150x y +-=的距离的最小值．【答案】（1）22(1)(2)10x y -++=（2【解析】【分析】（1）根据题意，求得圆M的半径为r =，结合圆的标准方程，即可求解；（2）根据题意，求得圆心M到直线距离为，进而求得点P 到直线的距离的最小值．【小问1详解】解：因为圆M 的圆心的坐标为()1,2-，且经过点()2,1，可得圆M的半径为r ==，所以圆M 的标准方程为22(1)(2)10x y -++=．【小问2详解】解：由题意，圆心M 到直线3150x y +-=的距离为d ==，所以点P 到直线3150x y +-=的距离的最小值为=．19.已知,A B 分别是椭圆222:1(0)4y xM m m+=>的左顶点､上顶点，且AB =（1）求点,A B 的坐标；（2）若直线l 与AB 平行，且l 与M 相切，求l 的一般式方程．【答案】（1）()()1,0,0,2A B -（2）20x y -+=或20x y --=【解析】【分析】（1）根据椭圆的顶点可得22||54AB m ==+，求得m 即可得解；（2）根据直线得平行设:2l y x t =+，联立221,42,y x y x t ⎧+=⎪⎨⎪=+⎩得228440x tx t ++-=，再利用Δ0=即可得解.【小问1详解】由题意得22||54AB m ==+，得21m =，又0m >，所以1m =，所以()()1,0,0,2A B -．【小问2详解】由题意得20201AB k -==+．因为l 与AB 平行，所以l 的斜率为2．设:2l y x t =+，联立221,42,y x y x t ⎧+=⎪⎨⎪=+⎩得228440x tx t ++-=．因为l 与M 相切，所以()22Δ164840t t =-⨯-=，得t =±故l的一般式方程为20x y -+=或20x y --=．20.如图，在直三柱111A B C ABC -中，1,2,4,6AC AB AC AB AA ⊥===，,E F 分别为1CA ，AB 的中点．（1）若11111EF xB B yB C zB A =++，求,,x y z 的值；（2）求1B C 与平面AEF 所成角的正弦值．【答案】（1）11,,022x y z ==-=（2）33535【解析】【分析】（1）根据向量的运算法则，化简得到1111122EF B B BC =- ，结合11111EF xB B yB C zB A =++，即可求解；（2）以1A 为坐标原点，建立空间直角坐标系，求得()12,4,6B C =- 和平面AEF 的法向量为()3,0,1n =，结合向量的夹角公式，即可求解.【小问1详解】解：由向量的线性运算法则，可得()11122EF AF AE AB AA AC =-=-+ ()111111112222AA AB AC B B B C =-+-=- ，又由11111EF xB B yB C zB A =++ ，所以11,,022x y z ==-=．【小问2详解】解：以1A 为坐标原点，11111,,AC A B A A 所在直线分别为,,x y z 轴，建立空间直角坐标系，如图所示，则()()()()()10,0,6,2,0,6,0,4,0,1,0,3,0,2,6A C B E F ，所以()()()12,4,6,1,0,3,0,2,0B C AE AF =-=-=．设平面AEF 的法向量为(),,n x y z =r ，则3020n AE x z n AE y ⎧⋅=-=⎪⎨⋅==⎪⎩，取3x =，可得0,1y z ==，所以()3,0,1n =，设1B C与平面AEF所成的角为θ，可得11sin35||B C nB C nθ⋅==．21.已知ABC的内角,,A B C的对边分别为,,a b c，且πsin cos cos4A b A B⎛⎫+=⎪⎝⎭．（1）求B；（2）若b=，求ABC面积的最大值．【答案】（1）π3B=（2）【解析】【分析】（1）由πsin cos cos4A b A B⎛⎫+=+⎪⎝⎭，利用两角和的正弦公式得到sin cosb A B=，再利用正弦定理求解；（2）利用余弦定理，结合基本不等式得到8ac≤，然后利用三角形面积公式求解.【小问1详解】πsin cos cos4A b A B⎛⎫+=+⎪⎝⎭，所以sin cos cos cosb A b A b A B+=，即sin cosb A B=．由正弦定理得sin sin cosB A A B=．由()0,πA∈，得sin0A≠，则sintancosBBB==，由()0,πB∈，得π3B=．【小问2详解】由余弦定理得2222cos b a c ac B =+-，则228a c ac =+-．由2282a c ac ac ac =+-≥-，得8ac ≤，当且仅当a c ==时，等号成立．故13sin 24ABC S ac B ac ==≤ ABC面积的最大值为22.已知椭圆2222:1(0)x y E a b a b +=>>的左､右焦点分别为()()121,0,1,0F F -，其离心率为3，M 是E上的一点．（1）求椭圆E 的方程；（2）过右焦点2F 的直线l 与椭圆E 交于,A B 两点，线段AB 的垂直平分线交直线l 于点P ，交直线2x =-于点Q ，求PQ AB的最小值．【答案】（1）22132x y +=（2）153【解析】【分析】（1）根据题意，得到1c =且3c a =，求得,a b 的值，即可求得椭圆的标准方程；（2）设方程为1x my =+，联立方程组，得到12122244,2323m y y y y m m --+==++，利用弦长公式，求得)22123m AB m +=+和224923m PQ m +=+，得到212PQ AB =结合换元法和基本不等式，即可求解.【小问1详解】解：由椭圆E 的左､右焦点分别为()()121,0,1,0F F -，其离心率为3，可得1c =且3c a =，解得2222a b a c ==-=，故椭圆E 的方程为22132x y +=．【小问2详解】解：由题意知直线l 的斜率不为0，设其方程为1x my =+，设点()()1122,,,A x y B x y ，联立方程221321x y x my ⎧+=⎪⎨⎪=+⎩，可得()2223440m y my ++-=，所以12122244,2323m y y y y m m --+==++，可得)22123m AB m +=+．又因为122223,122323P P Py y m y x my m m +-===+=++，所以2249223P m PQ x m +=--=+，可得212PQ AB =令1t t =≥，上式245541212123PQt t AB t t +⎛⎫=⨯=+≥⨯= ⎪⎝⎭，当且仅当54t t =，即12m =±时，PQ AB取得最小值153．【点睛】方法策略：解答圆锥曲线的最值与范围问题的方法与策略：（1）几何转化代数法：若题目的条件和结论能明显体现几何特征和意义，则考虑利用圆锥曲线的定义、图形、几何性质来解决；（2）函数取值法：若题目的条件和结论的几何特征不明显，则可以建立目标函数，再求这个函数的最值（或值域），常用方法：（1）配方法；（2）基本不等式法；（3）单调性法；（4）三角换元法；（5）导数法等，要特别注意自变量的取值范围；3、涉及直线与圆锥曲线的综合问题：通常设出直线方程，与圆锥曲线联立方程组，结合根与系数的关系，合理进行转化运算求解，同时抓住直线与圆锥曲线的几何特征应用.。
江苏省盐城市五校联考2024-2025学年高二上学期10月月考试题英语
6.What’s the man?
A.A hotel receptionist.B.A salesman.C.A painter.
7.Which colour will the woman try on?
A.Red.B.Black.C.Purple.
A.It’s in a hurry.
B.It’s unimportant.
C.It’s timeconsuming.
15.What’s the man’s last task?
A.Writing a report.
B.Starting a new project.
C.Sending an email.
16.When will the woman give a presentation?
A.Today.B.Next week.C.Next month.
听下面一段独白，回答以下小题。【此处可播放相关音频，请去附件查看】
17.What is Belfast famous for?
A.Making ropes.B.Building ships.C.Selling tea.
A.She failed to behave herself in public.
B.She got lost with her brother.
C.She served the wrong dish.
第二节（共15小题；每小题1.5分，满分22.5分）
听下面5段对话或独白。每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。每段对话或独白读两遍。
湖南省岳阳市岳阳县2024-2025学年高二上学期9月月考语文试题含答案
2024年9月高二语文月考试题（答案在最后）一、现代文阅读（共2小题，满分36分，每小题18分）阅读下面的文字，完成各题。
生死交锋吕啸天北方八月的这天夜里，突然下起了一场鹅毛大雪。
汉军驻扎的秃柳营几乎被大雪所覆盖。
锋利的长枪枪头挂满了雪花，在夜中发出炫目的青光，有些刺眼。
骠骑将军霍去病帐下亲兵魏中悄悄地溜出营门，朝匈奴军驻扎的狼子山狂奔而去。
这个时候，匈奴军元帅呼韩武扬正在帐中喝酒。
他一人喝掉了两瓶烈性的胡冰烧，烈酒烧红了他的双眼，但没有驱散他心中的郁闷。
开春之后，他受单于之命，率二十万大军，从西城长驱而入，占领了河西，打通了入侵汉朝的一条重要的也是唯一的通道。
汉军派出两路人马反击匈奴。
前锋八万人马由骠骑将军霍去病率领，后路军五万人马由征西大将军卫青统领。
霍去病率领的前锋八万人马在离河西匈奴军三四十里外的单旗镇扎营。
呼韩武扬这时才相信汉军的前锋统帅是一位二十出头的年轻人。
这位要统兵入侵汉朝、二十余年征战沙场的胡将，兴奋得连呼：今夜就去劫营，杀霍去病一个人仰马翻！呼韩武扬派前锋呼韩元率五万人马连夜突袭汉军。
半夜时分，一脸血污的呼韩元狼狈不堪地逃了回来，说：汉军早有准备，偷袭不成，反而折损了一万人马。
呼韩武扬暗暗惊讶：没想到霍去病年纪轻轻，竟是这样的统兵奇才！在接下来的交锋中，霍去病采用派出小股军队扰乱敌军，敌军追击再用伏兵消灭的办法，打了几场漂亮的胜仗。
匈奴军士气低落，呼韩武扬率兵退驻漠北。
霍去病率兵追击，在漠北匈奴军三十里外的秃柳营扎营。
两军形成对峙局面。
霍去病在等卫青的后路军前来支援，两军会合后，再一举出击，将匈奴军赶出边塞。
匈奴军二十万人马经过几番厮杀，已经折损了近三万人马，寸土未得。
而且对手还是一个年轻的小将和他率领的仅八万人马。
呼韩武扬觉得作为匈奴最骁勇的大将，这是他统兵征战以来遭受的最致命的重创，也是他生命中的奇耻大辱。
呼韩式扬开启第二瓶胡冰烧酒时，声称有重要情报献给元帅以换取千两黄金赏赐的魏中被带进了帐中。
四川省成都2024-2025学年高二上学期10月月考试题 数学含答案
成都2024—2025学年度高二上期10月月考数学试卷（答案在最后）注意事项：1．本试卷分第I 卷和第II 卷两部分；2．本堂考试120分钟，满分150分；3．答题前，考生务必将自己的姓名、学号正确填写在答题卡上，并使用2B 铅笔填涂；4．考试结束后，将答题卡交回．第I 卷一、单选题：本题共8小题，每小题5分，共40分．在每小题给出的选项中，只有一项符合题目要求．1．现须完成下列2项抽样调查：①从12瓶饮料中抽取4瓶进行食品卫生检查；②某生活小区共有540名居民，其中年龄不超过30岁的有180人，年龄在超过30岁不超过60岁的有270人，60岁以上的有90人，为了解居民对社区环境绿化方面的意见，拟抽取一个容量为30的样本.较为合理的抽样方法分别为（）A ．①随机数法，②抽签法B ．①随机数法，②分层抽样C ．①抽签法，②分层抽样D ．①抽签法，②随机数法2．已知向量()1,2,1a =- ，()3,,b x y = ，且//a b r r，那么实数x y +等于（）A ．3B ．-3C ．9D ．-93．若,l n 是两条不相同的直线，,αβ是两个不同的平面，则下列命题中为真命题的是（）A ．若l n ⊥，n β⊥，则l //βB ．若αβ⊥，l α⊥，则l //βC ．若//αβ，l α⊂，则l //βD ．若//l α，//αβ，则l //β4．如图，空间四边形OABC 中，,,OA a OB b OC c ===，点M 为BC 中点，点N 在侧棱OA上，且2ON NA =，则MN =（）A ．121232a b c--+B ．211322a b c-++C ．211322a b c-- D ．111222a b c+-5．为了养成良好的运动习惯，某人记录了自己一周内每天的运动时长（单位：分钟），分别为53，57，45，61，79，49，x ，若这组数据的第80百分位数与第60百分位数的差为3，则x =（）A ．58或64B ．59或64C ．58D ．596．已知点D 在ABC V 确定的平面内，O 是平面ABC 外任意一点，正数,x y 满足23DO xOA yOB OC =+- ，则yx 21+的最小值为（）A ．25B ．29C ．1D ．27．现有一段底面周长为12π厘米和高为12厘米的圆柱形水管，AB 是圆柱的母线，两只蜗牛分别在水管内壁爬行，一只从A 点沿上底部圆弧顺时针方向爬行π厘米后再向下爬行3厘米到达P 点，另一只从B 沿下底部圆弧逆时针方向爬行π厘米后再向上爬行3厘米爬行到达Q 点，则此时线段PQ 长（单位：厘米）为（）A ．B ．C ．6D ．128．如图，四边形,4,ABCD AB BD DA BC CD =====ABD △沿BD 折起，当二面角A BD C --的大小在[,63ππ时，直线AB 和CD 所成角为α，则cos α的最大值为（）A ．16B C ．16D ．8二、多选题：本题共3小题，每小题6分，共18分．在每小题给出的选项中，有多项符合题目要求．全部选对的得6分，部分选对的得部分分，有选错的得0分．9．下列命题中，正确的是（）A ．两条不重合直线12,l l 的方向向量分别是()2,0,1a =-，()4,0,2b =- ，则12//l l B ．直线l 的方向向量()1,1,2c =-，平面α的法向量是()6,4,1m =- ，则l α⊥C ．两个不同的平面α，β的法向量分别是()2,2,1u =-，()3,4,2v =- ，则αβ⊥D ．直线l 的方向向量()0,1,1d = ，平面α的法向量()1,0,1n =，则直线l 与平面α所成角的大小为π310．小刘一周的总开支分布如图①所示，该周的食品开支如图②所示，则以下说法正确的是（）A ．娱乐开支比通信开支多5元B ．日常开支比食品中的肉类开支多100元C ．娱乐开支金额为100元D ．肉类开支占储蓄开支的1311．已知四面体OABC 的所有棱长都为1,,D E 分别是,OA BC 的中点.N M ,是该四面体内切球球面上的两点，P 是该四面体表面上的动点.则下列选项中正确的是（）A.DE 的长为44B.D 到平面ABC 的距离为66C.当线段MN 最长时，PN PM ⋅的最大值为31D.直线OE 与直线AB 所成角的余弦值为33第II 卷三、填空题：本题共3小题，每小题5分，共15分．12．某校高一年级共有学生200人，其中1班60人，2班50人，3班50人，4班40人．该校要了解高一学生对食堂菜品的看法，准备从高一年级学生中随机抽取40人进行访谈，若采取按比例分配的分层抽样，则应从高一2班抽取的人数是．13．已知(2,1,3),(1,4,2)a b =-=-- ，c (4,5,)λ=，若,,a b c 三向量不能构成空间向量的一组基底，则实数λ的值为.14．在正方体ABCD A B C D -''''中，点P 是AA '上的动点，Q 是平面BB C C ''内的一点，且满足A D BQ '⊥，则平面BDP 与平面BDQ 所成角余弦值的最大值为．四、解答题：本题共5小题，共77分．解答应写出文字说明，证明过程或演算步骤．（满分13分）15．已知向量()6a m = ,，()1,0,2=b ，()()2R c m =∈ (1)求()a b c ⋅-的值；(2)求cos b c ,；(3)求a b - 的最小值.（满分15分）16．成都市政府委托市电视台进行“创建文明城市”知识问答活动，市电视台随机对该市1565～岁的人群抽取了n人，绘制出如图所示的频率分布直方图，回答问题的统计结果如表所示．组号分组回答正确的人数回答正确的人数占本组的频率第一组[15，25)500.5第二组[25，35)180a第三组[35，45)x0.9第四组[45，55)90b第五组[55，65)y0.6a b x y的值；（1）分别求出,,,（2）从第二、三、四、五组回答正确的人中用分层抽样的方法抽取7人，则从第二、三、四、五组每组回答正确的人中应各抽取多少人.-中，ABCD是边长为2的正方形，平面PBC⊥（满分15分）17．如图，在四棱锥P ABCDPC=.平面ABCD，直线PA与平面PBC所成的角为45︒，2（1）若E，F分别为BC，CD的中点，求证：直线AC⊥平面PEF；（2）求二面角D PA B--的正弦值.（满分17分）18．随着时代不断地进步，人们的生活条件也越来越好，越来越多的人注重自己的身材，其中体脂率是一个很重要的衡量标准.根据一般的成人体准，女性体脂率的正常范围是20%至25%，男性的正常范围是15%至18%.这一范围适用于大多数成年人，可以帮助判断个体是否存在肥胖的风险.某市有关部门对全市100万名成年女性的体脂率进行一次抽样调查统计，抽取了1000名成年女性的体脂率作为样本绘制频率分布直方图,如图.(1)求a ；(2)如果女性体脂率为25%至30%属“偏胖”，体脂率超过30%属“过胖”，那么全市女性“偏胖”，“过胖”各约有多少人？(3)小王说：“我的体脂率是调查所得数据的中位数.”小张说：“我的体脂率是调查所得数据的平均数.”那么谁的体脂率更低？（精确到小数点后2位）（满分17分）19．如图，四面体ABCD 中，2,AB BC BD AC AD DC ======(1)求证：平面ADC ⊥平面ABC ；(2)若(01)DP DB λλ=<<，①若直线AD 与平面APC 所成角为30°，求λ的值；②若PH ⊥平面,ABC H 为垂足，直线DH 与平面APC 的交点为G ．当三棱锥CHP A -体积最大时，求DGGH的值．高二上10月月考数学答案一、单选题：C D C C A B A B二、多选题：AC;BCD;BC3三、填空题：10；5；318:（1）由频率直方图可得，（2）由频率分布直方图可得样本中女性⨯=，所以全市女性50.020.1⨯=，10000000.1100000。
2024年沪科版高二数学上册月考试卷178
2024年沪科版高二数学上册月考试卷178考试试卷考试范围：全部知识点；考试时间：120分钟学校：______ 姓名：______ 班级：______ 考号：______总分栏题号一二三四五六总分得分评卷人得分一、选择题(共9题，共18分)1、从装有2支铅笔和2支钢笔的文具袋内任取2支笔；那么互斥而不对立的两个事件是（）A. 恰有1支钢笔；恰有2支铅笔。
B. 至少有1支钢笔；都是钢笔。
C. 至少有1支钢笔；至少有1支铅笔。
D. 至少有1个钢笔；都是铅笔。
2、（2x-sinx）dx的值是（）A.B.C.D.3、设不等的两个正数a，b满足a3﹣b3=a2﹣b2，则a+b的取值范围是（）A. （1，+∞）B.C.D. （0，1）4、设函数f（x）是定义在R上的奇函数，且f（x）= 则g[f（﹣7）]=（）A. 3B. ﹣3C. 2D. ﹣25、如图，底面为正方形且各侧棱长均相等的四棱锥V﹣ABCD可绕着棱AB任意旋转，若AB⊂平面α，M，N分别是AB，CD的中点，AB=2，VA= 点V在平面α上的射影为点O，则当ON的最大时，二面角C﹣AB﹣O的大小是（）A. 90°B. 105°C. 120°D. 135°6、已知z（1+2i）=4+3i，则|z|=（）A.B.C. 2D.7、已知函数f（x）=函数g（x）=-f（1-x），则函数y=f（x）-g（x）的零点的个数为（）A. 2C. 4D. 58、不同的直线m和n，不同的平面α，β，γ，下列条件中能推出α∥β的是（）A. α∩γ=n，β∩γ=m，n∥mB. α⊥γ，β⊥γC. n∥m，n⊥α，m⊥βD. n∥α，m∥β，n∥m9、事件A，B是相互独立的，P（A）=0.4，P（B）=0.3，下列四个式子：①P（AB）=0.12；②P（B）=0.18；③P（A）=0.28；④P（）=0.42．其中正确的有（）A. 4个B. 2个C. 3个D. 1个评卷人得分二、填空题(共9题，共18分)10、若函数是函数的反函数，其图象经过点则______________．11、【题文】在数列中，已知记为数列的前项和，则____.12、【题文】将函数的图象向左平移个单位，得到函数的图象，则____13、数列{a n}中，a1=1，a n+1=2a n+1，则通项a n=____14、已知等差数列{a n}中，a1+a13=10，则a3+a5+a7+a9+a11=____15、如果圆：x2+y2+2x+4y+m=0上恰有两点到直线l：x+y+1=0的距离为则m的取值范围是______ ．16、已知随机变量X～N（1，4）且P（X＜2）=0.72，则P（1＜X＜2）= ______ ．17、将二进制数10101（2）化为十进制是 ______ ．18、若实数xy满足{x鈮�1y鈮�0x+y鈮�4则z=2x+y的最大值是 ______ ．评卷人得分三、作图题(共6题，共12分)19、著名的“将军饮马”问题：有一位将军骑着马要从A地走到B地；但途中要到水边喂马喝一次水，则将军怎样走最近？20、A是锐角MON内部任意一点，在∠MON的两边OM，ON上各取一点B，C，组成三角形，使三角形周长最小．（如图所示）21、已知，A，B在直线l的两侧，在l上求一点，使得PA+PB最小．（如图所示）22、著名的“将军饮马”问题：有一位将军骑着马要从A地走到B地；但途中要到水边喂马喝一次水，则将军怎样走最近？23、A是锐角MON内部任意一点，在∠MON的两边OM，ON上各取一点B，C，组成三角形，使三角形周长最小．（如图所示）24、已知，A，B在直线l的两侧，在l上求一点，使得PA+PB最小．（如图所示）评卷人得分四、解答题(共3题，共6分)25、为了检测某条生产线上产品的尺寸．现从该条生产线上每隔一定时间取一件产品；共取了50件，测得其产品尺寸后，画得其频率分布直方图如图．（1）分别求尺寸在[10；15）和[20，25）内产品的频率．（2）求尺寸在[20；25）内产品的个数．26、在数列{a n}中，．（1）计算a2，a3，a4，猜想数列{a n}的通项公式并加以证明；（2）求证：．27、【题文】 (本题满分14分；其中第1小题6分，第2小题8分)在中，分别为角的对边，且满足(1)求角大小；(2)若求的面积的最大值.评卷人得分五、计算题(共3题，共6分)28、如图，正三角形ABC的边长为2，M是BC边上的中点，P是AC边上的一个动点，求PB+PM的最小值．29、解不等式组．30、在（1+x）6（1+y）4的展开式中，记x m y n项的系数为f（m，n），求f（3，0）+f（2，1）+f（1，2）+f（0，3）的值．评卷人得分六、综合题(共1题，共10分)31、已知S n为等差数列{a n}的前n项和，S6=51，a5=13．参考答案一、选择题(共9题，共18分)1、A【分析】A 恰有1支钢笔和恰有2支铅笔互斥但不对立．B至少有1支钢笔和都是钢笔不互斥．C至少有1支钢笔和至少有1支铅笔不互斥．D 至少有1个钢笔和都是铅笔是对立事件．故选 A．【解析】【答案】根据恰有1支钢笔和恰有2支铅笔互斥但不对立；至少有1支钢笔和都是钢笔不互斥，至少有1支钢笔和至少有1支铅笔不互斥，至少有1个钢笔和都是铅笔是对立事件，得到答案．2、A【分析】==．故选A．【解析】【答案】利用握微积分基本定理即可求出．3、B【分析】【解答】解：由a2+ab+b2=a+b；得：（a+b）2﹣（a+b）=ab；而所以得．故选B．【分析】根据题意及立方差公式的展开形式可得出a2+ab+b2=a+b的值，然后可求出ab与a+b的关系式，结合基本不等式即可得出答案．4、D【分析】【解答】解：函数f（x）是定义在R上的奇函数，且f（x）=设x＜0，则﹣x＞0，则f（﹣x）=log2（﹣x+1）；∵f（﹣x）=﹣f（x）；∴f（x）=﹣f（﹣x）=﹣log2（﹣x+1）；∴g（x）=﹣log2（﹣x+1）（x＜0）；∴f（﹣7）=g（﹣7）=﹣log2（7+1）=﹣3；∴g（﹣3）=﹣log2（3+1）=﹣2；故选：D．【分析】先设x＜0，则﹣x＞0，根据函数的奇偶性，即可求出g（x），再代值计算即可．5、B【分析】【解答】解：设∠VMO=θ；则∵M、N分别是AB、CD的中点，AB=2，VA=∴AM=1，VM= = =2；MN=BC=AB=2；VN=VM=2；则三角形VNM为正三角形；则∠NMV=60°；则OM=2cosθ；在三角形OMN中；ON2=MN2+OM2﹣2MN•OMcos（60°+θ）=4+4cos2θ﹣2×2×2cosθcos（60°+θ）=4+4cos2θ﹣8cosθ（cosθ﹣sinθ）=4+4cos2θ﹣4cos2θ+4 sinθcosθ=4+2 sin2θ；∴要使ON最大；则只需要sin2θ=1，即2θ=90°即可，则θ=45°；此时二面角C﹣AB﹣O的大小∠OMN=60°+θ=60°+45°=105°；故选：B【分析】根据条件确定二面角的平面角，结合余弦定理以及两角和差的余弦公式以及倍角公式进行求解即可．6、D【分析】【解答】解：∵z（1+2i）=4+3i；∴|z（1+2i）|=|4+3i|；即：|z||1+2i|=|4+3i|；即：|z|∴|z|=故选：D．【分析】利用积的模等于模的积，通过复数方程两边求模，化简即可．7、C【分析】解：函数f（x）= 可得则令f（x）-g（x）=0；可得f（x）+f（1-x）=画出y=f（1-x）+f（x）与y= 的图象如图所示：由图可得：y=f（1-x）+f（x）与y= 有4个交点。
高二数学第一次月考试题
高二数学第一次月考试题高二数学第一次月考试题第一部分：选择题（每小题5分，共计50分）1.设函数f(x) = 2x + 3，g(x) = x^2 - 4x + 1，则f(g(2))的值为（） A.-3 B. 3 C. 7 D. 112.已知函数f(x) = x^2 - 2x - 3，则方程f(x) = 0的根为（） A. 1和-3B. 3和-1C. 1和3D. -1和33.若两个正整数x和y满足x^2 - y^2 = 48，则x - y的值为（） A. 4 B.6 C. 8 D. 124.已知函数f(x) = 2x + 5，g(x) = 3x - 1，则f(g(x))的值为（） A. 6x+ 14 B. 6x - 4 C. 6x + 4 D. 6x - 145.若函数f(x) = x^2 + kx + 8与函数g(x) = 2x^2 - 3x - 4相等，则k的值为（） A. -4 B. -2 C. 2 D. 46.若两个正整数x和y满足x + y = 7，x - y = 3，则x的值为（） A. 5B. 4C. 3D. 27.已知函数f(x) = x^2 - 2x - 3，g(x) = x + 1，则f(g(2))的值为（） A.6 B. 3 C. 0 D. -38.若函数f(x) = x^2 - 5x + 6与函数g(x) = x - 2相等，则x的值为（）A. 6B. 4C. 2D. 19.若两个正整数x和y满足x^2 + y^2 = 34，x - y = 2，则x + y的值为（） A. 8 B. 9 C. 10 D. 1110.设函数f(x) = 2x + 3，g(x) = x^2 - 2x + 1，则f(g(1))的值为（） A.-1 B. 1 C. 3 D. 5第二部分：填空题（每小题5分，共计50分）1.函数f(x) = x^2 - 4x - 3的图像开口向上，顶点的坐标为（）。
高职高二月考试题及答案
高职高二月考试题及答案一、选择题（每题2分，共20分）1. 以下哪个选项是正确的？A. 地球是平的B. 地球是圆的C. 地球是方的D. 地球是三角形的答案：B2. 光年是什么单位？A. 时间单位B. 长度单位C. 质量单位D. 速度单位答案：B3. 计算机中存储数据的基本单位是什么？A. 字节B. 比特C. 兆D. 吉答案：B4. 以下哪个选项不是中国的传统节日？A. 春节B. 圣诞节C. 中秋节D. 端午节答案：B5. 以下哪个选项是正确的？A. 1米等于100厘米B. 1米等于10厘米C. 1米等于1000厘米D. 1米等于10000厘米答案：A6. 以下哪个选项不是元素周期表中的元素？A. 氢B. 氧C. 氮D. 碳答案：D（注：碳是元素周期表中的元素）7. 以下哪个选项是正确的？A. 牛顿是物理学家B. 牛顿是化学家C. 牛顿是生物学家D. 牛顿是天文学家答案：A8. 以下哪个选项是正确的？A. 光速是宇宙中最快的速度B. 光速是宇宙中最慢的速度C. 光速是宇宙中唯一的速度D. 光速是宇宙中可变的答案：A9. 以下哪个选项是正确的？A. 地球是太阳系的第八大行星B. 地球是太阳系的第八小行星C. 地球是太阳系的第八大卫星D. 地球是太阳系的第八小卫星答案：A10. 以下哪个选项是正确的？A. 1千克等于1000克B. 1千克等于100克C. 1千克等于10克D. 1千克等于1克答案：A二、填空题（每题2分，共20分）1. 光年是指光在一年内传播的距离，其长度约为_____km。
答案：9.46×10^122. 元素周期表中，氢的原子序数是____。
答案：13. 计算机中，1字节等于____比特。
答案：84. 地球的赤道周长大约是____公里。
答案：40,0755. 牛顿的三大定律是______、______和______。
答案：第一定律、第二定律、第三定律6. 元素周期表中，氧的原子序数是____。
天津市宝坻区大口屯高中2024_2025学年高二英语上学期第一次月考试题扫描版无答案
2024-2025学年度第一学期第一次月考试卷高二英语一、听力理解（15分）二、单选（15分）16．—Shall I give you a ride as you live so far away?—Thank you. _________.A．It couldn’t be better B．Of course you canC．If you like D．It’s up to you17.The police thought he was_______ the murder case in the shop.A.connected toB. related toC. joined inD. linked and18.Don’t take______ for granted ______ everyone should adore you.A. that; whatB. that; whichC. it; whatD. it ;that19. If you are interested in this job, please ______ us as soon as possible.A. contractB. contactC. considerD. combine20.I will tell you what trouble I had ______ your house on the way I came here.A. findB. foundC. findingD. founded21. Those prisoners made a (an) ______ to escape from the prison but failed.A. tryB. runC. attemptD. attract22 . _____his timely help ,Kate overcame the hardship at last.A. ForB. Thanks toC. As a resultD. Because23. It is almost five years we saw each other last time.A. beforeB. sinceC. forD. when24. He couldn’t continue to l ive such a poor life, so he left home, ______ not tocome back if he couldn’t get rich.A. determiningB. determinedC. determineD. being determined25. She got into______ when she thought she’d forgotten the tickets, and this _______her husband, too.A. panic; panicB. a panic; panickedC. a panic; panicD. panic; panicked26. It was dark. But ______ the light of the moon , I saw a man ____ in the streetcorner.A. in; lyingB. in; to lieC. by; lyingD. by; to lie27. The boy hurried home ______ the room had been stolen and everything valuable wasgone.A. only to findB. only foundC. findingD. and find28．Please tell me how the accident _______. I am still in the dark.A．came by B．came upon C．came to D．came about29．—Hurry up ! Alice and Sue are waiting for you at the school gate .—Oh ! thought they without me .A．went B．are going C．have gone D．had gone30．The manager, _______ it clear to us that he didn’t agree with us，left the meeting room.A．who has made B．having made C．made D．making三、完型填空（30分）A Welcome GiftDario and his mother loved their new apartment.The living room was large enoughfor their piano. That night,the two of them 31 side by side at the piano.Theyplayed jazz music to celebrate their new home.The loud 32 filled the room andmade them feel very happy.The next morning, 33 ,their happiness disappeared.Someone had left a 34under their door during the night.One of their neighbors had written to complain(埋怨) about the sound of the piano.Dario’s mother asked the building superintendent(管理员) if he knew anything about it.But he said that they were all 35 people and he couldn’t imagine any of them had done ter that morning,Dario suggested that they write a letter to their 36 and apologize for their playing.“Maybe we could go and 37 everyone in person,”his mother said.“What if we invited them to come here for a 38 instead?”Dario asked.They both loved the 39 .Over the next few days,they sent out invitations and prepared desserts 40 their guests.They decorated the apartment with streamers(彩带) and party lights.Finally,the day of the party 41 .Some guests brought presents.Others brought flowers.Some even brought desserts to 42 .One woman,Mrs.Gilbert, 43 Dario’s mother with a book of piano music by Chopin.“I heard you playing the other night,”she said.“The sounds woke me out of bed.I 44 that you might play like this every night.So I wrote a short note.I hope you don’t think I disliked the playing.”Dario’s mother smiled at Mrs.Gilbert.“I think maybe we 45you an apology,”she said.“I didn’t 46 how late it was when we were playing.Maybe we should play some quieter music at night.”“You play,you play!”Mrs.Gilbert said.“I like w hat you play!Just not so loud at night.”She pointed to the book she had given them.“These songs are not such 47 music.”“These songs are beautiful music,”Dario’s mother said.“We will be 48 to play them in the evening.”“And we won’t play so loud or late!”Dario said.He was already looking forward to 49 the new music.More than that,however,he was happy to see the big smile on his mother’s face.It gave him a feeling of 50 and made him feel that they were home at last.31.A.sat B.stood y D.walked32.A.voice B.ring C.music D.cry33.A.therefore B.however C.otherwise D.instead34.A.note B.poster C.bill D.report35.A.proud B.rich C.lucky D.nice36.A.neighbors B.friends C.relatives D.audiences37A.blame B.instruct C.question D.visit38.A.party B.concert C.show D.play39.A.experience B.idea C.performance D.action40.A.to B.with C.for D.from41.A.continued B.arrived C.passed D.finished42.A.order B.sell C.share D.advertise43.A.treated B.presented C.helped D.served44.A.promised B.admitted C.agreed D.worried45.A.give B.send C.offer D.owe46.A.realize B.remember C.understand D.accept47.A.sweet B.strange C.funny D.loud48.A.brave B.sorry C.happy D.afraid49.A.changing B.practicing C.recording D.writing50.A.equality B.freedom C.warmth D.sympathy四、阅读理解 (共15小题；每小题2分，满分30分)AThere are over 10,000 various species of birds across the world. These creatures are warm-blooded, can fly due to their wings, and lay eggs. From different sizes, communication skills, shapes, colors, to types of flight, the creatures are thought to be a wonder.AvocetsThere are four different species of Avocets birds found around the world. This bird is found in North and South America, Europe, and even Australia. They live in large groups, and have been known to become quite eager to fight, if they feel they are in danger.Eastern bluebirdsThese types of birds are around 6.5 inches in length. Such birds are found mainly in gardens, and woodlands with the arrival of spring. Male Eastern Bluebirds are bright blue and white. Female Eastern Bluebirds are gray. New York and Missouri have named this creature as their state bird.CatbirdsCatbirds are known to imitate the sounds of other birds. This bird is gray in color and has a shade of chestnut, just under its tail. There are different species of Catbirds found in various parts of the world.DovesDoves are smaller than pigeons and have a longer tail in appearance. Doves are found throughout the world and these birds are also a symbol of romance as well as peace. They feed on fruits, plants and seeds to survive. They are different species Doves found.There are many other beautiful and attractive birds which can be seen in nature. Birds would prefer to have their own freedom rather than be trapped in a cage, so if you think you can have it as a pet, you need to think again.51.According to the passage, birds .A. have less than 10,000 various speciesB. have different lifestylesC. can lay eggs as result of their wingsD. can live long52. We can learn from the passage that Avocets .A. can be rarely seen in AsiaB. are about 6.5 inches in lengthC. have a shade of chestnutD. are a symbol of romance and peace53. Male Eastern Bluebirds are different from female Eastern Bluebirds in .A. sizeB. habitC. lengthD. color54. Which birds can copy the speech of other birds?A. Avocets.B. Eastern bluebirds.C. Catbirds.D. Doves.55. Where would you most probably see the text?A. In a sports newspaper.B. In a poster.C. In a travel guide.D. In a science magazine..BWhether in the home or the workplace,social robots are going to become a lot more common in the next few years.Social robots are about to bring technology to the everyday world in a more humanized way,said Cynthia Breazeal,chief scientist at the robot company Jibo.While household robots today do the normal housework,social robots will be much more like companions than mere tools.For example,these robots will be able to distinguish when someone is happy or sad.This allows them to respond more appropriately to the user.The Jibo robot,arranged to ship later this year,is designed to be a personalized assistant.You can talk to the robot,ask it questions and make requests for it to perform different tasks.The robot doesn’t just deliver general answers to questions;it responds based on what it learns about each individual in the household.It can do things such as reminding an elderly family member to take medicine or taking family photos.Social robots are not just finding their way into the home.They have potential applications in everything from education to health care and are already finding their way into some of these spaces.Fellow Robots is one company bringing social robots to the market.The company’s “Oshbot” robot is built to assist customers in a store,which can help the customers find items and help guide them to the product’s location in the store.It can also speak different languages and make recommendations for different items based on what the customer is shopping for.The more interaction the robot has with humans,the more it learns.But Oshbot,like other social robots,is not intended to replace workers,but to work alongside other employ ees.“We have technologies to train social robots to do things not for us,but with us,”said Breazeal.56.How are social robots different from household robots?A.They can control their emotions.B.They are more like humans.C.They do the normal housework.D.They respond to users more slowly.57.What can a Jibo robot do according to Paragraph 3?municate with you and perform operations.B.Answer your questions and make requests.C.Take your family pictures and deliver milk.D.Obey your orders and remind you to take pills.58.What can Oshbot work as?A.A language teacher.B.A tour guide.C.A shop assistant.D.A private nurse.59.We can learn from the last paragraph that social robots will .A.train employeesB.be our workmatesC.improve technologiesD.take the place of workers60.What does the passage mainly present?A.A new design idea of household robots.B.Marketing strategies for social robots.rmation on household robots.D.An introduction to social robots.CA Language Programme for TeenagersWelcome to Teenagers Abroad! We invite you to join us on an amazing journey of language learning.Our CoursesRegardless of your choice of course, you’ll develop your language ability both quickly and effectively.Our Standard Course guarantees a significant increase in your confidence in a foreign language, with focused teaching in all 4 skill areas----speaking, listening, reading and writing.Our Intensive Course builds on our Standard Course, with 10 additional lessonsＥｖａｌｕａｔｉｏｎＳｔｕｄｅｎｔｓａｒｅplaced into classes according to their current language skills. The majority of them take on online language test before starting their programme. However, if this is not available, students sit the exam on the first Monday of their course.Learning materials are provided to students throughout their course, and there will never be more than 15 participants in each class.Arrivals and TransferOur programme offers the full package—students are take good care of from the start through to the very end. They are collected from the airport upon arrival and brought to their accommodation in comfort. We require the student’s full details at least 4 weeks in advance.Meals/Allergies(过敏)/Special Dietary RequirementsStudents are provided with breakfast, dinner and either a cooked or packedlunch(which consists of a sandwich, a drink and a dessert). Snacks outside of mealtimes may be purchased by the student individually.We ask that you let us know of any allergies or dietary requirements as well as information about any medicines you take. Depending on the type of allergies and/ or dietary requirements, an extra charge may be made for providing special food.61. How does Intensive Course differ from Standard Course?A. It is less effective.B. It focuses on speaking.C. It includes extra lessons.D. It give you confidence62. When can a student attend Standard Course?A. 13:00-14:30 Monday.B. 9:00-12:30 TuesdayC. 13:00-14:30 Friday.D. 9:00-12:30 Saturday.63. Before starting their programme, students are expected to _____.A. take a language testB. have an online interviewC. prepare learning materialsD. report their language levels64. With the full package, the programme organizer is supposed to_____.A. inform students of their full flight detailsB. look after students throughout the programmeC. offer students free sightseeing tripsD. collect students’ luggage in advance65. Which of the following may require an extra payment?A. Cooked dinner.B. Mealtime dessert.C. Packed lunch.D. Special diet.五、阅读理解（10分）Six days a week,up and down the red hills of northeast Georgia,my grandfather brought the mail to the folks there.At age 68,he retired from the post office,but he never stopped serving the community.On his 80th birthday,I sent him a letter, noting the things we all should be thankful for—good health,good friends and good outcomes.By most measurements he was a happy man.Then I suggested it was time for him to slow down. At long last,in a comfortable home,with a generous pension he should learn to take things easy.“Thank you for your nice words,”he wrote in his letter back,“and I know what you meant,but slowing down scares me.Life isn’t having it made;it’s getting it made.”“The finest and happiest years of our lives were not when all the debts were paid,and all difficult experiences had passed,and we had settled into a comfortable home.No.I go back years ago,when we lived in a three-room house,when we got up before daylight and worked till after dark to make ends meet.I rarely had more than four hours of sleep.But what I still can’t figure out is why I never got tired,never felt better in my life.I guess the answer is,we were fighting for survival,protecting and providing for those we loved.What matters are not the great moments,but the partial victories,the waiting,and even the defeats.It’s the journey,not the arrival,that counts.”The letter ended with a personal request:“Boy,on my next birthday,just tell me to wake up and get going,because I will have one less year to do things—and there are ten million things waiting to be done.”Christina Rossetti,an English poet,once said:“Does the road wind uphill all the way?Yes,to the very end.”Today,at 96,my grandfather is still on that long road,climbing.66.Wh at was the author’s grandfather before he retired?(no more than 5 words)_________________________________________________________________67.What did the author advise his grandfather to do in his letter?(no more than 10 words)_________________________________________________________________68.What is the grandfather’s view on life according to his letter back?(no more than 10 words)_________________________________________________________________69.How do you understand the underlined sentence in the last paragraph?(no more than 10 words)_________________________________________________________________70.Do you agree with the grandfather’s view on life?Give reasons in your own words.(no more than 20 words)_________________________________________________________________六：书面表达（满分20分）假设你是新华中学的学生李华，你校英语协会正在招募志愿者，来接待来访的外国中学生。
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高二月考试题一.听力第一节（共5小题，每小题1分，满分5分）：听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题，每段对话仅读一遍。
例：How much is the shirt?A、￡19.15 B.￡9.15 C.￡9.18答案是B( ）1.Why doesn’t the woman like t he blue dress?A.It’s too bright。
B.It’s too short.C.It’s too long( )2.What can we learn about the man?A.He’s not in good healthB.He is all rightC.He likes to stay in the same place( )3.What did the woman ask the man to do?A.She asked him to give her sister a bike.B.She asked him to teach her sister to ride a bike.C.She asked him to give her sister a ride home( )4.Why can’t the woman go to Japan?A.Because she doesn’t have enough money.B.Because she will have to help her father at home.C.Because she will have to look after her sick mother.( )5.What can we learn about the weather?A.The weather is quite nice.B.The weather is neither good nor bad.C.The weather is quite changeable.第二节（共15小题，每小题1分，满分15分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料，回答第6至7题（）6.What does the man think of the film?A.The film is frightening, but not interesting.B.The film is interesting but frightening.C.The film is neither interesting nor frightening.( )7.Which of the following is true?A.The film is about a swimmer killing a shark(鲨鱼）.B.The film is about two swimmers killed by shards off the beaches at Shenzhen.C.The film is about a shark killing swimmers on a beach.听第7段材料，回答第8至10题。
( )8.What can we infer about Gary?A.He hopes to become a painter some day.B.He isn’t very familiar with painting.C.He doesn’t like the course at all.( )9.Who is Lisa Frank?A.The painter Desiree.B.The professor of the course.C.The woman talking with Gary.( )10.When does this conversation probably take place?A.Before class.B.In the middle of the class.C.After class.听第8段材料，回答第11至12题。
( )11.Why did the man come to see the woman?A.Because she asked him to visit her.B.Because she is not well.C.Because the man wanted to ask the woman to go to the cinema.( )12.What did the man bring to the woman?A.Some medicine.B.Some magazines.C.Some flowers.听第9段材料，回答第13至16题。
( )13.Where do Mary and Paul come from?A.England and Japan.B.England and America.C.America and England.( )14.What did both Mary and Paul have for breakfast?A.Bread and eggs.B.Bread and butter.C.Ham and orange.( )15.What do many Chinese young people think of the western breakfast?A.Cheap and convenient.B.Very convenient and good for health.C.Delicious but very expensive.( )16.What can we know from the conversation?A.Americans usually drink afternoon tea with cake.B.English people usually drink afternoon tea with cake.C.Both American people and English people love to drink afternoon tea with cake.听第10段材料，回答第17至20题。
( )17.Why did 0.Henry go to prison?A.He broke the law by not using his own name.B.He wanted to write stories about prisoners.C.People thought he had taken money from the bank.( )18.Where was O.Henry born?A.He was born in North Carolina.B.He was born in New York city.C.He was born in Texas.( )19.Why did people enjoy reading O Henry’s stories?A.Because they were easy to understand.B.Because they showed love for the poor.C.Because they had surprising endings.( )20.Where did 0.Henry get most materials for his stories?A.From the newspaper.B.From his life in prisonC.From the city and people of New York.第二部分：二、单项填空：从A、B、C、C四个选项中，选出可以填入空白处的最佳选项。
(25分）21.—Do you believe we went to Shanghai yesterday?—, for we’ve been working together recently.A.Yes, I believeB.Yes, I believe itC.No, I don’t believe itD.No, I believe not22.He went to many places to find a job, but he had bad .A.chanceB.successC.wayD.luck23.—Have you found the village?—No, we don’t know .A.where is itB.how to get thereC.what to get thereD.how get there24.—How do you know this man?—I with him.A.was used to worked to workingC.was used to workinged to work25.My daughter has grown up, she is no longer she used to be.A.whatB.whichC.where D .that26.—How did you do in the maths exam?—Not very well, .A.I’m sureB.of courseC.I’m afraidD.thank you27.—Would you mind ?—Go ahead. I don’t mind.A.if I turned on the lightB.whether I turned on the lightC.if I turned on the lightD.to turn on the light28. theirs, our city is more beautiful. It is always a garden.pare to; compare topared with; compared topare with; compare withparing; compared to29.Tudy likes smoking her sister doesn’t.A.howeverB.andC.whenD.while30.—Can you make in the hall?—I don’t think so.A.you hearB.yourself hearC.you heardD.yourself heard31.You will be successful unless you your work immediately.A.ever; gets down toB.never; get down toC.over; getD.never; get dow32.English is not only used in English-speaking countries, non-English-speaking countries .A.but; alsoB.and; eitherC.but;as wellD.and; too33.Rock music at a time was pupular young men.A.amongB.toC.byD.with34.The girl was not interested in playing but she was made so.A.piano; doB.the piano; to doC.a pianoD.the piano; doing35.The scienist was honoured a special way hiscontributions the country.A.in; of; forB.of; as; forC.in; for; toD.with; in; to36.The mother got when she saw her son.A.excited; missingB.exciting; missingC.excited; missedD.excited; losing37.—W hat’s on at the Ping Yang Theatre tonight?—A comedy is said to .A.be put outB.be put onC.give a showD.be given a performance38.— .—What a shame!A.I have passed the entrance examB.My mother is satisfied with what I didC.He never gives up studying in the time of difficulty.D.I took a wrong bus and couldn’t get there on time.39.The books written in English are more difficult than written inFrance.A.thoseB.onesC.the oneD.that40.Look at her two cocks. They the same weight.A.are fromB.have ofC.have hadD.are of41.Generally , women live longer than men.A.sayingB.to speakC.spokenD.speaking42.The factory one third of the town. It is so big.A.covers B .take up C.works D.was built43.Nobody but Jane and Mary the secret.A.knowB.knowsC.have knownD.is known44.Not only I but also Tom and Tim tired of having one examination after another.A.isB.areC.amD.be45.They all thought ten years in the long history.A.is a short timeB.are a short timeC.were short timesD.was a short time三、完形填空：阅读下列短文，掌握其大意，然后从46-65各题所给的四个选项中，选出一个最佳答案。