湖南师范大学附属中学2020-2021学年高一上学期期末考试英语试题含答案
湖南师范大学附属中学2020-2021学年高一上学期期末英语试题

湖南师范大学附属中学2020-2021学年高一上学期期末英语试题学校:___________姓名:___________班级:___________考号:___________一、阅读选择San Francisco Fire Engine ToursSan Francisco Winery TourRunning: February 1st through April 30thThis delicious tour goes through the city on its way to Treasure Island where we will stop at the famous Winery SF. Here you can enjoy 4 pours of some of the best wine San Francisco has to offer.(Included in tickets price)Departing from the Cannery: Tell time upon request.Duration(时长):2 hoursPrice: $90Back to the Fifties TourRunning: August 16th through August 31stThis tour transports you back in time to one of San Francisco’s most fantastic periods, the 1950s! Enjoy fun history as we take you through San Francisco for a free taste of ice cream.Departing from the Cannery 5:00 pm and 7:00 pmDuration:2 hoursPrice:$90Spooky Halloween TourRunning: October 10th through October 31stJoin us for a ride through the historical Presidio district .Authentic fire gear (服装)is provided for your warmth as our entertainers take you to some of the most thrilling parts of San FranciscoDeparting from the Cannery:6:30 pm and 8:30 pmDuration :1 hour and 30 minutesPrice: Available upon requestHoliday Lights TourRunning: December 6th through December 23ndThis tractive four takes you to some of San Francis’s most cheerful holiday scenes.Authentic fire gear is provided for your warmth as you get into the holiday spirit.Departing from the Cannery 7:00 pm and 9:00 pmDuration: 1 hour and 30 minutesAdvance reservations required.1.Which of the tours is available in March?A.Back to the Fifties Tour. B.San Francisco Winery Tour. C.Spooky Hallowen Tour. D.Holiday Lights Tour.2.What can tourists do on Back to the Fifties Tours?A.Go to Treasure Island B.Enjoy the holiday scenes.C.Have free ice cream. D.Visit the Presidio district.3.What are tourists required to do to go on Holiday Lights Tour?A.Take some drinks. B.Make reservations in advance.C.Set off early in the morning. D.Wear warm clothes.Fifteen years ago, I took a summer vacation in Lecce in southern Italy. After climbing up a hill for a panoramic(全景的) of the blue sea, white buildings and green olive trees, I paused to catch my breath and then positioned myself to take the best photo of this panorama.Unfortunately, just as I took out my camera, a woman approached from behind, and planted herself right in front of my view. Like me, this woman was here to stop, sigh and appreciate the view.Patient as I was, after about 15 minutes, my camera scanning the sun and reviewing the shot I would eventually take, I grew frustrated. Was it too much to ask her to move so I could take just one picture of the landscape? Sure, I could have asked her, but something prevented me from doing so. She seemed so content in her ob servation. I didn’t want to mess with that.Another 15 minutes passed and I grew bored. The woman was still there. I decided to take the photo anyway. And now when I look at it, I think her presence in the photo is what makes the image interesting. The landscape, beautiful on its own, somehow comes to life and breathes because this woman is engaging with it.This photo, with the unique beauty that unfolded before me and that woman who “ruined” it, now hangs on a wall in my bedroom. What would she think if she knew that her figure is captured and frozen on some stranger’s bedroom wall? A bedroom, after all, is a very private space, in which some woman I don’t even know has been immortalized. In some ways, shelives in my house.Perhaps we all live in each oth er’s spaces. Perhaps this is what photos are for: to remind us that we all appreciate beauty, that we all share a common desire for pleasure, for connection, for something that is greater than us.That photo is a reminder, a captured moment, an unspoken conversation between two women, separated only by a thin square of glass.4.What happened when the author was about to take a photo?A.Her camera stopped working. B.A woman blocked her view. C.Someone asked her to leave. D.A friend approached from behind. 5.In the author’s opinion, what makes the photo so alive?A.The rich color of the landscape. B.The perfect positioning of the camera. C.The woman’s existence in the photo.D.The soft sunlight that summer day. 6.The passage can be seen as the author’s reflect ions upon ________.A.a particular life experience B.the pleasure of travelingC.the art of photography D.a lost friendshipA meteorite(陨石)moved quickly across the sky and exploded(爆炸)over central Russia on Feb. 15, raining fireballs over a vast area and causing a shock wave that smashed windows, damaged buildings and injured 1,200 people.People heading to work in Chelyabinsk heard what sounded like an explosion, saw a bright light and then felt the shock wave, according to a Reuters journalist in the industrial city 1 , 500 km east of Moscow.The fireball, travelling at a speed of 30 km per second according to Russian Federal Space Agency (Roscosmos), had blazed(熊熊燃烧)across the horizon(地平线),leaving a long white trail that could be seen as far as 200 km away.Car alarms went off, thousands of windows were broken and mobile phone networks were interrupted for a short time. The Interior Ministry said the meteorite explosion, a very rare sight, also released a great explosive sound.“I was driving to work. It was quite dark, but it suddenly became bright as if it were day," said Viktor Prokofiev, 36, a resident(居民)of Yekaterinburg in the Ural Mountains. felt like I was blinded by headlights(车前灯).”The meteorite, which weighed about 10 tonnes and may have been made of iron, enteredEarth's atmosphere and broke apart 30 km—50 km above ground, according to Russia's Academy of Sciences.“The energy released((释放)when it entered the Earth's atmosphere was equal to a few kilo tonnes," the academy said, “the power of a small atomic weapon exploding. ”No deaths were reported but the Emergencies Ministry said 20, 000 rescue and clean-up workers were sent to Ural Region after President Vladimir Putin told Emergencies Minister Vladimir Puchkov to ease and help the victims.The Interior Ministry said about 1,200 people had been injured, at least 200 of them were children, and most from broken pieces of glass.7.What do we learn about the meteorite from the passage?A.It is a very huge ball made of iron.B.It quickly broke apart on the ground.C.It exploded over Russia's Ural Region.D.It's similar to an A-bomb in weight.8.The underlined word “smashed" in Paragraph 1 is closest in meaning to “_____”. A.broke B.meltedC.burned D.cleared9.We can know from the passage that _____.A.Moscow is 1,500 kilometers away from the east of ChelyabinskB.many houses were destroyed, with lots of people reported missingC.Viktor Prokofiev became blind after seeing the rare sightD.the shock wave briefly influenced mobile phone networks10.What can be the best title for the passage?A."Meteorite Rush” Begins in RussiaB.President Putin Orders AssistanceC.Meteorite Hits Russia, 1,200 People HurtD.Meteorite Flies Quickly Across Russia二、七选五I recently received an e-mail from a wise speaker. In his e-mail, he pointed out some obstacles that lie ahead on the way to success. 11.Laziness. Even with a right goal and the courage to pursue it, your efforts will be in vainunless you're willing to take actions. 12.Post your visions and plans in your bedroom, bathroom and office. Share them with others. In that case, everyone could be your supervisor. Make yourself responsible and become the master of your destiny.Doubt. 13.Life and work can be hard and even cruel. Remember, the race is not for the smartest but for those who don't give up. Rather than allowing doubt to stand in your path, you owe it to yourself to remain confident in your plan. 14.Dishonesty. As you begin to be successful, you'll tend to lie, exaggerate(夸大), and cheat in order to move your agenda forward. However, taking the easy way of dishonesty will make you become the person you hate. 15.True success comes when you are a person of your word, when you have a pure conscience(良心),and when you have not cheated others on your way to the top.A.Only the brave can overcome this first obstacle.B.His thoughts were so deep and insightful that I edited them.C.Write down your goals and the action steps you'll take to pursue those goals.D.In the end, it causes far more problems than taking the risk of telling the truth.E.Adjust it as needed along the way, but always know that success will ultimately be yours.F.Once you've made a decision, doubt is a worm that eats away at your ability to succeed.G.If you can't experience gratitude, you might as well have stayed exactly where you started.三、完形填空Dale Carnegie rose from the unknown of a Missouri farm to international fame because he found a way to fill a universal human need.It was a need that he first 16 back in 1906 when young Dale was a junior at State Teachers College in Warrensburg. To get an education, he was 17 against many difficulties. His family was poor. His Dad couldn't afford the 18 at college, so Dale had to ride horseback 12 miles to 19 classes. Study had to be done 20 his farm-work routines. He stopped taking part in many school activities because he didn't have the time or the 21 . He had only one good suit. He tried for the football team, 22 the coach turned him down for being too 23 . During this period Dale was slowly 24 an inferiority complex (自卑感),which his mother knew could 25 him from achieving his real potential. She suggested that Dale join the 26 team, believing that 27 in speaking could give him the confidence and recognition that he needed.Dale took his mother's advice, tried desperately and after several attempts 28 made it. This proved to be a 29 point in his life. Speaking before groups did help him gain the 30 he needed. And his hard work 31 . By the time Dale was a senior, he had won every top 32 in speech. Now other students were coming to him for coaching and later they, 33 , were winning contests.Out of this early struggle to 34 his feelings of inferiority, Dale came to understand that the ability to 35 an idea to an audience builds a person's confidence. And, with it, Dale knew he could do anything he wanted to do—and so could others.16.A.wanted B.recognized C.supplied D.filled 17.A.dealing B.succeeding C.struggling D.trying 18.A.board B.equipment C.teaching D.training 19.A.skip B.participate C.instruct D.attend 20.A.between B.during C.over D.through 21.A.idea B.interest C.clothes D.talent 22.A.so B.which C.but D.as 23.A.outstanding B.light C.optimistic D.easygoing 24.A.gaining B.achieving C.seeking D.developing 25.A.prevent B.protect C.save D.free 26.A.singing B.debating C.running D.horse-riding 27.A.presence B.potential C.patience D.practice 28.A.hopefully B.certainly C.finally D.naturally 29.A.key B.turning C.breaking D.basic 30.A.confidence B.experience C.ability D.progress 31.A.paid in B.paid up C.paid back D.paid off 32.A.race B.work C.praise D.honor 33.A.in return B.in brief C.in turn D.in charge 34.A.convey B.overcome C.understand D.build 35.A.express B.stress C.contribute D.reply四、用单词的适当形式完成短文阅读下面材料,在空白处填入适当的内容(1个单词)或括号内单词的正确形式。
湖南师范大学附属中学2019-2020学年高一上学期期末英语试题

湖南师大附中2019—2020学年度高一第一学期期期末考试英语试题第一部分听力(共两节,满分30分)做题时,先将答案标在试题卷上。
录音内容结束后,你将有两分钟的时间将试题卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7. 5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例:How much is the shirt?A. £ 19. 15.B. £ 9. 18.C. £ 9. 15.答案是C。
.1. What does the man want to do?A. To buy a new watch.B. To get his watch repaired. .C. To return the watch.2. What does Li Hua want to be?A. To be a physicist.B. To be a scientist.C. To be a writer.3. When will they go to Thailand?A. June.B. July.C. October.4. What does the woman like about the new job?A. It pays better.B. It has less work.C. It is more interesting.5. What does the man suggest the woman do?A. Take weight-loss pills.B. Watch advertisements on TV.C Exercise regularly.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
湖南省长沙市湖南师范大学附属中学2024-2025学年高三上学期月考(一)数学试题及答案

大联考湖南师大附中2025届高三月考试卷(一)数学命题人:高三数学备课组 审题人:高三数学备课组时量:120分钟 满分:150分一、选选选:本选共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的,1. 已知{}()260,{lg 10}Axx x B x x =+−≤=−<∣∣,则A B = ( )A. {}32xx −≤≤∣ B. {32}x x −≤<∣ C. {12}x x <≤∣D. {12}x x <<∣2. 若复数z 满足()1i 3i z +=−+(i 是虚数单位),则z 等于( )A.B.54C.D.3. 已知平面向量()()5,0,2,1ab ==−,则向量a b +在向量b上投影向量为( )A. ()6,3−B. ()4,2−C. ()2,1−D. ()5,04. 记n S 为等差数列{}n a 的前n 项和,若396714,63a a a a +==,则7S =( ) A. 21B. 19C. 12D. 425. 某校高二年级下学期期末考试数学试卷满分为150分,90分以上(含90分)为及格.阅卷结果显示,全年级1200名学生的数学成绩近似服从正态分布,试卷的难度系数(难度系数=平均分/满分)为0.49,标准差为22,则该次数学考试及格的人数约为( )附:若()2,X Nµσ∼,记()()p k P k X k µσµσ=−≤≤+,则()()0.750.547,10.683p p ≈≈.A 136人 B. 272人C. 328人D. 820人6. 已知()π5,0,,cos ,tan tan 426αβαβαβ∈−=⋅=,则αβ+=( ) A.π6 B.π4C.π3D.2π37. 已知12,F F 是双曲线22221(0)x y a b a b−=>>的左、右焦点,以2F 为圆心,a 为半径的圆与双曲线的一条的.渐近线交于,A B 两点,若123AB F F >,则双曲线的离心率的取值范围是( )A.B.C. (D. (8. 已知函数()220log 0x a x f x x x ⋅≤= > ,,,,若关于x 的方程()()0f f x =有且仅有两个实数根,则实数a 的取值范围是( ) A. ()0,1B. ()(),00,1−∞∪C. [)1,+∞D. ()()0,11,+∞二、多选题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分9. 如图,在正方体111ABCD A B C D −中,E F M N ,,,分别为棱111AA A D AB DC ,,,的中点,点P 是面1B C 的中心,则下列结论正确的是( )A. E F M P ,,,四点共面B. 平面PEF 被正方体截得的截面是等腰梯形C. //EF 平面PMND. 平面MEF ⊥平面PMN10. 已知函数()5π24f x x=+,则( )A. ()f x 的一个对称中心为3π,08B. ()f x 的图象向右平移3π8个单位长度后得到的是奇函数的图象 C. ()f x 在区间5π7π,88上单调递增 D. 若()y f x =在区间()0,m 上与1y =有且只有6个交点,则5π13π,24m∈11. 已知定义在R 上的偶函数()f x 和奇函数()g x 满足()()21f x g x ++−=,则( )A. ()f x 的图象关于点()2,1对称B. ()f x 是以8为周期的周期函数C. ()20240g =D.20241(42)2025k f k =−=∑ 三、填空题:本题共3小题,每小题5分,共15分.12. 6(31)x y +−的展开式中2x y 的系数为______.13. 已知函数()f x 是定义域为R 的奇函数,当0x >时,()()2f x f x ′−>,且()10f =,则不等式()0f x >的解集为__________.14. 已知点C 为扇形AOB 弧AB 上任意一点,且60AOB ∠=,若(),R OC OA OB λµλµ=+∈,则λµ+的取值范围是__________.四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15. ABC V 的内角,,A B C 的对边分别为,,a b c ,已知22cos a b c B +=. (1)求角C ;(2)若角C 的平分线CD 交AB于点,D AD DB =,求CD 的长.16. 已知1ex =为函数()ln af x x x =的极值点. (1)求a 的值; (2)设函数()ex kxg x =,若对()120,,x x ∀∈+∞∃∈R ,使得()()120f x g x −≥,求k 的取值范围. 17. 已知四棱锥P ABCD −中,平面PAB ⊥底面,ABCD AD∥,,,2,BC AB BC PA PB AB AB BC AD E ⊥==为AB 的中点,F 为棱PC 上异于,P C 的点.的(1)证明:BD EF ⊥;(2)试确定点F 的位置,使EF 与平面PCD18. 在平面直角坐标系xOy 中,抛物线21:2(0)C ypx p =>的焦点到准线的距离等于椭圆222:161C x y +=的短轴长,点P 在抛物线1C 上,圆222:(2)E x y r −+=(其中01r <<).(1)若1,2r Q =为圆E 上的动点,求线段PQ 长度的最小值; (2)设()1,D t 是抛物线1C 上位于第一象限的一点,过D 作圆E 的两条切线,分别交抛物线1C 于点,M N .证明:直线MN 经过定点.19. 龙泉游泳馆为给顾客更好的体验,推出了A 和B 两个套餐服务,顾客可选择A 和B 两个套餐之一,并在App 平台上推出了优惠券活动,下表是该游泳馆在App 平台10天销售优惠券情况. 日期t 12345678910销售量千张 1.9 1.98 2.2 2.36 2.43 2.59 2.68 2.76 2.7 04经计算可得:10101021111 2.2,118.73,38510i i i i i i i y y t y t ======∑∑∑ (1)因为优惠券购买火爆,App 平台在第10天时系统出现异常,导致当天顾客购买优惠券数量大幅减少,已知销售量y 和日期t 呈线性关系,现剔除第10天数据,求y 关于t 的经验回归方程结果中的数值用分数表示;(2)若购买优惠券的顾客选择A 套餐的概率为14,选择B 套餐的概率为34,并且A 套餐可以用一张优惠券,B 套餐可以用两张优惠券,记App 平台累计销售优惠券为n 张的概率为n P ,求n P ; (3)记(2)中所得概率n P 的值构成数列{}()N n P n ∗∈.①求n P 的最值;②数列收敛的定义:已知数列{}n a ,若对于任意给定的正数ε,总存在正整数0N ,使得当0n N >时,n a a ε−<,(a 是一个确定的实数),则称数列{}n a 收敛于a .根据数列收敛的定义证明数列{}n P 收敛...参考公式: ()()()1122211ˆˆ,n ni ii ii i n n i i i i x x y y x y nx yay bx x xx nx====−−−==−−−∑∑∑∑.大联考湖南师大附中2025届高三月考试卷(一)数学命题人:高三数学备课组 审题人:高三数学备课组时量:120分钟 满分:150分一、选选选:本选共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的,1. 已知{}()260,{lg 10}Axx x B x x =+−≤=−<∣∣,则A B = ( )A. {}32xx −≤≤∣ B. {32}x x −≤<∣ C. {12}x x <≤∣ D. {12}x x <<∣【答案】D 【解析】【分析】通过解一元二次不等式和对数函数的定义域,求出集合,A B ,再求交集. 【详解】集合{}()32,{lg 10}{12}A x x B x x x x =−≤≤=−<=<<∣∣∣,则{12}A B xx ∩=<<∣, 故选:D .2. 若复数z 满足()1i 3i z +=−+(i 是虚数单位),则z 等于( )A.B.54C.D.【答案】C 【解析】【分析】由复数的除法运算计算可得12i z =−+,再由模长公式即可得出结果. 【详解】依题意()1i 3i z +=−+可得()()()()3i 1i 3i 24i12i 1i 1i 1i 2z −+−−+−+====−+++−,所以z =. 故选:C3. 已知平面向量()()5,0,2,1a b ==−,则向量a b +在向量b上的投影向量为( )A. ()6,3−B. ()4,2−C. ()2,1−D. ()5,0【答案】A 【解析】【分析】根据投影向量的计算公式即可求解.【详解】()()7,1,15,a b a b b b +=−+⋅==所以向量a b +在向量b 上的投影向量为()()236,3||a b b b bb +⋅==− .故选:A4. 记n S 为等差数列{}n a 的前n 项和,若396714,63a a a a +==,则7S =( ) A. 21 B. 19C. 12D. 42【答案】A 【解析】【分析】根据等差数列的性质,即可求解公差和首项,进而由求和公式求解.【详解】{}n a 是等差数列,396214a a a ∴+==,即67a =,所以67769,a a a a == 故公差76162,53d a a a a d =−=∴=−=−,()767732212S ×∴=×−+×=, 故选:A5. 某校高二年级下学期期末考试数学试卷满分为150分,90分以上(含90分)为及格.阅卷结果显示,全年级1200名学生的数学成绩近似服从正态分布,试卷的难度系数(难度系数=平均分/满分)为0.49,标准差为22,则该次数学考试及格的人数约为( )附:若()2,X Nµσ∼,记()()p k P k X k µσµσ=−≤≤+,则()()0.750.547,10.683p p ≈≈.A. 136人B. 272人C. 328人D. 820人【答案】B 【解析】【分析】首先求出平均数,即可得到学生的数学成绩2~(73.5,22)X N ,再根据所给条件求出(5790)P X ≤≤,即可求出(90)P X ≥,即可估计人数.【详解】由题得0.4915073.5,22µσ=×==,()()(),0.750.547p k P k X k p µσµσ=−≤≤+≈ ,()5790P X ∴≤≤ ()0.750.547p ≈,()()900.510.5470.2265P X ≥×−,∴该校及格人数为0.22651200272×≈(人),故选:B . 6. 已知()π5,0,,cos ,tan tan 426αβαβαβ∈−=⋅=,则αβ+=( ) A.π6 B.π4C.π3D.2π3【答案】D 【解析】【分析】利用两角差的余弦定理和同角三角函数的基本关系建立等式求解,再由两角和的余弦公式求解即可.【详解】由已知可得5cos cos sin sin 6sin sin 4cos cos αβαβαβαβ⋅+⋅=⋅ =⋅ , 解得1cos cos 62sin sin 3αβαβ⋅=⋅=,,()1cos cos cos sin sin 2αβαβαβ∴+=⋅−⋅=−,π,0,2αβ∈,()0,παβ∴+∈, 2π,3αβ∴+=,故选:D .7. 已知12,F F 是双曲线22221(0)x y a b a b−=>>的左、右焦点,以2F 为圆心,a 为半径的圆与双曲线的一条渐近线交于,A B 两点,若123AB F F >,则双曲线的离心率的取值范围是( )A.B.C. (D. (【答案】B 【解析】【分析】根据双曲线以及圆的方程可求得弦长AB =,再根据不等式123AB F F >整理可得2259c a <,即可求得双曲线的离心率的取值范围.【详解】设以()2,0F c 为圆心,a 为半径的圆与双曲线的一条渐近线0bx ay −=交于,A B 两点, 则2F 到渐近线0bx ay −=的距离d b,所以AB =, 因为123AB F F >,所以32c ×>,可得2222299a b c a b −>=+, 即22224555a b c a >=−,可得2259c a <,所以2295c a <,所以e <,又1e >,所以双曲线的离心率的取值范围是 .故选:B8. 已知函数()220log 0x a x f x x x ⋅≤= > ,,,,若关于x 的方程()()0f f x =有且仅有两个实数根,则实数a 的取值范围是( ) A. ()0,1 B. ()(),00,1−∞∪C. [)1,+∞D. ()()0,11,+∞【答案】C 【解析】【分析】利用换元法设()u f x =,则方程等价为()0f u =,根据指数函数和对数函数图象和性质求出1u =,利用数形结合进行求解即可. 【详解】令()u f x =,则()0f u =.�当0a =时,若()0,0u f u ≤=;若0u >,由()2log 0f u u==,得1u =. 所以由()()0ff x =可得()0f x ≤或()1f x =.如图所示,满足()0f x ≤的x 有无数个,方程()1f x =只有一个解,不满足题意;�当0a ≠时,若0≤u ,则()20uf u a =⋅≠;若0u >,由()2log 0f u u==,得1u =. 所以由()()0ff x =可得()1f x =,当0x >时,由()2log 1f x x==,可得2x =, 因为关于x 的方程()()0f f x =有且仅有两个实数根,则方程()1f x =在(,0∞−]上有且仅有一个实数根,若0a >且()(]0,20,xx f x a a ≤=⋅∈,故1a ≥; 若0a <且()0,20xx f x a ≤=⋅<,不满足题意.综上所述,实数a 的取值范围是[)1,+∞, 故选:C .二、多选题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分9. 如图,在正方体111ABCD A B C D −中,E F M N ,,,分别为棱111AA A D AB DC ,,,的中点,点P 是面1B C 的中心,则下列结论正确的是( )A. E F M P ,,,四点共面B. 平面PEF 被正方体截得的截面是等腰梯形C. //EF 平面PMND. 平面MEF ⊥平面PMN【答案】BD 【解析】【分析】可得过,,E F M 三点的平面为一个正六边形,判断A ;分别连接,E F 和1,B C ,截面1C BEF 是等腰梯形,判断B ;分别取11,BB CC 的中点,G Q ,易证EF 显然不平行平面QGMN ,可判断C ;EM ⊥平面PMN ,可判断D.【详解】对于A :如图经过,,E F M 三点的平面为一个正六边形EFMHQK ,点P 在平面外,,,,E F M P ∴四点不共面,∴选项A 错误;对于B :分别连接,E F 和1,B C ,则平面PEF 即平面1C BEF ,截面1C BEF 是等腰梯形,∴选项B 正确;对于C :分别取11,BB CC 的中点,G Q ,则平面PMN 即为平面QGMN , 由正六边形EFMHQK ,可知HQ EF ,所以MQ 不平行于EF ,又,EF MQ ⊂平面EFMHQK ,所以EF MQ W = ,所以EF I 平面QGMN W =, 所以EF 不平行于平面PMN ,故选项C 错误;对于D :因为,AEM BMG 是等腰三角形,45AME BMG ∴∠=∠=°, 90EMG ∴∠=°,EMMG ∴⊥,,M N 是,AB CD 的中点,易证MN AD ∥,由正方体可得AD ⊥平面11ABB A ,MN ∴⊥平面11ABB A ,又ME ⊂平面11ABB A ,EM MN ∴⊥,,MG MN ⊂ 平面PMN ,EM ∴⊥平面GMN ,EM ⊂ 平面MEF ,∴平面MEF ⊥平面,PMN 故选项D 正确.���BD .10. 已知函数()5π24f x x=+,则( )A. ()f x 的一个对称中心为3π,08B. ()f x 的图象向右平移3π8个单位长度后得到的是奇函数的图象 C. ()f x 在区间5π7π,88上单调递增 D. 若()y f x =在区间()0,m 上与1y =有且只有6个交点,则5π13π,24m∈【答案】BD 【解析】【分析】代入即可验证A ,根据平移可得函数图象,即可由正弦型函数的奇偶性求解B ,利用整体法即可判断C ,由5πcos 24x+求解所以根,即可求解D.【详解】对于A ,由35π3π2π0848f =+×=≠,故A 错误;对于B ,()f x 的图象向右平移3π8个单位长度后得: 3π3π5ππ228842y f x x x x=−−++,为奇函数,故B 正确; 对于C ,当5π7π,88x∈时,则5π5π2,3π42x +∈ ,由余弦函数单调性知,()f x 在区间5π7π,88 上单调递减,故C 错误;对于D ,由()1f x =,得5πcos 24x+ππ4x k =+或ππ,2k k +∈Z , ()y f x =在区间()0,m 上与1y =有且只有6个交点,其横坐标从小到大依次为:ππ5π3π9π5π,,,,,424242, 而第7个交点的横坐标为13π4, 5π13π24m ∴<≤,故D 正确. 故选:BD11. 已知定义在R 上的偶函数()f x 和奇函数()g x 满足()()21f x g x ++−=,则( )A. ()f x 的图象关于点()2,1对称B. ()f x 是以8为周期的周期函数C. ()20240g =D.20241(42)2025k f k =−=∑ 【答案】ABC 【解析】【分析】根据函数奇偶性以及所满足的表达式构造方程组可得()()222f x f x ++−=,即可判断A 正确;利用对称中心表达式进行化简计算可得B 正确,可判断()g x 也是以8为周期的周期函数,即C 正确;根据周期性以及()()42f x f x ++=计算可得20241(42)2024k f k =−=∑,可得D 错误. 【详解】由题意()()()(),f x f x g x g x −=−=−,且()()()00,21g f x g x =++−=, 即()()21f x g x +−=①, 用x −替换()()21f x g x ++−=中的x ,得()()21f x g x −+=②, 由①+②得()()222f x f x ++−=, 所以()f x 的图象关于点(2,1)对称,且()21f =,故A 正确;由()()222f x f x ++−=,可得()()()()()42,422f x f x f x f x f x ++−=+=−−=−, 所以()()()()82422f x f x f x f x +=−+=−−= , 所以()f x 是以8为周期的周期函数,故B 正确; 由①知()()21g x f x =+−,则()()()()882121g x f x f x g x +=++−=+−=,故()()8g x g x +=,因此()g x 也是以8为周期的周期函数, 所以()()202400g g ==,C 正确;又因为()()42f x f x ++−=,所以()()42f x f x ++=, 令2x =,则有()()262f f +=,令10x =,则有()()10142,f f +=…, 令8090x =,则有()()809080942f f +=, 所以1012(2)(6)(10)(14)(8090)(8094)2222024f f f f f f ++++++=+++=个所以20241(42)(2)(6)(10)(14)(8090)(8094)2024k f k f f f f f f =−=++++++=∑ ,故D 错误.故选:ABC【点睛】方法点睛:求解函数奇偶性、对称性、周期性等函数性质综合问题时,经常利用其中两个性质推得第三个性质特征,再进行相关计算.三、填空题:本题共3小题,每小题5分,共15分.12. 6(31)x y +−的展开式中2x y 的系数为______. 【答案】180− 【解析】【分析】根据题意,由条件可得展开式中2x y 的系数为213643C C (1)⋅−,化简即可得到结果. 【详解】在6(31)x y +−的展开式中, 由()2213264C C 3(1)180x y x y ⋅⋅−=−,得2x y 的系数为180−. 故答案为:180−.13. 已知函数()f x 是定义域为R 的奇函数,当0x >时,()()2f x f x ′−>,且()10f =,则不等式()0f x >的解集为__________.【答案】()()1,01,−∪+∞ 【解析】【分析】根据函数奇偶性并求导可得()()f x f x ′′−=,因此可得()()2f x f x ′>,可构造函数()()2xf x h x =e并求得其单调性即可得()f x 在()1,+∞上大于零,在()0,1上小于零,即可得出结论. 【详解】因为()f x 为奇函数,定义域为R ,所以()()f x f x −=−,两边同时求导可得()()f x f x ′′−−=−,即()()f x f x ′′−=且()00f =,又因为当0x >时,()()2f x f x ′−>,所以()()2f x f x ′>. 构造函数()()2xf x h x =e,则()()()22x f x f x h x ′−′=e , 所以当0x >时,()()0,h x h x ′>在()0,∞+上单调递增,又因为()10f =,所以()()10,h h x =在()1,+∞上大于零,在()0,1上小于零, 又因为2e 0x >,所以()f x 在()1,+∞上大于零,在()0,1上小于零, 因为()f x 为奇函数,所以()f x 在(),1∞−−上小于零,在()1,0−上大于零, 综上所述,()0f x >的解集为()()1,01,−∪+∞. 故答案为:()()1,01,−∪+∞14. 已知点C 为扇形AOB 的弧AB 上任意一点,且60AOB ∠=,若(),R OC OA OB λµλµ=+∈,则λµ+的取值范围是__________.【答案】【解析】【分析】建系设点的坐标,再结合向量关系表示λµ+,最后应用三角恒等变换及三角函数值域求范围即可. 【详解】方法一:设圆O 的半径为1,由已知可设OB 为x 轴的正半轴,O 为坐标原点,过O 点作x 轴垂线为y 轴建立直角坐标系,其中()()1,1,0,cos ,sin 2A B C θθ ,其中π,0,3BOC θθ ∠=∈ , 由(),R OC OA OB λµλµ=+∈,即()()1cos ,sin 1,02θθλµ =+,整理得1cos sin 2λµθθ+=,解得cos λµθ=,则ππcos cos ,0,33λµθθθθθ+=++=+∈,ππ2ππ,,sin 3333θθ+∈+∈所以λµ +∈ . 方法二:设k λµ+=,如图,当C 位于点A 或点B 时,,,A B C 三点共线,所以1k λµ=+=; 当点C 运动到AB的中点时,k λµ=+,所以λµ +∈故答案为:四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15. ABC V 的内角,,A B C 的对边分别为,,a b c ,已知22cos a b c B +=. (1)求角C ;(2)若角C 的平分线CD 交AB于点,D AD DB =,求CD 的长.【答案】(1)2π3C = (2)3CD = 【解析】【分析】(1)利用正弦定理及两角和的正弦定理整理得到()2cos 1sin 0C B +=,再利用三角形的内角及正弦函数的性质即可求解;(2)利用正弦定理得出3b a =,再由余弦定理求出4a =,12b =,再根据三角形的面积建立等式求解. 【小问1详解】 由22cos a b c B +=,根据正弦定理可得2sin sin 2sin cos A B C B +=,则()2sin sin 2sin cos B C B C B ++=,所以2sin cos 2cos sin sin 2sin cos B C B C B C B ++=,整理得()2cos 1sin 0C B +=, 因为,B C 均为三角形内角,所以(),0,π,sin 0B C B ∈≠, 因此1cos 2C =−,所以2π3C =. 【小问2详解】因为CD 是角C的平分线,AD DB=所以在ACD 和BCD △中,由正弦定理可得,,ππsin sin sin sin 33AD CD BD CDA B ==, 因此sin 3sin BADA BD==,即sin 3sin B A =,所以3b a =, 又由余弦定理可得2222cos c a b ab C =+−,即222293a a a =++, 解得4a =,所以12b =.又ABCACD BCD S S S =+△△△,即111sin sin sin 222ab ACB b CD ACD a CD BCD ∠∠∠=⋅⋅+⋅⋅, 即4816CD =,所以3CD =. 16. 已知1ex =为函数()ln af x x x =的极值点. (1)求a 的值; (2)设函数()ex kxg x =,若对()120,,x x ∀∈+∞∃∈R ,使得()()120f x g x −≥,求k 的取值范围. 【答案】(1)1a = (2)(]()10,−∞−+∞ , 【解析】【分析】(1)直接根据极值点求出a 的值;(2)先由(1)求出()f x 的最小值,由题意可得是求()g x 的最小值,小于等于()f x 的最小值,对()g x 求导,判断由最小值时的k 的范围,再求出最小值与()f x 最小值的关系式,进而求出k 的范围. 【小问1详解】()()111ln ln 1a a f x ax x x x a x xα−−==′+⋅+,由1111ln 10e e e a f a −=+=′,得1a =, 当1a =时,()ln 1f x x =′+,函数()f x 在10,e上单调递减,在1,e∞ +上单调递增, 所以1ex =为函数()ln af x x x =的极小值点, 所以1a =. 【小问2详解】由(1)知min 11()e ef x f ==−. 函数()g x 的导函数()()1e xg x k x −=−′ �若0k >,对()1210,,x x k ∞∀∈+∃=−,使得()()12111e 1e k g x g f x k=−=−<−<−≤,即()()120f x g x −≥,符合题意. �若()0,0kg x =,取11ex =,对2x ∀∈R ,有()()120f x g x −<,不符合题意.�若0k <,当1x <时,()()0,g x g x ′<在(),1∞−上单调递减;当1x >时,()()0,g x g x ′>在(1,+∞)上单调递增,所以()min ()1ekg x g ==, 若对()120,,x x ∞∀∈+∃∈R ,使得()()120f x g x −≥,只需min min ()()g x f x ≤, 即1e ek ≤−,解得1k ≤−. 综上所述,k 的取值范围为(](),10,∞∞−−∪+.17. 已知四棱锥P ABCD −中,平面PAB ⊥底面,ABCD AD ∥,,,2,BC AB BC PA PB AB AB BC AD E ⊥==为AB 的中点,F 为棱PC 上异于,P C 的点.(1)证明:BD EF ⊥;(2)试确定点F 的位置,使EF 与平面PCD【答案】(1)证明见解析 (2)F 位于棱PC 靠近P 的三等分点 【解析】【分析】(1)连接,,PE EC EC 交BD 于点G ,利用面面垂直的性质定理和三角形全等,即可得证; (2)取DC 的中点H ,以E 为坐标原点,分别以,,EB EH EP 所在直线为,,x y z 轴建立,利用线面角公式代入即可求解.小问1详解】如图,连接,,PE EC EC 交BD 于点G .因为E 为AB 的中点,PA PB =,所以PE AB ⊥.因为平面PAB ⊥平面ABCD ,平面PAB ∩平面,ABCD AB PE =⊂平面PAB , 所以PE ⊥平面ABCD ,因为BD ⊂平面ABCD ,所以PE BD ⊥.因为ABD BCE ≅ ,所以CEB BDA ∠∠=,所以90CEB ABD ∠∠+= , 所以BD EC ⊥,因为,,PE EC E PE EC ∩=⊂平面PEC , 所以BD ⊥平面PEC .因为EF ⊂平面PEC ,所以BD EF ⊥. 【小问2详解】如图,取DC 的中点H ,以E 为坐标原点,分别以,,EB EH EP 所在直线为,,x y z 轴建立空间直角坐标系,【设2AB =,则2,1,BC AD PA PB ====则()()()()0,0,1,1,2,0,1,1,0,0,0,0P C D E −,设(),,,(01)F x y z PF PC λλ=<<, 所以()(),,11,2,1x y z λ−=−,所以,2,1x y z λλλ===−,即(),2,1F λλλ−.则()()()2,1,0,1,2,1,,2,1DC PC EF λλλ==−=−,设平面PCD 的法向量为(),,m a b c =,则00DC m PC m ⋅=⋅=,,即2020a b a b c += +−= ,,取()1,2,3m =−− , 设EF 与平面PCD 所成的角为θ,由cos θ=sin θ=.所以sin cos ,m EF m EF m EF θ⋅===整理得2620λλ−=,因为01λ<<,所以13λ=,即13PF PC = ,故当F 位于棱PC 靠近P 的三等分点时,EF 与平面PCD18. 在平面直角坐标系xOy 中,抛物线21:2(0)C ypx p =>的焦点到准线的距离等于椭圆222:161C x y +=的短轴长,点P 在抛物线1C 上,圆222:(2)E x y r −+=(其中01r <<).(1)若1,2r Q =为圆E 上的动点,求线段PQ 长度的最小值;(2)设()1,D t 是抛物线1C 上位于第一象限的一点,过D 作圆E 的两条切线,分别交抛物线1C 于点,M N .证明:直线MN 经过定点.【答案】(1(2)证明见解析【解析】【分析】(1)根据椭圆的短轴可得抛物线方程2y x =,进而根据两点斜率公式,结合三角形的三边关系,即可由二次函数的性质求解,(2)根据两点坐标可得直线,MN DM 的直线方程,由直线与圆相切可得,a b 是方程()()()2222124240r x r x r −+−+−=的两个解,即可利用韦达定理代入化简求解定点. 【小问1详解】 由题意得椭圆的方程:221116y x +=,所以短半轴14b = 所以112242p b ==×=,所以抛物线1C 的方程是2y x =. 设点()2,P t t ,则111222PQ PE ≥−=−=≥, 所以当232ι=时,线段PQ . 【小问2详解】()1,D t 是抛物线1C 上位于第一象限的点,21t ∴=,且()0,1,1t D >∴设()()22,,,M a a N b b ,则: 直线()222:b a MN y a x a b a −−=−−,即()21y a x a a b −=−+,即()0x a b y ab −++=. 直线()21:111a DM y x a −−=−−,即()10x a y a −++=. 由直线DMr =,即()()()2222124240r a r a r −+−+−=..同理,由直线DN 与圆相切得()()()2222124240r b r b r −+−+−=. 所以,a b 是方程()()()2222124240r x r x r −+−+−=的两个解, 22224224,11r r a b ab r r −−∴+==−− 代入方程()0x a b y ab −++=得()()222440x y r x y +++−−−=, 220,440,x y x y ++= ∴ ++= 解得0,1.x y = =− ∴直线MN 恒过定点()0,1−.【点睛】圆锥曲线中定点问题的两种解法(1)引进参数法:先引进动点的坐标或动线中系数为参数表示变化量,再研究变化的量与参数何时没有关系,找到定点.(2)特殊到一般法:先根据动点或动线的特殊情况探索出定点,再证明该定点与变量无关.技巧:若直线方程为()00y y k x x −=−,则直线过定点()00,x y ;若直线方程为y kx b =+ (b 为定值),则直线过定点()0,.b 19. 龙泉游泳馆为给顾客更好的体验,推出了A 和B 两个套餐服务,顾客可选择A 和B 两个套餐之一,并在App 平台上推出了优惠券活动,下表是该游泳馆在App 平台10天销售优惠券情况. 日期t 1 2 3 4 5 6 7 8 9 10 销售量千张 1.9 1.98 2.2 2.36 2.43 259 2.68 2.76 2.7 0.4经计算可得:10101021111 2.2,118.73,38510i i i i i i i y y t y t ======∑∑∑. (1)因为优惠券购买火爆,App 平台在第10天时系统出现异常,导致当天顾客购买优惠券数量大幅减少,已知销售量y 和日期t 呈线性关系,现剔除第10天数据,求y 关于t 的经验回归方程结果中的数值用分数表示;..(2)若购买优惠券的顾客选择A 套餐的概率为14,选择B 套餐的概率为34,并且A 套餐可以用一张优惠券,B 套餐可以用两张优惠券,记App 平台累计销售优惠券为n 张的概率为n P ,求n P ;(3)记(2)中所得概率n P 的值构成数列{}()Nn P n ∗∈. ①求n P 的最值;②数列收敛的定义:已知数列{}n a ,若对于任意给定的正数ε,总存在正整数0N ,使得当0n N >时,n a a ε−<,(a 是一个确定的实数),则称数列{}n a 收敛于a .根据数列收敛的定义证明数列{}n P 收敛.参考公式: ()()()1122211ˆˆ,n ni ii i i i n n ii i i x x y y x y nx y ay bx x x x nx ====−−−==−−−∑∑∑∑. 【答案】(1)673220710001200y t + (2)433774n n P =+⋅−(3)①最大值为1316,最小值为14;②证明见解析 【解析】 【分析】(1)计算出新数据的相关数值,代入公式求出 ,ab 的值,进而得到y 关于t 的回归方程; (2)由题意可知1213,(3)44n n n P P P n −−=+≥,其中12113,416P P ==,构造等比数列,再利用等比数列的通项公式求解;(3)①分n 为偶数和n 为奇数两种情况讨论,结合指数函数的单调性求解;②利用数列收敛的定义,准确推理、运算,即可得证. 【小问1详解】 解:剔除第10天的数据,可得2.2100.4 2.49y ×−==新, 12345678959t ++++++++=新, 则9922111119.73100.4114,73,38510285i i i i t y t = =−×==−= ∑∑新新,所以912922119114,7395 2.4673ˆ2859560009i i i i t y t y b t t == − −×× ==−× − ∑∑新新新新新, 可得6732207ˆ 2.4560001200a =−×=,所以6732207ˆ60001200y t +. 【小问2详解】 解:由题意知1213,(3)44n n n P P P n −−=+≥,其中12111313,444416P P ==×+=, 所以11233,(3)44n n n n P P P P n −−−+=+≥,又由2131331141644P P ++×, 所以134n n P P − +是首项为1的常数列,所以131,(2)4n n P P n −+=≥ 所以1434(),(2)747n n P P n −−=−−≥,又因为1414974728P −=−=−, 所以数列47n P − 是首项为928−,公比为34−的等比数列, 故1493()7284n n P −−=−−,所以1934433()()2847774n n n P −=−−+=+−. 【小问3详解】 解:①当n 为偶数时,19344334()()28477747n n n P −=−−+=+⋅>单调递减, 最大值为21316P =; 当n 为奇数时,19344334()()28477747n n n P −=−−+=−⋅<单调递增,最小值为114P =, 综上可得,数列{}n P 的最大值为1316,最小值为14. ②证明:对任意0ε>总存在正整数0347[log ()]13N ε=+,其中 []x 表示取整函数, 当 347[log ()]13n ε>+时,347log ()34333333()()()7747474n n n P εε−=⋅−=⋅<⋅=, 所以数列{}n P 收敛.【点睛】知识方法点拨:与新定义有关的问题的求解策略:1、通过给出一个新的定义,或约定一种新的运算,或给出几个新模型来创设新问题的情景,要求在阅读理解的基础上,依据题目提供的信息,联系所学的知识和方法,实心信息的迁移,达到灵活解题的目的;2、遇到新定义问题,应耐心读题,分析新定义的特点,弄清新定义的性质,按新定义的要求,“照章办事”,逐条分析、运算、验证,使得问题得以解决.方法点拨:与数列有关的问题的求解策略:3、若新定义与数列有关,可得利用数列的递推关系式,结合数列的相关知识进行求解,多通过构造的分法转化为等差、等比数列问题求解,求解过程灵活运用数列的性质,准确应用相关的数列知识.。
湖南省湖南师范大学附属中学2023-2024学年高一上学期期中考试英语试题

湖南师大附中2023—2024学年度高一第一学期期中考试英语时量:120分钟满分:150分第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
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例:How much is the shirt?A.£19.15B.£9.18C.£9.15答案是C。
1.What will the woman do tomorrow?A.Enjoy flowers.B.Watch birds.C.Buy a camera.2.What are the speakers mainly talking about?A.Moving house.B.Working overtime.C.Doing some cleaning.3.Who is Lucy?A.The woman’s boss.B.The woman’s daughter.C.The woman’s coworker. 4.Where is the conversation probably taking place?A.In a hospital.B.In a restaurant.C.In an office.5.What does the woman mean?A.She wants to keep the window open.B.The man should wear thick clothes.C.The room needs cleaning.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。
2020-2021学年湖南师范大学附属中学高一上学期期末考试英语试题

湖南师范大学附属中学2020-2021学年高一上学期期末考试英语试题一、阅读选择The COVID-19 pandemic led to a great number of rescheduling release dates (.上映日期).Despite how the reality of the calendar develops, these arc some films we're crossing our fingers that well get to see this next year.Malcolm & MarieRelease date: February 5Director: Sam LevinsonA director and his girlfriend's relationship is tested after they return home from his movie premiere (首映)and await critics* responses, he romantic drama is directed by Sam Levinson.Shang-Chi and the Legend of the Ten RingsRelease date: July 9Director: Destin Daniel CrettonIt's about time for the Marvel Cinematic Universe (漫威电影宇宙)to have its first Asian superhero on the silver screen. And there are few better heroes to pick than Shang-Chi, the Master of Kung Fu, who has the knowledge of nearly every martial art. This upcoming film will feature a 98% Asian cast.West Side StoryRelease date: December 10Director: Steven SpielbergSteven Spielberg's new adaptation of the famous Broadway musical of the same name, which itself was based on Shakespeare's Romeo and Juliet, is finally seeing the light of day in late 2021.The Matrix 4Release date: December 22Director: Lana WachowskiLana Wachowski is set to bring us another sci-fi action-adventure set in the digital world she helped create way back in 1999.1.What type of film is Malcolm & Marie?A. Comedy.B. Fantasy.C. Romance.D. Sci-fi.2.What do we know about Shang-Chi and the Legend of the Ten Rings?A.It is Marvel Studio's upcoming superhero film.B.It stars Destin Daniel Cretton.C.Its hero knows everything about martial art.D.It is a film with an all-Asian cast.3. Which of the following film is adapted from a musical?A.Malcolm & Marie.B.Shang-Chi and the Legend of the Ten Rings.C.West Side Story.D.The Matrix 4.【答案】C1.AC【分析】23.考查动词词义辨析。
湖南师范大学附属中学2020-2021学年高一上学期第一次大练习数学试题 含答案

19.(本题满分 12 分)
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湖南省2020-2021学年上学期高一英语期末试卷精选汇编:完形填空专题

完形填空专题湖南省永州市2020-2021学年高一上学期期末考试英语试题第一节完形填空(共15小题;每小题1分,满分15分)阅读下面短文,从短文后各题所给的A、B、C和D四个选项中,选出可以填入空白处的最佳选项。
When I was a boy, I played the piano six hours a day. I love the instrument. My mother____21____ me to read notes, and my father showed me how to control the ___22___. At first I played on clunky (沉闷的) Chinese keyboards ___23___, but the best we could afford. Later my parents bought me a Swedish piano, but I broke half the keys on it playing Tchaikovsky.To be a serious ___24___, I would have to move to Beijing where millions of pianists in China were competing for fame. To remove to Beijing with me, my father ___25___ a great sacrifice. He quit his concertmaster’s (首席小提琴手) job and my mother still stayed in Shenyang to keep working to ___26___ us. Before we ___27___Beijing, they both warned me, “Being a pianist is hard. Can you live without your mother?” I said, “I want my ___28___!” But I knew I needed to be in Beijing.Suddenly my father and I were newcomers—outsiders. The only apartment we could afford was in an unheated building, with five families ___29___ one bathroom. My father became an house-wife mostly.I was miserable, but not from the poverty or ___30___. My new teacher in Beijing didn’t like me. “You have no ___31___, ” she often told me. “You will never be a pianist.” And one day, she ___32___ me.I was just nine years old then and I didn’t want to be a pianist anymore, I wanted to go home to my mother. For the next two weeks I didn’t touch the piano. ___33___, my father didn’t push. H e just ___34___. That day I told my father what he waited to hear—that I wanted to study with a new teacher. ___35___ that time on, everything turned around.21. A. allowed B. asked C. taught D. forced22. A. sounds B. voices C. strings D. keys23. A. safe B. cheap C. fine D. convenient24. A. scientist B. genius C. musician D. doctor25. A. created B. produced C. got D. made26. A. support B. understand C. provide D. supply27. A. left for B. turned to C. got in D. stayed in28. A. mother B. father C. hometown D. friends29. A. cleaning B. living C. keeping D. sharing30. A. pleasure B. pressure C. success D. leisure31. A. talent B. patience C. money D. confidence32. A. prevented B. stopped C. fired D. punished33. A. Unfortunately B. Hopefully C. Sadly D. Wisely34. A. cried B. waited C. smiled D. shouted35. A. Until B. From C. Since D. After【答案】21. C 22. D 23. B 24. C 25. D 26. A 27. A 28. A 29. D 30. B 31. A 32. C 33. D 34. B 35. B【解析】【分析】这是一篇记叙文。
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湖南师大附中2020—2021学年度高一第一学期期末考试英语时量:120分钟满分:150分第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例:How much is the shirt?A. £19.15.B. £9.18.C. £9.15.答案是C。
1. What's the probable relationship between the speakers?A. Good friends.B. Fellow workers.C. Salesman and customer.2. Why did the woman catch a cold according to the man?A. She wore too little clothing.B. She had a cold bath.C. She slept in a cold room.3. When did the man move to London?A. In his twenties.B. In his thirties.C. In his forties.4 Whose computer does the man think is the best?A. The woman’s.B. Peter’s.C. Tom’s.5. How often does the restaurant offer its dinner specials?A. Twice a day.B. Twice a week.C. Twice a month.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6、7题。
6. What kind of room does the man want?A. A single room.B. A double room.C. Two single rooms.7. How long will the man stay?A. For three nights.B. For two nights.C. For one night. 听第7段材料,回答第8、9题。
8. What are the speakers mainly talking about?A. An earthquake.B. A storm.C. A tree.9. What happened before the man fell asleep?A. He heard noises of birds.B. He felt a shake of the house.C. He saw a tree fall down.听第8段材料,回答第10至12题。
10. How does the man find the woman's room?A. Dark.B. Comfortable.C. Messy.11. What color does the woman want to paint her room at first?A. Yellow.B. White.C. Green.12. What will the woman probably do on Saturday?A. Paint her room.B. Change her desk.C. Buy a mirror. 听第9段材料,回答第13至16题。
13. Which film are the speakers going to see?A. Field of Green.B. Sunn1y Day.C. Heart of Gold.14. How will the speakers go to the cinema?A. By car.B. By bus.C. On foot.15. When will the speakers arrive at the cinema?A At about 3:45. B. At about 4:05. C. At about 4:20.16. Why does the woman plan to take more money?A. She wants to buy a drink.B. She'd like to buy the man a ticket.C. She can take a taxi home afterwards.听第10段材料,回答第17至20题。
17. How did the couple order their meal?A. By speaking English.B. By using body language.C. By speaking slow and poor Chinese.18. Why did the couple call the waiter back?A. To change their order.B. To ask him to walk their dog.C. To order some food for their dog.19. How might the couple probably feel in the end?A. Angry.B. Satisfied.C. Tired.20. What do we know about the waiter?A. He lost the couple's dog.B. He misunderstood the couple.C. He only knew a little French.第二部分阅读(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项。
AThe COVID-19 pandemic led to a great number of rescheduling release dates(上映日期).Despite how the reality of the calendar develops,these are some films we're crossing our fingers that well get to see this next year.Malcolm & MarieRelease date: February 5Director: Sam LevinsonA director and his girlfriend's relationship is tested after they return home from his movie premiere(首映)and await critics' responses. he romantic drama is directed by Sam Levinson.Shang-Chi and the Legend of the Ten RingsRelease date: July 9Director: Destin Daniel CrettonIt's about time for the Marvel Cinematic Universe(漫威电影宇宙)to have its first Asian superhero on the silver screen. And there are few better heroes to pick than Shang-Chi, the Master of Kung Fu, who has the knowledge of nearly every martial art. This upcoming film will feature a 98% Asian cast.West Side StoryRelease date: December 10Director: Steven SpielbergSteven Spielberg's new adaptation of the famous Broadway musical of the same name, which itself was based on Shakespeare's Romeo and Juliet, is finally seeing the light of day in late 2021.The Matrix 4Release date: December 22Director: Lana WachowskiLana Wachowski is set to bring us another sci-fi action-adventure set in the digital world she helped create way back in 1999.1. What type of film is Malcolm & Marie?A. Comedy.B. Fantasy.C. Romance.D. Sci-fi.2. What do we know about Shang-Chi and the Legend of the Ten Rings?A. It is Marvel Studio's upcoming superhero film.B. It stars Destin Daniel Cretton.C. Its hero knows everything about martial art.D. It is a film with an all-Asian cast.3. Which of the following film is adapted from a musical?A. Malcolm & Marie.B. Shang-Chi and the Legend of the Ten Rings.C. West Side Story.D. The Matrix 4.BI was never very neat, while my roommate Kate was extremely organized. Each of her objects had its place, but mine always hid somewhere. She even labeled (贴标签) everything. I always looked for everything. Over time, Kate got neater and I got messier. She would push my dirty clothing over, and I would lay my books on her tidy desk. We both got tired of each other.War broke out one evening. Kate came into the room. Soon, I heard he r screaming, “Take your shoes away! Why under my bed!” Deafened, I saw my shoes flying at me. I jumped to my feet and started yelling. She yelled back louder.The room was filled with anger. We could not have stayed together for a single minute but for a phone call. Kate answered it. From her end of the conversation, I could tell right away her grandma was seriously ill. When she hung up, she quickly crawled under her covers, sobbing. Obviously, that was something she should not go through phone.All of a sudden, a warm feeling of sympathy rose up in my heart.Slowly, I collected the pencils, took back the books, made my bed, cleaned the socks and swept the floor, even on her side. I got so into my work that I even didn’t notice Kate had sat up. She was watc hing, her tears dried and her expression one of disbelief. Then, she reached out her hands to grasp mine. I looked up into her eyes. She smiled at me, “Thanks.”Kate and I stayed roommates for the rest of the year. We didn’t always agree, but we learned th e key to living together: giving in, cleaning up and holding on.4. How is Paragraph 1 mainly developed?A. By analyzing causes.B. By describing a process.C. By showing differences.D. By following time order.5. What made Kate angry one evening?A. She couldn’t find her books.B. She heard the author shouting loud.C. She got the news that her grandma was ill.D. She saw the author’s shoes beneath her bed.6. The author tidied up the room most probably because _______.A. she wanted to show her careB. she was asked by Kate to do soC. she was scared by Kate’s angerD. she hated herself for being so messy7. What might be the best title for the story?A. My Friend KateB. Hard Work Pays OffC. How to Be OrganizedD. Learning to Be RoommatesCSleep StruggleOne in every five young people has a sleep problem, so you're not alone. Getting enough sleep has become as important as eating vegetables and exercising regularly. It's very important for your body.Most young people only get seven hours of sleep each night, when they actually need nine hours. And making up for lost sleep during the week by sleeping on weekends doesn't really work. In fact, sleeping late on weekends may actually do you more harm than good, if you have sleep problems.What happens if you don't get enough sleep? If your sleep problem continues for a few nights, you could suffer serious problems. Lack of sleep can affect learning and memory. Worse,if your sleep difficulties last a long time,that could lead to anxiety(焦虑). Therefore,you've got to have some healthy sleep habits. Below are some suggestions:* Go to bed at the same time—including weekends, if possible.* Wake up around the same time every morning. When you sleep late just one morning during the week, it may disturb your body clock. This will make it hard for you to sleep that night.* Do something relaxing before going to bed.* Exercise during the day. Don't exercise right before going to bed.* Avoid drinking. Alcohol(酒精)makes you excited. This prevents you from falling asleep or wakes you up during the night.* Don't smoke. Smoking is always bad for the body. Smoking before bedtime keeps you awake.If trying these tips over a couple of weeks does not help you, consult your doctor. Do not take any medicine without first asking your doctor. Many of them have strong side effects.8. The passage suggests that people with sleep problems should .A. eat vegetables and exercise regularlyB. make up for lost sleep on weekendsC. follow a fixed timetable for sleepD. sleep seven hours every day9. According to the suggestions, which of the following makes it easier for you to fall asleep?A. Getting up earlier than usual in the morning.B. Listening to soft music before going to bed.C. Drinking alcohol before going to bedD. Doing exercise in the evening.10. What should you do if these tips don't work on you over a period of time?A. Just keep trying.B. Turn to a doctor for help.C. Try some medicines.D. Wait for your sleeping problems to get better.11. Where is the text most likely from?A. A diary.B. A novel.C. A travel guide.D. A magazine.DPart of a research study, by scientists at McMaster University, which is ongoing into the influence of drinking milk after heavy weightlifting, has observed that milk helps exercisers burn more fat.The scientists took three groups of young men 18 to 30 years of age, 56 in total, and put them through a strict, five day per week weightlifting program over a 12-week period. Following their workouts, study participants drank either two cups of skim milk, or a soy beverage with equal amounts of protein and energy, or a carbohydrate beverage with an equal amount of energy.Upon the study's conclusion, scientists observed that: the milk drinking group had lost nearly twice as much fat—two pounds—as those in the carbohydrate beverage group, who lost one pound of fat. Those drinking soy beverages lost no fat. At the same time, the gain in muscle was much greater among the milk drinkers than either the soy or carbohydrate beverage participants.As published in the first stage of the study, the milk drinking group came out on top in terms of muscle gain with an estimated 40 percent or 2.5 pounds more muscle mass than the soy beverage drinkers. In addition, this group gained 63 percent or 3.3 pounds more muscle mass than the carbohydrate beverage drinkers."I think the evidence is beginning to increase," says Stuart Phillips—the leader of the study. "Milk may be best known for its calcium content in supporting bone health, but our research, and later others', can continually support milk's ability to aid in muscle growth and also promote body fat loss. Milk is the ideal post workout drink for recreational exercisers and athletes alike."12. How many days did the participants lift weights in the program?A. 56 days.B. 84 days.C. 60 days.D. 12 days.13. What does the underlined word "beverage" probably mean?A. A kind of medicine.B. A sort of drink.C. A type of exercise.D. A piece of equipment.14. According to the passage, we can know thatA. the scientists chose people aged 18, 30 and 56 as participants of the researchB. a soy beverage is a proper choice for losing weight over the long termC. people who drink milk every day are always healthier and thinner than othersD. soy beverages are better than carbohydrate beverages for exercisers to gain muscle15. What does the passage mainly talk about?A. What exercisers should do to lose weight.B. How milk influences people's health and figure.C. The differences between milk and soy or carbohydrate beverages.D. A research about the effect of drinking milk on exercisers.第二节(共5小题;每小题2.5分,满分12.5分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。