综合测试二
广东省广州市2023届普通高中毕业班综合测试政治试题(二)(含答案)

广东省广州市2023届普通高中毕业班综合测试政治试题(二)学校:___________姓名:___________班级:___________考号:___________须自身硬,从制定和落实中央八项规定开局破题,提出和落实新时代党的建设总要求,经过不懈努力,党找到了自我革命这一跳出治乱兴衰历史周期率的第二个答案。
这表明()①中国共产党以自我革命引领社会革命②中国共产党是中国特色社会主义事业的领导核心③加强党的建设,必须推动全面从严治党向纵深发展④中国共产党必须时刻保持解决大党独有难题的清醒和坚定A.①②B.①③C.②④D.③④二、选择题组今年3月,十四届全国人大一次会议在京开幕。
近3000名新一届全国人大代表齐聚首都共商国是,为全面建设社会主义现代化国家开好局起好步凝心聚力。
据此回答下列小题。
4.2022年12月中旬至2023年1月,在全国人大常委会主持下,35个选举单位依法选举产生了新一届全国人大代表。
其中,少数民族代表占代表总数14.85%,全国55个少数民族都有代表;一线工人、农民代表占代表总数16.69%,与上届相比提高了0.99个百分点。
可见()①全国人大代表通过直接选举产生②人大代表来自人民,肩负人民的重托③人大代表结构得到优化,具有广泛代表性④人大代表享有提案权、质询权等职权A.①②B.①④C.②③D.③④5.十四届全国人大一次会议表决通过了关于修改立法法的决定。
立法法第五条规定:“立法应当符合宪法的规定、原则和精神,依照法定的权限和程序,从国家整体利益出发,维护社会主义法制的统一、尊严、权威。
”对该规定理解正确的是()①科学立法要合理设定权利与义务②我国坚持依宪立法,依法立法的原则③推进科学立法,要拓宽公民有序参与立法的途径④享有立法权的国家机关应在法治轨道上制定规范性文件A.①③B.①④C.②③D.②④三、单选题6.亚里士多德认为,哲学是超越经验领域,从而到达了最高本体和终极原因的领域的一门学问。
2023年广州市普通高中毕业班综合测试(二)地理试题含答案

秘密★启用前试卷类型:B 2023年广州市普通高中毕业班综合测试(二)地理本试卷共8页,19小题,满分100分。
考试用时75分钟。
注意事项:1.答卷前,考生务必用黑色字迹钢笔或签字笔将自己的姓名、考生号、试室号和座位号填写在答题卡上。
用2B铅笔将试卷类型(B)填涂在答题卡相应位置上。
并在答题卡相应位置上填涂考生号。
2.作答选择题时,选出每小题答案后,用2B铅笔把答题卡对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案。
答案不能答在试卷上。
3.非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新答案;不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
4.考生必须保持答题卡的整洁。
考试结束后,将试卷和答题卡一并交回。
一、选择题:本大题共16小题,每小题3分,共48分。
在每小题列出的四个选项中,只有一项符合题目要求。
围绕高铁站点而建的高铁新城促进了中心城区发展,也影响了城镇空间布局。
高铁新城与中心城区之间的空间关系,可分为副中心式、双城式和飞地式三种模式(图1)。
据此完成1~3题。
图11.甲、乙、丙三种模式分别表示A.双城式城市副中心式飞地式B.飞地式双城式城市副中心式C.城市副中心式双城式飞地式D.飞地式城市副中心式双城式2.三种模式中,中心城区对高铁新城起促进作用A.最小的是甲模式B.最小的是乙模式C.最小的是丙模式D.三种模式一样大3.与甲模式相比,乙模式土地利用最突出的优势是A.类型多样B.成本低C.利用率高D.面积大为减少近地轨道报废卫星对正常工作卫星的影响,科学家研制了离轨帆。
卫星报废后,离轨帆展开,增加了卫星受到的阻力,加快了卫星减速降轨,使其在距地数百千米的大气层中开始销毁。
图2示意卫星离轨帆。
据此完成4~6题。
图24.报废卫星对正常工作卫星造成的最严重危害是A.阻挡光照B.干扰信息传输C.阻碍观察D.增加撞击风险5.加快报废卫星减速降轨的动力主要来源于离轨帆受到的A.地球引力B.太阳辐射C.空气阻力D.天体撞击6.报废卫星开始销毁于A.高层大气B.平流层C.臭氧层D.对流层减震器活塞杆是汽车重要的零部件,其质量影响着汽车的安全性和舒适性。
2024广州市 高中毕业班综合测试 二 英语

2024广州市高中毕业班综合测试二英语The 2024 Comprehensive Examination for High School Graduates in Guangzhou City was a significant milestone for the students of the class of 2024 As they prepared to embark on the next chapter of their lives the exam served as a culmination of their years of hard work and dedication Throughout the examination process the students demonstrated their mastery of the English language showcasing their ability to comprehend complex texts analyze information and articulate their thoughts with clarity and precisionThe reading comprehension section of the exam challenged the students to engage with a variety of passages covering diverse topics from scientific breakthroughs to historical events Students were required to demonstrate their understanding of the main ideas supporting details and the authors underlying message They were also tasked with drawing inferences and making connections between the information presented in the texts This section assessed the students ability to think critically and apply their knowledge to new contextsIn the writing portion of the exam students were presented with thought-provoking prompts that required them to craft well-organized and persuasive essays They were expected to take a clear stance on the issue at hand support their position with relevant evidence and examples and anticipate and address counterarguments This section evaluated the students proficiency in areas such as content development coherence and cohesion as well as their command of English grammar and mechanicsThe listening comprehension component of the test assessed the students ability to comprehend spoken English in a range of contexts from academic lectures to news reports Students were required to listen attentively and answer questions about the main ideas key details and the speakers tone and purpose This section tested the students ability to process information in real-time and demonstrate their understanding through their responsesFinally the speaking portion of the exam provided students with the opportunity to showcase their oral communication skills They were required to engage in a variety of tasks such as delivering a prepared presentation participating in a discussion and responding to impromptu questions This section evaluated the students fluency pronunciation vocabulary usage and ability to express their ideas clearly and effectivelyThroughout the examination process the students demonstrated their strong foundation in the English language and their ability to apply their knowledge in diverse contexts They showcased their critical thinking skills their attention to detail and their capacity to communicate their ideas with clarity and precisionThe 2024 Comprehensive Examination for High School Graduates in Guangzhou City was a testament to the hard work and dedication of the class of 2024 The students rose to the challenge displaying their mastery of the English language and their readiness to take on the next phase of their educational and professional journeys As they move forward they can be proud of their accomplishments and confident in their ability to succeed in the years to come。
广东省韶关市2022-2023学年高三下学期综合测试(二)化学试题

广东省韶关市2022-2023学年高三下学期综合测试(二)化学试题学校:___________姓名:___________班级:___________考号:___________二、单选题三、未知6.化合物M()是一种有机合成的中间体。
下列关于M的说法错误的是KMnO溶液褪色B.所有原子可能共平面A.可使酸性4C H OC.能发生取代反应和氧化反应D.分子式为8637.利用下列装置(夹持装置略)进行实验,能达到实验目的的是四、单选题8.物质类别和元素价态,是学习元素及其化合物性质的重要认识视角。
结合硫元素的“价—类”二维图分析,下列有关说法正确的是A.在酸性条件下,将e和f的钠盐溶液混合,会有d生成B.若上图中盐为钠的正盐,则图中既有氧化性又有还原性的物质有3种C.将b的稀溶液滴加到品红溶液中,品红溶液褪色,体现了b的强氧化性D.将c的浓溶液滴加在胆矾晶体上,晶体由蓝色变成白色,体现了c的脱水性9.室温下,下列各组离子在指定溶液中能大量共存的是A.0.1 mol·L−1NaOH溶液:Na+、K+、23CO-、2AlO-B.0.1 mol·L−1FeCl2溶液:K+、Mg2+、24SO-、4MnO-C.0.1 mol·L−1K2CO3溶液:Na+、Ba2+、Cl−、OH−D.0.1 mol·L−1H2SO4溶液:K+、4NH+、3NO-、3HSO-五、未知A .AB .BC .CD .D13.近日,某科研团队研制设计了一种高性能碱性阴离子交换膜直接氨燃料电池(DAFC),其工作原理如图所示。
下列说法错误的是A .电极A 为负极,发生氧化反应B .若交换膜中通过0.3mol OH -,A 电极区消耗2.24LNH 3C .电极B 的电极反应式为22O 4e 2H O 4OH --++=D .电流方向:电极B→灯泡→电极A→电极B14.下列实验操作能达到实验目的且离子方程式正确的是 A .向少量澄清石灰水中加入足量的3NaHCO 溶液:223323Ca 2OH 2HCO CaCO 2H O CO +---++=↓++B .用KSCN 溶液检验2FeCl 是否完全变质:()3Fe 3SCN Fe SCN -+=C .用NaOH 溶液除去乙酸乙酯中的少量乙酸:332CH COOH OH CH COO H O --+=+D .用盐酸清洗进行银镜反应后试管内壁的银白色固体:22Ag 2Cl 2H H 2AgCl -+++=↑+↓六、单选题15.氮的氧化物是大气污染物之一,如图为科研人员探究消除氮氧化物的反应机理,下列说法错误的是A .整个过程中2Ni +作催化剂B .过程Ⅰ中发生的化学反应为2322Ni 2NO=2Ni 2O N ++-+++C .过程中涉及的反应均为氧化还原反应D .过程Ⅱ中氧化剂与还原剂的物质的量之比为1∶216.常温下,向10.00mL0.1000mol·L -1NaHCO 3溶液中滴加0.1000 mol·L -1的盐酸,溶液的pH 随加入的盐酸体积V 的变化如图所示,选项错误的是A .a 点溶液中,c (HCO 3-)>c (H 2CO 3)>c (CO 23-)B .b 点溶液中,()()-2-33HCO +2CO c c <()()+-Na+Cl c cC .c 点溶液中,共含有7种微粒。
期末复习综合测试卷(二)+++++2022-2023学年部编版语文九年级下册+

部编版九年级语文下册期末总复习综合性检测试卷(二)一、积累与运用。
(20分)1.下列加点字的注音完全正确的一项是()A.国殇.(shāng)伫.立(chù)诡谲.(jué)波澜.(lán)B.睥.睨(bì)稽.首(qǐ)行.头(xíng)污秽.(huì)C.踌躇.(chú)囫.囵(hú)童谣.(yáo)鞭挞.(tà)D.瘦削.(xuē)咀嚼.(jué)羡.慕(xiàn)弄.堂(nòng)2.下列词语书写完全正确的一项是()(3分)A.掬躬收揽犀利骂骂咧咧B.雷霆幌子侦辑咬牙跺脚C.怯懦忌讳拾掇摄手摄脚D.捣蛋凄惨竹匾喃喃自语3.下列各句中加点的成语运用不正确的一项是()(3分)A.母亲在家庭里极能任劳任怨....。
她性格和蔼,没有打骂过我们,也没有同任何人吵过架。
B.父亲老实厚道低三下四....累了一辈子,没人说过他有地位,父亲也从没觉得自己有地位。
C.但这是没有办法的,只得裹一条毯子,横着心躺下去。
因为实在太疲倦,一会儿就酣然..入梦了...。
D.假如一个男人跟朋友和熟人见面时彬彬有礼....,可是在家里对妻子儿女动不动就大发雷霆——那就可以肯定他不是一个有教养的人。
4.下列句子没有语病的一项是()(3分)A.是否注重用非语言沟通与孩子交流,才能让孩子培养更加优秀的语言能力。
B.那种不顾生态环境,片面强调经济效益,无疑是杀鸡取卵,到头来只能是得不偿失。
C.风油精的主要成分是由薄荷脑、樟脑桉油、丁香酚、水杨酸甲酯等配制而成的。
D.在各方重点扶持下,我们中国传统戏剧这颗璀璨明珠终会再焕光彩。
5.综合性学习材料:每年在湖北龙感湖自然保护区越冬的天鹅超过了6万只,为了让天鹅安心栖息,管理站划出300亩稻田,不予收割,为鸟留食。
但前不久发生的一件事,让管理站开始对天鹅“不近人情”:一只受伤的小天鹅在经过两周的救治后,放回水城时却趴在岸边一动不动。
高考数学_综合测试卷(二)

综合测试卷(二)时间:120分钟 分值:150分一、选择题:本题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.(2021湖北黄冈中学三模,3)已知复数z 满足z 2+4i=0,则|z|=( ) A.4 B.2 C.√2 D.1答案 B 设z=a+bi(a,b ∈R),则z 2+4i=(a+bi)2+4i=a 2-b 2+(2ab+4)i=0,所以a 2-b 2=0且2ab+4=0,解得a=√2,b=-√2或a=-√2,b=√2,则|z|=√a 2+b 2=2.故选B.2.(2021海淀一模,1)已知集合A={1},B={x|x ≥a}.若A ∪B=B,则实数a 的取值范围是( ) A.(-∞,1) B.(-∞,1] C.(1,+∞) D.[1,+∞)答案 B 由A ∪B=B,得A ⊆B,从而有a ≤1,所以实数a 的取值范围是(-∞,1],故选B.3.(2020湖南衡阳一模)我国古代有着辉煌的数学研究成果,《周髀算经》《九章算术》《海岛算经》《孙子算经》《缉古算经》等10部专著是了解我国古代数学的重要文献,这10部专著中5部产生于魏晋南北朝时期,某中学拟从这10部专著中选择2部作为“数学文化”课外阅读教材,则所选2部专著中至少有一部是魏晋南北朝时期专著的概率为( ) A.79 B.29 C.49 D.59答案 A 设所选2部专著中至少有一部是魏晋南北朝时期的专著为事件A,所以P(A )=C 52C 102=29,因此P(A)=1-P(A )=1-29=79.故选A.4.(2022届广州10月调研,5)双曲线C:x 2a 2-y 2b 2=1的一条渐近线方程为x+2y=0,则C 的离心率为( )A.√52B.√3C.2D.√5答案 A 由题意得12=b a ,即a=2b,又∵b 2=c 2-a 2,∴5a 2=4c 2,∴e=c a =√52,故选A.5.(2021广州模拟,5)某学校组织学生参加数学测试,某班成绩的频率分布直方图如图,数据的分组依次为[20,40),[40,60),[60,80),[80,100].若不低于60分的人数是35,则该班的学生人数是( )A.45B.50C.55D.60答案 B 由频率分布直方图得不低于60分的频率为(0.02+0.015)×20=0.70,∵不低于60分的人数是35,∴该班的学生人数是350.70=50.故选B.6.(2021百校大联考(六),9)已知向量a=(3,100),若λa =(3λ,2μ)(λ,μ∈R),则λμ=( )A.50B.3C.150D.13答案 C 根据题意得λa =(3λ,100λ)=(3λ,2μ),所以2μ=100λ,所以λμ=150,故选C.7.(2022届江苏省天一中学月考,6)若函数f(x)=sin(4x-φ)(0≤φ≤π2)在区间[0,π6]上单调递增,则实数φ的取值范围是( ) A.[π6,π4] B.[π4,π3] C.[π3,π2] D.[π6,π2] 答案 D 当x ∈[0,π6]时,-φ≤4x-φ≤2π3-φ.因为函数y=sin x 在[-π2,π2]上单调递增,且函数f(x)=sin(4x-φ)(0≤φ≤π2)在区间[0,π6]上单调递增,所以得{-φ≥−π2,2π3-φ≤π2,解得π6≤φ≤π2,所以实数φ的取值范围是[π6,π2]. 8.(2022届重庆巴蜀中学11月月考,8)在棱长为2的正方体ABCD-A 1B 1C 1D 1中,点E,F,G,H 分别为棱AB,BC,C 1D 1,A 1D 1的中点,若平面α∥平面EFGH,且平面α与棱A 1B 1,B 1C 1,B 1B 分别交于点P,Q,S,其中点Q 是棱B 1C 1的中点,则三棱锥B 1-PQS 的体积为( ) A.1 B.12 C.13 D.16答案 D如图所示,取AA1,CC1的中点N,M,连接NH,NE,MG,MF,由正方体的性质可知,NE∥GM,HG∥EF,HN∥MF,所以H,G,M,F,E,N六点共面,又因为平面α∥平面EFGH,所以平面PQS∥平面HGMFEN,又平面BB1C1C∩平面PQS=QS,平面BB1C1C∩平面HGMFEN=MF,所以QS∥MF,由M,F,Q为所在棱中点可知S为BB1的中点,同理可知,P 为A1B1的中点,所以B1P=B1Q=B1S=1,且B1P,B1Q,B1S两两垂直,所以三棱锥B1-PQS的体积为V=13×1×12×1×1=16,故选D.9.(2021八省联考,8)已知a<5且ae5=5e a,b<4且be4=4e b,c<3且ce3=3e c,则()A.c<b<aB.b<c<aC.a<c<bD.a<b<c答案D因为ae5=5e a,a<5,所以a>0,同理b>0,c>0,令f(x)=e x x,x>0,则f '(x)=e x(x-1) x2,当0<x<1时, f '(x)<0,当x>1时, f '(x)>0,故f(x)在(0,1)上为减函数,在(1,+∞)上为增函数,因为ae5=5e a,故e55=e a a,即f(5)=f(a),又0<a<5,故0<a<1,同理可得 f(4)=f(b), f(3)=f(c),则0<b<1,0<c<1,因为f(5)>f(4)>f(3),所以f(a)>f(b)>f(c),所以0<a<b<c<1.故选D.10.(2022届宁夏期末,7)“a≥4”是“二次函数f(x)=x2-ax+a有零点”的()A.充分不必要条件B.必要不充分条件C.充分必要条件D.既不充分也不必要条件答案 A 若a ≥4,则Δ=a 2-4a=a(a-4)≥0,故方程x 2-ax+a=0有解,即二次函数f(x)=x 2-ax+a 有零点.若二次函数f(x)=x 2-ax+a 有零点,则方程x 2-ax+a=0有解,则Δ=a 2-4a ≥0,解得a ≥4或a ≤0.故“a ≥4”是“二次函数f(x)=x 2-ax+a 有零点”的充分不必要条件,故选A.11.(2022届黑龙江模拟,11)关于函数f(x)=cos 2x-2√3sin xcos x,有下列命题:①对任意x 1,x 2∈R,当x 1-x 2=π时,f(x 1)=f(x 2)成立;②f(x)在区间[-π6,π3]上单调递增;③函数f(x)的图象关于点(π12,0)对称;④将函数f(x)的图象向左平移5π12个单位长度后所得图象与函数y=2sin 2x 的图象重合.其中正确的命题是( )A.①②③B.②C.①③D.①②④答案 C f(x)=cos 2x-2√3sin xcos x=cos 2x-√3sin 2x=2cos (2x +π3).因为x 1-x 2=π,所以f(x 1)=2cos (2x 1+π3)=2cos [2(x 2+π)+π3]=2cos (2x 2+π3)=f(x 2),故①正确;当x ∈[-π6,π3]时,2x+π3∈[0,π],所以函数f(x)在区间[-π6,π3]上单调递减,故②错误;f (π12)=2cos (2×π12+π3)=2cos π2=0,故③正确;将函数f(x)的图象向左平移5π12个单位长度后得到y=2cos [2(x +5π12)+π3]=-2cos (2x +π6)的图象,易知该图象与函数y=2sin 2x 的图象不重合,故④错误.故选C.12.(2022届北京四中10月月考,10)对于函数y=f(x),若存在x 0,使得f(x 0)=-f(-x 0),则称点(x 0, f(x 0))与点(-x 0, f(-x 0))是函数f(x)的一对“隐对称点”.若函数f(x)={x 2+2x,x <0,mx +2,x ≥0的图象存在“隐对称点”,则实数m 的取值范围是( ) A.[2-2√2,0) B.(-∞,2-2√2] C.(-∞,2+2√2] D.(0,2+2√2]答案 B 由“隐对称点”的定义可知, f(x)={x 2+2x,x <0,mx +2,x ≥0的图象上存在关于原点对称的点,设函数g(x)的图象与函数y=x 2+2x,x<0的图象关于原点对称.令x>0,则-x<0, f(-x)=(-x)2+2(-x)=x 2-2x,所以g(x)=-x 2+2x(x>0),故原问题等价于关于x 的方程mx+2=-x 2+2x 有正根,故m=-x-2x+2,而-x-2x +2=-(x +2x )+2≤-2√x ·2x+2=2-2√2,当且仅当x=√2时,取得等号,所以m ≤2-2√2, 故实数m 的取值范围是(-∞,2-2√2],故选B.二、填空题:本题共4小题,每小题5分,共20分.13.(2021海淀一模,11)已知函数f(x)=x 3+ax.若曲线y=f(x)在点(1, f(1))处的切线的斜率为2,则实数a 的值是 . 答案 -1解析 由题意得f '(x)=3x 2+a,所以f '(1)=3+a=2,从而得a=-1.14.(2022届广西北海模拟,15)函数f(x)=(1+√3tan x)cos x 的最小值为 . 答案 -2解析 f(x)=(1+√3tan x)cos x=cos x+√3sin x=2sin (x +π6)(x ≠π2+kπ,k ∈Z),∵sin (x +π6)∈[-1,1],∴f(x)=2sin (x +π6)∈[-2,2],∴函数f(x)=(1+√3tan x)cos x 的最小值为-2. 15.(2018北京文,14,5分)若△ABC 的面积为√34(a 2+c 2-b 2),且∠C 为钝角,则∠B= ;c a的取值范围是 . 答案π3;(2,+∞) 解析 依题意有12acsin B=√34(a 2+c 2-b 2)=√34×2accos B,则tan B=√3,∵0<∠B<π,∴∠B=π3.c a =sinC sinA =sin (2π3-A )sinA =12+√3cosA 2sinA =12+√32·1tanA, ∵∠C 为钝角,∴2π3-∠A>π2,又∠A>0,∴0<∠A<π6,则0<tan A<√33,∴1tanA >√3,故c a >12+√32×√3=2. 故ca的取值范围为(2,+∞). 16.(2021四川南充二模,16)设函数f(x)=x+e |x|e |x|的最大值为M,最小值为N,下述四个结论:①M+N=4;②M -N=2e ;③MN=1-1e 2;④M N =e -1e+1.其中所有正确结论的序号是 .答案 ②③解析 f(x)=1+x e |x|,设g(x)=xe |x|,可知g(x)为奇函数,其最大值和最小值互为相反数,当x>0时,g(x)=x e x ,g'(x)=1−xe x ,当0<x<1时,g(x)单调递增,当x>1时,g(x)单调递减,可知x=1时,g(x)取得极大值1e ,也为最大值,由g(x)为奇函数可知,当x<0时,g(x)的最小值为-1e ,则M=1+1e ,N=1-1e ,则M-N=2e ,M+N=2,MN=1-1e 2,M N =e+1e -1.故答案为②③.三、解答题:共70分.解答应写出文字说明,证明过程或演算步骤.(一)必做题17.(2021湘豫名校联盟4月联考,17)在△ABC 中,已知内角A,B,C 所对的边分别为a,b,c,且bsin A=acos (B -π6).(1)求B;(2)若c=5,b=7,求△ABC 的周长.解析 (1)由bsin A=acos (B -π6)及正弦定理,得sin Bsin A=sin Acos (B -π6),因为sin A ≠0,所以sin B=cos (B -π6),即sin B=√32cos B+12sin B,即sin (B -π3)=0, 由于0<B<π,所以-π3<B-π3<2π3,所以B-π3=0,所以B=π3.(2)在△ABC 中,由余弦定理b 2=a 2+c 2-2accos B 及已知,得a 2-5a-24=0,解得a=8或a=-3(舍), 故△ABC 的周长为a+b+c=8+7+5=20.18.(2014北京文,17,14分)如图,在三棱柱ABC-A 1B 1C 1中,侧棱垂直于底面,AB ⊥BC,AA 1=AC=2,BC=1,E,F 分别是A 1C 1,BC 的中点.(1)求证:平面ABE ⊥平面B 1BCC 1; (2)求证:C 1F ∥平面ABE; (3)求三棱锥E-ABC 的体积.解析 (1)证明:在三棱柱ABC-A 1B 1C 1中,BB 1⊥底面ABC.所以BB 1⊥AB. 又因为AB ⊥BC,BB 1∩BC=B,所以AB ⊥平面B 1BCC 1.又因为AB ⊂平面ABE,所以平面ABE ⊥平面B 1BCC 1.(2)证明:取AB 的中点G,连接EG,FG.因为G,F 分别是AB,BC 的中点, 所以FG ∥AC,且FG=12AC.因为AC ∥A 1C 1,AC=A 1C 1,且E 为A 1C 1的中点, 所以FG ∥EC 1,且FG=EC 1. 所以四边形FGEC 1为平行四边形. 所以C 1F ∥EG.又因为EG ⊂平面ABE,C 1F ⊄平面ABE, 所以C 1F ∥平面ABE.(3)因为AA 1=AC=2,BC=1,AB ⊥BC, 所以AB=√AC 2-BC 2=√3. 所以三棱锥E-ABC 的体积V=13S △ABC ·AA 1=13×12×√3×1×2=√33. 19.(2022届山东济宁一中开学考,18)为提高教育教学质量,越来越多的高中学校采用寄宿制的封闭管理模式.某校对高一新生是否适应寄宿生活十分关注,从高一新生中随机抽取了100人,其中男生占总人数的40%,且只有20%的男生表示自己不适应寄宿生活,女生中不适应寄宿生活的人数占高一新生抽取总人数的32%,学校为了调查学生对寄宿生活适应与否是否与性别有关,构建了如下2×2列联表:不适应寄宿生活适应寄宿生活合计男生 女生 合计(1)请将2×2列联表补充完整,并判断能否有99%的把握认为“适应寄宿生活与否”与性别有关; (2)从男生中以“是否适应寄宿生活”为标准采用分层随机抽样的方法随机抽取10人,再从这10人中随机抽取2人.若所选2名学生中的“不适应寄宿生活”的人数为X,求随机变量X 的分布列及数学期望. 附:K 2=n(ad -bc)2(a+b)(c+d)(a+c)(b+d),P(K 2≥k 0)0.15 0.10 0.05 0.025 0.01 0.001 k 02.0722.7063.8415.0246.63510.828解析 (1)根据题意填写列联表如下:不适应寄宿生活适应寄宿生活合计 男生 8 32 40 女生 32 28 60 合计4060100K 2=100×(8×28−32×32)240×60×40×60≈11.11,因为11.11>6.635,所以有99%的把握认为“适应寄宿生活与否”与性别有关.(2)用分层随机抽样的方法随机抽取10人,有2人不适应寄宿生活,8人适应寄宿生活, 所以随机变量X 的可能取值是0,1,2,P(X=0)=C 82C 102=2845,P(X=1)=C 81·C 21C 102=1645,P(X=2)=C 22C 102=145,所以随机变量X 的分布列为X 012P28451645145数学期望E(X)=0×2845+1×1645+2×145=25.20.(2021河南尖子生诊断性考试,21)已知函数f(x)=e x-ax 2(其中e 为自然对数的底数,a 为常数). (1)若f(x)在(0,+∞)上有极小值0,求实数a 的值; (2)若f(x)在(0,+∞)上有极大值M,求证:M<a.解析 (1)f '(x)=e x-2ax.设f(x 0)=0(x 0∈(0,+∞)),则f '(x 0)=0.由{e x 0-ax 02=0,e x 0-2ax 0=0,解得x 0=2,a=e 24.经检验,a=e 24满足f(x)在(0,+∞)上有极小值,且极小值为0.故a=e 24.(2)证明:设f(x)在(0,+∞)上的极大值点为x 1,则f '(x 1)=0,即e x 1-2ax1=0,则有a=e x 12x 1. 此时M=f(x 1)=e x 1-a x 12.故M-a=e x 1-a x 12-a=e x 1-a(x 12+1)=e x 1-(x 12+1)·e x 12x 1=e x 1·[1−12(x 1+1x 1)]≤0(当且仅当x 1=1时取等号).而当x 1=1时,a=e 2,f '(x)=e x -ex,f ″(x)=e x-e,x ∈(0,1)时,f ″(x)<0,x∈(1,+∞)时,f ″(x)>0.则f '(x)在(0,1)上单调递减,在(1,+∞)上单调递增,且f '(1)=0.则f '(x)≥f '(1)=0,故f(x)在(0,+∞)上单调递增,此时f(x)在(0,+∞)上无极值. 与已知条件矛盾,故x 1≠1,则M-a<0,即M<a.21.(2021湖南六校4月联考,21)已知A,B 分别为椭圆E:x 2a 2+y 23=1(a>√3)的左,右顶点,Q 为椭圆E 的上顶点,AQ⃗⃗⃗⃗⃗ ·QB ⃗⃗⃗⃗⃗ =1. (1)求椭圆E 的方程;(2)已知动点P 在椭圆E 上,定点M (-1,32),N (1,−32).①求△PMN 的面积的最大值;②若直线MP 与NP 分别与直线x=3交于C,D 两点,问:是否存在点P,使得△PMN 与△PCD 的面积相等?若存在,求出点P 的坐标;若不存在,说明理由.解析 (1)由题意得A(-a,0),B(a,0),Q(0,√3),则AQ ⃗⃗⃗⃗⃗ =(a,√3),QB ⃗⃗⃗⃗⃗ =(a,-√3),由AQ ⃗⃗⃗⃗⃗ ·QB ⃗⃗⃗⃗⃗ =1,得a 2-3=1,解得a=2,所以椭圆E 的方程为x 24+y 23=1.(2)①设P(2cos θ,√3sin θ),易知直线MN:y=-32x,即3x+2y=0,点P 到直线MN 的距离d=√3sinθ|√13=4√3|sin (θ+π3)|√13≤4√3913,又|MN|=√13,则S △PMN =12|MN|·d ≤2√3,即(S △PMN )max =2√3.②设P(x 0,y 0),由①知|MN|=√13,点P 到直线MN 的距离d 1=00√13,则S △PMN =12|MN|·d 1=12|3x 0+2y 0|.直线MP:y=y 0-32x 0+1(x+1)+32,令x=3,可得C (3,4y 0-6x 0+1+32);直线PN:y=y 0+32x 0-1(x-1)-32,令x=3,可得D (3,2y 0+3x 0-1-32),则|CD|=|(3x 0+2y 0)(x 0-3)x 02-1|,又P 到直线CD 的距离d 2=|3-x 0|,则S △PCD =12|CD|·d 2=12|3x 0+2y 0x 02-1|·(3-x 0)2,∵△PMN 与△PCD 的面积相等,∴12|3x 0+2y 0|=12|3x 0+2y 0x 02-1|·(3-x 0)2,故3x 0+2y 0=0(舍)或|x 02-1|=(3-x 0)2,解得x 0=53,代入椭圆方程得y 0=±√336,故存在点P 满足题意,点P 的坐标为(53,√336)或(53,-√336). (二)选做题(从下面两道题中选一题做答)22.(2021郑州一中周练(二),22)已知平面直角坐标系xOy,以O 为极点,x 轴的正半轴为极轴建立极坐标系,P 点的极坐标为(3,π3),曲线C 的极坐标方程为ρ=2cos (θ-π3).(1)写出点P 的直角坐标及曲线C 的直角坐标方程;(2)若Q 为曲线C 上的动点,求PQ 的中点M 到直线l:ρcos θ+2ρsin θ=2√3的距离的最小值. 解析 (1)点P 的直角坐标为(32,3√32).由ρ=2cos (θ-π3)得ρ2=ρcos θ+√3ρsin θ①,将ρ2=x 2+y 2,ρcos θ=x,ρsin θ=y 代入①,整理可得曲线C 的直角坐标方程为(x -12)2+(y -√32)2=1.(2)直线l:ρcos θ+2ρsin θ=2√3的直角坐标方程为x+2y-2√3=0.设点Q 的直角坐标为12+cos θ,√32+sin θ, 则M (1+cosθ2,√3+sinθ2), 所以点M 到直线l 的距离d=|(1+cosθ2)+2(√3+sinθ2)-2√3|√12+22=2√5=√5sin(θ+φ)|2√5,其中tan φ=12.所以点M 到直线l:ρcos θ+2ρsin θ=2√3的距离的最小值为0. 23.(2021山西运城月考,23)已知函数f(x)=|2x-1|+|x+1|. (1)解不等式f(x)≤6;(2)记函数g(x)=f(x)+|x+1|的最小值为m,若a,b,c ∈R,且a+2b+3c-m=0,求a 2+b 2+c 2的最小值.解析 (1)f(x)={ -3x,x ≤−1,-x +2,−1<x <12,3x,x ≥12.当x ≤-1时,令f(x)≤6,解得x ≥-2,则-2≤x ≤-1; 当-1<x<12时,令f(x)≤6,解得x ≥-4,则-1<x<12;第 11 页 共 11 页 当x ≥12时,令f(x)≤6,解得x ≤2,则12≤x ≤2. 所以-2≤x ≤2.故f(x)≤6的解集为[-2,2].(2)g(x)=f(x)+|x+1|=|2x-1|+2|x+1|=|2x-1|+|2x+2|≥|2x-1-(2x+2)|=3, 当且仅当(2x-1)(2x+2)≤0时取“=”,∴m=3,∴a+2b+3c=3.由柯西不等式得(a 2+b 2+c 2)(12+22+32)≥(a+2b+3c)2=9,整理得a 2+b 2+c 2≥914,当且仅当a 1=b 2=c 3,即a=314,b=37,c=914时“=”成立,故a 2+b 2+c 2的最小值是914.。
综合测试题二
综合测试题二一、选择题(一)单项选择题(共10小题,每题1分,共10分)1.马克思主义是()A 马克思和恩格斯创立的基本理论、基本观点和学说的体系,包括其继承者在实践中不断发展着的马克思主义。
B 马克思和恩格斯创立的哲学和政治经济学的理论体系。
C 马克思和恩格斯创立的科学社会主义和政治经济学的理论体系。
D 马克思和恩格斯创立的政治经济学和哲学的理论体系。
2.马克思主义产生于()A 19世纪20年代B 19世纪30年代C 19世纪40年代D 19世纪50年代3.学习马克思主义的根本方法是()A理论联系实际B精读和泛读结合C早期著作和晚期著作结合D、马克思著作和毛泽东著作结合4.哲学基本问题是()A.物质和运动的关系问题 C.思维和存在的关系问题 C.社会和自然的关系问题 D.主体和客体的关系问题5.哲学上的两大阵营是指()A.唯物主义和唯心主义B.辩证法和形而上学C.一元论和二元论D.可知论和不可知论6.划分唯物主义和唯心主义的唯一标准是()A.对思维和存在何者为第一性的不同回答B.对思维和存在有没有同一性的不同回C.对世界是否具有统一性的不同回答 D.对世界是否普遍联系的不同回答7.时间和空间是( )A.物质的本质特性B.物质的根本属性C.运动着的物质的存在形式D.人们头脑中形成的观念8.下列选项中正确表述意识本质的是()A.意识是自然界长期发展的产物B.意识是客观世界的主观映像C.意识是社会劳动的产物D.意识是人脑自生的一种形式9.下列命题中,正确阐述了实践含义的是()A.实践是个人的日常生活活动B.实践是主观创造客观的活动C.实践是主体改造客体的活动D.实践是主体应付环境的活动10.唯物辩证法认为,发展的实质是( )A.事物数量的增加B.事物的量变引起质变C.事物的运动变化D.新事物的产生和旧事物的灭亡(二)多项选择题(共10小题,每题1分,共10分)1.马克思主义的根本特性是()A、实用性B阶级性C科学性D实践性E革命性2.马克思主义的三个组成部分是()A马克思主义哲学B马克思主义社会学C马克思主义政治学D马克思主义政治经济学E科学社会主义3.从意识的本质看,意识是()A.自然界长期发展的产物B.人脑的机能C.人的头脑中固有的D.物质世界的主观映象E.人脑的分泌物4.实践的特点是()A客观性B有用性C创造性D社会历史性E主观性5.下列选项中,属于唯物辩证法基本规律的有()A.质量互变规律 B.对立统一规律C.联系发展规律 D.否定之定规律E.因果作用规律6.实践是认识的基础,对认识有决定作用,表现在()A.实践是认识的来源B.实践是认识发展的动力C.实践是认识的本质 D.实践是检验认识真理性的标准E.实践是认识的最终目的7.上层建筑由诸多要素构成,下列各项属于上层建筑要素的有()A.军队、警察、法院等设施 B.政治思想和政治制度 C.法律思想和法律制度 D.逻辑学、语言学、自然科学 E.文艺、道德、宗教8.下列选项中,正确说明真理与谬误关系的有( )A.在一定范围内真理和谬误是对立的B.真理和谬误相比较而存在C.真理和谬误相斗争而发展D.真理和谬误相互包含 E.在一定条件下真理和谬误相互转化9.经济全球化的主要表现有()A生产全球化B贸易全球化C金融全球化D货币全球化E企业经营全球化10.历史唯物主义关于经济基础决定上层建筑的原理认为() A. 经济基础决定上层建筑的产生 B. 经济基础的性质决定上层建筑的性质 C. 经济基础决定上层建筑的各个细节 D. 经济基础决定上层建筑的具体形式 E. 经济基础的变化决定上层建筑的变化二、判断题,正确的打√,错误的打×(共10小题,每题一分,共10分)1.马克思主义最鲜明的政治立场是一切理论和奋斗都应致力于实现以劳动人民为主体的最广大人民的根本利益( )2.一切唯心主义的共同观点是都认为世界是主观精神的产物( )3.从动物心理发展到人的意识起决定性作用的是生产劳动( )4.唯物辩证法的实质与核心是永恒发展规律( )5.辩证唯物主义认识论首要的和基本的观点是实践的观点( )6.人类全部社会关系中最基础的关系是血缘关系( )7.人类社会的基本矛盾是生产力和生产关系、经济基础和上层建筑之间的矛盾( )8.欧洲资本主义萌芽于15世纪末16世纪初( )9.国家政权和私人垄断资本垄断资本主义结合是国家垄断资本主义( )10.商品经济的基本矛盾是生产与消费的矛盾( )三、材料分析题(12分)分析下列材料并回答问题:美国著名的企业管理家艾科卡在刚接任美国克莱斯勒汽车公司董事长时,该公司正面临着破产的绝境。
广东省2024-2025学年高三上学期11月综合测试(二)地理含答案
2025届高三综合测试(二)地理(答案在最后)满分:100分时间:75分钟注意事项:1.答卷前,考生务必用黑色字迹的钢笔或签字笔将自己的班别、姓名、考号填写在答题卡指定位置,并用铅笔准确填涂考号。
2.选择题每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑;如需改动,用橡皮擦干净后,再选涂其它答案;不能答在试卷上。
3.非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内的相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液。
不按以上要求作答的答案无效。
4.考生必须保持答题卡的整洁,考试结束后,答题卡由监考老师收回。
一、选择题:本大题共16小题,每小题3分,共48分。
在每小题列出的四个选项中,只有一项符合题目要求。
2024年6月7日,深中通道这项集“桥、岛、隧、水下互通”于一体的超级工程,正式进入收尾工作阶段,6月底具备通车条件,通车后中山、珠海、江门及粤西等地区通往深圳、粤东地区的过江时间从以前的2小时缩短为20分钟左右,极大缩短珠江东西两岸的时空距离,缓减虎门大桥等过江通道交通压力。
工程采取了东隧西桥的方式,海底隧道采用超大型沉管隧道,沉管在陆地上制造完成后,再运送到海上拼装,拼装时需精准对接,不能有丝毫偏差。
下图为深中通道主体工程示意图。
据此完成下面小题。
1.深中通道超大型沉管隧道施工难度大主要是由于该地()A.基岩埋藏深B.全年高温C.水流速度不稳D.海水深度大2.深中通道的建成通车,有利于深圳()①集聚资金、技术和人才等资源②吸引人口迁入,迅速扩大规模③增强对周边城市辐射带动作用④强化服务功能,提高服务成本A.①②B.①③C.②③D.③④2024年9月11日,蓝箭航天公司研制的液氧甲烷火箭“朱雀三号”完成垂直起降返回飞行试验。
除传统液氢燃料外,甲烷逐渐成为火箭推进剂之一。
不同于以往“先研发、再实验、再转化”的发展路径,蓝箭公司引入社会资本融资,探索出“边研究、边应用、边转化”的发展模式。
大学有机化学综合测试题(二)
综合测试题(二)一.命名下列各化合物或写出结构式.1. 2.CH 3CH 2CHCHCH 3CH 3CH 2CH 33. 4. (标出R/S 构型)5. 6.E-3-甲基-2-已烯 7.2-丙基甲苯 8.N-甲基苯胺9.3-已烯-2-酮 10.β-D-吡喃葡萄糖二.填空1.已烷中碳原子的杂化形式是 ,其碳链在空间呈现出 状排布。
2.写出1-甲基环已烯分别与HBr 和KMnO 4/H +试剂的反应式:; 。
3.写出甲苯分别与Br 2+FeBr 3和KMnO 4/H +试剂的反应式:; 。
4.甲苯在化学性质上表现为芳香性,芳香性化合物具有 的特殊结构.5.甲酚是三种位置异构体的混合物,写出对位异构体的结构式 。
甲酚还有两种官能团异构体,它们的结构分别为 、 ,其中对氧化剂稳定的是 。
6.邻羟基苯甲酸俗称水杨酸,其结构式为 ;分别写出水杨酸与乙酐,水杨酸与甲醇在浓H 2SO 4存在下的反应式:; CH 3HH OH CH 3COCH2COOH COOH CH 3H NH 2CH3CH CHCHO。
7.丁酮二酸又称草酰乙酸,草酰乙酸有较稳定的烯醇型异构体,写出其烯醇型结构: ,草酰乙酸受热易发生反应.8. 卵磷脂组成中有甘油、高级脂肪酸、磷酸和胆碱,它们主要通过、两种结合键彼此结合.在生理pH值下,卵磷脂主要以形式存在。
9.丙氨酸(pI =6.02)溶于纯水中,其pH值所在范围为。
三.选择题(1—20题为单选题;20—30题为多选题)1.下列化合物中只有σ键的是()A、CH3CH2CHOB、CH3CH=CH2OHC、CH3CH2OHD、2.含有2种官能团的化合物是()A、CH3CH2CHOB、CH2=CHCHOC、CH3CH2CH2OHD、HOOCCH2COOH3.下列化合物中不具顺反异构的是()A、CH3CH=CHCH3B、(CH3)2C=CHCH3C、CH2=CHCH=CH2D、CH3CH=CHCHO4.下列化合物中能被酸性高锰酸钾氧化的有()A、甲烷B、甲醇C、乙醚D、乙酸5.下列化合物中酸性最强的是()A、丁酸B、丁醇C、2-羟基丁酸D、丁醛6.下列化合物中碱性最强的是()A、乙胺B、苯胺C、二乙胺D、N-乙基苯胺7.下列化合物中不属于酮体的是()A、丙酮B、丁酸C、β-羟基丁酸D、β-丁酮酸8.下列化合物中可发生银镜反应的是()A、丙烷B、丙醇C、丙醛D、丙酮9.下列化合物中熔点最高的是()A、丙酸B、丙酮C、乙醚D、甘氨酸10.在稀碱液中能发生醇醛缩合反应的是()A、甲醛B、丙醛C、苯甲醛D、丙酸11.下列化合物中能发生碘仿反应的是()A、1-丙醇B、 2-丙醇C、丙醛D、3-戊酮12.加热发生脱羧反应的二元酸是()A、丙二酸B、丁烯二酸C、戊二酸D、邻苯二甲酸13.与亚硝酸反应有黄色油状物生成的胺是()A、苯胺 B、N-甲基苯胺C、苄胺D、N,N-二甲基苯胺14.具有变旋光现象的葡萄糖衍生物是()A、葡萄糖酸B、葡萄糖二酸C、葡萄糖醛酸D、甲基葡萄糖苷15.不能水解的物质是()A、油脂B、神经磷脂C、甲基葡萄糖苷D、胆固醇16.下列二糖不具有还原性的是()A、蔗糖B、乳糖C、麦芽糖D、纤维二糖17.鉴定氨基酸常用的试剂是()A、希夫试剂B、班氏试剂C、茚三酮溶液D、莫利许试剂18.谷氨酸在纯水中带负电荷,其pI值可能是()A、10.76B、9.40C、7.58D、3.2219.根据下列油脂的皂化值,可以确定平均分子量最小的是()A、猪油 195-203B、奶油 210-230C、牛油 190-200D、豆油 189-19520.下列关于“必需脂肪酸”的描述中不正确的是()A、“必需脂肪酸”是含有偶数个碳原子的不饱和酸;B、“必需脂肪酸”是含有偶数个碳原子的不饱和一元酸;C、哺乳动物本身不能合成,必需从食物中获得;D、它们对哺乳动物的生长和发育是必不可缺的。
大学英语2(高起专)综合测试2及答案
中国地质大学(武汉)远程与继续教育学院大学英语 2 课程综合测试2一.Vocabulary and Structure(30 points)1 . Don’t you think that article still has much to be __D_____? .A. satisfiedB. examinedC. reviewedD. improved2. In the supermarket the customers felt it hard to ___B____the temptation to spend money on things that they didn’t really ________. .A. comfort; expectB. resist; needC. cause; wantD. relieve; wish3. After the new technique was introduced, the factory produced ____C___TV sets in 1998 as the year before.A. as twice as manyB. as many twiceC. twice as manyD. twice many as4. Since Linda is both diligent and smart, I never doubt that she will____B______. .A. successB. succeedC. successfulD. successor5. You can have the magazine_____B______ I finish reading it.A. in the momentB. the momentC. the moment asD. in the moment when6. _____C________, she knows a lot of things.A. A child as is sheB. As she is a childC. Child as she isD. Child as is7. You are supposed to write your composition every _C_____ line.A. oneB. aC. otherD. another8. It was in this house ___B___ the important meeting in history was held.A. whereB. thatC. whichD. in which9. Mrs. Brown as well as her children __A____ to go Paris on holiday next week.A. is B.are C.will D. will be10. We’ll_D__ what our country expects of us.A. keep up withB. put up withC. stand up toD. live up to11. The rain was heavy and ___B____the land was flooded.A. consistentlyB. consequentlyC. constantlyD. continuously12. Another issue _C_____the new republic is the problem of the education of its citizens.A. confiningB. confirmingC. confrontingD. contributing13. Some people consider it unwise to __B____themselves in a quarrel between husband and wife.A. participateB. involveC. combineD. associate14. When ___A____, he denied _______ anything illegal.A. questioned, doingB. being questioned, doingC. questioning, doingD. questioning, having done15.____D_____from the European continent, England had been in close contact with the outside world.A. Because cutting offB. While to be cut offC. Although cut itself offD. Even if cut off16. The actors have to __C_____ before they appear in front of the audience.A. cover upB. paint upC. make upD. do up17. The proposal _C__we start doing the experiment two days earlier has been agreed upon by all.A. whichB.whatC. thatD. of which18. The young people are ___B____ of their responsibility toward society.A consistent B. conscious C. considerable D. creative19. The more ___D___ you feel in yourself, the more chances you will stand to win the game.A. significanceB. sympathyC. fortuneD. confidence20. The days when he was ___D__ his best is already a thing of the past.A in B. on C. with D. at二.Cloze(20 points)Robert Edwards was blinded in a traffic accident. He was also a little deaf _21_ old age. Last week, he was taking a walk near his home when a thunderstorm came. He hid _22_ the storm under a big tree and was struck by lightning. He was knocked _23_ the ground and woke up some 20 minutes _24_,lying face down in water below a tree. He went into the house and lay down in bed. A short time later,he awoke;his legs felt _25_ and he was trembling,but,when he opened his eyes,he could see the clock across the room fading in and out in front of him. When his wife entered,he _26_ her for the first time in nine years. Doctors _27_ that he had regained his sight and hearing obviously from the flash of lightning,but they were unable to explain that. The only _28_ explanation offered by one doctor was that _29_ Edwards lost his sight as a result of trauma in a terrible accident, perhaps the only way it could be restored was by _30_ trauma.B21. A. because B. because of C. as D. sinceA22.A. from B. away C. against D. contraryD23.A. at B. in C. to D. onC24.A. late B. soon C. later D. afterB25.A. dying B. dead C. die D. being diedA26.A. saw B. watched C. noticed D. examinedC27.A. say B. thought over C. made sure D. agreed toB28.A. possibly B. possible C. probably D. mainlyD29.A. although B. because of C. even though D. sinceC30.A. others B. other C. another D. one other三.Reading Comprehension(20points)Passage OneA young man who lived in London was in love with a beautiful girl. Soon she became his girl friend. The man was very poor while the girl was rich. The young man wanted to send her a present on her birthday. He wanted to buy something beautiful for her, but he had no idea how to do it, as he had very little money. The next morning he went to a shop. There were many fine things there: rings, gold watches, diamonds—but all these things were too expensive. There was one thing he could not take his eyes off. It was a beautiful vase. That would be a wonderful present for his girl friend. He had been looking at the vase for half an hour when the manager asked what had happened to him.The young man told him everything. The manager felt sorry for him and decided to help him.A brilliant idea struck him. The manager pointed to the corner of the shop. To his great surprise the young man saw a vase broken into many pieces. The manager said, “I can help you. I shall order my servant to pack it and take it to your girl friend. When he enters the room, he will drop it.”On the birthday of his girl friend, the young man was very excited. Everything happened as had been planned. The servant brought in the vase, and as he entered the room, he dropped it. There was horror on everybody’s face. When the vase was unpacked, the guests saw that each piece was packed separately.31. The story took place in __B____.A. FranceB. EnglandC. GermanyD. the United States32. Which of the following is true? AA. The young man’s family was poor while the girl’s was rich.B. A rich young man fell in deep love with a beautiful girl.C. The young man loved the girl but the girl did not love him.D. The young man had enough money to buy a beautiful vase for his girl friend.33.Why did the young man want to buy a present for the girl? CA. He wanted to give her a Christmas present.B. He fell in love with her.C. Her birthday was coming soon.D. They were going to get married.34. The shop manager was ___B___.A. very rich and kind – heartedB. sympathetic and cleverC. kind but did nothing for the young manD. curious about the young man’s problem35. Who do you think packed each piece separately? BA. The managerB. The servantC. The girlD. The young manPassage TwoNonverbal communication has to do with gestures, movements, and closeness of two people when they are talking. The scientists say that these gestures, movements, and so forth have the meaning our words do not carry.For example, the physical distance between two speakers can be important. North Americans often complain that South Americans are being “pushy” because they tend to stand close to the North American when speaking, whereas the South American often considers the North American to be “cold” or “distant” because he keeps a greater distance between himself and the person he is speaking to. In the Middle East it is considered flirtatious(调情) for a woman to allow a man to look at her in the eye. This “eye contact”provides another example of what we’re calling nonverbal communication. A social psychologist has observed that there is more eye contact between people who like each other than there is between people who don’t like each other. The length of time that the person whom you are speaking to looks at your eyes indicates the amount of interest he has in you rather than the amount of interest he has in the thing you are talking about.36. Nonverbal communication includes all forms listed below except __C______.A. gesturesB. body distanceC. talksD. eye contact37. While talking, the South Americans tend to ___B______.A. talk loudlyB. be close to each otherC. keep a certain distance between themD. push each other38. While they are talking, the North Americans tend to ____C____ .A. talk loudlyB. be close to each otherC. keep a certain distance between themD. be cold39. It would be considered ____D____ in the Middle East, if a woman allows a man to look at her in the eye.A. politeB. impoliteC. acceptableD. unacceptable40. More eye contacts may indicate all of the following except that __B______.A. people like each otherB. people are interested in the topicC. people are interested in each otherD. people want to keep talking四.Translate the following sentences into English.(15 points)41. 杰克才开始工作了三个月,经验尚不足,所以让他独立完成这项任务是有困难的。
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模拟试卷一一、单项选择题(每题只有一个正确答案,每题1分,共10分)1. The switch, circuit switches, have no capability of ______ user’s data on their way to the destination.A. calling, storedB. called, storingC. to call, to storeD. be called, be stored2. The switching element is a computer a message processor, with processing and storage capabilities. Message travels independently and asynchronously, their own way from source to destination.A. be referred to as; findingB. referred to as, findingC. be referred to as, to findD. referred to, finding3. The telephone contains a transmitter and receiver for_______ back and forth analog voice and analog electrical signals.A. convert, inB. converting, betweenC. conversion, toD. converted, into4. The trunks are designed multiple voice-frequency circuits either FDM or synchronous TDM.A. carry, useB. carried, usedC. to carry, to useD. to carry, using5. Designers have found it convenient these nodes into a hierarchy or tree topology, five classes of switching centers or nodes.A. organization, consistB. organize, consistingC. to organize, consisting ofD. organizing, to consist6. The term ISDN was first defined within the CCITT in 1972. Itreferred to a network end-to-end digital connectivity ________a range of services.A. providing, forB. provision, toC. provided, withD. provide, into7. In fact, ISDN conceived a quarter of a century agoand is only now to reach maturity.A. is, beginB. was, beginningC. be, to beginD. will be, began8. As regards economy, early studies suggested that digital services _______significant advantages since a substantial quantity of interface equipment in the telephone exchange could .A. offered, be eliminatedB. offer, eliminateC. offers, is eliminatedD. to offer, to eliminate9. The enhanced quality is achieved when a signal is digitally encoded degradation the transmission medium.A. overcome, toB. overcame, withC. overcoming, overD. to overcome, due to10. Similarly, the introduction of voice encoding techniques_______ pulse code modulation contributed the ISDN’s concept evolution.A. usage, onB. using, toC. use, withD. used, so as to二、英译汉短语(每题1分,共15分)1. the capability of storing or manipulating user’s data2. the information regarding the source and destination addresses3. the overall transmission delay of the message4. packet switching5. transmission unit6. low channel utilization7. the switching nodes called tandem switches8. architectural components9. full duplex10. multiple voice-frequency circuits11. isolated subnetworks12. two subscribers attached to different end offices13. degradation due to the transmission medium14. digital communication15.public communication carriers16. bandwidth limitations17.basic access signaling rate三、汉译英短语(每题1分,共15分)1、电路交换.2、双绞线3、存储转发方式4、交换技术5、信息转换6、公众电信网7、本地环路8、收费中心9、中间交换节点10、拓扑11、灵活性12、综合业务数字网13、接口设备14、语音编码15、基本接入四、阅读理解(每题2分,共20分),根据文章内容判断(√)(X)PASSAGE ONEBy far the largest circuit-switched network is the public telecommunications network—the telephone network. This is actually a collection of national networks interconnected to form an international service. Although originally designed and implemented to service analog telephone subscribers, it handles substantial data traffic via modem, and is gradually being converted to a digital network.The public telecommunication network, as with any communications network, can be described using four generic architectural components.·Stations: generally denoted as subscribers, these are the devices that attach to the network.·Interfaces:the interface between the stations and the network, referred to in the phone system as the local loop.·Nodes: the switching centers in the network.·Links: the branches between nodes, referred to as trunks.Most of the subscribers on the network are telephones. The telephone contains a transmitter and receiver for converting back and forth between analog voice and analog electrical signals. With the introduction of the digital data system, some subscribers that transmit digital signals have been incorporated into the network.The local loop is a pair of wires, generally twisted pair, That connects a subscriber to one of the nodes in the network. The local loop generally covers a distance of a few kilometers to a few tens of kilometers at most.1) The largest circuit-switched network is referred to as the public telecommunications network-the telephone network.( )2) The telephone network originally designed and implemented toserve a digital network. ( )3) We can describe the public telecommunications network with Stations, Nodes and Links. ( )4) The telephone only contains a receiver for converting back and forth between analog voice and anolog electrical signals. ( )5) The local loop is a pair of wires, generally twisted pair, that connects a subscriber to one of the nodes in the network . ( )6) The local loop generally covers a distance of a few meters to a few kilometers. ( )PASSAGE TWOThe term ISDN was first defined within the CCITT in 1972. It referred to a network providing end-to-end digital connectivity for a range of services. It also used the idea of a totally open network with universally available and standardized “ports”that can plug in everywhere. The concept has since then evolved from the existing telephone networks of countries undergoing changes due to the introduction of totally new digital technology in the switching and transmission equipment. Similarly, the introduction of voice encoding techniques using pulse code modulation contributed to the concept’s evolution. Initially, voice encoding was based upon a 64 kbit/s transmission rate. Today two 64 kbit/s, or 2B-channels coupled with a basic access signaling rate of 16 kbit/s, that is, the D-channel, constitute the essential ISDN transmission rate of 144 kbit/s. Currently PSTN, available in almost 200 countries and territories around the world, offers universal voice access to almost 750 million telephones around the world. ISDN is the network which will progressively provide a similar universal access for not only voice but data, facsimile, video, text, and other services as well.In the industrialized countries, the evolutionary nature of the ISDN concept has been a matter of economic practicality considering the vast telephone infrastructure already in place. The primary emphasis, however,has been the enhancement of the services rather than a single replacement of the services rather than a single replacement of existing equipment. This evolutionary approach has also merit for most of the developing countries, although in some instances where analog facilities do not exist presently or where they are very limited, the direct installation of digital facilities could allow a direct leapfrog to ISDN capabilities.Many planners believe that the transition form experimental ISDN technology to operational system will be convincingly made in the next few years. Certainly the 1990s will be the time of rapid operational growth. If true, a lot of issues will have to be resolved in coming months rather than in coming years . The current study period of the CCITT (1989~1992) will, of necessity, resolve virtually all standards issues on ISDN including even wideband ISDN for transmission rates up to 155 Mbit/s.ISDN is not a four-letter work. It is a blueprint to the electronic communications system of the future.7) The term ISDN was first defined with the CCITT in 1982. ( )8) ISDN referred to a network providing end-to-end digital connectivity for a range of services. ( )9) Today two 64 kbit/s, or 2 B-channels coupled with a basic access signaling rate of 16 kbit/s, that is ,the D-channel, constitute the essential ISDN transmission rate of 144 kbit/s (2B+D).( )10) ISDN is the network which will progressively provide a similar universal access for only voice, facsimile and video. ( )11) ISDN is a blueprint to the electronic communications system of the future. ( )12) The author thinks that a lot of issues on ISDN will have to be resolved in a few months. ( )五、英译汉短文(每题10分,共40分)1. Each subscriber connects via local loop to a switching center, known as an end office. Typically, an end office will support many thousands ofsubscribers in a localized area. There are over 19,000 end offices in the United States, so it is clearly impractical for each end office to have a direct link to each end other office. Rather, intermediate switching nodes are used.2. By far the largest circuit-switched network is the public telecommunications network—the telephone network. This is actually a collection of national networks interconnected to form an international service. Although originally designed and implemented to service analog telephone subscribers, it handles substantial data traffic via modem, and is gradually being converted to a digital network.3. The local loop is a pair of wires, generally twisted pair, that connects a subscriber to one of the nodes in the network. The local loop generally covers a distance of a few kilometers to a few tens kilometers at most.A two wire connection is inherently half-duplex; that is, it can carry voice in one direction at a time only. Similarly, it can carry digital signals in one direction at a time only. For full-duplex DDS connections, two twisted-pair links are generally used.4. In the industrialized countries, the evolutionary nature of the ISDN concept has been a matter of economic practicality considering the vast telephone infrastructure already in place. The primary emphasis, however, has been the enhancement of the services rather than a single replacement of the services rather than a single replacement of existing equipment. This evolutionary approach has also merit for most of the developing countries, although in some instances where analog facilities do not exist presently or where they are very limited, the direct installation of digital facilities could allow a direct leapfrog to ISDN capabilities.。