PHP连接MYSQL数据库代码

PHP连接MYSQL数据库代码

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$mysql_server_name='localhost'; //改成自己的mysql数据库服务器

$mysql_username='root'; //改成自己的mysql数据库用户名

$mysql_password='12345678'; //改成自己的mysql数据库密码

$mysql_database='mycounter'; //改成自己的mysql数据库名

$conn=mysql_connect($mysql_server_name,$mysql_username,$mysql_password,$mysql_da tabase);

$sql='CREATE DATABASE mycounter DEFAULT CHARACTER SET gbk COLLATE gbk_chinese_ci; ';

mysql_query($sql);

$sql='CREATE TABLE `counter` (`id` INT(255) UNSIGNED NOT NULL AUTO_INCREMENT ,`count` INT(255) UNSIGNED NOT NULL DEFAULT 0,PRIMARY KEY ( `id` ) ) TYPE = innodb;';

mysql_select_db($mysql_database,$conn);

$result=mysql_query($sql);

//echo $sql;

mysql_close($conn);

echo "Hello!数据库mycounter已经成功建立！";

?>

PHP连接MS SQL数据库代码方法

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1.安装SQL服务器并添加PHP的MSSQL扩展

2.使用以下代码连接并测试

$myServer = localhost; //主机

$myUser = sa; //用户名

$myPass = password; //密码

$myDB = Northwind; //MSSQL库名

$s = @mssql_connect($myServer, $myUser, $myPass)

or die(Couldnt connect to SQL Server on $myServer);

$d = @mssql_select_db($myDB, $s)

or die(Couldnt open database $myDB);

$query = SELECT TitleOfCourtesy+ +FirstName+ +LastName AS Employee ;

$query .= FROM Employees ;

$query .= WHERE Country=USA AND Left(HomePhone, 5) = (206);

$result = mssql_query($query);

$numRows = mssql_num_rows($result);

echo

. $numRows . Row . ($numRows == 1 ? : s) . Returned

;

while($row = mssql_fetch_array($result))

{

echo

. $row[Employee] .

;

}

?>

-------------------------------------------------------------------------------- 通过PHP连接MYSQL数据库

$conn = mysql_connect("localhost","root","password") or die("无法连接数据库");

mysql_select_db("table" ,$conn) or die ("找不到数据源");

通过PHP创建MYSQL数据库

$conn = mysql_connect("localhost","root","password") or die("无法连接数据库");

mysql_create_db("webjx") or die("无法创建数据库");

$sqlstr = "create database other_webjx";

mysql_query($sqlstr) or die("无法创建,一般请检查权限什么的");

创建mysql的表

$conn = mysql_connect("localhost","root","password") or die("无法连接数据库");

mysql_select_db("webjx",$conn) or die("无法连接数据库webjx");

$sql = "create table webjx_table(

ids integer not null auto_increment ,

primary key(ids)

)";

$mysql_query($sql) or die(mysql_error());

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